Q:

Work being done without distance

I have this issue:
If you push a 40.0 kg crate at a constant speed of 1.40 m/s across a horizontal floor 
(µk=0.25 ), at what rate (a) is work being done on the crate by you and (b) is the 
energy dissipated by the frictional force?
For starters, here is what I have so far:
RN = mg = 40*9.8 = 392 N
Ff = muRN = 0.25*392 = 98 N
KE = 0.5mv^2  =  0.5*40*(1.40)^2 = 39.2 J
At this point, I don't know how to answer part (a).
If W = FD   , how do I find the work being done without a distance?

A:

SO work done by frictional force will be frictional force * distance trvelled per second or per minute in this it will be 137.2 Jules/sec. And work done by you will be the same because you are applying the force only to keep it moving not for accelerating it which in case would have been F=ma. And if you want to calculate the work done in travelling a particular distance then you wil be given the time interval in which you have to calculate it.

