Hint: You've probably already been doing it without knowing!
Many people are intrigued when they first hear the term "therapeutic photography" and while some instinctively get it, others are unsure if they know how it works.
It's common that people are worried about the quality or technical aspects of their photos, sharing something that they feel is not up to par with other members, but that's the beauty of therapeutic photography and our community.
We're not about photography as an art or profession, it's simply a way of communicating and expressing yourself in a non-verbal form.
You don't need a fancy camera or any specific type, the one in your phone will do, or use a point-and-shoot, DSLR, film camera — whatever you have is enough.
The next thought and barrier is often not knowing where to begin.
I get it. Every single one of us has been there before and the most important thing is to just get started. Share something – no matter how simple or small. It's the only way that we can meet you and start to get you connected in the community.
We've worked really hard to connect our community so that people can often get feedback as quickly as possible on their stories — and it's always improving.
The brilliance of therapeutic photography techniques and using photos as a way to express yourself, especially in the context of mental health, is that it can take the place of words when you're not sure how to say it.
Say it through your photo.
Anyone who has gone through something similar may see it and be able to relate.
There are lots of reasons why taking photos is therapeutic and beneficial for your mental health, which you can read more about on our page on therapeutic photography – yet there's so much more to it.
You can learn more about our specific therapeutic photography techniques that many have used as a way to better express, understand and overcome issues like depression and anxiety in our flagship course, Build Your One Project — which is free within our private community.


text:
Local Football Club in KwaThema Gains Support from Community
Refilwe Lentsitse 23/03/2021
Local soccer teams are being recognised and supported in the community of KwaThema (a township on the Eastrand of Gauteng). Football tournaments have been happening in KwaThema every year and they have shown the great skill from the young stars and their coaches.
Tshepiso Paul Football Club (TPL) is one of the popular soccer teams in the area. It was established in 2018, and has been playing and gaining recognition ever since. Tshepiso Paul is the name of player of TPL who passed on in 2018. Before the team was named after him, it was known as Eastern Gunners.
Kagiso Magosi, a young 29-year-old man from White City (a location in KwaThema), is known as 'Coach' to the kids he trains. He is the founder and coach of
TPL. Kagiso has been playing football from a young age, which he learnt from his late father, Simon Mphuthi. Mphuthi was a soccer player who played with legendary Orlando Pirates goalkeeper Innocent Mayoyo and had a team of his own.
When the team started, they only had two balls, no kit, no sponsors and no resources but through their dedication and hard work they managed to get noticed by local businesspeople and parents of the dedicated and talented players.
Kagiso is a passionate young man so he never gave up. "Having a skill and talent is very important, so it gives me great joy to see these boys having fun and being competitive," said Kagiso.
TPL has been playing for and qualifying in tournaments since it was established. In 2019 they won a League and the Ayoba Regional League Tournament, and they were also finalists in both editions of the James Moloto Tournament in the 2019/2020 games played in KwaThema last year. Many players in the tournament won themselves medals and trophies – one got for Player of the Tournament and one for Top Goal Scorer, among other awards.
The team practices once a week and the players are still dedicated and wishing for more medals and trophies.
Previous Daveyton Old Age Home Gets Back on Its Feet
Next Covid-19 Youth Brigades Still Wait for Payment 8 Months Later
Refilwe Lentsitse
The Inkanyezi netball team gets children off the streets
Football Hero of the People, Diego Maradona Dies
No one deserves to starve
Decision looming on landmark labour-broking case
Housing is a sensitive issue in Marikana
The Struggle of Un-contracted CHWs in Gauteng
ESKOM Refuses to Repair Transformers In Orange Farm Due To Non-Payments
Gangsterism Taking Over Daveyton
South Johannesburg erupts in protest
Siyabonga Mviko 29/05/2017

redpajama_set_name: RedPajamaCommonCrawl


text:
\section{Introduction}\label{sec1}

One of fundamental distinctions of the quantum world from the
classical world is expressed by the uncertainty principle
\cite{heisenberg}. We mention here only several developments
concerning this issue. More extensive discussion with the
corresponding references can be found in the reviews
\cite{lahti,ww10,brud11}. Recent studies of entropic relations are
often connected with advances in quantum information science. It
treats quantum states and effects as informational resources
\cite{nielsen,watrous1}. Due to the influential works
\cite{deutsch,maass}, entropic functionals are now typically used
in formulating the uncertainty principle. Entropic relations are
essential in analyzing the security of quantum cryptographic
schemes \cite{dmg07,ngbw12}. Reformulations in the presence of
quantum memory are discussed in \cite{BCCRR10,ccyz12,fan12}. With
respect to quantum operations, an entropic approach has been
developed in \cite{rprz12}. In expressing entropic relations,
various kinds of entropic functionals have found to be useful. Such
entropic bounds were utilized in studying several specific topics
such as quantifying number-phase uncertainties
\cite{rast105,rast12num}, incompatibilities of anti-commuting
observables \cite{ww08} and reformulations in quasi-Hermitian
models \cite{rast12quasi}. The R\'{e}nyi \cite{renyi} and Tsallis'
entropies \cite{tsallis} are both especially important. They are
particular cases of unified $(q,s)$-entropies introduced in
\cite{hey06} and further studied in \cite{rastjst}. Formally,
entropic uncertainty relations are posed as lower bounds on the
sum of two or more entropies. Each of these entropies characterize
an uncertainty in measurement statistics with respect to the
corresponding basis.

In the paper \cite{rprz12}, the authors derived a lower bound on
the sum of two entropies, corresponding to complementary
characteristics of the same quantum operation. Inequalities of
such a kind are usually referred to as trade-off relations. The
formalism of quantum operations provides a general tool for
description of open quantum systems. Deterministic protocols are
represented by trace-preserving operations also known as quantum
channels. In quantum information theory, several channel
representations are significant. The Jamio{\l}kowski--Choi and
natural representations are both utilized in entropic
characterizing given quantum channel. The entropy exchange
\cite{glind91,bsch96} and the map entropy \cite{zb04} are
respectively used to describe entanglement transmission and
decoherence induced by a quantum channel. A family of map
entropies is defined in terms of the dynamical matrix. The writers
of \cite{rprz12} have defined the receiver entropies related to
the natural representation of a channel. They further showed that
the sum of the map and receiver entropies is bounded from below.
This bound is written in terms of system dimensionality and
compares two complementary characteristics of a single quantum
channel. Thus, it differs in character from uncertainty relations
posed in \cite{rast104} for extremal unravelings of two channels.
The writers of \cite{rprz12} utilized R\'{e}nyi's entropic
functionals. Other entropic functionals have found use in studying
various quantum properties
\cite{raggio,majer03,kim11,rastfn,rastctp}.

The aim of the present work is to formulate trade-off relations
for a single quantum channel in terms of the map and receiver
$(q,s)$-entropies. The paper is organized as follows. In section
\ref{sec2}, the required material is reviewed. First, definitions
of the Schatten norms and anti-norms are discussed. Second, we
briefly recall the concept of map entropies studied in
\cite{zb04,rfz10,rzf11,rast11a}. Then, the family of receiver
entropies are extended in terms of quantum $(q,s)$-entropies.
Section \ref{sec3} is devoted to formulating the main results.
Before their derivation, we collect several auxiliary statements.
In particular, some relations with the Schatten norms and
anti-norms are obtained. These inequalities could be used in other
questions, in which we deals with norms and anti-norms of matrices
related by reordering the same entries. Non-trivial lower bounds
on the sum of the map and receiver $(q,s)$-entropies are obtained
for all considered values of the parameters. Here, we establish
lower bounds for arbitrary quantum channels as well as stronger
bounds for unital channels. In section \ref{sec4}, we conclude the
paper with a summary of results.

\section{Definitions and notation}\label{sec2}

In this section, we introduce terms and conventions that will be
used through the text. First, required material on operator norms
and anti-norms is presented. Second, we discuss the map
$(q,s)$-entropy. Then the notion of the receiver $(q,s)$-entropy
is introduced.

\subsection{Operators, norms and anti-norm}\label{sc21}

Let $\lnp(\hh)$ be the space of linear operators on
$d$-dimensional Hilbert space $\hh$. By $\lsp(\hh)$ and
$\lpp(\hh)$, we respectively denote the set of positive
semidefinite operators on $\hh$ and the set of strictly positive
ones. A density operator $\bro\in\lsp(\hh)$ has unit trace, i.e.
$\Tr(\bro)=1$. For $\ax,\ay\in{\mathcal{L}}(\hh)$, we define the
Hilbert--Schmidt inner product by \cite{watrous1}
\begin{equation}
\langle\ax{\,},\ay\rangle_{\rm{hs}}:=\Tr(\ax^{\dagger}\ay)
\ . \label{hsdef}
\end{equation}
The Schatten norms, which form an important class of unitarily
invariant norms, are defined in terms of singular values. The
singular values $\sigma_{j}(\ax)$ of operator $\ax$ are put as
eigenvalues of $|\ax|=\sqrt{\ax^{\dagger}\ax}\in\lsp(\hh)$. For
$q\geq1$, the Schatten $q$-norm of
$\ax\in{\mathcal{L}}({\mathcal{H}})$ is then defined by
\cite{watrous1,bhatia97}
\begin{equation}
\|{\mathsf{\ax}}\|_{q}:=
\left(\sum\nolimits_{j=1}^{d}\sigma_{j}({\mathsf{\ax}})^q\right)^{1/q}
=\Tr\!\left(\bigl(\ax^{\dagger}\ax\bigr)^{q/2}\right)^{1/q}
{\,}. \label{shndf}
\end{equation}
Here, the singular values should be inserted according to their
multiplicities. The family (\ref{shndf}) gives the trace norm
$\|\ax\|_{1}$ for $q=1$, the Frobenius norm $\|\ax\|_{2}$ for
$q=2$, and the spectral norm
$\|\ax\|_{\infty}=\max\bigl\{\sigma_j(\ax):{\>}1\leq{j}\leq{d}\bigr\}$
for $q=\infty$. Note that the Frobenius norm can be rewritten as
\begin{equation}
\|\ax\|_{2}=\langle\ax{\,},\ax\rangle_{\rm{hs}}^{1/2}
\ . \label{fvhs}
\end{equation}
For this reason, it is often called the Hilbert--Schmidt norm.
This norm induces the Hilbert--Schmidt distance, which is very
useful to analyze a geometry of quantum states \cite{dunk11}. The
formula (\ref{fvhs}) shows that the squared $2$-norm is expressed
as the sum of squared modulus of all the matrix entries. In the
following, this fact will be essential.

In the papers \cite{bh10a,bh10b}, Bourin and Hiai examined
symmetric anti-norms of positive operators. They form a class of
functionals containing the right-hand side of (\ref{shndf}) for
$q\in(0;1)$ and, with strictly positive matrices, for $q<0$. For
arbitrary $\ax\in\lsp(\hh)$, we consider a functional
$\ax\mapsto\|\ax\|_{!}$, taking values on $[0;\infty)$. If this
functional enjoys the homogeneity, the symmetry
$\|\ax\|_{!}=\|\vm\ax\vm^{\dagger}\|_{!}$ for all unitary $\vm$,
and the superadditivity
\begin{equation}
\|\ax+\ay\|_{!}\geq\|\ax\|_{!}+\|\ay\|_{!}
\ , \label{sups}
\end{equation}
it is said to be a symmetric anti-norm \cite{bh10a}. Let
$\lambda_{j}({\mathsf{\ax}})$ denote $j$-th eigenvalue of operator
$\ax$. For $\ax\in\lpp(\hh)$ and $q\leq1\neq0$, we put the
Schatten $q$-anti-norm as
\begin{equation}
\|{\mathsf{\ax}}\|_{q}=\left(\sum\nolimits_{j=1}^{d}\lambda_{j}({\mathsf{\ax}})^q\right)^{1/q}
{\,}. \label{shnaf}
\end{equation}
Using given anti-norm $\|\ax\|_{!}$, for any $q\in(0;1)$ we can
build another anti-norm (see proposition 3.7 of \cite{bh10a})
\begin{equation}
\ax\mapsto\|\ax^{q}\|_{!}^{1/q}
\ . \label{afunex}
\end{equation}
Note that the trace norm is actually an anti-norm on positive
matrices. Indeed, the superadditivity inequality is satisfied here
with equality. Combining this with (\ref{afunex}), the right-hand
side of (\ref{shnaf}) is an anti-norm on positive operators for
$q\in(0;1)$. With $\ax\in\lpp(\hh)$ and arbitrary non-zero
$q\leq1$, the inequality (\ref{sups}) for the Schatten
$q$-anti-norm was proved in \cite{rastcejp}. Note that the
restriction to positive matrices is essential in the sense of
superadditivity condition (\ref{sups}). Following
\cite{bh10a,bh10b}, the Schatten $q$-anti-norm of $\ax$ will also
be denoted as $\|\ax\|_{q}$. Some relations for anti-norms and
their applications to entropic functionals are examined in
\cite{rastjst12}. We will further assume that use of anti-norms
tacitly implies the corresponding restriction on matrices. For all
$0<p<q$, we have
\begin{equation}
\|\ax\|_{q}\leq\|\ax\|_{p}
\ . \label{npqr}
\end{equation}
This relation is actually no more than theorem 19 of \cite{hardy}.
In the following, we will use the Schatten $q$-norms for
$q\in[1;\infty]$ and the Schatten $q$-anti-norms of positive
operators for $q\in(0;1)$.

\subsection{Two channel representations and the corresponding $(q,s)$-entropies}\label{sc22}

By $\hh$, we mean $d$-dimensional space of the principal quantum
system $Q$. Consider a linear map
$\Phi{\>}:\lnp(\hh)\rightarrow\lnp(\hh)$, which also satisfies the
condition of complete positivity. Let $\id^{R}$ be the identity
map on $\lnp(\hh_{R})$, where the space $\hh_{R}$ is assigned to
auxiliary reference system. The complete positivity implies that
$\Phi\otimes\id^R$ transforms a positive operator into a positive
operator again for all extensions. When the identity operator is
mapped into itself, i.e. $\Phi(\pen)=\pen$, the map is unital.
Unital quantum channels are often called bistochastic
\cite{bengtsson}. There are many interesting classes of quantum
channels such as unistochastic channels and degradable channels.
The former implies that the principal system unitarily interacts
with the $d$-dimensional environment, which was initially
completely mixed \cite{bengtsson}. The notion of degradable
channels is related to studying capacities for various processing
scenarios \cite{des05}.

Linear maps can formally be described in several ways. We will use
two representations, when the map is represented by a single
matrix of size $d^{2}\times{d}^{2}$. The family of map entropies
is introduced within the Jamio{\l}kowski--Choi representation
\cite{jam72,choi75}, for which we take $\hh_{R}=\hh$. To fixed
orthonormal basis $\{|\nu\rangle\}$ in $\hh$, we assign the
normalized pure state
\begin{equation}
|\phi_{+}\rangle:=\frac{1}{\sqrt{d}}{\,}\sum_{\nu=1}^{d}
{|\nu\rangle\otimes|\nu\rangle}
\ . \label{phip}
\end{equation}
One defines the operator
$\bomg(\Phi):=\Phi\otimes\id{\,}\bigl(|\phi_{+}\rangle\langle\phi_{+}|\bigr)$,
acting on the space $\hh\otimes\hh$. The dynamical matrix is then
written as $\D(\Phi)=d{\,}\bomg(\Phi)$ \cite{zb04}. In shortened
notation, we write the dynamical matrix and the rescaled one as
$\D_{\Phi}$ and $\bomg_{\Phi}$, respectively. For all
$\ax\in{\mathcal{L}}(\hh)$, the action of $\Phi$ can be expressed
as \cite{watrous1}
\begin{equation}
\Phi(\ax)=\Tr_{R}\left(\D_{\Phi}(\pen\otimes\ax^{T})\right)
{\>}, \label{chjis}
\end{equation}
where $\ax^{T}$ denotes the transpose operator to $\ax$. The map
$\Phi$ is completely positive, if and only if the matrix
$\D(\Phi)$ is positive. Further, the preservation of the trace is
expressed as $\Tr_{Q}(\D_{\Phi})=\pen$, whence $\Tr(\D_{\Phi})=d$
and $\Tr(\bomg_{\Phi})=1$.

The concept of entropy is one of fundamentals in both statistical
physics and information theory \cite{wehrl,petz08}. We focus an
attention on the notions of the map and receiver entropies. The
former is put through the Jamio{\l}kowski--Choi representation.
For any quantum channel, the dynamical matrix is positive one with
trace $d$. For $q>0\neq1$ and $s\neq0$, the map $(q,s)$-entropy of
quantum channel $\Phi$ is defined as
\begin{equation}
\rmm(\Phi):=\frac{1}{(1-q){\,}s}{\,}
\left(\frac{\|\D_{\Phi}\|_{q}^{qs}}{d^{qs}}-1\right)
=\frac{1}{(1-q){\,}s}{\,}
\left\{\left(d^{-q}\sum\nolimits_{j=1}^{d^{2}}{\,}\lambda_{j}(\D_{\Phi})^{q}\right)^{\!{s}}-1\right\}
{\>}. \label{mapqs}
\end{equation}
In the limit $s\to0$, one leads to the map R\'{e}nyi entropy
defined as
\begin{equation}
\mathrm{M}_{q}^{(0)}(\Phi):=
\frac{q}{1-q}{\>}\Bigl(\ln\|\D_{\Phi}\|_{q}-\ln{d}\Bigr)=
\frac{1}{1-q}{\,}\left\{\ln\!\left(\sum\nolimits_{j=1}^{d^{2}}\lambda_{j}(\D_{\Phi})^q\right)-q\ln{d}\right\}
{\>}. \label{mapqs0}
\end{equation}
Taking $s=1$, we have the case of Tsallis entropy
\begin{equation}
\mathrm{M}_{q}^{(1)}(\Phi)=\frac{d^{-q}{\,}\|\D_{\Phi}\|_{q}^{q}-1}{1-q}=
-\sum_{j=1}^{d^{2}}\left(\frac{\lambda_{j}(\D_{\Phi})}{d}\right)^{\!q}\ln_{q}\!\left(\frac{\lambda_{j}(\D_{\Phi})}{d}\right)
{\>}, \label{tmap}
\end{equation}
where the $q$-logarithm $\ln_{q}(x)=\bigl(x^{1-q}-1\bigr)/(1-q)$
is defined for $q>0\neq1$ and $x>0$. When $q\to1$, we obtain the
usual logarithm and the map von Neumann entropy. For brevity, we
will usually omit the summation range, when it is clear from the
context. The expression (\ref{mapqs}) is a two-parametric
extension of the standard map entropy introduced in \cite{zb04}.
Note that the map entropy coincides with the entropy exchange
calculated for given channel with the completely mixed input
\cite{rfz10,wfz08}. Properties of the map $(q,s)$-entropies are
examined in \cite{rast11a,rastcejp}. Therein, the map
$(q,s)$-entropy was introduced in terms of the rescaled matrix
$\bomg_{\Phi}$. In the present consideration, however, the
definitions (\ref{mapqs}) and (\ref{mapqs0}) are more convenient.

To consider the natural representation, we will use a variant of
operator-vector correspondence
$\lnp(\hh)\rightarrow\hh\otimes\hh$. With respect to the standard
basis $\{|\nu\rangle\}$, one defines the mapping \cite{watrous1}
\begin{equation}
\big|\vc(|\mu\rangle\langle\nu|)\bigr\rangle=|\mu\rangle\otimes|\nu\rangle
\ . \label{vcdf}
\end{equation}
By linearity, this mapping is determined for arbitrary input
$\ax\in\lnp(\hh)$. It is an isometry in the sense that
$\langle\ax{\,},\ay\rangle_{\mathrm{hs}}=\bigl\langle\vc(\ax)\big|\vc(\ay)\bigr\rangle$
\cite{watrous1}. We now define the matrix
$\km(\Phi)\in\lnp(\hh\otimes\hh)$ such that, for all
$\ax\in\lnp(\hh)$,
\begin{equation}
\big|\vc\bigl(\Phi(\ax)\bigr)\bigr\rangle=\km(\Phi)\big|\vc(\ax)\bigr\rangle
\ . \label{kmdf}
\end{equation}
Following \cite{rprz12,wfz08}, this matrix will be referred to as
the superoperator matrix. Some properties of superoperator
matrices are indicated in section 5.2.1 of \cite{watrous1}. Note
that the superoperator matrix is not generally Hermitian. In
characterizations of quantum channels, the natural representation
is not so frequently used as other representations
\cite{watrous1}. Nevertheless, the authors of \cite{rprz12} have
shown that entropic characteristics of $\km_{\Phi}$ are
demonstrative as well. Namely, the family of receiver entropies is
defined in terms of the superoperator matrix \cite{rprz12}. In
line with the right-hand sides of (\ref{mapqs}) and
(\ref{mapqs0}), we define the receiver $(q,s)$-entropy by
\begin{align}
\rmr(\Phi)&:=\frac{1}{(1-q){\,}s}{\,}
\left\{\left(\|\km_{\Phi}\|_{1}^{-q}\sum\nolimits_{j=1}^{d^{2}}{\,}\sigma_{j}(\km_{\Phi})^{q}\right)^{\!{s}}-1\right\}
\qquad (s\neq0) \ , \label{repqs}\\
\mathrm{R}_{q}^{(0)}(\Phi)&:=
\frac{1}{1-q}{\,}\left\{\ln\!\left(\sum\nolimits_{j=1}^{d^{2}}\sigma_{j}(\km_{\Phi})^{q}\right)-q\ln\|\km_{\Phi}\|_{1}\right\}
{\>}, \label{repqs0}
\end{align}
where $\|\km_{\Phi}\|_{1}=\sum_{j}\sigma_{j}(\km_{\Phi})$. This
definition can be rewritten in terms of the Schatten $q$-norm of
$\km_{\Phi}$ for $q\geq1$ and $q$-anti-norm of positive
$|\km_{\Phi}|$ for $q\in(0;1)$. The right-hand side of
(\ref{repqs0}), i.e. R\'{e}nyi's variety, was previously
introduced in \cite{rprz12}. It characterizes an amount, with
which the receiver {\it a priori} knows the channel output. For
our purposes, the following relation between the above matrices is
essential. The standard basis in $\hh\otimes\hh$ is formed by the
vectors $|\mu\nu\rangle\equiv|\mu\rangle\otimes|\nu\rangle$. For
arbitrary vectors of this basis, we have
\begin{equation}
\langle\alpha\beta|\km_{\Phi}|\mu\nu\rangle=
\langle\alpha\mu|\D_{\Phi}|\beta\nu\rangle
\ . \label{kmdm}
\end{equation}
In other words, the superoperator matrix is obtained from the
dynamical one by the reshuffling operation \cite{rprz12}. It is
for this reason that the matrices $\D_{\Phi}$ and $\km_{\Phi}$
instead of rescaled ones are to be used in our definitions. Matrix
operations of such a kind and their essential role in quantum
information are reviewed in \cite{jam11}.  The map end receiver
entropies provide two mutually complementary characteristics of
given quantum channel. This issue is considered in the next
section.

\section{Trade-off relations in terms of the $(q,s)$-entropies}\label{sec3}

In this section, we formulate trade-off relations for a single
quantum channel in terms of the map and receiver
$(q,s)$-entropies. To avoid too long derivation, we first present
several auxiliary results. In particular, some relations between
Schatten norms and anti-norms are given. Then, lower bounds on the
$(q,s)$-entropic sum are derived for all values of the parameters.

\subsection{Preliminaries}\label{sc31}

As was already mentioned, the dynamical and superoperator matrices
are $d^{2}\times{d}^{2}$-matrices related by the reshuffling
operation. Since the operation does not change the matrix entries,
these matrices have the same Schatten $2$-norm \cite{rprz12}.
Hence, relations between $2$-norm and other norms or anti-norms
are essential for our purposes.

\newtheorem{lem1}{Proposition}
\begin{lem1}\label{lan1}
For all $\ax\in\lnp(\hh)$ and $q\geq1$, the Schatten $q$-norm
satisfies
\begin{eqnarray}
\|\ax\|_{q}^{q}&\leq&\|\ax\|_{2}^{2(q-1)}{\,}\|\ax\|_{1}^{2-q}
\qquad (1\leq{q}\leq2)
\ , \label{lq1}\\
\|\ax\|_{q}^{q}&\geq&
\|\ax\|_{2}^{2(q-1)}{\,}\|\ax\|_{1}^{2-q}
\qquad (2\leq{q}<\infty)
\ . \label{lq2}
\end{eqnarray}
For $\ax\in\lsp(\hh)$ and $0<q<1$, the Schatten $q$-anti-norm
satisfies (\ref{lq2}). When $\ax\in\lpp(\hh)$, the relation
(\ref{lq2}) holds for $q<0$ as well.
\end{lem1}

{\bf Proof.} Let us introduce positive numbers
$x_{j}=\sigma_{j}(\ax){\,}\|\ax\|_{1}^{-1}$, which obey
$\sum_{j}x_{j}=1$. Assuming $q\geq1$, we apply Jensen's inequality
to the function $x\mapsto{x}^{q-1}$. As this function is concave
for $q\in[1;2]$ and convex for $q\in[2;\infty)$, we have
\begin{equation}
\sum\nolimits_{j} x_{j}^{q}=\sum\nolimits_{j} x_{j}{\,}x_{j}^{q-1}
\left\{
\begin{array}{cc}
\leq, & 1\leq{q}\leq2 \\
\geq, & 2\leq{q}<\infty
\end{array}
\right\}
\left(\sum\nolimits_{j} x_{j}^{2}\right)^{q-1}
{\,}. \label{jen1}
\end{equation}
The left-hand side of (\ref{jen1}) is equal to
$\|\ax\|_{q}^{q}{\,}\|\ax\|_{1}^{-q}$, the right-hand side of
(\ref{jen1}) is equal to
$\Bigl(\|\ax\|_{2}^{2}{\,}\|\ax\|_{1}^{-2}\Bigr)^{q-1}$. After
substituting these expressions, we respectively obtain (\ref{lq1})
and (\ref{lq2}). Restricting a consideration to strictly positive
$\ax$, we take $x_{j}=\lambda_{j}(\ax){\,}\|\ax\|_{1}^{-1}>0$.
Since the function $x\mapsto{x}^{q-1}$ is convex for $q<1$, the
above relation provides the claim (\ref{lq2}) for the Schatten
$q$-anti-norm. $\blacksquare$

We above mentioned that $\|\D_{\Phi}\|=\Tr(\D_{\Phi})=d$. Deriving
entropic relations, we will also use an upper bound on
$\|\km_{\Phi}\|_{\infty}$. The statement of theorem 1 in
\cite{rprz12} says that
\begin{equation}
\|\km_{\Phi}\|_{\infty}\leq{d}^{1/2}{\,}\|\Phi(\bro_{*})\|_{\infty}^{1/2}
\ , \label{upkp}
\end{equation}
where $\bro_{*}=\pen/d$ is the completely mixed state. Clearly,
one has
$\|\Phi(\bro_{*})\|_{\infty}\leq\|\Phi(\bro_{*})\|_{1}=\Tr\bigl(\Phi(\bro_{*})\bigr)=1$
for any quantum channel, whence
$\|\km_{\Phi}\|_{\infty}\leq{d}^{1/2}$. For unital channels, we
merely obtain
$\|\Phi(\bro_{*})\|_{\infty}=\|\bro_{*}\|_{\infty}=1/d$ and
$\|\km_{\Phi}\|_{\infty}\leq1$. It follows from lemma 3 of
\cite{rprz12} that, for arbitrary $\ax\in\lnp(\hh)$,
\begin{equation}
\|\ax\|_{2}\leq\|\ax\|_{\infty}^{1/2}{\,}\|\ax\|_{1}^{1/2}
\ . \label{21in}
\end{equation}
Combining the above facts with the equality
$\|\D_{\Phi}\|_{2}=\|\km_{\Phi}\|_{2}$, we then write
\begin{equation}
\frac{\|\D_{\Phi}\|_{1}}{\|\D_{\Phi}\|_{2}}{\>}\frac{\|\km_{\Phi}\|_{1}}{\|\km_{\Phi}\|_{2}}
=\frac{\|\D_{\Phi}\|_{1}{\,}\|\km_{\Phi}\|_{1}}{\|\km_{\Phi}\|_{2}^{2}}
\geq\frac{\|\D_{\Phi}\|_{1}}{\|\km_{\Phi}\|_{\infty}}
\geq
\left\{
\begin{array}{ll}
d^{1/2}{\>}, & {\mathrm{for{\ }all{\ }channels}}{\>}, \\
d{\>}, & {\mathrm{for{\ }unital{\ }ones}}{\>}.
\end{array}
\right.
\label{cbn0}
\end{equation}
Thus, the left-hand side of (\ref{cbn0}) is bounded from below. To
get trade-off relations from bounds on norms and anti-norms, some
analytical results are required as well. Let $a$ and $b$ be
strictly positive numbers such that $a<1$ and $1<b$. We consider
the following two-dimensional domains:
\begin{align}
\cald_{a}&:=\bigl\{(x,y):{\>}0\leq{x}\leq1,{\>}0\leq{y}\leq1,{\>}xy\leq{a}\bigr\}
\ , \label{dadf}\\
\cald_{b}&:=\bigl\{(x,y):{\>}1\leq{x}<\infty,{\>}1\leq{y}<\infty,{\>}b\leq{x}y\bigr\}
\ . \label{dbdf}
\end{align}
The minimum of the function $(x,y)\mapsto2-x-y$ in the domain
(\ref{dadf}) is equal to
\begin{equation}
{\min}\bigl\{2-x-y:{\>}(x,y)\in\cald_{a}\bigr\}=1-a
\ . \label{gmin}
\end{equation}
Indeed, this function decreases with each of $x$ and $y$. Hence,
the minimum is reached on the part of the curve $xy=a$ between the
points $(a,1)$ and $(1,a)$. As the function $x\mapsto2-x-a/x$ is
concave and takes the same value (\ref{gmin}) at the end points,
this value is actually the minimum. Further, the minimum of
$(x,y)\mapsto{x}+y-2$ in the domain (\ref{dbdf}) is equal to
\begin{equation}
{\min}\bigl\{x+y-2:{\>}(x,y)\in\cald_{b}\bigr\}=2\bigl(\sqrt{b}-1\bigr)
\ . \label{fmin}
\end{equation}
Since this function increases with each of $x$ and $y$, the
minimum is reached on the part of the curve $xy=b$ between $(b,1)$
and $(1,b)$. Then the claim is merely obtained by applying the
ordinary inequality between the arithmetic and geometric mean. The
results (\ref{gmin}) and (\ref{fmin}) will be used in obtaining
desired unified-entropy relations.

\subsection{Lower bounds on the sum of map and receiver entropies}\label{sc32}

Using the above preliminaries, we now derive lower bounds on the
sum of map and receiver $(q,s)$-entropies for all values of the
parameters.

\newtheorem{thm1}[lem1]{Proposition}
\begin{thm1}\label{tam1}
For $q>0$ and all real $s$, the sum of the map and receiver
$(q,s)$-entropies is bounded from below. For
$q\in(0;1)\cup(1;\infty)$ and $s\neq0$, the lower bound is written
as
\begin{align}
\rmm(\Phi)+\rmr(\Phi)&\geq\frac{\gamma}{s}{\>}
\ln_{q}\bigl(d^{s\varkappa/\gamma}\bigr)
\qquad{for{\ }all{\ }channels}
{\>}, \label{mnrs1}\\
\rmm(\Phi)+\rmr(\Phi)&\geq\frac{\gamma}{s}{\>}
\ln_{q}\bigl(d^{2s\varkappa/\gamma}\bigr)
\qquad{for{\ }unital{\ }ones}
{\>}. \label{mnrs2}
\end{align}
Here, the parameters $\gamma$ and $\varkappa$ are defined as
\begin{equation}
\gamma:=
\left\{
\begin{array}{ll}
1{\>}, & (1-q){\,}s<0{\>}, \\
2{\>}, & (1-q){\,}s>0{\>},
\end{array}
\right.
\qquad
\varkappa:=
\left\{
\begin{array}{ll}
1{\>}, & q\in(0;2]{\>}, \\
q\bigl(2(q-1)\bigr)^{-1}{\>}, & q\in[2;\infty){\>}.
\end{array}
\right.
\label{gamdf}
\end{equation}
\end{thm1}

{\bf Proof.} In the first place, we consider the case $q\in(0;1)$.
The sum of the map and receiver $(q,s)$-entropies is represented
as the function
\begin{equation}
f(x,y):=\frac{x+y-2}{(1-q){\,}s}
\ , \qquad x:=\frac{\|\D_{\Phi}\|_{q}^{qs}}{\|\D_{\Phi}\|_{1}^{qs}}
\ , \qquad y:=\frac{\|\ay_{\Phi}\|_{q}^{qs}}{\|\ay_{\Phi}\|_{1}^{qs}}
\ , \label{fudf}
\end{equation}
where $\ay_{\Phi}=|\km_{\Phi}|\in\lsp(\hh\otimes\hh)$. Suppose
also that $s>0$, then $x\geq1$ and $y\geq1$. Due to (\ref{lq2})
and (\ref{cbn0}), the anti-norms of positive matrices $\D_{\Phi}$
and $\ay_{\Phi}$ satisfy
\begin{equation}
\left(\frac{\|\D_{\Phi}\|_{q}}{\|\D_{\Phi}\|_{1}}{\>}\frac{\|\ay_{\Phi}\|_{q}}{\|\ay_{\Phi}\|_{1}}\right)^{\!q}\geq
\left(\frac{\|\D_{\Phi}\|_{1}}{\|\D_{\Phi}\|_{2}}{\>}\frac{\|\ay_{\Phi}\|_{1}}{\|\ay_{\Phi}\|_{2}}\right)^{\!2(1-q)}
\geq
\left\{
\begin{array}{ll}
d^{1-q}{\>}, & {\mathrm{for{\ }all{\ }channels}}{\>}, \\
d^{2(1-q)}{\>}, & {\mathrm{for{\ }unital{\ }ones}}{\>}.
\end{array}
\right.
\label{nrm0p}
\end{equation}
Therefore, the function $f(x,y)$ should be minimized in the domain
(\ref{dbdf}) with $b=d^{s(1-q)}$ for all quantum channels and
$b=d^{2s(1-q)}$ for unital channels. Using (\ref{fmin}), we obtain
the lower bound
\begin{equation}
\min\bigl\{f(x,y):{\>}(x,y)\in\cald_{b}\bigr\}=\frac{2}{s}
\left\{
\begin{array}{ll}
\ln_{q}\bigl(d^{s/2}\bigr){\>}, & {\mathrm{for{\ }all{\ }channels}}{\>}, \\
\ln_{q}\bigl(d^{s}\bigr){\>}, & {\mathrm{for{\ }unital{\ }ones}}{\>}.
\end{array}
\right.
\label{bun0p}
\end{equation}
Since $\gamma=2$ for $q\in(0;1)$ and $s>0$, the bound
(\ref{bun0p}) respectively concurs with (\ref{mnrs1}) and
(\ref{mnrs2}).

Defining $x$ and $y$ by (\ref{fudf}), we have $x\leq1$ and
$y\leq1$ in the case $q\in(0;1)$ and $s<0$. Since $(1-q){\,}s<0$,
the sum of the map and receiver $(q,s)$-entropies is rewritten as
the function
\begin{equation}
g(x,y):=\frac{2-x-y}{\bigl|(1-q){\,}s\bigr|}
\ . \label{gudf}
\end{equation}
Raising (\ref{nrm0p}) to the power $s<0$, we have arrived at the
following task. The function $g(x,y)$ should be minimized in the
domain (\ref{dadf}) with $a=d^{s(1-q)}$ for all quantum channels
and $a=d^{2s(1-q)}$ for unital channels.  Using (\ref{gmin}), we
obtain the lower bound
\begin{equation}
\min\bigl\{g(x,y):{\>}(x,y)\in\cald_{a}\bigr\}=\frac{1}{s}
\left\{
\begin{array}{ll}
\ln_{q}\bigl(d^{s}\bigr){\>}, & {\mathrm{for{\ }all{\ }channels}}{\>}, \\
\ln_{q}\bigl(d^{2s}\bigr){\>}, & {\mathrm{for{\ }unital{\ }ones}}{\>}.
\end{array}
\right.
\label{bun0m}
\end{equation}
Since $\gamma=1$ for $q\in(0;1)$ and $s<0$, the bound
(\ref{bun0m}) concurs with (\ref{mnrs1}) and (\ref{mnrs2}) as
well.

In the second place, we consider the case $q\in(1;\infty)$. For
$s>0$, the entropic sum is also taken as (\ref{gudf}) due to
$(1-q){\,}s<0$. Taking (\ref{lq1}) for $1\leq{q}\leq2$ and
(\ref{npqr}) for $2\leq{q}<\infty$, one gives
\begin{equation}
\left(\frac{\|\D_{\Phi}\|_{q}}{\|\D_{\Phi}\|_{1}}{\>}\frac{\|\km_{\Phi}\|_{q}}{\|\km_{\Phi}\|_{1}}\right)^{\!q}\leq
\left(\frac{\|\D_{\Phi}\|_{2}}{\|\D_{\Phi}\|_{1}}{\>}\frac{\|\km_{\Phi}\|_{2}}{\|\km_{\Phi}\|_{1}}\right)^{\!2\varkappa(q-1)}
\leq
\left\{
\begin{array}{ll}
d^{\varkappa(1-q)}{\>}, & {\mathrm{for{\ }all{\ }channels}}{\>}, \\
d^{2\varkappa(1-q)}{\>}, & {\mathrm{for{\ }unital{\ }ones}}{\>}.
\end{array}
\right.
\label{nrm1p}
\end{equation}
Here, we also used the inequality (\ref{cbn0}) and the definition
(\ref{gamdf}). Raising (\ref{nrm1p}) to the power $s>0$, the
variables $x$ and $y$ range in the domain (\ref{dadf}) with
$a=d^{s\varkappa(1-q)}$ for all quantum channels and
$a=d^{2s\varkappa(1-q)}$ for unital channels. By (\ref{gmin}), the
minimum is formally posed just as (\ref{bun0m}) but with the term
$s\varkappa$ instead of $s$ in powers of $d$ in the $q$-logarithm.
As $\gamma=1$ for $(1-q){\,}s<0$, this minimum concurs with
(\ref{mnrs1}) and (\ref{mnrs2}). For $s<0$, the entropic sum is
taken as (\ref{fudf}) due to $(1-q){\,}s>0$. Raising (\ref{nrm1p})
to the power $s<0$, the variables $x$ and $y$ range in the domain
(\ref{dbdf}) with $b=d^{s\varkappa(1-q)}$ for all quantum channels
and $b=d^{2s\varkappa(1-q)}$ for unital channels. Using
(\ref{fmin}), the minimum is formally posed as (\ref{bun0p}) but
again with the term $s\varkappa$ instead of $s$ in powers of $d$
in the $q$-logarithm. As $\gamma=2$ for $(1-q){\,}s>0$, this
minimum concurs with (\ref{mnrs1}) and (\ref{mnrs2}) as well.
$\blacksquare$

The inequalities (\ref{mnrs1}) and (\ref{mnrs2}) provide
unified-entropy trade-off relations for a given quantum channel
$\Phi$. They are an extension of the results of the paper
\cite{rprz12} with use of the family of $(q,s)$-entropies. In more
details, the physical sense of such bounds was considered in
\cite{rprz12}. When $s=1$, the formulas (\ref{mnrs1}) and
(\ref{mnrs2}) give trade-off relations in terms of Tsallis'
entropies, namely
\begin{equation}
\mathrm{M}_{q}^{(1)}(\Phi)+\mathrm{R}_{q}^{(1)}(\Phi)\geq
\left\{
\begin{array}{ll}
\gamma\ln_{q}\bigl(d^{\varkappa/\gamma}\bigr){\>}, & {\mathrm{for{\ }all{\ }channels}}{\>}, \\
\gamma\ln_{q}\bigl(d^{2\varkappa/\gamma}\bigr){\>}, & {\mathrm{for{\ }unital{\ }ones}}{\>}.
\end{array}
\right.
\label{tsrs1}
\end{equation}
Taking the limit $s\to0$, we recover the R\'{e}nyi formulation,
which is written as
\begin{equation}
\mathrm{M}_{q}^{(0)}(\Phi)+\mathrm{R}_{q}^{(0)}(\Phi)\geq
\left\{
\begin{array}{ll}
\varkappa\ln{d}{\>}, & {\mathrm{for{\ }all{\ }channels}}{\>}, \\
2\varkappa\ln{d}{\>}, & {\mathrm{for{\ }unital{\ }ones}}{\>}.
\end{array}
\right.
\label{rsrso}
\end{equation}
These trade-off relations for a single quantum channel were
originally formulated in \cite{rprz12}. Of course, we can obtain
(\ref{rsrso}) directly by taking the logarithm of both
(\ref{nrm0p}) and (\ref{nrm1p}). Since the R\'{e}nyi case was
explicitly examined in \cite{rprz12}, we refrain from presenting
the details here.

As is shown in \cite{hey06}, values of the $(q,s)$-entropy of
finite-dimensional density matrix $\bro$ are bounded from above.
Adapting this result for the considered case, we obtain
\begin{eqnarray}
\rmm(\Phi)&\leq&\frac{1}{s}{\>}\ln_{q}\Bigl(\mathrm{rank}\bigl(\D_{\Phi}\bigr)^{s}\Bigr)
\leq\frac{1}{s}{\>}\ln_{q}\bigl(d^{2s}\bigr)
\qquad (s\neq0) \ , \label{upbmn}\\
\mathrm{M}_{q}^{(0)}(\Phi)&\leq&\ln\Bigl(\mathrm{rank}\bigl(\D_{\Phi}\bigr)\Bigr)
\leq2\ln{d}
\ , \label{upbmn0}
\end{eqnarray}
since $\mathrm{rank}(\D_{\Phi})\leq{d}^{2}$. The right-hand sides
of (\ref{upbmn}) and (\ref{upbmn0}) give the upper bound on
the receiver $(q,s)$-entropy as well. The value (\ref{upbmn}) is also
obtained from (\ref{mnrs2}) for $q\in(0;1)$ and $s<0$ as well for
$q\in(1;2]$ and $s>0$. Here, the sum of the map and receiver
$(q,s)$-entropies is not less than the maximal possible value for
each of them. Thus, they may be regarded as mutually complementary
characteristics of a single quantum channel.

\section{Conclusions}\label{sec4}

We have obtained two-parametric family of entropic bounds for a
single quantum channel. These entropic relations are a
unified-entropy extension of the relations recently formulated in
\cite{rprz12}. In general, an existence of such lower bounds has
the physical relevance as some trade-off property in a single
measuring process \cite{rprz12}. For a given quantum channel, two
entropic characteristics are expressed in terms of singular values
of the dynamical and superoperator matrices, respectively. These
matrices are related to the Jamio{\l}kowski--Choi representation
and the natural representation of the channel. It is significant
that the two matrices are connected by the reshuflling operation.
Hence, they have the same Schatten $2$-norm. Entropic trade-off
relations for a single quantum channel have been formulated in
terms of the map and receiver $(q,s)$-entropies for all considered
values of the parameters. The derivation is essentially based on
some inequalities for the Schatten norms and anti-norms. Such
inequalities could be interesting in other contexts, in which we
deal with matrices related by reordering the same matrix entries.
The cases of arbitrary and unital quantum channels were both
examined. In the latter case, when bistochastic maps are treated,
we see the following. For a wide range of the parameters $q$ and
$s$, the lower bound on the sum of two entropies coincides with
the upper bound on each of the summands. This result gives an
additional reason for the fact that the map and receiver entropies
characterize mutually complementary properties of a given quantum
channel. Hence, it is interesting to study entropic bounds for
more specialized types of quantum channels, including
unistochastic maps and degradable channels. This issue could be
the subject of a separate research.

\vspace{1.0cm}

redpajama_set_name: RedPajamaArXiv


Originally published in 1935, this volume provides a discussion of the structures of belief and practice in popular Hinduism. Taking into account the complexity of Hinduism, and its position as a composite religion of many diverse elements, the text goes on to find certain common elements which draw together its various aspects. The relationship between Hinduism and social organisation is also considered, with detailed discussion regarding the importance of the caste system. This book will be of value to anyone with an interest in historical interpretations of Hinduism and religious studies in general.


Follow the trail of thousands of emigrants from the thatched cottages of Ulster, on board a full-scale emigrant sailing ship to the log cabins of the American Frontier.
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Home Our Top Picks Anti-religious group wants football coach investigated for promoting 'Christianity to his students'
Anti-religious group wants football coach investigated for promoting 'Christianity to his students'
Liberty-Benton Eagles' Football/ Facebook
The Freedom from Religion Foundation (FFRF), whose idea of religious freedom is barring people from freely expressing their religion to other people while doing anything remotely government-funded, is going after an Ohio high school football team whose coach "is using his position to promote Christianity to his students."
As is their usual practice, the FFRF claimed that an anonymous "community member" complained to the organization and brought its scrutiny onto the Liberty-Benton Eagles football team, according to reporting by The Courier in Ohio.
The letter that FFRF sent to district Superintendent Mark Kowalski, dated Sept. 1, reported that "Coach [Scott] Garlock requires players to lead prayers at team meals, leads students in the Lord's Prayer before games, and leads students in a post-game prayer. Our complainant reports that Coach Garlock started these practices many years ago when he was the team's coach and that he passed them onto the next coach, who also implemented these practices until Coach Garlock became head coach again this year and resumed these practices himself."
The letter came from a staff attorney with the nonprofit, which is based in Madison, Wis.
"We also understand there is a school-sponsored prayer that takes place before each game. We understand this 'Friday Night Prayer' tradition involves the school marching band playing 'Amazing Grace,' and then leading parents, families and cheerleaders onto the field for prayer," the letter said.
Saying that the U.S. Supreme Court has continually struck down school-sponsored prayer in public schools, the FFRF called both practices illegal, and demanded that the coach's freedom of speech be nullified.
The superintendent responded to the complaint in a letter dated Sept. 29. He did not call the coach's actions illegal, but did say that measures were taken to address the complaints. Kowalski's response also said staff members would be briefed about "the sensitivities surrounding school employees being involved in prayer with students on school grounds and on school time."
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text:
Q: "SOLVED" object after be created with firstOrCreate have 0 as Id in php and right id in DB i saving object to DB with firstOrCreate eloquent method.
code:

        $card = Card::firstOrCreate(
            [
                'id' => $product->id
            ],
            [
                'foil' => $data->foil,
                'nonfoil' => $data->nonfoil,
                'oversized' => $data->oversized,
                'reserved' => $data->reserved,
                'booster' => $data->booster,
                'scryfallCollectorNumber' => $data->collector_number,
                'fullArt' => $data->full_art,
                'promo' => $data->promo,
                'story_spotlight' => $data->story_spotlight,
                'textless' => $data->textless,
            ]);
        \Debugbar::info($card->id);

in DB is for example 10258 but in debugbar is 0

A: [SOLVED]

*thank you porloscerros.

That was the problem. I didnt set incrementing to false in model.
public $incrementing = false;

*

*dd($card->id); gives 0 too.

2., 4. that happend only whew new row was created.
with right Id in DB and object was returned with 0 Id.

redpajama_set_name: RedPajamaStackExchange


text:
by Noah Yoo
Billy Corgan Teases Virtual Reality Experience With New Music Video
William Patrick Corgan's new "Aeronaut" video sends him through colorful digital landscapes
William Patrick Corgan has shared the 2-D version of a new VR video for "Aeronaut," which finds the Smashing Pumpkins frontman seated in front of a glowing grand piano that seemingly traverses throughout time and space as he sings the song. The song is taken from Corgan's new solo album Ogilala. Corgan recruited San Francisco artist and filmmaker Danny Bittman to create the virtual world, which will be made fully available to the public in early 2018. He recently covered Miley Cyrus' hit "Wrecking Ball" and also went on "CBS This Morning" to discuss his name change.


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Mayanti Langer Wiki, Age, Family, Caste, Husband, Biography & More – StarBio
Post category:Television
Post last modified:April 12, 2018
Mayanti Langer
Mayanti Langer Binny or Maya is a renowned sports anchor and journalist. Due to her in-depth knowledge of different games and beautiful ways of anchoring, she receives many contracts from different sports channels every year. People love to watch the beginning and consequences of the games that she presents after deep analysis and investigation with the sports experts and experienced players. Check out Mayanti Wiki, Height, Weight, Age, Boyfriend, Family, Husband, Biography, Facts & More.
Mayanti Langer With Cricket Experts Anil Kumble, Dav Whatmore and Aakash Chopra Discussing 2018 IPL
Biography/Wiki
Family, Caste & Boyfriend
Mayanti was born on 8 February 1985 in Delhi, India. As her father Sanjiv Langer was an army man in Indian Army, she brought up in a cantonment and used to do various sports activities in her childhood. During this time, she developed an interest in sports, especially in football.
READ MORE Sumeet Vyas Wiki, Age, Height, Weight, Family, Wife, Biography & More – StarBio
She is a talented and beautiful lady with a fit physique of 36-32-38 and 5′ 6″ height. She has dark brown eyes and black hair.
She belongs to a Christian Indian family in which her father Sanjiv Langer is an Indian Army Personnel and mother Preminda Langer is a teacher.
Mayanti Langer's Father Sanjiv Langer
Mayanti Langer's Mother Preminda Langer
She met her future husband cricketer Stuart Binny, son of the former Indian cricketer Roger Binny, at the sports event in 2012, and after dating for around 6 months, they got married in the same year. She is older (4 months) than Stuart and living a happy married life with him for almost six years.
Mayanti Langer With Her Husband Stuart Binny
Mayanti is graduated in Arts from the Hindu College in New Delhi. After graduation, she was pursuing the masters in arts. At this time, officials of Zee Sports came to know about her through the Indian Youth Soccer Association (IYSA) league in Delhi, that she used to run a few years ago, and they called her for an audition. After being selected and successful performance, she continued her journey in this field.
READ MORE Lilliput (Actor) Height, Weight, Age, Wiki, Wife, Family
In 2010, her first broadcasting on TV was as an anchor for the FIFA beach football league. As a host, her first live event was the football Federation Cup in Goa. Despite being nervous and inexperienced, she got into the action, and took it as a conversation among her group of friends over a particular topic, without fearing from the cameras or millions of viewers.
Till now, she has hosted various tournaments- 2010 Commonwealth Games, 2010 FIFA World Cup (broadcast on ESPN), 2011 Cricket World Cup, First Indian Super League in 2014, and 2015 ICC Cricket World Cup. She has hosted 6 World Cups across 3 different sports successfully. She has also worked as an associate producer of a football show that she used to anchor for Zee Sports.
Mayanti Langer With Cricketer Anil Kumble
Initially, she wanted to become a graphic designer and never thought about appearing on TV, but after her studies, when she got an opportunity of anchoring for the FIFA beach football, via a television channel Zee Sports, she accepted it and decided to continue further in this field.
In an interview, she revealed the fact that she used to cover the Olympics with a long 8-hour stint daily.
She likes to watch football and cricket on TV.
She is a fan of Vietnamese cuisine and she enjoys travel Europe with her husband.
Moroccan-American rapper and songwriter French Montana is her favourite artist.
She considers the Chinnaswamy stadium (Bangalore) very beautiful.
Her favourite commentator is John Dykes, whereas, her favourite co-hosts are Jatin Sapru and Arjun Pandit.
According to Mayanti, the 2015 WC cricket match between India and Pakistan at Adelaide is the best match that she ever been a part of.
READ MORE Deepthi Sunaina Wiki, Age, Height, Weight, Family, Caste, Biography & More – StarBio


text:
Justia US Law US Codes and Statutes US Code 2011 US Code Title 29 - Labor Chapter 8 - FAIR LABOR STANDARDS (§§ 201 - 219) Section 217 - Injunction proceedings
View the 2020 US Code | View Previous Versions of the US Code
2011 US Code
Chapter 8 - FAIR LABOR STANDARDS (§§ 201 - 219)
Section 217 - Injunction proceedings
Publication Title United States Code, 2006 Edition, Supplement 5, Title 29 - LABOR
Category Bills and Statutes
Collection United States Code
SuDoc Class Number Y 1.2/5:
Contained Within Title 29 - LABOR
CHAPTER 8 - FAIR LABOR STANDARDS
Sec. 217 - Injunction proceedings
Contains section 217
Laws in Effect as of Date January 3, 2012
Positive Law No
Disposition standard
Source Credit June 25, 1938, ch. 676, §17, 52 Stat. 1069; Oct. 26, 1949, ch. 736, §15, 63 Stat. 919; Pub. L. 85-231, §1(3), Aug. 30, 1957, 71 Stat. 514; Pub. L. 86-624, §21(c), July 12, 1960, 74 Stat. 417; Pub. L. 87-30, §12(b), May 5, 1961, 75 Stat. 74.
Statutes at Large References 52 Stat. 1069
63 Stat. 919
75 Stat. 74
92 Stat. 3781
Public Law References Public Law 85-231, Public Law 86-624, Public Law 87-30, Public Law 96-70
29 USC § 217 (2011)
§217. Injunction proceedings
The district courts, together with the United States District Court for the District of the Canal Zone, the District Court of the Virgin Islands, and the District Court of Guam shall have jurisdiction, for cause shown, to restrain violations of section 215 of this title, including in the case of violations of section 215(a)(2) of this title the restraint of any withholding of payment of minimum wages or overtime compensation found by the court to be due to employees under this chapter (except sums which employees are barred from recovering, at the time of the commencement of the action to restrain the violations, by virtue of the provisions of section 255 of this title).
(June 25, 1938, ch. 676, §17, 52 Stat. 1069; Oct. 26, 1949, ch. 736, §15, 63 Stat. 919; Pub. L. 85–231, §1(3), Aug. 30, 1957, 71 Stat. 514; Pub. L. 86–624, §21(c), July 12, 1960, 74 Stat. 417; Pub. L. 87–30, §12(b), May 5, 1961, 75 Stat. 74.)
1961—Pub. L. 87–30 substituted ", including in the case of violations of section 215(a)(2) of this title the restraint of any withholding of payment of minimum wages or overtime compensation found by the court to be due to employees under this chapter (except sums which employees are barred from recovering, at the time of the commencement of the action to restrain the violations, by virtue of the provisions of section 255 of this title" for ": Provided, That no court shall have jurisdiction, in any action brought by the Administrator to restrain such violations, to order the payment to employees of unpaid minimum wages or unpaid overtime compensation or an additional equal amount as liquidated damages in such action".
1960—Pub. L. 86–624 struck out reference to the District Court for Territory of Alaska.
1957—Pub. L. 85–231 included the District Court of Guam within the enumeration of courts having jurisdiction of injunction proceedings.
1949—Act Oct. 26, 1949, included a more precise description of United States courts having jurisdiction to restrain violations and inserted proviso denying jurisdiction to order payment of unpaid minimum wages, overtime, and liquidated damages in injunction proceedings.
Effective Date of 1961 Amendment
Amendment by Pub. L. 87–30 effective upon expiration of one hundred and twenty days after May 5, 1961, except as otherwise provided, see section 14 of Pub. L. 87–30, set out as a note under section 203 of this title.
Amendment by Pub. L. 85–231 effective upon expiration of ninety days from Aug. 30, 1957, see section 2 of Pub. L. 85–231, set out as a note under section 213 of this title.
Amendment by act Oct. 26, 1949, effective ninety days after Oct. 26, 1949, see section 16(a) of act Oct. 26, 1949, set out as a note under section 202 of this title.
Termination of United States District Court for the District of the Canal Zone
For termination of the United States District Court for the District of the Canal Zone at end of the "transition period", being the 30-month period beginning Oct. 1, 1979, and ending midnight Mar. 31, 1982, see Paragraph 5 of Article XI of the Panama Canal Treaty of 1977 and sections 2101 and 2201 to 2203 of Pub. L. 96–70, title II, Sept. 27, 1979, 93 Stat. 493, formerly classified to sections 3831 and 3841 to 3843, respectively, of Title 22, Foreign Relations and Intercourse.
Transfer of Functions
Functions relating to enforcement and administration of equal pay provisions vested by this section in Secretary of Labor transferred to Equal Employment Opportunity Commission by Reorg. Plan No. 1 of 1978, §1, 43 F.R. 19807, 92 Stat. 3781, set out in the Appendix to Title 5, Government Organization and Employees, effective Jan. 1, 1979, as provided by section 1–101 of Ex. Ord. No. 12106, Dec. 28, 1978, 44 F.R. 1053.
Disclaimer: These codes may not be the most recent version. The United States Government Printing Office may have more current or accurate information. We make no warranties or guarantees about the accuracy, completeness, or adequacy of the information contained on this site or the information linked to on the US site. Please check official sources.


Secret Bangs Reviews - Glamorous in SECONDS?
Secret Bangs is a hairpiece for women that claims to give you instant bangs without scissors, commitment, or an expensive salon appointment. They state Secret Bangs comes in 13 colors that will blend with your hair and 2 interchangeable headbands for more variety and will allow you to go from "flirty casual" to "daytime professional" to "nighttime glamorous" in seconds.
What is Secret Bangs Made From and How Does It Work?
Secret Bangs states its hair follicles are made from a proprietary blend of polyester that is coated in keratin, a fibrous protein found in human hair and used in many hair extension or hair loss concealing products. They insist this makes it look, move, and feel like real human hair.
Secret Bangs is said to come in 13 multi-blended salon inspired colors, ranging from Jet Black to Platinum, so they promise you will find one that matches your hair or they'll give you your money back.
Secret Bangs works by being attached to a headband, which they state comes in Tortoise and Black. To use Secret Bangs, they instruct you to choose the headband you desire and attach the hairpiece to it via a Velcro-like strip. Then, place the headband over your head and, voila! Instant bangs that they claim are effortless and natural looking that will give you a variety of looks you can wear to the office or the nightclub. If you would like more volume instead, they tell you to reverse the headband and let the Secret Bangs fall over the back of your head.
Secret Bangs uses the celebrity power of Kristin Cavallari, star of reality series Laguna Beach: The Real Orange County and The Hills. They also appear to set up a camera at a shopping mall and let real women try it on. It should be noted that while these women appear to be fascinated and happy with their Secret Bangs, the ones that didn't like it ended up on the cutting-room floor.
Secret Bangs says their product is washable and should be cleaned after 5-7 times being worn, but you should brush it out after every use. You should use mild shampoo with lukewarm water, rinse, and let dry. They caution you to not brush out Secret Bangs while wet. You can cut or style Secret Bangs with water-soluble products but do not add color. They state that the life of your Secret Bangs will vary depending on how often you wear them and how well you take care of them.
What Does Secret Bangs Cost?
Secret Bangs sells on the website for $29.99 for one set, which includes free shipping. If you would like to order additional Secret Bangs, they are $19.99 each, which also includes shipping.
Secret Bangs promises that it will match and blend with your hair or your money back, and they give you 30 days to try it. If within that time you are not satisfied, you can return it for your money back, minus what it costs you to ship it back to them.
Bottom Line: Are Secret Bangs a Good Hair Accessory?
As of this writing (July 2015) Secret Bangs are still a new product and we couldn't find any customer reviews (aside from the glowing testimonials on their own website).
However, Secret Bangs appears to be brought to you by the same people who sell Secret Cover and Secret Extensions, two other "secret" hair products to add volume and length, respectively. Both of these products receive overwhelmingly negative reviews on our website from customers who tried them. The main complaints are long shipping times, lousy customer service, and a flimsy product that is "fake looking" and doesn't work as advertised.
Will Secret Bangs receive the same harsh comments from people who tried them? (They appear to be made of the same materials.) If you order Secret Bangs, please share your experience so we can let others know if they are great or a waste of money below!
I ordered the secret bangs twelve days ago, and they came today. They were lighter than the picture, so keep that in mind. They are very soft and silky. They have three little combs inside that you attach them with, they do not clip. My hair is short, so they did not stay in well. I am returning it. You do need to get an authorization code by phone to return them but they were very nice, I experienced a short wait and it's very easy. They are worth a try, I wish my hair was longer.


I was fortunate enough to be located in a hotbed of activity on Hainan Island. While Schmidt-Curley was working on a 22 course resort for Mission Hills (later reduced to 10) there was even more work on the Island with stunning seaside courses being constructed by Coore & Crenshaw, Tom Doak, and a 36 hole project by Tom Weiskopf. Schmidt-Curley also had numerous projects in the design and construction phase (in addition to the Mission Hills project) with a variety of courses on and off the Island. I will go through some of these projects in detail throughout the series.
One of the first discovery trips I made in China was a visit to the Tom Weiskopf designed, Dunes at Shenzhou Peninsula in 2009. I was fortunate to see the course under construction where I was able to gain an understanding of how much of the site was manipulated and how uninteresting the property was in its original form as an old fish farming village with little to no elevation change. When you work in sand the possibilities for a creative design are pretty much limitless but it sure helps when the views and rock formations you have to work with are absolutely breathtaking. The team did a great job restoring native plants and grasses to an intricate system of faux dunes, we would later use a similar palette of plant life at Mission Hills Haikou to create a sandy dunescape on one of our 10 courses. This golf course is an absolute must see for anyone visiting Hainan Island.
During the 2011 Chinese New Year a few of us on the Schmidt-Curley team made a golf trip to Kunming to play the reigning #1 course in China, Spring City and to visit a few of the Schmidt-Curley courses under construction. Spring City is a 36 hole resort and the old dog so to speak in the Chinese golf industry, the conditioning is always top notch as the area's location and elevation made for spring like weather year round.
A shot of the bunkering on the Mountain course at Spring City.
Other stops made on our trip included a few rounds at the recently opened, 54 hole, Stone Forest International Country Club and construction visits to Yulong Bay, Jiadali, and Sun Hill golf projects. All four of these courses faced some opposition from the government after they reinforced a moratorium on golf development. Jiadali has still not finished construction but it looks like the other 3 projects have survived, for now. Even with very serious environmental controls, such as capturing and re-using all on site water and the installation of impermeable liners underneath turf (to prevent chemicals from entering the groundwater), some holes still needed to shifted away from the lake shoreline at Sun Hill to meet the government's demands. Meanwhile, sewage and chemical runoff from nearby farmland seems to be ignored.
Another highlight of my golf travels back on Hainan Island was a visit to the Coore & Crenshaw designed Shanqin Bay, which was under construction at the time. No machines were running and their shapers were holed up on site as they faced numerous delays that anybody working in China would understand. I made a follow up visit a year or two later to play the golf course with Brian Curley and Travelin' Joe Passov. I knew there was huge potential for this course to become one of the best in China when I made my first site visit, the rolling topography and brilliant routing that plays along the cliff tops overlooking the south china sea and tumbles down to the beach and back up again is one of a kind in China. The team did a great job incorporating native plant materials on their bunker edges (like wild pineapple), and preserved old rock walls giving the course a unique and vintage character.
Despite its $1,000,000 membership fee there are always a few gentle reminders of one's humble beginnings in China.
Final grassing at Tom Doak's Simapo Island in Hainan, China.
A few more highlights of my golf travels in China were playing some of the Schmidt-Curley designed courses on the Island like, Agile Clearwater Bay, Sanya Dragon Valley, White Stone Hot Spring Resort and a preview round at Simapo Island with some old work mates at Renaissance Golf Design. Although the golf course is currently shut down by the Chinese government it was great catching up with some of the guys I had met almost 6 years earlier while working as a construction intern in Montana. Now here we were on the other side of the globe, practically working next door.


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Cabinet approval granted to amend 2 key laws in Sri Lanka
The cabinet of Ministers has granted approval to amend two key laws in Sri Lanka.
Cabinet approval has been granted to amend the Land Acquisition Act and the Assistance to and Protection of Victims of Crime and Witnesses Act, No. 04 of 2015.
The Land Acquisition Act is to be amended to simplify the process of acquiring land in Sri Lanka.
The amendment will minimize the time taken for the procedure, such as land acquisition process and the payment of compensation.
Meanwhile, Section 10 of the Assistance to and Protection of Victims of Crime and Witnesses Act, No. 04 of 2015 will be amended as approved by the cabinet.
The amendment will allow suspects to file bail applications at the High Court instead of the Appeal Court. (NewsWire)


This article is about the capital city of Zakuul. You may be looking for other uses of the word.
The Spire, also known as Zakuul City, was the capital city of the planet Zakuul. A shining golden metropolis that sprawled outwards from the central tower, the Spire was a vertical city, with skyscrapers and pyramid-shaped buildings suspended above each other in a climb nearly to the atmosphere. All roads on Zakuul eventually led to the Spire, which was built atop the Old World—Emperor Valkorion's first attempt at building a city, which had not been grand enough for him. The very peak of the Spire reached out past the planet's atmosphere and contained the Emperor's throne room, where the Eternal Throne was located.


Last weekend, news broke that Justin Bieber and Hailey Baldwin were engaged. Immediately, attention turned to Justin's longtime on-again, off-again girlfriend, Selena Gomez, because Jelena shippers had to know how she was taking the news.
The answer? She's taking it just fine because she's an adult and busy with her own life. Selena was spotted filming her upcoming zombie movie (tentatively titled Killed the Head) in upstate New York and looking one thousand percent happy and carefree.
She was all smiles in a picture with her costar, Austin Butler. Both actors were covered in (we assume) fake blood and having a great time fighting fake zombies.
Honestly, that's exactly the right attitude to have. There is plenty of happiness in the world to go around. Justin and Selena have tried to make things work off and on since 2010 and split again earlier this year.
Justin confirmed the engagement this week in a lengthy Instagram post.
Was gonna wait a while to say anything but word travels fast, listen plain and simple Hailey I am soooo in love with everything about you! So committed to spending my life getting to know every single part of you loving you patiently and kindLY. I promise to lead our family with honor and integrity letting Jesus through his Holy Spirit guide us in everything we do and every decision we make. My heart is COMPLETELY and FULLY YOURS and I will ALWAYS put you first! You are the love of my life Hailey Baldwin and I wouldn't want to spend it with anybody else. You make me so much better and we compliment eachother so well!! Can't wait for the best season of life yet!. It's funny because now with you everything seems to make sense! The thing I am most excited for is that my little brother and sister get to see another healthy stable marriage and look for the same!!! Gods timing really is literally perfect, we got engaged on the seventh day of the seventh month, the number seven is the number of spiritual perfection, it's true GOOGLE IT! Isn't that nuts? By the way I didn't plan that, anyways My goodness does feel good to have our future secured! WERE GONNA VE [sic] BETTER AT 70 BABY HERE WE GO! "He who finds a wife finds a good thing and obtains FAVOR from the Lord!" This is the year of favor!!!!
Congrats to the happy couple and to the very content ex.
Biste li operirali tijelo s lizanjem?
Cardi B og Nicki Minaj Spottet sammen på Met Gala – Er Cardi B og Nicki Minaj Feud over?
Cheryl Burke derina rauginimą ir tai, ką jis patinka plaukų ir makiažo kėdėje * DWTS *!


text:
Q: How to resolve error in pom.xml - android eclipse application? I have error in pom.xml file. I don't understand what means xml elements in this file. I'm using eclipse's maven plugin version 1.4.0.
Is there problem in pom.xml elements, versions of plugins, platforms...  The code in pom.xml file is:
     <?xml version="1.0" encoding="UTF-8"?>
<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/maven-v4_0_0.xsd">
    <modelVersion>4.0.0</modelVersion>
    <groupId>at.axtesys</groupId>
    <artifactId>soljoy</artifactId>
    <version>0.0.1-SNAPSHOT</version>
    <packaging>apk</packaging>
    <name>soljoy</name>

<properties>
    <project.build.sourceEncoding>UTF-8</project.build.sourceEncoding>
    <platform.version>4.1.1.4</platform.version>
    <android.plugin.version>3.9.0-rc.1</android.plugin.version>
</properties>

<repositories>
    <repository>
        <id>codehaus</id>
        <url>http://repository.codehaus.org/org/codehaus</url>
    </repository>
</repositories>

<dependencies>
    <dependency>
        <groupId>com.google.android</groupId>
        <artifactId>android</artifactId>
        <version>${platform.version}</version>
        <scope>provided</scope>
    </dependency>

    <dependency>
        <groupId>org.codehaus.jackson</groupId>
        <artifactId>jackson-mapper-asl</artifactId>
        <version>1.9.13</version>
    </dependency>
    <dependency>
        <groupId>com.loopj.android</groupId>
        <artifactId>android-async-http</artifactId>
        <version>1.4.4</version>
        <type>jar</type>
    </dependency>

    <dependency>
        <groupId>com.github.tony19</groupId>
        <artifactId>logback-android-core</artifactId>
        <version>1.1.1-2</version>
    </dependency>
    <dependency>
        <groupId>com.github.tony19</groupId>
        <artifactId>logback-android-classic</artifactId>
        <version>1.1.1-2</version>
    </dependency>
    <dependency>
        <groupId>org.slf4j</groupId>
        <artifactId>slf4j-api</artifactId>
        <version>1.7.6</version>
    </dependency>

</dependencies>

<build>
    <finalName>${project.artifactId}</finalName>
    <sourceDirectory>src</sourceDirectory>
    <pluginManagement>
        <plugins>
            <plugin>
                <groupId>com.jayway.maven.plugins.android.generation2</groupId>
                <artifactId>android-maven-plugin</artifactId>
                <version>${android.plugin.version}</version>
                <extensions>true</extensions>
            </plugin>
        </plugins>
    </pluginManagement>
    <plugins>
        <plugin>
            <groupId>com.jayway.maven.plugins.android.generation2</groupId>
            <artifactId>android-maven-plugin</artifactId>
            <executions>
              <execution>
                <goals>
                  <goal>deploy</goal>
                </goals>
              </execution>
            </executions>
            <configuration>
                <sdk>
                    <platform>19</platform>
                </sdk>
                <undeployBeforeDeploy>true</undeployBeforeDeploy>
            </configuration>
        </plugin>
    </plugins>
</build>

Error is:
Failure to transfer org.apache.maven.wagon:wagon-provider-api:pom:2.10 from https://repo.maven.apache.org/maven2 was cached in the local repository, resolution will not be reattempted until the update interval of central has elapsed or updates are forced. Original error: Could not transfer artifact org.apache.maven.wagon:wagon-provider- api:pom:2.10 from/to central (https://repo.maven.apache.org/maven2): repo.maven.apache.org

Is problem in some configuration parametar or versions of maven plugin in pom.xml file and my eclipse version of plugin?

A: The error contains the Maven coordinates org.apache.maven.wagon:wagon-provider- api:pom:2.10 - notice the space between provider- and api? Might this be the culprit?
If this is not the issue (and just a copy'n'paste problem) I'd check if the artifact can be fetched if you force its re-fetch via the -U Maven option.


text:
Q: Beacon_Triangulation_python_centroid
*

*I am working on Beacon Triangulation Algorithm using Python. I have beacon data from the reader and calculating the distance using RSSI value. can anyone please guide me how to approach this method?

*I am reading a text file which has large no of RSSI values. I am unable to process these large no of values. Let say I have 30 RSSI values in a file. How can I calculate 30 distance values using these values?

*Any method to calculate the centroid of the intersection of three circles?
Thanks


The window dressing associated with visual merchandising is currently an essential tool to connect with a new typology of consumer, more critical and informed, who is looking for a meaningful interaction with the brand in its selling space.
In an increasingly competitive and dynamic market, the window dresser can use their specific tools to generate innovative environments that become the first line of brand identity construction and, with it, design retail spaces based on creativity, staging and the use of new information technologies.
This course aims to approach the retail universe through window dressing, analyze the latest trends in the sector and generate innovative concepts and productions that provide experiences within the new paradigm of relationship between brand and consumer.
Certification: Shop Window Design - Design of Experiences in the Retail Space (Summer Course).
- Understanding the current situation and the latest trends in shop window design and visual merchandising.
- Mastering the different specific tools of window dressing and visual merchandising integrated into commercial spaces.
- Learning how to integrate window dressing and visual merchandising principles with communication campaigns and marketing strategies for each brand.
- Creating, designing and producing a creative concept for the facade, the shop windows and the interior space of a store.
Designers, architects, window dressers and professionals directly related to trade, design and/or fashion.
Discover the creations of our Interior Design students.


text:
Melville House Books
Moby Lives!
The Jane Austen Rules
What's a strong, independent-minded woman supposed to do in a world of insipid dating guides? Witty scholar Sinéad Murphy responds by asking: Who has more time-tested secrets than Jane Austen, whose novels continue to captivate us—read after read—almost two hundred years later?
Whether you can recite paragraphs from Pride and Prejudice or just admire Colin Firth in his wet T-shirt, the romance of Jane Austen's world is one you'll never forget. Does love like that even exist today? Yes, it does!
If you look closely at Jane Austen's books, as Murphy has, you'll discover Austen's countless tips for women on finding the right leading man, navigating the ups and downs of courtship, and building a happy, independent life for yourself.
You'll also learn:
• How to flirt like a regular Lizzy Bennet.
• To lead a conversation with a man (even if he's leading the dance).
• When to ignore advice from your girlfriends and listen to your mother.
• How to discuss your future with your own Mr. Darcy.
Whether you're in the throes of early dating or pondering a leap in a long-term relationship, The Jane Austen Rules is your essential guide to approaching love with, well, sense and sensibility.
Paperback ($12.75) EPUB ($11.15) PDF ($11.15) KINDLE ($11.15)
Create a collection with the handle of related and add some products to it for them to be displayed here.
Melville House / 145 Plymouth St, at Pearl St / Brooklyn, New York


Isaacson does an amazing job of recounting Franklin's impressive life and how it helped shape America's values and character. Franklin rose through the ranks to become one of the world's most foremost scientist, writer, inventor, diplomat and political leader.
So impressive to me how many different fields Franklin was successful in. He took practical and actionable steps in every one of these fields and I think that is what set him apart. He did not waste much time on theorizing or on other pursuits that would not have some immediate benefit.
This entry was posted in Books and tagged America, Benjamin Franklin, History, Walter Isaacson on March 11, 2015 by Blas.


Duncan Farmer looks at the possibility of better mortgage deals for energy-efficient properties.
Companies and other organisations of all shapes and sizes are being urged to go greener, and UK Finance, the body that represents banks and building societies, wonders whether mortgage lenders could do their bit.
It is hard to see how, but in a blog post Carla Sateriale, has tried to examine what lenders are doing and what more they could do to save the planet. She says that some smaller firms have had green mortgages for a while but that they have been a mainstream product for only the past 12 months.
The trouble with theory, she says, is that there is no suggestion that environmental credentials are any greater a factor than any other aspect of the borrower's lifestyle or spending habits. "It is possible that consumers who purchase eco-friendly properties may be more conscientious than the average consumer, which may motivate both their preferences for green products and their financial behaviours," she says.
She concludes that it is too early tell whether the green credentials of a borrower or their home have any bearing at all on what matters to most the organisation lending them the money to buy it – their chances of getting it back.


text:
I Need to Get This Off My Chest: Seth Cohen Was the WORST Character on The O.C.
Why Seth Cohen Was the Worst on The O.C.
6 March 2019 by Perri Konecky
Image Source: Everett Collection
Please bear with me, because I'm going where no '90s baby has gone before. It's uncharted territory and quite possibly the most jarring position of devil's advocate that's ever been played, but I'm about to tell you why Seth Cohen was the f*cking worst on The O.C.. If you don't want to ruin your perception of the so-called nice boy of Newport, I don't recommend reading further. But if you're ready to see the characters of your favourite early 2000s show in a whole new light, buckle up and enjoy the ride.
I recently found myself with some time on my hands. Game of Thrones is taking its sweet time to return for season eight, and there's only so many times I can rewatch Curb Your Enthusiasm and Entourage episodes, so I decided to binge all four seasons of The O.C. on Hulu. As one of my favourite shows growing up, I figured it would be interesting to relive all the excitement (and drama) of the OG "core four" — Ryan Atwood (Benjamin McKenzie), Seth Cohen (Adam Brody), Summer Roberts (Rachel Bilson), and Marissa Cooper (Mischa Barton) — as an adult. But after just a few episodes into season one, it occurred to me that everything I thought about the Ryan-Seth dynamic in my preteen years is quite the opposite when revisited in my twenties.
The second Ryan arrives at the Cohen's gorgeous Newport Beach home, we know he's poised to be the show's bad boy. (I mean, that choker alone made my middle school self weak in the knees.) We then see Seth hunched over playing video games on the floor of the living room, and as far as first impressions go, he comes off as a sweet, harmless dude. After the two get acquainted and the season progresses, however, adult me came to realise that Ryan was actually the nice guy, while Seth was the wooooooorst. (No hate to Adam Brody, I love you and I think you're adorable.)
Please note: I'm mainly referring to season one Seth being the worst. While he slightly matures seasons two through four, he peaked in his Seth-ness during season one.
Anyone who's ever seen or heard about the series likely knows that Seth is obsessed with Summer. From the day she recited that mermaid poem in sixth grade, Seth was smitten. (Ironically we find out in season four that Summer actually stole the poem from Taylor Townsend.) The next year, he was heartbroken when Summer RSVP'd yes to his bar mitzvah and never showed up (it was also the day of Luke's birthday party). Years later and still very much head-over-heels, he names his sailboat the "Summer Breeze," while she still has yet to acknowledge his existence. Seth and Summer finally connect after Ryan gets the two of them invited to Holly's house party, and eventually Summer realises how much he cares about her.
"[I] came to realise that Ryan was actually the nice guy, while Seth was the wooooooorst."
So, tell me WHY Seth is willing to risk it all for sweet Anna Stern (played by Samaire Armstrong) when she transfers to the Harbor School. Sure, Anna's interest in comic books is something Summer can't relate to, but really, Seth? Really? You're finally in a good place with Summer and you decide to put that on the line for your lab partner? This results in the first of many frustrating love triangles that play out in the series.
After Summer and Anna give Seth an ultimatum and demand he picks one of them over Thanksgiving, he backs out and says he can't choose. Yep, even after Summer wears that Wonder Woman costume, Seth eventually chooses Anna. Never one to back down, Summer then inserts herself into Seth and Anna's relationship, eventually driving them apart and so that she and Seth can get back together. Whew. Crisis averted, right? Wrong.
Once Summer break rolls around, Ryan decides to go back to his hometown of Chino, CA. And what does Seth do? He disappears to Portland, OR, to live with Luke, leaving Summer only a damn note before sailing away. With Seth out of the picture, she eventually starts dating the the hotter, water-polo-playing version of him: Zach Stevens.
Some time after Anna moves back to Pittsburgh, Seth starts dating the superhot Alex (played by Olivia Wilde), who might I add is waaaay out of his league, yet he still manages to perseverate about Summer's relationship with Zach. Seth proceeds to wreck Summer's relationship with Zach, Zach's relationship with Summer's dad, and even Summer's relationship with Zach's family when she leaves him at the airport and cancels her trip to Italy with the Stevens family. Seth is literally having sleepovers at Alex's apartment and showing up to school in the same clothes from the day before, yet whining about his fears that Summer and Zach are going to have sex? Really?!
While Seth is busy sabotageing relationships left and right, Ryan is out here making huge romantic gestures to Marissa, Lindsay (who turned out to be Caleb Nichol's illegitimate love child), and Theresa, his first love. Ryan saves Marissa from an obsessed Oliver, a depressed Johnny, and a rage-filled Volchok, yet Seth can't even save himself from his own damage?
Fast forward to later in the series when Summer and Seth are back together. Everything should be perfect because they're finally reunited, but disaster inevitably strikes. Seth and Ryan go to Florida for Spring break to visit Sofia "the Nana" Cohen, and they end up on TV for "MVN Spring Break" participating in a whipped cream contest. While hanging out at her now-friend Zach's house, Summer watches Seth kiss a random girl on live television, so, she proceeds to kiss Zach over a bowl of gnocchi (my own personal dream come true). So, of course, Seth reacts by getting mad at Summer for kissing Zach, even though he's the one who messed up in the first place.
Now, let's move on to his compulsive lying problem. After smoking a few joints and blowing his Brown interview, Seth continues to lie to Summer about how the interview went and his newfound pot habit. Months later and still neck-deep in lies, he tells his entire family that he GOT INTO BROWN when he didn't! I get it: high school kids lie to their parents, but their parents are not Seth and Kirsten Cohen. Making matters worse, Seth ends up burning down the freakin' Newport Group building after leaving a lit joint in the office.
I know we all had bits of immaturity in high school, but only as an adult did I realise that Seth was far from the nice, nerdy boy he initially seems to be in the first season. The homie slightly matures throughout the series and eventually Anna helps him come to his senses to apply to RISD to be in Rhode Island while Summer is at Brown, but I'd like to give it up for the real hero here: Ryan Atwood. He took the heat as the bad boy with a tendency to throw punches throughout my entire youth, but he was only doing it to protect the people he loved, including Seth, who absolutely was in need of protection.
TL;DR: re-watching the shows we were so obsessed with as kids years later as adults can really make you see characters and story lines in an entirely different light. I love the relationship that Seth and Ryan had, but it would've taken Seth a lot longer to mature had Ryan not been there. In short, thank you for coming to my TED talk, which shall henceforth be known as "Summer Deserved Better."
The O.C.NostalgiaAdam BrodyTV


text:
Gov. Noem Pushes Back on Argument that Pro-Lifers are Anti-Woman, Calls Pro-Abortion Advocates 'Hypocritical'
Vic Eldred » Groups » We the People » Discussions » Gov. Noem Pushes Back on Argument that Pro-Lifers are Anti-Woman, Calls Pro-Abortion Advocates 'Hypocritical'
Via: XXJefferson51 • 2 months ago • 12 comments
By: Madeline Leesman
"This is an issue that those who are pro-choice try to dehumanize," Noem said, according to Fox News. "They [pro-choice advocates] try to make an argument that we [pro-life supporters] don't care about women, that we don't care about these babies," she added. "That's just a false narrative that we have to push aggressively back against."
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Way to go Gov. Noem! So very well said. Thank you for being pro life and standing with other women who are. You take and shred the pro aborts arguments and excuses and make a strong case for being pro life.
Madeline Leesman
Source: AP Photo/Harry Hamberg, File
This week, South Dakota Gov. Kristi Noem (R) issued remarks pushing back against the Democratic narrative that pro-life supporters do not care about women or babies. In her remarks, Noem also took aim at telemedicine abortions, claiming that this method has made pro-abortion advocates change their narrative on abortion being a decision between a woman and her doctor.
The remarks, which were reportedly made during an online press briefing with pro-life organization Susan B. Anthony List (SBA), came ahead of Supreme Court case Dobbs v. Jackson Women's Health Organization , which surrounds the constitutionality of a Mississippi law in that bans abortions at 15 weeks gestation.
On Wednesday, the Supreme Court of the United States will hear oral arguments for Dobbs , which has the potential to overturn landmark abortion cases Roe v. Wade and Planned Parenthood v. Casey , which occured in 1973 and 1992, respectively.
"This is an issue that those who are pro-choice try to dehumanize," Noem said, according to Fox News.
"They [pro-choice advocates] try to make an argument that we [pro-life supporters] don't care about women, that we don't care about these babies," she added. "That's just a false narrative that we have to push aggressively back against."
On the issue of telemedicine abortions, Noem added that this method of abortion is more dangerous for woman, which shows that pro-abortion advocates are "hypocritical" because it allows women to make an "impromptu" and "not well-informed" decision.
"For years and years, we've heard liberals talk about this decision on abortion being between a woman and her doctor," she explained. "Now, they're changing their complete argument to now this can be a decision between a woman and virtually any stranger over the phone – that she doesn't even have to prove it's a doctor…or an informed decision."
In September, as Landon covered , Noem signed an Executive Order banning telemedicine abortions in the state. The order requires that abortion-inducting drugs, such as mifepristone and misoprostol, be picked up in-person rather than transported via mail. The Order requires that abortion-inducing drugs can only be provided by a physician licensed in South Dakota after an in-person examination.
After signing the Order. Noem appeared in an interview with Fox News where she noted that she is ardently pro-life and appointed someone in her office to work as a pro-life advocate. Additionally, she noted that she has been in touch with lawmakers in Texas to look at how South Dakota could create legislation similar to S.B. 8.
"Everybody knows that I'm pro-life and do not support any kind of abortions," Noem said in the interview. "But, here what the Biden administration is doing is trying to put forward abortion on demand. And we're going to stop them and make sure that that's not available in our state."
Noem, who has three children and a granddaughter, also reportedly argued that women do not need to choose between career success and having children. She and more than 200 other women signed an amicus brief challenging Casey's contention that abortion has allowed women to participate equally in "the economic and social life" of the United States.
"It may be possible to claim anecdotally that a particular woman's abortion seemed to preserve her opportunity to pursue a particular job or degree. But it is impossible to claim that abortion access is specially responsible for the progress that American women have made," the brief states. "The Casey plurality claimed that the ability of women to participate in the economic and social life of the nation depended on their access to abortion. Yet historical review of the half-century preceding Roe demonstrates a steady expansion of social, economic, and political opportunities for women—all without legal access to abortion."
"You Are NOT Answering My Questions": GOP Lawmaker Eviscerates Pro-Abortion Witnesses
Rep. Mike Johnson (R) dismantles the arguments of pro-abortion activists during a House hearing.
Senior Guide
1 seeder XXJefferson51 2 months ago
"It may be possible to claim anecdotally that a particular woman's abortion seemed to preserve her opportunity to pursue a particular job or degree. But it is impossible to claim that abortion access is specially responsible for the progress that American women have made," the brief states. "The Casey plurality claimed that the ability of women to participate in the economic and social life of the nation depended on their access to abortion.
thenewstalkers
1.1 seeder XXJefferson51 replied to XXJefferson51 @1 2 months ago
Gov. Noem signs pro-life bills into law
by Siouxland News
https://siouxlandnews.com/resources/media/9019d4dd-e854-4728-8e62-8934b20f518a-medium16x9_AP203047594093861.jpg?1616785133938 768w,
siouxlandnews
320w,
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FILE - In this July 3, 2020 file photo South Dakota Gov. Kristi Noem, center, waves to supporters at Mount Rushmore National Memorial near Keystone, S.D. Midwest governors credit their lack of restrictions for low unemployment rates, but economists and others say other factors might be more important in the states low jobless rates. (AP Photo/Alex Brandon, File)
PhD Guide
2 Thrawn 31 2 months ago
pro-life supporters do not care about women or babies.
They don't considering these same people are always the ones pushing back against programs meant to help mothers and young children, especially those in poverty. If they wanted to ban abortion but also pushed for more assistance to mothers and children then okay, fair enough. But they don't.
My personal opinion the "pro-lifers" should just fuck off and let everyone make their own decisions. A woman's decision to have an abortion has zero effect on me and as such I don't give a shit if she has one or not.
2.1 seeder XXJefferson51 replied to Thrawn 31 @2 2 months ago
Actually the point of the article you never read to the end is the opposite of what you said. Pro life do care about the mother and the baby and always have. Noem is exactly right about what she called pro aborts and I'm happy she said it so it could be said here.
the look on a person's face when she goes to visit her cult hero and demigod [ deleted ]
4.1 Tessylo replied to devangelical @4 2 months ago
4.1.1 seeder XXJefferson51 replied to Tessylo @4.1 2 months ago
You know that she's right! Overturn roe vs Wade now! The worst Supreme Court decision ever in our national story.
4.2 JohnRussell replied to devangelical @4 2 months ago
Another one that Trump will roll over like a cement truck if she gets in his way for the 24 nomination.
4.2.1 seeder XXJefferson51 replied to JohnRussell @4.2 2 months ago
She'd be more likely to be his 24 running mate if he runs. She won't run against him. Only former NJ gov. Chris Christie is for sure running even if he is too. Still, her position on abortion is so right on, the perfect counter to the democrat party US senator threatening a revolution if her side didn't get its way on the Supreme Court.
4.3 seeder XXJefferson51 replied to devangelical @4 2 months ago
Nothing wrong with the picture. It's not like Kamala Harris climbing the career ladder on Willie Browns slippery pole.
4.3.1 JBB replied to XXJefferson51 @4.3 2 months ago
No wonder women are leaving the gop...
4.3.2 seeder XXJefferson51 replied to JBB @4.3.1 2 months ago
They aren't actually. The pro life movement is largely women now. Many Single college educated women have left while many married with family and career or homemaker women have joined.
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