Trying to determine all characters in a file.

The file `sample` consists of:

```
a eɪ
abandon əˈbændən
ability əˈbɪləti
able ˈeɪbəl
able ˈeɪbl
abortion əˈbɔrʃən
abortion əˈbɔrʃn
about əˈbaʊt
above əˈbʌv
abroad əˈbrɔd

```

Confirmed locale is correct:

```
$ echo $LANG

en_US.UTF-8

```

A command to take the second field, split by character, then count how many:

```
$ cat sample | awk '{print $2}' | grep -o . | sort | uniq -c | sort -n

  1 a
  1 æ
  1 i
  1 v
  2 d
  2 t
  3 e
  3 l
  3 ɔ
  3 r
  4 n
  9 b
 11 ə
 17 ɪ

```

Where is `ʃ` and `ˈ`? They aren't combining characters or anything special. Note that other UTF-8 characters are pulled out: `ɔ`, `ə` and `ɪ`, for example.

BTW using `sed 's/\(.\)/\1\n/g'` has nearly the same results as `grep -o .`, except it adds a line for '\n'.

Is there something I'm missing? Does grep have a hidden UTF-8 option?

In case it matters I'm using `Ubuntu 12.04.2 LTS`.