text:
Grange Hill's Lee 'Zammo' MacDonald: "I gave Nancy Reagan a copy of Just Say No. She threw it under her chair"
The man who was Zammo tells Paul Kirkley about life at Grange Hill, meeting Nancy Reagan, the accident that derailed his career and why he's now happy to be a locksmith first and an actor second...
By Paul Kirkley
Monday, 21st December 2015 at 2:35 pm
This article was first published in December 2015
Who are the greatest Grange Hill characters of all time?
Like your choice of Doctor Who, the answer to that question probably depends on when you were born. For many, it will be the original intake of Tucker, Trisha, Benny and co; if you're a bit younger, you might look back fondly on the Danny Kendall versus Mr Bronson years. But BBC4 has made its choice: this week, as part of an evening celebrating classic children's TV, the station has opted for a 1986 Grange Hill episode focusing on Samuel "Zammo" McGuire and Roland "Row-land" Browning.
"It's great news," says Lee MacDonald, who played Zammo for five years between 1982 and 1987. "Erkan rang me to tell me it's on, and we're really excited." Erkan is Erkan Mustafa, who played Row… sorry, Roland. After 30 years, the pair are still good friends who speak to each other most weeks.
You can understand the BBC's thinking: over three decades, hundreds of pupils passed through TV's most famous comprehensive school, but only one – Zammo – made real-life headlines (including a Newsround Special, no less), inspired a hit single and secured himself and his cast-mates an invitation to meet Nancy Reagan at the White House. More on all that later.
MacDonald's route to Grange Hill has a sad story behind it: as a child, he'd been badly affected by the death of his older sister, Karen, who had been disabled since birth. "It knocked me for six," he says. "At primary school I was very quiet – I didn't really mingle or talk to people."
To help build his confidence and social skills, a teacher recommended he try evening classes at the local Anna Scher community theatre school in North London, which led to "bits and pieces" of TV work, including playing Mike Reid's son in a children's drama called Noah's Castle. But when he suggested joining his Anna Scher classmates Susan Tully and Mark (Stewpot) Burdis in auditioning for Grange Hill, his mother put her foot down, insisting he couldn't afford to take time out of his first year at secondary school.
Twelve months later, satisfied his academic career was on track, his mum agreed to let him try out for a part (though she later got a job as an on-set chaperone in order to keep an eye on him). "They were looking for two characters, Jonah and Zammo," recalls MacDonald. "Jonah was the good looking one with all the chat, and I was the beefy sort of one; I turned up with a skinhead, and I did boxing, and I just fitted the role."
Was he already a fan? "Oh god yeah. I loved it. I can remember running home to watch it when Tucker was in it. I was a massive fan."
One of his first scenes, as it turned out, was with Todd Carty, making one of his final appearances before heading off for his own spin-off show, Tucker's Luck. "That was amazing. To be in a scene with him, at that time, was unbelievable. He was like my icon. Suddenly being in Grange Hill and working with Todd, it was unreal."
After just one episode, the 13-year-old found he couldn't walk down the street without being recognised – and admits he "loved every minute of it". "The worst years, when you're growing up, are probably 14 to 18, when you're shy and it's all a bit awkward," he reflects. "But because of Grange Hill, that was all different. I remember going to a museum with my school, and getting chased by all the girls from a girls' school. The security guard said, 'Sorry, he's going to have to leave,' and I was escorted outside. When you're 14 or 15, being chased by girls… well, let's just say I'd love it to happen now."
He enjoyed being part of the Zammo-Jonah double act, but when Lee Sparke left because his parents wouldn't agree to his character drowning in a swimming pool (a fate that eventually befell Jonah's cousin, Jeremy), Zammo was paired with a girlfriend instead.
Jackie Wright (Melissa Wilks) was the object of many a schoolboy crush (or, er, so RadioTimes.com understands) – and it turns out MacDonald was no exception. In fact, he virtually got to handpick his love interest himself.
"She was at Anna Scher's with me, and I used to fancy the pants off her," he reveals. "Even before we did Grange Hill, I used to check she was going to be in my lessons and stuff. So when they asked me if there was anyone I'd like to play my girlfriend, I said 'She's brilliant, get her.'"
"I used to check the scripts to make sure she was in them, and for years I'd get butterflies in my tummy when she was coming in. I had a real big crush on her."
Presumably he kept a keen eye out for kissing scenes… "Oh yes. I remember there was one in a lift once. I used to love scenes that were just me and her, because I knew then I had her full attention. I was smitten, absolutely smitten."
But the romance never spilled over into real life? "No, no, I was too nervous to ask her out. I was petrified. And then we worked together so long, we just became really good friends."
In 1986, Zammo suddenly changed from being a loveable scamp to a shifty, thieving wrong 'un only too happy to sell his mates – and even the lovely Jackie – down the river. Then, in scenes that shocked the nation, Roland discovered his friend slumped in an amusement arcade toilet in a dead-eyed heroin stupor.
The BAFTA-winning storyline had been developed as part of the BBC's Drugwatch campaign by the late Anthony Minghella, who served as Grange Hill's script editor before finding fame as the Oscar-winning director of The English Patient and The Talented Mr Ripley.
"Anthony spoke to my parents and said they were going to do this drugs story," MacDonald recalls. "At the time, I wasn't really aware of drugs at all. It was only when we started going to rehabilitation centres for research that I realised what it meant. It was good for me as an actor, I really enjoyed doing it."
Initially, MacDonald tells RadioTimes.com, the producers had planned to kill Zammo off, before having a change of heart. Even so, the story had a powerful effect on viewers. "That pan-out, with no music, where I was sort of overdosed in the toilet, was really hard-hitting – especially at five past five in the afternoon on a children's show."
To help raise awareness of the issue, it was decided the cast should release a charity single, Just Say No – a cover version of a song previously recorded by La Toya Jackson as part of an anti-drug campaign in America. Except the kid at the centre of it all wasn't actually allowed to sing on it.
"They took me off to a room and asked me to sing a few lines," recalls MacDonald. "And the woman slammed the piano lid down, stood up and said, 'Okay, you won't be singing on the record'. I was mortified. So I don't sing on it, and I can't dance either, which is why I'm doing weight training in the video."
The single caught the attention of the people behind the original US Just Say No campaign – named in honour of Nancy Reagan's advice on how schoolchildren should respond if offered drugs – which is how a handful of Grange Hill pupils found themselves being flown across the Atlantic, performing at New York's Yankee Stadium and, surreally, meeting the First Lady herself at the White House.
"I gave her a copy of the record, which she swiftly threw underneath her chair," laughs MacDonald. "I didn't really appreciate it at the time but, looking back, you realise what a massive thing it was to do. It was just mad."
In recent years, it has mischievously been suggested that some of the cast may have undermined the anti-drugs message by smoking funny fags in the Presidential residence, but MacDonald is having none of it. "Honestly, if you've ever been to the White House, there's a security guard following you everywhere – even to the toilet – and if they smelled puff… It's just not even feasible. And my mum was there!"
Did the Americans know who they were? "They didn't have a Scooby!" he laughs. "I remember they organised a press conference in the hotel. There about 60 chairs, and only two people turned up. No-one had a clue who we were."
Eventually, it was time for a now clean and sober Zammo to move on from Grange Hill and make his way in the world. Was MacDonald sorry to go?
"You knew it was coming, obviously. And I had no intention of being an actor – I wanted to box. But the last day was really, really sad. It had been part of my life for a long time."
Boxing had been part of his life for even longer: it was another activity he'd been encouraged to take up to help him cope with losing his sister. For a while after Grange Hill, he was a real contender, winning the Junior ABA, boxing for London and even being tipped as a future Olympian. But, just as he was on the verge of turning pro, his van was hit by a car being chased by the police; both people in the car died, and MacDonald was thrown 47 feet through the windscreen. He needed 43 stitches in his head, and suffered serious concussion. It was the end of his boxing career.
"Even months afterwards, I remember going into a garage and I couldn't work out the change from a pound," he recalls. "I went home to my dad and cried, because I couldn't focus properly. It was soul-destroying. It put me out for about two years before I was back to normal."
Through his dad, he'd got a job working for a locksmith's. It was only supposed to be temporary, until he'd established himself as a professional boxer but, after the accident, he ended up staying for "years and years and years".
"I remember getting a call saying John Alford [who played his Grange Hill contemporary Robbie Wright] was in London's Burning, and that felt like a real blow. I was like, 'Christ, what am I doing working here?'. Then when I was about 28, I met a girl and she said, 'What are you doing with your life? You're working in a warehouse, you need to sort yourself out. When you've done that, come back to me.'
"So I did. I used a bit of money I'd saved up from Grange Hill to buy a flat, and I got a new job. Then," he says with a rueful chuckle, "I phoned her up about a year later and she said, 'Nah, it's alright, I'm getting married'."
Still, it was the kick up the backside he needed. In 2000, he bought his own locksmith and key-cutting shop in South London, where being the bloke who used to be Zammo has proved useful: having spent a long time trying to distance himself from the role, these days he has a picture of his younger self, resplendent in his Grange Hill uniform, in the shop window, while his website advises customers to 'Choose the best – and Just Say No to the rest'.
"It gets me work," he says. "Estate agents ring me up and say, 'Is that Zammo? Can you do a job for us?' It's great."
Now, at 47, MacDonald is only too happy to do interviews and public appearances – often with his mate Erkan – and is back in touch with several of the old Grange Hill gang through Facebook. He's also done various reality shows, including Sky's Cirque de Celebrité and BBC3's Celebrity Scissorhands, and tells RadioTimes.com he'd "jump at the chance" to be in the I'm A Celebrity jungle. He's even got himself an agent and started picking up the odd bit of acting and presenting work, including fronting a property show for Sky.
"My agent wants me to drop the shop," he says. "She says I should try and push myself as an actor and not a locksmith. But I'm quite happy to say I'm a locksmith, 'cos that's what pays the mortgage!"
Today, MacDonald lives with his partner, Jess, who he met on a dating website, his son Harry and Jess's daughter, Katie, both 7. He seems relaxed and chirpy, and says life is good. So how long did it take him to 'fess up to Jess that he was Zammo?
"Well… I've got to be careful what I say here," he laughs. "Jess comes from quite a posh family – who are lovely, but I'm not sure they watched Grange Hill. So she didn't really know who I was. Even now, she finds it really weird when people say hello or ask for selfies."
As for MacDonald, he'll happily pose for as many selfies as people want. "For years I hated it," he admits. "Until I was in my late 20s or early 30s, I didn't want to be associated with Grange Hill. But not now. I've got so many good memories of my time on the show. I loved every minute of it."
Peter Duncan: "Blue Peter was never middle class. What did they expect us to do, film it in a sweatshop?"
Live and Kicking's Trevor and Simon: "Looking back, we're a little bit surprised at some of the things we got away with"
All about Grange Hill
News, photos, videos and full episode guide
Johnny Ball: "I had to research everything for my shows… I'd only got two O-levels!"
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text:
Q: Nth largest element in a binary search tree How to find the Nth largest node in a BST?
Do I keep a count variable while doing In Order Traversal of a BST? Return the element when the count = N???

A: See my answer here. You can do this in O(log n) on average where n = number of nodes. Worst case is still O(n) IF the tree isn't balanced (always O(log n) if it is balanced however). In order traversal is always O(n) however.

A: The idea is very simple: traverse the tree in decreasing order of the values of each node. When you reach the Nth node, print that node value. Here is the recursive code.
void printNthNode(Node* root, int N)
{
   if(root == NULL)
       return;

   static int index = 0; //These will initialize to zero only once as its static

   //For every Node go to the right of that node first.
   printNthNode(root->right, N);

   //Right has returned and now current node will be greatest
   if(++index == N)
   {
    printf("%d\n", root->data);
    return;
   }

   //And at last go to the left
   printNthNode(root->left, N);
}

Edit -
     As per the comments below, looks like this is one-time call function due to the static local variable. This can be solved by passing wrapper object for index as follows:
    class WrapIndex {
         public: int index;
    };

and method signature would change to
void printNthNode(Node* root, int N, WrapIndex wrapInd)
Now, we don't need a local static variable; instead use index of the wrapper object. The call would look like
WrapIndex wrapInd = new WrapIndex();
wrapInd.index=0;
printNthNode(root,7,wrapInd);

wrapInd.index=0;
printNthNode(root,2,wrapInd);

A: Hint: use inorder traversal of the tree. It can print out the items in sorted order, so you can sure find the Nth largest item. Keep a counter as you "walk", incrementing each time you "visit" a node.
Edit: while IVlad's answer is indeed faster, it requires you to keep extra information in the nodes. This answer doesn't but it's O(n). Just pointing out that this is a tradeoff you have to be aware of.

A: *

*Maintain size of subtree at eachnode(root.size some thing like that). for example {2,3,1} is a binary tree with root 2 then the size of node (2) is 3, node (1) size is 1, and node (2) size is 1

*if u want to find 4 th larget element in the tree with root node size 23 , think about its rank

*the max element rank is 23, because the root node size is 23. so 4 th largest element rank is 23-4+1= 20

*so we have to find 20th rank element in the given tree

*initially declare a rank=0  flag to zero

*starting from root node find its rank (rank+ size of left child + 1) for example left child size is 16 then root element rank is 17(rank+size of left child +1)

*so we have to look for the element with the rank 20. so obviously we have to traverse to its right child

*traverse to right child and based on above formula find right child rank(based on above formula, note: now rank flag value is is 17),decide whether to go right or left based on the  rank

*repeat this process recursevely untill we found rank==20

A: Use a inverted inorder tranversal.that is go to right child first instead of left child.
recursively this can be obtained as follows:
The most important issue that a global count must be used when considering recursive solution.
reverseInorder(root){
 if(root!=null){
reverseInorder(root->rightChild);
self
reverseInorder(root->leftChild);
}
}

Solution in java
    package datastructure.binaryTree;

import datastructure.nodes.BinaryTreeNode;

public class NthElementFromEnd {
    private BinaryTree tree=null;
    int currCount=0;
    public NthElementFromEnd(int[] dataArray) {
        this.tree=new BinaryTree(dataArray);

    }
    private void getElementFromEnd(int n){
        getElementFromEnd(this.tree.getRoot(),n);
    }
    private void getElementFromEnd(BinaryTreeNode node,int n){
        if(node!=null){
            if(currCount<n)
            getElementFromEnd(node.getRightChild(),n);
            currCount++;

            if(currCount==n)
            {
                System.out.print(" "+node.getData());
                return;
            }
            if(currCount<n)
            getElementFromEnd(node.getLeftChild(),n);
        }
    }

    public static void main(String args[]){
        int data[]={1,2,3,4,5,6,7,8,9};
        int n=2;
        new NthElementFromEnd(data).getElementFromEnd(n);
    }
}

A: int nLargeBST(node *root, int N) {
    if (!root || N < 0) {
        return -1;
    }
    nLargeBST(root->left, N);
    --N;
    if(N == 0) {
        return root->val;
    }
    nLargeBST(root->right, N);
}

A: This piece of code is from my assignment and one of the condition was not to use
arrays. In order to make the code more compact and readable you can use
stringName.split("|"). Since the method is recursive I use the stringBuilder
which has the following structure: "counter|orderOfElementToFind|dataInrequiredNode"
protected StringBuilder t(StringBuilder s)
{
    if (lc != null)
    {
        lc.t(s);
}

if((s.toString().charAt(s.toString().length() - 1)) == '|')
{
        String str = s.toString();
    s.delete(0, s.length());

        int counter = 0, k = 0;

        String strTemp = "", newStrBuilContent = "";

        for (int i = 0, c = 0 ; i < str.length(); ++i)
        {
            if (c == 0)
            {
            if (str.charAt(i) != '|')
    {
        strTemp += str.charAt(i);
    }
    else
    {
        counter = Integer.parseInt(strTemp);
        ++c;

        strTemp = "";
    }
            }
    else
    {

            if (str.charAt(i) != '|')
        {
            strTemp += str.charAt(i);
            }
        else
        {
                k = Integer.parseInt(strTemp);
        }

    }

    counter ++;

            newStrBuilContent = (counter + "|" + k + "|");
    s.append(newStrBuilContent);
    if (counter == k)
    {
        double ldata = this.getData();
        s.append(ldata);

    }

}

if (rc != null)
{
    rc.t(s);
}

    return s;

}

and the method call:
// the value of counter ad the beginning is 0 and data
// segment is missing
String s = ("0|" + order +"|");
StringBuilder strBldr = new StringBuilder(s);
String content = sTree.t(strBldr).toString();

s = "";

for (int i = 0, c = 0; i < content.length(); ++i)
{
    if (c < 2)
{
    if (content.charAt(i) == '|')
    {
        ++c;
        }
    }
else
{
    s += content.charAt(i);
}
}
    `

A: I would do it by going though the tree from biggest to smallest element and returning value when asked position is reached. I implemented similar task for second largest value. Value of 2 is hardcoded, but is it easy to change with additional parameter :)
void BTree::findSecondLargestValueUtil(Node* r, int &c, int &v)
{
    if(r->right) {
        this->findSecondLargestValueUtil(r->right, c, v);
    }

    c++;

    if(c==2) {
        v = r->value;
        return;
    }

    if(r->left) {
        this->findSecondLargestValueUtil(r->left, c, v);
    }
}

int BTree::findSecondLargestValue()
{
    int c = 0;
    int v = -1;

    this->findSecondLargestValueUtil(this->root, c, v);

    return v;
}

A: // C++ program to find k'th largest element in BST
#include<iostream>
using namespace std;

struct Node
{
    int key;
    Node *left, *right;
};

// A utility function to create a new BST node
Node *newNode(int item)
{
    Node *temp = new Node;
    temp->key = item;
    temp->left = temp->right = NULL;
    return temp;
}

// A function to find k'th largest element in a given tree.
void kthLargestUtil(Node *root, int k, int &c)
{
    // Base cases, the second condition is important to
    // avoid unnecessary recursive calls
    if (root == NULL || c >= k)
        return;

    // Follow reverse inorder traversal so that the
    // largest element is visited first
    kthLargestUtil(root->right, k, c);

    // Increment count of visited nodes
    c++;

    // If c becomes k now, then this is the k'th largest
    if (c == k)
    {
        cout << "K'th largest element is "
             << root->key << endl;
        return;
    }

    // Recur for left subtree
    kthLargestUtil(root->left, k, c);
}

// Function to find k'th largest element
void kthLargest(Node *root, int k)
{
    // Initialize count of nodes visited as 0
    int c = 0;

    // Note that c is passed by reference
    kthLargestUtil(root, k, c);
}

/* A utility function to insert a new node with given key in BST */
Node* insert(Node* node, int key)
{
    /* If the tree is empty, return a new node */
    if (node == NULL) return newNode(key);

    /* Otherwise, recur down the tree */
    if (key < node->key)
        node->left  = insert(node->left, key);
    else if (key > node->key)
        node->right = insert(node->right, key);

    /* return the (unchanged) node pointer */
    return node;
}

// Driver Program to test above functions
int main()
{
    /* Let us create following BST
              50
           /     \
          30      70
         /  \    /  \
       20   40  60   80 */
    Node *root = NULL;
    root = insert(root, 50);
    insert(root, 30);
    insert(root, 20);
    insert(root, 40);
    insert(root, 70);
    insert(root, 60);
    insert(root, 80);

    int c = 0;
    for (int k=1; k<=7; k++)
        kthLargest(root, k);

    return 0;
}

A: Swift version. This follows closely with what Vallabh Patade said. The counter is increased by 1 when it tries to go through a node that has no child though. A bit different than his.
class BinaryNode {
    var val: Int
    var left: BinaryNode?
    var right: BinaryNode?

    init(value: Int) {
        self.val = value
    }
}

func findMaxValue(_ n: Int, from root: BinaryNode?) {
    var counter = 0
    maxValue(counter: &counter, n: n, node: root)
}

private func maxValue(counter: inout Int, n: Int, node: BinaryNode?) {
    if node == nil {
        counter += 1
        return
    }
    maxValue(counter: &counter, n: n, node: node?.right)
    // If the counter has reached the nth node we're looking for.
    if counter == n {
        if let val = node?.val { print(val) }
    }
    maxValue(counter: &counter, n: n, node: node?.left)
}

A: K'th Largest Element in BST . Learn how to think for such problem and solve with recursion . Kth Larget Explanation Recursion

A: Here is how you can do this by a slight modification of the in-order traversal of the binary search tree - we are finding the kth largest element;
    void kthLargest(Node node, int k, int count) {

      if(node != null) {

         nthLargest(node.left,k,count); //traversing the left node

         //while visit the node we do the following
         count++; // increment the count and check if that is equal to k
         if ( count == k ) {
           System.out.println("Node found "+node.value);
         }

         nthLargest(node.right,k,count); //traversing the right node
      }

    }

But the problem in this way you are going to reach the kth smallest element and hence you method call should be this: as kth largest element = (n-k)th smallest element.
    nthLargest(root,n-k,0);

redpajama_set_name: RedPajamaStackExchange


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text:
Q: How to evaluate BSplineFunction I have the following code to plot value of a bspline curve but it doesn't evaluate when I specify weights and knots and I'm not sure what's going wrong, the weights and knots vectors have the correct length (and if I change them I get an error) but for f I end up with a function that doesn't evaluate.
knots = {0,1,2,3,4,5,6,7,8};
points = {{0,0},{1/2,1},{1,1/4},{3/2,1},{2,0}};
weights = {1,1,1,1,1};
degree= 3;
f = BSplineFunction[points,SplineDegree->degree, SplineKnots->knots,SplineWeights->weights]
g = BSplineFunction[points,SplineDegree->degree]
g[0]
f[0]

Here's a screenshot of my output using Mathematica 10.3 on Windows:

A: For the B-spline curve:
$$
\overset{\rightharpoonup }{C}(u)=\sum _{i=0}^n N_{i,p}(u) \overset{\rightharpoonup }{P}_i
\text{    }\qquad
(a\leq u\leq b)
$$
where, $P_i$ is the control point, the $N_ {i, p} (u)$ are the $p$th - degree B-spline basis functions defined on the non-periodic (and non-uniform) knot vector:
$\{\underbrace {a,\cdots ,a}_{p+1},u_{p+1},\cdots u_{m-p-1},\underbrace {b,\cdots,b}_{p+1}\}$
Here, $m=n+p+1$ and the domain of curve is $[u_p,u_{n}]$
For your example
knots = {0,1,2,3,4,5,6,7,8};
points = {{0,0},{1/2,1},{1,1/4},{3/2,1},{2,0}};
weights = {1,1,1,1,1};
degree= 3;

f = BSplineFunction[points, SplineDegree -> degree,
                    SplineKnots -> knots, SplineWeights -> weights]

So the spline function domain is $[3,5]$, you can verify it via the below code:
GraphicsColumn[
  {ParametricPlot[f[u], {u, 3, 5}],
   Graphics[
    {BSplineCurve[points, SplineDegree -> degree,
                  SplineKnots -> knots, SplineWeights -> Automatic]}]}]

Owing to the built-in BSplineFunction[] using the default domain $[0,1]$ to generate the spline icon, so f will lost the spline icon like this:

Normalize the knots to $[0,1]$,
BSplineFunction[
  points, SplineDegree -> degree,
  SplineKnots -> {-(3/2), -1, -(1/2), 0, 1/2, 1, 3/2, 2, 5/2},
  SplineWeights -> Automatic]


text:
The Justice League Movie and Green Lantern [SPOILERS]
For months Green Lantern fans have been waiting to see if, and who, might show up as the protector of Sector 2814 in the new Justice League movie. Rumors have been floating about surprise appearances in the final act or Abin Sur dying on-screen and Hal Jordan being recruited in an end credits scene. Well, the movie is out now and we can finally confirm whether or not there is a Green Lantern in the film or not. There are spoilers ahead, so be forewarned.
Disappointing as it may be there is no Green Lantern serving as a member of the Justice League in the film, however that's not to say that there is no Green Lantern presence to be found. In a terrific battle scene which recounts Steppenwolf's previous visit to Earth centuries ago there is a caped alien Green Lantern in the battle who has about ten seconds of screen time using his ring to dispatch Parademons. He dies at the hands of Steppenwolf before his ring takes off to find a new bearer. While I still maintain that a Justice League without a Green Lantern isn't the Justice League, I do appreciate how this small cameo ties deep into DC history.
When DC was trying to rectify how Alan Scott connects to the larger Green Lantern mythology they published the story of Yalan Gur, the Green Lantern of Sector 2814 centuries before – and that's who shows up during the film. While his appearance here doesn't line up exactly with his comic book roots it does show how DC Entertainment in mining the rich history of their universe and using those elements versus taking the easy way out and just making something up to fit the narrative.
The short version of Yalan Gur's backstory from the comics is that he was once one of the greatest members of the Green Lantern Corps, and when he was nearly defeated by a yellow clad army the Guardians removed the impurity from his ring. Gur became abusive of his limitless power and he tried to enslave the people of 10th century China. For his hubris the Guardians gave Gur a new weakness, wood, which they thought would humble Yalan Gur. Instead Gur was severely wounded by the primitive weapons dying as he tried to leave Earth to exact revenge on the Guardians. He and his power ring fused together with a portion of the Starheart, burning up as they re-entered the atmosphere, forming the basis for the origin of Alan Scott's magically infused power ring. Yalan Gur appeared in Green Lantern volume 3 issue 19 and Green Lantern Corps Quarterly #7, both published in the early 1990's.
Armie Hammer Shuts Down Green Lantern Rumors
Podcast of Oa Episode 117
Abin Sur Alan Scott Hal Jordan Steppenwolf Yalan Gur
Cory November 20, 2017 at 5:10 pm
Anyone catch the Parademons feeding off of fear and glowed yellow? A foreshadowing to the Sinestro corps.

redpajama_set_name: RedPajamaCommonCrawl


text:
Preferred Hotels & Resorts Welcomes 25 New Member Hotels
Preferred Hotels & Resorts – the world's largest independent hotel brand representing more than 750 distinctive hotels, resorts, and residences across 85 countries – is pleased to announce the addition of 25 new member hotels to its global portfolio between January 1 to March 31, 2019. From iconic heritage buildings in the cosmopolitan cities of Sydney and London to contemporary beachfront luxury in New Jersey, these exciting new properties deliver authentic, one-of-a-kind experiences that embody the spirit of independent travel and capture the essence of #ThePreferredLife.
New member highlights include:
The Fullerton Hotel Sydney (Sydney, Australia)
Situated in the heart of Sydney's Central Business District on Martin Place, The Fullerton Hotel Sydney resides in the city's landmark Victorian-era General Post Office building. Set to launch in October, the luxury hotel will feature 416 elegant guestrooms and suites, replete with carefully curated art pieces. Guests will be able to enjoy heritage walking tours that reveal the building's origins and its connection to the history and culture of the surrounding area. Visitors will also benefit from the hotel's location to partake in memorable activities such as an exhilarating ascent on the Harbour Bridge Climb for 360-degree panoramas, a show at the Sydney Opera House or zipping through the city on a motorcycle sidecar tour.
Sea Containers London (London, United Kingdom)
Located on the South Bank of the River Thames, a stone's throw from world-famous landmarks including the Tate Modern, Royal Festival Hall, and the London Eye, this 359-room hotel captures the imagination with its unique maritime design exemplified by a copper-clad exterior wall evoking the hull of a 1920s cruise ship. Guestrooms are outfitted with retro-futuristic furniture and custom amenities from award-winning British designer Tom Dixon. Sea Containers London offers three 'drink, dine, and dance' options including Lyaness – an exciting new bar concept created by world-renowned bartender Ryan Chetiyawardana, a deluxe spa, and its very own intimate 56-seat cinema.
Wave Resort (New Jersey, United States)
Opening in May, Wave Resort is a spectacular beachfront resort that will offer 67 airy deluxe rooms with lounge areas and private walk-out terraces. Other standout facilities include an outdoor pool deck with swim-up cocktail bar, rooftop lounge, onsite spa with blow bar salon, state-of-the-art fitness center, five exciting dining outlets, loft event space with floor-to-ceiling windows framing panoramic ocean views, and a mobile concierge team that can help guests enjoy pampering experiences on the beach. Located in the heart of the award-winning Pier Village, guests can take a bike ride down to the newly renovated Long Branch Boardwalk or visit more than 30 independent shops and restaurants including The New Jersey Repertory Company where they can catch an evening play.
The Hotel Kitano Tokyo (Tokyo, Japan)
One of the rare luxury boutique hotels in Japan, The Kitano Hotel Tokyo is an intimate family-owned property that embodies the Japanese spirit of "wa" (harmony) through its 72 thoughtfully appointed guestrooms and refined service style. Recently re-opened after an extensive refurbishment, the hotel now houses two restaurants including the three-Michelin Star Sant Pau, a rooftop bar with panoramic skyline views, and the Tea Lounge which will offer Japanese matcha (green tea) services. Located in central Tokyo, the hotel is steps away from the Imperial Palace and the National Theatre, which is considered to be the heart of traditional Japanese Arts, as well as endless shopping, dining, and entertainment options.
Narcissus Hotel & Residences (Riyadh, Saudi Arabia)
This award-winning luxury hotel offers 280 private apartment-style rooms and suites that blend classic opulent elegance with contemporary comfort, three exquisite restaurants including a rooftop restaurant specializing in authentic Argentinian-style grilled meats, and a destination spa. Situated in the heart of downtown Riyadh, Narcissus Hotel & Residences is perfectly located for a discovery of the capital city's magnificent architectural beauty, rich culture and fascinating heritage with nearby attractions including Al Bujairi Heritage Park, the National Museum, and the King Centre Tower. For guests who are looking for retail therapy, the hotel is a few minutes' drive from five major shopping malls.
Hotel Henri (New York, United States)
Just steps from Madison Square Park, the iconic Empire State, and Flatiron Buildings, as well as some of New York City's top-rated restaurants and bars, Hotel Henri is the ideal lodging choice for travelers seeking a theatrical experience in the Big Apple. The newly independent hotel's 118 guestrooms feature design touches that evoke the backstage ambiance of a Broadway theatre, with stylish lighting and graffiti-inspired artwork. Dining at Hotel Henri includes the contemporary, Mediterranean-inspired fine-dining restaurant Rodos, as well as a Prohibition-style rooftop bar Sir Henri that serves up artisanal cocktails alongside breathtaking views of the city.
Other member hotels to join Preferred Hotels & Resorts from January 1 through March 31, 2019 include:
Yoo2 Rio De Janeiro by Intercity (Rio de Janeiro, Brazil)
The Diaoyutai Mansion Frankfurt (Frankfurt, Germany)
Fortune Park JP Celestial (Bengaluru, India)
River Hotel & Spa (Florence, Italy)
Villa Marina Capri Hotel & Spa (Naples, Italy)
Palazzo Dama (Rome, Italy)
D-O-M Hotel (Rome Italy)
Hotel Tyrol (Selva Val Gardena, Italy)
Hotel Montecatini Palace & Spa (Tuscany, Italy)
The Sense Experience Resort (Tuscany, Italy)
Atelier Playa Mujeres (Cancun, Mexico)
Living Cefiro by Stara (Mexico City, Mexico)
26 SUNSET VILLA (Cape Town, South Africa)
Resort Hotel Alex (Zermatt, Switzerland)
Oatlands Park Hotel (Weybridge, United Kingdom)
Hotel Casa del Mar (California, USA)
Shutters on the Beach (California, USA)
Inn at Perry Cabin (Maryland, USA)
Hotel Rock Lititz (Pennsylvania, USA)
Hard Rock Announces Hotel in Bangalore
Fraser Residence Opens in Singapore
First W Hotel to Debut in Argentina
Marriott International has signed an agreement with GNV Group to bring its iconic W Hotels Worldwide brand to Argentina for the first time in dynamic Buenos Aires, underscoring growing demand from developers and...
Radisson Hotel Opens in Algier
Radisson Hotel Group announces the signing of the Radisson Hotel La Baie d'Alger in Algiers; its second hotel in Algeria and first Radisson-branded hotel in the country. The new hotel will be a strong addition to the...
Aloft Hotel Opens in Madrid
Aloft Hotels brings a new beat to Spain this month with the opening of Aloft Madrid Gran Vía. Located in the vibrant heart of the capital, the new hotel is a stone's throw from hotspots including the iconic Plaza de...


text:
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Blood test could help predict breast cancer survival
Long-term NSAID use linked to kidney cancer
Breath test spots cancer signs, new research finds
Guideline to help GPs spot cervical cancer early
Hopes for kidney cancer treatment
New biomarker found for kidney cancer
Common enzyme could predict response to treatment
Jo Carlowe
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A common enzyme that is easily detected in blood may predict how well patients with advanced kidney cancer will respond to a specific treatment.
The finding, published this week in the Journal of Clinical Oncology, could lead to the first blood test to determine the best treatment for late-stage kidney cancer.
"Being able to direct these patients to a treatment we know will help them would be a major advancement in their care," said Andrew Armstrong, associate professor of medicine and surgery at Duke Cancer Institute in North Carolina, and lead author of the study.
"At the same time, patients who would not benefit from the treatment would be spared from undergoing a drug regimen with potential side effects that could diminish their quality of life."
Armstrong and colleagues focused on an enzyme known as lactate dehydrogenase, or LDH, which is found in almost all body tissues and plays a role in converting food to energy. As cells die or are injured, they release LDH, so elevated levels of the enzyme have long been used in blood tests to identify cancer, tissue damage, and other disorders.
In kidney cancer, elevated LDH levels have been considered a risk factor for aggressive disease, signalling tumour progression. More recent studies have suggested that elevated LDH may also indicate the activation of key genetic alterations that lead to cancer proliferation. One of these cancer gene pathways relies on a protein called mammalian target of rapamycin, or mTOR, and drugs called mTOR inhibitors work to shut down the process.
An international Phase III trial testing an mTOR inhibitor known as temsirolimus found that the then-investigational drug extended the lives of patients with kidney cancer that had spread to other areas of the body, and it even helped the patients with high LDH levels who typically have a poor prognosis.
Intrigued by those results, the Duke researchers used data from the trial to determine whether a high LDH level was more than just a prognostic tool in advanced kidney cancer, and could perhaps also predict the effectiveness of an mTOR inhibitor.
Armstrong and colleagues analysed the outcomes of 404 of the study participants, approximately half of whom received a standard therapy, interferon-alpha, and half who received temsirolimus, which has since been approved by the U.S. Food and Drug Administration to treat kidney cancer. LDH levels had been measured at the start of the study for all participants.
In their analysis, the Duke team found that patients with high LDH levels at the start of the study survived significantly longer on the mTOR inhibitor drug than they did on interferon-alpha. Median survival for patients with high LDH levels was 6.9 months on temsirolimus compared to 4.2 months for the high LDH level patients on the standard drug. At six months, 53.7% of high LDH level patients taking temsirolimus were alive, compared to 39.5% taking interferon-alpha. Patient survival rates at 12 months were 34.3% for temsirolimus, vs. 12.7% for interferon-alpha.
Patients with low LDH at the start of the study showed little difference in survival based on the drug they received, with median survival of 11.7 months for the mTOR inhibitor patients compared to 10.4 months for those taking interferon-alpha.
"This is an exciting finding," Armstrong said. "In breast cancer, for example, we can test for HER-2 expression and offer effective treatments based on that. Having a similar biomarker for kidney cancer that could direct patients to the best therapies for their cancer would be a major step forward."
Armstrong said additional studies are needed to verify the finding, and to determine whether LDH might predict the success of additional drugs that target other cancers.
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text:
Il Gran Premio del Belgio 1995 è stata l'undicesima prova del Campionato mondiale di Formula 1 1995. Disputatasi il 27 agosto 1995 sul circuito di Spa-Francorchamps ha visto la vittoria di Michael Schumacher su Benetton-Renault, seguito da Damon Hill e da Martin Brundle che sale sul podio per l'ultima volta in carriera, la nona complessivamente, senza riuscire dunque ad aggiudicarsi nemmeno una prova mondiale di Formula 1 dopo aver partecipato a 158 Gran Premi.

Qualifiche

Cronaca
Le qualifiche videro prevalere le due Ferrari di Berger ed Alesi, autori rispettivamente del primo e del secondo tempo. Questa prestazione fu in larga parte favorita da una corretta strategia elaborata al muretto, in quanto i due piloti vennero fatti uscire dai box all'inizio della sessione di prove prima che un violento scroscio si abbattesse sul circuito. Dietro di loro si classificarono la McLaren di Häkkinen e la Benetton di Herbert.

Maggiori difficoltà ebbero invece i due principali contendenti al titolo iridato: Damon Hill non andò oltre l'ottavo posto, compromettendo il suo miglior giro con un'uscita di pista, mentre Michael Schumacher, complice il fatto di dover correre con la vettura di riserva e un guasto al cambio, concluse le qualifiche con il sedicesimo tempo.

Nonostante il buon risultato ottenuto i ferraristi si dichiararono preoccupati per l'affidabilità della vettura in gara e lo stesso Jean Todt invitò alla prudenza.

Risultati

Gara

Resoconto
Al via Berger pattina troppo e lascia via libera ad Alesi ed Herbert. Quarto Häkkinen, davanti alle Williams di Coulthard e Hill. Herbert prova subito a passare Alesi: il francese resiste all'Eau Rouge, ma sul rettilineo del Kemmel il britannico prende la scia della Ferrari, si porta all'esterno e con una staccata profondissima si prende la leadership. Alesi non molla e continua a rimanere negli scarichi di Herbert, mentre dietro di loro Häkkinen finisce in testacoda alla Source ed è costretto al ritiro già al secondo passaggio. Sempre al secondo giro Alesi si riporta al comando, rendendo ad Herbert il sorpasso al Kemmel.

Il francese è velocissimo e cerca di allungare, mentre Berger è in difficoltà: al terzo giro resiste su Coulthard, ma al quarto passaggio lo scozzese e Hill passano con facilità la Ferrari numero 28. Ma il 4º giro diventa ancora più nero per la Ferrari: Alesi va ai box credendo di avere una foratura, ma in realtà sulla sua monoposto si è rotta una sospensione: gara finita per lui. Herbert è al comando, ma le Williams gli mettono una pressione tale da costringerlo all'errore. Il britannico della Benetton poi sbaglia nuovamente alla Bus Stop, andando in testacoda e bloccando Blundell: Irvine e Schumacher ne approfittano.

Mentre davanti Coulthard vola seguito da Hill, Schumacher è quinto dopo una bella rimonta, ma fatica a passare Irvine, che è velocissimo sui rettilinei. All'11º giro il tedesco supera l'irlandese alla Bus Stop e si lancia all'inseguimento di Berger. Coulthard continua a volare, ma al 13º giro rallenta improvvisamente prima di Pouhon e si ferma a bordo pista: Hill è il nuovo leader. Il britannico, così come Berger ed Irvine, effettua il primo pit stop, mentre Schumacher resta in pista per qualche giro con lo scopo di marcare qualche giro veloce. Il tedesco, dopo il suo rifornimento, si ritrova in seconda posizione con una quindicina di secondi da recuperare su Hill. La giornata della Ferrari è stregata, visto che Berger rallenta improvvisamente per un problema al motore: doppio ritiro per le vetture di Maranello.

Hill è al comando della gara, ma a Spa inizia a piovere. Il leader della corsa, così come Irvine, Blundell, Herbert, Brundle e Panis, rientra ai box per montare gomme da bagnato. Schumacher invece resta in pista con le slick. La scelta di Hill sembra azzeccata, visto che in un giro annulla il gap di cinque secondi su Schumacher e si porta in scia alla Benetton. Hill affianca il tedesco sul rettilineo del Kemmel e il sorpasso sembra una formalità, visto che piove a dirotto e Schumacher ha le gomme da asciutto, ma il tedesco tira una staccatona incredibile all'esterno e tiene dietro il rivale. Nel giro successivo però Schumacher tenta nuovamente di difendersi con una frenata ritardata, ma finisce lungo e Hill va al comando.

La pioggia però sparisce, la pista va via via asciugandosi, e Hill fatica a tenere la macchina, tanto che sbanda vistosamente: Schumacher ne approfitta e torna in testa. La Williams richiama Hill ai box per rimettere gomme da asciutto e per rifornire la macchina di benzina. Schumacher guida indisturbato la corsa davanti a Hill, con le Ligier di Brundle e Panis e la Tyrrell di Katayama che si giocano il podio (nulla da fare invece per Irvine, la cui vettura aveva preso fuoco durante il pit). Ma la pioggia ritorna e a farne le spese è Katayama, che va a sbattere a Malmedy mentre è quarto. La direzione corsa decide di mandare in pista la Safety Car, con Schumacher, Hill e gli altri che rientrano ai box a montare gomme rain.

Alla ripartenza, Panis si gira e scivola in fondo al gruppo. Hill sbaglia nel tentativo di riprendere Schumacher, ma all'inglese arriva una notizia ben peggiore: la direzione corsa ha deciso di sanzionarlo con uno Stop & Go di 10 secondi per aver superato i limiti di velocità ai box. Il pilota della Williams è secondo anche dopo aver scontato la penalità, ma alla Source va in testacoda e Brundle gli prende la posizione. Schumacher davanti guida tranquillo, mentre dietro infuria la lotta tra Blundell, Frentzen, Herbert e Barrichello per le posizioni dalla quarta alla settima. Barrichello riesce a infilare Herbert e Frentzen mette la sua Jordan davanti alla McLaren di Blundell. Hill spinge per riprendere Brundle e proprio all'ultimo giro si mette in scia al britannico. Brundle chiude la porta alla Source, ma non può nulla contro la potenza della Williams-Renault sul lungo rettilineo del Kemmel.

Hill completa così la rincorsa al secondo posto, ma davanti a fare festa è Schumacher, che conquista la sesta vittoria stagionale dopo una fantastica rimonta, una strategia perfetta e una resistenza da applausi su Damon Hill in condizioni di palese inferiorità tecnica. Il tedesco della Benetton precede sul traguardo Hill e Brundle. Quarto Frentzen, che nei giri finali era il pilota più veloce in pista. Blundell e Barrichello chiudono la zona punti. Con questo successo Schumacher si porta a 15 lunghezze di vantaggio su Hill e mette una seria ipoteca sulla conquista del secondo titolo piloti in carriera.

Risultati

Classifiche Mondiali

Piloti

Costruttori

Note
Salvo indicazioni diverse le classifiche sono tratte da

Vittoria di Schumacher sotto la pioggia di Spa, f1race.it, 27 agosto 2019.

Bibliografia

 11

redpajama_set_name: RedPajamaWikipedia


We adore this cute First Look video of our bride Katelyn and her handsome husband. Doesn't Katelyn look adorable in her Emmie gown? Congratulations Katelyn!
>> First Look | Katelyn + Jordan from December Rose Film on Vimeo.
Phoebe wore one of our off-the-rack gowns, with a lace form-fitting top, and a fun layered tulle bottom. It's so fun to help brides like Phoebe find the gown of their dreams and then see the end results of them in their beautiful gowns with their new husbands. Congratulations Phoebe, you looked incredible!


text:
AD–WO
Emanuel Admassu and Jen Wood
Jen Wood and Emanuel Admassu, Founding Principals, AD-WO. Portrait by Rachel Hulin.
Register here to receive a link to join.
Emanuel Admassu, Founding Principal, AD–WO, and Associate Professor, Rhode Island School of Design, and Jen Wood, Founding Principal, AD–WO, present the lecture "Immeasurability" on Wednesday, April 14, at 12:00 p.m. via Zoom as recipients of the 2021 Rice Design Alliance Spotlight Award.
Founded in 2015, AD–WO is an art and architecture practice based in Providence, Rhode Island, and by extension, between Melbourne and Addis Ababa. The practice aims to establish an operational terrain between architecture's content and container: equally committed to designing buildings and reimagining their dynamic sociopolitical contexts.
The firm has undertaken various projects in Ethiopia, Tanzania, South Korea, Germany, and the United States, engaging with multi-family residential, agricultural township revitalization, civic infrastructure, collaborative art installations, and exhibition design. Their work has been exhibited at the Tel Aviv Museum of Art, Studio Museum in Harlem, Architekturmueum der TU München, and Art Omi. They are currently developing a mid-sized apartment building in Addis Ababa and are responsible for an installation in the exhibition Reconstructions: Architecture and Blackness in America, which opened recently at The Museum of Modern Art in New York City.
Emanuel Admassu (Addis Ababa, Ethiopia) is a founding partner of AD–WO and an Associate Professor at the Rhode Island School of Design, where he teaches design studios and theory seminars. He has taught at Columbia GSAPP and worked with design practices in Atlanta and New York City. Admassu's teaching, research, and design practices examine the international constellation of Afrodiasporic spaces. Admassu completed his Bachelor of Architecture at Southern Polytechnic State University, followed by a Master of Advanced Architectural Design and Advanced Architectural Research at Columbia University.
Jen Wood (Melbourne, Australia) is a founding partner of AD–WO and a licensed Architect in the state of New York. Until 2018, Wood was at BIG as a Project Leader of The Spiral tower in New York City. Wood has also worked with Toshihiro Oki Architect in New York, LAB Architecture Studio, and Minifie van Schaik in Melbourne. Her project experience ranges from residential through to large-scale urban development. Wood received her Bachelor and Master of Architecture at the Royal Melbourne Institute of Technology, and a Master in Advanced Architectural Design at Columbia University.
The Spotlight Award recognizes the work of exceptionally gifted national and international architects in the early stages of their professional career who have demonstrated design excellence and curiosity through their body of work.
Learn more about the Spotlight Award and view a list of past awardees here.
RDA's Spotlight Award + Lecture is made possible through the generous support of Rice University's Humanities Research Center, with additional support from the Texas Commission on the Arts. Funding also is provided by RDA Underwriters: MAREK, W.S. Bellows Construction Corp., Harvey | Harvey-Cleary, Tellepsen, Hines, HKS, Inc., IBEW, MLN Company, m Strategic Partners, TDIndustries, TRIO Electric, and Walker Engineering, Inc.
The Spotlight Award Lecture is eligible for one AIA/CES Learning Unit. Rice Design Alliance is an AIA/CES Registered Provider of quality educational programs.


Treatment Design of North Holly Water Treatment Plant | Freese and Nichols, Inc.
The North Holly Water Treatment Plant was first constructed in 1892, and remains a critical component of the City of Fort Worth's water production facilities with a rated capacity of 80 MGD. A major plant upgrade was completed in 2002 and included new rapid mix and filters, enhanced flocculation and sedimentation facilities, backwash clarification and other related facilities. These upgrades were accommodated without acquiring additional space for new facilities, leading to several interesting design challenges.
Earlier improvements at both the South Holly and North Holly plants accommodated amendments to the federal Safe Drinking Water Act, including complete replacement of the chlorine and ammonia feed facilities at both plants, construction of filter backwash clarification facilities and filter renovation at the south plant and chemical feed improvements at both plants. Emergency gas scrubbers were included at both plants to improve safety of disinfection facilities.


Hey! Welcome to the awkward but awesome profile belonging to a scratcher called CodeAlien. I make weird projects and i don't like going outside either. I like drawing, art and memes.
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Under the general direction of the OR/PACU Unit Manager, the OR/P.A.R. nurse provides direct nursing care to the peri-operative patient according to established standards/policies and provides work direction to nursing and non-nursing staff as required. The OR/P.A.R. nurse assesses the physical and psychological needs; plans, implements, evaluating and documents the nursing care for the patient during the peri-operative process, and the immediate post-operative period. Willing to do a minimum of 8 days on call per month.
- Registration with BC College of Nursing Professionals as a practicing RN registrant.
- Current Level C CPR certification required.
- Post graduate certificate in perioperative nursing or a minimum of one-year recent related experience in peri-operative nursing.
- Work as a member of an interdisciplinary team.
- Make and apply nursing judgment using analytical skills.
- Communicate effectively both verbally and in writing.
- Interact with others effectively.
- Maintain the physical ability to carry out the duties of the position.
- Maintain own physical, mental and emotional well being.
- Using Critical Thinking skills, prioritize and organize patient care.
- Teach and provide clinical supervision.


The subject of play calling on both sides of the ball came up during Cowboys coach Jason Garrett's year-end press conference on Monday.
Garrett shot down the notion that he would bring in someone else to handle the offensive play calls that have remained Garrett's responsibility since he was promoted from offensive coordinator to head coach. He was less forthcoming about who would be handling things on the defensive side of the ball.
Garrett did not say whether or not Rob Ryan would return for a third year as the team's defensive coordinator. Ryan's defense ranked in the bottom half of the league in both points and yards allowed, a performance that was impacted by the loss of several key players to injury over the course of the season. Garrett complimented Ryan's handling of "the challenges" he faced this season.
While there is a fine line between doing "a really good job managing that situation" and doing a really good job overall, it doesn't sound like the Cowboys are convinced they need to change coaches to find the defensive improvement they'll need in 2013. If they remain unconvinced, Ryan will have a chance to prove injuries were the defense's biggest problem this year.
Wow! Enough with the excuses. Next man up!
Why do they show so much of rob ryan when cowboy games are on TV?
What has he done? Anything?
Ryan is not a horrible coach. He just thinks he is better than he is.
The league has gotten better as a whole because of teams like the cowboys constantly falling on their face. Keep up the good work Jerry Jones.
1. The next person has to be better.
2. They have to want to come to Dallas.
And if you find somebody like that, the other 8 teams want him, too. Good luck with that.
Team has a ton of talent, but in Garrett's 3 years they are 21 -19.
Not a good coach, but a great yes man for the owner.
lol. even haslett did more with less.
not ryan or garretts fault. get rid of romo. problem solved. how many coaches need to be fired before you realise its not the coaches but the bonehead turnover machine that is tony romo.
what marquee names? Lee? ok who else?? Redskins defense is without both starting safeties, RAK, starting defense end …you dont hear them making excuses..I believe the saying is "Next man Up"…..Hats off to the Redskins for adding capable back-ups….
I guess you have to have escape goat for the interception from Romo.
Ryan stays – who did he have left? This defense will be top 3 next year with our Briggs/ Urlacher duo of Lee / Carter with Carr and Claiborne in the secondary. OMG! I can't wait. And now, drum roll please… Bring in Norv to be the play caller JG! Norv Turner to Dallas for OFFENSIVE COORDINATOR. !!!!!!!
Garret / Ryan for coaches of the year for coaching up all these guys off the street. Never seen a team so decimated with injuries still have a chance at the tournament. Oh my, if the boys can stay healthy!
Are the Cowboys the only team in the NFL with injuries?? Sure sounds like it……….
I support Jason Garret as HC, Ryan as DC and Romo as QB.
Dallas has four major problems ~ Garrett, Ryan, Romo, and Jones. The first three are fixable but not the fourth ~ ~ soooo, Dallas will continue with four major problems. It doesn't matter who holds the HC or coorinator positions, Problem #4 will ensure mediocrity simply because as a football person, Jerry is mediocre. Good money manager but horrible GM and that will not change for it would require admitting a mistake ~ and Jerry Jones never makes a mistake. Ask him for verification.
Don't blame Rob Ryan for the Cowboys season. The fault lies at the feet of Jason Garrett. I have been a Boys fan ever since Coach Landry. And I cannot another year of Jason Garrett. He was a lousy quarterback and a worst coach. The only reason he got the job is because he's a good "yes" man. And finally Romo is done. Stick a fork in him. His best days have gone bye. So it's time for him to go. Let's get Tebow!!!
injuries are the worst excuse, every team has them. They did a poor job of handling them. they should have a freakin limit on how many times they show this guy on TV, it is absolutely sickening.
Wow! Injuries? Seriously? Haslett lost two starting safeties ,cornerback, outside linebacker and defensive end. It's called coaching that's what they get pad to do. Rob needs to realize he s not that great of a coach and go bye-bye. Wait!! What am I saying? Please keep the status quo in Dallas?
Rob Ryan is not the Cowboys problem. The problem is Tony Romo and Jason Garrett's vanilla playcalling! You get a turnover and wind up on the opponents 29 yard line you TAKE A SHOT AT THE ENDZONE. what do they do? Lose yardage on a run, pass on 2nd and 3rd downs. Every Cowboys game I've seen I've been able to call what they'd do next. Piss Poor Situational Football.
most overated coaches I have ever seen if it weren't for there dad buddy Ryan's these two idiots wouldn't even be coaching pop Warner league.
OK he had injuries on defense so did everyone else blah blah blah. Ryan still had some really good players available that didn't perform at a very high level. Their tackling was a joke and that is pretty fundamental. On a regular basis they had break downs in coverage and responsibilities. Defenders often look confused.
I've seen enough of Ryan and Garrett!
Giants fan here that doesn't fear the cowgirls defense under loudmouth Ryan at all. Usually safe to take the over playing against Dallas. I hope Rob Ryan stays.
The press and others make Romo, Garrett, Ryan, and "their marquis players" to be more than their average performance (8 and 8). This is what was predicted by honest experts before the season began and they were right. Garrett and Ryan need to go. Why? Because Romo and his offense scored more points in the 4th quarter this year in their final seven games (not including the last one) than any other team in NFL history during a 7-game span. They are always behind. They don't prepare their game plans worth a hoot. Children raised by woplves would have prepared for Washington's running game after RGIII hurt his knee and reduced his mobility. Get rid of the coaches and you'll get better. It's not Romo.
He's a good coach, he got a win over the Patriots when Mangini was there…he just never had the personnel he had in previous stops.
Romo deserves the heat he takes. He comes up short in the big games, but he is not our only problem. If we had a head coach with some emotion and that can discipline this team like a Gruden, Tomlin, Parcells, etc, they could light a fire under them and hold them accountable for their play. There is no accountability in Dallas right now. Ryan talks a lot but when the defense was healthy early on, they were pretty good. The backups brought in weren't that great, nor is our OL or DL. I'd vote for Norv for OC if they insist on keeping Garrett. And bring in OL and DL help this off season.
Nearly every team lost several key players on defense.
I watched Ryan in cleveland and Dallas. Never cracked the top 15 in defense. I truely believe he lives off the Ryan name but is a disposable DC like the 25 others in the NFL.
The problem in todays's game is we have too few great coordinators on both sides.
These guys have proven in different places that their coaching will improve a teams off/def rankings. Rob Ryan is an not in this class and I wish people would stop putting him there.
The impressive thing with Ryan's defense is, he wasn't doing it with backups. This wasn't the case that the 1st stringers went out and the 2nd stringer stepped in. Ryan got decent work from guys who weren't even in football at the time they were called up.
Next year, depending on FA, we stand a real chance of having 3 or 4 of our LBs in the ProBowl.
Regardless of how impressive Ryan's effort was with no-name players, this team needs to crap the 3-4 and go back to traditional 4-3 defense. The 4-3 is much friendlier to substitution and rotation. It doesn't require the specialize hybrid players that the 3-4 does.
The 3-4 is like the vanilla offense Dallas ran in the SB years – as long as you have the most dominant personnel the scheme works. When you don't, then the scheme is exposed. With the longer season and more exposure to injury it's better to use a scheme that is more flexible with personnel.


text:
set -e

#Variables
PACKAGE_NAME=pyenchant
PACKAGE_VERSION="${1:-v3.2.0}"
PACKAGE_URL=https://github.com/pyenchant/pyenchant.git

#Install dependencies.
yum -y install git python36 python36-devel enchant

pip3 install pytest tox

#Clonning repo
git clone $PACKAGE_URL
cd $PACKAGE_NAME/
git checkout $PACKAGE_VERSION

if ! tox -e py36; then
	echo "------------------$PACKAGE_NAME:install_success_but_test_fails---------------------"
else
	echo "------	------------$PACKAGE_NAME:install_and_test_both_success-------------------------"
fi

redpajama_set_name: RedPajamaGithub


The Mysterious Traveler Sets Out: 10 seconds to noise-cancelling iPhone headphones!
Macworld's Rob Griffiths, who kindly posted the detailed photos and instructions for this hack, said he was able to convert his Bose noise-cancelling headphones to fit the iPhone's proprietary recessed jack in "less than a minute" using a box knife.
And now, for a delightful flight to Las Vegas Wednesday, watching a movie on the iPhone.


* added that video content now, there are a lot more videos available now.
* added a really cool [url=http://www.amprosoft.com/info/updates/]update page in the info section[/url].
* next I need to tackle the music section, but for the moment I have a few soundcload tracks in there.
* oh, and I put a shared calendar WNY Region calendar in the info section. I need to refine it a bit, but it's good for the moment.


The links above help you share our experiences week by week.
The Route section gives details of each day's journey ( date, where we stayed, distance walked and amount of climbing ).
In the Accommodation details you will find our personal comments on those places together with links, where possible, to the websites of places where we stayed.
Each week Pete sent back Blogs to family and friends relating his experiences on his first long-distance trek. We enjoyed reading them so much we wanted to share them with you.