Q:

Why does "1" == 1 return true in Javascript?

I'm trying to learn more about this liberal language and a good explanation would be awesome.
Thanks!

A:

From the spec

The Abstract Equality Comparison Algorithm
The comparison x == y, where x and y are values, produces true or
  false. Such a comparison is performed as follows:

If Type(x) is the same as Type(y), then
a. If Type(x) is Undefined, return true.
b. If Type(x) is Null, return true.
c. If Type(x) is Number, then
i. If x is NaN, return false.

ii. If y is NaN, return false.

iii. If x is the same Number value as y, return true.

iv. If x is +0 and y is −0, return true.

v. If x is −0 and y is +0, return true.

vi. Return false.

d. If Type(x) is String, then return true if x and y are exactly the same sequence of characters (same length and same characters in
  corresponding positions). Otherwise, return false.
e. If Type(x) is Boolean, return true if x and y are both true or both false. Otherwise, return false.
f. Return true if x and y refer to the same object. Otherwise, return false.
If x is null and y is undefined, return true.
If x is undefined and y is null, return true.
If Type(x) is Number and Type(y) is String,    return the result of the comparison x == ToNumber(y).
If Type(x) is String and Type(y) is Number,    return the result of the comparison ToNumber(x) == y.
If Type(x) is Boolean, return the result of the comparison ToNumber(x) == y.
If Type(y) is Boolean, return the result of the comparison x == ToNumber(y).
If Type(x) is either String or Number and Type(y) is Object,    return the result of the comparison x == ToPrimitive(y).
If Type(x) is Object and Type(y) is either String or Number,    return the result of the comparison ToPrimitive(x) == y.
Return false.

