I want to get some number, and assign the result to a custom string。I want to get numbers and I can use it in the next part of this script

the name of this cript is calQue.sh. the content of it is like:

```
#!/bin/bash

lsfDir=/opt/ibm/lsf/10.1/linux3.10-glibc2.17-x86_64/bin

Queue="ser short medium large"

for i in $Queue
do
  queName=`echo $i"idleNum"`
  $queName"idleNum"=`$lsfDir/bhosts hg_$i | grep ok | awk '{if($5==0) print $0}' | wc -l`
done

echo $seridleNum

```

I ran it,

```
sh calQue.sh

```

and it is wrong. the result i got is:

```
calQue.sh: line 14: seridleNumidleNum=1: command not found
calQue.sh: line 14: shortidleNumidleNum=7: command not found
calQue.sh: line 14: mediumidleNumidleNum=37: command not found
calQue.sh: line 14: largeidleNumidleNum=4: command not found

```

So i tried other ways like:

```
for i in $Queue
do
  queName=`echo $i`
  idleNum=`$lsfDir/bhosts hg_$i | grep ok | awk '{if($5==0) print $0}' | wc -l`

  #`echo $i`Num=$idleNum   //it is wrong

  #$queName=$idleNum       //it is wrong

```

done

and

```
Queue="ser short medium large"

for i in $Queue
do
  queName=`echo $i`
  "$i"idleNum=`$lsfDir/bhosts hg_$i | grep ok | awk '{if($5==0) print $0}' | wc -l`
   echo $"$i"idleNum  //it is wrong
done

```

How do i can get correct result, for example:

string seridleNumidleNum should be equal 1;

I find it is right when the string without variable $i

```
idleNum=`$lsfDir/bhosts hg_$i | grep ok | awk '{if($5==0) print $0}' | wc -l`
echo $idleNum

```