I'm using a code that I also found here that filters a table based on a dropdown selection. I'm not well-versed with JQuery/Javascript. My Question is how can I "show all" the data using this code snippet:

dropdown:

* Show All
* Done
* On-going
* Not yet started

```js
$(document).ready(function($) {
  $('#selectField').change(function() {
    var selection = $(this).val();
    var dataset = $('table').find('tr');
    dataset.show();
    dataset.filter(function(index, item) {
      return $(item).find('td:nth-child(1)').text().split(',').indexOf(selection) === -1;
    }).hide();
  });
});
```

```html
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.0/jquery.min.js"></script>
<select id='selectField'>
  <option value=" "> Show All </option>
  <option value="Done"> Done </option>
  <option value="On-going"> On-going</option>
  <option value="Not yet started"> Not yet started </option>
</select>

<table border="2">

  <tr>
    <td>Done</td>
  </tr>
  <tr>
    <td>On-going</td>
  </tr>
  <tr>
    <td>Done</td>
  </tr>
  <tr>
    <td>Not yet started</td>
  </tr>
  <tr>
    <td>Not yet started</td>
  </tr>

</table>
```