Weegy: -12x + 5x = -7x User: Simplify 3x + (-12x) - 5x. Weegy: 3x + (-12x) - 5x = 3x - 12x - 5x = -9x - 5x = -14x ...
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What is the volume of the gas at STP if 20.0ml of 0.1M HCl is used to dissolve all the Mg? (note, you need to cover gas laws before you can answer this).
http://www.ualr.edu/rebelford/chem1402/q1402/X2/C4/4-5/4-5.htm
One reaction that produces hydrogen gas can be represented by the following unbalanced chemical equation: a. what mass of HCl(aq) is consumed by the reaction of 2.50 moles of magnesium?
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Weegy: -4(N + 9) = -4N - 36 User: Simplify 6(x + y) + (x-y). Weegy: 6(x + y) + (x-y) = 6x + 6y + x-y = 7x + 5y ...
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Report Abuse. You can see from the equation that 1 mole of Mg and 1 mol of HCl produces 1 mol of MgCl2 and 1 mol of H2. So if you use 2.50 moles of HCl, you must use 2.50 moles of Mg. So, find the molar mass of Mg and multiply that by 2.50 moles. Because you have 2.50 moles of Mg and 2.50 moles of HCl, you will produce 2.50 moles of MgCl2 and H2 each, according to the equation.
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After (.1) Mg was added to HCL bubbled and temp increased to 33.9. pressure- 1.86. volume- 129.9. When letting it cool back to room temp (21.5 C) the new pressure was 1.76 atm. 3. Use the ideal gas equation in the Background section of the lab manual (PV=nRT) to find the number of moles of gas produced by the reaction. The gas constant, R, is given as: R = 0.082057 (L*atm)/(K*mole) You will need to convert the temperature from Celsius to Kelvin by adding 274. 4. Use the balanced equation for the reaction to convert moles of hydrogen gas, H2, to moles of Mg consumed in the reaction. 5.
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The reaction between HCl and Mg produces Hydrogen gas and Magnesium Chloride.   A balanced equation for this reaction:   Mg(s)+2HCl(l)→H2(g)+MgCl2(l).
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… moles HCl/0.250 liters = 0.75 moles HCl ----------------------------now, refer to equation and drive reactant against product to get moles H2 0.75 moles HCl (1 mole H2/2 mole HCl) = 0.375, or 0.38 mole hydrogen gas produced ------------------------------------------------------------. 2 people found this useful.
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We can use PV = nRT to find moles of HCl (1 atm)(4.60 L) = n(0.08206 L*atm/mol*K)(298.15 K) moles HCl = 0.188 moles Molarity = moles of solute/Liters of solution Molar … ity = 0.188 moles HCl/0.240 liters = 0.783 Molar HCl =====. BJ Sullivan.
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Lab 1: Volume of Hydrogen Gas Purpose: to determine the volume of hydrogen gas formed when a sample of Mg reacts with 6 M HCl according to: Mg (s) + 2 HCl (aq)  MgCl 2(aq) + H 2(g) and to compare the actual measured volume to the theoretical volume expected. 1. Measure the length of the Mg ribbon in cm.
http://www.emsb.qc.ca/laurenhill/science/h2lab.pdf
which gas is produced when mg(s) is added to hcl(aq
When MG is added to HCL, H2 is produced.