<|system|>
Simplify $\sqrt[3]{1+8} \cdot \sqrt[3]{1+\sqrt[3]{8}}$.</s>.
<|user|>
Can you answer based on context?
<|assistant|>
The first cube root becomes $\sqrt[3]{9}$. $\sqrt[3]{8}=2$, so the second cube root becomes $\sqrt[3]{3}$. Multiplying these gives $\sqrt[3]{27} = 3$.