Blackberry Cheesecake: Jim's Birthday Cake | be mindful. be human.
C – Happy Birthday, Jim!!!
I made Jim a special cake this year. Not a normal chocolate or vanilla cake, but a cheesecake. I hope he likes it. Over the six years I have known Jim, I have never made or bought him a good birthday cake. It's really sad. Mainly, sad for me. I know him well enough to know when he doesn't like something. After I gave a cake to him, he wouldn't eat much of it. His reaction was always trying to be nice.
I have tried to make him a few different cakes. I haven't been successful. I ask him every year what he wants. He never gives me a straight answer. I actually told him for a couple of years that he won't get a cake. But, for some reason, I feel bad and end up making or buying him a cake. It ended up the same. Me being disappointed.
This year it's different. I asked Jim what he really wanted for a cake. He took half a day to think about it — knowing about my disappointing past cakes – and finally came up with a Blackberry-topped Cheesecake.
Yay! It's only a half cake! Or, is it a cake at all? I am happy he finally told me what he wanted. Unfortunately, I have never made a cheesecake in my life. I am really scared it might not turn out right. Some cheesecakes are too tart or are too cheesy. I am really scared. I really don't want to ruin his birthday again.
Well, cheesecake might get me to change my mind about getting a mixer. I made this by hand. It really uses a lot of arm work, especially if you don't have the cream cheese at room temperature. The cream cheese seemed not to be softened enough to make it smooth. It might taste like my worst fears coming true. But, so far, it looks like a cheesecake at least.
Well, I am glad that I didn't throw a birthday party for Jim. My cheesecake didn't turn out perfect. But, it still tasted great and that's what really matters. It wasn't fully cooked. I guess I should have let it cook a little bit longer. I blame it on the horrible thing in the kitchen I call an oven. I needed to cook it for maybe 50 minutes or longer. It was underdone in the middle, so it didn't hold together. But, the flavors are wonderful. Nice, rich and creamy. Not too sweet. It had a great flavor of berries and lemon that made it very refreshing.
In a mixing bowl, combine the ingredients with a fork until evenly moistened.
Lightly coat the bottom and sides of an 8-inch spring-form pan with non-stick cooking spray.
In the bowl of an electric mixer or by hand, beat the cream cheese on low speed for 1 minute until smooth and free of any lumps.
Add the eggs, 1 at a time, and continue to beat slowly until combined.
Gradually add sugar and beat until creamy, for 1 to 2 minutes.
Add sour cream, lemon zest, and vanilla.
Periodically scrape down the sides of the bowl and the beaters.
The batter should be well-mixed, but not over-beaten.
Set the cheesecake pan on a large piece of aluminum foil and fold up around the sides.
Place the cake pan in a large roasting pan.
Pour boiling water into the roasting pan until the water is about halfway up the sides of the cheesecake pan. The foil will keep the water from seeping into the cheesecake.
Bake for 45 minutes. The cheesecake should still jiggle (it will firm up after chilling), so be careful not to overcook.
Let cool in pan for 30 minutes.
Chill in the refrigerator, loosely covered, for at least 4 hours.
In a small saucepan add blackberries, sugar and lemon zest. Simmer over medium heat for 5 minutes, or so until the fruit begins to break down slightly.
Let cool before spreading on cheesecake.
Loosen the cheesecake from the sides of the pan by running a thin metal spatula or knife around the inside rim.
Release spring-form sides and transfer base to a cake plate.
Using a spatula, spread a layer of Warm Lemon Blueberry topping over the surface.
Jim commented that he wouldn't mind me testing this recipe again. That means he liked the birthday cake. YAY! I guess I will be making another cheesecake next year.
Happy Birthday, again, Jim. I am so glad you liked the cheesecake.
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text:
VEC Technology wins National Guard contract
VEC Technology, a division of J&D Acquisitions LLC, announced it was awarded an initial $4 million contract for VEC Mobile Recruiting Offices from the Army National Guard.
All 50 states, plus Guam and Puerto Rico, will be receiving one or more of the offices.
"We've been working with the NG for over two years to develop a new MRO that is capable of traveling with NG recruiters directly to those locations where the NG will be soliciting new NG recruits throughout the U.S.," VEC chairman Irwin Jacobs said in a statement.
"We believe our new VEC MROs are potentially the answer to the U.S. government's present and future needs in replacing many of their high-cost, non-performing recruiting storefronts that are presently being used by all branches of the U.S. armed forces," he added.
vec technologyirwin jacobsJ&D Acquisitions

redpajama_set_name: RedPajamaCommonCrawl


text:
package io.crate.execution.engine.sort;

import static io.crate.testing.TestingHelpers.createReference;
import static org.hamcrest.MatcherAssert.assertThat;
import static org.hamcrest.Matchers.instanceOf;

import org.apache.lucene.search.SortedSetSortField;
import org.elasticsearch.index.fielddata.NullValueOrder;
import org.junit.Test;

import io.crate.expression.reference.doc.lucene.NullSentinelValues;
import io.crate.metadata.ColumnIdent;
import io.crate.types.CharacterType;
import io.crate.types.DataType;
import io.crate.types.DataTypes;

public class SortSymbolVisitorTest {

    @Test
    public void test_missing_object_is_implemented_for_all_primitives() {
        for (DataType<?> primitiveType : DataTypes.PRIMITIVE_TYPES) {
            NullSentinelValues.nullSentinel(primitiveType, NullValueOrder.FIRST, false);
        }
    }

    @Test
    public void test_character_type_reference_can_be_mapped_to_sort_field() {
        var ref = createReference("c", ColumnIdent.fromPath("c"), CharacterType.INSTANCE);
        var sortField = SortSymbolVisitor.mappedSortField(ref, false, NullValueOrder.FIRST);
        assertThat(sortField, instanceOf(SortedSetSortField.class));
    }
}

redpajama_set_name: RedPajamaGithub


text:
Thrones (band)
Sol Invictus (band)
The Thrones (Ancient Greek: θρόνος, pl. θρόνοι; Latin: thronus, pl. throni) are a class of celestial beings mentioned by Paul the Apostle in Colossians 1:16. According to the New Testament, these high celestial beings are among those Orders at the Christ's service. They are the carriers of the Throne of God, hence the name.
According to Matthew Bunson, the corresponding order of angels in Judaism is called the abalim or "arelim/erelim, but this opinion is far from unrivaled. The Hebrew word erelim is usually not translated "Thrones", but rather "valiant ones", "heroes", "warriors". The function ascribed to erelim in Isaiah 33:7 and in Jewish folklore is not consonant with the lore surrounding the Thrones.
The Ophanim (Wheels or Galgallin) is a class of celestial beings, from Daniel 7:9, that are also equated with the "Thrones" occasionally. They are said to be great wheels covered in eyes.
Western Wisdom Teachings
Dionysius the Areopagite includes the Thrones as the third highest of 9 levels of angels.
This page contains text from Wikipedia, the Free Encyclopedia -	https://wn.com/Thrones
Thrones is the solo project of bassist Joe Preston.
Thrones began in 1994 with an untitled cassette on the Punk in My Vitamins? label. He soon released the "Reddleman" single. In 1996, Thrones signed to Communion Records to issue the full-length album Alraune. Thrones then signed to Kill Rock Stars and released the single "The Suckling." In late 1997, Preston began a recording project under the working title "White Rabbit, White Rabbit, White Rabbit". The project was eventually released as two 12 inch EPs; White Rabbit in 1999, followed by Sperm Whale in 2000. Both EPs were compiled in the Sperm Whale CD. In 2005, a compilation of various Thrones material spanning from 1994 to 2001 was released by Southern Lord Records under the title Day Late, Dollar Short.
After an extended hiatus beginning in 2001, Thrones began regularly performing live again in May 2006, although there were sporadic live appearances during this period supporting bands such as Sunn O))). Preston has also performed as part of Sunn O))) using Moog synthesizers and has previously been a member of Earth, The Melvins and High on Fire.
This page contains text from Wikipedia, the Free Encyclopedia -	https://wn.com/Thrones_(band)
Sol Invictus is an English neofolk and neoclassical group fronted by Tony Wakeford. Wakeford has been the sole constant member of the group since its inception, although numerous musicians have contributed and collaborated with Wakeford under the Sol Invictus moniker over the years.
After disbanding his controversial project Above the Ruins, Wakeford returned to the music scene with Sol Invictus in 1987. Since then Sol Invictus has had many musician contributions, including Sarah Bradshaw, Nick Hall, Céline Marleix-Bardeau , Nathalie Van Keymeulen, Ian Read and Karl Blake.
Wakeford repeatedly referred to his work as folk noir. Beginning with a mixture of a rough, bleak, primitive post punk sound and acoustic/folk elements, the band's music gradually evolved toward a lush, refined style, picking up classically trained players such as Eric Roger, Matt Howden, and Sally Doherty. In the mid-1990s, Sol Invictus spun off a side project called L'Orchestre Noir (later changed to Orchestra Noir) to explore an even more classically influenced direction. 2005 saw the departure of longtime contributors Roger and Blake, leading to a new line-up including Caroline Jago, Lesley Malone and Andrew King.
This page contains text from Wikipedia, the Free Encyclopedia -	https://wn.com/Sol_Invictus_(band)
source: Loudpack Jax's show
source: McSb
"A Throne!"
source: Franklyn Monk's Dronecast
source: TANGENTS
source: Mare Out There: Leaving a Message
source: CrossPoint Church | East Peoria, Illinois
source: Brentwood Baptist Church Podcast
source: SMOKEY OFFICIAL
source: Free Your Mind
The Throne Of Grace Is The Throne Of Opportunities
source: Yankee Arnold Ministries
Game of Thrones: The Iron Throne
source: Fiends Watch
NOOO THRONE NOOO THRONE
source: TALKIN' TV
Drafting For The Throne
source: Smark Sports
The Iron Throne
source: Flycast Buzz: Technology And Process Briefs For IT Professionals
source: VIDEO GRANDPA
Throne of Weapons
source: A History of the World in 100 Objects
Money and the Thrones
source: Cheap Heat with Peter Rosenberg
To the Throne - Confidently
source: Westminister Pulpit Podcast
Throne speech
source: Information Morning Fredericton from CBC Radio New Brunswick (Highlights)
This Old Rotting Heart released: 2014
This Old Rotting Heart
Day Late, Dollar Short released: 2005
Sperm Whale released: 2003
Alraune released: 1996
The Suckling
Young Savage
Reddleman
Senex
Silvery Colorado
Coal Sack
Epicus Doomicus Bumpitus
Piano Handjob
Simon Legree
Easter Woman
Valley of the Thrones
Black Blade
Obolus
David's Lib
A Quick One
Nostos Algos
Oso Malo
Nuts and Berries
Manmtn
Acris Venator
The Anguish of Bears
Gifthorse
Ursa Minor / Buio Omega
Mercuric
Googander
Thrones, Sol Invictus
Thrones, Code Orange Kids
Thrones, Alexisonfire
I saw a maiden by the river side
Waiting for her lover to come a-riding by
She dressed her hair with a golden comb
Love, it seemed, had gained the throne
And then he killed her
Struck once, then twice
With his knife
From stately mansion to the lowest slum
Love and death beat their drums
Lovers touch and lovers sigh
Lovers part and lovers cry
How easily love's vine does wilt
How easily love's vine is spilt
Latest News for: thrones
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Well, the actor who has been a famous Scottish actor was also among those who was approached for a role on the popular fantasy series Game Of Thrones ... Game of Thrones became a massive phenomenon globally ... Game of Thrones Entertainment.
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Metal detectorist finds one of England's earliest gold coins on farmland in Hemyock
The Times/The Sunday Times 17 Jan 2022
It features the first portrait of a king upon the English throne since the time of William the Conqueror, who ruled from 1066 to 1087 ... .
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Sony is reportedly working on its Spartacus program, details on which seem extremely scarce, apart from the fact that it might be an Xbox Game Pass competitor. One of the main features of Spartacus includes the ability to play classic titles from old PlayStation consoles ... Uhhh ... Unless pic.twitter.com/5CTACWGh7s ... The Two Thrones HD ... .
Tory MPs attack Boris in local papers
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It's easier than ever for Tory MPs to attack the PM ... And indeed many have made the most of such sites in recent weeks, as the pressure on Boris Johnson over partygate steadily increases ... And, in a sign which should worry No ... Not all Tories were critical ... a tree-planting initiative to mark the Queen's 70 years on the throne ... .
Film review: 'The Tragedy of Macbeth' bewitches audiences with striking sound, set design
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Something remarkable this way comes ... 25 and on Apple TV+ on Jan. 14, the film follows the titular Macbeth's (Denzel Washington) fated plan to rise to the throne of Scotland and his inevitable descent into evil and ultimately death ... [Related. Film review. Love isn't a low score in Venus and Serena Williams' 'King Richard'] ... [Related. Film review ... Part II'].
The icy grip eased on Sunday. But misery arrives Monday with snow, sleet, freezing rain ...
The Berkshire Eagle 17 Jan 2022
Quote. "A cold wind was blowing from the north, and it made the trees rustle like living things.". George R.R. Martin ("A Game of Thrones," 1996). Wintry weather was a late arrival this season, but the intensity of the extreme cold over the past few days has been quite remarkable ... Sunday morning's low was also 7 below ... Day, a federal holiday.Day by day.
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Jonathan Lisco is no stranger to television hits, having overseen the critically-acclaimed dramas Southland, Halt and Catch Fire, and Animal Kingdom ... "It sort of crept up on us," he says with a grin ... Later, they begrudgingly (well, except Misty) attend their 25-year high school reunion ... It's not exactly a Starbucks cup on Game of Thrones ... Exactly ... .
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Is there anything in common between Cyrano and Tyrion, your character in "Game of Thrones"? ... You spent a decade playing Game of Thrones, do you miss the series? ... I can speak from experience because, after playing "Game of Thrones," I discovered that it's impossible to convince everyone.
The Downfall of Prince Andrew: Here's What You Need to Know
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Elizabeth is poised to celebrate her 70th anniversary on the throne this year, and the monarchy — the symbol and unifier of an often restive nation — has been seeking to burnish and renew its brand for future generations ... A spare, rather than the heir, to the throne, his busy ...
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Antiwar | 17 Jan 2022


text:
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Amsterdam's Milkshake Festival 2018 at Westerpark on 28th – 29th of July is just around the corner and is almost SOLD OUT according to the organisers. The last tickets are on sale for Sunday which is known as the gayest day of the Festival. If you want Saturday tickets then you might want to checkout Ticketswap.
UPDATE: Milkshake is SOLD OUT. So checkout Ticketswap for last minute tickets! Also, don't fall for fake ticket sellers according to the festival organisers.
Use your imagination! This is one of the most open minded festivals in Europe. Anything from fetish wear (leather, latex, spandex, etc) is welcome along with flowing summer wear. Keep in mind that the weather can be unpredictable so it can be beautiful summer weather or pouring rain, so check the weather forecast before leaving the house! The festival grounds are mostly grass, so when it rains expect it to get very muddy so you might take that into account when selecting footwear. 😉 The organisers provide free ponchos (rain capes) when rain is predicted. There are tents also where you can dance the rain away. Lockers can be purchased before hand to store your extra layers in case of bad weather.
Milkshake festival takes place in the Westerpark which has a huge open space. The festival is broken into several areas with stages and tents and each stage has it's own theme. Be prepared to dance your a$$ off as some of the hottest DJs in Europe spins some hot tracks. Checkout some of the stages and line ups below.
Milkshake festival is located at Westerpark which is easily accessible by public transportation.
– From East/Centre: Tram 10 to Van Hallstraat; tramstop Limburg van Stirumstraat/ Van Hallstraat.
– From West: stadsbus 21 to Central station; tramstop Van Hallstraat/Haarlemmerweg.
– From East: Stadsbus 22 to Spaarndammerbuurt; busstop Haarlemmerplein.
– From Central Station citybus 21 to Geuzeveld; busstop Van Hallstraat/Haarlemmerweg.
The park is also easily accessible by bike and there are usually extra bike parking areas provided. Bikes & scooters can be parked at the Kanaalpromonade near the Gashoudervijver and the Marktplein. Both parking spaces can be found near the festival entrance.
If you take an Uber or Taxi, there is a taxi stop at the entrance of the park at Slingelandtstraat.
If you come by car, there is a car park at the corner of the park called Parkeergarage Westerpark.


It the new diet that has been featured in several television shows such as Oprah, BBC and 60 minutes. According to tests and testimonials it has proven to be safe and effective in loosing weight hassle free. It's the latest and most popular diet to come out today.
There a lot of diet pills in the market today. Due to the rampant problem with obesity a lot of people have come up with "miracle pills" along with a thousand other fake ones. With so many selections yet so little efficacy many people have become desperate. Fortunately a new diet pill has come up with a new way for weight loss. If you have a problem with eating then why not stop it?
The hoodia diet pill works by naturally suppressing your appetite. Its chemical components act on the satiety center located in the hypothalamus. This causes the hypothalamus to signal to the brain that it has already consumed enough.
With proper intake of these diet pills you will eat less without finding yourself craving for food. It's a much easier way of controlling your calorie intake without forcing yourself. Its active ingredient is patented which means it has gone through clinical testing before being used. People loose as much as a pound in every three or four days when taking the diet pill.
The diet pills main source is a plant which makes it 100% natural and safe. Unlike other diet pills and drug supplements it is not chemically formulated. It does not contain any ephedra, caffeine and other stimulants. It has no unpleasant side effects. It is also scientifically studied and tested which means it is effective. People using the diet pill were able to lower their calorie intake by 900 calories and as high as 1,100 calories daily.
Individuals don't have to go through the hassle of preparing meals. They also don't have to follow a strict regiment that restricts them from foods which later on turn into cravings. They don't have to calculate their calorie intake. They also don't have to restrain themselves from eating what they want. It's a better way to control your cravings rather than desperately controlling yourself.
Consumers have to be careful when buying these pills online or on EBAY. Due to its popularity there have been a lot of fake ones in the market. Be sure to read the label before buying the pills to make sure it does not contain any other ingredient other than hoodia gordonii. If it contains other ingredients it will not be effective.
Picking the right diet for you is important. Weight loss is not just about fitting back into your clothes but also to keep yourself healthy. Keep in mind that the diet pills are for maintenance only.


Cushion Pack machines , from Germany, will shred cardboard boxes and recycle them in to soft, flexible packing material. Reduce your eco footprint and save money !
Where high volume output is required, opt for the CP430-S2 which is designed for heavy grade cardboard. It features a 4.0kW motor and is suitable for 24hr operation.


Three groups are deciding the success of your business while you read this sentence.
METHODS USED OR RESULTS ACHIEVED.
SLAP has achieved legendry metrics impact for many of the world's most successful, demanding companies. The kind that don't include "Patience" on their list of corporate values.
Our founder/CEO Stan Slap regularly gives keynotes focused on maximizing commitment in manager, employee and customer cultures. His talks are based on the POV, processes and results that the SLAP company really achieves. Stan is also the New York Times bestselling author of Bury My Heart at Conference Room B and Under the Hood, which mine the path to Manager and Employee commitment, respectively. Stay tuned for Stan's third book, The Hungry and the Hunted, which sheds much needed light on how to activate your Customer Culture.


Tempeh is a traditional fermented whole-soybean food from Java, Indonesia where is it one of the most important protein sources in the country. This is a prestige product and the first export of genuine soybean tempeh from Indonesia, personally supervised to meet the highest standards of quality and hygiene. The soybeans are sourced from local Javanese farmers accepting only non-GM soybeans from Central Java. These are transformed by culturing with an edible mushroom culture that transforms it into a distinctly new food with an attractive aroma and flavour. This tempeh is made by artisans in a highland town of Java, famous for its superior cool climate and for the purity of the air, it is the only one of its kind and quality both inside and outside of Indonesia.The sauce is made from market fresh local spices; lemon grass, kafir lime leaves, coconut, coriander, red chillies, galangal root, and cooked with rare Indonesian salam leaves for their unique flavor. This is a prestige vegetarian and vegan ready prepared meal . Just heat and serve.
Soybean Tempeh (50%), Sauce: Coconut Milk, Shallots, Garlic, Lemongrass, Fresh Turmeric, Kafir Lime Leaves, Salam Leaves, Caraway Seeds, Vegetable Oil, Salt.
The flavour of the curry is not to my liking.


text:
\section{Introduction}

For numbers $x$ coprime to 10, i.e.\ numbers ending with 1, 3, 7 or 9, there exist infinitely many binary numbers $b$ such that the greatest common divisor of $b$ and rev($b$) = $x$ and the sum of digits of $b = x$. rev($b$) is the digit reversal of $b$, e.g.\ rev(123) = 321. The solutions $b$ converted to decimal numbers form the sequence A348480 of the On-Line Encyclopedia of Integer Sequences \cite{A348480}.\\

For example
$$gcd(1011,1101)=3$$
and since there is no smaller binary number that satisfies this constraint, $b = 1011$ is the solution for $x=3$. $b$ contains 3 ones and 1 zero and is called a short solution because there are more ones than zeros. If there are just a few zeros in the solution a computer search program will find the solution very quickly. However, in the cases $x = 7, 11, 13$ and $37$, there are many more zeros in the solution than ones and only for $x = 7$ and 11, the computer program is able to find the solution in a reasonable amount of time. The solution for $x = 13$ has 73 digits, which is beyond the capabilities of a systematic search.\\

Nevertheless, requirements for the long solutions can be established and the search space will collapse to a single degree of freedom. In the case of the porous numbers $x = 11$ and 37, it was demonstrated in \cite{jehn} that every number $m$ with sum of digits = $x$ and $x$ is a divisor of both $m$ and digit reversal of $m$ must have repeating zeros in their digits. And since a palindrome $m$ where $m$ = rev($m$) like 10101 cannot have 11 or 37 as greatest common divisor of $m$ and rev($m$), more zeros need to be added and the solutions for $x = 11$ and 37 have more zeros than ones.\\

For the sequence A348480, the requirements are even stricter: not only must $x$ be a divisor of both $m$ and digit reversal of $m$, $x$ must also be the greatest common denominator of the two numbers. In the case of 7 and 13, this complicates the search for the smallest solution, because for short numbers $m$ for which $7$ is a divisor of both $m$ and digit reversal of $m$, both $m$ and rev($m$) are also divisible by 13 and vice versa. And therefore no short solution exist for $x = 7$ and 13, as will be shown in this paper.\\

In the last chapter, the special case of $x = 39$ will be treated shortly. 39 does not have a long solution, but it also has no really short solution like all other cases up to and including $x = 71$. The explanation is that the multiplicative order of 10 modulo 39 is 6, the same as the multiplicative order of 10 modulo 7 or modulo 13 and therefore possible solutions are often also divisible by 7 or 13.

\section{Required mathematical tools}
\label{tools}

For our  proof, only a very few simple mathematical tools or fundamentals are required. The first fundamental deals with the parity of numbers. The following statement can be made:\\

If, $x, y, p$ and $q$ are integer numbers and
\begin{equation}
    x + y = p + q
\label{parity}
\end{equation}
then $x + p - y - q$ is an even number.\\

Proof: \\
$a + b$ has the same parity as $a - b$. Then $x + p - y - q = (x - y) + (p - q)$ is the sum of two numbers with the same parity which gives an even number.\\

A second tool that will be applied are divisibility rules. A number is divisible by 7 if the sum of blocks with length 6 is divisible by 7: You cut the number $b$ in blocks of length 6 starting from the right and sum up the blocks and check if the sum is divisible by 7. The same rule applies for all numbers $x$ where the multiplicative order 10 modulo $x$ is 6, like for 13 and for 39.\\

The last required prowess deals with Diophantine equations. For example, if $r$ and $s$ are integers and
$$5r + 8s \mbox{ is a multiple of } 13$$
then all solutions can be parameterized by:
$$r = 13n + s\mbox{ with } n \mbox{ being any integer.}$$

With these tools in hand we can start the proof.

\section{Requirements for a solution for $x = 7$}

The first requirement is that the sum of the digits of the solution $b$ is 7.\\

The second requirement is derived from the fact that 7 divides $b$ since 7 is the greatest common divisor of $x$ and $rev(x)$. The multiplicative order 10 modulo 7 is 6. Hence a number $b$ is divisible by 7 if the sum of blocks with length 6 is divisible by 7.\\

Let "$b_{s-1} ... b_3 b_2 b_1 b_0$" be a number $b$ with $s$ digits. We define:\\

A = $b_0 + b_6 + b_{12} + $ ... ,

B = $b_1 + b_7 + b_{13} + $ ... ,

C = $b_2 + b_8 + b_{14} + $ ... ,

D = $b_3 + b_9 + b_{15} + $ ... ,

E = $b_4 + b_{10} + b_{16} + $ ... and

F = $b_5 + b_{11} + b_{17} + $ ...\\

When $10^i$ ($i>1)$ is divided by 7, the first six remainders are 1, 3, 2, 6, 4 and 5 and then this sequence is repeating. We define:
$$
\delta_i = \left\{
    \begin{array}{rl}
        1 & \mbox{if } mod(i,6) = 0  \\
        3 & \mbox{if } mod(i,6) = 1  \\
        2 & \mbox{if } mod(i,6) = 2  \\
        6 & \mbox{if } mod(i,6) = 3  \\
        4 & \mbox{if } mod(i,6) = 4  \\
        5 & \mbox{if } mod(i,6) = 5  \\
    \end{array}
\right.
$$

With these definitions the powers of 10 can be written as:\\

$10^i = j_i \cdot 7 + \delta_i$\\

with some integer $j_i$. Then $b$ can be written as:

$$b = \sum_{i=0}^{s-1} b_i 10^i =  \sum_{i=0}^{s-1} b_i (j_i \cdot 7 + \delta_i) $$\\

Since 7 must divide this sum, the multiples of 7 can be dropped and it follows
\begin{equation}
   \sum_{i=0}^{s-1} b_i \delta_i  = l_1 \cdot 7
   \label{eq:7}
\end{equation}

Hence we get this requirement for the distribution of the 7 ones:

\begin{equation}
    A + 3 B + 2 C + 6 D + 4 E + 5 F = l_1 \cdot 7
   \label{eq:7a}
\end{equation}

The third requirement is derived from the fact that 7 also divides $rev(x)$ since 7 is the greatest common divisor of $x$ and $rev(x)$. As above $rev(b)$ can be written as:

$$b = \sum_{i=0}^{s-1} b_{s-i-1} 10^i =  \sum_{i=0}^{s-1} b_{s-i-1} (j_i \cdot 7 + \delta_i) $$\\

Again, the multiples of 7 can be dropped and it follows
\begin{equation}
   \sum_{i=0}^{s-1} b_{s-i-1} \delta_i  = m_1 \cdot 7
   \label{eq:7rev}
\end{equation}

If 7 divides $b$ then 7 also divides $10b$ and therefore we can add as many zeros to $b$ as needed such that $s$, without loss of generality, can be assumed to be a multiple of 6\footnote{To be on the safe side, the author repeated the proof individually for the other 5 cases of $s$ where $1 \leq mod(s,6) \leq 5$.}. In this case, eq.~\ref{eq:7rev} translates into our third requirement for the distribution of the ones in $b$:

\begin{equation}
    5 A + 4 B + 6 C + 2 D + 3 E + F = m_1 \cdot 7
   \label{eq:7b}
\end{equation}

Adding eq.~\ref{eq:7a} and eq.~\ref{eq:7b} yields:

\begin{equation}
    6 (A + F) + C + D = l_2 \cdot 7
   \label{eq:7plus}
\end{equation}

Note the term $8C$ reduces to $C$ because $7C$ can be subtracted on both sides and is absorbed in a new $l_2$ on the right-hand side of the equation. The same holds for $7E$ and $7B$ which disappear on the left-hand side.\\

Subtracting eq.~\ref{eq:7a} from eq.~\ref{eq:7b} yields:

\begin{equation}
    4 (A + C - D - F) + B - E = m_2 \cdot 7
   \label{eq:7minus}
\end{equation}

In summary, these are the 3 requirements for the positive integers $A, B, C, D, E$ and $F$ such that the greatest common divisor of $b$ and rev($b$) equals 7 and the sum of the digits of $b$ equals 7:

$$
    \begin{array}{rl}
            A + B + C + D + E + F & = 7 \\
                6 (A + F) + C + D & = l_2 \cdot 7 \\
        4 (A + C - D - F) + B - E & = m_2 \cdot 7  \\
    \end{array}
$$

\section{Requirements for a solution for $x = 13$}

The first requirement is that the sum of the digits of the solution $c$ is 13.\\

The second requirement is derived from the fact that 13 divides $c$ since 13 is the greatest common divisor of $x$ and $rev(x)$. The multiplicative order 10 modulo 13 is 6. Hence a number $c$ is divisible by 13 if the sum of blocks with length 6 is divisible by 13.\\

Let "$c_{t-1} ... c_3 c_2 c_1 c_0$" be a number $c$ with $t$ digits. We define:\\

A' = $c_0 + c_6 + c_{12} + $ ... ,

B' = $c_1 + c_7 + c_{13} + $ ... ,

C' = $c_2 + c_8 + c_{14} + $ ... ,

D' = $c_3 + c_9 + c_{15} + $ ... ,

E' = $c_4 + c_{10} + c_{16} + $ ... and

F' = $c_5 + c_{11} + c_{17} + $ ...\\

When $10^i$ ($i>1)$ is divided by 13, the first six remainders are 1, 10, 9, 12, 3 and 4 and then this sequence is repeating. We define:
$$
\theta_i = \left\{
    \begin{array}{rl}
        1 & \mbox{if } mod(i,6) = 0  \\
       10 & \mbox{if } mod(i,6) = 1  \\
        9 & \mbox{if } mod(i,6) = 2  \\
       12 & \mbox{if } mod(i,6) = 3  \\
        3 & \mbox{if } mod(i,6) = 4  \\
        4 & \mbox{if } mod(i,6) = 5  \\
    \end{array}
\right.
$$

With these definitions the powers of 10 can be written as:\\

$10^i = k_i \cdot 13 + \theta_i$\\

with some integer $k_i$. Then $c$ can be written as:

$$c = \sum_{i=0}^{t-1} c_i 10^i =  \sum_{i=0}^{t-1} c_i (k_i \cdot 13 + \theta_i) $$\\

Since 13 must divide this sum, the multiples of 13 can be dropped and it follows
\begin{equation}
   \sum_{i=0}^{t-1} c_i \theta_i  = l_3 \cdot 13
   \label{eq:13}
\end{equation}

Hence we get this requirement for the distribution of the 13 ones:

\begin{equation}
    A' + 10 B' + 9 C' + 12 D' + 3 E' + 4 F' = l_3 \cdot 13
   \label{eq:13a}
\end{equation}

The third requirement is derived from the fact that 13 also divides $rev(x)$ since 13 is the greatest common divisor of $x$ and $rev(x)$. As above $rev(c)$ can be written as:

$$c = \sum_{i=0}^{t-1} c_{t-i-1} 10^i =  \sum_{i=0}^{t-1} c_{t-i-1} (k_i \cdot 13 + \theta_i) $$\\

Again, the multiples of 13 can be dropped and it follows
\begin{equation}
   \sum_{i=0}^{t-1} c_{t-i-1} \theta_i  = m_3 \cdot 13
   \label{eq:13rev}
\end{equation}

In this case, again without loss of generality assuming that $t$ is a multiple of 6, eq.~\ref{eq:13rev} translates into our third requirement for $c$:

\begin{equation}
    4 A' + 3 B' + 12 C' + 9 D' + 10 E' + F' = m_3 \cdot 13
   \label{eq:13b}
\end{equation}

Adding eq.~\ref{eq:13a} and eq.~\ref{eq:13b} yields:

\begin{equation}
    5 (A' + F') + 8 (C' + D') = l_4 \cdot 13
   \label{eq:13plus}
\end{equation}

Subtracting eq.~\ref{eq:13a} from eq.~\ref{eq:13b} yields:

\begin{equation}
    3 (A' + C' - D' - F') + 6 (B' - E') = m_4 \cdot 13
   \label{eq:13minus}
\end{equation}

In summary, these are the 3 requirements for the positive integers $A', B', C', D', E'$ and $F'$:

$$
    \begin{array}{rl}
            A' + B' + C' + D' + E' + F' & = 13 \\
            5 (A' + F') + 8 (C' + D')   & = l_4 \cdot 13 \\
    3 (A' + C' - D' - F') + 6 (B' - E') & = m_4 \cdot 13  \\
    \end{array}
$$

\section{Proof that 7 has a long solution}

We will prove that 5 out of the 6 positions $A, B, C, D, E$ and $F$ will be zero and all 7 ones must be located in one position. If we define $R = A + F$ and $S = C + D$ then eq.~\ref{eq:7plus} translates into:
$$ 6 R + S = l_2 \cdot 7$$

This Diophantine equation has the solution space

$$R = 7 n_1 + S$$
with $n_1$ being any integer.\\

Since $0 \leq R, S \leq 7$, $n_1$ can only be -1, 0 or +1.
\begin{enumerate}
    \item $n_1 = -1 \Rightarrow R = 0$, $S = 7$. This means all ones are in positions $C$ and $D$ and $A = B = E = F = 0$. Then it follows from eq.~\ref{eq:7minus} that $4 (C - D) = m_2 \cdot 7$ or $C - D = m_2 \cdot 7$. Since $C + D = 7$ this is only possible if $C$ or $D$ equals 7. Hence all ones are located in one position, either $C$ or $D$, qed.
    \item $n_1 = +1 \Rightarrow R = 7$, $S = 0$. This means all ones are in positions $A$ and $F$ and $B = C = D = E = 0$. Then it follows from eq.~\ref{eq:7minus} that $4 (A - F) = m_2 \cdot 7$ or $A - F = m_2 \cdot 7$. But this is only possible if $A$ or $F$ equals 7. Hence all ones are located in one position, either $A$ or $F$, qed.
    \item $n_1 = 0 \Rightarrow R = S$. In this case we can conclude two facts: first, if we define $U = A + C - D - F$ then $U$ is even (see Chapter~\ref{tools}) and second, eq.~\ref{eq:13plus} holds because $5 R + 8 S$ is a multiple of 13.
\end{enumerate}

This means either we have proved that 7 has a long solution or $U$ must be even and eq.~\ref{eq:13plus} holds.\\

In the latter case, we define $V = B - E$. Then eq.~\ref{eq:7minus} translates into:
$$ 4 U + V  = m_2 \cdot 7$$

This Diophantine equation has the solution space

$$U = 7 n_2 - 2 V$$
with $n_2$ being any integer.\\

Since $U$ is even, also $n_2$ must be even and since  $-7 \leq U, V \leq 7$, $n_2$ can only be -2, 0 or +2.
\begin{enumerate}
    \item $n_2 = -2 \Rightarrow U = 0$, $V = -7$. This means all ones are in position $E$, qed.
    \item $n_2 = +2 \Rightarrow U = 0$, $V = 7$. This means all ones are in position $B$, qed.
    \item $n_2 = 0 \Rightarrow U = -2 V$. In this case eq.~\ref{eq:13minus} holds because $3U + 6V = -6V + 6V = 0 = m_4 \cdot 13$.
\end{enumerate}

So either we have a long solution or both equations \ref{eq:13plus} and \ref{eq:13minus} hold. But if both equations are true, then $b$ and rev($b$) are divisible by 13 and the greatest common divisor cannot be 7. Hence 7 has a long solution, qed.\\

The shortest "long solution" for $x=7$ is

$$1000000000001000001000001000001000001000001,$$ with all ones in position $A$. Digit $b_{36}$ must also be a zero, because the solution cannot be a palindrome, otherwise the greatest common divisor will not be 7.

\section{Proof that 13 has a long solution}

We will prove that 5 out of the 6 positions $A', B', C', D', E'$ and $F'$ will be zero and all 13 ones must be located in one position. If we define $R' = A' + F'$ and $S' = C' + D'$ then eq.~\ref{eq:7plus} translates into:
$$ 5 R' +  8 S' = l_4 \cdot 13$$

This Diophantine equation has the solution space

$$R = 13 n_3 + S$$
with $n_3$ being any integer.\\

Since $0 \leq R, S \leq 13$, $n_3$ can only be -1, 0 or +1.
\begin{enumerate}
    \item $n_3 = -1 \Rightarrow R' = 0$, $S' = 13$. This means all ones are in positions $C'$ and $D'$ and $A' = B' = E' = F' = 0$. Then it follows from eq.~\ref{eq:13minus} that $3 (C' - D') = m_4 \cdot 13$ or $C' - D' = m_4 \cdot 13$. But this is only possible if $C'$ or $D'$ equals 13. Hence all ones are located in one position, either in $C'$ or $D'$, qed.
    \item $n_3 = +1 \Rightarrow R' = 13$, $S' = 0$. This means all ones are in positions $A'$ and $F'$ and $B' = C' = D' = E' = 0$. Then it follows from eq.~\ref{eq:13minus} that $4 (A' - F') = m_4 \cdot 13$ or $A' - F' = m_4 \cdot 13$. But this is only possible if $A'$ or $F'$ equals 13. Hence all ones are located in one position, either in $A'$ or $F'$, qed.
    \item $n_3 = 0 \Rightarrow R' = S'$. In this case we can conclude two facts: first, if we define $U' = A' + C' - D' - F'$ then $U'$ is even (see Chapter~\ref{tools}) and second, eq.~\ref{eq:7plus} holds because $6 R' + S'$ is a multiple of 7.
\end{enumerate}

This means either we have proved that 13 has a long solution or $U'$ must be even and eq.~\ref{eq:7plus} holds.\\

In the latter case, we define $V' = B' - E'$. Then eq.~\ref{eq:13minus} translates into:
$$ 3 U' + 6 V'  = m_4 \cdot 13$$

This Diophantine equation has the solution space

$$U' = 13 n_4 - 2 V'$$
with $n_4$ being any integer.\\

Since $U'$ is even, also $n_4$ must be even and since  $-13 \leq U', V' \leq 13$, $n_4$ can only be -2, 0 or +2.
\begin{enumerate}
    \item $n_4 = -2 \Rightarrow U' = 0$, $V' = -13$. This means all ones are in position $E'$, qed.
    \item $n_4 = +2 \Rightarrow U' = 0$, $V' = 13$. This means all ones are in position $B'$, qed.
    \item $n_4 = 0 \Rightarrow U' = -2 V'$. In this case eq.~\ref{eq:7minus} holds because $4U' + V' = -8V' + V' = -7V'$ is a multiple of 7.
\end{enumerate}

So either we have a long solution or both equations \ref{eq:7plus} and \ref{eq:7minus} hold. But if both equations are true, then $b$ and rev($b$) are divisible by 7 and the greatest common divisor cannot be 13. Hence 13 has a long solution, qed.

\section{39 has quite a long "short solution"}

Since the multiplicative order 10 modulo 39 is also 6, it turns out that for most numbers $b$ where the sum of digits of $b$ is 39 and 39 divides both $b$ and rev($b$), also 7 divides both $b$ and rev($b$) and therefore 39 is not the greatest common divisor. In fact the smallest $b$ where the greatest common divisor is 39 has 16 zeros, i.e.\ $b$ has 55 digits in total. With a computer program, an iterative search was performed given these three constraints:

$$
    \begin{array}{rl}
        A + B + C + D + E + F & = 39 \\
        A + 10 B + 22 C + 25 D + 16 E + 4 F & = l_5 \cdot 39 \\
        4 A + 16 B + 25 C + 22 D + 10 E + F & = m_5 \cdot 39  \\
    \end{array}
$$
The result was $A = 10$, $B = C = 9$, $D = 6$, $E = 0$ and $F = 5$. In binary terms, this translates into
b = 1000111000111000111001111101111101111101111101111101111 or in decimal form 20016007615544303 which is term 16 of A348480.

redpajama_set_name: RedPajamaArXiv


text:
Srebrna Gwiazda, Medal Srebrnej Gwiazdy (ang. Silver Star, Silver Star Medal) – gwiazda Sił Zbrojnych Stanów Zjednoczonych przyznawana żołnierzom sił zbrojnych USA za odwagę w obliczu nieprzyjaciela. W szczególnych wypadkach może być przyznana również żołnierzom innych państw. Jest to czwarte najwyższe amerykańskie odznaczenie wojskowe po Medalu Honoru, Krzyżu za Wybitną Służbę i Medalu za Wybitną Służbę.

Odznaczenie może być nadane wielokrotnie. Kolejne nadanie jest oznaczane poprzez nałożenie na wstążkę (oraz baretkę) brązowej odznaki w formie pęku liści dębowych (oak leaf cluster) w Siłach Lądowych i Powietrznych, lub złotej pięcioramiennej gwiazdki w Marynarce Wojennej, Piechocie Morskiej i Straży Wybrzeża USA. Pięć odznak brązowych lub gwiazdek złotych jest zastępowanych odznaką względnie gwiazdką srebrną.

Odznaczeni

Linki zewnętrzne

Przypisy

Amerykańskie odznaczenia wojskowe

redpajama_set_name: RedPajamaWikipedia


text:
Azealia Banks Vows To Never Return To Israel
Written By Malcolm Wyche
Source: Sergi Alexander / Getty
Azealia Banks has had her fair share of controversy over the years. The Harlem artist has found herself feuding with the country of Israel for her latest grievance after claims of mistreatment and other issues.
While on the road to perform at Tel Aviv's Barby Club, her excitement was shown through her Twitter feed. After arriving in Israel, her excitement turned to frustration as she faced terrible service at her hotel and during her flight.
Banks took to social media and stated, "Sidebar: "I love my fans but the people in Tel Aviv are really very rude. The folks at the hotel, in restaurants, at the grocery store treated me with such disregard I really didn't enjoy my time here. The show was great tho". This prompted an extended rant where she opened up about feeling as if the airport was discriminating against her because she was black.
Her tweets can still be found her profile "Cheapy XO." The Israel Airports Authority states that Azealia Banks was treated like every other customer that comes to them. Check out Azealia Banks complaints below.
No some old Jewish lady on my el al flight screamed at me in front of the whole plane for trying to put my bag where hers was. It was so racist I sat in my seat and cried
— CHEAPY XO (@cheapyxo) May 8, 2018
More By Malcolm Wyche
Kevin Hart Is Thankful For His Angels After Private Jet Incident
Waffle House Hero James Shaw Jr. Raises Money For Families Of Victims


text:
Emergent Tech
Invasion of the virus-addled lightbulbs (and other banana stories)
Why Pinky? What are we doing tomorrow?
By Alistair Dabbs 7 Oct 2016 at 09:31
Something for the Weekend, Sir? Yikes, all I have to do is go away for a couple of weeks and all hell breaks loose. But at least it's the right kind of hell: that is, the veritable technological hell that I've been predicting in these columns for years.
First off as I sit back in my late-vacation sun lounger to read the news on my tablet is that the Krebs on Security blog was booted offline after suffering a 665Gbps DDoS attack.
Who can we blame for this cybercrime assault on cybercrime writer Brian Krebs? The culprit turns out to be a million or more dipshit Internet of Things devices such as cameras and thermostats that passively allowed themselves to be rogered by infected code before spontaneously forming a botnet of mutual insanity.
So you may as well forget about human hackers, laugh in the masked face of Anonymous, tell Mr Robot it's "Game Over" and slip an exploding Galaxy Note 7 into Zero Cool's high-waisted '90s slacks.
No, thanks to IoT, your worldwide organisation is most likely to be taken down by a fucking light bulb.
And to think Lucy Orr has been harbouring a hardened cybercriminal all this time.
This is possibly why the topic of robots taking over the world came up (again, yawn) during Professor Nick Bostrom's keynote speech on artificial intelligence at the opening of IP Expo Europe this week in London.
In the future, you can never have enough paperclips. Prof Nick Bostrom at IP Expo Europe.
In fact, he was a bit of a killjoy for sci-fi fans in the audience by dismissing the scenario in which an AI becomes self-aware and self-determining before ridding the world of that pestilence known as humanity. "An AI might have a high level of intellectual performance," he noted, "but that's not the same as human-like consciousness. It won't have a human-like sensory experience or understanding of pain and suffering, for example."
Aha but isn't that the very danger we're talking about? Ultimately, those unfeeling lightbulbs are psychopaths, calmly wiping out everything in their way without being restrained by conventional human morality.
Prof Bostrom is having none of it. "The argument is that an AI might decide to hack its way out of itself. However, an AI won't do something that goes against its purpose."
The trick, then, is making sure the AI is focused on doing something sensible rather than letting it decide for itself what it should do based on a limited sensory experience of real life. Get an AI to run your paperclip factory more efficiently, sure, but give it a tightly controlled context.
He also reminds us of the legend of King Midas – fintech AI developers please take note.
In other words, programmers design the AI to do something and, as a result, effectively set the direction and values of its self-learning process. If you design an AI toaster to make toast, it shouldn't want to do much else other than to make the best toast it can, and lots of it.
I toast therefore I am.
On the other hand, Prof Bostrom is more concerned with who determines what morality an AI should abide by. There are social and, inevitably, political issues to be fought over when choosing the kind of ethics and value alignment to be built into AIs of the future. This is partly what the Partnership on AI group was set up to discuss, with the involvement of Amazon, DeepMind, Google, Facebook, IBM and Microsoft.
Let's hope they like toast.
The professor's take on cybersecurity is that hackers will be hackers, and that an AI is pretty much like any other computer system in this respect: it needs to be made secure. The awkward bit, he admits, is that AIs are only as good as the data you feed them, citing the example earlier this year of Microsoft's Tay chatbot being groomed into spouting racist slurs by mischievous Tweeters.
Well that's just spanky: if a hoard of rampaging lightbulbs don't get us, the nazi toasters will.
We can learn two important lessons from this:
1. Despite all the warnings, today's IoT devices remain a stinking cesspool of insecurity. And I'm not convinced their manufacturers give a hoot. Where's the protection? Where's the self-patching? Where's the will to do the right thing by its gullible fools customers?
2. We should limit AI's exposure to the general public. An AI is, by definition, a "high level machine intelligence". The public is, by definition, a "bunch of nutters". They should be kept well apart until AI development reaches the big take-off point which, Prof Bostrom reckons, may still be 50 years away.
In the meantime, we poor humans will have to make our own entertainment. Sci-fi doom-mongers are safe for a good number of novels and movies yet.
On that note, I was pleased to read during my holiday about researchers at Stanford University who had persuaded a monkey to type "To be or not to be. That is the question."
No roomful of primates was required, nor an unlimited number of typewriters – which, when you think about it, are even more difficult to source these days than the monkeys.
What actually happened was that two monkeys were trained to use neural implants to move a cursor across a computer display to trigger circles as they turned green. It was an easy matter to trick the poor hairy buggers to spell out a line of Shakespeare, gain some valuable public relations and have a laugh in the process.
It's a far cry from Planet of the Apes. As long as the IoT lamp in my IoT fridge isn't harbouring Pinky-and-the-Brain plans to take over the world, I think we're safe for a while yet. Besides, even if left to their own devices (ho ho), these monkeys are unlikely to want to aspire to either Shakespearean pretensions or world domination.
The best we could probably hope for is to turn up at the lab one morning to find that one short-sighted monkey has typed one line:
"Is this a banana I see before me?"
Alistair Dabbs is a freelance technology tart, juggling IT journalism, editorial training and digital publishing. Despite all the holiday pizzas, he continues to diet, exercise and lose weight. Naturally, he thinks this makes him look younger, leaner and athletic. According to Mrs Dabbsy, however, his neighbours have been asking: "Is he ill?"
FBI Update: 15kg.


text:
Q: Is there any benefit to having both an ordered and unordered index on the same column in postgres? I have inherited a postgres database where there are two identical indexes except for their order:
CREATE INDEX avail_time_ix ON table (availability_time);
CREATE INDEX avail_time_dc_ix ON table (availability_time DESC);

Is there any benefit to having both the ordered index and the unordered index?

A: I am combining several good comments into a comprehensive answer.
Order on a mutli-column index could have a bigger impact on efficiency than a single column. In my case it is only one column.
Postgres can scan indexes forwards and backwards just as efficiently. The index which does not have an explicit order is ordered ASC by default.

Specifies ascending sort order (which is the default).

This means that the two indexes are redundant.

redpajama_set_name: RedPajamaStackExchange


If you've missed previous chances to catch the Legendary Pokemon Mewtwo, Articuno, Zapdos or Moltres in Pokemon Go, you've now got another chance.
Over the past few months, Pokemon Go developers Niantic have been testing the Pokemon trainers across the world, setting goals for them through Professor Willow as part of what they've been calling the Global Research Challenge. This challenge has had numerous events available to fans both out in the real world at specific locations adn online for everyone to participate in – and over these months, fans have been able to earn the chance to catch very rare Pokemon.
It's fair to say that fans smashed expectations, with each stage of the research challenge quickly completed by Pokemon Go's dedicated user-base. That means there's one more reward to come: a chance for everyone to catch Mewtwo, as well as legendary birds Articuno, Zapdos and Moltres. These are super rare beasts that rate highly on our Pokemon Go tier list of the best Pokemon so they're well worth having, and that's not even the only bonus of this event.
Region-exclusive Kanto Pokemon Farfetch'd, Kangaskhan, Mr. Mime and Tauros can now potentially hatch from 7km Pokemon Eggs, which are obtained through gifts from friends. Previously, the 7km eggs only contained the Alolan Pokemon forms.
Articuno, Zapdos and Moltres will appear in regular Raid Battles across the world through September 20. This is a chance to catch these legendary Pokemon from the Kanto region (Pokemon Red/Blue/Green/Yellow) of the oriignal games. There's even a chance that the Shiny forms of these Pokemon will appear in a raid near you, so keep an eye out.
Finally, on September 20 (from 1pm Pacific), Mewtwo will appear in Raid Battles. Prior to this Mewtwo has only shown up as an EX Rade encounter, but now the ultra-rare genetically engineered Pokemon can show up as a part of raids.
Mewtwo will replace Articuno, Zapdos and Moltres come September 20, so you'll want to target catching those three Pokemon first. It isn't currently clear for how long Mewtwo will stick around for, but the region-exclusive Pokemon will remain in 7km eggs through the end of September – so the end of the month seems like a safe bet at an absolute minimum.


text:
Here's What We Know About Rebecca King-Crews, the Wife of AGT's New Host
Profession Actresses
The first thing that comes to mind when the name Rebecca King-Crews pops up has to be the one and only Terry Crews, the macho Hollywood star who is known for his comedic talents on shows like Brooklyn Nine-Nine and Everybody Hates Chris. But while her husband is undoubtedly the most famous face in the family, Mrs. Crews also holds her own as she has also made a splash in the entertainment industry. She has been featured for not just stories that revolve around her being married to a very famous man, but for her exploits on a few other things that include appearing in the reality TV show, The Family Crews.
Thanks to the family's openness on the show, fans across the world have gotten to learn a thing or two about the matriarch of the Crews family. Here is what we have been able to find out about Rebecca King-Crews.
1 Origin and Background of Rebecca King-Crews
2 What Does She Do For a Living?
3 Her Life with Terry Crews
Origin and Background of Rebecca King-Crews
Due to the color of her skin, many would be surprised to learn that Rebecca King-Crews is partly African American. She was born to an interracial couple; Jack Winston Lund and Anna Mae Parks, on Christmas Eve 1965 in Benton Harbor, Michigan, but was raised in Gary, Indiana, along with two siblings; Elizabeth and Samuel Taylor.
Growing up in Indiana consisted of several moments and milestones in Rebecca's young life. She attended different schools before graduating from Lew Wallace High School as an honors student. She was also a beauty queen, winning the crown of Miss Gary Indiana at the age of 19.
In addition to her exploits in pageantry and academic achievements, Rebecca King-Crews was also interested in acting in the theater. During her high school years and her college days at Western Michigan University where she studied and graduated with a degree in Musical Theatre, she was known to have performed in a number of plays, including Music Man, The Wiz, and Oklahoma.
What Does She Do For a Living?
Just like her husband, the bulk of Rebecca King-Crews' professional career has been in the entertainment industry. After a few years of making red carpet appearances alongside her husband, she made her debut television appearance in 2010 in the reality TV show, The Family Crews.
The BET show, where Rebecca equally served as a producer, explored the life of her family. The Family Crews ran for 17 episodes between 2010 and 2011 before it was canceled over poor ratings. She has since gone ahead to make other appearances in shows like Life After, Extra, Celebrity Family Feud, and Black Love.
While her dominant onscreen appearances have had her appear as herself, Rebecca King-Crews has made a few appearances playing other characters. She appeared in the 2018 short video, Blueberry, playing the character of Grace.
Beyond appearing in front of the camera, Rebecca has also made strides towards having a music career. She has released a couple of singles, some of which include I Keep Holding On, and Destiny. Singing under the pseudonym, Regina Madre, the wife of the host of America's Got Talent has gone on tours and been on a few promotions.
Outside of her music and acting career, she is also the CEO & Founder of Crews Arts Ltd.; a company believed to be a vehicle for the family's entertainment interests. Other noteworthy career milestones of Mrs. Crews include appearances in several fashion magazines like Today's Black Woman, Heart and Soul, Jet, Television Guide, and Reality Magazine. She is also involved with different charities in the Christian community.
Her Life with Terry Crews
Rebecca King-Crews' relationship with husband Terry Crews is undoubtedly one of the defining facts of her public life. The couple, who got married in 1989, started dating long before that time, however, details surrounding when exactly they met are few and far between. According to them, they started off as friends before their friendship unexpectedly blossomed into a romantic relationship, culminating in them exchanging vows on the 29th of July, 1989.
During what has sometimes been a tumultuous marriage that included infidelity and porn addiction, Rebecca and Terry have remained together, and are proud parents to five children.
Their first child is Azriel Crews, who was born in 1990. Others are Tera (born in 1999), Wynfrey (born in 2004), and Isaiah (born in 2007). Their fifth child, Naomi Burton-Crews, was born before their marriage. She was born out of a previous relationship between Rebecca and an unknown man. Through Naomi, Terry and Rebecca have become grandparents to a girl named Miley Crews.
While all five children made appearances in The Family Crews reality TV show, only Azriel has taken a step further by pursuing a career as an actress. Some of her acting credits include shows like Katy Keene, In Development, Crashing, and High Maintenance.
Top 3 Richest Actresses
Dina Merrill - $5 Billion
Robyn Moore Gibson - $400 Million
Kathryn Eastwood - $375 Million
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text:
In questa lista dei ponti medievali in Francia sono compresi tutti i ponti costruiti fra il 500 d.C. e il 1500 nel territorio di quella che è l'attuale Francia, ossia includendo anche regioni che allora non rientravano nel nome di Francia, come le regioni dei Burgundi, l'Alsazia, la Lorena e la Savoia. Contando anche i ponti Romani rimasti in uso in tutto questo periodo, la lista arriva ad annoverare quasi 700 strutture.

Note

Bibliografia
Marjorie Nice Boyer: Medieval French Bridges. A History, Cambridge: Massachusetts, The Mediaeval Academy of America, 1976, ISBN 0910956588, pp. 171–195

Altri progetti

Francia

Ponti medievali
Liste di ponti
Architetture medievali della Francia