Q:

Splitting a Java String with '.'

I have 
1. This is a  test message

I want to print 
This is a  test message

I am trying 
String delimiter=".";
String[] parts = line.split(delimiter);
int gg=parts.length;

Than want to print array
 for (int k ;k <gg;K++)
    parts[k];

But my gg is always 0.
am I missing anything.
All I need is to remove the number  and . and white spaces
The number can be 1 (or) 5 digit number

A:

You are using "." as a delimiter, you should break the special meaning of the . char.
The . char in regex is "any character" so your split is just splitting according to "any character", which is obviously not what you are after.
Use "\\." as a delimiter
For more information on pre-defined character classes you can have a look at the tutorial.
For more information on regex on general (includes the above) you can try this tutorial

EDIT:
P.S. What you are up to (removing the number) can be achieved with a one-liner, using the String.replaceAll() method.
System.out.println(line.replaceAll("[0-9]+\\.\\s+", ""));

will provide output
This is a  test message

For your input example.
The idea is: [0-9] is any digit. - the + indicate there can be any number of them, which is greater then 0. The \\. is a dot (with breaking as mentioned above) and the \\s+ is at least one space. 
It is all replaced with an empty string.
Note however, for strings like: "1. this is a 2. test" - it will provide "this is a test", and remove the "2. " as well, so think carefully if that is indeed what you are after.

A:

Use following code..
String delimtor="\\."; // use this because . required to be skipped
String[] parts = line.split(delimtor);

For your for loop.
 for (int k=0 ;k <gg.length;K++)
    parts[k];

