Well it's a little question:

How do you prove that:

> 
> 
> > 
> > $$\lim\_{x\to 0}\frac{\sin(x)}{x}=\lim\_{x\to 0}\Gamma(x)\sin(x)=1$$
> > 
> > 
> > 
> 
> 
> 

Where we speak about [the Gamma function](https://en.wikipedia.org/wiki/Gamma_function).

The most quick proof uses the reflection Euler formula because:

$$\lim\_{x\to 0}\Gamma(x)\sin(x)=\lim\_{x\to 0}\Gamma(x)\Gamma(1-x)\sin(x)=1$$

Well I think there are a lot of proofs so I add the tag "big-list".

Particularly I would be happy to see a proof using the squeeze theorem.

Thanks in advance!!!