The balanced equation is the only way to relate NaCl, HCl, and NaOH; therefore, the amounts of HCl, NaCl, and NaOH must be related using moles. That means all the concentrations must be converted to moles each time the solutions are used.
http://www.westfield.ma.edu/cmasi/gen_chem1/Solutions/Molarity/molarity.htm
Relevance. Rating Newest Oldest. Best Answer: Quick formula to use C(in molarity)= 10x(%m/m)xd/MM=10*37*1.11/37=11.1 M In which %m/m =37 d=1.11 MM= 37 g/mol (molar mass) Explanation: 37% means there are 37g of HCl in 100 g solution.
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37g HCl----------------------------100g solution A-From the 37 g calculate the number of moles B-From the 100g of solution and density calculate the V A-n=m/MM, n=37/37=1 mol B-d=m/V, V=m/d, V=100/1.11 =90 ml Now you can calculate the concentration of the solution, C=n/V C=1/0.090= 11.1 M.
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RE: Molarity of a concentrated hydrochloric acid solution? What is the molarity of a concentrated 37.0% hydrochloric acid solution, given that the density of the solution is 1.11 g/mL? I have been staring at this problem forever, please help! Please do not just give me the answer, explaining how it is done step by step would be greatly appreciated.
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It is one liter of solution not one liter of water.. Be careful on this, especially when you get to molality. The most typical molarity problem looks like this: What is the molarity of whatever grams of whatever substance dissolved in whatever mL of solution. To solve it, you convert grams to moles, then divide by the volume, like this: The two steps just mentioned can be combined into one equation.
http://www.chemteam.info/Solutions/Molarity.html
Rating Newest Oldest. Best Answer: Molarity is defined as moles per liter. To find the number of moles of HCl, you need its density at the desired temperature, and then multiply it by the number of mL (10). That will give you the number of grams present in your 10mL sample. Then, divide that number by the molar mass of HCl (36.46 g/mol).
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Molarity Problems. First kind: Determine the concentration of a solution. What is the concentration (molarity) of a solution made by dissolving 0.20 mol ammonium nitrate (NH 4 NO 3) in enough water to make 500.0 mL of an NH 4 NO 3 solution. Since molarity is just moles per liter if you know how many moles are present in a certain number of liters then you know the molarity. Second kind: Determine the number of moles in a certain volume of a solution of known concentration.
http://www.westfield.ma.edu/cmasi/gen_chem1/Solutions/Molarity/molarity.htm
Composition of concentrated reagent grade acids, ammonium hydroxide, and sodium and potassium hydroxide solutions (with dilution directions to prepare 1N solution).
http://www.sigmaaldrich.com/chemistry/stockroom-reagents/learning-center/technical-library/reagent-concentrations.html
Boy, does it! The molarity of a solution is calculated by taking the moles of solute and dividing by the liters of solution. This is probably easiest to explain with examples. Example #1: Suppose we had 1.00 mole of sucrose (it's about 342.3 grams) and proceeded to mix it into some water. It would dissolve and make sugar water.
http://www.chemteam.info/Solutions/Molarity.html
Purpose: The purpose of this lab is to determine the concentration of a hydrochloric acid solution using acid‐base titration. Background: Titration is a technique that chemists use to determine the unknown concentration of a known solution (we know what chemical is dissolved, but not how much in a solution).
https://www.apsu.edu/sites/apsu.edu/files/chemistry/SP12_1011_Titration_of_Hydrochloric_Acid_with_Sodium_Hydroxide_0.pdf
what is the molarity of hcl
The morality of HCl is equal to the density at the desired temperature, multiplied by the number of milliliters. The molarity of HCL is a density at the desired temperature and then multiply it by the number of 10 mL.