are all monosaccharides optically active
With only one exception, the monosaccharides are optically active compounds. Although both D and L isomers are possible, most of the monosaccharides found in nature are in the D configuration. Structures for the D and L isomer of the simplest aldose, glyceraldehyde, are shown below. With only one exception, the monosaccharides are optically active compounds. Although both D and L isomers are possible, most of the monosaccharides found in nature are in the D configuration. 4.1.2 Monosaccharides. In general all monosaccharides are soluble in water, sparingly soluble in ethanol and insoluble in ether, are optically active, possess reducing properties (ie. reduce Fehling's solution), can be represented by the general formula C x H 2x O x, and generally possess a sweet taste. In general all monosaccharides are soluble in water, sparingly soluble in ethanol and insoluble in ether, are optically active, possess reducing properties (ie. reduce Fehling's solution), can be represented by the general formula C x H 2x O x, and generally possess a sweet taste. OPTICALLY ACTIVE SUGARS. The property pos sessed by sugars of rotating the plane of polar ized light to the right or left when passed through their solutions has long served as a basis for classification. Sugars possessing this prop erty are said to be optically active.and those which do not are said to be inactive. To decide whether a compound should be optically active, we look for evidence that the molecules are chiral. The instrument with which optically active compounds are studied is a polarimeter, shown in the figure below. Glyceraldehyde serves as the basis in naming monosaccharides since it is the simplest monosaccharide, having only one asymmetric carbon. (+)-Glyceraldehyde was arbitrarily named the D-enantiomer (the hydroxy group is on the right when drawn as a Fischer Projection). (Assume that any chiral compound would be isolated in enantiomerically pure form.) I deduced that the... show more Dr. Isent T. Sweet isolated a monosaccharide and determined that it had a molecular weight of 150. Much to his surprise, he found that it was not optically active. One enantiomer of these chiral compounds is dextrorotatory; the other is levorotatory. To decide whether a compound should be optically active, we look for evidence that the molecules are chiral. The instrument with which optically active compounds are studied is a polarimeter, shown in the figure below. Sugars possessing this prop erty are said to be optically active.and those which do not are said to be inactive. Those that turn the plane of polarization to the right are called dextro-rotatory; those to the left, lxvo-rotatory.
Yes