<|system|>
Given a right triangle whose side lengths are all integer multiples of 8, how many units are in the smallest possible perimeter of such a triangle?</s>.
<|user|>
Can you answer based on context?
<|assistant|>
I want to find the smallest possible right triangle with side lengths that are multiples of 8. I know that a right triangle has to satisfy the Pythagorean theorem, so if the legs are 8a and 8b, and the hypotenuse is 8c, then I have (8a)^2 + (8b)^2 = (8c)^2. I can divide both sides by 64 to get a^2 + b^2 = c^2. This is a familiar equation, and I know that one of the smallest solutions is a = 3, b = 4, and c = 5. That means the side lengths of the triangle are 8 * 3 = 24, 8 * 4 = 32, and 8 * 5 = 40. The perimeter of the triangle is the sum of the side lengths, so I get 24 + 32 + 40 = 96. 