Q:

Gradient of the point with x coordinate

I am not even sure where to begin on solving this question
f(x) = $ax^2$ + bx + c, where a = -32, b = 9 and c = 14.  What is the gradient of the point, with x coordinate 11, on the graph of y = f(x)?

A:

Ya actually the answer was something like this according to the given formula

In general, if f(x)= $ax^2$ + bx + c then the gradient at any point on
  the graph of y=f(x) is given by f prime (x) = 2ax + b

so in the above sums case it will be 2(-32)(11)+9 = -695

