text:
\section*{Introduction}
Although this program has not been realized, Voevodsky has constructed a triangulated category of geometric motives over a perfect field, which has many of the properties expected of the derived category of the conjectural abelian category of motives. The construction of the triangulated category of motives has been extended by Cisinski-D\'{e}glise (\cite{cd}) to a triangulated category of motives over a base-scheme $S$, denoted $DM_S$. Hanamura (\cite{hana}) has also constructed a triangulated category of motives over
a field, using the idea of a ``higher correspondence", with morphisms built out of Bloch's cycle complex.
Recently, Bondarko (in \cite{bondarko}) has refined Hanamura's idea and limited it to smooth projective varieties to construct a DG category of motives. Assuming resolution of singularities, the homotopy category of this DG category is equivalent to
Voevodsky's category of effective geometric motives.
Soon after, Levine (in \cite{smmot}) extended this idea to construct a DG category of ``smooth motives''
over a base-scheme $S$ generated by the motives of smooth projective $S$-schemes,
where $S$ is itself smooth over a perfect field. Its homotopy category is equivalent to the full subcategory of  Cisinski-D\'{e}glise category of effective motives over $S$ generated by the smooth
projective $S$-schemes.
Both these constructions lack a tensor structure in general. However, passing to $\mathbb{Q}$-coefficients, Levine replaced the cubical construction with alternating cubes, which yields a tensor structure on his DG category.

In \cite{tenssmmot}, a pseudo-tensor structure is constructed on a  DG category ${dg_e} Cor_S$ which induces a tensor structure on the homotopy category of DG complexes,  such  that, in case $S$ is semi-local and essentially smooth over a field of characteristic zero, it
induces a tensor structure on the category of smooth motives over $S$. It is proved that
\begin{thmintro}\label{int} Suppose $S$ is semi-local and essentially smooth over a field of characteristic zero. Then,
there is a tensor structure on the category $SmMot^{\mathrm{eff}}_{gm}(S)$ of smooth effective geometric motives over $S$ making it into a tensor triangulated category.
\end{thmintro}
In \cite{smmot}, Levine constructed a functor from his category of smooth motives to the Cisinski-D\'{e}glise category of motives over $S$
\[\rho_S:SmMot_{gm}(S)\to DM_S. \]
In this article, we show that
\begin{thmintro}\label{tf} If $S$ is semi-local and essentially smooth over a field of characteristic zero, then $\rho_S$ is a tensor functor with respect to the tensor structure on $SmMot_{gm}(S)$ defined in Theorem~\ref{int}.
\end{thmintro}
This is done by first defining a morphism $\rho_S(M)\otimes\rho_S(N)\to \rho_S(M\otimes N)$ in $DM_S$, for objects $M,N$ in  $SmMot_{gm}(S)$, and then showing that this is an isomorphism for $M=M_S(X)$ and $N=M_S(Y)$, where $X,Y$ are smooth projective schemes and $M_S$ is the functor $\mathbf{Proj}_S\to SmMot_{gm}(S)$. We also show that
\begin{corintro}
Under the same conditions on $S$, we have an exact duality
\[ SmMot_{gm}^{op}(S)\to SmMot_{gm}(S). \]
\end{corintro}

We begin with proving some general results on pseudo-tensor DG categories and pseudo-tensor functors, and then prove Theorem~\ref{tf} over the next two sections.

\section{Generalities on pseudo-tensor categories}
In this section, we extend some results from \cite[\S~2.3]{tenssmmot}. Let $(\mathcal{A}, P^\mathcal{A})$ and $(\mathcal{B}, P^\mathcal{B})$ be pseudo-tensor DG categories.
\begin{dfn}
A DG functor $X:\mathcal{A}\to\mathcal{B}$ is called a pseudo-tensor functor if $X$ induces a map of complexes
\[P^\mathcal{A}_I(\{E_i\},F)^*\longrightarrow P^\mathcal{B}_I(\{X(E_i)\},X(F))^*. \]
which is compatible with composition as given by the following commutative diagram:
\begin{equation}
\label{eq:pstfunc}
\begin{xy}
\xymatrix{ P^\mathcal{A}_I(\{F_i\},G)^*\otimes\bigotimes_{i\in I}P^\mathcal{A}_{J_i}(\{E_j\}_{j\in J_i},F_i)^*\ar[d]\ar[r] & P^\mathcal{A}_J(\{E_j\},G)^*\ar[d]\\
P^\mathcal{B}_I(\{X(F_i)\},X(G))^*\otimes\bigotimes_{i\in I}P^\mathcal{B}_{J_i}(\{X(E_j)\}_{j\in J_i},X(F_i))^*\ar[r] & P^\mathcal{B}_J(\{X(E_j)\},X(G))^*
}
\end{xy}\end{equation} and $X({\operatorname{id}}_{E})={\operatorname{id}}_{X(E)}$.

Furthermore, let $(\mathcal{A}, P^\mathcal{A})$ and $(\mathcal{B}, P^\mathcal{B})$ be {\em homotopy tensor categories}, that is, their pseudo-tensor structure induce a tensor structure on their respective homotopy categories. $X$ would be called a {\em homotopy
tensor functor}, if, in addition, $H^0X:H^0\mathcal{A}\to H^0\mathcal{B}$ is a tensor functor with respect to the tensor structures on $H^0\mathcal{A}$ and $H^0\mathcal{B}$ induced by $P^\mathcal{A}$ and $P^\mathcal{B}$ respectively.
\end{dfn}

\begin{dfn}
A functor $X:\mathcal{A}\to \mathcal{B}$ between tensor categories $\mathcal{A}$ and $\mathcal{B}$ is called a {\em lax tensor functor}, if for every $E,F\in ob(\mathcal{A})$, there is a morphism \[
X(E)\otimes_{\mathcal{B}}X(F) \longby{\theta_{E,F}} X(E\otimes_{\mathcal{A}}F)\]
in $\mathcal{B}$, which is associative, commutative and unital (see \cite[Part II, Chap.~1, \S 1.3.7]{Mxmot}. In \cite{Mxmot}, Levine calls such a functor a pseudo-tensor functor -- we would not use this terminology to avoid confusion).
\end{dfn}

\begin{rem}
Note that a pseudo-tensor functor between two tensor categories (with pseudo-tensor structures induced by the respective tensor structures) is a lax tensor functor. \end{rem}
Thus, if $(\mathcal{A}, P^\mathcal{A})$ and $(\mathcal{B}, P^\mathcal{B})$ are homotopy tensor categories and $X:\mathcal{A}\to\mathcal{B}$ a pseudo-tensor DG functor,
then $H^0X:H^0\mathcal{A}\to H^0\mathcal{B}$ is a { lax tensor functor}.

The set of small homotopy tensor categories form a category whose morphisms are homotopy tensor functors. It is shown in \cite[\S~2.3]{tenssmmot} that if $\mathcal{A}$ is a homotopy tensor category, so is $\mathcal{A}^\mathrm{pretr}$. Here, we are going to show that the assignment $\mathcal{A}\mapsto\mathcal{A}^\mathrm{pretr}$ is an endofunctor of the category of small homotopy tensor categories.
\begin{prop}\label{prop:homtens}
{\it i.} If $X:\mathcal{A}\to\mathcal{B}$ is a pseudo-tensor DG functor between pseudo-tensor DG categories $\mathcal{A}$ and $\mathcal{B}$, then there is an induced pseudo-tensor DG functor
$X^\mathrm{pretr}:\mathcal{A}^\mathrm{pretr}\to\mathcal{B}^\mathrm{pretr}$.\\

\noindent {\it ii.} Further, if $\mathcal{A}$ and $\mathcal{B}$ are homotopy tensor categories, then $H^0X^\mathrm{pretr}:H^0\mathcal{A}^\mathrm{pretr}\to H^0\mathcal{B}^\mathrm{pretr}$ is a lax tensor functor.\\

\noindent {\it iii.} Also, if in addition, $X:\mathcal{A}\to\mathcal{B}$ is a homotopy tensor functor, so is $X^\mathrm{pretr}:\mathcal{A}^\mathrm{pretr}\to\mathcal{B}^\mathrm{pretr}$.
\end{prop}

\begin{proof}
{\it i.} Given a DG functor $X:\mathcal{A}\to\mathcal{B}$, we define a functor $X^\mathrm{pretr}:\text{Pre-Tr}(\mathcal{A})\to\text{Pre-Tr}(\mathcal{B})$ as follows:\\
Let $\mathcal{E}=\{E_i,\,e_{ij}:E_j\to E_i\}$ be an object in $\text{Pre-Tr}(\mathcal{A})$. We define $X^\mathrm{pretr}(\mathcal{E}):={\{X(E_i),\,X(e_{ij}):X(E_j)\to X(E_i)\}}$ and for a morphism $\phi:\mathcal{E}\to\mathcal{F}$ in $\text{Pre-Tr}(\mathcal{A})$, $X(\phi):={\{X(\phi_{ij}):X(E_j)\to X(F_i)\}}$. $X^\mathrm{pretr}$ is a DG functor since so is $X$. Clearly, by definition, we have
\[ X^\mathrm{pretr}(\mathcal{E}[n])=X^\mathrm{pretr}(\mathcal{E})[n];\quad X^\mathrm{pretr}(Cone(\phi))=Cone(X^\mathrm{pretr}(\phi)). \]
Thus, restricting to $\mathcal{A}^\mathrm{pretr}$, we get a functor \[ X^\mathrm{pretr}:\mathcal{A}^\mathrm{pretr}\to\mathcal{B}^\mathrm{pretr}. \]

Now, for objects $\mathcal{E}^1,\ldots,\mathcal{E}^n,\mathcal{F}$ in $\mathcal{A}^\mathrm{pretr}$, and $I=\{1,\ldots,n\}$, the pseudo-tensor structure on $\mathcal{A}^\mathrm{pretr}$ is defined as:
\[ P^{\mathcal{A}^\mathrm{pretr}}_I(\{\mathcal{E}^i\},\mathcal{F}):=\bigoplus_{j,k} P^\mathcal{A}_I(\{E^i_j\},F_k)[j-k]. \]
Thus, since $X$ is a pseudo-tensor functor, we have the map
\[
\begin{xy}\xymatrix{ P^{\mathcal{A}^\mathrm{pretr}}_I(\{\mathcal{E}^i\},\mathcal{F}) \ar@{=}[d] \ar@{-->}[r] & P^{\mathcal{B}^\mathrm{pretr}}_I(\{X^\mathrm{pretr}(\mathcal{E}^i)\},X^\mathrm{pretr}(\mathcal{F})) \ar@{=}[d] \\
\bigoplus_{j,k} P^\mathcal{A}_I(\{E^i_j\},F_k)[j-k] \ar[r] & \bigoplus_{j,k} P^\mathcal{B}_I(\{X(E^i_j)\},X(F_k))[j-k]}
\end{xy}
\]
It also follows that the required commutativity of the square \eqref{eq:pstfunc} is satisfied, thus proving {\em i}.

{\it ii.} Let $\mathcal{E},\,\mathcal{F}\in Ob(H^0\mathcal{A}^\mathrm{pretr})$. We first show that
\begin{clm} We have the following isomorphism in $H^0\mathcal{A}^\mathrm{pretr}$:
\[\mathcal{E}\otimes\mathcal{F}\by{\sim}\{(\oplus_{i+j=l}E_i\otimes F_j)_l,g_{kl}:\oplus_{i+j=l}E_i\otimes F_j\to\oplus_{i+j=k}E_i\otimes F_j\}
\] where $g_{kl}:=\oplus_i\left((-1)^{(l-k+1)(l-i)}e_{(i+k-l),i}\otimes{\operatorname{id}}_{F_{l-i}} + (-1)^i{\operatorname{id}}_{E_i}\otimes f_{(k-i),(l-i)}\right)$.
\end{clm}
\begin{proof}[Proof of Claim]
We make use of the fact that $\mathcal{A}^\mathrm{pretr}$ is generated by $i(\mathcal{A})$ by taking translations and cones and proceed by  induction. For objects $E,F$ in $\mathcal{A}$, and any $\mathcal{G}$ in $\mathcal{A}^\mathrm{pretr}$, we have
\begin{align*}
Hom_{H^0\mathcal{A}^\mathrm{pretr}}(i(E)\otimes i(F),\mathcal{G})& \by{\sim} H^0P^{\mathcal{A}^\mathrm{pretr}}(\{i(E),i(F)\},\mathcal{G})\\
& \by{\sim} \bigoplus_kH^0P^\mathcal{A}(\{E,F\},G_k)[-k]\\
& \by{\sim} \bigoplus_kH^0Hom_\mathcal{A}(E\otimes F,G_k)[-k]\\
& \by{\sim} Hom_{H^0\mathcal{A}^\mathrm{pretr}}(i(E\otimes F),\mathcal{G})
\end{align*}
This implies $i(E)\otimes i(F)\by{\sim} i(E\otimes F)$ in $H^0\mathcal{A}^\mathrm{pretr}$. Thus, $(i(E)\otimes i(F))_0=E\otimes F$ and $(i(E)\otimes i(F))_l=0$ for $l\neq 0$. Also $(i(E)\otimes i(F))_{ij}=0$.

Also, note that it follows from the definition of the pseudo-tensor structure on $\mathcal{A}^\mathrm{pretr}$, $\mathcal{E}[n]\otimes\mathcal{F}\by{\sim}(\mathcal{E}\otimes\mathcal{F})[n]$ and $\mathcal{E}\otimes\mathcal{F}[n]\by{\sim}(\mathcal{E}\otimes\mathcal{F})[n]$ in $H^0\mathcal{A}^\mathrm{pretr}$. Now, we show that for objects $\mathcal{E},\mathcal{F},\mathcal{G}$ and a morphism $\phi\in Z^0Hom_{\mathcal{A}^\mathrm{pretr}}(\mathcal{F},\mathcal{G})$, if the claim is true for $\mathcal{E}\otimes\mathcal{F}$ and $\mathcal{E}\otimes\mathcal{G}$, then it is true for
$\mathcal{E}\otimes Cone(\phi)$. That is, we have
\begin{eqnarray*}
(\mathcal{E}\otimes\mathcal{F})_l &\by{\sim} & \bigoplus_{i+j=l}E_i\otimes F_j\\
(\mathcal{E}\otimes\mathcal{G})_k &\by{\sim} & \bigoplus_{i+p=k}E_i\otimes G_k
\end{eqnarray*}
We have from \cite[Proposition~6.1]{tenssmmot} that in $H^0\mathcal{A}^\mathrm{pretr}$, $\mathcal{E}\otimes Cone(\phi)\by{\sim} Cone(\mathcal{E}\otimes\mathcal{F}\to\mathcal{E}\otimes\mathcal{G})$. Thus,
\begin{eqnarray*}
(\mathcal{E}\otimes Cone(\phi))_l &=& (\mathcal{E}\otimes\mathcal{G})_l\oplus (\mathcal{E}\otimes\mathcal{F})_{l+1}\\
&=& (\oplus_{i+j=l}E_i\otimes F_j)\oplus(\oplus_{i+p=l+1}E_i\otimes G_p)\\
&=& \oplus_{i+k=l}E_i\otimes Cone(\phi)_{l-i}
\end{eqnarray*}
Also, $(\mathcal{E}\otimes Cone(\phi))_{kl}=cone(\mathcal{E}\otimes\mathcal{F}\to\mathcal{E}\otimes\mathcal{G})_{kl}=$
\[ \left(\begin{array}{lr}
\oplus_i\big((-1)^{(l-k+1)(l-i)}e_{(i+k-l)\,i}\otimes{\operatorname{id}}_{G_{l-i}}+(-1)^i{\operatorname{id}}_{E_i}\otimes g_{(k-i)\,(l-i)}\big) & \hspace*{-7.5cm} \oplus_i(-1)^i\phi^*_{(k-i)\,(l-i+1)}\\
0 & \hspace*{-7.5cm}\oplus_i\big((-1)^{(l-k+1)(l-i+1)}e_{(i+k-l)\,i}\otimes{\operatorname{id}}_{F_{l-i+1}}+(-1)^i{\operatorname{id}}_{E_i}\otimes f_{(k-i+1)\,(l-i+1)}\big)
\end{array}\right) \]
which is equal to
\[ \bigoplus_i\Big[(-1)^{(l-k+1)(l-i)}e_{(i+k-l)\,i}\otimes{\operatorname{id}}_{Cone(\phi)_{l-i}}
+(-1)^i{\operatorname{id}}_{E_i}\otimes \left(\begin{array}{cc}g_{(k-i)\,(l-i)}& \phi_{(k-i)\,(l-i+1)}\\0& f_{(k-i+1)\,(l-i+1)}\end{array}\right)\Big] \]
This proves the claim.
\end{proof}
Thus, we have in $H^0\mathcal{B}^\mathrm{pretr}$, \begin{eqnarray*}
X^\mathrm{pretr}(\mathcal{E}\otimes\mathcal{F})&=&\{(\oplus_{i+j=l}X(E_i\otimes F_j))_l;\\
&&{\displaystyle\oplus_i\left((-1)^{(l-k+1)(l-i)}X(e_{(i+k-l),i}\otimes{\operatorname{id}}_{F_{l-i}})\right.}\\
&& \left. + (-1)^iX({\operatorname{id}}_{E_i}\otimes f_{(k-i),(l-i)})\right)\}\\
\text{and\hspace*{3cm}}&& \\
X^\mathrm{pretr}(\mathcal{E})\otimes X^\mathrm{pretr}(\mathcal{F})&=&\{(\oplus_{i+j=l}X(E_i)\otimes X(F_j))_l;\\
&&{\displaystyle\oplus_i\left((-1)^{(l-k+1)(l-i)}X(e_{(i+k-l),i})\otimes{\operatorname{id}}_{X(F_{l-i})}\right.}\\
&& \left. + (-1)^i{\operatorname{id}}_{X(E_i)}\otimes X(f_{(k-i),(l-i)})\right)\}
\end{eqnarray*}
Note that, for objects $\mathcal{G}:=\{{G_i},g_{ij}:G_j\to G_i\},\,\mathcal{H}:=\{H_n,h_{mn}:h_n\to h_m\}$ in $\mathcal{B}^\mathrm{pretr}$, if we have maps $\phi_{ii}:G_i\to H_i$ in $H^0\mathcal{B}$ such that $\phi_{ii}g_{ij}=h_{ij}\phi_{jj}$, then we get
a morphism $\phi:=\{\phi_{ij}\}:\mathcal{G}\to\mathcal{H}$ in $H^0\mathcal{B}^\mathrm{pretr}$ defined as $\phi_{ij}=\phi_{ii}$ if $i=j$ and $0$ otherwise.
Since $H^0X$ is a lax tensor functor, it follows from above that there is a map $\theta:X^\mathrm{pretr}(\mathcal{E})\otimes X^\mathrm{pretr}(\mathcal{F})\to X^\mathrm{pretr}(\mathcal{E}\otimes\mathcal{F})$ in $H^0\mathcal{B}^\mathrm{pretr}$, that is $H^0X^\mathrm{pretr}$ is also a lax tensor functor.

{\it iii.}
If $X$ is a homotopy tensor functor, by the argument above,  \[X^\mathrm{pretr}(\mathcal{E})\otimes X^\mathrm{pretr}(\mathcal{F})\by{\sim} X^\mathrm{pretr}(\mathcal{E}\otimes\mathcal{F})\] in $H^0\mathcal{B}^\mathrm{pretr}$. Indeed, if the $\phi_{ii}:E_i\to F_i$ are isomorphisms in $H^0\mathcal{B}$, then so is $\phi:\mathcal{E}\to\mathcal{F}$ in $H^0\mathcal{B}^\mathrm{pretr}$.
\end{proof}

\begin{rem}\label{rem:lax}
Note that in the proof of Proposition~\ref{prop:homtens}{\it ii.}, $X$ need not be a pseudo-tensor functor, we only need that $X$ is a DG functor and $H^0X$ is a lax tensor functor.
\end{rem}

\section{The  functor $\mathcal{K}^b(dgPrCor_S)\to DM^{\mathrm{eff}}(S)$ is lax tensor}
In \cite[\S~6.3]{smmot}, Levine constructs an exact functor
\[ \rho^\mathrm{eff}_S: SmMot^\mathrm{eff}_{gm}(S)\to DM^\mathrm{eff}(S). \]
The aim in this section is to show that when $S$ is regular semi-local and essentially smooth over
a field of characteristic zero,
 $\rho^\mathrm{eff}_S$ is a lax tensor functor.

 Recall from \cite[Lemma~1.9]{smmot} that we can associate a DG category $dg\mathcal{C}$ to a tensor category $(\mathcal{C},\otimes)$ with a co-cubical object $\square^*$ with co-multiplication $\delta^*$.
 $dg\mathcal{C}$ has the same objects as $\mathcal{C}$, and for objects $X,Y$ in $dg\mathcal{C}$, $Hom_{dg\mathcal{C}}(X,Y)^*$
is the non-degenerate complex associated with the cubical abelian group
\[ \underline{n}\mapsto Hom_\mathcal{C}(X\otimes\square^{n},Y). \]
i.e.\  \[ Hom_{dg\mathcal{C}}(X,Y)^n:= Hom_\mathcal{C}(X\otimes\square^{-n},Y)/\mathrm{degn}. \] (Also see \cite[\S~1.2.5]{tenssmmot}.)

We also have the extended DG category ${dg_e}\mathcal{C}$, with the same objects as $\mathcal{C}$. The Hom complexes are defined as follows: For each $m$, we have the non-degenerate complex $Hom_{dg\mathcal{C}}(X,Y\otimes\square^m)^*$; let
$Hom_{\mathcal{C}}(X,Y\otimes\square^m)^*_0$ be the subcomplex consisting of $f$   such that
\[
p_{m,i}\circ f=0\in Hom_{\mathcal{C}}(X,Y\otimes\square^{m-1})^*;\quad i=1,\ldots, m.
\]
Then,
\[
Hom_{{dg_e}\mathcal{C}}(X,Y)^p:=\prod_{m-n=p}Hom_{dg\mathcal{C}}(X,Y\otimes\square^m)^{-n}_0.
\]
See \cite[\S~1.3.3]{tenssmmot} for details. It is shown in \cite[Theorem~2.4.2]{tenssmmot} that there is a homotopy tensor structure on ${dg_e}\mathcal{C}$, when $\square^*$ admits bi-multiplication and is homotopy invariant.

Let us assume that $S$ is semi-local and essentially smooth over
a field of characteristic zero. From \cite[Remark~1.4.4]{tenssmmot}, we have that $SmMot^\mathrm{eff}_{gm}(S)$ is equivalent to $\mathcal{K}^b(dgPrCor_S)^\natural$ where $^\natural$ denotes the idempotent completion. We describe below the construction of Levine in \cite[\hbox{\it loc. cit}]{smmot} to give a functor
\[ \rho^\mathrm{eff}_S: SmMot^\mathrm{eff}_{gm}(S)\to  DM^\mathrm{eff}(S). \]

We also recall from \cite[\S~5.1]{smmot} that for $X, Y$ in $\boldsymbol{Sm}/S$, the cubical Suslin complex $C^S(Y,r)^*(X)$ is the complex associated to the cubical object \[ n\mapsto z^S_{equi}(Y,r)(X\times\square^n_S), \]
where $\square^n_S\simeq\mathbb{A}^n_S$ and $z^S_{equi}(Y,r)(X)$ is the free abelian group on the integral subschemes $W\subset X\times_S Y$
such that the projection $W\to X$ dominates an irreducible component $X'$ of $X$, and such that, for each $x\in X$, the fiber $W_x$ over $x$
has pure dimension $r$ over $k(x)$, or is empty. If $X$ is in $\mathbf{Proj}/S$, then $C^S(X,0)$ is the presheaf $Hom_{dgCor_S}(\underline{\;\;},X)^*$ on
$\boldsymbol{Sm}/S$.
Sending $U$ in $\boldsymbol{Sm}/S$ to $C^S(X,0)(U)$ gives the object $C^S(X)$ in $C^-(Sh^{tr}_{\mathrm{Nis}}(S))$.

For $X, Y$ in $\mathbf{Proj}/S$, the composition law in $dgCor_S$ defines a natural map
\[ \tilde{\rho}_{X,Y}:Hom_{dgPrCor_S}(X,Y)^*\to Hom_{C(Sh^{tr}_{\mathrm{Nis}}(S))}(C^S(X),C^S(Y)). \]
This defines a DG functor
\[ \tilde{\rho}:dgPrCor_S\to C(Sh^{tr}_{\mathrm{Nis}}(S)).\]
Applying the functor $\mathcal{K}^b$ and composing with the total complex functor
\[ {\operatorname{\rm Tot}}:\mathcal{K}^b(C(Sh^{tr}_{\mathrm{Nis}}(S)))\to K(Sh^{tr}_{\mathrm{Nis}}(S))\]
and the quotient functor
\[ K(Sh^{tr}_{\mathrm{Nis}}(S))\to DM^\mathrm{eff}(S) \]
gives us the exact functor
\[ \mathcal{K}^b(dgPrCor_S)\to DM^\mathrm{eff}(S). \]
Extending canonically to the idempotent completion, we define the exact functor
\[ \rho^\mathrm{eff}_S: SmMot^\mathrm{eff}_{gm}(S)\to  DM^\mathrm{eff}(S). \]

We also have a map (see \cite[Proposition~1.3.5]{tenssmmot})
\[ \pi_{X,Y}: Hom_{{dg_e} PrCor_S}(X,Y)^* \to Hom_{dgPrCor_S}(X,Y)^* \]
giving us a functor of DG categories
\[ \hat{\rho}:=\tilde{\rho}\circ\pi: {dg_e} PrCor_S \to C(Sh^{tr}_{\mathrm{Nis}}(S)). \]

We will first show that
\begin{prop}\label{prop:pstensf}
$\hat{\rho}$ is a pseudo-tensor functor with respect to the pseudo-tensor structure on ${dg_e} PrCor_S$ defined in \cite{tenssmmot} and one induced from the tensor structure $\otimes^{tr}_S$  on $C(Sh^{tr}_{\mathrm{Nis}}(S))$. \end{prop}
The tensor structure $\otimes^{tr}_S$ on $Sh^{tr}_{\mathrm{Nis}}(S)$ is defined as follows: we take the canonical left resolution $\mathcal{L}(\mathcal{F})$ of a sheaf
$\mathcal{F}$ by taking the canonical surjection
\[ \mathcal{L}_0(\mathcal{F}):=\bigoplus_{\begin{array}{c}\scriptstyle X\in\boldsymbol{Sm}/S \\ \scriptstyle s\in\mathcal{F}(X)\end{array}}\mathbb{Z}^{tr}_S(X)\longby{\phi_0}\mathcal{F} \]
where $\mathbb{Z}^{tr}_S(X):=Cor_S(\underline{\;\;},X)$ is the representable presheaf for $X\in\boldsymbol{Sm}/S$. Setting $\mathcal{F}_1:=\ker \phi_0$ and iterating, we get the complex
$\mathcal{L}(\mathcal{F})$. Then, we define
\[ \mathcal{F}\otimes^{tr}_S\mathcal{G}:=H_0(\mathcal{L}(\mathcal{F})\otimes^{tr}_S\mathcal{L}(\mathcal{G})) \]
using the fact that
\[ \mathbb{Z}^{tr}_S(X)\otimes^{tr}_S\mathbb{Z}^{tr}_S(X'):=\mathbb{Z}^{tr}_S(X\times_S X'). \]

\begin{lem}
For $X,X'\in \mathbf{Proj}_S$, there exists a map of presheaves
\[ C^S(X)^m\otimes^{tr}_S C^S(X')^n \to C^S(X\times_S X')^{m+n}. \]
\end{lem}

\begin{proof}
Note that
\[ \mathcal{L}_0(C^S(X)^m)=\bigoplus_{\begin{array}{c}\scriptstyle Y\in\boldsymbol{Sm}/S \\ \scriptstyle s\in C^S(X)^m(Y)\end{array}}\mathbb{Z}^{tr}_S(Y)
\longby{\;\phi_0^{X,m}}C^S(X)^m \]
where $Cor_S(Y\times_S\square^*_S,X)_0$ is the non-degenerate complex associated to the cubical abelian group $\underline{n}\mapsto Cor_S(Y\times_S\square^n_S,X)$.

Firstly, we want to produce a map of presheaves
\begin{equation}\label{eqn:Lmap}
\mathcal{L}_0(C^S(X)^m)\otimes^{tr}_S\mathcal{L}_0(C^S(X')^n) \to \mathcal{L}_0(C^S(X\times_S X')^{m+n}).
\end{equation}
We have $\mathcal{L}_0(C^S(X)^m)\otimes^{tr}_S\mathcal{L}_0(C^S(X')^n) =$ \\
\begin{align*}
 = & \Big( \bigoplus_{\begin{array}{c}\scriptstyle Y\in\boldsymbol{Sm}/S \\ \scriptstyle s\in C^S(X)^m(Y)\end{array}}\mathbb{Z}^{tr}_S(Y)\Big) \otimes^{tr}_S \Big( \bigoplus_{\begin{array}{c}\scriptstyle Y'\in\boldsymbol{Sm}/S \\ \scriptstyle s'\in C^S(X')^n(Y')\end{array}}\mathbb{Z}^{tr}_S(Y')\Big) \\
=& \bigoplus_{\begin{array}{c}\scriptstyle Y,Y'\in\boldsymbol{Sm}/S \\ \scriptstyle s\in C^S(X)^m(Y)\\ \scriptstyle s'\in C^S(X')^n(Y')\end{array}}\mathbb{Z}^{tr}_S(Y\times_SY')
\end{align*}

Using the map \eqref{eqn:cstimes}, we thus get a map
\[ \xymatrix{ \mathcal{L}_0(C^S(X)^m)\otimes^{tr}_S\mathcal{L}_0(C^S(X')^n)\ar[r]&  \displaystyle\bigoplus_{\begin{array}{c}\scriptstyle Y\times_SY'\in\boldsymbol{Sm}/S \\
\scriptstyle s\boxtimes s'\in C^S(X\times_S X')^{m+n}(Y\times_SY')\end{array}}\mathbb{Z}^{tr}_S(Y\times_SY') \ar@{^{(}->}[d] \\
\mathcal{L}_0(C^S(X\times_S X')^{m+n}) \ar@{=}[r] & \displaystyle\bigoplus_{\begin{array}{c}\scriptstyle Y''\in\boldsymbol{Sm}/S \\
\scriptstyle t\in C^S(X\times_S X')^{m+n}(Y'')\end{array}}\mathbb{Z}^{tr}_S(Y'') } \]

The map \begin{equation}\label{eqn:cstimes} C^S(X)^m(Y)\otimes C^S(X')^n(Y') \by{\boxtimes} C^S(X\times_S X')^{m+n}(Y\times_SY') \end{equation}
is given as follows:
\[ \xymatrix{ Hom_{dgCor_S}(Y,X)^m\otimes Hom_{dgCor_S}(Y',X')^n \ar[d]^{F_{Y,X}\otimes F_{Y',X'}} \\
Hom_{{dg_e} Cor_S}(Y,X)^m\otimes Hom_{{dg_e} Cor_S}(Y',X')^n \ar@{=}[d] \\
P_1^{{dg_e} Cor_S}(\{Y\},X)^m\otimes P_1^{{dg_e} Cor_S}(\{Y'\},X')^n \ar[d]^-{[\text{By representability of the pseudo-tensor structure }P^{{dg_e} Cor_S}]} \\
P_2^{{dg_e} Cor_S}(\{Y,Y'\},X\times_S X')^{m+n} \ar[d]^{\sum_{a=0}^{m+n}\delta^*_{a,m+n-a}} \\
Hom_{{dg_e} Cor_S}(Y\times_S Y',X\times_S X')^{m+n} \ar[d]^{\pi_{Y\times_S Y',X\times_S X'}} \\
Hom_{dgCor_S}(Y\times_S Y',X\times_S X')^{m+n} } \]
Here, $\delta^*_{a,b}$ is induced by the map $\delta_{a,b}$ defined as the composition
\[ \square^{a+b}\longby{\delta^{a+b}}\square^{a+b}\otimes\square^{a+b}\xrightarrow{p^1_{a,b}\otimes p^2_{a,b}}\square^{a}\otimes\square^{b}. \]

Composing the map \eqref{eqn:Lmap} with $\phi_0^{X\times_S X',m+n}$ gives us a map
\[ \mathcal{L}_0(C^S(X)^m)\otimes^{tr}_S\mathcal{L}_0(C^S(X')^n) \to C^S(X\times_S X')^{m+n}. \]
The fact that this induces a map on $H_0(\mathcal{L}(C^S(X)^m)\otimes^{tr}_S\mathcal{L}(C^S(X')^n))$ follows from definition, noting that
\begin{multline*}
(\mathcal{L}(C^S(X)^m)\otimes^{tr}_S\mathcal{L}(C^S(X')^n))_1=\\
=\Big(\bigoplus_{\begin{array}{c}\scriptstyle Z,Z'\in\boldsymbol{Sm}/S \\ \scriptstyle t\in \ker(\phi_0^{X,m})(Z)\\ \scriptstyle t'\in C^S(X')^n(Z')\end{array}}\mathbb{Z}^{tr}_S(Z\times_SZ')\Big)\oplus\Big(\bigoplus_{\begin{array}{c}\scriptstyle Z,Z'\in\boldsymbol{Sm}/S \\ \scriptstyle t\in C^S(X)^m(Z)\\ \scriptstyle t'\in \ker(\phi_0^{X',n})(Z')\end{array}}\mathbb{Z}^{tr}_S(Z\times_SZ')\Big) \\
\overset{(\phi_1^{X,m}\otimes^{tr}_S{\operatorname{id}}) + ({\operatorname{id}}\otimes^{tr}_S\phi_1^{X',n})}{\xrightarrow{\hspace*{3.4cm}}} \bigoplus_{\begin{array}{c}\scriptstyle Y,Y'\in\boldsymbol{Sm}/S \\ \scriptstyle s\in C^S(X)^m(Y)\\ \scriptstyle s'\in C^S(X')^n(Y')\end{array}}\mathbb{Z}^{tr}_S(Y\times_SY')\\
=(\mathcal{L}(C^S(X)^m)\otimes^{tr}_S\mathcal{L}(C^S(X')^n))_0
\end{multline*}
and that $\phi_0^{X\times_S X',m+n}\circ\big((\phi_1^{X,m}\otimes^{tr}_S{\operatorname{id}}) + ({\operatorname{id}}\otimes^{tr}_S\phi_1^{X',n})\big)=0$. This completes the proof of the lemma.
\end{proof}

\begin{proof}[Proof of Proposition~\ref{prop:pstensf}]
It directly follows from the lemma that we have a map in $C(Sh^{tr}_{\mathrm{Nis}}(S))$,
\[ C^S(X)\otimes^{tr}_S C^S(X') \longby{\gamma_{X,X'}} C^S(X\times_S X'). \]
Note that $\gamma_{X,X'}$ is natural in $X$ and $X'$, since so is $\boxtimes$ (in \eqref{eqn:cstimes}).
Thus, we have maps, for $X,Y,Z$ in $\mathbf{Proj}_S$,
\[ \xymatrix{ P_2^{{dg_e} PrCor_S}(\{X,Y\},Z) \ar[r] & Hom_{{dg_e} PrCor_S}(X\times_S Y,Z) \ar[d]^{\pi_{X\times_S Y,Z}} \\
& Hom_{dgPrCor_S}(X\times_S Y,Z) \ar[dl]_{\tilde{\rho}_{X\times_S Y,Z}} \\  Hom_{C(Sh^{tr}_{\mathrm{Nis}}(S))}(C^S(X\times_S Y),C^S(Z)) \ar[r]_-{\gamma^*_{X,X'}} & Hom_{C(Sh^{tr}_{\mathrm{Nis}}(S))}(C^S(X)\otimes^{tr}_S C^S(Y),C^S(Z)).} \]

That this map is compatible with composition follows from the fact that $\gamma_{X,X'}$ is natural in $X$ and $X'$. This shows that $\hat{\rho}$ is a pseudo-tensor functor.
\end{proof}

\begin{cor}
If $S$ is regular semi-local and essentially smooth over
a field of characteristic zero, $\rho^\mathrm{eff}_S$ is a lax tensor functor.
\end{cor}
\begin{proof}
Combining Proposition~\ref{prop:pstensf} with Proposition~\ref{prop:homtens}.{\it ii.} and noting that $\mathcal{K}^b(\mathcal{A})$ is equivalent to $H^0\mathcal{A}^\mathrm{pretr}$, we get that $\mathcal{K}^b(\hat{\rho})$ is a lax tensor functor. Recall from \cite[\S~1.3.3]{tenssmmot}, that there is a quasi-equivalence $dgPrCor_S\by{F}{dg_e} PrCor_S$ such that $\pi\circ F={\operatorname{id}}$. Thus, $\tilde{\rho}=\hat{\rho}\circ F$.
Since the tensor structure on the category $\mathcal{K}^b(dgPrCor_S)$ is induced from $\mathcal{K}^b({dg_e} PrCor_S)$ via the equivalence of categories $\mathcal{K}^b(F)$, we have that $\mathcal{K}^b(\tilde{\rho})$ is also a lax tensor functor.

Since ${\operatorname{\rm Tot}}$ is a tensor functor and the tensor structure $\otimes_S$ on $DM^\mathrm{eff}(S)$ is induced from the tensor product $\otimes^{tr}_S$ via the localization map, we get that
\[ \mathcal{K}^b(dgPrCor_S)\to DM^\mathrm{eff}(S) \]
is a lax tensor functor.
Since extending to idempotent completion preserves tensor structure, it follows from definition that $\rho^\mathrm{eff}_S$ is a lax tensor functor.
\end{proof}

\section{$\rho^\mathrm{eff}_S$ is a tensor functor}

Let $\tilde{ChMot}^\mathrm{eff}_S$ be the category with the same objects as $\mathbf{Proj}_S$ and with morphisms (for $X\to S$ of pure dimension $d_X$
over $S$)
\[ Hom_{\tilde{ChMot}^\mathrm{eff}_S}(X,Y):=CH_{d_X}(X\times_S Y), \]
and let ${ChMot}^\mathrm{eff}(S)$ be its idempotent completion. We have the functor
\[ c_S: \mathbf{Proj}_S \to ChMot^\mathrm{eff}(S) \]
sending a morphism $f:X\to Y$ to the graph of $f$. In \cite{smmot}, Levine showed that
\begin{prop}[\cite{smmot}, Proposition~5.19]\label{prop:chmot} {\it i}. There is a fully faithful embedding $\psi^\mathrm{eff}_S:ChMot^\mathrm{eff}(S)\to SmMot^\mathrm{eff}_{gm}(S)$ such that
there is a commutative diagram \[
\xymatrix{ \mathbf{Proj}_S \ar[rd] \ar[r]^-{c_S} &  ChMot^\mathrm{eff}(S) \ar[d]^{\psi^\mathrm{eff}_S} \\ & SmMot^\mathrm{eff}_{gm}(S) } \]

\noindent {\it ii}. $\psi^\mathrm{eff}$ extends to a fully faithful embedding $\psi:ChMot(S)\to SmMot_{gm}(S)$. \\

\noindent {\it iii}. The maps $\psi^\mathrm{eff}$ and $\psi$ are compatible with the action of $Cor_S$.
\end{prop}

Note that we have the following commutative diagram of functors

\[ \xymatrix{ \mathbf{Proj}_S \ar[r]_-{M_S} \ar@/^1.5pc/[rr]^{m_S} \ar[rd]_{c_S} & SmMot_{gm}^\mathrm{eff}(S) \ar[r]_-{\rho^\mathrm{eff}_S} & DM^\mathrm{eff}(S) \\
& ChMot^\mathrm{eff}(S) \ar[u]^{\psi^\mathrm{eff}_S} & } \]

where $m_S(X)$ is the image of $\mathbb{Z}^{tr}_S(X)$ in $DM^\mathrm{eff}(S)$. That $m_S=\rho^\mathrm{eff}_S\circ M_S$ follows from \cite[Lemma~6.8]{smmot}. We first show that
\begin{lem} For $X,Y$ in $\mathbf{Proj}_S$, we have
\[ \rho^\mathrm{eff}_S(M_S(X)\otimes M_S(Y))\by{\sim} \rho^\mathrm{eff}_S(M_S(X))\otimes_S\rho^\mathrm{eff}_S(M_S(Y)). \]
\end{lem}
\begin{proof}
It follows from Proposition~\ref{prop:chmot}.{\it iii}. that,
\[ \psi^\mathrm{eff}_S(c_S(X)\otimes c_S(Y))\by{\sim} \psi^\mathrm{eff}_S(c_S(X))\otimes\psi^\mathrm{eff}_S(c_S(Y)). \]
Also, since $c_S(X)\otimes c_S(Y) \by{\sim} c_S(X\times_S Y)$, we have
\[ M_S(X\times_S Y) \by{\sim} M_S(X)\otimes M_S(Y). \]
Composing both sides with $\rho^\mathrm{eff}_S$, we get
\[ m_S(X\times_S Y) \by{\sim} \rho^\mathrm{eff}_S(M_S(X)\otimes M_S(Y)). \]
But, $m_S(X\times_S Y)=m_S(X)\otimes_Sm_S(Y)$ by definition. The lemma follows by noting that $m_S=\rho^\mathrm{eff}_S\circ M_S$.
\end{proof}

\begin{thm}
The functors $\rho^\mathrm{eff}_S$ and $\rho_S$ are tensor functors.
\end{thm}
\begin{proof}
In the previous section, we have already shown that $\rho^\mathrm{eff}_S$ is a lax tensor functor. That is, for objects $M, N$ in $SmMot^\mathrm{eff}_{gm}(S)$, there is a morphism in $DM^\mathrm{eff}(S)$
\[ \rho^\mathrm{eff}_S(M)\otimes_S\rho^\mathrm{eff}_S(N) \to \rho^\mathrm{eff}_S(M\otimes N). \]
which is natural in $M$ and $N$. But, by the above lemma, this is an isomorphism when $M=M_S(X)$ and $N=M_S(Y)$ for $X,Y$ in $\mathbf{Proj}_S$. Since $SmMot_{gm}^\mathrm{eff}(S)$ is generated by objects in $\mathbf{Proj}_S$ as an idempotently complete triangulated category, this shows that $\rho_S^\mathrm{eff}$ is a tensor functor.
Since the composition
\[ SmMot_{gm}^\mathrm{eff}(S) \xrightarrow{\rho_S^\mathrm{eff}} DM^\mathrm{eff}(S)\to DM(S) \]
is a tensor functor that sends $\underline{\;\;}\otimes\mathbb{L}$ to an invertible endomorphism, it factors through a canonical extension
\[ \rho_S: SmMot_{gm}(S) \to DM(S) \]
which is also a tensor functor.
\end{proof}

\begin{cor}
For $X\in \mathbf{Proj}_S$ of dimension $d$, $X\mapsto X^D:=X\otimes \mathbb{L}^{-d}$ gives an exact duality
\[ D: SmMot_{gm}(S)^{op}\rightarrow SmMot_{gm}(S).\]
\end{cor}
\begin{proof}
Note that for $X\in \mathbf{Proj}_S$ of dimension $d$ over $S$, the dual of $m_S(X)$ is $m_S(X)(-d)[-2d]$ in $DM(S)$. Since $\rho_S$
is fully faithful (see \cite[Corollary~6.14]{smmot}) and $\rho_S(X\otimes\mathbb{L}^{-d})=m_S(X)(-d)[-2d]$, we immediately get the duality in $SmMot_{gm}(S)$ as required. Since the dual object in a tensor category is unique upto unique isomorphism, this defines an exact duality involution $D$.
\end{proof}

redpajama_set_name: RedPajamaArXiv


If you were Thierry, what would you want?
Why don't you just talk to Kimmo about it?
Donald has lost quite a lot of weight.
I want to make sure nothing will happen to Panos.
I'm sure that Roland can handle it.
Randell, can I have a moment with you alone?
I don't know where Claire works.
Was Emil telling the truth?
Don's wedding ring is made of pure gold.
Horst is trying to change that.
Alan has no choice but to go.
If Matthias doesn't do what he's supposed to do, he'll regret it.
Pria can't have done it.
Jim chased after his dog.
Ozan doesn't have that problem.
Johnny asked me if I wanted to go to a movie with him.
I didn't see Hume do that.
Thuan said he was planning on visiting an old girlfriend in Boston.
Chuck is a little taller than I am.
Axel had to pay for damages.
Naoto has lots of things to tell Avery.
Owen is a very beautiful girl.
Klaudia apologized for calling so late at night.
Dieter and Ning are both good teachers.
Jinchao wants to see you in his office right away.
Rob may be feeling dizzy.
Donne put the photograph on the table.
Noemi has a bad hangover today.
Ritalynne made the same mistake again.
Francis went to the zoo with Jong.
Rajarshi! What are you doing?
Guillermo was just trying to protect himself.
Nick is naked from the waist up.
You said that Francisco wasn't hungry.
Siegurd has a meeting this morning.
Alastair is a shy boy.


text:
Q: UWP ColorPickerButton in UWP DataGrid cell won't be selected I use DataGrid and ColorPickerButton from here
xmlns:toolkit="using:Microsoft.Toolkit.Uwp.UI.Controls

When I click on the ColorPickerButton it keeps open and no color property changed.

How to fix it?
Thank you!
XAML
 <toolkit:DataGrid
                    x:Name="dataGridLayers"
                    Margin="0,0,0,0"
                    VerticalAlignment="Stretch" HorizontalAlignment="Stretch"
                    HorizontalScrollBarVisibility="Visible"
                    VerticalScrollBarVisibility="Visible"
                    AlternatingRowBackground="Transparent"
                    AreRowDetailsFrozen="False"
                    AreRowGroupHeadersFrozen="True"
                    AutoGenerateColumns="False"
                    CanUserSortColumns="False"
                    CanUserReorderColumns="True"
                    RowGroupHeaderPropertyNameAlternative=""
                    CanUserResizeColumns="True"
                    ColumnHeaderHeight="32"
                    MaxColumnWidth="400"
                    FrozenColumnCount="0"
                    GridLinesVisibility="None"
                    HeadersVisibility="Column"
                    IsReadOnly="False"
                    Height="400"
                    RowDetailsVisibilityMode="Collapsed"
                    SelectionMode="Single">
                                <toolkit:DataGrid.Columns>
                                    <toolkit:DataGridTextColumn Header="Name" Binding="{Binding LayerName}"  Tag="LayerName" IsReadOnly="True" />
                                    <toolkit:DataGridCheckBoxColumn IsThreeState="False"  Header="Включить в карту" Binding="{Binding LayerVisibility,Mode=TwoWay, UpdateSourceTrigger=PropertyChanged}"  Tag="LayerVisibility"  />
                                    <toolkit:DataGridTextColumn Header="Stroke" Binding="{Binding LayerStroke, Mode=TwoWay, UpdateSourceTrigger=PropertyChanged}"   Tag="LayerStroke" />
                                    <toolkit:DataGridTemplateColumn  Header="Color"  Tag="LayerColor">
                                        <toolkit:DataGridTemplateColumn.CellTemplate>
                                            <DataTemplate >
                                                <toolkit:ColorPickerButton SelectedColor="{Binding LayerColor, Mode=TwoWay, UpdateSourceTrigger=PropertyChanged}" />
                                            </DataTemplate>
                                        </toolkit:DataGridTemplateColumn.CellTemplate>
                                    </toolkit:DataGridTemplateColumn>
                                </toolkit:DataGrid.Columns>
                            </toolkit:DataGrid>

C#
 public abstract class EtherMapLayerBase : INotifyPropertyChanged
    {
        public Windows.UI.Color _layerColor { get; set; }
        public Windows.UI.Color LayerColor
        {
            get
            {
                return _layerColor;
            }

            set
            {
                if (_layerColor != value)
                {
                    _layerColor = value;
                    OnPropertyChanged();
                }
            }
        }

        public int _layerStroke { get; set; }
        public int LayerStroke
        {
            get
            {
                return _layerStroke;
            }

            set
            {
                if (_layerStroke != value)
                {
                    _layerStroke = value;
                    OnPropertyChanged();
                }
            }
        }

        public string _layerName { get; set; }
        public string LayerName
        {
            get
            {
                return _layerName;
            }

            set
            {
                if (_layerName != value)
                {
                    _layerName = value;
                    OnPropertyChanged();
                }
            }
        }

        public bool _layerVisibility { get; set; }
        public bool LayerVisibility
        {
            get
            {
                return _layerVisibility;
            }

            set
            {
                if (_layerVisibility != value)
                {
                    _layerVisibility = value;
                    OnPropertyChanged();
                }
            }
        }

        public event PropertyChangedEventHandler PropertyChanged;

        protected void OnPropertyChanged([CallerMemberName] string propertyName = null)
        {
            PropertyChanged?.Invoke(this, new PropertyChangedEventArgs(propertyName));
        }

        protected bool SetProperty<T>(ref T storage, T value, [CallerMemberName] String propertyName = null)
        {
            if (object.Equals(storage, value))
            {
                return false;
            }
            else
            {
                storage = value;
                OnPropertyChanged(propertyName);
                return true;
            }
        }
    }

    public class EtherMapLayerView : EtherMapLayerBase
    {
        public EtherMapLayerView()
        {
            LayerStroke = 1;
            LayerColor = Colors.Black; // using Windows.UI;
            LayerVisibility = true;
        }
    }

Update #1
It seems like a bug...
So when you select color in the first TAB nothing happen but if do the same on others TABs it works and color could be selected successfully.

A:
When I click on the ColorPickerButton it keeps open and no color property changed.

The problem is you have set the base color as Black LayerColor = Colors.Black, and that will make the color wheel can't be selected.
Please try to set the default color as Transparent, and it will work as expect.
LayerColor = Colors.Transparent

redpajama_set_name: RedPajamaStackExchange


Oshkosh, WI Lesson RateNot listed available time 12pm - Please email directly at Goaliesinc35@gmail.com to book lesson slot. 1:1 100.00/hr 2:1 75.00/hr All lessons include the ice rateOnce booked, lessons are not confirmed until each rink approves time slot. Once confimred by rink, Coach Stanaway will finalize lesson times. Please pay at time of lesson - Cash Perferred.


A new blood test measures autoantibodies called anti-vinculin, which have been found to be higher in scleroderma patients and have also been associated with gastrointestinal complications and pulmonary hypertension.
The test, called sclero-smart, was developed through a partnership with the Medically Associated Science and Technology (MAST) program at Cedars-Sinai Medical Center in Los Angeles, and is commercially available from Gemelli Biotech.
Vinculin is an intracellular cytoskeketal protein, present in many different types of tissues, that plays a role in cell structure and growth.
The prevalence of the most commonly measured autoantibody markers known to be associated with scleroderma — namely anti-centromere, anti-Scl-70, and anti-RNA-pol-III — ranges between 10% and 30%.
In contrast, up to 38% of scleroderma patients tested positive for autoantibodies against vinculin, according to an abstract published recently by the American College of Rheumatology, making these autoantibodies more prevalent than other biomarkers for scleroderma.
In addition, an association has been reported between the presence of anti-vinculin autoantibodies and gastrointestinal complications or pulmonary hypertension, suggesting that the new biomarker could help rheumatologists predict the risk of these conditions developing in scleroderma patients.
Scleroderma commonly affects the gastrointestinal tract of patients, therefore markers of GI complications are needed. In fact, researchers believe there is a link between scleroderma and the gut microbiome.
"We know from a substantial volume of research that bacterial infection in the gut can cause an autoimmune response that involves the abnormal production of anti-vinculin," Mark Pimentel, MD, executive director of the MAST program and co-founder of Gemelli Biotech, said in a press release.
"The connection between anti-vinculin and scleroderma means that the gut microbiome could help us answer many of the questions we still have about diagnosing and treating scleroderma," he added.
According to Gemelli, sclero-smart is the first and only commercially available test to measure the levels of anti-vinculin autoantibodies in the blood.
"Given how common the antibody appears to be in the patient population, this test could provide us with a more detailed understanding of the disease's underlying causes. As a potential catalyst for such a breakthrough, this test is an important development for helping patients with scleroderma," said Matt Mitcho, CEO of Gemelli.
Tagged anti-vinculin autoantibodies, biomarker, blood test, gastrointestinal complications, Gemelli Biotech, pulmonary hypertension, sclero-smart, vinculin.


text:
Karl Aegli (né le  et mort à une date inconnue) est un joueur suisse de football, qui évoluait au poste de milieu de terrain.

Biographie
Il commence sa carrière de footballeur au pays avec le club du FC Winterthur, avant de partir rejoindre l'Italie à Turin.

En 1909, il signe au club du FBC Torino, club à forte connotation suisse, où il ne joue qu'une seule saison. Il joue son premier match avec les granata le  lors d'un Milan - Torino (victoire 0-1) et son second et dernier le  lors d'une défaite 7 à 2 contre l'Inter Milan.

En 1910, il rejoint l'autre grand club turinois de la Juventus, rival du Torino. Il reste au club jusqu'en 1912 et y joue au total 19 matchs.

Liens externes

  Stats sur myjuve.it

Naissance en février 1887
Date de décès non renseignée (XXe siècle)
Footballeur suisse
Joueur du FC Winterthour
Joueur du Torino FC
Joueur de la Juventus FC

redpajama_set_name: RedPajamaWikipedia


text:
South Plains College
Official Home of the South Plains College Texans
Instagarm
Watch Games
Inside SPC
Texan Club
Equity in Athletics
Texan Club Schedule
SPC Bookstore
About SPC Athletic Training
#2 Lady Texans, #18 Texans set to host New Mexico Junior College Monday night
LEVELLAND — The South Plains College men's and women's basketball teams are set to host New Mexico Junior College on Monday evening at the Texan Dome in a pair of perennial WJCAC matchups.
The second-ranked Lady Texans will do battle with the sixth-ranked Lady Thunderbirds at 5:45 p.m., followed by the men's game at 7:30. Both games will stream live at spctexans.com and can be heard on KLVT Radio Levelland AM1230.
Currently tied for the conference lead, the Lady Texans come in with a record of 19-0 on the year, while New Mexico brings in a 12-4 mark, with both teams sitting at 3-0 in league play. The Lady Texans routed Clarendon college 86-44 in their previous outing on Jan. 6, as sophomore Ruth Koang tallied 17 points and 10 boards for South Plains.
Currently the top defensive team in the WJCAC allowing just 43.3 points per game, the Lady Texans will look to slow down a New Mexico team who averages just over 73 points per game and is shooting 42.9 percent from the floor on the season. The Lady Thunderbirds have won five of their last six, including wins over #8 Northwest Florida State and #7 Trinity Valley Community College.
The Texans come in looking to stop a two-game skid after falling to Clarendon and New Mexico Military Institute in their last two outings. Averaging 73 points per game and shooting 41.9 percent as a team, South Plains is led by freshman Rivaldo Soares who leads the Texans on the offensive end with 14.8 points and 4.7 rebounds per game. Soares has scored in double figures in six straight games as he looks to help get the Texans back in the win column Monday night.
New Mexico has won three of its last four, most recently a 73-58 victory over Howard College on Jan. 9. Averaging 73.7 points per game and shooting a 46.6 percent clip on the year, New Mexico is led by sophomore Terence Lewis who leads the conference in scoring with 20.8 points and 9.2 rebounds per game. Lewis is shooting over 58 percent on the year and has scored in double figures every game this season.
copyright @ 2015, south plains college.all rights reserved.
Levelland, Texas

redpajama_set_name: RedPajamaCommonCrawl


This comment was posted to reddit on Mar 29, 2015 at 1:33 pm and was deleted within 13 minutes.
Hey everyone, this is PSnipe and I wanted to share the meta data I've collected during my March legend climb and answer any questions regarding match-ups for Control Warrior and Zoolock. I focus on playing Hearthstone competitively but, like many people, I also deal with making my climb to legend each month with limited time (I play less than 10 games a day on average), so I'm also open to answering any questions people may have regarding strategies for climbing to legend.
Here is a table of the decklists I used, as well as the stats for each deck against classes and recognized decklists. Under the Vs. Classes table, I have also broken down the deck's win rate against Aggro, Midrange, and Control decks.
Footnote: There is a slight variation in number of games between classes and decks as some decks did not fit known archetypes.
This is the deck I ultimately piloted to Legend from Rank 5.
Decklist comments - Compared to standard lists, my Control Warrior decklist runs x1 Unstable Ghoul, x1 Bomb Lobber, and x1 Ragnaros instead of Alexstraza.
Unstable Ghoul: A really versatile card in this deck that helps in a few ways. I prefer this card over whirlwind as it puts not only a body but a taunt on the board. Unstable Ghoul benefits Face Hunter match-ups (due to the taunt and several 1 health minions), Druid match-ups (another taunt in addition to Sludge Belchers, also enables Execute), Paladin match-ups (counters Shielded Mini-bot, dudes and Muster for Battle [weaker than WW if they follow with Quartermaster]), Zoolock (taunt and counter Imp-losion and 1-health minions), and Oil Rogue (another taunt which denies Southsea Deckhand and prevents the Rogue from doubling their blade damage by hitting your face then using Blade Flurry). You can also drop Acolyte of Pain and/or Armorsmith behind Unstable Ghoul or when you are going to trade for more cards/armor off of the deathrattle. One advisory though, keep in mind how the opponent could use the deathrattle against you and your other minions on board (e.g. activating opponent Warrior's Grommash, giving one extra damage against your board for a Druid Swipe, etc.).
Bomb Lobber: I feel more has already been said here, so as much commentary is not needed. I prefer this card over Piloted Shredder for the tempo gain, the flexibility in gives you as pseudo-removal, and it's ability to target minions you may normally be unable to (e.g. Shade of Naxxramas).
Ragnaros vs. Alexstrasza: My goal for this Warrior deck is to take a more aggressive stance in most match-ups instead of waiting to Alexstrasza them before dropping my big guns. I found by the time I dropped Ragnaros, my opponent's rarely have a good answer for him, and this month I preferred his immediate board impact over Alextrasza due to the large number of midrange decks being played this month. Although Alexstrasza is more superior in Control match-ups and gives you a defensive bounceback in some aggro match-ups, I felt this dragon's impact generally offered little to no value for the board state in most match-ups this month compared to Ragnaros.
Face Hunter: I was a bit slow on learning this match-up and how to prioritize my health. Although the chart shows a 64% win rate, my win rate after adding Unstable Ghoul was 78% (7-2).
Oil Rogue: This is one of the primary reasons to play Control Warrior. At a whopping 91% win rate (20-2), Oil Rogues were also the most common deck I faced on ladder. You have to be very unlucky to lose against Oil Rogue, with my two losses being attributed to drawing zero removal (FWA, Death's Bite, Shield Slam, Execute) until turn 7 or 8.
This was the most effective deck I found for efficiently climbing the ladder to Rank 5. It is a killer for Mech Mage and Tempo Mage and I also found it to be strongly favored in my early climb against Face Hunter, though the win rate against Face Hunter slipped significantly after Rank 5. Zoolock also has a favorable win rate against Midrange Druid due to their lack of board clear and Oil Rogue due to the deathrattle minions and limited board clear options with Blade Flurry. I have seen Payton's Zoolock list as well as a couple others with the higher mana curve and bigger drops and I simply don't like them. They obviously have seen some success on the ladder for some people, but I find the higher curve gives too much inconsistency for a Zoolock deck.
For thoroughness I included every deck I used in this post; however, these decks I used in a limited capacity for one reason or another.
Trampoline Warrior - Very interesting deck made by /u/Glutol and within my wheelhouse as a Warrior player, but I couldn't pilot this deck with a reasonable amount of success. Anything this deck could beat (besides Mech Mage), I could beat more consistently with Control Warrior. I attribute the lack of success to my lack of experience with playing it.
Handlock - I had never tried Handlock before I wanted to get a better breadth of experience for when I play against it. Seems like a strong deck.
Splashyship Mech - This is a very unique deck made by my friend Splashyship at the end of last season. He didn't intend for it to be competitive and was messing around in legend ranks with it. It is solid against Control decks like Control Warrior, but ultimately too inconsistent against several other decks.
Also noteworthy is that 43% of the decks I played against were Midrange decks (vs. 28% Aggro and 29% Control), with the midrange charge being led by Oil Rogue and Midrange Druid.
I will footnote here that my count of Control Paladin vs. Midrange Paladin may be a bit fuzzy in some cases as it is difficult to distinguish the two without seeing a large number of cards.
Well, that is it for now. Please leave your comments/questions below and I will my best to respond to them. Thank you to this sub for its wonderful contributors and wealth of data.


text:
Dad transforms hallway with DIY panelling for less than £130
Russell Tomlin is delighted with the hallway's transformation
hulldailymail
A dad took inspiration from Houzz and Pinterest to create DIY panelling which transformed his hallway.
Russell Tomlin, a dad-of-one and head chef at a local restaurant, wanted to jazz up the hallways and staircase of his new home, but also wanted to stick to a budget.
The 28-year-old used supplies from B&Q and white paint he already had to makeover his hallway and staircase into a Pinterest-worthy panelled space – and it cost him just £128.
Russell, who lives in Colchester, told money-saving community LatestDeals.co.uk: "I bought the house a year ago and wanted to make it my own. I used Houzz and Pinterest to get a couple of ideas and came across a panelled hallway.
"I decided that's what I wanted – it's a very small hallway entrance and I wanted to make it look bigger and this was a great way of doing that.
"I am pretty handy with DIY and I do have a good collection of tools so I knew I could do it.
"I'm a chef but I've just loved making things since I was a child with my grandad – he's the one I've got all my DIY skills from.
"I ordered my materials from B&Q and picked them up.
"I did have them cut them down so I could get them in the car, but then I did all the final big cuts at home with a table saw.
"Measuring everything was the hardest part, especially the staircase with all the different angles.
"The process is to start from the top and work down – it's slightly more work but you know you are getting it nice and straight then.
"Cut and stick the top panels down, making sure to check with a level that everything is straight.
Couple's before and after living room photos will make you want to redecorate your own home
Woman shares before and after pictures of hallway transformation on a budget
"Then cut the next panels all the same size – I used a table saw to do this.
"Stick them all down using a square ruler measuring each one as you go.
"Then cut the next long pieces and stick them down, making sure to hold them for at least two minutes.
"Then for the bottom panels, cut three at a time, as they will probably be different sizes due to the uneven floor and walls most houses have.
"Then seal all edges with decorators caulk and paint.
"There are many different styles of panelling you can go for, so my advice would be to do lots of research.
"The end result was worth all the hard work. It took me about four days to do and the total cost was £128 for everything.
"Some bits I already had, like the light fitting and the white paint.
"The £128 included wood, adhesive glue, decorator's caulk, and paint. The picture frames are from The Range.
"I'm very happy with it and I hope it may even have added a bit of value to my house."
Russell is delighted with the hallway's transformation and says that preparing properly is key to pulling off the look.
"My top tips for people who want to do it would be to measure everything twice and cut once," he adds.
"Try to have more than one person helping just to help hold bits up while the glue sticks as I had to do it all by myself.
"Always use a levelling stick and also don't be afraid of a hard job – be confident.
"This project is great to do while in lockdown as it keeps you busy and possibly would be making you money by adding value to your home and it just feels good to do it yourself.
"Ordering supplies is easy and delivery is quick – just measure everything twice so you get everything you need the first time."
Tom Church, co-founder of LatestDeals.co.uk, comments: "If you're interiors-obsessed, you probably spend hours scrolling through Pinterest looking at expensive homes.
"However, as Russell proves, you don't need to spend a fortune to bring high-end features to your own house.
"If you don't know where to start, there are loads of online tutorials all about panelling – just go onto YouTube for free step-by-step guides."


The meeting was convened by HCD and facilitated by USAID-KAVES through the Kenya Flower Council in collaboration with FPEAK and KEFE. It was attended by HCD, KEPHIS, USAID-KAVES and County Governments representative among others.Presenters included representatives from the Horticulture Crop Directorate.
HCD appreciated the USAID KAVES for funding the system saying that the initiative started two years ago following the numerous interceptions of Kenya's Horticultural produce at the EU market.
To instill confidence to consumers the Government with the assistance of USAID KAVES initiated the NHTS project piloting with 12 companies including two flower farms. He said that the reason for the meeting was to deliberate on how the system can be adopted by the industry. The system is set to be rolled out to all export companies across the country in the long run.
KEPHIS enumerated the services offered to the industry by his institution and welcomed the system saying it will go a long way to ensure exporters comply with market requirements.
The Kenya Flower Council exhorted exporters to adopt traceability. It gave the genesis of the NHTS saying that it was a result of the myriad interceptions and there was need to find a way of dealing with them. It said the system will weed out rogue famers and ensure sustainability of the industry.
It noted with happiness that the process which was prompted by the interceptions crisis is now at the tail end. It expressed profuse gratitude to USAID KAVES for funding the process.
It emphasized that sustainability of the project is key as the development partner is soon leaving. He said the industry is committed to the cause of NHTS and urged all actors in the horticulture space to ensure that the system is taken up positively and that the anticipated investment in the system is a small price to pay vis a vis the benefits that will accrue from implementing the system.
It called for the integration of existing systems into the NHTS, e.g the 'e' phyto, KS 1758 I & II.
It stressed that in investing in the system the industry gives the country an opportunity to brand itself as a source of quality products and that it will be a first for Kenya.
It was reported that Agriculture is the backbone of Kenya's economy contributing 25% of the country's GDP. She noted that horticulture contributes 36% of the Agriculture GDP. She noted 6.5 million Kenyans are employed in the sector. That production is mainly by smallholder farmers thus contributing significantly in poverty alleviation especially in rural areas. She observed that the sector generated 101 billion KES last year (2016).
The representative added that the markets are regulated by stringent requirements which Kenya must meet to enhance and sustain market access. She said that Counties have been supporting farmers to comply and hence traceability is thus a critical step to achieve market access.
She thanked USAID KAVES for funding the NHTS. She also thanked HCD, KEPHIS, and PCPB, Ministry of Agriculture Livestock and Fisheries (MOALF) and the farmers currently piloting the product.
She noted that the product will increase confidence in Kenya's products in the market-that the horticultural produce from Kenya is compliant to standards and food safety requirements. That this will in turn increase trade between Kenya and the World.
She called upon all players in the horticulture value chain to support the NHTS. She noted that individual companies have their own traceability system and urged them to look at the greater good of selling one system to the market-branding Kenya as a source of quality and safe produce. She ended by saying that regulators have played their role and now the ball is in the farmers' court.
HCD noted that the main ingredients of the system are a smart phone and a printer and only then can one download the application. It noted that the system is composed of several modules including Exporter, HCD,KEPHIS,Consumer.
It reiterated the significance of horticulture to Kenya's economy and added that the major destination is the European Union.
It enumerated the challenges facing the industry including non-compliance and interceptions.
It noted that previously the movement of produce was uncontrolled and unmonitored-that it was not possible to trace produce from the EU market- in case of a notification- to Kenyan farms but with the introduction of the NHTS this is now possible.
It observed that the system provides unique codes to farmers and can be able to isolate and identify uniquely all farms in Kenya who are registered in the system. It said the system can comfortably accommodate a million farmers.
It said the scope of the system will be expanded to cover the local produce too in the near future. He said the system will be integrated with labs where inspectors will be able to send samples directly from the phone and get results online.
It noted that currently 1,266 farms are registered in HCD database and there are 60 collection centers countrywide. He said that HCD has already equipped 16 packhouses with printers and currently 12 farms including 2 flower farms are piloting the system. It was reported that HCD targets all exporters to be in the system soon.
USAID-KAVES noted that few commercial systems exist in the market but none fitted the EU regulations and HCD expressed concern over this and approached USAID KAVES. It noted that over 400 companies registered to offer the system but none met the required threshold.
It urged exporters to support the implementation of the system as USAID-KAVES is exiting the stage come 12th January 2018. It asked exporters to consider the cost of implementing the system as opposed to the cost of not implanting it and most importantly to deliberate on how it will be implemented.
Mr Tim made a comprehensive presentation on the NHTS business plan. He asked actors to design a framework that will make the system work-the roles of individuals/institutions, management structure, financing and available options around financing. He noted that there is general consensus that to have an efficient and effective traceability system in place is essential, that it should be self-regulating, that it should be managed within the private sector, that it should be responsive and operate 24 hours a day seven days a week all year round.
He took participants through the various laws and regulations stressing the need for traceability-these are found in the Horticultural Code of Practice, Crops Act sec 40, MOU with HCD, among others.
He said the the main benefit of the NHTS is creating confidence and trust in the market.
He said that not having a credible system may lead to bankruptcy of companies, business closures, market loss and brand damage.
He then presented the business plan and offered various management options and structures.
The management of the system will be jointly by KHC and the regulators using the HCAS model.


No new action has been taken to ensure Virgin Care properly reports any safety concerns, it appears.
Local health bosses reassured Bath residents they would keep a close eye on Virgin Care after revelations the private company encouraged staff not to report their safety concerns to the health watchdog, which the firm said was to not to stop reports being made but rather to prevent duplication of reports that were already being handled centrally.
The local authority and NHS Clinical Commissioning Group (CCG) for the region said in October they would "closely monitor" the services provided by the private company in Bath and North East Somerset.
* request that councillor Vic Pritchard, the member for adult care, health and wellbeing, ensure issues of concern are reported through the appropriate council bodies so as to ensure full transparency.
What will change under Virgin Care?
Asked what had been done since the council passed the motion tabled by councillor Will Sandry (Oldfield, Lib Dems) on November 9, the CCG and the council provided the following joint response.
"The council's head of safeguarding and quality assurance and the CCG's director of nursing and quality have confirmed that the Virgin Care contract sets out clear and rigorous requirements in relation to the reporting of any patient safety concerns, including how these concerns will be addressed," a spokeswoman said.
"Adherence to these requirements is managed and monitored at monthly contract review meetings between the three organisations.
Mr Pritchard referred the Chronicle to the council's press office after we approached him for an interview.
At the last full council meeting he said he would "answer concerns about ongoing scrutiny" and assured councillors that the health and wellbeing select committee would be kept informed.
A Virgin Care spokesperson said: "There was no attempt to prevent concerns from being raised with the health watchdog or with any other organisation and, indeed, we pro-actively shared information with the CQC and our commissioners.
"Colleagues were supported to deliver care while our local and senior teams met regularly to monitor progress and brief our commissioners and the CQC on the issues and what was being done to resolve them; we have shared comprehensive details with the CQC and they have not raised any concerns.
"We are now focused on working with those colleagues to deliver what we promised local people: bringing health and social care together and focusing on helping people to get well and stay well. We are already having successes such as the rapid response falls team, our home first partnership with Royal United Hospitals which is ensuring people are discharged from hospital and supported at home more quickly, and working with commissioners to shape local mental health services around people who use them."
Note: This story has been updated with a response from Virgin Care.


text:
News from MFA Serbia Fifteen apartments handed over to the refugees from Bosnia and Herzegovina and...
Fifteen apartments handed over to the refugees from Bosnia and Herzegovina and Croatia in Arilje, within the framework of the Regional Housing Programme
The address of First Deputy Prime Minister and Minister of Foreign Affairs Ivica Dacic in Arilje, at the ceremony of delivering keys of 15 apartments to refugees from Bosnia and Herzegovina and Croatia, within the framework of the Regional Housing Programme in Serbia:
"Distinguished guests,
Dear friends of the Regional Housing Programme,
It gives me great pleasure to address you at this ceremony and mark with you the completion of apartment building construction and a new beginning for the people who will move into these housing units. The pleasure is even greater to know that a week after we laid the foundation stone for new apartments in Veternik, keys to 15 apartments will be given to our fellow citizens who were forced to flee conflict areas of the former Yugoslavia. The apartments we hand over today are housing units completed under Subproject 4 of the Regional Housing Programme.
I would like to recall that the construction of housing units in Arilje represents a part of implementation of the Regional Housing Programme as the most important regional initiative to reach durable solutions to the long-standing problems of persons displaced by conflicts in the 1991-1995 period. The Republic of Serbia is committed to an efficient implementation of undertaken obligations as exemplified by our today's participation in the key delivery ceremony, which is an important symbolic gesture of support for the refugees who opted to settle in the municipality of Arilje.
The construction of housing units in Arilje commenced in July 2017. The project was financed by the Regional Housing Programme Fund, in the amount of 330 thousand EUR and by a contribution of the municipality of Arilje, in the amount of 10 million RSD. Within this project of the Regional Housing Programme, five country houses totalling 55 thousand EUR in value terms, have also been bought.
I would also like to underline that within the Subproject 4 of the Regional Housing Programme there will be a total of 661 housing units for refugees throughout Serbia. Apart from 261 apartments, other types of housing units within this Project, whose worth amounts to 13 million EUR, are almost complete – 70 country houses have been bought out, 30 prefabricated houses have been built, and the largest part of 300 packages of construction material has been delivered.
Refugees who were forced to leave their homes throughout the former Yugoslavia at the end of the last century deserve certainty and life in dignity after more than 20 years living as refugees and in conditions unworthy of human beings. In this respect, arriving at a solution for the refugee issue is the single most important moral obligation of the state and of the international community. Our belief, but also the belief of our partners from international organizations, is that we have achieved significant results in this regard, which makes the Regional Housing Programme a successful initiative and a positive example of reaching durable solutions to humanitarian consequences of forced displacement.
The Government of the Republic of Serbia, with other partners, remains firmly committed to and engaged in implementing the Regional Housing Program which will ensure housing for 6,000 families in Serbia, out of which 2 102 persons will have been provided for following today's ceremony. The full implementation of the Programme will improve each individual person's life, although it is only a partial compensation for the suffering triggered by forced displacement from their home regions. We hope that our fellow citizens who move into the apartments today will find peace and security in them, after two decades of hardships. I wish them a warm welcome to their new homes and a successful new beginning!
I would like to thank representatives of the local self-government and the citizens of Arilje for their cooperation, not just in the implementation of the Housing Programme, but also for their help and solidarity during the reception of a few hundred refugees and displaced persons. The understanding and support of the local community remains invaluable.
Last but not least, without mentioning anyone in particular, I would like to take this opportunity to thank all donor countries, as well as our partners from international organizations, who have been supportive since the very beginning of our efforts to help with providing housing for the most adversely affected refugees from Croatia and Bosnia and Herzegovina.
Previous articleMinister Dacic received a farewell call from the Ambassador of the Republic of Korea
Next articleTimișoara: Twenty-fifth anniversary of the "Days of Transfiguration", a literary and spiritual event organized by the Serbs in Romania
Addis Ababa: Ambassador Ristic participates in a mini football tournament
Dacic: "It is necessary to build strategic relations with Peru"
Consulate of the Republic of Serbia, headed by the Honorary Consul, was opened in Lima
French President Emanuel Macron visited Serbia July 16, 2019
Автопробег «Дороги славы – наша история» в Сербии July 16, 2019
Ancient Antiquities, Reda's Folklore, Arabic Contemporary Music and Virtual Reality Commemorate History, Present and Future At The National Day Celebration of the Egyptian Embassy in Belgrade at the National Museum of Serbia July 15, 2019
The Bastille Day marked in Belgrade July 15, 2019
dp - July 16, 2019
Обавештење о олуји на Халкидикију
Irak : au moins cinq morts dans une attaque suicide à Bagdad July 15, 2019
Au moins cinq personnes ont été tuées et une dizaine blessées lundi soir lorsque deux... Irak : au moins cinq morts dans une attaque suicide à Bagdad
Il y a trop de sucres dans la nourriture pour bébé, prévient l'OMS July 15, 2019
L'Organisation mondiale de la santé a analysé près de 8000 produits dans plus de 500... Il y a trop de sucres dans la nourriture pour bébé, prévient l'OMS
Macron en Serbie s'engage à oeuvrer pour un compromis avec le Kosovo July 15, 2019
Emmanuel Macron a promis lundi à Belgrade de tout faire pour oeuvrer à un compromis... Macron en Serbie s'engage à oeuvrer pour un compromis avec le Kosovo
DE.News Front — Aktuelle Nachrichten auf Deutsch. Online lesen
Video: In Paris kam es zu Zusammenstößen zwischen Gelbwesten und der Polizei July 14, 2019
Auch am Nationalfeiertag Frankreichs gingen die Gelbwesten auf die Straße und es kam zu... Video: In Paris kam es zu Zusammenstößen zwischen Gelbwesten und der Polizei
Gastbeitrag «Die Woche Compact» : Wahlfälschungen in Sachsen, Schlagabtausch um Höcke July 14, 2019
Ist Massenmord in der bunten Republik ein Ausdruck von Toleranz und Vielfalt? Mit einem Schreiben,... Gastbeitrag «Die Woche Compact» : Wahlfälschungen in Sachsen, Schlagabtausch um Höcke
Russisches Militär liefert die achte Ladung der S-400-Komponenten in die Türkei July 14, 2019
Russische Militärtransportflugzeuge haben eine weitere Ladung von Komponenten für die S-400-Raketensysteme in die Türkei geliefert,... Russisches Militär liefert die achte Ladung der S-400-Komponenten in die Türkei


text:
Lifting the veil of despair
Published:Wednesday | April 14, 2010 | 12:00 AM
Dennie Quill, Contributor
The opening of the state-of-the-heart Orchard health clinic on Monday was a landmark moment for western Jamaica and, indeed, the entire country. This clinic is the latest philanthropic gesture from American Edgar Cullman who has been a tryall resident for many years.
Cullman, 92, described as king of the cigar business, was named Commander of Distinction by the Jamaican Government in 1989. I was curious about this benefactor and was drawn to his curriculum vitae. Apart from being a cigar man, he has been involved in a variety of businesses which range from plastics, packaging, potato chips, laxative to real estate.
"I love Jamaica," Cullman declared at the formal opening ceremony. "Words cannot describe how much I love Jamaica and its people."
Big ticket items
In a country of so many needs, Mr Cullman must have thought very carefully about where his million-dollar contribution would be best spent. I am happy that he chose health care. Health care is one of the big-ticket items on the national budget and, in the current economic environment, it provides one of the greatest challenges to the administration to provide medical and personnel with the requisite resources.
Politicians eager to impress the electorate always promise to provide affordable health care for its citizens. They are given to making elaborate claims and often unrealistic promises. Many industrialised countries already provide near universal health coverage for its citizens. The debate continues to rage over whether the current government's socialised health care is working. There are arguments on both sides. Some say persons who would normally forego a visit to the doctor will not postpone that visit any longer since the service is free, which is good for preventative care because it can often lead to detection of a major problem in the early stages.
Yet, there are others who argue that with the limited resources at health care facilities the staff is stretched and find it challenging to deal effectively with the increased numbers of patients who turn up on a daily basis. They suggest that this leads to greater inefficiencies.
Current imbroglio
The practical ones among us say people who can afford to pay ought to pay. This is especially important given the current imbroglio over wages, which has kept the nurses and Government in an ugly embrace for most of this Government's life. Orchard is a private facility, so one expects that patients will pay for the services offered there.
Scores of Jamaicans, including those with limited means, are reaching out to help Jamaica's next generation. Future doctors, lawyers, accountants, teachers, nurses etc are being helped to get an education by persons who foot expenses such as tuition, accommodation, books and other day-to-day living expenses. Many do their bit quietly and without fanfare.
These kind souls have helped to lift the veil of hopelessness and despair from scores of talented children who would otherwise fall by the wayside.
We also have to thank those in corporate Jamaica and alumni associations, who continue to give scholarships and other support to students. The Government must now find creative ways to encourage more social enterprise because this is sure means of empowering communities.
Dennie Quill is a veteran journalist. Send your feedback to editor@gleanerjm.com


text:
Arsenal 1 Stoke City 0: match report
Read a full match report of the Premier League game between Arsenal and Stoke City at the Emirates on Wednesday Feb 23 2010.
By Jeremy Wilson 23 February 2011 • 23:18 pm
Dejected: Arsenal captain Cesc Fabregas trudges off after picking up a leg injury against Stoke Credit: Photo: GETTY IMAGES
From the flair of Barcelona to the functionality of Stoke City, Arsenal continue to surmount all variety of obstacles in their quest for an unprecedented quadruple.
They now trail Manchester United by just one point at the top of the Premier League and, on Sunday, an inviting opportunity awaits against Birmingham City in the Carling Cup final to end their five year trophy famine.
After the aesthetic beauty of their Champions League victory over Barcelona last week, this was quite simply a demonstration of their new-found ability to win ugly. Arsene Wenger called it "resilience" and it is a quality that clearly excites him just as much as their flowing football.
Yes, it was a result that came at some cost following the injuries to Cesc Fabregas and Theo Walcott but, make no mistake, this was precisely the sort of occasion on which their title ambitions have recently foundered. "We have matured greatly," declared Wenger.
As well as the Carling Cup final, Sunday will be the one year anniversary of Aaron Ramsey's double-leg fracture and, on the first meeting between the two clubs since that dreadful incident, it was clear that neither set of fans had forgotten.
Ryan Shawcross, who inflicting the mistimed tackle, was jeered relentlessly, something that only prompted the Stoke City supporters to chant the name of their captain. Despite both sets of players remaining admirably committed rather than reckless, it led to an unpleasant atmosphere.
The boos, though, were soon interspersed by gasps as Arsenal began with some breathtaking football.
Jack Wilshere, picking up from where he left off against Barcelona, immediately carried the ball into a dangerous position deep inside the Stoke half and cleverly picked out Fabregas. The Arsenal captain glanced up and duly executed a defence-splitting pass for Walcott.
The angle was acute but Walcott's shot appeared precise as it thundered past Asmir Begovic's out-stretched arm.
Walcott, though, had just curled his finish away from Begovic and, with what must have been its final rotation, the ball moved sufficiently to catch the inside of the post and rebound to safety.
The Arsenal pressure continued and, even after only eight minutes, there was a sense of inevitability when the first goal arrived.
Nicklas Bendtner, who had been given the chance to lead Arsenal's attack in the absence of Robin van Persie, diverted Wilshere's partially cleared corner back across the six-yard box for an unmarked Sebastien Squillaci to head past Begovic.
It was Squillaci's first Premier League goal and, after a difficult settling-in period since his £3.2 million summer move from Sevilla, clearly important for his confidence.
Arsenal's momentum, however, was checked by the sudden departure of Fabregas. Andrei Arshavin is no bad replacement but, with Samir Nasri shifting into the central Fabregas role, the team lost their impetus.
Stoke also deserved credit for the way they got themselves back into the game and began to test Wojciech Szczesny. The Arsenal goalkeeper was required to make one outstanding first-half save when he dived, full length, to claw John Carew's volley to safety with an out-stretched hand.
After the recent history between the clubs — Wenger likened a Stoke goal earlier this season to "rugby" — it was unsurprising that there should also be moments of controversy.
Tony Pulis, the Stoke manager, became particularly agitated when a challenge from Squillaci on Carew was ignored, but Jonathan Walters was then booked for impeding Walcott.
The temperature was further raised when Rory Delap's studs-up tackle left Bacary Sagna in obvious pain.
Stoke also maintained a footballing threat throughout the second-half.
Jermaine Pennant, the former Arsenal winger, crossed accurately for Shawcross but what would probably have been the most unpopular goal ever scored at the Emirates was prevented by Djourou's block.
Delap's long throws were also causing problems, with Robert Huth directing one header beyond Szczesny but narrowly over.
Arsenal's threat had become sporadic but, shortly before being stretchered off, Walcott did miss one excellent chance after Arshavin had skillfully beaten Shawcross.
Stoke, though, ultimately lacked sufficient quality to punish that profligacy. The final chant of "1-0 to the football team" was slightly harsh. Arsenal had joined Stoke down in the trenches and, after 90 wounding minutes, still emerged with all three points.


B100x 2300T Li-Ion Battery. If ordering as a replacement to another capacity battery, must order PMLN6745 Battery Cover.
Motorola often changes the product SKU name. This product may have also been known as PMNN4468a, PMNN4468b, PMNN4468c, PMNN4468d, PMNN4468e, PMNN4468f, PMNN4468ar.


Call Holiday Heating & Air Conditioning for a $79.99 maintenance check today!
Ameren Missouri utility rebates up to $900 when you replace your old HVAC with a high-efficiency model. Rebates range from $100 to $900.


Vote City of Heroes for a Chance to Win!
MMOsite.com is holding their 2012 Reader's Choice Awards and City of Heroes is nominated in two categories, Best Community and Most Classic MMO. City of Heroes has already climbed the ranks quickly and is battling toward the top spot in both categories.
We would like nothing better than to see City of Heroes take top honors, but we've also thought of a way you can be a winner, too!
Below you will find information on how to enter a contest to win a Commemorative AP33 Unity Rally Patch! You can earn multiple entries by completing each of the tasks listed in the giveaway widget below. Yes, it's a real world task force!
Visit MMOsite.com and vote for City of Heroes in both categories. You can vote once per day, so please continue voting through January 6th, if you can!
I voted 🙂 And I will vote again tomorrow, COH deserves to be recognized.
I've been voting since I heard of it!
I voted… and it would be a nice thing for CoH to win even with NC Soft pulling what they did. It'll show that they got rid of a good thing.
I hope CoH wins that way NCSoft can have their jaws fall to the floor.
For this particular giveaway, yes, but we have more patches and will be sure to give some away via Twitter.
Voted and will continue to do so. Long live Paragon!
Thank you for offering the patches this way. I have already voted on the MMO site for the City.
Voted for it as soon as I heard about it. And I voted a second time for each this morning.
I can't wait to give these patches away! Be sure to spread the word!!


Klebefolie Fliesen - Welcome in order to our weblog, in this particular time period I'll explain to you in relation to Klebefolie Fliesen . And today, this is actually the primary graphic: 47 Luxus Galerie Von Fliesen Klebefolie Bad from Klebefolie Fliesen , source:maryland-business.net Badezimmer Klebefolie from Klebefolie Fliesen , source:capitaliproductions.com Why don't you consider picture preceding? is of which amazing???. if you feel thus, I'l d teach you a number of photograph once more beneath: Bad Fliesen Ideen Bilder from Klebefolie Fliesen , source:agracioushome.com 47 Luxus Galerie Von Fliesen Klebefolie Bad from Klebefolie Fliesen , source:maryland-business.net Bad Fliesen Ideen Bilder from Klebefolie Fliesen , source:agracioushome.com Fliesenfolie Küche Mosaik from Klebefolie Fliesen , source:astrallis.com Hornbach Klebefolie from Klebefolie Fliesen , source:capitaliproductions.com Fliesen Folie Trendy Resimdode Abziehen With Fliesen Folie Fliesen from Klebefolie Fliesen , source:fliesendesign.facilblog.com Bad Fliesen Ideen Bilder from Klebefolie Fliesen , source:agracioushome.com 58 Hervorragende Wohnzimmer Fliesen from Klebefolie Fliesen , source:hausinnen.club Fliesenfolie Bad from Klebefolie Fliesen , source:brokenprismgames.com Badezimmer Klebefolie from Klebefolie Fliesen , source:capitaliproductions.com So, if you desire to receive all of these fantastic pictures about (Klebefolie Fliesen ), click save icon to save the pictures to your personal pc. There're prepared for down load, if you appreciate and wish to take it, click save logo on the post, and it will be immediately down loaded in your pc. As a final point if you would like secure unique and the recent photo related to (Klebefolie Fliesen ), please follow us on google plus or save this site, we try our best to provide regular up-date with all new and fresh photos. We do hope you like keeping here. For most up-dates and recent news about (Klebefolie Fliesen ) shots, please kindly follow us on tweets, path, Instagram and google plus, or you mark this page on book mark section, We attempt to provide you with up grade periodically with fresh and new pictures, love your exploring, and find the ideal for you. Thanks for visiting our website, contentabove (Klebefolie Fliesen ) published by at . Nowadays we are delighted to declare that we have found a veryinteresting nicheto be pointed out, namely (Klebefolie Fliesen ) Many individuals looking for information about(Klebefolie Fliesen ) and certainly one of them is you, is not it?


text:
Two men sentenced to die
Two men, sentenced to die in the electric chair on the same day, were led down to the room in which they would their maker. The priest had given them last rites, the formal speech had been given by the warden, and a final prayer had been said among the participants.
The warden, turning to the first man, solemnly asked, "Son, do you have a last request?"
To which the man replied, "Yes sir, I do. I love dance music. Could you please play the Macarena for me one last time?"
"Certainly," replied the warden. He turned to the other man and asked, "Well, what about you, son? What is your final request?"
"Please," said the condemned man, "kill me first."
What do ya call a
What do ya call a bunch of guys breaking into a music store and helping themselves to the stringed instruments?
Luters.
Q What do ya call
Q: What do ya call a bunch of guys breaking into a music store and helping themselves to the stringed instruments?
A: Luters.
a blonde buys a record
a blonde buys a record device that she is trying to hook up to her tv but she couldnt get it to work. frustrated after 3 hours of trying she calls customer support she tells them she wants to wants to record a tv show but she couldnt hook it up. so the man came to her house and took a quick scan and nods twice. he says first of all thats a record player an- the blonde interrupts and says REALLY!!! whats that do? ...it plays music he replied. also why are you trying to hook a record player to a radio?
After 17 years of marriage
After 17 years of marriage, a man dumped his wife for a younger woman.
The house was in his name and he wanted to remain there with his new love so he asked the wife to move out and then he would buy her another place.
The wife agreed to this, but asked that she be given 3 days on her own there, to pack up her things.
While he was gone, the first day she lovingly put her personal belongings into boxes and crates and suitcases.
On the second day, she had the movers come and collect her things.
On the third day, she sat down for the last time at their candlelit dining table, soft music playing in the background, and feasted on a pound of shrimp and a bottle of Chardonnay.
When she had finished, she went into each room and deposited a few of the resulting shrimp shells into the hollow of the curtain rods. She then cleaned up the kitchen and left.
The husband came back, with his new girl, and all was bliss for the first few days. Then it started; slowly but surely.
Clueless, the man could not explain why the place smelled so bad. They tried everything; cleaned & mopped and aired the place out. Vents were checked for dead rodents, carpets were steam cleaned, air fresheners were hung everywhere. Exterminators were brought in, the carpets were replaced, and on it went.
Finally, they could take it no more and decided to move.
The moving company arrived and did a very professional packing job, taking everything to their new home ... including the curtain rods.
Apple announced today that it
Apple announced today that it has developed a breast implant that can store and play music.
The iTit will cost from $499 to $699, depending on cup size, speaker size, and storage capacity.
This is considered a major social breakthrough, because women are always complaining about
men staring at their breasts and not listening to them.
Q What type of monster
Q: What type of monster really loves dance music?
A: The boogieman.


This sturdy, round garden parasol concrete stand weighs approx. 15kg. If you're investing in a decent garden parasol then it's important to consider the right parasol stand for the job. In a sudden gust of wind an unanchored outdoor parasol can cause havoc.
Particularly with larger wooden framed parasols you shouldn't underestimate the power of the wind and the need to securely anchor your outdoor parasol with a substantially weighted parasol stand.
With a 42cm (16.5″) diameter, this robust concrete garden parasol stand features a rubber ring around the base for ease of use. This makes it easy to roll into position if you can't lift it.
An essential anchor for your parasol!
There are also a number of rubber feet on the underside to grip the floor, making sure it won't slide around. Well built, reliable and weatherproof, this round garden parasol concrete stand is perfectly designed to stand firmly under your garden table and prevent your outdoor parasol from blowing away in your on-going battle with mother nature.
A coated steel support tube screws to the centre of the concrete base. A set of various plastic inserts are supplied to enable the tube to accommodate a variety of different sized umbrella shafts.
This top quality concrete umbrella base is suitable for umbrella and parasol poles with a maximum diameter of 4.4cm (1¾ ") and a minimum diameter of 2.5cm (1"). An adjustable screw, inserted in a hole at the top of the tube clamps onto and supports the parasol shaft.
Your concrete parasol base will be shipped protected in moulded polystyrene packaging in a single outer carton with simple assembly instructions included.
Need something heavier? Try this 50kg beast for size!