say i have a line of text in a file as follows:

```
-config1=/path/to/config1.cfg -config2=/path/toconfig2.cfg -input=/path/to/file.txt -output=/path/to/file.out

```

How can i have awk parse out only `-input=/path/to/file.txt`

Right now i'm doing:

```
echo $data | awk -F"-input=" '{print $2}'

```

and it returns to me the entire line above. 

Is there a way to do this without using the cut command? Not that i CAN'T use it but, i'm trying to avoid a lot of fork/execs.

Edit: I rushed typing this question. What i really wanted to get my hands on was the name of the input file. In my example that would be `file.txt`. I was using `-input=` as a delimeter to awk because at first i thought i wanted `/path/to/file.txt`. This returned to me `/path/to/file.txt -output=/path/to/file.out`. Which i did not want. 

Later I realized that i really just wanted/needed the name of the input file.

Sorry about that!