The following sequence was given to me by one of my friend:

> 
> $$\color{red}{2 \star 8 \star 8 = 161642}$$
> $$\color{blue}{4 \star 9 \star 7 = 362843}$$
> $$\color{red}{7 \star 5 \star 9 = 356344}$$
> $$\color{blue}{9 \star 6 \star 8 = 547245}$$
> $$\color{red}{5 \star 7 \star 9 = 354546}$$
> $$\color{blue}{3 \star 9 \star 9 = 272748}$$
> $$\color{red}{4 \star 8 \star 9 = \text{M}}$$
> $\color{red}{\text{M}}$ = ? 
> 
> 
> 

**My Thoughts**: 

The first two digits of R.H.S can be found by $a.b$ , where L.H.S = $a \star b \star c$ ,  

i.e, For 1st relation: $2.8=16 = 1^{st}$ two digits of $\color{green}{16}1642$ 

Similarly,the second two digits of R.H.S can be found by $a.c$ , where L.H.S = $a \star b \star c$ ,  

i.e, For 2nd relation: $4.7=28 = 2^{nd} $ two digits of $36 \color{green}{28}43$ 

$$\implies M= 3236 \, \\_ \, \\_$$

How do I find the $3^{rd}$ two digits of R.H.S?