text:
\section{Introduction}

Solitonic states  play an important r\^ole in understanding the
nonperturbative dynamics in quantum field theory
and string theory (for a review, see for ex. \cite{DKL}). In supersymmetric
theories,  BPS states are believed to be stable
under quantum corrections \cite{WO}.
Their presence is very important in checking
various duality conjectures, where solitons in one theory are mapped
into elementary particles in the dual theory.

It was shown by Strominger in 1990 \cite{S} that the low-energy limit of
the ten-dimensional (10d) heterotic strings have classical solutions coming
from instantons in the gauge group dressed with background values for the
gravitational multiplet. This solution turned out to be crucial for
the conjectured string-five brane duality in 10d \cite{Duff}.

Recently, it was argued \cite{HW} that the strong coupling limit of the
$E_8 \times E_8$ heterotic string is the eleven-dimensional supergravity,
the eleventh coordinate being defined on the interval $0 \le x^{11} \le l$,
with the two gauge groups sitting on the boundaries $x^{11}=0$ and $x^{11}=l$,
respectively. The length $l$ is related to the string coupling constant
$e^{\phi_0}$ by
\begin{equation}
l={1 \over 2} (4 \pi k_{11}^2)^{1/9} e^{2 \phi_0 \over 3} \ .
\end{equation}
  This conjecture seems to be free of gauge and gravitational
anomalies \cite{DA} and is in agreement with constraints coming from
membrane-five brane Dirac quantization condition \cite{DA}, \cite{BM}.

 The purpose of this paper is the study of classical
 five-brane solutions in the
Horava-Witten theory, thus generalizing the heterotic solutions \cite{S}
(this was also studied recently in \cite{LLO}; our results of Section 2
partly overlap with this paper). A particular
emphasis will be put on the dependence of the solutions on the eleventh
coordinate. In particular, we will find here a new manifestation of the
phenomenon observed in \cite{W}, namely that by compactification,
if we put an instanton on one boundary, the volume of the compact space on the
other boundary becomes smaller, with a quantity related in our case to the
instanton size. We study this
phenomenon in more detail and show that even at weak coupling, for very
small instanton size, the Strominger solution has important corrections.
We also consider the neutral five-brane solution and find that space-time
is effectively eleven-dimensional near the center of the five-brane even at very weak coupling.

\section{Supersymmetric five-brane solutions in Horava-Witten Lagrangian}

We look for a solution of the Horava-Witten supergravity
with six dimensional Poincar\'e  and
four dimensional Lorentz invariances and which preserves half of the supersymmetries.
The six dimensional coordinates
parametrising the world-volume of the five-brane
are denoted by $y^a, \ a=0,\dots,5$, the four dimensional ones by $x^ \mu$
and the eleventh coordinate parametrizing $S^ 1/Z^2$ by $x^{11}$. In the following,
we shall be interested in five-branes that are transverse to the eleventh dimension.

The most general metric with the mentioned
isometries is of the form
\begin{equation}
g=e^{2A}dy^{a}dy^{b}\eta_{ab}+e^{2B}dx^{\mu}dx^{\nu}\delta_{\mu \nu}
+e^{2C}dx^{11}dx^{11} \ , \label{1}
\end{equation}
where $A, B$ and $C$ are functions of $x^2=x^\mu x^\nu \delta_{\mu \nu}$
and $x^{11}$. In the following all indices are raised and lowered with the
Minkowski and Euclidean metric.
The moving basis is given by
\begin{equation}
\theta^a=e^{A}dy^a,\quad \theta^\mu=e^{B}dx^\mu,\quad
\theta^{11}=e^{C}dx^{11} \ . \label{2}
\end{equation}
The four-form field strength, in order to be invariant under
the isometries,
has to have vanishing components where at least one of the indices is $a$.
The equation of motion for this field reads $d^*G=0$,
because $G\wedge G=0$ \footnote{The term $\int C\wedge X_8$ where $X_8=dX_7$
is a polynomial in the curvature of order $8$ modifies the equation of motion by a term in $X_8$.
This term turns out to be vanishing for the five-brane
solution as can be checked by calculating the curvature of the the metric (1).}.
This equation may be solved as
$G=^*d\Lambda$
where $\Lambda$ is a six-form. The most general six-form compatible with
the isometries can be written as $\Lambda=D\epsilon_6$,
where $D$ is a function of $x^2$ and $x^{11}$
and $\epsilon_6$ is given by $dy^0\wedge\dots\wedge dy^{5}$.
So $G$ is determined by a single function $D$ and is given by
\begin{equation}
G=e^{-6A +2B+C}{{\epsilon^{\mu}_{\ \nu \alpha \beta}}\over{6}}\partial_\mu D
dx^{\nu} \wedge dx^{\alpha} \wedge dx^{\beta} \wedge dx^{11}+
e^{-6A-C+4B}\partial_{11} D
dx^{1}\wedge\dots\wedge
dx^{4} \ , \label{3}
\end{equation}
where $\epsilon^{\mu}_{\ \nu \alpha \beta}
$ is the totally antisymmetric tensor
with values $\pm 1$ and $0$. In the moving basis we have
\begin{equation}
G=e^{-6A -B}{{\epsilon^{\mu}_{\ \nu \alpha \beta}}\over{6}}\partial_{\mu}D
\theta^{\nu} \wedge \theta^{\alpha} \wedge \theta^{\beta} \wedge \theta^{11}+
e^{-6A-C}{{\epsilon_{\mu\nu\alpha\beta}}
\over{24}}\partial_{11}D
\theta^{\mu}\wedge\dots\wedge
\theta^{\beta} \ . \label{4}
\end{equation}

We now demand that the solution preserve a fraction
of the eleven-dimensional supersymmetries.
We use conventions where $\{\Gamma^I,\Gamma^J\}=2\eta^{IJ}$
and $\Gamma^{I_1 I_2\dots\ I_n}={{1}\over{n!}}(\Gamma^{I_1}\Gamma^{I_2}\dots\Gamma^{I_n}\pm$
permutations).
The supersymmetry transformation rule of the eleven dimensional gravitino is
given by
\begin{equation}
\delta\Psi_I=D_I\epsilon+
{{\sqrt{2}}\over{288}}(
\Gamma_{I}^{\ JKLM}-8\delta_{I}^{J}\Gamma^{KLM})G_{JKLM}\epsilon \ ,
\label{5}
\end{equation}
where $G_{JKLM}$ are the components of $G$ in the moving basis.

The covariant derivative when acting on spinors reads explicitly
\begin{eqnarray}
D=d+{{1}\over{2}}[\Gamma^a\Gamma^{11}e^{-C}\partial_{11}A+\Gamma^a\Gamma^\mu
e^{-B}\partial_{\mu}A]
\theta_a\nonumber\\+{{1}\over{2}}[
\Gamma^{\mu\nu}e^{-B}\partial_{\nu}B+\Gamma^{\mu}\Gamma^{11}e^{-C}\partial_{11}B]
\theta_\mu-
{{1}\over{2}}\Gamma^{\mu}\Gamma^{11}e^{-B}
\partial_{\mu}C\theta_{11} \ . \label{7}
\end{eqnarray}

In order to impose that the solution preserve some supersymmetries we have
to look for a solution to
\begin{equation}
\delta\Psi_I=0.\label{5p}
\end{equation}
A straightforward calculation gives
\begin{eqnarray}
\Gamma_{a}^{\ JKLM}G_{JKLM}=
24\Gamma_a\Gamma^{5}e^{-6A-C}\partial_{11}D+24\Gamma_a\Gamma^{\mu}\Gamma^5\Gamma^{11}
e^{-6A-B}\partial_\mu D \ , \nonumber \\
\Gamma_{\mu}^{\ JKLM}G_{JKLM}=
24\Gamma^5\Gamma^{11}e^{-6A-B}
\partial_{\mu}D \ , \
\Gamma_{11}^{\ JKLM}G_{JKLM}=
24\Gamma^{11}\Gamma^{5}e^{-6A-C}\partial_{11}D \ , \nonumber \\
\Gamma^{KLM}G_{\mu KLM}=6\Gamma_\mu\Gamma^{5}e^{-6A-C}\partial_{11}D-6\Gamma^\lambda_{\ \mu}\Gamma^{5}\Gamma^{11}e^{-6A-B}\partial_\lambda D \ , \nonumber \\
\Gamma^{KLM}G_{11KLM}=-6\Gamma^\lambda\Gamma^5e^{-6A-B}\partial_\lambda D \ ,
\ \Gamma^{KLM}G_{aKLM}=0 \ . \label{10}
\end{eqnarray}
In order to obtain these relations we have used
\begin{eqnarray}
\Gamma^{5}={{1}\over{24}}\epsilon_{\mu\nu\alpha\beta}\Gamma^{\mu\nu\alpha\beta}
\ ,\quad
\Gamma^{\mu\nu\alpha}=-\epsilon^{\mu\nu\alpha\beta}\Gamma_{\beta}\Gamma^{5}
\ ,\quad
\epsilon_{\alpha\beta\mu\nu}\Gamma^{\mu\nu}=-2\Gamma^{5}\Gamma_{\alpha\beta} \ .
\label{11}
\end{eqnarray}
We look for solutions to (\ref{5p}) of the form
$\epsilon=e^{-E}\eta$,
with $\eta$ an arbitrary constant spinor of positive
eleven dimensional chirality $\Gamma^{11}\eta=\eta$
and $E$ a function of $x^2$ and $x^{11}$.
The $a$ component of the condition (\ref{5p}) is
\begin{equation}
{{1}\over{2}}[\Gamma_a\Gamma^{11}e^{-C}
\partial_{11}A+\Gamma_a\Gamma^\mu
e^{-B}\partial_{\mu}A]
\eta+{{\sqrt{2}}\over{12}}[
\Gamma_a\Gamma^{5}e^{-6A-C}\partial_{11}D+\Gamma_a\Gamma^{\mu}\Gamma^5\Gamma^{11}
e^{-6A-B}\partial_\mu D]\eta=0, \label{12}
\end{equation}
which gives
\begin{eqnarray}
\Big(
{1\over 2}
\Gamma_a\Gamma^{11}e^{-C}
\partial_{11}A+{{\sqrt{2}}\over{12}}
\Gamma_a\Gamma^{5}e^{-6A-C}\partial_{11}D
\Big)
\eta=0 \ , \\
\Big( {{1}\over{2}}
\Gamma_a \Gamma^\mu
e^{-B}\partial_{\mu}A+
{{\sqrt{2}}\over{12}}
\Gamma_a\Gamma^{\mu}\Gamma^5\Gamma^{11}
e^{-6A-B}\partial_\mu D\Big)\eta=0 \ . \label{13}
\end{eqnarray}
The first equation implies that $\eta$ is chiral in the four dimensional space,
say $\Gamma^5\eta=\alpha\eta$, where $\alpha=\pm 1$,
and
\begin{equation}
e^{6A}\partial_{11}A+\alpha
{{\sqrt{2}}\over{6}}
\partial_{11}D=0 \ . \label{14}
\end{equation}
The solution reads
\begin{equation}
e^{6A}=-\alpha\sqrt{2}D+a \ , \label{15}
\end{equation}
where $a$ does not depend on $x^{11}$.
The second equation  gives
\begin{equation}
e^{6A}\partial_{\mu}A+\alpha{{\sqrt{2}}\over{6}}\partial_\mu D=0 \ ,
\label{16}
\end{equation}
which implies that $a$ is a constant.

The $\mu$ component of the equation (\ref{5p}) gives
\begin{eqnarray}
-e^{-B}\partial_\mu E\eta+
 {{1}\over{2}}[
\Gamma^{\mu\nu}e^{-B}\partial_{\nu}B+\Gamma^{\mu}\Gamma^{11}e^{-C}\partial_{11}B]\eta
\nonumber\\
+{{\sqrt{2}}\over{12}}[\Gamma^5\Gamma^{11}e^{-6A-B}
\partial_{\mu}D-2\Gamma_\mu\Gamma^{5}e^{-6A-C}\partial_{11}D+
2\Gamma^\lambda_{\ \mu}\Gamma^{5}\Gamma^{11}e^{-6A-B}\partial_\lambda D]\eta=0 \ . \label{17}
\end{eqnarray}
Setting all the terms to zero gives
\begin{eqnarray}
-\partial_\mu E+
{{\sqrt{2}}\over{12}}\alpha e^{-6A}
\partial_{\mu}D=0 \ , \ \partial_{\nu}B-
{{\sqrt{2}}\over{3}}\alpha e^{-6A}\partial_\nu D=0 \ , \nonumber \\
\partial_{11}B-
{{\sqrt{2}}\over{3}}\alpha
e^{-6A}\partial_{11}D=0 \ . \label{18}
\end{eqnarray}
The last two equations combined with (\ref{15}) give
\begin{equation}
\partial_{I}B={{\sqrt{2}}\over{3}}\alpha
{{\partial_{I}D}
\over{-\alpha\sqrt{2}D+a}} \ . \label{19}
\end{equation}
The solution of (\ref{19}) is
\begin{equation}
e^{3B}={{b}\over{-\alpha\sqrt{2}D+a}} \ , \label{20}
\end{equation}
where $b$ is a constant which can be set to one by a rescaling of the $x^{\mu}$,
so we get $e^{3B}=e^{-6A}$.

The $11$ component of the equation (\ref{5}) reads
\begin{eqnarray}
-e^{-C}\partial_{11}E\eta-
{{1}\over{2}}\Gamma^{\mu}\Gamma^{11}e^{-B}
\partial_{\mu}C\eta\nonumber\\
+{{\sqrt{2}}\over{12}}[\Gamma^{11}\Gamma^{5}e^{-6A-C}\partial_{11}D+2
\Gamma^\lambda\Gamma^5e^{-6A-B}\partial_\lambda D]\eta=0 \ . \label{21}
\end{eqnarray}
Setting all the terms to zero, we get
\begin{eqnarray}
-\partial_{11}E+{{\sqrt{2}}\over{12}}\alpha e^{-6A}\partial_{11}D=0 \ , \
\partial_{\mu}C-{{\sqrt{2}}\over{3}}\alpha
e^{-6A}\partial_\mu D=0 \ . \label{22}
\end{eqnarray}
The last equation combined with (\ref{15}) gives
\begin{equation}
e^{3C}={{c(x^{11})}\over{-\alpha\sqrt{2}D+a}} \ , \label{23}
\end{equation}
where $c(x^{11})$ depends only on $x^{11}$.
By reparametrisation of $x^{11}$, $c$ can be set to one so we get
$C=B$. Finally, from equations (\ref{18}) and (\ref{22}) we get
$E=-A/2$.

In summary, for the solution to be supersymmetric
the metric has to be of the form
\begin{equation}
g=e^{2A}dy^a dy^b\eta_{ab}+e^{-4A}
(dx^\mu dx^\nu\delta_{\mu\nu}+dx^{11}dx^{11}) \ , \label{24}
\end{equation}
and the four-form $G$ be given by
\begin{equation}
G={{1}\over{(-\alpha\sqrt{2}D+a)^2}}\Big[
{{\epsilon^{\mu}_{\ \nu \alpha \beta}}\over{6}}\partial_\mu D
dx^{\nu}dx^{\alpha}dx^{\beta}dx^{11}+
\partial_{11} D
dx^{1}\wedge\dots\wedge
dx^{4}\Big] \ . \label{25}
\end{equation}
The two function $A$ and $D$ are related by (\ref{14}).

It is convenient to define $\tilde D$ by
\begin{equation}
\tilde D=
{{1}\over{-\alpha\sqrt{2}D+a}} \ , \label{26}
\end{equation}
so the expression of $G$ simplifies to
\begin{equation}
\alpha {\sqrt 2} G={{\epsilon^{\mu}_{\ \nu \alpha \beta}}\over{6}}\partial_\mu \tilde D
dx^{\nu} \wedge dx^{\alpha} \wedge dx^{\beta} \wedge dx^{11}+
\partial_{11} \tilde D
dx^{1}\wedge\dots\wedge
dx^{4} \ . \label{27}
\end{equation}
$A$ is given by $e^{6A}={\tilde D}^{-1}$,
so finally the metric is given by
\begin{equation}
g={\tilde D}^{-{{1}\over{3}}}dy^a dy^b\eta_{ab}+{\tilde D}^{{{2}\over{3}}}
(dx^\mu dx^\nu\delta_{\mu\nu}+dx^{11}dx^{11}) \ . \label{28}
\end{equation}
The Bianchi identity is also simply expressed with the aid of $\tilde D$ since
\begin{equation}
\alpha {\sqrt 2} dG=(\partial^{\mu}\partial_\mu\tilde D+\partial^2_{11}\tilde D)
dx^1\wedge\dots dx^4\wedge dx^{11}, \label{29p}
\end{equation}
so  the Bianchi identity in the bulk reads
\begin{equation}
\Delta_5\tilde D=0,\label{29}
\end{equation}
where $\Delta_5$ is the five-dimensional Euclidean Laplacian.

The gaugino transformation rule under supersymmetry is given by
$\delta\chi=\Gamma^{IJ}F_{IJ}\epsilon$.
Since the solution we are seeking is invariant under the the six-dimensional
Poincar\'e group
we have $F_{aI}=0$, so the transformation rule can be written as
$\delta\chi=\Gamma^{\mu\nu}F_{\mu\nu}\epsilon$.

The spinorial parameter is chiral in four dimensions, so
\begin{equation}
\delta\chi=\Gamma^{\mu\nu}F_{\mu\nu}
{{1+\alpha\Gamma^5}\over{2}}
\epsilon={{1}\over{2}}F_{\mu\nu}(\Gamma^{\mu\nu}-{{\alpha}\over{2}}
\epsilon^{\mu\nu}_{\ \ \alpha\beta}\Gamma^{\alpha\beta})\epsilon \ .
\label{30}
\end{equation}
The vanishing of $\delta\chi$ implies that the field strength must be self or
anti-self-dual depending on the four dimensional chirality
\begin{equation}
F_{\alpha\beta}=
{{\alpha}\over{2}}
\epsilon_{\alpha\beta}^{\ \ \mu\nu}F_{\mu\nu} \ . \label{31}
\end{equation}

In the following sections we shall examine various solutions to
the self-duality equations and the Bianchi identity subject to the Horava-Witten
boundary conditions
for $G$. We end this section with some general remarks.

There is a class of solutions we can get by using a spinor $\epsilon$
which vary along $x^{11}$ such that it is chiral, but of opposite chirality,
on the two boundaries and non-chiral for $x^{11} \not= 0,l$. The spinor
must satisfy the Horava-Witten projection condition $\epsilon (-x^{11})
=\Gamma_{11} \epsilon (x^{11})$. Then, in the
Weyl representation, the spinor we are searching corresponds to the
following ansatz
\begin{equation}
\epsilon= e^{-E}
\left(
\begin{array}{c}
\cos {\pi x^{11} \over 2l} \epsilon_1 \\
\sin{\pi x^{11} \over 2l} \epsilon_2
\end{array}
\right) \ , \label{310}
\end{equation}
where $\epsilon_i$ are Majorana-Weyl spinors.
 Inserting this ansatz into (\ref{5}),
as before, it turns out that the former solution (\ref{27}), (\ref{28})
still satisfies the supersymmetry conditions $\delta \Psi_a =
\delta \Psi_{\mu}=0$. However, the supersymmetry is necessarily broken
along the eleventh dimension
\begin{equation}
\delta \Psi_{11}= e^{-E}
\left(
\begin{array}{c}
-{1 \over 2l} \sin {\pi x^{11} \over 2l} \epsilon_1 \\
{1 \over 2l} \cos{\pi x^{11} \over 2l} \epsilon_2
\end{array}
\right) \
\end{equation}
and for every value of $x^{11}$. Notice also that the spinor (\ref{310})
has a discontinuity $\epsilon (-l)=-\epsilon (l)$, which is also present in
supersymmetry breaking driven by a gaugino condensation \cite{H} or in
the Scherk-Schwarz mechanism \cite{DG}, \cite{AQ}.

 It is of some interest to rewrite the solution above (\ref{27}),
(\ref{28}), after the Wick rotation, from
the point of view of the $4d-5d$ theory obtained after the compactification
of the six coordinates $y_a$, in the simplest
Calabi-Yau like truncation \cite{Witten}, where the truncated fields are
invariant under the $SU(3)$ holonomy group of the compactified space.
The Einstein 5d metric can be obtained through the Weyl rescaling
\begin{equation}
g^{(11)}_{ab}={\tilde D}^{-1/3} \delta_{ab} \ , g^{(11)}_{\mu \nu}=
{\tilde D}^{2/3} g^{(5)}_{\mu \nu} \ , \label{311}
\end{equation}
where here $\mu,\nu=1 \cdots 5$.
The solution (\ref{28}) becomes in the $5d$ units simply
\begin{equation}
g={\tilde D}^{-{{1}\over{3}}}dy^a dy^b\eta_{ab}+
dx^\mu dx^\nu\delta_{\mu\nu}+dx^{5}dx^{5} \ , \label{321}
\end{equation}
hence the gravitational part of the solution becomes trivial.
The $5d$ theory contains a (universal)
hypermultiplet, which in $4d$ gives, after the Horava-Witten projection,
the dilaton $S$ containing as the real part the volume $V_6$ and as
imaginary part the Hodge dual of the
antisymmetric tensor field $C_{5\mu\nu}$. A second complex modulus $T$
appears by the $5d \rightarrow
4d$ compactification, the real part of which is the fifth radius $R_5$ and
the imaginary part the pseudoscalar defined by $C_{5i \bar j}
=\epsilon_{i \bar j} b$ \cite{N},
\cite{DG}, where $i, \bar j=1,2,3$ are complex indices in compactified
space. Then we can reexpress the solution (\ref{27}), (\ref{28}) as the
background functions
\begin{equation}
S= {\tilde D}^{-1} + i {\sqrt 2} (c-{\tilde D}^{-1}) \ , \ T=1 \ ,
\label{312}
\end{equation}
where $c$ is an arbitrary real constant corresponding to the Peccei-Quinn
symmetry $S \rightarrow S + i \alpha$. So our solution corresponds by
compactification to an axionic string, generalizing the ones discussed in
the weakly-coupled case in \cite{R}.

\subsection{Heterotic gauge five-brane}

The simplest solution to the self-duality equations
is obtained by first chosing a $SU(2)$ subgroup of $E_8$ and putting the
t'Hooft solution in this $SU(2)$.
In order to write the solution define $\sigma^{\mu}$ by $(1,i\alpha\vec\sigma)$,
where $\vec \sigma$ are the Pauli matrices. Then the
solution may be written as
\begin{equation}
F=
\left({{\rho}\over{\rho^2+x^2}}\right)^2\sigma_\mu
dx^\mu\sigma^{\dagger}_\nu dx^\nu \ , \label{32}
\end{equation}
where $\rho$ is the size of the instanton and $\int tr F \wedge F = 16
\alpha \pi^2$.  Our definition is such that $tr F \wedge F = (1/30) Tr F
\wedge F$, where $Tr$ is the trace in the adjoint of $E_8$.

Supersymmetry invariance as well as anomaly
cancellation require that the restriction of $G$ to the boundaries be
given by
\cite{HW}
\begin{eqnarray}
G|_{x^{11}=0}= -{1 \over \sqrt2} {k_{11}^{2/3} \over  (4 \pi)^{5/3}}
[tr(F\wedge F)-{{1}\over{2}}tr(R\wedge R)]\equiv {1 \over \sqrt 2 \alpha}
f(x^2)\epsilon_4 \ , \nonumber \\
G|_{x^{11}=l}= {1 \over \sqrt2} {k_{11}^{2/3} \over  (4 \pi)^{5/3}}
[tr(F\wedge F)-{{1}\over{2}}tr(R\wedge R)]\equiv -{1 \over \sqrt 2 \alpha}
g(x^2)\epsilon_4 \ , \label{33}
\end{eqnarray}
where $\epsilon_4 = dx^1 \wedge \cdots \wedge dx^4$ and for the one
instanton solution given above we have
$tr(F\wedge F)=96\alpha\left({\rho}^4 /{(\rho^2+x^2)}^4 \right) \epsilon_4$.
Finally, the soliton is determined by $\tilde D$ which verifies the Laplace
equation (\ref{29}) and is subject to the boundary conditions
\begin{equation}
\partial_{11}\tilde D|_{x^{11}=0}=f(x^2),\quad
\partial_{11}\tilde D|_{x^{11}=l}=- g(x^2) \ . \label{34}
\end{equation}

In order to solve the equation (\ref{29}) subject to the boundary conditions
(\ref{34}) it is very convenient to  consider $\tilde D$ to be the restriction of
an even and  periodic function in $x^{11}$ with period $2l$.
Then $\tilde D$ with the given boundary conditions
satisfies the following equation
\begin{equation}
(\Delta_4 + \partial_{11}^2)\tilde D=2f\delta(x^{11})+2g\delta(x^{11}-l) \ ,
\label{35}
\end{equation}
where $\delta(x^{11})$ is the delta distribution {\it periodic}
with period $2l$:
\begin{equation}
\delta(x^{11})={{1}\over{2l}}+{{1}\over{l}}\sum_{n=1}^{\infty}
\cos{{n\pi x^{11}}\over{l}} \ . \label{36}
\end{equation}
In order to solve the equation (\ref{35}), introduce the Green function
${\cal G} (x^2, x^{11})$ defined by
\begin{equation}
(\Delta_4+\partial_{11}^{2}){\cal G}=\delta^{4}(x)\delta(x^{11}) \ .
\label{37}
\end{equation}
From the Fourier transform of the above equation  we get
\begin{eqnarray}
{\cal G}(x,x^{11})=-{1 \over 2l} \sum_{n=-\infty}^{\infty}
\int {d^5 k \over (2 \pi)^4}
{e^{ikx} \over k^2} \delta (k_5 - {n \pi \over l}) \ , \label{370}
\end{eqnarray}
where $x^5=x^{11}$. By performing a Poisson resummation on $n$, we can
recast the result in the form
\begin{equation}
{\cal G}=-{1 \over{8 \pi^2}}
\sum_{n=-\infty}^{\infty}
{1 \over{[x^2+(x^{11}+2nl)^2]^{3/2}}} \ . \label{371}
\end{equation}
This form of $\cal G$ is particularly suitable to examine the behavior
for large $l$ since only the term $n=0$ contributes
to the sum and the Green function is
that of $R^5$.
The Fourier expansion in $x^{11}$ can be obtained by calculating the
integral in (\ref{370}); it is given by
\begin{equation}
{\cal G}=-{{1}\over{2l(2\pi)^2}}\Big( {{1}\over{x^2}}+
\sum_{n=1}^{\infty}{{2n\pi}\over{lx}}K_1(nx \pi/l)\cos{{n\pi x^{11}}\over{l}}
\Big) \ , \label{38}
\end{equation}
where $x=\sqrt{x^2}$ and $K_1$ is the McDonald function of order one.
This form of $\cal G$ is convenient to study the limit where $x$ is much
larger than
$l$; the asymptotic behavior of $\cal G$ in this case is given by
\begin{equation}
{\cal G}=-{{1}\over{2l(2\pi)^2}}
\Big( {{1}\over{x^2}}+{{\sqrt{2}\pi}\over{\sqrt{l} x^3}}e^{-x\pi/l}\cos{{\pi x^{11}}\over{l}}
\Big)+\dots \label{39}
\end{equation}
The first term represents the Green function on $R^{4}$.

Taking into account the condition for asymptotic flatness,
the solution to equation (\ref{35}) is given by
\begin{equation}
\tilde D= 1 +2\int d^{4}y {\cal G}(x-y, x^{11})f(y)+2\int d^{4}y
{\cal G}(x-y,x^{11}-l) g(y) \ . \label{40}
\end{equation}
The Fourier expansion in $x^{11}$ of
$\tilde D$ can be obtained by using the form (\ref{38}) of $\cal G$.
The gauge five-brane is obtained by neclecting the term $tr  R^2$, which
is legitimate to the first order in $k_{11}^{2/3}$.
In particular, the zero mode can be explicitly calculated and is given
for $g=0$ and $f$ given by the instanton solution (\ref{32}), by
\begin{equation}
{\tilde D}_{10d} = 1  + {4 k_{11}^{2/3} \over l
(4 \pi)^{5/3}} {{x^2+2\rho^2}\over
{(x^2+\rho^2)^2}} \ . \label{43}
\end{equation}
This is precisely the 10d Strominger solution expressed in M-theory
units, as it should be\footnote{Expressed in string units, the coefficient
multiplying the instanton factor in the right-hand side is equal to
$\alpha'$, in agreement with ref. \cite{DKL}.}. The relation between
${\tilde D}$ and the $10d$ dilaton is $e^{2 \phi}=((2l)^3/(4 \pi
k_{11}^2)^{1/3}) {\tilde D}$.

The exact solution (\ref{40}) gives however, even in weak-coupling regime
$l \rightarrow 0$, important corrections to (\ref{43}) coming from
instantons of small size. In order to
study this quantitatively, notice that,
by using (\ref{371}) , for $\rho << l$, we can expand the expressions
\begin{eqnarray}
{\tilde D}(0,0)=1
-{{\zeta}\over{4\pi^2}\rho^3}
\int d^4y  {1 \over ({1+y^2})^4 y^3}\nonumber
\\ -{\zeta \over 2 \pi^2} \sum_{n=1}^{\infty}{ 1 \over{(2nl)^3}}
\int d^4y \left( {{1}\over{1+y^2}}\right)^4
{1 \over{\left[ {{\rho^2}\over{(2nl)^2}}
y^2+1\right]^{3/2}}} \ , \nonumber \\
{\tilde D}(0,l)=1
-{{\zeta}\over{2\pi^2}}\sum_{n=0}^{\infty}
{1 \over{(2n+1)^{3}l^3}}
\int d^4y \left( {1 \over{1+y^2}}\right)^4
{1 \over{[{{\rho^2}\over{(2n+1)^2l^2}} y^2+1]^{3/2}}} \ , \label{44}
\end{eqnarray}
where $\zeta=-192k_{11}^{2/3} /(4\pi)^{5/3}$ reads from (\ref{33}).
We get
\begin{eqnarray}
{\tilde D} (0,0)=1
-{5 \pi {\zeta}\over 64 \rho^3}
-{\zeta \over{96 l^3}} (\sum_{n=1}^{\infty} {1 \over{n^3}}) +
{{3\zeta \rho^2}\over{ 16 l^5}}
(\sum_{n=1}^{\infty} {1 \over{n^5}}) +\cdots \ , \nonumber \\
{\tilde D}(0,l)=1
-{\zeta \over{12 l^3}} (\sum_{n=0}^{\infty} {1 \over{(2n+1)^3}}) +
{{\zeta \rho^2}\over{ 4 l^5}}
(\sum_{n=0}^{\infty} {1 \over{(2n+1)^5}}) +\cdots \ . \label{45}
\end{eqnarray}
By comparing (\ref{45}) with (\ref{43}), it is clear that we get
important corrections to the Strominger solution for $x=0$ and if
$\rho \le l$,
i.e. in the center of the instanton and for instantons
of a size smaller than the eleventh dimension. The leading term of the
Strominger solution is ${1/l \rho^2}$, to be compared to (\ref{45}), which
shows in addition that the leading terms have different behaviour on the
two boundaries. This means that even if the ten-dimensional solution
gives the average in $x^{11}$ of the exact eleven-dimensional solution the
latter has important fluctuations around this average. Notice that the
space-time near the center of the instanton is eleven-dimensional even
in the limit of small $l$.

In the $l >>x>>\rho$ limit, the leading term in the solution behaves as
\begin{equation}
{\tilde D}=1+{(4\pi k_{11}^2)^{1/3} \over 4\pi^2(x^2+x_{11}^2)^
{3/2}} \ ,
\end{equation}
which is essentially the eleven-dimensional solution, too.

If we compactify the soliton solution to 4d, by considering the $y_a$
coordinates as compact coordinates and performing  a Wick rotation
we get an instantonic four-dimensional solution. We can define the volume of the
compactified space
\begin{eqnarray}
V_6 (x^2, x^{11}) = \int d^6 y \sqrt{g_6} = {\tilde D}^{-1}
(x^2,x^{11})
V_0 \ , \label{41}
\end{eqnarray}
where $V_0$ is a reference volume. It is well known that in explicit
compactifications, the volume of compact 6-manifold defines the (inverse of)
gauge couplings. It is therefore of interest to see the dependence of the
volume on $x^{11}$ and in particular the values on the two boundaries.
By a straightforward computation we get
\begin{eqnarray}
{\tilde D}(x^2,l)-{\tilde D}(x^2,0) = {1 \over 4 \pi^2} \sum_{n=-\infty}^{\infty}
\int {d^4 y } (f-g)(y) { (-1)^n \over [(x-y)^2 + n^2 l^2]^{3/2}}
= \nonumber \\
{1 \over 2 \pi^{5/2}} \int {d^4 y} (f-g)(y) \int_0^{\infty} dt\
 t^2 e^{-(x-y)^2 t^2}
\theta_4 ({i l^2 t^2 \over \pi}) \ , \label{42}
\end{eqnarray}
where $\theta_4 (\tau) = \sum_{n= -\infty}^{\infty} (-1)^n e^{i \pi n^2 \tau}$
is the Jacobi function. We find therefore a dependence on $x^{11}$ of the
volume, in analogy with the dependence found in \cite{W}. If we put, for
example, an instanton in $x^{11}=0$, we find $V_6 (l) < V_6 (0)$ and the
gauge coupling becomes stronger on the boundary without the instanton.

\subsection{Neutral five-brane}

Consider the limit $\rho\rightarrow 0$ of the gauge five-brane. Then
then  gauge potential tends to zero but
\begin{equation}
tr(F \wedge F)\rightarrow 16 \alpha\pi^2\delta^{4}(x) \epsilon_4 \
\end{equation}
and if $g=0$, the equation for $\tilde D$ becomes
\begin{equation}
\Delta_5\tilde
D=-2 (4\pi k_{11}^2)^{1/3} \delta^{5}(x),
\end{equation}
which represents a neutral five-brane localised at the boundary
in $x^{11}=0$ and $x^\mu=0$.

Neutral five-branes localised in the bulk are characterized by
\begin{equation}
f(x^2)=g(x^2)=0 \ . \label{46}
\end{equation}
In this case the function ${\tilde D}$ satisfies the equation
\begin{equation}
(\Delta_4 + \partial_{11}^2 ) \tilde D=q
 \delta^{4}(x-x_0)
\left[ \delta (x^{11}-x^{11}_0)+ \delta (x^{11}+x^{11}_0) \right] \ ,
\label{47}
\end{equation}
where a source in $-x^{11}_0$ has been added because from its construction
$\tilde D$ must be even.
On the other hand, the Bianchi identity is modified by a five-brane in a
way $dG=- {\sqrt 2}  k_{11}^2 \alpha T_6 \delta$  that fixes the charge
to be
\begin{equation}
q=-2 k_{11}^2  T_6 \ . \label{470}
\end{equation}
Note that $\alpha=1$ corresponds to a five-brane and $\alpha=-1$
to an anti-five-brane.
We will see in the next paragraph that this is consistent with the
five-brane Dirac quantization  condition.

The solution of  equation (\ref{47}) is
\begin{equation}
{\tilde D}= 1 +q
\left[ {\cal G}(x-x_0, x^{11}-x^{11}_0)+
{\cal G}(x-x_0,x^{11}+x^{11}_0) \right] \ . \label{471}
\end{equation}
In the decompactified limit $l \rightarrow \infty$, this becomes the
(symmetric under $x^{11} \rightarrow -x^{11}$) solution found in
\cite{G} in the context of 11d SUGRA. For $l \rightarrow 0$, we recover
the 10d neutral solution \cite{S}.
For $x-x_0,x^{11}-x^{11}_0 <<l$,
\begin{equation}
{\tilde D}=1+{k_{11}^2 T_6  \over 4\pi^2} \left( {1\over [(x-x_0)^2+
(x^{11}-x^{11}_0)^2]^{3/2}}+{1\over [(x-x_0)^2+
(x^{11}+x^{11}_0)^2]^{3/2}} \right) \ .
\end{equation}
As for the gauge five-brane this means that near the center the solution
differs from its ten-dimensional limit and is basically eleven-dimensional.
In analogy with the computation we did for the heterotic five-brane, we
can compute the difference of the compactified space volume for the two
boundaries. The result is
\begin{eqnarray}
{\tilde D}(x^2,l)-{\tilde D}(x^2,0) = {q \over 8 \pi^2}
\sum_{a=\pm 1} \sum_{n=-\infty}^{\infty}  {1 \over [(x-x_0)^2 +
(nl+a x^{11}_0)^2]^{3/2}}   \nonumber \\
= {q \over 4 \pi^{5/2}} \sum_{a=\pm 1} \int_0^{\infty} dt t^2
e^{-(x-x_0)^2t^2 +i\pi a {x^{11}_0 \over l}} \theta
\left[
\begin{array}{c}
a{x_{11,0}\over l} \\
1/2
\end{array}
\right] ({i l^2 t^2 \over \pi}) \ . \label{48}
\end{eqnarray}
Notice that for $x^{11}_0=l/2$ we get ${\tilde D}(x^2,l)={\tilde D}(x^2,0)$,
so the difference in the two volumes really comes here from the asymmetric
position of the center of the soliton with respect to the two boundaries.

\section{Mass and charges of solitons}

We compute in the following the mass and the magnetic charge
of the soliton solutions, checking that they are compatible with the Dirac
quantization condition of the fundamental membrane-five-brane pair.
We can consider more general solutions of type $(n_1,n_2)$, in an obvious
notation. As an example, let us explicitly write the heterotic five-brane
soliton
in the particular case of one instanton on each boundary, denoted by the
$(1,1)$ case. The solution (\ref{40}) reads
\begin{eqnarray}
{\tilde D}=1 + {4 k_{11}^{2/3} \over l
(4 \pi)^{5/3}}
\left\{ {(x-x_1)^2 + 2 \rho_1^2 \over [(x-x_1)^2 + \rho_1^2]^2 }
+  {(x-x_2)^2 + 2 \rho_2^2 \over [(x-x_2)^2 + \rho_2^2]^2 } \right\}
+ \cdots \ , \label{49}
\end{eqnarray}
where $x_1,x_2$ are the positions of the two instantons and the dots are
the contributions of the Kaluza-Klein modes in the expansion (\ref{38}),
which will turn out to give no contribution in computing the mass and the
charges of the soliton solution. In the following, we use the orbifold
picture of $S^1/Z_2$ and the integrals over the eleventh dimension are
half of the integrals on the corresponding circle $S^1$.
For the Strominger $(1,0)$ case, we get in a straightforward way
\begin{eqnarray}
Q={1 \over k_{11}} \int_{S^3 \times S^1/Z_2} G = {1 \over 2k_{11}} \int_{S^3
\times S^1} G
= -{1 \over {\sqrt 2} \alpha}({4 \pi \over k_{11}})^{1/3} \ .
\label{50}
\end{eqnarray}
We therefore find that the magnetic charge is the
same as in the Strominger solution \cite{S}, which is expected for a BPS
soliton.
For a more general solution $(n_1,n_2)$, the magnetic charge is
simply multiplied by $n_1+n_2$.
Notice that the quantization condition for a four-cycle
discussed in \cite{Wi} is here automatically satisfied.

The ADM mass per unit volume \cite{DGHR} is given here by
\begin{eqnarray}
M = {1 \over 4 k_{11}^2} \int_{S^3 \times S^1} dx^{11} \sqrt{g_{11,11}}
d \Omega_3 x^3 n^\mu \left( {\partial h_{\mu \nu} \over \partial x^{\nu}} -
{\partial h_{\nu \nu} \over \partial x^{\mu}}-
\sum_{a=1}^5 {\partial h_{aa} \over \partial x^{\mu}} \right)  \nonumber \\
 \ , \label{51}
\end{eqnarray}
where $\mu, \nu$ are indices on $S^3 \times S^1$, $\Omega_3=2\pi^2$ and $x
\rightarrow \infty$. The result is
\begin{eqnarray}
M={1 \over 2} ({4 \pi \over k_{11}^4})^{1/3} = T_6 \ , \label{52}
\end{eqnarray}
where $T_6$ is the five brane tension. We must check that this result is
compatible with the membrane-five brane quantization condition
\begin{equation}
k_{11}^2 T_3 T_6 = n \pi \ , \ {T_3^2 \over T_6}=m \pi \ , \label{53}
\end{equation}
where $T_3$ is the membrane tension. It is readily seen that the above
expression (\ref{52}) is indeed in agreement with (\ref{53}).
From equations (\ref{50}) and (\ref{53})
we get the following  relation between the charge and the mass of
the soliton expressing its BPS saturation \cite{DGHR}
\begin{equation}
M=-{\alpha \over {\sqrt 2} k_{11}} Q.
\end{equation}

For the neutral five-brane with $x^{11}_0$,  the quantization condition
on $\int G$ over a
four-cycle [14] implies that the charge of the soliton $q$ must be
quantized:
\begin{equation}
q={{\alpha}\over{\sqrt{2}}}\int_{S^3\times S^1} G =
\alpha\sqrt{2}k_{11}Q=
- (4\pi k_{11}^2)^{1/3} n,
\end{equation}
where $n$ is an integer. For $n=1$ we find that $q=-(4\pi
k_{11}^2)^{1/3}$, which is identical with the result we would get from eq.
(\ref{470}).
The corresponding mass, computed with (\ref{51}) is
\begin{equation}
M=-{q \over 2 k_{11}^2} = T_6=-{{\alpha}\over{\sqrt{2}k_{11}}}Q \ . \label{54}
\end{equation}
The relation between the mass and the charge is the same as that
of the gauge five-brane.

\section{Conclusions}

The purpose of this letter is to find classical solutions in the M-theory
context of Horava-Witten and study the phenomena arising as a
consequence of the dependence of the solutions on the eleventh coordinate.
By interpreting the world-volume of the five-brane as the $6d$
compactified space, we find that the compactified space volume depends
on $x^{11}$. In the compactified theory, our classical solutions are
interpreted as axionic strings depending on the fifth coordinate.
It was shown that, for heterotic five-brane solutions, new features
appear for small (compared to the eleventh radius) instanton size,
changing significantly the Strominger solution.
We shown by an explicit computation that the mass of the heterotic and neutral
five-brane solutions are in agreement with the membrane-five-brane
quantization condition and derive the quantized charge for the neutral,
five-brane solution.

We would like to make one comment concerning the $tr R^2$ part of the
boundary conditions (\ref{33}).
It can be easily verified that the Riemannian curvature of our
solution (\ref{40}) has vanishing $tr(R^2)$. However from the derivation
 of the boundary conditions from ten-dimensional anomalies
 it seems that one has to use in $tr(R^2)$
not the spin connection but a connection which is the analog
of the generalised connection $\Omega_-$ which contains the spin connection
plus terms depending on $G_{11\mu\nu\lambda}$. Moreover, the spin connection
is the one calculated in the string metric and not in the M-theory metric.
In any case, the gauge solution is obtained as in the ten-dimensional case
by neglecting the terms $tr(R^2)$,
in order to obtain a solution to first order in $k_{11}^{2/3}$.
The discussion concerning $tr(R^2)$ is relevant for generalising the
symmetric five-brane \cite{S}. No obvious generalization is possible,
however, so this issue is not important for our purposes.

The perspectives of the strongly-coupled $E_8 \times E_8$ heterotic
string for particle physics phenomenology seem
to be promising \cite{BD}, \cite{N}, \cite{DG}, \cite{AQ}. The classical
solutions we found in this
paper lead, by compactification, to classical solutions in 4d which may be
relevant for cosmological issues and for understanding nonperturbative
aspects of the compactified theory.

\newpage

redpajama_set_name: RedPajamaArXiv


text:
The Bravewell Collaborative
Letter from Bravewell's President
How Bravewell Worked
Bravewell Accomplishments
Bravewell Leadership
Bravewell Staff
Bravewell Advisors
History of The Bravewell Collaborative
The Benefits of Integrative Medicine
The Efficacy and Cost-Effectiveness of Integrative Medicine
A Healthy Nation
The Summit on Integrative Medicine and the Health of the Public
The New Medicine PBS Special
Pioneers of Integrative Medicine Lectures
Declaration for a New Medicine
The Patient's Bill of Rights
Philosophical Foundation for Integrative Medicine
Bravewell Initiatives
Leadership Program in Integrative Healthcare
The 2013 Bravewell Leadership Award Event
2013 Lectures & Luncheon
BraveNet
Mapping the Field of Integrative Medicine
Bravewell Clinical Network
The Bravewell Fellowship Program
Best Practices in Integrative Medicine
Academic Consortium for Integrative Medicine and Health
Bravewell Publications
Home › Integrative Medicine › The New Medicine PBS Special
Cost-Effectiveness Analysis
Summit on Integrative Medicine
Bravewell Pioneer Lectures
Patient's Bill of Rights
You'll need the latest, free Macromedia Flash Player to view media assets on this site. It appears that you don't have it. Get Flash Now
Extraordinary changes are underway in today's American health care system. The New Medicine, a special PBS series on integrative medicine, aired on March 29, 2006 to an audience of over 4.2 million people.
Recognizing the importance of public awareness to the growth of integrative medicine, early in its history, The Bravewell Collaborative resolved to create a high-quality Public Broadcasting Service (PBS) series similar in scope and quality to Bill Moyers' Healing and the Mind.
Judith Moyers, executive producer for most of Bill Moyers' work, provided counsel to the Bravewell Collaborative on a pro bono basis. Middlemarch Films, an award-winning and highly respected producer of documentary programming was retained and Twin Cities Public Television (TPT), highly regarded in the industry for its national productions, was secured as the sponsoring station.
PBS approved the two-part series for nationwide, prime time viewing and made it part of the PBS Health Initiative. The New Medicine series aired for the first time on March 29, 2006. More than 561 local PBS stations nationwide broadcast the show to an estimated 4.2 million viewers.
Episode I reveals how science is proving the power of the mind-body connection. It features advances in immunology and neurobiology and NIH-funded research studying the underlying biological mechanisms involved in healing. Relationships between stress and the immune system, and between the brain and treatment of chronic pain are explored.
Episode II examines the growing acceptance of holistic, mind-body medicine and ways it is changing health care in areas such as physician training, the hospital environment and the doctor/patient relationship, and how it is ultimately making medicine more humanistic.
On November 3, 2006 the production was awarded a FREDDIE for excellence in health and wellness media, the nation's highest honor for medical media.
Go to visit The New Medicine website
Go to order The New Medicine DVD
Produced by Muffie Meyer and Jennifer Raikes. Directed by Muffie Myer. Written and co-produced by Ronald Blumer. Editors/Co-Producers: Donna Marino and Sharon Sachs. Music composed by Richard Einhorn. Sponsoring station: Twin Cities Public Television
Major funding for The New Medicine was provided by WebMD Health Foundation.
Additional major funding was provided by: The George Family Foundation and Penny and Bill George, The Lura & David Lovell Foundation, The Christy & John Mack Foundation and Christy and John Mack, The Simms & Mann Family Foundations, The Bernard Osher Foundation, the Fannie E. Rippel Foundation, William Sarnoff, and Ruth Stricker and Bruce B. Dayton.
Additional funding was provided by: Wyeth, The Globe Foundation, Novartis, Definity Health Corporation, Colburn and Alana Jones, The Michele & David Mittelman Foundation, The Rudolf Steiner Foundation, Complementary Care Foundation, The Fullerton Foundation and The Arnold P. Gold Foundation.
The New Medicine Physician Advisory Board:
Brian M. Berman, MD
Founder and Director, Center for Integrative Medicine, University of Maryland School of Medicine
Erminia (Mimi) Guarneri, MD
Founder and Medical Director, Scripps Center for Integrative Medicine, La Jolla, CA
Mack Lipkin, MD
Director, Division of Primary Care, Department of Medicine, New York University Medical Center School of Medicine
Woodson Merrell, MD
Executive Director, Continuum Center for Health and Healing, Beth Israel Medical Center/Albert Einstein College of Medicine, New York
Ralph Snyderman, MD
Chancellor Emeritus and James B. Duke Professor of Medicine, Duke University School of Medicine
Esther Sternberg, MD
Director, Integrative Neural Immune Program and Chief of the Section on Neuroendocrine Immunology and Behavior, National Institute of Mental Health and National Institutes of Health
Contributing institutions:
Duke University Medical Center, College of Medicine, and Duke Integrative Medicine
The David Center for Children's Pain and Palliative Care, Hackensack University Medical Center
Institute for Behavioral Medicine Research, Ohio State University Medical Center
University of Maryland Center for Integrative Medicine
W.M. Keck Laboratory for Functional Brain Imaging and Behavior, University of Wisconsin-Madison
University of California, San Diego Student-Run Free Clinic
Center for Integrative Medicine, Cleveland Clinic Foundation
Scripps Center for Integrative Medicine
Center for Spirituality and Healing, University of Minnesota
Contact Us Privacy and Copywrite Credits
© 2015 The Bravewell Collaborative

redpajama_set_name: RedPajamaCommonCrawl


As they unfold, cognitive technologies will help open up a wealth of applications that were previously unavailable to enterprises. Mphasis NEXT Labs' Ganesh reviewed some key areas where AI and ML are making a difference, including search and advertising algorithms; friend, movie, and book recommendation algorithms; driving-pattern recommendations; ?money-lending-related credit recommendations of peer-to-peer lending platforms; and the prediction of journey times to frequently visited locations.
Along with the enterprise data being gathered, this predictive power "gets enhanced as more partners—such as hotels, car rental companies, airlines, banks, and retailers—share user data. Enterprises are generating insights from multi-structured and multimedia datasets, the digital footprints of customer interactions, and customer intelligence across multiple channels, touch points, as well as social networks," said Ganesh. Predictive analytics is also being leveraged for better planning, forecasting, and support for decisions concerning cross-sell, upsell, retention, loyalty management, risk mitigation, fraud detection, campaign management, and inventory management, he added.
In addition, a service called Reuter News Tracer "helps weed out rumor and false news from social media feeds," said John Hudzina, a researcher and architect in the Emerging Technology Group at Thomson Reuters. "Tracer mines potentially untrustworthy sources from Twitter for breaking events, the application applies cognitive computing to verify the event," said Hudzina, noting that it examines the source's social network and also attempts to determine potential biases. Hudzina added that his organization is relatively mature with its AI technology, as applied to its text-based information products—news, legal, and tax.


text:
Q: Javascript Euler Fibonacci for loop I'm doing the Euler project problem 2 in which the objective is to sum the even numbers of the fibonacci sequence that have a value of less than 4 million. I've searched a bit and I've seen several solutions using a while loop but nothing simple using a for loop. I'm curious why I'm returning zero with the following code:
var array = [];
array[0] = 0;
array[1] = 1;

var total = 0;

for(var i=2;total<=4000000;i++) {
array[i] = array[i-1] + array[i-2];};

for(var x=0;x<array.length;x++){
if(array[x]%2 === 0){
total += array[x]};};

alert(total);

I'm guessing the problem is in my for loop using the total variable. I couldn't get it to work using array[i]<=4000000 either and I'm really curious behind the why here. Anyone know why this is? What can I change in the for loop condition (second statement) to get a correct total here?

A: I fixed it for you.
var i, data = [ 0, 1 ], total = 0;

for (i = 2; i <= 4000000; i++)
{
    data[i] = data[i - 1] + data[i - 2];

    if (data[i] % 2 === 0)
    {
        total += data[i];
    }
}

alert(total);

I'm not sure what you termination condition should be like, you say have a value of less than 4 million, but this is ambiguous. Maybe it should be total <= 4000000 or data[i] <= 4000000. Your phrasing is not precise enough.

A: First of all there is an infinite loop at first for. Your condition must be array[i-1] < 4000000. After that your second for loop will find the correct result.
Also for the problem, you don't need to store all fibonacci numbers then find sum of even numbers.
You can calculate sum when calculating fibonacci.
var first = 0;
var second = 1;
var sum = 0;

for(var current=first+second; current < 4000000; current = first+second){
    if(current%2 === 0){
        sum+=current;
    }
    first = second;
    second = current;
}

A: Sorry but for me your code going in a dead loop. first "for" use total as check but it's never incremented. If you want This is a solution for fibonacci sequence based on dinamic programming with memoization tecnic.
var f1 = 1;
 var f2 = 1;

 for(var i = 2; i < 40000; i++){
  console.info(i, f1, f2);
  var temp = f1 + f2;
  f1 = f2;
  f2 = temp;
 }

 alert(f2);

redpajama_set_name: RedPajamaStackExchange


text:
Search for Great Deals on Flooring
New Support for an Old Floor
Scott Gibson, Contributing Editor
My father built a cabin about 40 years ago. He has since passed away and I'm trying to solve a problem there. The floor upstairs is made from particleboard and seems to be weak or spongy when I walk on it. He put the floor down, and then he added the walls to separate three rooms. Dad didn't have a lot of money so he did things cheap and his way. Do I need to have the entire floor cut out and then replaced?
I'm sorry about your father. The cabin must be a special place, and you should be able to rescue the floor without tearing anything out. In fact, you'll probably be adding material to what's already there.
Many an old house (and cabin) was put together with floor framing that wasn't quite stiff enough. Strength and flexibility are two different things -- a bouncy floor may be irritating or unnerving but still up to the job structurally. But if you want to take out the bounce, start on the first floor.
Adding new framing from below
Your job will be a great deal easier if there is no finished ceiling on the first floor and you have a clear view (and access to) the flooring above. Start by looking for cracked beams, split floor joists, punky wood and signs of insect infestation. Wood that has deteriorated from exposure to water or bugs generally should come out and be replaced with new material. In the case of a major beam that can't be removed, repairs can sometimes be made with epoxy fillers.
But let's assume for now that the floor joists (the framing that supports the floor) are simply undersized. One approach is to add a column or even a short, framed wall to support the framing roughly half-way across its span. If you can, the load from above should be carried all the way to a solid footing.
You also can add new material to one or both sides of the existing joists, which is called "sistering." Choose lumber that's the same width as what's already there, and use a combination of construction adhesive and bolts or lag screws to attach it to the under-sized joists. Where joists intersect beams at the perimeter of the room, you can use metal joist hangers for support. Those are available at just about any store that carries building supplies. This approach isn't going to do much for the charm of an old cabin, but the repairs could be disguised with a simple finished ceiling on the first floor.
Carry the weight from above
We once owned an old house with an attached barn where an enterprising carpenter had found a way to support a major beam from above rather than below. This involved drilling a hole down through the beam at mid-span, inserting a length of threaded rod and putting a washer and nut on the bottom where it popped through the beam. The top of the rod went through the ridge and was attached in the same way.
Once everything was tightened up, part of the weight from the floor was distributed throughout the roof structure. Of course if the roof on your cabin is structurally lacking, this isn't going to work. You'd need stout rafters and ridge.
If the flooring upstairs is rotten, take it out
If the floor upstairs is truly spongy because of water damage, you should cut out the bad spots and splice in new pieces. While particleboard makes good floor underlayment, it does not take kindly to water. But unless the damage is widespread, you should be able to reinforce the floor without removing it.
If you're not sure how to proceed, or you're concerned that the floor is teetering on the edge of collapse, don't take any chances. It just isn't worth it. Ask a carpenter you trust to take a look and offer suggestions for repairs.
An accomplished woodworker and carpenter, Scott Gibson is the former editor of Fine Woodworking magazine, and a former editor at Today's Homeowner and Fine Homebuilding magazines. He also is former managing editor of the Kennebec Journal, a daily newspaper in Maine.


It's summer time and the heat is on. One favorite choice of most people for beating the heat is to get a smoothie. But for people trying to lose weight and not miss out, are there any healthy options? Yes. You can make your own smoothies.
From a health point of view, blended smoothies are great for a concentrated meal that's ready in a minute. You can combine a variety of fruit with some water, possibly add some dates or genuine maple syrup and make a delicious smoothie that can be enjoyed anytime as a healthy meal while on your weight loss program.
Actually friends, this may be a better choice than juicing as you will also get the fibre, which is an essential nutrient present in our fruits and vegetables for several reasons and in regards to losing weight, the fibre will serve as intestinal brooms to push all unwanted debris out. Hey, we are seeking weight loss right?
Now, the recipes listed below are my personal favorites for smoothies. I think they are creative ways to enjoy the proper diet and not entirely miss out on pleasuring ourselves occasionally.
You can always experiment to find tasty recipes as well, but here are some to get you started.
Blend everything starting with the fruits then the coconut.
Blend everything and prepare for something outta this world!
4. My Milk Shake tastes much better than yours…!
Who said fruits and veggies were boring again?
Well, there you have it. Thought you'd have to give up smoothies eh? Hope, I'll be able to save you some money in buying less healthy and-as you'll discover-not as tasty smoothies with these.


Peasants and human rights defenders in Brazil are indignant over the acquittal of the man accused of ordering the May 2011 murders of two prominent Amazon activists, José Cláudio Ribeiro da Silva and his wife Maria do Espírito Santo.
Unknown to the Israeli government or the Israeli electorate, hundreds of Palestinians from the West Bank and Gaza took part in the recent Israeli elections by default thanks to an act of civil disobedience by Israeli peace activists.
The return to power of Japan's conservative and hard-line Liberal Democratic Party (LDP) on Sunday indicates that voters traded urgently needed social and environmental reforms for traditional male-led leadership, according to analysts here.
Wendy Hlophe* is still visibly grieving for her long-term friend, 28-year-old Sanna Supa, who was shot and killed outside her home in Braamficherville, a South African township, two weeks ago.


text:
Rugby World Cup Sevens 2022: How an "incredible" weekend unfolded
13 September, 2022 in Featured, News by Asia Rugby
Following the conclusion of RWC Sevens 2022 in Cape Town, we recap some of the highlights from a truly special weekend.
Following 84 incredible matches, the curtain came down on an enthralling Rugby World Cup Sevens 2022 with Australia and Fiji sitting on the top step of the podium.
Australia dominated the women's tournament from the very first match, while Fiji were made to work hard to end their season on a high in Cape Town.
But that only tells part of the story. We recap some of the highlights from a memorable weekend that sets up both the men's and women's World Rugby Sevens Series 2023 perfectly.
Sevens? Completed it 🏆
Charlotte Caslick and Sharni Williams are the first @Aussie7s players to complete a unique quartet of Sevens titles
🥇 Olympics
🥇 Rugby World Cup Sevens
🥇 World Rugby Sevens Series
🥇 Commonwealth Games#RWC7s | #HereToSevens pic.twitter.com/mTnUxO5lxt
— Rugby World Cup 7s 2022 (@WorldRugby7s) September 12, 2022
AUSTRALIA COMPLETE HISTORIC HAT-TRICK
Heading into the 2022 season, Australia's women were determined to bounce back from a disappointing Tokyo Olympic Games in style.
Ten months later, they have created history as the first team to win the World Rugby Sevens Series, Commonwealth Games and Rugby World Cup Sevens in the same year.
In Cape Town they hit the ground running with a 48-0 win against Madagascar and didn't look back, beating England 35-5 in the quarter-finals and the USA 17-7 in the semi-finals.
New Zealand stood between them and a second RWC Sevens title but a Maddison Levi hat-trick and a ninth try of the tournament for Faith Nathan helped them to a nail-biting 24-22 victory.
"It's a pretty special feat that this group of young girls has done. It was something we've been brave enough to put out there and put everything on the line to come away with," co-captain Charlotte Caslick said.
"It's incredible. I'm so proud of the girls – it's been an honour to lead them this year and to watch the growth they've had as a group and as a team.
"It's really special for me to be a part of. At the moment, I'm just really proud – proud of our coaching staff, proud of the girls, proud of Demi [Hayes] and I, and getting them to have this bond that is becoming a real force on the world stage."
Co-captain Hayes added: "I am so proud of our group, the 12 of us, and everyone back home, the whole of Australia. Hopefully, we have done all of them proud. It's never been done before, so to take that home is really special."
FIJI BACK ON TOP OF THE WORLD
By Fiji's extremely high standards, 2022 had been a slightly disappointing one, missing out on the men's Series title by four points and losing in the Commonwealth Games final to South Africa.
The team put that right in Cape Town, however, to end Ben Gollings' first season as coach on a high and come away with a third RWC Sevens title – and first of those won outside of Hong Kong.
Wales were dispatched 29-5 in the round of 16 on Friday before Fiji overcame Pacific Island rivals Samoa 21-10 in a bruising quarter-final the following evening.
A 38-14 defeat of Australia in the semi-finals set up a showpiece match against defending champions, New Zealand. Fiji ran in five tries through five different scorers in the final to topple the All Blacks Sevens 29-12.
Flying finish for @fijirugby! ✈
Scenes were made in Cape Town thanks to Fellipe Sauturaga!#HereToSevens | #RWC7s pic.twitter.com/Zy3nG8FYiA
"It was huge. These boys have been fantastic this whole week," Gollings said. "They set themselves a goal and they came and finished the job this evening, and it was just incredible.
"Words don't really express it right now. They deserve everything they have done today."
Try-scorer in the final, Kaminieli Rasaku added: "Today was unreal for the boys. It's quite a long time since we won the World Cup. I think the boys are proud of themselves – their performance throughout the three days of the tournament."
RWC SEVENS 2022 HIGHLIGHTS
It did not take long for Australia and Faith Nathan to find their form in Cape Town, the exciting finisher becoming the first player ever to score five tries in a single RWC Sevens match in the opening tie of the women's tournament.
Madagascar were on the receiving end as Nathan touched down twice in the first half, before crossing the whitewash another three times in the second.
"It feels really good. They were more team tries rather than individual but it feels good," she said after the 48-0 win.
Nathan went on to score a hat-trick in the quarter-final against England before a try in the final against New Zealand took her tournament tally to nine.
In the men's tournament, several of Ireland's players danced their way through the media mixed zone after they capped a stunning weekend with the bronze medal on Sunday night.
Having played and won the opening match of the tournament against Portugal in the pre-round of 16, Ireland then overcame England before beating South Africa in front of their home crowd in the last eight.
Following that win, Mark Roche had claimed his team-mates had "got great things ahead" of them, and after losing narrowly to the All Blacks Sevens in the semi-finals, they claimed third place with a 19-14 win against Series champions Australia.
How's your football skills Terry Kennedy!
Phenomenal as he sets up Harry McNulty in the TUDOR Daring Play of the Day! 🤩#BornToDare pic.twitter.com/5N1cv0jhcL
"It is incredible," try-scorer Terry Kennedy said after the bronze final. "We never fail to surprise, every time our backs are against the wall, we stand up.
"It was a tough loss today against New Zealand in the semis, so to come out there and put on that performance was unbelievable."
As the goalposts are taken down at DHL Stadium and the dust settles on a remarkable three days, both Australia and Fiji are now tied as the most successful teams in women's and men's Rugby World Cup Sevens respectively.
Fiji's triumph in Cape Town was their third at a men's RWC Sevens, taking them level with the All Blacks Sevens, who tasted victory in 2001, 2013 and 2018.
Australia, meanwhile, have now won two tournaments – having lifted the inaugural women's title in 2009 – and are now level with the Black Ferns Sevens, who claimed RWC Sevens glory in 2013 and 2018.
Like the rest of the teams who competed in Cape Town, Australia and Fiji will now enjoy a well-earned rest, but they will also take a great deal of confidence into the 2023 Series.
Fiji have less than eight weeks to wait until the men's World Rugby Sevens Series 2023 gets underway in Hong Kong, the scene of their first two RWC Sevens triumphs.
Australia, meanwhile, have an extra month to prepare for the start of the women's Series, which kicks off with a joint event in Dubai at the beginning of December.
Much work will go in on the road to Hong Kong and Dubai as teams aim to close the gap on Fiji and Australia, while others attempt to rebound from disappointment in Cape Town.
If any extra significance was needed, the 2023 Series will also act as a qualification pathway for the Paris 2024 Olympic Games. See you at Hong Kong Stadium on 4 November!
Filed Under: Featured, News Tagged: Rugby World Cup, Rugby World Cup Sevens 2022, Australia Rugby, RWC Sevens, Fiji Rugby, RWC


text:
Teejay Lanka consolidates in Q2 to post 6-month revenue of Rs 23.1 billion
Topline grows 71% on higher demand for fabric
Net profit improves by 59% to Rs 954.1 million for 1H
Teejay Lanka PLC has built on its robust first quarter performance in Q2 of 2021-22, helped by strong demand for fabric from strategic customers due to the changing dynamics of the global market, increased capacities and the depreciation of the Rupee.
Sri Lanka's leading fabric manufacturer has reported revenue of Rs 23.1 billion at Group level for the six months ending 30th September 2021, reflecting topline growth of 71%. The second quarter contributed Rs 12.7 billion to the topline with an improvement of 44% over the corresponding quarter of last year.
The Group posted profit before tax of Rs 1.15 billion for the six months, up 44%. Pre-tax profit for the second quarter amounted to Rs 763.7 million, largely as a result of reduced margins due to predicted raw material and commodity price increases and higher distribution and marketing costs linked to the increased volumes.
Group profit after tax for the six months improved by a noteworthy 59% to Rs 954.1 million despite the second quarter's net profit growing by only 2% to Rs 643.5 million, according to interim financial statements filed by Teejay Lanka with the Colombo Stock Exchange (CSE).
Commenting on the Group's performance, Teejay Lanka Chairman Mr Bill Lam said: "While we continue to see growth opportunities, we also see challenges in this turbulent environment, notably increases in the prices of cotton, dyes, chemicals, auxiliaries and logistics. Considering these factors as well as the challenging operating conditions in the first half due to the Covid waves in India and Sri Lanka, our growth and improvement in profit are noteworthy."
He said the Group is strategically approaching suppliers to secure yarns at a better price, and negotiations are in progress with customers to manage the margins at better pricing. "The teams are constantly collaborating with suppliers to minimise the impact of supply chain disruptions and higher freight rates,"Mr Lam added.
Teejay Lanka CEO Mr Pubudu De Silva noted that the Group's US$ 26 million expansion project in India is progressing to planned timelines, with plant construction ongoing and orders for additional machines placed. "As part of our strategy of adapting to the changing environment we are progressing with an upgrade to the SAP-HANA relational database management system," he disclosed, adding that "Teejay is navigating the journey to achieve the goal of US$ 300 million by 2023 amidst changing business dynamics and uncertainties, with cautiously-placed strategies that will achieve the targets set for our stakeholders."
Sri Lanka's largest textile manufacturer and the first textile manufacturer in the country to receive membership of the US Cotton Trust Protocol, Teejay Lanka PLC is a public quoted company with 40 per cent public ownership. The company is backed by Sri Lanka's largest apparel exporter Brandix Lanka which has a 32 per cent stake. Pacific Textiles of Hong Kong whose key shareholder is the Tokyo Stock Exchange listed Toray Industries Inc., owns 27 per cent of Teejay Lanka.
The Company has been adjudged the Best Textile Exporter in Sri Lanka at the Presidential Export Awards presented by the Export Development Board (EDB) and has been named among the 100 Most Respected Companies in Sri Lanka by LMD.
An ISO 9001:2015, ISO 14001:2015 and OHSAS 18001:2007 compliant company and the first in the industry to develop green fabric, Teejay has been listed on the Colombo Stock Exchange (CSE) since 2011 and was included in the S&P Top 20 Index in Sri Lanka. The Company has also been named among the Forbes '200 Best under a Billion in Asia' and been recognised as the 'International Textile Firm of the Year' and the 'International Dyer and Finisher' by World Textile Institute, London.


Some resources, values and messages are not related to the reasons for designation. This section should contain information on these.
In applying the first element of commemorative integrity, emphasis is clearly on resources directly related to reasons for designation as a national historic site and their values. However, the CRM Policy applies to all cultural resources, as well as significant ecosystem features.
A CIS is developed to assist managers/owners in managing all the resources for which they have responsibility. The overall stewardship of a national historic site is called into question and commemorative integrity is threatened if resources not related to the reasons for designation are not managed in accordance with the CRM Policy .
resources not related to reasons for designation (both cultural and natural), with their values and objectives.
any other values of the site not related to the reasons for designation, with their objectives.
messages not related to reasons for designation, with their objectives.
Section 2.2.2.1 of the CRM Policy states that "Parks Canada will establish and apply criteria to determine which resources under its jurisdiction are of this type. A resource may be included in this category by virtue of its historical, aesthetic or environmental qualities. Criteria will also give consideration to factors such as regional or local association; or provincial, territorial or municipal designations."
The identification of cultural resources not related to reasons for designation is done by a multi-disciplinary team. This ensures that a variety of perspectives are represented and a degree of consistency is achieved. This team should include representatives from all cultural resource management functions, but must have the requisite information and specialists on what is being evaluated.
The team evaluating the resources will give consideration to the evaluation done by others such as provincial, territorial or municipal designations.
Classified or Recognized Federal Heritage Buildings will automatically be considered as resources in this category, unless they meet the requirements that have been described for resources directly related to the reasons for designation as a national historic site, as per the CRM Policy .
With the exception of the evaluation of federal heritage buildings, there are no national evaluation guidelines for resources which fall into this category.
Natural ecosystem features of special significance as outlined in section 1.1.7 of the CRM Policy should also be described here.
Any resource not related to the reasons for designation, but part of the area for which the CIS is being written, should be included in this section of the CIS. In cases where such resources are numerous, they should be presented in a way which does not overwhelm the resources directly related to the reasons for designation as a national historic site.
This section is used to identify those heritage values that are important for the site and have not already been dealt with elsewhere in the CIS.
The CIS should include a set of objectives for resources and heritage values not related to the reasons for designation. The standard objectives which are used for resources directly related to the reasons for designation, described in section 2.3.3.1, should be used.
This section should contain any messages not related to reasons for designation which are to be communicated at the site. All messages should be expressed in full sentences.
a message about the family of national historic sites.
a message linking the site to other national historic sites related to it thematically or geographically.
a message about related national historic designations of people or events.
a message about international, provincial or municipal designations relating to the site.
at sites administered by Parks Canada, a message stating that these sites belong to all Canadians.
part of the heritage presentation experience conveys the messages not related to the reasons for designation as a national historic site.
the messages not related to the reasons for designation as a national historic site and their presentation do not overwhelm or detract from the presentation and understanding of the site's national historic significance.
visitors understand the messages not related to the reasons for designation as a national historic site.
management decisions are based on adequate and sound information and are made in accordance with the principles and practice of the CRM Policy.


text:
<!DOCTYPE html>

<title>Quota Internals</title>
<meta charset="utf-8">
<link rel="stylesheet" href="main.css">

<link rel="stylesheet" href="chrome://resources/css/tabs.css">
<link rel="stylesheet" href="chrome://resources/css/tree.css">

<tabbox>
  <tabs>
    <tab>Summary</tab>
    <tab>Usage & Quota</tab>
    <tab>Data</tab>
  </tabs>
  <tabpanels>
    <tabpanel>

Summary

            Free disk space for the profile directory.
            N/A

Misc Statistics

    </tabpanel>

    <tabpanel>

Usage and Quota Database Browser

        <button id="refresh-button">Refresh</button>
        <tree id="tree-view"></tree>

    </tabpanel>

    <tabpanel>

      <button id="dump-button">Dump</button>

    </tabpanel>
  </tabpanels>
</tabbox>

redpajama_set_name: RedPajamaGithub


text:
Palpoteleia citrea är en stekelart som först beskrevs av Alan Parkhurst Dodd 1914.  Palpoteleia citrea ingår i släktet Palpoteleia och familjen Scelionidae. Inga underarter finns listade i Catalogue of Life.

Källor

Steklar
citrea

redpajama_set_name: RedPajamaWikipedia


text:
Asia stands to create 230m jobs by 2030
Asian companies are well-placed to reap some of the trillions of dollars of opportunities opened up by adopting more sustainable business models, a new report says.
Businesses in the region could unlock new market opportunities worth US$5 trillion (S$6.9 trillion) and create 230 million jobs by 2030, by pursuing strategies in line with the United Nations' sustainable development goals, it found.
The report is from the UN Foundation-backed Business and Sustainable Development Commission (BSDC) - launched at the World EconomicForum in Davos last year.
The UN goals set out 17 targets to eliminate poverty, improve education and healthcare, create jobs and address climate change.
"Asia represents 40 per cent of the global value (at US$12 trillion), and nearly two-thirds of total jobs," said the commission.
Its report highlighted four key areas that will drive economic value creation.
BTS fans join swarm of Ants chasing S Korea's hit IPO
SIA Q2 earnings jumps to $189.9m
Gaming firm Razer prices IPO near top end
Tee Land buys Casa Contendere for $72m
The energy and minerals sector accounts for the lion's share of the value at US$1.9 trillion, followed by city infrastructure development at US$1.5 trillion, food and agriculture at US$1 trillion, and health and well-being at US$670 billion. -THE STRAITS TIMES
FOR MORE, READ THE STRAITS TIMES TODAY
FinanceBusinessEnvironment


You're reading novel The Demonic King Chases His Wife: The Rebellious Good-for-Nothing Miss Chapter 1111 online at LightNovelFree.com. Please use the follow button to get notification about the latest chapter next time when you visit LightNovelFree.com. Use F11 button to read novel in full-screen(PC only). Drop by anytime you want to read free – fast – latest novel. It's great if you could leave a comment, share your opinion about the new chapters, new novel with others on the internet. We'll do our best to bring you the finest, latest novel everyday. Enjoy!
Relatively speaking, Zi Yan's words were much sharper and even more unforgiving of a person's face.
However, with regards to these greedy, vile characters, even sharper words couldn't make them blush.
Luo Haochen curled his lips and turned his face away.
"Although there aren't any more crystal nucleus from Magical Beast Rat leaders, however, there are still a lot of crystal nucleus from the small Magical Beast Rats. It can still be considered that we have earned a profit!" Zi Yan laughed out loud with 'hahaha' and turned around to pick at the Magical Beast Rats' corpses.
Seeing Zi Yan begin to collect them, everyone also didn't want to be outdone, they joined in, one by one.
"Luo Luo, you're not coming?" Zi Yan pulled at Beichen Ying, the two people picked the nucleus in great delight yet still didn't forget to call out to Su Luo.
These Magical Beast Rats were all at the fourth and fifth rank, the majority of these crystal stones were red and yellow-colored. Although they already had no use for these magical beast crystal nucleus, however, with regards to the younger generations in their family, it was still very good crystal stones for their cultivation.
Su Luo smiled lightly and shook her head slightly.
Her several spirit pets could find their own food, the Amethyst Crystal Fish in her s.p.a.ce also laid eggs at a fixed time. These low-leveled crystal stones on the ground didn't have any attractiveness to her.
Suddenly, Nangong Liuyun's gaze slightly creased.
"What's wrong?" Su Luo was the first to discover his fis.h.i.+ness.
Nangong Liuyun's cultivation was the highest among them, if even he was frowning, clearly, the matter was somewhat grave.
"There's danger approaching, take precautions." Nangong Liuyun's voice was ice-cold like cold iron.
Those several people that were happily picking up things immediately stiffened from head to toe. They straightened up one after another, directly entering a battle-ready state.
It was simply because Nangong Liuyun's unfeeling image had already entered deeply into people's hearts, making people's heart palpitate.
At the moment, the sun in the mid-air had already ascended to the center.
The temperature all around gradually rose to another height.
"Ah!" Between the time it took Beichen Ying to raised his head, he suddenly discovered something was wrong, "Why are there two suns!"
Everyone, one by one. raised their heads to look!
Sure enough, it was like what Beichen Ying had said. Now, there really were two suns in the sky! This moment was simply too bizarre!
The two suns were up in the middle of the sky, like this, the effect it caused was absolutely not as simple as one plus one.
At this moment, the temperature in the surroundings was very clearly going up quickly!
In the desert, one after another, streams of greenish-black smoke were subsequently given off.
As far as the eye could reach, it was a misty and confusing color, blurring their line of sight.
Everyone felt as if they were in an oven, all around was the boiling hot fire element. So hot as to nearly suffocate them.
"So hot!" Li Yaoyao was the very first to be unable to bear it, both her eyes flipped outwards, her figure on the verge of collapse, nearly falling down.
At this moment, she almost couldn't breathe.
"What's to be done? If another sun was to appear, the consequences are too horrible to contemplate!" Luo Dieyi called out loudly.
Because, she was also nearly unable to go on.
"It's another sun! Luo Dieyi, f*ck, you truly have a crow's beak! You quickly give me to shut up!!!" Zi Yan was almost roasted into human jerky, her temper also became more irascible.
Luo Dieyi, seeing the phenomenon in front of her, was completely stunned.
She only said the sentence in a moment of desperation, who would have thought that another sun would really appear? If she had known earlier, even if you beat her to death, she wouldn't say it!
Luo Dieyi tightly covered her mouth, fearing that she would once again make an inauspicious remark.
However, at present, three scorching hot suns in the sky roasted the desert, one after another, streams of greenish-black smoke lingered and intertwined, lingering and pervading through the air.
"My feet are almost scalded to the point of being cooked……" Li Yaoyao dispiritedly said.
Situ Ming, without saying another word, directly put Li Yaoyao on his back.
"Now, what's to be done about this temperature?" Su Luo, seeing the circ.u.mstances were becoming more and more dire, asked Nangong Liuyun in a low voice.
Nangong Liuyun frowned slightly: "This is still not the most grave matter."
You're reading novel The Demonic King Chases His Wife: The Rebellious Good-for-Nothing Miss Chapter 1111 online at LightNovelFree.com. You can use the follow function to bookmark your favorite novel ( Only for registered users ). If you find any errors ( broken links, can't load photos, etc.. ), Please let us know so we can fix it as soon as possible. And when you start a conversation or debate about a certain topic with other people, please do not offend them just because you don't like their opinions.
You're reading The Demonic King Chases His Wife: The Rebellious Good-for-Nothing Miss Chapter 1111. This novel has been translated by Updating. Author: Su Xiao Nuan,苏小暖 already has 10360 views.
Current Time is Apr-21-2019 02:53:32 AM.


David B. Dempsey is co-founder and partner at Dempsey Fontana, PLLC, with over 38 years of experience in procurement laws, regulations and policies pertinent to contracting with federal and state agencies as well as their international counterparts.
His areas include rights in technical data and computer software (and accompanying protection of contractor intellectual property); DCAA audits; cost principles; Cost Accounting Standards; contract pricing and price adjustments; information technology contracts; research & development contracts; architect & engineering contracts; federal grants and audits; foreign contracting (e.g., Buy American Act, NATO MOUs, Trade Agreements Act, NAFTA, WTO Government Procurement Agreement, SOFAs, EU procurement, Recovery Act); contingency contracting (e.g., operations in Iraq/Afghanistan); organizational conflicts of interest; small business issues (size appeals, affiliation, SBIR regulations); contract terminations; change order proposals, change order accounting and equitable adjustments; GSA / VA Schedule contracting; contract types (e.g., IDIQ, T&M, cost reimbursement); international transactions (contract formation, negotiation, administration, arbitration, litigation); teaming agreements and joint ventures (including subcontract issues and negotiations); procurement related labor statutes (e.g., Service Contract Act, Defense Base / War Hazards Act, Davis-Bacon Act, Fair Labor Standards Act exemptions); corporate ethics / compliance; industrial security compliance (NISPOM); foreign military sales/foreign military funding, export control compliance and planning (EAR, ITAR); federal, state and local outsource and privatization contracting; Freedom of Information Act strategies; bid protests and contract disputes litigation in all forums; suspension / debarment.
Mr. Dempsey was appointed to the Federal Advisory Committee to the Department of Defense (the "§ 807 Committee" established under Pub. L. 102-109, § 807) to revise the Defense Department's guidance and contract clauses regarding technical data and computer software rights (1992-95).
In the procurement community, Mr. Dempsey is involved with the Professional Services Council, Council of Defense & Space Industry Associations (Operations Committee, Chair 1997-2000; Project Officer for the FAR 15 Rewrite). He was General Counsel to the Contract Services Association prior to its merger with the Professional Services Council (1990-2007; Chair, Procurement Committee, 1995-98). Over the years, his articles have appeared over 40 times in such industry publications as Service Contractor, Service Scope, The Metropolitan Corporate Counsel, Contract Management, E-Gov Journal, Proposal Management, The Clause, Outsourcing & Privatization Forum, National Contract Management Journal, Contract Management Magazine, Government Contract Costs, Pricing, and Accounting Report, The Government Contractor, and the Public Contract Law Journal. He is a member of the American Bar Association (Public Contract Law; Law and Technology Sections); the Federal Bar Association (co-Chair, International Procurement Committee, 2002); the Court of Federal Claims Bar Association; and the Boards of Contract Appeals Bar Association.
Mr. Dempsey's government experience includes: Assistant Counsel, Defense Logistic Agency; Associate Counsel, Defense Fuel Supply Center, and Attorney-advisor, Defense Logistics Agency; Counsel, DAR Council Subcommittee on Cost Principles (1981-82); Chair, DAR Council Subcommittee on Foreign Purchases (principal author for DFARS Part 25, Foreign Acquisitions for the implementation of NATO MOUs and Trade Agreements Act of 1979 (1978-80)).
Mr. Dempsey was selected by American Lawyer Media and Martindale-Hubbell as one of the "Top Rated Lawyers in Technology" (April 2013); as one of "Virginia's Top Rated Lawyers" (October 2013); as one of "Washington, D.C. and Baltimore's Top Rated Lawyers" (February 2014) and identified by ALM / Martindale-Hubbell as having an "AV Preeminent" peer review rating (March 2013). He has also been selected by Marquis Who's Who as follows: Who's Who in American Law (1991, 1993, 2001, 2015-2016); Who's Who in America (1995, 1996, 2012, 2013, 2014); Who's Who in the World (1986, 2014); Who's Who of Emerging Leaders in America (1987); Who's Who in the East (1994).


Two charged in alleged Kmart card scam were Kmart employees, charged with theft.
A man and woman who worked as Kmart's loss prevention employees used prepaid credit cards to fraudulently get over $100,000 in cash back, according to a magistrate's complaint filed Thursday in the Superior Court of Guam.
Parent company Sears Holdings conducted an internal investigation into the Guam Kmart and found Candelaria Blas and Gerard Pangelinan used several prepaid MyVanilla credit cards to take money from the company, documents state.
A Sears employee told police that people would use the MyVanilla card to buy something of lower value and get cash back, documents state. The card was only charged 50 cents, but the person would get back $50, documents state.
The store wouldn't get any reimbursement, the charging documents state.
Blas had three cards linked to her in which about 865 transactions were logged and a total $77,100 was given in cash back, documents state. This occurred between May 2018 and August 2018.
Pangelinan had four cards linked to him with 811 transactions logged between July and August 2018, documents state. Over $40,000 was given in cash back on those cards, according to the charging documents.
The Sears employee stated that Blas told him that loading $50 on the card could get up to $2,000 back and the card could be used over and over, documents state.
Blas and Pangelinan made written statements to the Sears employee. In hers, Blas wrote that she didn't realize she was hurting Kmart but did use the "vanilla card" and got about $3,500, documents state.
Blas also wrote she wasn't the only one using the cards, the magistrate's complaint states.
Pangelinan told the Sears employee that he didn't feel like he was doing anything wrong and thought Kmart was getting their money back, documents state.
Pangelinan estimated he took less than $10,000, court papers state.
Both Pangelinan and Blas were each charged with theft of property as a second-degree felony.
Police on Wednesday said they also arrested another woman, Abigail Caporno, in connection with the case. Caporno wasn't charged in the criminal complaint and authorities have not detailed what her role was in the case.
This isn't Pangelinan's first run-in with the law. He was charged in December with first-degree criminal sexual conduct and was accused of sexually abusing a 14-year-old girl.


2009 Thomas J. Dodd Prize in International Justice & Human Rights.
Committee to Protect Journalists -- Awards.
Thomas J. Dodd Research Center -- Awards.
Speakers, UConn president Michael J. Hogan, U.S. Senator Christopher Dodd, Joel Simon, Michael Massing, Mariane Pearl.
Recorded in the Dodd Center plaza on Oct. 6, 2009.
System requirements: Windows Media Player.; Mode of access: World Wide Web.
Ceremony for the awarding of the fourth Thomas J. Dodd Prize in International Justice and Human Rights to the Committee to Protect Journalists for its work on making the world aware of where abuses against journalists are occuring. Accepting the award on behalf of the Committee to Protect Journalists is Joel Simon, Executive Director for CPJ; Michael Massing, Co-Founder of CPJ; and Mariane Pearl, author and wife of slain Wall Street Journal Reporter Daniel Pearl.
Add tags for "2009 Thomas J. Dodd Prize in International Justice & Human Rights.". Be the first.
Thomas J. Dodd Research Center.
<http://www.worldcat.org/oclc/451229530> # 2009 Thomas J. Dodd Prize in International Justice & Human Rights.
library:placeOfPublication <http://experiment.worldcat.org/entity/work/data/336424430#Place/storrs_conn> ; # Storrs, Conn.
schema:about <http://experiment.worldcat.org/entity/work/data/336424430#Organization/committee_to_protect_journalists> ; # Committee to Protect Journalists.
schema:about <http://experiment.worldcat.org/entity/work/data/336424430#Organization/thomas_j_dodd_research_center> ; # Thomas J. Dodd Research Center.
<http://experiment.worldcat.org/entity/work/data/336424430#Organization/committee_to_protect_journalists> # Committee to Protect Journalists.
<http://experiment.worldcat.org/entity/work/data/336424430#Organization/thomas_j_dodd_research_center> # Thomas J. Dodd Research Center.
schema:about <http://www.worldcat.org/oclc/451229530> ; # 2009 Thomas J. Dodd Prize in International Justice & Human Rights.
schema:location <http://experiment.worldcat.org/entity/work/data/336424430#Place/storrs_conn> ; # Storrs, Conn.


Feb 10, 2017, by Paola Trujillo.
When we were children the only limits were our dreams and imagination. Before we realized it, we were all grown up and making our lives fit other people's expectations.
You can build your career to satisfy others, or you can take charge of your life and build a legacy.
Before I got to Nearsoft, I worked at a good, yet traditional company. They had an incredible growth rate. I was very diligent in shaping my life to fit their expectations. I wanted to be a professional, such and others expected of me.
When I arrived at Nearsoft, I was asked to come up with a way to calculate salaries. I very confidently came up with a proposal starting with the company's financial goals. Little did I realize that I was basing my work on my legacy corporate bias.
I was flabbergasted and confused.
I obviously had a huge learning curve ahead of me.
In that moment, everything I knew about key performance indicators shattered to smithereens in my mind. I realized then that this place was different—placing the individual first was actually good for business! In fact, being a source of happiness for its employees was even part of the company's vision.
… placing the individual ahead of the company is actually good for business!
I felt terrified. I consulted with a businessman I trusted. I also spoke with Nearsoft's founders, and with every Nearsoftian who would talk to me.
I got into a period of unlearning in order to learn new stuff.
I read a lot to better understand the culture. I devoured books such as "Peak: How Great Companies Get Their Mojo from Maslow", by Chip Conley, and "The Alliance: Managing Talent in the Networked Age" by Reid Hoffman.
Then I took on a new approach: I had to do it as a team process. Little by little we created Building My Legacy, a blueprint for Nearsoftians to design their own growth plan.
Each of us is unique, with personal aspirations, goals, and desires. Through this new approach, we transformed the way people can define their own growth objectives.
Exploring what makes you happy and what you see in your ideal future.
Finding your personal growth mission and connecting it with Nearsoft's.
Designing your own transformation plan.
Transcend to the next level, one step closer to your dream.
Although it seems easy on paper, it's not.
We are used to being told what to do and not to be asked what we want to do with our lives. Facing our future and the possibilities ahead of us paralyzes us. Whatever we do will take us closer or further away from our dreams. Realizing that we are responsible for this can be overwhelming, but worth the shot.
Many new Nearsoftians join the tribe with a specific job in mind. However, as time passes they realize that their abilities can be used to impact the whole company.
Take, for example, the career missions of Nearsoftians Isaac Lopez and Artemisa Yescas.
Isaac Lopez originally joined Nearsoft as a software developer.
He did great and soon showed himself as the goto guy for various technologies and software development practices. It didn't take him long to gain the respect of everybody at Nearsoft.
They even started to call him Sensei.
Through the Building My Legacy program Isaac discovered that he could make an even bigger impact at Nearsoft.
He started by taking the leadership of the Nearsoft Academy program. The program already existed and we graduated a few people a year from it. But, it lacked direction and discipline. Isaac revamped it and we went from graduating 10% of each class to 80%, all accepted into client teams.
But he didn't stop there. He also brought more structure and discipline to our Training program. Before, people asked for support to take a course or go to a conference and we didn't have a consistent way of responding.
Isaac called for a Leadership Team to figure out what to do with our Training budget. Today, requests for training go through faster, our Training budget is put to better use, reaches more people, and people are happier with the process and its results.
Artemisa Yescas started out as a Manual Tester at Nearsoft.
She became well integrated into the culture and was well liked by the folks here. She also became a mentor and resource to other teams throughout Nearsoft.
Through the Building My Legacy Program she figured out how that she could do more. She could become an outspoken evangelist for Agile Testing, beyond Nearsoft.
Nearsoft is more than making a living, it is a way to live my life!
So, she became a Certified Agile Tester (CAT). In fact, she's even certified to approve others for certification as CAT.
Next she created a workshop to certify other Nearsoftians. This made it possible for them to take the next step into their own career paths. As a side-effect, she has impacted the software development cycle throughout Nearsoft.
She has even helped to "Agilize" the service areas at Nearsoft.
Her legacy has brought a new high in productivity and teamwork.
Creating this model has changed everything for me. I have evolved to a position where I can help people discover a greater vision of themselves.
Being aware of the great impact they can have allows them to transcend beyond a 9-to-5 job.
We are continuously challenging ourselves to improve, and reach our highest inspirations as individuals and as a team.
We all yearn to be able to choose which way we want to grow as we make our contribution, and to be part of something bigger than just ourselves.
Written by Paola Trujillo, on Feb 10, 2017, in Agile, Culture, Design, Workplace Democracy.


text:
And our winners for 2019 are….
What the judges said…
The winner for this category was chosen because she demonstrates resilience, passion, self-sacrifice and determination to rise above challenges both personally and professionally. She inspires and motivates her team to see the sunshine at the end of the tunnel.
The winner for this category was chosen because she is a visionary who gives selflessly to her community, industry and colleagues. Overcoming many challenges, not just in her business life but also personally, she is a worthy recipient of this award; who will give not only to the CBWC but to the wider Cairns community.
The winner for this category was chosen because she exhibits determination and spirit. She continues to inspire and motivate others to achieve their goals; and is a shining star for men & women, young & old. Her savvy and creative business mind is what nailed it for this award winner.
The winner for this category was chosen because of her determination, bravery and vision for the future. She has accomplished so much personally and professionally in her young life; and her dynamic combination of vulnerability and strength enables this young woman to stand out as a champion.
The winner for this category has displayed a true entrepreneurial spirit. She has taken a passion for helping others to a whole new level. She teaches women to ask for what they want, rather than accepting things as they present. Her compassion and empathy shines through every single aspect of her work. She has clearly defined goals and her finger firmly on the pulse of her multi-faceted business.
The winner for this category is a determined and confident woman who has taken her failures and past experiences and turned them into valuable lessons to learn and grow from. She is a proactive leader and a do-er; and in the judges words, 'She does it!
The winner for this category is a woman who gives her time to not just one, but multiple organisations that directly contribute to bringing together the Cairns community for the greater good. Her willingness to put her hand up for any challenge is inspiring, and we believe that she will use this recognition to inspire others and further spread the message of bettering the world for future generations.


The new 620 Trident is one of Outer Reef most waited models, presenting a new range of modern looking explorer yachts from the North American company targeting European customers. Launching in mid 2016 and designed by Setzer from Stuart, Florida the Outer Reef 620 Trident is a modern explorer type yacht with comfortable accommodation solutions in all areas. It is clear that with the 620 Trident Outer Reef is looking to expand its European client base. Interesting to know that the Outer Reef 620 Trident was born as a 53 feet project in 2014, expanding in length to the current over eighteen meters to achieve customers requests for a large owners midships stateroom. The Outer Reef 620 Trident will be powered by Cummins 550hp with ZF Zeus pods type propulsion which deliver a top speed of 23 knots.


Biohazards need to be eliminated, cleaned, decontaminated, transported and correctly disposed of to ensure the health and safety of all involved. Biohazards consist of bacteria and viruses that pose health threats to family, pals or staff members who may come in contact with biohazards. Blood-borne diseases, bacteria, and viruses found in blood and other bodily fluids can live outside the body for days and often weeks. HIV & Hepatitis are the most commonly understood threats that can be contracted from biohazards. When a distressing accident, suicide, criminal activity, death happens in Hialeah or you have biohazards on your home or business it must be cleaned up and decontaminated properly.
In your home, in the workplace, as well as in an automobile, boat or airplane, safeguarding yourself and others from exposure to biohazards and blood-borne pathogens must be your primary concern and priority. When blood does not get cleaned up properly the biomaterial starts to decompose, a strong odor emanates and flies are drawn in to the scene that spread out pollutes to other areas that must also be found and cleaned up. We will check the residential or commercial property and determine all areas that have actually been exposed to biohazards and get rid of, decontaminate, and clean up whatever to alleviate the health risk.
We are an expert biohazard clean-up business in Hialeah 33017 licensed by the Department of Public Health that will make sure the cleanup is done properly to lower future danger on infection to others. Our expertly experienced crew will clean, sanitize, and dispose of all blood and biohazard materials so you can progress and be ensured that you, your household, pals or coworkers are safe.
Can My Worker Cleanup Biohazards In Hialeah 33017?
Business must follow rigorous guidelines which mandates that staff members have proper and comprehensive training before they are placed in a position to tidy up or deal with any incident that might expose.
What Does A Criminal Activity Scene Clean-up in Florida Business Do?
We sanitize, tidy and eliminate all biohazards that exist. Cleanup is needed from top to bottom; ceiling, walls, furnishings, personal items and even lights. Each tiny area and square inch in a space that is exposed to biohazards is thought about a possible source of infection and must be correctly decontaminated and cleaned up.
There is more than exactly what meets the eye and our service technicians are trained to determine, clean and decontaminate the tiniest droplets of biohazard material. A thumbnail spot on the floor or carpet might mean a two-foot diameter bloodstain on the sub flooring under it or on the floorboard. A small droplet of blood on the top of a dresser drawer or counter top is an indication of more blood inside the drawer or beneath the handle. With time biohazards start to cause a smell and should be found, decontaminated and cleaned to be sure that the environment is safe, safe and secure and ready for use.
Each and every cleanup is unique and positions various difficulties. In most hoarded houses we discover biohazards and conditions that present a biological issue that needs to be dealt with so no one gets ill. We are a Biohazard company that concentrates on Hoarding removal when there is a great deal of particles, which in most cases consists of biohazards.
When residents of a home can not freely move about the home, must climb up over debris to obtain from one room to another, or are not able to utilize the bathroom, bathe, or safety store and cook food in the kitchen area it poses a significant risk to their health and wellness. We typically get calls from a relative or pal of somebody who has fallen or became ill due to the excess debris in the house. Extreme hoarding is also a fire hazard and a risk to the local and their neighbors.
We securely navigate risks such as rodent feces, human waste, bed bugs, fleas, animals, mold, asbestos, and years of dirt and dust hidden underneath, in or behind the debris. Rodents and their droppings position the risk of Hantavirus, a breathing disease that can be deadly if not attended to properly.
What Do Forensic Crime Scene Cleaners In Hialeah 33017 Do?
Our focus as forensic cleaners is to clean up biohazards such as blood, bodily fluids and the contaminated surroundings at a crime scene, or any other injury scene. An enormously unsafe job for those who don't have the training, protective gear and specific equipment to handle biohazard material. We use our extensive knowledge to thoroughly clean-up a trauma scene with careful attention to detail and large experience together with the legal authorizations needed to get rid of any biohazards. When we're done, you can be positive the area is completely cleaned up, disinfected, and safe to use.
Who Utilizes Forensic Cleansing And Death/Trauma Cleaning Services In Hialeah?
Many people handling a scenario that requires forensic cleaning and remediation do not realize what it takes to completely clean and bring back an area where there has been a distressing event. When we hear about your specific circumstance, we will discuss to you what our procedure would be to effectuate an appropriate clean-up for your specific scenario. With our in-depth knowledge and wealth of experience, we make sure the location is free of biohazards and safe to use offering you a new beginning and assurance.
Providing Forensic Cleaning service throughout all Florida has a group of specialist forensic cleansing specialists readily available 24/7 to assist in the remediation and repair of your home or business. Our professionals are passionate about improving the biohazard removal industry standards and providing a quick and inclusive service to all regions in full. Our specialists are the market leaders in forensic cleaning, offering blood and injury clean ups, death and suicide cleansing, sewage leak repair, meth laboratory decontamination and biohazard remediation. Making use of innovative biohazard cleaning procedures coupled with state-of-the-art equipment, we offer our clients with an exceptional service by the implementation of tried and tested, job-specific removal treatments for a prompt, trustworthy and effective biohazard remediation and forensic cleaning service. When it pertains to biohazard remediation services, we are committed to providing our professionals with ongoing training, affording our clients with a service where security and professionalism is second to none.
We utilize discreetly marked cars to maintain confidentiality and will record the work we perform in a comprehensive report supplied at the completion of each and every job for your insurance company. We value the nature of our job is frequently an outcome of an extremely distressing and distressing period, and offer a considerate and compassionate service, preserving our respectable requirement of service by offering guidance and support through these trying times. We believe our clients are worthy of the highest quality of service supplied with and respect. By selecting us, we will supply you with the assurance that trained and competent remediation technicians are performing our service.