This is the perfect tour for Madagascar discovery, it combines everything the Island has to offer. It is a total immersion in the country where you will be spoting the rare, endemic fauna and flora, you will appreciate the Malagasy know-how and will be relaxing in one of the most beautiful golden beaches in the world.
Speak to one of our specialists today, we can tailor made this holiday according to your taste.
Immerse yourself in a tour full of luxury discovery. From wildlife to culture, you will fulfil your curiosity about Madagascar. You will be discovering different species lemurs, national parks with unique wildlife, stunning landscape, and diverse cultures as you journey through varied landscape from highland to the semi-arid South. You will enjoy walking in the breathtaking varied scenery, spotting nocturnal animals in the night walks, meeting Malagasy tribes along the way and understanding the conservation in practice.
''Manao ahoana'' & ''Salama'' Welcome to tropical paradise. You will be welcomed & greeted by your guide or representative on arrival at Antananarivo Ivato International Airport. You will be transferred to your hotel in Antananarivo. The travel time will be approximately 10 minutes depending on the road traffic.
Today you will fly from Antananarivo to Fort Dauphin. Fort Dauphin, the city at the end of the world, offers exceptional scenery. Nestled at the foot of the Saint Louis' peak, the city and its regions offer incredible walks in breathtaking scenery.
Azura Hotel & Spa is located close to Beach Libanona in Fort Dauphin, Madagascar. The hotel boasts elegant and well decorated rooms.
Set on the banks of the Mandrare River, your accommodation is a fantastic base to explore the surrounding forests and mountains.
Your accommodation has a whole range of exciting excursions for you to choose from.
The seclusion of Mandrare River Camp affords intimate access and insight to the spiny forest; home to an abundance of unique wildlife and the fascinating Antandroy tribe that inhabit this arid and otherworldly landscape.
After breakfast you will depart from the hotel on the Evatra tour to the stunning Lokaro Bay in Fort Dauphin.
You will travel to Lake Lanirano where you will board a small boat. As you cross Lake Lanirano to Evatra you will pass through a lagoon and river mangroves with aquatic vegetation such as elephants' ears and palm trees where you may spot endemic birdlife. This exciting boat journey will take approximately an hour and a half.
When you reach Evatra, the traditional fisherman village, you may have the chance to meet the Antanosy people. Here you will begin a 3-4 hour hike depending on your level of fitness. During your hike, you will pass beautiful creeks, visit the local village and experience the enchanting Lokaro Bay. Here beach lovers can enjoy a refreshing swim and visit the deserted coves known for snorkelling and diving. You will then continue to get a great view of the second village of Evatra called Fisherman's Bay. En route to Mahanoro, enjoy a stunning 180° panoramic view where you may spot some whales during July to August. For lunch, you will stop at the bay of Mahanoro where you can enjoy a cooked picnic seafood lunch with a view of the tropical turquoise water. This region is famous for its seafood. In the afternoon, depending on the weather, you may get to swim so don't forget your swimwear.
At approximately 16:00pm, you will begin your return to Fort Dauphin by hiking and taking the boat via the same route across Lake Lanirano. After your boat trip you will transfer by car to your hotel.
Today you will be transferred to Fort Dauphin airport for your flight to Antananarivo.
Today you will be transferred to Antananarivo airport for your flight to Anjajavy.
Anjajavy le lodge is located on the west coast of Madagascar 120 kilometres north of Majunga. Anjajavy is a remote fishing village on an extraordinary peninsula at the heart of the Boeny Sakalava territory. The lodge along this welcoming peninsula is set on a private stretch of 550 hectares surrounded by water and is a shining example of sustainable conservation.
Relax at Anjajavy. Anjajavy le lodge has plenty to offer on land and in the sea.
Within the 750-hectare private natural reserve, there are a wide variety of wonderful walks that you can do on your own with a clear map, or with one of the hotel's guides. Discover the majestic baobabs and unusual tsingy. There is a wonderful beach perfect for a swim, as well as a 200 metre infinity pool. The Marina, on the Mozambique Channel, protected from the wind, is also a good spot. A wide variety of water based activities are available from the beach in front of the hotel and from the marina.
Today you will fly to Antananarivo.
In the evening, witness the best sunset with Sundowner drinks and dinner at Lokanga. It is the best place to say "cheers" to a great trip around Madagascar with a glass of wine, a beautiful view of Antananarivo and to look back at the great memories you have made.
This small boutique hotel is within the same building as the Consulate of Monaco. Therefore you will have a rare opportunity to stay at the Ambassador's house.
Depending on your flight time you will travel to the airport to fly back home.


text:
Q: How do I retrieve an image uploaded to Amazon S3 via CollectionFS:S3 In a Meteor project I am using CollectionFS:S3 to save images to a bucket in S3. I'm not able to see how to load them back into the project.
I have tried to use the FSFile.url() method as show in the code below but it's returning:
/cfs/files/images/e6jQ4Txgvb37GisEQ/imagename.jpg?token=XXX
I was expecting an Amazon S3 url as in s3-eu-west-1.amazonaws.com/mybucket/myfolder/imagename.jpg
view.html:
  {{#each images}}
    URL: {{this.url}}

  {{/each}}

view.js
 images: function () {
  return images.find();
 }

All examples I can see on the CollectionFS github page use the url method so can't see why I'm not able to access the images.

A: This how it worked for me.
In client side (template or client folder)
Insure that store variable is defined before, and has corresponding values. Should be the same names as you defined them in S3 configuration. Example:
store = {
  bucket: 'my bucket name',
  folder: 'folder name where files are stored'
}

Define S3Url function:
FS.File.prototype.S3Url = function(storeName) {
  var self = this;
  var store = self.getCollection().storesLookup[storeName];
  var urlHost = 'https://s3.amazonaws.com/';
  var urlPath = [store.bucket, store.folder, this.copies[storeName].key].join('/');
  return urlHost + urlPath;
}

After use it like:
{{#each images}}
    URL: {{this.S3Url}}

{{/each}}

Hope it helps.
PS. Insure that store.bucket and store.folder are set in the Client.

A: That's actually correct. You're getting a url from the server which the server redirects to the correct file on S3.
In other words conceptually the server serves as a proxy to S3 that serves temporary access to files on S3 (hence the token at the end).
If you inspect the image collection server-side (meteor shell) you'll see that it's pointing to the relative path within your S3 collection.
If it's not displaying the image correctly there's something else going on, but it should with the url provided by cfs.

redpajama_set_name: RedPajamaStackExchange


text:
layout: page
title: Seattle Police Officer 6603 Simon J. Edison
permalink: /information/agencies/city_of_seattle/seattle_police_department/copbook/6603/
---

**Age as of Feb. 24, 2016:** 43

redpajama_set_name: RedPajamaGithub


Catfish...the one closest to where you live is always the best !!!
The one in the middle.....Madison.
Sorry I can't compare the two, I haven't been to the Milwaukee Zoo since Sampson was alive! I have been to the Minnesota Zoo though. That is very nice. They have done some recent remodeling and it's really a good time, my kids love it. There is another zoo in Mpls., The Como Zoo, that is a smaller zoo and is really nice too. The Como Zoo is about the size of the Henry Vilas Zoo in Madison, maybe a little bigger but comparible in size.
Gee, I thought the zoo in Madison was centered around the capital !
I actually prefer the Como Zoo in Saint Paul, MN. It's free The MN Zoo is nice but expensive. It has a different concept than most zoos. You ride an elevated train to see most of the animals. The Como Zoo is just your old fashioned zoo that you remember from childhood. I've been to the Milwaukee Zoo but it was 40 years ago, no idea what it's like now.
It`s changed a lot in 40 years.
There`s a different event going on constantly.


text:
TEDx Longford goes down a storm at Backstage Theatre
Jessica Thompson
jessica.thompson@longfordleader.ie
TEDx Longford Organiser Shane Crossan with Chas Jewett, Gemma O'Doherty, Seamus Maye, Davie Philip, Anna Kavanagh and Patrick Kent.
It may have been the hottest day of the year, and the theatre may have been like a furnace, but it didn't stop people from turning up in their droves to TEDx Longford on Friday, June 29, last.
The event was sold out, with any cancellations being promptly sold out again, and there wasn't a seat without a bum on it.
"It wasn't your usual Backstage Theatre audience either," said organiser, Shane Crossan, on Monday afternoon, adding that there were a lot of young people and people who travelled from all over the country to see the inspirational speakers.
"It was nice to see something so critical, honest and thought-provoking come to Longford," said Shane.
"The event went really well. We had a full house and everything went to time," he added before giving thanks to Creative Ireland Longford for their support in the organisation of the event.
The theme for TEDx Longford was 'Change Makers', with six inspirational guest speakers from Ireland and USA taking to the stage and speak about their various passions.
The impressive line-up included award-winning journalist Gemma O'Doherty, US activist Chas Jewett, founder of FEASTA and Sustainable Projects Ireland Davie Philip, businessman and competition advocate Seamus Maye, ICSA President Patrick Kent, and local educator and environmentalist Anna Kavanagh.
For more information, follow @TEDxLongford on Facebook and Twitter.

redpajama_set_name: RedPajamaCommonCrawl


We're uploading a stack of boat tests from our archived back issues and we've just finished a big lot of almost 100 boat tests — which are free to view here.
These reviews go back for years and are sorted by manufacturer. Some of these boatbuilders you are very much familiar with because they are still around today; others you've probably never heard of; and others still you may know but are now only found on the used boat market. There's everything from diminiuitive pocket rockets to trailerable floating cruisers — and of course all the runabouts, watersports machines and fishing boats in between.
Some of the two dozen or so brands that have been uploaded include boats from Trophy, Yellowfin, Grady-White, Caribbean, Northbank, Razerline, Scout, Noble, Four Winns, Boston Whaler, Surtees, Tournament and many, many, many more.
And did we mention they're free to view?


Though Shakespeare is celebrated for his diverse and rich characters, his treatment of mothers is oddly repetitive. These characters are either inexplicably missing from the family unit, or they are corrupted, lacking maternal authority. There is no concrete explanation for the absence of maternal authority. In order to interpret this pattern, this paper investigates the cultural and theological context of Shakespeare's time, specifically focusing on the Protestant Reformation and its effects on both English mothers and the cult of the Virgin Mary. Next, it examines six of Shakespeare's plays, Titus Andronicus, Hamlet, Macbeth, The Merchant of Venice, King Lear, and The Tempest and the treatment of mother in these plays. This paper argues that the effects of the Protestant rejection of the Virgin Mary are reflected in Shakespeare's revision of motherhood. It concludes that the rejection of maternal authority in Shakespeare's work is a symptom of the theological shift in England from Catholicism to Protestantism. In doing so, the paper maintains that the elimination of maternal authority in Shakespeare's work mirrors England's necessary rejection of medieval Catholicism in order to make the transition into Protestant individualism.
Tuttle, Alisha Joy, "Bent and Orphaned: Shakespeare's Disappearing Mothers" (2007). MSU Graduate Theses. 2887.


I am a zoological animal trainer turned pet photographer based in Pittsburgh, PA. While I do have a family division of my business, I know that my pet clients certainly feel that their pets are family too! I had the pleasure of meeting Satori on a gorgeous sunny day near downtown Pittsburgh for her pet photography session. She is not only an incredibly sweet and gorgeous Rottweiler, but she loves to go for rides in her vintage orange VW Beetle! Who doesn't love that?


text:
\section{Introduction}\label{Intro}

\IEEEPARstart{T}{his} paper addresses the statistical properties of the $M$-Band Discrete Wavelet Packet Transform, hereafter abbreviated as $M$-DWPT.
In \cite{pesquet99}, asymptotic analysis is given for the correlation structure and the distribution of the $M$-Band wavelet packet coefficients of stationary random processes.
The limit autocorrelation functions and distributions are shown to be the same for every $M$-DWPT path. This seems to be a paradox because the $M$-DWPT paths are characterised by several sequences of wavelet filters. Two arbitrary sequences are different, and thus, do not have the same properties. In addition, the results presented in \cite{pesquet99} seem to be in contradiction with those stated in \cite{atto07} concerning the autocorrelation functions of the standard discrete wavelet packet transform ($M$-DWPT with $M=2$) of wide-sense stationary random processes. The results presented in \cite{atto07} highlight that the limit variance of the wavelet packet coefficients does depend on the path followed in the wavelet packet tree.

In fact, as shown below, the limit results in \cite[Corollary 5, Proposition 12]{pesquet99} apply to only one path of the $M$-DWPT, namely the standard approximation path (only low-pass filters are used in this path).
The same holds true for \cite[Proposition 7]{pesq07}, which extends \cite[Corollary 5]{pesquet99} to the case of the dual-tree $M$-DWPT.
Actually, the limit analysis of the autocorrelation and distributions of the $M$-DWPT coefficients is more intricate than presented in \cite{pesquet99} and \cite{pesq07} because, as shown below, this analysis depends on the path chosen and the wavelet filters used for decomposing the input random process. This analysis is presented for the Shannon $M$-DWPT filters and standard families of paraunitary filters that converge to the Shannon paraunitary filters.

\section{Preliminary results}\label{Mband}

\subsection{General formulas on the $M$-DWPT}\label{Mband1}

In what follows, $j$ and $M$ are natural numbers and $M\geqslant 2$. An $M$-DWPT is performed by using wavelet paraunitary filters with impulse responses $h_{m}, m =0, 1, 2, \ldots, M-1$. For further details about the computation and the properties of $M$-DWPT filters, the reader is asked to refer to \cite{steffen93}.
Let
\begin{equation}
H_{m}(\omega) = \frac{1}{\sqrt{M}}  \sum_{\ell \in \mathbb{Z}} h_{m}[{\ell}] \exp \left ( {-i\ell \omega} \right ),
\label{eqHm}
\end{equation}
and $\Phi$ be a function such that $\{\tau_k \Phi~: k\in \mathbb{Z}\}$ is an orthonormal system of $L^2(\mathbb{R})$, where $ \tau_k \Phi~: t \longmapsto \Phi(t-k)$. Let $\mathbf{U}$ be the closure of the space spanned by this orthonormal system.

The $M$-DWPT decomposition of the function space $\mathbf{U}$ involves splitting $\mathbf{U}$ into $M$ orthogonal subspaces (an easy extension \cite[Lemma 10.5.1]{daub92} established for the standard DWPT):
\begin{equation}
\mathbf{U} = \bigoplus_{m=0}^{M-1}  \mathbf{W}_{1,m},
\label{eq10avanta}
\end{equation}
and recursively applying the following splitting
\begin{equation}
\mathbf{W}_{j,n} = \bigoplus_{m=0}^{M-1}  \mathbf{W}_{j+1,Mn+m},
\label{eq10a}
\end{equation}
for every natural number $j$ and every $n = 0, 1, 2, \ldots, M^j-1$. In this decomposition, the \emph{wavelet packet space} $\mathbf{W}_{j,n}$ is the closure of the space spanned by the orthonormal set of the \emph{wavelet packet functions} $\{ W_{j,n,k} : k \in \mathbb{Z}\} $ whose Fourier transforms are given by
\begin{equation}
{\mathcal{F}}{W_{j, n, k}}(\omega)
=
\exp \left ( {-i M^j k \omega} \right ) {\mathcal{F}}{W_{j, n}}(\omega),
\label{eqWPFjnk}
\end{equation}
with
\begin{equation}
\label{eqWPFwjn}
{\mathcal{F}} W_{j,n}(\omega) = M^{j/2} {\mathcal{F}} W_n(M^j \omega),
\end{equation}
where the sequence $W_{n}, n=0,1,2, \ldots,$ is recursively defined by
\begin{equation}
\label{eq winit}
{\mathcal{F}} W_m(\omega) = H_m( \omega / M ) {\mathcal{F}} \Phi ( \omega / M ),
\end{equation}
and
\begin{equation}
{\mathcal{F}} W_{Mn+m}(\omega) = H_{m}(\omega / M) {\mathcal{F}} W_{n}(\omega / M),
\label{eqWPF-bis}
\end{equation}
for $m = 0, 1, 2, \ldots, M-1$ and $n \in \mathbb{N}$.

Note that the function $\Phi$ in Eq. \eqref{eq winit} is not necessarily the standard scaling function associated with the low-pass filter $h_0$ (see \cite[Lemma 10.5.1]{daub92} for more details). If $\Phi$ is this scaling function, we have $W_{0}=\Phi$ in Eq. \eqref{eq winit}.

\subsection{$M$-ary representations of the $M$-DWPT paths}\label{Mband1-}

A given wavelet packet path $\mathcal{P}$ is described by a sequence of nested functional subspaces: $\mathcal{P}=\left(\mathbf{U}, \{\mathbf{W}_{j,n(j)}\}_{j \in \mathbb{N}}\right)$, where $\mathbf{W}_{j,n(j)}\subset \mathbf{W}_{j-1,n(j-1)}$, with $n(0) = 0$ by convention and
\begin{equation}
\label{eqdpter}
n(j) = M n(j-1) + m_j,
\end{equation}
for $j\geqslant 1$, where $m_j\in \{0, 1, \ldots, M-1\}$. Therefore, the shift parameter is
\begin{equation}
n(j) = \displaystyle \sum_{\ell = 1}^{j} m_{\ell} M^{j-\ell} \in \{0, 1, \ldots, M^j-1\}
\label{eqdpbis}
\end{equation}
at every resolution level $j$.
By construction, each $\mathbf{W}_{j,n(j)}$ is obtained by recursively decomposing $\mathbf{U}$ \emph{via} a particular sequence of filters $(h_{m_{\ell}})_{\ell=1,2, \ldots, j}$ where each $m_\ell$ belongs to $\{0, 1, \ldots, M-1\} $.
Thus, path $\mathcal{P}$ can be associated with a unique $M$-ary sequence $\lambda=(m_{\ell})_{\ell  \in \mathbb{N}}$ of elements of $\{0, 1, \ldots, M-1\}$.
From now on, any given $M$-DWPT decomposition path will be represented by an $M$-ary sequence $\lambda$.
Since the shift parameter $n$ depends on $j$ and $\lambda$ \emph{via} Eq. \eqref{eqdpbis}, the notation $n=n_{\lambda}(j)$ will hereafter be used to indicate this dependence if required. Therefore, an $M$-ary sequence $\lambda$ associated with an $M$-DWPT decomposition path specifies a unique sequence $(\mathbf{W}_{j,n_{\lambda}(j)})_{j \in \mathbb{N}}$ of wavelet packets.
Now we have:

\medskip
\begin{lemma}\label{lemma chemin approx}
Let $\mathcal{P}=\left(\mathbf{U}, \{\mathbf{W}_{j,n_\lambda(j)}\}_{j \in \mathbb{N}}\right)$ be some path of the $M$-DWPT decomposition tree.
If the shift parameter $n_\lambda$ is a bounded function of $j$, then $\lambda$ is the null sequence $\lambda_0=(0,0, \ldots)$.
\end{lemma}

\medskip
\begin{IEEEproof}
If there exists some $j_0$ such that $n_\lambda(j_0) \neq 0$, then it follows from Eq. \eqref{eqdpbis} that $n_\lambda(j)\geqslant M^{j-j_0}$ for every $j\geqslant j_0$.
Therefore, $n_\lambda$ cannot be upper-bounded by a constant.
\end{IEEEproof}

\medskip
\begin{remark}\label{remark a propos de pesquet}
Lemma \ref{lemma chemin approx} states that the approximation path (associated with the null sequence) is the unique $M$-DWPT decomposition path for which the shift parameter $n$ is bounded by a constant independent of $j$. As a consequence, the results established in \cite[Corollary 5, Proposition 12]{pesquet99} and \cite[Proposition 7]{pesq07} concern the approximation path only, because the assumption that $n$ is constant is made in this reference to derive the asymptotic analysis.
\end{remark}

\medskip
The results given in the present paper depends on the path chosen in the $M$-DWPT tree. In fact, the $M$-ary representation of the $M$-DWPT paths plays an important role throughout because it allows a complete path characterization.
The following lemma will prove useful in the sequel.
\medskip
\begin{lemma}\label{dp}
For $n = n(j)$ given by Eq. \eqref{eqdpbis},
we have
\begin{equation}
{\mathcal{F}}{W}_{n}(\omega) = \left[ \prod_{\ell=1}^{j} H_{m_{\ell}}(\frac{\omega}{M^{j+1-\ell}}) \right] {\mathcal{F}}{\Phi}(\frac{\omega}{M^{j}}).
\label{eqlemma}
\end{equation}
\end{lemma}

\medskip
\begin{IEEEproof}
An easy extension of \cite[Lemma 1]{atto07}.
\end{IEEEproof}

\subsection{Shannon $M$-DWPT and the Paley-Wiener space of $\pi$ band-limited functions}\label{Mband1.1}

The Shannon $M$-DWPT filters are hereafter denoted $h_{m}^{\mathsf{S}}$ for $m = 0, 1, \ldots, M-1$. These filters are ideal low-pass, band-pass and high-pass filters. We have
\begin{equation}
H_{m}^{\mathsf{S}}(\omega) = \sum_{\ell \in \mathbb{Z}}  {\mbox{\rm 1\hspace{-0.26em}l}}_{\Delta_{m}}(\omega-2\pi \ell),
\label{HmShannon}
\end{equation}
where ${\mbox{\rm 1\hspace{-0.26em}l}}_K$ denotes the indicator function of a given set $K$: ${\mbox{\rm 1\hspace{-0.26em}l}}_K(x) = 1$ if $x \in K$ and ${\mbox{\rm 1\hspace{-0.26em}l}}_K(x) = 0$, otherwise, and $\Delta_{m}= \left[ -\frac{(m+1)\pi}{M} , -\frac{m\pi}{M} \right] \cup \left[\frac{m\pi}{M} , \frac{(m+1)\pi}{M} \right]$.
The scaling function $\Phi^{\mathsf{S}}$ associated with these filters is defined for every $t \in \mathbb{R}$ by $\Phi^{\mathsf{S}}(t) = \mathsf{sinc}(t) = {\sin(\pi t)}/{\pi t}$ with $\Phi^{\mathsf{S}}(0) = 1$. The Fourier transform of this scaling function is
\begin{equation}
{\mathcal{F}}{\Phi^{\mathsf{S}}}={\mbox{\rm 1\hspace{-0.26em}l}}_{[-\pi,\pi]}.
\label{eqshanscal}
\end{equation}

The closure $\mathbf{U}^{\mathsf{S}}$ of the space spanned by the orthonormal system $\{ \tau_k \Phi^{\mathsf{S}}: k \in \mathbb{Z} \}$ is then the Paley-Wiener (PW) space of those elements of $L^2(\mathbb{R})$ that are $\pi$ band-limited in the sense that their Fourier transform is supported within $[-\pi,\pi]$.

Let $X$ be any band-limited Wide-Sense Stationary (WSS) random process whose spectrum is supported within $[-\pi, \pi]$. We have (see \cite[Appendix D]{atto07})
\begin{equation}
X[k]=\int_{\mathbb{R}} X(t)\Phi^{\mathsf{S}}(t-k) dt,
\label{eqechantillon}
\end{equation}
so that $\mathbf{U}^{\mathsf{S}}$ is the natural representation space of such a process. Any $M$-DWPT of $X$ can thus be initialized with the samples $X[k]$, $k \in \mathbb{Z}$.

Now, let us consider the Shannon $M$-DWPT of the PW space $\mathbf{U}^{\mathsf{S}}$. The wavelet packet functions $W_{j,n}^{\mathsf{S}}$ of this $M$-DWPT can be computed by means of Eqs. \eqref{eqWPFwjn}, \eqref{eq winit} and \eqref{eqWPF-bis}, by setting $\Phi = \Phi^{\mathsf{S}}$ and $H_m = H_m^{\mathsf{S}}$, $m = 0, 1, \ldots, M-1$. The Fourier transforms of these wavelet packet functions are given by proposition \ref{propShannon} below, which extends \cite[Proposition 8.2, p. 328]{mallat99} since the latter follows from the former with $M = 2$.

\medskip
\begin{proposition}\label{propShannon}
For every non-negative integer $j$ and every $n \in \{0, \ldots, M^j-1\}$,
\begin{equation}
{\mathcal{F}}{W_{j,n}^{\mathsf{S}}} = M^{j/2} {\mbox{\rm 1\hspace{-0.26em}l}}_{\Delta_{j,G(n)}},
\label{eq33modulobis}
\end{equation}
where, for any non-negative integer $k$,
\begin{equation}
\Delta_{j,k} = \left[ -\frac{(k+1)\pi}{M^{j}} , -\frac{k \pi}{M^{j}} \right]
\cup \left[\frac{k \pi}{M^{j}} , \frac{(k+1)\pi}{M^{j}} \right]
\label{eq33modulo}
\end{equation}
and $G$ is defined by recursively setting, for $m = 0, 1, \ldots, M-1$ and $\ell = 0, 1, 2, \ldots$, $G(0)=0$ and
\begin{equation}
G(M \ell + m)=
\left\{
\begin{array}{l}
\begin{array}{l c c}
M G(\ell) + m & \textrm{if} \: G(\ell) \: \textrm{is even},\\
M G(\ell) - m + M-1 & \textrm{if} \: G(\ell) \: \textrm{is odd}.
\end{array}
\end{array}
\right.
\label{eqGpermute}
\end{equation}
\end{proposition}

\medskip
In the rest of the paper, we set, for any pair $(j,k)$ of non-negative integers,
\begin{equation}
\Delta_{j,k}^{+} = \left[\frac{k \pi}{M^{j}} , \frac{(k+1)\pi}{M^{j}} \right].
\label{deltajp+}
\end{equation}

\section{Asymptotic analysis for the autocorrelation functions of the $M$-DWPT of second-order WSS random processes}\label{Section Decorrelation}

Let $X$ denote a centred second-order real random process assumed to be continuous in quadratic mean. The autocorrelation function of $X$, denoted by $R$, is defined by $ R(t,s) = \mathbb{E}[X(t) {X(s)} ]$.
The projection of $X$ on $\mathbf{W}_{j,n}$ yields a sequence of random variables, the wavelet packet \emph{coefficients} of $X$:
\begin{equation}
c_{j,n}[k] = \displaystyle \int_{\mathbb{R}} X(t) W_{j,n,k}(t) dt, \quad k \in \mathbb{Z},
\label{eq11}
\end{equation}
provided that the integral
\begin{equation}
\iint_{\mathbb{R}^2} R(t,s) W_{j,n,k}(t) W_{j,n,k}(s) dt ds
\end{equation}
exists, which will be assumed in the rest of the paper since commonly used wavelet functions are compactly supported or have sufficiently fast decay. The sequence given by Eq. \eqref{eq11} defines the discrete random process $c_{j,n}=(c_{j,n}[k])_{k\in\mathbb{Z}}$ of the wavelet packet \emph{coefficients} of $X$ at any resolution level $j$ and for any shift parameter $n\in \{0, 1, \ldots, M^j-1\}$.

\subsection{Problem formulation}\label{Assymp Decorrelation 1}

Let $R_{{j,n}}$ stand for the autocorrelation function of the random process $c_{j,n}$. We have
\begin{IEEEeqnarray}{l}
R_{{j,n}}[k,\ell] =\mathbb{E} \big [ c_{j,n}[k] {c_{j,n}[\ell]} \big ]
=
\iint_{\mathbb{R}^2} R(t,s) W_{j,n,k}(t) W_{j,n,\ell}(s) dt ds.
\label{eqRCJ}
\end{IEEEeqnarray}

If $X$ is WSS, we write $R(t,s) = R(t-s)$ with some usual and slight abuse of language. From Eq. \eqref{eqRCJ}, it follows that
\begin{equation}
R_{{j,n}}[k,\ell] = \iint_{\mathbb{R}^2} R(t) W_{j,n,k}(t+s) W_{j,n,\ell}(s) dt ds.
\label{eq25renew}
\end{equation}

In the sequel, the spectrum $\gamma$ of $X$, that is, the Fourier transform of $R$, is assumed to exist.
By using Fubini's theorem and Parseval's equality, we can proceed as in \cite[Appendix C]{atto07} to derive from Eqs. \eqref{eqWPFjnk}, \eqref{eqWPFwjn} and \eqref{eq25renew} that $c_{j,n}$ is WSS. For any $k, \ell \in \mathbb{Z}$, and with the same abuse of language as above, the value $R_{{j,n}}[k,\ell]$ of the autocorrelation function of the discrete random process $c_{j,n}$ is $R_{{j,n}}[k-\ell]$ with
\begin{equation}
R_{{j,n}}[k] =  \frac{1}{2\pi} \int_{\mathbb{R}} \gamma(\frac{\omega}{M^j}) \vert {\mathcal{F}}{W_{n}}(\omega) \vert^2  \exp \left ( {i k \omega} \right ) d\omega.
\label{eqauto}
\end{equation}

Let us assume that $\gamma \in L^{\infty}(\mathbb{R})$ and is continuous at $0$. These two assumptions have two easy consequences. First, the integrand on the right hand side (rhs) of Eq. \eqref{eqauto} is integrable since its absolute value is upper-bounded by $\Vert \gamma \Vert_{\infty}  \vert {\mathcal{F}}{W_{n}}(\cdot) \vert^2$, whose integral equals $\Vert \gamma \Vert_{\infty}$; second, the limit of $\gamma(\frac{\omega}{M^j})$ is $\gamma(0)$ when $j$ tends to $\infty$. Therefore, for every given natural number $n$, it follows from Lebesgue's dominated convergence theorem applied to Eq. \eqref{eqauto} that
\begin{IEEEeqnarray}{rCl}
\displaystyle \lim_{j\rightarrow +\infty}  R_{{j,n}}[k]
& = & \frac{1}{2\pi}  \displaystyle \int_{\mathbb{R}} \gamma(0) \vert {\mathcal{F}}{W}_{n}(\omega) \vert^2  \exp \left ( {i k \omega} \right ) d\omega, \nonumber \\
& = & \gamma(0) \displaystyle \int_{\mathbb{R}} {W}_{n}(t) {W}_{n}(t-k)  dt = \gamma(0) \delta[k],
\label{eq rjn tend vers 0}
\end{IEEEeqnarray}
where $\delta$ is the standard Kronecker symbol defined for $k \in \mathbb{Z}$ by
$
\delta[k]=
\left\{
\begin{array}{l}
\begin{array}{c c c}
1 & \textrm{if} & m=0,\\
0 & \textrm{if} & m\neq 0.
\end{array}
\end{array}
\right.
$

\noindent
The result thus obtained is that given in \cite[Corollary 5]{pesquet99}.

\medskip
From Lemma \ref{lemma chemin approx}, we distinguish two cases, for any given $M$-DWPT path $\mathcal{P}=\left(\mathbf{U}, \{\mathbf{W}_{j,n_\lambda(j)}\}_{j \in \mathbb{N}}\right)$.
First, if $n_\lambda$ is a constant function of $j$, then $\lambda$ is the null sequence $\lambda_0$, and thus, $\mathcal{P}$ is the approximation path.
In this case, the shift parameter $n_\lambda(j)$ is $0$ at each resolution level $j$ and the $M$-DWPT of $X$ through path $\mathcal{P}=\mathcal{P}_{\lambda_0}$ consists of an infinite sequence of low-pass filters. The decorrelation is then guaranteed by Eq. \eqref{eq rjn tend vers 0} (see also \cite[Corollary 5]{pesquet99}).
The second case is that of a function $n_\lambda$ which cannot be upper-bounded by a constant independent of $j$ when $j$ tends to infinity\footnote{Example: for the sequence $\lambda = (1, 1, \ldots)$, we have $n_\lambda(j) = M^j-1$ . The nodes $(j,M^j-1)$ are those of the path located at the extreme rhs of the $M$-DWPT decomposition tree.}.  In such cases where $n_\lambda$ is not a constant function of $j$, the asymptotic decorrelation of the $M$-DWPT coefficients at node $(j,n_\lambda(j))$ when $j$ tends to $\infty$ is no longer a mere consequence of Eq. \eqref{eq rjn tend vers 0} since Lebesgue's dominated convergence theorem does not apply. To proceed, we then write Eq. \eqref{eqauto} in the form
\begin{equation}
R_{j,n}[k] =  \frac{1}{2\pi} \int_{\mathbb{R}} \gamma(\omega) \vert {\mathcal{F}}{W_{j, n}}(\omega) \vert^2  \exp \left ( {i M^j k \omega} \right ) d\omega.
\label{eq40ter}
\end{equation}
This equality derives from Eq. \eqref{eqauto} after a change of variable and by taking into account Eq. \eqref{eqWPFwjn}.

The purpose of the next section is then to analyse the behaviour of $R_{j,n}$ in the case of the Shannon filters and some families of filters that converge to the Shannon filters.

\subsection{Asymptotic decorrelation achieved by the Shannon $M$-DWPT}\label{Assymp Decorrelation 2}

Let $\lambda = (m_\ell)_{\ell \in \mathbb{N}}$ be an $M$-ary sequence of elements of $\{0, 1, \ldots, M-1\}$. Consider the Shannon $M$-DWPT, that is, the decomposition of $\mathbf{U^{\mathsf{S}}}$ associated with the Shannon $M$-DWPT filters $(h_{m}^{{\mathsf{S}}})_{m = 0, 1, \ldots, M-1}$. Let $\mathcal{P}_{\lambda} = (\mathbf{U^{\mathsf{S}}}, \{\mathbf{W}_{j,n_{\lambda}(j)}^{\mathsf{S}}\}_{j \in \mathbb{N}})$ be the path associated with $\lambda$ in the Shannon $M$-DWPT decomposition tree. It follows from proposition \ref{propShannon} that the support of $W_{j,n_{\lambda}(j)}^{\mathsf{S}}$ is $\Delta_{j,p_{\lambda}(j)}$, where $p_{\lambda}(j)=G(n_{\lambda}(j))$. For $j \in \mathbb{N}$, the sets $\Delta_{j,p_{\lambda}^+(j)}$ are nested closed intervals whose diameters tend to $0$. Therefore, their intersection contains only one point $\omega_{\lambda}$. It then follows from \eqref{eq33modulo} that
\begin{equation}
\omega_{\lambda} = \lim_{j\rightarrow +\infty} \frac{p_{\lambda}(j)\pi}{M^j}.
\label{eq42}
\end{equation}

Let $X$ be some centred second-order WSS random process, continuous in quadratic mean, with spectrum $\gamma$. The autocorrelation function $R_{j,n}^{\mathsf{S}}$ resulting from the projection of $X$ on $\mathbf{W}_{j,n}^{\mathsf{S}}$ derives from Eq. \eqref{eq40ter} and is given by
\begin{equation}
R_{j,n}^{\mathsf{S}}[k] = \frac{1}{2\pi} \int_{\mathbb{R}} \gamma(\omega) \vert {\mathcal{F}}{W_{j,n}^{{\mathsf{S}}}}(\omega) \vert^2  \exp \left ( {i M^j k \omega} \right ) d\omega.
\label{eq40-}
\end{equation}
From Eqs. \eqref{eq33modulobis} and \eqref{eq40-} and by taking into account that $\gamma$ is even, as the Fourier transform of the even function $R$, it follows that
\begin{equation}
R_{j,n}^{\mathsf{S}}[k]
=
\frac{M^j}{\pi} \displaystyle \int_{\Delta_{j,p}^{+}} \! \! \! \! \gamma(\omega)\cos{(M^j k \omega)}  d\omega.
\label{eqproof1-}
\end{equation}
where $\Delta_{j,p}^{+}$ is given by Eq. \eqref{deltajp+} and $p = G(n)$. When $X$ satisfies some additional assumptions, the following theorem \ref{thmShannon} states that the Shannon $M$-DWPT of $X$ yields coefficients that tend to be decorrelated when $j$ tends to infinity. One of these additional assumptions is that $X$ is band-limited in the sense that its spectrum is supported within $[-\pi,\pi]$. When $M=2$, theorem \ref{thmShannon} is equivalent to \cite[Proposition 1]{atto07}.

\medskip
\begin{theorem}\label{thmShannon}
Let $X$ be a centred second-order WSS random process, continuous in quadratic mean.
Assume that the spectrum $\gamma$ of $X$ is an element of $L^{\infty}(\mathbb{R})$ and is supported within $[-\pi, \pi]$. Let $\lambda = (m_\ell)_{\ell \in \mathbb{N}}$ be an $M$-ary sequence of elements of $\{0, 1, \ldots, M-1\}$
and $\mathcal{P}_{\lambda}=(\mathbf{U}^{\mathsf{S}},\{\mathbf{W}_{j,n_{\lambda}(j)}^{\mathsf{S}}\}_{j \in \mathbb{N}})$ be the Shannon $M$-DWPT decomposition path associated with $\lambda$.

If the spectrum $\gamma$ of $X$ is continuous at point $\omega_{\lambda}$, then
\begin{equation}
\lim_{j\rightarrow +\infty} R_{j,n_{\lambda}(j)}^{\mathsf{S}}[k] = \gamma(\omega_{\lambda})\delta[k]
\label{eq41}
\end{equation}
uniformly in $k \in \mathbb{Z}$, where $R_{j,n_{\lambda}(j)}^{\mathsf{S}}$ is the autocorrelation function of the coefficients resulting from the projection of $X$ on $\mathbf{W}^{\mathsf{S}}_{j,n_{\lambda}(j)}$.
\end{theorem}

\medskip
\begin{IEEEproof}
The proof is an easy generalisation of that of \cite[Proposition 1]{atto07}, which concerns the standard wavelet packet transform ($M=2$). The key point of the proof is proposition \ref{propShannon} above, which makes it possible to compute Eq. \eqref{eq42}.
\end{IEEEproof}

\medskip
The foregoing theorem is mainly of theoretical interest since the Shannon $M$-DWPT filters have infinite supports and are not really suitable for practical purpose. In order to obtain a result of the same type for filters of practical interest, the $M$-DWPT is now assumed to be performed by using decomposition filters of order $r$, $h_{m}^{[r]}$, $m = 0, 1, \ldots, M-1$, such that
\begin{equation}
\lim_{r \rightarrow \infty} H_{m}^{[r]} =  H_{m}^{\mathsf{S}}  \quad (\textrm{a.e.}).
\label{eq45}
\end{equation}
The parameter $r$ is called the order of the $M$-DWPT filters.
According to \cite{shen98}, the Daubechies filters satisfy Eq. \eqref{eq45} for $M = 2$ when $r$ is the number of vanishing moments of the Daubechies wavelet function; according to \cite{Aldroubi}, Battle-Lemari\'e filters also satisfy Eq. \eqref{eq45} for $M = 2$ when $r$ is the spline order of the Battle-Lemari\'e scaling function. The existence of such families for $M > 2$ remains an open issue to address in forthcoming work. However, it seems reasonable to expect that general $M$-DWPT filters of the Daubechies or Battle-Lemari\'e type converge to the Shannon filters in the sense given above.

\medskip
\begin{theorem}\label{thm2}
Let $X$ be a centred second-order WSS random process, continuous in quadratic mean.
Assume that the spectrum $\gamma$ of $X$ is an element of $L^{\infty}(\mathbb{R})$ and is supported within $[-\pi, \pi]$. Assume that the $M$-DWPT of the PW space $\mathbf{U}^{\mathsf{S}}$ is achieved by using decomposition filters $h_{m}^{[r]}$, $m = 0, 1, \ldots, M-1$, satisfying Eq. \eqref{eq45}.

For every natural number $j$ and every $n = 0, 1, \ldots, M^j-1$, let $R_{{j,n}}^{[r]}$ stand for the autocorrelation function of the wavelet packet coefficients of $X$ with respect to the packet $\mathbf{W}^{[r]}_{j,n}$.
We have
\begin{equation}
\lim_{r\rightarrow +\infty}
R_{{j,n}}^{[r]}[k]= R_{{j,n}}^{\mathsf{S}}[k],
\label{eq47suite2}
\end{equation}
uniformly in $k \in \mathbb{Z}$ and $n$, where $R_{{j,n}}^{\mathsf{S}}$ is given by Eq. \eqref{eqproof1-}.
\end{theorem}

\medskip
\begin{remark}
Since the $M$-DWPT concerns the space $\mathbf{U}^{\mathsf{S}}$, we have
\begin{equation}
{\mathcal{F}}{W_{n}^{\mathsf{S}}}(\omega) = \left [ \prod_{\ell=1}^{j} H_{m_{\ell}}^{\mathsf{S}}(\frac{\omega}{M^{j+1-\ell}}) \right ] {\mathcal{F}}{\Phi^{\mathsf{S}}}(\frac{\omega}{M^{j}}),
\label{eqdp}
\end{equation}
\begin{equation}
{\mathcal{F}}{W_{n}^{[r]}}(\omega) = \left [ \prod_{\ell=1}^{j} H_{m_{\ell}}^{[r]}(\frac{\omega}{M^{j+1-\ell}}) \right ] {\mathcal{F}}{\Phi^{\mathsf{S}}}(\frac{\omega}{M^{j}}),
\label{eqdpblabla}
\end{equation}
where $n$ is given by Eq. \eqref{eqdpbis}. These equations
straightforwardly derive from Eq. \eqref{eqlemma} of lemma \ref{dp}. From Eqs. \eqref{eqWPFwjn}, \eqref{eq45}, \eqref{eqdp} and \eqref{eqdpblabla}, we obtain, for every given natural number $j$, that
\begin{equation}
\lim_{r\rightarrow +\infty}
{\mathcal{F}}{W_{j,n}^{[r]}} = {\mathcal{F}}{W_{j,n}^{\mathsf{S}}} \quad (\textrm{a.e.}),
\label{eq47}
\end{equation}
uniformly in $n$.
The three equalities above will prove useful below.
\end{remark}

\medskip
\begin{IEEEproof} \emph{(of theorem \ref{thm2})}.
The autocorrelation function $R_{j,n}^{[r]}$ is given by Eq. \eqref{eq40ter} and is equal to
\begin{equation}
R_{j,n}^{[r]}[k] =  \frac{1}{2\pi} \int_{\mathbb{R}} \gamma(\omega) \vert {\mathcal{F}}{W_{j,n}^{[r]}}(\omega) \vert^2  \exp \left ( {i M^j k \omega} \right ) d\omega.
\label{eq46}
\end{equation}
In addition, we have
\begin{IEEEeqnarray}{l}
\big|R_{j,n}^{[r]}[k] - R_{j,n}^{{\mathsf{S}}}[k] \: \big|
\leqslant
\frac{1}{2\pi} \int_{\mathbb{R}} \vert \gamma(\omega) \vert \left| \:| {\mathcal{F}}{W_{j,n}^{[r]}}(\omega)|^2 - | {\mathcal{F}}{W_{j,n}^{\mathsf{S}}}(\omega) |^2 \right| d\omega,
\label{eqblabla}
\end{IEEEeqnarray}
where $R_{j,n}^{{\mathsf{S}}}$ is given by Eq. \eqref{eqproof1-}.
From Eqs. \eqref{eqWPFwjn}, \eqref{eqdp} and \eqref{eqdpblabla}, and by taking into acount that $|H_{m_{\ell}}^{[r]}(\omega)|$ and $|H_{m_{\ell}}^{\mathsf{S}}(\omega)|$ are less than or equal to $1$ (due to the paraunitarity of the $M$-DWPT filters), we obtain
\begin{equation}
\left| \:| {\mathcal{F}}{W_{j,n}^{[r]}}(\omega)|^2 - | {\mathcal{F}}{W_{j,n}^{\mathsf{S}}}(\omega) |^2 \right| \leqslant 2 M^{j} \left|{\mathcal{F}}{\Phi^{\mathsf{S}}}(\omega) \right|^2.
\label{eq47suite1}
\end{equation}
The results derives from Eqs. \eqref{eq47}, \eqref{eqblabla}, \eqref{eq47suite1} and Lebesgue's dominated convergence theorem.
\end{IEEEproof}

\section{Central limit theorems}\label{Loi}

We now consider a real random process $X$ that has finite cumulants and polyspectra.
Denote by
\begin{IEEEeqnarray}{l}
{\mathsf{cum} (t,s_1,s_2,\ldots,s_{N})}
=
\mathsf{cum} \{X(t), X(s_1), X(s_2), \ldots, X(s_{N})\},
\end{IEEEeqnarray}
the cumulant of order $N+1$ of $X$. The above cumulant is hereafter assumed to belong to $L^2(\mathbb{R}^{N+1})$ and to be finite for any natural number $N$ (see \cite[Proposition 1]{pesq02} for a discussion about the existence of this cumulant).
The cumulant of order $N+1$ of the random process $c_{j,n}$ has the integral form given by (see \cite[Proposition 1]{pesq02}):
\begin{IEEEeqnarray}{l}
\mathsf{cum}_{{j,n}} [ k,\ell_1, \ldots, \ell_{N} ]
= \mathsf{cum} \big \{ c_{j,n}[k] c_{j,n}[\ell_1] \ldots c_{j,n}[\ell_{N}] \big \} \nonumber \\
\qquad \qquad = \int_{\mathbb{R}^{N+1}} dt ds_1 \ldots ds_{N} \mathsf{cum}(t,s_1,s_2,\ldots,s_{N}) W_{j,n,k}(t)
W_{j,n,\ell_1}(s_1) \ldots W_{j,n,\ell_{N}}(s_{N}).
\label{eqRCJcum1}
\end{IEEEeqnarray}

Assume that $X$ is strictly stationary so that $\mathsf{cum}(t,t+t_1,t+t_2,\ldots,t+t_{N}) = \mathsf{cum}(t_1,t_2,\ldots,t_{N})$, then $c_{j,n}$ is a strictly stationary random process with cumulants $\mathsf{cum}_{{j,n}}[k,k+k_1, k+k_2, \ldots, k+k_{N}] = \mathsf{cum}_{{j,n}}[k_1, k_2, \ldots, k_{N}]$.
Assume also that $X$ has a polyspectrum $\gamma_N(\omega_1, \omega_2, \ldots, \omega_{N})\in L^{\infty}(\mathbb{R}^N)$ for every natural number $N$ and every $(\omega_1, \omega_2, \ldots, \omega_{N}) \in \mathbb{R}^N$. The polyspectrum is the Fourier transform of the cumulant $\mathsf{cum}(t_1,t_2,\ldots,t_{N})$. When $N=1$, $\gamma_{1}$ is the spectrum of $X$ and is simply denoted $\gamma$ as in section \ref{Section Decorrelation}. Then after some routine algebra, Eq. \eqref{eqRCJcum1} reduces:
\begin{IEEEeqnarray}{l}
\mathsf{cum}_{{j,n}}[k_1, \ldots, k_{N}] =\frac{M^{-j({N-1})/{2}}}{(2\pi)^{N}} \int_{\mathbb{R}^{N}}
d\omega_1 \ldots d\omega_{N}  \exp \left ( {-i (k_1 \omega_1 + \ldots + k_{N} \omega_{N})} \right )   \nonumber \\
\qquad \cdots \gamma_{N}(-{\omega_1}{M^{-j}}, \ldots, -{\omega_{N}}{M^{-j}})    {\mathcal{F}}{W_{n}}(-\omega_1 - \ldots - \omega_{N})   {\mathcal{F}}{W_{n}}(\omega_1)
\ldots
{\mathcal{F}}{W_{n}}(\omega_{N}).
\label{eqRCJcum4en0}
\end{IEEEeqnarray}

If $n$ is a bounded function of $j$, it follows from Lebesgue's dominated convergence theorem that, for any natural number $N > 1$, $\mathsf{cum}_{{j,n}}[k_1, k_2, \ldots, k_{N}]$ tends to $0$ uniformly in $k_1, k_2, \ldots, k_N$ when $j$ tends to $\infty$. This is a consequence of \cite[Proposition 11]{pesquet99}. On the other hand, if $n$ cannot be upper-bounded by a constant independent with $j$, the situation is similar to that discussed in section \ref{Assymp Decorrelation 1}: the shift parameter $n$ depends on $j$ and Lebesgue's dominated convergence theorem does not apply to Eq. \eqref{eqRCJcum4en0} to prove the vanishing behaviour of the cumulants. The vanishing behaviour of the cumulants are hereafter given by theorems \ref{thm3} and \ref{thm4}.

\medskip
By taking into account Eq. \eqref{eqWPFwjn}, Eq. \eqref{eqRCJcum4en0} can also be written, with an easy change of variables:
\begin{IEEEeqnarray}{l}
\mathsf{cum}_{{j,n}}[k_1, \ldots, k_{N}] =
\frac{1}{(2\pi)^{N}}
\int_{\mathbb{R}^{N}}
d\omega_1 \ldots d\omega_{N} \exp \left ( {-i M^j (k_1 \omega_1 + \ldots + k_{N} \omega_{N})} \right )  \nonumber \\
\qquad \gamma_{N}(-\omega_1, \ldots, -\omega_{N})  {\mathcal{F}}{W_{j, n}}(-\omega_1 - \ldots - \omega_{N})  {\mathcal{F}}{W_{j, n}}(\omega_1)  \ldots {\mathcal{F}}{W_{j, n}}(\omega_{N}).
\label{eqRCJcum4}
\end{IEEEeqnarray}

\medskip
\begin{theorem}\label{thm3}
Let $X$ be a centred second-order strictly stationary random process, continuous in quadratic mean. Assume that the polyspectrum $\gamma_N$ of $X$ is an element of $L^{\infty}(\mathbb{R}^N)$ for any $N\geqslant 1$ and that the spectrum $\gamma$ is supported within $[-\pi, \pi]$.
If $N>1$, then we have, uniformly in $k_1, k_2, \ldots, k_N$,
\begin{equation}
\lim_{j\rightarrow +\infty}
\mathsf{cum}_{j,n}^{{\mathsf{S}}}[k_1, k_2, \ldots, k_N]= 0.
\label{eq48b}
\end{equation}
\end{theorem}

\medskip
\begin{IEEEproof}
When the wavelet packet functions are the functions $W_{j,n}^{{\mathsf{S}}}$, it follows from Eqs. \eqref{eq33modulobis} and \eqref{eqRCJcum4} that the cumulant $\mathsf{cum}_{{j,n}}^{\mathsf{S}}[k_1, k_2, \ldots, k_{N}]$ of the discrete random process returned at node $(j,n)$ by the Shannon $M$-DWPT of $X$ satisfies
\begin{equation}
\vert \mathsf{cum}_{{j,n}}^{\mathsf{S}}[k_1, k_2, \ldots, k_{N}] \vert \leqslant
\frac{M^{\frac{j(N+1)}{2}} \Vert \gamma_{N} \Vert_{\infty}}{(2\pi)^{N}}
\int_{\Delta_{j,p}^{N}}
d\omega_1 d\omega_2 \ldots d\omega_{N}
\label{eqProofThm3-1}
\end{equation}
where $\Delta_{j,p}^{N} = \underbrace{\Delta_{j,p} \times \Delta_{j,p} \times \ldots \times \Delta_{j,p}}_{N \hbox{ times}}$ and $p = G(n)$.

\medskip
According to Eq. \eqref{eq33modulo}, $\int_{\Delta_{j,p}} \! d\omega = 2\pi/M^j.$ Therefore, we obtain
\begin{equation}
\vert \mathsf{cum}_{{j,n}}^{\mathsf{S}}[k_1, k_2, \ldots, k_{N}] \vert \leqslant
\Vert \gamma_{N} \Vert_{\infty} M^{-j(N-1)/2}.
\label{eqProofThm3-2}
\end{equation}
Given any natural number $N > 1$, the rhs of the latter inequality does not depend on $n$, $k_1, \ldots, k_N$ and vanishes when $j$ tends to $\infty$, which completes the proof.
\end{IEEEproof}

\medskip
\begin{corollary}\label{thm4corrol}
With the same assumptions and notation as those of theorems \ref{thmShannon} and \ref{thm3}, assume that $\gamma$ is continuous at $\omega_{\lambda}$. Then, when $j$ tend to infinity, the sequence
$\left(c_{j,n_{\lambda}(j)}^{{\mathsf{S}}}\right)_{r, j}$ converges in the following distributional sense to a white Gaussian process with variance $\gamma(\omega_{\lambda})$:
for every $x\in\mathbb{R}^N$ and every $\epsilon>0$, there exists $j_0=j_0(x, \epsilon)>0$ such that, for every $j\geqslant j_0$, the absolute value of the difference between the value at $x$ of the probability distribution of the random vector $$(c_{j,n_{\lambda}(j)}^{{\mathsf{S}}}[k_1], c_{j,n_{\lambda}(j)}^{{\mathsf{S}}}[k_2], \ldots, c_{j,n_{\lambda}(j)}^{{\mathsf{S}}}[k_{N}])$$ and the value at $x$ of the centred $N$-variate normal distribution ${\cal N}(0, \gamma(\omega_{\lambda}) \mathrm{I}_{N})$ with covariance matrix $\gamma(\omega_{\lambda}) \mathrm{I}_{N}$ is less than $\epsilon$.
\end{corollary}

\medskip
\begin{IEEEproof}
A straightforward consequence of theorems \ref{thmShannon} and \ref{thm3}.
\end{IEEEproof}

\medskip
Consider filters satisfying Eq. \eqref{eq45}. Let $\lambda$ be an $M$-ary sequence of elements of $\{0, 1, \ldots, M-1\}$.
The following results describe the asymptotic distribution of the discrete random process $c_{j,n_\lambda(j)}^{[r]}$ returned at node $(j, n_\lambda(j))$ when the resolution level $j$ and the order $r$ of the filters increase.

\medskip
\begin{theorem}\label{thm4}
Let $X$ be a centred second-order strictly stationary random process, continuous in quadratic mean.
Assume that the polyspectrum $\gamma_N$ of $X$ is an element of $L^{\infty}(\mathbb{R}^N)$ for every natural number $N\geqslant 1$ and that the spectrum $\gamma$ is supported within $[-\pi, \pi]$.

For every given natural number $j$ and every $n \in \{0, 1, \ldots, M^j-1 \}$, let $\mathsf{cum}_{j,n}^{[r]}$ stand for the cumulant of order $N+1$ of the wavelet packet coefficients of $X$ with respect to the packet $\mathbf{W}^{[r]}_{j,n}$.

We have, uniformly in $n, k_1, k_2, \ldots, k_N$,
\begin{equation}
\hspace*{-0.5cm} \lim_{r \rightarrow +\infty}
\mathsf{cum}_{j,n}^{[r]}[k_1, k_2, \ldots, k_N]
=
\mathsf{cum}_{j,n}^{{\mathsf{S}}}[k_1, k_2, \ldots, k_N].
\label{eq48bcd}
\end{equation}
\end{theorem}

\medskip
\begin{IEEEproof}
By applying Eq. \eqref{eqRCJcum4} to $W_{j,n}^{[r]}$ and $W_{j,n}^{{\mathsf{S}}}$, we obtain
\begin{IEEEeqnarray}{l}
\vert \mathsf{cum}_{{j,n}}^{[r]}[k_1, \ldots, k_{N}] - \mathsf{cum}_{{j,n}}^{{\mathsf{S}}}[k_1, \ldots, k_{N}] \vert  \leqslant
\frac{1}{(2\pi)^{N}}
\vert \vert \gamma_{N} \vert \vert_{\infty}
\int_{\mathbb{R}^{N}}
d\omega_1 \ldots d\omega_{N}  \nonumber \\
\quad
\Big{|}
{\mathcal{F}}{W_{j,n}^{[r]}}(-\omega_1 \ldots - \omega_{N})
{\mathcal{F}}{W_{j,n}^{[r]}}(\omega_1)
\ldots
{\mathcal{F}}{W_{j,n}^{[r]}}(\omega_{N})
-
{\mathcal{F}}{W_{j,n}^{\mathsf{S}}}(-\omega_1 \ldots - \omega_{N})
{\mathcal{F}}{W_{j,n}^{\mathsf{S}}}(\omega_1)
\ldots
{\mathcal{F}}{W_{j,n}^{\mathsf{S}}}(\omega_{N})
\Big{|}.  \nonumber
\\
\label{eqproof4-1}
\end{IEEEeqnarray}
\noindent
The integrand on the rhs of the second inequality above can now be upper-bounded by
\begin{IEEEeqnarray}{l}
2M^{j(N+1)/2}\Phi^{\mathsf{S}}(\omega_1)\Phi^{\mathsf{S}}(\omega_2)\ldots \Phi^{\mathsf{S}}(\omega_{N})
\label{eqproof4-1-1}
\end{IEEEeqnarray}
where we use Eqs. \eqref{eqWPFwjn}, \eqref{eqdp}, \eqref{eqdpblabla}, and take into acount that $|H_{m_{\ell}}^{[r]}(\omega)|$ and $|H_{m_{\ell}}^{\mathsf{S}}(\omega)|$ are less than or equal to $1$.
The upper-bound given by Eq. \eqref{eqproof4-1-1} is independent of $r$ and integrable; its integral equals $2M^{j(N+1)/2}(2\pi)^N$. By taking Eq. \eqref{eq47} into account, we derive from Lebegue's dominated convergence theorem that the upper bound in Eq. \eqref{eqproof4-1} tends to $0$ when $r$ tends to $+\infty$.
\end{IEEEproof}

\medskip
\begin{corollary}\label{thm4corrol}
With the same assumptions and notations as those of theorems \ref{thm2} and \ref{thm4}, assume that $\gamma$ is continuous at $\omega_{\lambda}$. Then, when $j$ and $r$ tend to infinity, the sequence
$\left(c_{j,n_{\lambda}(j)}^{[r]}\right)_{r, j}$ converges in the following distributional sense to a white Gaussian process with variance $\gamma(\omega_{\lambda})$:
for every $x\in\mathbb{R}^N$ and every $\epsilon>0$, there exists $j_0=j_0(x, \epsilon)>0$ and there exists $r_0=r_0(x, j_0, \epsilon)$ such that, for every $j\geqslant j_0$ and every $r\geqslant r_0$, the absolute value of the difference between the value at $x$ of the probability distribution of the random vector $$(c_{j,n_{\lambda}(j)}^{[r]}[k_1], c_{j,n_{\lambda}(j)}^{[r]}[k_2], \ldots, c_{j,n_{\lambda}(j)}^{[r]}[k_{N}])$$ and the value at $x$ of the centred $N$-variate normal distribution ${\cal N}(0, \gamma(\omega_{\lambda}) \mathrm{I}_{N})$ with covariance matrix $\gamma(\omega_{\lambda}) \mathrm{I}_{N}$ is less than $\epsilon$.
\end{corollary}

\medskip
\begin{IEEEproof}
The result follows from Eqs. \eqref{eq41}, \eqref{eq47suite2}, \eqref{eq48b} and \eqref{eq48bcd}.
\end{IEEEproof}

\balance
\bibliographystyle{IEEEtran}

redpajama_set_name: RedPajamaArXiv


Build the wall ( Great Wall of America). That probably can be achievable .
Appeal Obama Care. Difficult. That can be achieved partially by improving it.
Have a term limit on congress. Probably not achievable at all. Establishment and status quo will be always there and opposed it at their best effort.
Appoint at least one supreme court nominee, which will prevail. This is partially thanks to Harry Reid's nuclear option which set a bad precedent (https://en.wikipedia.org/wiki/Nuclear_option). Now Harry Reid is old and gone and leaving the mess to other democrats to battle. He has been in Congress for more than 30 years.
Rebuilding the country's aging infrastructure. This should be achievable. Both democrats and republican are indeed interested in this.
Negotiate NAFTA. That is partially achievable. Canada's president already agreed to begin the talk. This is what I talked before in my previous post. We should help Mexico both politically and economically such that Mexico will grow better both politically and economically. Then illegal immigration will not be a problem at all. Drug abuse in this country will be less a problem too. All countries can still grow its economy and benefit from treaties at different levels, even still argue with each other.
Prosecute Hillary Clinton. He would be really silly to do that.
Actually there is a list by Washington Post. https://www.washingtonpost.com/news/post-politics/wp/2016/01/22/here-are-76-of-donald-trumps-many-campaign-promises/#comments.
I actually love politicians flip-flop sometimes. As time goes, situation changes, their stand on issues should reflect those changes and evolve too. They need convert this point clearly as well. Double standard should not be equal to "flip-flop", for sure.


All hail the new NPFL KINGS…Rangers International!
Rangers took no chances in their final push for the Nigeria Professional Football League (NPFL)title as they went rampant against visiting El-Kanemi by smashing them 4-0 on the last match day of the season played at the Nnamdi Azikiwe Stadium, Enugu, now nicknamed 'The Cathedral,' on Sunday evening.
They had come into the game with one grip on the trophy, being on top of the log with 60 points while their closest rivals, Rivers United was on 57 points but permutations were on that should anything go wrong for Rangers and should Rivers United defeat Akwa United in Uyo, it would be down to checking goals difference, a situation that Rangers did not particularly fancy.
Moreso, the El-Kanemi players had sent a threat, as voiced by their top scorer, Ibrahim Mustapha that they were in Enugu for a revenge, recalling that two seasons ago, they were at the point of victory but it was Rangers that denied them the needed points on the final day.
Given these El-Kanemi pre-match comments, Rangers went for the sledge hammer which they unleashed furiously on El-Kanemi with Chisom Egbuchulam opening score on three minutes from a well executed spot kick.
Osas Okoro made sure to double the lead before the half time while Egbuchulam called again in the middle of the second half following an exhibition of beautiful combination with Obinna Nwobodo and Okoro.
Egbuchulam returned to the box to get his hat-trick after substitute, Ifeanyi Egwim was brought down in the box by El-Kanemi goalkeeper Kazeem Yekeen who was immediately red carded.
Egwim's injury however produced a bit of an anti-climax to the celebrations when the ambulance arrived to take him away and news filtered out that the damage to his leg was serious.
Enugu State Governor, Ifeanyi Ugwuanyi, we gathered, has ordered that he should be immediately flown abroad for specialist treatment.
Overwhelmed with joy for bringing Rangers back to reckoning, Coach Imama Amapakabo said he was optimistic from the beginning of the season that Rangers will finish with the title and they worked hard for it.


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Watch The Superman Dream Come True On Smallville Season 10 Episode 5
Feel the music more through lyrics
Watch Clark's Journey to Being the World's Greatest Hero on Smallville Season 10 Episode 8
Why and how to secure Smallville download?
Watch Smallville online to enjoy the meteoric rise of Superman
Smallville season 10 – The beginning of the end
Smallville Season 10 Episode 19, Will Clark Kent Kneel Before Zod?
Smallville Season 10 Episode 2 to Dish out Some Deadly Encounters
Watch Smallville season 10 episode 14 to explore the one behind Masquerade
Let's analyze advantages of Web to Watch Smallville
Watch Smallville Online To Meet Alternate Superman
Watch Smallville season 10 episode 1 online to decipher countless mysteries!
The inspiring qualities of Clark Kent of Smallville
Humor: Not Everyone Can Hear The Funny
Go for Smallville season 10 Episode 11 to be Witness of Icarus
Craig Thornburrow
Music In Smallville Delivers True Emotion To Audience
Entertainment Articles | March 9, 2011
When looking at television shows, there are numerous facets that can take it over the top. But sometimes it is the music that will give it that last little edge, which is precisely what can be found from the music in Smallville.
When looking at television shows, there are numerous facets that can take it over the top. From the plots to the characters to the emotion that is expressed, every little detail can captivate an audience. But sometimes it is the music that will give it that last little edge, which is precisely what can be found from the music in Smallville.
Smallville is an American television series that is based on the DC Comics character Superman. It is an intense show that follows the adventures of Clark Kent who resides in the fictional town of Smallville, Kansas. Through each passionate scene, action-packed adventure, and suspenseful mishap, the music from the show really helps the audience feel the characters emotions.
Music is a powerful tool that can do wonders for a show. During a climactic moment, the right tones can deliver shrills up one's spine. When a love connection is being made, the perfect song can enhance the perfect moment between two characters. And during an extreme scene, the proper music can have you sitting at the edge of your seat.
Music in Smallville has managed to capture all of this throughout the long history of the show. Each year music that is just right for what is happening seems to get played. It is just one more sign to a terrific show that has created a reputable image.
There is not much more to say about what you will hear each episode other than the mere fact that it is feeling, inspiring and even uplifting during the right moments. The only way to relive the magic is to pick up the official soundtrack, which is packed with true hits from a wide array of artists.
There are two separate mixes that can be purchased online, in stores and of course on iTunes. Some of the top artists in the industry are featured on these mixes including the likes of Weezer, Lifehouse, The All-American Rejects and Rascal Flatts.
Rascal Flatts shares their hit Feels Like Today on the second volume entitled Metropolis Mix. This mix also features You and Me by Lifehouse and Almost Honest by Josh Kelley. As for the first volume, The Talon Mix, you will find the classic Island in the Sun by Weezer, I Just Wanna Be Loved by AM Radio, and Superman by Five for Fighting.
The right tone, the right song , and the right music can really enhance a scene. This is precisely what music in Smallville has done and continues to do to this day.
"Now I would like to invite you to garner more valuable information on the music in Smallville at http://www.smallvillemusic.com
From Craig Thornburrow - A writer, small business owner and big fan of Smallville"


The ability to write is at the heart of primary, secondary and higher. Children need to be encouraged to write a lot to learn, whether taking notes, writing homework, reports, data manipulation, writings invention or dissertations. Keyboards touchscreens are uncomfortable with high error rates and how to save, network or print is tortuous.
Interestingly, by providing a device so hostile to the creation of writing, you can switch the desire to write for beginning students. Answer this by saying that it is possible to buy keyboards for tablets is to admit defeat. It is told that the tablets do not work unless you turn on the computer. What additional costs?
The tablets are made to consume content; computers (laptops) allow the creation of content. It is not because things are beautiful on the iPad they are easy to make with its creation tools in most areas of art and design are very different dissemination tools. Try using Photoshop, Illustrator or 3D Studio on a tablet.
Try to make a selection pixel by pixel, to use layers to make precise adjustments. The screen is just not big enough for this kind of work. It is a device that is held in the hand, not a tool.
The shelves are rare in the world of work where writing is still needed. The keyboard skills and expertise on other devices you may need in real life are unlikely to be gained from the iPad.
Whatever the purpose of learning the computer, programming or information technology at school, I do not think the iPad or tablets are appropriate. Learning to manipulate a spreadsheet on an iPad is painful. Want to learn to program with, ridiculous. What sane person would want to use a touch interface to the program, which involves a lot of detailed records, deleting, adding lines, as well as in a more open environment?
Above all, iPad is a consumer tool, is to read and not to write. It has a role to play in learning, particularly at the pre – school level for toddlers, but beyond that, there is no serious argument to justify large-scale investment in this kind of material.
The best proof is that when students or students equip themselves with computers, they do not buy tablets. They buy desktop computers, netbooks or laptops.
There is the example of a school that had traded his laptop against the shelves, and who now wants to back down. "The staff room laments," because the educational problems are obvious. From a technical perspective, teachers have experienced it as a nightmare.
Most teachers and teaching materials they use are based on Word and PowerPoint, and use of tablets resulted in incompatibility. Some teachers have had to host their content outside of the institution, which has posed problems of access to resources. Without true knowledge of software and the needs of teachers, there is no added value for learners.
The iPad is expensive to buy and maintain, and are complicated to implement in terms of network and peripherals. They are designed to be used at home and not in school, in laboratories or classrooms. So there is a real question about the strength of the technology in school and in the pages of students, where these are abused, fall and are scratched. Worse, 20% of those who have been sent for repair are in their second or third return to service. Although he was asked to parents € 50 per shelf, the latter actually cost € 450 and students do not seem to take special care of something they did not buy. The final cost, when added repairs, is still higher than expected.
A person very knowledgeable, having attended a meeting at the highest levels of government that has decided to introduce the tablet at school told me that it was painful and messy. Tablets, data by a computer company, were delivered well in school, where the head of the institution hid the other teachers. This is exactly how NOT to introduce new technologies in schools: buy fashionable devices in large quantities, distributed in beautiful boxes and hope that all will be well.
This is the danger with these projects based on tablets, we rarely rely on extensive analysis to select the most appropriate technology, and we tend to rely on the fact that Apple is fashionable or advise fans of this brand. We must avoid as everyone and implement pretentious projects presuppose that what is cool for adult consumers will be cool for school.
I have spent my entire adult life to encourage technology adoption in education but I want to be sure we are not shooting itself in the foot with projects that have not taken into account seven points above.
To be honest, I'm not at all sure of the merits of a technology imposed on classrooms. Let the teachers teach and if you bring this stuff, rather book a good share of the budget to train.
Ellen is a smart and very creative writer who is working with the proficient writer team of the Click 2 Assignment. Currently he is working for the students who needs help with assignment UK to accomplish big challenges.
What Evidence Should I Gather If I Have Been Bitten by A Dog?
Purebred Dogs Vs Hybrid Dogs: Why Choose Hybrids?


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We are happy for donors to fund specific pieces of work which are in accordance with our mission and our values. However, we don't take money with strings attached and donors don't have a role in our governance structure.


A Georgia middle school is under fire after one of its teachers asked sixth-graders to draw Nazi mascots for homework.
"The year is 1935 and you have been tasked with creating a mascot to represent the Nazi party at its political rallies," the assignment read, the Atlanta Journal Constitution reported.
Jamie Brown, whose 11-year-old son attends Shiloh Middle School, said he was shocked by the assignment, CBS46 reported.
"In studying this time period, they learn about Nazism, the use of propaganda, and events which resulted in the Holocaust," the statement said.
A spokesperson said that the assignment was not okayed by the school.


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Event Information Active Directory could not shut down successfully, threads are still active. Restart the domain controller and confirm that Active Directory is successfully running again.


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We Eat Films / Featured / Movie Review: "Rogue One" – The Episode We Deserved
Movie Review: "Rogue One" – The Episode We Deserved
Written by Jesse Gelinas December 21, 2016
Isn't it great being able to say you're on your way to see Star Wars in THEATERS again? No longer do Episodes I-III have to be our generation's Star Wars films. The biggest sci-fi franchise in the world is back with a vengeance with two huge films already. Episode VII took the safe nostalgic route, letting us relive the glory of A New Hope. Gareth Edwards' Rogue One, on the other hand, has decided to do things a little differently, taking a few more risks and giving us a few more surprises. For a story we already know the conclusion of, the film manages a few impressive twists and turns, and manages to recapture the classic Star Wars charm without being too in-your-face about it.
Rogue One takes place shortly before the beginning of the original Star Wars (aka Ep IV: A New Hope). An Imperial defector has alerted the Rebel Alliance to the existence of a new super weapon, that is about to be tested: the Death Star. Under the command of Director Krennic (Ben Mendelsohn), the planet-killing space station will usher in a new era of oppression and terror across the galaxy. Rescued from an Imperial prison, Jyrn Erso (Felicity Jones) becomes the Rebellion's one hope at discovering the whereabouts of the Death Star's creator (Mads Mikkelsen), and the blueprints that could lead to its destruction.
"You are rebels, aren't you?"
Rogue One's biggest hurdle going into it, is that every Star Wars fan knows the story already. Or rather, we know the gist, and the outcome. The Rebels steal the Death Star plans. Leia gives them to the droids. Luke and Han save the galaxy. These are not spoilers at this point. That said, the film manages to keep the story fresh with interesting characters, surprising obstacles for our heroes, and a few clever cameos that don't feel overly shoehorned in. When I remembered the Rogue One story, I imagined a simple smash and grab operation. Not a planet hopping jailbreak, followed by full out space battles. It was grand without feeling grandiose, and different without feeling contradictory.
Felicity Jones' Jyn Erso carries the film on her shoulders, and does it with grace and general badassery. Her ragtag team of comrades all bring something different, and manage to almost rival the charm and naturalism of the original cast. Donnie Yen is terrific as the Force-faithful monk. Forest Whitaker and Mads Mikkelsen feel a tad wasted in htheir small roles, but are enjoyable as hell, as expected. And keeping with the tradition of great droids like C-3PO and BB-8, K-2SO (Alan Tudyk) brings humour, charm, and still a few cool moments to the film. He also has most of the best lines for this very reason.
"I'm one with the Force. The Force is with me."
When I saw The Force Awakens I was blown away. I still am; it's a NEW Star Wars movie, and it doesn't suck. It is a great film, but once you take off the rose-coloured glasses, it does have its flaws. Yes, we all knew we ere just getting A New Hope 2.0. Yes, the winks and nods to the audience are many, and obvious. Rogue One manages to be just as enjoyable and nostalgic without feeling so forced. When R2 and 3PO show up, it doesn't feel superfluous; it seems natural. When the Imperial Destroyer floats across the screen looking like a miniature model, it doesn't seem like a throwback. It feels consistent. The film is full of little joyous moments like this, but you actually have to look for them, which actually makes it more rewarding, especially for hardcore fans.
Rogue One is a fantastic Star Wars installment. And while it's not an "episode," this "Star Wars Story" certainly matches the criteria and the quality. It gives me new hope (Do you see what I did there? Do you? Do you see?) for the prequels and spin-offs on the horizon, of which I was previously very wary. The film entertains, surprises, and manages to make the hard choices come the end that really raise it up to new heights in the revived franchise. I don't want to put it on too much of a pedestal, but honestly, Rogue One should be the benchmark for Star Wars going forward.
About Jesse Gelinas
After years attempting to escape the Matrix, Jesse has accepted his fate as a writer and Senior Editor. Now that's he finished with his film degree, it gives him something to do while waiting for the machines to get careless.
Browse Archived Articles by Jesse Gelinas
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The Catawba County Sheriff's Office is searching for two suspects they say robbed a video game arcade this week.
Around 6 a.m. on Monday, deputies responded to the report of an armed robbery at The Hook arcade in the 2800 block of Springs Road.
The video arcade was open when two men wearing mask entered the business. One of the men was carrying a firearm, the press release said.
The duo robbed the business with an undisclosed amount of cash.
The suspects then left the business and were seen driving west on Springs Road in a four door vehicle, possibly a Honda.
Anyone with information can contact the Catawba County Sheriff's Office at (828) 464-3112 or Sgt. Russ Boger at (828) 466-7227.


previous version (February 14, 2018 - 11:00).
Dr. Joseph Yeboah, Heart and Vascular Center of Excellence, Wake Forest School of Medicine, Medical Center Boulevard, Winston-Salem, North Carolina 27157.
Objectives This study assessed the utility of the pooled cohort equation (PCE) and/or coronary artery calcium (CAC) for atherosclerotic cardiovascular disease (ASCVD) risk assessment in smokers, especially those who were lung cancer screening eligible (LCSE).
Background The U.S. Preventive Services Task Force recommended and the Centers for Medicare & Medicaid Services currently pays for annual screening for lung cancer with low-dose computed tomography scans in a specified group of cigarette smokers. CAC can be obtained from these low-dose scans. The incremental utility of CAC for ASCVD risk stratification remains unclear in this high-risk group.
Methods Of 6,814 MESA (Multi-Ethnic Study of Atherosclerosis) participants, 3,356 (49.2% of total cohort) were smokers (2,476 former and 880 current), and 14.3% were LCSE. Kaplan-Meier, Cox proportional hazards, area under the curve, and net reclassification improvement (NRI) analyses were used to assess the association between PCE and/or CAC and incident ASCVD. Incident ASCVD was defined as coronary death, nonfatal myocardial infarction, or fatal or nonfatal stroke.
Results Smokers had a mean age of 62.1 years, 43.5% were female, and all had a mean of 23.0 pack-years of smoking. The LCSE sample had a mean age of 65.3 years, 39.1% were female, and all had a mean of 56.7 pack-years of smoking. After a mean of 11.1 years of follow-up 13.4% of all smokers and 20.8% of LCSE smokers had ASCVD events; 6.7% of all smokers and 14.2% of LCSE smokers with CAC = 0 had an ASCVD event during the follow-up. One SD increase in the PCE 10-year risk was associated with a 68% increase risk for ASCVD events in all smokers (hazard ratio: 1.68; 95% confidence interval: 1.57 to 1.80) and a 22% increase in risk for ASCVD events in the LCSE smokers (hazard ratio: 1.22; 95% confidence interval: 1.00 to 1.47). CAC was associated with increased ASCVD risk in all smokers and in LCSE smokers in all the Cox models. The C-statistic of the PCE for ASCVD was higher in all smokers compared with LCSE smokers (0.693 vs. 0.545). CAC significantly improved the C-statistics of the PCE in all smokers but not in LCSE smokers. The event and nonevent net reclassification improvements for all smokers and LCSE smokers were 0.018 and −0.126 versus 0.16 and −0.196, respectively.
Conclusions In this well-characterized, multiethnic U.S. cohort, CAC was predictive of ASCVD in all smokers and in LCSE smokers but modestly improved discrimination over and beyond the PCE. However, 6.7% of all smokers and 14.2% of LCSE smokers with CAC = 0 had an ASCVD event during follow-up.
This research was supported by grant T32HL076132 and contracts HHSN268201500003I, N01-HC-95159, N01-HC-95160, N01-HC-95161, N01-HC-95162, N01-HC-95163, N01-HC-95164, N01-HC-95165, N01-HC-95166, N01-HC-95167, N01-HC-95168, and N01-HC-95169 from the National Heart, Lung, and Blood Institute and by grants UL1-TR-000040 and UL1-TR-001079 from the National Center for Research Resources. Dr. Herrington is the principal investigator for grant T32HL076132 from the National Heart, Lung, and Blood Institute. Dr. Budoff has received grant support from the National Institutes of Health and GE Healthcare. All other authors have reported that they have no relationships relevant to the contents of this paper to disclose.
Revision received December 21, 2017.


James Slaby, MD, Plastic and Reconstructive Surgeon, received his medical degree at Medical College of Ohio in Toledo, OH. He completed his residency in General Surgery at Rush-Presbyterian St. Luke's Medical Center in Chicago, Ill. He received a fellowship in Plastic Surgery with Medical College of Ohio in Toledo. He is certified by the American Board of General Surgery and the American Board of Plastic Surgery.


Jeremy Corbyn is under huge pressure to shift party policy on Brexit as an exclusive poll for the Observer reveals a substantial majority of existing and potential Labour voters want him to back permanent membership of the EU's single market and customs union.
Four times as many Labour supporters favour that option as oppose it. The survey by Opinium also finds that more than twice as many in this group want Corbyn to support a second referendum on the eventual Brexit deal as reject it.
The poll comes at a time when senior European politicians are signalling that Britain could reverse its decision to leave the EU and warning that there will be no prospect of reaping the benefits of membership from outside the bloc.
Emmanuel Macron will say on Sunday on The Andrew Marr Show that he would love to see Britain return, adding: "It depends on you. I do respect this vote, I do regret this vote, and I would love to welcome you again." However, he warns that full access to the single market for the UK's huge financial services industry will be "not feasible".
Meanwhile, Italy's minister for European affairs, Sandro Gozi, said that the Brexit decision could be reversed. He told LBC radio that "by definition, Britain cannot have the benefits of remaining in the union" while being outside it.
The CBI is preparing this week to call on the government to abandon the pursuit of global trade deals in favour of long-term EU customs union membership. In the wake of the Observer poll, senior Labour MPs are saying it is no longer credible for a party that is serious about power to overlook the demands of so many trade unions, supporters and business leaders.
The former shadow business secretary, Labour MP Chuka Umunna, said: "It is absolutely vital, as the party of work and social justice, that we have a clear and unequivocal policy to keep the UK in the single market and the customs union.
Opinium found that among all potential Labour voters at the next election, 56% want the party to back permanent membership of the single market and customs union, while just 13% think it should remain opposed; 30% had no firm view either way.
Among younger voters, the balance in favour was even clearer: 63% of all "young professionals" who are potential Labour backers were in favour, against 10% who were opposed. Of the "young blue collar workers" who might back Corbyn's party, 61% were in favour of the change against just 4% who were against.
Significantly, even among Labour voters who backed Leave, 37% said they want Corbyn to support permanent single market and customs union membership compared with just 26% who did not.
Some 51% of Labour's potential pool of support backs a second referendum on the final Brexit deal, against 23% who oppose the idea.
Despite mounting disquiet among pro-Remain Labour MPs, Corbyn has so far rejected calls to back staying in the single market and customs union. Remaining as full participants in both would require the UK to abide by EU rules on free movement of people and workers, and to submit to the jurisdiction of the European Court of Justice on trade issues.
Labour's current policy is to keep the UK in both only for the duration of a post-Brexit transition of up to four years. After that it would try to negotiate a relationship offering the "exact same benefits" for the UK post-Brexit. Corbyn has also refused to endorse a second referendum.
Overall, most voters think that both the Labour and Tory positions on Brexit are unclear. Only a quarter (26%) think Labour's position is clear, while 60% think its position is unclear. The Conservatives – who are committed to taking the UK out of the single market and customs union after a transition period – fare only slightly better. Just over a third (36%) think the Tories are clear on Brexit while just over half (53%) think their position is unclear.
In a speech on Monday, Carolyn Fairbairn, director general of the CBI, will say that the benefits of signing new trade deals with the United States and others are far outweighed by maintaining good links to the EU.
She will propose that a comprehensive customs union between the UK and the EU would be a "practical, real-world answer" that would help solve many of the trading and Irish border issues created by Brexit.
"The idea behind a customs union is simple: a single set of tariffs for goods imported from outside the EU, enabling tariff-free trade within it," she will say. "It brings no obligations over freedom of movement, or payment, and removes some of the heaviest trade barriers. Importantly, it would go a long way towards solving the border problem in Ireland.
"We recognise this isn't easy, and of course it's worth looking at the alternatives. Yet unless and until we find one that works, a customs union is part of a practical, real-world answer.
56%: Potential Labour voters in favour of the single market. Only 13% of those polled opposed it.


text:
package com.cloudTop.starshare.ui.main.adapter;

import android.content.Context;
import android.widget.TextView;

import com.cloudTop.starshare.R;
import com.cloudTop.starshare.base.ListBaseAdapter;
import com.cloudTop.starshare.base.SuperViewHolder;
import com.cloudTop.starshare.been.WithDrawCashHistoryBean;
import com.cloudTop.starshare.utils.FormatUtil;

/**
 * Created by sll on 2017/5/25.
 */

public class CashHistoryAdapter extends ListBaseAdapter<WithDrawCashHistoryBean> {

    public CashHistoryAdapter(Context context) {
        super(context);
    }

    @Override
    public int getLayoutId() {
        return R.layout.adapter_cash_history_item;
    }

    @Override
    public void onBindItemHolder(SuperViewHolder holder, int position) {
        WithDrawCashHistoryBean item = mDataList.get(position);

        TextView time = holder.getView(R.id.tv_cash_time);
        TextView bankName = holder.getView(R.id.tv_bank_name);
        TextView cashMoney = holder.getView(R.id.tv_cash_money);

        time.setText(item.getWithdrawTime());
        bankName.setText(String.format(mContext.getResources().getString(R.string.bank_end_number),
                item.getBank(), FormatUtil.getCardEnd(item.getCardNo())));
        cashMoney.setText("-" + item.getAmount());

    }
}


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Tag Archives: Rolling Stone Magazine
You should be listening to The Strokes!
The Strokes are the hip, happening New York band that careened on to the music scene in 2001 with their garage rock debut Is This It. They packed the one, two punch of critical acclaim; their debut recently was listed as one of the top 50 Albums of the Decade by Rolling Stone Magazine, and commercial success.
In addition to playing a variety of festivals, they had some sweet opening slots for bands such as the Rolling Stones, Tom Petty, Weezer, and The White Stripes. In 2003 they released Room On Fire, which was also well received by critics and achieved Gold status. This was followed by the release of First Impressions of Earth. The album was seen as a bit of a musical retreat for the band and did not receive the commercial or critical success of their previous two efforts.
The Strokes Discography:
Is This It
Room On Fire
First Impression of Earth
The Strokes Top 5 Songs:
Last Night (Is This It)
Is This It (Is This It)
12:51 (Room On Fire)
You Only Live Once (First Impressions of Earth)
Reptilia (Room On Fire)
Their music is daring with a slight pop edge and exploding with an early raw punk sound. Reminiscent of the 70's New York scene, think Stooges and Velvet Underground, yet, they manage to sound fresh and original while not hiding their influences.
Check out The Stokes at www.thestrokes.com.
www.youtube.com/watch?v=YlYsDNilKDQ
www.youtube.com/watch?v=jSieZdwxxuk&feature=PlayList&p=CE5BEB60627F516D&playnext=1&playnext_from=PL&index=4
Leave a comment	| tags: 12:51, First Impressions of Earth, Is This It, Last Night, Music you should be listening to!, Reptilia, Rolling Stone Magazine, Room On Fire, Stooges, The Rolling Stones, The Strokes, The White Stripes, Tom Petty, Velvet Underground, Weezer, www.thestrokes.com, You Only Live Once	| posted in Alternative Music, Music, Pop Music, Rock Music
You should be listening to The Avett Brothers!
The Avett Brothers are the folksy, rocking, alt/country with a tinge of bluegrass band from North Carolina. With such a diverse pedigree, is it any wonder the Rick Rubin took notice, signed them to his label, and produced their major label debut "I and Love and You"?
As mentioned, I and Love and You is the major label debut but actually finds The Avett Brothers in the double digits for their release total. They have released numerous albums as well as EP's and live albums.
Loosely formed in 2000 just prior to be the end of Seth and Scott Avett's rock band Nemo, the brothers are joined by Bob Crawford on stand up bass. Their self titled debut was release in 2000 and in 2002 released their first album "Country Was" as a full band.
In 2007 the Avett Brothers won the Americana Music Association Duo/Group of the Year award and 2007 Emerging Artist of the Year. In 2009 they opened for the Dave Matthews Band's spring tour across the southern United States as well as an opening spot for Wide Spread Panic. And, to add to an already great year, Rolling Stone Magazine named The Avett Brothers "The Artist to Watch in 2009".
While their major label is not a dramatic musical departure from their previous work, however, there is less reliance on banjo, with the exception of "January Wedding" while the piano plays a prominent role on this ballad heavy album. The album is sonically rich with harmonies provided by Scott and Seth. The melodies are tight and the musical arrangement has a certain level of complication but not in an overly dramatic fashion.
The Avett Brothers Discography:
The Avett Bros.
Country Was
Live at the Double Door Inn
A Carolina Jubilee
Swept Away (EP)
Live, Vol. 2
Four Thieves Gone: The Robbinsville Sessions
The Gleam
Emotionalism
The Second Gleam
Key tracks form I and Love and You:
Head Full of Doubt/Road Full of Promise
Ten Thousand Words
Ill With Want
Kick Drum Heart
Check out The Avett Brothers @ www.theavettbrothers.com
http://www.youtube.com/watch?v=jgnZ0wEi2JU
http://www.youtube.com/watch?v=qqZZlL0l5Uk&feature=channel
The Avett Brothers' music is available at iTunes, record stores, and www.theavettbrothers.com
2 Comments	| tags: A Carolina Jubilee, Americana Music Association, Bob Crawford, Country Was, Dave Matthews Band, Emotionalism, Four Thieves Gone: The Robbinsville Sessions, Head Full of Doubt/Road Full of Promise, I and Love and You, Ill With Want, iTunes, January Wedding, Kick Drum Heart, Live at the Double Door Inn, Live Vol. 2, Mignonette, Music you should be listening to!, Nemo, Rick Rubin, Rolling Stone Magazine, Scott Avett, Seth Avett, Swept Away, Ten Thousand Words, The Avett Bros., The Avett Brothers, The Gleam, The Second Gleam, Wide Spread Panic, www.theavettbrothers.com	| posted in Alt/Country Music, Alternative Music, Folk Music, Indie Music, Live Music, Music, Pop Music, Rock Music
You should be listening to Wilco!
And from the ashes of Uncle Tupelo, Jeff Tweedy and Wilco rose like a phoenix! Created in 1994 after the demise of the oft contentious Uncle Tupelo, the original line up of Wilco consisted of the entire band of Uncle Tupelo minus Jay Farrar. Wilco was named after the voice procedure idiom "wilco" meaning "Will Comply" which Tweedy found to be an ironic choice for a rock band.
With their debut album A.M., released in 1995, Wilco was still well-established in the Alt/Country sound, however, their musical evolution has found them experimenting with alternative rock and pop. The band considered the album a failure due to the modest reception by critics and fans alike and the fact that Jay Farrar's new band Son Volt had released their debut album Trace and it fared better both critically and commercially.
Being There was the overly ambitious (19 songs) sophomore effort that was released as a double album but sold for a single album price. This was accomplished by Tweedy agreeing to give the label (Reprise) Wilco's share of album royalties. It is estimated that the band lost more than half a million dollars. The album was a hit with critics and reached 73 on the Billboard album chart.
Yankee Hotel Foxtrot was released in 2001, after much turmoil and confusion, and eventual dismissal from their previous label. It became their best selling album and to date has sold almost 600,000 copies. In addition to the commercial success, critics raved and Billboard ranked it 13 on its charts and Rolling Stone Magazine listed as one of the 50 best albums of the decade. With the follow up release of A Ghost is Born Wilco received a Grammy for Best Alternative Music Album and became the bands first top ten album.
Wilco discography:
Summerteeth
Yankee Hotel Foxtrot
A Ghost is Born
Kicking Television (Live in Chicago)
Sky Blue Sky
Wilco (The Album)
Top 5 Wilco Songs:
Either Way (Sky Blue Sky)
Box Full of Letters (A.M.)
Sunken Treasure (Being There)
Jesus, Etc. (Yankee Hotel Foxtrot)
Theologians (A Ghost is Born)
Wilco, in the face of their career long major label affiliation, is seen more as an indie band and have been categorized as alt/country, alternative rock, pop, and roots-rock. Critics have even referred to them as an Americanized adaptation of Radiohead; this is in large part to the diversity of their sound and catalog. The diversity has certainly been enabled by the rotating members of the band. Since their inception, Jeff Tweedy and bassist John Stirratt are the only original members.
Whatever the comparison or classification, they simple truth is that Wilco is a great band that has maintained their integrity while staying relevant. As fickle as critics and consumes are, this band has persevered and in many ways influenced countless bands along the way.
Check out Wilco at www.wilcoweb.com.
Wilco's music is available at iTunes, record stores, and www.wilcoweb.com.
33 Comments	| tags: A Ghost is Born, A.M., Being There, Billboard, Box Full of Letters, Either Way, Etc., iTunes, Jay Farrar, Jeff Tweedy, Jesus, John Stirratt, Kicking Television (Live in Chicago), Music you should be listening to!, Rolling Stone Magazine, Sky Blue Sky, Son Volt, Summerteeth, Sunken Treasure, Theologians, Trace, Uncle Tupelo, Wilco, Wilco (The Album), www.wilcoweb.com, Yankee Hotel Foxtrot	| posted in Alt/Country Music, Alternative Music, Folk Music, Indie Music, Music, Pop Music, Rock Music
You should be listening to Fleet Foxes!
Fleet Foxes are a five piece Seattle band that came to light in 2008 with the release of "Sun Giant (EP), which was released on famed Seattle indie label Sub-Pop, and their self titled debut album. Both releases received critical acclaim. Despite great reviews in Rolling Stone magazine and other musical press, they were moderately received in the United States but did well in Europe. With great festival performances in 2008 at SXSW and the Sasquatch Festival, Fleet Foxes gained some national exposure and positive press. They opened for Wilco shortly after the release of their debut album.
Fleet Foxes combine the retro feel of early pop (The Beach Boys) with the ethereal harmonies of folk. Their sound is bathed in reverb, multi layered harmonies, and brilliant melodies. While enjoyable to listen to, it takes a few spins to fully appreciate the dense harmony and the varied acoustic instrumentation that define their sound. Four part harmony is not uncommon in their songs.
Their youth, Robin Peckold, lead singer is 23, belies their sound, in this age of sampled tracks and autotune, it is rich, textured music with lush harmonies and revealing lyrics.
Fleet Foxes Discography
Sun Giant (EP)
Top 5 Fleet Foxes Songs according to Butler (Albums listed to right of song):
White Winter Hymnal (Fleet Foxes)
Mykonos (Sun Giant EP)
Your Protector (Fleet Foxes)
English House (Sun Giant EP)
He Doesn't Know Why (Fleet Foxes)
Check out Fleet Foxes and let me know what you think.
Fleet Foxes' music is available is available on iTunes and record stores.
Also, if you have a facebook page, you can become a fan of the blog.
http://www.facebook.com/?ref=home#/pages/Music-you-should-be-listening-to/261897107787?ref=ts
Leave a comment	| tags: English House, Fleet Foxes, He Doesn't Know Why, iTunes, Music you should be listening to!, Mykonos, Robin Peckhold, Rolling Stone Magazine, Sasquatch Festival, Seattle, Sub-Pop, Sun Giant, SXSW, The Beach Boys, White Winter Hymnal, Wilco, Your Protector	| posted in Alternative Music, Folk Music, Indie Music, Music, Pop Music


text:
<bill session="115" type="hj" number="97" updated="2017-05-05T20:45:06Z">
  <state datetime="2017-04-06">REFERRED</state>
  <status>
    <introduced datetime="2017-04-06"/>
  </status>
  <introduced datetime="2017-04-06"/>
  <titles>
    <title type="official" as="introduced">Providing for congressional disapproval under chapter 8 of title 5, United States Code, of the rule submitted by the Department of Agriculture relating to "Tongass National Forest Land and Resource Management Plan Amendment".</title>
    <title type="display">Providing for congressional disapproval under chapter 8 of title 5, United States Code, of the rule submitted by the Department of Agriculture relating to "Tongass National Forest Land and Resource Management Plan Amendment".</title>
  </titles>
  <sponsor bioguide_id="Y000033"/>
  <cosponsors/>
  <actions>
    <action datetime="2017-04-06">
      <text>Introduced in House</text>
    </action>
    <action datetime="2017-04-06" state="REFERRED">
      <text>Referred to the House Committee on Natural Resources.</text>
    </action>
  </actions>
  <committees>
    <committee subcommittee="" code="HSII" name="House Natural Resources" activity="Referral"/>
  </committees>
  <relatedbills/>
  <subjects>
    <term name="Public lands and natural resources"/>
    <term name="Administrative law and regulatory procedures"/>
    <term name="Alaska"/>
    <term name="Congressional oversight"/>
    <term name="Department of Agriculture"/>
    <term name="Forests, forestry, trees"/>
    <term name="Land use and conservation"/>
  </subjects>
  <amendments/>
  <summary date="2017-04-06T04:00:00Z" status="Introduced in House">This joint resolution nullifies the rule finalized by the Department of Agriculture on December 8, 2016, relating to the Tongass National Forest Land and Resource Plan Amendment for the Tongass National Forest in Alaska.</summary>
  <committee-reports/>
</bill>


Ah I forgot to look under GameFX, thank you!
So all you have to do to use incremental loading is convert .babylon file using http://www.babylonjs.com/converter.html, put all the converted files in the same directory as scene.babylon file and in the code use the scene.incremental.babylon file instead?
I noticed that freeCamera and arcRotateCamera can rotate limitless on the x axis yet they have limits on the y axis. Is possible to have them able to rotate limitless on the y axis? And why are are they limited in the y axis, is it to prevent seeing things up side down?
Is it possible to change the render distance of the babylon engine or would it just be better to scale everything down instead?
ok, thank you very much! I was looking through examples and the tutorials and I never found anyone doing this so I was starting to worry! Glad to hear that I was wrong!
@Deltakosh, but that's only for when you use new and create a camera, or are you saying that I can do camera.alpha and camera.beta to change those properties of an existing camera?
When you link a mesh(child) to another mesh(parent) is there a way to get the child mesh's position? Because currently the position that is returned is just the initial position of the child mesh in relation to the parent mesh.
Using an ArcRotateCamera you can set the rotation on creation of the camera, is there a way to do something like, camera.rotation.x and camera.rotation.y to change the rotation of a camera already in the world? I'm assuming that it would be better to not just make a gazillion cameras every time that I want to manually change the rotation though as far as I can see the only way to set a camera is on creation! When I try my method above it just says "Cannot set property 'x' of undefined".


So i got this cute outfit from *CK* Candy Kitten today. The top and overall is seperat, so u can wear one or the other or both. They both come with nice color huds (for box, lace, belt, overall & top).
S.O.S Festival (Spoonful of Sugar) is still going on and OPEN until Sunday, September 25 and is a fundraiser for Doctors without Borders/Medicines Sans Frontieres.
S.O.S Festival (Spoonful of Sugar) is now OPEN!!! From 9th, 12 am SLT, and open until Sunday, September 25 and is a fundraiser for Doctors without Borders/Medicines Sans Frontieres.


text:
Home >Impact >Malawi >ODK – Open Data Kit Solutions
VillageReach is implementing ODK solutions to enable a more efficient paper-to-digital process, with potential to significantly improve communications by illuminating data through to the "last mile" of the health system.
Bridging the Paper to Digital Data Gap
Many rural and/or low-income communities worldwide rely on predominantly paper-based systems for supply chain management. Often there is no standardized system for collecting and reporting logistics data, particularly in the tracking of health commodities. The lack of such a reporting system leads to frequent stockouts and an inability to provide treatment and services to patients. Improved data visibility is essential for more timely and accurate decision making by health supply chain managers, immunization officers, and other health officials who experience significant challenges in receiving and analyzing data from paper-based systems. Developed in partnership with the University of Washington Department of Computer Science and Engineering, ODK Scan is a practical and low-cost mHealth solution that uses an Android application to enable a more efficient paper-to-digital process that can
Translate paper data to digital format for more accurate and timely statistical analysis and aggregation.
Significantly reduce the amount of time health workers spend on manual data input, allowing more time for frontline health service and delivery.
Alleviate the burden on health supply chain managers in receiving and analyzing data from paper-based systems.
Learn More About VillageReach ICT Capabilities
ODK Scan Field Test Report- Malawi (2015)
Paper-Digital Workflows in Global Development
ICTD Journal: Integrating ODK Scan into the Supply Chain in Mozambique
ODK Scan Overview Poster (PDF)
Gates Foundation to Support Enhanced ODK Solutions
Opendatakit.org
ODK Scan Product Reccomendations Report
ODK Scan Field Test - TB Registers in Pakistan
ODK Scan is an Android application that combines a device's built-in camera with specialized image-processing technology to automatically digitize data from paper forms, simply by snapping a photo.
Health workers in low-resource settings fill out the paper form as normal, without reliance on additional training, device power supply, or Internet connectivity.
Data collection managers take a photo of the form using the built-in camera on their smartphone or tablet.
Machine-readable data from the form is automatically digitized using computer vision running on the device.
Form fields that are not machine-readable are displayed as image snippets to the user for easy editing and transcription.
Data is synchronized to a local or cloud server, providing easy access to aggregated data and customized reports essential to health system decision-makers.
What is ODK?
ODK stands for Open Data Kit, a free and open-source set of tools that help organizations author, field, and manage data collected via Android devices. ODK tools have been used to track clean water projects in Kenya, monitor election fraud in Afghanistan, and enable epidemiological studies in Brazil, among many other projects.
ODK Scan In Action
ODK Scan has garnered interest from a wide range of sectors, including vaccine logistics, maternal health, applied psychology, education, and capacity building.
Two field tests in Mozambique with vaccine statistics and medical supply forms tested bubble and checkbox accuracy and provided essential usability feedback from community health workers.
Development work in 2014 added handwritten number and QR code recognition, as well as improved accuracy in the detection classifiers.
Locally-based field testing with a University of Washington Psychology Department project proved usability and technological relevance even in high-resource environments.
Two more field deployments are planned in 2015, specifically targeting low resource settings where other means of digitization are inaccessible.
ODK Scan beta will be released in Spring 2015 as open source for public use.
Appropriate Innovation: The Last Mile Perspective
Even with its obvious advantages, a transition to a paperless, strictly-digital data collection and management system is not feasible for low-resource environments with weak information communications infrastructure. These settings need a scalable bridge between hard and soft copy. ODK Scan is an appropriate solution in this context as it allows organizations and institutions to continue to use inexpensive, familiar paper forms while adding an easy to use technology to improve the efficiency of the paper-based system.


There's something about a disaster gif where you can see it unfold slowly, knowing full well what's going to happen. The slow build up towards the inevitable catastrophe which you know is coming but the poor person in front of a camera doesn't, even though they really should, is a uniquely hilarious thing. Why is it so funny? No one knows, but we've gone out and found some of the best examples of people who could've saved themselves by just being a little bit smarter. This one'll definitely make you laugh!
1. Having a drone take a family picture is just begging for pain.
2. Turns out oil on a real life race track is as funny as it is in Mario Kart.
The General is going to be mad at us!
6. The entire time I watched this I kept wondering how she was planning on stopping. The answer was "with her face".
7. The way this crane just slowly tilts until it falls builds tension better than most films!
8. Ouch. This one must've hurt, like, really badly.
10. It's actually freaky to see just how close this woman comes to a serious injury. Thankfully, she's okay.
11. George, George, George of the Jungle, watch out for that tree!!
14. It's like watching Speed 2 all over again except this isn't terrible.
It just suddenly jumped out in front of me. I didn't have a chance to swerve.