Q:

Heating power of a room affecting object of different temperature

I have a object with a surface area of about $16 \, \mathrm{cm}^2 ,$ and I'm trying to calculate the rate at which it will be heating up if placed into a warmer room, so I can apply the same amount of cooling to make the temperature constantly lower than the room temperature.
For instance my room temperature is $20 \sideset{^{\circ}}{}{\mathrm{C}}$ and the object's temperature is $0 \sideset{^{\circ}}{}{\mathrm{C}} .$ If it helps, the object is made out of a ceramic material $\left(\text{Al}_2 \text{O}_3 \right) .$
I know it can be somehow calculated with Newton's law of cooling, but I can't seem to get past the heat transfer coefficient.

A:

Assume the room's temperature to be $T_0$ and constant, the object's temperature $T$ (considered uniform), its surface area $A$, its mass $m$, its heat capacity $c_p$ and $h$ the heat transfer coefficient.
With Newton's Cooling/Heating Law we get:
$$\frac{dQ}{dt}=hA(T_0-T)$$
For an infinitesimal increase in temparature of the object $dT$, then:
$$dQ=mc_pdT$$
Combined we have:
$$\frac{mc_p dT}{dt}=hA(T_0-T)$$
$$\frac{dT}{T_0-T}=\alpha dt$$
Where $\alpha=\frac{hA}{mc_p}$.
Integrated we get, with $T_i$ the initial temperature of the object:
$$-\ln\frac{T_0-T(t)}{T_0-T_i}=\alpha t$$
So that:
$$T(t)=T_0-(T_0-T_i)e^{-\alpha t}$$
So the rate of change of $T$ isn't linear, it's exponential. 'On paper' it takes $t\to +\infty$ for the object's temperature to reach $T_0$.

Edit:
The OP revealed in the comments that the object is laying on the floor. So it is partially exposed to the floor (through surface area, say $A_1$) and partially to the air in the room (through surface area, say $A_2$). If we assume floor and air to be at the same constant temperature $T_0$ then we have two heat flows: 
$$\frac{dQ}{dt}=h_1A_1(T_0-T)+h_2A_2(T_0-T)=(h_1A_1+h_2A_2)(T_0-T)$$
The rest of the derivation is then the same as above, except:
$$\alpha=\frac{h_1A_1+h_2A_2}{mc_p}$$

