<|system|>
In right triangle $ABC$ with $\angle A = 90^\circ$, we have $AB = 6$ and $BC = 10$.  Find $\cos A$.</s>.
<|user|>
Can you answer based on context?
<|assistant|>
Since $\angle A = 90^\circ$, we have $\cos A = \cos 90^\circ= 0$.