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Carl Jules Weyl est un directeur artistique allemand, né le  à Stuttgart, Empire allemand et décédé le  à Los Angeles, Californie, États-Unis

Biographie

Filmographie

Directeur artistique
 1935 : The Case of the Curious Bride de Michael Curtiz
 1935 : The Florentine Dagger de Robert Florey
 1935 : We're in the Money de Ray Enright
 1935 : Personal Maid's Secret d'Arthur Greville Collins
 1935 : The Payoff de Robert Florey
 1935 : Stars Over Broadway de William Keighley
 1936 : The Singing Kid de William Keighley
 1936 : I Married a Doctor de Archie Mayo
 1936 : Guerre au crime (Bullets or Ballots) de William Keighley
 1936 : The Big Noise de Frank McDonald
 1936 : The Captain's Kid de Nick Grinde
 1936 : King of Hockey de Noel M. Smith
 1937 : Smart Blonde de Frank McDonald
 1937 : God's Country and the Woman de William Keighley
 1937 : Ready, Willing and Able de Ray Enright
 1937 : Men in Exile de John Farrow
 1937 : Le Dernier Combat (Kid Galahad) de Michael Curtiz
 1937 : Dance Charlie Dance de Frank McDonald
 1937 : Varsity Show de William Keighley
 1937 : L'Aventure de minuit (It's Love I'm After) d'Archie Mayo
 1938 : Les Aventures de Robin des Bois (The Adventures of Robin Hood) de Michael Curtiz et William Keighley
 1938 : Le Mystérieux docteur Clitterhouse (The Amazing  Clitterhouse) de Anatole Litvak
 1938 : Nuits de bal (The Sisters) d'Anatole Litvak
 1939 : Yes, My Darling Daughter de William Keighley
 1939 : Women in the Wind de John Farrow
 1939 : Les Aveux d'un espion nazi (Confessions of a Nazi Spy) d'Anatole Litvak
 1939 : Agent double (Espionage Agent) de Lloyd Bacon
 1939 : Nous ne sommes pas seuls (We Are Not Alone) d'Edmund Goulding
 1940 : La Balle magique du Docteur Ehrlich ( Ehrlich's Magic Bullet) de William Dieterle
 1940 : L'Étrangère (All This, and Heaven Too) d'Anatole Litvak
 1940 : La Lettre (The Letter) de William Wyler
 1941 : Le Grand Mensonge (The Great Lie) d'Edmund Goulding
 1941 : Shining Victory  d'Irving Rapper
 1941 : Out of the Fog d'Anatole Litvak
 1941 : One Foot in Heaven d'Irving Rapper
 1942 : Crimes sans châtiment (Kings Row) de Sam Wood
 1942 : La Glorieuse Parade  (Yankee Doodle Dandy) de Michael Curtiz
 1942 : Sabotage à Berlin (Desperate Journey) de Raoul Walsh
 1942 : Casablanca de Michael Curtiz
 1943 : Mission à Moscou (Mission to Moscow) de Michael Curtiz
 1943 : Tessa, la nymphe au cœur fidèle (The Constant Nymph) d'Edmund Goulding
 1943 : Quand le jour viendra (Watch on the Rhine) de Herman Shumlin
 1944 : Passage pour Marseille (Passage to Marseille) de Michael Curtiz
 1945 : Le blé est vert (The Corn Is Green) d'Irving Rapper
 1945 : L'Intrigante de Saratoga (Saratoga Trunk) de Sam Wood
 1946 : Le Grand Sommeil (The Big Sleep) d'Howard Hawks
 1947 : Le Loup des sept collines (Cry Wolf) de Peter Godfrey
 1947 : Escape Me Never de Peter Godfrey et LeRoy Prinz

Chef décorateur
 1943 : Tessa, la nymphe au cœur fidèle (The Constant Nymph) d'Edmund Goulding

Distinctions

Récompense
 Carl Jules Weyl reçu l'Oscar de la meilleure direction artistique en 1939 pour le film Les Aventures de Robin des Bois

Nomination
 Carl Jules Weyl fut nommé à l'Oscar de la meilleure direction artistique pour les décors intérieurs en noir et blanc en 1944 pour le film Mission to Moscow

Liens externes

  Carl Jules Weyl sur l'Internet Movie Database.

Notes et références

Naissance en décembre 1890
Naissance à Stuttgart
Décès en juillet 1948
Directeur artistique
Chef décorateur allemand
Oscar des meilleurs décors
Décès à Los Angeles
Personnalité inhumée au Forest Lawn Memorial Park (Glendale)
Décès à 57 ans

redpajama_set_name: RedPajamaWikipedia


apply the rules for definite integration to two engineering problems that involve summation.
The voltage in a circuit is given by v = 60(1 —e 0.2f where t is the time in seconds. Plot a graph of voltage against time for seconds.
I. Measure the gradient at the point representing an elapsed time of 9 seconds. H. Differentiate the above expression for voltage and find the rate of change of the voltage after 9 seconds have elapsed. III. Calculate the percentage error in the value from your graph.
For a certain material, Newton's law of cooling can be represented by the decay equation 0= 25 + 80e where t is the time in seconds. And 0 is the temperature at any given instant in time.
II. From your graph, find the initial temperature and the temperature that the body approaches as time increases to infinity.
III. Determine the slope at t = 3 seconds both from the graph and by differentiation and give your comment as you compare the results.


Synthetic lubricant containing a high amount of solid lubricants for heavily loaded sliding contacts subjected to high temperatures. To be used as fluid lubricant up to approximately +200 °C.
High amount of solids, good adherence, excellent wear protection, does not form any hard or tacky residues, very low smoke formation even when applied on hot surfaces, free of solvents or toxic heavy metals, can be applied by hand spray units.
Lubrication of loose kiln tyres of rotary kilns and dryers. Heavily loaded chains, track beams, slide ways and mounting systems subjected to high temperatures.


text:
Tag: Tom Woods
LIBERTARIAN: Libertarians don't have to move to Somalia to demonstrate anarchy isn't a terrible as the "experts" teach
Published on Thursday, December 1, 2022 Saturday, November 26, 2022 by reinkefjLeave a comment
https://mailchi.mp/tomwoods/som?e=39307912ab
In the Journal of Economic Behavior & Organization in 2008, Professor Benjamin Powell and his colleagues wrote:
"This paper's main contribution to the literature has been to compare Somalia's living standards to those of 41 other sub-Saharan African countries both before and after the collapse of the national government. We find that Somalia's living standards have generally improved and that they compare relatively favorably with many existing African states. Importantly, we find that Somali living standards have often improved, not just in absolute terms, but also relative to other African countries since the collapse of the Somali central government."
Libertarians NEVER predict "paradise"; just a better country without an oppressive Gooferment.
Imagine that the USA returns to a Federal Gooferment funded by tariffs and excise taxes.
Eliminate whole unnecessary Gooferment agencies — BATF, ATF, DoE, DoEd, etc. etc.
Oh, and don't forget the FED. Put the USA back on the gold standard. Repeal the 17th Amendment.
Get back to the original Constitution Republic that the Dead Old White Guys designed.
Categories LIBERTARIAN•Tags Benjamin Powell, Journal of Economic Behavior & Organization, Somali, Somali living standards, Tom Woods
VOCABULARY: new definition of "Democracy" — rule by a self-identified elite, or people endorsed by that elite
Published on Wednesday, October 5, 2022 Monday, September 26, 2022 by reinkefjLeave a comment
https://mailchi.mp/tomwoods/denew definitimocracymeaning?e=39307912ab
This is how their modern counterparts can say, in all seriousness, that they're "saving democracy" even when they're sabotaging officials who won democratic elections. In case it sounds like they're contradicting themselves, they're really not. They are democracy. They and their colleagues and cronies and so-called experts are democracy, and the stupid rubes who won't just bend the knee to them and do as they say are the enemies of democracy.
Have a future in mind that doesn't involve crippling energy prices, eating bugs, having your kids brainwashed, and watching central banks siphon away your wealth? Why, you may be a danger to "democracy," citizen.
As Sam Francis wrote back in 2004, "What they mean by 'democracy' is nothing more than the system of dominance that came to prevail in the United States and the Western world in the last half of the last century. That system has nothing to do with elections, opposition parties, civil and political rights, or 'liberty,' nor does it have anything to do with political theory, ancient or modern. 'Democracy,' as the neocons and the President and most others who are enthusiastic about it use the word, means the centralized leviathan state under the firm and unqualified control of the managerial bureaucracy and those political forces able to influence it."
Certainly not the old definition of "democracy" which was basically mob rule.
Categories VOCABULARY•Tags ancient, centralized leviathan state, democracy, managerial bureaucracy, modern, Political Theory, Sam Francis, Tom Woods
VOCABULARY: "Fact checker" — a hyperpartisan fanatic
Published on Tuesday, September 13, 2022 Friday, September 9, 2022 by reinkefjLeave a comment
https://mailchi.mp/tomwoods/checkers?e=39307912ab
The "fact checker" scam
One of the most laughable developments of recent years has been the rise of the "fact-checker."
The fact-checker, in the fantasy version, is a nonpartisan, dispassionate expert who wants to prevent people from being misled.
In the planet-Earth version, the fact checker is a hyperpartisan fanatic who wants to prevent people from entertaining thoughts at odds with the narrative the regime is trying to present.
And usually paid for by the folks that profit from the regime's narrative.
Categories VOCABULARY•Tags Tom Woods
GUNS: Our guns prevent your genocide
https://www.globalresearch.ca/overkill-deadly-illogical-gun-rights/5781444
Overkill: The Deadly Illogical of Gun Rights
By Greg Guma
Global Research, May 26, 2022
Theme: Law and Justice
When a disturbed teenager or adult commits mass murder it has nothing to do with liberty. Yet, since the weapon is usually a gun, many people in the US essentially respond that the freedom to be armed is more important that the right to be safe. In fact, millions claim that being armed is the only way to be safe. Like most arguments against gun control, it's cruel and illogical.
For decades now, leaders of gun rights groups have made the same case. They claim, for example, that the only thing separating Americans from people living in dictatorships is their unrestricted access to weapons. If the government has all the guns, they say, attacks against defenseless citizens will become as common in the US as they are in oppressed countries. This is one of the reasons why gun owners oppose the banning of so-called assault rifles.
Does this sound familiar? It certainly should. The same argument is still being made today by those who say nothing can be done to stop mass shootings like the recent ones in Texas and upstate New York. They also warn that only way to prevent a police state here, which many people claim is on the verge of happening, is to allow the wide and unregulated distribution of all sorts of weapons.
This idea, which assumes that any regulation is the first step toward confiscation, represents a paranoid and individualist mentality that for decades has dominated debate about gun violence in the US. We are free, the argument goes, only as long as we can defend ourselves with guns, not only against criminals but also against the law and the State.
The arguments against regulation tend to fall into three categories: 1) the right to bear arms is constitutionally protected, 2) gun control won't reduce violence in society, and 3) gun laws are a serious threat to freedom. But do these assertions hold up to scrutiny?
The roots of traditional US ideas about the relationship between weapons and society actually go back centuries to the Florentine political philosopher Niccolo Machiavelli, who noted that military service should be the responsibility of every citizen, but soldiering the professional of none. Basing his ideas on the Roman suspicion of professional soldiers, he concluded that military force should only be used to assure the common good.
This idea of citizens bearing arms in defense of the State, to avoid the potential tyranny of a standing army, was translated by the authors of the Bill of Rights into the Second Amendments and helps to explain its unusual wording:
"A well-regulated militia, being necessary to the security of a free State, the right of the people to keep and bear arms, shall not be infringed."
Many libertarians have interpreted this sentence to mean that individuals are guaranteed the right to possess firearms for their personal defense or for any other use they choose. What this fails to acknowledge is the meaning of citizenship as it was understood two and a half centuries ago. In the 18th century, citizenship directly involved militia service for men, which was part of the commitment to the greater public good. An armed citizenry did not mean an armed population. In fact, even then it was clearly understood that access to weapons was a communal rather than an individual right.
The bottom line is this: Effective regulation, combined with a comprehensive national database and a serious training program for gun users, would establish over time that less access to guns leads to less violent crime. This has been the case in Europe and some US states. Success would also help shatter the myth that government is the problem, and that people are better off armed to the teeth and on their own.
The debate over guns is not about restricting rights. That's the cover story, an assumption promoted by the gun lobby to shape public perceptions. It's not even about "control." The goal is security, freedom from the fear and anxiety sweeping across this over-armed society.
A well-regulated militia is a altruistic idea, certainly preferable to the military-industrial complex. But almost 400 million guns in private hands is — pardon the expression — overkill.
In a long eloquent screed, the author makes an argument for "effective regulation" and that the Dead Old White Guys didn't meant everyone.
I almost spit out my coffee at "effective regulation". Would the author please point out ANY example of such "effective regulation" ANYWHERE in the world. He cite cars as an example. Has he dealt with the DMV lately? And, even this week before the tragic shooting in Texas the ATF is accused of creating a permanent online gun registry in direct violation of Federal law. So much for that argument.
Funny how if they meant militia, they didn't say it. It's generally conceded that "well regulated" in their generation meant "hit what you aim at" not a bunch of bureaucrats making diktats. If the Federal Gooferment would return control of the Army to the State governors, disband all the TLAs (three letter agencies), and disarm all the bureaucrats like at the Department of Agriculture, then maybe we can get back to the Dead Old White Guys' intents. Then maybe we don't need about ⅓ of "We, The Sheeple" armed like citizen soldiers.
I notice that the author doesn't point out how Israel dealt with classroom shootings.
Further I notice that the author doesn't address how mass shootings seem to take place in "gun free zones" or as I like to call then "target rich environments" AKA shooting galleries.
Stiff further I notice that the author doesn't address violent crime in all major cities where "gun control" id the diktat.
Finally I notice that the author doesn't address how genocides seem to happen when the citizenry is disarmed. (And yes it does happen here — Waco, Ruby Ridge, the Native Americans, the Bonus Brigade, etc etc)
As a gun owning pro-life pro-choice little L libertarian, there are better scholars on these issues than me (i.e., John Lott; Tom Woods; Scott Horton; and litany of libertarian writers like Heinlein) who can do a better job of responding.
And with "gun control" fixated Democrats in charge of all branches of the Federal Gooferment why haven't they advanced the agenda? Because they know it's a loser. Nothing will will bring 100 million voters to the polls quicker than that infringement of the Second Amendment.
P.S., Don't even bring up the concept of "social contract" because it's a meaningless phrase. See Lysander Spooner.
In summation, we live in the Fascist State controlled by an oligarchy of the rich who regard us with contempt. Only the knowledge of an armed citizenry prevents them from loading the trains with "deplorable" and sending us to camps.
If that be paranoid, then I'l misquote a 60's meme "Just because I'm paranoid doesn't mean they aren't out to get me!"
"And how we burned in the camps later, thinking: What would things have been like if every Security operative, when he went out at night to make an arrest, had been uncertain whether he would return alive and had to say good-bye to his family? Or if, during periods of mass arrests, as for example in Leningrad, when they arrested a quarter of the entire city, people had not simply sat there in their lairs, paling with terror at every bang of the downstairs door and at every step on the staircase, but had understood they had nothing left to lose and had boldly set up in the downstairs hall an ambush of half a dozen people with axes, hammers, pokers, or whatever else was at hand? . . ." — Alexander Solzhenitsyn
So, whomever is sent to collect the guns, should be aware that unlike Germany in the 1920's, gun owners in the USA will not go quietly.
BTW your link to comment is broken. I assume it's an accident; not deliberate.
Categories GUNS•Tags Global Research, Greg Guma, John Lott, Ruby Ridge, the Bonus Brigade, the Native Americans, Tom Woods, Waco
GOLDBUG: Gold prevents theft by the politicians
Published on Monday, November 16, 2015 Friday, November 13, 2015 by reinkefj1 Comment
http://tomwoods.com/podcast/ep-529-leftist-site-attacks-gold-standard-heres-our-smackdown/
Ep. 529 Leftist Site Attacks Gold Standard; Here's Our Smackdown
ThinkProgress, the heresy-hunting thought-control site, lashed out at Ted Cruz last week for advocating some kind of tie between the dollar and gold. Cruz himself is not the issue; the issue is how terrible their article was. Their article is the bologna; the Tom Woods Show is the slicer.
About the Guests
Joseph T. Salerno is academic vice president of the Mises Institute, a professor of economics at Pace University, and the John V. Denson II Professor of Economics at Auburn University.
Jeffrey M. Herbener is chairman of the department of economics at Grove City College and associate editor of the Quarterly Journal of Austrian Economics.
SALERNO: Yeah, that's true, absolutely. In the 19th century, prices from 1800 or so toabout 1896 fell by about 20%. In other words, $1 bought roughly 20% more in 1896 than it did in 1800, whereas if you compare the timespan that the Fed was in existence from 1914 until today, our dollar's worth about 4 cents. So in other words, the value of the dollar has declined by over 95%, and it has nothing to do with — that is, the 19th century performance — had nothing to do with the fact that the dollar was tied to a"shiny metal" and that the value was real; it's simply that the gold standard restrained the number of dollars that politicians could print.
I think the essential point, of a "gold standard" or any "sound money", is the restraint it put on the banksters to dilute the value of money. At least the Kings and Princes of old had to "clip" the gold and silver out of the coins.
I came to this epiphany when I saw a Smithsonian exhibit of the French franc over time. IT started as a "hockey puck" of gold and wound up as a "very very thin shirt button" of gold. Argh! That's when the light bulb went off. All I could think at the time was William Jennings Bryan saying "I will not help to crucify mankind upon a cross of gold." We should have stuck with gold!
I can't imagine what America would be like if we didn't have the FED (The Federal Reserve Bank is a misnomer. IT ain't "federal". It reserves nothing. And, it ain't a "bank". It is a private cartel of the elite banks run for their benefit and that of the entrenched politicians.) which allowed the welfare / warfare state to silently rob the people of their wealth. Argh!
Now try to lock the proverbial barn door.
The FED's "zero interest rate" policy for the last eight years (?) is a double disaster — (1) without interest rates to filter "bad" capital projects, all sorts of mistakes are being made; AND (2) the poor old senior citizen on a fixed income have had their wealth destroyed.
Hope there is a special circle of Hell for these people.
Good job by Woods, Salerno, and Herbener to knock this out of the "park".
Categories GOLDBUG•Tags Gold Standard, Jeffrey M. Herbener, Joseph T. Salerno, Ted Cruz, ThinkProgress, Tom Woods
ECONOMICS: Tom Woods give a clear definition and distinction
Published on Tuesday, July 29, 2014 Wednesday, July 23, 2014 by reinkefjLeave a comment
http://www.lewrockwell.com/2014/07/no_author/why-were-winning/
The Role of Austrian Economics in the Liberty Movement
Tom Woods kicks-off this year's Mises University with a brilliant discussion of the 'Role of Austrian Economics in the Liberty Movement'.
An interesting hour.
I was fascinated by his clear definition and distinction between "Austrian Economics" (i.e., von Mises et al.) and the "Liberty Movement" spawned by Ron Paul.
Are "we" a minority? Absolutely.
So were the Dead Old White Guys!
The interesting part is about "we are winning" because "our" ideas align more closely with reality that do the Keynesian Economics and the big Gooferment welfare / warfare state with it's Crony Capitalism, corrupt politicians, and lifetime lazy bureaucrats.
On to New Hampshire, as part of the Free State Project (http://freestateproject.org) to make it the FIRST truly "Free State".
Categories ECONOMICS•Tags Austrian Economics, crony capitalism, Free State Project, Keynesian Economics, Liberty Movement, Mises University, New Hampshire, Ron Paul, Tom Woods

redpajama_set_name: RedPajamaCommonCrawl


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Q: How can I add a search field on my processing page? I have created a custom processing page called "Kardex Process", by default it doesn't add a search field, and I want to include it.
See the screenshot below:

I want to include it as well as on the Release AP Documents screen, see the screen below:

Can you help me with this?

A: You need to define FastFilterFields property in the grid control and list fields that you want to be included in the search.
<px:PXGrid ID="grid" runat="server" DataSourceID="ds" ... SkinID="PrimaryInquire"       FastFilterFields="RefNbr,VendorID,VendorID_Vendor_acctName">

redpajama_set_name: RedPajamaStackExchange


A 47% plurality of respondents believe the nominations of Moore and Cain along with the president's critical remarks about the Fed are "reducing the central bank's independence" and they think that could have implications for markets and the economy.
For the moment, respondents don't believe the president's criticism will affect monetary policy, but there's more concern now. Sixty-five percent say the president's comments has "no effect on rate hikes" but that is down from 83% when the question was last asked in November. And 22% believe President Trump's remarks make rate hikes less likely, up from 14%.
Robert Brusca at Fact and Opinion Economics said the president has a right to speak out on Fed policy, "… but it's dumb…The Fed may wait too long to do what the president wants it to do to avoid the appearance of being bullied successfully." Brusca thinks the Fed might actually have raised rates in December to avoid the appearance of caving to political pressure.
It also appears that markets are getting somewhat more accustomed to the president's Fed criticism. President Trump has broken with a decades-long tradition of presidents not commenting on monetary policy. In July, when the question was last asked, 83% found President Trump's commentary inappropriate. Now, it's 61%.
"These are very different times and I don't believe this challenge to the Fed's independence will continue after Trump leaves office," said Chris Rupkey, Chief Financial Economist, MUFG.


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using System;
using System.Collections.Generic;
using System.Linq;

class SubSetSums
{
	// declarations
	static int[] numbers;
	static int N;
	static bool solution = false;

	static void Main()
	{
		N = int.Parse(Console.ReadLine());
		numbers = Console.ReadLine().Split(' ').Select(int.Parse).ToArray();

		Console.WriteLine();
		List<int> subset = new List<int>();
		MakeSubset(0, subset);

		// if no sum matches S
		if (!solution)
			Console.WriteLine("No matching subsets.");
	}

	static void MakeSubset(int index, List<int> subset)
	{
		int sum = subset.Sum();
		if (sum == N)
		{
			PrintSubset(subset);
			solution = true;
		}

		if (subset.Count == numbers.Length)
			return;

		for (int i = index; i < numbers.Length; i++)
		{
			subset.Add(numbers[i]);

			MakeSubset(i + 1, subset);
			subset.RemoveAt(subset.Count - 1);
		}
	}

	static void PrintSubset(List<int> subset)
	{
		Console.WriteLine("{0} = {1}", string.Join(" + ", subset), N);
	}
}

redpajama_set_name: RedPajamaGithub


I got up a little later than usual, it was almost 8am so I decided to go for a really quick run because I was feeing kind of lazy and I didn't want to be too sweaty for our walk into the town markets for breakfast. As it turns out Yenzu decided she would drive us in anyway, she is such a gem. Apparently last night Shen kept partying all the way up until Yenzu drove him to the airport at 4am, he is a machine and she is unstoppable! Eugenia went back for some family time and Justin, Yenzu, Kristina and I headed into town. We had steam buns and bean porridge for breakfast and got a few bits and pieces at the grocery store. We're all a bit hooked on the Nescafe instant sachets of super sweet fake coffee, we also stocked up on dessert bun things, pretty much buying whatever the shop assistant pointed to. We came back to Shen's and I got stuck into planning my work timetable for when I get home. We had a big lunch with loads of delicious vegetarian stuff and all headed back to our respective work spots. I started writing a bit of a speech that I have to deliver next month. The theatre next door seemed to be testing their equipment and there was some quite beautiful, but incredibly loud music blasting out all afternoon. Around 4pm Justin and I did a bit of exercise and Eugenia, Susan, Ida and Qino arrived to hang out and have dinner. We hung around chatting for a bit and had a vegetarian dinner. Next door seemed to come to life again and there was a very fancy event going on. After dinner we headed upstairs to check it out ad could see a full stage show with a DJ and live Chinese opera, spotlights and a huge LED moon. There were lot's of rich looking people streaming in and out and a lot of chefs walking around. Ida as having a great time dancing away while everyone else kept her from getting too close to the railing. The show finished and we wandered inside one of the upstairs studio to find Yenzu busily painting away for Shen. Seriously, she does so much work cooking, driving, cleaning, giving head massages as well as being an amazing painter finishing massive works for Shen on a Sunday night. Completely unstoppable. I hung out with Justin for a while and chatted to Anna before doing a little more grant writing. Time for bed I reckon.


Holiday camping can be seen as the easiest form of camping. You go to a designated camping area where toilets and showers are available, where often you have electricity outputs and where there's plenty of activities organized by the camping staff. But even though nature is not going to be a real challenge here, there's plenty of other things you have to keep in mind to make them most out of it.
What campsite: Book a campsite according to your needs. Are you bringing an animal? Do you want showers on site? Is barbecuing allowed? Is it a family friendly camping? Is there a bar nearby?
Buying: Camping gear can be pretty expensive so make sure to buy it off season. Also make sure to see your tent pitched before you buy it.
Pitching the tent: After buying the tent, pitch it at home so you know how to do it. It can take some time to get the hang of it, something you don't want to figure out at the campsite.
The pitch: One of the most important things of camping is the pitch itself. Especially with holiday camping because people tend to stay in one place for a few weeks. Make sure its flat, there's no rocks, it's not too close to a stream (flooding) or under trees (falling branches).
Direction: First: face the front of the tent away from the wind. Second: depending on what sort of campsite you're on, don't face the door right to your neighbors but favorably towards nature.
Packing: Put some care in folding and rolling the tent because it will be a real challenge to put in in the bag if you don't. Last but not least, to prevent molding make sure the tent is dry when you pack it.


When looking up places to eat in New York City, Ellen's Stardust Diner features on almost every list. This diner located in Times Square is famous for its singing servers, who are all auditioning for roles on Broadway. I'd been quite hesitant to visit as I'd heard that the food isn't great and I wasn't sure if it would actually be fun or a bit gimmicky. But when two of my friends were visiting NYC at the end of January and wanted to visit - I thought it was about time I tried it out for myself.
Ellen's Stardust Diner is located in Times Square at 1650 Broadway. It's a good location if you're right in the centre of New York and would be fantastic for those staying at hotels in the area. The B, C, D, E, F, N, R and W subway lines all run closeby too. We arrived around 6pm on a Saturday night so real prime time and waited around 40 minutes for a table. I don't think this is bad at all, it is not uncommon to wait at New York restaurants so it's actually a pretty short line for somewhere so famous. Although, do consider that larger groups will wait longer (we were a three).
This diner is so much fun. All of the wait staff are aspiring Broadway stars and sing as they serve. The songs were a mix of musical songs or well-known ballads. Not only were they fantastic but they really interacted with the customers and it was a lot of fun. It was just a really good atmosphere! Considering how busy it was, we didn't feel rushed at all. We noticed that they generally repeated what they were doing every hour with certain announcements etc. They aren't always singing though. Sometimes they stop and play some music between songs but the staff definitely deserve a break. You can see some clips from my visit in this vlog.
For my main, I decided to go for chicken tenders which were served with honey mustard, waffle fries and onion rings. The portion was a good size and the chicken tenders were huge. I wasn't able to finish it all. The waffle fries were delicious, so tasty and crunchy. The onion rings were thin and crispy. I was struggling by the time I got around to the tenders but the meat was fresh and the breadcrumbs had a delicious flavour to them.
The menu features a lot of classic diner food: burgers, sandwiches, salads etc. Not particularly exciting but something to suit everyone. I went for the tenders because I was in a funny mood, not feeling great and just fancied something plain. I really enjoyed my food but it certainly isn't the best food I've ever had in NYC. But that being said, I don't think the food is the main attraction at Ellen's Stardust Diner. If I were to go back, I'd try their fish and chips or maybe a burger.
To optimise our time in the restaurant we also ordered a dessert. I'd recommend going for at least 2 courses to get the maximum amount of time there. We ordered a salted caramel cheesecake to share between the three of us as at this point we were all really full. It was really good!
Between the three of us, our bill (tip included) came to about $100 for mains, soft drinks and a shared dessert. This is very reasonably priced for New York and especially Times Square. I'd say that would be expensive for the same food at another diner but here you're really paying for the experience. They also come round with a bucket once an hour to collect additional tips.
All in all, we loved our experience at Ellen's Stardust Diner and I would really recommend it. That being said, don't go here expecting the best food in the city and to be able to get a table without a wait.


text:
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Beaman Oak (1902)
The Beaman Oak has been mentioned several times in previous historical posts, but we have never before we shared an actual photograph of the tree. The Beaman Oak existed long before Ezra Beaman settled in what would become West Boylston. The tree overlooked Beaman Cemetery, where Ezra and his descendants were buried for generations (their graves were later relocated to Mount Vernon Cemetery). The tree was chopped down on January 21st, 1902. At the time of its removal, it was 75 feet tall with a trunk base 27 feet in circumference. The branches stretched over a range of over 100 feet. The Oak had 227 rings when it was cut down. Legend says that Ezra fitted the base of the tree with numerous iron spikes to prevent the tree being cut down.
In July of 1902, the Beaman Oak was turned into furniture by Joseph L. Howe and his son, Ernest Howe. Parts of the tree went to its final owners, the Dorcas Society of the West Boylston First Congregational Church. The Dorcas Society used parts of the tree to furnish the parlor and mantel of the Congregational Church and made souvenirs to sell to people from surrounding towns. There are chairs, gavels, tables, canes, toothpick holders, and others made from the Beaman Oak. The historic tree is represented on West Boylston's town seal.
Below are two photographs of the Beaman Oak. One depicts the Oak on a sunny day, while the other depicts the Oak shortly before its end. This photograph is featured in a frame…made from the Beaman Oak! While it was sad for such a historic tree to fall, it's wonderful to think that it became part of everyday life here in West Boylston and Worcester County.
← Water Trough (1700's)Christmas Eve (1917) →


Assessing the effects of labor market reforms from a global perspective at the International Labour Organization headquarters, Geneva.
The annual meeting of the Society of Labor Economists (SOLE) attracts more than 300 economists from academic, government and private sectors.
The IZA Summer School brings together PhD students and senior lecturers to study new areas in labor economics, present their work, and discuss ideas in a relaxed and open atmosphere.
AM² provides a unique environment for experts, researchers, and junior scholars to present innovative research and exchange ideas related to migration. Professor George J. Borjas will deliver this year's Julian Simon Lecture.
This year, the Organisation for Economic Co-operation and Development (OECD) forum takes the theme of "Productive Economies, Inclusive Societies."
Investigating ways in which international migration affects economic and social change in developing countries.
The 30th Annual Conference of the European Society for Population Economics (ESPE) is being organized by the German Socio-Economic Panel (SOEP) and the German Institute for Economic Research (DIW Berlin).
Bringing together academics and policy makers to discuss labor markets dynamics and their relation with growth. Drawing on state-of-the-art economic research, we are looking for new evidence on the labor market responses to macroeconomic and policy changes after the Great Recession, and on how employment levels and wages are likely to react to different labor market programs and policies.
Three days before the EU referendum, IZA World of Labor and the Bloomsbury Institute present a panel discussion on the effects a possible Brexit might have on the UK labor market and EU immigration. The panel features economist Jonathan Portes, Conservative politician and MEP Geoffrey Van Orden, Professor L. Alan Winters, and Allie Renison of the Institute of Directors. Moderated by Economist journalist Philip Coggan.
The Leibniz Institute of Agricultural Development in Transition Economies (IAMO) Forum focuses on the interlinkages between people's mobility across localities, countries, sectors and types of employment as well as local economic development.
This joint conference will present new research on employer engagement in education and technical pathways, and explore implications for policy and practice.
The joint committee of the University (Geneva School of Economics and Management) and the Graduate Institute of International and Development Studies of Geneva are delighted to host the 31st annual congress of the European Economic Association and the 69th European meeting of the Econometric Society.
The aim of the 2016 workshop of IZA's "Environment and Employment" program area is to bring together researchers analyzing wider labor market impacts of environmental policies.
AIEL are pleased to invite you to attend the 31st annual Conference of the Italian Association of Labour Economists which will be hosted by the University of Trento, on September 22–23, 2016.
The event addresses evidence-informed policy globally across all sectors, with active participation from both producers and users of evidence.
The annual conference of the German Economic Association.
The bi-annual conference on labor market policy evaluation organized by IFAU Uppsala and IZA.
A workshop on job quality in post-transition, emerging, and developing countries.
A conference to bring together policymakers and researchers to discuss developments in counterfactual methods applied to the impact evaluation of policy interventions, with a focus on EU employment and social policies.
An expert discussion on the consequences of Brexit.
A workshop to analyze the Chinese labor market.
Joint IZA/OECD seminar to discuss policies to improve people's working environments.


A fussy bachelor who imagines himself the last word in child care runs afoul of the adorable Baby Peggy and is corrected by this pint-sized expert. Introduced, March 10, 2006, by the film's star, Diana Serra Cary, the former Baby Peggy Montgomery. Live music by David Drazin.
In the 1920s there were two adored child stars, silent era precursors to that adored moppet of the 1930s, Shirley Temple. One was Jackie Coogan, whose costarring role with Charlie Chaplin in The Kid assured his place in the movie star pantheon. The other was Baby Peggy Montgomery, whose astronomical salary, million and a half yearly fan letters and variety of official licensed Baby Peggy products put her at the vanguard of both celebrity and merchandising at the beginning of the studio era.
Wheras Chaplin's concern with his own immortality assured Coogan's as well, Baby Peggy was a different story. She worked mostly for a small, cheapskate studio, the Century Film Corporation, churning out two reel comedies, first in tandem with Brownie, the Wonder Dog (also a Chaplin star, in A Dog's Life) and then as a solo. Jackie Coogan continued his career by starring in a series of classic stories in which a boy was the hero, like Oliver Twist. There were a few classics with little girls as the main character, and which lacked a female star. Independent producer Sol Lesser signed her to star in film versions of the famous novels Helen's Babies, Captain January and Heidi, although the latter was never made. The last two became Shirley Temple hits a decade later. Baby Peggy made only nine features and two of them, Helen's Babies and Captain January, have recently been preserved by the Library of Congress.
and this one of Rudolph Valentino in The Sheik.
Baby Peggy's father, Jack Montgomery, was a real life cowboy. With the decline of the Old West, many cowboys found themselves at the end of the cattle drive, Los Angeles. The bar where they hung out and swapped stories in the 'teens was near one of the early movie studios, and soon they were being hired to do what was essentially their old job—only in front of a camera. For many years, these cowboys, proud to keep working on horse back and not have to take a "standing up" job, were the mainstays of the Hollywood stunt world—the riders you see making the Charge of the Light Brigade, or racing through Sherwood Forest, are cowboys.
Lured away from Century Studios, she signed a lucrative contract with Sol Lesser for a year, one and a half million 1920s dollars, and a 50/50 split on her films' profits. Nationwide public appearance tours not only promoted her pictures, but products like the very first book-movie tie-in, a lavishly illustrated movie version of Captain January, along with Baby Peggy dolls and numerous product endorsements.
Many child actors are washed up at adolescence, but for Baby Peggy, the fall came much earlier, when her front teeth fell out, at six. She embarked on a vaudeville tour at $1500 a week that lasted as long as vaudeville did, but then, with no formal schooling and few prospects, her fortune, naturally, squandered by her parents and managers, stardom was over. The high life for the tiny star had consisted primarily of hard work. When her early films returned from their circuit, the economical Century Studio owners had melted the prints down to salvage the silver in the film emulsion, and many of her other films were destroyed in a studio fire, erasing most of Baby Peggy's career from film history. It took Diana Serra Carey a long time to find a new career as a writer, a scholar of Western history, and of child performers on stage and screen, and to eventually reconcile with her childhood avatar, that adorable sprite, Baby Peggy.
Richard Griffith, author of The Movies, a book I studied religiously as a child, called Baby Peggy "long forgotten" but he didn't forget to include a photo of her in his book.
Diana Serra Carey is virtually the only surviving silent film star still making public appearances. Her unique insight into the lives and careers of young actors in her books Hollywood's Children, What Ever Happened to Baby Peggy? (her autobiography) and Jackie Coogan: The World's Boy King: A Biography of Hollywood's Legendary Child Star make her an authority on a phenomenon often analyzed, but rarely from the inside out. Only the rare child star wants to remember those years, not of carefree fun in the studio, but grinding work and exploitation by parents and managers. She has been a friend of, and a mentor to many subsequent child stars, who have benefited from the experiences of this pioneer of film and film stardom.
This newly restored print of Helen's Babies made by the Library of Congress was premiered at the Pordenone Silent Film Festival in 2002, and shown there again in 2004. Baby Peggy may have been good at following direction and displaying emotions, but as you will see in Helen's Babies, she has a real instinct for improvisation—she steals scenes from veteran Edward Everett Horton not just because she is cute, but because she is skilled. We're so pleased to have shown this charming film, with the excitement of live music by Maestro David Drazin and the added attraction of the presence of its star.
After the enthusiastically received screening of Helen's Babies, the elegant Ms. Cary graciously answered questions. The audience was curious about what it was like on the set of a silent film. So many of us have internalized the scenes from Singin' in the Rain as the definitive representation of filmmaking in the 1920s. But, Ms. Cary said that sets were quiet during shooting, the cry "Hold the hammers" signaled for silence amidst construction. Just because a film was silent didn't mean you didn't have to learn dialogue, she explained. A muffed line might not be a problem, but it was important that you were speaking proper dialogue. Most surprising was her description of the gagman's role on the set. The most memorable scenes to me in the film are the sequences where Baby Peggy attempts to return some springy stiff collars to their circular box, and tries to wipe a smudge off the nose of the sleeping Edward Everett Horton. In fact, those bits of business were supplied on the set by gagman Lewis Milestone, who would one day win an Oscar as the director of All Quiet on the Western Front. It was he who would recommend to Horton, don't just pick up Peggy and set her on the bed, set her on your hat. The fact that such moments were the provenance of neither the director or the scriptwriter was surprising. One question was whether she was really crying when she appeared to cry in the film. She said yes, each actor had their "crying music" which would always produce tears. For her it was "I'll Take You Home Again, Kathleen," "Danny Boy" and "My Buddy." At the screening of Captain January the following day at the Sunrise Theater in Southern Pines, NC, when Baby Peggy burst into tears, David Drazin played "My Buddy" for her. After the screening, Ms. Cary said it made her cry then, too.
Diana Serra Cary with some of the Baby Peggy dolls sold in the 1920s during the height of her stardom.
For everything else you want to know, here is Tim Lussier's Silents Are Golden Helen's Babies feature.
David Drazin, who played for the March 10, 2006 showing at the North Carolina Museum of Art, is a pianist and jazz archivist living in Chicago. His regular gig is with the Gene Siskel Center at the Art Institute of Chicago, but he has played in venues all over the country, and in 2003 and 2004 was invited to play at the world's most prestigious silent film festival at Podenone, Italy. He not only accompanied the curtain raiser, Daddy Don't, a short silent film made with a hand-cranked camera by the Wisconsin Biograph Company at the University of Madison, Wisconsin, but he stars in it, too. In a 2005 review of David's music for a retrospective of Yasujiro Ozu's silent films, Chicago's second most famous film critic, Jonathan Rosenbaum of the Chicago Reader, said, "the accompaniments of David Drazin alone are worth the price of admission." Here is the link to the David Drazin website.
(Photos courtesy of Ms. Cary unless otherwise noted. Sources include her books as noted, as well as her Hollywood Posse).


text:
Q: Google is returning an 'App isn't verified' error when trying to authenticate with a Gmail account Google is returning an 'App isn't verified' error when trying to authenticate with a Gmail account. This is happening on both Android and iOS.
Some users are seeing an error that the 'app isn't verified' and need to click 'Advanced' to proceed and others do not see an option at all.
I've attempted the following, yet the issue persists.

*

*Verified ownership of all authorized domains used

*Provided all scopes that the project uses

*Updated the OAuth consent screen, including all authorized domains and application scopes

Does anyone have any ideas on what else I need to do to resolve this ?


text:
Slack Messaging List
The Society for Conservation Biology's Conservation Genetics Working Group (SCB CGWG) is a global community of conservation-minded people interested in the application of genetics to the conservation of biological diversity.
Slack is an instant messaging platform CGWG uses for communication within committees, and also reposts all announcements sent to the SCB listserv. Request an invitation by sending an email with subject line "Join Slack," a sentence about your interest in conservation genetics, and your preferred email to conservegeneticswg@conbio.org.
Hashtags: #conservationgenetics #congen #SCBcongen
Over the past 20 years, genetics has emerged as a very important tool for conservation and it is now well established that it can be used to accomplish conservation-oriented goals. Nevertheless, there is a gap between genetic research outcomes and conservation management.
Our vision is to promote the use of genetics in conservation by having a community of conservation scientists that are aware of how genetics can contribute to conservation decisions.
We intend to become a leading organization for the integration of genetics in the practice of biodiversity conservation, partnering with other conservation genetics groups and organizations.
The aim of the CGWG is to promote the incorporation of genetic studies into the wider field of conservation and to improve the way results of genetic studies are communicated to the broader conservation audience, by:
Facilitating the incorporation of genetics in conservation practice
Making the CGWG a well-established working group within and beyond the SCB
Developing and carrying out organizational core functions for an efficiently running working group.
To join the Conservation Genetics Working Group you must be an active member of the Society for Conservation Biology. If you are already an SCB member, you can become a member at any time by logging into your member profile webpage and using the "Member Quick links" to view and edit the groups you are part of.
Non-members are free to use any resources on our webpage as well as join our Slack group and participate in the group's activities. If you are not a member but would like to join the Working Group you can start here.
If you have any questions, please contact us: conservegeneticswg@conbio.org
Donate to the Conservation Genetics Working Group! Go
Conservation Genetics
Tweets by SCB CGWG


text:
Tag: Final Fantasy XIV
Final Fantasy: Record Keeper crossover event with Final Fantasy XIV begins today
On Sep 21, 2015 5:04 pm, by AndrewH
Last month we reported on Square Enix hosting a crossover event between Final Fantasy: Record Keeper and Final Fantasy XIV. Well that crossover event has now begun as of today and players of Final Fantasy: Record Keeper will now be able to experience some of the popular content from the MMORPG.
Final Fantasy: Record Keeper will have a cross-over event with Final Fantasy XIV next month
On Aug 27, 2015 7:04 pm, by AndrewH
DeNA and Square Enix have announced today that they will be doing a cross-over event with Final Fantasy: Record Keeper and Final Fantasy XIV which will start next month. Final Fantasy: Record Keeper will be featuring the more popular content from the MMORPG during the cross-over event.


text:
const fs = require('mz/fs')
const path = require('path')
const parseArgs = require('minimist')

const { printHelp } = require('./utils/cli')

module.exports = async function (target) {
  const args = parseArgs(process.argv.slice(2))
  const subCmd = args._[0]
  delete args._
  const opts = args

  let stats = await fs.stat(target)
  if (stats.isDirectory()) {
    target = path.resolve(target, subCmd)
  } else if (!stats.isFile()) {
    throw new Error(`${target} is not applicable as a command`)
  }

  const command = require(target)
  if (opts.help || subCmd === 'help') {
    process.stdout.write(printHelp(command.describe || command.desc, command.options))
  } else {
    return await command.handler(opts)
  }
}


text:
The Nerd Signal
AQUAMAN Movie's On The Way, But From Which Writer?
Skott Stotland August 12, 2014 Leave a Comment on AQUAMAN Movie's On The Way, But From Which Writer?
Aquaman is definitely heading to the big screen, even if he doesn't show up in Batman v Superman (but he totally will) and regardless of whether or not Jason Momoa is playing him (but he totally is).
According to The Hollywood Reporter, Warner Bros. is moving forward on the Aquaman film but they're not exactly sure what they want it to be yet so they've hired two writers to work on it. The catch is that they're not working together.
Will Beall, writer of Gangster Squad and a bunch of episodes of Castle is going to take a crack at the King of Atlantis, while Kurt Johnstad, who wrote both 300 movies and Act of Valor (that weird movie where real Navy SEALs played themselves) is going to be turning in a presumably much more testosterone-fueled version.
I'm predicting Johnstad's script will be easier to picture Momoa in. In fact, given his previous work and history with Snyder, I'd be very surprised if Johnstad didn't get the job. And as much as I'd do literally anything to see Jason Momoa play the Brave and the Bold version of Aquaman, he'll probably be more like this.
Author: Skott Stotland
Skott Stotland is a thousand monkeys in a man suit. He has been writing for the internet for over a decade.
Michael Bay Quits TRANSFORMERS Movies, Fans Celebrate Like The End Of RETURN OF THE JEDI →
← We're Getting Even More VERONICA MARS… Kinda
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JUSTICE LEAGUE SNYDER CUT To Be R-Rated Because Of Course
READY OR NOT – A Review
HARRY POTTER Mystery Flying Snitch – A Review
Watch Every Movie Trailer From San Diego Comic Con 2018
Watch Every TV Trailer From Comic Con 2018
Cast Announced For ADDAMS FAMILY Animated Film
NECA's SDCC Exclusive NINJA TURTLES Are Amazing
SUSPIRIA Remake Gets A Surprisingly Good Trailer
Toys R Us Wants Your Kids To Go Play
Copyright © 2021 The Nerd Signal


text:
Seeking justice for mother's murder, son visits India for 89th time in 16 years
NH Bureau Sunday, 12 January 2020 10:56:16 AM 3 minutes, 46 seconds
New Delhi : For the 89th time in 16 years, Vancouver (Canada) businessman Sanjay Goyal has come to India to seek justice against his mother's murder. Mr. Goyal said, "I am hoping and praying that the justice system in India will no longer delay any case".
Goyal on Monday 13th January before leaving for Mumbai for a test management conference in front of T. Ghadge at 11.15 AM to Additional Sessions Judge N, said, "I have been wandering in India for last 16 years for justice against killing my mother. We want justice for my mother and hope to see the culprits behind the bars. "
Sanjay Goel's mother, Dr. Asha Goyal, was a 62-year-old Canadian obstetrician woman from Orangeville. In August 2003, she was stabbed to death in a property dispute in Malabar Hills Flat, Mumbai. Asha Goyal, 40, an obstetrician and gynecologist who also worked in Saskatchewan was murdered amid a bitter dispute over the inheritance of $ 10 million (about 70 million) that pitted her against her brothers. "She wanted to broker peace between her brothers and was killed in cold blood," Goyal said.
The Mumbai Police believes that the four murderers were hired by Dr. Goyal's warring brothers - Suresh and Subhash Aggarwal to kill their sister and make it look like suicide.
Suresh, who lived in India, died in November 2003. Subhash Aggarwal lives in the Toronto as a Canadian citizen. He denies his involvement in Asha Goyal's murder and in court's documents he describes the police charges against him as "a vilification campaign". About a month after Dr. Goyal's murder, the Mumbai police arrested a suspected killer, but the case was inexplicably dropped.
Son Sanjay told, "We were angry with this information so in January 2004 this case was transferred to Mumbai Crime Branch."
The case registered with Malabar police station and was later transferred to the Mumbai crime branch. However, since 2006, the case has been stuck in legal tangle in the higher courts.
In 2005, suspected accused Pradeep Parab had said in a confession filed by a magistrate that his brother Suresh Aggarwal had hired him to kill Asha Goyal.
He had also identified his colleagues. His names are P.K. Goenka, M. Shinde and Narenda Goyal (no relation to the victim).
After he was charged by the police, he listed Canadian brother Subhash Aggarwal as the "wanted accused". Pradeep Parab became a witness after submitting a written statement, while another accused M. Shinde died.
In 2017, the magistrate court finally committed the case to the sessions court for trial following the Supreme Court's directive.
Goyal said, "Two of the main accused have died and I have been told that some evidence has gone missing. We may never get justice if there is further delay. Justice delayed is justice denied. I have been trying for 16 years, but I did not get any help from the Government of Canada to investigate or take action againstSubhash Aggarwal, who lives in Toronto. Despite being listed by Interpol for the murder, they (Interpol) call it an Indian case and say it doesn't fall under their purview. My mother was a proud Canadian. She was an advocate for the protection and women's health care system. But I did not get any help from Canadian government after her killing."
Subhash Aggarwal, who is listed on the Interpol Red Notice website, says he is ready to talk to investigators in Canada, but is not in favor of detention in India.
The son's fight to bring justice to his mother is reminiscent of the long-running Canadian-British assassination incident involving Jasvinder Kaur Sidhu, a beautician from Maple Ridge in British Columbia.
Legal experts said that according to a report by the Vancouver-based South Asian Post, the Dr Goyal and Jassi murder cases are dozens of "NRI (non-resident Indian) contract murders" conducted by the convicts, who believe that India cannot extradite accused.
Reportedly, in many cases, poorly paid Indian policemen play a role in murders or help cover up evidence after they are paid in foreign dollars.
In most cases, broken marriages, illegal cases and property disputes are ordering NRIs to be killed.
It may be noted that in 2017, the main accused, Asha Goyal's son-in-law, Narendra Goyal was released. Asha Goyal had 21 injury marks on her body.
In 2005, the magistrate's court upheld the case in the sessions court. In 2006, when the court was supposed to frame charges against the accused, they went free from the case. But his sessions were dismissed by the sessions court in 2012. Today, for 16 years, Asha Goyal's sons has come to India 89th times, seeking justice for his mother.
Murder Case
Indian Court
Asha Goyal
Asha Goyal Murder Case
Hate rains during travel? Try these three places on your travel bucket
Odisha tourism roadshow in Raipur to present "India's Best Kept Secret"


Meaning and definitions of brow, translation in Bengali language for brow with similar and opposite words. Also find spoken pronunciation of brow in Bengali and in English language.
What brow means in Bengali, brow meaning in Bengali, brow definition, examples and pronunciation of brow in Bengali language.


Direct Federal Credit Union (www.direct.com) of Needham announces that Maria Mendez has received the 2018 National Federal Credit Union Association (NAFCU) Paul Revere Award. The award recognizes Mendez as the credit union grassroots activist of the year.
The award was presented to Mendez in Washington D.C. on September 11th at the 2018 NAFCU Congressional Caucus.
Mendez is the Legislative and Regulatory Affairs Liaison at Direct Federal. In this role she focuses on congressional advocacy, political correspondence and various grassroot efforts at the local and national level. She serves as the liaison between credit union and federal, state, and local government; and has developed and maintained strategic relationships with policy makers to help shape public policy initiatives.
Mendez is a member of the NAFCU Political Action Committee and the Cooperative Credit Union Association (CCUA) Advocacy Committee. Through her committee designations, Mendez works to build awareness of important political influences in the Credit Union Movement. She has also assisted Direct Federal Board of Directors in corresponding with congress regarding key initiatives. During the past summer, Mendez launched a companywide "#DirectAdvocacy" program to educate and engage Direct Federal employees in the Credit Union Movement.
In her spare time, she has used public records and voting statistics to support midterm candidates that demonstrate support for the credit union industry. Maria is NAFCU certified compliance officer, NCCO.
"Maria is a very talented person and she has great deal of passion for her work. Her full skills have been an asset to Direct Federal and the credit union industry at large. She is a very capable leader for our industry," said Joe Walsh, President/CEO of Direct Federal Credit Union.


text:
\section{Introduction.}

 Discovered by Drinfeld \cite{Dr1}
and Jimbo \cite{J1},
Quantum group as a Hopf algebra
presents  a new structure in both mathematics and physics. One of the
fundamental features of this   structure comes from  its
comultiplication, which is basically related  to all the new  concepts in
this structure, such as R-matrix, etc. The  most  widely used
 comultiplication  is given  with  the definition of a  quantum group
 by the basic generators and the relations based on the data coming from the
corresponding Cartan matrix. However, in  the case of quantum affine algebras,
there is a  neglected aspect of the story. In this case, Drinfeld
presented a different formulation of quantum affine algebras with generators
in the form of current operators \cite{Dr3}, for which he proposed another
comultiplication formula \cite{DF1} based  on the current
 formulation. The
fundamental feature of this comultiplication is its simplicity,
as opposed to the comultiplication formula induced from the conventional
 comultiplication which
simply can not be written in a closed form with those current operators.
However, this new comultiplication is seldom  used beyond its definition.
We propose to use this comultiplication formula to study
the vertex operators coming from such a comultiplication.

In this paper,  we will first study the vertex operators
for the fundamental
representations at the level 1 for the case of $U_q(\mbox{$\hat{\gtsl}$}_n)$.
Using  the  Frenkel-Jing construction of level 1 representations of
 $U_q(\mbox{$\hat{\gtsl}$}_n)$ and the conventional comultiplication, the Kyoto
group \cite{DFJMN} \cite{DO} \cite{Ko} studied
the related vertex operators and its application to
XXZ model in statistical mechanics. They obtained
 the bosonization of the
vertex operators, which  is partially  incomplete because
the bosonization can be done only for one component of the vertex operators
while the rest are implicit. With the new comultiplication, we
give a complete and simple formula for the related intertwiners. In the
classical case, these vertex operators are the corresponding Clifford
algebras, from which we can reconstruct the level 1  representations,
otherwise called spinor representations. This gives
the  boson-fermion correspondence \cite{F1} \cite{Di1}. With the
new formula of the vertex operators, which can be interpreted as the
deformed fermions, we  recover the current operators of
$U_q(\mbox{$\hat{\gtsl}$}_n)$.

The main paper contains two sections. In Section 2, we will present the
basic definitions and prove the new comultiplication
formulas. In Section 3, we will present the Frenkel-Jing\cite{FJ}
 construction and
present the explicit formulas for all the corresponding vertex operators.
We will also give some formulas of the construction of the quantum
current from those vertex operators and discuss its connection with
quantum boson-fermion correspondence. In this paper, we will restrict
ourselves to the case of $U_q(\mbox{$\hat{\gtsl}$}_n)$. The extension
of these results to other cases is straightforward and will be the subject
in a subsequent paper.

\section{Drinfeld comultiplication}
The first definition of quantum groups as
a Hopf algebra given by Drinfeld \cite{Dr1} and Jimbo \cite{J1}
are given in terms of
basic generators and relations with corresponding Cartan matrices.
For the case of quantum affine algebras, Drinfeld gave a realization
in terms of operators in the form of current \cite{Dr3}.
We will first present this  realization for the case of
 $U_q(\mbox{$\hat{\gtsl}$}_n)$.

Let $A=(a_{ij})$ be the Cartan matrix of type $A_{n-1}$.
\begin{defn}
The algebra $U_q(\mbox{$\hat{\gtsl}$}_n)$ is an associative algebra with unit
1 and the generators: $\varphi_i(-m)$,$\psi_i(m)$, $x^{\pm}_i(l)$, for
$i=i,...,n-1$, $l\in \mbox{${\Bbb Z}$} $ and $m\in \mbox{${\Bbb Z}$}_{\geq 0}$ and central
 elements $q^{\pm\frac{1}{2}c}$. Let $z$ be a formal variable and
 $x_i^{\pm}(z)=\sum_{l\in \mbox{${\Bbb Z}$}}x_i^{\pm}(l)z^{-l}$,
$\varphi_i(z)=\sum_{m\in -\mbox{${\Bbb Z}$}_{\geq 0}}\varphi_i(m)z^{-m}$ and
$\psi_i(z)=\sum_{m\in \mbox{${\Bbb Z}$}_{\geq 0}}\psi_i(m)z^{-m}$. In terms of the
formal variables,
the defining relations are
\begin{align*}
& q^{\frac{1}{2}c}q{-\frac{1}{2}c}=1, \\
& \varphi_i(z)\varphi_j(w)=\varphi_j(w)\varphi_i(z), \\
& \psi_i(z)\psi_j(w)=\psi_j(w)\psi_i(z), \\
& \varphi_i(z)\psi_j(w)\varphi_i(z)^{-1}\psi_j(w)^{-1}=
  \frac{g_{ij}(z/wq^{-c})}{g_{ij}(z/wq^{c})}, \\
& \varphi_i(z)x_j^{\pm}(w)\varphi_i(z)^{-1}=
  g_{ij}(z/wq^{\mp \frac{1}{2}c})^{\pm1}x_j^{\pm}(w), \\
& \psi_i(z)x_j^{\pm}(w)\psi_i(z)^{-1}=
  g_{ij}(w/zq^{\mp \frac{1}{2}c})^{\mp1}x_j^{\pm}(w), \\
& [x_i^+(z),x_j^-(w)]=\frac{\delta_{i,j}}{q-q^{-1}}
  \left\{ \delta(z/wq^{-c})\psi_i(wq^{\frac{1}{2}c})-
          \delta(z/wq^{c})\varphi_i(zq^{\frac{1}{2}c}) \right\}, \\
& (z-q^{\pm a_{ij}}w)x_i^{\pm}(z)x_j^{\pm}(w)=
  (q^{\pm a_{ij}}z-w)x_j^{\pm}(w)x_i^{\pm}(z), \\
& [x_i^{\pm}(z),x_j^{\pm}(w)]=0 \quad \text{ for $a_{ij}=0$}, \\
& x_i^{\pm}(z_1)x_i^{\pm}(z_2)x_j^{\pm}(w)-(q+q^{-1})x_i^{\pm}(z_1)
  x_j^{\pm}(w)x_i^{\pm}(z_2)+x_j^{\pm}(w)x_i^{\pm}(z_1)x_i^{\pm}(z_2) \\
& +\{ z_1\leftrightarrow z_2\}=0, \quad \text{for $a_{ij}=-1$}
\end{align*}
where
\[ \delta(z)=\sum_{k\in \mbox{${\Bbb Z}$}}z^k, \quad
   g_{ij}(z)=\frac{q^{a_{ij}}z-1}{z-q^{a_{ij}}}\quad \text{about $z=0$} \]
\end{defn}

In \cite{Dr3}, Drinfeld only gave the formulation of the algebra.
If we  extend the conventional comultiplication to
those current operators,
the result would be a very  complicated formula which  can not be written
in a closed form with only those current operators.
However, Drinfeld also gave the Hopf algebra structure
for such a formulation in an unpublished note \cite{DF1}.

\begin{thm}
The algebra $U_q(\mbox{$\hat{\gtsl}$}_n)$ has a Hopf algebra structure, which is  given
by the following formulae.

\noindent{\bf Coproduct $\Delta$}
\begin{align*}
\text{(0)}& \quad \Delta(q^{\frac c2})=q^{\frac c 2}\otimes q^{\frac c 2}, \\
\text{(1)}& \quad \Delta(x_i^+(z))=x_i^+(z)\otimes 1+
            \varphi_i(zq^{\frac{c_1}{2}})\otimes x_i^+(zq^{c_1}), \\
\text{(2)}& \quad \Delta(x_i^-(z))=1\otimes x_i^-(z)+
            x_i^-(zq^{c_2})\otimes \psi_i(zq^{\frac{c_2}{2}}), \\
\text{(3)}& \quad \Delta(\varphi_i(z))=
            \varphi_i(zq^{-\frac{c_2}{2}})\otimes\varphi_i(zq^{\frac{c_1}{2}}), \\
\text{(4)}& \quad \Delta(\psi_i(z))=
            \psi_i(zq^{\frac{c_2}{2}})\otimes\psi_i(zq^{-\frac{c_1}{2}}),
\end{align*}
where $q^{\frac {c_1}2}= q^{\frac c2}\otimes 1$ and
 $q^{\frac {c_2}2}= 1\otimes q^{\frac c2}$.
\noindent{\bf Counit $\varepsilon$}
\begin{align*}
\varepsilon(q^c)=1 & \quad \varepsilon(\varphi_i(z))=\varepsilon(\psi_i(z))=1, \\
            & \quad \varepsilon(x_i^{\pm}(z))=0.
\end{align*}
\noindent{\bf Antipode $\quad a$}
\begin{align*}
\text{(0)}& \quad a(q^c)=q^{-c}, \\
\text{(1)}& \quad a(x_i^+(z))=-\varphi_i(zq^{-\frac{c}{2}})^{-1}
                               x_i^+(zq^{-c}), \\
\text{(2)}& \quad a(x_i^-(z))=-x_i^-(zq^{-c})
                               \psi_i(zq^{-\frac{c}{2}})^{-1}, \\
\text{(3)}& \quad a(\varphi_i(z))=\varphi_i(z)^{-1}, \\
\text{(4)}& \quad a(\psi_i(z))=\psi_i(z)^{-1}.
\end{align*}

\end{thm}
It is therefore
clear that the comultiplication structure requires certain completion
on the tenor space. For certain  representations, such
as the n-dimensional representations of $U_q(\mbox{$\hat{\gtsl}$}_n)$, which will be
presented in the next section,
 this comultiplication may not be  well defined. Nevertheless, in the
case of
any two highest weight representations,  this comultiplication
is well-defined and is already used in \cite{DM} to study the poles and zeros
of the current operators for integrable representations.
We will further
 present the  proof for the theorem above for the case of
$U_q(\mbox{$\hat{\gtsl}$}_2)$.
However, this proof  should
be completely attributed to Drinfeld \cite{DF1}.

 \noindent\underline{Proof for the case of  $U_q(\mbox{$\hat{\gtsl}$}_2)$}

For the comultiplication above we have that
\begin{align*}
\text{(1)}& \quad \Delta(x_1^+(z))=x_1^+(z)\otimes 1+
            \varphi_1(zq^{\frac{c_1}{2}})\otimes x_1^+(zq^{c_1}), \\
\text{(2)}& \quad \Delta(x_1^-(z))=1\otimes x_1^-(z)+
            x_1^-(zq^{c_2})\otimes \psi_1(zq^{\frac{c_2}{2}}), \\
\text{(3)}& \quad \Delta(\varphi_1(z))=
            \varphi_1(zq^{-\frac{c_2}{2}})\otimes\varphi_1(zq^{\frac{c_1}{2}}), \\
\text{(4)}& \quad \Delta(\psi_1(z))=
            \psi_1(zq^{\frac{c_2}{2}})\otimes\psi_1(zq^{-\frac{c_1}{2}}).
\end{align*}
It is clear that
 $$\Delta\varphi_1(z)\Delta\varphi_1(w)=\Delta\varphi_1(w)\Delta\varphi_1(z),$$
$$\Delta\psi_1(z)\Delta\psi_1(w)=\Delta\psi_1(w)\Delta\psi_1(z).$$
Then,
$$ \Delta\varphi_1(z)\Delta\psi_1(w)\Delta\varphi_1(z)^{-1}\Delta\psi_1(w)^{-1}=$$
  $$\varphi_1(zq^{-\frac{c_2}{2}})\psi_1(wq^{\frac{c_2}{2}})
\varphi_1(zq^{-\frac{c_2}{2}})^{-1}\psi_1(wq^{\frac{c_2}{2}})^{-1}
\otimes  \varphi_1(zq^{\frac{c_1}{2}})\psi_1(wq^{-\frac{c_1}{2}})
\varphi_1(zq^{\frac{c_1}{2}})^{-1}\psi_1(wq^{-\frac{c_1}{2}})^{-1}=$$
$$   \frac{g_{11}(z/wq^{-c_1}q^{-{c_2}} )}
{g_{11}(z/wq^{c_1}q^{-{c_2}})}
\frac{g_{11}(z/wq^{-c_2}q^{{c_1}})}{g_{11}(z/wq^{c_2}q^{{c_1}})}=$$
$$\frac{g_{11}(z/wq^{-c_1-c_2} )}
{g_{11}(z/wq^{c_1+c_2})}.$$

$$  \Delta\varphi_1(z)\Delta x_1^{+}(w)\Delta\varphi_1(z)^{-1}=$$
$$\varphi_1(zq^{-\frac{c_2}{2}})\otimes\varphi_1(zq^{\frac{c_1}{2}})
(x_1^+(w)\otimes 1+
            \varphi_1(wq^{\frac{c_1}{2}})\otimes x_1^+(wq^{c_1}))
 (\varphi_1(zq^{-\frac{c_2}{2}})\otimes\varphi_1(zq^{\frac{c_1}{2}}))^{-1}=$$
$$ g_{11}(z/wq^{ -\frac{1}{2}(c_1+c_2)})(x_1^+(w)\otimes 1+
            \varphi_1(wq^{\frac{c_1}{2}})\otimes x_1^+(wq^{c_1})). $$

$$  \Delta\varphi_1(z)\Delta x_1^{-}(w)\Delta\varphi_1(z)^{-1}=$$
$$\varphi_1(zq^{-\frac{c_2}{2}})\otimes\varphi_1(zq^{\frac{c_1}{2}})
(1\otimes x_1^-(w)+
            x_1^-(wq^{c_2})\otimes \psi_1(wq^{\frac{c_2}{2}}))
(\varphi_1(zq^{-\frac{c_2}{2}})\otimes\varphi_1(zq^{\frac{c_1}{2}}))^{-1}=$$
$$1\otimes x_1^-(w) g_{11}(z/wq^{ \frac{1}{2}(c_1+c_2)})^{-1}
+x_1^-(wq^{c_2})\otimes \psi_1(wq^{\frac{c_2}{2}})
g_{11}(z/wq^{ \frac{1}{2}(c_1-3c_2)})^{-1}
\frac {g_{11}(z/wq^{ \frac{1}{2}(c_1-3c_2)})}
      {g_{11}(z/wq^{ \frac{1}{2}(c_1+c_2)})}=$$
$$\Delta x_1^{-}(w)g_{11}(z/wq^{ \frac{1}{2}(c_1+c_2)})^{-1}.$$

The relation between $\Delta\psi_1(z)$ and $\Delta x_1^{\pm}(w)$
 can be proved in the same way demonstrated,

$$ [\Delta x_1^+(z),\Delta x_1^-(w)]=$$
$$[x_1^+(z)\otimes 1+
            \varphi_1(zq^{\frac{c_1}{2}})\otimes x_1^+(zq^{c_1}),$$
$$
1\otimes x_1^-(w)+
            x_1^-(wq^{c_2})\otimes \psi_1(wq^{\frac{c_2}{2}})]=$$
$$[x_1^+(z)\otimes 1, x_1^-(wq^{c_2})\otimes \psi_1(wq^{\frac{c_2}{2}})]+
[\varphi_1(zq^{\frac{c_1}{2}})\otimes x_1^+(zq^{c_1}),
1\otimes x_1^-(w)]+$$
$$ [\varphi_1(zq^{\frac{c_1}{2}})\otimes x_1^+(zq^{c_1}),
            x_1^-(wq^{c_2})\otimes \psi_1(wq^{\frac{c_2}{2}})].$$
It is easy to show that the last term above is 0, therefore we have that
$$ [\Delta x_1^+(z),\Delta x_1^-(w)]=$$
$$\frac{(\delta(z/wq^{-c_1-c_2})\psi_1(wq^{\frac{c_1}{2}+c_2})-
\delta(z/wq^{c_1-c_2})\varphi_1(zq^{\frac{c_1}{2}}))\otimes
\psi_1(wq^{\frac{c_2}{2}})}{q-q^{-1}}+$$
$$\frac{\varphi_1(zq^{\frac{c_1}{2}})\otimes
 ( \delta(z/wq^{c_1-c_2})\psi_1(wq^{\frac{1}{2}c_2})-
          \delta(z/wq^{c_1+c_2})\varphi_1(zq^{c_1+\frac{1}{2}c_2}))}{q-q^{-1}}=$$
$$ \frac{ \delta(z/wq^{-c_1-c_2})\psi_1(zq^{\frac{c_2}{2}+\frac{c_1+c_2}{2}})
\otimes\psi_1(zq^{-\frac{c_1}{2}+\frac{c_1+c_2}{2}})-
\delta(z/wq^{c_1+c_2})\varphi_1(zq^{-\frac{c_2}{2}+\frac{c_1+c_2}{2}})
\otimes\varphi_1(zq^{\frac{c_1}{2}+\frac{c_1+c_2}{2}})}{q-q^{-1}}.$$

$$ (z-q^{2}w)\Delta x_1^{+}(z)\Delta x_1^{+}(w)=$$
$$(z-q^2w)(x_1^+(z)\otimes 1+
            \varphi_1(zq^{\frac{c_1}{2}})\otimes x_1^+(zq^{c_1}))
(x_1^+(w)\otimes 1+
            \varphi_1(wq^{\frac{c_1}{2}})\otimes x_1^+(wq^{c_1}))=$$
$$ (q^{2}z-w)x_1 ^{+}(w)x_1^{+}(z)\otimes 1+
(z-q^2w)\varphi_1(wq^{\frac{c_1}{2}})x_1^+(z)\otimes x_1^+(wq^{c_1})
\left(\frac {q^2z/w-1}{z/w-q^2} \right)+$$
$$
(z-q^2w)x_1^+(w)\varphi_1(zq^{\frac{c_1}{2}})\otimes
x_1^+(zq^{c_1}) \left(\frac {q^2z/w-1}{z/w-q^2}\right)+$$
$$ (q^{2}z-w) \varphi_1(wq^{\frac{c_1}{2}})\varphi_1(zq^{\frac{c_1}{2}})
   \otimes x_1^+(wq^{c_1})x_1^+(zq^{c_1})= $$
$$(q^{2}z-w)\Delta x_1^{+}(w)\Delta x_1^{+}(z).$$

Similarly we can prove the relation between
$\Delta x^-(z)$ and $\Delta x^-(w)$.

Let $M$ be the operator from $U_q(\mbox{$\hat{\gtsl}$}_n)\otimes U_q(\mbox{$\hat{\gtsl}$}_n)$ to
$U_q(\mbox{$\hat{\gtsl}$}_n)$ defined by the algebra multiplication. We can check that
$M(1\otimes \varepsilon)\Delta=\text{ id}$.

$$ M(1\otimes a) \Delta(x_i^+(z))=$$
$$M(1\otimes a)( x_i^+(z)\otimes 1+
            \varphi_i(zq^{\frac{c_1}{2}})\otimes x_i^+(zq^{c_1}))=$$
$$ x_i^+(z)-\varphi_i(zq^{\frac{c}{2}})(\varphi_i(zq^{\frac{c}{2}}))^{-1}
 x_i^+(z)=$$
$$0=\varepsilon(x_i^+(z))$$
Similarly we can check all the other relations to show that
$M(a\otimes 1)=\varepsilon.$
Thus, we prove that the comultiplication, the counit and the
antipode give a Hopf algebra
structure for  $U_q(\mbox{$\hat{\gtsl}$}_2)$.

Presently, there still exist a number of open problems
related to this new Hopf algebra structure.
One is  whether this Hopf
algebra is isomorphic, as a Hopf algebra,  to the
conventional  $U_q(\mbox{$\hat{\gtsl}$}_n)$.

\section{Bosonization of vertex operators}

\noindent{\bf vector representation}

Let $V=\oplus_{i=0}^{n-1} \mbox{${\Bbb C}$}|i\rangle$ be an n-dimensional space,
where $\{ |i\rangle \}$ is its standard basis. Let
$V_z=V\otimes \mbox{${\Bbb C}$}[z,z^{-1}]$, where $z$ is a formal variable.

\begin{lemma}There exists an  n-dimensional representation of $U_q(\mbox{$\hat{\gtsl}$}_n)$
on $V_z$. The action of the current operators is given by the following:
\begin{align*}
\circ& \quad x_i^+(w).|j\rangle= \delta_{ij}
                                 \delta(\frac{w}{q^iz})|i-1\rangle, \\
\circ& \quad x_i^-(w).|j\rangle= \delta_{i-1j}
                                 \delta(\frac{w}{q^iz})|i\rangle, \\
\circ& \quad \begin{cases}
             \varphi_i(w).|i-1\rangle
       & =\dfrac{q^{-1}-q^{-i+1}\frac{w}{z}}{1-q^{-i}\frac{w}{z}}
         |i-1\rangle, \\
             \varphi_i(w).|i\rangle
       & =\dfrac{q-q^{-i-1}\frac{w}{z}}{1-q^{-i}\frac{w}{z}}
         |i\rangle    \\
             \varphi_i(w).|j\rangle
       &=|j\rangle \quad (j\neq i,i-1)
       \end{cases} \in \mbox{${\Bbb C}$}[[\frac{w}{z}]], \\
\circ& \quad \begin{cases}
             \psi_i(w).|i-1\rangle
       & =\dfrac{q-q^{i-1}\frac{z}{w}}{1-q^{i}\frac{z}{w}}
         |i-1\rangle, \\
             \psi_i(w).|i\rangle
       & =\dfrac{q^{-1}-q^{i+1}\frac{z}{w}}{1-q^{i}\frac{z}{w}}
         |i\rangle   \\
             \psi_i(w).|j\rangle
       & =|j\rangle \quad (j\neq i,i-1)
       \end{cases} \in \mbox{${\Bbb C}$}[[\frac{z}{w}]].
\end{align*}
where we set $|-1\rangle =|n\rangle=0$.
\end{lemma}

Let $E_{ij}~(i,j=0,1)$ be the matrix elements such that
$E_{ij}|k\rangle =\delta_{kj}|i\rangle$, let $R(z/w)$ be an
operator on $V_z\otimes V_w$, which is defined as:
$$E_{00}\otimes E_{00}+E_{11}\otimes E_{11}+ E_{00}\otimes E_{11}
\frac{q-q^{-1}z/w}{1-z/w}+E_{11}\otimes E_{00} \frac{1-z/w} {q^{-1}-qz/w}.$$

\begin{prop}
Let $x$ be an operator in $U_q(\mbox{$\hat{\gtsl}$}_2)$, then  on $V_z\otimes V_w$, we have
that $R(z/w)\Delta(x)=\Delta'(x)R(z/w),$
where $\Delta'$ is the opposite comultiplication.
\end{prop}

Similarly, we can write the operator $R(z/w)$ for $U_q(\mbox{$\hat{\gtsl}$}_n)$, which is
diagonal.

Next, we will give the Frenkel-Jing construction of level $1$ representation
of  $U_q(\mbox{$\hat{\gtsl}$}_n)$ on the Fock space.

Let $\overline{Q}=\oplus_{j=1}^{n-1} \mbox{${\Bbb Z}$} \alpha_j$ be the root lattice of
$\mbox{\g sl}_n$, $\overline{\Lambda}_j=\Lambda_j-\Lambda_0$ be the classical
part of the $i$-th fundamental weight.

Let Heisenberg algebra be an algebra generated by
$\{ a_{i,k}|1\leq i \leq n-1,~k\in \mbox{${\Bbb Z}$} \setminus \{ 0\} \}$
satisfying:
\[ [a_{i,k},a_{j,l}]=\delta_{k+l,0}\frac{[(\alpha_i,\alpha_j)k][k]}{k}. \]

Now let's define a group algebra $\mbox{${\Bbb C}$}(q) [\overline{\mbox{${\cal P}$}}]$.
Let $\overline{\mbox{${\cal P}$}}$ be the weight lattice of $\mbox{\g sl}_n$.
We fix our free basis $\alpha_2,\cdots, \alpha_{n-1},\overline{\Lambda}_{n-1}$.
They satisfy
\begin{align*}
& e^{\alpha_i}e^{\alpha_j}=(-1)^{(\alpha_i,\alpha_j)}e^{\alpha_j}e^{\alpha_i}
  \qquad 2\leq i,j\leq n-1, \\
& e^{\alpha_i}e^{\overline{\Lambda}_{n-1}}=(-1)^{\delta_{i,n-1}}
  e^{\overline{\Lambda}_{n-1}}e^{\alpha_i},
  \qquad 2\leq i\leq n-1.
\end{align*}
For $\alpha=m_2\alpha_2+\cdots m_{n-1}\alpha_{n-1}
     +m_n\overline{\Lambda}_{n-1}$, we set
\[ e^{\alpha}=e^{m_2\alpha_2}\cdots e^{m_{n-1}\alpha_{n-1}}
              e^{m_n\overline{\Lambda}_{n-1}}. \]
Note that the following equations hold.
\begin{align*}
& \overline{\Lambda}_i=-\alpha_{i+1}-2\alpha_{i+2}-\cdots
                      -(n-i-1)\alpha_{n-1}+(n-i)\overline{\Lambda}_{n-1}, \\
& \alpha_1=-2\alpha_2-3\alpha_3-\cdots -(n-1)\alpha_{n-1}
           +n\overline{\Lambda}_{n-1}.
\end{align*}

Put
\[ a_{ik}^{\ast}=\frac{1}{[k]^2[nk]}\sum_{j=1}^{n-1}
   [ \min (i,j)k][ \min (n-i,n-j)k]a_{jk},\quad 1\leq i< n, k\neq 0. \]
Then they satisfy
\[ [ a_{ik}^{\ast}, a_{jl}]= \delta_{ij}\delta_{k+l,0}\frac{[k]}{k}. \]
We define the Fock space as:
\[ \mbox{${\cal F}$}_{i}:=\mbox{${\Bbb C}$}(q) [a_{j,-k}(1\leq j\leq n-1,~k\in \mbox{${\Bbb Z}$}_{>0})]\otimes
            \mbox{${\Bbb C}$}(q) [\overline{Q}]
              e^{\overline{\Lambda}_i}
   \quad (0\leq i\leq n-1). \]

The action of operators
$a_{j,k},\partial_{\alpha_j},e^{\alpha}$~
$(1\leq j \leq n-1, \alpha \in \overline{Q})$ is given by
\begin{align*}
a_{j,k}\cdot f\otimes e^{\beta}& =\begin{cases}
                      a_{j,k}f \otimes e^{\beta}          & k< 0  \\
            \text{$[a_{j,k},f]$}  \otimes e^{\beta} \quad & k> 0
                                  \end{cases}, \\
\partial_{\alpha}\cdot f\otimes e^{\beta}&
        =(\alpha,\beta)f\otimes e^{\beta},
         \qquad \text{for}~f\otimes e^{\beta}\in \mbox{${\cal F}$}_{i} \\
e^{\alpha}\cdot f\otimes e^{\beta} &
=f\otimes e^{\alpha}e^{\beta}.
\end{align*}

\begin{lemma}
Let
\begin{align*}
\circ & \quad x_j^{\pm}(z)\mapsto
        \exp[\pm \sum_{k>0}\frac{a_{j,-k}}{[k]}q^{\mp \frac{1}{2}k}z^k]
        \exp[\mp \sum_{k>0}\frac{a_{j,k}}{[k]}q^{\mp \frac{1}{2}k}z^{-k}]
        e^{\pm \alpha_j}z^{\pm \partial_{\alpha_j}+1}, \\
\circ & \quad \varphi_j(z)\mapsto
        \exp[-(q-q^{-1})\sum_{k>0}a_{j,-k}z^k]q^{-\partial_{\alpha_j}}, \\
\circ & \quad \psi_j(z)\mapsto
        \exp[(q-q^{-1})\sum_{k>0}a_{j,k}z^{-k}]q^{\partial_{\alpha_j}},
\end{align*}
which  gives level 1 highest representations with  the $i$-th  fundamental
weight on $\mbox{${\cal F}$}_{i}$.
\end{lemma}

\begin{defn}
Vertex operators are intertwiners of the following types:
\begin{enumerate}
\renewcommand{\labelenumi}{(\roman{enumi})}
\item (type $I$) \hspace{1 in}
      $\displaystyle{ \Phi^{(i,i+1)}(z):\mbox{${\cal F}$}_{i+1}\longrightarrow
                      \mbox{${\cal F}$}_{i}\otimes V_{z}, }$
\item (type $II$) \hspace{0.95 in}
      $\displaystyle{ \Psi^{(i,i+1)}(z):\mbox{${\cal F}$}_{i+1}\longrightarrow
                      V_{z}\otimes \mbox{${\cal F}$}_{i}. }$
\item (dual of type $I$) \hspace{0.5 in}
      $\displaystyle{ \Phi^{*(i+1,i)}(z):\mbox{${\cal F}$}_{i}\otimes V_{z}
                      \longrightarrow \mbox{${\cal F}$}_{i+1}, }$
\item (dual of type $II$)\hspace{0.45 in}
      $\displaystyle{ \Psi^{*(i+1,i)}(z):V_{z}\otimes \mbox{${\cal F}$}_{i}
                      \longrightarrow \mbox{${\cal F}$}_{i+1}, }$
\end{enumerate}
Here the indices are considered modulo $n$.
\end{defn}
Set
\begin{align*}
&  \Phi^{(i,i+1)}(z)=\sum_{j=0}^{n-1} \Phi^{(i.i+1)}_j(z)\otimes |j\rangle,
\qquad
   \Psi^{(i,i+1)}(z)=\sum_{j=0}^{n-1} |j\rangle\otimes \Psi^{(i.i+1)}_j(z),
\\
&  \Phi^{*(i+1,i)}(z)(u\otimes |j\rangle )=\Phi^{*(i+1,i)}_j(z)u, \quad
   \Psi^{*(i+1,i)}(z)(|j\rangle \otimes u)=\Psi^{*(i+1,i)}_j(z)u, \qquad
   u \in \mbox{${\cal F}$}_{i+1}.
\end{align*}
The normalization of those operators is  given by
\begin{enumerate}
\renewcommand{\labelenumi}{(\roman{enumi})}
\item $\displaystyle{
       \langle \Lambda_{i}|\Phi^{(i,i+1)}_{i}(z)|\Lambda_{i+1}\rangle=1,
\qquad \langle \Lambda_{i}|\Psi^{(i,i+1)}_{i}(z)|\Lambda_{i+1}\rangle=1,
       } $
\item $\displaystyle{
       \langle \Lambda_{i+1}|\Phi^{*(i+1,i)}_{i}(z)|\Lambda_{i}\rangle=1,
\qquad \langle \Lambda_{i+1}|\Psi^{*(i+1,i)}_{i}(z)|\Lambda_{i}\rangle=1.
       } $
\end{enumerate}

We will first give the list of OPEs (operator product expansions), where
we abbreviate the superscript of vertex operators.

\noindent \underline{Type $I,II$}
\begin{align*}
& [\Phi_j(z),x_i^+(w)]=\delta_{i-1,j}\delta(\frac{w}{q^{i-1}z})
                       \varphi_i(wq^{\frac{1}{2}})\Phi_i(z), \\
& \Phi_j(z)x_i^-(w)=\begin{cases}
                    \dfrac{q-q^{i-1}\frac{z}{w}}{1-q^i\frac{z}{w}}
                    x_i^-(w)\Phi_{i-1}(z)
                    & \quad \text{for $j=i-1$} \\
                    \dfrac{q^{-1}-q^{i+1}\frac{z}{w}}{1-q^i\frac{z}{w}}
                    x_i^-(w)\Phi_{i}(z)+\delta(\frac{w}{q^{i}z})
                    \Phi_{i-1}(z)
                    & \quad \text{for $j=i$} \\
                    x_i^-(w)\Phi_j(z)
                    & \quad \text{otherwise}
                    \end{cases}, \\
& \Phi_j(z)\varphi_i(w)=\begin{cases}
                    \dfrac{q^{-1}-q^{-i+\frac{3}{2}}\frac{w}{z}}
                          {1-q^{-i+\frac{1}{2}}\frac{w}{z}}
                    \varphi_i(w)\Phi_{i-1}(z)
                    & \quad \text{for $j=i-1$} \\
                    \dfrac{q-q^{-i-\frac{1}{2}}\frac{w}{z}}
                          {1-q^{-i+\frac{1}{2}}\frac{w}{z}}
                    \varphi_i(w)\Phi_i(z)
                    & \quad \text{for $j=i$} \\
                    \varphi_i(w)\Phi_j(z)
                    & \quad \text{otherwise}
                    \end{cases}, \\
& \Phi_j(z)\psi_i(w)=\begin{cases}
                    \dfrac{q-q^{i-\frac{1}{2}}\frac{z}{w}}
                          {1-q^{i+\frac{1}{2}}\frac{z}{w}}
                    \psi_i(w)\Phi_{i-1}(z)
                    & \quad \text{for $j=i-1$} \\
                    \dfrac{q^{-1}-q^{i+\frac{3}{2}}\frac{z}{w}}
                          {1-q^{i+\frac{1}{2}}\frac{z}{w}}
                    \psi_i(w)\Phi_i(z)
                    & \quad \text{for $j=i$} \\
                    \psi_i(w)\Phi_j(z)
                    & \quad \text{otherwise}
                    \end{cases}, \\
& \Psi_j(z)x_i^+(w)=\begin{cases}
                    \dfrac{q^{-1}-q^{-i+1}\frac{w}{z}}{1-q^{-i}\frac{w}{z}}
                    x_i^+(w)\Psi_{i-1}(z)+\delta(\frac{w}{q^iz})
                    \Psi_i(z)
                    & \quad \text{for $j=i-1$} \\
                    \dfrac{q-q^{-i-1}\frac{w}{z}}{1-q^{-i}\frac{w}{z}}
                    x_i^+(w)\Psi_i(z)
                    & \quad \text{for $j=i$} \\
                    x_i^+(w)\Psi_j(z)
                    & \quad \text{otherwise}
                    \end{cases}, \\
& [\Psi_j(z),x_i^-(w)]=\delta_{i,j}\delta(\frac{w}{q^{i-1}z})
                       \psi_i(wq^{\frac{1}{2}})\Psi_{i-1}(z), \\
& \Psi_j(z)\varphi_i(w)=\begin{cases}
                    \dfrac{q^{-1}-q^{-i+\frac{1}{2}}\frac{w}{z}}
                          {1-q^{-i-\frac{1}{2}}\frac{w}{z}}
                    \varphi_i(w)\Psi_{i-1}(z)
                    & \quad \text{for $j=i-1$} \\
                    \dfrac{q-q^{-i-\frac{3}{2}}\frac{w}{z}}
                          {1-q^{-i-\frac{1}{2}}\frac{w}{z}}
                    \varphi_i(w)\Psi_i(z)
                    & \quad \text{for $j=i$} \\
                    \varphi_i(w)\Psi_j(z)
                    & \quad \text{otherwise}
                    \end{cases}, \\
& \Psi_j(z)\psi_i(w)=\begin{cases}
                    \dfrac{q-q^{i-\frac{3}{2}}\frac{z}{w}}
                          {1-q^{i-\frac{1}{2}}\frac{z}{w}}
                    \psi_i(w)\Psi_{i-1}(z)
                    & \quad \text{for $j=i-1$} \\
                    \dfrac{q^{-1}-q^{i+\frac{1}{2}}\frac{z}{w}}
                          {1-q^{i-\frac{1}{2}}\frac{z}{w}}
                    \psi_i(w)\Psi_i(z)
                    & \quad \text{for $j=i$} \\
                    \psi_i(w)\Psi_j(z)
                    & \quad \text{otherwise}
                    \end{cases},
\end{align*}
\noindent \underline{Dual of type $I,II$}
\begin{align*}
& [x_i^+(w),\Phi^*_j(z)]=\delta_{i,j}\delta(\frac{w}{q^{i-1}z})
                         \Phi^*_{i-1}(z)\varphi_i(wq^{\frac{1}{2}}), \\
& x_i^-(w)\Phi^*_j(z)=\begin{cases}
                     \dfrac{q-q^{i-1}\frac{z}{w}}{1-q^i\frac{z}{w}}
                     \Phi^*_{i-1}(z)x_i^-(w)+\delta(\frac{w}{q^iz})
                     \Phi^*_i(z)
                     & \quad \text{for $j=i-1$} \\
                     \dfrac{q^{-1}-q^{i+1}\frac{z}{w}}{1-q^i\frac{z}{w}}
                     \Phi^*_i(z)x_i^-(w)
                     & \quad \text{for $j=i$} \\
                     \Phi^*_j(z)x_i^-(w)
                     & \quad \text{otherwise}
                     \end{cases}, \\
& \varphi_i(w)\Phi^*_j(z)=\begin{cases}
                     \dfrac{q^{-1}-q^{-i+\frac{3}{2}}\frac{w}{z}}
                           {1-q^{-i+\frac{1}{2}}\frac{w}{z}}
                     \Phi^*_{i-1}(z)\varphi_i(w)
                     & \quad \text{for $j=i-1$} \\
                     \dfrac{q-q^{-i-\frac{1}{2}}\frac{w}{z}}
                           {1-q^{-i+\frac{1}{2}}\frac{w}{z}}
                     \Phi^*_i(z)\varphi_i(w)
                     & \quad \text{for $j=i$} \\
                     \Phi^*_j(z)\varphi_i(w)
                     & \quad \text{otherwise}
                     \end{cases}, \\
& \psi_i(w)\Phi^*_j(z)=\begin{cases}
                     \dfrac{q-q^{i-\frac{1}{2}}\frac{z}{w}}
                           {1-q^{i+\frac{1}{2}}\frac{z}{w}}
                     \Phi^*_{i-1}(z)\psi_i(w)
                     & \quad \text{for $j=i-1$} \\
                     \dfrac{q^{-1}-q^{i+\frac{3}{2}}\frac{z}{w}}
                           {1-q^{i+\frac{1}{2}}\frac{z}{w}}
                     \Phi^*_i(z)\psi_i(w)
                     & \quad \text{for $j=i$} \\
                     \Phi^*_j(z)\psi_i(w)
                     & \quad \text{otherwise}
                     \end{cases}, \\
& x_i^+(w)\Psi^*_j(z)=\begin{cases}
                     \dfrac{q^{-1}-q^{-i+1}\frac{w}{z}}{1-q^{-i}\frac{w}{z}}
                     \Psi^*_{i-1}(z)x_i^+(w)
                     & \quad \text{for $j=i-1$} \\
                     \dfrac{q-q^{-i-1}\frac{w}{z}}{1-q^{-i}\frac{w}{z}}
                     \Psi^*_i(z)x_i^+(w)+\delta(\frac{w}{q^iz})
                     \Psi^*_{i-1}(z)
                     & \quad \text{for $j=i$} \\
                     \Psi^*_j(z)x_i^+(w)
                     & \quad \text{otherwise}
                     \end{cases}, \\
& [x_i^-(w),\Psi^*_j(z)]=\delta_{i-1,j}\delta(\frac{w}{q^{i-1}z})
                        \Psi^*_i(z)\psi_i(wq^{\frac{1}{2}}), \\
& \varphi_i(w)\Psi^*_j(z)=\begin{cases}
                     \dfrac{q^{-1}-q^{-i+\frac{1}{2}}\frac{w}{z}}
                           {1-q^{-i-\frac{1}{2}}\frac{w}{z}}
                     \Psi^*_{i-1}(z)\varphi_i(w)
                     & \quad \text{for $j=i-1$} \\
                     \dfrac{q-q^{-i-\frac{3}{2}}\frac{w}{z}}
                           {1-q^{-i-\frac{1}{2}}\frac{w}{z}}
                     \Psi^*_i(z)\varphi_i(w)
                     & \quad \text{for $j=i$} \\
                     \Psi^*_j(z)\varphi_i(w)
                     & \quad \text{otherwise}
                     \end{cases}, \\
& \psi_i(w)\Psi^*_j(z)=\begin{cases}
                     \dfrac{q-q^{i-\frac{3}{2}}\frac{z}{w}}
                           {1-q^{i-\frac{1}{2}}\frac{z}{w}}
                     \Psi^*_{i-1}(z)\psi_i(w)
                     & \quad \text{for $j=i-1$} \\
                     \dfrac{q^{-1}-q^{i+\frac{1}{2}}\frac{z}{w}}
                           {1-q^{i-\frac{1}{2}}\frac{z}{w}}
                     \Psi^*_i(z)\psi_i(w)
                     & \quad \text{for $j=i$} \\
                     \Psi^*_j(z)\psi_i(w)
                     & \quad \text{otherwise}
                     \end{cases}.
\end{align*}

\begin{rem}We remark that 2 OPE's related to
$\Psi_i(z)x_i^-(w)$ and $x_i^+(w)\Phi^*_i(z)$ are
$$\Psi_i(z)x_i^-(w)=x_i^-(w)\Psi_i(z),$$
$$x_i^+(w)\Phi^*_i(z)=\Phi^*_i(z)x_i^+(w).$$
However the two sides of the equations are in different expansion directions,
which implies that both sides have poles .
These two equations will not degenerate the classical
intertwiner relations when
$q=1$. For this
case, we impose the following locality conditions:
\[ (1-\frac{w}{q^{i+1}z})[\Psi_i(z),x_i^-(w)]=0, \qquad
   (1-\frac{w}{q^{i+1}z})[x_i^+(w),\Phi^*_i(z)]=0,  \]
which ensure that the degeneration of these  formulae is consistent with its
classical degeneration when $q=1$.
\end{rem}

\begin{thm}
The vertex operators are given as:
\begin{align*}
\Phi_j^{(i,i+1)}(z)=
& \exp[-\sum_{k>0}a_{j-k}^{\ast}q^{\frac{3}{2}k}(q^jz)^k
       +\sum_{k>0}a_{j+1-k}^{\ast}q^{\frac{1}{2}k}(q^jz)^k] \\
& \exp[-\sum_{k>0}a_{jk}^{\ast}q^{-\frac{1}{2}k}(q^jz)^{-k}
       +\sum_{k>0}a_{j+1k}^{\ast}q^{\frac{1}{2}k}(q^jz)^{-k}] \\
& e^{\overline{\Lambda}_j-\overline{\Lambda}_{j+1}}
  (q^{j+1}z)^{\partial_{\overline{\Lambda}_j}}
  (q^jz)^{-\partial_{\overline{\Lambda}_{j+1}}}
  (-1)^{(n-1)\partial_{\overline{\Lambda}_1}}(c)_j^i, \\
\Psi_j^{(i,i+1)}(z)=
& \exp[-\sum_{k>0}a_{j-k}^{\ast}q^{\frac{1}{2}k}(q^jz)^k
       +\sum_{k>0}a_{j+1-k}^{\ast}q^{-\frac{1}{2}k}(q^jz)^k] \\
& \exp[-\sum_{k>0}a_{jk}^{\ast}q^{-\frac{3}{2}k}(q^jz)^{-k}
       +\sum_{k>0}a_{j+1k}^{\ast}q^{-\frac{1}{2}k}(q^jz)^{-k}] \\
& e^{\overline{\Lambda}_j-\overline{\Lambda}_{j+1}}
  (q^{j+1}z)^{\partial_{\overline{\Lambda}_j}}
  (q^jz)^{-\partial_{\overline{\Lambda}_{j+1}}}
  (-1)^{(n-1)\partial_{\overline{\Lambda}_1}}(c)_j^i, \\
\Phi_j^{*(i+1,i)}(z)=
& \exp[\sum_{k>0}a_{j-k}^{\ast}q^{\frac{3}{2}k}(q^jz)^k
       -\sum_{k>0}a_{j+1-k}^{\ast}q^{\frac{1}{2}k}(q^jz)^k] \\
& \exp[\sum_{k>0}a_{jk}^{\ast}q^{-\frac{1}{2}k}(q^jz)^{-k}
       -\sum_{k>0}a_{j+1k}^{\ast}q^{\frac{1}{2}k}(q^jz)^{-k}] \\
& e^{-\overline{\Lambda}_j+\overline{\Lambda}_{j+1}}
  (q^{j+1}z)^{-\partial_{\overline{\Lambda}_j}}
  (q^jz)^{\partial_{\overline{\Lambda}_{j+1}}}
  (-1)^{-(n-1)\partial_{\overline{\Lambda}_1}}(c^{\ast})_j^i, \\
\Psi_j^{*(i+1,i)}(z)=
& \exp[\sum_{k>0}a_{j-k}^{\ast}q^{\frac{1}{2}k}(q^jz)^k
       -\sum_{k>0}a_{j+1-k}^{\ast}q^{-\frac{1}{2}k}(q^jz)^k] \\
& \exp[\sum_{k>0}a_{jk}^{\ast}q^{-\frac{3}{2}k}(q^jz)^{-k}
       -\sum_{k>0}a_{j+1k}^{\ast}q^{-\frac{1}{2}k}(q^jz)^{-k}] \\
& e^{-\overline{\Lambda}_j+\overline{\Lambda}_{j+1}}
  (q^{j+1}z)^{-\partial_{\overline{\Lambda}_j}}
  (q^jz)^{\partial_{\overline{\Lambda}_{j+1}}}
  (-1)^{-(n-1)\partial_{\overline{\Lambda}_1}}(c^{\ast})_j^i,
\end{align*}
where $(c)_j^i=(-q)^{j-i}(c)_i^i,(c^{\ast})_j^i=(c^{\ast})_i^i$ and
\begin{align*}
(c)_i^i=&
[(-1)^{-(n-1)}z]^{\frac{n-i-1}{n}}(-1)^{\frac{1}{2}(n-i-1)(n-i-2)}, \\
(c^{\ast})_i^i=&
[(-1)^{n-1}]^{\frac{n-i}{n}}[q^nz]^{\frac{i}{n}}(-1)^{\frac{1}{2}(n-i)(n-i-1)}.
\end{align*}
Here $\ast$ means dual.
\end{thm}

From this theorem, we can derive all the correlation functions of
vertex operators. We will give a simple example of the case of
$U_q(\mbox{$\hat{\gtsl}$}_2)$ to show what they are like.

Let $v$ be the highest weigh vector in $\mbox{${\cal F}$}_{0}$
$$<v, \Phi_0^{(0,1)}(z_1) \Phi_0^{(1,0)}(z_2), v>=
  <v, \Phi_1^{(0,1)}(z_1) \Phi_1^{(1,0)}(z_2), v>= 0,$$
$$<v, \Phi_1^{(0,1)}(z_2) \Phi_0^{(1,0)}(z_1), v>=-q^{-1}(z_1/z_2)^{1/2}
\frac {(qz_1/z_2;q^4)_\infty}{(q^3z_1/z_2,q^4)_\infty},$$
$$<v, \Phi_0^{(0,1)}(z_2) \Phi_1^{(1,0)}(z_1), v>=
z_1^{1/2}z_2^{3/2}\frac {(q^4z_1/z_2;q^4)_\infty}{(q^6z_1/z_2,q^4)_\infty},$$
where  $(z,p)_\infty=\prod^\infty_0(1-zp^m)$.

With those vertex operators, we can derive the following
formulae.
\begin{thm}
\begin{align*}
\text{$(1)$}& \quad  :\Phi_{i-1}^{(i-1,i)}(z)\Phi_i^{\ast(i+1,i)}(z):
               =x_i^-(q^iz), \\
\text{$(2)$}& \quad  :\Psi_i^{(i-1,i)}(z)\Psi_{i-1}^{\ast(i+1,i)}(z):
               =-qx_i^+(q^iz), \\
\text{$(3)$}& \quad  :x_i^+(q^{\frac{1}{2}}z)x_i^-(q^{-\frac{1}{2}}z):
               =z^2 \psi_i(z), \\
\text{$(4)$}& \quad  :x_i^+(q^{-\frac{1}{2}}z)x_i^-(q^{\frac{1}{2}}z):
               =z^2 \varphi_i(z),
\end{align*}
where $: \cdot :$ is the normal ordering.
\end{thm}

In \cite{Di1}\cite{Di2}, we showed  that the vertex operators in the classical
case have the structure of Clifford algebras, which is used to
construct representations of $\mbox{$\hat{\gtsl}$}_n$. This is the
boson-fermion correspondence. We also established
a quantum version of boson-fermion correspondence, where the quantum
fermions are identified as vertex operators with the conventional
comultiplication. However the quantum boson-fermion correspondence is very
implicit due to the incomplete formulae for intertwiners. With Theorem
3.4 and Theorem 3.5, the correlation functions of all the
vertex operators are clear. Utilizing
 all these results,  we hope that we can
present a different definition of quantum Clifford algebras and derive a
more explicit boson-fermion correspondence. Furthermore
 we recognize that
our formulae may be related to the quantum ${\cal W}$-algebras \cite{AKOS}
\cite{FF} especially the bosonization of those algebras.

\begin{ack}
J.D. is supported by the grant Reward research (A) 08740020 from the
Ministry of Education of Japan. K.I. is partly supported by the Japan Society
for the Promotion of Science.
\end{ack}

redpajama_set_name: RedPajamaArXiv


text:
I want you to hit me as hard as you can
Bradford City think that Kyle Bennett's should not be banned for three games for hitting another footballer in the neck in Tuesday night's game with Preston North End and the crazy thing is that the Football Association agree.
In the video of Bennett's clash with Neil Kilkenny – the less said about his actions the better but nothing he doe impacts that Bennett has done – the Bradford City player very clearly strikes Kilkenny. If you can't see it watch it again until you do and you will.
He does not strike him hard, he does not wound or injury him but he does strike him and that is the violent conduct that the player was dismissed for. This is as open and shut a case as you could expect to see in football and referee Stuart Attwell has rightly sent him off.
But the FA have decided that Bennett should serve only a one match and not a three match ban and the indication from the Bradford City website is that that is because he made "limited" contact or – if you will – he hit him that hard.
Consider that again for a moment.
Bennett hit Kilkenny (again, I'm not talking about Kilkenny's antics) which was judged and rejudged as violent conduct and no one contests that yet the FA have decided that it is not the absolute of violent conduct that he is punished for but rather the effectiveness of it.
In April this year the same FA banned Liverpool striker Luis Suarez for 10 games for biting Chelsea defender Branislav Ivanovic. Ivanovic suffered no lasting effects from the nibble and I have deeper cuts on my arm from my kitten Leo but nevertheless that was judged on the violence of the action not the result.
Which is not to say I'm not glad that Bennett has only got a one game and not a three game ban but I would be incensed if this ruling went the other way and someone were allowed to get a lesser ban for hitting a City player softly.
In fact I recall Etienne Verveer playing for City at Huddersfield Town and taking a dive after Tom Cowan swung a fist at at him. The referee saw the dive but sent Cowan off because you are not allowed to throw punches even if they miss.
Both John Finnigan of Cheltenham and Ívar Ingimarsson of Reading were left complaining that Dean Windass had done something unspeakable to them that provoked red cards they got for hitting the City player but provocation is not a defence against a charge of violent conduct either.
Those were good decisions based on the clear statement in football that for all the wrongs you may perceive the game is a game and it is not for players to hand out justice with violence. We are not talking about questionable elbows or hard tackles. We are talking arms and hands striking above the shoulder. We are talking hitting someone else.
If – in football – you have to resort to throwing fists during a game then you get sent off and you get punished with severity. The action is punitive – not something I always like – and is their to tell the player not to start fighting while playing a game.
The FA have undermined what should be a clear statement but the FA's approach to discipline is to underline strange and unusual punishments.
I'm glad Bennett will be back sooner but I cannot agree with the idea that obvious violent conduct can be downgraded for how poor it was carried out or how little damage was done.
More about Branislav Ivanovic, Dean Windass, Etienne Verveer, Ívar Ingimarsson, John Finnigan, Kyle Bennett, Luis Suarez, Neil Kilkenny, Preston North End, Stuart Atwell, The FA, Tom Cowan.


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While at Georgetown University, Charles wrote his thesis on retirement communities: The nursing home institution, a Foucauldian paradigm (2006). Around the same time, his grandmother was diagnosed with Alzheimer 's disease and moved to a nursing home. These two experiences helped Charles realize how lonely, bored and secluded many residents of nursing homes and retirement communities were. Linked Senior was created to enhance the quality of the lives of these seniors.
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