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text:
Q: Google Drive Picker API - How to find folder ID I'm completely new to Google Drive API!  I've managed to get the Google Drive Picker API to work and do most of what I need.  But here is my problem:  Consider two folders:
root/test1/folder1
root/test2/folder1
Everything in the API uses ID for files and folders.  How can I get the folder ID for those two "folder1" folders to use in .setParent?  All the examples I can find both for Picker and the Drive API in general use hard coded IDs!  I don't know where to start.
Many thanks in advance :)

redpajama_set_name: RedPajamaStackExchange


Channel Supply experts consist of a team of experienced consultants, who are former Amazon workers, themselves. We understand everything there is to know about the Amazon marketplace and their selling support system. We know the steps that are involved in getting approved for a specific category can be exhausting. Our experts can handle all the important details, big or small, to get you approved quickly to sell in the category of your choice.
Here are some commonly asked questions about the approval process and how we can help.
As an Amazon seller, what do I need to know about their selling categories?
Amazon offers what's called open and restricted categories to sell your products under. Open categories are departments that allow you to sell your product in without an approval. These are great for getting started and building a reputation as a seller. Once you're a little more established and have a good sales history, you can try to apply for approval to access some of the restricted categories, to further your marketing efforts. We can evaluate your situation and consult with you on which is better for your Amazon selling the business.
Why should I gain approval to sell my products on Amazon?
Having access to sell in some of the more lucrative categories, within the Amazon marketplace, can be a game-changer for you and your business. By opening up more departments to sell it, you're increasing your customer base as well as product exposure. But, gaining the approval necessary to start making profits in the category of your choice may be an uphill battle. Amazon has an approval process that contains some steep hurdles to overcome, in some cases. Each part of the application process can be a nightmare with all the documentation requirements and detailed information they request. We are familiar with the Amazon's approval process and can pinpoint exactly what you need to increase your chances of getting approval.
What is a restricted category and why does Amazon have them?
Amazon takes their reputation seriously when it comes to providing their customers with top-notch products. We all know that they've worked long and hard to gain the trust of their customers, and they want to keep it that way. What company wouldn't be choosy about the sellers they allow on their website, in those circumstances? Amazon wants to make sure that anyone listing products for sale, under their company's marketplace, is not going to offer knock-off items or provide shabby products.
That's why they have restricted categories to sell in. You must be able to show that you can be one of their trusted sellers, who care about their customers just as much as they do. Yes, it can be tiresome to get through all the paperwork necessary to get approved, but it's worth it in the end. Don't worry if the thought of trudging through all the application steps overwhelms you. We're experts at this and can help you prepare everything you need to start the application process.
Is the application process hard?
It can be long and burdensome for some categories while being quick and easy for others. It all depends on the product or category you're asking permission to gain access to. It's important to note that Amazon's approval process will require more than just some basic information. The requirements for each category will be different but expect to provide images of your products to show the quality and its authenticity. You may also be asked to provide invoice documents that prove you have stock to sell on hand, and where you got them from.
Amazon doesn't mess around when it comes to their business reputation. They need you to prove that you're providing high-quality goods that aren't fake or pirated from elsewhere. We know just what you'll need to become one of their tops, trusted sellers. We can help you prepare all the necessary paperwork to lessen the frustrations the application process brings.
Is there anything else I'll need to get category approval for selling my product?
Well, this depends on what you're wanting to sell. There are instances where you'll need permission from a brand owner before gaining approval to sell in a category. In that case, you're not just representing Amazon; you're representing the company that owns the brand of that product. Your reputation as a seller needs to be top-notch and they want to protect their brand by making sure you're not trying to sell counterfeit items of their product.
What is meant by Ungating Services and is this something I need?
Amazon has many different "gated" categories, where they place strict restrictions on the sellers that are allowed to sell within those departments. Ungating means that you have gone through the approval process and were accepted by Amazon to gain access to that category to list your products in. A reputable business, in this field, will offer engaging services to help increase your chances of getting accepted by Amazon as a seller in that category.
We know what requirements are necessary and we know what needs to be done to get you permission to sell in the department you want. If you're a proven seller, we can get you an approval on the category you need to bring your selling business to a more lucrative level.


text:
Other Pennsylvania Offerings
"THE GREATEST OF EARLY AMERICAN MAPS"
One of the Earliest Announcements of Independence
The Acting Governor of New York
Thanks William Penn for a Gift
Calling Deputy Governor Markham to Run the Dividing Line Between Pennsylvania and Maryland
Benjamin Franklin Responds to the Grievances of the Paxton Boys in the Wake of Their Violent Attacks During the 1763 Conestoga Massacre
Earliest Known Letter from John to Thomas Penn
Also Signed Many Times by Thomas Penn
Thomas Paine Transmits Act for Resolution
of the PA-VA Border
"Oaths & Declarations": William Penn, Jr. and Quakers
Sign Separate Declaration to Sit on Pennsylvania Council with Non-Quakers
Pennsylvania Founder William Penn Signs Birth Certificate for Isaac Penington, a Member of His Extended Family
William Penn Sells Land in Pennsylvania to English Yeoman in 1681
John Penn on the Final Year of the Mason-Dixon Line Survey
Documenting Declaration of Independence Signer
Robert Morris's Financial Troubles
Pennsylvania Prepares to Meet French Encroachments at Start of French and Indian War
Robert Morris Promissory Note,
Used As Evidence In His Bankruptcy Trial
Pennsylvania Lieutenant Governor and General Assembly Disagree over Military Funding at Beginning of French and Indian War
Declaration Signer Francis Hopkinson Gives Address at Academy of Philadelphia
Pennsylvania Deputy Governor Urges General Assembly to Resist French Expansion in North America in Early Stages of the French and Indian War
Declaration Signer George Ross Gets Promissory Note for First Treason Trial in Pennsylvania
William Penn Wanted For Treason
A Revolutionary War Doctor Defends His Reputation, Pennsylvania War News, and Congress Takes a Huge Loan
Edward Hand apprises a Pennsylvania political ally of recent developments at the state convention for framing a new constitution. "Some time ago I forwarded you the plan of the Legislative Branch, & now send those for the Executive & Judicial, as agreed on by the Committee of the whole."
EDWARD HAND. Autograph Letter Signed, to Jasper Yeates, February 4, 1790, Philadelphia, Pa. 2 pp., 6¾ x 8 in.
Inventory #20731.99 Price: $3,500
Complete Transcript
Philadelphia 4th. Feby. 1790
Dear Yeates
I last evening recd. your favr. of 10th. Ultimo. I have no doubt of receiving your depretiation interest in money or a rect. from Turbet before I return the treasurer told me as much the evening before last.
Some time ago I forwarded you the plan of the Executive Legislative Branch, & now send those for the Legislative Executive & Judicial, as agreed on by the Committee of the whole[.] the Bill of rights is gone through, one Section, (on the liberty of the press) excepted, expect the Committee of the whole will report tomorrow, and as the business has already been so amply discussed [2] hope it will pass easiely thro the Convention unless our absentees give an opening to the Overhill gentlemen, and some of them are well dispose to profit by such an advantage[.]
with Complements to Mrs. Yeates and the family, I am Dr. Yeates
your very affectionate
Hble Servt.
Edwd: Hand
The new Pennsylvania Constitution was passed just two days following this letter, on February 6, 1790. Whereas the 1776 state constitution was characterized by a dominant, unicameral legislature, Pennsylvania Republicans (most of whom were Federalists in national politics) sought a bicameral legislature and a stronger executive on the model of both the Massachusetts constitution of 1780 and the U.S. Constitution.
Dr. Edward Hand (1744-1802) commanded troops in the battles of Long Island and Trenton. As Adjutant General of the Continental Army, he assisted George Washington in the siege of Yorktown, and was a member of the board convened by Washington to investigate Benedict Arnold's treason. After the war, Hand resumed the practice of medicine. He served as a member of the Confederation Congress (1784-1785) and the Pennsylvania Assembly (1785-1786), as well as a Delegate to the convention for the 1790 Pennsylvania Constitution.
Jasper Yeates (1745-1817) was a successful Lancaster attorney who was selected as a delegate to the Pennsylvania convention for considering the U.S. Constitution. He was a Federalist, and he supported like-minded Republicans in Pennsylvania politics such as Hand, who sought to reform the state constitution. Yeates was later a justice on the state Supreme Court, and he published the Reports of Cases Adjudged in the Supreme Court of Pennsylvania, 1791-1808.

redpajama_set_name: RedPajamaCommonCrawl


Don't miss your chance to taste the delectable Louisiana Shrimp Pizza. Grab it while you still can! Order now via Facebook Messenger, visit http://bit.ly/ORDERLouisianaShrimpPizza, use the Shakey's Mobile App, call 77-777 or #77-777 toll-free for Globe & TM. *Delivery price for Large Thin Crust.


text:
ir@SITOMobile.com
Thomas M. CandelariaDirector
In 2009, Thomas M. Candelaria, 60, began with SITO Mobile, Inc. (then known as Single Touch Systems, Inc.) as EVP of Corporate Development. Prior to joining Single Touch Systems, he was a private investor in several commercial real estate, angel-round, and start-up ventures. In 2005 he served as President of StreamWorks Technologies, up until the sale of the company's patent portfolio to Single Touch Systems, Inc. In 1997, Mr. Candelaria co-founded Digital On-Demand, Inc. a private digital music distribution company that was later sold in 2000 to Alliance Entertainment, Inc. and subsequently merged in 2005 with Source Interlink (SORC). Prior to that, Mr. Candelaria was an Executive VP with Paine Webber, and Prudential Bache securities. He attended UC Santa Barbara majoring in Business Economics.
Stephen BaksaDirector
Mr. Baksa, who has previously served on the Board and is a significant stockholder of the Company, was a General Partner at The Vertical Group, a private equity and venture capital firm focused on the fields of medical technology and biotechnology. For more than 30 years, The Vertical Group has been an early stage investor and major shareholder of some of the medical technology industry's most successful companies. Before Mr. Baksa joined The Vertical Group, he was co-founder of Paddington Partners, a firm engaged in special situation investing focused on public health care equities. Mr. Baksa holds an M.B.A. from The Rutgers School of Business and a B.A. in Economics from Gettysburg College.
Gavin ScottiDirector
Mr. Scotti has been a long-term shareholder with the company and most recently participated in Debtor in Possession (DIP) financing for the company.
Consumer Behavior and Location Sciences™, transforming data into deep insights that power media and solutions for the world's biggest brands.
SALES@SITEMOBILE.COM
100 Town Square Pl. Suite 204, Jersey City, NJ 07310
SITO MobileTerms & ConditionsPrivacy PolicySpeak Up
You are about to review presentations, reports and/or filings of SITO Mobile Ltd, that contain time-sensitive information. The information contained therein is only accurate as of the date thereof. SITO Mobile Ltd will not be reviewing or updating the material that is contained in these items after the date thereof. The information contained therein may be updated, amended, supplemented or otherwise altered by subsequent presentations, reports and/or filings by SITO Mobile Ltd.


Located on Grand River near Warren this striking facility has sat empty for years.
I put this beautiful facility in this site even though I had not found out what it functioned as.
"On the columns on the front porch there are heads, which are ex-police chiefs... The inside is very plain since it was a police station. The carriage house is attached, with the jail being the top half. The bars are still there. The back side of the building is flat! No architectural details.
"One last comment, I was just driving by it a few weeks ago [late '99] and it looks like it is occupied. There might be apartments in the back now. There were cars and I saw new light fixtures inside. The front is still boarded up."


text:
Q: How to convert Task to JArray I am trying to call an async method from a console application. The method returns Task to the Main method. When I try to query the FirstOrDefault, I am getting, "Task doesn't contain a definition for FirstOrDefault". I tried to cast the result to (JArray), but it says, "Can not convert type System.Tasks.Task to Newtonsoft.Json.Linq.JArray
static async  void  Main(){
     var result = Task.Run(() => MakeClientRequest());
     string employeeId = result
      .FirstOrDefault(x => x.Value<string>("employeeSequence") == "284")?
      .Value<string>("id");
}

static async Task<JArray> MakeClientRequest()
{
....
....
JArray data = JArray.Parse(jsonString);
    return data;
}

A: Simply await the result:
static async void Main()
{
     var result = await MakeClientRequest();
     string employeeId = result
      .FirstOrDefault(x => x.Value<string>("employeeSequence") == "284")?
      .Value<string>("id");
}

There isn't any good reason to kick off a Task here to get the result, at least not that I can see in the code that the OP posted.
If you really don't want to use await here for some reason, you could wait for the task to complete:
var result = MakeClientRequest().GetAwaiter().GetResult();

But really this is the same thing the compiler generates when you write var result = await ....


film profile] will be representing the Nordic countries in the official programme at this year's Cannes International Film Festival, which runs from 14-25 May – Force Majeure in the Un Certain Regard sidebar and The Salvation enjoying a gala midnight screening out of competition.
film profile] (2011) was selected for the Directors' Fortnight, before it won the Nordic Council Film Prize. "Östlund's third invitation to the Côte d'Azur is an honour and an important affirmation of the work we have done. It is going to be incredibly fun to finally screen this film," said his producer and occasional co-writer Erik Hemmendorff, who has realised the project with Marie Kjellson, for Plattform Produktion.
An avid skier himself (he has directed three skiing films), Östlund has written the story about a Swedish family on a skiing holiday. Owing to a trivial 'state of emergency', the family comes into contact with human mechanisms that they have never had to confront before. They are then forced to ascribe impulses and instincts to themselves, which they have learnt to despise and ignore. Östlund promises the most spectacular avalanche scene in film history. Force Majeure was produced with Eurimages, Swedish regional film centre Film i Väst, Rhône-Alpes Cinéma, Société Parisienne de Production, Motlys and the Coproduction Office, which is handling international sales.
An "homage to the classic western, inspired by the Nordic sagas", The Salvation is Levring's second entry in Cannes, after The King Is Alive – one of the four original Dogme films – was premiered in Un Certain Regard in 2000. The "epic tale of revenge, lost love and greed" is set in 1870s America, where an otherwise peaceful Danish settler, John, kills the murderer of his family, thus unleashing the fury of his brother, a notorious gang leader. But he knows how to cleanse the town's black heart.
Scripted by Levring and Danish Oscar-winning writer Anders Thomas Jensen, it stars Mads Mikkelsen as the settler, with an international cast including Eva Green, Jeffrey Dean Morgan, Mikael Persbrandt and Jonathan Pryce. The Salvation was produced by Sisse Graum Jørgensen for Zentropa Entertainments, with Spier Films (South Africa) and Forward Films (UK). Nordisk Film Distribution has scheduled a local release for October, while TrustNordisk is handling international sales.
Norwegian director Hallvar Witzø's Yes We Love will be the only Nordic short in competition at Cannes, following his Tuba Atlantic (2010) being awarded Best Foreign Film at the Student Oscars. Scripted by Witzø, it follows four generations on Norwegian Independence Day – each is in some form of crisis, in four different parts of Norway. Elisabeth Kvithyll produced the film for Hummelfilm.


text:
\section{Estimation of Probability}

It is a ubiquitous problem to estimate the probability of an event.  Such probability can be interpreted as the expectation, $\mathbb{E} [X]$, of a
Bernoulli random variable $X$.  More generally, if $X$ is a random variable bounded in interval $[0, 1]$ with mean $\mathbb{E} [X] = \mu \in (0,
1)$, we can draw $n$ i.i.d. samples $X_1, \cdots, X_n$ of $X$ and estimate $\mu$ as $\widehat{\boldsymbol{\mu}} = \frac{\sum_{i = 1}^n X_i } { n
 }$.   Since $\widehat{\boldsymbol{\mu}}$ is of random nature, it is crucial to control the statistical error. For this purpose, we have

\begin{theorem} Let $\varepsilon_a \in (0, 1)$ and $\varepsilon_r \in (0, 1)$ be real numbers such that $\frac{ \varepsilon_a}{ \varepsilon_r} + \varepsilon_a \leq \frac{1}{2}$.  Let $\delta \in
(0,1)$. Let $X_1, \cdots X_n$ be i.i.d. random variables defined in probability space $(\Omega, \mathscr{F}, \Pr)$ such that $0 \leq X_i \leq 1$ and
$\mathbb{E} [X_i] = \mu \in (0,1)$ for $i = 1 \cdots, n$. Let $\widehat{\boldsymbol{\mu}} = \frac{\sum_{i = 1}^n X_i } { n
 }$. Then,
 \begin{equation}
 \label{cov}
 \Pr \left \{ |\widehat{\boldsymbol{\mu}} - \mu| < \varepsilon_a  \; \; \mathrm{or} \;\; \left | \frac{
\widehat{\boldsymbol{\mu}} - \mu } {\mu} \right | < \varepsilon_r  \right \} > 1 - \delta \end{equation}
 provided that \begin{equation} \label{con}
 n > \frac{ \varepsilon_r \ln \frac{2}{\delta} } { \left ( \varepsilon_a + \varepsilon_a \varepsilon_r \right ) \ln (1 + \varepsilon_r) + \left ( \varepsilon_r - \varepsilon_a -
\varepsilon_a \varepsilon_r \right ) \ln \left ( 1 -  \frac{ \varepsilon_a \varepsilon_r } { \varepsilon_r - \varepsilon_a  }
 \right )  }.
\end{equation} \end{theorem}

\bigskip

It should be noted that conventional methods for determining sample sizes are based on normal approximation, see \cite{Desu} and the references
therein.  In contrast, Theorem 1 offers a rigorous method for determining sample sizes.  In the special case that $X$ is a Bernoulli random
variable, a numerical approach has been developed by Chen \cite{Chen} which permits exact computation of the minimum sample size.

\section{Optimization of Probability}

In many applications, it is desirable to find a vector of real numbers $\theta$ to minimize a probability, $p(\theta)$, which can be expressed as
\[
p(\theta) = \Pr \{ Y (\theta, \boldsymbol{\varDelta}) \leq 0 \},
\]
where $Y(\theta, \boldsymbol{\varDelta})$ is piece-wise continuous with respect to $\theta$ and $\boldsymbol{\varDelta}$ is a random vector.  If we define
\[
\mu (\lambda, \theta) = \mathbb{E} [ e^{ - \lambda Y (\theta, \boldsymbol{\varDelta})  } ],
\]
then, applying Chernoff bound \cite{Chernoff}, we have
 \[
p(\theta) \leq \inf_{\lambda > 0} \mu (\lambda, \theta).
 \]
This indicates that we can make $p(\theta)$ small by making $\mu (\lambda, \theta)$ small.  Hence, we shall attempt to minimize $\mu (\lambda, \theta)$ with
respect to $\lambda
> 0$ and $\theta$.

To make the new objective function $\mu (\lambda, \theta)$ more tractable, we take a sampling approach. Specifically, we obtain $n$ i.i.d. samples
$\boldsymbol{\varDelta}_1, \cdots, \boldsymbol{\varDelta}_n$ of $\boldsymbol{\varDelta}$ and approximate $\mu (\lambda, \theta) $ as
\[
g(\lambda, \theta) = \frac{ \sum_{i=1}^n e^{ - \lambda Y (\theta, \boldsymbol{\varDelta_i})  }  } { n }.
\]
A critical step is the determination of sample size $n$ so that $g(\lambda, \theta)$ is sufficiently close to $\mu(\lambda, \theta)$. Since $0 < e^{ - \lambda Y
(\theta, \boldsymbol{\varDelta}) }
 < 1$, an appropriate value of $n$ can be computed based on (\ref{con}) of Theorem 1.

Finally, we have transformed the problem of minimizing the probability function $p(\theta)$ as the problem of minimizing a piece-wise continuous
function $g(\lambda, \theta)$.  Since $g(\lambda, \theta)$ is a more smooth function, we can bring all the power of nonlinear programming to solve the
problem. An extremely useful tool is the {\it gradient descendent algorithm}, see, e.g. \cite{ba} and the references therein.

\section{Proof of Theorem 1}

To prove the theorem, we shall introduce function
\[
g(\varepsilon, \mu) =  (\mu + \varepsilon) \ln \frac{ \mu}{\mu + \varepsilon} + (1 - \mu - \varepsilon) \ln \frac{1 - \mu}{1 - \mu - \varepsilon}
\]
where $0 < \varepsilon < 1 - \mu$.   We need some preliminary results.

The following lemma is due to Hoeffding \cite{Hoeffding}.

\begin{lemma} \label{lem1}
\[
\Pr \{ \widehat{\boldsymbol{\mu}} \geq \mu + \varepsilon \} \leq \exp ( n \; g(\varepsilon, \mu) ) \quad \text{for} \quad 0 < \varepsilon < 1 - \mu < 1,
\]
\[
\Pr \{ \widehat{\boldsymbol{\mu}} \leq \mu - \varepsilon \} \leq \exp ( n \; g(-\varepsilon, \mu) ) \quad \text{for} \quad 0 < \varepsilon < \mu < 1.
\]
\end{lemma}

\begin{lemma}  \label{lem2}

Let $0 < \varepsilon < \frac{1}{2}$. Then, $g(\varepsilon, \mu)$ is monotonically increasing with respective to $\mu \in (0,  \frac{1}{2} - \varepsilon)$ and monotonically
decreasing with respective to $\mu \in (\frac{1}{2},  1 - \varepsilon)$.  Similarly, $g(- \varepsilon, \mu)$ is monotonically increasing with respective to $\mu
\in (\varepsilon, \frac{1}{2})$ and monotonically decreasing with respective to $\mu \in (\frac{1}{2} + \varepsilon,  1)$.\end{lemma}

\begin{pf}

Tedious computation shows that
\[
\frac{ \partial  g(\varepsilon, \mu) } { \partial \mu } = \ln \frac{ \mu ( 1 - \mu - \varepsilon) } { (\mu + \varepsilon) (1 - \mu) }  + \frac{ \varepsilon } { \mu} + \frac{ \varepsilon } { 1 - \mu}
\]
and
\[
\frac{ \partial^2  g(\varepsilon, \mu) } { \partial \mu^2 } = - \frac{ \varepsilon^2 } { \mu^2 (\mu+\varepsilon) } - \frac{ \varepsilon^2 } { (1 - \mu)^2 (1 - \mu - \varepsilon) } < 0
\]
for $0 < \varepsilon < 1 - \mu < 1$.  Note that
\[
\frac{ \partial  g(\varepsilon, \mu) } { \partial \mu } |_{\mu = \frac{1}{2}} =  \ln \frac{ 1 - 2 \varepsilon  } { 1 + 2 \varepsilon } + \varepsilon < 0
\]
because
\[
\frac{d \left [  \ln \frac{ 1 - 2 \varepsilon  } { 1 + 2 \varepsilon } + \varepsilon \right ]} { d \varepsilon } = - \frac{4}{1 - 4 \varepsilon^2} < 0.
\]
Moreover,
\[
\frac{ \partial  g(\varepsilon, \mu) } { \partial \mu } |_{\mu = \frac{1}{2} - \varepsilon }  = \ln \frac{ 1 - 2 \varepsilon  } { 1 + 2 \varepsilon } + \frac{4 \varepsilon}{1 - 4 \varepsilon^2} > 0
\]
because
\[
\frac{ d \left [ \ln \frac{ 1 - 2 \varepsilon  } { 1 + 2 \varepsilon } + \frac{4 \varepsilon}{1 - 4 \varepsilon^2} \right ] }{d \varepsilon  } = \frac{ 32 \varepsilon^2 } { (1 - \varepsilon^2)^2} > 0.
\]

Similarly,
\[
\frac{ \partial  g(- \varepsilon, \mu) } { \partial \mu } = \ln \frac{ \mu ( 1 - \mu + \varepsilon) } { (\mu - \varepsilon) (1 - \mu) }  - \frac{ \varepsilon } { \mu} - \frac{ \varepsilon } { 1 - \mu}
\]
and
\[
\frac{ \partial^2  g(- \varepsilon, \mu) } { \partial \mu^2 } = - \frac{ \varepsilon^2 } { \mu^2 (\mu - \varepsilon) } - \frac{ \varepsilon^2 } { (1 - \mu)^2 (1 - \mu + \varepsilon) } < 0
\]
for $0 < \varepsilon < \mu < 1$.  Hence,
\[
\frac{ \partial  g(- \varepsilon, \mu) } { \partial \mu } |_{\mu = \frac{1}{2}} =  \ln \frac{ 1 + 2 \varepsilon  } { 1 - 2 \varepsilon } - \varepsilon > 0
\]
because
\[
\frac{d \left [  \ln \frac{ 1 + 2 \varepsilon  } { 1 - 2 \varepsilon } - \varepsilon \right ]} { d \varepsilon } =  \frac{4}{1 - 4 \varepsilon^2} > 0;
\]
and
\[
\frac{ \partial  g(- \varepsilon, \mu) } { \partial \mu } |_{\mu = \frac{1}{2} + \varepsilon }  = \ln \frac{ 1 + 2 \varepsilon  } { 1 - 2 \varepsilon } - \frac{4 \varepsilon}{1 - 4 \varepsilon^2} < 0
\]
as a result of
\[
\frac{ d \left [ \ln \frac{ 1 + 2 \varepsilon  } { 1 - 2 \varepsilon } - \frac{4 \varepsilon}{1 - 4 \varepsilon^2} \right ] }{d \varepsilon  } = - \frac{ 32 \varepsilon^2 } { (1 - \varepsilon^2)^2} < 0.
\]

Since $\frac{ \partial  g(\varepsilon, \mu) } { \partial \mu } |_{\mu = \frac{1}{2}} < 0, \; \frac{ \partial  g(\varepsilon, \mu) } { \partial \mu } |_{\mu = \frac{1}{2} - \varepsilon }
> 0$ and $g(\varepsilon, \mu)$ is concave with respect to $\mu$, it must be true that $g(\varepsilon, \mu)$ is monotonically increasing with respective to $\mu \in (0,  \frac{1}{2} - \varepsilon)$ and
monotonically decreasing with respective to $\mu \in (\frac{1}{2},  1 - \varepsilon)$. Since $\frac{ \partial  g(- \varepsilon, \mu) } { \partial \mu } |_{\mu = \frac{1}{2}} >
0, \; \frac{ \partial  g(- \varepsilon, \mu) } { \partial \mu } |_{\mu = \frac{1}{2} + \varepsilon } < 0$ and $g(\varepsilon, \mu)$ is concave with respect to $\mu$, it must be true
that $g(- \varepsilon, \mu)$ is monotonically increasing with respective to $\mu \in (\varepsilon, \frac{1}{2})$ and monotonically decreasing with respective to
$\mu \in (\frac{1}{2} + \varepsilon,  1)$.

\end{pf}

\begin{lemma} \label{lem3}

Let $0 < \varepsilon < \frac{1}{2}$.  Then,
\[
g(\varepsilon, \mu) > g(-\varepsilon, \mu) \qquad \forall \mu \in \left (\varepsilon, \frac{1}{2} \right ],
\]
\[
g(\varepsilon, \mu) < g(-\varepsilon, \mu) \qquad \forall \mu \in \left (\frac{1}{2}, 1 - \varepsilon \right ).
\]
\end{lemma}

\begin{pf}

It can be shown that
\[
\frac{ \partial  [g(\varepsilon, \mu) - g(-\varepsilon, \mu)] } { \partial \varepsilon } = \ln \left [ 1 + \frac{ \varepsilon^2 ( 1 - 2 \mu) } { (\mu^2 - \varepsilon^2) ( 1 - \mu)^2 } \right ]
\]
for $0 < \varepsilon < \min (\mu, 1 - \mu)$.  Note that \[ \frac{ \varepsilon^2 ( 1 - 2 \mu) } { (\mu^2 - \varepsilon^2) ( 1 - \mu)^2 }  > 0 \quad \mathrm{for} \quad  \varepsilon <
\mu < \frac{1}{2}
\]
and \[ \frac{ \varepsilon^2 ( 1 - 2 \mu) } { (\mu^2 - \varepsilon^2) ( 1 - \mu)^2 }  < 0 \quad \mathrm{for} \quad  \varepsilon < \frac{1}{2} < \mu < 1 - \varepsilon.
\]
Therefore,
\[ \frac{ \partial  [g(\varepsilon, \mu) - g(-\varepsilon, \mu)] } { \partial \varepsilon }  > 0 \quad \mathrm{for} \quad  \varepsilon < \mu < \frac{1}{2}
\]
and \[ \frac{ \partial  [g(\varepsilon, \mu) - g(-\varepsilon, \mu)] } { \partial \varepsilon } < 0 \quad \mathrm{for} \quad  \varepsilon < \frac{1}{2} < \mu < 1 - \varepsilon.
\]
So, we can complete the proof of the lemma by observing the sign of the partial derivative {\small $\frac{ \partial  [g(\varepsilon, \mu) - g(-\varepsilon, \mu)] } {
\partial \varepsilon }$} and the fact that $g(\varepsilon, \mu) - g(-\varepsilon, \mu) = 0$ for $\varepsilon = 0$.

\end{pf}

\begin{lemma} \label{lem4}

Let $0 < \varepsilon < 1$.  Then, $g \left ( \varepsilon \mu, \mu \right )$ is monotonically decreasing with respect to {\small $\mu \in \left (0, \frac{1}{1 + \varepsilon}
\right )$}. Similarly, $g \left (- \varepsilon \mu, \mu \right )$ is monotonically decreasing with respect to $\mu \in (0, 1)$. \end{lemma}

\begin{pf} Note that
\[
\frac{ \partial   g \left ( \varepsilon \mu, \mu \right )} { \partial \mu } = (1 + \varepsilon) \ln \frac{ 1 - (1 + \varepsilon) \mu } { 1 - \mu } - (1 + \varepsilon) \ln (1 + \varepsilon) +
\frac{\varepsilon}{1 - \mu}
\]
and
\[
\frac{ \partial^2   g \left ( \varepsilon \mu, \mu \right )} { \partial \mu^2 } = - \frac{ \varepsilon^2 } { (1 - \mu)^2 [1 - (1 + \varepsilon) \mu ] } < 0
\]
for any $\mu \in \left (0, \frac{1}{1 + \varepsilon} \right )$.

Since $\frac{ \partial   g \left ( \varepsilon \mu, \mu \right )} { \partial \mu }|_{\mu = 0} = \varepsilon  - (1 + \varepsilon) \ln (1 + \varepsilon) < 0$, we have
\[
\frac{ \partial   g \left ( \varepsilon \mu, \mu \right )} { \partial \mu } < 0, \quad \forall \mu \in \left (0, \frac{1}{1 + \varepsilon} \right )
\]
and it follows that $g \left ( \varepsilon \mu, \mu \right )$ is monotonically decreasing with respect to {\small $\mu \in \left (0, \frac{1}{1 + \varepsilon} \right )$}.

Similarly, since
\[
\frac{ \partial   g \left ( - \varepsilon \mu, \mu \right )} { \partial \mu }|_{\mu = 0} = - \varepsilon  - (1 - \varepsilon) \ln (1 - \varepsilon) < 0 \] and \[ \frac{ \partial^2   g \left ( \varepsilon
\mu, \mu \right )} { \partial \mu^2 } = - \frac{ \varepsilon^2 } { (1 - \mu)^2 [1 - (1 - \varepsilon) \mu ] } < 0, \quad \forall \mu \in (0, 1)
\]
 we have
\[
\frac{ \partial   g \left ( - \varepsilon \mu, \mu \right )} { \partial \mu } < 0, \quad \forall \mu \in (0, 1)
\]
and, consequently, $g \left (- \varepsilon \mu, \mu \right )$ is monotonically decreasing with respect to $\mu \in (0, 1)$.

\end{pf}

\begin{lemma} \label{lem5}  Suppose $0 < \varepsilon_r < 1$ and $0 < \frac{\varepsilon_a}{\varepsilon_r} + \varepsilon_a \leq \frac{1}{2}$.  Then, \begin{equation} \label{ineqm}
 \Pr \{ \widehat{\boldsymbol{\mu}} \leq \mu - \varepsilon_a \} \leq \exp \left (n \; g \left ( -
\varepsilon_a, \frac{\varepsilon_a}{\varepsilon_r}\right ) \right ) \end{equation} for $0 < \mu \leq \frac{\varepsilon_a}{\varepsilon_r}$.  \end{lemma}

\begin{pf} We shall show (\ref{ineqm}) by investigating three cases as follows.  In the case of $\mu < \varepsilon_a$, it is clear that
\[
\Pr \{ \widehat{\boldsymbol{\mu}} \leq \mu - \varepsilon_a \} = 0  < \exp \left (n \; g \left ( - \varepsilon_a, \frac{\varepsilon_a}{\varepsilon_r}\right ) \right ).
\]

In the case of $\mu = \varepsilon_a$, we have \begin{eqnarray*} \Pr \{ \widehat{\boldsymbol{\mu}} \leq \mu - \varepsilon_a \} & = & \Pr \{ \widehat{\boldsymbol{\mu}} = 0  \} = \Pr \{ X_i = 0, \; i = 1, \cdots, n \}\\
&  = & \sum_{i = 1}^n \Pr \{ X_i = 0 \} =  (\Pr \{ X = 0 \})^n\\
& = & (1 -  \Pr \{ X \neq 0 \})^n \leq  (1 -  \mathbb{E} [ X ] )^n\\
& = & (1 - \mu)^n =  (1 - \varepsilon_a)^n\\
& = & \lim_{\mu \to \varepsilon_a} \exp (n \; g(- \varepsilon_a, \mu))\\
& < &  \exp \left (n \; g \left ( - \varepsilon_a, \frac{\varepsilon_a}{\varepsilon_r}\right ) \right ), \end{eqnarray*} where the last inequality follows from Lemma \ref{lem2} and the fact
that $\varepsilon_a < \frac{\varepsilon_a}{\varepsilon_r} \leq \frac{1}{2} - \varepsilon_a$.

In the case of $\varepsilon_a < \mu \leq \frac{\varepsilon_a}{\varepsilon_r}$,  we have
\[
\Pr \{ \widehat{\boldsymbol{\mu}} \leq \mu - \varepsilon_a \} \leq \exp (n \; g(- \varepsilon_a, \mu)) < \exp \left (n \; g \left ( - \varepsilon_a, \frac{\varepsilon_a}{\varepsilon_r}\right ) \right ),
\]
where the first inequality follows from Lemma \ref{lem1} and the second inequality follows from Lemma \ref{lem2} and the fact that $\varepsilon_a <
\frac{\varepsilon_a}{\varepsilon_r} \leq \frac{1}{2} - \varepsilon_a$.  So, (\ref{ineqm}) is established. \end{pf}

\begin{lemma} \label{lem6}  Suppose $0 < \varepsilon_r < 1$ and $0 < \frac{\varepsilon_a}{\varepsilon_r} + \varepsilon_a \leq \frac{1}{2}$.   Then, \begin{equation} \label{ineqmm}
 \Pr \{ \widehat{\boldsymbol{\mu}} \geq (1 + \varepsilon_r) \mu \} \leq \exp \left (n \; g \left (
\varepsilon_a, \frac{\varepsilon_a}{\varepsilon_r}\right ) \right ) \end{equation} for $\frac{\varepsilon_a}{\varepsilon_r} < \mu < 1$.  \end{lemma}

\begin{pf} We shall show (\ref{ineqmm}) by investigating three cases as follows.  In the case of $\mu > \frac{1}{1 + \varepsilon_r}$, it is clear that
\[
\Pr \{ \widehat{\boldsymbol{\mu}} \geq (1 + \varepsilon_r) \mu \} = 0  < \exp \left (n \; g \left ( \varepsilon_a, \frac{\varepsilon_a}{\varepsilon_r}\right ) \right ).
\]

In the case of $\mu = \frac{1}{1 + \varepsilon_r}$, we have \begin{eqnarray*} \Pr \{ \widehat{\boldsymbol{\mu}} \geq (1 + \varepsilon_r) \mu \} & = & \Pr \{ \widehat{\boldsymbol{\mu}} = 1  \} = \Pr \{ X_i = 1, \; i = 1, \cdots, n \}\\
&  = & \sum_{i = 1}^n \Pr \{ X_i = 1 \} =  (\Pr \{ X = 1 \})^n\\
& \leq & \mu^n =  \left (\frac{1}{1 + \varepsilon_r} \right )^n\\
& = & \lim_{\mu \to \frac{1}{1 + \varepsilon_r}} \exp (n \; g( \varepsilon_r \mu, \mu))\\
& < &  \exp \left (n \; g \left ( \varepsilon_a, \frac{\varepsilon_a}{\varepsilon_r}\right ) \right ), \end{eqnarray*} where the last inequality follows from Lemma \ref{lem4} and the fact
that $ \frac{\varepsilon_a}{\varepsilon_r} \leq \frac{1}{2} \frac{1}{1 + \varepsilon_r} < \frac{1}{1 + \varepsilon_r}$ as a result of $0 < \frac{\varepsilon_a}{\varepsilon_r} + \varepsilon_a \leq \frac{1}{2}$.

In the case of $\frac{\varepsilon_a}{\varepsilon_r} < \mu < \frac{1}{1 + \varepsilon_r}$,  we have
\[
\Pr \{ \widehat{\boldsymbol{\mu}} \leq (1 + \varepsilon_r) \mu \} \leq \exp (n \; g(\varepsilon_r \mu, \mu)) < \exp \left (n \; g \left ( \varepsilon_a, \frac{\varepsilon_a}{\varepsilon_r}\right ) \right
),
\]
where the first inequality follows from Lemma \ref{lem1} and the second inequality follows from Lemma \ref{lem4}.  So, (\ref{ineqmm}) is
established. \end{pf}

\bigskip

We are now in a position to prove the theorem. We shall assume (\ref{con}) is satisfied and show that (\ref{cov}) is true.  It suffices to show
that
\[
\Pr \{ |\widehat{\boldsymbol{\mu}} - \mu | \geq \varepsilon_a, \; |\widehat{\boldsymbol{\mu}} - \mu | \geq \varepsilon_r \mu \} < \delta.
\]

For $0 < \mu \leq \frac{\varepsilon_a}{\varepsilon_r}$, we have \begin{eqnarray} \Pr \{ |\widehat{\boldsymbol{\mu}} - \mu | \geq \varepsilon_a, \; |\widehat{\boldsymbol{\mu}} - \mu | \geq \varepsilon_r \mu \} & =
& \Pr \{ |\widehat{\boldsymbol{\mu}} - \mu | \geq \varepsilon_a  \} \nonumber\\
& = & \Pr \{ \widehat{\boldsymbol{\mu}}  \geq \mu + \varepsilon_a \} + \Pr \{ \widehat{\boldsymbol{\mu}} \leq \mu - \varepsilon_a \} \label{ineq6}. \end{eqnarray}

Noting that $0 < \mu + \varepsilon_a \leq \frac{\varepsilon_a}{\varepsilon_r} + \varepsilon_a \leq \frac{1}{2}$, we have
\[
\Pr \{ \widehat{\boldsymbol{\mu}}  \geq \mu + \varepsilon_a \} \leq \exp (n \; g(\varepsilon_a, \mu)) \leq \exp \left (n \; g \left ( \varepsilon_a, \frac{\varepsilon_a}{\varepsilon_r} \right ) \right ),
\]
where the first inequality follows from Lemma \ref{lem1} and the second inequality follows from Lemma \ref{lem2}.  It can be checked that
(\ref{con}) is equivalent to
\[
\exp \left (n \; g \left ( \varepsilon_a, \frac{\varepsilon_a}{\varepsilon_r} \right ) \right ) < \frac{\delta}{2}.
\]
Therefore,
\[
\Pr \{ \widehat{\boldsymbol{\mu}}  \geq \mu + \varepsilon_a \}  < \frac{\delta}{2}
\]
for $0 < \mu \leq \frac{\varepsilon_a}{\varepsilon_r}$. \bigskip

On the other hand, since $\varepsilon_a < \frac{\varepsilon_a}{\varepsilon_r} < \frac{1}{2}$, by Lemma \ref{lem5} and Lemma \ref{lem3}, we have
\[
 \Pr \{ \widehat{\boldsymbol{\mu}} \leq \mu - \varepsilon_a \} \leq \exp \left (n \; g \left ( -
\varepsilon_a, \frac{\varepsilon_a}{\varepsilon_r}\right ) \right ) \leq \exp \left (n \; g \left ( \varepsilon_a, \frac{\varepsilon_a}{\varepsilon_r}\right ) \right ) < \frac{\delta}{2}
\]
for $0 < \mu \leq \frac{\varepsilon_a}{\varepsilon_r}$.  Hence, by (\ref{ineq6}),
\[
\Pr \{ |\widehat{\boldsymbol{\mu}} - \mu | \geq \varepsilon_a, \; |\widehat{\boldsymbol{\mu}} - \mu | \geq \varepsilon_r \mu \} < \frac{\delta}{2} + \frac{\delta}{2} = \delta.
\]
This proves (\ref{cov}) for $0 < \mu \leq \frac{\varepsilon_a}{\varepsilon_r}$.

\bigskip

For $\frac{\varepsilon_a}{\varepsilon_r} < \mu < 1$, we have \begin{eqnarray*} \Pr \{ |\widehat{\boldsymbol{\mu}} - \mu | \geq \varepsilon_a, \; |\widehat{\boldsymbol{\mu}} - \mu | \geq \varepsilon_r \mu \} & = &
\Pr \{ |\widehat{\boldsymbol{\mu}} - \mu | \geq \varepsilon_r \mu \}\\
& = & \Pr \{ \widehat{\boldsymbol{\mu}}  \geq \mu + \varepsilon_r \mu \} + \Pr \{ \widehat{\boldsymbol{\mu}} \leq \mu - \varepsilon_r \mu \}. \end{eqnarray*}  Invoking Lemma \ref{lem6}, we have
\[
\Pr \{ \widehat{\boldsymbol{\mu}}  \geq \mu + \varepsilon_r \mu \} \leq \exp \left (n \; g \left ( \varepsilon_a, \frac{\varepsilon_a}{\varepsilon_r} \right ) \right ).
\]
On the other hand,
\[
 \Pr \{ \widehat{\boldsymbol{\mu}}
\leq \mu - \varepsilon_r \mu \} \leq \exp (n \; g( - \varepsilon_r \mu, \mu)) \leq \exp \left (n \; g \left ( - \varepsilon_a, \frac{\varepsilon_a}{\varepsilon_r}\right ) \right ) \leq \exp
\left (n \; g \left ( \varepsilon_a, \frac{\varepsilon_a}{\varepsilon_r}\right ) \right )
\]
where the first inequality follows from Lemma \ref{lem1}, the second inequality follows from Lemma \ref{lem4}, and the last inequality follows
from Lemma \ref{lem3}.  Hence,
\[
\Pr \{ |\widehat{\boldsymbol{\mu}} - \mu | \geq \varepsilon_a, \; |\widehat{\boldsymbol{\mu}} - \mu | \geq \varepsilon_r \mu \}  \leq  2 \exp \left (n \; g \left ( \varepsilon_a,
\frac{\varepsilon_a}{\varepsilon_r} \right ) \right ) < \delta. \] This proves (\ref{cov}) for $\frac{\varepsilon_a}{\varepsilon_r} < \mu < 1$. The proof of Theorem 1 is thus completed.

redpajama_set_name: RedPajamaArXiv


She sent the internet into hysterics after she was seen bizarrely applauding in a seal-like fashion at the Oscars last month.
And Nicole Kidman, 49, has finally broken her silence on the incident, confessing to KIIS FM's Kyle And Jackie O that she was afraid of damaging her giant Harry Winston diamond ring.
'It was really awkward, and I was like: 'Gosh, I really want to clap', she explained.
'I don't want to not be clapping, which would be worse right? Why isn't Nicole clapping?' she said, mimicking what she believed would be the subsequent media headlines.
'So therefore I'm clapping but it was really difficult because I had this huge ring on which was not my own but was absolutely gorgeous and I was terrified of damaging it,' she said.
Indeed, Nicole was bejewelled with over 119 carats worth of Harry Winston diamonds, including a 13.58-carat cluster pearl-shaped diamond ring set in platinum.


30 January, 2009 | Page 3 Fiordland Advocate LOCAL NEWS The circus is coming to Te Anau next month and, with it, possibly the last chance for residents to see an elephant in their own back yard. Loritz Circus is touring New Zealand for the first time and will spend two days in Te Anau on February 17 and 18. Marketing manager Paul Johnson said the show, themed "Out of Africa", would include an appearance by New Zealand's only circus elephant, Jumbo. Jumbo, a circus performer for some 30 years, has been the topic of much controversy in the past with animal rights campaigners protesting at her living conditions and role as a performer. She was previously a drawcard for Whirling Brothers Circus but when its owner Tony Ratcliffe retired he was unable to find a zoo to take Jumbo so she found a home with a new circus. Mr Johnson said Loritz Circus had worked extremely hard to satisfy the concerns of animal rights activists. She now had a new, $350,000 purpose-built trailer enclosure and her role in the show was a small walk-on appearance rather than tricks. Those measures have failed to satisfy some people around the country. Almost a year ago the New Zealand Herald reported that several complaints had been made to the SPCA about Jumbo's care and wellbeing when the circus was performing in Papakura. However, two SPCA inspectors ruled the 4-tonne animal was in good condition and being well cared for. Despite that, protests have continued to follow the circus in Christchurch, Nelson, Porirua and South Auckland. However, Jumbo is not the only headline act of the Loritz Circus. The troupe boasts 30 performers from all over the world. Among them The Royal Kenyan Acrobats is the six-year-old star of television talent quest New Zealand's Got Talent, hula-hooper Americus Wilson who has been a circus performer since the age of four-and-a-half. The Royal Kenyan Acrobats, who have made their New Zealand debut with the circus, are an outstanding team of young men who add breath- taking stunts to human pyramids, rope skipping, limbo and fire eating. There are also Chinese acrobats and jugglers who can juggle two Diablo at once. Mr Johnson said the circus had sold out at recent stops in Ashburton and Nelson and was as popular with children as it was with those in their nineties.The big top was one of the most modern in the circus industry with grandstand seating for 500 people. In keeping with the "Out of Africa" theme, visitors would pass through an inflatable African-style village to get to the marquee, he said. Outside people could see Jumbo and the minature ponies that perform in the show, along with circus pets – llama and a goat. The circus is coming to town February 17 and 18: •	Te Anau Lions Park February 20, 21 and 22: •	Winton School Grounds February 24 and 25: •	Riverton Racecourse February 27 to March 15: •	Invercargill Gala Street Reserve Tickets and information: •	www.loritzcircus.com Phone 021 709 788 LoriTz circuS iN ThE SouTh Photos supplied Jumbo, New Zealand's only circus elephant, has joined the Loritz Circus. Photo: Prime Television Americus Wilson, 6, a crowd favourite in New Zealand's Got Talent, will be appearing in the Loritz Circus which opens in Te Anau on February 17. Loritz Circus – Out of Africa will be making its first southern stop at Te Anau next month.


WKU Libraries is proud to announce the addition of the Washington Post Historical edition to our electronic collection. Provided by ProQuest, this database provides full-text access to the entire run of the Washington Post from 1877 to 1996. WKU already offers the full text of the Washington Post from 1997 to the present as part of the ProQuest Newstand database.
Known for its comprehensive political reporting, first-rate photo essays, Pulitzer Prize-winning editorial writing, and in-depth investigative reporting, the Washington Post is a vital resource for today's budding journalists, political historians, and students of government.
Links to these and all of other our other research databases may be found in the Databases list on the Library web page. These databases are available both on and off campus — off-campus access requires a valid WKU NetID and password. If you need assistance please stop at the Reference Desk in the Commons at Cravens, call for assistance at (270) 745-6125, or email us at web.reference@wku.edu.
Our New Core Resource for Newspaper Access!
WKU Libraries has added ProQuest Newsstand, a searchable database offering one the of the best full text collections of international, national and regional newspapers, such as The New York Times, The Wall Street Journal, USA Today, the Louisville Courier-Journal and the Tennessean.
ProQuest Newstand also provides full-text access to historic issues of the New York Times, Los Angeles Times, and Chicago Tribune. Abstracting and indexing are available for the more than 1,370 newspapers; of these, over 1,270 are full text.
This resource is available through campus computers and off-campus using your WKU NetID and password.


The No. 9-ranked Cardinal men's tennis team (4-1) took its first loss of the season this past Saturday to the No. 2 Ohio State Buckeyes (6-0) in a crushing 1-6 rout. The loss represented Stanford's largest margin of loss since April 2016's hammering by USC.
The match was the first of three season matches on the road against ranked opponents for the Cardinal. Next weekend, the team takes on No. 5 USC and No. 7 UCLA before heading to the ITA National Team Indoor Championships in Chicago on February 15th.
Stanford's duo of sophomore Axel Geller and freshman Alexandre Rotsaert took their first loss of the season to junior JJ Wolf and senior Martin Joyce (6-4). Ranked No. 3 nationally in ITA Division I Men Singles, Wolf is the youngest American player in the world's Top 500-ranked men's tennis players at age 19.
Junior William Genesen earned Stanford's only victory on the day, taking down redshirt junior Kyle Seelig in a second set tiebreak (6-3, 7-6).
The dual match saw first losses on the season for Geller and Rotsaert in singles as well. Geller defeated Oregon's No. 5 Thomas Laurent in straight sets (6-4, 6-2) last week, and was building momentum with singles wins against players Santa Clara and UCF earlier in January. A second-year player for the Cardinal, Geller currently sits at No. 20 on the ITA Division 1 Men's Singles rankings, with plenty of time to make his mark over the coming years.
The team will return to campus this week shortly before heading down to Los Angeles for road matches against USC and UCLA on Friday and Saturday. With rain in the forecast for the weekend, however, rescheduling may be in the works for the matches.
After a tough loss to the Buckeyes, the Cardinal look to retain their Top 10 ranking this coming week with strong showings against Top 10 in-state rivals in the No. 5 Trojans and No. 7 Bruins.


text:
Q: Substring ERROR: argument of WHERE must be type boolean, not type text SELECT substring(category FROM '[0-9]+') from microwaves;

This works fine and returns the microwave categories that are numeric.
UPDATE microwaves SET category = '' WHERE substring(category FROM '[0-9]+');

This throws an error in Postgres 9.5

ERROR:  argument of WHERE must be type boolean, not type text

How can I update the numeric fields?

A: The WHERE clause is used to filter the results to all items that make the clause true, but SUBSTRING() returns text.  You're probably looking for one of the following:
UPDATE microwaves SET category = '' WHERE substring(category FROM '[0-9]+') is null;

-or-
UPDATE microwaves SET category = '' WHERE substring(category FROM '[0-9]+') is not null;


text:
Als Selbstung versteht man die Inzucht von einhäusigen Pflanzen durch künstliche Selbstbestäubung zur Herstellung von Inzuchtlinien. Die wiederholte Selbstung auch bei nachfolgenden Generationen hat die Reinerbigkeit zum Ziel und ist die Voraussetzung für den Heterosis-Effekt bei der  Züchtung von Pflanzenhybriden wie zum Beispiel Blizzard-Mais.

Einzelnachweise

Literatur
 Heiko Becker: Pflanzenzüchtung 2. Auflage. UTB, 2008, ISBN 978-3-8252-1744-0.
 Wulf Diepenbrock, Jens Léon, Frank Ellmer: Ackerbau, Pflanzenbau und Pflanzenzüchtung, Grundwissen Bachelor. Ulmer, 2005, ISBN 978-3-8252-2629-9. (UTB Uni-Taschenbücher, Band 2629)
 Noel Kingsbury: Hybrid. The History and Science of Plant Breeding. The University of Chicago Press, 2009, ISBN 978-0-226-43704-0.
 Thomas Miedaner: Pflanzenzüchtung. Eine Einführung. DLG, 2010, ISBN 978-3-7690-0752-7.
 Manfred G. Raupp: The Debate Concerning the Effects on Bioinformatics on Food Production. In: Scientia Agriculturae Bohemica. Tschechische Universität Prague-Suchdol 4/2001, S. 261–269. .
 Rolf Schlegel: Concise Encyclopedia of Crop Improvement. Institutions, Persons, Theories, Methods, and Histories. Haworth Press, New York/London 2007, ISBN 978-1-56022-146-3, S. 331ff.
 Rolf Schlegel: Dictionary of Plant Breeding. 2. Auflage. Taylor & Francis, 2009, ISBN 978-1-4398-0242-7, S. 584.

Bestäubung
Genetik
Pflanzenzucht

redpajama_set_name: RedPajamaWikipedia


If you need to make bail in Conroe TX, Harris County, Humble TX, Katy TX, Liberty TX or Pearland TX. All About Bail Bonds can help. They are bail agents and they specialize in posting bail for people who want to get out of jail fast – and does not?
Bail is core part of the criminal justice system. It is built on the concept that a person is innocent until proven guilty. It is also a practical way to prevent overcrowding in jails. There is normally a long delay between the time someone is charged with an offence or crime, and the date the actual trial will take place. Unless the crime is exceptionally serious, it would be unfair and unjust to keep an accused in custody for a lengthy period without trial.
Bail is the system that enables an accused to remain free pending trial. Bail is generally set in relation to the crime or charge. The more serious the offence, the higher the bail. Generally bail is set at an amount that will make it unlikely that the accused will skip bail.
In most cases a judge will determine the amount of bail. In most instances courts have set amounts for specific offences. In most cases bail will be granted. However, if the judge thinks there is a reasonable flight risk or a danger to the community. People with string ties to the community are normally not considered flight risks.
After bail is set a defendant or surety can post bail with the clerk of the court or after hours at a county jail. A receipt will be issued, and the accused will be set free. If the accused does not return to court, the court will set a bail forfeiture hearing and issue a warrant of arrest.


text:
Q: Screen not registering contact In MainActivity I have the following method:
 @Override
public boolean onTouch(View view, MotionEvent event) {
    Log.i("log_tag","In onTouch");
    Log.i("log_tag", event.getRawX() + " " + event.getRawY());
    return  true;
}

Theoretically whenever I click/touch the screen this method should log the location of the contact. Yet whenever I click the screen nothing happens.
The screen is blank, the only thing on the screen is a relative layout that covers the entire screen and is set to "clickable".
How can I get this method to register contact/clicks?

A: You need to set a view that will received the touch, you can do like that in the MainActivity onCreate():
findViewById(R.id.main_layout).setOnTouchListener(this);

A: Make sure your Activity is extending OnTouchListener first, like the following:
public class MyActivity extends Activity implements OnTouchListener{}

The RelativeLayout should have an id set in the XML.
android:id="@+id/myRelativeLayout"

Then put this in the onCreate() of your Activity after setContentView:
RelativeLayout layout= (RelativeLayout) findViewById(R.id.myRelativeLayout);
layout.setOnTouchListener(this);


text:
Hurricanes Start Final Week of their Season with 3-2 Loss to the Panthers
The Canes couldn't play spoiler, finish on wrong side of 3-2 score in Sunrise, Florida.
By Brett Finger@brettfinger Apr 2, 2018, 10:11pm EDT
Share All sharing options for: Hurricanes Start Final Week of their Season with 3-2 Loss to the Panthers
Jasen Vinlove-USA TODAY Sports
Despite being mathematically eliminated from postseason contention with their 2-1 loss to the New York Rangers on Saturday night, the Carolina Hurricanes entered BB&T Center in Sunrise, Florida on Monday, still with a role to play in the Eastern Conference playoff race - the role of spoiler.
The Panthers, however, had different plans. Thanks to a late goal from Alex Petrovic, the Cats will live to fight another day as they look to make a late surge into the Eastern Conference's top-eight.
After a handful of chance early on, the Hurricanes broke through and scored the game's first goal.
At the 3:44 mark, Trevor van Riemsdyk pinched down and cashed in on a loose puck in front of a sprawled out Roberto Luongo. The former Blackhawk netted his third goal of the season and gave the road team an early lead.
That didn't last long, though.
19 seconds later, Panthers rookie defenseman MacKenzie Weegar out-waited Scott Darling on an odd-man rush and was able to beat him short-side for his second goal of the year. Just like that, the two teams were back on even terms.
The Hurricanes failed to score on a man advantage with just under six minutes to go in the first period. The Panthers were then presented with an opportunity of their own when Elias Lindholm went to the box for hooking with just 33 seconds left in the frame.
On the powerplay, Vincent Trocheck found an uncovered Evgenii Dadonov streaking to the front of the night and, with ten seconds left in the period, the Russian winger - and former property of the Hurricanes - netted his 27th of the season to give his club a 2-1 lead going into the first intermission.
Florida outshot Carolina 19-10 through 20 minutes.
The Hurricanes' offensive attack started to intensify in the early stages of the middle frame. As the midway point of the game neared, it looked like the Canes were on the verge of getting things tied up and, at the 13:48 mark of period two, they did just that.
Lee Stempniak found Derek Ryan for a short breakaway chance on Luongo, and the pending UFA center made a nifty move in tight and sent a backhand shot top-shelf to make it a 2-2 hockey game.
30 seconds later, Brock McGinn was on the receiving end of an illegal hit into the boards by Florida's first goal scorer, MacKenzie Weegar. Roland McKeown dropped gloves with the assailant but was given an instigator penalty and a ten-minute misconduct for his role in the incident.
That nullified the powerplay Carolina would have gotten for the boarding call, so the teams stayed at even strength and the period came to a close with the scoreboard reading "2-2".
A back and forth third period finally rendered a goal at the 12:02 mark. Alex Petrovic's long-distance wrist shot beat Darling through traffic and gave the Panthers a late 3-2 lead.
With the goalie pulled, the Canes made one final push down the stretch, but they came up just short.
On home ice, the Cats got the big win and will, in turn, remain in the thick of the playoff race. Their 3-2 win will up the already high stakes of their matchup against the Nashville Predators on Tuesday night.
The Hurricanes, on the other hand, will go back to the drawing board in hopes of finishing this failed season on a high note as they take on a pair of playoff-bound teams in their final week of regular season play.
Rank the Performances
Here's your chance to weigh in on how you think the team performed tonight. Upvote the players you think played well and downvote the ones who didn't.
About Last Night: Offensive Depth, Defensive Star and Goaltending Milestone The Carolina Hurricanes continue to be one of the most impressive teams in the league as they added yet another blowout win to their ever growing season resume.
Carolina Hurricanes at Boston Bruins: Lineups and Game Discussion The Hurricanes are headed to Boston for their first road game since New Year's Day.


Anyway, two things. One, for anyone in or near Scottsdale this Sat, 10/17, I'll be signing at the Saguaro Hotel with Kristen Ashley and J.B. Salsbury from 11-4, open free to everyone so come join us!!! I hope to see some of you there!!
And two, THANK YOU ALL for putting Parker and Zoe from ALL I WANT on the New York Times bestseller lists (print, digital AND the combined list) and the USA Today bestseller list!
They thank you! And so do I!
And I guess there's three things. :grin: Leave a comment. A few of you will win a book from my backlist!!!


text:
United Airlines Expands LAX-Sydney Service
Additional flight reinforces United's leadership position in the Pacific and at LAX
CHICAGO, July 13 /PRNewswire-FirstCall/ — United will offer three additional weekly flights between its airport hub at Los Angeles International Airport (LAX) and Sydney Kingsford-Smith Airport in Australia, between Dec. 15, 2005, and April 27, 2006.
"Our service expansion builds on the success of our existing daily flight between Sydney and Los Angeles," said Graham Atkinson, United's senior vice president-Worldwide Sales and Alliances. "This flight addition also reinforces United's leadership position in the Pacific, on the U.S. West Coast and specifically at LAX."
The new Los Angeles-Sydney flights are timed to maximize convenience and connections at both airports, and will be operated with B747-400 aircraft, configured with United First(R) 14 seats, 73 United Business(R) seats, 88 seats in Economy Plus(R) and 172 seats in United Economy(R).
Flights opened for sale on July 9.
Service between Sydney and Los Angeles
Flight Origin Destination Departure Arrival
UA827 Los Angeles Sydney 8:35 p.m. (M,Th,Sat.) 6:15 a.m.
(2 days
later)
UA826 Sydney Los Angeles 2:00 p.m. (M,W,Sat.) 8:35 a.m.
(same day)
About United
United Airlines (BULLETIN BOARD: UALAQ) is the world's second largest airline and operates more than 3,400 flights a day on United, United Express and Ted to more than 200 U.S. domestic and international destinations from its hubs in Los Angeles, San Francisco, Denver, Chicago and Washington, D.C. With key global air rights in the Asia-Pacific region, Europe and Latin America, United is one of the largest international carriers based in the United States. United is also a founding member of Star Alliance, which provides connections for our customers to nearly 800 destinations in 139 countries worldwide. United's 58,500 employees reside in every U.S. state and in many countries around the world. News releases and other information about United can be found at the company's Web site at united.com.
For Great Prices on Airline Tickets Shop Around First. Click Here: http://www.itravelmag.com/travel-links-bycat.php?category=Air%20Tickets
United Airlines Expands San Francisco-Sydney ServiceAdditional flight reinforces United's leadership position in the Pacific and at the San Francisco International Airport, and its commitment to international service. CHICAGO, Sept. 28 /PRNewswire-FirstCall/ — United will offer three additional weekly roundtrip flights between San Francisco International Airport (SFO), a major gateway to...
United Airlines Launches Liberia, Costa Rica ServiceU.S. Midwest Gets Access to Another Sun Destination, from Chicago O'Hare CHICAGO, Oct. 19 /PRNewswire-FirstCall/ — United is launching new service Dec. 17 through April 29 from Chicago to Liberia, Guanacaste in Costa Rica, just in time for the winter holidays. "The new service is...
United Expands explus Service, Adds New United Express RouteNew explus service includes Washington Dulles-San Antonio, TX, and an additional San Antonio-Los Angeles frequency CHICAGO, Aug. 29 /PRNewswire-FirstCall/ — United Airlines (BULLETIN BOARD: UALAQ) today announced an expansion of explus(sm) service — the United Express(R) line featuring three classes of seating on state-of-the-art Embraer-170...
United Airlines Further Expands Asia ServiceUnited offers new service between Nagoya and Taipei; expands service between Chicago and Hong Kong; and upgrades to larger aircraft on its Chicago-Beijing route CHICAGO, Feb. 23 /PRNewswire-FirstCall/ — With strong customer demand in international markets continuing, United announced today that it will offer new...
United Airlines Expands International Service Through Code-share Agreement With South African AirwaysService Agreement Expands the Reach of United's Network in Africa and Europe CHICAGO, Sept. 12 /PRNewswire-FirstCall/ — United Airlines today announced it has reached a code-share agreement with South African Airways, expanding international destination options for customers of both carriers. Under the agreement, passengers on...
United Airlines Expands Service to MunichNew Nonstop Service Between Chicago and Munich Takes off June 7, 2005 United Offers Bonus Miles for Summer Travelers* CHICAGO, Feb. 15 /PRNewswire-FirstCall/ — United today announced it will launch a daily nonstop flight between Chicago O'Hare and Munich, beginning June 7, 2005. This new...
United Express Expands Service from United's U.S. Domestic HubsNew Daily Explus Service Between San Francisco and Edmonton, Alberta; Denver and Knoxville, Tenn., Begins Today United Express Also Expands Its Service with New Routes and Added Frequencies from Chicago, Washington-Dulles, Los Angeles to Other Key Cities CHICAGO, Feb. 8 /PRNewswire-FirstCall/ — Beginning today, United...


With only three very luxurious suites you will never be part of a crowd! Themed on an 18th century farm house, the lodge offers travelers a luxurious refuge from the modern world.In the main lodge visitors may relax around the large screen tv, enjoy the pub and indulge in home cooked meals.For those who require Internet connection visitors may connect via satellite connection. Relax with a good book from our extensive library or take a dip in the large pool overlooking the waterhole while enjoying the sights and sounds of the bush.Full English Breakfasts, Packed lunches and sumptuous Dinners are a signature of Klipspringer Lodge.In addition to some of the worlds best game viewing opportunities, the lodge is perfectly located to explore the surrounding, beautiful Lowveld area which is steeped in human and geological history.The Phalabowra gate into Kruger National Park is only 15 minutes away- making Klipspringer Lodge a wonderful base from which to explore the majestic central regions of the park. Far less trafic than the southern area's. Treat the lodge as your home away from home, while you enjoy this unique bush experience.


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2020 Ford Mustang EcoBoost 2.3L High Performance Pack Preview: What a Nice RS Gets You | rR
Search our Automotive News stories and articles for auto industry news.
Rebel EditorApril 15, 2019
Manufacturer images
Competes with: Chevrolet Camaro RS 1LE, Dodge Challenger GT
Looks like: A Mustang GT with special stripes
Powertrains: 330-horsepower, turbocharged 2.3-liter EcoBoost four-cylinder engine; six-speed manual or 10-speed automatic transmission; rear-wheel drive
Hits dealerships: Fall 2019
The Ford folks are passionate about making their Mustang a true and proper sports car, one that doesn't just go fast in a straight line, but also handles corners and circuit tracks as well as it takes on drag strips and stoplight races. The V-8-powered Mustangs have gotten a lot of love recently — several Performance Packs are available for the GT, and there are new Shelby GT350, GT350R and GT500 models coming this year.
Now it's time for the four-cylinder Mustang to get some love. For 2020, Ford is (Eco)boosting its performance game for the entry-level Mustang by giving the turbocharged version an engine swap and a handling upgrade, called the 2.3L High Performance Package.
Related: More 2019 New York Auto Show Coverage
Changes to the Mustang's exterior are minimal, and frankly won't help differentiate it very much from the myriad other Mustang appearance packages you're likely to see. The most obvious changes are a grille, lower side sills, spoiler, wheels and rear lower bumper painted in Magnetic Gray. Two gray "whisker stripes" adorn the hood, and wider tires are fitted. The front splitter and spoiler are parts that are originally part of the GT's Performance Pack 1. The new 2.3L High Performance Pack can be had on the coupe or convertible model, and in one of the four new colors available on Mustang for 2020: Twisted Orange, Grabber Lime, Iconic Gray and Red Hot Metallic.
2020 Ford Mustang EcoBoost 2.3L High Performance Pack
Inside, there's nothing to really see, either. The High Performance Pack can be had with either of the two trims of EcoBoost Mustang, meaning you can get one with the base-level interior's cloth seats and fewer frills if you're looking to make a budget racer, or with the leather-lined plusher cabin if you're looking for some more zoot with your scoot. The dash gets an engine-turned aluminum look with oil pressure and turbo boost gauges, and a serialized dash plaque is also included.
Here's where the magic happens. Ford took the turbocharged 2.3-liter EcoBoost four-cylinder engine from the now-discontinued Ford Focus RS, the one built in Valencia, Spain, and modified it for use in the Mustang. It involved "switching it around," repositioning some components to allow for a longitudinal orientation in a rear-wheel-drive car instead of the transverse mounting in the Focus RS. A different turbocharger was fitted — one with a five percent larger, 63-millimeter twin-scroll compressor — as were some different radiators. The modified engine makes 330 horsepower and 350 pounds-feet of torque, down from the 350 hp it made in the Focus RS, but that's due to the different plumbing and charge intercoolers, according to Carl Widmann, Mustang chief engineer. What it can do is make 90 percent of its torque from just 2,500 rpm and maintain it all the way up to 5,300 rpm — with a redline topping out at 6,500 rpm.
The basic High Performance Pack comes with the aero parts and several other upgrades. The GT's brakes are included, 352-mm front rotors with four-piston calipers and 330-mm rear rotors. A strut-tower brace keeps the front suspension in line, while new shocks are fitted. Active exhaust is standard, as is a 3.55:1 limited-slip rear axle. Tires are Pirelli summer tires in 255/40ZR19 size, while stabilizer bars are upgraded to a tubular 32 mm in front and 24 mm in the rear.
If you want to max out your autocross or track day abilities, you can add the EcoBoost Handling Pack on top of the 2.3L High Performance Pack. It brings wider, specially developed Pirelli P Zero Corsa 265/40ZR19 summer tires. The rear sway bar gets upgraded from tubular 24 mm to solid 24 mm, Ford's excellent MagneRide electronic suspension is also added, and the limited-slip differential is swapped out for a Torsen unit. The EcoBoost Handling Pack is available only on the coupe model of the Mustang EcoBoost that also has the 2.3L High Performance Pack, but it can be had with either a manual or automatic transmission. In GT-speak, think of this as the GT Performance Pack 2 to the 2.3L High Performance Pack's GT Performance Pack 1.
More From Cars.com:
The new 2020 Mustang EcoBoost with these new performance upgrades will be available in the fall, but Ford has not yet said how much they will cost. Ford officials have assured us, however, that just like the current model's four-cylinder performance package, you can get one for less than the entry price of the V-8-powered GT. With its lighter weight and excellent balance, this one should be an absolute riot to drive.
Cars.com's Editorial department is your source for automotive news and reviews. In line with Cars.com's long-standing ethics policy, editors and reviewers don't accept gifts or free trips from automakers. The Editorial department is independent of Cars.com's advertising, sales and sponsored content departments.
Detroit Bureau Chief Aaron Bragman grew up in the Detroit area, comes from an automotive family and is based in Ann Arbor, Mich. Email Aaron


Besca USA is proud to service Georgia with any and all commercial coffee roaster needs. As a family owned and operated business, working with some of the largest coffee roasting companies in the world, we understand how frustrating it can be to have production halted. That's why we are here to give your coffee roasting business the care it deserves, care that lasts a lifetime. And, as your coffee production needs increase and your company grows, we would be delighted to help you upgrade with our many commercial coffee roaster options.


do you know how the blessing for sneezing started? waaayyy back when... they knew the heart stopped when you sneezed so, to ward off the devil from entering the body during that moment, people were blessed. old folk stuff. and the knocking on wood? houses used to be build of wood and have all kinds of thick wood for tables and such so they would consistently bang on all of it because they thought it would scare off those dang evil spirits.


Buy Bentyl 'Dicyclomine' Online Without Prescriptions. No Prescription Needed. Only $0.44. Order Bentyl 'Dicyclomine' Online Without Prescriptions. Cheap Bentyl 'Dicyclomine' Online No Prescription.
Bentyl is used for the treatment of functional bowel/irritable bowel syndrome.
Bentyl is used for treating symptoms of irritable bowel syndrome. Bentyl is an anticholinergic. It works by blocking a chemical in the smooth muscle of the stomach and intestines, causing them to relax, which reduces cramping.
Use Bentyl as directed by your doctor.
Do not take Bentyl in larger amounts, or take it for longer than recommended by your doctor.
Take Bentyl with a full glass of water.
If you miss a dose of Bentyl, take it as soon as possible. If it is almost time for your next dose, skip the missed dose and go back to your regular dosing schedule. Do not take 2 doses at once.
Ask your health care provider any questions you may have about how to use Bentyl.
Store Bentyl at room temperature, below 86 degrees F (30 degrees C). Protect from freezing. Store away from heat, moisture, and light. Do not store in the bathroom. Keep Bentyl out of the reach of children and away from pets.
if you have heart disease, heart failure, a history of rapid heartbeat, or high blood pressure.
Digoxin because the risk of its side effects may be increased by Bentyl.
This may not be a complete list of all interactions that may occur. Ask your health care provider if Bentyl may interact with other medicines that you take. Check with your health care provider before you start, stop, or change the dose of any medicine.
Bentyl may cause drowsiness, dizziness, blurred vision, or lightheadedness. These effects may be worse if you take it with alcohol or certain medicines. Use Bentyl with caution. Do not drive or perform other possible unsafe tasks until you know how you react to it.
Do not drink alcohol or use medicines that may cause drowsiness (eg, sleep aids, muscle relaxers) while you are using Bentyl; it may add to their effects. Ask your pharmacist if you have questions about which medicines may cause drowsiness.
Bentyl may cause dizziness, lightheadedness, or fainting; alcohol, hot weather, exercise, or fever may increase these effects. To prevent them, sit up or stand slowly, especially in the morning. Sit or lie down at the first sign of any of these effects.
Bentyl may make your eyes more sensitive to sunlight. It may be helpful to wear sunglasses.
Use Bentyl with caution in the elderly; they may be more sensitive to its effects.
Bentyl should not be used in children younger 6 months; safety and effectiveness in these children have not been confirmed.
Pregnancy and breast-feeding: If you become pregnant, contact your doctor. You will need to discuss the benefits and risks of using Bentyl while you are pregnant. Bentyl is found in breast milk. Do not breastfeed while taking Bentyl.
Blurred vision; constipation; decreased sweating; difficulty sleeping; dizziness; drowsiness; dry mouth; headache; lightheadedness; loss of taste; nausea; nervousness.
Severe allergic reactions (rash; hives; itching; difficulty breathing; tightness in the chest; swelling of the mouth, face, lips, or tongue); agitation; confusion; diarrhea; difficulty focusing your eyes; difficulty moving; difficulty speaking; difficulty urinating; disorientation; exaggerated sense of well-being; fainting; hallucinations; pounding in the chest; rapid heartbeat; short-term memory loss; unusual weakness; vomiting.


Idaho's POST Council requires all peace officers to complete a ten week basic academy. The strenuous curriculum focuses on the foundation of knowledge and practical skills necessary for patrol duties. Upon successful completion of this course, a student will be eligible for basic certification as a patrol officer.
Once your packet has been received and approved, you will be notified in an acceptance letter with further direction prior to your arrival to POST.
Please direct any questions pertaining to the Patrol Academy Packet to Jeremy Beck at (208) 884-7337 or via email at jeremy.beck@post.idaho.gov.


text:
Q: Prevent MySql from mangling queries by casting string to int On one of my tables I have an auto incrementing ID field. It also has another field (richter_code) with a unique constraint but, over the seasons, this field can change - that's why I'm not using it as the primary key.
In my program's code, I have a load function. First thing it does is check the richter_code field for the search parameter. If it doesn't return anything, it then goes on to search the on the ID field for the same parameter.
The problem is that it seems to truncate the value as soon as it encounters an alpha character. So I'm getting complete garbage from my query. See screenshot for example.
Can I prevent mysql from changing the query?

A: The problem here is that MySQL is doing an implicit conversion from the string to an int when doing the comparison....
SELECT * FROM cloths WHERE id = "3R100C"

making the conversion explicit, this is what MySQL is doing:
SELECT * FROM cloths WHERE id = CAST("3R100C" as int)

Instead, what you want to do is cast the id to a string, and compare that way. The solution is simply to:
SELECT * FROM cloths WHERE CAST (id as varchar(10)) = "3R100C"

That will remove any need for the integer handling/parsing on the string side.

A: Gotta love MySql ;)
I searched Stack Overflow for a MySql equivalent to some isnumeric function, and found this.
This rather convoluted WHERE clause would return the expected 0 rows:
where Id = case when concat('','3R100C'*1) = '3R100C' then '3R100C' else null end

The idea is to only match the parameter against Id when it is a valid numeric value. Hope it helps!

I'd create an actual isinteger function to abstract away this sheer madness:
CREATE FUNCTION `isinteger`(v varchar(255)) RETURNS bit(1)
BEGIN

    RETURN CASE WHEN CONCAT('', v * 1) = v THEN 1 ELSE 0 END;

END

That said I don't think it's right to use an auto-incremented Id field as a search-fallback column - this ID is your table's primary key, its meaning belongs strictly on the database side, no program should ever care about it, even less a program's user.


text:
Bonar Andrew A (Andrew Alexander)
Porte John Fielder
Yerxa Leroy
Schwartz Julia Augusta
Burkett Ray D
Barlow Jon C
Lewes George Henry
Ian Janis
Chadsey Charles E (Charles Ernest)
Benton Thomas Hart
The Song of Hiawatha
Longfellow Henry Wadsworth
Archeological Investigations Bureau of American Ethnology, Bulletin 76
Fowke Gerard
Illustrated Catalogue of the Collections Obtained from the Indians of New Mexico And Arizona in 1879 Second Annual Report of the Bureau of Ethnology to the Secretary of the Smithsonian Institution, 1880-81, Government Printing Office, Washington, 1883, p
Stevenson James
Illustrated Catalogue of the Collections Obtained from the Indians of New Mexico in 1880 Second Annual Report of the Bureau of Ethnology to the Secretary of the Smithsonian Institution, 1880-81, Government Printing Office, Washington, 1883, pages 429-466
The Treaty Held with the Indians of the Six Nations at Philadelphia, in July 1742 To which is Prefix'd an Account of the first Confederacy of the Six Nations, their present Tributaries, Dependents, and Allies
The Drama of the Forests: Romance and Adventure
Heming Arthur
The Delight Makers
Bandelier Adolph Francis Alphonse
Great Indian Chief of the West; Or, Life and Adventures of Black Hawk
Drake Benjamin
The Composition of Indian Geographical Names Illustrated from the Algonkin Languages
Trumbull J Hammond (James Hammond)
Navaho Houses Seventeenth Annual Report of the Bureau of Ethnology to the Secretary of the Smithsonian Institution, 1895-1896, Government Printing Office, Washington, 1898, pages 469-518
Mindeleff Cosmos
Animal Carvings from Mounds of the Mississippi Valley Second Annual Report of the Bureau of Ethnology to the Secretary of the Smithsonian Institution, 1880-81, Government Printing Office, Washington, 1883, pages 117-166
Henshaw Henry W (Henry Wetherbee)
The Mound Builders
Bryce George
Contribution to Passamaquoddy Folk-Lore
Fewkes Jesse Walter
Navajo weavers Third Annual Report of the Bureau of Ethnology to the Secretary of the Smithsonian Institution, 1881-'82, Government Printing Office, Washington, 1884, pages 371-392.
Matthews Washington
Throwing-sticks in the National Museum Third Annual Report of the Bureau of Ethnology to the Secretary of the Smithsonian Institution, 1883-'84, Government Printing Office, Washington, 1890, pages 279-289
Mason Otis Tufton
Casa Grande Ruin Thirteenth Annual Report of the Bureau of Ethnology to the Secretary of the Smithsonian Institution, 1891-92, Government Printing Office, Washington, 1896, pages 289-318
The Repair Of Casa Grande Ruin, Arizona, in 1891 Fifteenth Annual Report of the Bureau of Ethnology to the Secretary of the Smithsonian Institution, 1893-94, Government Printing Office, Washington, 1897, pages 315-348
Sign Language Among North American Indians Compared With That Among Other Peoples And Deaf-Mutes First Annual Report of the Bureau of Ethnology to the Secretary of the Smithsonian Institution, 1879-1880, Government Printing Office, Washington, 1881, page
Mallery Garrick
Indian Linguistic Families of America, North of Mexico Seventh Annual Report of the Bureau of Ethnology to the Secretary of the Smithsonian Institution, 1885-1886, Government Printing Office, Washington, 1891, pages 1-142
Powell John Wesley
Navajo Silversmiths Second Annual Report of the Bureau of Ethnology to the Secretary of the Smithsonian Institution, 1880-1881, Government Printing Office, Washington, 1883, pages 167-178