Q:

Smallest python script to print even numbers 0 to 100

I'm work on a problem which I set myself for fun, which is to create a python script which prints the even numbers from 0 to 100. The challenge is to make the script as small as possible. This is what I have so far:
for x in range(0, 101):
    if (x % 2 == 0):
        print x

Currently it is 60 bytes. Can anyone think of a way to make it smaller?

Edit: print(*range(2,101,2),sep='\n') which is 30 bytes. Any smaller?

A:

Python 2 - 12 characters
print 8**999

The decimal representation of all even numbers from 0 to 100 can be found in the output:
153778990270139647116444851659594064330089236967104214470764753645007350076834118596920008479824182447803706156756475613564110522612279602948135310258168541404369918794480627176627915013920083365328091029969610052054309789461709376676636344651086297099162082351332867728061686056465813162964114500668343488577962834185114919242101638217077550294093097112980059735456387540301162747936045475366317560310988720435512281742591085641505551107966844283901574058972330493685836063965131445246304097593431852972101058022587137885482726523043570690342524474585327775688980689010069001288756281975198668705741000141718184277589376710426738442847382969979234512669279398030637083755270090078676447687796406001053805898105262326290072552249025832780916090265261064205460488458795026145331708830141367124625271312584437671840499845750728447412590406684361326531266896486146862384988911439049971734022314877278748672

As a bonus, so can the odd numbers.

A:

Python 3, 22 (Possibly not allowed)
If the challenge is "to create a python script which prints the even numbers from 0 to 100" and not "to create a python script which prints the even numbers from 0 to 100, newline separated", then the shortest solution is:
print(*range(0,101,2))

Remember, it's very important in code golf not to put any limitations on yourself you don't have to - do what the problem asks, and no more.

A:

Python2 26
i=0;exec"print i;i+=2;"*51

independent discovery of @bitpwner's solution

