text:
The man in my basement
Published 2004 by Serpent"s Tail in London .
Statement Walter Mosley.
Download The man in my basement
The Man in My Basement by Walter Mosley was one of those books. To say I devoured this book would be an understatement, but I simply devoured this book. I started it on a whim in the afternoon and I resisted putting it down to go to sleep, that is how engrossing this book is. /5(). Buy a cheap copy of The Man in My Basement book by Walter Mosley. Hailed as a masterpiece-the finest work yet by an American novelist of the first rank-The Man in My Basement tells the story of Charles Blakey, a young black man Free shipping over $/5(6). The Man in My Basement by Walter Mosley was one of those books. To say I devoured this book would be an understatement, but I simply devoured this book. I started it on a whim in the afternoon and I resisted putting it down to go to sleep, that is how engrossing this book is/5. Unlock This Study Guide Now. Start your hour free trial to unlock this The Man in My Basement study guide and get instant access to the following. Summary; You'll also get access to more than.
Original and compelling, The Man in My Basement is a literary feat from "one of the country's best writers." (Denver Post) © Walter Mosley (P) Time Warner AudioBooks, a division of the Time Warner Book Group. The Man in My Basement Walter Mosley, Little, Brown & Co. pp. ISBN Summary Charles Blakey is a young black man whose life is slowly crumbling. His parents are dead, he can't find a job, he drinks too much, and his friends have begun to desert him. the man in my basement walter mosley book review fiction review little brown and company. Music. best music of The 20 Best Metal Albums of Adrien Begrand. 01 May nona : Popmatters Staff. The Man in My Basement, by Walter Mosley (Serpent's Tail, £). Mosley is primarily known as the writer of the Easy Rawlins detective series, .
The Man in My Basement audiobook, by Walter Mosley Hailed as a masterpiece-the finest work yet by an American novelist of the first rank-this is the mysterious story of a young black man who agrees to an unusual bargain to save the home that has belonged to his family for man at Charles Blakey's door has a proposition almost 3/5. "The Man in the Basement" is the second episode of the sixth season of the American television drama series Homeland, and the 62nd episode overall. It premiered on Showtime on Janu Plot. Carrie (Claire Danes) and Reda (Patrick Sabongui) consult Sekou (J. Mallory Directed by: Keith Gordon. I didn't care. That white man was a fool. We didnt take in white boarders in my part of the Sag Harbor. I was trying to understand why the real-estate agent Teddy Odett would even refer a white man to my neighborhood. "I want to rent your basement /5(22). I Hate the Man in My Basement () Plot. Showing all 1 items Jump to: Summaries (1) Summaries. After his wife's death, Claude struggles to appear normal while living with a Secret. —Dustin.
subtlety of white racism
Stories of the Old South
The white divel, or, The tragedy of Paulo Giordano Ursini, Duke of Brachiano
Title Page & Contents for U.S. Congressional Serial Set, Senate Document Nos. 19 & 20, 103d Congress, 2d Session.
Cognitive structures in human story
HIV/AIDSinformation for children
Mushroom growing
Nanosecond pulse techniques
Donovan Pasha and some people of Egypt
The 2007-2012 Outlook for Parts and Accessories for Commercial Cooking and Food-Warming Equipment in the United States
Essays presented to Amy G. Stock, professor of English, Rajasthan University, 1961-65.
The Sheridans.
Golden country
Standard Commodity Classification Manual


When March arrives, many Chicagoans prepare to observe Casimir Pulaski Day (March 5), a city holiday that commemorates a Polish-born cavalry officer in the Revolutionary War who went on to inspire a Sufjan Stevens song. In recent years, local brewery Goose Island has also tried to add an (admittedly, entirely made-up) holiday to the calendar by celebrating 312 Day on March 12 (or 3/12) with a slew of events that involve plenty of the beer that shares its name with first three digits of many Chicago phone numbers.
This year, Goose Island is turning 312 Day into an entire week of festivities and happenings, teaming with local nightlife website Do312 to curate eight days of activities that celebrate Chicago culture. The week kicks off on March 5 with a screening of quintessential Chicago movie Ferris Bueller's Day Off and continues with free pizza parties, cheap concerts, free museum admission and discounted Bulls tickets (all accompanied by complimentary Goose Island beer).
In honor of 312 Day, Goose Island will give away a select number of tickets to Second City's Dream Freaks Fall from Space on March 8, free hot dogs at Superdawg on March 9 and vouchers for free museum days at the Chicago History Museum, Shedd Aquarium and Museum of Contemporary Art on March 11. The festivities culminate on March 12 at House of Vans, with performances from Detroit rapper Danny Brown and local hip-hop star Joey Purp.
Check out the complete list of 312 Week programming below—if you find something you want to attend, you can enter to win tickets or RSVP for entry here.


text:
\section{Introduction}

The invention of the electronic transistor has laid the cornerstone of the
information age. With the development of quantum information technology, the
research and fabrication of optical transistor have become an important
branch. In general, the fabrication of optical transistors is based on optical
non-reciprocity\cite{[1],[2]}. Early, optical non-reciprocity has been
achieved in optical waveguides \cite{[3],[4],[5],[6]} or optical nonlinear
system \cite{[7],[8],[9]} by breaking the time-reversal symmetry. Recently,
several alternative schemes based on different principles are proposed, such
as photoacoustic effects \cite{[10],[11]}, indirect interband photon
transitions \cite{[12],[13],[14]}, space symmetric fracture structures
\cite{[15],[16],[17],[18]}, moving systems \cite{[19],[10]} and parity
time-symmetric structures \cite{[21],[22],[23]}. In addition, for the
potential applications in photonic quantum information processing, the
abilities to be integrated on a chip, non-local control at long-range
\cite{[24],[25],[26]} and operated on a single-photon level
\cite{[27],[28],[29]} are desirable features for the realization of
nonreciprocal all-photonic devices in the future. With the rapid development
of new micro integrable devices, optomechanical systems have shown enormous
potential for application in quantum information processing
\cite{[30],[31],[32]}. It has previously been shown that optomechanical
systems can be used to induce nonreciprocal effects for light
\cite{[33],[34],[35]}. Multi-mode optomechanical systems have drawn much
attention recently. Numbers of novel and interesting phenomena are noted, such
as high-fidelity quantum state transfer \cite{[36],[37],[38]}, enhanced
quantum nonlinearities \cite{[39],[40]}, phonon lasing \cite{[41],[42]},
coherent perfect absorption (CPA) \cite{[43],[44]} and so on. Especially, the
CPA could view as an inverse process of laser \cite{[45],[46]}, which provides
a new mechanism in optomechanical system for controlling optical non
reciprocity. Currently, most of investigations on atom-assisted optomechanical
cavities coupled with independent cold atoms driven by quantum cavity modes
and classical coherent control fields \cite{[47],[48],[49],[50]}. However,
Rydberg atoms, coupled by dipole-dipole interactions (DDI), have recently been
shown to be efficient nonlinear media in cavities in order to achieve
additional control freedom of optomechanical interactions and applications
\cite{[51],[52],[53]}. An essential blockade effect based upon DDI prevents
the excitation of more than one atom into a Rydberg state within a macroscopic
volume of several micrometers in radius \cite{[54],[55],[56],[57]}. Meanwhile,
based on dipole blockade, many promising proposals have been put forward for
manipulating quantum states of atoms and photons \cite{[58],[59],[60]},
simulating many-body quantum systems \cite{[61],[62]}, generating reliable
single photons \cite{[63],[64],[65]}, and revealing some novel behaviors in
EIT \cite{[66],[67],[68],[69],[70],[71],[72]}, etc.

In this paper, we study the optical response of a symmetric double-cavity
optomechanical system assisted by Rydberg atomic ensemble (Superatom SA) with
a movable mirror of perfect reflection and driven by two coupling fields and
two probe fields. The transition from ground state to excited state of an atom
is coupled by a cavity mode, and the transition from the excited state to
Rydberg state is coupled by a classical control field. There are vdW
interactions among the Rydberg atoms in the cavity or from outside the system.
So the optical response of the hybrid system can be manipulated by controling
the Rydberg excitation of SA.

We focus especially on the transmission and reflection properties of two side
weak probe fields, by switching on and off the external control. In case (I),
we find a controlled optical diode effect, that photons only pass through the
system from one direction. In case (II), we get a controlled photon rectifier,
which can change the propagation direction of the photons, instead. In case
(III) and (IV), we achieve the function of amplification in two different
ways. The first one is based on coherent perfect synthesis (CPS), and the
other is owing to FWM effect of atom-assisted opto-mechanical system. We
expect that the all-optical controlled transistor (the optical correspondence
of classical electrical transistor), which sets controller, rectification,
amplification and other functions as a whole, could be explored to build new
tunable photonic devices on quantum information networks.

\begin{figure}[th]
\centering\includegraphics[width=8.0
cm]{Fig1.eps}\caption{Schematic diagram of the hybrid system double
opto-mechanical cavity coupled with Rydberg atomic ensembles. (a$_{1}$) and
(a$_{2}$) show a Rydberg superatom both couple with the left cavity and the
other superatom outside. (b$_{1}$) and (b$_{2}$) show that the double-cavity
decouple with atomic ensembles swiching off the external control.
\label{Fig1
\end{figure}

\section{Theoretical Model}

We consider a hybrid optomechanical system with one movable mirror (membrane
oscillator) of perfect reflection inserted between two fixed mirrors of
partial transmission, which form two machanical-coupled Fabry--Perot cavities.
And in the left cavity there are $n_{sa}$ atoms with a Rydberg state
$|r\rangle$ [see Fig. \ref{Fig1}]. We describe the two optical modes in the
left or right cavity, respectively, by annihilation (creation) operators
$c_{l}$ $(c_{l}^{\dagger})$ or $c_{r}$ $(c_{r}^{\dagger})$. And the only
mechanical mode is described by $b$ $(b^{\dagger})$. These annihilation and
creation operators $\hat{O}=\{c_{l},c_{r},b\}$ are bosons and satisfy the
commutation relation $\left[  \hat{O}_{i},\hat{O}_{j}^{\dagger}\right]
=\delta_{i,j}$ $(i,j=c_{l},c_{r},b)$. Two probe (coupling) fields are used to
drive the double-cavity system from either left or right fixed mirrors with
their amplitudes denoted by $\varepsilon_{l}=$\textbf{ }$\sqrt{2\kappa\wp
_{L}/(\hbar\omega_{p})}$ and $\varepsilon_{r}=$\textbf{ }$\sqrt{2\kappa\wp
_{R}/(\hbar\omega_{p})}$\textbf{ (}$\varepsilon_{cL}=$\textbf{ }$\sqrt
{2\kappa\wp_{cL}/(\hbar\omega_{c})}$ and \textbf{ }$\varepsilon_{cR}=$\textbf{
}$\sqrt{2\kappa\wp_{cR}/(\hbar\omega_{c})}$\textbf{)}. Here $\kappa$ is the
decay rate of both cavity modes, $\wp_{L},\wp_{R},\wp_{cL}$ and $\wp_{cR}$ are
the relevant field powers, $\omega_{p}$ ($\omega_{c}$) is the probe (coupling)
field frequency. The membrane oscillator has an eigen frequency $\omega_{m}$
and a decay rate $\gamma_{m}$ and thus exhibits a mechanical quality factor
$Q$ = $\gamma_{m}/\omega_{m}$. Two identical optical cavities of lengths $L$
and frequencies $\omega_{0}$ are got when the membrane oscillator is at its
equilibrium position in the absence of external excitation. And in the left
Fabry--Perot cavity, cavity field $c_{l}$ also drives an ensemble of $n_{sa}$
cold atoms into the three level ladder configuration together with an external
control field with frequency $\omega_{r}$. Levels $|g\rangle$, $|e\rangle$,
and $|r\rangle$ \ correspond, respectively, to $5S_{1/2}|F=1\rangle$,
$5P_{3/2}|F=2\rangle$ and $60S_{1/2}|F=1\rangle$ of $^{87}$Rb atoms.

\bigskip Then the total Hamiltonian of our hybrid system in the rotating-wave
frame can be written as
\[
H=H_{c}+H_{m}+H_{cp}+H_{mc}+H_{a}+H_{ac}+H_{vdW},
\]
where the first four terms describe the two free optical cavities, the free
movable mirror, and the optomechanical interaction, respectively, with the
following expressions

\begin{align}
H_{c} &  =\mathcal{\hbar}\Delta_{c}(c_{l}^{\dagger}c_{l}+c_{r}^{\dagger
c_{r}),\text{ \ }H_{m}=\mathcal{\hbar}\omega_{m}b^{\dag}b,\nonumber\\
H_{cp} &  =i\mathcal{\hbar}\varepsilon_{cL}(c_{l}^{\dagger}-c_{l
)+i\mathcal{\hbar}(\varepsilon_{l}c_{l}^{\dagger}e^{-i\delta t}-\varepsilon
_{l}^{\ast}c_{l}e^{i\delta t})\nonumber\\
&  \mathcal{+}i\mathcal{\hbar}\varepsilon_{cR}(c_{r}^{\dagger}-c_{r
)+i\mathcal{\hbar}(\varepsilon_{cR}c_{r}^{\dagger}e^{i\theta}e^{-i\delta
t}-\varepsilon_{cR}^{\ast}c_{r}e^{i\theta}e^{i\delta t}),\nonumber\\
H_{mc} &  =\mathcal{\hbar}g_{0}(c_{r}^{\dagger}c_{r}-c_{l}^{\dagger
c_{l})(b^{\dag}+b),\label{Eq1
\end{align}

where we define $\Delta_{c}=\omega_{0}-\omega_{m}$ the detuning between cavity
modes and coupling fields, $\delta=\omega_{p}-\omega_{c}$ the detuning between
probe fields and coulping fields, $\theta$ the relative phase between left-
and right-side probe fields, $g_{0}=\frac{\omega_{0}}{L}\sqrt{\hbar
/(2m\omega_{m})}$ the hybrid coupling constant between mechanical and optical
modes ($m$ quality of the oscillator, $V$ the volume of the cavity, and
$\varepsilon_{0}$) the vacuum dielectric constant. The free atomic ensemble
and the atom-light interaction Hamiltonian are $H_{a}=\mathcal{\hbar
\sum\limits_{i=1}^{n_{sa}}(\omega_{eg}\sigma_{ee}^{(i)}+\omega_{rg}\sigma
_{rr}^{(i)})$ and $H_{ac}=-\hbar\sum\limits_{i=1}^{n_{sa}}(\Omega_{r
\sigma_{re}^{(i)}e^{-i\omega_{r}t}+g_{ac}c_{l}\sigma_{eg}^{(i)}+H.C.)$,
respectively, with coupling constant between atomic ensemble and left cavity
mode $g_{ac}=\wp_{ge}\sqrt{\omega_{c}/(2\hbar V\varepsilon_{0})}$ and atomic
transition dipole moment $\wp_{ge}$. We will focus on the new optomechanical
features resulting from DDI as expressed by a vdW potentia

\[
H_{vdW}=\mathcal{\hbar}\sum\limits_{i<j}^{n_{sa}}\frac{C_{6}}{R_{ij}^{6
}\sigma_{rr}^{(i)}\sigma_{rr}^{(j)}.
\]
Here $n_{sa}$ is the atomic number in the microvolume such that only one atom
can be excited to the state $|r\rangle$, with $C_{6}$ denoting the vdW
coefficient. And $R_{ij}$ is the interatomic distance between the $i$th and
$j$th atoms in the SA.

Considering dissipation and quantum noise of the system, we can get the
following Heisenberg-Langevin equations:
\begin{widetext
\begin{align}
\dot{b} &  =-i\omega_{m}b-ig_{0}[c_{l}^{\dag}c_{l}-c_{r}^{\dag}c_{r
]-\frac{\gamma_{m}}{2}b+\sqrt{\gamma_{m}}b^{in},\nonumber\\
\dot{c}_{l} &  =-[\kappa+i\Delta_{c}-ig_{0}(b^{\dag}+b)]c_{l}+\varepsilon
_{cL}+\varepsilon_{l}e^{i\delta t}-ig_{ac}\sqrt{n_{sa}}\tilde{P}+\sqrt
{2\kappa}c_{l}^{in},\nonumber\\
\dot{c}_{r} &  =-[\kappa+i\Delta_{c}+ig_{0}(b^{\dag}+b)]c_{r}+\varepsilon
_{cR}+\varepsilon_{r}e^{i\theta}e^{-i\delta t}+\sqrt{2\kappa}c_{r
^{in},\nonumber\\
\dot{P} &  =-[i\Delta_{1}+\gamma_{e}]\hat{P}+i\Omega_{r}^{\ast}\hat{S
+ig_{ac}\tilde{c}_{l}+f_{1}(t),\nonumber\\
\dot{S} &  =-[i\Delta_{2}+i\left\langle V\right\rangle +\gamma_{r}]\hat
{S}+i\Omega_{r}\hat{P}+f_{2}(t),\label{Eq2
\end{align}
\end{widetext}
where $\hat{\sigma}_{ge}=\sum_{i=1}^{n_{sa}}\hat{\sigma}_{ge}^{(i)\ }=\hat
{P}e^{-i\omega_{c}t}$ ($\hat{\sigma}_{gr}=\sum_{i=1}^{n_{sa}}\hat{\sigma
_{gr}^{(i)\ }=\hat{S}e^{-i(\omega_{c}+\omega_{r})t}$) denotes the collective
polarization (spin) operator of atoms, with $\tilde{c}_{l}=c_{l}e^{i\omega
_{c}t}$ and $\tilde{P}=\hat{P}e^{-i\omega_{c}t}$. $\kappa,$ $\gamma_{m},$
$\gamma_{e}$ and $\gamma_{r}$ correspond to the decay rate of cavities,
oscillator, excited state $\left\vert e\right\rangle $ and that of Rydberg
state $\left\vert r\right\rangle $, respectively. $\left\langle V\right\rangle
=$ $\sum_{i=1}^{n_{sa}}v^{(i)}$ is the mean value of total vdW potential in a
superatom with $v^{(i)}$ the vdW potential of single atom. $b^{in}$ being the
thermal noise on the movable (zero mean value), and $c_{l}^{in}(c_{r}^{in})$
is the input quantum vacuum noise from the left (right) cavity with zero mean
value. Here we are more interested in the mean optical response of the
optomechanical system to probe field in the presence of both strong driving
fields. In this regard, we can safely ignore the quantum fluctuations of all
relevant operators and use the factorization assumption $b\langle c_{i
\rangle=\langle b\rangle\langle c_{i}\rangle$ to generate the mean values in
steady state. In order to solve Eqs. (2), we write each operator as the sum of
its mean value and its small fluctuation $\hat{O_{1}}=\langle\hat{O_{1
}\rangle+\delta\hat{O_{1}},\hat{O_{1}}=\{b,c_{l},c_{r},\hat{P},\hat{S}\},$
when both coupling fields are sufficiently strong. Then we get two series of
equations about steady-state or fluctuation of operators, respectively,

\begin{widetext
\begin{align}
\dot{b_{s}} &  =-i\omega_{m}b_{s}-ig_{0}[c_{ls}^{\ast}c_{ls}-c_{rs}^{\ast
}c_{rs}]-\frac{\gamma_{m}}{2}b_{s},\nonumber\\
\dot{c}_{ls} &  =-[\kappa+i\Delta_{c}-ig_{0}(b_{s}^{\ast}+b_{s})]c_{ls
+\varepsilon_{c_{L}}-ig_{ac}\sqrt{n_{sa}}\tilde{P},\nonumber\\
\dot{c}_{rs} &  =-[\kappa+i\Delta_{c}+ig_{0}(b_{s}^{\ast}+b_{s})]c_{rs
+\varepsilon_{c_{R}},\nonumber\\
\dot{P_{s}} &  =-[i\Delta_{1}+\gamma_{e}]P_{s}+i\Omega_{r}^{\ast}S_{s
+ig_{ac}\sqrt{n_{sa}}\tilde{c}_{ls},\nonumber\\
\dot{S_{s}} &  =-[i\Delta_{2}+i\left\langle V\right\rangle +\gamma_{r
]S_{s}+i\Omega_{r}P_{s},\label{Eq3
\end{align}
\end{widetext}

\begin{widetext}
\begin{align}
\delta\dot{b} &  =-i\omega_{m}\delta b-ig_{0}[c_{ls}^{\ast}\delta c_{l
+c_{ls}\delta c_{l}^{\dag}-c_{rs}^{\ast}\delta c_{r}-c_{rs}\delta c_{r}^{\dag
}]-\frac{\gamma_{m}}{2}\delta b+\sqrt{\gamma_{m}}b^{in},\nonumber\\
\delta\dot{c_{l}} &  =-[\kappa+i\tilde{\Delta_{c}}]\delta c_{l}-ig_{0
c_{ls}(\delta b^{\dag}+\delta b)+\varepsilon_{l}e^{-i\delta t}-ig_{ac
\sqrt{n_{sa}}\delta\tilde{P}+\sqrt{2\kappa}c_{l}^{in},\nonumber\\
\delta\dot{c_{r}} &  =-[\kappa+i\tilde{\Delta_{c}}]\delta c_{r}+ig_{0
c_{rs}(\delta b^{\dag}+\delta b)+\varepsilon_{R}e^{i\theta}e^{-i\delta t
\sqrt{2\kappa}c_{r}^{in},\nonumber\\
\delta\hat{P} &  =-[i\Delta_{1}+\gamma_{e}]\delta\hat{P}+i\Omega_{r}^{\ast
}\delta\hat{S}+ig_{ac}\sqrt{n_{sa}}\delta\tilde{c}_{l}+f_{1}(t),\nonumber\\
\delta\hat{S} &  =-[i\Delta_{2}+iV^{s}+\gamma_{r}]\delta\hat{S}+i\Omega
_{r}\delta\hat{P}+f_{2}(t),\label{Eq3
\end{align}
\end{widetext}
where the effective detuning is $\tilde{\Delta_{c}}=\Delta_{c}-g_{o}b_{s}$ and
$c_{is}=\langle c_{i}\rangle$ ($i=l,r$) is the steady state average of cavities.

\bigskip It is difficult to solve Eqs. (3) and (4) directly. So we first solve
the atomic part of the equations above, taking the part of the cavities as a
constant. In general, the optical response of the Rydberg atomic ensembles are
affected by the vdW interactions. And in our system, the vdW shift reads,
\begin{align}
V^{s}  &  =\left\langle \sum_{j}^{n_{sa}}\frac{C_{6}}{R_{j}^{6}}\sigma
_{rr}^{(j)}\right\rangle .\nonumber
\end{align}

Note that $V^{s}$ tends to infinite for one Rydberg excitation $\left\langle
\hat{\sigma}_{rr}\right\rangle =1$ or vanishing for zero Rydberg excitation
$\left\langle \hat{\sigma}_{rr}\right\rangle =0$. Then Eqs.~(3) cannot be
solved straightforwardly owing to the dipole-dipole correlation between
different atoms in the rigid blockade regime. Therefore we choose to define
the $n_{sa}$ cold atoms as a single SA whose volume $V_{sa}$ of radius
$R_{sa}$ is slightly smaller than the blockade volume $V_{b}$ of radius
$R_{b}=\sqrt[6]{\frac{C_{6}\left\vert \gamma_{e}+i\Delta_{1}\right\vert
}{\left\vert \Omega_{r}\right\vert ^{2}}}$ \cite{[67]}. For a very weak cavity
field, this SA can be described by three symmetric states containing at most
one Rydberg excitation $\left\vert G\right\rangle =\left\vert g\right\rangle
^{\otimes n_{sa}},\left\vert E^{(1)}\right\rangle =\frac{1}{\sqrt{n_{sa}}
\sum_{i=1}^{n_{sa}}\left\vert g_{1},g_{2},...,e_{i},...,g_{n_{sa
}\right\rangle ,$ and $\left\vert R^{(1)}\right\rangle =\frac{1}{\sqrt{n_{sa
}}\sum_{i=1}^{n_{sa}}\left\vert g_{1},g_{2},...,r_{i},...,g_{n_{sa
}\right\rangle $ [21]. According to the Superatom theory model, the Rydberg
excitation $\Sigma_{RR}$ in an SA will determine the effective SA
polarization, which is
\[
P_{s}=\langle P_{2}\rangle\Sigma_{RR}+\langle P_{3L}\rangle\lbrack
1-\Sigma_{RR}].
\]
Here $\langle P_{2}\rangle$ is the polarization of a two level atomic system
and $\langle P_{3L}\rangle$ is that of a three level Ladder type system.
\begin{align}
\left\langle P_{2}\right\rangle  &  =\frac{ig_{ac}\sqrt{n_{sa}}\tilde{c}_{ls
}{i\Delta_{1}+\gamma_{e}},\\
\left\langle P_{3L}\right\rangle  &  =\frac{ig_{ac}\sqrt{n_{sa}}(i\Delta
_{2}+iV+\gamma_{r})\tilde{c}_{ls}}{(i\Delta_{1}+\gamma_{e})(i\Delta
_{2}+iV+\gamma_{r})+\Omega_{r}^{\ast}\Omega_{r}},\nonumber
\end{align}
And we get
\begin{widetext
\[
\Sigma_{RR}=\frac{g_{ac}^{2}n_{sa}\Omega_{r}^{\ast}\Omega_{r}\tilde{c
_{ls}^{\ast}\tilde{c}_{ls}}{g_{ac}^{2}n_{sa}\Omega_{c}^{\ast}\Omega_{c
\tilde{c}_{ls}^{\ast}\tilde{c}_{ls}+(\gamma_{e}\gamma_{r}-\Delta_{1}\Delta
_{2}+\Omega_{r}^{\ast}\Omega_{r})^{2}+\gamma_{e}^{2}\Delta_{2}^{2}+\gamma
_{r}^{2}\Delta_{1}^{2}},
\]
\end{widetext}
with $\sum_{GG}+\sum_{RR}\approx1$, neglecting the excitation of the
intermediate states of SAs.

We can get the steay-state solutions,
\begin{align}
b_{s}  &  =\frac{ig_{0}(\tilde{c}^{\ast}_{ls}\tilde{c}_{ls}-c^{\ast
_{rs}c_{rs})}{i\Delta_{m}+\frac{\gamma_{m}}{2}},\nonumber\\
\tilde{c}_{ls}  &  =\frac{\varepsilon_{cL}-ig_{ac}\sqrt{n_{SA}}P_{s}
{[\kappa+i\Delta_{c}-ig_{0}(b_{s}^{\ast}+b_{s})]},\nonumber\\
c_{rs}  &  =\frac{\varepsilon_{cR}}{[\kappa+i\Delta_{c}+ig_{0}(b_{s}^{\ast
}+b_{s})]},
\end{align}

Considering the term of crossing vdW interactions $V^{c}$, if the Rydberg
excitation $\left\langle \hat{\sigma}_{r^{\prime}r^{\prime}}\right\rangle =1$,
$(i\Delta_{2}+iV^{s}+\gamma_{r})$ ( $\gg\Omega_{c}^{2}$) will tends to be
infinite, which causes $\left\langle P_{3L}\right\rangle \approx\left\langle
P_{2}\right\rangle $ Solving equations $\partial_{t}P_{s}=-(i\Delta_{1
+\gamma_{e})P_{s}+i\Omega_{r}^{\ast}S_{s}+ig_{ac}\sqrt{n_{SA}}\tilde{c
_{ls},\partial_{t}S_{s}=-(i\Delta_{2}+iV^{s}+\gamma_{r})S_{s}+i\Omega_{r
P_{s}$, we can get

Using the same method, from equation $\delta\dot{\hat{P}}=-(i\Delta_{1
+\gamma_{e})\delta\hat{P}+i\Omega_{r}^{\ast}\delta\hat{S}+ig_{ac}\sqrt{n_{sa
}\delta\tilde{c}_{l}+f_{1}(t)$ and $\delta\dot{\hat{S}}=-(i\Delta
_{2}+iV+\gamma_{r})\delta\hat{S}+i\Omega_{r}\delta\hat{P}+f_{2}(t),$ we can
get \ $\left\langle \delta\hat{P}\right\rangle =\left\langle \delta\hat{P
_{2}\right\rangle \sum_{RR}+\left\langle \delta\hat{P}_{3L}\right\rangle
(1-\sum_{RR}),$ where
\begin{align}
\left\langle \delta\hat{P}_{2}\right\rangle  &  =\frac{ig_{ac}\sqrt{n_{sa
}\left\langle \delta\tilde{c}_{l}\right\rangle }{i\Delta_{1}+\gamma_{e
},\nonumber\\
\left\langle \delta\hat{P}_{3L}\right\rangle  &  =\frac{ig_{ac}\sqrt{n_{sa
}(i\Delta_{2}+iV+\gamma_{r})\left\langle \delta\tilde{c}_{l}\right\rangle
}{(i\Delta_{1}+\gamma_{e})(i\Delta_{2}+iV+\gamma_{r})+\Omega_{r}^{\ast
\Omega_{r}}.
\end{align}

Then keeping only the linear terms of fluctuation operators and moving into an
interaction picture by introducing: $\delta\hat{O}\rightarrow\delta\hat
{O}e^{-i\Delta_{i}t},\delta\hat{O}^{in}\rightarrow\delta\hat{O}^{in
e^{-i\Delta_{i}t},\hat{O}=\left\{  b,c_{l},c_{r},\hat{P},\hat{S}\right\}
,\Delta_{i}=\left\{  \Delta_{1},\Delta_{2}+V,\tilde{\Delta_{c}},\omega
_{m}\right\}  ,$we obtain the linearized quantum Langevin equations

\begin{align}
\delta\dot{b} &  =-ig_{0}(c_{ls}^{\ast}\delta c_{l}-c_{rs}^{\ast}\delta
c_{r})-\frac{\gamma_{m}}{2}\delta b+\sqrt{\gamma_{m}}b^{in},\nonumber\\
\delta\dot{c}_{l} &  =-\kappa\delta c_{l}-ig_{0}c_{ls}\delta b+\varepsilon
_{L}e^{ixt}-ig_{ac}\sqrt{n_{sa}}\delta\hat{P}e^{-i\omega_{c}t}+\sqrt{2\kappa
}c_{l}^{in},\nonumber\\
\delta\dot{c}_{r} &  =-\kappa\delta c_{r}+ig_{0}c_{rs}\delta b+\varepsilon
_{R}e^{i\theta}e^{-ixt}\sqrt{2\kappa}c_{r}^{in},\label{Eq6
\end{align}
where $x=\delta-\omega_{m}.$ And expectations of fluctuation operators satisfy
the equations
\begin{align}
\left\langle \delta\dot{b}\right\rangle  &  =-ig_{0}(c_{ls}^{\ast}\left\langle
\delta c_{l}\right\rangle -c_{rs}^{\ast}\left\langle \delta c_{r}\right\rangle
)-\frac{\gamma_{m}}{2}\left\langle \delta b\right\rangle ,\nonumber\\
\left\langle \delta\dot{c}_{l}\right\rangle  &  =-\kappa\left\langle \delta
c_{l}\right\rangle -ig_{0}c_{ls}\left\langle \delta b\right\rangle
+\varepsilon_{L}e^{-ixt}-ig_{ac}\sqrt{n_{sa}}\left\langle \delta\hat
{P}\right\rangle e^{-i\omega_{c}t},\nonumber\\
\left\langle \delta\dot{c}_{r}\right\rangle  &  =-\kappa\left\langle \delta
c_{r}\right\rangle +ig_{0}c_{rs}\left\langle \delta b\right\rangle
+\varepsilon_{R}e^{i\theta}e^{-ixt},\label{Eq7
\end{align}
where the osillating terms can be removed if steady-state solutions of Eqs.~7
are assumed to be form: $\langle\delta s\rangle=\delta s_{+}e^{-ixt}+\delta
s_{-}e^{ixt}$ with $s=b,c_{l},c_{r}$. Then it is easy to attain the following
results,
\begin{align}
\delta b_{+} &  =\frac{inGg_{AC}^{\prime}\varepsilon_{r}e^{i\theta}-iG^{\ast
}\kappa^{\prime}\varepsilon_{l}}{\gamma_{m}^{\prime}\kappa^{\prime
g_{AC}^{\prime}+G^{2}\kappa^{\prime}+G^{2}n^{2}g_{AC}^{\prime}},\nonumber\\
\delta c_{l+} &  =\frac{Gn\varepsilon_{r}e^{i\theta t}+[G^{2}n^{2}+\gamma
_{m}^{\prime}\kappa^{\prime}]\varepsilon_{l}}{\gamma_{m}^{\prime
\kappa^{\prime}g_{AC}^{\prime}+G^{2}\kappa^{\prime}+G^{2}n^{2}g_{AC}^{\prime
},\\
\delta c_{r+} &  =\frac{[\gamma_{m}^{\prime}g_{AC}^{\prime}+G^{2
]\varepsilon_{r}e^{i\theta}+G^{2}n\varepsilon_{l}}{\gamma_{m}^{\prime
\kappa^{\prime}g_{AC}^{\prime}+G^{2}\kappa^{\prime}+G^{2}n^{2}g_{AC}^{\prime
},\nonumber\label{Eq8
\end{align}
where we set $G=g_{0}c_{ls}$ as the effective optomechanical coupling rate and
$n^{2}=|c_{rs}/c_{ls}|^{2}$ as the photon number ratio of the two cavity
modes, with $\kappa^{\prime}=ix-\kappa,\gamma_{m}^{\prime}=ix-\frac{\gamma
_{m}}{2},g_{AC}^{\prime}=ix-\kappa-\lambda,\lambda=\frac{g_{ac}^{2}n_{sa
}{i\Delta_{1}+\gamma_{e}}\sum_{RR}+\frac{g_{ac}^{2}n_{sa}(i\Delta
_{2}+iV+\gamma_{r})}{(i\Delta_{1}+\gamma_{e})(i\Delta_{2}+iV+\gamma
_{r})+\Omega_{r}^{\ast}\Omega_{r}}[1-\sum_{RR}].$ In deriving Eqs.\symbol{126
(8), we have also assumed that $c_{ls,rs}$ is real-valued without loss of generality.

It is possible to determine the output fields $\varepsilon_{outl}$ and
$\varepsilon_{outr}$ leaving from both cavities with the following
input-output relation \cite{[44]

\begin{align}
\varepsilon_{outl}+\varepsilon_{l}e^{-ixt} &  =2\kappa\langle\delta
c_{l}\rangle,\nonumber\\
\varepsilon_{outr}+\varepsilon_{r}e^{i\theta}e^{-ixt} &  =2\kappa\langle\delta
c_{r}\rangle,\nonumber
\end{align}
where the oscillating terms can be removed if we set $\varepsilon
_{outl}=\varepsilon_{outl+}e^{-ixt}+\varepsilon_{outl-}e^{ixt}$ and
$\varepsilon_{outr}=\varepsilon_{outr+}e^{-ixt}+\varepsilon_{outr-}e^{ixt}.$
Note that the output components $\varepsilon_{outl+}$ and $\varepsilon
_{outr+}$ have the same Stokes frequency $\omega_{p}$ as the input probe
fields $\varepsilon_{l}$ and $\varepsilon_{r}$ while the output components
$\varepsilon_{outl-}$ and $\varepsilon_{outr-}$ are generated at the
anti-Stokes frequency $2\omega_{c}-\omega_{p}$ in a nonlinear four wave mixing
process of optomechanical interaction. Then with Eq.s (8) we can obtain
\begin{align}
\varepsilon_{outl+} &  =2\kappa\delta c_{l+}-\varepsilon_{l},\nonumber\\
\varepsilon_{outr+} &  =2\kappa\delta c_{r+}-\varepsilon_{r}e^{i\theta
},\nonumber
\end{align}
oscillating at the Stokes frequency of our special interest. So it is easy to
find
\begin{widetext
\begin{align}
\varepsilon_{outl+} &  =\frac{2\kappa nG^{2}\varepsilon_{r}e^{i\theta
+[\gamma_{m}^{\prime}\kappa(2\kappa-g_{AC}^{\prime})+G^{2}(2\kappa
n^{2}-\kappa^{\prime}-n^{2}g_{AC}^{\prime})]\varepsilon_{l}}{\gamma
_{m}^{\prime}\kappa g_{AC}^{\prime}+n^{2}g_{AC}^{\prime}G^{2}+\kappa^{\prime
}G^{2}}\nonumber\\
\varepsilon_{outr+} &  =\frac{2\kappa nG^{2}\varepsilon_{l}-[(ix-3\kappa
)(\gamma_{m}^{\prime}g_{AC}^{\prime}+G^{2})+n^{2}g_{AC}^{\prime
G^{2}]\varepsilon_{r}e^{i\theta}}{\gamma_{m}^{\prime}\kappa g_{AC}^{\prime
}+n^{2}g_{AC}^{\prime}G^{2}+\kappa^{\prime}G^{2}}.\nonumber
\end{align}
\end{widetext}

\section{Results and discussion}

In this section, we numerically simulate the optical response of the hybrid
system, which features controlled non-reciprocity and potential use for
optical diode and transistor. The transmission coefficient $T_{l
=|\varepsilon_{outr+}/\varepsilon_{l}|^{2}$ ($T_{r}=|\varepsilon
_{outl+}/\varepsilon_{r}|^{2}$) and reflection coefficient $R_{l
=|\varepsilon_{outl+}/\varepsilon_{l}|^{2}$ ($R_{r}=|\varepsilon
_{outr+}/\varepsilon_{r}|^{2}$) are important. And they are both the functions
of the probe frequency $x/\kappa$. In the following discussion, we only
consider the two extremes of the system: (a) optical reciprocity and (b)
optical non-reciprocity. The case (a) corresponds to decoupling between atomic
ensemble and left cavity [see Fig.2(a)]. Under the condition, we get
reflection coefficient of cavities,
\begin{widetext
\begin{align}
R_{l} &  =|\frac{\varepsilon_{outl+}}{\varepsilon_{l}}|^{2}=|\frac{2\kappa
n^{2}G^{2}e^{i\theta}+[\gamma_{m}^{\prime}\kappa\kappa^{\prime}+2\kappa
G^{2}-(n^{2}+1)\kappa^{\prime}G^{2}]\varepsilon_{l}/\varepsilon_{r}
{\gamma_{m}^{\prime}\kappa\kappa^{\prime}+(n^{2}+1)\kappa^{\prime}G^{2}
|^{2},\nonumber\\
R_{r} &  =|\frac{\varepsilon_{outr+}}{\varepsilon_{r}}|^{2}=|\frac{2\kappa
n^{2}G^{2}+[\gamma_{m}^{\prime}\kappa\kappa^{\prime}+2\kappa G^{2
-(n^{2}+1)\kappa^{\prime}G^{2}]\varepsilon_{r}e^{i\theta}/\varepsilon_{l
}{\gamma_{m}^{\prime}\kappa\kappa^{\prime}+(n^{2}+1)\kappa^{\prime}G^{2}
|^{2}.
\end{align}
\end{widetext}
The system satisfies the space reversal symmetry, because $R_{l}=R_{r}$. On
the contrary, in the case (b), the coupling between the atomic ensemble and
the cavity break the space reversal symmetry of the system. Base on the two
cases above, three functions of an optical transistor can be achieved in the
hybrid system under different conditions. We focus on the achievement of these
functions, but the external control from case (a) to case (b) will be
discussed at the end of the letter.

\begin{figure}[th]
\centering\includegraphics[width=8cm]{Fig2.eps}\caption{Standardization energy
of the output probe field $R_{r}=|\varepsilon_{outR+}/\varepsilon_{R}|^{2}$
(reflection coefficient of left cavity, blue) and $R_{l}=|\varepsilon
_{outL+}/\varepsilon_{L}|^{2}$ (reflection coefficient of right cavity, red
circle ) as the function of $x/\kappa$, $(a)$ switching off the external
control (coupled with atoms) and $(b)$ switching on that (decoupled with
atoms), with $G=\kappa,n=1$ and $\theta=\pi$.
\label{Fig2
\end{figure}

\subsection{Controlled Photon Diode ($\gamma=2\kappa,\theta=n\pi$ and
$\varepsilon_{l}=\varepsilon_{r}\neq0$)}

The first function achieved with the system is controlled optical diode, which
allows photons pass through only in one direction. It is coherent perfect
absorption effect (CPA) that is the basis for implementing of this function
above. The parameters should be set as $\gamma=2\kappa,\theta=n\pi$ and
$\varepsilon_{l}=\varepsilon_{r}\neq0$. CPA will occur at $x_{\pm}=\pm
\sqrt{(n^{2}+1)G^{2}-\kappa^{2}}$ \cite{[43],[44]}. However, the coupling
between atoms and the left cavity changes the CPA conditions.

In this case, Fig.~3 display the transmission coefficient of left $T_{l}$ and
right side $T_{r}$ of the hybrid system, with different $G$. It is obvious to
find the transmissions of the two sides are absolutely the same $T_{l}=T_{r}$
[see Fig.~3($a_{1}$ and $b_{1}$)], because the atomic ensemble is decoupled
with the left cavity, switching off the external control. Photons can flow
through the hybrid system in different directions, symmetrically. And then,
the optical symmetry of system will be broken ($T_{l}\neq T_{r}$),when
switching on the control causes the atoms to couple with the cavity system. In
particular, $T_{l}\simeq1$ [Fig.\symbol{126}3$(a_{2})$] in the range
$-4<x/\kappa<4$ because $g_{AC}^{\prime}>>\kappa^{\prime}$ owing to enough
large $n_{sa}^{2}$ and $|\kappa|\simeq|3\kappa-ix|<<g_{AC}^{\prime}$,
\begin{equation}
T_{l}\approx\left\vert \frac{\lbrack(3\kappa-ix)(\gamma_{m}^{\prime
g_{AC}^{\prime}+G^{2})+n^{2}g_{AC}^{\prime}G^{2}]}{\gamma_{m}^{\prime}\kappa
g_{AC}^{\prime}+n^{2}g_{AC}^{\prime}G^{2}+\kappa^{\prime}G^{2}}\right\vert
^{2}\approx1
\end{equation}
but $T_{r}$ also can be equal to zero [Fig.\symbol{126}3$(b_{2})$].
Furthermore, $T_{l}=1$ and $T_{r}=0$ means that we get the photon diode
framework which is an controlled unidirectional transmission device [see
Fig.\symbol{126}3($c_{1,2}$)].

\begin{figure}[th]
\centering\includegraphics[width=8cm]{Fig3.eps}\caption{Transmission
coefficient of left side $T_{l}$ (in $a_{1}(b_{1})$) and right side $T_{r}$
(in $a_{2}(b_{2})$) of the hybrid system vs. detuning $x/\kappa$ and $G$,
without (with) external control, when $\gamma=2\kappa$ and $\theta=n\pi$ with
$n=1$. $c_{1}$ and $c_{2}$ are the functional sketch maps.
\label{Fig3
\end{figure}

\subsection{Controlled Photon Rectifier ($\gamma_{m}\longrightarrow0$,
$\theta=n\pi$, $\varepsilon_{l}\neq0$ and $\varepsilon_{r}=0$)}

Aiming to achieve optical rectification, we set $\gamma_{m}=0.1\kappa$,
$\theta=n\pi$, $\varepsilon_{l}\neq0$ and $\varepsilon_{r}=0$ (without input
field of right side). Coherent perfect transmission effect (CPT) is the basis
for implementing of this function.

In this case, if there is no coupling between atoms and cavity, we can find
$R_{l}=0$ [Fig.\symbol{126}4($a_{1}$)] and $T_{l}=1$ [Fig.\symbol{126
4($b_{1}$)] near the range $-0.5<x<0.5$ with $G>\kappa$. Photons flow through
the hybrid system perfectly without reflection [Fig.\symbol{126}4($c_{1}$)].
This perfect transmission is due to quantum coherence of the
double-opto-mechanical system, which can be controlled by phase $\theta$.
However, the optical properties of the system have changed, once there are
effective coupling between atoms and cavity system. We find
\begin{align}
T_{l}  &  \approx\left\vert \frac{2\kappa nG^{2}}{\gamma_{m}^{\prime}\kappa
g_{AC}^{\prime}+n^{2}g_{AC}^{\prime}G^{2}+\kappa^{\prime}G^{2}}\right\vert
^{2}\approx0,\\
R_{l}  &  \approx\left\vert \frac{\lbrack(ix-3\kappa)(\gamma_{m}^{\prime
}g_{AC}^{\prime}+G^{2})+n^{2}g_{AC}^{\prime}G^{2}]}{\gamma_{m}^{\prime}\kappa
g_{AC}^{\prime}+n^{2}g_{AC}^{\prime}G^{2}+\kappa^{\prime}G^{2}}\right\vert
^{2}\approx1,\nonumber
\end{align}
[Fig.\symbol{126}4 ($a_{2}$ and $b_{2}$)]. Photons are reflected back from the
hybrid system around the same range with $2\kappa<<g_{AC}^{\prime}$. It will
be an framework for photon rectifier, if the manipulation has been achieved to
control the direction of photon flow effectively.

\begin{figure}[th]
\centering\includegraphics[width=8cm]{Fig4.eps}\caption{Reflection coefficient
of left side $R_{l}$ (in $a_{1}(a_{2})$) and Transmission coefficient of right
side $T_{r}$ (in $b_{1}(b_{2})$) of the hybrid system vs. detuning $x/\kappa$
and $G$, without (with) external control, when $\gamma=2\kappa$, $\gamma_{m}
\longrightarrow0$ and $\theta=n\pi$ with $\varepsilon_{l}\neq0, \varepsilon
_{r}=0$. $c_{1}$ and $c_{2}$ are the functional sketch maps only with left
side input probe field $\varepsilon_{L}$
\label{Fig4
\end{figure}

\subsection{External control}

The purpose of external control is to allow the atomic ensemble in the cavity
to be decoupled from the left cavity, controllably. We can achieve it in a
variety of ways, . Firstly, we cosider the control switching on/off the
coupling field $\Omega_{r}$, without the long range Rydberg vdW blockade
effect between two Rydberg atomic ensembles. We set $\Delta_{1}\gg g_{ac}$
with $\kappa\approx\Delta_{2}\approx0,$ which is typical Rydberg-EIT resonance
with large single photon detuning condition. Under the case, $\Omega_{r}\neq0$
is the necessary condition for effective coulping between cavity system and
Rydberg atomic ensembles, because large single photon detuning $\Delta_{1}$
will result in decoupling without $\Omega_{r}$. It is a kind of typical
coherent control, which is easy to do in the experiments. However, it is
obviously not a nonlocal or single photon level quantum control.

Secondly, we consider the control scheme that double-cavity optomechanical
system with the long range Rydberg vdW blockade effect between two Rydberg
atomic ensembles [see Fig.1(b)]. Similar to self-interactions, external vdW
interactions owing to Rydberg excitation of $\left\vert r^{\prime
}\right\rangle $ can lead to a large frequency shift of $\left\vert
r\right\rangle .$ Under the case, $i\Delta_{2}+iV+\gamma_{r}\longrightarrow
\infty$, $\left\langle P_{3L}\right\rangle \approx\left\langle P_{2
\right\rangle $ and we dispense with calculating $\sum_{RR}.$ With a large
single photon detuning $\Delta_{1}\gg g_{ac}$, the atoms are still decoupled
from the system. In other words, we can control the excitation of $\left\vert
r^{\prime}\right\rangle $ in the external Rydberg atomic ensembles to
manipulate the optical response of hybrid systems, which is a long range
nonlocal optical manipulation. Moreover, the control of Rydberg excitation of
the atomic ensemble outside the system can reach single-photon level.

\section{Conclusions}

\bigskip In summary, we have studied the optical response of the
Rydberg-atom-assisted double-cavity opto-mechanical system. We switch on and
off the Rydberg blockade effect to control whether the atomic ensembles
decouple with the left cavity. And whether the optical reciprocity of the
original symmetric system will be destroyed is controllable. We consider four
special cases depending on the choice of actual parameters: (I) with
$\theta=n\pi$ and $\varepsilon_{l}=\varepsilon_{r}\neq0$; (II) with
$\theta=n\pi$, $\gamma_{m}\longrightarrow0$, $\varepsilon_{l}\neq0$ and
$\varepsilon_{r}=0$.
In case (I), our numerical calculations show that atomic ensembles coupled
with single cavity break the optical reciprocity of the symmetric system.
Photons can only flow through the system in one direction, which is the
optical diode effect, switching on the control. In case (II), turning off the
input field of right side, the system has became an controlled photon
rectifier, which controls propagation behavior of the photons. In other words,
photons that should have transmitted have been reflected back absolutely.
Then, we propose two types of optical amplifier schemes with our hybrid
system. Though recent study on optical transistors have achieved great
progress, most of them have only achieved optical control. There are no the
optical correspondence of classical electric transistors which set controller,
rectification, amplification or other functions as a whole. Owing to the
blockcade effect between Rydberg atoms, it is great promising to make this
type of control to the single photon level. We hope our work can provide a new
way of thinking and a substantial role in promoting the study of optical
transistor and other all-optical devices.

\bigskip

redpajama_set_name: RedPajamaArXiv


Well looks like I got the next few days free!!
Thread: Well looks like I got the next few days free!!
What do normal folk get up to on a Saturday imo?
Go flying, naturally. Lunch in Le Touquet?
Many years ago my nephew did appear h, but it wasn't t.
Good Lord c ... the tricks one's memory plays. I would almost have put money on it. I distinctly remember, with vivid clarity, firing my old chap up your mum's 'aris but I don't suppose I could have.
We used to golf and then lunch in Le Touquet, then fly back to Biggin Hill. Happy days.
Did you, a? What was your means of conveyance? This is remarkable. I have been flying out of Biggin Hill since 1987. Our paths most certainly must have crossed.
You may well have done. Many, many did.
Don't have to see the parole officer this weekend?
boring lunches with other couples.


text:
Nurse and health visitor earnings down by 8% in real terms
Nurse and health visitor pay has reduced by 8% in real terms over the last eight years, according to an analysis of new figures from NHS Digital.
The average salary of a nurse or health visitor at the end of August 2010 was £29,599, increasing by 7% to £31,683 by the end of March 2018.
But the consumer price index – the index used to measure inflation – has increased by 16.9% in the same period of time, leaving average health visitor and community nurses just under £3,000 worse off over the eight years from August 2010.
Midwives were found to be even worse off, with earnings down by more than £4,000 when adjusted for inflation, down by 11.2% in real terms. The average salary of a midwife at the end of March 2018 was £31,671, up from £30,527 in August 2010 but still below the increase in inflation.
The analysis of the figures by union GMB comes weeks after a new pay deal was agreed with NHS nurses in England, with rises of between 6.5% and 22%, dependent on the nurse's current position within a given pay band.
GMB, the only union to vote against the pay deal, say that these figures show the new deal is 'not good enough', as many nurses will be receiving pay rises that are still below some projected increases in inflation.
Rachel Harrison, national office for the union, said: 'Inadequate pay is driving experienced professionals out of the NHS, contributing to worsening services for patients.
'NHS staff have endured nearly ten years of wage freezes and caps. Does Jeremy Hunt think he can buy them off with a further three years real terms pay cuts?'
Care home nurses: 'Let us vaccinate our residents without supervision'
Over half of staff absent for some care providers

redpajama_set_name: RedPajamaCommonCrawl


I'm going to BBNP & BBRSP next week and I'm unable to find some notes I had made about how long it normally takes to drive on some of the 4x4 roads. I have distances but not duration. The main question I have is whether or not 8-10 hours is enough time to drive down Black Gap Rd and Old Ore Rd in one day if we also want to stop and see Ernst Tinaja and Mariscal Mine? We currently have two days set aside for those two roads but if we can fit them in one day (without rushing or skipping sights), that will free up time for us to see some other areas on the other day.
If we take Black Gap north to south, which is quickest getting back to Glenn Springs: Black Gap south to north or River Road East to Glenn Springs? Or, if we can fit both roads in one day and we do Black Gap first, would we cut across on River Road East all the way from Black Gap to the connections for Old Ore Rd (Hot Springs & Park Rd)?
We're leaving the gas station in Study-Butte/Terlingua around 8:30am. If we're still on Old Ore Rd after the sun sets, I think that'll be okay. Also, is there a gas station in Rio Grande Village? I saw one on a map but don't remember reading about it or seeing that before.
Thanks for whatever tips y'all want to share!
That is an ambitious day, especially if you want to look around the mine and other places. I guess it's doable but I would try to get started earlier than 8:30 since it gets dark pretty early now. Even leave when it's still dark in the morning (say, around 7). If it were me, and starting from Study Butte, I would go down Glen Springs and Black Gap first, then take RR East around to RG Village and from there catch the main park road to Old Ore Road. If you only want to get back to Glenn Springs, I would take RR East to Glenn Springs Road rather than go back up Black Gap.
The only gas station in the park is at Panther Junction.
Thanks, BK. I get to RGV so infrequently that I didn't remember seeing it.
old ore road can take me five to 6 hours, there is a lot to see. also dagger flats auto trail is close to the north end of the o.o.r. and worth the short trip to see. for me it's more enjoyable to take my time and stop often. you'll want to spend some time at ernst tinaja. it's a short hike, to a very unique spot. river road east is usually in decent shape, much smoother and wider than the o.o.r.. you should be able to get from pavement to the mine in an hour and a half. when you go glenn springs check out glenn springs draw, it's a drainage that leads to the spring. there's a place to park close to head of the draw, you can get into the draw and follow it all the way to the spring then return to your truck on the road.
Jim is right. Do one loop or the other in order to do either justice. Two days of driving and exploring or way too much ground. OOR is a easily a day in of its self.
Thanks everyone! All of this feedback was very helpful! I'll keep it at two days then. Cheers & Merry Christmas!
I'm late to this but concur. Even if doable, not nearly as enjoyable.


I've pledged to read 100 for 2017. What about you?
In 2016, I read 132 books (that I remembered to record on Goodreads. I'm sure one or two slipped by somewhere). Many factors contributed to this high number, though yes, I do read quickly. I spent half of 2016 in New Zealand, traveling around, working in hotels and hostels, and then spent the other half of 2016 almost exclusively in planes, trains, and automobiles traveling from one US college campus to another. There's a lot of time to read when you're traveling. Especially with these handy-dandy phones and tablets that have so many e-reader apps, and the fact that I belong to at least 4 libraries with e-book programs.
Pre-New Zealand, I was strictly a real book girl, preferably purchased from a brick-and-mortar independent bookstore. Post-New Zealand, I'm still a staunch indie supporter (THAT will never change), but I now thank my lucky stars that e-books were invented, because how would I otherwise carry the selection of books with me that I must have wherever I go?
That said, nothing could replace the feel of a real book: the smooth paper, perhaps ending in a deckle edge that's fun to fan; the weight of it in your lap or falling on your face if you're reading in bed; the ability to underline, make a note, dog-ear a page (yes, I'm one of those horrible people) as you read along; and most importantly, the way you proudly announce to the world the book you're currently enjoying.
Of course, there are some books whose covers I might not want to proudly display to the world, and so I'm doubly grateful to read my bodice-rippers in the privacy of my app, thank you very much.
Two of the other reasons my numbers are high for 2016, is that 1) I did a lot of rereading and 2) I focused on series. Actually, I combined the two by rereading the entire IN DEATH series by JD Robb (aka Nora Roberts), and things sort of snowballed from there. When you're in the world of a series, I believe you can read faster, as you're already immersed in the characters and setting and so your brain doesn't have to take the same time to adjust. That's just my theory, but it seems to work for me. I breeze through them at a frantic pace, and then have to adjust to the whiplash when it's all over.
Clearly I'll still sneak the occasional novel (actually, the first book I read this year was Jayne Ann Krentz's most recent, WHEN ALL THE GIRLS HAVE GONE), but I'd like to try to broaden my reading horizons by picking up more non-fiction this year. The title of this blog is Wildly Read, because I can at least claim to be wildly, if not widely, read, but I'd like to be a little more wide, strictly in the book sense, this year.
Luckily, I'm off to a great start! Before 2016 had ended, I had started Jared Diamond's GUNS, GERMS, AND STEEL: THE FATES OF HUMAN SOCIETIES, and my partner and I are reading out loud together IVORY VIKINGS: THE MYSTERY OF THE MOST FAMOUS CHESSMEN IN THE WORLD AND THE WOMAN WHO MADE THEM by Nancy Marie Brown. My partner is reading COLLAPSE: HOW SOCIETIES CHOOSE TO FAIL OR SUCCEED, another Diamond book, so we'll switch when we're done. I can't say enough about how fun it is to share the excitement of books with your significant other, so I'll write that one smug line and let it go.
Back on the road again for work, and I stopped into the Raleigh airport's 2nd Edition Booksellers, a wonderful second-hand shop right in terminal 2, near the D gates. While there, I picked up THE DEAD BEAT: LOST SOULS, LUCKY STIFFS, AND THE PERVERSE PLEASURES OF OBITUARIES by Marilyn Johnson. This is my first Marilyn Johnson book, but it got me thinking about other other non-fiction female writers, especially when I realized IVORY VIKINGS was also written by a woman.
I've been a long-time fan of Sarah Vowell, who writes delightful political treatises (no, that's not an oxymoron) that bring the past and present together while swirling around a central subject like Lafayette or Hawaii.
Mary Roach is another favorite, having read STIFF: THE CURIOUS LIVES OF HUMAN CADAVERS a few years ago, and I've wanted to pick up more of her work since. I'm not sure if I'll be reading her latest, GRUNT: THE CURIOUS SCIENCE OF HUMANS AT WAR, as war is not my favorite subject, but that's also partly the point of reading non-fiction this year: to gain a fresh perspective on a topic I thought I knew something about.
So, I've got politics/history covered, I've got hard sciences covered, and now that I've discovered Marilyn Johnson, I seem to have social science covered as well. One of the reasons I purchased THE DEAD BEAT is that in looking Ms. Johnson up on Goodreads, I saw that she had two other books about topics I adore: librarians and archaeologists. Having worked on digs and in libraries, you can imagine my excitement level.
What non-fiction books do YOU recommend for 2017?
Writers of color, female or transgender, from a country other than the US are all a bonus, but ultimately I'm looking for engaging non-fiction on any and every topic. Ready, set, go!
Posted on January 16, 2017 January 16, 2017 by WildlyLivedPosted in Genre: adult book, Genre: non-fiction, Series: book review, UncategorizedTagged book recommendation, book recommendations, books, Genre: non-fiction, jared diamond, marilyn johnson, mary roach, sarah vowell.


text:
package uk.ac.ox.krr.logmap2.division;

import java.util.ArrayList;
import java.util.Collections;
import java.util.HashSet;
import java.util.List;
import java.util.Random;
import java.util.Set;

import org.semanticweb.owlapi.model.IRI;
import org.semanticweb.owlapi.model.OWLOntology;
import org.semanticweb.owlapi.model.OWLOntologyCreationException;

import uk.ac.ox.krr.logmap2.io.LogOutput;
import uk.ac.ox.krr.logmap2.lexicon.LexicalUtilities;
import uk.ac.ox.krr.logmap2.statistics.StatisticsTimeMappings;

/**
 *
 * This class aims at predicting the number of partitions (i.e. matching tasks) given a desired module size.
 * It may be the case the desired module size is not possible or very expensive to get
 * (large number or partitions)
 *
 * @author ernesto
 * Created on 6 Mar 2018
 *
 */
public class BasicDivisionPredictor extends AbstractDivision implements OntologyAlignmentDivision{

	int required_module_size;

	int max_number_tasks=500;

	int predicted_number_tasks=-1;

	boolean strict_requirement=false;

	/**
	 * Predicts number of matching tasks to (approximately) obtain modules of the given size.
	 * If "strict_requirement"=true then both source and target ontology modules must be smaller than required_module_size
	 * If "strict_requirement"=false then one of the  module (source or target) is required to be smaller than required_module_size
	 * @param required_module_size
	 * @param strict_requirement
	 */
	public BasicDivisionPredictor(int required_module_size, boolean strict_requirement){
		this.required_module_size=required_module_size;
		this.strict_requirement = strict_requirement;
	}

	/**
	 * Default is 1000
	 * @param max_number_tasks
	 */
	public void setMaxNumbertasks(int max_number_tasks){
		this.max_number_tasks=max_number_tasks;
	}

	@Override
	public List<MatchingTask> createPartitionedMatchingTasks(OWLOntology source, OWLOntology target)
			throws OWLOntologyCreationException, Exception {

		StatisticsTimeMappings.setInitGlobalTime();

		List<MatchingTask> tasks=null;

		predicted_number_tasks=-1;

		createTaskSizesList();

		for (int n_tasks : number_tasks_list){
			BasicDivision partitioning = new BasicDivision(n_tasks);

			//We only require one
			partitioning.setNumTask2Outout(1);

			tasks = partitioning.createPartitionedMatchingTasks(source, target);

			if ((tasks.get(0).getSignatureSourceOntology().size()<=required_module_size && tasks.get(0).getSignatureTargetOntology().size()<=required_module_size) ||
				(!strict_requirement && (tasks.get(0).getSignatureSourceOntology().size()<=required_module_size || tasks.get(0).getSignatureTargetOntology().size()<=required_module_size))){

				predicted_number_tasks = n_tasks;

				LogOutput.print("\tPREDICTED NUMBER TASKS: " + predicted_number_tasks);

				break;
			}

		}

		if (predicted_number_tasks < 0){
			System.err.println("The required module size is too small for the maximun number of tasks set to '" + max_number_tasks + "'. The current maximum number of tasks leads to modules of size (approximately): " +
						tasks.get(0).getSignatureSourceOntology().size() + " in the source ontoology, and "+ tasks.get(0).getSignatureTargetOntology().size() + " in the target ontology.");
			tasks =  new ArrayList<MatchingTask>();

		}
		else{
			//Return partitioning for prediction
			BasicDivision partitioning = new BasicDivision(predicted_number_tasks);

			//Return tasks
			tasks= partitioning.createPartitionedMatchingTasks(source, target);

		}

		total_time = StatisticsTimeMappings.getTotalRunningTime();
		LogOutput.print("Total time (s): " + total_time);

		return tasks;
	}

	List<Integer> number_tasks_list=new ArrayList<Integer>();

	/**
	 * @return
	 */
	private void createTaskSizesList() {
		number_tasks_list.add(1);
		number_tasks_list.add(2);
		number_tasks_list.add(5);
		number_tasks_list.add(10);
		number_tasks_list.add(20);
		number_tasks_list.add(30);
		int size = 50;
		int i=1;

		while ((i*size)<max_number_tasks){
			number_tasks_list.add(i*size);
			i++;
		}

	}

	@Override
	public List<MatchingTask> createPartitionedMatchingTasks(String sourceIRIStr, String targetIRIStr)
			throws OWLOntologyCreationException, Exception {
		return createPartitionedMatchingTasks(loadOWLOntology(sourceIRIStr), loadOWLOntology(targetIRIStr));
	}

}

redpajama_set_name: RedPajamaGithub


text:
BMW secures 'millions of semiconductors'
Stellantis intensifies semiconductor and software push
GKN Automotive launches eDrive research centre in UK
The Renault Zoe has become the third car in history to be awarded a zero-star rating by Euro NCAP, following the latest round of safety testing by the organisation.
Renault Group's Dacia Spring also scored poorly, achieving just one star out of a possible five. Testing saw other carmakers achieve the industry-leading five-star standard for their latest models.
The Renault Zoe was one of the first mainstream mass-produced battery-electric vehicles (BEVs) launched, having gone on sale in 2013. The carmaker offered an upgraded model in 2017. However, some safety elements were removed and this, coupled with increasing standards for Euro NCAP testing in the intervening years, saw the model achieve the unwanted stain on its reputation.
Zero-star
Only Fiat has ever achieved a zero-star rating for a vehicle, doing so twice with the Punto and Panda in 2017 and 2018, respectively. These models had not been updated in several years as the carmaker failed to invest in them, leading Euro NCAP to retest and ascertain just how safe they were compared to modern standards.
The Renault Zoe saw a facelift launched four years ago. However, according to Euro NCAP, at this time, certain safety equipment was downgraded. Specifically, seat-mounted head and thorax side-protection airbags were removed, and thorax-only units were added.
In the frontal offset crash, the results were rated as 'poor', specifically due to weak protection for the chest area of the driver-side dummy. But it was Euro NCAP's severe side-pole test that revealed the most drastic results, with the driver's head directly impacting the intruding pole.
Thatcham Research, which undertakes testing for Euro NCAP, highlighted that the red body parts seen on the dummy in the image below show a potential threat of serious injury and threat to life in the event of an accident.
Source: Thatcham Research
The test replicates real-world impacts involving a vehicle travelling sideways into rigid roadside objects such as trees or poles. According to Thatcham Research, 33% of these impact types are classified as fatal or serious accidents. As the forces on the car are so localised, the pole can end up deep inside the passenger compartment.
'It is a serious concern to see results like this in 2021, especially from a carmaker which has previously performed well in Euro NCAP testing,' said Matthew Avery, Thatcham Research's chief research strategy officer and Euro NCAP board member. 'Renault was the first to achieve the full five-star rating in 2001, in part because it was also the first to include a combined head and thorax airbag in the Laguna 2. Although this was a new and revolutionary safety measure at the time, today this airbag is available on most modern cars.
'Unfortunately, a conscious decision has been made to remove the head protection from this vital passive-safety feature, by the brand that pioneered the use of it. As a result, the safety of occupants within the vehicle has been severely impacted.'
The Renault Zoe also lacks active-safety technology commonly fitted as standard in most new vehicles, such as lane-departure warnings and standard-fit autonomous emergency braking (AEB). This led to a 14% score in the Safety Assist category, 61% lower than the average (75%) achieved by carmakers in the same category this year.
The Dacia Spring fared slightly better with a one-star rating. In its review, Euro NCAP stated: 'The Spring's performance in crash tests is downright problematic, with a high risk of life-threatening injuries for the driver's chest and rear passenger's head in frontal crash tests and marginal chest protection in a side impact. The mediocre crash performance and poor crash-avoidance technology result in a one-star rating.'
Unlike the Fiat Punto and Panda, the Zoe is unlikely to be pulled from sale due to the zero-star rating. Indeed, Fiat stopped sales of the Punto prior to the results being made public. The Zoe is an important car for Renault, as its leading BEV model and one which is synonymous with electric technology and pioneering spirit at the carmaker.
The Spring, meanwhile, is poised to lead a low-cost BEV attack on the automotive market for Renault Group. It is heavily based on the Chinese-made Renault City K-ZE, itself a derivative of the Renault Kwid, sold in India and Brazil for several years.
'Renault was once synonymous with safety. The Laguna was the first car to get five stars, back in 2001,' commented Michiel van Ratingen, president of Euro NCAP. 'But these disappointing results for the ZOE and the Dacia Spring show that safety has now become collateral damage in the group's transition to electric cars. Not only do these cars fail to offer any appreciable active safety as standard, but their occupant protection is also worse than any vehicle we have seen in many years. It is cynical to offer the consumer an affordable green car if it comes at the price of higher injury risk in the event of an accident.'
Renault response
In response to an Autovista24 request, Renault stated: 'We take note of the results published by Euro NCAP following specific tests on Zoe E-Tech Electric according to its new protocol implemented in 2020.
'First of all, Renault reaffirms that Zoe E-Tech Electric is a safe vehicle, which complies with all regulatory safety standards. These standards are constantly evolving and are becoming more stringent in all domains, especially in safety. Renault therefore continually improves its offer in order to comply with the regulations applicable where its vehicles are sold. Zoe was launched in 2013 and received five stars with the Euro NCAP protocol at that time. The Euro NCAP protocol has, since 2013, undergone five changes. With the same equipment, a model can lose up to two stars in each protocol change.
'The evolution of the current Zoe was decided in 2017, adapting the passive safety equipment to real accidentology and updating the car with state-of-the-art ADAS equipment such as advanced emergency braking with pedestrian and cyclist detection, lane-departure alert and lane-keeping assist, using a radar and a camera.'
Companies Vehicle Manufacturers
Schaeffler announces 'painful' closure of ICE-based plant
VW says French regulator backs Europcar takeover
Stagnation takes grip in France's electric used-car market
Vulcan Energy secures lithium deal with Renault


"No one's irreplaceable." Advice I have been given and that I've offered to many a leader who have struggled with personnel decisions. While I've always offered it with the hope of providing reassurance or encouragement for making a difficult move, I must admit that the last time I heard the expression, it didn't sit right. Each of us is irreplaceable because we were made uniquely by God. Each of us has a unique role to play. We shouldn't overplay it, but we shouldn't underplay it either. As a leader, am I aware of the true value of those I lead? Does their contribution stop with my needs or do I strive to understand their irreplaceability as God does? Perhaps my lens, is what needs the most replacing.


He's been linked to a few films, but now James Gray ("Two Lovers," "The Yards") looks set to make "Low Life" his next project and has scored three stars to join him reports Deadline.
Marion Cotillard plays a woman attempting to immigrate from Poland. While sailing to Ellis Island, her sister grows deathly ill and she is forced to trade sexual favors for medicine and food to keep her sister alive.
Warned to keep quiet and laden with immigration papers that deem her a woman with bad morals, she falls prey to a charming sleazebag (Joaquin Phoenix), who persuades her to turn tricks in New York.
Jeremy Renner is close to signing on to play the sleazebag's cousin, a magician who sweeps the young woman off her feet and is her best chance to escape the nightmarish life.
Greg Shapiro is producing. Wild Bunch will likely finance and shooting kicks off next year.


text:
London Palladium – teatr rozrywkowy znajdujący się przy Argyll Street w dzielnicy Westminster w Londynie. Z powodu wielu nagrań telewizyjnych, które tam zrealizowano, oraz gwiazd muzyki, które występowały w tym miejscu, London Palladium uznawany jest za jeden z najsłynniejszych teatrów Londynu i Wielkiej Brytanii.

Budynek
London Palladium został zbudowany z inicjatywy przedsiębiorcy Waltera Gibbonsa, aby rywalizować z Hippodrome Edwarda Mossa i Coliseum Theatre Oswalda Stolla. Budynek teatru pochodzi z 1910 roku, chociaż jego fasada powstała w XIX wieku. Przed powstaniem Palladium na jego miejscu znajdował się drewniany budynek o nazwie "Corinthian Bazaar", w którym mieściła się ptaszarnia, która miała na celu przyciągnięcie klientów z pobliskiego "Pantheon Bazaar" (obecnie należącego do Marks & Spencer) przy Oxford Street. Został on przez przebudowany przez Fredricka Henglera, syna linoskoczka i służył jako siedziba cyrku "Henglers Grand Cirque". W budynku znajdował się także "National Skating Palace" – lodowisko z prawdziwym lodem. Jednakże lodowisko zbankrutowało i Palladium po raz kolejny uległo przebudowie, tym razem według projektu Franka Matchama, słynnego architekta teatrów, który zaprojektował również Coliseum Theatre.

Najbliżej położoną stacją metra londyńskiego jest Oxford Circus. Na widowni znajdują się 2302 miejsca (w tym 20 stojących). W budynku umieszczono tablice pamiątkowe upamiętniające Lewa Grade'a i Frankiego Vaughana. Palladium miał własny system telefoniczny, dzięki któremu abonenci lóż mogli dzwonić między sobą. Posiadał także scenę obrotową.

Teatr zachował wiele ze swojego oryginalnego wystroju i we wrześniu 1960 roku został włączony do rejestru zabytków Wielkiej Brytanii.

Historia

Okres przedwojenny i wojenny
Teatr otwarto 26 grudnia 1910 roku. Początkowo nosił nazwę "The Palladium" i był miejscem przedstawień rewiowych. Wiązało się to zwłaszcza z corocznymi spektaklami Royal Variety Performances, których wiele (również pierwsze w historii) odbyły się w tym miejscu. Od 1928 roku był zarządzany przez George'a Blacka, który kontrolował Moss Empires, przedsiębiorstwo posiadające wiele brytyjskich teatrów. Przez trzy miesiące w Palladium działo kino. W latach 30. XX wieku teatr był stałą siedzibą kabaretu The Crazy Gang. W 1934 roku do nazwy dodano człon "London". Podczas bombardowania Londynu był nieczynny. Odpowiedzialnym za rezerwacje był Val Parnell.

Era Vala Parnella
W 1945 roku zmarł Black. Funkcję sekretarza generalnego Palladium, jak i Moss Empires, przejął po nim Parnell. Przyjął kontrowersyjną, ale bardzo udaną politykę zatrudniania drogich gwiazd ze Stanów Zjednoczonych, wypierając tym samym ówczesnych brytyjskich artystów, którzy byli gorzej opłacani i traktowani jako gwiazdy drugiej kategorii. Wśród wielu amerykańskich gwiazd występujących wówczas byli m.in. Judy Garland, Sophie Tucker, Bing Crosby, Danny Kaye, The Andrews Sisters, Bob Hope, Ella Fitzgerald, Frank Sinatra, Liza Minnelli, Sammy Davis Jr., Frankie Laine i Johnnie Ray.

W latach 1955-1967 London Palladium był miejscem powstawania popularnego coniedzielnego show rewiowego Sunday Night at the London Palladium. Gospodarzem programu był najpierw Tommy Trinder, później zostali nim Bruce Forsyth i Norman Vaughan. Show był transmitowany przez Associated Television (ATV), będącą częścią sieci telewizyjnej ITV. Producentem był Val Parnell. Między majem a sierpniem 1966 roku sześć odcinków wyemitowała amerykańska stacja telewizyjna NBC.

Parnell związał się z firmą deweloperską, której zaczął sprzedawać teatry należące do Moss Empires w celu ich przebudowy. Kiedy w 1966 roku okazało się, że taki los czeka m.in. London Palladium, Theatre Royal przy Drury Lane i Victoria Palace Theatre; Prince Littler, mając na celu ochronę zabytkowych teatrów, zorganizował przejęcie kontroli nad nimi. Ostatecznie Val Parnell odszedł na emeryturę i osiadł we Francji.

Nowym dyrektorem generalnym Stoll-Moss został Louis Benjamin, który równocześnie nadal sprawował funkcję dyrektora zarządzającego wytwórni fonograficznej Pye Records, części ATV Group.

Musicale
W 1968 roku Sammy Davis Jr. wystąpił w Golden Boy, pierwszym musicalu wystawionym w Palladium. Od tego czasu musicale stanowią znaczącą część repertuaru London Palladium.

W 1970 roku kierownictwo Palladium próbowało nakłonić Elvisa Presleya do czternastu występów w przeciągu jednego tygodnia. Gdy menedżer Presleya, Tom Parker, usłyszał, że oferta opiewa na kwotę 28 tys. dolarów, podobno powiedział: "To dobre dla mnie, ale za ile możesz dostać Elvisa?" Gdyby Presley wystąpił w Palladium, byłby to jego pierwszy występ zagraniczny. Ostatecznie Presley nigdy nie wystąpił poza Ameryką Północną.

W styczniu 1973 roku glam rockowa grupa muzyczna Slade dała w Palladium koncert, w wyniku którego balkon niemal zawalił się. W 1976 roku odbył się koncert Marvina Gaye, który został w następnym roku w postaci albumu koncertowego Live at the London Palladium.

W późnych latach 80. teatr ponownie był miejscem, z którego nadawano telewizyjny program telewizyjny, tym razem był nim Live From the Palladium, prowadzony przez Jimmy'ego Tarbucka.

W tym okresie właścicielem Palladium był Stoll Moss Theatres Group, którego główni akcjonariusze, Margaret i David Locke zarządzali działalnością teatru.

Epoka Really Useful Group
W 2000 roku teatr uległ kolejnej zmianie własnościowej, stając się częścią Bridgepoint Capital i Really Useful Group Andrew Lloyda Webbera.

Od 5 maja 2000 roku do 5 stycznia 2002 w Palladium wystawiano musical Król i ja, który był adaptacją broadwayowskiej produkcji z 1996 roku. W rolach głównych wystąpili Elaine Paige i Jason Scott Lee. Po zakończeniu tej produkcji, usunięto słynną, ale przestarzałą scenę obrotową.

Od kwietnia 2002 roku do 4 września 2005 roku w Palladium grano musical Chitty Chitty Bang Bang, który stały się dużym sukcesem. Była to najczęściej grane przedstawienie w historii teatru. Od grudnia 2005 roku całkowitym właścicielem London Palladium jest Really Useful Group.

Na przełomie 2005 i 2006 roku, w okresie świąt Bożego Narodzenia, wystawiano Scrooge – The Musical. Od lutego 2006 grano musical Sinatra At The London Palladium, oparty na największych przebojach Franka Sinatry.

W listopadzie 2006 roku rozpoczęto pokazywanie musicalu Dźwięki muzyki, który nie schodził z afisza do 21 lutego 2009 roku. Producentami byli Lloyd Webber i Ian David. W roli głównej wystąpiła Connie Fisher, zwyciężczyni telewizyjnego programu rozrywkowego o charakterze konkursu Jak znaleźć Marię? produkcji BBC.

18 i 25 lutego 2007 roku Rufus Wainwright wystąpił na dwóch recitalach poświęconych pamięci Judy Garland.

20 maja 2007 roku London Palladium był miejscem wręczania nagród Brytyjska Akademia Sztuk Filmowych i Telewizyjnych.

Od czerwca 2009 roku w Palladium grany jest musical Zakonnica w przebraniu. Producentką jest Whoopi Goldberg.

Po zakończeniu produkcji Zakonnicy w przebraniu w 2011 roku, jej miejsce zajął musical Czarnoksiężnik z Oz, którego producentem jest Lloyd Webber. Rolę Dorotki Gale grała Danielle Hope, zwyciężczyni brytyjskiego programu telewizyjnego Over the Rainbow. Ostatni spektakl Czarnoksiężnika odbył się we wrześniu 2012 roku, a jego miejsce w zajmie wznowienie Scrooge – The Musical. Na lipiec 2013 roku planowano premierę Charliego i fabryki czekolady.

Przypisy

Teatry w Londynie
Zabytki Londynu
Ogólnodostępne obiekty kulturalne w Londynie

redpajama_set_name: RedPajamaWikipedia


text:
Skyscanner Engineering
Whispers: Advanced secrets detection
Skyscanner's Continuous Integration and Delivery (CI/CD) pipeline is built to support tens of thousands of deployments per day. The frequency of production deployments cannot come at the expense of security. In fact, security processes need to be integrated within the CI/CD pipeline. That's why we added continuous security validation at each step of the pipeline, from development to production, to help ensure our applications stay secure.
Roll up to speed up: Improving OpenTSDB query performance
This post describes how we improved the query performance for our OpenTSDB cluster and enabled queries that previously were impossible by reducing the resolution of historic data.
Skyscanner's focus is to drive every decision in Skyscanner by complete, timely and accurate data. As part of this, we're operating a large metrics and logging platform that enables all engineers in Skyscanner to monitor their service 24 hours a day. We provide application logs and any metrics that our engineers would like to record; for instance, business and operational metrics for their services. We store and serve the data that powers Grafana dashboards and our alerting infrastructure which comprises Bosun and VictorOps. …
Cloud Governance with CFRipper
Skyscanner's products are powered by hundreds of services hosted on AWS. In order to deploy changes and new services to production with zero clicks, we have an automated pipeline that´s responsible for building, testing and deploying new code, and provisioning and configuring new infrastructure. Developers perform these changes by writing CloudFormation templates that model their service's Infrastructure as Code (IaC).
CloudFormation is an AWS service that essentially allows developers to programmatically provision AWS resources. CloudFormation templates could have security issues similar to regular source code, such as hardcoded secrets, overly permissive permissions, and many more.
Our goal at the Security Automation team is to inject security into the pipeline as early as possible, and to make sure that the relevant security scans and audits are performed at every step, minimising the risk of any vulnerable code getting into production. …
3 (+1) Questions for impactful Sprint Goals!
Cristiano Balducci is one of our squad leaders. A problem-solver at heart, Cristiano shares valuable insights on how you can identify issues and achieve your goals as a team. Read this short blog to discover his top tips on how to achieve some of the most impressive sprint goals. If you want to find out about how we troubleshooting our process and what we have learnt doing this click here.
How do we choose impactful sprint goals?
Here at Skyscanner we are arranged into squads and tribes; I'm a squad lead, and my squad — like many of the other engineering squads at the company — uses an 'agile' methodology called 'Scrum' for the purposes of effective software development. …
Kubernetes Security monitoring at scale with Sysdig Falco
Two years ago in Skyscanner we made the decision to start moving our workloads to Kubernetes. Today, even though this transition is far from complete, our infrastructure is using >2000 nodes spread across 30 different clusters to power a fleet of >160 services.
As part of the transition to Kubernetes, the Security team had to come up with a way to detect malicious activity in Skyscanner's Kubernetes clusters. Due to the sheer size of the target we want to monitor, the solution we chose needed to be able to scale as much as our most demanding services, without hindering their performance while allowing us to be immediately alerted if one of the machines in any cluster is compromised. Also, not only do we need the ability to scale to all the Kubernetes clusters, we also need an automated way of mapping and contacting the owners of the affected services if anything were to happen. …
The (curious) case of the thirty-something graduate
When Alexandra Haret heard the 'call of the code', she left behind a ten year marketing career to retrain as a software engineer. Along the way she realised that her story is not as uncommon as she thought — and that not all grad schemes are created equal.
Students attend a graduation ceremony at Walla Walla University in Washington, USA
In June I (re)joined Skyscanner as a thirty-plus year-old graduate software engineer. How did this come about? The answer to this question has two parts…
Part one — my not-so-uncommon story of career change
A few years ago, I decided to pivot from an almost ten-year career in marketing and address a question that was echoing more and more loudly in my head: would I enjoy working as a software engineer more? So I decided to woman-up, quit my job, and spend a couple of months on full-time home learning — and sooner than I ever dreamed possible, I got my first job as a web developer.
I remember being anxious at first about how awkward and difficult it would be to explain to others how and why I made this change. Yet to my very pleasant surprise, the more I spoke about it, the more I understood how common this story is becoming nowadays. Our professional careers are now more fluid and flexible than even before — and it's no wonder: we live in a day and age where high quality learning resources are very accessible — and either free, or very inexpensive. Changing career is no longer such an uncommon story, and it's becoming a choice bravely made by more and more people. …
Our Engineers move people: George Goodyer, Skyscanner Chief Technology Officer
Over the last few weeks Skyscanner has been looking for some of the best talent to join its engineering team. In this video, our Chief Technology Officer, George Goodyer talks about some of reasons he works at Skyscanner and what inspires the team day to day.
Being a principal engineer at Skyscanner
In this follow-up to her influential post, Finding the steps on the individual contributor ladder, Nicky Wrightson discusses her experiences as a principal engineer at Skyscanner, and assesses the company's support for individual contributors — does it run deep, or is it skin-deep? Read on for her take…
The sun rises over London, UK, where Skyscanner's engineering team includes a closely knit community of principal engineers
Skyscanner is growing and our Engineers don't just love working here — they love telling people about it. Over the next few months some of our most passionate engineers will be writing to showcase our London hotbed of software engineering talent, and how we're impacting millions of travellers, all over the world.
In my recent blog post, Finding the steps on the individual contributor ladder, I wrote about the problems that exist in the industry around defining and finding senior individual contributor (IC) roles like that of principal engineer (my own role). As I observed in my blog post, you can tell if a company is committed to helping their individual contributors grow by asking if they have job specs prepared for IC roles — if they can provide you with a spec it is a good indicator that they can and will support individual contributors. …
Finding the steps on the individual contributor ladder
What does it actually mean to be a 'principal engineer'? Skyscanner's Nicky Wrightson draws on her experiences, her missteps, and her research to profile one of the most in-demand roles in the world of individual contributors. Read on to find out if the IC route is for you…
A plane flies through the cage of a building ladder in Kota Bharu, Malaysia
Skyscanner is growing and our Engineers don't just love working here — they love telling people about it. Over the next few months some of our most passionate engineers will be writing to showcase our London hotbed of software engineering talent, and how we're impacting millions of travellers, all over the world. Nicky Wrightson has also written a follow-up to this blog on what it's like to be a principal engineer at Skyscanner, which you can find right here.
I rose through the ranks to become principal engineer at the Financial Times. Since leaving there I have had two principal engineer roles, with the second of those taking me to where I am at the moment: Skyscanner. During this journey of promotion and seeking a new role I have had to get what a principal engineer actually is really clear in my mind. I didn't get it right initially, and found myself in a role at a company that was not yet ready for a principal, so having me was not good for them — or for me. I found a few useful resources which helped me to understand what it means to be a principal engineer, but it's fair to say that there's not much information out there. So I thought I would pull together my experiences, learnings and questions and write something to help people decide if the individual contributor (IC) route is for them. …
How we scaled our design system to unleash Skyscanner's new brand
Skyscanner's design system, 'Backpack', played a crucial role in enabling the company's recent brand refresh. In this piece, Shaun Donnelly looks at how having a design system helped Skyscanner — and could help other businesses give themselves a makeover
In September 2019, our new brand launched. It was the culmination of over a year of work, touching every part of the company.
Our iOS app showing off our new brand.
The squad I work in looks after Backpack — Skyscanner's design system. We were tasked with using Backpack to seamlessly roll out the new brand across all of Skyscanner's products. Here's how we did it.
We describe Backpack as 'the codification of Skyscanner's design language' — a representation of all the discussions, debates and decisions that make up design at Skyscanner.
Backpack is the codification of Skyscanner's design language.
Backpack provides components for three platforms: Android (Kotlin/Java, React Native), iOS (Swift/Objective-C, React Native) and web (React). These components are used to build a consistent interface for travellers regardless of the platform they're using. …
We are the engineers at Skyscanner, the company changing how the world travels. Visit skyscanner.net to see how we walk the talk!


Ready in 25 minutes, this healthier pizza uses Lebanese bread as the base and is loaded with vegies and ricotta. It's also budget-friendly costing less than $4 a serve.
Combine oil, garlic and rosemary in a bowl. Combine ricotta and half the rosemary mixture in a separate bowl. Season with salt and pepper.
Remove and discard stems and centre veins from kale. Roughly tear leaves. Place bread on prepared trays. Spread with ricotta mixture. Sprinkle with half the parmesan. Top with kale, zucchini and tomatoes. Sprinkle with remaining parmesan. Drizzle with remaining rosemary mixture. Bake for 10 minutes or until vegetables soften and parmesan is golden and melted.
Sprinkle with basil leaves. Cut into pieces. Serve.


, we choices the best libraries together with greatest image resolution simply for you all, and this photographs is actually considered one of photographs series in your best graphics gallery regarding Auto Parts Fremont Ca. I really hope you'll enjoy it.
published simply by Paul Cook in 2019-01-04 01:20:18. To see most images within Auto Parts Fremont Ca graphics gallery remember to comply with that web page link.
Auto Parts Fremont Ca Luxury Don S Antique Auto Parts Closed Auto Parts & Supplies Uploaded by Paul Cook on Friday, January 4th, 2019 in category Nissan OEM Parts.
See also Auto Parts Fremont Ca Luxury 2019 Nissan Sentra S 3n1ab7ap0ky from Nissan OEM Parts Topic.
Here we have another image Auto Parts Fremont Ca Best Of New 2018 Nissan Murano Sv In Fremont Ca Fremont Auto Mall featured under Auto Parts Fremont Ca Luxury Don S Antique Auto Parts Closed Auto Parts & Supplies. We hope you enjoyed it and if you want to download the pictures in high quality, simply right click the image and choose "Save As". Thanks for reading Auto Parts Fremont Ca Luxury Don S Antique Auto Parts Closed Auto Parts & Supplies.