Q:

Is there a rotational analog for Newton's laws of motion?

In context of rotational dynamics my textbooks interminably states that there always exists a rotational analog for every linear variable and they are related to one another through similar equation. (And for the fact I know about most of these analogs and the related equations) 
Though till now I haven't yet seen/learnt of rotational analog of Newton's Laws of Motion. So 

Does there exist a rotational analog for Newton's laws of Motion? 
If possible, then are they generalizable to non-rigid body? 

Edit:
To further clarify the question I am going to write down the rotational analog of Newton's laws of motion. Assuming that there exists a rotational analog of Newton's laws of motion, I suppose they would look like the following:

A body continues it's state of rest and uniform rotation unless acted upon by an external torque. 
The torque acting on a body is directly proportional to the rate of change of angular momentum. i.e.,

$$ \boldsymbol {\tau} = \frac {d\mathbf L}{dt}$$

For every torque there is an equal and opposite torque. 

So are these statements (that I made as an analog of Newton's laws of Motion) true for all kind of rotational motion?
Is there any exception to them? 

A:

The following are the most common rotational analogues of linear motion terms:
1) Distance $(x)$ - Angle $(\theta)$
2) Velocity $(v)$ - Angular Velocity $(\omega)$
3) Acceleration $(a)$ - Angular Acceleration $(\alpha)$
4) Mass $(m)$ - Moment of Inertial $(I)$
5) Force $(F)$ - Torque $(\tau)$
All differential formulae still apply such as $\frac {dx}{dt}=v$ and $\frac {d\theta}{dt}=\omega$. A particularly important relation is $\tau=I\alpha.$ You can substitute all the equation of motion with their rotational counterparts and get perfectly valid formulae. For example $v=u+at$ becomes $\omega_f=\omega_i+\alpha t$. Non-rigid body dynamics can also be generalized using these terms although that becomes quite complicated.
Edit:
Yes, your statements are correct. They always hold just like in linear motion. However, you must be careful with the frame of reference. Any rotational frame of reference is non-inertial and hence these will not apply in that case.

A:

This kind of conceptualization may be useful at some level, but it is not accurate. You learn about kinematics and dynamics in 1D, and it is natural to want about the real 3D picture of those things. I was never comfortable with the statement of analogue between translational and rotational motion. The underlying assumption is that these two are separate mechanics working independently of each other. Just as the analogue between circuit (voltage, current) and dynamics (force, velocity) implies that similar behavior exists between these two systems.
But in real life (in three dimensions) the story is rather more convoluted.
We are afforded a certain level of separation between translational and rotational motion when things are resolved around the center of mass of a body. Then you can state the translational and rotational equations of motion as
$$ \begin{aligned}
  \boldsymbol{p} & = m \, \boldsymbol{v}_C \\
  \boldsymbol{F} & = \frac{\rm d}{{\rm d}t} \boldsymbol{p} \\
  \pmatrix{ F_x \\ F_y \\ F_z } & = m \pmatrix{a{x}_C \\ a{y}_C \\ a{z}_C}
\end{aligned} \tag{1}$$
$$\begin{aligned}
 \boldsymbol{L}_C & = \mathbf{I}_C \boldsymbol{\omega} \\
 \boldsymbol{\tau}_C & = \frac{\rm d}{{\rm d}t}  \boldsymbol{L}_C \\
 \pmatrix{\tau x_C \\ \tau y_C \\ \tau z_C} & = \left[ \matrix{ I_{xx} & I_{xy} & I_{xz} \\ I_{xy} & I_{yy} & I_{yz} \\ I_{xz} & I_{yz} & I_{zz} } \right] \pmatrix{\alpha_x \\ \alpha_y \\ \alpha_z} + \pmatrix{Lz_C\, \omega_y - Ly_C\, \omega_z \\ Lx_C\, \omega_z - Lz_C\, \omega_x \\ Ly_C\, \omega_x - Lx_C\, \omega_y}
\end{aligned} \tag{2}$$
Above $p$ is momentum and $L$ angular momentum, and $a$ acceleration $\alpha$ rotational acceleration, $F$ is force and $\tau$ is torque.
Equation (1) is Newton's second law, and (2) is the Euler equations of rotational motion. Point C is the center of mass, and each vector quantity is indicated with bold symbols, and their components resolved into x,y and z directions. 
Note that the two sets of equations are de-coupled (independent of each other), but this only happens at the center of mass. The general equations as seen in this post are far more complex to write down in component form, so you need to familiarize your self with vector calculus before going that way. So your teacher understandably at this point reverts to the equivalency simplification.
On your last point, rigid body mechanics cannot be generalized on non-rigid bodies, because the notion of angular velocity doesn't exist. Look at Jupiter, which is spinning, but each part is spinning at a different rate. The dynamics exist, but the kinematics are all wrong. You can no longer calculate the velocity of a point, based on the rotation and the velocity of another point like you can do with rigid bodies.

