Q:

How do I solve $3xy=4xz=5yz$ ${x+y \over x-z}=?$

$3xy=4xz=5yz$
$ {x+y \over x-z}=?$
The answer is ${9 \over 2}$
But how to solve?
I am preparing for exam.

This question comes from metropol mathematics 1 testbook

A:

$x=\frac{5y}{4}$ and $z=\frac{3y}{4}$
Does this help?

