Q:

How to convert hexadecimal string to character with that code point?

I have the string x = '0x32' and would like to turn it into y = '\x32'.
Note that len(x) == 4 and len(y) == 1.
I've tried to use z = x.replace("0", "\\"), but that causes z = '\\x32' and len(z) == 4.  How can I achieve this?

A:

You do not have to make it that hard: you can use int(..,16) to parse a hex string of the form 0x.... Next you simply use chr(..) to convert that number into a character with that Unicode (and in case the code is less than 128 ASCII) code:
y = chr(int(x,16))

This results in:
>>> chr(int(x,16))
'2'

But \x32 is equal to '2' (you can look it up in the ASCII table):
>>> chr(int(x,16)) == '\x32'
True

and:
>>> len(chr(int(x,16)))
1

A:

Try this:
z = x[2:].decode('hex')

