text:
Getting to Perry's Bridge Hollow
Directions from Kruger Airport
Exit the airport taking the second exit at the roundabout onto the R538.
Turn left at the next T-junction and immediately right towards Plaston (R538).
Carry on straight for 8.7 km until you get to the first traffic lights in White River (Mosque is on your left hand side) and turn right onto the R40 towards Hazyview (Pass straight through the roundabout, traveling approximately 43 km)
At the T-junction turn left into Hazyview and continue straight through the C.B.D.
Once you have passed the Total Filling Station on the left, 500m further on you will find Perry's Bridge Hollow on your left hand side.
Directions from Johannesburg
Take the N12 or N4 to Nelspruit via Witbank and Middleburg.
Approximately 2km before Nelspruit take a slight left (traveling approximately 270 m) then take a right toward the R37.
Carry on straight through the first roundabout, taking the first exit at the second roundabout. At the second set of traffic lights take a left turn onto the R40 (traveling approximately 15km) until you reach the first Robot in White River.
Take a slight left at the first traffic lights then turn right, continue straight and take a slight left at the second set of traffic lights onto the R40. Carry on, passing straight through the roundabout (traveling approximately 43km)
At the T-junction, turn left into Hazyview and continue straight, passing through two stop streets, then two traffic lights and then another stop street.
Turn left into Perry's Bridge Shopping Centre.
Road Transfers
Getting to Hazyview in Mpumalanga is easy with Seasons in Africa Transfers & Excursions – offering professional, knowledgeable, and experienced guides. With vehicles based in the Hoedspruit, Hazyview and White River, all major airports, game lodges, hotels and attractions throughout the region are easily accessible. All vehicles carry the necessary transport permits and are covered by comprehensive passenger liability insurance. Chilled bottled mineral water is provided on all transfers and tours.
Air Transfers
Kruger Mpumalanga Airport is ± 50km from Perry's Bridge Hollow (depending on traffic a 45 minutes to an hour transfer by road). Seasons in Africa Transfers & Excursions offer safe and reliable transfers to Perry's Bridge Hollow from the airport. Currently Airlink operate daily scheduled flights into Kruger Mpumalanga International Airport from Johannesburg, Durban and Cape Town.
www.flyairlink.com


Rent Villa Lucca Tuscany, Tuscan farmhouse with panoramic pool - Beautiful Tuscan villa in a panoramic position on the hills of Lucca.
The villa is surrounded by 3 acres of green fields and olive groves.
Guests dispose of a beautiful private area with pool and hot jacuzzi for 5 people, private swimming pool of 14 x 6,5 mt.
The Villa is on two levels and is equipped with 6 bedrooms and 4 bathrooms for a total of 10 beds.
The interiors and tastefully furnished giving our guests warmth and familiarity creating an atmosphere of pleasant intimacy.


text:
A komplex analízisben egy függvény lényeges szingularitása egy erős szingularitás, azaz olyan hely, aminek közelében a függvény furcsán viselkedik. A viselkedést analitikus esetben a nagy Picard-tétel írja le. A szingularitások harmadik fajtája a megszüntethető szingularitás és a pólus mellett.

Formális leírás

Legyen  U a  C nyílt részhalmaza, és a az U egy eleme, továbbá f : U \ {a} → C holomorf függvény. Az a pont lényeges szingularitása az f függvénynek, ha szingularitása, de nem megszüntethető és nem is pólus.

Például az  f(z) = e1/z függvénynek lényeges szingularitása van a z = 0 helyen.

Alternatív megfogalmazás
A következőkben a komplex szám, és az f(z) függvény nem értelmezhető a-ban, de egy U környezetében igen; továbbá a minden környezetének nem üres a metszete U-val.

Ha a :    és     határértékek egyike sem létezik, akkor a szingularitás lényeges.

Holomorf esetben a lényeges szingularitás környékén a Casorati–Weierstrass-tétel és a nagy Picard-tétel szerint viselkedik. Ezek azt mondják ki, hogy a lényeges szingularitás minden környezetében legfeljebb egy kivétellel minden érték fel van véve, mégpedig végtelenszer.

A lényeges szingularitás jellemzője, hogy  a szingularitás körüli Laurent-sornak végtelen sok negatív fokú tagja van, azaz a lényegi rész végtelen sok tagból áll. Egy kapcsolódó definíció szerint ha van egy  pont, ahol az  egyik deriváltja sem konvergál egy határértékhez, ha   tart -hoz, akkor  lényeges szingularitása az  függvénynek.

Jegyzetek

Források
Lars V. Ahlfors; Complex Analysis, McGraw-Hill, 1979
Rajendra Kumar Jain, S. R. K. Iyengar; Advanced Engineering Mathematics. Page 920. Alpha Science International, Limited, 2004.

Fordítás

Komplex analízis

redpajama_set_name: RedPajamaWikipedia


Confidence doesn't guarantee success, and success doesn't guarantee happiness. Why? As long as we identify ourselves with the impure mind and the selfish ego, we will still be affected by ignorance and impurities in our mind, affected by craving and aversion coming from the ego, then no matter how successful we can be, we will still be in miseries, full of fear and worries, anger and hatred, pride and arrogance, dissatisfaction and disappointment. There is no peace. How can there be happiness?
There is nothing wrong to put some make up on the face or the body, or to wear certain style of clothing, or decorate the face and body with some accessories and ornaments.
Just know that all these qualities of names and forms that we apply onto the face and body, are just some appearances with certain style of image that we try to apply onto this physical body and telling ourselves and the world, "Hey! This is me…", but it doesn't determine us for who we really are.
We can allow our ego to enjoy itself by changing the physical appearance through changing how we look and what we wear, but without attaching to the ego to identify as who we are, nor allowing the ego to determine whether we will be happy or not, as confidence, thinking and feelings are "products" derived from the ego attaching to the qualities of names and forms to think and feel good or not. But know that this is just the function of the ego. It is not who we really are.
We are who we are. We are not the ego. The ego is not us.
The ego needs to look good to feel good. The ego needs to be successful to be confident. Our true nature doesn't need to look good to feel good. Our true nature doesn't need to be successful to be confident. It is always peaceful and truthful as it is. It doesn't need to be confident, to think positive, or to feel good.
If we attached to the ego, or identifying with the ego as us, then we will believe or think that we need to depend or rely on how we look, or what we wear, or what we can do and attain, to be confident, to feel good and be happy about ourselves and our life, and we don't know the unconditional true confidence which is not coming from the physical appearance, physical condition and physical ability, nor determine by how the mind feels whether it is positive or negative feelings. That real confidence is our true nature being aware of the truth of things as they are, and not being determined by all the impermanent changing qualities of names and forms, nor being determined or influenced by the impurities that are arising and passing away in the mind.
The conditional confidence that comes from physical condition, ability and appearance, and which is influenced by the state of mind as well as achievements or success that we could attain in life, is impermanent. It is forever fluctuating and will fade away eventually. It is not real.
How can we hang on to something that is not permanent, not real, to be "somebody" who we identify as who we are, or what we like us to be?
It is only when we are not attached to all these impermanent qualities of the condition and ability of the physical body and its appearance, stop identifying with the ego, stop identifying with the qualities of names and forms, then our whole being will be naturally "confident" as it is, which is unchanging or unmovable. We don't need anything nor do something to give us confidence. There is nothing can take away this unconditional confidence which is our true nature, because it is the truth, being free form ignorance, doubts or any impurities, uncontaminated by the qualities of names and forms.
We don't need to be "pretty", or "beautiful", or "slim and fit", or "strong and flexible", or "successful", or "famous and influential", or "in good health", or "in good relationships", or be "positive", or be "happy", or be anything that we relate to what we think "confidence" comes from.


text: Example to try branching

redpajama_set_name: RedPajamaGithub


A comedian posted a video of herself holding the head of an old elephant. People tweeted this was "Inappropriate", "Disgusting", "Upsetting", and "Dumb". But two head-hunting sons of a tycoon asked if they could mount the head. This just in! Our reporter's tweet was modified by spell-check.
During the unveiling, the boys cried out "Covfefe!"


text:
// Copyright © 2012 onwards, Andrew Whewell
// All rights reserved.
//
// Redistribution and use of this software in source and binary forms, with or without modification, are permitted provided that the following conditions are met:
//    * Redistributions of source code must retain the above copyright notice, this list of conditions and the following disclaimer.
//    * Redistributions in binary form must reproduce the above copyright notice, this list of conditions and the following disclaimer in the documentation and/or other materials provided with the distribution.
//    * Neither the name of the author nor the names of the program's contributors may be used to endorse or promote products derived from this software without specific prior written permission.
//
// THIS SOFTWARE IS PROVIDED BY THE COPYRIGHT HOLDERS AND CONTRIBUTORS "AS IS" AND ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE ARE DISCLAIMED. IN NO EVENT SHALL THE AUTHORS OF THE SOFTWARE BE LIABLE FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL DAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION) HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF SUCH DAMAGE.

using System;
using System.Text;
using System.Collections.Generic;
using System.Linq;
using Microsoft.VisualStudio.TestTools.UnitTesting;
using VirtualRadar.Interface;
using InterfaceFactory;
using System.IO;

namespace Test.VirtualRadar.Library
{
    [TestClass]
    public class BitStreamTests
    {
        #region TestContext, fields, TestInitialise etc.
        public TestContext TestContext { get; set; }

        private IBitStream _BitStream;

        [TestInitialize]
        public void TestInitialise()
        {
            _BitStream = Factory.Singleton.Resolve<IBitStream>();
        }

        private byte[] ParseBinary(string binary)
        {
            List<byte> result = new List<byte>();

            int bit = 7;
            byte b = 0;

            foreach(char ch in binary) {
                if(ch == '0') --bit;
                else if(ch == '1') b += (byte)(1 << bit--);
                if(bit == -1) {
                    result.Add(b);
                    bit = 7;
                    b = 0;
                }
            }

            if(bit != 7) result.Add(b);

            return result.ToArray();
        }
        #endregion

        #region LengthRemaining
        [TestMethod]
        public void BitStream_LengthRemaining_Returns_Zero_If_Called_Before_Initialise()
        {
            Assert.AreEqual(0, _BitStream.LengthRemaining);
        }

        [TestMethod]
        public void BitStream_LengthRemaining_Returns_Zero_If_Called_After_Stream_Has_Been_Depleted()
        {
            _BitStream.Initialise(new byte[] { 0x0f });
            _BitStream.ReadByte(8);
            Assert.AreEqual(0, _BitStream.LengthRemaining);
        }
        #endregion

        #region Initialise
        [TestMethod]
        [ExpectedException(typeof(ArgumentNullException))]
        public void BitStream_Initialise_Throws_If_Passed_Null()
        {
            _BitStream.Initialise(null);
        }

        [TestMethod]
        public void BitStream_Initialise_Does_Not_Throw_If_Passed_Empty_Array()
        {
            _BitStream.Initialise(new byte[] {});
        }

        [TestMethod]
        public void BitStream_Initialise_Resets_The_Stream()
        {
            _BitStream.Initialise(new byte[] { 0x00, 0x00 });
            for(int i = 0;i < 16;++i) {
                Assert.AreEqual(16 - i, _BitStream.LengthRemaining);
                Assert.IsFalse(_BitStream.ReadBit());
            }

            _BitStream.Initialise(new byte[] { 0xff, 0xff });
            for(int i = 0;i < 16;++i) {
                Assert.AreEqual(16 - i, _BitStream.LengthRemaining);
                Assert.IsTrue(_BitStream.ReadBit());
            }
        }
        #endregion

        #region ReadBit
        [TestMethod]
        public void BitStream_ReadBit_Returns_Correct_Values()
        {
            var binary = "00110100 11001011";
            _BitStream.Initialise(ParseBinary(binary));

            int posn = 0;
            foreach(char ch in binary) {
                if(ch != '0' && ch != '1') continue;
                var bit = _BitStream.ReadBit();
                if(ch == '0') Assert.IsFalse(bit, "Expected false at bit {0}, ReadBit returned true", posn);
                else          Assert.IsTrue(bit, "Expected true at bit {0}, ReadBit returned false", posn);
                ++posn;
            }
        }

        [TestMethod]
        [ExpectedException(typeof(EndOfStreamException))]
        public void BitStream_ReadBit_Throws_Exception_If_Reading_Past_End_Of_Stream()
        {
            _BitStream.Initialise(new byte[] {});
            _BitStream.ReadBit();
        }

        [TestMethod]
        public void BitStream_ReadBit_Updates_LengthRemaining()
        {
            _BitStream.Initialise(new byte[] { 0x00, 0x00 });
            for(var i = 16;i > 0;--i) {
                Assert.AreEqual(i, _BitStream.LengthRemaining);
                _BitStream.ReadBit();
                Assert.AreEqual(i - 1, _BitStream.LengthRemaining);
            }
        }
        #endregion

        #region Skip
        [TestMethod]
        public void BitStream_Skip_Jumps_Over_Bits_In_The_Stream()
        {
            var binary = "11001010001101011101001111110000";
            for(int i = 0;i < binary.Length;++i) {
                var expectedBit = binary[i] == '1';

                _BitStream.Initialise(ParseBinary(binary));
                _BitStream.Skip(i);

                Assert.AreEqual(expectedBit, _BitStream.ReadBit(), "Expected {0} after skipping {1} bits, ReadBit returned {2}", expectedBit, i, !expectedBit);
            }
        }

        [TestMethod]
        [ExpectedException(typeof(EndOfStreamException))]
        public void BitStream_Skip_Throws_If_Moved_Past_End_Of_Stream()
        {
            _BitStream.Initialise(new byte[] { 0x00 });
            _BitStream.Skip(9);
        }

        [TestMethod]
        [ExpectedException(typeof(EndOfStreamException))]
        public void BitStream_Skip_Throws_If_Moved_Past_Start_Of_Stream()
        {
            _BitStream.Initialise(new byte[] { 0x00 });
            _BitStream.Skip(-1);
        }

        [TestMethod]
        public void BitStream_Skip_Does_Not_Throw_If_Skipped_To_End_Of_Stream()
        {
            _BitStream.Initialise(new byte[] { 0x00 });
            _BitStream.Skip(8);
        }

        [TestMethod]
        public void BitStream_Skip_Can_Move_Backwards_Through_Stream()
        {
            _BitStream.Initialise(new byte[] { 0x0C }); // 00001100
            _BitStream.Skip(4);
            _BitStream.ReadByte(2);
            _BitStream.Skip(-2);
            Assert.AreEqual((byte)3, _BitStream.ReadByte(2));
        }

        [TestMethod]
        public void BitStream_Skip_Can_Move_Backwards_Over_Byte_Boundaries()
        {
            _BitStream.Initialise(new byte[] { 0x03, 0xC0 }); // 00000011 11000000
            _BitStream.Skip(6);
            _BitStream.ReadByte(4);
            _BitStream.Skip(-4);
            Assert.AreEqual((byte)0x0f, _BitStream.ReadByte(4));
        }

        [TestMethod]
        public void BitStream_Skip_Can_Jump_Backwards_Over_Bits_In_The_Stream()
        {
            var binary = "11001010001101011101001111110000";
            for(int i = 0;i < binary.Length;++i) {
                int index = (binary.Length - 1) - i;
                int skipBackwardsFromEnd = 0 - (i + 1);

                var expectedBit = binary[index] == '1';

                _BitStream.Initialise(ParseBinary(binary));
                _BitStream.Skip(binary.Length);
                _BitStream.Skip(skipBackwardsFromEnd);

                Assert.AreEqual(expectedBit, _BitStream.ReadBit(), "Expected {0} after skipping {1} bits from end, ReadBit returned {2}", expectedBit, skipBackwardsFromEnd, !expectedBit);
            }
        }
        #endregion

        #region ReadByte
        [TestMethod]
        public void BitStream_ReadByte_Throws_If_Reading_Less_Than_One_Or_More_Than_8_Bits()
        {
            for(int i = -2;i < 10;++i) {
                _BitStream.Initialise(new byte[] { 0x00 });

                bool expectException = i < 1 || i > 8;
                bool sawException = false;
                try {
                    _BitStream.ReadByte(i);
                } catch(ArgumentOutOfRangeException) {
                    sawException = true;
                }

                Assert.AreEqual(expectException, sawException, "ReadByte did not behave correctly when asked to read {0} bits", i);
            }
        }

        [TestMethod]
        public void BitStream_ReadByte_Can_Read_A_Simple_8_Bit_Value()
        {
            _BitStream.Initialise(new byte[] { 0x00, 0xff });
            Assert.AreEqual(0x00, _BitStream.ReadByte(8));
            Assert.AreEqual(0xff, _BitStream.ReadByte(8));
        }

        [TestMethod]
        public void BitStream_ReadByte_Can_Read_Partial_Bytes_That_Straddle_Byte_Boundaries()
        {
            var binary = "00110101 11001010".Replace(" ", "");

            for(int bits = 1;bits <= 8;++bits) {
                for(int startPosition = 0;startPosition < binary.Length - bits;++startPosition) {
                    var expectedBinary = String.Format("{0}{1}", new String('0', 8 - bits), binary.Substring(startPosition, bits));
                    var expectedValue = ParseBinary(expectedBinary)[0];

                    _BitStream.Initialise(ParseBinary(binary));
                    _BitStream.Skip(startPosition);
                    var actualValue = _BitStream.ReadByte(bits);
                    Assert.AreEqual(expectedValue, actualValue, "Expected the value 0x{0:X} ({1}) when reading {2} bits starting at {3} - ReadByte returned 0x{4:X}", expectedValue, expectedBinary, bits, startPosition, actualValue);
                }
            }
        }

        [TestMethod]
        [ExpectedException(typeof(EndOfStreamException))]
        public void BitStream_ReadByte_Throws_Exception_When_Reading_Past_End_Of_Stream()
        {
            _BitStream.Initialise(new byte[] {});
            _BitStream.ReadByte(8);
        }

        [TestMethod]
        [ExpectedException(typeof(EndOfStreamException))]
        public void BitStream_ReadByte_Throws_Exception_When_Reading_Past_End_Of_Stream_Over_Byte_Boundary()
        {
            _BitStream.Initialise(new byte[] { 0xff });
            _BitStream.Skip(6);
            _BitStream.ReadByte(4);
        }
        #endregion

        #region ReadUInt16
        [TestMethod]
        public void BitStream_ReadUInt16_Throws_If_Reading_Less_Than_One_Or_More_Than_16_Bits()
        {
            for(int i = -2;i < 18;++i) {
                _BitStream.Initialise(new byte[] { 0x00, 0x00 });

                bool expectException = i < 1 || i > 16;
                bool sawException = false;
                try {
                    _BitStream.ReadUInt16(i);
                } catch(ArgumentOutOfRangeException) {
                    sawException = true;
                }

                Assert.AreEqual(expectException, sawException, "ReadUInt16 did not behave correctly when asked to read {0} bits", i);
            }
        }

        [TestMethod]
        public void BitStream_ReadUInt16_Can_Read_A_Simple_16_Bit_Value()
        {
            _BitStream.Initialise(new byte[] { 0xff, 0x00, 0x00, 0xff });
            Assert.AreEqual(0xff00, _BitStream.ReadUInt16(16));
            Assert.AreEqual(0x00ff, _BitStream.ReadUInt16(16));
        }

        [TestMethod]
        public void BitStream_ReadUInt16_Can_Read_Partial_Words_That_Straddle_Byte_Boundaries()
        {
            var binary = "00110101 11001010 10101010 01010101".Replace(" ", "");

            for(int bits = 1;bits <= 16;++bits) {
                for(int startPosition = 0;startPosition < binary.Length - bits;++startPosition) {
                    var expectedBinary = ParseBinary(String.Format("{0}{1}", new String('0', 16 - bits), binary.Substring(startPosition, bits)));
                    var expectedValue = (ushort)((expectedBinary[0] << 8) | expectedBinary[1]);

                    _BitStream.Initialise(ParseBinary(binary));
                    _BitStream.Skip(startPosition);
                    var actualValue = _BitStream.ReadUInt16(bits);
                    Assert.AreEqual(expectedValue, actualValue, "Expected the value 0x{0:X} ({1}) when reading {2} bits starting at {3} - ReadUInt16 returned 0x{4:X}", expectedValue, expectedBinary, bits, startPosition, actualValue);
                }
            }
        }

        [TestMethod]
        public void BitStream_ReadUInt16_Throws_Exception_When_Reading_Past_End_Of_Stream()
        {
            for(int i = 0;i < 2;++i) {
                _BitStream.Initialise(new byte[i]);
                bool seenException = false;
                try {
                    _BitStream.ReadUInt16(16);
                } catch(EndOfStreamException) {
                    seenException = true;
                }
                Assert.IsTrue(seenException);
            }
        }

        [TestMethod]
        [ExpectedException(typeof(EndOfStreamException))]
        public void BitStream_ReadUInt16_Throws_Exception_When_Reading_Past_End_Of_Stream_Over_Byte_Boundary()
        {
            _BitStream.Initialise(new byte[] { 0xff, 0xff });
            _BitStream.Skip(6);
            _BitStream.ReadUInt16(11);
        }
        #endregion

        #region ReadUInt32
        [TestMethod]
        public void BitStream_ReadUInt32_Throws_If_Reading_Less_Than_One_Or_More_Than_32_Bits()
        {
            for(int i = -2;i < 34;++i) {
                _BitStream.Initialise(new byte[] { 0x00, 0x00, 0x00, 0x00 });

                bool expectException = i < 1 || i > 32;
                bool sawException = false;
                try {
                    _BitStream.ReadUInt32(i);
                } catch(ArgumentOutOfRangeException) {
                    sawException = true;
                }

                Assert.AreEqual(expectException, sawException, "ReadUInt32 did not behave correctly when asked to read {0} bits", i);
            }
        }

        [TestMethod]
        public void BitStream_ReadUInt32_Can_Read_A_Simple_32_Bit_Value()
        {
            _BitStream.Initialise(new byte[] { 0xff, 0x01, 0x02, 0x03, 0x03, 0x02, 0x01, 0xff });
            Assert.AreEqual(0xff010203U, _BitStream.ReadUInt32(32));
            Assert.AreEqual(0x030201ffU, _BitStream.ReadUInt32(32));
        }

        [TestMethod]
        public void BitStream_ReadUInt32_Can_Read_Partial_Double_Words_That_Straddle_Byte_Boundaries()
        {
            var binary = "00110101 11001010 10101010 01010101 11110000 00001111 11000011 00111100".Replace(" ", "");

            for(int bits = 1;bits <= 32;++bits) {
                for(int startPosition = 0;startPosition < binary.Length - bits;++startPosition) {
                    var expectedBinary = ParseBinary(String.Format("{0}{1}", new String('0', 32 - bits), binary.Substring(startPosition, bits)));
                    var expectedValue = (uint)((expectedBinary[0] << 24) | expectedBinary[1] << 16 | expectedBinary[2] << 8 | expectedBinary[3]);

                    _BitStream.Initialise(ParseBinary(binary));
                    _BitStream.Skip(startPosition);
                    var actualValue = _BitStream.ReadUInt32(bits);
                    Assert.AreEqual(expectedValue, actualValue, "Expected the value 0x{0:X} ({1}) when reading {2} bits starting at {3} - ReadUInt32 returned 0x{4:X}", expectedValue, expectedBinary, bits, startPosition, actualValue);
                }
            }
        }

        [TestMethod]
        public void BitStream_ReadUInt32_Throws_Exception_When_Reading_Past_End_Of_Stream()
        {
            for(int i = 0;i < 4;++i) {
                _BitStream.Initialise(new byte[i]);
                bool seenException = false;
                try {
                    _BitStream.ReadUInt32(32);
                } catch(EndOfStreamException) {
                    seenException = true;
                }
                Assert.IsTrue(seenException);
            }
        }

        [TestMethod]
        [ExpectedException(typeof(EndOfStreamException))]
        public void BitStream_ReadUInt32_Throws_Exception_When_Reading_Past_End_Of_Stream_Over_Byte_Boundary()
        {
            _BitStream.Initialise(new byte[] { 0xff, 0xff, 0xff, 0xff });
            _BitStream.Skip(6);
            _BitStream.ReadUInt32(27);
        }
        #endregion

        #region ReadUInt64
        [TestMethod]
        public void BitStream_ReadUInt64_Throws_If_Reading_Less_Than_One_Or_More_Than_64_Bits()
        {
            for(int i = -2;i < 66;++i) {
                _BitStream.Initialise(new byte[] { 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00 });

                bool expectException = i < 1 || i > 64;
                bool sawException = false;
                try {
                    _BitStream.ReadUInt64(i);
                } catch(ArgumentOutOfRangeException) {
                    sawException = true;
                }

                Assert.AreEqual(expectException, sawException, "ReadUInt64 did not behave correctly when asked to read {0} bits", i);
            }
        }

        [TestMethod]
        public void BitStream_ReadUInt64_Can_Read_A_Simple_64_Bit_Value()
        {
            _BitStream.Initialise(new byte[] { 0xff, 0xfe, 0xfd, 0xfc, 0xfb, 0xfa, 0xf9, 0xf8,
                                               0x01, 0x02, 0x03, 0x04, 0x05, 0x06, 0x07, 0x08 });
            var value1 = _BitStream.ReadUInt64(64);
            var value2 = _BitStream.ReadUInt64(64);
            Assert.AreEqual(0xfffefdfcfbfaf9f8UL, value1, "Expected {0:X}, actual {1:X}", 0xfffefdfcfbfaf9f8UL, value1);
            Assert.AreEqual(0x0102030405060708UL, value2, "Expected {0:X}, actual {1:X}", 0x0102030405060708UL, value2);
        }

        [TestMethod]
        public void BitStream_ReadUInt64_Can_Read_Partial_Quad_Words_That_Straddle_Byte_Boundaries()
        {
            var binary = ("00110101 11001010 10101010 01010101 11110000 00001111 11000011 00111100" +
                          "11111111 00000000 10111101 01000010 11011011 00100100 11101110 00010001").Replace(" ", "");

            for(int bits = 1;bits <= 64;++bits) {
                for(int startPosition = 0;startPosition < binary.Length - bits;++startPosition) {
                    var expectedBinary = ParseBinary(String.Format("{0}{1}", new String('0', 64 - bits), binary.Substring(startPosition, bits)));
                    var expectedValue = (ulong)expectedBinary[0] << 56 | (ulong)expectedBinary[1] << 48 | (ulong)expectedBinary[2] << 40 | (ulong)expectedBinary[3] << 32 |
                                        (ulong)expectedBinary[4] << 24 | (ulong)expectedBinary[5] << 16 | (ulong)expectedBinary[6] << 8  | (ulong)expectedBinary[7];

                    _BitStream.Initialise(ParseBinary(binary));
                    _BitStream.Skip(startPosition);
                    var actualValue = _BitStream.ReadUInt64(bits);
                    Assert.AreEqual(expectedValue, actualValue, "Expected the value 0x{0:X} ({1}) when reading {2} bits starting at {3} - ReadUInt64 returned 0x{4:X}", expectedValue, expectedBinary, bits, startPosition, actualValue);
                }
            }
        }

        [TestMethod]
        public void BitStream_ReadUInt64_Throws_Exception_When_Reading_Past_End_Of_Stream()
        {
            for(int i = 0;i < 8;++i) {
                _BitStream.Initialise(new byte[i]);
                bool seenException = false;
                try {
                    _BitStream.ReadUInt64(64);
                } catch(EndOfStreamException) {
                    seenException = true;
                }
                Assert.IsTrue(seenException);
            }
        }

        [TestMethod]
        [ExpectedException(typeof(EndOfStreamException))]
        public void BitStream_ReadUInt64_Throws_Exception_When_Reading_Past_End_Of_Stream_Over_Byte_Boundary()
        {
            _BitStream.Initialise(new byte[] { 0xff, 0xff, 0xff, 0xff, 0xff, 0xff, 0xff, 0xff });
            _BitStream.Skip(6);
            _BitStream.ReadUInt64(59);
        }
        #endregion

        #region All Read Methods
        [TestMethod]
        public void BitStream_AllReadMethods_Consume_Stream()
        {
            var binary = "1" +                                                                        // true
                         "00111111" +                                                                 // 3F
                         "01010101 01010101" +                                                        // 5555
                         "11111111 00000000 11110000 00001111" +                                      // FF00F00F
                         "01111110 11111111 00110011 01010101 11001111 00110000 10101010 11000011";   // 7EFF3355CF30AAC3
            _BitStream.Initialise(ParseBinary(binary));
            Assert.IsTrue(_BitStream.ReadBit());
            Assert.AreEqual(0x3f, _BitStream.ReadByte(8));
            Assert.AreEqual(0x5555, _BitStream.ReadUInt16(16));
            Assert.AreEqual(0xFF00F00FU, _BitStream.ReadUInt32(32));
            Assert.AreEqual(0x7EFF3355CF30AAC3UL, _BitStream.ReadUInt64(64));
        }
        #endregion
    }
}


text:
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE language SYSTEM "language.dtd">
<!--

  G-code syntax highlighting for KatePart

  Copy this file to :  ~/.kde/share/apps/katepart/syntax/

  Copyright © 2016 by Fernand Veilleux (fernveilleux@gmail.com)

  This library is free software; you can redistribute it and/or
	modify it under the terms of the GNU Library General Public
	License as published by the Free Software Foundation; either
	version 2 of the License, or (at your option) any later version.

	This library is distributed in the hope that it will be useful,
	but WITHOUT ANY WARRANTY; without even the implied warranty of
	MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the GNU
	Library General Public License for more details.

	You should have received a copy of the GNU Library General Public
	License along with this library; if not, write to the
	Free Software Foundation, Inc., 51 Franklin Street, Fifth Floor,
	Boston, MA  02110-1301, USA.

-->
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text:
IOJT Newsletter
Member of IAAJS
International Law Associations
Judicial Affairs of Tufts University
Internationalization of Law network
School of Advanced International Studies
UCL Judicial Institute
History of Legal system of Saudi Arabia
Sources of law in Saudi Arabia
The courts and the judiciary in Saudi Arabia
Major areas of law in Saudi Arabia
Human rights and rule of law issues in Saudi Arabia
God soul
International Alliance for Advanced Judicial Studies (IAAJS)
Commercial law, also known as trade law, is the body of law that applies to the rights, relations, and conduct of persons and businesses engaged in commerce, merchandising, trade, and sales. It is often considered to be a branch of civil law and deals with issues of both private law and public law.
Commercial law includes within its compass such titles as principal and agent; carriage by land and sea; merchant shipping; guarantee; marine, fire, life, and accident insurance; bills of exchange, negotiable instruments, contracts and partnership. Many of these categories fall within Financial law, an aspected of Commercial law pertaining specifically to financing and the financial markets. It can also be understood to regulate corporate contracts, hiring practices, and the manufacture and sales of consumer goods. Many countries have adopted civil codes that contain comprehensive statements of their commercial law.
In the United States, commercial law is the province of both the United States Congress, under its power to regulate interstate commerce, and the states, under their police power. Efforts have been made to create a unified body of commercial law in the United States; the most successful of these attempts has resulted in the general adoption of the Uniform Commercial Code, which has been adopted in all 50 states (with some modification by state legislatures), the District of Columbia, and the U.S. territories.
Various regulatory schemes control how commerce is conducted, particularly vis-a-vis employees and customers. Privacy laws, safety laws (e.g., the Occupational Safety and Health Act in the United States), and food and drug laws are some examples.
Copyright й International Alliance for Advanced Judicial Studies (IAAJS) 2019. All Rights Reserved.

redpajama_set_name: RedPajamaCommonCrawl


Famous Youtube star and large media company in competition: PewDiePie against T-Series. Image courtesy of Dexerto labeled for reuse.
In the vast media universe, competition is always present.
With over 70 million subscribers on YouTube, a channel titled PewDiePie competes for social media power and influence. PewDiePie was started by a man named Felix Arvid Ulf Kjellberg. He is a video producer and has been extremely successful on the YouTube platform; he is the number one most subscribed person in the world since 2013.
Viewers' concern over PewDiePie losing his number-one spot on the Youtube charts has to do with companies' trend of overpowering self-made content producers.
Super Cassettes Industries Private Limited, better known as T-Series, is a music, video and DVD/VCD play system production company based in Noida, India. The rivalry between T-Series and Pewdiepie is the result of the T-Series obtaining over 69.4 million subscribers and coming extremely close to passing Kjellberg's channel.
According to Social Blade, subscriber and viewer count statistics suggest that T-Series is growing four times faster than PewDiePie and may eventually overtake the number one spot on YouTube.
This antipathy between the two channels has brought many responses from the YouTube community, encouraging some of the people subscribed to PewDiePie to take the situation into their own hands and support him.
A popular YouTuber, MrBeast, whose channel has over 10 million subscribers, created a trend to promote PewDiePie and negate the success of T-Series. In order to support and promote Kjellberg's channel, people in MrBeast's video bought billboards and ads in airports, on the radio and in bathrooms.
With all the support going toward PewDiePie, little has been done to defend T-Series.
JusReign is one of the few channels supporting T-Series. The owner of the channel, Jasmeet Singh, made a video defending the media content (such as movies and videos) that the company puts out.
There is a live subscriber count people can visit to see the current numbers of subscribers each channel has.


text:
Postdoctoral Fellow (Nidhi Sahni laboratory)
Employer: The University of Texas M. D. Anderson Cancer Center
The University of Texas M. D. Anderson Cancer Center
Location: Houston, TX
The University of Texas MD Anderson Cancer Center invites applications for postdoctoral fellowships in experimental cancer biology, CRISPR, and functional genetics/epigenetics starting immediately. Using state-of-the-art gene-editing and functional genomics/proteomics techniques, we seek to identify genetic and epigenetic biomarkers for human cancer precision medicine, synthetic lethal and resistance mechanisms underlying disease development, and signal transduction at the systems level.
The postdoctoral research will be performed in a highly interdisciplinary and collaborative environment with world-class experts, advanced technologies, and facilities, providing unique and ideal career development opportunities for postdocs. Successful candidates will be supervised by Dr. Nidhi Sahni, a faculty member and recognized leader in cancer genetics and systems biology at MD Anderson Cancer Center. Dr. Sahni has received numerous prestigious awards and strong funding support, including AACR NextGen Star, Sloan Scholar Award, CPRIT Scholar Award, NIH Outstanding Investigator Award (MIRA), DoD grant, Pinnacle Research Award, and Rising STARs Award, among others.
Recent representative publications include Cancer Cell (2020), 37: 371-86; Cell (2015), 161: 647-60; Nature Rev Genet (2017), 18: 395-410; Cancer Cell (2018), 33: 450-462; Cell (2015), 161: 661-73; Cell (2017), 168: 856-66; Nature Commun. (2018), 9: 1317. For more information, please visit https://faculty.mdanderson.org/profiles/nidhi_sahni.html
The trainee will learn how to execute and design high throughput screens using CRISPR-Cas9, reporter assays, single-cell technologies, and Perturb Seq assys combing CRISPR with sc-RNA/sc-ATAC. The trainee will participate in collaborative projects and present findings at a prestigious national/international conference.
Applicants should have a recent Ph.D. degree (or equivalent) in molecular biology, cancer biology, genetics/epigenetics, immunology, or relevant fields. We are interested in passionate and self-motivated candidates who ask fundamentally important questions and are bold in taking innovative approaches. Candidates should have previous expertise with tissue culture. Experience with high-throughput biology, CRISPR screens, and next-generation sequencing is a plus.
It is the policy of The University of Texas MD Anderson Cancer Center to provide equal employment opportunity without regard to race, color, religion, age, national origin, sex, gender, sexual orientation, gender identity/expression, disability, protected veteran status, genetic information, or any other basis protected by institutional policy or by federal, state or local laws unless such distinction is required by law. http://www.mdanderson.org/about-us/legal-and-policy/legal-statements/eeo-affirmative-action.html


Coming Down the Stretch: Who's out of the West Playoffs?
Things have gotten a whole lot tighter in the bottom half of the Western Conference, and two weeks from now, somebody between the Dallas Mavericks, Golden State Warriors and Denver Nuggets will be spending the second half of their April at home.
Before we dive into the final stretch of the regular season, let's stop to genuflect just how competitive, exciting and talented this Western Conference has been.
Unlike the junior-varsity Eastern Conference – where teams double-digit games under .500 may get in the playoffs – who gets the seventh and eighth spots in the West has a big affect on the playoff picture. Nothing that can happen in the first round of the West playoffs will surprise me because the conference is so good from top to bottom.
In the NBA Playoffs, it's all about match-ups.
Warriors team that simply knew how to play them.
After Sunday's games, there is a three-way tie between the Mavericks, Nuggets and Warriors (all at 45-28) for the seventh seed of the West with nine games left.
The Mavericks are probably the most talented of the three teams, but they'll have the toughest road down the stretch.
What makes it toughest, obviously, is the status of Dirk Nowitzki's ankle – his knee is hurt, too, but that's no big deal. This isn't Andrew Bynum or Tony Parker missing time. This is the reigning MVP and the guy who the Mavs run their entire offense for. He's returning this week and is obviously being rushed back, and how he responds is going to make or break Dallas.
But it's not even Dirk.
The entire Mavs offense got a facelift when Jason Kidd came over from New Jersey, and Dallas – more than anyone – needed time to adapt to one another.
You can throw that out the window.
But of the three teams, the Mavericks are good at doing two things championship teams do: play defense (sixth in the NBA in opponent points per game and fourth in opponent field-goal percentage) and shoot free throws (first in free-throw percentage).
Of Dallas' nine games remaining, five will be on the road and six will be against plus-.500 teams.
The Nuggets looked like the odd team out for a while, but they've been rolling of late, winning five straight games and eight of their last 10.
Denver plays no defense whatsoever (26th in opponents' points per game) but they generate a lot of turnovers (first in steals per game) and can score with the best of them.
Their inability to run a halfcourt defensive set won't allow them to make any sort of run in the playoffs, but Allen Iverson and Carmelo Anthony should be good enough to carry the Nuggets for the last two weeks of the season.
Denver finishes with five games on the road and five games against plus-.500 teams (the easiest schedule of the three).
My question is this: At what point do we say A.I. is just not as good as hyped up to be? A lot of people list him as one of the top 10 shooting guards of all time, but he has one of the best players in the NBA right next to him (not to mention a pretty good supporting cast of Marcus Camby and Kenyon Martin), and he barely has his team in the playoffs.
This would be my pick for odd team out.
The Warriors are statistically the worst defensive team and the best offensive team in the NBA. But over a stretch of two weeks, I'll take an offense with 'Melo and A.I. over Baron Davis and Stephen Jackson.
As sad as this may sound, the Warriors were counting on significant contributions from recently retired Chris Webber because of their lack of depth in the front line. As of late, 6-foot-5, 220-pounder Kelenna Azubuike has been seeing a lot of minutes at center.


text:
Guaraná (Paullinia cupana) ist eine Pflanzenart innerhalb der Familie der Seifenbaumgewächse (Sapindaceae). Sie ist im Amazonasbecken beheimatet. Der Name Guaraná bezieht sich auf das südamerikanische indigene Volk der Guaraní. Sie besitzt eine lange ethnobotanische Tradition und ihre coffeinhaltigen Samen werden häufig als Nahrungsergänzungsmittel und Zusatz in Getränken verwendet.

Beschreibung

Erscheinungsbild und Rinde
Guaraná ist eine immergrüne, verholzende Pflanze; sie wächst als rankender, bis 2–3 Meter hoher Strauch oder als Liane, die an den tropischen Naturstandorten Wuchshöhen von bis zu 12 Meter erreichen kann. Die Rinde ist anfangs bräunlich weich behaart und verkahlt bald. Nur bei Paullinia cupana var. sorbilis sind achselständige Ranken vorhanden.

Blatt
Die wechselständig angeordneten Laubblätter sind 20 bis 35 Zentimeter lang und in Blattstiel sowie -spreite gegliedert. Der bis 15 Zentimeter lange Blattstiel und die Blattrhachis sind oben rinnenförmig, konvex und dazwischen etwas gestreift. Die unpaarig gefiederte Blattspreite enthält fünf oder mehr, ledrige und fast kahle, 10 bis 25 cm lange sowie 4,5 bis 10 cm breite, kurz gestielte bis sitzende Blättchen. Die spitzen bis zuspitzten Blättchen sind eiförmig bis elliptisch, die Basis ist gestutzt bis keilförmig und teils kurz herablaufend. Der Blättchenrand ist mehr oder weniger grob gesägt, gekerbt oder gezähnt. Die kleinen Nebenblätter sind 2 bis 3 Millimeter lang.

Blütenstand und Blüte
Guaraná ist einhäusig gemischtgeschlechtig (monözisch). Jeweils wenige Blüten stehen in achsel-, endständigen oder an den Ranken initiierten, thyrsig-traubigen und gemischten Blütenständen zusammen. Es kann ein Blütenstandsschaft vorhanden sein. Die Blütenstandsachse (Rhachis) besitzt einen Durchmesser von etwa 2 mm. Die Tragblätter sind bei einer Länge von 1 bis 1,5 mm pfriemlich. Die 4 bis 5 mm langen Blütenstiele sind unterhalb ihrer Mitte "gegliedert".

Die relativ kleinen, funktionell eingeschlechtigen, kurz gestielten, duftenden Blüten sind zygomorph und vier- bis fünfzählig mit doppelter Blütenhülle. Die 5 freien, etwas ungleichen und feinhaarigen Kelchblätter sind bis 4 mm lang. Die 4 weißen Kronblätter, mit innen einem Anhängsel, einer Schuppe, sind bei einer Länge von etwa 5 mm länglich. Die männlichen Blüten besitzen acht kurze, ungleich lange Staubblätter mit weich behaarten Staubfäden und kahlen Staubbeuteln sowie einen stark reduzierten Pistillode. Die weiblichen Blüten besitzen einen kahlen, oberständigen und dreikammerigen Fruchtknoten mit kurzem Griffel und dreilappiger Narbe sowie kürzere, behaarte Staminodien mit Antheroden. Es ist jeweils ein gelappter Nektardiskus vorhanden.

Frucht und Samen
Die bei Fruchtreife 6 bis 8 mm lang gestielte, septizid-septifrage, 2 bis 3,5 cm lange, tief eingeschnittene, dreifächerige Kapselfrucht färbt sich bei Reife orangerot, öffnet sich teilweise und enthält nur ein bis drei Samen. Die etwa 12 mm langen, kahlen, schwarzen bis grünlichen Samen besitzen an ihrer Basis eine weiße Sarkotesta. Die aufgesprungene Frucht mit ihrem Samen darin wirkt wie ein Auge, daran knüpfen sich Legenden der indigenen Völker.

Ökologie
Es liegt Fremdbestäubung (Allogamie) vor und die Bestäubung erfolgt durch Bienen der Gattungen Melipona sowie Apis.

Die Samen werden auf natürliche Weise durch große Vögel ausgebreitet. Die Samen verlieren normalerweise bereits nach drei Tagen ihre Keimfähigkeit und überstehen Austrocknung oder Frost nicht. Die Keimdauer kann über 100 Tage betragen.

Systematik und Verbreitung
Die Erstbeschreibung von Paullinia cupana erfolgte 1821 durch Karl Sigismund Kunth in Alexander von Humboldt, Aimé Bonpland und Karl Sigismund Kunth: Nova Genera et Species Plantarum, 4. Auflage, Band 5, S. 117–118. Das von Humboldt und Bonpland gesammelte Typusmaterial trägt die Aufschrift: "Crescit in ripa obumbrata fluminis Orinoci, prope S. Fernando de Atabàpo. Floret Majo".

Es gibt von Paullinia cupana  zwei Varietäten:
 Paullinia cupana  var. cupana: Sie kommt in Venezuela, Brasilien (besonders in Manaus und Parintins) und Peru vor.
 Paullinia cupana var. sorbilis  (Syn.: Paullinia sorbilis ): Sie kommt nur in Peru vor.

Paullinia cupana var. cupana besitzt im Gegensatz zu Paullinia cupana var. sorbilis keine Ranken, die Laubblätter sind stärker gelappt und die Blüten sowie Früchte sind größer.

Nutzung

Guaraná ist den Indios im Amazonasgebiet schon seit Jahrhunderten bekannt. Ähnlich Kakao/Schokolade wurde die Guaraná-Paste verwendet. Sie wurde vielfältig in der Volksmedizin verwendet.

Guaraná wird als Kletterpflanze in Plantagen in Brasilien, Venezuela und Paraguay angebaut. Die Nachzucht aus Samen ist schwierig.

Die geschälten und getrockneten Samen werden zu einem hellbraunen Pulver zermahlen, in Wasser aufgeschwemmt und mit Honig gesüßt getrunken. Das Getränk wirkt ähnlich wie Kaffee anregend und dämpft Hungergefühle.

Aus Guaranáextrakten wird von vielen brasilianischen Getränkeherstellern (unter anderem Antarctica, Brahma, Kicos, Kuat) ein für Brasilien typisches limonadeähnliches Erfrischungsgetränk hergestellt, welches homonym als Guaraná bezeichnet wird.

Verbreitung finden auch Schokolade, Kräuter- und Früchtetees, Kaugummi, Energy-Drinks sowie Gleitgele mit Guaranáanteil. Die Substanz ist aber auch separat als Nahrungsergänzungsmittel erhältlich. Der Anteil der Gerbstoffe liegt bei etwa 25 Prozent, was die Wirkung des enthaltenen Coffeins verzögert und verlängert. Die Produkte werden als "Wachmacher" und "Energiespender" beworben. Außerdem gelten Guaraná-Produkte in Fitnesskreisen und bei Bodybuildern als leistungsfördernd.

Guaraná hat einen äußerst herben bis sehr bitteren Geschmack, weshalb es meist nicht pur konsumiert, sondern verschiedenen Lebensmitteln, wie den zuvor genannten, zugesetzt wird.

Die Samen von Paullinia cupana var. sorbilis werden pulverisiert und mit Cassava-Mehl (Manihot esculenta Crantz) gemischt. Daraus stellt man die sogenannte "pasta guarana" her, die nach Belieben in heißem oder kaltem Wasser gelöst wird. Der Coffein-Gehalt der "pasta guarana" beträgt 3 bis 6 %, der Tannin-Gehalt 2 bis 3 %. Das Getränk ist adstringierend.

Inhaltsstoffe
Ihre roten Früchte mit den bitter schmeckenden Kernen zeichnen sich durch ihren hohen Coffeingehalt aus (4–8 % in der Trockenmasse).

Guaraná hat die stimulierende Wirkung des Coffeins. Fälschlicherweise wird die anregende Substanz oft auch als "Guaranin" bezeichnet; eine solche Substanz gibt es jedoch nicht.
Im Guaranáextrakt sind enthalten: Tannine (über 12 %) davon ca. 10 % Proanthocyanidine, Coffein (4–6 %), Theophyllin (0–0,25 %), Theobromin (0,02–0,04 %), (+)-Catechin (6 %), (−)-Epicatechin (3 %), Saponine, Stärke, Mineralstoffe (3–4 %) und Wasser (6–8 %).

Wirkung
Guaraná soll leicht fiebersenkend wirken und bei körperlicher Schwäche das Durchhaltevermögen stärken. Ähnlich wie Kaffee hat Guaraná eine anregende Wirkung auf das Herz-Kreislauf-System. Es dämpft ferner Hunger- und Durstgefühle, was die Gefahr einer Dehydratation bei Sportlern erhöht.

Nebenwirkungen und Risiken
Es können die gleichen Nebenwirkungen wie beim übermäßigen Genuss von Coffein aus anderen Quellen auftreten, etwa erhöhte Reizbarkeit, Schlafstörungen, Tachykardie, Kopfschmerzen, Zittern oder Muskelschmerzen. Beim Absetzen der Produkte nach längerfristigem Konsum kann es zu körperlichen Entzugserscheinungen kommen. Ungeeignet sind Guaraná-Produkte für Menschen mit Bluthochdruck und chronischen Kopfschmerzen sowie für Schwangere und in der Stillzeit.

Als Überdosierung bei Coffein gelten in der Regel sieben bis zehn Tassen Kaffee innerhalb eines kurzen Zeitraums oder 20 Gramm reines Guaranápulver. Mediziner empfehlen als Sofortmaßnahme in diesem Fall, eine größere Menge Wasser zu trinken.

Siehe auch
 Liste von Pflanzen mit psychotropen Wirkstoffen

Literatur
 Lidilhone Hamerski, Genise Vieira Somner, Neusa Tamaio: Paullinia cupana Kunth (Sapindaceae): A review of its ethnopharmacology, phytochemistry and pharmacology. In: Journal of Medicinal Plants Research. Vol. 7(30), 2013, S. 2221–2229, doi:10.5897/JMPR2013.5067, (PDF).
 Odilo Duarte, Robert E. Paull: Exotic Fruits and Nuts of the New World. CABI, 2015, ISBN 978-1-78064-505-6, S. 173–183.
 T. K. Lim: Edible Medicinal And Non-Medicinal Plants. Volume 6: Fruits, Springer, 2013, ISBN 978-94-007-5627-4, S. 80–91.
 Claudia Afras de Queiroz, Kedma da Silva Matos, Igor Kelvyn Cavalcante Lobo u. a.: Morpho-Anatomical and Molecular Characterization of the Oversprouting Symptoms Caused by Fusarium decemcellulare in Guarana Plants (Paullinia cupana var. sorbilis). In: Tropical Plant Biology. 13(38), 2020, doi:10.1007/s12042-020-09256-1 (Detailbilder der Blüten).

Weblinks

 .
 Paullinia cupana bei Useful Tropical Plants.

 Sigma-Aldrich: Guarana (Paullinia cupana) (englisch)
 Paullinia cupana bei Enzyklopaedie der Drogen – Kelich Andreas.

Einzelnachweise

Seifenbaumgewächse
Kletterpflanze
Pflanze mit psychotropem Wirkstoff
Stimulans


text:
Lisa Monti's Notebook
Bay Council agenda: All motions
Building permits: It's new roof season
A popular store is getting a new name. Watch for the sign!
Building permits: Apartments & wedding hall in the works
Hancock County building permitsNov. 28 – Dec. 2 Total permits 5 2 commercial, 3 residentialTotal value $463,481Total fees $2,230 Residential projects: New house on Road 366Install pole barn on Rufus Lee RoadReplace bathroom/add bedroom to cottage on Loren Ladner Road Commercial projects: New construction of Extend A Stay apartments at 16185 Highway 603. Owner/contractor is…
Sunday photos: Holiday Tree Gala, Nativity Walk & fall foliage (finally)
Nativity Walk today
Turkey Trot 2022!
Great turnout for the annual Turkey Trot!
November 24, 2022 in Bay St. Louis, Hancock County, Holidays.
Bay Council agenda: Pickleball!
November 22, 2022 in Bay St. Louis.
Bay Council agenda: P&Z votes & school board vacancy
Vote today!
November 8, 2022 in Bay St. Louis, Real estate.
Boo in the Bay Parade is today!
Boo in the Bay 2022 is HERE! And the parade route has expanded. Classic cars, Jeeps, golf carts, dance teams and trailers will gather at the Depot ahead of today's 5:30 p.m. start. The parade ends at the intersection of Main Street and Necaise Avenue. www.boointhebay.com
October 22, 2022 in Bay St. Louis, Hancock County, Holidays.
CASA's Red Bean Cook-Off is Saturday
CASA of Hancock County, City of Diamondhead host Red Bean Cook-Off CASA of Hancock County is partnering with the City of Diamondhead to host its second annual Red Bean Cook-Off from 4-7 p.m. on Saturday, Oct. 22, on the grounds of Diamondhead City Hall (5000 Diamondhead Circle). Twenty teams are vying for the title of having…
October 19, 2022 in Food, Hancock County, Nonprofits.
Bay Council agenda: Tourism Board appointment
More motions than letters in the alphabet. Meet aa, ab and ac.
October 18, 2022 in Bay St. Louis.
Building permits: Meh.
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Sunday photos: You are here.
October 16, 2022 in Bay St. Louis, Food, Hancock County, Photo gallery.
Say 'Thanks, Eddie' today
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Two new restaurants opening in Bay St. Louis
Seafood, pizza, wings. Oh my.
October 12, 2022 in Bay St. Louis, Food, New business, Restaurants.


Police reponded to a domestic dispute at 31 Ingell St., and arrested Raymond Hampton, 30, same address, for assault and battery.
• Police reponded to a domestic dispute at 31 Ingell St., and arrested Raymond Hampton, 30, same address, for assault and battery.
• Two out-of-town women were arrested just after 2 p.m. for shoplifting in Kohl's, police said.
Both Eugenia Fontes, 20, 120 Sumner St., Quincy, and Jandira Deandrade-Borges, 53 Richmond St., Brockton, were charged with larceny over $250.
• Police arrested Nathan Houston, 25, of 79 Washington St. for two charges, including destruction of property over $250, as well as malicious breaking and entering.
• Police arrested 17- year old Isaac Rodriguez of 37 Dewert Ave. Rodriguez was charged with under-age posession of alcohol as well as illegally posessing mace without a F.I.D. I.D. card.


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Chucky movies are true classics and never goes out of style! and FrightFest is the first to show Chucky's latest movie Cult of Chucky.
My Good Guy friend Steve "friends to the end" took me along to see the World Premiere of Cult of Chucky (the seventh instalment to the Chucky franchise) at the opening of FrightFest (24 August 2017) which was shown at Cineworld in Leicester Square, London.
As this was a World Premiere as you can imagine most of the stars of the movie were there being interviewed and snapped on the red carpet. There was the sweet Fiona Dourif who plays Nica in the movie. She came across as such a nice young lady plus she is the daughter of Brad Dourif who plays the voice of Chucky. Don Mancini the director and writer also turned up. It was great to see such a great horror writer/director of such a classic franchise at the premiere and a few other stars but what really was great was seeing the fabulous Jennifer Tilly she was lovely, she is perfect in every single way. I also got to have my photo with her and literally my heart and soul felt like it was going to rip out of my body as she is one of my female idols and I got to hold her hand briefly. Jennifer told the press that she loves playing Tiffany in the past few Chucky movies and that she really hopes that a eighth Chucky movie will be made as she would love to star in the next one again.
After watching and listening to the interviews it was onto the screening. Time to play!
If you are not aware what Chucky movies are about it's about a serial killer Charles Lee Ray who gets killed and he transfers his soul via voodoo ritual whilst he is dying into a Good Guy doll. It is then a race against time for him to transfer his soul into a living person that he has told his secret to before his soul gets trapped in a Good Guy doll forever. As you can imagine he still has not achieved this over the past six movies.
The new movie Cult of Chucky is much more darker than the original movies and far more tense, with lots of twists and lots of unique killings with a few added witty comical moments from Chucky. In this movie Chucky (voiced by Brad Dourif) returns to terrorize Nica once again who was the disabled female star from the last movie Curse of Chucky. However, the killer doll also has some scores to settle with some other old enemies, with the help of his former wife (he wed Tiffany whom is played by Jennifer Tilly in Bride of Chucky). I love the fact that not only has this movie got many twists and turns and that it's far more darker than the usual Chucky movies but the continuity from the last movie is done very well. Like all Chucky movies there are plenty of killings but in this one there was certainly much more gore, blood and practical effects (no CGI) which made the whole movie far better than the last one which used a lot of CGI and looked odd in my opinion. Chucky might say about his latest movie "I'm new and improved" or "we are".
After the movie it was not "night night" just yet as there was a surprise Q&A with the stars of the movies and Don. This was great as I got to see the amazing Jennifer again and hear them easier without the clicking of paparazzi cameras. It was fun to watch and listen to. Don is really passionate about the franchise he has helped write and direct and urged us fans to go out and support this one so he can then continue telling the story with another instalment. However in the Q&A Don also told us to keep the whole story and twists of the movie a secret as he wants it to be a surprise for when people see it in October when Cult of Chucky officially gets released this is why I have not mentioned about the actual story of the movie.
Trust me though you won't want to miss this movie as it totally breathes new life to the franchise "Do it!" as "Life is short!" and "Trust me, you'll love it".
I will always be a fan of the Chucky movies 'til the end!
Plus whilst I was at this World Premiere I met Garett Zima who has made the most amazing replica doll of Chucky plus he makes other replica memorabilia such as Freddy Krueger's hand. He bought along his Chucky replica and it looked exactly like the one in the movie. I got to learn about his love of the Chucky movies and found out more about his talent and future projects so I just had to interview him further.
Who inspired you to make and create? I think special effects artist like Tony Gardner and Kevin Yagher inspired me to try making the dolls.
How you get started? It all started at an art gallery when I met a man that worked on the Child's Play films and he had some things from the movie that I got from him.
In the Cult of Chucky what did you supply? I supplied the shoe laces. It was great and quite interesting to see that the shoe laces had so much screen time and a lot of close up shots. It made me very happy. I am even credited at the end of the movie for historical reference.
Do you sell the dolls? Currently I have a deal with Trick or Treat Studios and will be mass producing the dolls next year.


Comprehensive information about Dayaram including biographical information, facts, literary works, and more. Dayaram (Gujarati :) (1777–1853) was a Gujarati poet. He belongs to middle age or " Madhya-kal " in Gujarati literature. He was known for his literary form called " Garbi " in Gujarat. He was a follower of Pushtimarg of Hindu religion. Dayaram, along with Narsinh Mehta and Meera, is considered as major contributor in Bhakti-kal in Gujarati literature. This educational Dayaram resource has information about the author's life, works, quotations, articles and essays, and more.
Articles about Dayaram or articles that mention Dayaram.
Here are a few random quotes by Dayaram.


Coconino County Supervisor Lena Fowler has been selected as the 2017 recipient of the Coconino Community College Distinguished Service Award.
Originally Published: June 27, 2017 1:49 p.m.
FLAGSTAFF, Ariz. — Coconino County Supervisor Lena Fowler has been selected as the 2017 recipient of the prestigious Distinguished Service Award at Coconino Community College (CCC).
Fowler was selected for her outstanding contribution to the mission of CCC.
Fowler is now in her third term as supervisor for District 5, which includes Tuba City and the city of Page. Being Navajo and raised traditionally, Fowler has lived in Tuba City for more than 25 years and has been a part of a wide array of community service projects. She worked in the Office of Continuing Education and Dine' College; was a founding member of Tuba City Concerned Citizens, an organization devoted to cleanup of uranium mine tailings; was a founding member and vice president of Tuba City Regional Health Care Corporation Board of Directors; was president of the Association for Indian Self-Determination in Healthcare; was president of Navajo United Way, Inc. and much more.
In recent years, she has been heavily involved in the development of a Higher Education Consortium Project located at the CCC Page Instructional Site. The project brings together CCC, Dine' College, Navajo Technical University and Northern Arizona University to provide higher education and job training to residents of northern Coconino County.
Fowler has also worked with the CCC Page Instructional Site student services coordinator to promote success for potential and current students; helped secure funding for dual enrollment classes in Page; organized efforts across the Navajo Nation to keep the Page Instructional Site open; and has been a speaker at several CCC events in Page, including awards ceremonies.
The CCC Distinguished Service Award recognizes outstanding service, leadership and support to the College and to the educational enrichment of Coconino County. Nominees must be a resident of Coconino County at the time of nomination, and they must have affected or substantially contributed a major accomplishment for the benefit of CCC and to the educational enrichment of district residents. The award is normally given to one recipient annually, and any resident of the county may nominate a person for the award. Current members of the CCC District Governing Board and individuals employed by the College are exempt from nomination.
The award will be presented during the CCC Foundation Annual Meeting, Alumni & Awards Breakfast, Friday, Sept. 8, 2017, 7:30 to 9 a.m., at the CCC Lone Tree Campus Commons, 2800 S. Lone Tree Road in Flagstaff.


text:
Новое () — село в Чаплинском районе Херсонской области Украины.
В 2022 году, во время вторжения России на Украину, село было захвачено. На данный момент находится под оккупацией ВС РФ.

Население по переписи 2001 года составляло 315 человек. Почтовый индекс — 75204. Телефонный код — 5538. Код КОАТУУ — 6525455101.

Местный совет
75200, Херсонская обл., Чаплинский р-н, пгт Чаплинка, ул. Парковая, 40

Ссылки
 Новое на сайте Верховной рады Украины

Примечания

Населённые пункты Чаплинского района


text:
Shizuru-chan 2018-12-11 17:56:24 UTC #219
I don't think it is a ridiculous theory because the tree could be a metaphor of Ayu's good memories with Yuuichi which, I suppose, lead him in a dream where he meets Ayu again and can remember what he forgot in order to fulfill his promise and returns to her. But what's good with Kanon is that we can imagine a lot of theories.
Spoiler warning for Mob Psycho 100's manga (not yet adapted in anime): I'm fairly convinced that the aliens that Tome and friends met came from the planet that the early Key heroines inhabited
RazoRTR 2019-04-30 22:14:18 UTC #221
(Spoilers for Planetarian, Little Busters and Mahou Shoujo Madoka Magica)
Imagine Yumemi being the actual God of everything that has happened in Key universes, but some of her features was actualy a government project that's made after obtaining a certain alien element called Keyonionum from a space expedition (minor LB spoilers from Kud's route) (one which Kudryavka's mother [or even Kudryavka herself] has taken part in). The element was then has made experiments on throughout the years, with the help of quantum computers causing the Third World War, a war of power clashing between nations. Sealed in a planetarium for years to hide from the outer nations, with a hidden feature of creating microuniverses, simulations that create an energy source of a certain wavelength, out of some Keyonionum; observing the world around her through the cameras outside the planetarium, Yumemi sees a human that's affected from the after effects of a Keyonionum but on a cellular level (our boi Junker). After her encounter with him, his condition activates her secret feature of creating microuniverses to alter the time-space continuum, she puts her knowledge of the world (Main Realm) into the work and creates little sentient programs called Users to interact with the microuniverses. These microuniverses come with pre-made scenarios that are made by certain scientists that worked on the project. With the activation of the feature called God's Hand, the Junker's conscience is made into the Overseer of all microuniverses and the main power source of all the simulations. And her only purpose is to create a utopia that everything is okay… by feeding off of the emotions of the people inside Key universes, kinda like (Madoka spoilers) the Incubator from Madoka that's trying to maintain the energy balance of the universe by clashing the Witches and Magical Girls.
Kandy 2019-05-12 23:38:52 UTC #222
What if Akio from CLANNAD went through the same light orb experience as Tomoya?
It's exactly what I thought ! It would be great if it was true and it would explain a lot of things.
stupid 2019-05-13 22:43:04 UTC #224
Kandy:
This actually makes a lot of sense when i think about it.
Kagura 2019-05-15 22:29:51 UTC #225
Kuze from Kanon was actually the good guy and Mai was really just going to school at night to bust some windows
Full Kanon and Clannad spoilers.
So, while I was making the image below, I realized something; obviously, Ayu and Fuko's routes share the same skeleton. But why? Once upon a time, I put in the back of my head as Maeda possibly honoring Hisaya as a writer following their companionship from Kanon (a theory I base on absolutely nothing) but then I wondered something. What if Ayu and Fuko aren't different. What if, and bear with me here, they're the same person? Anyone who's seen a time loop in fiction can tell you, reality is only what our small brains can perceive. Kouko claims Fuko had been in her coma for seven years, but I don't think once it is said that Clannad actually takes place in 2003. 1999, perhaps? Ayu has also been in a coma for the exact amount of time. Both of them are still children. Both of them are the same person.
Fuko comes from a timeline where Yuuichi failed. Nay, the timelines where Yuuichi failed. Fuko is the result of every bad end Ayu, punished for her sins of taiyaki avarice. Further trapped in a time loop, winter ends, and spring begins. Ayu loved nothing and no one, thus is granted someone to take care of. To earn her wings and free her from the infinity loop, God grants her a sister to take of and a home to go back to. Paradise isn't something given to you, it's something you create yourself. Yuuichi can't save her anymore; in the end, Ayu realizes that she can only really save herself. Thus, because she has short hair, she grows it out instead of doing the anime trope of cutting it all off. All she has is a knife and all the wood in Hikarizaka's forests. Ayu died that day, because of the wind. Then, Fuko (wind child) is born.
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text:
Cook Inlet Regional Citizens Advisory Council
Representing the citizens of Cook Inlet in promoting environmentally safe marine transportation and oil facility operations in Cook Inlet.
Long Range Plan
Biological & Chemical Monitoring
Oil Behavior
Response Strategies by Location (GRS)
Oil Spill Prevention & Response
Oil Spill Contingency Plan Review
25-Year Anniversary 1990-2015
You are here: Home / What We Do / Biological & Chemical Monitoring / Arctic Relict Fauna and Flora
Arctic Relict Fauna and Flora
Through the Coastal Marine Institute (CMI), a partnership between the University of Alaska Fairbanks and the Minerals Management Service (now BOEM), Cook Inlet RCAC partnered on the project "Evaluating a Potential Relict Arctic Invertebrate and Algal Community on the West Side of Cook Inlet." This project was an analysis of archived samples and specimens collected during intertidal and subtidal surveys in Cook Inlet to evaluate whether they are relict Arctic species. The study is based on previous work conducted on the lower west side of Cook Inlet when taxonomic identifications of epifaunal invertebrates collected in the 1970s for the Outer Continental Shelf Environmental Assessment Program bore a striking resemblance to species reported for the Alaskan Arctic. Additional information provided by other historical invertebrate collections in the area indicate that these west side species and assemblages more closely matched Arctic species and assemblages than those on Cook Inlet's east side or in other areas of the Gulf of Alaska and this study will further evaluate these historical specimens. Appropriate international taxonomic experts for each group of species were contracted to provide the level of detail required to assess the potential for a relict Arctic flora and fauna assemblage on Cook Inlet's west side.
Given the potential isolation of an Arctic relict assemblage, these western Cook Inlet populations could be at risk from habitat perturbation and might be sensitive indicators of climate change or other ecological shifts. In addition, industrial development could threaten these populations and baseline information is needed to fully evaluate that potential. Monitoring their distributions and abundance could provide insight into changes in marine fauna and flora that may occur with changing physical oceanographic conditions. The persistence of these species in spite of their restricted distributions, relative to the prevailing currents, raises some interesting questions about their reproductive mechanisms and strategies. This evaluation addressed the CMI framework need for "better understanding marine, coastal or human environments affected or potentially affected by offshore oil and gas or other mineral exploration and extraction on the outer continental shelf."
This study evaluated archived specimens of intertidal and subtidal invertebrates and algae from Cook Inlet's west side to compare assemblages to other areas of Cook Inlet and Alaska. There has been speculation in the literature that these assemblages on the west side of Cook Inlet more closely reflect species that occur in the Alaskan Arctic than those in other areas of Cook Inlet. The study compared species lists from Cook Inlet's west side to species lists form the Arctic and other areas of Cook Inlet (e.g. Kachemak Bay). In addition, archived samples from the University of Alaska museum were sorted and identified to the lowest taxon possible by taxonomists who specialize in the various classes of plants and animals. We found a strong relationship between Arctic and west-side bryozoan fauna and weaker relationships for other invertebrate groups. Our results suggest that the disjunct distributions of many Arctic-affiliated species, both algae and invertebrates may be due to a contraction in their distributional ranges in the north Pacific from wider distributions occupied before the most recent glacial retreat.
The final report can be found here.
Identify and evaluate risks and potential impacts of oil industry operations to ecosystem components of the Cook Inlet RCAC area of concern.
Assess and monitor status and trends of biological and chemical components in the Cook Inlet RCAC area of concern.
Make data accessible to stakeholders to improve our understanding of biological and chemical environments in the Cook Inlet RCAC area of concern.
OPA 90 Language That Guides This Program:
5002 (e) (2) Duties-In fulfilling its responsibilities, the [EMC] shall-
(A) advise the Council on a monitoring strategy that will permit early detection of environmental impacts of terminal facility operations and crude oil tanker operations while in ...Cook Inlet;
(B) develop monitoring programs and make recommendations to the Council on the implementation of those programs;
(C) at its discretion, select and contract with universities and other scientific institutions to carry out specific monitoring projects authorized by the Council pursuant to an approved monitoring strategy.
Program Specifics
Program Manager:
Susan Saupe,
Director of Science and Research
saupe@circac.org
Recent Cook Inlet RCAC Projects in support of Biological & Chemical Monitoring Program:
History of Monitoring Program »
Environmental Monitoring and Assessment Program (EMAP) »
Integrated Cook Inlet Environmental Monitoring and Assessment Program (ICIEMAP) »
Cook Inlet Beluga Whale Habitat and Prey »
Cook Inlet Beluga Whale Ecosystem Portal
Arctic Relict Fauna and Flora »
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Air pollution in one of the significant problems in the world. Due to air pollution, Delhi is facing health problems. AQI is increased to a large extent. The problem is in the in the form of asthma and many other dangerous diseases. A large portion of society in DELHI NCR is facing suffering from health issues due to this pollution. Scrap filter contains crucial data related to the Drastic increase of AQI level in Delhi.
Air pollution nowadays is one of the top pollutions. This form is this is at its apex level. Smoke is being trapped up in the atmosphere. Human beings inhale this smoke and this generates a problem in the lungs and other body parts. There are various reasons for the pollution. One of the vital reason is due to the smoke which comes out of the vehicles.
The next day after Diwali, this air is being converted to Hazardous. This is only due to a large amount of smoke. This is the smoke which is being released from igniting up of the crackers. Now the air is reported as the "severe plus emergency". Delhi's air is reported as the worst air quality from all preceding years. Anand Vihar in Delhi was being recorded as the most polluted due to air quality.
Supreme court pass an order for Delhi NCR to fire the crackers just for 2 hours that is from 8 to 10 pm. The use of green crackers is also been recommended. Green crackers don't appear to come in the play. The burst sound of crackers was being listened even after 10:00 PM. This indicates that society is responsible for this condition of the atmosphere. The society plays a vital role in the atmosphere. If this society is irresponsible then the outcome will be critical.


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Home WinBuzzer News Sony PS4 Becomes Second Best-Selling Console Ever but Suffers Xbox-Like Generation Ending...
WinBuzzer News
Sony PS4 Becomes Second Best-Selling Console Ever but Suffers Xbox-Like Generation Ending Decline
Sony's PlayStation 4 (PS4) has shifted 102.8 million units and is only behind the PS2 as the second-best selling console ever.
Luke Jones
October 30, 2019 3:04 pm CET
A week ago, Microsoft announced its Xbox revenue declined by 7% year-on-year during its fiscal Q1 2020. Much of that decline was driven by declining sales of the Xbox One. Hardware sales dipped 34% compared to the previous year as the 8th console generation comes to an end. However, while Xbox One sales are falling, Sony's are seemingly still doing for the PlayStation 4 (PS4).
Indeed, the company says it sold 2.8 million units during the second quarter of 2019. We already know the PlayStation 4 has vastly outsold the Xbox One over this generation, but the quarterly sales pushed Sony to a new milestone.
In total, the PS4 has now sold up to 102.8 million units. With this jump, the console has become the second best-selling games console ever, topping the 102.49 million sales of the original PlayStation. However, the device is certainly not going to surpass the 155 million units the PlayStation 2 sold.
Still, Sony has become the dominant console brand, with three of its devices in the top three best-selling models ever. Nintendo's Wii remains a massive success but has moved down to fourth with 101.63 million units sold.
Declining Sales
While this is good news for Sony, the results also point to a wider trend we observed with Microsoft's decline. Indeed, Sony's gaming revenue fell 17% year-on-year and profits dipped 28%. Like with Microsoft, Sony is feeling the pinch at the end of the console generation.
Customers who wanted a PS4 already have one, and many who don't are willing to wait until the PS5 and Xbox Scarlett launch next year.
All eyes will be on those two consoles as they will compete directly and are launching in the same frame. Microsoft has significantly lost this generation based on sales. It will be interesting to see if customers start the ninth generation with a clean slate attitude or will be biased towards the brand they chose this generation.
SOURCESony (PDF)
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Luke has been writing about all things tech for more than five years. He is following Microsoft closely to bring you the latest news about Windows, Office, Azure, Skype, HoloLens and all the rest of their products.
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Once again the Haywards Heath & Lindfield Committee of Horsham based charity Action Medical Research for Children would like to extend a big thank you to all those kind people who have given so generously to the charity during 2015.
This was evident through various fundraising events including our annual Bridge Drive, the return of the very popular Strawberry Tea and a Christmas Coffee Morning. A special mention must go to all the local companies and individuals who supported our annual Peter James Golf Classic held at Haywards Heath Golf Club which this year was sponsored by Caffyns. With all this support, team entries and donations we raised an amazing £10,500 on the day.
We are truly grateful to all those people who have worked so hard to support us. A mention must also go to our band of willing helpers who step in to assist at events. We really couldn't manage without them. Without all this wonderful support we could not continue to fund the groundbreaking work that we know helps to save and change so many children's lives.
If anyone has time to spare and would like to help with events, provide sponsorship or maybe consider joining the local committee, please telephone 01444 482362.


Kevin Godbee, owner of the website St. Petersburg Foodies, has declared May 9th National Foodies Day. Many restaurants in his hometown of St. Petersburg, FL are getting in on the fun. While it can take an Act of Congress to declare a day a national holiday, Foodie Day sounds like a great idea to us, and we think it's a day that can be celebrated coast to coast.
Try a new food, especially one you've never heard of or have been scared to try.
Sign up for a local cooking class.
Take some friends out for a fun restaurant meal.
Book a reservation for May 9th at your favorite restaurant.
Try a pop-up dining event to experience food in a whole new way.
Sign up for a food tour or wine tasting to combine travel and eating.
Try a private dining experience, such as Table at Bricco, and ask all your friends to join you.
Ask a chef for recommendations.
If you'd like to celebrate, book a reservation today or start dreaming up a menu for a special party.
Why Is a Food Holiday Overdue?
Foodies do a great deal for us, and we think it's a good idea to recognize them. Simply defined, foodies are gourmands who really focus on food. If you have someone like this in your life, you may be exposed to taste and dining experiences you haven't even considered. Connoisseurs tend to expand and influence the palates of everyone around them.
Food is essential for life, but it's also crucial to health. It is part of some our most important celebrations, and when we "break bread" with loved ones, we form bonds. Eating together can help us strengthen relationships as we nourish our bodies.
Foodies tend to focus on local, organic and fresh ingredients over processed foods, too. This can have a big impact on health, since convenience foods tend to be very high in artificial ingredients, sodium, sugar and other ingredients that may be harmful when eaten to excess.
The focus on local foods is also important in changing local economies, the environment and how we look at food. Going local means less reliance on imported ingredients, which place enormous pressure on transportation systems and use up a great deal of fuel. Foodies who focus on getting to know regional and organic foods are often willing to get to know local producers. They might also encourage methods of production that help create local jobs and are gentler on the environment when compared to mass-produced foods shipped globally.
Whether you identify as a gourmand yourself or have friends who are foodies, plan something fun this May for National Foodie Day to celebrate what food can do in our lives.


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Weet-Bix Official Breakfast of Socceroos
Weet-Bix has extended its support of Australia's great national sporting teams through a new three-year suppliership deal with the Socceroos. Weet-Bix is now the official breakfast of the Socceroos.
Weet-Bix has extended its support of Australia-s great national sporting teams through a new three-year suppliership deal with the Socceroos. Weet-Bix is now the official breakfast of the Socceroos.
The three-year agreement announced today will see the Australian team through their Powerade Cup match against Greece at the MCG on 25 May, the 2006 World Cup in Germany, Asian Cup qualifiers and a host of International matches between now and 2009.
Additionally, dynamic Qantas Socceroo midfielder Tim Cahill has been appointed as football-s new -Weet-Bix Kid-. Tim and the Socceroos will feature heavily in advertisements and other promotions surrounding Weet-Bix and its support of football.
Chief Executive Officer of Football Federation Australia (FFA), Mr John O-Neill, said: "We are delighted to establish a relationship with one of Australia-s great iconic products and health food companies.
"An association with Weet-Bix also further emphasises the position that football - and particularly the Socceroos - now holds in the Australian sporting psyche.
"The Socceroos are a great Aussie team with significant national support and I look forward to watching the enormous patriotic fervour they will generate over the coming months.
"And, of course, the players continue to eat their Weet-Bix every step of the way!"
Qantas Socceroo and new Weet-Bix Kid, Tim Cahill, said that he was delighted with his new role.
"Like most kids in Australia, I grew up on Weet-Bix. I have aspired to be a great football player but to be chosen as a Weet-Bix Kid is something I never would have imagined.
"I am proud to tell my kids that I am one of the faces in the Weet-Bix advertisements and on over 14 million packs.
"I start my day with five Weet-Bix because it provides long lasting energy and the right nutrients to perform at my best," Tim added.
"In regard to the World Cup, we-re in full preparation mode right now, and it-s just great to know we-ve got so much fantastic support back home not only from companies like Sanitarium but from Australians everywhere."
Sanitarium Marketing Manager, Rex Sheehy says partnership with the Socceroos is a natural progression for a brand that has already enjoyed successful relationships with many of Australia-s national teams.
"Like Brett Lee and the Australian Cricket team, Tim Cahill and the Socceroos are down-to-earth outstanding young sportsmen who bring to life a key characteristic of the Weet-Bix brand - that is, Be Your Best," Sheehy said.
"Weet-Bix is Australia-s No.1 breakfast cereal, and we think the Socceroos are already winners and poised to play a major role on what is football-s biggest stage.
"Australia-s largest health food company Sanitarium aims to educate and inspire kids to eat a healthy breakfast like Weet-Bix," Rex added.
"Partnerships with elite national sporting teams, like the Socceroos, and individuals, such as Tim Cahill, personify good health and fitness that children aspire to."
"It-s an exciting time for the game in Australia, and just as exciting for Weet-Bix as it becomes the official breakfast of the Socceroos for the next three years."
An advertisement featuring the Socceroos and Tim Cahill was shot at the recent Socceroo training camp in the Netherlands, and will commence on-air in May.
The star of the film shoot, Tim Cahill, mused: "We had loads of fun shooting the ad in Holland, and of course loved getting stuck into our Weet-Bix. But we still can-t get the Weet-Bix song out of our heads!"


During one of his shows over the weekend, rising singer Jake Miller decided to quench the thirst of some of his panting fans by opening a bottle of water and splashing the crowd. Some in attendance were pissed they got wet, while others wished they got to shower in Jake's backwash. The #JakeMillerWaterChallenge became a thing as a result.
"So apparently there's a #JakeMillerWaterChallenge all because that 1 girl complained how I threw water on her during the show," Jake tweeted out to fans in a not-so-sly effort to get more of supporters to hop on this bandwagon.
Take a look at some fans taking part in the #JakeMillerWaterChallenge below.
If @jakemiller threw water on me.