The back of a stop sign is visible in front of the stone building.
There is a stone building.
Having a stop sign visible in front of a building must mean that there is a building.
exists s1 x1 x2 x3 x4 x5 x6.(n_building(x5) & of(x5,x6) & n_stone(x6) & n_back(x1) & in(s1,x4) & of(x4,x5) & n_front(x4) & Theme(s1,x1) & a_visible(s1) & of(x1,x2) & n_sign(x2) & of(x2,x3) & n_stop(x3))
exists p1 x1 x2 x3.((x1 = x2) & n_building(x2) & of(x2,x3) & n_stone(x3))