Telecom reseller Primus Telecommunications Inc. has extended its contract with MTS Allstream Inc., which provides wholesale local, long-distance and data services to Primus.
The contract will be extended by three year. Primus Canada, which offers voice, data, e-commerce, Web hosting and VoIP service, is owned by McLean, Va.-based Primus Telecommunications Group Inc.
MTS Allstream's enterprise solutions division, based in Toronto, provides voice and data services. It operated as AT&T Canada until 2003, and was purchased the following year by MTS.AT&T Canada was formed nearly a decade ago when AT&T Long Distance merged with MetroNet, an early competitive local exchange carrier and ISP Netcom Canada.


text:
Coffs Harbour Marina Reopens After Storm Leaves Marina in Tatters
Thanks to an amazing team effort, Coffs Harbour International Marina expects to be back to full operating capacity this month. The marina suffered substantial damage when an east coast low passed over the region in June. Wild surf conditions caused waves to crash over the marina's northern breakwall. The force of the waves broke apart many of the marina's docks.
During an east coast low, huge waves crash over Coffs Harbour's northern breakwall causing substantial damage to the marina.
If you have ever had the pleasure of working on a 100-year old house that has been through multiple renovations, you know the many challenges this type of work can bring. Uniformity is lacking and daily surprises are the norm.
It takes a special contractor to tackle these jobs with the skill, finesse and creativity required to execute them successfully.
Performing repair work on a large, older marina is not much different than doing repair work on a 100-year old house, especially if the marina has been built or repaired in a piece-meal fashion over time.
If you spend time walking the docks of marinas worldwide, you are bound to see those with a hodgepodge of docks – it is a reality of the industry. Many of the large, older marinas have been added to and renovated over time. As a result, it is common for these marinas to have a variety of dock types. You may see a mix of fixed and floating or of concrete and aluminum. The marina may have a single type of dock but because it was erected over an extended period, the design and construction of the marina's docks varies from tree to tree.
One of the major challenges for marinas like these is repair work. Because their docks are a mishmash of systems, repair work is often complicated and requires a different solution for each type/generation of dock.
In June 2016, a strong storm system swept through Australia's New South Wales territory. The storm caused considerable damage to infrastructure along the coastline. Coffs Harbour was particularly hard hit. The local marina, Coffs Harbour International Marina sustained significant damage and was forced to close until repair work could be completed.
In an effort to reopen the marina's berths as quickly as possible, the marina limited repair work to storm damaged items only. The aim was to address and repair or replace the damaged dock sections.
Coffs Harbour is a 150-berth marina built over 10 years with parts of the marina 25 years old. The marina has four different dock types including two types built to metric measurements and two built with imperial dimensions. This made repair work particularly challenging. All four types were timber waler thru-rod construction, so there was some consistency. However, the docks were from multiple manufacturers and were built over an extended period, so there were a number of inconsistencies between them.
When Bellingham Marine's crew surveyed the damaged docks to prepare a quote for repair work, they noted differences in the following:
Module lengths
Module widths
Thru-rod diameters – some were 16mm and others were 20 ¾mm
Thru-rod spacing (a mix of metric and imperial)
Thru-rod placement from top of deck to rod hole
Mixed-use of plastic inserts and full thru-rods
Variations in knee-bracket and pile guide design
These differences significantly complicated repair work.
Each section marked for repair or replacement had a unique set of conditions and required custom tooling.
The fabrication process for walers and brackets was complex and time consuming. Unique hole patterns were required where one type of dock joined another. Differing walkway modules coupled with differing types of fingers required knee-brackets to have up three different drill patterns.
Bellingham Marine's team attacked the work with skilled execution and an appreciation for the owner's urgency to get the marina's docks reopened as quickly as possible. "It was about getting the boaters back in their berths," remarked Bellingham Marine Manager of Project Development Gary Charlwood.
"Our crews commenced on site early November 2016 and had completed all contracted work by February 2017," said Charlwood. "We replaced 390 square meters of pontoons, 3 km of timber walers and 5 km of thru-rods."
Bellingham's scope of work also included replacement of service units, plumbing and electrical services, knee-brackets, pile guides and fendering.
Bellingham Marine was hired to carry out repair work. In total, 390 m2 of pontoons were replaced.
"Communication, early involvement from key team members and an attitude of flexibility were some of the attributes that led to the success of the Coffs Harbour repair project," shared Charlwood.
"We pulled staff from metal fabrication, float fabrication and our sub-contractors together early in the planning phase. We asked them to tell us how quickly they could help us. We worked the program around what they could deliver and when. This allowed us to identify fabrication and casting challenges early and identify timing solutions more readily."
"We also utilized a local crane operator, plumber and electrician who were all familiar with the marina, its staff and the site. Their knowledge and experience was instrumental. They knew exactly what was there before the storm; they knew about any skeletons in the closet, and they knew how to 'open doors.'"
"Throughout the entire process we were upfront, honest and realistic about how soon works could be carried out. Although there was pressure on all parties to get the repair work completed quickly, it was critical that expectations remained realistic and that allowances in material and time were built into the program."
Sections of the marina that could not be repaired were replaced with new concrete pontoon modules.
"This was a challenging but extremely rewarding project. We had a great team; those relationships are even stronger now. Everyone put forth a tremendous effort that was appreciated by all."
Posted in: Construction, Storm Repair Tagged: repair Author: NICOLE CAPLAN

redpajama_set_name: RedPajamaCommonCrawl


text:
LA Clippers Game Recaps
Los Angeles Clippers 112 Oklahoma City 100. A Signature Win For The Clippers
By John O'Connor Jan 30, 2012, 11:43pm PST
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When you you recap a blowout loss your first time out of the gate, you brush it off as unfortunate. When it happens again the second time around, you start to get nervous. The masses will begin to turn on you at 3 recaps and three losses (Clipper fans are prone to believing in curses and jinxes). So naturally, I figured I would write recap number 3 of the year for a game on the second night of back to backs against scoring champion Kevin Durant and the league leading Oklahoma City Thunder. Luckily for me, things worked out this time, with the Clippers pulling out a fantastic win in front of their home crowd, defeating the thunder 112-100. Check out the box score here.
I did quite a bit of research before this one, trying to find the teams tendencies, and determine where either team may have an advantage against the other. The Thunder have a tendency to turn the ball over (worst in the league heading into this game at 16.5/per), advantage Clippers. The Thunder on the other hand are the best free throw shooting team in the league at 80.9%, while the clips have been dreadful in that department,at 66.2% to date (only Orlando has been worse). The difference in three point shooting is marginal, with the Clippers just narrowly edging out the thunder 36% to 35.3% (The Clippers shoot about 3 more per game). Perhaps the more significant stat in this game (and a big part of Oklahoma City's success) should have been the defense of the Thunder. Heading into this matchup, the thunder have held opposing teams to 29.5% from beyond the arc,and at 6.8 blocks a game. On top of that their bigs they do a pretty nice job of defending the rim as well, 2nd in the league in blocked shots per game at 6.8. As it would turn out, the statistics heading into the game would not be indicative of the end result.
The Clippers came out of the gate red hot from downtown in this game, picking up right where they left off in Denver. They built a comfortable lead early in the first quarter, andwere in control for much of the first half. Oklahoma City looked as though their game plan on defense was to throw defenders at Blake Griffin, and they did a pretty effective job, with Griffin looking out of sync in the first half, winding up with only 7 points heading into the break. Unfortunately for OKC, the rest of the Clipper starting lineup picked up the slack. Caron Butler continued his trend of hot starts,racking up 16 points in the first half. The Clippers were on pace to put this game out of reach early, but Russell Westbrook and Kevin Durant would not go down without a fight. The freakishly gifted duo scored 37 of the Thunder's 46 first half points, and had a run where they looked unstoppable, getting to the rim with ease hitting some big threes. WIth less than 2 minutes to go in the half, the Clippers hot start was erased, and the lead was cut to 6. And then, the most fun minute and a half in the history of clippers regular season basketball happened.
The Clippers went to an interesting lineup of Deandre Jordan, Caron Butler, Mo Williams, Chauncey Billups, and Chris Paul. 1:21, left in the half, Mo Williams hits a big three. After a Clippers stop, Caron Butler responds with a three of his own at the 0:56 second mark. Another Clippers stop leads to a break for the Clippers, with Mo Williams pulling up for another 3. Heat check: all systems go. 9-0 run by the Clippers. Caron Butler then managed to get a steal so quickly the camera man didn't even catch it. at the 0:33 second mark, Chauncey Billups got in on the fun, knocking down a 4th three point basket, and capping off a 12-0 run to end the quarter. This truly was a dagger, as the Thunder never truly got back into the game.
A lot of credit has to be given to the Clippers. After a remarkable display of shooting (10/14 from deep in the first half), they came out in the third quarter and did not rely on the hot shooting to continue. They kept playing defense, and found ways to get to the rim at the end of the shot clock. In the past (even this season), with about 7 seconds left in the shot clock, the Clippers often settle for a long three or a 19 footer from the top of the key by Griffin. Not the case tonight. The Clips played patient basketball and found a way to execute, essentially putting their foot on the throat of the thunder in the third quarter.
The hot shooting was fun. So were the high flying plays of of Westbrook, Durant, and DJ, all of whom attacked the rim ferociously. But everything else that took place in this game would take a back seat the Dunk Blake Griffin threw down in the third quarter. Following a pick and roll, Chris Paul found Blake Griffin several feet away from the basket. Blake Griffin grabbed the ball, and immortalized Kendrick Perkins in a way that Perk could never do himself. Timofey Mozgov, Frederic Weiss, there is a new member in your club (if the club has meetings, I hope they serve alcohol). If somehow you missed the game, do yourself a favor and go find that play. You will not be sorry.
The Thunder would make a run in the fourth quarter, cutting the lead down to 11. In the past, it would be nervous time for the Clippers, with many of us even doubting Lawler's law. But that's why this season is unlike any other we as Clipper fans have ever had. We have a superstar. A superstar who is every bit as amazing as Kevin Durant. A superstar with ability and will to win a game. When the Clippers needed a hoop and it seemed like they couldn't buy one, Chris Paul came up big, braking down defenders, Scoring 6 big points on a brilliant drive to the hoop, a deep two towards the end of the shot clock with a hand in his face, and step back jumper from about 17 feet that I am convinced is the best in the league. I don't know how long Chris Paul will be a Clipper, but I sure hope its for a long time. What I do know is that I have enjoyed every second of Clippers basketball this season, and Clips nation needs to appreciate this brilliant basketball player and everything that he brings to the game for as long as he's here,because kind of talent does not come along very often.
I'm running behind on time, so just a few quick notes:
NO Ryan Gomes tonight, and it didn't seem like the Clippers missed him very much. More than any other position, the Clippers in my opinion need a backup swing man who can score and play a little D.
Deandre Jordan: DJ played an excellent game. He is really progressing as a basketball player. The offensive repertoire still has room for improvement, but he is clearly a much more confident player this year. He might just earn that contract he signed.
Mo WIlliams: 4-11 tonight, but all four were threes and all 4 felt big. Love having this guy off the bench.
28 assists tonight. Clippers were moving the ball and got a terrific balances scoring attack. They will be a tough team to beat when they play like that. Sharing the ball and executing down the stretch (only 3 threes in the second half and still manged to win by a wide margin). Impressive
Free Throw Shooting: 9 of 15 tonight is right around that season average. Still not good. Thankfully Oklahoma City was only 15-23. I really believe that Griffin can improve his free throw shooting, and doing so will really give the Clippers a boost. It was relatively inconsequential tonight, but in close games those free throws go a long way.
Tweet of the night: "Triple Town, Lob City, 90210ooooooooooh"- @HP basketball


text:
\section{Introduction}

Let $\mathbb{D}$ be the unit disk equipped with the hyperbolic metric and $f:\mathbb{D}\to\mathbb{D}$ a quasiconformal map. Then $f$ extends by continuity to a
quasisymmetric map $h:S^1\to S^1$ of the unit circle $S^1$. Conversely, a quasisymmetric map $h:S^1\to S^1$ extends to a quasiconformal map of $\mathbb{D}$ and there are
infinitely many such extensions (See \cite{GL}, \cite{LV}).

The {\it universal Teichm\"uller space} $T(\mathbb{D})$ consists of all quasiconformal maps $f:\mathbb{D}\to\mathbb{D}$ up to an equivalence relation (See \cite{L}, \cite{GL}).
Namely, two quasiconformal maps $f_1,f_2:\mathbb{D}\to\mathbb{D}$ are equivalent if there exists a conformal map $c:\mathbb{D}\to\mathbb{D}$ such that $f_2^{-1}\circ c\circ
f_1$ extends by continuity to the identity on $S^1$. We will use an equivalent definition (See \cite{L}, \cite{GL}):
$$
T(\mathbb{D})=\{ h:S^1\to S^1:\ h\ \mathrm{ is\ quasisymmetric\ and\ fixes }\ 1,\ i,\ -1\}.
$$
The Thurston boundary of the universal Teichm\"uller space $T(\mathbb{D})$ is identified with the space $PML_b(\mathbb{D})$ of projective bounded measured laminations on
$\mathbb{D}$
(See \S\ref{sec:Thurston-bordification}. See also \cite{BonSar},  \cite{Sar1}).
In this paper, we describe the closure of Teichm\"uller disks in the Thurston bordification $T(\mathbb{D})\cup PML_b(\mathbb{D})$ of the universal Teichm\"uller space $T(\mathbb{D})$. In particular, if a sequence in the parameter of the Teichm\"uller disk converges to a point on the unit circle the corresponding sequence in $T(\mathbb{D})$ converges to a unique point in $PML_b(\mathbb{D})$ independently of the type of approach (e.g. along a geodesic, along a horocycle or even outside any horoball).

In previous works \cite{HaSar1}, \cite{HaSar2}, \cite{HaSar3}, Hakobyan and the second author of this paper showed that for an integrable holomorphic quadratic differential $\varphi$ on $\mathbb{D}$, the corresponding Teichm\"uller geodesic of $T(\mathbb{D})$ has a unique limit point on Thurston boundary of $T(\mathbb{D})$. The limit point $[\mu_{\varphi}]\in PML_b(\mathbb{D})$ is the projective class of the transverse measure to the geodesic straightening  of the vertical foliation of $\varphi$
multiplied by the reciprocal of the length of the vertical leaves (See Remark \ref{remark:1}).
For an integrable holomorphic quadratic differential $\varphi$ on $\mathbb{D}$,
the {\it Teichm\"uller disk} is a holomorphic disk in $T(\mathbb{D})$
given by the family of Beltrami differentials
$\{\lambda \overline{\varphi}/|\varphi|\}_{\lambda\in \mathbb{D}}$.
Let $D_\varphi(\lambda)$ be the Teichm\"uller  equivalence class
associated to the Beltrami differential $\lambda \overline{\varphi}/|\varphi|$.
 We will prove the following,
 which is a generalization of a result in \cite{HaSar1}.

\begin{theorem}[Teichm\"uller deformation has the limit]
\label{thm:Teich-has-limit}
As $\lambda\to e^{i\theta}\in \partial \mathbb{D}=S^1$, $D_\varphi(\lambda)$ converges to the projective class of $\mu_{e^{-i\theta}\varphi}$ in the Thurston boundary $PML_b(\mathbb{D})$ of $T(\mathbb{D})$. Furthermore, the Teichm\"uller disk $D_\varphi\colon \mathbb{D}\to T(\mathbb{D})$ is extended as a homeomorphism from the closed unit disk $\overline{\mathbb{D}}$ onto the image in the Thurston bordification $T(\mathbb{D})\cup PML_b(\mathbb{D})$.
\end{theorem}

\begin{remark}[Limiting measured laminations] \label{remark:1}
Almost all vertical leaves of $e^{-i\theta}\varphi$ have exactly two limit points on $S^1$ (See \cite{Strebel}). The measured lamination $\mu_{e^{-i\theta}\varphi}$ has support on the geodesic lamination of $\mathbb{D}$ obtained by replacing the (vertical) leaves of $e^{-i\theta}\varphi$ with geodesics (for the hyperbolic metric) of $\mathbb{D}$ that have the same endpoints as vertical leaves. The transverse measure of $\mu_{e^{-i\theta}\varphi}$ is given by the integral
$$
\int_I \frac{1}{l(z)}dx
$$
where $l(z)$ is the length of the vertical trajectory through $z=x+yi\in I$ and $dx$ is the differential of the horizontal displacement  in the natural parameter $z=x+yi$ of $e^{-i\theta}\varphi$.
Notice that (unlike in the case of closed surfaces) it is not simply the horizontal transverse measure induced by $\varphi$. In fact, almost all vertical leaves of $e^{-i\theta}\varphi$ have finite length (in the metric $|\sqrt{e^{-i\theta}\varphi (\zeta )}d\zeta|$)
and the transverse measure is scaled by the reciprocal of the length of the vertical leaves thus giving us a new type of limit when compared to closed surfaces (See \cite{HaSar1}).
\end{remark}

Theorem \ref{thm:Teich-has-limit} suggests that the behavior of the Teichm\"uller disks
in $T(\mathbb{D})$ is ``tame'' when compared to  the behavior of those in the finite dimensional Teichm\"uller space.
Namely,
when $S$ is a closed Riemann surface of genus at least two, Masur \cite{Mas} proved that the Teichm\"uller geodesics in $T(S)$ corresponding to holomorphic quadratic differentials with uniquely ergodic vertical foliations have a unique limit point on the Thurston boundary of $T(S)$. However, when the vertical foliation of a holomorphic quadratic differential on $S$ is not  uniquely ergodic the corresponding Teichm\"uller geodesic can have more than one limit point on the Thurston boundary of $T(S)$ (See \cite{CMW}, \cite{LLR}, \cite{Len}).
As related topic,
for a closed Riemann surface $S$ of genus at least two and a holomorphic quadratic differential on $S$ whose vertical foliation is uniquely ergodic,
Jiang-Su \cite{JiangSu} and Alberge \cite{Alberge} proved that the corresponding horocyclic path has a unique limit point on the the Thurston boundary of $T(S)$ which is the projective class of the vertical foliation.
However,
to the authors knowledge,
the other cases (e.g. the convergence to $S^1$ outside any horoball based at $S^1$)
are still not understood for compact surfaces.

A geodesic current on $\mathbb{D}$ is a positive Radon measure on the space of geodesics of $\mathbb{D}$ (See \cite{Bon}, \cite{BonSar}, \cite{Sar1}. See also $\S$ 2).
The Liouville map $\mathcal{L}$ maps the universal Teichm\"uller space $T(\mathbb{D})$ into the space of geodesic currents by taking the pull-back of the Liouville measure $L$ on the space of geodesics of $\mathbb{D}$ (See \cite{Bon}, \cite{BonSar}, \cite{Sar1}. See \S 2). The universal Teichm\"uller space $T(\mathbb{D})$ is homeomorphic to its image $\mathcal{L}(T(\mathbb{D}))$ inside the space of geodesic currents (See \cite{Bon} and \cite{BonSar}).

By definition, the Thurston boundary of the universal Teichm\"uller space $T(\mathbb{D})$  consists of  limit points in the space of projective geodesic currents of the projectivization of $\mathcal{L}(T(\mathbb{D}))$. Let $h_{\lambda}:S^1\to S^1$ be the quasisymmetric map fixing $1$, $i$ and $-1$ that represents the Teichm\"uller deformation $D_{\varphi}(\lambda )$. Since $\mathcal{L}(h_{\lambda})\to\infty$ in the space of geodesic currents as $\lambda\to e^{i\theta}$, it is natural to consider the rate of convergence to the infinity.

\begin{theorem}[Asymptotics of Teichm\"uller deformation]
\label{thm:Teich-asymptotics}
Let $h_{\lambda}:S^1\to S^1$ be the quasisymmetric map that represents
$D_\varphi(\lambda)$ in $T(\mathbb{D})$. Then, as $\lambda\to e^{i\theta}$,
$$
\frac{1-|\lambda |}{2\pi}\mathcal{L}(h_{\lambda})\to\mu_{e^{-i\theta}\varphi}.
$$
\end{theorem}

\subsection*{Acknowledgement}
The authors thank the referee for his/her fruitful comments and careful reading.

\section{Thurston boundary of the universal Teichm\"uller space}
\label{sec:Thurston-bordification}
Denote by $\mathbb{D}=\{ z:|z|<1\}$ the unit disk equipped with the hyperbolic metric $\frac{2|dz|}{1-|z|^2}$. Each oriented hyperbolic geodesic is uniquely determined by an ordered pair of distinct endpoints, the initial point and  end point of the geodesic.
Therefore, the space of all oriented (hyperbolic) geodesics of $\mathbb{D}$ is identified with $(S^1\times S^1)\setminus diag$, where $diag$ is the diagonal of $S^1\times S^1$
and $S^1=\partial \mathbb{D}$.
The space of geodesics contains a unique (up to a positive multiple) positive Borel measure of full support which is invariant under the isometries of $\mathbb{D}$, called the {\it Liouville measure}. It is defined by
$$
L(A)=\int_A\frac{d\alpha d\beta}{|e^{i\alpha}-e^{i\beta}|^2}
$$
for any Borel set $A\subset (S^1\times S^1)-diag$.  For a {\it box of geodesics} $[a,b]\times [c,d]$, with $a,b,c,d\in S^1$ given in the counterclockwise order, the Liouville measure is given by (See Bonahon \cite{Bon})
$$
L([a,b]\times [c,d])=\log\frac{(c-a)(d-b)}{(d-a)(c-b)}.
$$

The universal Teichm\"uller space $T(\mathbb{D})$ consists of all quasisymmetric maps $h:S^1\to S^1$ that fix $1$, $i$ and $-1$.
A {\it geodesic current} on $\mathbb{D}$ is a positive Radon measure on the space of geodesics $(S^1\times S^1)-diag$.  Let $\mathcal{G}(\mathbb{D})$ be the space of geodesic currents on $\mathbb{D}$.
Bonahon \cite{Bon} introduced an embedding of the Teichm\"uller space $T(S)$ into the space of geodesic currents equipped with the weak* topology via the Liouville map, where $S$ is a closed surface of genus at least two. Moreover, $T(\mathbb{D})$ and $T(X)$, for $X$ any Riemann surface, embeds into the space of geodesic currents when equipped with the uniform weak* topology (See \cite{BonSar}, \cite{Sar1}). The {\it Liouville map}
$$
\mathcal{L}:T(\mathbb{D})\to \mathcal{G}(\mathbb{D})
$$
is defined by
$$
\mathcal{L}(h)=(h^{-1})_{*}(L)
$$
where $h:S^1\to S^1$ is quasisymmetric and $(h^{-1})_{*}(L)$ is the push-forward of the Liouville measure $L$ by $h^{-1}$ (i.e. the pull-back of $L$ by $h$).

By definition, the Thurston boundary of $T(\mathbb{D})$ is the set of all boundary points of the image of $\mathcal{L}(T(\mathbb{D}))$ in the projective geodesic currents $P\mathcal{G}(\mathbb{D})$ equipped with the quotient of the uniform weak* topology. It turns out that the Thurston boundary consists of all projective bounded measured laminations $PML_b(\mathbb{D})$, where the projective class of a geodesic current $[\beta]\in P\mathcal{G}(\mathbb{D})$ is said to be a \emph{projective measured lamination} if the support of $\beta$ consists of non-intersecting geodesics. A projective measured lamination $[\beta]$ is said to be \emph{bounded} if $\sup_I \beta(I)$ is bounded where $I$ runs all transverse geodesic arc of unit length (See \cite{BonSar}, \cite{Sar1}).

Given an integrable holomorphic function $\varphi :\mathbb{D}\to \mathbb{C}$, the corresponding Teichm\"uller geodesic is given by the equivalence class of quasiconformal maps
$$
g_t(z)=x+\frac{1-t}{1+t}yi
$$
where $0\leq t< 1$ and $z=\int_{*}\sqrt{\varphi (\zeta )}d\zeta $ is the natural parameter for $\mathbb{D}$ defined by $\varphi$.
Let $k_t:S^1\to S^1$ be a quasisymmetric map representing the equivalence class of $g_t$.
Notice that the maximal dilatation $K(g_t)$ of $g_t$ is equal to $\frac{1+t}{1-t}$
when $0\leq t< 1$.

Let $\mu_{\varphi}$ be measured lamination on $\mathbb{D}$ whose support is the closure of the set of (hyperbolic) geodesics which have the same endpoints on $S^1$ as vertical trajectories of $\varphi$, i.e the leaves of $\mu_{\varphi}$ are obtained by straightening the vertical trajectories of $\varphi$. Since almost all vertical trajectories have two distinct limit points on $S^1$ (See \cite{Strebel}), it follows that to almost every vertical trajectory there corresponds a unique hyperbolic geodesic in the support of  $\mu_{\varphi}$.

We define the $\mu_{\varphi}$-measure of a box of geodesics $[a,b]\times [c,d]$ as follows. If no vertical  trajectories have one endpoint in $[a,b]$ and another endpoint in $[c,d]$ then $\mu_{\varphi}([a,b]\times [c,d])=0$. In general, consider the set of all vertical trajectories that have one endpoint in $[a,b]$ and another endpoint in $[c,d]$. Let $\{ J_k\}_k$ be at most countable collection of compact subarcs of the  horizontal arcs of $\varphi$ such that every vertical trajectory with one endpoint in $[a,b]$ and another endpoint in $[c,d]$ intersects exactly one $J_k$, and no other vertical trajectory of $\varphi$ intersects any $J_k$. We define
$$
\mu_{\varphi}([a,b]\times [c,d]):=\sum_{k=1}^{\infty}\int_{J_k}\frac{\left|{\rm Re}(\sqrt{\varphi (\zeta )}d\zeta )\right|}{l(\zeta)}=\sum_k\int_{J_k'}\frac{|dx|}{l(z)}
 $$
 where $J_k'$ is the image of $J_k$ under the canonical coordinates $z=x+ti$ corresponding to $\varphi$ and $l(\zeta )$ is the $\varphi$-length of the vertical trajectory through $\zeta$, and similar for $l(z)$.

Then (See \cite{HaSar1})
$$
\lim_{t\to 1} K(g_t)^{-1}\mathcal{L}(k_t)= \mu_{\varphi}
$$
in the weak* topology on the geodesic currents $\mathcal{G}$, where $\mu_{\varphi}$ is the above measured lamination of $\mathbb{D}$. This implies that $\mu_\varphi$ is bounded. In general, an example showed that the above convergence does not hold for the uniform weak* topology (See \cite{HaSar1}).

\section{Modulus of a curve family}

Let $\Gamma$ be a family of curves in $\mathbb{C}$. A metric $\rho (z)|dz|$, where $\rho (z)\geq 0$ and measurable, is said to be {\it allowable for} $\Gamma$ if for every $\gamma\in\Gamma$ we have
$$
\int_{\gamma}\rho (z)|dz|\geq 1.
$$

The {\it modulus} of a curve family $\Gamma$ is given by
$$
\mathrm{mod}(\Gamma )=\inf_{\rho }\iint_{\mathbb{C}}\rho^2(z)dxdy
$$
where the infimum is over all allowable metrics $\rho (z)|dz|$ for the curve family $\Gamma$.

The following properties of the modulus of families of curves are standard:
\begin{itemize}
  \item[1.] If $\Gamma_1\subset\Gamma_2$ then $\mathrm{mod} (\Gamma_1)\leq
      \mathrm{mod} (\Gamma_2)$.
  \item[2.]  $\mathrm{mod} (\bigcup_{i=1}^{\infty} \Gamma_i) \leq
      \sum_{i=1}^{\infty}\mathrm{mod} (\Gamma_i)$. The equality holds if $\Gamma_i$ and $\Gamma_j$ ($i\ne j$) are contained in mutually disjoint domains.
  \item[3.] If every $\gamma_2\in\Gamma_2$ contains some $\gamma_1\in\Gamma_1$ as a subcurve then $\mathrm{mod} (\Gamma_1 )\geq \mathrm{mod}
      (\Gamma_2)$.
\end{itemize}

\section{Liouville measure of boxes and modulus of curves}

In \cite{HaSar2}, Hakobyan and
the second author observed that the Liouville measure and the modulus of a curve family are asymptotic to each other.

 \begin{lemma}[See \cite{HaSar2}]
\label{lem:mod_liouville_measure} Let $(a,b,c,d)$ be a quadruple of points on
$\mathbb{S}^1$ in the counterclockwise order. Let $\Gamma_{[a,b]\times
[c,d]}$ consist of all differentiable curves $\gamma$ in $\mathbb{D}$ which
connect $[a,b]\subset \mathbb{S}^1$ with $[c,d]\subset \mathbb{S}^1$. Then
$$
\mathrm{mod}(\Gamma_{[a,b]\times [c,d]})-\frac{1}{\pi}{L}([a,b]\times [c,d])-\frac{2}{\pi}\log 4\to 0
$$
as $\mathrm{mod}(\Gamma_{[a,b]\times [c,d]})\to\infty$, where ${L}$ is the
Liouville measure.
\end{lemma}

If $\mathrm{mod} (h_t(\Gamma_{[a,b]\times [c,d]}))\to \infty$ as $t\to\infty$, then Lemma \ref{lem:mod_liouville_measure} implies
\begin{equation}
\label{eq:mod/liou}
\lim_{t\to\infty}\frac{\mathrm{mod}( h_t(\Gamma_{[a,b]\times [c,d]}))}{\mathcal{L}(h_t)([a,b]\times [c,d])}\to\frac{1}{\pi}.
\end{equation}

Moreover, $\mathrm{mod} (h_t(\Gamma_{[a,b]\times [c,d]}))$ is bounded if and only if $\mathcal{L}(h_t)([a,b]\times [c,d])$ is bounded.

\section{Proof of the Theorems}

\subsection{Convergence of Liouville measures}

For $s+ti\in \mathbb{H}_{>0}=\{w\in \mathbb{C}\mid {\rm Re}(w)>0\}$,
we consider quasiconformal mappings $f_{s+ti}:\mathbb{D}\to \mathbb{D}$
with
Beltrami coefficients
$$
\frac{1-(s+ti)}{1+(s+ti)}\frac{\overline{\varphi}}{|\varphi|}.
$$
In the natural parameter $z=x+yi=\int_{*}\sqrt{\varphi(\zeta )}d\zeta$,
the corresponding quasiconformal mappings are
$$
f_{s+ti}(z)=\frac{1}{s}x-\frac{t}{s}y+yi
$$
for $s+ti\in \mathbb{H}_{>0}$. Define
$$
D^{*}_{\varphi}:\mathbb{H}_{>0}\to T(\mathbb{D});\ \ \ D_{\varphi}^{*}(s+ti)=\Big{[}\frac{1-(s+ti)}{1+(s+ti)}\frac{\overline{\varphi}}{|\varphi|}\Big{]}.
$$
 We will prove

\begin{theorem}
\label{thm:rephrase-main-theorem}
For any box of geodesics $[a,b]\times [c,d]$,
$$
\frac{s}{s^2+t^2}\mathrm{mod}(f_{s+ti}(\Gamma_{[a,b]\times [c,d]}))\to \mu_{-\varphi}([a,b]\times [c,d])
$$
as $s+|t|\to \infty$, where $\Gamma_{[a,b]\times [c,d]}$ is the set of arcs connecting $[a,b]$ and $[c,d]$ in $\mathbb{D}$.
\end{theorem}

\noindent
{\bf Proof of Theorem \ref{thm:Teich-has-limit}.} Let $A:\mathbb{H}_{>0}\to\mathbb{D}$ be given by $A(z)=\frac{-z+1}{z+1}$. Note that $A(0)=1$, $A(1)=0$ and  $A(\infty )=-1$. Let $\lambda (s+ti):=A(s+ti)$ and note that $\lambda\to -1$ if and only if $s+|t|\to\infty$. Since $\mu_{\varphi}$ has no atoms (See \cite{HaSar1}) and $(D_{\varphi}\circ A)(s+ti)=D_{\varphi}^{*}(s+ti )$ we have that $D_{\varphi}(\lambda )\to [\mu_{-\varphi}]$ as $\lambda\to -1$ by Theorem \ref{thm:rephrase-main-theorem} and Lemma \ref{lem:mod_liouville_measure}. Moreover, $D_{\varphi}(-e^{i\theta}\lambda )=[-e^{i\theta}\lambda\frac{\bar{\varphi}}{|\varphi |}]=[\lambda\frac{-\overline{e^{-i\theta}\varphi}}{|-e^{-i\theta}\varphi |}]=D_{-e^{-i\theta}\varphi}(\lambda )\to [\mu_{e^{-i\theta}\varphi}]$ as $\lambda\to -1$ by Theorem \ref{thm:rephrase-main-theorem}. This gives the first statement of Theorem \ref{thm:Teich-has-limit} since $-e^{i\theta}\lambda\to e^{i\theta}$ as $\lambda\to -1$.

We define the extension of the Teichm\"uller disk $D_\varphi$
to the closed disk $\overline{\mathbb{D}}$
by setting
$$
D_\varphi(e^{i\theta})=[\mu_{e^{-i\theta}\varphi}]\quad (e^{i\theta}\in S^1).
$$
We proved above that if $\{\lambda_n\}_n\subset \mathbb{D}$
is a sequence  converging to $e^{i\theta_{0}}\in S^1$ then $D_\varphi(\lambda_n)\to [\mu_{e^{-i\theta_0}\varphi}]$
as $n\to \infty$
in the Thurston bordification.
To finish the proof of continuity, let $e^{i\theta_n}\to e^{i\theta_{\infty}}$ as $n\to\infty$. We need to prove that $[\mu_{e^{-i\theta_n}\varphi}]\to [\mu_{e^{-i\theta_{\infty}}\varphi}]$ and this
 follows by the diagonal argument. The injectivity of the extension of $D_{\varphi}$ to the unit circle $S^1$ follows by \cite[Theorem 2]{HaSar1}.

\subsection{Proof of Theorem \ref{thm:rephrase-main-theorem}}
An elementary computation gives the Beltrami coefficient of $f_{s+ti}(z)$ to be
$$
\mu (z)=\mu_{s+ti}(z)=\frac{1-(s+ti)}{1+(s+ti)}.
$$
Since $s^2+t^2\to \infty$ as $s+|t|\to \infty$,
the maximal dilatation $K(f_{s+ti})$ of $f_{s+it}$ behaves
\begin{align}
K(f_{s+ti})
&=\frac{\sqrt{(1+s)^2+t^2}+\sqrt{(1-s)^2+t^2}}{\sqrt{(1+s)^2+t^2}-\sqrt{(1-s)^2+t^2}}
\label{eq:K-at-infinity}
\\
&=
\frac{(\sqrt{(1+s)^2+t^2}+\sqrt{(1-s)^2+t^2})^2}{4s}
\nonumber
\\
&=
\frac{s^2+t^2}{4s}\left(
\sqrt{1+\frac{2s+1}{s^2+t^2}}+\sqrt{1-\frac{2s-1}{s^2+t^2}}
\right)^2
=
\frac{s^2+t^2}{s}\left(
1+o(1)
\right)
\nonumber
\end{align}
as $s+|t|\to \infty$.

{\it Acknowledgement.} We include the proposition below for the convenience of the reader. The main ideas and techniques are already contained in \cite{HaSar1}. In particular, the idea of estimating the modulus of a curve family under vertical shrinking by a subfamily of curves which have horizontal variation at most $\delta >0$ is already used in \cite{HaSar1}, \cite{HaSar2}. Lemma \ref{lem:mod_liouville_measure} from Section 3 also appears in \cite{HaSar1}, \cite{HaSar2}.

\begin{proposition}
\label{prop:upper}
Under the above notation
$$
\limsup_{s+|t|\to\infty} \frac{1}{s+\frac{t^2}{s}}
\mathrm{mod}(f_{s+ti}(\Gamma_{[a,b]\times [c,d]}))\leq
\mu_{-\varphi}([a,b]\times [c,d]).
$$
\end{proposition}

\begin{proof}
Let $B=[a,b]\times [c,d]\subset (S^1\times S^1)-diag$ be a fixed box of geodesics. Let $\nu =\left|{\rm Im}(\sqrt{\varphi (\zeta )}d\zeta)\right|=|dy|$ be the horizontal foliation of $\nu$ which is also the vertical foliation of $-\varphi$.  Note that $\nu$ is a measured foliation of $\mathbb{D}$ while $\mu_{-\varphi}$ is a measured geodesic lamination of $\mathbb{D}$.

Let $\Gamma_B$ be the family of all Jordan curves that connect $[a,b]$ to $[c,d]$ inside $\mathbb{D}$. Let $\delta >0$ be fixed. Define $\Gamma^{\geq\delta}_B$ to be the family of all $\gamma\in \Gamma_B$ such that $\nu (\gamma )\geq\delta$, and define $\Gamma^{<\delta}_B$ to be all $\gamma\in \Gamma_B$ such that $\nu (\gamma )<\delta$ (See \cite{HaSar1}). Since $f_{s+ti}$ does not change the $y$-coordinate in the canonical parameter of $\varphi$, we have that
curves in $\Gamma_B^{\geq \delta}$ are mapped onto curves in $\Gamma_{f_{s+ti}(B)}^{\geq\delta}$ and curves in $\Gamma_B^{< \delta}$ are mapped onto curves in $\Gamma_{f_{s+ti}(B)}^{<\delta}$.

Define $\rho_{\delta} (z')=\frac{1}{\delta}$ in the canonical parameter $z'=f_{s+ti}(z)=x'+y'i$ of the terminal quadratic differential on $f_{s+ti}(\mathbb{D})$ corresponding to $\varphi$ and the map $f_{s+ti}$. Since $l_{\rho}(\gamma ):=\int_{\gamma}\rho_{\delta} (z')|dz'|\geq\int_{\gamma}\frac{1}{\delta}dy'$, we have
$$
l_{\rho}(\gamma )\geq\frac{1}{\delta}\delta =1
$$
for all $\gamma\in f_{s+ti}(\Gamma^{\geq\delta}_B)=\Gamma_{f_{s+ti}(B)}^{\geq\delta}$. Thus $\rho_{\delta}$ is allowable for the family
$f_{s+ti}(\Gamma_B^{\geq\delta})=\Gamma_{f_{s+ti}(B)}^{\geq\delta}$ and by the definition of the modulus $\mathrm{mod}(f_{s+ti}(\Gamma_B^{\geq\delta}))\leq \frac{1}{\delta^2}\int_{\mathbb{D}}|\varphi (\zeta )|d\xi d\eta$. We obtain
\begin{equation}
\label{eq:limsup1}
\lim_{s+|t|\to\infty}\frac{1}{s+\frac{t^2}{s}}\mathrm{mod}(f_{s+ti}(\Gamma_B^{\geq\delta}))\leq\lim_{s+|t|\to\infty}\frac{1}{s+\frac{t^2}{s}}\frac{1}{\delta^2}\int_{\mathbb{D}}|\varphi (\zeta )|d\xi d\eta=0.
\end{equation}
From \eqref{eq:K-at-infinity}
and the quasi-invariance of the modulus we obtain
\begin{equation}
\label{eq:limsup}
\lim_{s+|t|\to\infty}\frac{1}{s+\frac{t^2}{s}}\mathrm{mod}(f_{s+ti}(\Gamma_B^{<\delta}))\leq \lim_{s+|t|\to\infty}\frac{1}{s+\frac{t^2}{s}}K(f_{s+ti}) \mathrm{mod}(\Gamma_B^{<\delta})=\mathrm{mod}(\Gamma_B^{<\delta}).
\end{equation}
If all points on $S^1$ are on a finite $\varphi$-distance from a point in $\mathbb{D}$, then as $\delta\to 0$,
$\Gamma_B^{<\delta}$ converges to
the set $|\nu_B|$ of horizontal trajectories of $\varphi$ that have one endpoint in $[a,b]$ and the other endpoint in $[c,d]$ (See \cite{HaSar1}).
Here,
a sequence of rectifiable curves $\gamma_n$ \emph{converges} to a curve $\gamma$ if there is a uniformly Lipschitz parametrizations of all curves by the same interval so that $\gamma_n$ converge uniformly to $\gamma$ as functions.
A sequence $\Gamma_n$ of families of rectifiable curves has  \emph{limit} $\Gamma$ if $\Gamma$ consists of all curves $\gamma$ such that there is a sequence $\gamma_n\in\Gamma_n$ with $\gamma_n$ converges to $\gamma$ in the above sense.
By applying Keith's theorem (See \cite{Keith} and \cite{HaSar1}) we have
\begin{equation}
\label{eq:delta0}
\limsup_{\delta\to 0}\mathrm{mod}(\Gamma_B^{<\delta})\leq \mathrm{mod}(|\nu_B|)
\end{equation}
as $\delta\to 0$. Keith's theorem is stated for compact metric spaces and in the metric induced by an integrable holomorphic quadratic differentials some points of $S^1$ could be on infinite distance from the interior points.  Note that even when some points of $S^1$ are on infinite $\varphi$-distance the formula (\ref{eq:delta0}) holds (See \cite[proof of Theorem 1.4]{HaSar1}).

Therefore by (\ref{eq:limsup}) and (\ref{eq:limsup1}) we obtain
\begin{align*}
\limsup_{s+|t|\to\infty}\frac{1}{s+\frac{t^{2}}{s}}
\mathrm{mod}(f_{s+ti}(\Gamma_B))
&\leq
\limsup_{s+|t|\to\infty}\frac{1}{s+\frac{t^{2}}{s}}\mathrm{mod}(f_{s+ti}(\Gamma_B^{<\delta}))
\\
&\qquad
+\limsup_{s+|t|\to\infty}\frac{1}{s+\frac{t^{2}}{s}}\mathrm{mod}(f_{s+ti}(\Gamma_B^{\geq\delta}))
\\
&=
\mathrm{mod}(\Gamma_B^{<\delta}).
\end{align*}
Since the left hand side of the above inequality does not depend on $\delta$ and the right hand side converges to $\mathrm{mod}|\nu^B|$ as $\delta\to 0$, we obtained
$$
\limsup_{s+|t|\to\infty}\frac{1}{s+\frac{t^{2}}{s}}
\mathrm{mod}(f_{s+ti}(\Gamma_B))\leq \mathrm{mod}(|\nu^B|).
    $$
By the use of the Beurling's criteria
(See \cite{Ahlfors}),
 we conclude that the metric $\frac{dy}{l(z)}$ in the canonical coordinates $z=x+yi$ of $\varphi$ is extremal for the family of curves $|\nu^B|$, where $l(z)$ is the $\varphi$-length of the horizontal trajectory through $z$. Consequently,
we get $\mathrm{mod}(|\nu^B|)=\mu_{-\varphi}(B)$ and the proof of Proposition \ref{prop:upper} is finished.
\end{proof}

We also need a converse inequality whose proof is  our main contribution. When the convergence is only along the Teichm\"uller geodesic this inequality follows essentially by Beurling's criteria (See \cite{HaSar1}) while the proof when the convergence is along an arbitrary sequence in $D_{\varphi}$ is more substantial. We first prove a special case of the converse inequality in the following lemma.

\begin{lemma}
\label{lem:rectangle}
Let $R=[0,a]\times [0,b]$ and $A\subset [0,b]$ be a measurable subset of a possibly positive Lebesgue measure $m(A)$. Let $\Gamma$ be the family of curves in $R$ that connects $\{0\}\times ([0,b]\setminus A)$ and $\{a\}\times ([0,b]\setminus A)$. Then
$$
\lim_{s+|t|\to \infty}\frac{1}{s+\frac{t^2}{s}}\mathrm{mod}(f_{s+ti}(\Gamma ))\geq\frac{b-2m(A)}{a}.
$$
\end{lemma}

\begin{figure}
\includegraphics[width=10cm, bb=0 0 589 281]{figure2-1.pdf}
\caption{The parallelogram $R_{s+ti}=f_{s+ti}(R)$.}
\label{fig:slanted-rectangle}
\end{figure}

\begin{proof}
From the large right angled triangle in Figure \ref{fig:slanted-rectangle} we get
$$
\tan\alpha =\frac{b}{\frac{|t|}{s}b}=\frac{s}{|t|}.
$$
Let $h$ be the Euclidean length of the orthogonal arcs to the two slanted sides of $f_{s+ti}(R)$. Then the small right-angled triangle gives
$$
\sin\alpha =\frac{h}{\frac{1}{s}a}.
$$
The above two equalities give
$$
h=\frac{a}{s}
\frac{\frac{s}{|t|}}{\sqrt{1+\frac{s^2}{t^2}}}=\frac{a}{\sqrt{s^2+t^2}}.
$$

Let $l$ be the length of the subarc of the slanted side of $f_{s+ti}(R)$ that consists of endpoints of the arcs of length $h$ orthogonal to both slanted sides. Then we have
$$
l=\sqrt{b^2+\frac{t^2}{s^2}b^2}-\cos\alpha \frac{a}{s}=\frac{b}{s}\sqrt{s^2+t^2}-\frac{1}{\sqrt{1+\frac{s^2}{t^2}}}\frac{a}{s}
$$
which gives
$$
l=\frac{b(s+\frac{t^2}{s})-a\frac{|t|}{s}}{\sqrt{s^2+t^2}}.
$$

The family of curves $f_{s+ti}(\Gamma )$ contains a subfamily $\Gamma_{s+ti}'$ of all line segments that are orthogonal at both ends to the slanted boundary sides of $f_{s+ti}(R)$ except the line segments that have at least one endpoint in $f_{s+ti}((\{ 0\}\times A)\cup (\{ a\}\times A))$. The total Lebesgue measure of the set of endpoints of $\Gamma_{s+ti}'$ is at least $l-2m(A)\sqrt{1+\frac{t^2}{s^2}}$. This gives
$$
\mathrm{mod} (f_{s+ti}(\Gamma ))\geq \mathrm{mod}(\Gamma_{s+ti}')\geq \frac{l-2m(A)\sqrt{1+\frac{t^2}{s^2}}}{h}.
$$
Using the above estimates we obtain
\begin{align*}
\mathrm{mod} (f_{s+ti}(\Gamma ))
&\geq \Big{[}\frac{b(s+\frac{t^2}{s})-a\frac{|t|}{s}}{\sqrt{s^2+t^2}}-2m(A)\sqrt{1+\frac{t^2}{s^2}}\Big{]}:\frac{a}{\sqrt{s^2+t^2}}\\
&=\frac{b}{a}(s+\frac{t^2}{s})-\frac{|t|}{s}-\frac{2m(A)}{a}\frac{s^2+t^2}{s}
\end{align*}
and
$$
\liminf_{s+|t|\to\infty} \frac{\mathrm{mod}( f_{s+ti}(\Gamma ))}{s+\frac{t^2}{s}} \geq \liminf_{s+|t|\to\infty} \Big{[}
\frac{b}{a} -\frac{|t|}{s(s+\frac{t^2}{s})}-\frac{2m(A)}{a}\Big{]}.
$$

Note that $\limsup_{s+|t|\to\infty} \frac{|t|}{s(s+\frac{t^2}{s})}=\limsup_{s+|t|\to\infty}\frac{|t|}{s^2+t^2}=0$ and
 we obtain
 $$
\liminf_{s+|t|\to\infty} \frac{\mathrm{mod} (f_{s+ti}(\Gamma ))}{s+\frac{t^2}{s}} \geq \frac{b-2m(A)}{a}
$$
\end{proof}

We consider the following situation. Let $D=\{ z=x+yi| y\in [0,s_0], h_2(y)<x<h_1(y)\}$ where $h_1$ is lower semicontinuous and $h_2$ upper semicontinuous function such that $h_1(y)>c_1>0$ and $h_2(y)<c_2<0$. Then $D$ is a domain in $\mathbb{C}$ and we further assume that $D$ has finite Lebesgue area. Denote by $\Gamma_D$ the family of curves that connects the graphs of $h_1$ and $h_2$ inside $D$.
Let $R=[a,b]\times [0,s_0]$ be a rectangle that contains the graphs of $h_1$ and $h_2$ over $[0,s_0]-A$, where $A\subset [0,s_0]$ is Lebesgue measurable and $2m(A)<s_0$.
Then we prove

\begin{lemma}
\label{lem:one_rectangle_approx}
Under the above notation,
$$
\liminf_{s+|t|\to\infty}\frac{1}{s+\frac{t^2}{s}}\mathrm{mod}(f_{s+ti}(\Gamma_D))\geq\frac{s_0-2m(A)}{b-a}.
$$
\end{lemma}

\begin{proof}
Let $D_{s+ti}:=f_{s+ti}(D)$ and $R_{s+ti}:=f_{s+ti}(R)$. Let $\Gamma_{s+ti}^{\perp}$ be the family of curves that consists of orthogonal segments to the slanted sides of the parallelogram $R_{s+ti}$ such that the endpoints of each $\gamma\in\Gamma_{s+ti}^{\perp}$ do not belong to $(\{ a\}\times A)\cup(\{b\}\times A)$ (cf. Figure \ref{fig:slanted-rectangle}).  We claim that each $\gamma\in \Gamma_{s+ti}^{\perp}$ contains a subcurve in $f_{s+ti}(\Gamma_D)$.

Indeed, since the graphs of $h_1$ and $h_2$ over $[0,s_0]-A$ are in $R$ it follows that both endpoints of $\gamma$ are outside $D_{s+ti}$. On the other hand $\gamma$ intersects $D_{s+ti}$ and does not intersect the real axis or the line parallel to the real axis through point $s_0i$. This implies that $\gamma$ intersects the images under $f_{s+ti}$ of both graphs of $h_1$ and $h_2$ over $[0,s_0]$. Therefore there is a subsegment $\gamma'$ of $\gamma$ that is in $f_{s+ti}(\Gamma_D)$.

By the monotonicity of the module (See \S 3, property 3) we have
$$
\mathrm{mod}(f_{s+ti}(\Gamma_D))\geq\mathrm{mod}(\Gamma_{s+ti}^{\perp}).
$$
The family of curves $\Gamma_{s+ti}^{\perp}$ is used in the proof of Lemma \ref{lem:rectangle} to obtain the lower bound. Therefore the lower bound in Lemma \ref{lem:rectangle} implies
$$
\liminf_{s+|t|\to\infty}\frac{1}{s+\frac{t^2}{s}}\mathrm{mod}(f_{s+ti}(\Gamma_D))\geq
\frac{s_0-2m(A)}{b-a}.
$$
\end{proof}

 We are ready to prove the lower bound for the general case.

\begin{proposition}
\label{prop:lower}
Under the above notation we have $$
\liminf_{s+|t|\to\infty}\frac{1}{s+\frac{t^2}{s}}\mathrm{mod}(f_{s+ti}(\Gamma_B))\geq \mu_{-\varphi}([a,b]\times [c,d]),
$$
for all boxes of geodesics $[a,b]\times [c,d]\subset (S^1\times S^1)-diag$.
\end{proposition}

\begin{proof}
Consider the set of all horizontal trajectories of $\varphi$ that connect $[a,b]$ to $[c,d]$. They are divided into at most countably many horizontal strips $\{ S_{\omega}\}_{\omega =1}^{\infty}$ such that $S_{\omega}$ and $S_{\omega'}$ can have in common at most one of their boundary horizontal trajectories for $\omega\neq \omega'$. Let $\beta_{\omega}$ be a segment of the vertical trajectory that defines $S_\omega$ (See Strebel \cite{Strebel}). Denote by $\Gamma_\omega$ the family of curves in the strip $S_{\omega}$ that connects the vertical sides of $S_{\omega}$. Then $\Gamma_\omega\subset \Gamma_B$ and by monotonicity and  additivity
$$
\mathrm{mod}(f_{s+ti}(\Gamma_B))\geq\sum_{\omega}\mathrm{mod}(f_{s+ti}(\Gamma_{\omega})).
$$

We fix $\omega$ and estimate $\mathrm{mod}(f_{s+ti}(\Gamma_{\omega}))
$.
Let $D$ be the image of $S_\omega$ in the natural parameter such that $\beta_\omega$ is mapped onto the interval $[0,s_0]$ of the $y$-axis.
Then there exist $h_1,h_2:[0,s_0]\to\mathbb{R}\cup\{-\infty ,\infty\}$ such that
$$
D=\{x+yi\in \mathbb{C}\mid  0<y<s_0, h_2(y)<x<h_1(y)\},
$$
$h_1(y)>0>h_2(y)$ for all $y\in [0,s_0]$ and that $\liminf_{y\to y_0}h_1(y)\geq h_1(y_0)$ and $\limsup_{y\to y_0}h_2(y)\leq h_2(y_0)$ for all $y_0\in [0,s_0]$. The function $h_1$ is lower semicontinuous and the function $h_2$ is upper semicontinuous. Thus $h_1$ has a minimum $c_1>0$ and $h_2$ has a maximum $c_2<0$ on $[0,s_0]$.

 In particular, both $h_1:[0,s_0]\to [c_1,\infty ]$ and $h_2:[0,s_0]\to [-\infty ,c_2]$ are  Lebesgue measurable and thus so are $1/h_1:[0,s_0]\to [0,1/c_1]$ and $1/h_2:[0,s_0]\to [1/c_2,0]$.
 By a corollary to Lusin's theorem applied to $1/h_1$ and $1/h_2$ (See Rudin \cite[page 56]{Rudin}),  there exist sequences  of continuous functions $1/g_n:[0,s_0]\to [0,1/c_1]$ and
 $1/f_n:[0,s_0]\to [1/c_2,0]$ such that $1/g_n(y)\to 1/h_1(y)$ and $1/f_n(y)\to 1/h_2(y)$ as $n\to\infty$ for a.a. $y\in [0,s_0]$. Since $g_n(y)-f_n(y)\geq c_1-c_2$ (again by Lusin's theorem), Lebesgue Dominated Convergence Theorem implies that
 \begin{equation}
 \label{eqn:convergence_funct}
 \int_B\frac{dy}{g_n(y)-f_n(y)}\to\int_B\frac{dy}{h_1(y)-h_2(y)}
 \end{equation}
 for any Lebesgue measurable set $B\subset [0,s_0]$ as $n\to\infty$.

We fix $n$ and divide the interval $[0,s_0]$ into $p$ subintervals $I_k=[\frac{k-1}{p}s_0,\frac{k}{p}s_0)$ for $k=1,2,\dots ,p$. Define $s_p^1(y)=\max_{I_k}g_n$ and $s_p^2(y)=\min_{I_k}f_n$ for $y\in I_k$. The two step functions satisfy $s_p^1\geq g_n$ and $s_p^2\leq f_n$ on $[0,s_0]$. Since $1/(g_n-f_n)$ is bounded and continuous on $[0,s_0]$, it follows that
$$
\int_{B}\frac{1}{s_p^1(y)-s_p^2(y)}dy\to \int_{B}\frac{1}{g_n(y)-f_n(y)}dy
$$
for any Lebesgue measurable $B\subset [0,s_0]$ as $p\to\infty$.

Denote by $A_{n}\subset [0,s_0]$ the set of all $y$ such that either $g_n(y)\neq h_1(y)$ or $f_n(y)\neq h_2(y)$. The Lebesgue measure $m(A_{n})$ is going to zero as $n\to\infty$ by Lusin's theorem.
Let $D_p$ denote the domain between the graphs of $s_p^1$ and $s_p^2$.
Since $s_p^j$ for $j=1,2$ each have $p$ steps we conclude that $D_p$ is the union of $p$ rectangles $D_{p,k}$ for $k=1,2,\ldots ,p$ whose vertical sides are the steps of $s_p^j$ for $j=1,2$. Let $A_{n,k}=A_n\cap I_k$.

We consider the curve family $(\Gamma^{p,k}_{s+ti})^{\perp}$ that consists of all Euclidean segments orthogonal at both endpoints to the slanted sides of the parallelogram $f_{s+ti}(D_{p,k})$ such that the endpoints do not belong $f_{s+ti}[\{ (s_p^1(y),y)|y\in A_{n,k}\}\cup \{ (s_p^2(y),y)|y\in A_{n,k}\} ]$.

By Lemma \ref{lem:one_rectangle_approx} we get that
$$
\liminf_{s+|t|\to\infty}\frac{1}{s+\frac{t^2}{s}}\mathrm{mod}((\Gamma^{p,k}_{s+ti})^{\perp})\geq
\frac{s_0-2m(A_{n,k})}{s_p^1(y_{k})-s_p^2(y_{k})}
$$
where $y_k\in I_k$ is arbitrary. Since $(\Gamma^{p,k}_{s+ti})^{\perp}$ for $k=1,2,\ldots ,p$ are pairwise disjoint and each curve in $(\Gamma^{p,k}_{s+ti})^{\perp}$ contains a curve in $f_{s+ti}(\Gamma_\omega)$,  we get
$$
\liminf_{s+|t|\to\infty}\frac{1}{s+\frac{t^2}{s}}\mathrm{mod}(f_{s+ti}(\Gamma_\omega))\geq\sum_{k=1}^p\frac{m(I_k)}{s_p^1(y_{k})-s_p^2(y_{k})}-2\sum_{k=1}^p\frac{m(A_{n,k})}{s_p^1(y_{k})-s_p^2(y_{k})}
$$
which gives
$$
\liminf_{s+|t|\to\infty}\frac{1}{s+\frac{t^2}{s}}\mathrm{mod}(f_{s+ti}(\Gamma_\omega))\geq\int_{[0,s_0]}\frac{dy}{s_p^1(y)-s_p^2(y)}-2\int_{A_n}\frac{dy}{s_p^1(y)-s_p^2(y)}.
$$
By letting $p\to\infty$ in the above inequality we obtain
$$
\liminf_{s+|t|\to\infty}\frac{1}{s+\frac{t^2}{s}}\mathrm{mod}(f_{s+ti}(\Gamma_\omega))\geq\int_{[0,s_0]}\frac{dy}{g_n(y)-f_n(y)}-2\int_{A_n}\frac{dy}{g_n(y)-f_n(y)}.
$$
Since $\int_{A_n}\frac{dy}{g_n(y)-f_n(y)}\geq \frac{m(A_n)}{c_2-c_1}\to 0$ as $n\to\infty$, by letting $n\to\infty$ the above inequality gives
$$
\liminf_{s+|t|\to\infty}\frac{1}{s+\frac{t^2}{s}}\mathrm{mod}(f_{s+ti}(\Gamma_\omega))\geq \int_{[0,s_0]}\frac{dy}{h_1(y)-h_2(y)}=\mu_{-\varphi}(\beta_{\omega}).
$$
The proposition follows by summing the above inequality over all $\omega$.
\end{proof}

Let $h_{\lambda}:S^1\to S^1$ be the quasisymmetric map representing $D_{\varphi}(\lambda )$.
Propositions \ref{prop:upper} and \ref{prop:lower} imply the projective weak* convergence of $\mathcal{L}(h_{\lambda})$ to $\mu_{e^{-i\theta}\varphi}$ as $\lambda\to e^{i\theta}$ and this finishes the proof of Theorem \ref{thm:rephrase-main-theorem}.

\subsection{Proof of Theorem \ref{thm:Teich-asymptotics}} If $B=[a,b]\times [c,d]$ is a box of geodesics, in the previous section we established that $\lim_{s+|t|\to\infty}\frac{1}{s+\frac{t^2}{s}}\mathrm{mod}(f_{s+ti}(\Gamma_B))=\mu_{-\varphi}(B)$. Let $A(z)=\frac{-z+1}{z+1}$ and $\lambda =A(s+ti)$.
Note that $s+ti =\frac{-\lambda+1}{\lambda +1}$ and $s=\frac{1-|\lambda |^2}{|1-\lambda |^2}$.
Then $s+|t|\to\infty$ if and only if $\lambda\to -1$ and we have
$$
\lim_{s+|t|\to\infty}\Big{[}\frac{s^2+t^2}{s}\Big{]}/\Big{[}\frac{2}{1-|\lambda |}\Big{]}=1.
$$
Then Lemma \ref{lem:mod_liouville_measure} implies $\lim_{\lambda\to -1}\frac{1-|\lambda |}{2\pi}\mathcal{L}(h_{\lambda})=\mu_{-\varphi}$.

Let $B_{\theta}(z)=-e^{-i\theta}z$. Then we have
$$
D_{\varphi}(\lambda )=\left[\lambda\frac{\bar{\varphi}}{|\varphi |}\right]=\left[B_{\theta}(\lambda )\frac{-\overline{e^{-i\theta}\varphi}}{|\varphi |}\right].
$$
Note that $B_{\theta}(\lambda )\to -1$ if and only if $\lambda\to e^{i\theta}$. Then the above limit implies that
$\lim_{\lambda\to e^{i\theta}}\frac{1-|\lambda |}{2\pi}\mathcal{L}(h_{\lambda})=\mu_{e^{-i\theta}\varphi}$ for each $e^{i\theta}\in S^1$ and the proof is completed.

redpajama_set_name: RedPajamaArXiv


text:
Q: Compile a minimal Linux 3.5 Kernel for Hyper-V I'm looking for to compile a minimal linux 3.5 kernel for Hyper-V.
The "selecting" hyper-v drivers part is quite easy. However, how to remove unnecessary modules/drivers and improve performance.

A: Read Linux Kernel in a Nutshell by Greg Kroah
http://www.kroah.com/lkn/

redpajama_set_name: RedPajamaStackExchange


text:
Yellow Quill Prairie, MB (Photo by NCC)
www.natureconservancy.ca > Home > Where We Work > Manitoba > Featured Projects
Yellow Quill Prairie
Bur oak with mixed-grass prairie on the Yellow Quill Prairie, MB (Photo by NCC)
The Nature Conservancy of Canada (NCC) established the Yellow Quill Prairie Preserve south of Brandon, Manitoba in 1998. The property is giving the few remaining species at risk in this area a better chance for survival, by maintaining the last intact remnants of their natural habitats.
NCC's Yellow Quill Prairie Preserve is located 20 kilometres southeast of the city of Brandon and two kilometres north of the junction of the Souris and Assiniboine Rivers. It abuts the western boundary of the Canadian Forces Base Shilo training grounds and is immediately north of 800 acres (324 hectares) of the Assiniboine Corridor Wildlife Management Area.
View a PDF of the Yellow Quill Prairie trail map here >
Please note: visitors are asked to contact NCC's Manitoba Regional office at 1-866-683-6934 prior to visiting Yellow Quill to ensure land management activities are not active onsite.
An ecosystem under threat
A recent increase in cultivation and irrigation of native range in southwestern Manitoba has put new pressure on the few remnants of mixed grass prairie grasslands. At one time, these grasslands covered thousands of square kilometres. Less than 10 per cent remains intact today.
Conservation values
The prevalence of dry, sandy soils has historically limited the agricultural capability of these lands. A rare piece of intact native mixed grass prairie, it is a rolling sandy prairie of mixed grasses interspersed with aspen forests. Rare plants like red three-awned grass and sand bluestem are also found here.
Wilderness enthusiasts enjoy spotting the species that roam here, including red tailed hawk, moose, elk, deer and fox. The Yellow Quill Prairie is a preferred site for bird watchers wishing to see mountain bluebird and Sprague's pipit in their natural habitat. The latter is listed as a threatened species, as is mule deer.
Endangered species such as northern prairie skink, discovered in the preserve just two years ago, also fight for survival here.
Partners in conservation
The Yellow Quill Prairie Preserve was established in partnership with Mountain Equipment Co-op, Wawanesa Insurance Company, The Thomas Sill Foundation, Manitoba Naturalists Society, TD Canada Trust Friends of the Environment Foundation and several exceptionally generous individuals.
The Crown Lands Department of the Manitoba Government added 800 acres (324 hectares) of adjacent prairie land to complete the project.
Faces of NCC
Supporter Spotlight


text:
Stefanie Simon (* 6. Oktober 1950 in Markneukirchen; gebürtig Stefanie Wetzel; bürgerlicher Name Stefanie Wölke) ist eine deutsche Sängerin und Schauspielerin.

Leben
Stefanie Simon zog im Alter von einem Jahr mit ihrem Vater, dem Holzblasinstrumentenbaumeister Werner Wetzel und ihrer Mutter Elisabeth Wetzel nach Berlin. Sie studierte im Fachbereich Musical/Show an der Universität der Künste Berlin; im Jahr 1974 schloss sie ihr Studium ab.

Schon während ihres Studiums tourte die Schlagersängerin mit Rudi Carrell, Jürgen Marcus, Paul Kuhn und Peter Petrel durch Deutschland. Von 1969 bis 1983 war sie ständige assistierende Sängerin in der Radiosendung "Zweites Frühstück" mit John Hendrik beim Radiosender Rias Berlin.

Seit den 1970er Jahren hat Simon regelmäßige Engagements auf diversen Kreuzfahrtschiffen, wie der Maxim Gorki, Sagafjord, MS Astor und der MS Europa, dem bekannten Kreuzfahrtschiff aus der Fernsehserie Das Traumschiff.

Neben zahlreichen Musikproduktionen tritt Simon auch als Solokünstlerin sowie mit ihrem Gesangspartner Bert Beel seit 1990 im Duett "Steffi & Bert" auf. In mehreren Fernsehsendungen waren sie als Schlagerpaar zu sehen. Es erschienen mehrere CD-Veröffentlichungen. In der Schlagerparade der Volksmusik (NDR) waren beide 1992 mehrfach zu Gast. Bei Galas und Schlagerrevuen treten beide bis heute in Berlin und Brandenburg auf.
Im Opernpalais Berlin gestalten sie seit 2007 den von Beel inszenierten Abend als eine Hommage an Harald Juhnke. Dort gastieren sie mit unterschiedlichen Programmen (meist mit Bezug auf Berlin) seit 2003.

Simon tourt mit verschiedenen Musik- und Entertainmentprojekten, unter anderem auch an der Seite von Julian F.M. Stoeckel, durch Deutschland. Aktuell spielt sie in der Fernsehproduktion Berlin – Tag & Nacht (RTL 2) die Rolle der Lilo Dittrich.

Sie wirkte als Zeitzeugin in dem Dokudrama Rex Gildo – Der letzte Tanz (2022) von Rosa von Praunheim mit.

Stefanie Simon lebt in Berlin.

Diskografie

Alben
 2017: Mein Weihnachten mit dir
 2017: 7 Leben hat die Liebe

Singles
 1967: Wie man in den Wald hineinruft
 1968: Kosakenfest
 1969: Da Capo Señor / Magic
 1970: Oh Joe
 1977: Wenn das deine Liebe ist
 1978: Wie wird es dir geh'n
 1984: Was haben alle so gern
 1987: Komm lass das sein
 1993: Der Trucker aus den Bergen
 1995: Was wäre die Welt ohne Country
 1996: Berlin-Brandenburg – Ein Land in Sicht!
 1996: Beim Fensterputzen
 2003: Du bist viel zu schön für mich
 2004: Und tschüüsss
 2004: Einmal Himmel und zurück
 2005: Das musste ausgerechnet mir passieren
 2005: Alles in Ordnung, alles okay
 2006: Sensationell
 2007: Dein Gute-Laune-Lächeln
 2008: Sag niemals nie
 2009: Es ist Weihnacht
 2010: Königin Luise
 2011: Du malst mir den Himmel blau
 2012: Alles fängt irgendwann von vorne an
 2013: Straßen unserer Stadt
 2014: Die besten Jahre
 2014: Von Null auf hundert
 2016: Männerherzen
 2017: Sieben verdammt lange Tage
 2017: Meine Träume haben Flügel
 2018: Da geht noch was
 2019: Sehnsucht nach Paris
 2019: Ich such' einen Traummann

Filmografie
 seit 2019: Berlin – Tag & Nacht (Fernsehserie, durchgehende Nebenrolle)
 2022: Rex Gildo – Der letzte Tanz (Dokudrama)
 2022: Hot oder Schrott Promi Spezial (VOX)

Weblinks

 Website von Stefanie Simon

Einzelnachweise

Schlagersänger
Deutscher
Geboren 1950
Frau

redpajama_set_name: RedPajamaWikipedia


The John Hampton Luckadoo Annual Lecture is named for "Lucky" Luckadoo who served in the 100th Bomb Group of the Army Air Forces in WWII.
The John Hampton Luckadoo Annual Lecture is funded by Elaine Luckadoo Abbott and Rick Abbott in recognition and love of "Lucky." The annual lecture provides for guest speakers who share their stories and experience about aviation and space flight with students in the next generation as part of the Museum's commitment to STEM education.
"Lucky" is a frequent visitor, speaker, and supporter of the Frontiers of Flight Museum. His contributions include the restoration funding of a B-17 "Flying Fortress" model on display in the Museum's World War II Gallery. In 2013, volunteers Mike Litvin, Gary Seidel, Ken Branscome, Willia Munroe, Peggy Upham, and Joe Swift built the "Lucky" Sim, a flight simulator used in the Museum's community outreach and STEM program.
Not a day goes by that John "Lucky" Luckadoo, 96, doesn't wonder how he could have made it past his 21st birthday. With the bombing of Pearl Harbor on Dec. 7, 1941, Luckadoo left college to serve in the Army Air Forces and graduated from flying school in February 1943.
He was immediately assigned to the newly formed 100th Bomb Group. The outfit flew B-17 heavy bombers that traveled in large formations during daylight raids against strategic targets such as weapons factories, oil refineries and shipyards. They could be in the air for up to eight hours.
German fighter planes attacked them from all directions. Of the 18 planes that the 100th Bomb Group sent out that day, only six returned. The rest, Luckadoo said, either exploded in the air, crashed or were shot down. Bullet holes in the fuselage of his plane let in so much freezing air that he developed frostbite in both feet as he struggled to get the craft back to England.
Luckadoo left the military after the war, settled in Denver with his wife, Bobbie, and became a real estate developer. Bobbie's family have lived in Colorado well before it even became a state. Their daughter, Elaine, was born in Denver. They moved to Dallas in 1960, after he built Big Town Mall in Mesquite, a fixture for more than 40 years. He retired in 1987.
A quote by Luckadoo appears in an exhibit at the World War II Museum in New Orleans. Luckadoo is quoted as saying that of the 40 co-pilots that began in the first class assigned to the newly formed 100th Bomb Group, he was one of only four who survived their twenty-five missions.
The 2019 Honorary Luckadoo speaker is Lt. Col. John R. "Bob" Pardo, featured speaker at the Museum's "Honoring our Nation's Heroes" event on 24 August 2019.
A native Texan, Bob Pardo enlisted in the Aviation Cadet Program of the U.S. Air Force in 1954. A naturally-gifted pilot, Pardo graduated near the top of his class, earning his wings on May 15, 1955. Pardo, a fighter pilot at heart, flew many famous Air Force fighter jets of the 1960s. In November 1966, Pardo deployed to Southeast Asia with the 433rd Tactical Fighter Squadron of the 8th Tactical Fighter Wing, based at Ubon Royal Thai AFB, Thailand. Under the command of WWII Ace Robin Olds, the 8th Tactical Fighter Wing became known as the "Wolf Pack" for their aggressiveness and teamwork in air combat over the skies of North Vietnam. Pardo was officially inducted into the Pack when he downed a North Vietnamese MiG-17F on May 20, 1967.


D.J. Reed returned a punt 62 yards for a touchdown. It was a big moment for the defensive back, as he fell four yards short of reaching the end zone on a 96-yard kickoff return in the first quarter. It was also a big moment for the Wildcats. Central Arkansas was hanging around, trailing 24-16, but Reed's score gave K-State enough momentum to pull ahead.
Offense: A. Give Central Arkansas credit for keeping K-State's rushing attack in check. The Bears twice made Alex Barnes lose yardage, something that didn't happen a single time last season. The Wildcats could have been better on the ground, rushing for just 186 yards, but they didn't have to be the way Ertz was throwing the ball. K-State receivers also deserve kudos for gaining big yardage after the catch.
Defense: C+. K-State was so shaky on defense, allowing 421 yards, that Bill Snyder joked he was going to hold a special midnight practice to teach his players how to defend the option. But the Wildcats improved as the game went on and only surrendered a field goal in the second half. Trent Tanking and Jayd Kirby need to improve at linebacker, but it's worth remembering this was their first game as starters.
Special Teams: A+. D.J. Reed and Byron Pringle are going to be tough for opposing teams to figure out on kickoffs and punts. With both of them on the field, there is no kicking away from them. They combined for 218 return yards and a touchdown on Saturday. Matthew McCrane also made a 53-yard field goal.
Coaching: B+. Bill Snyder's staff had K-State ready to go in most areas, and the Wildcats won comfortably.


Jun 10, 2016 iFighter offers nothing more than a very slick and well designed vertical shooter for the iPhone that belongs in anyone's arcade collection. Feb 17, 2017 Download ES File Explorer APK latest version 4.1.5 for iOS (iphone & ipad). February 17, 2017 By admin 11 Comments. Es File Explorer for. Got a question about the Moneydance iPhone, iPod Touch, iPad, and Android apps? Let us know here! MoneyDance 2017 Syncing with Android is Sporatic. Dungeon Fighter Online is an arcade-type belt-scrolling action game mixed with RPG . Announcement Known issues after Mar 21, 2017 maintenance.
Mar 11, 2017 . Top games, apps and services make the cut in WIRED's pick of the best free and paid-for iPhone Jan 18, 2017 A newly discovered bug in Apple's iOS mobile operating system is being exploited in a prank that lets anyone crash your iPhone or iPad by just. Mar 14, 2014 Employee access and permissions are controlled by the administrator, including LDAP and AD authentication for Android and iOS devices. May 15, 2012 One of the best gadgets to enjoy mobile games is iPhone. iFighter 2: The Pacific 1942 by EpicForce is one of the top games for iOS and we can.


text:
The Writer Files: Writing, Productivity, Creativity, and Neuroscience
Books Arts Award Winning Kelton Reid Podcasting Education
By Kelton Reid. Discovered by Player FM and our community — copyright is owned by the publisher, not Player FM, and audio is streamed directly from their servers. Hit the Subscribe button to track updates in Player FM, or paste the feed URL into other podcast apps.
The Writer Files: Writing, Productivity, Creativity, and Neuroscience « »
How Internationally Bestselling Author Leïla Slimani Writes
#PodcastersForJustice
Award-winning writer and journalist, Leïla Slimani, spoke to me about the challenges of writing historical fiction, impostor syndrome, and what it's like to live In the Country of Others.
"Imagination is the strongest, most powerful human capability. It allows everything: you can move in time, in space, create worlds. That's what I look for when I write, and when I read, too." – Leïla Slimani
Leïla is the French-Moroccan author of the award-winning, #1 internationally bestselling novel The Perfect Nanny – a New York Times Book Review 10 Best Books of the Year – for which she became the first Moroccan woman to win France's most prestigious literary prize, the Goncourt.
Her latest novel, In the Country of Others (first in a planned trilogy about how women's lives change over three generations), was named a Best Book of the Summer by Vogue, E Weekly, BuzzFeed, The Philadelphia Inquirer, Town & Country, Observer, The Millions, and Parade.
Salman Rushdie said of the book, "The world of this novel—Morocco after World War II, leading up to the revolt against French colonialism—is beautifully created.... An exceptional, powerful novel from this justly celebrated writer," and The New York Times Book Review wrote, "In the Country of Others . . . lays bare women's intimate, lacerating experience of war and its consequent trauma."
Leila is also an award-winning journalist and outspoken commentator on women's and human rights, and a French diplomat to French president Emmanuel Macron for the promotion of the French language and culture.
Stay calm and write on ...
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You can now have The Writer Files podcast dropped right into your email inbox every time there's a new show. No more shaking your podcast app!
As a subscriber, Kelton will send you added insights, the chance to get TWF merch (like "Stay Calm and Write On" t-shirts anyone?), curated collections of shows like The Publishing Series and The Writer's Brain, updates, and occasional special offers. Learn more at the link below and take our AuthorPods podcasting course survey.
Get 'The Writer Files' Podcast Delivered Straight to Your Inbox
If you're a fan of The Writer Files, please "Follow" us to automatically see new interviews. In this file Leïla Slimani and I discussed:
Giving voices to the voiceless and time traveling in your work
Racial inequality and the global taboos surrounding the history of colonization
The importance of coffee and cigarettes to the creative process
A writer's guilt, the perils of success...
And why writers just need a good glass of (French) red wine
In the Country of Others: A Novel by Leïla Slimani (Amazon)
Leïla Slimani Amazon author page
Hey, Creator!
Kelton Reid on Twitter
Similar to The Writer Files: Writing, Productivity, Creativity, and Neuroscience
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Where History Comes Alive! A fast-paced, well-researched weekly podcast covering a wide range of historical events, persons, places, legends, and mysteries, hosted by Jon Hagadorn. 1001 Heroes Podcast is a proud part of the 1001 Stories Podcast Network, which includes 1001 Classic Short Stories & Tales Podcast, 1001 Radio Days, and 1001 Stories For the Road Podcast. The network enjoyed over 5 million listens in the past year from a worldwide audience. SUPPORT OUR SHOW BY BECOMING A PATRON! w ...
Curious City
Ask questions, vote and discover answers about Chicago, the region and its people. From WBEZ.
The Book Review
The world's top authors and critics join host Pamela Paul and editors at The New York Times Book Review to talk about the week's top books, what we're reading and what's going on in the literary world.
The New Yorker: Poetry
Readings and conversation with The New Yorker's poetry editor, Kevin Young.


text:
Q: boost ptime from sql server timestamp_t is off by minutes. What did I do wrong? I have a SQL server database and I am pulling dates from it and converting the type of timestamp_t into Int64 as such:
Int64 from_timestamp_t(dtl::timestamp_t& t)
{
    // create a new posix time structure
    boost::posix_time::ptime pt
    (
    boost::gregorian::date           ( t.year, t.month, t.day),
    boost::posix_time::time_duration ( t.hour, t.minute, t.second, t.fraction )
    );

    ptime epoch(date(1970, Jan, 1));
    boost::posix_time::time_duration fromEpoch = pt - epoch;

    // return it to caller
    return fromEpoch.total_milliseconds();
}

I attempt to convert back to a boost ptime from an Int64 as such:
ptime from_epoch_ticks(Int64 ticksFromEpoch)
{
    ptime epoch(date(1970, Jan, 1), time_duration(0,0,0));
    ptime time = epoch + boost::posix_time::milliseconds(ticksFromEpoch);

    return time;
}

For some reason, and I can't figure out why, my dates, hours, etc are all correct, but my minutes are ahead a few minutes from what they should be.  Is it because timestamps from the database are in seconds resolution and I'm using milliseconds?  How do I fix this?
Applying the following modification as Dan suggested seems to have fixed the problem:
Int64 from_timestamp_t(dtl::timestamp_t& t)
{
    int count = t.fraction * (time_duration::ticks_per_second() % 1000);

    boost::posix_time::ptime pt
        (
        boost::gregorian::date           ( t.year, t.month, t.day ),
        boost::posix_time::time_duration ( t.hour, t.minute, t.second, count )
        );

    ptime epoch(date(1970, Jan, 1), time_duration(0, 0, 0, 0));

    boost::posix_time::time_duration fromEpoch = pt - epoch;

    return fromEpoch.total_milliseconds();
}

A: I'm not familiar with SQL Server 2005, but boost posix time has the seconds function if ticksFromEpoch is equivalent to one second.
ptime time = epoch + boost::posix_time::seconds(ticksFromEpoch);

However, the generic way to handle this is presented in the boost date_time documentation:

Another way to handle this is to utilize the ticks_per_second() method
  of time_duration to write code that is portable no matter how the
  library is compiled. The general equation for calculating a resolution
  independent count is as follows:

count*(time_duration_ticks_per_second / count_ticks_per_second)

For example, let's suppose we want to construct using a count
  that represents tenths of a second. That is, each tick is 0.1 second.

int number_of_tenths = 5; // create a resolution independent count --
                          // divide by 10 since there are
                          //10 tenths in a second.
int count = number_of_tenths*(time_duration::ticks_per_second()/10);
time_duration td(1,2,3,count); //01:02:03.5 //no matter the resolution settings


text:
See more General
Eugene bars cater to classic tastes.
By Vanessa Salvia (reprinted without permission)
I don't drink much. Between being a student and a parent, I can't bring home the bacon or fry it up in a pan if I'm soused half the week. But when my editor told me to taste and write about popular cocktails, with the emphasis on tasting the cocktails, I said "Hell yeah!"
My first thought was to find out what Jeffrey Morgenthaler serves a lot. He's the hunky guy behind the bar at Red Agave, and I completely trust his opinions about alcohol. Morgenthaler says drinkers are returning to the classics like Manhattans, Sidecars and Martinis – the kinds of drinks you can get at almost any bar in the world. "I think people are getting a little overwhelmed by all the exotic ingredients," he said. "I've been selling a lot of nice, simple drinks lately."
Manhattans are one of my favorite drinks, always have been, always will be. The bite of the bourbon is uniquely complemented by the sweetness of the vermouth and the dash of fresh cherry. It piques the appetite but leaves the palate clean. I wanted to sample Red Agave's Manhattan, which they make with Punt e Mes, an Italian vermouth made with quinine, in place of the traditional sweet vermouth. Morgenthaler said it was fantastic, and he was right. As a mixologist who creates his own elixirs, Morgenthaler's added other popular drinks to the Red Agave menu, including the Bad Apple, the quirky cousin of a Red Apple, made with blended fresh green apples, lemon juice, sugar and Absolut Citron Vodka. Garnished with a slice of fresh green apple, it's yummy.
Over at Soriah, orders for Cosmopolitans and Lemon Drops rang through the room like church bells on the hour. Feeling urbane out on the town, I had to have a Cosmo. With fresh lime, powdered sugar, vodka, cranberry juice and triple sec, it's tart, sweet and lusciously pink in the glass. Next I tossed back a perfectly puckery Rum Collins (rum, lime juice, orange juice, powdered sugar and a squirt of Collins mix) and found them both exquisite. My drinking companions opted for the classic Margarita, another ever-popular drink according to bartender Andrea Kaady, and were not disappointed.
Chanterelle's bartender, Dave Lawrence, echoed Morgenthaler's sentiments about the classics. Lemon Drops and Margaritas are what their customers crave. "There's been a resurgence of classic cocktails," he said. Through access to the Internet and a trend toward "retro style," 50-year-old cocktail recipes are finding their way into modern culture. Plus, Lawrence notes, flavored liquors like citron or vanilla vodkas can splash fresh life into a stale recipe. "There's variations on those classic cocktails and it's almost like a rebirth of those drinks when you can add something new to it," he said.
Rum and Cokes, Cosmos, Lemon Drops and Margaritas are "standard fare," according to The Horsehead's daytime bartender J. R. Ogden. He says, "We don't have a lot of the exotic liquors so what we sell is pretty basic." And, he added, he sells mostly beer.
Ring of Fire's Lava Lounge seems to defy the trend away from exotic ingredients. Brandon Davis says their fruit-infused liquors, which they began selling about seven years ago, are still their most popular bar item. "We turn them into cocktails called Kamikazes and we also have a Chili Margarita, which are by far our most popular drinks," he said.
The Lounge has its own specialty drink menu with so many delicious options most people forget about Martinis and down a "Thai Me Up" with Thai iced tea and Stoli Vanilla Vodka or a "Dragon Fly" with Crater Lake Vodka instead. Davis said he's seen no slow-down of interest in their exotic potions.
Whether you want to toast with a time-tested classic or a redefined trendy cocktail, you'll find it in Eugene's bar scene.
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text:
Appeal for information after gull shot dead from roof in Barry
RSPCA Cymru is appealing for information after a gull was shot dead in Barry.
Tragically the gull fell to the floor dead from the roof it had been standing on at Plymouth Road. The person who witnessed the bird fall then rang the RSPCA. The police were also informed as gunshots were heard.
RSPCA inspector Emma Smith said: "This incident took place at around 6pm on Friday (13 April). The gull was seen falling to the ground and gunshots were heard.
"The gull was taken to a vets to be examined and there was one large puncture wound found. There was no bullet found following an x-ray.
"Following this examination it has been suggested a high calibre gun may have been used.
"We're appealing to anyone who has any information about this incident or similar incidents to contact our inspectorate appeal line on 0300 123 8018. Calls are treated in confidence."
It is an offence to injure or kill a wild bird under the Wildlife and Countryside Act 1981 (except under licence) and offenders can face a fine of up to £5,000 and/or six months imprisonment.
If you spot an animal in distress, please call the RSPCA's 24-hour helpline on 0300 1234 999.
Should you wish to help the RSPCA, you can donate online. The RSPCA is a charity and relies on donations from the public to exist.
Region: Wales.


The original works and eclectic collections of two dozen people will be on display the afternoon of Sunday, October 14. Come and see more than 50 entries of photographs. paintings, sketches, textiles and crafts, multi-media and fun collections gathered by folks over the years. This second annual showing of "The Stuff of Story" is sponsored by The Gathering. Come and check out this fun, all-ages event! Free admission and free refreshments! Donations of canned goods for the South Sacramento Interfaith Partnership Food Closet will be greatly appreciated at the door. Questions? Want to help? Contact Cathy Sapunor.
Get an idea of what this event is all about by checking out photos from last year's Stuff of Story.


Oral presentations say a lot about you.
I was embarrassed for him. Technically, he was an excellent candidate. He was completing an internship at a prestigious company; his resume was impressive for a new graduate. Now, the downside: his body language spoke of intimidation. He hardly looked up from his notes. When I tested his analytical skills with a problem, his answer was spot on but he was talking to the table twelve inches in front of his face.
Success in engineering, as in business, depends on communication. I've talked about writing skills ("Take the Write Steps for Career Advancement"), now let's consider verbal skills.
I was fortunate that I spent some of my formative years in the military. My presentation skills were polished there, enabling me later to successfully handle a grilling by the head of chemical engineering at Princeton while delivering a paper to more than a hundred scientists. Outside of the military, organizations such as Toastmasters International can help bolster skills.
All presentations consist of two components: substance and appearance. You not only must anchor your argument in logic, but also should make your talk clear, concise, well organized and believable.
Let's consider appearance first. Poor eye contact makes you look shifty and scared. Stooping or slouching and down-turned eyes make matters worse. Remember body language contributes a lot to communication — from 55–80%, experts reckon. In face-to-face communication, look directly at the audience, smile and avoid unnecessary repetitive movement.
Smiling can soften your audience. It's a good idea to think of something pleasant, practice smiling in the mirror and ask those close to you about which friendly expression looks best on you. There's more to body language than facial expression. Don't cross your arms or legs or put your hands in your pockets. Don't lean forward or backward — sit erect in your chair with your shoulders straight.
When delivering a speech, move your eyes around the audience. Ideally, focus on a different group of people every few seconds. Watch for crossed arms and legs. That often indicates a person has an opinion; so, ask questions to ferret these out. Occasionally try pacing to keep your blood flowing, if that works for you.
The cliché "dress for success" applies here. Wear something that is comfortable, gives a professional look and, just as important, makes you feel competent. Look like you came to say something important. I've seen engineers give talks in torn tees and sweat pants and wondered why our client would take us seriously. Don't go too far the other way, though. Wearing a suit and tie in our business will make you the focus of ridicule. My operators at Anheuser-Busch loved to open valves on "suits" from the safety of the control room.
Now, let's talk about substance. Suppose you're trying to assure the client that you've considered the worst case of twenty drain pots that could potentially overwhelm the main header and vent in an alkylation unit collection tank. First, there are 190 potential pairs of pots as well as numerous triples, quadruples, etc. You've got to show the futility of running hundreds of simulations. Next, you must evaluate the potential for running multiple streams into the network. You must present the maximum potential flows and then show how several pairs could interact in the pipe network. These are logical steps that draw conclusions you can defend in your report. However, don't get into all the details in the presentation: capture the key points and link them together with good graphics and a short punch list.
In a face-to-face discussion your tools are limited. Stick to no more than three points, without preamble, just the facts.
Lastly, consider the delivery: make it clear, concise and well supported. Know the material well enough that you can put your notes aside. For a face-to-face meeting you should be able to speak your piece in less than 30 seconds. A major presentation may last 30 minutes and take weeks to prepare properly. (On projects get into the habit of summarizing all your work in a single notebook with updated abstracts — you can expand this into a presentation as needed.) You'll want to anticipate questions your audience might ask and plan how to steer them through the path you choose. This sounds Machiavellian but you don't want your good will with the audience to dissipate while you search for an answer. Create folders for questions with defense material inside. Don't forget to go over graphs and tables for hidden flaws.
Developing good presentation skills will go a long way to advancing your career.
Some common errors plague writing done by many engineers.


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Q: Azure Platform Training Kit AspProviders Configuration Error I just downloaded the Windows Azure Platform Training Kit - October Update and all of the examples working with ASP.NET Membership using their AspProviders project throw a Configuration Error exception. I've spent quite a bit of time trying to debug and correct but am stumped, has anyone seen this as well and have a solution?

A: Have you created your Developer Storage with DSInit.exe ? http://msdn.microsoft.com/en-us/library/windowsazure/gg433005.aspx


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Luke Combs Sees His CMA Trophies as a Reminder He Has 'the Ability to Get It Done'
At the 2019 CMA Awards, Luke Combs added to his already expansive collection of awards and accolades. The singer took home trophies for Song of the Year (for "Beautiful Crazy"), Male Vocalist of the Year and Musical Event of the Year (for "Brand New Man," a collaboration with Brooks & Dunn).
Backstage at the awards show, Combs admits he prefers to keep his trophy collection contained to one room in his house, in part because he doesn't want his professional life to overshadow his personal life with his fiancee, Nicole Hocking. "I don't have anything hanging in my house anywhere guests would be, or in our bedroom," the singer explains. "I always wanted my house to be about me and my fiancee, our life together -- not about my career."
That being said, Combs admits that being able to see those awards do serve a purpose, especially when they're hanging up in the room where he usually goes to write new material. "Going in that room and being able to write a song in there, it doesn't make me over-confident or cocky, it just makes me know that me and the people I work with have the ability to get it done, if we wanna get it done," he explains.
"When I'm in there, if I'm tired or I don't have an idea, I can look up at these [awards] -- especially the ones from tonight -- and go, 'Hey, you've been there. We've achieved some really great things, and we can do it again if we really put our minds to it,'" Combs adds.
Though each of his 2019 CMA Awards signifies a major achievement, Combs admits that winning the Song of the Year title just might be the most meaningful of all. "I [especially wanted this award]. I wanted it for these guys," he said in the media room, gesturing to his two co-writers on "Beautiful Crazy," Wyatt B. Durette III and Robert Williford, who were standing beside him.
"I get to be onstage and talk and be heard all the time, but the people who helped me do that don't always necessarily get the credit that I feel like they deserve. Tonight, two great people have gotten exactly what they deserve," the singer goes on to say. "I am so proud to call these guys really great friends, phenomenal co-writers and CMA winners."
Every CMA Awards Male + Female Vocalist of the Year Winner Ever
Source: Luke Combs Sees His CMA Trophies as a Reminder He Has 'the Ability to Get It Done'
Filed Under: CMA Awards, Editor's Picks, Luke Combs
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There are 6 full-time teachers educating a total of 56 students. 29 students receive a free lunch while 4 receive a reduced-price lunch.


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Greetings to one and all! On Friday morning we will welcome the annual visit of The Victorian Society. The Victorian Society, under the direction of Professor Richard Guy Wilson, runs a summer school program for architects and other related professionals out of Newport, RI. For more than thirty years, this group of architects and art historians have visited North Easton to see the H. H. Richardson buildings. At our museum we exhibit photos of the five Richardson buildings in North Easton, and give a brief history of the Ames family, the Ames Shovel Works, and how the buildings came to be. The group will also visit the Frederick Lothrop Ames Gate Lodge, the Oliver Ames Free Library, the Oakes Ames Memorial Hall, and Unity Church. It is a very nice event and introduces our architectural treasures to people from all across the United States and other countries.
Usually our June open house features the same exhibit of our Richardson buildings each year. This year, I will change things up a bit, and include other buildings by Richardson. Can you name a Richardson building outside of Easton? After visiting us Sunday afternoon between 1-5 p.m., you'll be able to! Over his relatively short career, more Richardson had more than seventy buildings erected including some after his death in 1886. He influenced a generation of architects who followed including Frank Lloyd Wright. There area many buildings in the United States that can trace their architecture to the Richardson Romanesque style, and even today, more recent buildings in Easton and the surrounding area have Richardsonian features. Did you know that Richardson also designed furniture? Many architects do, but little study has been done on Richardson's. On display will be a brochure that features a few of Richardson's designs for chairs and benches. And finally, I think that there was once a sixth Richardson building in Easton! I have found, in an old photo, a building that may have been the freight station designed for North Easton. It looks very similar to a known sketch that Richardson did for a freight house here. See if you agree! Until next time, Frank


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NEC appoints biometrics subject matter expert liaison for U.S. federal law enforcement agencies
May 21, 2019 | Stephen Mayhew
Categories Biometrics News | Biometrics Stocks | Law Enforcement
NEC Corporation of America has appointed former FBI consultant Paul DiPietra to its Advanced Recognition Systems Division to serve as the Senior Account Manager for the U.S. Department of Justice and Federal Law Enforcement. DiPietra will be the primary liaison for NEC with U.S. federal law enforcement agencies looking to use biometrics to help prevent crime, solve cases and protect public safety.
DiPietra started his career in the U.S. Navy and later transitioned to the federal civil service, first with the U.S. Department of Transportation as a member of the Secretary's Intelligence Briefing Staff, and later with the U.S. Department of Homeland Security as a Director for International Engagement and a Senior Policy Advisor for Biometric Technology. After that, he was a consultant to the FBI's CJIS Global Initiatives Unit, providing biometric subject matter expertise. He went on to lead biometric and digital identity partnership and business development efforts within IBM's Global Business Services.
"Paul's experience makes him uniquely qualified for the position," said Benji Hutchinson, Vice President of Federal Operations at NEC Corporation of America. "He brings a consultative and cooperative approach to the job, and a strong desire to deliver real value to the law enforcement community."
"I'm eager to work for a company where I can use my specific set of skills to promote high-quality recognition solutions to law enforcement," added DiPietra. "Not only is NEC the leader in identity matching accuracy as evaluated by NIST, but it is also a company that places priority on R&D and leverages advanced AI technology, allowing for the delivery of proven yet innovative front-line solutions to clients."
Last month NEC published a set of core principles for the application of biometrics and artificial intelligence with respect for privacy and human rights, along with commitments to three initiatives to support its corporate responsibility efforts.
IDGA's Biometrics in Government and Law Enforcement summit fast approaching
IJIS Institute creates Biometrics Task Force
IDEMIA launches mobile biometric fingerprint scanner for law enforcement
Facial biometrics to secure Brazilian digital bank transactions and Carnival celebrations
U.S. judge allows law enforcement to compel suspect to unlock smartphone with biometrics
Judge rules U.S. law enforcement cannot compel biometrics to unlock device
biometrics | law enforcement | NEC | U.S. Government | United States
SMEs Increasingly Using Spy Cameras
Explainer: Facial Thermography


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