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Tag Archives: Itraco
A few of these NOS (new old stock) models are appearing today and for a collector like me are almost a certain buy. Watches like this from the 1970's are slap bang in the middle of the worst period for Swiss watches as the cheap, accurate Quartz revolution from Asia hit them hard. Often the smaller Company or suppliers could move and adapt to not only compete with this new threat but importantly still manage to utilize their existing mechanical movements.
The Hudson Instalite (by Itraco) – 17 jewel pin lever "Jump" watch.
Hence the birth of the mechanical "digital", Digit Wheel or "Jump" watch, which managed the appearance of a Quartz digital watch, but with a more or less conventional mechanical movement.
Some were true "Jump" designs where the Hour digit only moved or "jumped" forward at the last second of the Minute Counter digit. Others sort of gradually slid into position as the changing of the Hour approached, though these often caused a little confusion when not fully changed, being sort of stuck in no-man's land between hours. This model falls into this category – at the hour and 55 seconds, it's sometimes tricky to tell which hour it actually is!
Quite a few different Brands appeared at this time such as Gigandet, Damas, Lanco, Lasser and others.
The model featured here was sold for retail by Hudson for the US market, though the Brand was actually manufactured by Itraco of Zurich (Itraco, Samba & Hudson) and features the Ebauches Bettlach EB8461 17 jewel pin lever mechanical wheel digit movement with a pretty decent 40hr reserve .
The Hudson Watch Co. was registered by Antoine Castelberg of Chaux-de-Fonds and New York in 1884. Other names were marketed via Hudson in the early 1970's, such as Adelphi, Carlton, Gisa, Globe, J Godat Geneve and others. In fact the list of "lost" names and Brands is extensive and to be certain of who made what, or who sold what and under what name and where and at that time is a near impossible task.
Suffice to say, this model is the Hudson logo'd Instalite model, which I consider one of the better ones. I have also seen the same watch with "Fashion-Time" and "Secory" and apart from slight cosmetic changes are obviously the same model. I understand that one of those variations did alter the movement to give that true "jump" hour and I have a feeling the movement was also an EB movement but calibre 8481 series.
The battery access for the "Instalite" accessed via this left sliding hatch. Access to the movement requires the back removed. The "slots" are simply grips to assist in sliding.
The term "Instalite" is in reference to the battery powered dial light which illuminates the dial digits rather well in this case and operated via the push button @1 above the central crown. The battery is easily accessible via the dark colored plastic sliding rear cover, which is separate from the movement, which itself can be seen only with the entire 2 piece metal "snap" back removed.
Various movements from Ebauches Bettlach were used in this model depending on the year, but all are similar in operation. It's fair to say Bettlach E after amalgamating many of the independent Swiss makers as a defence against the Quartz revolution, were focused more on the lower end. Historically Ebauches Bettlach SA was formed in 1926 and ended in 1980 as it finally merged into the Swatch Group under ETA, which aligned pretty much with Bettlach's core aim from it's inception. ( for details see under – https://www.watch-wiki.net/index.php?title=Ebauches_SA ).
Fits the wrist pretty well and very readable too. I have fitted a complimentary leather strap.
I have a few of these "jump" models, as for me they represent an important yet too easily forgotten milestone in the Swiss watch history – and many are rather unique and cleverly innovative for the time. They really provided a stopgap rescue for much of the Industry at a time where the Swiss Watch industry as a whole was under serious threat.
I hope the images show to best advantage, these intriguing watches which by the way are a delight to wear. The size is ideal and they sit well on the wrist, even an average one such as mine (6.5″).
This watch came with an after market steel mesh bracelet, but if you read this site regularly you will know I just love changing straps and bracelets to see the effect. It can sometimes make or break the wear-ability and often is surprising, which is half the fun! As shown I have fitted a brown leather strap which softens the look and for me is more comfortable.
Posted in Retro, Watch reviews.	Tagged Hudson Watch Co, Instalite, Itraco


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Nasrin As'ad Ibrahim, better known by the nom de guerre Umm Sayyaf, is the widow of Abu Sayyaf. She was captured in May 2015 by US Delta Force soldiers on the mission where they killed her husband, a suspected leader of the Islamic State.

During the raid Delta Force soldiers were also reported to have rescued a young Yazidi woman the couple had been keeping as a slave. National Security Council spokesperson Bernadette Meehan stated, "We suspect that Umm Sayyaf is a member of ISIL, played an important role in ISIL's terrorist activities, and may have been complicit in the enslavement of the young woman rescued last night."

Umm Sayyaf is believed to be an Iraqi citizen.

Initial reports said that she was in US custody in Iraq. On August 6, 2015 Umm Sayyaf was turned over to the Kurdish regional authorities in Erbil.
James Gordon Meek, of ABC News noted some American prosecutors wanted to try to prosecute her in the US justice system.  He characterized the Kurdish justice system as being "known for lightning-swift justice."

According to John Knefel, reporting for Al Jazeera, legal critics have challenged the Barack Obama administration for a lack of transparency over the justification for holding Umm Sayyaf in extrajudicial detention. He said, "The administration's secrecy surrounding the conditions of her imprisonment have led some lawyers and legal analysis to raise questions about what rights and protections she's being afforded, and what policy guidelines will govern treatment of new detainees in what some now refer to as the Forever War."

The family of American hostage Kayla Mueller reported that they had been told that, during her captivity, she was imprisoned by Abu Sayyaf and Umm Sayyaf and sexually abused by Abu Sayyaf before she was taken as a wife and sexually abused by Abu Bakr al-Baghdadi.  Yazidi girls, who had been held as sex slaves by Abu Sayyaf, and who later escaped, were the first to report that Mueller was also sexually abused before her death.  Interrogation of various individuals by intelligence officials seemed to indicate that al-Baghdadi had been Mueller's primary abuser.

On February 8, 2016, Sayyaf was charged by American prosecutors in Virginia with providing material support to a foreign terrorist organization that resulted in a person's death. The federal charge carries a maximum sentence of life imprisonment.

In May 2019, it was reported that she had been cooperating with the CIA and Kurdish intelligence in the hunt for al-Baghdadi.

References

Iraqi women
Islamic State of Iraq and the Levant members from Iraq

redpajama_set_name: RedPajamaWikipedia


We hid behind the tree. Get out of my sight! It'll be after dark by the time we land in Boston. I want to ask, just in case - we should wear our uniforms tomorrow, right? Jinchao is open-minded, isn't he? Erick was wearing an old pair of shoes. Lynn has no need to worry. I like women. An hour has sixty minutes, and a minute has sixty seconds. Do not read such a book.
It had to be an easy language, or it was math. I haven't spoken to Lou in a while. Which applications do you like best? We have to stick together. I can't stand this kind of music. I know you hired me. This one's free. The simplest sentences are the most elegant ones. Now get out. She lay awake for hours thinking about him.
Just don't kiss me. I went to Boston last year. One hand washes the other. Once selected to join the astronaut corps, training begins at the Johnson Space Center in Houston, Texas. The two of them have been in Boston for over three years. It's like putting Dracula in charge of the blood bank. You broke my heart. Who complained? Linda filed for a legal separation. They both want the same thing.
Barbra doesn't take his job very seriously. There is little wine left. Are you children all right? He did what he promised to do for me. Every day I come to university by bus. We became Americanized after World War II. At the most, he earns 50 dollars a week. Ninja had nothing to do with this. Parents often sacrifice themselves to ensure that their children receive a good education. Let's not talk.
If one could only teach the English how to talk, and the Irish how to listen, society here would be quite civilized. Bill was sent to live with his grandparents while his mother studied to become a nurse. Guy is quite a bit younger than Harold. Winston entered the room, carrying two pizzas. This will teach you not to annoy other people. A car passed by in the dark. I could order you to stay. The reverse seems true. She is not such a girl as you imagine. It's a nice day, isn't it?
She did not listen. Clever programming requires a computer. Tell Gerald how to do that. Why do you blame me for what happened? I hope Angus comes back soon. We're ready, I think. He saw in her eyes that she still loved him and hope arose inside him. Englishmen are, on the whole, conservative. Root is starting to get on my nerves. He stood motionless, like a pillar of salt.
Jean works as a waitress at a restaurant on Park Street. With bronze as a mirror one can dress neatly; with the example of another person one can see the advantages and disadvantages of himself; from the mirror of history one can know the reason for the rise and fall of states. I'm here to talk about her. I'm going to travel tomorrow. It is only January and already Easter eggs and Hot Cross Buns are appearing in the shops. Needless to say, I've come here to help you. Wenjin is a Chinese woman. He has long hair and wears jeans. That's Saturn. Are you still in Boston?
Gill managed a small bar near Boston for quite a long time. State your full name for the record. He is nice. Being silent is regarded in effect as approval. Where do you keep your textbooks? You don't know what I had to put up with! He'll really be happy, won't he? Skef is very cunning. You can't let Kristian eat anything that has peanuts in it. This ring is very expensive.
There was nothing for me to eat. You must really like her. I'd never leave him alone. Would you want to know how you're going to die? A democrat is, at the end of the day, one who admits that an opponent can be right, and therefore lets them express themselves and allows for reflection upon their arguments. When parties or men feel sufficiently persuaded by their own arguments that they allow the silencing of those that contradict them by means of violence, that isn't democracy. You got that right. She baked cookies. Want to come over to my place for pancakes? She never mentioned it again. I told you before that I'm not interested in hanging out with you.
It's been great fun. We're just looking out for them. I tried to stop Tracy from hurting Penny. Not worth the remembered value. Dawn is coming. I am not guided. I wouldn't hold my breath. The guards didn't see him. I can't think straight right now. The great question that has never been answered, and which I have not yet been able to answer, despite my thirty years of research into the feminine soul, is "What does a woman want?"


text:
E Brandan
Anchorage of collagen-tailed acetylcholinesterase to the extracellular matrix is mediated by heparan sulfate proteoglycans.
E Brandan, M Maldonado, J Garrido, N C Inestrosa
DOI: https://doi.org/10.1083/jcb.101.3.985
Heparan sulfate and heparin, two sulfated glycosaminoglycans (GAGs), extracted collagen-tailed acetylcholinesterase (AChE) from the extracellular matrix (ECM) of the electric organ of Discopyge tschudii. The effect of heparan sulfate and heparin was abolished by protamine; other GAGs could not extract the esterase. The solubilization of the asymmetric AChE apparently occurs through the formation of a soluble AChE-GAG complex of 30S. Heparitinase treatment but not chondroitinase ABC treatment of the ECM released asymmetric AChE forms. This provides direct evidence for the vivo interaction between asymmetric AChE and heparan sulfate residues of the ECM. Biochemical analysis of the electric organ ECM showed that sulfated GAGs bound to proteoglycans account for 5% of the total basal lamina. Approximately 20% of the total GAGs were susceptible to heparitinase or nitrous acid oxidation which degrades specifically heparan sulfates, and approximately 80% were susceptible to digestion with chondroitinase ABC, which degrades chondroitin-4 and -6 sulfates and dermatan sulfate. Our experiments provide evidence that asymmetric AChE and carbohydrate components of proteoglycans are associated in the ECM; they also indicate that a heparan sulfate proteoglycan is involved in the anchorage of the collagen-tailed AChE to the synaptic basal lamina.

redpajama_set_name: RedPajamaCommonCrawl


Democrat presidential candidate Kamala Harris is in California for a fundraiser hosted by prominent Hollywood power players, including the prolific television hitmaker Shonda Rhimes.
The Wednesday evening event is billed as a "reception in support of Kamala Harris for the People," and Harris is expected to attend, according to an invitation obtained by The Associated Press. The reception will be held at the Pacific Palisades home of director J.J. Abrams and his wife, Katie McGrath. Tickets cost $2,800 per guest, with co-chairs donating $10,000, according to the invitation.
On Tuesday, the California senator was a guest on ABC's "Jimmy Kimmel Live!" and posed for pictures with Star Wars star Mark Hamill, who also appeared on show.


This aught to make you blow a gasket.
Thread: This aught to make you blow a gasket.
Not mine. Just found it while searching. Not sure how to post pics for this listing.
Maybe I'm just being an optimist, but I'm not totally convinced that's an SVO.
Turn away, don't look. Got to be one of the ugliest things I ever saw.
Sure has all of the SVO specific items. Huh, 4X4 SVO. Interesting.
"Interesting" was not in the first 100 words to come to my mind.


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Home Marijuana News Gallup Poll Finds Almost Half Of US Adults Have Tried Marijuana
Gallup Poll Finds Almost Half Of US Adults Have Tried Marijuana
Gallup found that almost half of the adults in the US have tried cannabis at some point in their lives.
byA.J. Herrington
Gallup data shows that almost half of US adults have tried cannabis.
Almost half of adults in the United States said they have tried marijuana, according to the results of a new Gallup Poll released on Tuesday. At 49 percent, the figure is the highest that Gallup has recorded in its more than 50 years of asking Americans about their cannabis use.
When Gallup first began surveying Americans about cannabis in 1969, only four percent of adults said that they had tried marijuana. Since that time the rate has increased steadily, rising to more than 20 percent in the 1977 survey. Roughly a third of adults surveyed in 1985 said that they had tried cannabis, and by 2015 the percentage had surpassed 40 percent. Gallup noted that much of the increase in marijuana experimentation reported over the last 50 years can be explained by generational patterns in the United States.
"The oldest Americans living today, those born before 1945 whom Gallup calls 'traditionalists,' are much less likely than those in other birth cohorts to have tried marijuana, with just 19% saying they have done so. That compares with about half of millennials (51%), Generation Xers (49%, and baby boomers (50%)," the polling organization wrote in its report on the survey.
The generational data on marijuana use trends was taken from Gallup's annual Consumption Habits surveys from 2015 to 2021. Gallup noted that it does not yet have enough information on the trends of Generation Z, the oldest of whom are only 24 years old now. This year's Consumption Habits poll was conducted from July 6 to 21.
Only 12 percent of those surveyed said that they "smoked marijuana," a percentage that has held steady since 2017. In 2013, the first year Gallup asked if respondents smoked marijuana, only seven percent replied in the affirmative. The figure rose steadily to 11 percent by 2015 before peaking at 13 percent in 2016. Gallup did not ask the poll's respondents if they consumed marijuana in any way other than smoking.
Gallup Data: Marijuana Use Higher Among Younger Americans
While the percentage of those who said they have tried marijuana varies little among baby boomers and subsequent generations, Gallup noted that younger Americans are more likely to say that they currently smoke marijuana. The combined data from 2015 to 2021 show that about 20 percent of millenials smoke marijuana. For Gen Xers the figure is 11 percent, while nine percent of baby boomers and only one percent of traditionalists say they currently smoke pot.
In addition to differences by age, the survey revealed that the rate of marijuana use varied among other demographic groups including gender, education, and political orientation. While 16 percent of men said that they smoked marijuana, only nine percent of women said the same. Only five percent with a postgraduate education said that they smoked cannabis, compared to 14 percent of those with a four-year college degree or less education. And those who are politically liberal (22 percent) and Democrats (15 percent) were more likely than conservatives (six percent) and Republicans (seven percent) to say they currently smoked marijuana.
In its analysis of the generational patterns revealed by the survey, Gallup noted that the percentage of Americans who say they have tried cannabis might not rise much higher than 50 percent, despite the upward trend that has been recorded to date.
"The percentage of Americans who have tried marijuana has steadily climbed in recent decades," Gallup wrote. "Soon it should reach 50 percent, but it may not get much higher than that given the rates of experimentation have been steady around 50 percent in Gen Xers and among baby boomers. Half of millennials have also tried marijuana, and with many in that group approaching middle age, that proportion seems unlikely to increase in future years."
US adults
A.J. Herrington
A.J. Herrington is a San Diego-based freelance writer covering cannabis news, business, and culture.
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On May 25th our NJROTC unit hosted an assembly to honor all who have died or are presumed dead in combat. The main event of the assembly was the lighting of the candles. There were 9 total candles, representing the brave men and women who died in the Revolutionary War, the War of 1812, Civil War, World War I, World War II, the Cold War, the Gulf War, Operation Enduring Freedom, and Operation Iraqi Freedom.
Following this was a guest speaker, Lieutenant Colonel Koren. He told the story of his experiences in Vietnam, and of what it is like to lose a friend in war.
To conclude the ceremony, the song "Some Gave All", by Billy Ray Cyrus, was played.
After the main assembly ended, the cadets and guests moved outside to lay wreaths upon the memorial of Karl R. Linn and Jourdan L. Grez, our two JRHS graduates who gave their lives defending the first democratic elections in Iraq.
The price of freedom is a heavy toll, and we as Americans must be forever grateful and supportive to all who have given up their lives and families for the sake of it.
It was a memorable and meaningful ceremony!


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FIRST AIRED: December 4, 2018
Uproar over plans to relocate toppled Confederate statue
At least 23 feared dead in Japanese studio fire
>> Silent families must go away.>> Students at the University of North Carolina in Chapel Hill are refusing to stay silent on the school's plans to relocate a Confederate statue that was toppled during summer protest.>> This is what democracy looks like.>> More than 100 students marched through campus Monday night to denounce the school's plan to house the Silent Sam monument in a new $5 million campus facility being built to display the statue and other historical artifacts.
>> When you alot $5 million to a shrine to the Confederacy States of America instead of giving
UNKNOWN]
students a cultural center or investing resources.>>
>> Or investing resources in diversity programs. It is hard to believe that inclusively is genuinely in your hearts.>> The university's chancellor says a state law requires the school to keep the statue on campus.
That law, passed in 2015, prohibits state agencies, from removing or relocating state owned monuments.>> I have a preference to move it off-campus, but like everyone here, I swore to obey the law, and sometimes you don't agree with laws.>> The Silent Sam statue stood on UNC's campus for more than 100 years before it was pulled down by protesters in August.
The monument commemorated North Carolina's Confederate soldiers. The statue was 1 of more than 100 Confederate monuments that have been removed across the US in recent years. The university's plan to relocate Silent Sam still has to be approved by the board of governors. The new building is expected to be finished in four years and will cost more than $800,000 a year to operate.


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redpajama_set_name: RedPajamaGithub


text:
INTERVIEW: Ekin Oklap on translating Orhan Pamuk into English
William Armstrong - william.armstrong@hdn.com.tr
Orhan Pamuk's latest novel, "The Red-Haired Woman," is a complex tale blending realism with ruminations on ancient Greek and Persian myths. The Nobel laureate's 10th novel centers on the relationship between a traditional well-digger outside and his young apprentice outside the expanding megalopolis of Istanbul. This ostensibly simple central story develops into a symbolic parable with social and political undertones, coming to a gripping denouement.
At 250 pages, "The Red-Haired Woman" is a relatively slim book, following the 600-page epic "A Strangeness in My Mind," published in English in 2015. Both novels were translated into English by Ekin Oklap, who took over from Pamuk's long-time collaborator Maureen Freely.
Oklap spoke to the Hürriyet Daily News about translating Pamuk, including some of the technical and political difficulties she has experienced so far. The conversation has been edited for concision.
How did you start out as Pamuk's English translator?
I'm actually a literary agent in London, working at the agency that represents Orhan. Initially I started out there as a receptionist. But a few years ago, shortly after I started, my boss - who is Orhan's agent - said he was looking for a new translator. Because I happen to be Turkish he asked me to help out, so I suggested that he might also consider me. I translated a sample, Orhan liked it, and it went from there.
Did you have a background in translating or did it just come out of the blue?
I don't have a background in translating. I'd never studied it or even done it before. But I speak three languages. I was born in Turkey and grew up in Italy. So I've always lived with more than just one language and in a way I've always translated things throughout my life - in a much less difficult, more day-to-day context. The idea of translating a thought or a text into another language is something I've always been familiar with.
"The Red-Haired Woman" is the second Pamuk novel you have translated, after "A Strangeness in My Mind," which was published in English in 2015. How were the two experiences different?
I also translated a catalog that Orhan wrote five or six years ago called "The Innocence of Objects," about his Museum of Innocence in Istanbul. But that was a comparatively short text and very different to the novels. In terms of comparing the two novels, one is half of the length of the other. That corresponded almost exactly to the amount of time it took to translate them: It took just over four months to translate "A Strangeness in My Mind" and two months to translate "The Red-Haired Woman."
But apart from the length, they are very different books. "A Strangeness in My Mind" contains a multitude of characters and voices that pop up throughout the novel. It is almost Dickensian in terms of detail, which presents a different sort of challenge. "The Red-Haired Woman" had its own challenges. It is more philosophical in a way; I suppose you could consider parts of it almost a thought experiment. So the two are completely different kind of books.
Talk a bit about the translation process. What order does it take place in? Do you wait for it to be published in Turkish first or do you get cracking as soon as Pamuk has finished writing?
It depends. With "The Red-Haired Woman," the book had already been published in Turkish when I started translating it. So I had a physical copy alongside me. But with "A Strangeness in My Mind" I was already halfway through translating it when Orhan finished writing it. But that is accidental really, it's a matter of publishing schedules.
Pamuk's previous translator Maureen Freely has spoken about long, argumentative sessions translating alongside him on Büyükada, an island off Istanbul, arguing over almost every sentence. Do you also work alongside him or are you left alone?
I work with Orhan very closely. His English is very good so he's able to read the entire translation and comment on it. I haven't found him to be too argumentative, perhaps I've just gotten lucky. We tend to find something that works at the end of the day. In this kind of context the author knows best what they want to say. So unless the suggestion is somehow incorrect I usually find it has merit.
What are the main areas of disagreement?
English has so many more words than Turkish to express similar concepts. So one of the things that comes up fairly frequently when I talk to Orhan about translation is whether a particular word that is repeated in the Turkish version may be replaced with something else in English. That's a natural consequence of the differences between the two languages and their vocabulary.
I've heard that he tends to try to maintain the Turkish grammatical structure as much as possible. Turkish comes from a completely different language family than English, originating in Central Asia, so the way words and sentences are constructed is completely different. So if Pamuk wants to maintain that structure as much as possible it must be very challenging.
We don't tend to get into sentence-by-sentence detail in our conversations. It tends to be occasional words in a particular section. So I haven't been in a situation where we look at a situation and he asks to put a verb at the end because that's how it is in Turkish. As a translator I think it's important to stay faithful to the structures as well as literally what the text is saying, but there's only so much of that you can do. If you do it too much it just sounds odd.
I suppose that's the big debate in translation: Accuracy vs. fluency.
Yes this is one of the biggest debates. I have no academic background in this subject, but I go by my preferences as a reader. When I read a translated text, if possible I'd like to forget that it's a translation. I'm aware that in itself is actually a controversial position.
Translated fiction has a merit or value deriving from the very fact that it is translated. To sound cliched, it is a bridge into another world for readers. So saying that you should forget you are reading a translation almost seems to suggest that is irrelevant. So I'm aware that saying you should "forget" that a text is a translation is perhaps oversimplifying things. But at the same time when something sounds like it wasn't written in the language you're reading in, you quickly can be thrown from what you're reading.
So my unacademic and personal approach is to try to ensure that what I do as a translator stays as faithful as possible to the original text but reads almost like it could have been written in English.
Maureen Freely got embroiled in a lot of the political controversy that swirled around Pamuk during the 2000s. Do you ever concern yourself about this stuff or try to keep it at arm's length?
As I'm Turkish I have no choice but to worry about this stuff. All of this worried me even before I started translating Orhan Pamuk's books. I'm not more worried or more involved now. I haven't experienced anything negative in particular in the past few years related to this. That may be because Orhan's perhaps less in the news in Turkey compared to around 10 years ago. So I've been lucky so far.
Some in Turkey claim that Pamuk's English translators "improve" or "Westernize" his words, the implication being that he is not so good in Turkish. What do you make of that criticism?
I was aware of this kind of comment that he receives. I don't think it has any bearing on the truth. There's no way a translator can "improve" an author's work without changing it, and changing an author's work is not what a true translator should do. The author's role is the key role. Orhan's work is translated into so many languages, all over the world. So to suggest that he's only popular because his English translators have been good is misleading. It also wipes away the work of all his other translators, who work on his books in Chinese, French, German, Italian and dozens of other languages. I think there's a political element to that criticism and it tends to be rather disingenuous.
And of course there are plenty of people who find him difficult to read in English - probably the same proportion as readers in Turkish. So it's not like he's becoming transformed into a very broad popular novelist in English.
I think there are certain reasons behind it that have nothing to do with the actual writing and more to do with positions he has expressed in the past that have not gone down very well.
Is translating your main focus at the moment or do you have other irons in the fire?
I work full time as a literary agent and every couple of years, whenever Orhan finishes a book, I take some time off to translate it. I wish I could go home from the office and translate at night but that's not something I can do. I need to take time off and devote myself to translation, returning to work after it's done. Orhan is currently writing a new book but I haven't seen a single word of it yet, so we're just patiently waiting.
Orhan Pamuk, William Armstrong, ekin oklap


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Q: Compute sum (infinite series)
Compute the sum
  $$
\sum_{n=1}^\infty \frac{(n-1)!}{(n+k)!}
$$
  where $k = 1,2,\ldots$ is fixed.

I was able to compute the sum of a simpler infinite series:
$$
\sum_{n=1}^\infty \frac 1{n(n+1)(n+2)}
$$
In that case, my given hint was to notice that
$$
\sum_{n=1}^\infty \frac 2{n(n+1)(n+2)} = \sum_{n=1}^\infty \left(\frac 1{n(n+1)}-\frac 1{(n+1)(n+2)} \right)
$$
is a telescoping series.
How can I find a telescoping series for the generalized sum above?

A:
For $m\in\mathbb{N}$, define the sequence $s:\mathbb{N}\rightarrow\mathbb{R}$ via the infinite series
$$s_{m}:=\sum_{n=1}^{\infty}\frac{\left(n-1\right)!}{\left(m+n\right)!}.$$
Note that for each nonnegative integer $n\in\mathbb{N}\cup\{0\}$, we can express the factorial $n!$ in terms of the gamma function with the relation
$$n!=\Gamma{\left(n+1\right)}.$$
A related function known as the beta function may be defined via the integral representation
$$\operatorname{B}{\left(a,b\right)}:=\int_{0}^{1}t^{a-1}\left(1-t\right)^{b-1}\,\mathrm{d}t;~~~\small{a>0\land b>0}.$$
The beta function can be reduced to gamma functions through the following identity:
$$\operatorname{B}{\left(a,b\right)}=\frac{\Gamma{\left(a\right)}\,\Gamma{\left(b\right)}}{\Gamma{\left(a+b\right)}}.$$

Now, for each positive integer $m\in\mathbb{N}$, we find using the technique of summing under the integral sign that
$$\begin{align}
s_{m}
&=\sum_{n=1}^{\infty}\frac{\left(n-1\right)!}{\left(m+n\right)!}\\
&=\sum_{k=0}^{\infty}\frac{k!}{\left(m+k+1\right)!}\\
&=\sum_{k=0}^{\infty}\frac{\Gamma{\left(k+1\right)}}{\Gamma{\left(m+k+2\right)}}\\
&=\frac{1}{\Gamma{\left(m+1\right)}}\sum_{k=0}^{\infty}\frac{\Gamma{\left(k+1\right)}\,\Gamma{\left(m+1\right)}}{\Gamma{\left(m+k+2\right)}}\\
&=\frac{1}{\Gamma{\left(m+1\right)}}\sum_{k=0}^{\infty}\operatorname{B}{\left(k+1,m+1\right)}\\
&=\frac{1}{\Gamma{\left(m+1\right)}}\sum_{k=0}^{\infty}\int_{0}^{1}t^{k}\left(1-t\right)^{m}\,\mathrm{d}t\\
&=\frac{1}{\Gamma{\left(m+1\right)}}\int_{0}^{1}\sum_{k=0}^{\infty}t^{k}\left(1-t\right)^{m}\,\mathrm{d}t\\
&=\frac{1}{\Gamma{\left(m+1\right)}}\int_{0}^{1}\frac{\left(1-t\right)^{m}}{1-t}\,\mathrm{d}t\\
&=\frac{1}{\Gamma{\left(m+1\right)}}\int_{0}^{1}x^{m-1}\,\mathrm{d}x;~~~\small{\left[1-t=x\right]}\\
&=\frac{1}{\Gamma{\left(m+1\right)}}\cdot\frac{1}{m}\\
&=\frac{1}{m!\,m}.\blacksquare\\
\end{align}$$

A: This is not an answer but it is too long for a comment.
Considering the partial sums $$S_m^{(k)}=\sum_{n=1}^m \frac{(n-1)!}{(n+k)!}$$ and using the same ideas as  David H's in his answer, we can find a nice and simple expression $$S_m^{(k)}=\frac{1}{k^2}\left(\frac{1}{\Gamma (k)}-k\,\frac{\Gamma (m+1)}{\Gamma (k+m+1)}\right)$$ which seems to be valid for any $k$ (integer or not).
If $m\to \infty$, there is convergence only if $k>0$ because of the second term in brackets (Stirling approximation shows this point easily). In such a case, $$\lim_{m\to \infty } \, S_m^{(k)}=\frac{1}{k^2\,\Gamma (k)}=\frac{1}{k\,\Gamma (k+1)}$$ which leads to David H's if $k$ is an integer.
For small values of $k$, the asymptotics is given by $$\lim_{m\to \infty } \, S_m^{(k)}=\frac{1}{k}+\gamma +\left(\frac{\gamma ^2}{2}-\frac{\pi ^2}{12}\right)
   k+O\left(k^2\right)$$

A: $\newcommand{\braces}[1]{\left\lbrace\,{#1}\,\right\rbrace}
 \newcommand{\bracks}[1]{\left\lbrack\,{#1}\,\right\rbrack}
 \newcommand{\dd}{\mathrm{d}}
 \newcommand{\ds}[1]{\displaystyle{#1}}
 \newcommand{\expo}[1]{\,\mathrm{e}^{#1}\,}
 \newcommand{\ic}{\mathrm{i}}
 \newcommand{\mc}[1]{\mathcal{#1}}
 \newcommand{\mrm}[1]{\mathrm{#1}}
 \newcommand{\pars}[1]{\left(\,{#1}\,\right)}
 \newcommand{\partiald}[3][]{\frac{\partial^{#1} #2}{\partial #3^{#1}}}
 \newcommand{\root}[2][]{\,\sqrt[#1]{\,{#2}\,}\,}
 \newcommand{\totald}[3][]{\frac{\mathrm{d}^{#1} #2}{\mathrm{d} #3^{#1}}}
 \newcommand{\verts}[1]{\left\vert\,{#1}\,\right\vert}$

$\ds{\sum_{n = 1}^{\infty}{\pars{n - 1}! \over \pars{n + k}!}\quad}$ where
  $\ds{\quad k = 1,2,\ldots}$ is fixed.

Lets
$\ds{\,\mrm{f}\pars{x} \equiv
\sum_{n = 1}^{\infty}{\pars{n - 1}! \over \pars{n + k}!}\,x^{n}\quad}$
where $\ds{\quad x \in \pars{0,1}\quad}$ and
$\ds{\color{#f00}{\quad\sum_{n = 1}^{\infty}{\pars{n - 1}! \over \pars{n + k}!}} = \mrm{f}\pars{1^{-}}}$.

\begin{align}
x\,\mrm{f}'\pars{x} &\equiv
\sum_{n = 1}^{\infty}{\pars{n - 1}! \over \pars{n + k}!}\,n\,x^{n} =
\sum_{n = 1}^{\infty}{\pars{n - 1}! \over \pars{n + k - 1}!}\,\,x^{n} -
k\sum_{n = 1}^{\infty}{\pars{n - 1}! \over \pars{n + k}!}\,\,x^{n}
\\[5mm] & =
\sum_{n = 0}^{\infty}{n! \over \pars{n + k}!}\,\,x^{n + 1} -
k\,\mrm{f}\pars{x} =
{x \over k!} +
x^{2}\sum_{n = 1}^{\infty}{\pars{n - 1}! \over \pars{n + k}!}\,n\,x^{n - 1} -k\,\mrm{f}\pars{x}
\\[5mm] & =
{x \over k!} + x^{2}\,\mrm{f}'\pars{x} -k\,\mrm{f}\pars{x} \implies
\pars{x^{2} - x}\mrm{f}'\pars{x} - k\,\mrm{f}\pars{x} = -\,{x \over k!}
\\[5mm] \implies &
\bbox[8px,border:0.1em groove navy]{
\mrm{f}'\pars{x} - {k \over x^{2} - x}\,\mrm{f}\pars{x} =
{1 \over k!}\,{1 \over 1 - x}\,,\quad\mrm{f}\pars{0^{+}} = 0}
\end{align}

The above differential equation can be rewritten as:
\begin{align}
&\totald{\bracks{x^{k}\pars{1 - x}^{-k}\,\mrm{f}\pars{x}}}{x} =
{1 \over k!}\,\pars{1 - x}^{-k - 1}x^{k}
\\[5mm] &\ \implies\bbox[8px,border:0.1em groove navy]{
\mrm{f}\pars{x} = {1 \over k!}\,x^{-k}\pars{1 - x}^{k}
\int_{0}^{x}\pars{1 - t}^{-k - 1}t^{k}\,\dd t\,,\qquad x \in \pars{0,1}}
\end{align}

\begin{align}
\color{#f00}{\quad\sum_{n = 1}^{\infty}{\pars{n - 1}! \over \pars{n + k}!}} & =
\lim_{x \to 1^{-}}\bracks{%
{1 \over k!}\,x^{-k}\pars{1 - x}^{k}\int_{0}^{x}\pars{1 - t}^{-k - 1}t^{k}
\,\dd t} =
{1 \over k!}\,\lim_{x \to 1^{-}}
\bracks{{\pars{1 - x}^{-k - 1}x^{k} \over k\pars{1 - x}^{-k - 1}}}
\\[5mm] & =
\color{#f00}{1 \over k\,\, k!}
\end{align}

redpajama_set_name: RedPajamaStackExchange


text:
Marzan (; ) is a commune in the Morbihan department of Brittany in north-western France. Inhabitants of Marzan are called in French Marzannais.

See also
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References

External links

 Mayors of Morbihan Association

Communes of Morbihan


text:
\section*{I. Introduction}

One of the most interesting open problem in Conformal Field Theory
is the connection between its Integrable Structure~\cite{BLZ}  and
the Fermi--Bose correspondence. This correspondence manifests itself
in the generalizations of Roger--Ramanujian Identities for Characters
of Minimal Models of CFT~\cite{BPZ} discovered by Kedem, Klassen, McCoy
and Melzer~\cite{KKMM}.
The simplest example of such identity is the following equation
for a character of $M(3,4)$ minimal model(Ising model):
\begin{equation}
   \label{eq:a}
   \frac{1}{\prod_{n=1}^{\infty}(1-t^n)}
   \sum_{k=-\infty}^{\infty}
   [t^{k(12k+1)}-t^{(4k+1)(3k+1)}]
  =\sum_{\scriptstyle m\>-\>{\rm even}\atop
\scriptstyle m>0}^{\infty}\frac{t^{m^2/2}}{(1-t)\ldots(1-t^m)}
\end{equation}
The l.~h.~s.\ of the identity has a natural explanation
as Feigin--Fuchs-Felder representation of the space of states
of the model in terms of free bosonic field.
The r.~h.~s.\ can be interpreted~\cite{KKMM} as a partition
function of right moving (chiral) fermions of one kind.

The similar identities were found in~\cite {KKMM}
for generic Minimal Model $M(p,p+1)$ with $ p \geq 3 $.
In this case the r.~h.~s.\ can be considered as partition functions for
$ p-2 $ species of right moving fermions.
It was  shown by R.Kedem and B.McCoy tahat the fermionic  states arise as
low lying excitations in Bethe Ansatz approach for the 3-Potts model
which corresponds to $M(5,6)$ Minimal Model. It would be
interesting to generalize these results for general $M(p,p+1)$ case.

In~\cite{BLZ} the continuous field theory version of the
commuting transfer-matrices of Integrable lattice theory
have been constructed and the conjecture that eigenvectors
of these transfer-matrices form the fermionic basis of Virasoro
characters has been claimed.

So the investigation of the connection between Fermi-Bose correspondence
and Integrable Structure of CFT continues to be interesting both
in the continuous field theory and in the Integrable   lattice theory
and is one of the main motivations of this work~\cite{BF}.

The plan of the paper is the following. In part~II we consider
the integrable XXZ model with special open boundary conditions which
was investigated firstly by Alcaraz {\it et al.}~\cite{ALC}.
According to
Pasqier and Saleur~\cite{PS} we use the Quantum Group reduction
of this model for the definition Minimal Models of Interable lattice
theory ($LM(p,p+1)$) which coincide with Minimal Models of CFT $M(p,p+1)$
in the termodinamic limit. In part~III we show that after this Quantum Group
reduction Sklyanin's transfer-matrix $T(u)$ satisfies a closed system
of the Truncated Functional relations.
In part~IV we solve these equations for the case $LM(3,4)$.

\section*{II. Minimal Models of Integrable Lattice Theory}

Let us consider one dimensional XXZ chain with free
boundary conditions~\cite{ALC}
\begin{eqnarray}
   \label{eq:b}
   H_{xxz}&=&\sum_{n=1}^{N-1}[\sigma_n^{+}\sigma_{n+1}^{-}
   +\sigma_n^{-}\sigma_{n+1}^{+}
   +\frac{q+q^{-1}}{4}\,\sigma_n^z\sigma_{n+1}^z\nonumber\\
   & &\qquad
   +\frac{q-q^{-1}}{4}\,(\sigma_n^z-\sigma_{n+1}^z)]\\
   \sigma_n^\pm&=&1\otimes\ldots\otimes\sigma^\pm
   \otimes\ldots\otimes1\nonumber\\
   \sigma_n^z&=&1\otimes\ldots\otimes\sigma^z
   \otimes\ldots\otimes1\nonumber\\
   \sigma^{+}&=&\pmatrix{
      0&1\cr
      0&0},
\quad
   \sigma^{-}=\pmatrix{
      0&0\cr
      1&0},
\quad
   \sigma^z=\pmatrix{
      1&0\cr
      0&-1}
\nonumber
\end{eqnarray}

It was observed in~\cite{ALC,HAM} that the eigenvalues
of $2L$-site XXZ Hamiltonian~(\ref{eq:b}) with  the coupling
$\eta=\pi/4$ and $\eta=\pi/6$ (we denote $q\equiv e^{\imath\eta}$)
 are exactly coincide with some of the eigenenergies of
$L$-site self dual quantum Ising and 3-Potts models with free ends
(see also~\cite{ABF}).

The remarkable properties of the model are connected with its
$U_q(sl(2))$ symmetry found by Pasqier and Saleur~\cite{PS}.
Namely Hamiltonian $H_{xxz}$ commutes with the generators  $X$, $Y$, $H$ of
this quantum algebra defined as follows
\begin{eqnarray}
   & &  X=\sum_{n=1}^N q^{\frac{1}{2}(\sigma_1^z+\ldots+\sigma_{n-1}^z)}
 \sigma_n^{+}
q^{-\frac{1}{2}(\sigma_{n+1}^z+\ldots+\sigma_{N}^z)}\nonumber\\
   & &
   X\to Y,\quad \sigma^{+}\to\sigma^{-}\nonumber\\
   & &
   H=\sum_{n=1}^N\frac{\sigma_n^z}{2};\nonumber
\end{eqnarray}
and satisfy the following relations
\begin{equation}
   \label{eq:d}
   [H,X]=X,\quad [H,Y]=-Y,\quad
   [X,Y]=\frac{q^{2H}-q^{-2H}}{q-q^{-1}}
\end{equation}
Due to the Quantum Group symmetry the spectrum of the Hamiltonian
can be classified according to the Represenation Theory of the algebra.
For generic $q$ its representations are equivalent to the ones of
the ordinary $ U(sl(2)) $ algebra and the configuration space $({\bf C}^2)^N$
of the spin chain can be splited into a direct sum of irreducible
highest weight representations $ \rho _j $ ($j$ is the highest weight)
which are in one-to-one correspondence to the ordinary $ sl(2)$
representations.
For example in $N=4$ case $({\bf C}^2)^4$ can be decomposed as
$ \rho_2 + 3\rho_1 + 2\rho_0 $.

We will concentrate on the case $q^{p+1}=-1$~\cite {LUS,PS}.
In this case the generators $X$ and $Y$ are nilpotent
on the space of states of the model
\begin{equation}
 \label{eq:e}
   X^{p+1}=0, \quad Y^{p+1}=0
\end{equation}
As the consequence we obtain the very different picture of decomposition
the configuration space $({\bf C}^2)^N$.

For example if $q^4=-1$ and we try to decompose $({\bf C}^2)^4$ we get
the following~\cite{PS}.
The $({\bf C}^2)^N$ decomposes now into sum of one "bad" 8-dimensional
representation $(\rho_2,\rho_1)$  of type~I and four another
"good" representations $2\rho_2+2\rho_1$ of type~II~\cite{PS}.
The type~II representations are isomorphic to the ordinary $U(sl(2))$
ones. What about the type~I representation $(\rho_2,\rho_1)$ it can be
considered as a result of gluing of two representations $\rho_2$
and $\rho_1$. This  $(\rho_2,\rho_1)$ representation is
indecomposable,
but is not irreducible for it contains 3-dimensional invariant subspace.

In general $q^{p+1}=-1$ case~\cite{LUS,PS} the configuration space
splits into sum of ``bad" type~I representations with highest weights
$S_z\geq p/2$ and ``good" type~II repr-s with highest weights
$S_z< p/2$ which are simultaneously not subspaces of some ``bad" ones.
The highest weight vectors $v_j$ of the good repr-s can be
characterized~\cite{PS} by the following condition
\begin{equation}
 \label{eq:f}
   v_j \in V_p\equiv \mathop{\rm Ker}\nolimits X/\mathop{\rm Im}\nolimits X^p
\end{equation}
Because of $U_q(sl(2))$ invariance of $H_{xxz}$ we can restrict
its action on the space $V_p$.
We will call the result of this Quantum Group reduction as
the Minimal Model of Integrable Lattice Theory ($LM(p,p+1)$)
because its termodinamic limit is $M(p,p+1)$, the
ordinary Minimal Model of CFT with the Virasoro central charge
$c=1-\frac{6}{p(p+1)}$~\cite{ALC,PS,ZH}.

\section*{III. The Quantum Group reduction and the truncation\\
of the fusion functional relations}

The XXZ model(\ref{eq:b}) was solved by Alcaraz et al \cite{ALC}
using the coordinate Bethe ansatz method. Sklyanin constructed the
family of transfer-matrices $T(u)$~\cite{CHER,SKL,MN} commuting
between themselves and with $H_{xxz}$. It was shown in \cite{KUL}
that  Sklyanin's transfer-matrix $T(u)$ commutes with the Quantum
Group $U_q(sl(2))$. So  the action of $T(u)$ as well as $H_{xxz}$
can be restricted on the  space $V_p$ if $q^{p+1}=-1$.
To perform this Quantum Group reduction for $T(u)$ we will use
Baxter's $T$-$Q$ equation~\cite{ZH}
\begin{equation}
 \label{eq:g}
 t(u)Q(u)=\phi(u+\eta/2)Q(u-\eta) + \phi(u-\eta/2)Q(u+\eta)
\end{equation}
where $\phi(u)=\sin 2u\,\sin^{2N}u$ and $t(u)=\sin 2u\,T(u)$
and $Q(u)$  are  eigenvalues of Baxter's auxilary matrix $\hat Q(u)$
commuting with $\hat T(u)$.

The eigenvalue $Q(u)$ for the eigenvector with $M=N/2-S_z$ reversed spins
has the following form
\begin{equation}
 \label{eq:h}
 Q(u)= \prod\limits_{m=1}^M \sin (u-u_m) \sin (u+u_m)
\end{equation}
The equation (\ref{eq:g}) is equivalent to Bethe ansatz
equations~\cite{MN}
\begin{equation}
\label{eq:i}
\left[\frac{\sin (u_k+\eta/2)}{\sin (u_k-\eta/2)}\right]^{2N}=
\prod\limits_{m\not=k}^M \frac{\sin (u_k-u_m+\eta)\sin (u_k+u_m+\eta)}
   {\sin (u_k-u_m-\eta)\sin (u_k+u_m-\eta)}
\end{equation}
for the model (\ref{eq:b}) provided that $T(u)$ has no poles.

The Baxter's equation (\ref{eq:g}) can be thought as a discrete version of
a second
order differential equation~\cite{BLZ}.
So we can look for its second (linearly independent) solution $P(u)$ with
the same eigenvalue $t(u)$ as in (\ref{eq:g})
\begin{equation}
\label{eq:j}
t(u)P(u)=\phi(u+\eta/2)P(u-\eta) + \phi(u-\eta/2)P(u+\eta)
\end{equation}

It follows from (\ref{eq:g}) and (\ref{eq:j}) that
\begin{equation}
\label{eq:k}
\frac{Q(u+\eta)P(u)-P(u+\eta)Q(u)}{\phi(u+\eta/2)}=
\frac{Q(u)P(u-\eta)-P(u)Q(u-\eta)}{\phi(u-\eta/2)}
\end{equation}

If $\eta/\pi$ is irrational it means  that both parts of (\ref{eq:k})
are equal const and we can choose it be $1$. It means just a normalization
of $P(u)$. Thus we obtain the "quantum Wronskian" condition\cite{BLZ}
\begin{equation}
\label{eq:l}
  Q(u-\eta/2)P(u+\eta/2)-P(u-\eta/2)Q(u+\eta/2)=\phi(u)
\end{equation}

If $\eta$ is a rational part of $\pi$ the expresions in (\ref{eq:k})
could be equal a periodic function \\ $f(u)$ such that $f(u+\eta)=f(u)$,
but we  assume that in this case $f(u)$ is also equal to $1$.

Inserting (\ref{eq:l}) to (\ref{eq:g}) or (\ref{eq:j}) we obtain
\begin{equation}
\label{eq:m}
t(u)=Q(u-\eta)P(u+\eta)-P(u-\eta)Q(u+\eta)
\end{equation}

Let us divide (\ref{eq:l}) by $Q(u+\eta/2)Q(u-\eta/2)$, we get
\begin{equation}
\label{eq:n}
\frac{P(u+\eta/2)}{Q(u+\eta/2)}-\frac{P(u-\eta/2)}{Q(u-\eta/2)}=
\frac{\phi(u)}{Q(u+\eta/2)Q(u-\eta/2)}
\end{equation}

The r.~h.~s.\ of (\ref{eq:n}) a fraction of two trigonometric
polynomials. So there exist the single way to express it as
the following sum
\begin{eqnarray}
\label{eq:o}
\frac{\phi(u)}{Q(u+\eta/2)Q(u-\eta/2)}
&=&
R(u)+
\frac{A(u+\eta/2)}{Q(u+\eta/2)}-\frac{B(u-\eta/2)}{Q(u-\eta/2)}
\end{eqnarray}
where $R(u+\pi)=R(u)$ is a trigonometric polynomial whose
degree $degR(u)=2N+2-4M$ and $A(u+\pi)=A(u)$ and $B(u+\pi)=B(u)$
are some trigonometric polynomials whose degree are less than
$degQ(u)=2M$.
Then (\ref{eq:m}) can be rewritten as follows
\begin{eqnarray}
\label{eq:p}
\frac{t(u)}{Q(u+\eta)Q(u-\eta)}
&=&
R(u+\eta/2)+R(u-\eta/2)+\nonumber\\
&&{}+\frac{A(u+\eta)}{Q(u+\eta)}-\frac{B(u)}{Q(u)}-
\frac{A(u)}{Q(u)}-\frac{B(u-\eta)}{Q(u-\eta)}
\end{eqnarray}

The term $\frac{A(u)-B(u)}{Q(u)}$ in the r.~h.~s.\ must vanish for
it has extra poles which are absent in the l.~h.~s.\ of (\ref{eq:p}).
So we obtain that $A(u)=B(u)$ and hence
\begin{equation}
\label{eq:q}
\frac{\phi(u)}{Q(u+\eta/2)Q(u-\eta/2)}=R(u)+
\frac{A(u+\eta/2)}{Q(u+\eta/2)}-\frac{A(u-\eta/2)}{Q(u-\eta/2)}
\end{equation}

Provided that $F(u)$ is  such function that
\begin{equation}
\label{eq:r}
R(u)=F(u+\eta/2)-F(u-\eta/2)
\end{equation}
we can rewrite (\ref{eq:n})
\begin{eqnarray}
&&\frac{P(u+\eta/2)}{Q(u+\eta/2)}-\frac{P(u-\eta/2)}{Q(u-\eta)}=\nonumber\\
&&\qquad
=F(u+\eta/2)+\frac{A(u+\eta/2)}{Q(u+\eta/2)}-
F(u-\eta/2)-\frac{A(u-\eta/2)}{Q(u-\eta/2)}
\label{eq:u}
\end{eqnarray}

It means that we can choose the second solution of Baxter's equation
(\ref{eq:j}) in the following form~\cite{PRST}
\begin{equation}
\label{eq:v}
P(u)=F(u)Q(u)+A(u)
\end{equation}

The new constructed  solution of Baxter's equation is not a periodic
function in the general case. It is a periodic function if and only if
there exists a periodic solution of (\ref{eq:r}) $F(u)$.

We delay the discussion of the question when such solution does exist
and get now the consequences of its existence provided  it takes place.

Let us define the following function
\begin{equation}
\label{eq:w}
\textstyle
t_k(u)=Q\left(u-{(k+1)\eta\over2}\right)
P\left(u+{(k+1)\eta\over2}\right)-
P\left(u-{(k+1)\eta\over2}\right)
Q\left(u+{(k+1)\eta\over2}\right)
\end{equation}
where $k$ is any nonnegative integer.

Comparing with (\ref{eq:l}) and (\ref{eq:m}) we see that $t_0(u)=\phi(u)$
and $t_1(u)=t(u)$.
It is easily to obtain~\cite{PRST} from (\ref{eq:w}) the following
functional equations for $t_k(u)$
\begin{equation}
\label{eq:x}
\begin{array}{c}
t_k\left(u+{\eta\over2}\right)t_k\left(u-{\eta\over2}\right)-
t_{k+1}(u)t_{k-1}(u)=
\phi\left(u+{(k+1)\eta\over2}\right)
\phi\left(u-{(k+1)\eta\over2}\right)\\
\\
t_k(u)t_1\left(u-{(k+1)\eta\over2}\right)=
t_{k+1}\left(u-{\eta\over2}\right)\phi\left(u-{k\eta\over2}\right)+
t_{k-1}\left(u+{\eta\over2}\right)\phi\left(u-{(k+2)\eta\over2}\right)
\end{array}
\end{equation}

These functional relations~\cite{KR} coincide with the relations for
eigenvalues of the fused transfer-matrices of the XXZ model received by Zhou
in~\cite{ZH} and by Behrend, Pearce, and O'Brien in ~\cite {BPB} for
the ABF models with fixed boundary conditions.

Let us return now to the question about existence of the periodic
solution of (\ref{eq:r}).
Recalling that $\phi(-u)=-\phi(u)$ and the definition (\ref{eq:o})
of $R(u)$  we conclude that $R(u)$ also is an odd trygonometric
polynomial whose degree $degR(u)=2N+2-4M \geq 2$ provided
the number of the reversed spins $M$ is not more than $N/2$.
So such polynomial can be written as follows
\begin{equation}
\label{eq:y}
R(u)=\sum_{m=1}^{2N+2-4M}R_m\sin mu
\end{equation}
where $R_m$ are some coefficients which are defined from (\ref{eq:o}).

If $\eta/\pi$ is irrational the periodic solution of (\ref{eq:r}) does exist
and has the following form
\begin{equation}
\label{eq:z}
F(u)=-\frac12\sum_{m=1}^{2N+2-4M}\frac{R_m}{\sin\frac{m\eta}{2}}\cos mu
\end{equation}
But if  $\eta/\pi$ is rational number the situation is more
sophisticated. Namely we will concentrate on the case $\eta=\frac{\pi}{p+1}$
corresponding to $LM(p,p+1)$ model.
In this case we get from (\ref{eq:z})
\begin{equation}
\label{eq:A}
F(u)=-\frac12\sum_{m=1}^{2N+2-4M}
\frac{R_m}{\sin \frac{m\pi}{2(p+1)}}\cos mu
\end{equation}
So if we try to find the solution in sector when $2N+2-4M\geq 2(p+1)$
or equivalently $S_z\geq p/2$ we see from (\ref{eq:A}) that the periodic
solution does not exist. The reason is just a resonance.

Thus we conclude that a periodic $F(u)$ and the second periodic
solution of Baxter's equation exist if we apply it to subspaces
of the configuration space with $S_z<p/2$ !
We see that this inequality coinsides with the condition for
the Quantum Group reduction from the part II . So we arrive to the
main statement of this section:\\
{\bf The second periodic solution of Baxter equation for $\eta=\pi/(p+1)$
case exists if and only if the configuration space of the model
is undergone Quatum Group reduction}.\\
And for this case we have the additional relations for eigenvalues
of the transfer-matrices $t_k(u)$.
The equation (\ref{eq:w}) takes now the following form
\begin{equation}
\label{eq:B}
t_k(u)=Q\left(\textstyle u-\frac{(k+1)\pi}{2(p+1)}\right)
    P\left(\textstyle u+\frac{(k+1)\pi}{2(p+1)}\right)-
    Q\left(\textstyle u+\frac{(k+1)\pi}{2(p+1)}\right)
    P\left(\textstyle u-\frac{(k+1)\pi}{2(p+1)}\right)
\end{equation}
So we see that
\begin{equation}
\label{eq:C}
t_p(u)=0
\end{equation}
and
\begin{equation}
\label{eq:D}
t_{p-1-k}(u)=-t_k(u+\pi/2)
\end{equation}

So we obtain the second main statement of this section:\\
{\bf  Quantum Group reduction of the model is
equivalent to the truncation of functional relations }(\ref{eq:x}).
\footnote{This statement was also checked numerically by J.~Suzuki~\cite{SUZ}.}

\section*{IV. The solution of the truncated functional
           equatios. Case $\eta=\pi/4$.}

In the case $\eta=\pi/4$ (or $q^4=-1$) the truncated
fuctional equations take the following form
\begin{equation}
\label{eq:E}
t(u+\pi/8)t(u-\pi/8)=\phi(u+\pi/4)\phi(u-\pi/4)-
\phi(u)\phi(u+\pi/2)
\end{equation}
After substitution $\phi(u)=\sin2u\,\sin^{2N}u$ to (\ref{eq:E})
we obtain
\begin{equation}
\label{eq:F}
t(u+\pi/8)t(u-\pi/8)=2^{2N}[\sin^{2N+2}2u-\cos^{2N+2}2u]
\end{equation}
These equations have been considered and solved in ~\cite{BPW}
as the equations for the transfer matrix of Ising model on the
cylinder.

For $T(u)=\frac{t(u)}{\sin2u}$ we can rewrite
the last equation as

\begin{equation}
\label{eq:G}
2^{2N-1} T(u+\pi/8)T(u-\pi/8)=\prod_{k=1}^{N/2}|\varphi_k(u+\pi/8)|^2
|\varphi_k(u-\pi/8)|^2
\end{equation}
where we suggest $N$ be even and
\begin{equation}
\label{eq:H}
\varphi_k(u)=\sin(2u+\pi/4)-\omega^k\sin(2u-\pi/4)
\end{equation}
and $\omega=\exp \frac{\i math\pi}{N+1}$.

Using that $\varphi_k(u+\pi/8)=-\omega^k\varphi_k(u-\pi/8)$
we find $2^{N/2}$ real solutions of (\ref{eq:G})
\begin{equation}
\label{eq:I}
T(u)=T_{n_1,\ldots, n_{N/2}}\equiv2^{\frac{1-2N}{2}}
\prod_{k=1}^{N/2}|\varphi_k\left(u+\frac{\pi n_k}{4}\right)|^2
\end{equation}
where $n_1\ldots n_{N/2}=0,1$.

Another form the last expression is
\begin{equation}
\label{eq:K}
T_{n_1,\ldots, n_{N/2}}=2^{\frac{1-2N}{2}}
\prod_{k=1}^{N/2}\left[1+(-1)^{n_k}\cos \frac{\pi k}{N+1}\cos 4u\right]
\end{equation}

We recognize in integers $\{n_k\}$ the occupation numbers
of the fermions of one dimensional Ising model.
It is not suprising because $LM(3,4)$ exactly coincides
with Ising model as was mentioned above~\cite{ALC,HAM,ABF}.

\section*{Acknowledgements}

We are grateful to F.~Alcaraz, V.~Bazhanov, B.~Feigin, S.~Khoroshkin,
M.~Lashkevich, S.~Loktev, S.~Lukyanov,P.~Pearce, Ya.~Pugai, J.~Shiraishi and
J.~Suzuki for usefull discussions.A.~B. is very indebted to M.Lashkevich
for his help in the preparation of the TeX-version of this tekst.
We are thankful to Prof.P.Pearce who attracted our attention to works
~\cite{BPB,BPW}.
We would like to thank T.~Miwa for his kind hospitality in RIMS.
This work is supported in part by RBRF--99--02--16687,96--15--96821,
INTAS--97--1312 (A.~B.), RBRF--98-01-00070, INTAS--96--690 (Yu.~S.).

redpajama_set_name: RedPajamaArXiv


text:
Przebojowa noc – polski program rozrywkowy, którego prowadzącymi byli Natasza Urbańska, Janusz Józefowicz oraz Radosław Brzózka. Pierwszy cykl programów emitowany był od 9 września do 24 listopada 2007 w TVP1, w każdą sobotę o godzinie 22:05. Autorem formatu oraz reżyserem programu był Janusz Józefowicz. Gwiazdą każdego odcinka była m.in. aktorka, tancerka i piosenkarka Natasza Urbańska.

Program był zrealizowany na podstawie serii widowisk artystycznych tzw. "Wieczorów w Buffo" wystawianych w teatrze muzycznym Studio Buffo. Kierownictwo muzyczne objęli Janusz Stokłosa i Tomasz Filipczak, zaś za kostiumy odpowiadała Agnieszka Komornicka. Nagrania programu odbywały się w hali "Mera" w Warszawie.

Od 8 grudnia 2007 w TVP1 emitowany był drugi cykl programów o nazwie Złota sobota.

Zasady programu
Każdy odcinek poświęcony był muzyce z innego kraju. Podczas programu widzowie wybierali swoją ulubioną zagraniczną piosenkę w wydaniu włoskim, rosyjskim, amerykańskim, czeskim, niemieckim, francuskim, hiszpańskim, angielskim, żydowskim, latynoskim, austriackim, węgierskim, irlandzkim, greckim, australijskim, szwedzkim i kanadyjskim. Oprócz Nataszy Urbańskiej i Janusza Józefowicza w programie pojawiała się także zagraniczna gwiazda pochodząca z kraju, któremu poświęcony był kolejny odcinek. Gośćmi programu były także polskie sławy, w tym m.in. artyści, dziennikarze, sportowcy i politycy.

Goście specjalni
 Michael York – 9 września 2007
 Paul Anka – 15 września 2007
 Serebro – 22 września 2007
 Drupi – 29 września 2007
 Patricia Kaas – 6 października 2007
 Paul Young – 13 października 2007
 Dana International – 20 października 2007
 Ive Mendes – 27 października 2007
 Lou Bega – 3 listopada 2007

Spis odcinków
Poniższy spis uwzględnia daty emisji poszczególnych odcinków oraz listę piosenek i ich wykonawców w danym odcinku.

Skład zespołu Teatru Studio Buffo w programie Przebojowa noc
W skład zespołu Teatru Studio Buffo biorącego udział w programie Przebojowa noc weszli (w kolejności alfabetycznej):
Monika Ambroziak, Paweł Bączkowski, Iwan Biełkow, Paweł Biełkow, Michał Bogdanowicz, Mariusz Bromirski, Kamila Bujalska, Jan Bzdawka, Artur Chamski, Joanna Chmielewska-Chłopicka, Justyna Chowaniak, Mariusz Czajka, Anna Dereszowska, Barbara Deska, Emilia Dębska, Wojciech Dmochowski, Dominika Gajduk, Jędrzej Gociałkowski, Joanna Gołębiowska, Jerzy Grzechnik, Jarosław Janikowski, Janusz Józefowicz, Marina Łuczenko, Grzegorz Kowalczyk, Tomasz Krajewski, Karolina Królikowska, Natalia Krakowiak, Andrzej Kubicki, Magdalena Kumorek, Nicole Mirpuri, Paulina Mechecka, Mariola Napieralska,  Weronika Pelczyńska, Elżbieta Portka, Aleksandra Popławska, Antoni Powierża, Katarzyna Pypno, Paweł Orłowski, Maciej Robakiewicz, Krzysztof Rymszewicz, Krystian Sacharczuk, Paweł Skałuba, Natalia Srokocz, Bartłomiej Stec, Janusz Stokłosa, Paweł Suski, Joanna Teśla, Aneta Todorczuk-Perchuć, Maria Tyszkiewicz, Beata Urbańska, Natasza Urbańska, Joanna Wiśniewska, Weronika Wojciechowicz, Anna Wojczuk, Marta Wyłomańska, Michał Zawadka, Aleksandra Zawadzka,

Konkursy

Konkurs SMS
Konkurs SMS-owy na najlepszą piosenkę wieczoru oraz debiutanta:

 Najlepsza piosenka wieczoru
 Wieczór amerykański: Paul Anka – "Diana"
 Wieczór rosyjski: Natasza Urbańska – "Biełyje rozy"
 Wieczór włoski: Rafał Bartmiński – "'O sole mio"
 Wieczór francuski: Janusz Józefowicz – "Et si tu n'existais pas"
 Wieczór brytyjski: Jerzy Grzechnik – "Bohemian Rhapsody"
 Wieczór żydowski: Aleksandra Zawadzka – "Czumbalalajka"
 Wieczór latynoski: Teatr Studio Buffo – "Lambada"
 Wieczór niemiecki: Jerzy Grzechnik – "Wind of Change"
 Wieczór polski: Janusz Józefowicz – "Biały krzyż"
 Najlepsza z najlepszych:
 Jerzy Grzechnik – "Bohemian Rhapsody"

Debiutanci
 Jakub Józefowicz i The Age of Grapefruit
 Krystian Sacharczuk
 Krzysztof Rymszewicz
 Jerzy Grzechnik
 Marina Łuczenko
 Marysia Tyszkiewicz
 Natalia Srokocz
 Justyna Chowaniak
 Emilia Dębska
 Aleksandra Zawadzka
 Katarzyna Pypno
 Natalia Krakowiak
 Mariola Napieralska

Zwycięzca debiutów: Jerzy Grzechnik

Konkurs MMS - Pokaż co potrafisz!
Pokaż co potrafisz! był MMS-owym konkursem tanecznym dla telewidzów. Janusz Józefowicz i Natasza Urbańska podczas każdego odcinka Przebojowej nocy prezentowali układ choreograficzny do nauki dla widzów przed telewizorami i w studiu. Co tydzień para wyłaniała najlepszy taniec.

Oglądalność

Emisja
 sobota, godz. 21:55 - TVP1
 sobota, godz. 15:05 TVP1 (powtórka)
 sobota, godz. 21:05 TVP Polonia (powtórka)
 Program można również oglądać na iTVP

Przypisy

Telewizyjne programy rozrywkowe
Polskie telewizyjne programy muzyczne


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TEHRAN – Iran's Jowzan Valley traditional grape cultivation system has formally been recognized as Globally Important Agricultural Heritage System, during a meeting of the GIAHS Scientific Advisory Group, which was held in Rome from November 28 to 30.
The same privilege was also granted to Italy's Soave vineyards as the group approved their unique ways of growing grapes and grape-based products using traditional practices and knowledge while preserving biodiversity and ecosystems.
It is the second time that sites in Italy and Iran are added to the global agricultural heritage systems list. FAO's global agricultural heritage network now consists of 54 remarkable landscapes in 21 countries around the globe, FAO website reported.
The selection criteria includes that sites be of global importance, have value as a public good in terms of supporting food and livelihood security, agro-biodiversity, knowledge systems, adapted technologies, and culture, and have outstanding landscapes.
According to the FAO, Jowzan's farmers make the grape cultivation possible in extreme cold conditions thanks to unique techniques while traditional knowledge and tools allow the farmers to process more than 40 different grape products out of 130 different grape varieties.
Over the years, the system has significantly improved the people's living standards, but also provided an impetus for tourism development, and a unique opportunity to boost rural economy.
Jowzan Valley is situated in Malayer county, Hamedan province.


text:
Norview's Jada Bryant shows out on the same court her big brother, Joe, stars on to lead the No. 3 Pilots over Monacan
The story of white sauce, Virginia's unique contribution to Mexican American cuisine
CHKD seeks state approval for a $50 million mental health facility
By Elizabeth Simpson
In a move he described as tectonic, the president of Children's Hospital of The King's Daughters said the health system will expand its mental-health footprint in the community with a proposal for a $50 million psychiatric center.
The hospital must get state approval before moving forward, but president and CEO Jim Dahling said CHKD is committed to embracing what its community surveys have shown to be the No. 1 health concern: mental health services for children.
Three to five children a day arrive in the hospital's emergency room in need of a mental health evaluation, a number that has increased by 40 percent during the past four years, according to CHKD.
If the children have both a medical and psychiatric condition, they can be admitted for inpatient care. But if their sole diagnosis is psychiatric, they need to be referred to a psychiatric facility. In some situations, such as eating disorders, that means traveling out of state.
The hospital submitted paperwork to the Virginia Department of Health on March 1 to build a new medical tower, to be located just off Brambleton Avenue, on the same medical campus as CHKD, Eastern Virginia Medical School and Sentara Norfolk General Hospital. The tower would have three floors for mental health "day treatment" programs and 48 inpatient beds. Two more floors would be for other medical services, and four underground levels would be for parking.
The expanded mental health program would employ about 250 health care providers and support staff, and treat children 2 to 18 years of age.
The request for a "certificate of public need" would also include 12 beds in the current hospital for inpatient psychiatric treatment. The proposal will be reviewed by the state health officials to make sure the need for services is justified. A public hearing also will be conducted, likely in May or June. The state health commissioner is expected to make a final decision by early August.
"Everyone from parents to social workers to government agencies to school systems are telling us that mental health services for children are the No. 1 priority," Dahling said in an interview Tuesday.
National statistics are showing that 1-in-5 children need mental health services.
"The tipping point was the frequency of children coming into the ER in crisis," Dahling said. "Parents are saying, 'Please help.' There are simply not enough localities to place them. They stay in the ER sometimes for a day. You roll all of that together, and we cannot walk away."
A five-day snapshot of 14 mental health patients seen in the ER included:
A 5-year-old with a history of setting fires, and being violent to animals and adults.
A 16-year-old who took his parent's diabetes medication after experiencing suicidal thoughts. His brother died by suicide at 13.
A 13-year-old who experienced sexual assault and later overdosed on Benadryl.
An 8-year-old who expressed suicidal and homicidal thoughts and tried to jump out of a second-story window.
Currently, the system receives 15 to 20 mental health referrals a day from primary and specialty care providers. One day in February, 153 children were on the waiting list, with waits as long as six weeks.
The hospital has one psychiatrist and is now recruiting for more, but a national shortage has made that challenging.
Stephanie Osler, director of mental health services at CHKD, said there are four local inpatient units they can refer children to: Kempsville Center for Behavioral Health in Norfolk, Maryview Behavioral Medicine Center in Portsmouth, Riverside Behavioral Health Center in Hampton, and Newport News Behavioral Health Center in Newport News.
But there have been times when those facilities have been full or the situation would not be good for the child. For instance, if it's a young child or someone with autism, or a child who is gay, lesbian or transgender, sharing a room, or even a unit, would be difficult. Parents and caregivers often have to travel to Staunton, which has a state children's mental health facility, or to Northern Virginia, or even out of state.
Osler said it's particularly hard to find appropriate programs for children with eating disorders. The system has also struggled to find treatment for children as young as 3 or 4 getting kicked out of day-care and preschool settings because of behavior problems.
Courtney Boone, president of the Virginia Beach chapter of National Alliance on Mental Health, said parents with children who need mental health services often go outside the region, creating hardships for the children and parents. She shared an email from a local mother:
"When you are at the point of needing acute care for your child, neither of you are in a place you want to be. If you have done it more than once, a bad experience at a previous placement can also cause anxiety for both of you, and sometimes as a parent, you can delay getting needed help because of the options available."
Another woman, a 59-year-old Norfolk mother of a 13-year-old daughter and a 10-year-old son with mental health issues, said she's had to take her son to Johns Hopkins University in Baltimore for treatment for brain injury and psychiatric problems, and her daughter to Northern Virginia.
She and her husband were foster parents of the two children, who were severely abused when they were young, and they have since adopted them. "She was 4 years old when she was traumatized, but it's like it was yesterday," said the mother, who asked not to have their names used to keep private their background of abuse and mental illness.
They are both in and out of the hospital. At times, her daughter has had to wait more than a day at CHKD before a psychiatric bed was found for her.
"It's a shame to have to go so far to get help," she said. "Northern Virginia? That's ridiculous. That's shameful. But for so many people, that is what we have to do."
Amy Sampson, vice president over mental health services for CHKD, said that in the past, the health system has typically focused on medical and surgical needs of children and handed off acute psychiatric care to other facilities. But so many medical conditions have a psychiatric component, and the rate of children experiencing mental health problems is on the rise.
One pediatrician made the observation that diagnoses were shifting from typical ear infections to attention deficits, depression and obsessive-compulsive disorders: "I am stymied here and have little to no assistance. It is like fighting a battle and I am not armed."
In 2014, the health system assigned six licensed clinical social workers to do mental health assessments and interventions. The first year, the system's mental health team did 3,500 visits. Since then the number of mental health therapists assigned to that duty has grown to 25 and they are on track for 18,000 visits at nine different CHKD locations this year.
That was the first step in bolstering mental health services, along with getting mental health training for pediatricians.
"We want to give children a gliding path, post-discharge, so they don't end up back in the ER two weeks later," Dahling said.
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If the system gets state approval, it would take two years to get the 12 beds in use in the current hospital and four years for the new facility to be built.
The King's Daughters, founding organization of CHKD, has pledged $1 million to the mental health initiative. Dahling said the health system will be talking with government officials, community leaders and philanthropic organizations to raise funding for the effort.
Dahling said the move will eclipse the most recent shift in strategy, which was when they began building medical centers and urgent care clinics in other parts of the region 15 years ago.
"It's extremely exciting," he said. "And a little terrifying."
Elizabeth Simpson, 757-222-5003, elizabeth.simpson@pilotonline.com
Psychiatric Care
Certificate Of Public Need
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In today's globalized and ever-changing world, we are constantly faced with rapid shifts in various aspects of our environment and social landscape. It is important that as Singaporeans, we know our history as a nation and feel grateful of how far we have come together as one. It is also important that we are aware of and understand Singapore's achievements, uniqueness and heritage so that we can stand ready to respond to future challenges and opportunities in a timely manner.
According to the Heritage Awareness Survey conducted in 2014, 80% of Singapore residents agree that it is important to preserve all aspects of Singapore's heritage for current and future generations. 74% of Singapore residents agree that it is important to learn about the cultures and traditions of the countries our ancestors came from (e.g., cultures of China, India, the Malay Peninsula, etc.)". The Singapore Cultural Statistics 2017 also shows growing interest amongst Singaporeans in exploring their heritage and what it means to be a Singaporean.
With that in mind, a customized school-based curriculum was designed to educate our Primary 1 students on the following: Singapore's Hawker Culture and the origins and significance of festivals such as Dragon Boat Festival (Duan Wu Jie) and Pongal. On top of engaging in discussions with friends and teachers, real-life photos and videos were also used to illustrate and exemplify the various aspects of Singapore's Hawker Culture and festivals (food, rituals and significance).
Our students also got into action to design a poster to promote Singapore's hawker culture!
By recognizing and being aware of a shared common heritage, it helps to facilitate a deeper and stronger understanding of our cultures and traditions. This helps to encourage and foster national, community and personal identities which are pivotal to the development and growth of a more cohesive, confident and resilient society. Through these lessons, we are confident that our students will continue to contribute towards creating a cohesive society by valuing and engaging with Singapore's rich and multicultural heritage – enabling them to feel proud about Singapore and our connections to the world.
15 February is the day where Singapore commemorates "Total Defence Day". It is an important day that reminds us of 15 February 1942 – the day where Singapore fell to the Japanese troops. On this memorable day, Minister for Communications and Information and Minister-in-Charge of Cybersecurity, Mr S Iswaran, had officiated the launch of Digital Defence as the sixth pillar of Total Defence during the event, joining the other 5 pillars, namely Military Defence, Civil Defence, Economic Defence, Social Defence and Psychological Defence.
rootedness to Singapore. With the introduction of the new pillar for Total Defence – Digital Defence in 2019, the Character and Citizenship Education (CCE) department recognises the serious dangers that disinformation and cyber-attacks can pose to Singapore's social cohesion in this open and connected city-state.
Fake news are becoming increasingly sophisticated and pervasive, and they can be challenging to detect. With that in mind, a customized school-based curriculum was designed to educate our Primary 2 students on what fake news is all about and the importance of knowing how to discern between real news and fake news. Students discussed and worked together in pairs to apply the newly-learnt S.U.R.E (Source, Understand, Research and Evaluate) strategy on selected news articles to determine whether it is real or fake.
The concept of empathy was also explored when students discuss and think about the impact of fake news on its victims. If there is a possibility that a piece of information may be untrue, we can play our part in not encouraging fake news by not posting or forwarding it. We look forward to our Kellock girls continuing to display the Kellock Girl values of graciousness, integrity, and responsibility not only in the real world, but also in the digital world!


text:
D'Andra Simmons
Kary Brittingham Discusses Joining The Real Housewives Of Dallas
The Real Housewives of Dallas is one of the best kept secrets on Bravo. Although the show and its stars don't always get the attention or recognition of some of the other Housewife shows, the cast usually delivers. The ladies have real money, throw real drama and they aren't afraid to embarrass themselves on camera. Over and over. Isn't that right, Brandi Redmond?
Last season, we watched the painful disintegration of the friendship of LeeAnne Locken and D'Andra Simmons. Stephanie Hollman touchingly shared her history of mental health issues and how she has worked to overcome them. Kameron Wescott continued to welcome us into her fabulous pink and sparkly world. Now, a new lady has been added to the cast of RHOD.
Real Housewives Of Dallas
Kameron Westcott, Stephanie Hollman, & Other Real Housewives Of Dallas Stars Hint At New Housewife's Identity On Social Media
by Reality Teaon July 16th, 2019
Fans are eagerly anticipating Real Housewives of Dallas Season 4. Confessional interview photos hit social media, which included all of last season's cast members except for Cary Deuber. It seems like she got the Vicki Gunvalson treatment with a demotion to Friend of the Housewives status.
Ironically enough, it seems like she was replaced by someone who has the same first name, but with a different spelling. RHOD cast member Kameron Westcott hinted at the casting change. Even the new Real Housewives of Orange County star Braunwyn Windham-Burke got in on the social media hints.
Real Housewives Of Dallas,Real Housewives of Orange County
Gretchen Rossi Gives Birth To First Child After Years Of Fertility Struggles
by Glenn Rowleyon July 10th, 2019
Gretchen Rossi has given birth to her first child. Following a years-long struggle with infertility, the former Real Housewives of Orange County star welcomed daughter Skylar Gray on Wednesday, July 10.
The baby's father is Gretchen's fiancé and longtime love and OG Real Housewives of Orange County cast member Slade Smiley.
Real Housewives Of Dallas Visit Thailand- Check Out Photos Of Kameron Westcott, LeeAnne Locken, Stephanie Hollman, & D'Andra Simmons
by Reality Teaon May 29th, 2019
Social media can say a lot about a reality TV show in between seasons. For the most part, it is very easy to confirm who is filming for the next season. Conversely, it's a lot more difficult to determine who is not a part of the cast, or who got downgraded to a lesser role. There are some Real Housewives who don't post too much while filming for the sake of revealing spoilers.
But, for the most part, the Housewives love sharing their lives with the fans. Recently, Real Housewives of Dallas stars LeeAnne Locken, Stephanie Hollman, Kameron Westcott, and D'Andra Simmons posted photos from Thailand. But what about Brandi Redmond and Cary Deuber? Those OG Real Housewives of Dallas cast members did not post about Thailand at all on social media. Are they saving the pictures for a #tbt post? Or did they not go on the vacation? If it's the latter, does that mean they aren't a part of the show?
Hot Photos,Photos,Real Housewives Of Dallas
Gretchen Rossi & Slade Smiley's Baby Shower- Check Out Photos Of Scheana Marie, Phaedra Parks, D'Andra Simmons, & More!
Real Housewives of Orange County alums Gretchen Rossi and Slade Smiley have a baby girl on the way. It's the couple's first child together and they could not be more excited, especially after their tough journey to conceive.
Gretchen and Slade had a lavish baby shower for their soon-to-be baby girl Skylar Gray at the Seven 7 Seven in Laguna Beach, CA. There were actually a lot of past and present Bravolebrities present at the party. The event was beautifully decorated thanks to Ice Age Glacial Water, Chandon Champagne, Distillery 291, Glamour Flower Boutique, The Balloon Box, and Invitation Design Studio.
Hot Photos,Millionaire Matchmaker,Photos,Real Housewives of Atlanta,Real Housewives Of Dallas,Real Housewives of Orange County,Shahs of Sunset,Vanderpump Rules
Real Housewives Of Dallas Star LeeAnne Locken Is Married!
by Reality Teaon April 29th, 2019
Congratulations to LeeAnne Locken and Rich Emberlin! The Real Housewives of Dallas couple tied the knot on Saturday, April 27. And, it seems like they filmed the big day for Season 4. Or at least I hope they did since there were plenty of cast members present.
Plus, they did get engaged on the show. Why wouldn't she film the wedding for next season? Especially after D'Andra Simmons and Brandi Redmond said it was never going to happen. And, no, it doesn't seem like they attended. Or maybe they just kept the photos on the wraps for the sake of a storyline. But, it was most likely the first scenario.
Real Housewives Of Dallas Star Kameron Westcott Throws Wedding Shower For LeeAnne Locken- Photos
Real Housewives of Dallas star LeeAnne Locken got engaged to Rich Emberlin two seasons ago. Last season, D'Andra Simmons gave her a hard time about setting the date… among other things. Now, the future Mr. and Mrs. Emberlin have a date and they are moving full speed ahead with the pre-wedding events.
Fellow RHOD cast member Kameron Westcott even threw the wedding shower. It was a co-ed affair with significant others included. However, not everyone in the cast made the cut since it was a private event with about twenty people. Who was there? Who wasn't? How did everything look?
Exclusive Interview: Get To Know Another Side Of Kameron Westcott From Real Housewives Of Dallas
When Kameron Westcott first joined Real Housewives of Dallas, I couldn't help wondering what Nicole Kidman was doing on TV and why she was dressed like Elle Woods, the iconic character from Legally Blonde. Seriously though, if Nicole Kidman needs a body double, Kameron would be a prime candidate.
Right from the jump, she came through with a great tagline: "Dumb blondes get noticed. Smart blondes get everything." You would think that a Nicole Kidman doppelganger, with an all pink wardrobe, and a genuine passion for philanthropy would be an immediate hit among the fans.
However, it hasn't been an easy road for Kameron. And part of that is because the viewers don't get to see every side of Kameron. Sure, they don't get to see every side of any reality TV star. Nevertheless, there is more to Kameron than an enviable wardrobe and chatter about "Dallas society." Much, much more. Get to know a different side of the Dallas Housewife in our exclusive interview!
And, yes, she does discuss the Season 3 reunion fights with D'Andra Simmons and Brandi Redmond. She even answers some critical questions about her close relationship with LeeAnne Locken. This is truly a side of Kameron that you've never seen before.
Interviews,Real Housewives Of Dallas


Effectra is a map where you are tasked to complete Elytra courses but with a twist!
This map will make you rage, all the levels have been tested and are possible.
- Added Kill rod (Kills you when you right click).
- Cleaned up the map.
- Fixed when effects don't work when out of chunk.
Very glitchy and lvl 4? How is it possible? And I don't believe 12-year-old did it in 2 hours.
0 TraYCZ Very glitchy and lvl 4? How is it possible? And I don't believe 12-year-old did it in 2 hours.
What level is impossible? They have all been tested and are possible, also I have updated the map so it's not easy to cheat on, I have added more stages and updated the command blocks so it's not glitchy.
+2 RedDeadDevil1908 Hey guys I've recently noticed a glitch where If die or teleport while using an elytra you get stuck in the ground, all you have to do is shift and it should be fixed. :D I'm also going to update the map so you get some sort of stick/fishing rod that when you right click it kills you so it saves you the hassle of typing /kill all the time.


text:
Fargo Featured: Forestry
January 13, 2023 - 3:27pm | By Ty Schonert
Courtesy: Fargo's Forestry Department
(Fargo, ND) -- Scott Liudah, Fargo's City Forester, spoke to WDAY Radio about the roles and responsibilities of the department, how they manage species trees across the city, and how they work to educate the public about trees in their neighborhoods.
The Forestry Department's primary goal is to manage over 60,000 trees across Fargo's right-of-way. The department tasks itself with tree care and maintenance, disease identification and prevention, removal and risk assessment of trees for public safety reasons, and answering city resident's questions. Their services are overwhelmingly done in publicly owned land that aren't in the city's parks, which are managed by Fargo's Park District. However; citizens can normally request tree inspections for various reasons, including plant disease or overall risk assessment for the health of the tree.
"Most individuals think our responsibility is urban tree care, urban tree health - and of course it is, but our primary responsibility is public safety for starters, "said Liudahl, "We've got a large population of mature trees. Our responsibility is making sure public streets and sidewalks are safe for the public to utilize."
The Forestry Department says they prioritize public safety by ensuring streets and sidewalks are safe to use, especially following severe wind or winter storms. Forestry also works in tandem with local companies to prune, trim, shape, and possibly trees that have grown near power lines and other important infrastructure.
Tree Diversity and Disease Watch
The Forestry Department has several proactive measures and ordinances in place to stop the spread of two types of tree based diseases. Two diseases in particular are a high-priority within Fargo, Dutch Elm and Emerald Ash Borer. These two diseases target the two biggest tree species within Fargo, Elm and Ash.
Liudahl says one of the best ways to address tree diseases is species diversity. At one point in time, Elm represented more than 40% of all trees in Fargo. Liudahl says a switch from Elm to Ash was an attempt to fight against the highly prevalent Dutch Elm disease. The disease was threatening nearly half of the city's trees in the 1970's. Officials replaced the fallen or removed Elm with Ash trees, replacing the formerly dominant species and representing 40% of a all trees across the city. Liudahl says the Forestry Department is now proactively working to reduce the number of Ash trees before Emerald Ash Borer makes its way to the Red River Valley.
The watch for Dutch Elm and Emerald Ash Borer disease leads to the department having some jurisdiction when it comes to firewood entering and leaving Fargo. Only one type of firewood is banned within the city, elm with bark still on the log. This is because these logs are great habitats for Elm Bark beetles, which often carry a fungus that causes Dutch Elm Disease in Elm trees. The department watches for Emerald Ash Borer by setting baited traps for the beetles, who's larvae destroy Ash tree's ability to transport nutrients and water effectively. Emerald Ash Borer is credited with the destruction of hundreds of millions of Ash trees across the U.S. That is why Liudahl says the department is frequently investigating and surveying the vulnerable population.
"About 2010 is when we really started to throw in our diversity and bring down our Ash population down because we didn't want another Elm situation..."said Liudahl, "The closest is probably Center Minnesota, Winnipeg for sure, Sioux Falls has been dealing with it for a couple of years, it's out west. It's around us, and we are kinda right there too. It's just a matter of when it is confirmed."
Liudahl says a lot of the work he does these days corresponds to the education aspect of Forestry. He speaks at local gatherings, clubs, schools, and other locations upon request, often saying it is one of the more important aspects of his job.
One of the ways the department shares information with the public is through an interactive map of the 60,000 trees across Fargo. Liudahl says often shares the map with residents who want to learn more about the trees in their neighborhood, but also uses it to keep track of tree species diversity city-wide. Other tools used by the Forestry department includes a Street Tree Photo Gallery, instructions on the Brush Recycling Program, Planting Permit instructions, and more.
You can learn more about Fargo's Forestry Department by clicking here.
Original Air Date:
Fargo Featured
Forestry Department
Scott Liudahl
Fargo Featured: Fargo Cass Public Health
Fri, Dec 30th, 2022 - 5:46pm
Fargo Featured: Assessor's Office
Fri, Dec 9th, 2022 - 6:00pm
Fargo Featured: Fargo Public Library
Fri, Nov 18th, 2022 - 7:53pm
Fargo Featured: Fargo City Commission
Fri, Jan 6th, 2023 - 5:10pm


A rare opportunity to rent this open plan area with glass frontage.
The premises is located in a beautiful heritage building in the hub of Balmain and is available now for a short or long term lease.
The premises is located on the ground floor and is surrounded by busy coffee shops and restaurants.
Suitable for an office, retail shop or pop up shop.


Discover the 12 points that clarify the impact of nicotine on health and its use when applied to e cigarette or inhaled in cigarette smoke.
We are sometimes scared by DIY e liquid. Where to start ? Here are recipe ideas for a satisfying vape juice.
Both a preservative and a diluent, propylene glycol is a major ingredient in electronic cigarette e liquids. But what exactly do we know about it?
Are e-cigarette flavoring really dangerous ?
The media are trying to spread their articles on the dangerousness of e liquid flavoring. But are there flavors more dangerous than others ?
What about diacetyl in e liquid ?
The media regularly emphasize the presence of diacetyl in electronic cigarette e juices. But what is the truth of their claims ?


The college sector needs to be reformed, Boris Johnson has said.
The mayor of London has confirmed that he will be involved in the area review of FE provision in the capital, but said the process was still "in the early stages".
Reviews of FE provision by region were announced by the government earlier this year, with the intention of creating "fewer, larger and more financially resilient organisations". To date, seven regional reviews have been announced. The review of provision in the capital is expected to begin in spring 2016.
When asked what he believed London's college sector should look like after the review, Mr Johnson told TES: "It is premature to comment on that, but it is clear the sector needs reform."
Speaking after visiting the London Skills careers event this afternoon, Mr Johnson said public opinion on apprenticeships had shifted, with many more people seeing them as promising career paths.
Mr Johnson said they were "one way" of addressing the capital's skills needs, and could help young people "get into some of the more technical and difficult industries" the current education system was not preparing them for.