Q:

How to subtract a day from datetime format in python?

I'm trying print the day ranges from today up to a year ago. So i can apply this to a sql query in my other code.
I know my algorithm works but i need to subtract 1 day from the format '2014-05-15'
Here is the code
from datetime import date, timedelta
import datetime
current_date = datetime.date.today()
datecounter = 0
while datecounter != 365:
    print current_date
    date_start = current_date
    print date_start
    # current_date = current_date.timedelta(days=1)
    print current_date
    print 'the date is between', date_start, 'and', current_date
    datecounter += 1

im looking for this code to output
the date is between 2014-05-16 and 2014-05-15
the date is between 2014-05-15 and 2014-04-14

etc
i wrote a contrived example based on the logic, if you would like to run it yourself, you may better understand what i am trying to do.
x = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
curdate = 5
for i in x:
    print curdate
    date_start = curdate
    curdate = curdate - 1
    # print curdate

    print ' the date is between', date_start, 'and', curdate
    print ' ---------- '

A:

curdate=curdate-datetime.timedelta(days=1)

See this stackoverflow question
Edit 
Your code could also do with some cleaning:
from datetime import date, timedelta

cur_date = date.today()
for i in xrange(365):
    start_date, cur_date = cur_date, cur_date-timedelta(days=1)
    print "the date is between {} and {}".format(start_date.strftime("%Y-%m-%d"), cur_date.strftime("%Y-%m-%d"))

This will output exactly what you want.

