I'm using planning to use CP2102 as an USB/UART transceiver. Datasheet (can be found here: <https://www.silabs.com/documents/public/data-sheets/CP2102-9.pdf>) on page 21 shows example of self-powered schematic, and that's exactly my scenario: external 3.3V LDO regulator which feeds several ICs on the board, including CP2102. In this case divider circuit is needed in order CP2102 could safely detect USB Vbus presence. However, same picture shows that in total 4 decoupling capacitors are required, 2 on Vdd pin, and 2 on REGIN input to internal 3.3V regulator.
[![enter image description here](https://i.stack.imgur.com/wbIGC.png)](https://i.stack.imgur.com/wbIGC.png)

But these two pins are physically adjacent to each other, see picture below:
[![enter image description here](https://i.stack.imgur.com/5iDA4.png)](https://i.stack.imgur.com/5iDA4.png)

Do I really need to use 4 caps? Or I can connect these two pins by a trace, and use 2 capacitors for decoupling?
My schematic for this part of the board so far is below:
[![enter image description here](https://i.stack.imgur.com/eTYRI.png)](https://i.stack.imgur.com/eTYRI.png)

Also, can I omit resistor from 3.3V to RESET pin? It would be very convenient to connect them directly by short trace underneath the chip.