If I have a string such as

"17:31:51 up 134 days, 11:26, 1 user, load average: 0.22, 0.15, 0.10"

what is the best way to extract just the x3 load average values at the end? I have written a regexp that does this but is this the most efficient / fastest method?

```
>>> s = "17:31:51 up 134 days, 11:26,  1 user,  load average: 0.22, 0.15, 0.10"
>>> print re.findall(r"([0-9]\.\d+)", s)
['0.22', '0.15', '0.10']

```