I am trying to create a program that will ID items in a list by giving them a number from 0-9 followed by a letter. It works like this: the first 10 items would be 0A, 1A, 2A all the way to 9A. Then I want to 11th item to be 0B. Is there anyway to have python do this automatically? I'll put an example of a list of products that need an ID for question purposes.

```
import random
import string

alphabet= "ABCDEFGHIJKLMOPQRSTUVWYZ"
products_fruit = ["apple", "banana", "orange", "grapes"]
fruit_id = range(0, len(products_fruit))

for id, product in zip(fruit_id, products_fruit):
  print("0" + str(id) + str(alphabet[0]) + " =", product)

```

You can see that right now I'm just printing an A but I want my 11th item to automatically have str(alphabet[1]) (the letter B) printed after to be 0B.
The outcome for this code is:

```
00A = apple
01A = banana
02A = orange
03A = grapes

```

I want the 11th and 21st product to be:
 00B = product11
 00C = product21

Thank you!