If we have $x^3-9x-5=0$, then what $x^4-18x^3-81x^2-12$ equals to?

This is a multiple choices question. 
A)$5$ B)$25$ C)$42$ D)$67$ E)$81$.

My attempt, 

By long division of polynomials, we have $x^4-18x^3-81x^2-12=(x-18)(x^3-9x-5)+(-72x^2-157x-102)$

Since $x^3-9x-5=0$, whatever $x$ could be, $x^4-18x^3-81x^2-12=-72x^2-157x-102$ 

How to proceed? 

P/S. Conclusion, NONE of the options can be right.