Q:

Haskell: Check if all conditions are true. If they are return true otherwise false

I was writing some Haskell this afternoon and I have a list of conditions that must be satisfied. If they are all true I want to return true, if one of them is false then return false.
I have a method that is working but I was just wondering if there is a better way to implement it for readability/efficiency.
Here is what I have:
checkMatch :: Person -> Person -> Bool
checkMatch seeker candidate
    |  gender candidate == preferedGender seeker 
    && gender seeker == preferedGender candidate
    && minAcceptableAge seeker <= age candidate 
    && maxAcceptableAge seeker >= age candidate
    && minAcceptableAge candidate <= age seeker
    && maxAcceptableAge candidate >= age seeker = True
    |  otherwise = False

Gender is defined as:
data Gender = Male | Female (Eq)

So I just aligned the &&'s and |'s to make this look a little better but I feel there has to be a better way, but can't seem to come up with anything searching Google.
Thanks in advanced!

A:

You can lose the guards and use and to check your conditions:
checkMatch :: Person -> Person -> Bool
checkMatch seeker candidate = and [ 
    gender candidate           == preferedGender seeker 
  , gender seeker              == preferedGender candidate
  , minAcceptableAge seeker    <= age candidate 
  , maxAcceptableAge seeker    >= age candidate
  , minAcceptableAge candidate <= age seeker
  , maxAcceptableAge candidate >= age seeker
  ]

