text:
\section{Introduction and Preliminaries}
Let $\mathcal{B}\left( \mathcal{H} \right)$ be the algebra of all (bounded linear) operators on a  complex Hilbert space $\mathcal{H}$. An operator $A$ on $\mathcal{H}$ is said to be positive (in symbol: $A\ge 0$) if $\left\langle Ax ,x  \right\rangle \ge 0$ for all $x \in \mathcal{H}$. We write $A>0$ if $A$ is positive and invertible. For self-adjoint operators $A$ and $B$, we write $A\ge B$ if $A-B$ is positive, i.e., $\left\langle Ax ,x  \right\rangle \ge \left\langle Bx ,x  \right\rangle $ for all $x \in \mathcal{H}$. We call it the usual order. In particular, for some scalars $m$ and $M$, we write $m\le A\le M$ if $m\left\langle x ,x  \right\rangle \le \left\langle Ax ,x  \right\rangle \le M\left\langle x ,x  \right\rangle $ for all $x \in \mathcal{H}$. The spectrum of $A$ is denoted by $Sp\left( A \right)$. A linear map $\Phi :\mathcal{B}\left( \mathcal{H} \right)\to \mathcal{B}\left( \mathcal{H} \right)$ is positive if $\Phi \left( A \right)\ge 0$ whenever $A\ge 0$. It is said to be unital if $\Phi \left( I \right)=I$.

In \cite{4}, for $A,$ $B>0$, relative operator entropy was defined by
\[S\left( A|B \right)={{A}^{\frac{1}{2}}}\ln \left( {{A}^{-\frac{1}{2}}}B{{A}^{-\frac{1}{2}}} \right){{A}^{\frac{1}{2}}}.\]
For $A,$ $B>0$, the Tsallis relative operator entropy is defined as follows (see \cite{5})
\[
{{T}_{v}}\left( A|B \right)=\frac{A{{\natural}_{v}}B-A}{v} ={{A}^{\frac{1}{2}}}\ln_v \left( {{A}^{-\frac{1}{2}}}B{{A}^{-\frac{1}{2}}} \right){{A}^{\frac{1}{2}}},\qquad\left(v\in \left[ -1,0 \right)\cup \left( 0,1 \right]\right),
\]
where
$\ln_v(x) := \frac{x^{v}-1}{v}$ is $v$-logarithmic function defined for $x>0$ with $0\neq v \in \mathbb{R}$
and
\[A{{\sharp}_{v}}B={{A}^{\frac{1}{2}}}{{\left( {{A}^{-\frac{1}{2}}}B{{A}^{-\frac{1}{2}}} \right)}^{v}}{{A}^{\frac{1}{2}}}\]
is the weighted geometric mean for $v\in [0,1]$.
Here we use the similar symbol $A\natural_v B={{A}^{\frac{1}{2}}}{{\left( {{A}^{-\frac{1}{2}}}B{{A}^{-\frac{1}{2}}} \right)}^{v}}{{A}^{\frac{1}{2}}}$ for any $v \in \mathbb{R}$. We remark that
\[{{T}_{0}}\left( A|B \right)=\underset{v\to 0}{\mathop{\lim }}\,{{T}_{v}}\left( A|B \right)=S\left( A|B \right),\]
since $\underset{v\to 0}{\mathop{\lim }}\,\ln_v t=\ln t$ for $t>0$. \\
It is known that \cite{6}:
\[A-A{{B}^{-1}}A\le S\left( A|B \right)\le B-A\quad\text{ and }\quad A-A{{B}^{-1}}A\le {{T}_{v}}\left( A|B \right)\le B-A.\]
Regarding the concavity of $f:\left[ m,M \right]\to \mathbb{R}$, we have
\begin{equation}\label{3}
\frac{M-t}{M-m}f\left( m \right)+\frac{t-m}{M-m}f\left( M \right)\le f\left( t \right)\quad\text{ for } t\in \left[ m,M \right].
\end{equation}
Since the function ${{\ln }_{v}}\left( t \right)=\frac{{{t}^{v}}-1}{v}$ on $t >0$ is  concave for the case $v \leq 1$, we have
\begin{equation}\label{6}
\frac{\ln_v m}{M-m}\left(MA-B\right) +\frac{\ln_v M}{M-m}\left(B-mA\right) \leq T_v(A|B)
\end{equation}
whenever $mA\le B\le MA$ for some scalars $0<m<M$ and positive  invertible operators $A,B$. For the limit of $v\to 0$, \eqref{6} implies
\begin{equation}\label{2}
\frac{\ln m}{M-m}\left( MA-B \right)+\frac{\ln M}{M-m}\left( B-mA \right)\le S\left( A|B \right).
\end{equation}

Motivated by the inequality \eqref{2}, Dragomir \cite{2} established some upper and  lower bounds for the quantity
\[S\left( A|B \right)-\frac{\ln m}{M-m}\left( MA-B \right)-\frac{\ln M}{M-m}\left( B-mA \right).\]

In this note, we present some inequalities for Tsallis relative operator entropy, which are refinements and generalizations of some results obtained by Furuichi et al. \cite{6}. Some related and new inequalities, related to the information monotonicity of Tsallis relative operator entropy, are also established. We also give some alternative bounds for the recent result by Dragomir \cite{2}.

\section{Main Results}

At this point, for the reader's convenience,  we define the following two abbreviations:
\begin{equation}\label{1}
\xi \left( t \right)=1+\frac{{{2}^{\frac{t-m}{M-m}}}\left( t-m \right)\left( M-t \right){{M}^{\frac{t-M}{M-m}}}}{{{\left( M+m \right)}^{\frac{t+M-2m}{M-m}}}}\quad\text{ and }\quad \psi\left( t \right)=1+\frac{\left( t-m \right)\left( M-t \right){{M}^{\frac{t-M}{M-m}}}}{2{{m}^{\frac{t+M-2m}{M-m}}}}
\end{equation}
where $t\in \left[ m,M \right]$ with $0<m\le M$.
\begin{theorem}\label{a}
	Let $A,B\in \mathcal{B}\left( \mathcal{H} \right)$ be two positive invertible operators satisfying $mA\le B\le MA$ for some scalars $0<m<M$. Then
	\[\begin{aligned}
	0&\le {{A}^{\frac{1}{2}}}\ln \xi \left( {{A}^{-\frac{1}{2}}}B{{A}^{-\frac{1}{2}}} \right){{A}^{\frac{1}{2}}} \\
	& \le S\left( A|B \right)-\frac{\ln m}{M-m}\left( MA-B \right)-\frac{\ln M}{M-m}\left( B-mA \right) \\
	& \le {{A}^{\frac{1}{2}}}\ln \psi\left( {{A}^{-\frac{1}{2}}}B{{A}^{-\frac{1}{2}}} \right){{A}^{\frac{1}{2}}}.
	\end{aligned}\]
\end{theorem}
\begin{proof}
	In the previous paper (see the estimate (2.6) in \cite{1}), the authors stated that if $0<b\le a$ and $v\in \left[ 0,1 \right]$, then
		\[{{m}_{v}}\left( \frac{b}{a} \right){{a}^{1-v}}{{b}^{v}}\le \left( 1-v \right)a+vb\le {{M}_{v}}\left( \frac{b}{a} \right){{a}^{1-v}}{{b}^{v}},\]
	where
	\[{{m}_{v}}\left( \frac{b}{a} \right)=1+\frac{{{2}^{v}}v\left( 1-v \right){{\left( a-b \right)}^{2}}}{{{a}^{1-v}}{{\left( a+b \right)}^{1+v}}}\quad \text{ and }\quad {{M}_{v}}\left( \frac{b}{a} \right)=1+\frac{v\left( 1-v \right){{\left( a-b \right)}^{2}}}{2{{a}^{1-v}}{{b}^{1+v}}}.\]
	Assume that $t\in \left[ m,M \right]$ with $0<m\le M$. Choosing $a=M$, $b=m$ and $v=\frac{t-m}{M-m}$, we get
	\[\xi \left( t \right){{M}^{\frac{t-m}{M-m}}}{{m}^{\frac{M-t}{M-m}}}\le t\le \psi\left( t \right){{M}^{\frac{t-m}{M-m}}}{{m}^{\frac{M-t}{M-m}}}\]
	where $\xi\left( t \right)$ and $\psi\left( t \right)$ are defined as in \eqref{1}. By taking the logarithm we obtain
	\[\ln \xi \left( t \right)\le \ln t-\frac{\ln m}{M-m}\left( M-t \right)-\frac{\ln M}{M-m}\left( t-m \right)\le \ln \psi\left( t \right).\]
	Now, by setting $t={{A}^{-\frac{1}{2}}}B{{A}^{-\frac{1}{2}}}$ and then multiplying both sides by ${{A}^{\frac{1}{2}}}$ we deduce the desired result.
\end{proof}
\begin{remark}
Dragomir in \cite[Theorem 2]{2} has proved the following inequalities
\[\begin{aligned}
 0&\le K\left( \frac{M}{m} \right)\left( \frac{1}{2}A-\frac{1}{M-m}{{A}^{\frac{1}{2}}}\left| {{A}^{-\frac{1}{2}}}\left( B-\frac{M+m}{2}A \right){{A}^{-\frac{1}{2}}} \right|{{A}^{\frac{1}{2}}} \right) \\
& \le S\left( A|B \right)-\frac{\ln m}{M-m}\left( MA-B \right)-\frac{\ln M}{M-m}\left( B-mA \right) \\
& \le K\left( \frac{M}{m} \right)\left( \frac{1}{2}A+\frac{1}{M-m}{{A}^{\frac{1}{2}}}\left| {{A}^{-\frac{1}{2}}}\left( B-\frac{M+m}{2}A \right){{A}^{-\frac{1}{2}}} \right|{{A}^{\frac{1}{2}}} \right). \\
\end{aligned}\]
To compare Theorem \ref{a} and Dragomir's result, it is sufficient to compare the following inequalities for $0<x\le 1$:
\begin{equation}\label{4}
{{m}_{v}}\left( x \right){{x}^{v}}\le \left( 1-v \right)+vx\le {{M}_{v}}\left( x \right){{x}^{v}}
\end{equation}
where
\begin{equation}\label{7}
{{m}_{v}}\left( x \right)=1+\frac{{{2}^{v}}v\left( 1-v \right){{\left( x-1 \right)}^{2}}}{{{\left( x+1 \right)}^{v+1}}}\quad\text{ and }\quad{{M}_{v}}\left( x \right)=1+\frac{v\left( 1-v \right){{\left( x-1 \right)}^{2}}}{2{{x}^{v+1}}}
\end{equation}
and
\[{{K}^{r}}\left( x \right){{x}^{v}}\le \left( 1-v \right)+vx\le {{K}^{R}}\left( x \right){{x}^{v}},\]
where $v\in \left[ 0,1 \right]$, $r=\min \left\{ v,1-v \right\}$, $R=\max \left\{ v,1-v \right\}$ and $K\left( x \right)=\frac{{{\left( x+1 \right)}^{2}}}{4x}$. As we mentioned in \cite[Proposition 3.1]{1}, there is no ordering between ${{K}^{r}}\left( x \right)$ and ${{m}_{v}}\left( x \right)$ (and also between ${{K}^{r}}\left( x \right)$ and ${{M}_{v}}\left( x \right)$). Therefore we conclude that Theorem \ref{a} is not a trivial result.
\end{remark}
It seems worthwhile to point out the following remark.
\begin{remark}
Let $v\in \left( 0,1 \right]$. As we mentioned in \cite[Remark 1]{3}, for $x\ge 1$ we have
\[0\le 1-\frac{1}{x}\le {{\left( \frac{x+1}{2} \right)}^{v-1}}\left( x-1 \right)\le \frac{{{x}^{v}}-1}{v}\le \left( \frac{{{x}^{v-1}}+1}{2} \right)\left( x-1 \right)\le x-1.\]
It follows from \eqref{4} that
\begin{equation}\label{5}
1-\frac{1}{x}\le \frac{1}{{{M}_{v}}\left( x \right)}\left( \frac{1-v}{v}+x \right)-\frac{1}{v}\le \frac{{{x}^{v}}-1}{v}\le \frac{1}{{{m}_{v}}\left( x \right)}\left( \frac{1-v}{v}+x \right)-\frac{1}{v}\le x-1<0,
\end{equation}
where $0<x\le 1$ and $0< v \leq 1$.

Actually, the first inequality in (\ref{5}) is equivalent to the inequality
$$
v(x-1)^2 g(v,x) \geq 0,\quad g(v,x) \equiv 2x^{v+1}-(1-v)\left\{(1+v)x -v\right\}
$$
so that we have only to prove $g(v,x) \geq 0$ for $0 < v \leq 1$ and $0< x \leq 1$.\\
Since $\frac{dg(v,x)}{dx} = (1+v)(2 x^v-1+v)$ and $\frac{d^2g(v,x)}{dx^2}=2v(1+v)x^{v-1} \geq 0$, we have minimum value of the function $g(v,x)$ when $x=\left( \frac{1-v}{2}\right)^{1/v}$ and it is calculated as
$$
g\left(v,\left( \frac{1-v}{2}\right)^{1/v} \right) =v(1-v)\left\{ 1-\left(\frac{1-v}{2} \right)^{1/v}\right\} \geq 0.
$$

The second and third inequalities in (\ref{5}) are straightforward from (\ref{4}).
The forth inequality in  (\ref{5}) is  equivalent to  the inequality for $x>0$ and $0<v \leq 1$,
$$
\frac{\left(m_v(x)-1\right)}{m_v(x)} \left(\frac{(1-v)+vx}{v}\right) \geq 0
$$
by simple calculations.

\end{remark}
\begin{remark}
We know that (see \cite[Remark 2.11]{moradi2}) if $x>0$ and $v\notin \left[ 0,1 \right]$, then
\begin{equation}\label{15}
\left( 1-v \right)+vx\le {{x}^{v}}.
\end{equation}
The function ${{f}_{v}}\left( t \right)=\frac{v\left( 1-v \right)\left( t-1 \right)}{{{t}^{v+1}}}$ is convex for all $t>0$ and $v\in \left[ -1,0 \right]$. This follows from the following fact
	\[f_{v}^{''}\left( t \right)=\frac{v\left( v+1 \right)\left( 1-v \right)\left( v\left( x-1 \right)-2 \right)}{{{x}^{v+3}}}\ge0.\]

Using the Hermite-Hadamard inequality, one can get
\[{{f}_{v}}\left( \frac{1+x}{2} \right)\le \frac{1}{1-x}\int_{x}^{1}{{{f}_{v}}\left( t \right)dt}\le \frac{{{f}_{v}}\left( 1 \right)+{{f}_{v}}\left( x \right)}{2}\]
 for each $0<x\le 1$ and $v\in \left[ -1,0 \right]$. The above inequality entails that
 \begin{equation}\label{16}
{{M}_{v}}\left( x \right)\le \frac{\left( 1-v \right)+vx}{{{x}^{v}}}\le {{m}_{v}}\left( x \right)
 \end{equation}
where ${{M}_{v}}\left( x \right)$ and ${{m}_{v}}\left( x \right)$ are defined as in \eqref{7}.

Notice that for $0<x\le 1$ and $v\in \left[ -1,0 \right]$, the functions ${{m}_{v}}\left( x \right)$ and ${{M}_{v}}\left( x \right)$ are increasing and $0<{{M}_{v}}\left( x \right)\le {{m}_{v}}\left( x \right)\le 1$ (similar to that of \cite[Proposition 2.4]{1}, so we omit details).
Thus, inequality \eqref{16} provides a refinement and a reverse for the inequality \eqref{15}.
\end{remark}
\begin{theorem}\label{10}
Let $A,B\in \mathcal{B}\left( \mathcal{H} \right)$ be two positive invertible operators such that $Sp\left( A \right),Sp\left( B \right)\subseteq J\subset (0,\infty)$. Then
$$
(\ln_v t)A+\left( A{{\natural}_{v }}B-tA{{\natural}_{v -1}}B \right)\le
{{T}_{v}}\left( A|B \right)\le (\ln_v s)A+{{s}^{v-1}}\left( B-sA \right),
$$
for any $s,t\in J$ and $v\in \left[ -1,0 \right)\cup \left( 0,1 \right]$.
\end{theorem}
\begin{proof}
The differentiable function $f$ is concave on $J$ if, for any $s\in J$, the tangent line through $\left( s,f\left( s \right) \right)$  is above the graph of $f$. That is
\begin{equation*}
f\left( t \right)\le f\left( s \right)+f'\left( s \right)\left( t-s \right).
\end{equation*}
Of course, the function $f\left( x \right)=\ln_v x\,\,\left( v\in \left[ -1,0 \right)\cup \left( 0,1 \right] \right)$ is differentiable and concave so
\begin{equation}\label{12}
\ln_v t \le \ln_v s+{{s}^{v-1}}\left( t-s \right),
\end{equation}
for any $s\in J$.\\
Applying functional calculus for the positive operator ${{A}^{-\frac{1}{2}}}B{{A}^{-\frac{1}{2}}}$, we get
$$
\ln_v \left( {{A}^{-\frac{1}{2}}}B{{A}^{-\frac{1}{2}}} \right)\le (\ln_v s)I+{{s}^{v-1}}\left( {{A}^{-\frac{1}{2}}}B{{A}^{-\frac{1}{2}}}-sI \right).
$$
for any $s\in J$. By multiplying both sides by ${{A}^{\frac{1}{2}}}$ we deduce the second inequality.

On the other hand, from inequality \eqref{12}, we get
$$
(\ln_v t)I\le \ln_v \left( {{A}^{-\frac{1}{2}}}B{{A}^{-\frac{1}{2}}} \right)+ t{{\left( {{A}^{-\frac{1}{2}}}B{{A}^{-\frac{1}{2}}} \right)}^{v -1}}-{{\left( {{A}^{-\frac{1}{2}}}B{{A}^{-\frac{1}{2}}} \right)}^{v }} .
$$
Multiplying ${{A}^{\frac{1}{2}}}$ from both sides, we have the first inequality.
\end{proof}

\begin{remark}
In \cite[Theorem 3.6]{6}, Furuichi et.al. obtained the following inequality:
\begin{equation}\label{eq01_remark2.4}
A\sharp_vB-\frac{1}{\alpha}A\natural_{v-1}B+\left(\ln_v\frac{1}{\alpha}\right)A \leq T_v(A|B)\leq \frac{1}{\alpha}B-A-\left(\ln_v\frac{1}{\alpha}\right)A\sharp_vB,
\end{equation}
for $\alpha >0$ and $0 < v \leq 1$.
We see the first inequality of \eqref{eq01_remark2.4} is just same to
one in Theorem \ref{10} with $t=\frac{1}{\alpha}$. However, its proof is an entirely different proof to  \cite[Theorem 3.6]{6}.

The second inequalities of  \eqref{eq01_remark2.4} and in Theorem \ref{10} with $s=\frac{1}{\alpha}$ are different. In order to compare these, we have to compare $g_v(s,t):=(\ln_v s)+s^{v-1}t-s^v$ and $h_v(s,t):=st-1-(\ln_v s)t^v$ for $v \in [-1,0)\cup (0,1]$ and $s,t >0$.
However there is no ordering between them.
Actually, we have
$f_{0.5}(0.1,1) \simeq 1.01096$ and $f_{0.5}(0.1,0.1) \simeq -0.81$, where $f_v(s,t) :=g_v(s,t)-h_v(s,t)$.
In addition our Theorem \ref{10} holds for $v\in[-1,0)\cup(0,1]$, while the inequalities \eqref{eq01_remark2.4} given in \cite[Theorem 3.6]{6} were shown for $v \in (0,1]$.
Therefore our obtained upper bound for $T_v(A|B)$ in Theorem \ref{10} is not trivial result.

For the limit of $v \to 0$ in Theorem \ref{10} we have
$$
(\log t) A+(A-tAB^{-1}A) \leq S(A|B) \leq (\log s)A+s^{-1}B-A.
$$
In addition, if we take $t=\frac{1}{\alpha}$ and $s=\alpha$ in the above, then we obtain the known inequalities
$$
(1-\log \alpha)A-\frac{1}{\alpha}AB^{-1}A\leq S(A|B) \leq (\log \alpha -1)A+\frac{1}{\alpha}.
$$
Furthermore, if we put $\alpha =1$ above, then we recover
$$
A-AB^{-1}A \leq S(A|B) \leq B-A.
$$
See \cite{6} for these known inequalities, for example.
\end{remark}

Extending a work of Fujii \cite{fujii} for relative operator entropy, Furuichi et al. \cite[Proposition 2.3]{6} obtained:
\begin{equation}\label{13}
\Phi \left( {{T}_{v}}\left( A|B \right) \right)\le {{T}_{v}}\left( \Phi \left( A \right)|\Phi \left( B \right) \right)
\end{equation}
where $\Phi :\mathcal{B}\left( \mathcal{H} \right)\to \mathcal{B}\left( \mathcal{H} \right)$ is a unital positive linear map. In the following, we try to improve inequality \eqref{13}, which is often called the monotonicity for Tsallis relative operator entropy.
\begin{theorem}\label{14}
Let $A,B\in \mathcal{B}\left( \mathcal{H} \right)$ be two positive invertible operators and let $\Phi :\mathcal{B}\left( \mathcal{H} \right)\to \mathcal{B}\left( \mathcal{H} \right)$ be a unital positive linear map. Then for any $v \in \left[ 0,1 \right]$
\[\begin{aligned}
 \Phi \left( {{T}_{v}}\left( A|B \right) \right)&\le \int_{0}^{1}\frac{ \Phi \left( \left( A{{\sharp}_{v}}B \right){{\sharp}_{\mu }}A \right){{\sharp}_{v}}\Phi\left(  \left( A{{\sharp}_{v}}B \right){{\sharp}_{\mu }}B \right)  -\Phi \left( A \right)}{v} d\mu\\
& \le {{T}_{v}}\left( \Phi \left( A \right)|\Phi \left( B \right) \right).
\end{aligned}\]
\end{theorem}
\begin{proof}
First, we need the following inequality from \cite[Theorem 3.1]{moradi2}, which connects both sides of the Ando's inequality \cite{ando}:

\begin{equation}\label{8}
\Phi \left( A{{\sharp}_{v}}B \right)\le \Phi\left(  \left( A{{\sharp}_{v}}B \right){{\sharp}_{\mu }}A \right){{\sharp}_{v}}\Phi \left(  \left( A{{\sharp}_{v}}B \right){{\sharp}_{\mu }}B \right)\le \Phi \left( A \right){{\sharp}_{v}}\Phi \left( B \right)
\end{equation}
for $v,\mu \in \left[ 0,1 \right]$.
 Integrating the inequality \eqref{8} over $\mu \in \left[ 0,1 \right]$, we obtain
\begin{equation}\label{9}
\Phi \left( A{{\sharp}_{v}}B \right)\le \int_{0}^{1}{\Phi  \left(\left( A{{\sharp}_{v}}B \right){{\sharp}_{\mu }}A \right){{\sharp}_{v}} \Phi \left( \left( A{{\sharp}_{v}}B \right){{\sharp}_{\mu }}B \right) }d\mu \le \Phi \left( A \right){{\sharp}_{v}}\Phi \left( B \right).
\end{equation}
By virtue of \eqref{9}, we have
\[\begin{aligned}
 \frac{\Phi \left( A{{\sharp}_{v}}B \right)-\Phi \left( A \right)}{v}&\le \frac{\int_{0}^{1}{\Phi \left(  \left( A{{\sharp}_{v}}B \right){{\sharp}_{\mu }}A \right){{\sharp}_{v}} \Phi\left( \left( A{{\sharp}_{v}}B \right){{\sharp}_{\mu }}B \right) }d\mu -\Phi \left( A \right)}{v} \\
& \le \frac{\Phi \left( A \right){{\sharp}_{v}}\Phi \left( B \right)-\Phi \left( A \right)}{v}.
\end{aligned}\]
 It follows from the linearity of $\Phi$ that $\Phi \left( \frac{A{{\sharp}_{v}}B-A}{v} \right)=\frac{\Phi \left( A{{\sharp}_{v}}B \right)-\Phi \left( A \right)}{v}$. This completes the proof.
\end{proof}

We close this section by giving a complementary inequality of \eqref{13}.
\begin{proposition}\label{prop_2.2}
Let $A,B\in \mathcal{B}\left( \mathcal{H} \right)$ be two positive invertible operators such that $Sp\left( A \right),Sp\left( B \right)\subseteq J$ and let $\Phi :\mathcal{B}\left( \mathcal{H} \right)\to \mathcal{B}\left( \mathcal{H} \right)$ be a unital positive linear map. Then
\[\begin{aligned}
{{T}_{v}}\left( \Phi \left( A \right)|\Phi \left( B \right) \right)&\le \Phi \left( {{T}_{v}}\left( A|B \right) \right)+\left( \ln_v s-\ln_v t \right)\Phi \left( A \right) \\
&\quad +\Phi \left( tA{{\natural}_{v-1}}B-A{{\sharp}_{v}}B \right)+{{s}^{v-1}}\Phi \left( B-sA \right)
\end{aligned}\]
for any $s,t\in J$ and $v\in \left[ 0,1 \right]$.
\end{proposition}
\begin{proof}
It follows from the first inequality in Theorem \ref{10} that
\begin{equation}\label{17}
(\ln_v t)\Phi \left( A \right)+\Phi \left( A{{\sharp}_{v}}B-tA{{\natural}_{v-1}}B \right)\le \Phi \left( {{T}_{v}}\left( A|B \right) \right).
\end{equation}
This implies
\begin{equation}\label{17_01}
0 \le \Phi \left( {{T}_{v}}\left( A|B \right) \right) -(\ln_v t)\Phi \left( A \right)-\Phi \left( A{{\sharp}_{v}}B-tA{{\natural}_{v-1}}B \right).
\end{equation}
On the other hand, the second inequality in Theorem \ref{10} implies
\begin{equation}\label{18}
{{T}_{v}}\left( \Phi \left( A \right)|\Phi \left( B \right) \right)\le (\ln_v s)\Phi \left( A \right)+{{s}^{v-1}}\Phi \left( B-sA \right).
\end{equation}
Adding  \eqref{17_01} to \eqref{18},  we infer the desired inequality.
\end{proof}

\begin{remark}
For the limit of $v\to 0$ in Proposition \ref{prop_2.2}, we obtain the inequality:
$$
S(\Phi(A)|\Phi(B)) \leq \Phi(S(A|B))+\left(\log \frac{s}{t}-2\right)\Phi(A) +\Phi(t AB^{-1}A-s^{-1}B).
$$
\end{remark}

\section{another look at Tsallis relative operator entropy}
Entropies are usually defined by the use of logarithmic functions. They can be redefined by the use of exponential functions in artificially formal. We study relative operator entropies defined by exponential functions and give some operator inequalities for them.
We here use $v$-exponential function defined by $\exp_v(x):=(1+vx)^{1/v}$ for $x>0$ and $v \in [-1,0)\cup (0,1]$. The function $\exp_v$ is the inverse of $\ln_v$, and we have $\lim_{v\to 0}\exp_v(x) = \exp(x)$.

It is known that Shannon entropy is defined by logarithmic function as $H({\bf p}) =- \sum_{j=1}^n p_j \log p_j$ for probability distribution ${\bf p} =(p_1,\cdots,p_n)$, where $p_j \geq 0$ and $\sum_{j=1}^n p_j=1$.
Putting $p_j = e^{-s_j}$, we can rewrite $H({\bf p})$ as $H^{exp}({\bf s}) = \sum_{j=1}^n s_j e^{-s_j}$, with $s_j \geq 0$. For Tsallis entropy $T_v({\bf p}) = \sum_{j=1}^n p_j \ln_v\frac{1}{p_j}$ can be rewritten as $T_v^{exp}({\bf s})=\sum_{j=1}^n s_j \exp_{-v}(-s_j)$ with $s_j \geq 0$, by putting $\frac{1}{p_j} = \exp_v(s_j)$. Similar modifications happen for the relative entropy $D({\bf p}|{\bf q}) = \sum_{j=1}^n p_j (\log p_j -\log q_j)$ and the Tsallis relative entropy $T_v({\bf p}|{\bf q}) = \sum_{j=1}^n p_j^{1-r}(\ln_v p_j -\ln_v q_j)$, for probability distribution ${\bf q} =(q_1,\cdots,q_n)$, where $q_j \geq 0$ and $\sum_{j=1}^n q_j=1$. By putting actually $p_j=e^{-s_j}$ and $q_j=e^{-t_j}$, we can rewrite the relative entropy as $D^{exp}({\bf s}|{\bf t}) = \sum_{j=1}^n (t_j-s_j)e^{-s_j}$. Putting by $\frac{1}{p_j} = \exp_v(s_j)$ and $\frac{1}{q_j} = \exp_v(t_j)$, we can  rewrite the Tsallis relative entropy as $D_v^{exp}({\bf s}|{\bf t}) = \sum_{j=1}^n \left\{ \left(\frac{\exp_{-v}(-t_j)}{\exp_{-v}(-s_j)}\right)^vt_j -s_j\right\}\exp_{-v}(-s_j)$. We note that
$$\lim_{v \to 0} T_v^{exp}({\bf s}) = H^{exp}({\bf s})\quad  and \quad \lim_{v \to 0} D_r^{exp}({\bf s}|{\bf t}) =D^{exp}({\bf s}|{\bf t})$$ as known
$\lim_{v \to 0} T_v({\bf p}) = H({\bf p})$ and $\lim_{v \to 0} T_v({\bf p}|{\bf q})=D({\bf p}|{\bf q})$.

As we have seen some entropies can be written by  $\exp(x)$ and  $\exp_v(x)$ without $\ln(x)$ and $\ln_r(x)$.
However we give nothing for information theoretical insights for our quantities.
In this note, we just give mathematical inequalities for the relative operator entropies redefined by  $\exp(x)$ and $\exp_v(x)$.

We give scalar inequalities for the function $\exp_v(t)$ below.
\begin{lemma} \label{lemma01}
	Let $t>0$, then
	\[t\,{{\exp}_{{}^{v}/{}_{2}}}{{\left( t \right)}^{\frac{1-v}{2}}}\le {{\exp}_{v}}\left( t \right)-1\le \frac{t}{2} \left( 1+{{\exp}_{v}}{{\left( t \right)}^{1-v}} \right),\quad \left(-1\le v < 0\right),\]
	\[\frac{t}{2} \left( 1+{{\exp}_{v}}{{\left( t \right)}^{1-v}} \right)\le {{\exp}_{v}}\left( t \right)-1\le t\, {{\exp}_{{}^{v}/{}_{2}}}{{\left( t \right)}^{\frac{1-v}{2}}},\quad \left(0 < v \le 1\right).\]
\end{lemma}
\begin{proof}
	Consider the function ${{f}_{v}}\left( t \right)={{\left( 1+vt \right)}^{\frac{1-v}{v}}}$ where $t>0$ and $v \in [-1,0)\cup(0,1]$. We have that
	\begin{equation*}
	\left\{ \begin{array}{lr}
	f'{{'}_{v}}\left( t \right)\ge 0&\text{ }\left(-1\le v<0\right)\text{ } \\
	f'{{'}_{v}}\left( t \right)\le 0&\text{ }\left(0<v\le 1\right) \\
	\end{array} \right..
	\end{equation*}
	Now using the well-known Hermite-Hadamard inequality for convex (concave) function ${{f}_{v}}\left( t \right)$, we infer the desired result.
\end{proof}

Utilizing the definition of the $v$-exponential function $\exp_v(t)$ defined for $t>0$ and $v\in [-1,0)\cup(0,1]$, we can define
\[{{\mathcal{E}}_{v}}\left( A|B \right):= {{A}^{\frac{1}{2}}}{{\exp}_{v}}\left( {{A}^{-\frac{1}{2}}}B{{A}^{-\frac{1}{2}}} \right){{A}^{\frac{1}{2}}},\]
where $A,B\in \mathcal{B}\left( \mathcal{H} \right)$ are two positive invertible operators. It is easy to see that ${{\lim }_{v\to 0}}{{\exp}_{v}}\left( t \right)={{\exp}{(t)}}$. So we have
\begin{equation}\label{04}
{{\lim }_{v\to 0}}{{\mathcal{E}}_{v}}\left( A|B \right)={{A}^{\frac{1}{2}}}{{\exp}({{{A}^{-\frac{1}{2}}}B{{A}^{-\frac{1}{2}}}}}){{A}^{\frac{1}{2}}}=:{{\mathcal{E}}}\left( A|B \right)
\end{equation}

It is notable ${{\mathcal{E}}}\left( A|B \right)$ and ${{\mathcal{E}}}_v\left( A|B \right)$ are special cases for the perspective \cite{ENG2011,EH2014}.
Lemma \ref{lemma01} implies the following operator inequalities.
\begin{theorem}
	Let $A,B\in \mathcal{B}\left( \mathcal{H} \right)$ be positive invertible operators.
	If $-1 \leq v < 0$, then
	$$
	BA^{-1} \mathcal{E}_{v/2}(A|B)^{\frac{1-v}{2}} + A \leq \mathcal{E}_{v}(A|B) \leq A+\frac{1}{2}B +\frac{1}{2}BA^{-1}\mathcal{E}_{v}(A|B)^{1-v}.
	$$
	If $0< v \leq 1$, then
	$$
	A+\frac{1}{2}B +\frac{1}{2}BA^{-1}\mathcal{E}_{v}(A|B)^{1-v} \leq \mathcal{E}_{v}(A|B) \leq BA^{-1} \mathcal{E}_{v/2}(A|B)^{\frac{1-v}{2}} + A.
	$$
\end{theorem}

We also have  the following relations among four operators.

\begin{theorem}
	Let $A,B\in \mathcal{B}\left( \mathcal{H} \right)$ be positive invertible operators, then
	\begin{equation}\label{01}
	S\left( A|B \right)\le {{T}_{v}}\left( A|B \right)\le {{\mathcal{E}}_{v}}\left( A|B \right)\le \mathcal{E}\left( A|B \right),\quad \text{ }\left(0<v\le 1\right),
	\end{equation}
	\begin{equation}\label{02}
	\mathcal{E}\left( A|B \right)\le {{\mathcal{E}}_{v}}\left( A|B \right)\le {{T}_{v}}\left( A|B \right)\le S\left( A|B \right),\quad \text{ }\left(-1\le v<0,\,\,\,v\ne -\frac{1}{2}\right),
	\end{equation}
	where $S\left( A|B \right)$ and ${{T}_{v}}\left( A|B \right)$ are relative operator entropy \cite{03} and Tsallis relative operator entropy \cite{02}, respectively.
\end{theorem}
\begin{proof}
	The first inequality in \eqref{01} and the last inequality in \eqref{02} follows directly from \cite[Proposition 3.1]{01}. We know that for each $t>0$,
	\[\exp_v(t)\leq\exp(t),\quad \text{ }\left(0<v\le 1\right),\]
	\[\exp(t)\leq \exp_v(t),\quad \text{ }\left(-1\le v<0,\text{ }v\ne -\frac{1}{2}\right),\]
	these gives the last and the first inequality in \eqref{1} and \eqref{02}, respectively. On the other hand for each $t>0$,
	\[\ln_v(t)\leq\exp_v(t),\text{ }\left(0<v\le 1\right)\]
	\[\exp_v(t)\leq \ln_v(t),\text{ }\left(-1\le v<0,\,\,\,v\ne -\frac{1}{2}\right).\]
\end{proof}
\begin{theorem}
	Let $B\le C$. If $\frac{m-1}{v}A\le B\le \frac{M-1}{v}A$ with $0<m<M$, then
	\begin{equation}\label{05}
	{{\mathcal{E}}_{v}}\left( A|B \right)\le {{K}}\left( m,M,v \right){{\mathcal{E}}_{v}}\left( A|C \right),\quad \text{ }\left(v\in[-1,0)\cup(0,1]\right),
	\end{equation}
	where
	\[{{K}}\left( m,M,v \right)\equiv \frac{\left( m{{M}^{v}}-M{{m}^{v}} \right)}{\left( v-1 \right)\left( M-m \right)}{{\left( \frac{\left( v-1 \right)\left( {{M}^{v}}-{{m}^{v}} \right)}{v\left( m{{M}^{v}}-M{{m}^{v}} \right)} \right)}^{v}}>0.\]
\end{theorem}
\begin{proof}
	According to \cite[Theorem 1.5]{04},
	\[\left\langle {{\left( I+v{{A}^{-\frac{1}{2}}}B{{A}^{-\frac{1}{2}}} \right)}^{\frac{1}{v}}}x,x \right\rangle \le {{K}}\left( m,M,v \right){{\left\langle \left( I+v{{A}^{-\frac{1}{2}}}B{{A}^{-\frac{1}{2}}} \right)x,x \right\rangle }^{\frac{1}{v}}},\]
	holds for any unit vector $x\in \mathcal{H}$ and $v\in[-1,0)\cup(0,1]$.

	So we have
	\[\begin{aligned}
	\frac{1}{{{K}}\left( m,M,v \right)}\left\langle {{\left( I+v{{A}^{-\frac{1}{2}}}B{{A}^{-\frac{1}{2}}} \right)}^{\frac{1}{v}}}x,x \right\rangle &\le {{\left\langle \left( I+v{{A}^{-\frac{1}{2}}}B{{A}^{-\frac{1}{2}}} \right)x,x \right\rangle }^{\frac{1}{v}}} \\
	& \le {{\left\langle \left( I+v{{A}^{-\frac{1}{2}}}C{{A}^{-\frac{1}{2}}} \right)x,x \right\rangle }^{\frac{1}{v}}} \\
	& \le \left\langle {{\left( I+v{{A}^{-\frac{1}{2}}}C{{A}^{-\frac{1}{2}}} \right)}^{\frac{1}{v}}}x,x \right\rangle.
	\end{aligned}\]
	Whence
	\[{{\left( I+v{{A}^{-\frac{1}{2}}}B{{A}^{-\frac{1}{2}}} \right)}^{\frac{1}{v}}}\le {{K}}\left( m,M,v \right){{\left( I+v{{A}^{-\frac{1}{2}}}C{{A}^{-\frac{1}{2}}} \right)}^{\frac{1}{v}}}.\]
	Multiplying both sides by ${{A}^{\frac{1}{2}}}$ we deduce the desired inequality \eqref{05}.

\end{proof}

\section*{Acknowledgment}
The author (S.F.) was partially supported by JSPS KAKENHI Grant Number 16K05257.

\bibliographystyle{alpha}

redpajama_set_name: RedPajamaArXiv


text:
REVIEW: 'Better Things' - Max Agonizes Over How to Tell Sam About a Procedure She's Had in 'Oh, I'm Not Gonna Tell Her'
FX's Better Things - Episode 5.03 "Oh, I'm Not Gonna Tell Her"
Sam volunteers.
"Oh, I'm Not Gonna Tell Her" was written by Joe Hortua & Judy Gold and directed by Pamela Adlon
The kitchen is Sam's domain. It's her greatest expression of joy. Her kids know it's better to order food than make a mess in her space that she'll have to clean up later. And yet, the kitchen is invaded by Xander. He's the last person Sam would want there. She fears the worst. That's what she always does with him. It's a pattern she has been stuck in for awhile. It hasn't exactly been a healthy way for her to live. Her attempts to break the cycle haven't gone well either. As such, it's something that is always present. She loves venting about it to her friends. Their lives have moved on and grown though. They are annoyed she can still be stuck in this way. Sunny and Jeff have already gone through the whole array of emotions. They've gotten divorced as a result of Jeff's many heinous actions due to his addictions. They've resented each other while still trying to co-parent. They've moved on with respective love interests. They've both remained in Sam's life. They've acknowledged the great things the other has done lately. And now, they are seeing each other romantically again. All Sam can do is laugh. Jeff knows he just has to suffer through it and actually play towards the comedy. That's the best way to handle the situation. It was always going to be a struggle in telling her. Sunny wanted to hold off for as long as possible. Sam has a habit of pushing her way past the uncomfortable and into truth. It's a great skill she has. That makes her such an insightful director. She knows when things aren't playing well to the desired audience. But again, she is incredibly territorial. Bad energy sends her spiraling. That's all that Xander conjures at this point. He makes a delicious meal for the girls. He cleans up after himself. He leaves a plate for Sam to enjoy as well. No one would know he was in this space except for the documentation the girls provide. They see the precarious nature of him cooking. They taunt their mother with the footage too. They express glee from it. It's exciting. They recognize the importance. They soon move on with their lives. They fight with one another. Sam eventually makes it back home after a day volunteering. It's not rewarding or enriching work. She gets to spend a little bit of time with the kids in the community. She sees how little the world has actually changed and the impact that ultimately has on this young generation. She can't do much to make it better either. She simply opens a world of possibilities as they can be applied to jobs on TV and film sets. She understands the business. She knows the ins and outs. So much hope exists. She feels that on occasion. One wrong move is all it takes to drastically alter her mood though.
An uncomfortable conversation awaits Sam too. She will more than likely offer Max complete support upon learning she had an abortion. Max tightens up whenever someone asks about her day. She was sure of this decision. She has Rich to be there for her. She makes him a part of her secret. He doesn't want to keep things from Sam. He remains loyal to Max. That friendship is special. The girls know they can rely on Rich for anything. Their dad wanders in and out of their lives. Rich is always there. That has been a problem for him in the past with his own personal life. He has even wanted to put more distance in his friendship with Sam. He is still a reliable and constant presence in the house. He is always welcome. This secret lingers though. It brings out a fierceness in Max when interacting with her siblings. She knows when Frankie is being unreasonable and Duke is acting foolishly. She seeks to protect them. She can appreciate that while not wanting to become a mother right now. She doesn't have to explain herself. She knows she will have to offer more of the story when talking with her mom. She wants to delay that conversation for as long as possible. She knows she has to tell Sam eventually. She can't state she'll never tell her. She wants that freedom. She can't bear it though. That too weighs on her. She is surrounded by love and support. She doesn't need a reason to come home and spend time with her family. She loves her sisters. Sam doesn't have to justify the time she spends away from the family either. The girls are responsible enough so that she doesn't have to take care of them all the time. They frustrate her. The moods shift so quickly. Sam is guilty of that too. She was obsessed over her old baseball cards. She organized them into piles. All of that hard work can disappear in a second. Frankie exerts her own sorting system. She too seeks joy from this collection. Sam loses the special connection to it. She has her own projections onto this memory. It has become tangible once more. The cards are in her hands. She reflects. She's devastated when her perfection is disturbed. Her house is out of control. She can't accept the skull that has suddenly replaced the statue at the top of the stairs. The camera pointedly shoots that reveal from a new angle as well. It's suddenly a foreign and strange space. Those can still be discovered in this house despite the history it has for the family and the viewer. That takes a keen eye. It's being disturbed in a significant way. That disruption doesn't have to be bad. It's concerning for Sam because her order is no longer secure. That sets the stage for new qualities to be explored and cherished just as much. It's simply hard accepting how things have changed. The items that once brought comfort can evolve too even though they are seen as the same as they have always been.
Labels: Better Things , Episodic Reviews , FX

redpajama_set_name: RedPajamaCommonCrawl


text:
Home >> Bouvier's Law Dictionary >> Equal Protection Of The to Family Arrangement >> Family Arrangement
Family Arrangement
otherwise, children, benefit and rights
FAMILY ARRANGEMENT. An agree ment made between a father and his son, or children, or between brothers, to dispose of property in a different manner to that which would otherwise take place.
In these cases, frequently, the mere rela tion of the parties will give effect to bar gains otherwise without adequate consid eration. 1 Chitty, Pr. 67 ; 1 Turn. & R. 13 ; Boyd v. Robinson, 93 Tenn. 1, 23 S. W. 72; De Hatre v. De Hatre, 50 Mo. App. 1.
Such an arrangement may be upheld, al though there were no rights in dispute at the time of making it, and the court will not be disposed to scan with much nicety the quantum of the consideration ; L. R. 2 Ch. 294. It is said that a family arrange ment Is not by itself a valuable considera tion ; Brett, L. C. in Mod. Eq. 294. Wherever doubts and disputes have arisen with regard to the rights of different members of a family (especially when relating to legit imacy) and fair compromises have been en tered into to preserve harmony, they have been sustained, though, perhaps, resting upon grounds which would not have been consid ered satisfactory If the transaction had oc curred between mere strangers ; 2 Dr. & War. 503. The impossibility of estimating money considerations in family arrange ments has led to their exemption from the rules which affect other arrangements ; 7 Cl. & F. 280.
In ordinary cases a father's dealings with his child who has just come of age are open to suspicion, and so are dealings with a re versioner, but if these are in the nature of a family arrangement, the court will regard them, not with suspicion, but with favor ; 2 Giff. 232. It is not essential that the son
should have independent advice, nor will in quiry be made as to how far the father's in fluence was exerted. At the same time any unusual benefit secured to the father will be scrutinized and perhaps expunged ; 41 Ch. D. 200; and only the usual provisions should be inserted. It seems that resettlements un der a family arrangement will justify the ex ecution of a power under which the donee retains some benefit, which would otherwise be a fraud on the power. See 1 Swans. 129. An agreement between the children of a tes tator that the shares of the children shall be considered as vesting at the death of the testator divested of the survivorship clause contained in the will, will be upheld in equity; Ralston's Estate, 172 Pa. 104, 33 Atl. 273.
Evidence of circumstances to show a family arrangement at the execution of deeds is admissible, and a deed otherwise invalid would be good evidence if it formed a component part of such arrangement; Jourdan v. Jourdan, 9 S. & R. (Pa.) 268, 11 Am. Dec. 724. See FAMILY MEETING.
From "Bouvier's Law Dictionary and Concise Encyclopedia" by John Bouvier (1914)


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The other night I had a dream with a giant white swan in it. The swan made a nest and laid 71 eggs. In the dream I was trying to speculate at how many of the eggs would hatch. Random detail but the eggs were scattered around and were different sizes/shapes.
I woke up and was like WHAT DOES IT ALL MEAN?!?
Usually, I'm not one to place meaning to dreams because I think dreams are (usually) random compilations of your life but in sci-fi mode. But…something about the swan man. So I looked it up.
So basically, I had this swan dream and I'm going to be rich, happy and famous with new great ideas soon. Watch out y'all!
After I had this swan dream I noticed swans appearing throughout the day. I saw or read something about a swan on the internet/Instagram. They were mentioned in a podcast. I turned on a paused episode of Gilmore Girls and the first sentence they spoke was something about a swan! Coincidences be crazy!
2017 is now the year of the swan!
Have you had any prophetic dreams? I WOULD SERIOUSLY LOVE TO KNOW. EMAIL ME/COMMENT/USE TELEPATHY.


Drawing to be held on July 5th, at 8 PM CST. Winner to be notified via email.
Congratulations to our WINSDay winner: Savilsie Amos. We will contact you on how to receive those tickets.
Thank you to everyone who participated in the contest.


text:
Consolidation in Oligo industry and Growth for India based companies and outsourcing value proposition in Genomics and microarray/oligo industry
Posted on November 17, 2006 by Albin Paul
Ocimum Biosolutions acquires European based Oligo manufacturing company – Isogen Life Science
November 17, 2006, IJsselstein/Hyderabad – Ocimum Biosolutions, a leading provider of laboratory information management systems (LIMS), bioinformatics solutions, Microarrays and contract research headquartered in Hyderabad, India, has acquired the BioMolecules synthesis business of Isogen Life Science based in The Netherlands.
Ms. Anuradha Acharya, CEO of Ocimum Biosolutions said "We are very pleased to have taken a significant step towards becoming a global oligo player with the Isogen acquisition. We will continue looking for targets in related areas to scale up our oligo production capability. This acquisition will also help us become a more integrated genomics services provider with three delivery points in Indianapolis, IJsselstein and Hyderabad."
Mr. Hans Beijersbergen van Henegouwen, MD of Isogen Life Science said, "It is an excellent opportunity for the Biomolecules Division of Isogen Life Science to become a global player in this competitive business. The new business configuration will be much more flexible and will be able to play an important role in the vast growing demand for oligo nucleotides all over the world. Ocimum is the perfect partner for fulfilling a broad platform of needs in this market segment."
Avendus Advisors was the sole financial advisor to Ocimum for the deal. Commenting on the transaction, Shiraz Bugwadia, A.V.P., Avendus Advisors "Ocimum is one of the few Indian players within the BioIT and microarrays space to have scaled up successfully over the last couple of years. Ocimum has also been successful at using the inorganic route to scale rapidly by acquiring niche good quality companies in Europe such as MWG Biotech's division and now Isogen Life Science."
About Isogen Life Science:
Isogen Life Science (www.isogen-lifescience.com) is a leading supplier of products for the life science sector. The company provides a wide range of instruments, reagents and consumables in the areas of cell biology, molecular biology and biochemistry.
Isogen Life Science is a merger between B&L Systems (1987), the Benelux distributor for scientific instrument companies, and Isogen Bioscience (1988), a leading producer of DNA, RNA, peptides and related products, which are used around the world by pharmaceutical and biotechnology companies and leading research institutes.
About Ocimum Biosolutions:
Ocimum Biosolutions is a life sciences R&D enabling company with three main focus areas, BioIT, Microarrays and Contract research services. The US operations of the Company focuses on custom contract research services in the molecular biology area while the Indian operations provide BioIT services and Microarrays. Ocimum has more than 300 prestigious clients worldwide including the Centres for Disease Control, University of Toronto HIV clinic, National Research Council of Canada, Dow AgroSciences, Max Planck Institute etc.
Ocimum has adopted an inorganic strategy to ramp up the business fast and has demonstrated its capability to execute this strategy in the past. As a part of its strategy, Ocimum acquired a division of MWG Biotech, Germany in 2005. The Company has received a host of awards and recognitions. The Company has recently received the IT Innovation award by NASSCOM, presented by H.E. the President of India. Also, Red Herring magazine picked Ocimum as one of the eight compani es to watch in India. Deloitte ranked the Company as 4th Fastest growing Technology company in India and the Fastest growing Life Sciences Company in India.
For more information, please visit: www.ocimumbio.com
Filed under: bioinformatics, Blogroll, Consolidation in Oligo industry, ocimum biosolutions, Oligo, open source in microarray development, outsourcing, RNA, SNP analysis |	2 Comments »
standardization in microarray analysis software industry
scouting for the right software for the microarray analysis software , kept me thinkng why despite these software being used by scores or scientists no one has come forward to create what can be called as a standard for such software, the confusion rains in this field as one company's software data do not work with another one and vice versa, For an industry like biology and drug discovery that is trying to benefit from the knowledge of mathematics statitics and chemistry physics inability to port data across platform is a serious roadblock. there are standards such as MIAMe and MAGE but these are just data standards, not for softwares, I believe ther should be something similar to ISO standards, SEI CMI etc.
majority of the newsgroup and forums are used by graduate and at times senor researchers to find out which is the best software to be used, I thought of starting a wiki page where researchers can post their comments and rate the products and compare the features against each other,
Filed under: Affymetrix, analysis software, bioinformatics, bioinformatics software, bioinformatis software, cost efective custom array, custom microarray, india, microarray, microarray analysis, microarray analysis software, microarray software, open source in biotechnoligy, open source in microarray development, outsource, outsourcing, Uncategorized |	1 Comment »
can open source ideals begin to give a real answer to biotech's future
would it be possible to adopt the ideals of the open source in microarray development, there has been many research works that can be hailed as open source ideals in the biotechnology space, human genome project can be the perfect example, But apart from the few attempts by academia and non profits institutions there havnt been many attempts to look at this as a way forward, Microarray development can be termed as a lucrative field where such a coalition would accrue great benefits, By releasing the research works for others for free of cost it is possible to bring down the cost of microarray, there is no doubt that it would benefit the new research frontiers such as pharmacogenomics and toxicogenomics, by reducing the cost per array closer to any to other screening test currently adopted in hospitals or used by forensic labs. Microarray can also be used for reducing the costly PCR technique by closing in on a more focused number of genes to amplify from But it would mean that there has to be enough researchers out there who will be buying theses product in the first stage itself so as the company involved i such an audacious attempt would recover its cost and make profits to continue further work, thats a major hurdle to overcome, as custom microarray or at times even the existing one may not be useful to every researcher even if they are working on the same genome for example one person may be in toxicology research and the other in ecology or pure genetics even if they work on same genome the controls required and number of gene of interest would vary vastly across the spectrum, it may take a long time for the open source ideals to bear any fruit in this arena but that may be the way forward to bring meaningful results with less cost, till outsourcing can be a start for all things to come
Abin paul Xavier
http://www.ocimumbio.com
Filed under: Affymetrix, bioinformatics, bioinformatics software, bioinformatis software, Blogroll, cost efective custom array, custom microarray, india, microarray, microarray analysis, microarray software, open source in biotechnoligy, open source in microarray development, outsourcing |	Leave a comment »


text:
All Star Community Band
Every Saturday afternoon we come together and JAM!
Visually Impaired and Special Needs Program
Community Youth Development Institute
Music instruction and dance instruction during and after school.
Afterschool Matters
In partnership with Afterschool Matters, Music box Foundation provide a 6 week Summer Program at Collins High School on Chicago's Westside.
Year-long programs including marching band, jazz and concert band programs, choir and audio visual technology.
Music Box Foundation has 3 summer programs available to students of all ages.
We offer tailor made music programs to Chicagoland Schools, Park Districts and Communities where little to no programs currently exist. Programs take place before, during and after school hours.
We provide instruction and resources for all program types listed below
· General Music
· Instrumental Theory (Concert, Jazz, and Marching Bands)
· Vocal Theory
· Video/Audio Recording Technology
· Visually Impaired and Special needs
· Summer Camp
Our programs use music instruction as a means of expression, social connection and development. Students are taught in three specific areas: Instrumental Theory (learning to play instruments of the Brass, Percussion, Woodwind, Keyboard and String family), Voice Theory (how to use their voice as an instrument through basic music theory including scales, notes, rhythm, key signature and harmony) and Sound Recording Technology (how to mix audio and video tracks and create rhythmic beats).
Music Box Foundation ignites this passion for music through the 4E Endeavor:
Explore varying manners and methods in which music influence and affects students' lives. Through this exploration students recognize the scope and breadth of the musical landscape and their place in it.
Educate students in three specific areas of music theory, voice theory, and sound recording technology. Students receive lessons and direction from experts in the field as they work toward the completion of a cohort project. Students will receive instructions that will introduce them to instruments of the Brass, Percussion, Woodwind, Keyboards, and Guitar families. We will create a sound map for students to keep them involved where they will learn fundamental reading and notating music and performing with these instruments.
Expose students to many forms of music. Students will attend live performances and study the history of music types indigenous to the US (i.e. jazz, blues etc.). Students will gain exposure to marching and concert band traditions of HBCU through annual college tours as well as through participation in school activities and performances.
Empower students to make rational and informed decisions in pursuit of a career in music. We facilitate positive self-esteem and promote a sense of independence while providing peer interaction and sense of community.
Copyright © 2019 Music Box Foundation - All Rights Reserved.


text:
Q: Jupyter notebook and No module named 'bs4' I'm trying to use beautiful soup however the python kernel can't find it in jypter. When running:
!pip3 list
!pip3 install BeautifulSoup4
from bs4 import BeautifulSoup

I receive this error:
Package         Version
--------------- -------
beautifulsoup4  4.9.3
bs4             0.0.1
numpy           1.20.1
pandas          1.2.3
pip             21.0.1
python-dateutil 2.8.1
pytz            2021.1
setuptools      53.0.0
six             1.15.0
soupsieve       2.2
wheel           0.36.2
Requirement already satisfied: BeautifulSoup4 in /usr/local/lib/python3.9/site-packages (4.9.3)
Requirement already satisfied: soupsieve>1.2 in /usr/local/lib/python3.9/site-packages (from BeautifulSoup4) (2.2)
---------------------------------------------------------------------------
ModuleNotFoundError                       Traceback (most recent call last)
<ipython-input-11-c89f195c7568> in <module>
      1 get_ipython().system('pip3 list')
      2 get_ipython().system('pip3 install BeautifulSoup4')
----> 3 from bs4 import BeautifulSoup
      4 print("scapy time")
      5 for url in stillAlive:

beautiful soup is also installed outside of jupyter through pip

A: Jupiter notebook was not pointing at the correct pip packages. To resolve this I placed this at the top of my code:
import sys
sys.path.append("/usr/local/lib/python3.9/site-packages")

A: I think that the problem is with bs4 package: uninstall bs4 and try again. It overlaps with beautifulsoup4, and because of this you are getting an error.

A: I think this is the problem of the virtual environment. I had same problem and want to share one of the solutions.
Solution: Make sure when you run jupyter notebook in a virtual environment. There should be installed both jupyter notebook and BeautifulSoup. If they are missing, one of them in your existing environment won't be worked. Confusion raised because the default jupyter notebook launched in any virtual environment even though it hasn't been installed in the current working environment.
For instance:
Suppose default package pip list:
Package              Version
-------------------- -----------
argon2-cffi          21.3.0
argon2-cffi-bindings 21.2.0
asttokens            2.0.5
attrs                22.1.0
backcall             0.2.0
notebook             6.4.12

This is venv (Virtual Environment) (Missing notebook):
Package              Version
-------------------- -----------
argon2-cffi          21.3.0
argon2-cffi-bindings 21.2.0
asttokens            2.0.5
attrs                22.1.0
backcall             0.2.0
beautifulsoup4       4.11.1

When I run jupyter notebook in my venv, it run from the default package installed. Therefore, it give me following error:
from bs4 import BeautifulSoup

Traceback (most recent call last):
  File "/Users/lyons/Documents/scrape/scrape.py", line 2, in <module>
    from bs4 import BeautifulSoup
ModuleNotFoundError: No module named 'bs4'

After installation, of the jupyter notebook in venv. It fixed it

redpajama_set_name: RedPajamaStackExchange


The Irish Football Five's World Championships (F5WC) is a global initiative to select talented amateur football players through regional 5-a-side qualifying rounds around the world, to then compete in the World Finals in China in September of 2018. The tournament aims for mass participation amongst amateur football players, who play as amateurs whilst bringing together countries to celebrate the beautiful game.
In Ireland, Astropark and Inter7s.com have combined to bring you this amazing 5-a-side tournament with qualifiers all over the country. This is the largest small sided tournament in Ireland with the incredible prize of representing your country on offer.
- The Irish finals will bring together the top 32 teams from the nationwide qualifiers, in a one day tournament on [Date TBC] in Astropark Coolock, Dublin.
- The winning team will be crowned the Football 5s Irish Champions, with a top prize including flights, accommodation, full kit and all expenses paid for 7 players to the Shanghai World Finals.
- Cost per team is €129. Price includes qualifier, finals, vat and referee fees.
- Qualifying tournaments are round robin format through to knockouts. Minimum 3 games.


text:
Running with the Champ
My Forty-Year Friendship with Muhammad Ali
By Tim Shanahan
With Chuck Crisafulli
The "affectionate…charming" (Kirkus Reviews) story of Tim Shanahan's remarkable and little-known forty-year friendship with boxing legend Muhammad Ali, filled with stories never told as well as never-before-published personal photos.
In 1975, Tim Shanahan was a medical instruments salesman living in Chicago and working with a charity that arranged for pro athletes to speak to underprivileged kids. Muhammad Ali had just reclaimed his title as heavyweight champion of the world by defeating George Foreman (the "Rumble in the Jungle") and then successfully defended it in a rematch against Joe Frazier (the "Thrilla in Manila"). When Shanahan learned Ali was planning a move to Chicago, he contacted the Champ to ask whether he would participate in the charity program. Not only did Ali agree, he invited Shanahan to his new home, where the two spent a night talking, laughing, and bonding over bowls of ice cream—the beginning of an incredible friendship.
Ali soon enlisted Shanahan as his early morning running partner. Quickly, Shanahan became a trusted confidant and travel companion, and Ali often stunned strangers by introducing Shanahan as his cousin. The two grew even closer over family dinners with Shanahan's wife, Helga, and Ali's wife, Veronica. Shanahan was with Ali as the Champ trained for his legendary battles with Ken Norton, Earnie Shavers, Leon Spinks, and Larry Holmes, and moved to Los Angeles with Ali when the Champ prepared for a life after boxing. Shanahan was a recipient of and witness to Ali's tremendous generosity, and as Ali's health began to deteriorate, Shanahan had a chance to return the favor, encouraging and comforting his ailing friend.
Running with the Champ is an insightful personal portrait of the Greatest of All Time. But, above all, it is a touching, candid narrative of an extraordinary friendship that continued until Ali's death.
Running with the Champ ONE BACK TO PARADISE
AS I DROVE THROUGH THE security gates and into the community of luxury homes in Paradise Valley, Arizona, some very familiar feelings began to surge up once again. After all these years—nearly forty—those feelings hadn't ever really gone away. Steering the car toward a home back by the communal tennis courts, I thought about all that had been packed into those four decades: ups and downs, laughter and tears, one-of-a-kind moments and incredible adventures. The years could be measured in mansions and penthouse suites, Rolls-Royces and private jets, Hollywood encounters and Las Vegas events. But they could also be measured in quieter moments: morning runs, family dinners, late-night talks. Mostly it had been close to forty years of love, trust, and the deepest friendship I'd ever known.
I was here in Paradise Valley to visit my old friend Muhammad Ali. I pulled up in front of his home and couldn't help smiling. After all this time, the thought of spending a day with Muhammad still filled me with happiness and excitement. I felt the warmth and the joy that anyone might feel at the prospect of spending precious hours with a loved one. Even after all we'd been through, I still felt that our friendship was an incredible honor and privilege.
Back in 2005, Muhammad and his wife, Lonnie, purchased this second home in Paradise Valley and moved here from their longtime residence in Berrien Springs, Michigan. They hoped that the warmer, drier weather would help in Muhammad's ongoing battle with the symptoms of Parkinson's disease that had been slowly and steadily affecting him since his retirement from boxing in 1981 (he'd been officially diagnosed with Parkinson's in 1984, at the age of forty-two). In fact, the move had turned out to be extremely beneficial. The weather, intensive physical therapy, and a regimen of cutting-edge medications put Ali in the position he had been in many times in his career: the statistical underdog who astonishes everyone by battling back against a fierce opponent.
Of course, in the ring Ali was often able to finish off his opponents with a knockout. That wasn't the case now. The disease had weakened and stiffened his muscles, limiting his mobility and making speech difficult. The man who had once thrilled the press and the public with his loud, fast, funny rhymes and over-the-top braggadocio now spoke in a low, hoarse, barely intelligible growl, rarely getting out more than three or four words at a time. And on his bad days, the simplest of tasks was almost impossible without the assistance of Lonnie or her sister Marilyn, who worked as his live-in caregiver. But there were still plenty of good days, when despite his physical limitations, the twinkle in his eyes and the look of recognition and understanding told you he was still fully there: Muhammad Ali, three-time heavyweight champion of the world, and one of the brightest, wittiest, most beloved figures of our time.
Since his move to Paradise Valley, it had become much easier for me to see him. I was living in Southern California and working as regional sales manager for a medical products company. I oversaw eight distribution managers and more than three hundred sales reps across four western states, one of which was Arizona. It had been hard for me to get to Michigan, but now a couple of times a month I could find some reason to do business in Phoenix or Tucson, and whenever I set up those business trips I'd set aside a couple of days to spend time with Muhammad. As a business traveler, I wasn't very fussy. All I needed was a decent bed in a first-floor room, access to a business center, and a location that was easy to get in and out of. The accommodations were never important to me. What really mattered was spending as much time as possible with Muhammad without becoming an inconvenience to Lonnie or Marilyn. My wife, Helga, and I have always gotten along well with both of them and really appreciated the trust they extended to us. We didn't ever want to take for granted the fact that we had been allowed to remain an active part of Muhammad's life.
This particular trip had been thrown together quickly, so my visit with the Champ was going to be a surprise for him. I'd called Lonnie to make sure it was OK to come by, and she told me that while she'd be away for the day, Marilyn would be there with him and I could come by early and spend the entire afternoon with him.
IT'S ABOUT TEN A.M. AS I ring the bell at the front door of Muhammad's beautiful home. Marilyn greets me, shows me in, and tells me that Muhammad is still in bed. He's on some new medications and has been sleeping much later into the day. Marilyn is always completely focused on Muhammad's needs, and does a great job of making sure that his days are balanced between what he wants to do and what he's required to do as part of his ongoing treatment.
"I don't know what time he's going to get up," she says, "but yesterday it was noon."
It is actually good to hear that he is getting a good rest every night. As long as I've known Ali, he has been a chronic insomniac, and it has always been hard for him to get as much sleep as his body needed. He used to tell me that whenever he closed his eyes, he would start thinking about all the world's troubles and would stay wide awake figuring out how and where he might use his fame to help solve problems.
Muhammad is currently recovering from a medical procedure. He has recently had surgery on his throat to loosen his rigid vocal cords. The surgeon in Boston gave Lonnie and Marilyn high hopes that the surgery would release the pressure on Muhammad's larynx and trachea and would make it easier for him to swallow and speak. Marilyn tells me that she's been doing voice exercises with the Champ and that he is responding with enthusiasm. But it's still not clear whether the results of the surgery will be a brief relief or an ongoing success.
Marilyn walks me into the home's sunny kitchen, where Muhammad spends a good portion of his day. In the breakfast area there's Ali's throne—a high-end easy chair (with built-in vibrator), placed in front of a TV and DVD player that run almost constantly for Muhammad's benefit. He has a large library of favorite films, and as soon as one ends, Marilyn asks him what he wants to watch next. I am not at all surprised to see that the DVD currently loaded is a Clint Eastwood feature, The Good, the Bad and the Ugly. Muhammad loves westerns, and he always enjoys watching Clint, whom he first met back in 1969 in the greenroom of The David Frost Show. As Marilyn goes about her daily routine, I sit down at the breakfast table, pick up the remote, and start watching the film from where Muhammad left off.
After a while, Marilyn heads into Muhammad's bedroom to check on him. She comes back to tell me that he's awake and wants to get up, so she's going to help him get dressed. A few minutes later, he shuffles slowly into the kitchen with Marilyn at his side. Even on his bad days, he always wants to be fully dressed when he leaves his bedroom, and today he's in tracksuit pants and a knit T-shirt. But it does indeed look like this is one of his bad days—he has his eyes closed tightly and is letting Marilyn guide him to the kitchen table. I'm about to get up and help her, but she motions for me to stay seated. She helps him sit down, and puts his breakfast in front of him. With his eyes still closed and his head hanging down, he picks up his spoon and begins to eat.
I'm not terribly shocked, because I have seen this before. Light can bother some Parkinson's patients, and Muhammad will often keep his eyes closed to relieve the irritation. And sometimes—whether the light is bothering him or not—if he isn't feeling fully himself, he'll keep his eyes closed until he really feels ready to let the world in.
"Muhammad," says Marilyn in a cheerful voice. "Open your eyes. Somebody's here to see you, Muhammad. Open your eyes, Muhammad, you have a visitor."
I wait to see how long it takes for him to notice who's sitting at his table. I keep waiting for him to look at me but he doesn't look up. He just keeps his head down and continues to eat.
"Muhammad," I say softly. No response.
Marilyn speaks in an even quieter, gentler voice. "Muhammad, you have a surprise visitor. Open your eyes. Look who's here to see you."
Slowly, he lifts his head and focuses. His eyes light up and he makes a funny face at me—his "mocking" face. Then, he speaks.
"TIM SHANAHAN."
Now I am shocked. His voice is louder and clearer than it's been in years. It's loud enough that I'm actually knocked back in my chair. Marilyn is just as shocked, and almost instantly she has tears in her eyes.
"Muhammad Ali!" I shout back. "The heavyweight champion of the world! The Greatest of All Times! Muhammad Ali is saying my name. I haven't heard you say my name like that in twenty years. I don't even remember the last time I heard you say my name."
I'm smiling and laughing and looking at him across the table. He's looking straight back at me—his "mocking" face has shifted into a no-nonsense expression.
"Can you say that again, Muhammad?" I repeat my name for him.
"TIM SHANAHAN," he shouts back.
Now I'm a little choked up, too. In the earliest days of our friendship, this was his way of saying hello to me—booming out my name whenever he saw me, no matter where we were or who else was around. After a while, he stopped using the distinctive bellow and would just quietly say, "Shanahan," giving it a little emphasis as if it were a word from a magic spell. I knew from the start that he was certainly not the kind of friend from whom I was going to hear "Hi, Tim, how you doing?" or "Hey, Tim, what's going on?" and that was fine by me. I was very happy to get the occasional "Shanahan" mixed in with the more common "What's happenin'?" or "What it is?" But over the years, as it got harder and harder for him to speak, he just didn't say my name at all. He would simply find some other way to acknowledge me. I think it had been years since I had heard a "Shanahan" and probably decades since I had heard "Tim." Hearing my full name as loud and clear as he had shouted it was like taking a ride in a time machine.
Muhammad turns his attention back to his breakfast, and it doesn't look as though he's going to say anything more. That doesn't bother me at all.
"OK, Marilyn," I say. "If I die today, I'm a happy man."
I MET MUHAMMAD WHEN HE was the reigning heavyweight champ, and it hasn't been easy over the years to watch a man who had been such a perfect physical specimen become more and more dependent upon the care of others. He never surrendered his spirit to his physical problems, though, and anyone who knew Muhammad was not surprised that, through all his struggles, he maintained his dignity and his sense of humor. He made it clear to me that the last thing in the world he wanted was for people to pity him, and he had said to me many times, "Tell people I'm not suffering. I'm not in pain. I just get tired." He still appreciated what a unique, remarkable life he lived, and he didn't see any reason to view his circumstances in a negative way. I often thought of something he told me years ago when I asked him if he was satisfied with his life.
"I've lived the lives of a hundred men," he responded. "And I wouldn't do anything differently. My middle name is 'Controversy' and that's what made my life interesting."
As his illness progressed, Muhammad was always defying expectations. One day I would call him on the phone and could barely get a word out of him. Then just a few days later he'd be on the phone sounding sharp and responsive and would actually be initiating the conversation with prompts such as "Tell me about when we bought the Rolls in Chicago." I loved to retell our old stories to him, and on some of my visits we'd watch a DVD collection of his old interviews, some dating back to when he was just eighteen years old. I always got a kick out of hearing him hush the people around him because he wanted to hear once more how brilliantly "The Greatest" answered some decades-old question. In reliving those better days from the past, he could keep his mind alert and active.
Throughout his career, whenever he had obstacles to overcome or hard times to get through, his philosophy had been that the difficulties were challenges from God that he was expected to pass. To Ali, Parkinson's was simply one of the bigger tests he'd been faced with.
"God tests me every day that I wake up with my disease," he'd say, "and I pass the test every time."
With all that in mind, when I came to visit with him I made a point of treating him as I always had, never allowing his medical condition to come between us. I didn't put on an "act"—I just let the tone of our friendship be what it always had been—upbeat and full of humor. I'd talk the way I'd always talked to him, and I knew him well enough that I could speak his half of the conversation for him when I knew it would be too much trouble for him to respond. He'd told me that he actually preferred this form of communication, pointing out that it took him twice as much energy to respond as it did to listen. He'd rather listen intently than interrupt the flow of a story.
I know some people found it difficult or awkward to be around Ali now because they didn't know how to engage him. I never had a problem dealing with Muhammad's Parkinson's, maybe because I saw the disease develop from its onset over the years and knew what to expect each time I saw him. It helped that we had those decades of experiences to draw on, so when I launched into a story, I knew that he knew exactly what I was talking about.
Muhammad always loved getting gifts—any kind of gift—and ripped into a package like a kid at Christmas. I got into the habit of bringing a few special things along with me on my visits. I learned through Marilyn that Muhammad enjoyed playing any kind of board game that required mental agility and strategy. She was always buying new games to play with him, and I tried to find gifts that would give him pleasure but also challenge him. I sat with him for some very competitive hours of rolling dice and moving pieces, and was always happy to see that his will to win was not affected by his disease. He still loved showing off his ability to outthink an opponent, and when Marilyn or I lost a game to him, it was never on purpose. It was because he beat us.
I also always brought a big stack of eight-by-ten photos for us to look through. These would generally be all kinds of photos from our times together—shots from training camps, parties, family dinners, and get-togethers. I knew Muhammad still enjoyed the sight of a beautiful woman, so I'd make sure to include photos of him standing with such beauties as Sophia Loren, Lola Falana, Christie Brinkley, Bo Derek, and Diana Ross. When Helga and I first met Ali, he was with his third wife, Veronica Porche Ali, and within a couple of years they had two children, Hana and Laila. I had many pictures of Helga and me together with Muhammad, Veronica, Hana, and Laila, and Muhammad always seemed to enjoy these very much. Muhammad always wanted to hold all the pictures himself and go through them one at a time, deciding how long he wanted to look at each one (he tended to linger on pictures of the very beautiful Veronica). He would study them carefully and listen to me describe who was in the shot and where it was taken. I was always looking for signs of recognition, ready to give answers to whatever he might ask about. His most common questions were "How old is he?" "Where is he now?" "How many grandchildren?" "Is he still married?" "Is he still making money?" and "Is she still a fox?"
I might try to jog his memory once or twice, asking him if he remembered a particular day or place or person. If he didn't answer, I would move on.
"Sometimes I can remember thirty years ago but I can't remember three weeks ago," he would say—not as a complaint, just a statement of fact.
I would also bring Muhammad coffee-table books full of photos I knew he would like, though I had learned the hard way that these books often didn't last too long. Parkinson's patients can have a compulsion to engage in repetitive movements and one of the things that was very satisfying for Muhammad was tearing the pages out of books. He'd enjoy whatever the photos were, but with great concentration he'd rip them out, page by page, slowly and methodically. He was aware of what he was doing, and you could see that the tearing was soothing and relaxing for him. I never saw this ritual as the waste of a good book—I liked seeing Muhammad enjoy himself, and if tearing the books was what gave him pleasure, then so be it. I brought him some beautiful photo books of his favorite celebrities—Marilyn Monroe, Elvis, Sophia Loren, Cher, Clint Eastwood, the Beatles—and would actually look on with joy as he tore up each of them.
AFTER ALI FINISHES HIS BREAKFAST, we stay at the kitchen table and watch the rest of The Good, the Bad and the Ugly together. He grew up watching TV westerns such as Gunsmoke, Rawhide, Have Gun—Will Travel, and Wyatt Earp, and still loves anything that involves a showdown between the good guys and the bad guys. In addition to westerns, he is particularly fond of horror films—especially anything with Christopher Lee's Dracula—as well as films with great dance scenes (as an athlete who moved so well on his feet, he has a great appreciation for the grace of Fred Astaire and the athleticism of Gene Kelly, and he often said about them what people said about him: they made amazing moves look easy).
On this visit I've brought Muhammad two picture books—one on Marilyn Monroe and one on the Beatles. Not surprisingly, he asks to see the Marilyn Monroe book first. And by the time Clint Eastwood is staring down his opponents in the film's climactic "Mexican standoff," Muhammad has carefully torn half the Marilyn photos out of the book. I produce my usual stack of personal photos for him, and we start to go through them together. This time I've brought fifty or so pictures of Muhammad with some of his better-known celebrity friends.
"Do you remember him?" I ask.
"Travolta."
"Do you know who that is, Muhammad?"
"Kris." It's Kris Kristofferson, with whom Muhammad has had one of his longest-running Hollywood friendships. "Where is he now?"
"I think he's in his home on Maui, but he wants to come visit you again soon."
I show Muhammad a photo of him standing between Sir Paul McCartney and his then-wife, Heather Mills.
"Are they still married?" Muhammad asks.
"No, they got divorced."
"Was it bad?" he asks.
"Well, it was bad for Paul," I say. "It cost him a lot. But the good news is that it's a wonderful picture of you two. We can crop out the ex-wife and you and Paul will look terrific together."
Muhammad laughs his low, guttural laugh. Boy, do I love that laugh.
We work our way through the rest of the photos like that, and then he pulls out some of the shots of Veronica, Hana, and Laila and sets them aside—a sign that he wants me to leave these with him (I always leave all the photos with Marilyn anyway).
When we've made it through the pictures, Muhammad starts to get out of his chair. Part of maintaining his dignity comes in doing as much as he can for himself, no matter how long it takes. Marilyn is always there to help him, as am I, but we let him do whatever he can for himself. Now he stands, without my help, and begins to walk back toward the refrigerator. This is part of the routine of his day. He's gotten up and gotten dressed. He's taken his medicine and entertained his guest. Now he's earned a reward: ice cream.
He gets to the refrigerator, opens the freezer, selects a half-gallon container of vanilla, and sets it on the counter. Marilyn takes over and begins to scoop up a couple of bowls of ice cream. "Muhammad, you are one spoiled child. You get your way too much," she says, scolding him and granting his request at the same time. She has told me that the ice cream is not just a treat—it soothes his throat and makes it easier for him to swallow solid foods, and it is also an excellent medium for masking the taste of his medications.
Muhammad seems to be moving very well on his feet today, so I decide to ask if he can pull off one of his old magic tricks.
"Hey, Muhammad, can you still levitate?"
For as long as I've known him, Muhammad has had a fascination with magic, and over the years he has actually become fairly proficient at sleight-of-hand tricks. Muhammad once hired Terry Lasorda—a very talented magician and the nephew of the former Dodgers manager Tommy Lasorda—to move into his training camp so that he could learn new tricks as he prepared for a fight. Mostly Muhammad stuck with card tricks, but he had one larger classic illusion he loved to show people. He would angle himself with his back to a group of observers, and then, while holding his heels tightly together, would lean all of his weight on the toes of his right foot. He could then bring both heels up while balancing his body so that he appeared to be floating. I'd seen him mystify groups of fans with the trick many times, though just as often people seemed to assume he was showing off another of his natural abilities: He's Muhammad Ali—of course he can levitate.
This illusion is a hard move to pull off for a fit athlete, let alone a seventy-year-old man with Parkinson's. But, with some encouragement from Marilyn, Muhammad goes for it. He places one hand on the kitchen counter, one hand on my shoulder, and somehow manages to get all his weight on the toes of one foot so that he is up in the air for several seconds. I love it—in some ways the fact that he can still pull off a levitation is as wonderful as hearing him say my name so clearly and loudly. I make a fuss over the fact that he can still float like a butterfly, and ask if he can still "sting like a bee." He flicks a couple of quick, accurate jabs just shy of my face, then digs into his ice cream.
I have never had much of a sweet tooth, but for as long as I've known Muhammad, ice cream has been his main vice and a constant source of pleasure. And when Muhammad eats ice cream, he likes to see that you are sharing that pleasure with him. I couldn't possibly count the number of scoops of chocolate and vanilla I have eaten alongside Muhammad through the years. Today, I have another bowl of ice cream with the Champ.
I stay awhile longer, just joking around with Muhammad and going over some of our favorite stories. I don't ever really feel ready to leave Muhammad, but there always comes a time when it is clear that he's had enough activity for the day. There's never any big deal about my leaving—no "Thanks for coming" or special goodbyes. I don't need that. I always want to be confident that this will not be the last time I see my friend, and I want our goodbye to be as happy and easy as our goodbyes always have been.
I tell him it's time for me to leave and, as always, he puts both of his hands on the arms of the chair—he wants to get up and see me to the door. I go to his chair and kneel down next to him before he makes the effort to get up. I put my arm over his shoulders behind his neck and give him a kiss on the left cheek. Then I say what I always say at the end of our visits: "I love you, Champ."
And he says what he always says in these situations: "Maaaan . . ."
THERE HAVE BEEN TIMES WHEN I drive away from a visit with Muhammad feeling sad, mostly because my time with him has come to an end and I don't know when I will see him again. Even though I know he is being well cared for by Lonnie and Marilyn, I often can't help but worry about what his days are like when he doesn't have a visitor to break up the routine. He is the man responsible for the most exciting times in my life, and though his body has slowed, I know his amazing mind is still active. I hate the idea of him being alone, far from so many of the family members and friends who love him. After many of my visits, I find myself hoping that Muhammad still wants to be here. I hope that his moments of joy can still balance out the moments of pain.
Leaving his home this day, though, I do not feel sad. On the way from Muhammad's house to the airport, I am focused on all the amazing moments of our thirty-eight years of friendship, and I am grateful that I have just been able to spend a few more cherished moments with my friend. As I think about our friendship, I am aware that my own name is ringing in my ears. It's ringing that way because Muhammad Ali has shouted it out, loud and clear, and that has me beaming with happiness, hope, and love. I concentrate on that wonderful sound and as I do, it feels as if thirty-eight years have just melted away.
Photograph by Hana Yasmeen Ali
Tim Shanahan
Tim Shanahan has been a close and trusted friend of Muhammad Ali and his family for nearly forty years. He retired in 2013 as regional sales manager covering five Western states for a medical products company. Running with the Champ is his first book.
Publisher: Simon & Schuster (May 30, 2017)
Sports & Recreation > Boxing
Biography & Autobiography > Personal Memoirs
Biography & Autobiography > Sports
"When I heard that Tim Shanahan was writing a book about Muhammad Ali I was excited, because for the first time we'd get a chance to look at the Champ from the perspective of a real friend. In the years that I have spoken to Tim, it seems that we never run out of stories about the Great Ali. Tim has taken the term 'brother' to another level; no one has been as close to the Champ as Tim Shanahan. Read with me and celebrate true friendship."
– George Foreman
"Oh my! This is the reader's opportunity to get inside the ropes with 'The Greatest.' Tim Shanahan's book is a knockout read, offering rare insight into the man regarded as the most powerful and prominent athlete of his time."
– Dick Enberg
"Of all of his great achievements in life, from champion prizefighter to goodwill ambassador to instrument of hope for the underprivileged, it is quite lovely to learn that Muhammad Ali was also a devoted friend. In his affectionate memoir of their long and durable bond, Tim Shanahan reminds us of a sometimes overlooked aspect of The Champ—that in stride with the wonderful talent and wild antics that kept us so entertained walks a man of profound decency."
– Mark Kram, Jr., author of the PEN Literary Award-winning Like Any Normal Day
"An affectionate portrait of boxing legend Muhammad Ali. . . . Charming moments abound. . . . If you're wondering why Ali is called 'The Greatest,' this . . . pleasant memoir makes for a good place to start."
– Kirkus Reviews
"An engrossing story…of an enviable friendship. … Shanahan comes off as a likable guy…it's easy to understand why the fighter allowed him into his inner circle."
"Shanahan presents a complex but less bombastic person than is popularly associated with the name; generous to a fault, devoted to his religion and…family, and a champion of the less fortunate. This view of a fabled boxer from the unusual angle of friendship offers justification beyond the boxing ring for calling Ali 'The Greatest.'"
"If you thought you knew about the life of Muhammad Ali, think again. His best friend—unknown until now to all but Ali's closest insiders and family members—gives us new insight into Ali's thoughts, hopes, dreams and fears. Awesome!"
– Larry Elder, host of the nationally syndicated "The Larry Elder Show"
Book Cover Image (jpg): Running with the Champ
Author Photo (jpg): Tim Shanahan


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Samuel Stupp, Ph.D.
For the development of bioactive and self-assembling supramolecular biomaterials for regenerative medicine
Researchers develop new materials for energy and sensing
Via MIT | July 16, 2020
A team of researchers from MIT and Northwestern University has demonstrated the ability to fine-tune the electronic properties of hybrid perovskite materials, which have drawn enormous interest as potential next-generation optoelectronic materials for devices such as solar cells and light sources.
The materials are classified as "hybrid" because they contain inorganic components like metals, as well as organic molecules with elements like carbon and nitrogen, organized into nanoscale layers. In a paper published online this week in Nature Chemistry, the researchers showed that by strategically varying the composition of the organic layers, they could tune the color of light absorbed by the perovskite and also the wavelength at which the material emitted light. Importantly, they accomplished this without substantially changing the inorganic component… Continue reading.
Sam Stupp elected to the National Academy of Sciences
Via Northwestern University | April 28, 2020
Three Northwestern University faculty members — mathematician Laura DeMarco, engineer Yonggang Huang and materials scientist Samuel Stupp — have been elected to the prestigious National Academy of Sciences. Membership in the academy is one of the highest honors given to a scientist in the United States.
DeMarco, Huang and Stupp are among 120 new members and 26 new international members elected this year in recognition of distinguished and continuing achievements in original research. They will be inducted at the academy's annual meeting next year.
Samuel Stupp
Stupp is Board of Trustees Professor of Materials Science and Engineering, Chemistry, Medicine, and Biomedical Engineering in McCormick and Weinberg College.
Stupp's work integrates chemistry with materials science, biology and medicine. The overarching interest of his research group is the development of self-assembling organic materials, focusing on functions relevant to energy and medicine. One of his landmark achievements was the development of bioactive materials that can signal cells and be used in novel therapies for regenerative medicine.
He is a member of the National Academy of Engineering, the American Academy of Arts and Sciences, the Spanish Royal Academy, and the National Academy of Inventors, and a fellow of the American Physical Society, the Materials Research Society, and the Royal Society of Chemistry.
Stupp directs the Simpson Querrey Institute and its two affiliated research centers, the Center for Bio-Inspired Energy Science and the Center for Regenerative Nanomedicine… Continue reading.
Peptide Therapies Could Disable Coronavirus' Spike Proteins
Nanostructures could safely deliver a notoriously fragile drug to virus
Researchers are developing new peptide-based therapeutics for targeting and disabling the coronavirus' so-called "spike proteins."
Spike proteins — the crown of bulbous projections that give the coronavirus its signature halo effect — attach to and infect healthy cells, causing COVID-19. Led by Northwestern University and Massachusetts Institute of Technology (MIT), the research team is engineering a new nanostructured therapy that could potentially disable the virus and prevent its infection of human cells.
The idea is based on a recent discovery from the laboratory of Bradley L. Pentelute, an associate professor of chemistry at MIT. Pentelute's team discovered a peptide molecule that specifically and strongly binds to the coronavirus' spike protein… Continue reading.
New Technology to Manipulate Cells Could One Day Help Treat Parkinson's, Arthritis, Other Diseases
Via Northwestern University | July 10, 2017
DNA strands in materials act like traffic signals to start, stop cell activity or regenerate tissue
A groundbreaking advancement in materials from Northwestern University could potentially help patients requiring stem cell therapies for spinal cord injuries, stroke, Parkinson's disease, Alzheimer's disease, arthritic joints or any other condition requiring tissue regeneration, according to a new study.
"It's important in the context of cell therapies for people to cure these diseases or regenerate tissues that are no longer functional," said senior author Samuel I. Stupp, director of Northwestern's Simpson Querrey Institute for BioNanotechnology and Board of Trustees Professor of Materials Science and Engineering, Chemistry, Medicine and Biomedical Engineering.
The study was published today, July 10, in Nature Communications.
Cells in our bodies are constantly being signaled with many types of instructions coming from proteins and other molecules present in the matrices that surround them. For example, these can be cues for cells to express specific genes so they can proliferate or differentiate into several types of cells leading to growth or regeneration of tissues. One of the marvels of this signaling machinery is the built-in capacity in living organisms to make signals stop and re-start as needed, or to switch off one signal and activate a different one to orchestrate very complex processes. Building artificial materials with this type of dynamic capacity for regenerative therapies has been virtually impossible so far.
The new work published today reports the development of the first synthetic material that has the capability to trigger reversibly this type of dynamic signaling. The platform could not only lead to materials that manage stem cells for more effective regenerative therapies, but will also allow scientists to explore and discover in the laboratory new ways to control the fate of cells and their functions… Continue reading.
Samuel Stupp, Ph.D. To be Inducted into Medical and Biological Engineering Elite
WASHINGTON, D.C.— The American Institute for Medical and Biological Engineering (AIMBE) has announced the pending induction of Samuel Stupp, Ph.D., Board of Trustees Professor of Materials Science and Engineering, Chemistry, Medicine, and Biomedical Engineering, Director Simpson Querrey Institute, Director Center for Bio-inspired Energy Science, Materials Science and Engineering, Chemistry, Medicine, and Biomedical Engineering, Northwestern University, to its College of Fellows. Dr. Stupp was nominated, reviewed, and elected by peers and members of the College of Fellows For the development of bioactive and self-assembling supramolecular biomaterials for regenerative medicine.


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Q: 'Create a Campaign Conversion' linkedin API giving 'is not a Compound key' error with status 400 I am new to using linkedin APIs and all I am trying to do is use this API to create a campaign conversion, by making a PUT request through this API
https://api.linkedin.com/v2/campaignConversions/(campaign:urn%3Ali%3AsponsoredCampaign%3A337643194,conversion:urn%3Alla%3AllaPartnerConversion%3A70203)
However, I receive an error of the form 'is not a compound key' with status 400.
Any ideas on how to resolve it?
Linking official docs below for reference--
https://learn.microsoft.com/en-us/linkedin/marketing/integrations/ads-reporting/conversion-tracking?tabs=https#create-a-campaign-conversion


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Business Administration Schools
In Port Huron, Michigan
The city of Port Huron has 2 schools where business administration faculty can find employment. The trends in Port Huron's business administration academic community can be evaluated by looking at the statistics and graphs below, which includes business administration training at the following levels:
Port Huron Vs. Michigan Business Administration Employment
Port Huron 12,520
Michigan 46,360
Exactly 12,520 of the 46,360 business administration professionals employed in Michigan, work in Port Huron. Between 2006 and 2010, in Port Huron, there has been a 6% decline in the number of business administration professionals. As the number of business administration professionals in Port Huron has decreased, overall employment in Port Huron has increased.
Port Huron Vs. Michigan Business Administration employment growth
Grey: Michigan
Dark Yellow: Port Huron
Business Administration VS. All professions salaries in Port Huron
$93,240 $93,645 $90,990 $99,165 $103,000
Light Blue: Business Administration in Port Huron
Dark Yellow: All Professions in Port Huron
In Port Huron, salaries for business administration professionals have increased. In 2010 an average salary of $103,000 per year was earned by business administration professionals in Port Huron. Four years earlier in 2006, the average salary for business administration professionals in Port Huron was $93,240 per year. The growth in the salary of business administration professionals in Port Huron is slower than the salary trend for all careers in the city.
Salary percentiles for Business administration professionals in Port Huron
Business administration professionals in Port Huron make a median yearly salary of $87,365. The 10% of business administration professionals in the lowest pay bracket earn less than $43,880 per year, while those in the highest pay bracket earn approximately $153,370 per year.
Average Salaries for Business administration professionals and related professions in Port Huron
Human Resources $38,290
Project Management $79,344
Public Administration $95,795
Business Administration $103,000
Business Management $111,564
MBA $149,570
On average business administration professional salaries in Port Huron are higher than salaries earned by their professional counterparts in related professions.
Business Administration schools in Port Huron
There are 2 accredited business administration schools in the city. Many of Port Huron's business administration professionals are graduates of one of these schools.
Business Administration Programs Offered In Port Huron
Port Huron's business administration schools offer 5 business administration degree and certificate programs.
Student Completed Business Administration Degrees In Port Huron
In 2010 approximately 57 students completed business administration courses.
Business Administration Faculty Salaries in Port Huron, Michigan
The number of business administration faculty, growth in the field of business administration academia and business administration faculty salaries in Port Huron, is all data we are currently in the process of collecting. If you are involved in teaching business administration courses to students at the certificate in business administration, associates degree in business administration, and bachelors degree in business administration levels, please anonymously submit your information in the field below. By doing so, you will be helping us build a valuable database resource for the benefit of current and future business administration faculty in Port Huron. A summary of the data collected thus far will be available to you once you have submitted your information.
Michigan Schools
Michigan Business Administration Schools
Business Management Schools in Port Huron
Human Resources Schools in Port Huron
MBA Schools in Port Huron
Business Administration Schools in Clinton Township, MI
Business Administration Schools in Warren, MI


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