problem resolved (in comments)
i am making a project for school and i am getting this error Trying to access array offset on value of type null on this line of code

```
<div class="user-name"><?php echo $guests["firstName"] ?></div>

```

it is in this code and i retrieve the information out of a database

```
foreach((array)$result as $guests)
        {
    ?>
    <div class="posts-container">
        <div class="post-header">
            <div class="user-details">
                <div class="user-name"><?php echo $guests["firstName"] ?></div>
                <div class="user-email"></div>
            </div>
            <div class="time"></div>
        </div>
        <div class="post-message">
            <h3></h3>
            <p></p>
        </div>
    </div>
    <?php } ?>

```

people asked for the sql code and the type/structure of $result
type/structure:
object(mysqli\_result)#2 (5) { ["current\_field"]=> int(0) ["field\_count"]=> int(9) ["lengths"]=> NULL ["num\_rows"]=> int(5) ["type"]=> int(0)
sql/database:

```
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "guestbook";

// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
  die("Connection failed: " . $conn->connect_error);
}

$sql = "SELECT id, firstName, lastName, email, title, message, URL, showEmail, Date FROM guestbook";
$result = $conn->query($sql);

$conn->close();

```