<|system|>
Solve for $z$ in the following equation: $2-3iz = 3 + 2iz$.</s>.
<|user|>
Can you answer based on context?
<|assistant|>
$2-3iz = 3 + 2iz \Rightarrow -1 = 5iz \Rightarrow z = \frac{-1}{5i}$. Multiplying the numerator and denominator by $-i$, we get $z = \frac{-1}{5i} \cdot \frac{-i}{-i} = \frac{i}{5}$.