I have a project to build heating element using silver ink.  

My specification is the heating element must be in range 2 to 2.6ohm  

I will design the circuit for the heating element, but have a problem   

how to theoretically measure the resistance of the circuit(before send to print house).  

Based on reference on this website 

<http://circuitcalculator.com/wordpress/2006/06/14/conductive-ink-traces/>

the resistance can be measure as below  

Resistance = Sheet\_Resistivity\*(Length/Width)\*(Ref\_Thickness/Thickness)  

In my case,   

Sheet Resistivity = 10miliohms/square,   

Ref\_Thickness = 1mil(0.025mm)  

Thickness = 1mil(0.025mm)  

1) Based on the quotation, if I have 50mm x 50mm & another one is 10mm x 10mm  

silver ink with same thickness, the ohm will be the same which is 10miliohms.   

Is it logic?

2) Another question is, how to measure the resistance if I design a complicated  

circuit as per attached image? In the image, 1box considered as 1mm x 1mm  

Point "A" and point "B" will be connected to battery(+ve & -ve).   

Blue color indicate the silver ink  

![Circuit for heating element](https://i.stack.imgur.com/Ah7nq.png)

Your advice and explanation will be very helpfull. Thank you.