namespace tf {

/** @page graphtraversal Graph Traversal

We study the graph traversal problem by visiting each vertex in parallel following their
edge dependencies. Traversing a graph is a fundamental building block of many
graph applications especially for large-scale graph analytics.

@section GraphTraversalProblemFormulation Problem Formulation

Given a directed acyclic graph (DAG), i.e., a graph that has no cycles, 
we would like to traverse each vertex in order without breaking dependency constraints defined by edges.
The following figure shows a graph of six vertices and seven edges.
Each vertex represents a particular task and each edge represents a task dependency between two tasks.

@image html images/task-level-parallelism.svg width=50%

Traversing the above graph in parallel, the maximum parallelism we can acquire is three.
When Task1 finishes, we can run Task2, Task3, and Task4 in parallel.

@section GraphTraversalGraphRepresentation Graph Representation

We define the data structure of our graph. The graph is represented by an array of nodes of the following structure:

@code{.cpp}
struct Node {
  std::string name;
  size_t idx;                          // index of the node in a array
  bool visited {false};

  std::atomic<size_t> dependents {0};  // number of incoming edges
  std::vector<Node*> successors;       // number of outgoing edges

  void precede(Node& n) {
    successors.emplace_back(&n);
    n.dependents ++;
  }
};
@endcode

Based on the data structure, we randomly generate a DAG using ordered edges.

@code{.cpp}
std::unique_ptr<Node[]> make_dag(size_t num_nodes, size_t max_degree) {
  
  std::unique_ptr<Node[]> nodes(new Node[num_nodes]);
  
  // Make sure nodes are in clean state
  for(size_t i=0; i<num_nodes; i++) {
    nodes[i].idx = i;
    nodes[i].name = std::to_string(i);
  }

  // Create a DAG by randomly insert ordered edges
  for(size_t i=0; i<num_nodes; i++) {
    size_t degree {0};
    for(size_t j=i+1; j<num_nodes && degree < max_degree; j++) {
      if(std::rand() % 2 == 1) {
        nodes[i].precede(nodes[j]);
        degree ++;
      }
    }
  }

  return nodes;
}
@endcode

The function, @c make_dag, accepts two arguments, @c num_nodes and @c max_degree, to 
restrict the number of nodes in the graph and the maximum number of outgoing edges of every node.

@section GraphTraversalStaticTraversal Static Traversal

We create a taskflow to traverse the graph using static tasks (see @ref chapter1).
Each task does nothing but marks @c visited to @c true 
and subtracts @c dependents from one, both of which are used for validation after the graph is traversed.
In practice, this computation may be replaced with a heavy function.

@code{.cpp}    
tf::Taskflow taskflow;
tf::Executor executor;

std::unique_ptr<Node[]> nodes = make_dag(100000, 4);
std::vector<tf::Task> tasks;

// create the traversal task for each node
for(size_t i=0; i<num_nodes; ++i) {
  tf::Task task = taskflow.emplace([v=&(nodes[i])](){
    v->visited = true;
    for(size_t j=0; j<v->successors.size(); ++j) {
      v->successors[j]->dependents.fetch_sub(1);
    }
  }).name(nodes[i].name);

  tasks.push_back(task);
}

// create the dependency between nodes on top of the graph structure
for(size_t i=0; i<num_nodes; ++i) {
  for(size_t j=0; j<nodes[i].successors.size(); ++j) {
    tasks[i].precede(tasks[nodes[i].successors[j]->idx]);
  }
}

executor.run(taskflow).wait();

// after the graph is traversed, all nodes must be visited with no dependents
for(size_t i=0; i<num_nodes; i++) {
  assert(nodes[i].visited);
  assert(nodes[i].dependents == 0);
}
@endcode

The code above has two parts to construct the parallel graph traversal.
First, it iterates each node and constructs a traversal task for that node.
Second, it iterates each outgoing edge of a node and creates a dependency between the node and the other end
(successor) of that edge.
The resulting taskflow structure is topologically equivalent to the given graph.

@image html images/graph_traversal_2.svg width=100%

With task parallelism, we flow computation naturally with the graph structure.
The runtime autonomously distributes tasks across processor cores to obtain maximum task parallelism.
You do not need to worry about details of scheduling.

@section GraphTraversalDynamicTraversal Dynamic Traversal 

We can traverse the graph dynamically using tf::Subflow (see @ref chapter3).
We start from the source nodes of zero incoming edges and recursively spawn subflows 
whenever the dependency of a node is meet.
Since we are creating tasks from the execution context of another task,
we need to store the task callable in advance.
  
@code{.cpp}
tf::Taskflow taskflow;
tf::Executor executor;

// task callable of traversing a node using subflow
std::function<void(Node*, tf::Subflow&)> traverse;

traverse = [&] (Node* n, tf::Subflow& subflow) {
  assert(!n->visited);
  n->visited = true;
  for(size_t i=0; i<n->successors.size(); i++) {
    if(n->successors[i]->dependents.fetch_sub(1) == 1) {
      subflow.emplace([s=n->successors[i], &traverse](tf::Subflow &subflow){ 
        traverse(s, subflow); 
      }).name(n->name);
    }
  }
};

// create a graph
std::unique_ptr<Node[]> nodes = make_dag(100000, 4);

// find the source nodes (no incoming edges)
std::vector<Node*> src;
for(size_t i=0; i<num_nodes; i++) {
  if(nodes[i].dependents == 0) { 
    src.emplace_back(&(nodes[i]));
  }
}

// create only tasks for source nodes
for(size_t i=0; i<src.size(); i++) {
  taskflow.emplace([s=src[i], &traverse](tf::Subflow& subflow){ 
    traverse(s, subflow); 
  }).name(nodes[i].name);
}

executor.run(taskflow).wait();

// after the graph is traversed, all nodes must be visited with no dependents
for(size_t i=0; i<num_nodes; i++) {
  assert(nodes[i].visited);
  assert(nodes[i].dependents == 0);
}
@endcode

@image html images/graph_traversal_1.svg width=90%

In general, the dynamic version of graph traversal is slower than the static version due to the
overhead incurred by spawning subflows.
However, it may be useful for the situation where the graph structure is unknown at once but
being partially explored during the traversal.


*/

}








