Q:

Simple interest problem

I'm new to this site. I'm not sure exactly what appropriate tag I should use, but if anyone could help me with the tags, thens thats great :-) Anyways, I'm having difficulty figuring out a solution to my problem. I'm not really good with word problems so I'm not sure what type of equation I should format to get an answer. I'm not looking for the answer, I'm really looking for the equation to get my answer. I hope that makes sense. The question is below.... 

Michael invested $\$1,000$: one portion in a fund with 12% simple interest and the rest of money in a fund with 11% simple interest. In one year he earned $\$116$ in interest. How much was invested in each fund?

A:

Let $A_1$ be the amount invested in the first account and let $A_2$ be the amount invested in the second account.
Thus $A_1 + A_2 = 1000$ $(1)$
Also, interest earned in the first account is:
$I_1 = 0.12*A_1$
and similarly, interest earned in the second account is:
$I_2 = 0.11A_2$
Therefore,
$0.12A_1 + 0.11A_2 = 116$ $(2)$
Equations (1) and (2) can be solved simultaneously to arrive at:
$0.01A_2 = 4$
Thus,
$A_2 = 400$ and therefore $A_1 = 600$

