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Austin-ZeitgeistMusicJuly 6, 2017
Barbara Lynn: True Hero of Texas Music
This chapter is one of 42 profiles in "All Over the Map: True Heroes of Texas Music" by Michael Corcoran.
"Crazy Cajun" Huey P. Meaux was still working as a barber in Winnie and a DJ on KPAC-AM in Port Arthur, when he started making his name as a record producer and talent scout in the Houston/ Golden Triangle area. His first Top Ten hit was "Let's Talk About Livin'" by East Texas rockabilly singer Bob Luman in 1960, and Huey was hungry for Meaux.
He'd heard about a left-handed Creole girl who played electric guitar and sang like Guitar Slim's sister and as soon as he could, Meaux was there at The Palomino Club in Vinton, LA, just across the Texas border, watching Barbara Lynn Ozen fronting the band Bobbie Lynn and Her Idols. Meaux's jaw dropped when he watched the guitarist pick out leads with her thumb, while strumming with her index finger. Just seeing a female playing an electric guitar was impressive enough back then, but this southpaw had her own style. Then, when the 20-year-old sang with such soul and clarity, the regional music wildcatter knew he'd found his next strike!
The big bonus was that Barbara Lynn, as became her billing, also wrote her own songs, which was very rare for a female singer of the era. While attending Hebert High in Beaumont, Lynn penned such tunes as "Until Then I Suffer," "Teen Age Blues" and "You're Losing Me," based on her own experiences. She'd come up with the title first, then sit in her room for hours writing lyrics and melodies. One day she told her boyfriend Sylvester, whom she'd caught with a roving eye, that if he didn't watch it, he was going to lose a good thing and a great song just came rolling out.
"You'll Lose a Good Thing" was Barbara Lynn's only Top 40 hit, but it was a big one, knocking Ray Charles out of No. 1 on the R&B charts in 1962 and hitting No. 8 on the pop charts. Simple and bluesy, the tune was a ladies' choice slow dance favorite with an unmistakable New Orleans feel, because that's where it was recorded, at Cosimo's studio in the French Quarter. Lloyd Toups set the song's mood with mournful tenor sax, while piano player Mac "Dr. John" Rebennack pounds a Gulf Coast rhythm.
Follow-up single "Second Fiddle Girl," which hit No. 63, was the closest Lynn would ever get to the Billboard Pop Top 40 again, though 1963 single "You're Gonna Need Me" did reach R&B No. 13. Still, calling Lynn, who turned 73 last month, a "one-hit wonder" cheapens her influence. One hit wonders don't have streets named after them in their hometown, an honor Lynn received three years ago. Every female who ever picked up an electric guitar and fronted a rock or soul band owes a debt to the trailblazer who still lives in the house in Beaumont she had built with her first royalty check ($85,000!). "You'll Lose a Good Thing" (which lists Meaux as a co-writer) was covered by Aretha Franklin in 1964 and 12 years later taken to No. 1 on the country charts by Freddy Fender.
"There weren't really any women playing electric guitar that I knew of coming up," says Lynn, who says she didn't play guitar on her early records because she wanted to concentrate on singing. "But after I saw Elvis Presley on the TV when I was just a kid, I just wanted to play the guitar so bad."
She started off with a $10 right-handed ukulele, which she played upside down, but her factory-worker parents eventually saved up enough money to buy her an electric guitar down at Swicegood Music in Beaumont. "They had to special order a left-handed guitar, so I had to wait," Lynn says. "Longest three months of my life."
Playing mostly covers of Elvis, Chuck Berry and Brenda Lee, Lynn was the queen of the teen talent shows in the Golden Triangle, often performing with some of the other musically gifted kids in the area, including Johnny and Edgar Winters, Jerry LaCroix and Clarence "Gatemouth" Brown. The big man in Beaumont back then was guitarist Clarence "Bon Ton" Garlow, who had a couple of Cajun-flavored, minor R&B hits and played guitar for Clifton Chenier. As Lynn would do 20 years later, Garlow moved to Los Angeles after regional success in the Golden Triangle, but came back to Beaumont. The returning local hero got a part-time job as a DJ on East Texas R&B powerhouse KJET-AM and had an eye of discovering talent.
"Clarence Garlow had a little studio there at the corner of Houston and Washington Boulevard," she recalls, "and he wanted to cut a record on me, but that's around the time I met Huey Meaux." After Lynn signed with Meaux's Starfire label, Garlow and the Crazy Cajun had a falling out, Lynn says.
After Lynn's first single "Dina and Patrina" failed, "You'll Lose a Good Thing" didn't and was quickly picked up by Philadelphia-based Jamie Records. As the bluesy number shot up the charts and led to two appearances on American Bandstand, Lynn's simple life became wonderfully complicated almost overnight.
"Oh, boy, that was something!" Lynn remembers of the time Beaumont topped Billboard. "I went out on tour with all the big acts – Smokey Robinson and the Miracles, Jackie Wilson, Sam Cooke, Gladys Knight, Marvin Gaye. I met Michael Jackson when he was nine years old." Those package shows could get a little crazy out on the road, with gambling, drugs and sex at every stop, so Lynn's mother Mildred Richard quit her job at the box factory to look after her daughter, still a choir member of Our Mother of Mercy Catholic Church. Other musicians learned that you didn't have to watch out for just the authorities, but Mildred, or "Mag," who once interrupted a drug deal and told those boys to "get on away from here" and they did. "My stepdad thought I was too young to go on tour by myself, and he was right," says Lynn.
A true triple threat, singer/guitarist Lynn wrote 10 of the 12 songs on her debut LP You'll Lose a Good Thing, and also penned most of the 1964 follow-up LP Sister of Soul, including "Oh! Baby (We Got a Good Thing Goin'), which the Rolling Stones covered on their 1965 LP Now!
After recording four singles for Meaux's Tribe label, circa 1966, which yielded the minor hit "You Left the Water Running" (later covered by Otis Redding), Lynn signed to Atlantic Records. This was the deal she'd been waiting for. But after 1968's Here Is Barbara Lynn didn't take off, she was dropped from the label.
There were some big things happening in her life away from music at the time- like marrying an Army man from back home while he was on leave from Vietnam- and Lynn didn't make another album for 20 years. Instead, she and her husband moved to Houston, where he got a job as a conductor for the Southern Pacific Railroad and they raised a family. Occasionally, Lynn performed in clubs and released singles for Meaux's R&B label Jetstream that went nowhere, a Jetstream trademark.
In 1975, Lynn and a girl friend went to Las Vegas on vacation and when Barbara hit two jackpots on the slots in two hours, she decided to go on to Los Angeles, while her friend went back to Beaumont. "I wasn't divorced from my husband, but I needed a fresh start in L.A.," she says. Her three kids came out to live with her. "When word got around that I'd moved to L.A., I started getting booked at all the chitlin circuit clubs on the West Coast. I've never worked an 8- 5 job in my life."
Her estranged husband died of emphysema, and Lynn remarried in L.A., But the singer moved back to Beaumont in '85 after her second husband died of a heart attack. "I came home to take care of my mother," says Lynn, but back in Texas, she was tracked down by Port Arthur native Clifford Antone, who gave her an open invitation to play his blues club in Austin whenever she wanted. Lynn told Antone she didn't have a band and he said to just show up with a guitar and he'd take care of the rest. So a 42-year-old Barbara Lynn took a Greyhound bus from Beaumont to Austin and ended up playing one of the most memorable gigs of her life.
"They knew all my songs," she says of both the house band and the singing-along crowd. "That shocked me, but then I found out that Lou Ann (Barton) and Sarah Brown and Marcia Ball and Angela (Strehli) had been doing my songs for years."
Lynn also discovered she had a big following in Japan and was signed to record her first album in 20 years for the Ichiban label in 1988. You Don't Have To Go stayed in the Gulf Coast, with Lynn's cover of Lazy Lester's "Sugar-Coated Love" a standout. She also made it to the soundtrack of John Waters' 1988 film Hairspray, giving legs to "You'll Lose a Good Thing." In the '90s, she released So Good on Bullseye and took to the road to promote it. Club owners loved Lynn, whose sweet and accommodating personality is the opposite of diva.
Some nice royalty checks came in 2002 when Moby used "I'm a Good Woman," which Lynn released on Tribe in 1966, as the foundation of "Another Woman" on the platinum LP 18. The latest career uptick was in 2014, when Light In the Attic reissued This Is Barbara Lynn as a vinyl-only release, introducing her to the turntable-crazed hip crowd. When Lynn played a one-off show at the ND venue in Austin in December, the average age of the audience looked to be about 30-35, and that included all the pot-bellied grayhairs who used to see her an Antone's in the '80s.
She started off the set with a cover of Al Green's "Let's Stay Together," with the guitar in her lap like a Fender Pomeranian, and it seemed like it might be one of those walkthrough performances by an aging legend. But then Lynn and the pick-up band went into "I'd Rather Go Blind," the Etta James song she recorded in 1996 for oldies soul label ITP, and she picked out a lead on the guitar that excited and stung like a goodbye kiss. At age 73, Barbara Lynn has still not lost that good thing.
"Everybody knows her hits like 'You'll Lose a Good Thing' and 'Oh, Baby, We've Got a Good Thing Going,' but until you see her live, you don't realize what an incredible guitar player she is," says Ira Padros, who booked Lynn to play his Ponderosa Stomp in New Orleans for 10 straight years. He recalled a rehearsal at the November 2008 tribute to Les Paul at the Rock and Roll Hall of Fame in Cleveland, where Lynn was playing with Billy Gibbons of ZZ Top. The side of the stage was full of guitar greats, including James Burton, Slash, Duane Eddy and Lonnie Mack, and after Lynn ripped out the notes from her soul on one lead, percussion was provided by slaps on the forehead.
She may be the sweet grandmother of seven, but when she's got a guitar in her hands, Barbara Lynn will always be "The Empress of Gulf Coast Soul."
Barbara Lynn Huey P. Meaux
Luis Lapuente
Love Barbara Lynn!!!
Shelby (Don) Peterson
Since I'm the same age as Barbara Lynn I remember her music from the 60's. It was such a pleasure to re-discover her on line. Although I haven't seen her in person yet I enjoy all her videos & music. Most important I read every article I can find on line. In addition to her talent I'm so pleased to read that Barbara is a really good person. She is such an inspiration.
ROBERT W. BERNSTEIN
Thanks, nice.


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Funky wonderuful. Excellent progression of the band. I look forward to their career with great interest!
I've always loved them and they continue to make quality music, or real music if you prefer. What I don't really like is that they sound ever more like Amy whinehouse and less rockabilly or roots music.


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Where can you find the address book feature on Outlook.com? Your contacts are located in the People app. Emails are easy to find in Outlook.com, and addressing a new message to a known contact is simple as well.
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Sign in at the Office.com portal.
Open the Office Applications Launcher.
A quick way to find a contact you have received mail from or have added to your People contact list is to use the Search box at the top of the People window.
To find a contact, type a name and Outlook retrieves matches from your email and your People contacts. Select the contact and then search further by folder and date to retrieve specific emails from that contact.
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Choose the display order: At the top of the contact list, select the dropdown arrow and choose a display by order. Display names by first name or last name. This doesn't change where the contact appears on the list; that is determined by the sort order.
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THE CHAPEL OF OUR LADY OF CHAMORRO.
The chapel, built in the sixteenth century, is located on the hillside of the same name and from its atrium, 175 meters above sea level with a magnificent panoramic view of the ferrolana region, with the valley of Serantes in the foreground and the background the city of Ferrol. This chapel has a strange and unusual architecture. For example, do not go ahead but on a side, to which was added an overhang to integrate the pedestal with the statue of the Virgin, called Northwest, which seems to be Romanesque twelfth century. Here a busy pilgrimage is celebrated on Easter Monday since 1628, as thanksgiving to the Virgin for her intercession during a heavy storm.
The pilgrimage of A Virxe de Chamorro is one of the most traditional celebrations in recent years. In this pilgrimage to the patron saint of the city, "Nosa Señora de Nordés", also known as the "Virxe do Chamorro" is honored. Easter Monday is performed.
It seems that the name comes from a fisherman who, castaway, invoked the Virgin of Nordés saying "Xa morro" (I die). Of course, it saved his life.
Although this celebration was created in the 50s, the worship of "Nosa lady Nordés" and comes from the Golden Age, since the formation of the Brotherhood in 1666.
It was always the Virgen de Chamorro venerated by fishermen and people of the sea. The sanctuary is at a high in the manor of Serantellos, an old nautical reference point.
This pilgrimage is an ascent of all ferrolanos and pilgrims from around the hillside. Once up the Mass and various religious ceremonies as offerings to the Virgin is celebrated. When the religious side ends, he begins a journey that lasts country during the day. The place is very well conditioned to spend an unforgettable day pilgrimage.

redpajama_set_name: RedPajamaCommonCrawl


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Symp.tom was a Dutch record label that was founded in 2004 as a subdivision of Neophyte Records, meant as an outlet for releasing the divergent material of Mental Wreckage and Mute. Originally it was intended to revive Mid-Town's Darkside label for this purpose, but after giving it some careful thought it seemed better to create a whole new label for better distinction.
Symp.tom's releases were mostly focused towards dark and industrial orientated hardcore techno, while also giving its artists enough freedom to work on experimental projects from time to time. One of the label's peaks was that it was given the opportunity to host its very own "Industrial Hardcore Area" at the 2009 edition of Nightmare Outdoor, featuring a strong and suited line-up of artists. Also worth mentioning were Symp.tom's own editions of the Nightmare Outdoor CD compilations, widening the variety with darker and more underground material. Additionally, the label's 4th compilation, Life Below 20Hz, is considered to be one of the best representations of industrial hardcore techno among fans of the genre.
Main producers of Symp.tom were Mental Wreckage and Mute. (who both were also its founders, label managers & art directors), followed up by The Relic a while later. Throughout the years, the label's roster was accompanied by guest artists like Moleculez, The Outside Agency, Sei2ure, [c.ORP] and Meccano Twins, the latter delivering an excellent remix on Symp.tom 3.
In 2011, Symp.tom came to an sudden and unexpected end when their record company Mid-Town Records went bankrupt and auctioned off their entire label catalogue to Cloud 9 Music BV. Most of Symp.tom's artists decided to move on to Dark Descent, which is run by The Relic. As a tribute to its Symp.tom roots, that label started up a special sub-series of releases called Revisited: Symp.tom in 2017, which so far involved remixes of classic Symp.tom tracks like Lawaai and White Darkness.
SMPT015:
The Relic - The Fallen
Sei2ure - Noise Pollution
Moleculez - Raw Like Sushi
The Outside Agency - Return to the Point of No Return


It'd take a pretty ~smart cookie~ to get them all right.
Pate a Choux is another way of saying choux pastry, which is what eclairs are made from.
It involves piercing the dough, to avoid pie crust puffing up because of steam when you bake it.
The two-stage method is a way of making cakes. It involves adding about three-quarters of the liquid, as well as all the fat, to your dry ingredients and adding in the remaining liquid in stages.
Royal icing uses egg whites.
Muffins, and many other quick breads, can get "tunnelling", which is when big air pockets or tunnels form on the inside.
A savarin is a cake that is soaked in a liqueur-flavoured syrup.
"Cutting in" involves mixing fat, such as butter, with dry ingredients.
It involves heating up chocolate to break down the crystals in it, and then cooling it to improve its consistency and appearance.
Frangipane is an almond filling.
Laminated dough involves rolling and folding layers of dough and fat. An example of a laminated dough would be croissants.


Summer is less than one month away and I'm SO excited!!
Well, the "official" first day of summer, at least.
It's pretty much already summer here in Mississippi because of the heat, and also because I'm finally out of school. But still, it won't feel like summer to me until June 20th.
While we're waiting for the first official day of summer, we can just talk about (and eat, of course!) these tartlets, which are basically summer in pie form.
Before my oldest brother went off to college (he's going to be a junior in the fall), I used to make him this Sugar Cream Pie, from food network, ALL of the time. He loves pies more than the average pie lover, so I was pretty pleased that he liked a pie I made, even if it wasn't my recipe.
Since it's one of his favorite non-fruity pies, I would make it for him every time he came back in town from college on breaks.
Luckily, he goes to college in California or I would've had to make a lot of sugar cream pies in the past two years.
Anyways, after his Christmas break Sugar Cream Pie, he asked me to make a more fruity pie the next time he came.
There's something about a little mini hand pie that just screams "Summer" to me, but these tartlets are a pretty close match.
My brother and I pretty much have the same taste buds. We both like generally healthy food, loads of fruit, A LOT of (black) coffee, and green things, to be vague. So I knew he'd like these guys, especially with the coconut cream!
I've talked about my obsession with coconut milk, but I've been even more obsessed with coconut whipped cream lately. I tried making it a couple of times a while back but it always turned out it gritty and, well... not whipped cream. But finally, I realized you HAVE to chill the mixing bowl and whisk for it to work. I kind of always knew to do that, but I was just too lazy and impatient to. After I finally did, it turned out PERFECT! I've also found that some brands tend to work better than others. My favorite to use is Chaokoh, which does have some preservatives but works the best in my opinion!
Pre-heat oven to 350º F and place a mixing bowl & whisk attachment in the freezer.
Pulse all crust ingredients except for the eggs and the extra 1/4 cup flour together until formed into a ball. Take out of mixer, form a well in the middle of the dough, and knead the beaten eggs, starting from the middle of the well, until combined. Fold in 1/4 cup flour if dough is sticky or wet/too loose to roll out. Form into a ball, coat lightly with more flour, wrap in cling wrap, and refrigerate for 30 minutes to an hour.
Strain frozen blueberries, mashing them lightly to get rid of any juices, reserving the juices for later. Add all filling ingredients, except the fresh blueberries, to the frozen blueberries until combined, and set aside. Roll out 6 equal parts of the dough until round and 1/2 inch thick, on a floured surface. Scoop 3 tbs. mixture into the middle of each pie crust. Fold edges around it and stuff the openings with 2-3 tbs. fresh blueberries depending on amount of room left. Brush edges with olive oil/egg mixture sprinkle with 1/2 tbs. sugar on each tartlet and bake on a parchment lined baking sheet for 40-50 minutes or until golden brown on the edges and crust is hardened for the most part. Let sit on baking sheet for 15-20 minutes or until cool.
While tartlets are baking, whip the congealed and separated coconut cream risen from a can of coconut milk (be careful not to get any coconut water in it) in the chilled mixing bowl and whip until creamy. Add orange juice, zest, and maple syrup and continue to whip until mixed. Chill until ready to serve.
If you saved the blueberry juice, reduce down until thickened to make a blueberry sauce to drizzle over the tops, if wanted.
Top tartlets with whipped coconut cream, orange zest, blueberry sauce (if wanted), and fresh mint.


February 3, 2012—Debut novelist Shella Gillus landed a nomination for an NAACP Image Award in the "Outstanding Literary Work – Debut Author" category for her novel The Loom (Guideposts Books, 2011). Award winners will be announced at the annual NAACP gala held on February 17 in Los Angeles.
The Loom is a nineteenth century historical romance about a light-skinned female slave who disappears only to reemerge as a white woman on a plantation. Lydia knew her life as a slave on a Maryland plantation would end at the loom room—the same place on every plantation where slaves, particularly after years in the tobacco and cotton fields, spent their days weaving and making clothes for their masters' family. Gillus smoothly weaves this original tale, integrating the harsh, revealing truth of this nation's troubled racial past with the broader, universal themes of love and freedom. The Loom is an engaging, well-written page-turner rich with colorful detail and crisp dialogue.


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Management: Marketing Specialist: JOSE M DE CARDENAS CUESTA, Tel.
Sales Chief: IRINA GUZMAN, Tel.
Description: Repairs to tankers, general cargo, ferries, containerships, dredgers, tufs, bulkers, reefers and fishing vessels. Repairings in the following specialties: steel, aluminium, piping, mechanic, machining, electricity, carpentry, painting.


text:
Pharma in brief - Updated guidelines for Ontario formulary drug submission released
Kristin Wall
Global | Publication | September 2016
The Ontario Ministry of Health and Long-Term Care recently updated the Ontario Guidelines for Drug Submission and Evaluation ("Guidelines"). These Guidelines govern drug submissions for inclusion on the Ontario Drug Benefit Formulary or for listing as an interchangeable drug.
Despite various amendments to the regulations under the Ontario Drug Benefit Act and the Drug Interchangeability and Dispensing Fee Act ("Regulations"), this is the first time the Guidelines have been updated since 2000.
The Guidelines provide practical information and guidance to manufacturers making drug submissions to the province of Ontario in order to have drug products listed on the Ontario Drug Benefit Formulary or as interchangeable products under the Drug Interchangeability and Dispensing Fee Act.
The changes
This update to the Guidelines consolidates changes made to the Regulations as well as related changes to submission policy. The Guidelines do not address recent proposed changes to the Regulations intended to streamline generic interchangeability (found here).
The Guidelines can be found at the link below and include an executive summary of these changes.
Highlights of changes to the Regulations since 2000 include:
exemption from the requirement to provide in-vivo bioequivalence studies for dermatological glucocorticoids and certain aqueous solutions;
limiting the price for most interchangeable drug products to 25% of the price of the original product;
a rapid review process for single-source products that can take place prior to receiving a Notice of Compliance from Health Canada if certain criteria are met;
a requirement that manufacturers confirm that no rebates were provided to listed persons and that the product is not a private label product; and
allowing the Executive Officer to consider making an interchangeability designation for products containing the same amounts of the same or similar active ingredients in the same or similar dosage form.
Highlights of changes to submission policy since 2000 include:
streamlined processes in listing single-source products that have been reviewed by the Common Drug Review or the pan-Canadian Oncology Drug Review, and multiple-source products that have received a Declaration of Equivalence from Health Canada;
limitations that have been imposed on the consideration of non-prescription medications and natural health products;
a requirement that manufacturers advise that there are no outstanding patent issues; and
a challenge mechanism for non-streamlined multi-source product submissions.
The Guidelines can be found here: Ontario Guidelines for Drug Submission and Evaluation
kristin.wall@nortonrosefulbright.com


text:
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Home › Glossary of Careers › How to Become a Registered Nurse
How to Become a Registered Nurse
Quality Education & JobsPosted on September 9, 2015 Posted in Glossary of Careers, Medical and Health Professions	— No Comments ↓
Registered Nurse: A Quick Look
Median Salary $65,470 per year or $31.48 per hour
Entry-level Education Associate's degree
On-the-job training None
Primary employers Hospitals, clinics, doctors offices, schools
Number of positions (U.S.) 2,711,500
Job Growth (2012-2022) 19% (Incredibly faster than the national average)
New positions (2012-2022) 526,800
Registered Nurse Job Description:
The registered nurse job description includes giving and coordinating care for their patients. Registered nurses are also referred to as RNs. They may work with patients' family to convey information or they may provide educational training on various diagnoses and health concerns. Registered nurses typically work closely with other nurses, physicians, patients, and their families. RNs typically maintain their patients' records, give medication and other treatments, assist in conducting diagnostic tests, etc. Some registered nurses' job responsibilities vary depending upon the setting in which they work and the area in which they specialize (if they work in a particular setting that deals with one part or system of the body). You can discover more about the typical Registered Nurse job description here.
Registered Nurse Salary:
Data from the BLS indicates that the median value of a register nurse salary is currently $65,470 per year (or $31.48 per hour) as of 2012. The top 10 percent of registered nurses earned more than $94,720, and the lowest 10 percent earned less than $45,040. Registered nurses who work for the government earned the top salaries based on industry at $68,540. The registered nurse salary of RNs who work in a physician's office are the lowest at $58,420. Learn more about the registered nurse salary here.
How to Become a Registered Nurse:
At this point you might wonder How to Become a Registered Nurse. To become a registered nurse, you must typically pursue one of 3 educational routes. You can pursue a certificate in nursing from an accredited program, you can pursue an associate's degree in nursing (ADN), or a bachelor's degree in nursing (BSN). If you're interested, you can learn about How to Become a registered nurse here.
FIND LOCAL & ONLINE REGISTERED NURSE SCHOOLS
Registered Nurse Job Outlook:
As per BLS data, the Registered Nurse job outlook is projected to grow by about 19% between the years 2012 through 2022. That rate of growth is quite fast. The rate of growth for the registered nurse profession will grow more quickly than the average of all other professions. The following guide will tell you all about the registered nurse job outlook. Read more here.
Become a Nurse
The latest data calculated at a national level by the BLS, shows that the median registered nurse salary is $31.48 per hour per hour for a total annual salary of $65,470 per year. The median salary shouldn't be confused with an average of all salary earnings in an occupation. This median value reflects the exact 'middle' of all the salaries in the field; half of all registered nurses earn a little less than the median, and the other half of them earn more than this figure. Registered nurses tend to have opportunities for salary increases. If a nurse goes on for more education and becomes a nurse practitioner, he or she can expect to earn an even higher salary. The average Registered Nurse salaries for job postings nationwide are approximately 7% higher than average salaries for all job postings throughout the United States. Here are the higher vs. lower pay brackets for the salary of a registered nurse:
The lowest 10 percent of registered nurses earned less than $45,040
The top 10 percent of registered nurses earned more than $94,720
The registered nurse salary may vary due to the following influencing factors: the amount of previous work experience, education level, the industry which employs them, and the geographical location in which they are employed.
The highest-paid registered nurse positions are in California. Specifically, they are in the metropolitan areas of San Francisco, Vallejo, and San Jose.
Registered nurses who work in San Francisco typically earn $127,670 annually, registered nurses who work in San Jose, California tend to earn approximately $123,190 annually. For registered nurses working in Oakland, California, the average annual salary is $121,040, and registered nurses who work in Vallejo, California typically earn $121,670 annually.
As of October of 2014, Clinical Nurse Managers earned an average of $69,000, RN First Assistants typically earned an average of $65,000, and Cardiovascular Operating Room Nurses earned an average of $64,000. Other professionals in this field typically earned somewhere between $57,000 and $66,000.
The industry which employs the registered nurses influences salary. Registered nurses who work for the government typically earn an average annual salary of $68,540, Registered nurses who work for state, local, and private hospitals typically earn an average annual salary of $67,210, registered nurses who work for home health care services typically earn an average annual salary of $62,090, RNs who work in nursing and residential care facilities typically earn an annual salary of $58,830, and RNs who work in physicians' offices typically earn an annual salary of $58,420
Registered nurses who have a bachelor of science in nursing can expect to earn more money than registered nurses with an associate's degree or a certificate in nursing. RNs with higher levels of education are qualified for supervisory or leadership positions that are also higher paying. Also, seasoned nurses tend to earn higher salaries than newer nurses due to opportunities for promotions and raises. Registered nurses can also choose to go back to school to obtain a master's degree in nursing or a nursing doctorate. Both of these levels of higher education typically yield higher nursing salaries.
Do you want to learn how to become a registered nurse? Of course you do. That's probably why you're reading this guide. To become a registered nurse, you must typically pursue one of 3 educational routes. You can pursue a certificate in nursing from an accredited program, you can pursue an associate's degree in nursing (ADN), or a bachelor's degree in nursing (BSN). Regardless out the educational route taken to become a registered nurse, all nursing students take core classes on human anatomy and physiology, biology, chemistry, nutrition, social sciences, and psychology. Additional classes may be required for nursing students pursuing a bachelor's degree. Bachelor of Science in Nursing programs are typically completed in 4 years, whereas the associate's degree in nursing and certificate programs can typically be completed within 2 to 3 years. Nursing students must also complete clinical rotation experiences as part of their educational experience. These clinical rotations may be in psychiatry, pediatrics, intensive care, medical/surgical, labor and delivery, oncology, and geriatrics. A bachelor's degree is typically necessary (or beneficial) if a nurse wants to teach, conduct research, or advance to an administrative or leadership position. Nurses must be licensed by the state in which they are employed. In order to become licensed, nurses must graduate from an accredited nursing program and pass a licensing exam. Additional requirements for nurses vary from state to state. Certification in specialized areas is an option for registered nurses.
The registered nurse job description will vary based on the setting in which the nurse works, the patient group the nurse works with, and the level of experience the nurse has. For example, a neonatal nurse will complete tasks related to the care of babies, whereas a cardiac nurse will complete tasks related to the care of patients who have heart conditions. Some basic tasks will be required in both nursing positions (such as taking a pulse and blood pressure, completing physical examinations), but other more specific tasks will vary. Registered nurses can choose to specialize in a specific area such as oncology, dermatology, psychiatry, pediatrics, labor and delivery, gerontology, neonatology, nephrology, cardiology, etc. Nurses work under the direction of physicians, but they also work collaboratively with them and other health care professionals. Registered nurses may oversee other nurses such as licensed practical nurses (LPNs) or nursing assistants (NAs). Nurses can work in a variety of settings including hospitals, doctors offices, schools, skilled nursing facilities, correctional facilities, or for the government or the military. Common tasks completed by registered nurses include:
Give patients medications and other medical treatments
Monitor and observe their patients and take note of any changes in condition
Document symptoms, vital signs, medical histories, and other pertinent information
Complete or modify plans of care for patients
Assist with diagnostic tests and analysis of test results
Work collaboratively with physicians and other nurses
Operate various types of medical equipment
Educate patients about their illness or disease and teach care management
Educate families on how to complete necessary continual care at home
Some key qualities of a registered nurse include: being a critical quick thinker, ability to pay close attention to small details, being physically fit and have some degree of physical stamina as nurses are often on their feet, possess strong communication skills, good organizational skills, ability to cope with stress and trauma, and natural concern about others well being.
The Registered Nurse job outlook is projected to grow by about 19% between the years 2012 through 2022. The demand for nurses will continue to grow as the population changes and ages. As the baby boomer generation ages, their need for healthcare services will increase. Also, more individuals and families will likely seek medical services since the Affordable Healthcare Act passed. There will also continue to be a demand for nurses due to the focus on preventative care. Also, as chronic disease rates increase in the U.S., so will the demand for registered nurses to care for the diseases. It is anticipated that there will be various job opportunities for registered nurses seeking employment. Registered nurses who have higher levels of education (such as the Bachelor of Science in nursing) will have the best job prospects. Also, employers may prefer to hire registered nurses who have previous work experience. As nurses retire, positions will open up for younger nurses to fill. *All numeric data in this post has been provided by courtesy of the BLS (the government's Bureau of Labor Statistics), unless explicitly otherwise mentioned. The data has been calculated last in May 2014.
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Bahmni is an Open Source product, which you can download freely and use at your clinic, hospital, institute. However, if you don't have the required technical expertise or need help with certain aspects of implementation then Bahmni Implementation partners are best placed to provide you that help.
This is a global network of implementation partners who are committed to Bahmni development and implementation. They are critical to delivering local support and building new functionality that is tailored to your needs. Implementation partners offer services based on your needs like EMR / HIS consultancy, Configuration and Customizations, End user Training, IT team training, Production support and troubleshooting etc.
If you're looking for a Partner, send us your request.
IntelliSOFT Consulting is a Kenyan software development, implementation and consultancy firm that specializes in developing and implementing digital health solutions for the health care sector. Our primary focus is in digital health solutions that support delivery of healthcare services and health research. The company's overall goal is advancing the smart and meaningful use of Information and Communication Technology to support the discovery and delivery of quality healthcare services.
organisation focused on health care technologies. We have extensive experience in Bahmni implementation and OpenERP / Odoo customization.
We work across spectrum of healthcare providers from Doctors & Clinicians at hospitals to Village Health Workers / ASHAs & Community Clinics. We also help Government and NGO sector in their data collection initiatives which aid towards policy formulation and research.
Finding low cost, high quality and 'fit for purpose' solutions with tools and technologies in Open Source, is at the heart of our approach.
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text:
\section{Introduction}
The interaction of light with different types of orderings in condensed matter
systems is in the focus of current research in the field of
optoelectronics~\cite{refKirilyuk,refKimel,refFausti2011light,refSuda743,refVeshchunov2016optical}.
The  light controlled manipulation of magnetic and/or superconducting states
provides a perspective way to construct new fast operating switching
devices~\cite{refKirilyuk,refKimel} and
serves a basis for different experimental methods probing and characterizing
the order parameter structure and dynamics~\cite{refAltshuler,
refMatsunaga1145}.
In particular, remarkable progress has been recently achieved in the design of sensitive superconducting bolometers
and photon detectors \cite{refSemenov2001349,refGoltsman}. Fundamental issues of the order parameter dynamics have been investigated probing the Higgs mode
in the superconducting state \cite{refAltshuler,refMatsunaga1145}.

The simplest physical picture describing the effect of the light pulse on superconductor can be constructed starting
 from a so called ``hot spot'' model~\cite{refSemenov2001349,refMaingault,refZotovaPRB}. Within this approach one can assume the energy of the laser pulse to be transferred to the electronic subsystem
which results in further formation of the locally heated state with an increased electronic temperature. This increase in the local temperature
is responsible for the partial or complete suppression of the superconducting
order parameter in the region of the hot spot. The state with the
inhomogeneous temperature is unstable due to the heat diffusion and at the
next stage the hot spot disappears and  the order parameter relaxes to its
initial value before the light pulse absorption. The exact
picture depends of course on the electron-electron and electron-phonon relaxation rates
which are responsible for different stages of the evolution of the
nonequilibrium electronic distribution. Provided the relaxation stage is
rather short and can be considered as a rapid thermal quench the thermodynamic
order parameter fluctuations can complicate the return to the initial state
giving rise to the formation of the vortex - antivortex pairs according to the
Kibble-Zurek scenario~\cite{refKibble,refZurek,refVolovikKZ, refManivPolturak}.

Should we expect any essential changes in the above model if the superconducting order parameter
is not just a single
complex function but may have several components or possess a nontrivial anisotropy in the momentum space? In other words, does the study of the superconductor dynamics excited by the light pulse allows to distinguish the states with different internal structure of the Cooper pairs?
The goal of the present paper is to develop a theoretical basis for the use of the laser beam as a probe of such unconventional superconducting states,
more specifically the states with a nonzero internal average angular momentum
of the Cooper pairs $\mathbf{L}$\footnote{The projections of the angular momentum are bad
quantum numbers in the crystals due to the lack of continuous rotational
symmetry. The true structure of the gap is described by the basis functions of
some irreducible representation of the crystal symmetry group which
corresponds to the certain superconducting state. Still these
functions can be classified by the average value of the angular momentum.}. It is instructive to start our discussion
 of the appropriate generalization of the hot spot model from a qualitative
 analysis of inhomogeneous states for $\mathbf{L}\neq 0$.   The angular
 momentum of the relative motion of two electrons in the pair naturally
 interacts with the angular momentum of the motion of the pair center of mass.
 For any inhomogeneity of the superconducting state this interaction of the
 angular momenta can induce the supercurrents and corresponding magnetic
 field.
 Naively, one can expect these supercurrents to be proportional to the
 effective magnetization currents of the Cooper pairs: $\propto \mathop{\mathrm{curl}} \mathbf{L}$.
 However the orbital angular momentum of the sample bulk appears to be
 significantly
 reduced compared to expected $N\hbar / 2$ value where $N$ is the total amount
 of electrons in a volume. The orbital momentum of the
 bulk is determined by the contribution of the Cooper pairs which are smaller
 than the inter--pair distance so the momentum is reduced by factor $(T_c/
 E_F)^2$~\cite{refVolovik1981orbital}. A more precise analysis gives additional
 logarithmic factor and final expression has a form $L_z \propto \hbar N (T_c
 / E_F)^2 \ln (E_F /
 T_c)$~\cite{refVolovik1975angular,refCross1975generalized}.
 A noticeable contribution
to the supercurrent is provided by another mechanism, namely by the mixture of several order parameter components generated by the order parameter inhomogeneity. Such mixture originates from the obvious fact that the projection of the internal angular momentum can not conserve in the presence of the
inhomogeneity. Previously, the search of the corresponding spontaneous
currents was mainly related to the edge of the samples. Unfortunately, near
the edge the order parameter inhomogeneity and, thus, the generation of the
additional order parameter components and the resulting supercurrents
strongly depend on the details of the electron scattering at the surface, i.e.
on the surface quality~\cite{refSauls,refLederer,refHuang2,refBakurskiy}. As a consequence, the edge currents can be strongly
diminished and surface imperfections may cause the difficulties in their
experimental observation in $\mathrm{Sr_2RuO_4}$~\cite{refKirtley} which is considered to be
a most promising candidate for a superconductor with the chiral $p$-wave order
parameter~\cite{refKallin}. {
    The other explanations of the edge currents absence focus on possibility
    of chiral non $p$-wave pairing type in
    $\mathrm{Sr_2RuO_4}$~\cite{refScaffidi} for which the macroscopic orbital
    momentum vanishes in the finite size
    samples~\cite{refHuang,refTada,refVolovikChiral}. Also the properties of
    the edge currents appear to depend on the band structure of
    $\mathrm{Sr_2RuO_4}$~\cite{refBouhon,refImai}.
}

From this point of view the order parameter inhomogeneity created by the laser
beam far from the sample edge of uncontrolled quality provides much better
conditions for the study of the above supercurrents. The current circulating
around the hot spot (see Fig.~\ref{figSetup}) should be easily detected by any
experimental techniques sensitive to small local magnetic field such as SQUID
microscope or sensitive Hall sensor.
The generation of the magnetic field in the
inhomogeneously heated samples is common for the systems with the broken time
reversal symmetry. For example the magnetic field appears in the hot spots in
multiband $s+is$ and $s+id$ superconductors~\cite{refSilaevBTRS}.
The generation of the secondary order parameter components can be even more
pronounced at the late stage of the hot spot evolution. Indeed, provided the
spot dimension exceeds the coherence length one can expect that the rather
fast quench to the initial temperature can be accompanied by nucleation of
different order parameter components forming, thus, a domain structure in
addition to the well-known vortex-antivortex configurations induced by the
Kibble--Zurek mechanism.

For the further quantitative analysis of the above phenomena we choose a
rather general two-component Ginzburg--Landau model introduced previously in a
number of works~\cite{refHeeb,BarashMelnikovZhETFEn} for the description of
properties of  the $\mathrm{Sr_2RuO_4}$ compound~\cite{refHeeb,VadimovSilaevPhysRevLett111p177001}.
\begin{figure}
    \includegraphics{figure1.pdf}
    \label{figSetup}
    \caption{(Color online) The proposed experimental setup. The laser beam
    heats the sample inducing the supercurrents flowing around the hot spot.
    The magnetic field created by these currents can be observed by the SQUID
    microscope or the Hall sensor.}
\end{figure}

In the Section II we introduce Ginzburg--Landau free energy and the main
equations describing the superconducting state. For the case of a smooth order
parameter profile in the hot spot these equations are solved in the Section
III. The final expression for the magnetic field is
obtained for the Gaussian profile of temperature. The Section IV is devoted to
 superconductor dynamics in the thermal quench mode and study of
the chiral domain generation according to the Kibble--Zurek mechanism. The
stability of the domains and their interaction with the vortices is discussed
in the Section V. In the final Section VI we sum up the results of this paper.

\section{Model}

The superconducting order parameter has two components $(\Psi_+, \Psi_-)$
which stand for the Cooper pairs with opposite direction of internal orbital
momentum. The free energy of the superconductor is given by the following
expression\cite{refHeeb}:
\begin{multline}
    F =  \int \left\{-a \left(|\Psi_+|^2 + |\Psi_-|^2\right) + \frac{b_1}{2}\left(|\Psi_+|^2 +
    |\Psi_-|^2\right)^2 + \right. \\ b_2 \left|\Psi_+ \Psi_-\right|^2 + \\
    K_1 \left(|D_+ \Psi_+|^2 + |D_- \Psi_+|^2 + |D_+ \Psi_-|^2 + |D_-
    \Psi_-|^2\right) + \\
    K_2 | D_+ \Psi_- + D_- \Psi_+|^2 + \\ K_3 \left [ |D_+ \Psi_+|^2 + |D_-
    \Psi_-|^2 + (D_+ \Psi_-)^\ast (D_- \Psi_+) + c.c. \right] +\\
    \left.\frac{\left(\mathop{\mathrm{curl}} \mathbf A\right)^2}{8\pi}\right\}\;d^3 r\ ,
\end{multline}
where $\mathbf A$ is
the vector potential of the magnetic field, $\mathbf D = -i \nabla - 2 \pi /
\Phi_0 \mathbf A$ is the covariant derivative, $D_\pm = (D_x \pm i D_y) / \sqrt{2}$, $\Phi_0$ is the superconducting
flux quantum, $a$, $b_1$, $b_2$, $K_1$, $K_2$ and $K_3$ are the
phenomenological parameters. The coefficient $a$ depends on the temperature as
follows $a = \alpha (T_c - T)$. For simplicity we omitted the terms lowering
the symmetry of the free energy to $D_{4h}$
symmetry, restricting ourselves to the case of $D_{6h}$ crystal.Also we
assume that the spatial variations of the order parameter are only in $xy$
plane and neglect the variations along $z$-axis. If $b_2 > 0$ the equilibrium homogeneous states have form of chiral
domains $(\Psi_+,
\Psi_-) = (\sqrt{a / b_1}, 0)$ and $(\Psi_+, \Psi_-) = (0, \sqrt{a / b_1})$.

The laser pulse is absorbed by the electron subsystem of the superconductor
inducing, thus, non-equilibrium distribution of the quasiparticles in the
sample. In general case this distribution does not correspond to any
temperature though if we suppose that the electron--electron scattering
is the fastest process in the system the distribution of the quasiparticles
rapidly thermalizes. Then one can introduce an inhomogeneous temperature
$T(\mathbf r)$ and the parameter $a$ also becomes a function of the
coordinates $a = \alpha(T_c - T(\mathbf r))$. We suppose inhomogeneity to have a form of
a hot spot and the temperature to be
constant far from it, i.e. $a(\mathbf r) \to a_0 = \alpha (T_c - T_0)$ at $r
\to \infty$, where $T_0$ is the bath temperature.
Introducing the dimensionless order parameter components $\eta_\pm = \Psi_\pm
\sqrt{b_1 / a_0}$ we rewrite the free energy:
\begin{multline}
    \label{eq_gl_dimensionless}
    F = \frac{H_{cm}^2}{4\pi}\int \left\{-\tau(|\eta_+|^2 + |\eta_-|^2) + \frac{1}{2}
    \left(|\eta_+|^2 + |\eta_-|^2\right) + \right. \\ \beta |\eta_+ \eta_-|^2 +
    \xi^2 \left(|\mathbf D \eta_+|^2 + |\mathbf D \eta_-|^2\right) + \\ 2 \xi^2
    \zeta \left[ (D_+ \eta_-)^\ast (D_- \eta_+) + c.c.\right] +\\ \left.
        \frac{\left(\mathop{\mathrm{curl}} \mathbf A\right)^2}{2 H_{cm}^2} \right\}\;d^3 r\ ,
\end{multline}
where $H_{cm}= \sqrt{4\pi a_0^2 / b_1}$ is the thermodynamical critical field,
$\xi = \sqrt{(K_1 + K_2) b_1} / a_0$ is the coherence length, $\tau(\mathbf r)
= a(\mathbf r) / a_0$ and $\zeta = K_2 /
(K_1 + K_2)$ and $\beta = b_2 a_0^2 / b_1^2$. Here we assume that $K_2 -
K_3$ is negligible due to the small electron--hole
asymmetry\cite{refBalatksiMineev}.

One can obtain the Ginzburg--Landau equations for the order parameter
components:
\begin{multline}
    \xi^2\left(\mathbf D^2 \eta_+ + 2 \zeta D_+^2 \eta_-\right) - \tau \eta_+ +
    \eta_+ |\eta_+|^2 + \\ (1 + \beta) | \eta_-|^2 \eta_+ = 0 \ ,
\end{multline}
\begin{multline}
    \xi^2\left(\mathbf D^2 \eta_- + 2 \zeta D_-^2 \eta_+\right) - \tau \eta_- +
    \eta_- |\eta_-|^2 + \\ (1 + \beta) | \eta_+|^2 \eta_- = 0 \ .
\end{multline}
Varying the free energy functional over the vector potential $\mathbf A$ one
can obtain the expression for the
superconducting current:
\begin{multline}
    \label{eq_current}
    \mathbf j_s = -\frac{c \Phi_0}{16 \pi^2 \lambda^2} \left\{
        \eta_+^\ast (\mathbf D \eta_+)
        +
        \eta_-^\ast (\mathbf D \eta_-) + \phantom{\sqrt{2}}\right. \\
        \left.
        \zeta \sqrt{2} (\hat{\mathbf x}+ i \hat{\mathbf y}) \left[\eta_- (D_-
        \eta_+)^\ast + \eta_+^\ast (D_+ \eta_-)\right] + c.c.
        \right\} \ ,
\end{multline}
where $\lambda = \Phi_0  / [4 \sqrt{2\pi^3 (K_1 + K_2)}]$ is the London penetration length.
The first terms proportional to $\eta_+^\ast(\mathbf D \eta_+)$ and
$\eta_-^\ast(\mathbf D \eta_-)$ are common
for the Ginzburg--Landau theory of conventional superconductors.
The rest two terms  contain not only the contributions proportional to the
superfluid velocities of the different order parameter components but also a
non-zero contribution caused by the inhomogeneity of the magnitudes of the
order parameter components.
Below we show that the suppression of one of the order
parameter components can generate another component and the corresponding
superconducting current.

\section{Weak heating. Adiabatic approximation}

We choose for definiteness a chiral domain with $\eta_+ = 1$ and $\eta_- = 0$
and consider a hot spot located far from the domain boundaries.
To elucidate our main results we start from a simplified ``adiabatic'' model
assuming
that the temperature varies slowly at the length scale $\xi$, i.e.
$|\nabla \tau| \ll \tau / \xi$.
Under these assumptions
the dominating order parameter component $\eta_+$ ``follows'' the local temperature and
the other order parameter component $\eta_-$ can be found as a perturbation:
\begin{gather}
    \eta_+ \approx \sqrt{\tau} e^{i\phi} \ ,\\
    \eta_- \approx -\frac{2 \zeta \xi^2 D_-^2 \eta_+}{\beta \tau} \ ,
\end{gather}
where $\phi$ is the unknown phase. Also we assume that the
sample is a thin film with the thinkness $d$ much smaller than the London
penetration length $\lambda$. This simplification allows us to neglect the vector
potential and the screening effects. For simplicity we assume
that the temperature distribution is
axi-symmetric $\tau(\mathbf r) = \tau(r)$. Then we can omit the phase $\phi$
and find the order parameter components in the following form:
\begin{gather}
    \eta_+(r) = \sqrt{\tau} = f_+(r)\\
    \eta_-(r, \varphi) = \frac{\zeta \xi^2}{\beta \tau}
    \left(\frac{\partial^2 \eta_+}{\partial r^2} - \frac{1}{r} \frac{\partial
    \eta_+}{\partial r}\right) e^{-2 i\varphi}  = f_-(r) e^{-2i \varphi}\ ,
\end{gather}
where $r$ and $\varphi$ are the polar coordinates. Now we can substitute the
order parameter components into the expression~(\ref{eq_current}) obtain the following
expression for superconducting current, neglecting the terms of order
$\eta_-^\ast
\nabla \eta_-$:
\begin{equation}
    j_\varphi \approx -\frac{c \Phi_0 \zeta}{8 \pi^2 \lambda^2} \left(f_+
    \frac{\partial f_-}{\partial r} - f_- \frac{\partial f_+}{\partial r} +
    \frac{2}{r} f_+ f_-\right) \ .
\end{equation}
The current has only the azimuthal component. This current creates the magnetic
field which can be measured experimentally. The value of the field in the
center of the spot can be found as follows:
\begin{equation}
    \label{eq_field_adiabatic}
    B_z = -\frac{\Phi_0 \zeta}{4\pi
    \lambda_{\mathit{eff}}}\int\limits_0^\infty\frac{dr}{r} \left(f_+
    \frac{\partial f_-}{\partial r} - f_- \frac{\partial f_+}{\partial r} +
    \frac{2}{r} f_+ f_-\right) \ ,
\end{equation}
where $\lambda_{\mathit{eff}} = \lambda^2 / d$ is the effective penetration
length. The magnetic field far from the defect has a dipole form with the magnetic
moment equal to:
\begin{equation}
    m = -\frac{\Phi_0 \zeta}{8\pi
    \lambda_{\mathit{eff}}}\int\limits_0^\infty r^2 \left(f_+
    \frac{\partial f_-}{\partial r} - f_- \frac{\partial f_+}{\partial r} +
    \frac{2}{r} f_+ f_-\right) \; dr\ .
\end{equation}

The above approach, indeed, can be applied only if the temperature varies slowly
and is always below the critical one. Otherwise one should solve the
Ginzburg--Landau equations numerically.

\subsection{Gaussian beam}

The evolution of the local temperature is a complicated process which is governed by the heat diffusion, electron--phonon
interaction and nonequilibrium phonons escape to the
substrate~\cite{refGulyan1985electron}.
The diffusion can be neglected if all other characteristic times like time of
the electron--phonon interaction and phonon escape time are much less than the
characteristic diffusion time which depends on the beam size. With the
diffusion omitted the local temperature appears to be a function of
the local absorbed power which can be linearized in the vicinity of the bath
temperature $T_0$ for the weak heating.

Assuming a Gaussian profile of the laser beam we have the
following temperature profile:
\begin{equation}
    T(\mathbf r) = T_0 + \frac{\kappa P}{2\pi \sigma^2}
    \exp\left(-\frac{r^2}{2 \sigma^2}\right) \ ,
\end{equation}
where $\kappa$ is the proportionality coefficient between the local power and
the temperature. One can introduce the dimensionless power $\tau_0 = \kappa P
/ [\pi \xi^2 (T_c - T_0)]$ and obtain the following expression for the order
parameter components, magnetic field in the spot and the magnetic moment for a slightly
heated spot $(T - T_0) \ll (T_c - T_0)$:
\begin{gather}
    \eta_+ \approx 1 - \frac{\tau_0 \xi^2}{2 \sigma^2} e^{-r^2 / 2\sigma^2}
    - \frac{\tau_0^2 \xi^4}{8 \sigma^4}
    e^{-r^2 / \sigma^2}\ , \\

    \eta_- \approx -\frac{\zeta}{\beta}\left[\frac{\tau_0 \xi^4
    r^2}{2\sigma^6} e^{-r^2/2\sigma^2} + \frac{\tau_0^2 \xi^6 r^2}{\sigma^8}
e^{-r^2/\sigma^2}\right]\\

    B_z \approx \frac{\Phi_0}{4 \pi \lambda_{\mathit{eff}} \xi} \cdot
    \frac{7 \zeta^2 \tau_0 \sqrt{\pi}}{8 \beta}
    \left(\frac{\xi}{\sigma}\right)^5 \ , \\

    m \approx \frac{\Phi_0 \xi^2}{8\pi \lambda_{\mathit{eff}}} \cdot
    \frac{\zeta^2 \tau_0^2}{2 \beta} \left(\frac{\xi}{\sigma}\right)^4 \ .

\end{gather}
The magnetic
field and the magnetic moment reveal power-law dependence on the beam size
$B_z \propto
\sigma^{-5}$, $m \propto \sigma^{-4}$ and intensity $B_z \propto P$, $m
\propto P^2$.
\begin{figure*}[t]
    \centering
    \subfigure[]{
        \includegraphics[width=0.47\textwidth]{field-vs-size-2.pdf}
    }
    \subfigure[]{
        \includegraphics[width=0.47\textwidth]{field-vs-power-2.pdf}
    }
    \subfigure[]{
        \includegraphics[width=0.47\textwidth]{moment-vs-size.pdf}
    }
    \subfigure[]{
        \includegraphics[width=0.47\textwidth]{moment-vs-power.pdf}
    }

    \caption{(Color online) The magnetic field in the center of the spot (a), (b) and the magnetic
    moment (c), (d) vs the beam size (a), (c) and intensity (b), (d). The
    solid line correspond to the solutions obtained numerically. The
    results of the adiabatic approximation for the weak field are represented
    by the dashed lines. The parameters of the Ginzburg--Landau functional are
    $\beta = 1$ and $\zeta = 0.5$, no screening is considered.}
    \label{figRes}
\end{figure*}

The magnetic field in the center of the spot and the
magnetic moment of the currents versus the beam parameters $\sigma$ and $\tau_0$
are shown on the Fig.~\ref{figRes}. The adiabatic approximation works
reasonably for the slow temperature variations and fails if the local
temperature is close to the critical one.

The dependence of the magnetic field in the
center of the spot on the beam size $\sigma$ and the dimensionless power
$\tau_0$ calculated for the Gaussian spot within the adiabatic approach~(\ref{eq_field_adiabatic})
and numerically. The adiabatic approximation is reasonable for the slow
temperature variations and fails if the local temperature is close to the
critical temperature.

The maximal value of the field is reached when temperature in the center of
the spot is close to the critical one. The field is given in the units of $H_0
= \Phi_0 / (4\pi \lambda_{\mathit{eff}} \xi) = H_{cm} / \sqrt{2} \cdot d /
\lambda$ on the Fig.~\ref{figRes}(a) and (b). The plot shows that the maximal
field achieved for the small spots is between $10^{-2} \cdot H_0$ and $10^{-3}
\cdot H_0$.
At the border of applicability range we suppose that the thickness of the
film is $d = \lambda$ and consider low temperature parameters $\xi =
66$~nm and $\lambda = 152$~nm. These assumptions give us an estimate of
observable field up to $1.5$~G. In fact this value may be too optimistic due
to the Meissner screening which comes into play for the thick enough samples.

{The similar generation of the magnetic field in the hot spots may also occur in the other
superconductors with the broken time reversal symmetry like $s+id$
superconductors~\cite{refSilaevBTRS}. However the patterns of the magnetic
field in
the $s+id$ and the chiral $p$-wave superconductors
 appear to be qualitatively different due to the different symmetry of the
 superconducting states. Assuming an axially symmetric
 temperature distribution we find that the supercurrent and, thus, the magnetic
 field also has the axial symmetry. We neglected the terms in the
 free energy which reduce the symmetry of the superconductor to $D_{4h}$ so
 the pattern of the magnetic field is expected to have tetragonal distortions. This
 still qualitatively differs from the case of $s+id$ superconductor in which the
 pattern of the magnetic field has a pronounced two-fold
 symmetry~\cite{refSilaevBTRS}. Thus, these types of pairing may be
 distinguished using the spatially resolved magnetic field measurements.}

 {Another fingerprint of the chiral superconductivity is a nonzero magnetic
moment of the thermally induced currents in the superconducting films.
The key difference between the $s+id$ and $p_x+ip_y$ states is that the latter
is characterized by an internal vorticity in the momentum space directed along
the $z$ axis. Thus, in contrast to the $s+id$-wave superconductors the total
magnetic moment of the induced currents (integrated over the sample) can be
nonzero for a hot spot in a p-wave superconductor and the magnetic moment
direction should depend on the internal vorticity
 which is proved by the above direct
calculations. So magnetic moment measurements provide another possibility of
provide of the chiral $p$-wave superconductivity.}

\section{Strong heating. Domain generation}
In the case of the strong heating the temperature within the spot may exceed the
critical temperature of the superconductor. This results in the significant
suppression of the order parameter components. In this case one cannot apply the above
perturbation approach directly
however the qualitative picture is similar: there is a supercurrent flowing
around the normal spot which creates magnetic field.
However for a pulsed heat up the
relaxation of temperature can cause the formation of the chiral domains
 according to the Kibble--Zurek mechanism
\cite{refKibble,refZurek,VadimovSilaevPhysRevLett111p177001}. The domain walls
carry superconducting current\cite{refMatsumoto} which can be detected by
the techniques sensitive to the magnetic field. The same mechanism is responsible for creation of
vortex--antivortex pairs in non-equilibrium transitions in $s$-wave
superconductors~\cite{refManivPolturak} which can be identified by the specific magnetic field
pattern. In the case of chiral $p$-wave superconductors the pattern
of the magnetic field appears to reveal a number of specific features which
can be used to distinguish this type of pairing.

We are using the approximation of the local temperature assuming now that it
can depend on time. We start from the strongly non-homogeneous temperature
distribution
which gradually relaxes to the equilibrium value $T = T_0$. We studied the
growth of the chiral domains numerically within the time-dependent Ginzburg--Landau approach:
\begin{multline}
    -t_{\mathit{GL}} \left(\frac{\partial}{\partial t} + \frac{2\pi i c}{\Phi_0}
    \varphi\right) \eta_+ = \chi_+ (\mathbf r, t) - \tau(\mathbf r, t) \eta_+
    + \\ \eta_+
    |\eta_+|^2 + \eta_+ |\eta_-|^2 ( 1 + \beta) + \xi^2\left( \mathbf D^2 \eta_+ +
    2 \zeta D_+^2 \eta_-\right) \ ,\\
\end{multline}
\begin{multline}
    -t_{\mathit{GL}} \left(\frac{\partial}{\partial t} + \frac{2\pi i c}{\Phi_0}
    \varphi\right) \eta_- = \chi_- (\mathbf r, t) - \tau(\mathbf r, t) \eta_-
    + \\ \eta_-
    |\eta_-|^2 + \eta_- |\eta_+|^2 ( 1 + \beta) + \xi^2\left( \mathbf D^2 \eta_- +
    2 \zeta D_-^2 \eta_+\right) \ ,\\
\end{multline}
\begin{gather}
    \sigma_n \nabla^2 \varphi + {c} \div \frac{\delta F}{\delta
    \mathbf A} = 0 \ ,\\
    \frac{\sigma_n}{c} \frac{\partial \mathbf A}{\partial t} + \frac{c}{4\pi}\mathop{\mathrm{curl}}
    \mathop{\mathrm{curl}} \mathbf A + \sigma_n \nabla \varphi + c \frac{\delta
    F}{\delta \mathbf A} = 0 \ .
\end{gather}
The Coulomb gauge $\div \mathbf A = 0$ is considered, $\sigma_n$ is the
normal state conductivity, $t_{GL} = \Gamma / a_0$ is the order parameter
relaxation time and $\Gamma$ is a temperature independent constant.
The functions $\chi_\pm$ are
the delta--correlated noise sources $\langle \chi_\alpha(\mathbf r,  t)
\chi_\beta(\mathbf r',  t')\rangle = \chi^2 \delta_{\alpha_\beta} \delta(\mathbf r -
\mathbf r') \delta(t - t')$. Here we assume the thickness of the
superconducting film to exceed the penetration length $\lambda$ but to be
small
enough so that the sample could be heated homogeneously in $z$ direction. These simplifications allow us to consider 2D Meissner screening instead of solving the
full 3D problem.
The heat equation was not taken
into account selfconsistently. Instead the explicit model spatial and temporal profile of
temperature was specified $\tau = 1 - \frac{\tau_0 \xi^2}{\sigma^2}
\exp\left( -r^2 / [2 \sigma^2] - t / t_{\mathit{T}}\right)$, where
 $t_{\mathit{T}}$ is the
temperature relaxation time which is determined, e.g., by the heat flow into the
substrate.

If the temperature quench is adiabatically slow ($t_{T} \ggg t_{GL}$)
then the order parameter adiabatically follows the quasiequilibrium solution which is
slightly disturbed by the thermal fluctuations. In this case the homogeneous
domain appears after the quench is over.
However if the temperature quench has the similar rate as the
order parameter relaxation rate ($t_{T} \sim t_{GL}$) then the state of the
superconductor is essentially non-equilibrium till the late stage of the
quench. The nuclei of both order parameter components arise from the thermal
fluctuations and grow rapidly until they are stabilized by the nonlinear terms in
the Ginzburg--Landau equation. The order parameter relaxation time $t_{GL}$
diverges at the temperatures close to the critical one $t_{GL} \propto (T_c -
T_0)^{-1}$ so the domain nucleation is likely to occur in the vicinity of the
phase transition.

\begin{figure*}
    \subfigure[]{
        \includegraphics[height=0.48\textwidth]{domains_p_1.png}
    }
    \subfigure[]{
        \includegraphics[height=0.48\textwidth]{domains_p_2.png}
    }
    \subfigure[]{
        \includegraphics[height=0.48\textwidth]{domains_s_1.png}
    }
    \subfigure[]{
        \includegraphics[height=0.48\textwidth]{domains_s_2.png}
    }
    \caption{(Color online) The results of the Kibble--Zurek quench for
    a $p$-wave superconductor (a,b) and a $s$-wave superconductor described by a simple
    one--component Ginzburg--Landau model (c,d). (a,c) The absolute values of
    the superconducting order parameters.
    On the panel
    (a) only the component $\eta_+$ is shown (the component $\eta_-$ is
    dominant in the areas where $\eta_+$ is
    suppressed). (b,d) The pattern of the magnetic field within the sample
after the quench. The magnetic field outside the film is expected to be
partially
smoothed out.}
    \label{fig_domains}
\end{figure*}

The results of the simulation are shown in the Fig.~\ref{fig_domains} (a,b). The
peculiar picture of the chiral domains appears after a
long time of simulation when the temperature is stabilized. The currents of
the domain
structure generate the inhomogeneous
magnetic field pattern with the zero total flux. The distribution of the magnetic
field qualitatively differs from the case of conventional $s$-wave
superconductor
for which Kibble--Zurek mechanism is known to be responsible for generation of
vortex--antivortex pairs\cite{refManivPolturak} (see Fig.~\ref{fig_domains}
(c,d)). { One can expect that the generation of the domain structure should be
accompanied by the generation of the vortex--antivortex pairs in the bulk of the domains but most of the
vortices appear to be pinned at the domain walls. The pinned vortices can be
found in the Fig.~\ref{fig_domains}(b) as asymmetric peaks of magnetic field. At the
early stage of the Kibble-Zurek quench both the vortices and the domain walls
nucleate but eventually the vortices move to the domain walls
and remain trapped there. Thus, amount of unpinned vortices depends on the
vortex--domain wall interaction strength.}

{
    The same reasoning is valid for any multicomponent superconductor which
    supports the formation of the domain walls like $s+id$
    superconductors. In this case a similar magnetic field pattern which
    corresponds to the system of domain walls with the vortices pinned at the
    walls is expected after the Kibble--Zurek quench which complicates
    identification of the chiral $p$-wave superconductivity in the sample.
    However as we noted in the Section III  the magnetic moment of the currents in the films of the non-chiral
    superconductors vanishes so it it possible to distinguish these types of
    pairing performing the measurement of the magnetic moment of the sample
    after the quench.
}

\section{Domain stability}
The vortex--antivortex pairs which appear in the conventional superconductors according to the Kibble--Zurek scenario
are unstable due to the attraction between the vortices of the opposite
winding numbers. However the impurities in the sample can pin the vortices
thus preventing the relaxation to the homogeneous state. The similar scenario may be relevant for the
domains in the chiral superconductor: the domains can be unstable and shrink
eventually, so the domain picture can be observed only within a finite time after
the quench unless we take pinning into account. Though the total vorticity
of the dominating order parameter component is equal to zero the winding number around
some domains may be nonzero affecting the evolution of the domain. We are
going to discuss the dynamics of the domains
using an
extension of the London theory for the chiral $p$-wave superconductor assuming
$\lambda / \xi \gg 1$.

We restrict ourselves to the 2D case so the domain walls are the contours
which separate the domains of different chirality. The absolute values of the order
parameter components in the bulk of the domain are (1,0) or (0, 1) depending on the
domain type so we can consider the phase of the dominant order parameter
component as a
dynamic variable within the corresponding domains. This gives us the usual
expression for the free energy of the bulk of the domains:
\begin{equation}
    F_{\mathit{bulk}} = \frac{\Phi_0^2}{32 \pi^3 \lambda_{\mathit{eff}}}
    \sum\limits_{\alpha = +,-}
    \int\limits_{\Omega_\alpha} \left(\nabla \theta_\alpha - \frac{2 \pi}{\Phi_0}
    \mathbf A\right)^2\;d^2 r ,
\end{equation}
where $\theta_\pm$ are the phases of the order parameter components and $\Omega_\pm$ are
the areas occupied by the chiral domains.
The domain wall can be viewed as a Josephson junction between the domains
with a certain  equilibrium superconducting phase difference.
The optimal phase difference though depends on the wall orientation as $\theta_+
- \theta_- = 2\theta_n$ for the flat equilibrium walls where $\theta_n$ is the angle between the normal
direction to the wall and the crystal axis\cite{refSigristAgterberg} in
the abscence of tetragonal distortions. Assuming the
curvature of the wall to be much less than $\xi^{-1}$ one can consider the
wall to be almost flat at each point and write the free energy of
the domain wall as follows:
\begin{equation}
    F_{\mathit{wall}} = \frac{\Phi_0^2}{32 \pi^3 \lambda_{\mathit{eff}}} \oint\limits_{\mathit{DW}} \left\{\epsilon + j \cos\left(\theta_+ -
    \theta_+ - 2 \theta_n\right)\right\}\;dl \ ,
\end{equation}
where the integration is taken over all domain walls, $\epsilon$ and $j$
are
the positive constants which characterize the energy of the domain wall and
the Josephson energy per unit length, respectively.
The
domain walls are energetically unfavorable so the condition $\epsilon > j$ must be
satisfied. The energy of the wall can be obtained
straightforwardly from the Ginzburg--Landau functional by integrating the free
energy density over the short segment across the wall, assuming step--like
form of the absolute values of the order parameter components. Using this approach one
can estimate the parameters $\epsilon \propto \xi^{-1}$ and $j \propto
\zeta \xi^{-1}$, respectively, and find the additional corrections to the wall
energy which come from the phase gradients at the
sides of the wall. These corrections allow to take account of the
supercurrents
flowing along the wall~\cite{refSigristAgterberg} which cannot be described
within the simple Josephson--like model. However in the case of strong type-II
superconductor $\lambda/\xi \gg 1$ and weak interaction between the order
parameter components $\zeta\ll 1$  the Josephson--like
term gives the most significant contribution into the energy of the domain wall.
The free energy of the sample naturally comes as a sum
of bulk and interface terms:
\begin{equation}
    \label{eqLondon}
    F = F_{\mathit{wall}} + F_{\mathit{bulk}} \ .
\end{equation}
This functional yields Laplace equations for the both phases of the order
parameter components with the nonlinear boundary conditions at the domain walls:
\begin{gather}
    \label{eqEulerEqn}
    \nabla^2 \theta_\pm = 0 \ , \\
    \label{eqEulerBnd}
    \left.\frac{\partial \theta_\pm}{\partial n} - j \sin\left(\theta_+ -
    \theta_- - 2 \theta_n\right)\right|_{\mathit{DW}} = 0.
\end{gather}
Here $n$ stands for direction normal to the domain wall from the
``plus'' to the ``minus'' domains.

Using the above model we study the stability of a circular domain of radius
$R$ which
carries no magnetic flux. This requires the abscence of vorticity in the exterior
domain (for certainty we consider $\eta_+$ domain to be an exterior one),
i.e. the phase of the corresponding order parameter component must be a single-valued
function. We neglect the vector potential $\mathbf A$ assuming the sample to
be a thin film and the domain size $R$ to be much less than
the effective penetration length $\lambda_\mathit{eff}$. Due to the nonlinearity of the boundary
conditions~(\ref{eqEulerBnd}) the exact solution of the
equations~(\ref{eqEulerEqn}) appears to be complicated. However in the case of the small
domains and weak interaction between the order parameter components so $j R \ll 1$ one
can linearize the boundary conditions. We suppose that the phases are almost
constant, i.e.
$|\theta_\pm(\mathbf r) - \Theta_\pm| \ll 1$ for some $\Theta_\pm
= const$. Due to the gauge invariance
an arbitrary constant may be added to both $\Theta_+$ and $\Theta_-$ while
change of the difference $\Theta_+ - \Theta_-$ results in rotation of the
whole domain. Thus without a loss of generality we can assume $\Theta_+ =
\Theta_- = 0$. The phases $\theta_\pm$ must satisfy the Laplace equation
with the following boundaries:
\begin{gather}
    \frac{\partial \theta_+}{\partial r} = j \sin 2 \varphi \ , \\
    \frac{\partial \theta_-}{\partial r} = j \sin 2 \varphi \ .
\end{gather}
Here the angle $\theta_n$ which determines the direction of the normal simply
coincides with the polar angle $\varphi$. One can easily find the solutions
\begin{equation}
    \label{eqLinear}
    \theta_\pm = \mp \frac{j R}{2}
    \left(\frac{r}{R}\right)^{\mp 2} \sin 2 \varphi
\end{equation}
and obtain the free energy of the domain in the lowest order by $R$:
\begin{equation}
    F \approx 2\pi R \epsilon \ .
\end{equation}
The minimum is at $R=0$ which means than the small domains cannot be stable.

The solution~(\ref{eqLinear}) of the equation~(\ref{eqEulerEqn}) for the small domains can be
used as an appropriate ansatz
for the nonlinear problem which appears if the domain is large $jR \gg 1$. We
look for the solution in form of the trial function:
\begin{equation}
    \theta_\pm = \gamma_\pm \left(\frac{r}{R}\right)^{\pm 2} \sin 2
    \varphi\ ,
\end{equation}
where $\gamma_\pm$ are unknown parameters and substitute it into the free
energy~(\ref{eqLondon}):
\begin{equation}
    F = 2\pi\left[\gamma_+^2 + \gamma_-^2 + R \varepsilon + j R J_1 (\gamma_+ - \gamma_-)\right] \ .
\end{equation}
If $j R \gg 1$ the minimum is $\gamma_\pm = \mp x_0 / 2$ where
$x_0 \approx 1.84$
is the position of the first maximum of the Bessel function $J_1(x)$. The
final expression for the free energy is
\begin{equation}
    F \approx 2\pi R \left[\epsilon - j J_1(x_0)\right]
\end{equation}
The dependence also appears to be linear and $dF/dR > 0$ so the domain cannot
be stabilized though the slope of the curve $F(R)$ is reduced compared to the case of the small
domain.

\begin{figure*}
    \subfigure[]{
        \includegraphics[height=0.48\textwidth]{domain3vortices_1.png}
    }
    \subfigure[]{
        \includegraphics[height=0.48\textwidth]{domain3vortices_2.png}
    }
    \caption{(Color online) The order parameter (a) and the magnetic field (b) of the chiral domain with three vortices pinned by the domain wall.
    The winding number of the outer order parameter component $\eta_+$ is equal to -1.
    The vortices reveal themself as localized peaks of magnetic field. The domain shown on the figure is not stable
    configuration but a snapshot of the domain evolution.}
    \label{figVortices}
\end{figure*}

However the circular domain can be stabilized if it carries two quanta of
magnetic flux. The order parameter of the exterior domain thus has vorticity
equal to $\pm 2$ depending on the domain type. In our case $\theta_- = \pi$
and $\theta_+ = 2 \varphi$. This solution satisfies Laplace equation inside the
domains and the boundary conditions at the domain wall because it minimizes
the Josephson--like energy along the whole wall. The free energy of such
domain is given by the following expression:
\begin{equation}
    F =\frac{\Phi_0^2}{16 \pi^2 \lambda_\mathit{eff}}
            \left[ 4 \ln \frac{\lambda_\mathit{eff}}{R} + (\epsilon - j)
            R\right] \ .
        \end{equation}
The free energy of the exterior domain diverges logarithmically at $r\to
\infty$ so the integral was cutted off at $r = \lambda_\mathit{eff}$. The free
energy has a local minimum at $R_\ast = 4 / (\epsilon - j)$, i.e. the domain
carrying two quanta of the magnetic flux is stable to the radial
perturbations. The numerical simulations
performed within the time dependent
Ginzburg--Landau framework show stability of the two--quanta domains with
respect to the azimuthal perturbations.

The above model may be applied for arbitrary vorticity $n$ of the exterior
order parameter. The presence of nonzero vorticity leads to the logarithmic term
$\propto n^2 \ln (\lambda_\mathit{eff} / R)$ in the free energy expression
which comes from the kinetic energy of the Cooper pairs in the exterior
domain. This term stabilizes the domain at some finite radius.
However in this model all the domains are considered to be circular which is
not true if $n\ne \pm 2$. The Josephson energy is frustrated in this
case and such domains lose circularity due to the azimuthal instability.

This instability reveals itself in appearance of the vortices pinned by the
domain wall.
These vortices represent the short segments of the wall where the phases of the
order parameter components are inconsistent with the Josephson relation. Between these vortices the Josephson--like energy of the
domain wall is minimized. The simulations performed within the time dependent
Ginzburg--Landau model show that these vortices lead to the sharp bending of the
domain wall and loss of the cylindrical symmetry of the domain (see
Fig.~\ref{figVortices}). The azimuthal instability plays crucial role in the
evolution of the domains allowing the domains with $n\ne 0$ to shrink.

\section{Summary}

In this work we have studied the effect of the laser pulse on the film of a
chiral superconductor. Reducing the influence of the laser pulse to the only
effect of the sample heating
 we have found the distribution of the order parameter components and
the magnetic field within the hot spot. We have analyzed the dynamics of the
superconductor after the pulse absorption in the regime of a subsequent
temperature quench. We show that if the initial pulse was strong enough to suppress
superconductivity locally then the chiral domains may grow during the
temperature quench according to the Kibble--Zurek scenario. The magnetic field
created by the currents of the domain walls can be observed experimentally.
The field pattern of the domain walls differs qualitatively from the
field of vortex--antivortex pairs known to appear via Kibble--Zurek mechanism
in the conventional $s$-wave superconductors. Such a behavior is a fingerprint
of the chiral superconductivity and the appropriate experiments may be useful
for it's identification in $\mathrm{Sr_2RuO_4}$.

In order to study the stability of the domains we developed a model which
allows to analyze the samples with the given shape of the domains in London
limit assuming the domain wall to be a Josephson junction with
orientation--dependent Josephson energy. Using this model we studied
stability of the circular domains and show that two--quanta domains are
stable while zero--quanta domains shrink. Simulations within the time dependent
Ginzburg--Landau framework show that the circular domains are unstable with respect to the
azimuthal perturbations if the winding number of the exterior domain differs
from $\pm 2$ due to the Josephson energy frustration {similar to the
frustration in the circular Josephson junctions between the chiral $p$-wave
and the $s$-wave superconductors~\cite{refEtter}.}

We thank I. Shereshevskii, D. Vodolazov, A. Buzdin, Ph. Tamarat and B. Lounis for stimulating discussions. The work was supported by Russian Science Foundation No.
17-12-01383 (ASM), Foundation for the advancement of theoretical physics
``BASIS'' No. 109 (VLV) and Russian
Foundation for Basic Research (VLV).
\input{bibliography.bbl}

\end{document}

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