text:
\section{Introduction}
It is well known that, quantum correlations are the most important
physical quantities that have many applications in the context of
quantum information, communication and computations
\cite{Nielsen,El1,El4}. The behavior of entanglement between
different systems   has investigated for small and high dimensions
systems \cite{E3}. However, the properties of  systems which are
consists of different dimensional  subsystems have investigated in
different ways. For example, the behavior of entanglement for a
two-parameter class of qubit-qutrit system passes through
dissipative channels   has discussed by Wei et.al, \cite{Wei}.
Karat and Gedik \cite{Karpat} have discussed the quantum and
classical correlation of qubit-qutrit systems in the presence of
classical dephasing environment. The  quantum correlation's
behavior  of a qubit-qutrit system under the effect of dephasing
and bit flip channels  has investigated  by Guo et. al.,
\cite{Long}. Moreover, X. Xiao \cite{Xiao} has investigated the
possibility of protecting the quantum correlation of qubit-qutrit
system by using weak measurement and reversal.

Recently, the behavior of entanglement  in non-inertial frames has
investigated for different  dimensional systems. For example,
Alsing et. al.,  \cite{Alsing1} have discussed  the decay of
entanglement between two modes of a free Dirac field in a
non-inertial frame. The  correlation between two modes of Dirac
fields in non-inertial frames have investigated by Wang et. al,
\cite{Wang}. The  dynamics of a general two qubit system in
non-inertial frame is investigated   by Metwally \cite{Metwally1}.
The possibility of using an accelerated class of  $X$-state to
perform quantum coding is discussed in \cite{Metwally2}. Moreover,
teleportation in non-inertial frame is discussed by several
authors see for example (\cite{Alsing, Alsing1,Metwally3}).

However, for composite system which consists of different
dimensions subsystems, there are some limited efforts have been
done to study the entangled  properties of these systems in
non-inertial frames. The effect of global, collective, local and
multilocal depolarizing  noise on qutrit-qutrit states is studied
by S. Khan and M. Khan \cite{khan}. The measurement induced
disturbance for qubit-qutrit system  in non-inertial frames under
the effect of different noise channel has  investigated by Hao and
Lian-Fu \cite{Hao}. The importance of this problem appears clearly
in the the context of generating accelerated network. To clarify
this task,  assume that a source  supplies randomly  some  users
who located in different nodes with different dimensional states
to generated entangled network \cite{metwally4}. So, may any two
nodes of the same or different dimensions systems are  connected.
Then it is important to quantify the degree of entanglement to
find the optimal connection. Therefor, we are motivated to
consider a general class of qubit-qutrit system in non-inertial
frame, where we assume that these subsystems simultaneous and
non-simultaneous accelerated.

This manuscript is organized as follows: In Sec. $2$, we define
the general form of the suggested system. The final state of the
system is obtained analytically when one or both subsystems are
accelerated  simultaneously or non- simultaneously. In Sec. $3$,
the survival of entanglement between the two subsystems is
quantified by using the negativity as  a measure  of entanglement.
Finally, the results are summarized in Sec. $4$.

\section{System and its evolution}
In this contribution, it is assumed that we have a composite
system, consists of qubit $(A)$  and qutrit $(B)$, is given in its
general form. The evolution the final state of the qubit-qutrit
($Q_{bt}$ ) system  is investigated for three different  cases:
(i) the subsystem $(A)$ (qubit) is accelerated while qutrit $(B)$
is in a rest,(ii) the subsystem $(B)$ (qutrit) is accelerated
while the subsystem $(A)$ is in a rest, (iii) Both subsystems  are
accelerated. The general  state of the qubit-qutrit  system is
given by,
\begin{equation}\label{Qbt}
\rho_{Q_{bt}}=\frac{1}{6}\Bigl\{I_{2}\otimes
I{_3}+\sum_{i=1}^{3}s_i\sigma_i\otimes I_3+
\sum_{i=1}^{8}t_j\tau_j\otimes
I_3+\sum_{i=1}^{3}\sum_{j=1}^{8}c_{ij}\sigma_i\otimes\tau_j\Bigr\},
\end{equation}
where $I_{2}$ and $I_{ 3}$ are  the unit matrix of size $2\times
2$ and $3\times 3$ respectively,
$s_i=tr\bigl\{\rho_{Q_{bt}}\sigma_i\otimes I_{3\time
3}\bigr\},\quad t_j=tr\bigl\{\rho_{Q_{bt}}I_{2\time2}\otimes
\tau_j\bigr\}$ are the Bloch vectors for the qubit and the qutrit
respectively, $i=1..3,\quad j=1..8$. The operators $\sigma_i$ and
$\tau_j$ are the traceless hermitian generators of $Su(2)$ and
$Su(3)$ respectively. The elements
$c_{ij}=tr\bigl\{\rho_{Q_{bt}}\sigma_i\otimes \tau_j\bigr\}$,
represent the correlation matrix  between the qubit $(A)$ and the
qutrit $(B)$. In the computational basis $0$, $1$ and $2$, the
operators $\sigma_i$ and $\tau_j$ can be written as,
\begin{eqnarray}
\sigma_1&=&\ket{0}\bra{1}+\ket{1}\bra{0}, \quad
\sigma_2=i\ket{0}\bra{1}-\ket{1}\bra{0}),\quad
\sigma_3=\ket{1}\bra{1}-\ket{0}\bra{0}, \nonumber\\
\tau_1&=&\ket{0}\bra{1}+\ket{1}\bra{0},\quad
\tau_2=i(\ket{1}\bra{0}-\ket{0}\bra{1}),\quad\tau_3=\ket{0}\bra{0}-\ket{1}\bra{1},
\nonumber\\
\tau_4&=&\ket{0}\bra{2}+\ket{2}\bra{0}, \quad
\tau_5=i(\ket{2}\bra{0}-\bra{0}\ket{2}),\quad
\tau_6=\ket{1}\bra{2}+\ket{2}\bra{1}, \nonumber\\
\tau_7&=&i(\ket{2}\bra{1}-\ket{1}\bra{2}),\quad
\tau_8=(\ket{0}\bra{0}+\ket{1}\bra{1}-2\ket{2}\bra{2})/\sqrt{3}.
\end{eqnarray}
In the computational  basis, $\ket{00},\ket{01}, \ket{02},
\ket{10}, \ket{11}$ and $\ket{12}$, the state (\ref{Qbt}) can be
written as,
\begin{eqnarray}
\varrho_{00,ij}&=&\mathcal{A}_{\ell_1},\quad  \ell_1=1...6, \quad
\quad  \varrho_{01,ij}=\mathcal{A}_{\ell_2}, \quad \ell_2=7...12,
\quad
 \nonumber\\
\varrho_{02,ij}&=&\mathcal{A}_{\ell_3} \quad \ell_3=13...18, \quad
\varrho_{10,ij}=\mathcal{A}_{\ell_4},\quad  \ell_4=19...24, \quad
\nonumber\\
 \varrho_{11,ij}&=&\mathcal{A}_{\ell_51},\quad
\ell_5=25...30, \quad \varrho_{12,ij}=\mathcal{A}_{\ell_6},\quad
\ell_6=31...36,\quad
\end{eqnarray}
where    $ij=00,01,02,10,11,12$ and $\mathcal{A}_{\ell},
\ell=1...36$  are given in the appendix (A). For example, the
element $\varrho_{00,00}=\mathcal{A}_1,\quad
\varrho_{00,01}=\mathcal{A}_2, \quad
\varrho_{02,02}=\mathcal{A}_{15}\quad
\varrho_{12,12}=\mathcal{A}_{36}$ and so on.

Now we investigate the evolution of the $Q_{bt}$ state (1) in
non-inertial frame when one or both of its subsystems are
accelerated as following:

\begin{enumerate}
\item{\it Only the qubit is accelertaed\\} In this context, it is
important to review the behavior of a particle in non-inertial
frames. It has been shown that, in the inertial frames, Minkowsik
coordinates $(t,z)$ are  used to describe Dirac field, while in
the uniformly accelerated case, Rindler coordinates $(\tau, x)$
are more adequate. The relations between the Minkowski and Rindler
coordinates  are given by\cite{Alsing,Edu},
\begin{equation}\label{trans}
\tau=r~tanh\left(\frac{t}{z}\right), \quad x=\sqrt{t^2-z^2},
\end{equation}
where  $-\infty<\tau<\infty$, $-\infty<x<\infty$  and $r$ is the
acceleration of the moving particle. The relations (\ref{trans})
describe  two regions in Rindler's spaces: the first region $I $
for $|t|<x$  and the second region $II$ for $x<-|t|$.

 A single mode $k$ of fermions and anti-fermions
in Minkowski space is described by the annihilation operators
$a_{kU}$  and $b_{-kU}$ respectively. In terms of Rindler's
operators ( $c^{(I)}_{kR}, d^{(II)}_{-kL}$), the Minkowski
operators can be written as \cite{Walls,un},
\begin{eqnarray}\label{op}
a_{kU}&=&\cos r c^{(I)}_{k,R}-\exp(-i\phi)\sin r d^{(II)}_{-k,L},
\nonumber\\
 b^\dagger_{-kU}&=&\exp(i\phi)\sin r
c^{(I)}_{k,R}+\cos r d^{(II)}_{k,L},
\end{eqnarray}
where, $tan~ r=e^{-\pi\omega \frac{c}{a}}$, $0\leq r\leq \pi/$4, $
a$ is the acceleration such that $0\leq a\leq\infty$, $\omega$ is
the frequency of the travelling qubits, $c$ is the speed of light,
and $\phi$ is an unimportant phase that can be absorbed into the
definition of the operators \cite{Jason2013}. The operators
(\ref{op}) mix a particle in region $I$ and an anti particle in
region $II$ as,
\begin{eqnarray}\label{Min}
\ket{0_k}&=&\cos r\ket{0_k}_I\ket{0_{-k}}_{II}+ \sin
r\ket{1_k}_I\ket{1_{-k}}_{II}, \nonumber\\
\ket{1_k}&=&a^\dagger_k\ket{0_k} =\ket{1_k}_I\ket{0_k}_{II}.
\end{eqnarray}
Now,  by using the initial state of the qubit-qutrit system
$\rho_{Q_{bt}}$  (\ref{Qbt})  and the operators (\ref{Min}), the
final state in the first region $I$ of the Rindler space can be
written in the basis $00,01, 02, 10, 11$ and $12$. The density
operator is represented by  a matrix of size $6\times 6$. Its
elements are given by,
\begin{eqnarray}
\rho_{00,00}^{(q)}&=&c^2_q\varrho_{00,00}, \quad
\rho_{00,01}^{(q)}=c^2_q\varrho_{00,01},\quad
\rho_{00,02}^{(q)}=c^2_q\varrho_{00,02},\quad
\rho_{00,10}^{(q)}=c_q\varrho_{00,10},
\nonumber\\
\quad \rho_{00,11}^{(q)}&=&c_q\varrho_{00,11},\quad
\rho_{00,12}^{(q)}=c_q\varrho_{00,12},\quad
\rho_{01,00}^{(q)}=c^2_q\varrho_{01,00}, \quad
\rho_{01,01}^{(q)}=c^2_q\varrho_{01,01},\quad
\nonumber\\
\rho_{01,02}^{(q)}&=&c^2_q\varrho_{01,02},\quad
\rho_{01,10}^{(q)}=c_q\varrho_{01,10},\quad
\rho_{01,11}^{(q)}=c_q\varrho_{01,11},\quad
\rho_{01,12}^{(q)}=c_q\varrho_{01,12},
\nonumber\\
\rho_{02,00}^{(q)}&=&c^2_q\varrho_{02,00}, \quad
\rho_{02,01}^{(q)}=c^2_q\varrho_{02,01},\quad
\rho_{02,02}^{(q)}=c^2_q\varrho_{02,02},\quad
\rho_{02,10}^{(q)}=c_q\varrho_{02,10},\quad
\nonumber\\
\rho_{02,11}^{(q)}&=&c_q\varrho_{02,11},\quad
\rho_{02,12}^{(q)}=c_q\varrho_{02,12},\quad
\rho_{10,00}^{(q)}=c_q\varrho_{10,00}, \quad
\rho_{10,01}^{(q)}=c_q\varrho_{10,01},\quad
\nonumber\\
\rho_{10,02}^{(q)}&=&c_q\varrho_{10,02},\quad
\rho_{10,10}^{(q)}=s^2_q\varrho_{00,00}+\varrho_{10,10},\quad
\rho_{10,11}^{(q)}=s^2_q\varrho_{00,01}+\varrho_{10,11},
\nonumber\\
\rho_{10,12}^{(q)}&=&s^2_q\varrho_{00,02}+\varrho_{10,12},\quad
\rho_{11,00}^{(q)}=c_q\varrho_{11,00}, \quad
\rho_{11,01}^{(q)}=c_q\varrho_{11,01},\quad
\rho_{11,02}^{(q)}=c_q\varrho_{11,02},\quad
\nonumber\\
\rho_{11,10}^{(q)}&=&s^2_q\varrho_{01,00}+\varrho_{11,10},\quad
\rho_{11,11}^{(q)}=s^2_q\varrho_{01,01}+\varrho_{11,11},\quad
\rho_{11,12}^{(q)}=s^2_q\varrho_{01,02}+\varrho_{11,12},
\nonumber\\
\rho_{12,00}^{(q)}&=&c_q\varrho_{12,00}, \quad
\rho_{12,01}^{(q)}=c_q\varrho_{12,01},\quad
\rho_{12,02}^{(q)}=c_q\varrho_{12,02},\quad
\rho_{12,10}^{(q)}=s^2_q\varrho_{02,00}+\varrho_{12,10},\quad
\nonumber\\
\rho_{12,11}^{(q)}&=&s^2_q\varrho_{02,01}+\varrho_{12,11},\quad
\rho_{12,12}^{(q)}=s^2_q\varrho_{02,02}+\varrho_{12,12},
\end{eqnarray}
where $c_q=\cos r_q$ and $s_q=sin r_q$.

\item{\it Only the qutrit is accelerated\\} In this case, it is
assumed  that the qubit is in an inertial frame, while the qutrit
undergoes a constant acceleration.  For the  two level  qubit
system (spin $1/2$) particles, the Pauli-principle allows only two
occupation numbers i.e.,"0" and "1" \cite{Alsing1}. However, the
possibility of allowing the occupation number $"2"$ is discussed
by Le$\grave{o}$n and Mart$\grave{i}$nez \cite{Juan}. Under the
single mode-approximation, Minlowaski vacuum state $\ket{0_M}$ in
the Rindler space reads as,
\begin{equation}\label{Va}
\ket{0_M}=cos^2r\ket{0}_{I}\ket{0}_{II}+e^{i\phi}\sin r\cos
r(\ket{\mathcal{U}}_{I}\ket{\mathcal{D}}_{II}+\ket{\mathcal{D}}_{I}\ket{\mathcal{U}}_{II})
+e^{2i\phi}sin^2r\ket{\mathcal{D}}_{I}\ket{\mathcal{P}}_{II},
\end{equation}
where $\ket{\mathcal{U}}, \ket{\mathcal{D}}$ and
$\ket{\mathcal{P}}$ are the spin up, spin down and pair state
respectively. The spin up and down  in Rindler space are given by,
\begin{eqnarray}\label{qt}
\ket{\mathcal{U}_M}&=&cos
r\ket{\mathcal{U}}_I\ket{0}_{II}+e^{i\phi}\sin
r\ket{\mathcal{P}}_I\ket{\mathcal{U}}_{II},
\nonumber\\
\ket{\mathcal{D}_M}&=&cos
r\ket{\mathcal{D}}_I\ket{0}_{II}-e^{i\phi}\sin
r\ket{\mathcal{P}}_I\ket{\mathcal{D}}_{II}.
\end{eqnarray}
By using the initial state (\ref{Qbt}) and the transformation
(\ref{Va},\ref{qt}) one can obtain the final  state of the
accelerated system. After tracing out the mode in the second
region $II$, we obtain the final accelerated state in the first
region  $I$ of the Rindler space. In the  basis,
$\ket{\ell,0},\ket{\ell,\mathcal{D}},\ket{\ell,\mathcal{U}},
\ket{\ell,\mathcal{P}}~( \ell=0,1)$, the density operator is
defined by a matrix of size $8\times 8$, where its elements are
given by,
\begin{eqnarray}
 \rho^{(t)}_{00,00}&=&c_t^4\varrho_{00,00},
 \quad \rho{(t)}_{00,0\mathcal{D}}=c_t^3\varrho_{00,01}
 ,\quad \rho{(t)}_{00,0\mathcal{U}}=c_t^2\varrho_{00,02} , \quad
 \rho{(t)}_{00,0\mathcal{P}}=0,\quad
\nonumber\\
\rho{(t)}_{00,10}&=&c_t^4\varrho_{00,10},\quad
\rho^{(t)}_{00,1\mathcal{D}}=c_t^3\varrho_{00,11},\quad
\rho^{(t)}_{00,1\mathcal{U}}=c_t^2\varrho_{00,12},
 \quad \rho_{00,1\mathcal{P}}=0,\quad
\rho^{(t)}_{0\mathcal{D},00}=c_t^4\varrho_{01,00},\quad
 \nonumber\\
\rho^{(t)}_{0\mathcal{D},0\mathcal{D}}&=&c_t^2(s^2_t\varrho_{00,00}+\varrho_{01,01}),\quad
 \rho^{(t)}_{0\mathcal{D},0\mathcal{U}}=c_t^2\varrho_{01,02},
  \quad \rho_{0\mathcal{D},0\mathcal{P}}=c_ts^2_t\varrho_{00,02},
  \nonumber\\
\rho^{(t)}_{0\mathcal{D},\mathcal{D}0}&=&c_t^4\varrho_{01,10},\quad
\rho^{(t)}_{0\mathcal{D},\mathcal{D}\mathcal{D}}=c^2_t(s^2_t\varrho_{00,10}+\varrho_{01,11}),\quad
\rho^{(t)}_{0\mathcal{D},1\mathcal{U}}=c_t^2\varrho_{01,12},\quad
\rho^{(t)}_{0\mathcal{D},1\mathcal{P}}=c_ts^2_t\varrho_{00,12},
 \nonumber\\
\rho^{(t)}_{0\mathcal{U},00}&=&c_t^3\varrho_{02,00},\quad
\rho^{(t)}_{02\mathcal{U},0\mathcal{D}}=c_t^3\varrho_{02,01},\quad
\rho^{(t)}_{0\mathcal{U},0\mathcal{U}}=c^2_t(s^2_t\varrho_{00,01}+\varrho_{02,02}),\quad
\rho^{(t)}_{0\mathcal{U},0\mathcal{P}}=-c_ts^2_t\varrho_{02,10},\quad
\nonumber\\
\rho^{(t)}_{0\mathcal{U},10}&=&c_t^3\varrho_{02,10},\quad
\rho^{(t)}_{0\mathcal{U},1\mathcal{D}}=c_t^2\varrho_{02,11},\quad
\rho^{(t)}_{0\mathcal{U},1\mathcal{U}}=c^2_t(s^2_t\varrho_{02,10}+\varrho_{02,12}),\quad
\rho^{(t)}_{0\mathcal{U},1\mathcal{P}}=-c_ts^2_t\varrho_{00,11},\quad
 \nonumber\\
\rho^{(t)}_{0\mathcal{P},00}&=&0,\quad
\rho^{(t)}_{0\mathcal{P},0\mathcal{D}}=c_ts_t^2\varrho_{02,00},\quad
\rho^{(t)}_{0\mathcal{P},0\mathcal{U}}=-c_ts_t^2\varrho_{01,00},\quad
\rho^{(t)}_{0\mathcal{P},0\mathcal{P}}=s^2_t(s^2_t\varrho_{00,00}+\varrho_{01,02}),\quad
\nonumber\\
\rho^{(t)}_{0\mathcal{P},10}&=&0,\quad
 \rho^{(t)}_{0\mathcal{P},1\mathcal{D}}=c_ts_t^2\varrho_{02,10},\quad
\rho^{(t)}_{0\mathcal{P},1\mathcal{U}}=-c_ts_t^2\varrho_{01,10},\quad
\rho^{(t)}_{0\mathcal{P},1\mathcal{P}}=s_t^4\varrho_{00,10},
\nonumber\\
\rho^{(t)}_{10,00}&=&c^4_t\varrho_{10,00},\quad
\rho^{(t)}_{10,0\mathcal{D}}=c^3_t\varrho_{10,01},\quad
\rho^{(t)}_{10,0\mathcal{U}}=c^2_t\varrho_{10,02},\quad
\rho^{(t)}_{10,0p}=0
\nonumber\\
\rho^{(t)}_{10,10}&=&c^4_t\varrho_{10,10},\quad
\rho^{(t)}_{10,1\mathcal{D}}=c^3_t\varrho_{10,11},\quad
\rho^{(t)}_{10,12\mathcal{U}}=c^2_t\varrho_{10,12}, \quad
\rho^{(t)}_{10,1\mathcal{P}}=0,
 \nonumber\\
\rho^{(t)}_{1\mathcal{D},00}&=&c^3_t\varrho_{11,00},\quad
\rho^{(t)}_{1\mathcal{D},0\mathcal{D}}=c^2_t\varrho_{11,01},\quad
\rho^{(t)}_{1\mathcal{D},0\mathcal{U}}=c^2_t\varrho_{11,02}, \quad
\rho^{(t)}_{1\mathcal{D},0\mathcal{P}}=c_ts^2_t\varrho_{10,02},
\nonumber\\
\rho^{(t)}_{1\mathcal{D},10}&=&c^3_t\varrho_{11,10},\quad
\rho^{(t)}_{1\mathcal{D},1\mathcal{D}}=c^2_ts^2_t\varrho_{11,11},\quad
\rho^{(t)}_{1\mathcal{D},1\mathcal{U}}=c^2_t\varrho_{11,12}, \quad
 \rho^{(t)}_{1\mathcal{D},1\mathcal{P}}=c^2_ts^2_t\varrho_{10,12},
 \nonumber\\
\rho^{(t)}_{1\mathcal{U},00}&=&c^2_t\varrho_{12,00},\quad
\rho^{(t)}_{1\mathcal{U},0\mathcal{D}}=c^2_t\varrho_{12,01},\quad
\rho^{(t)}_{1\mathcal{U},0\mathcal{U}}=c^2_t\varrho_{12,02}, \quad
\rho^{(t)}_{1\mathcal{U},0\mathcal{P}}=-c_ts^2_t\varrho_{10,01},
\nonumber\\
\rho^{(t)}_{1\mathcal{U},10}&=&c^2_t\varrho_{12,10},\quad
\rho^{(t)}_{1\mathcal{U},1\mathcal{D}}=c^2_t\varrho_{12,11},\quad
\rho^{(t)}_{1\mathcal{U},1\mathcal{U}}=c^2_ts^2_t\varrho_{10,10},
\quad
 \rho^{(t)}_{1\mathcal{U},1\mathcal{P}}=-c^2_ts_t\varrho_{10,112},
 \nonumber\\
\rho^{(t)}_{1\mathcal{P},00}&=&0,\quad
\rho^{(t)}_{1\mathcal{P},0\mathcal{D}}=c^2_ts^2_t\varrho_{12,00},\quad
\rho^{(t)}_{1\mathcal{P},0\mathcal{U}}=-c_ts^2_t\varrho_{11,00},
\quad
\rho^{(t)}_{1\mathcal{P},0\mathcal{P}}=s^2_t(\varrho_{11,01}+\varrho_{12,02}),
\nonumber\\
\rho^{(t)}_{1\mathcal{P},10}&=&0,
 \rho^{(t)}_{1\mathcal{P},1\mathcal{D}}=c^2_t\varrho_{12,11},\quad
\rho^{(t)}_{1\mathcal{P},1\mathcal{U}}=-c_ts^2_t\varrho_{11,10},
\quad
 \rho^{(t)}_{1\mathcal{P},1\mathcal{P}}=s^2_t(\varrho_{11,12}+\varrho_{12,12}),
\end{eqnarray}
where $c_t=\cos r_t$ and $s_t=sin~ r_t$.

 \item{\it Both subsystems are accelerated:\\}
 In this case, we assume that both subsystems are accelerated. The  final state of the system in
the first region $I$ of the Rindler space is defined by a matrix
of size $8\times 8$ elements. The elements of this matrix are
given by,
\begin{eqnarray}
\rho^{(qt)}_{00,jk}&=&\mathcal{B}^{(qt)}_{\ell_1},\quad
\ell_1=1..3,\quad jk=00,0\mathcal{D},0\mathcal{U},\quad
\rho^{(qt)}_{00,jk}=\mathcal{B}_{\ell_2},\quad
\ell_2=4,5,\quad jk=10,1\mathcal{D}, \nonumber\\
 \rho^{(qt)}_{00,12}&=&\varrho_{00,1\mathcal{P}}=0, \quad
 \rho_{01,jk}^{(qt)}=\mathcal{B}_{\ell_3}, \quad
 \ell_3=\mathcal{B}_6...\mathcal{B}_{13}, \quad
 jk=00,0\mathcal{D},0\mathcal{U},0\mathcal{P},10,1\mathcal{D},1\mathcal{U},1\mathcal{P},\quad
 \nonumber\\
 \rho^{(qt)}_{02,jk}&=&\mathcal{B}_{\ell_4}, \quad
 \ell_4=\mathcal{B}_{14}...\mathcal{B}_{21},\quad
 jk=00,0\mathcal{D},0\mathcal{U},0\mathcal{P},10,1\mathcal{D},1\mathcal{U},1\mathcal{P},\quad
\rho^{(qt)}_{0\mathcal{P},00}= \rho_{0\mathcal{P},10}=0,\quad
\nonumber\\
\varrho^{(qt)}_{0\mathcal{P},jk}&=&\mathcal{B}_{\ell_5}, \quad
 \ell_5=\mathcal{B}_{22}...\mathcal{B}_{27},\quad
jk=0\mathcal{D},0\mathcal{U},0\mathcal{P},1\mathcal{D},1\mathcal{U},1\mathcal{P}
 \quad
\rho^{(qt)}_{10,0\mathcal{P}}= \rho^{(qt)}_{10,1\mathcal{P}}=0,
\nonumber\\
\rho^{(qt)}_{10,jk}&=&\mathcal{B}_{\ell_6}, \quad
 \ell_6=\mathcal{B}_{28}...\mathcal{B}_{33},\quad
 jk=00,0\mathcal{D},0\mathcal{U},10,1\mathcal{D},1\mathcal{U},\quad
 \rho_{11,00}=0,\quad
 \nonumber\\
\rho^{(qt)}_{1\mathcal{D},jk}&=&\mathcal{B}_{\ell_7}, \quad
 \ell_7=\mathcal{B}_{34}...\mathcal{B}_{40},\quad
 jk=0\mathcal{D}, 0\mathcal{U},0\mathcal{P},10,1\mathcal{D},1\mathcal{U},1\mathcal{P},
 \nonumber\\
\rho^{(qt)}_{1\mathcal{U},jk}&=&\mathcal{B}_{\ell_8}, \quad
 \ell_8=\mathcal{B}_{41}...\mathcal{B}_{48},\quad
 jk=00,0\mathcal{D},0\mathcal{U},10,1\mathcal{D},1\mathcal{U},1\mathcal{P},
 \nonumber\\
 \rho^{(qt)}_{1\mathcal{P},00}&=&
\rho^{(qt)}_{1\mathcal{P},0\mathcal{U}}=\rho^{(qt)}_{1\mathcal{P},10}=0,\quad
\rho^{(qt)}_{1\mathcal{P},0\mathcal{D}}=\mathcal{B}_{48},\quad
\rho^{(qt)}_{1\mathcal{P},0\mathcal{P}}=\mathcal{B}_{49},\quad
\nonumber\\
\rho^{(qt)}_{1\mathcal{P},jk}&=&\mathcal{B}_{\ell_9}, \quad
\ell_9=50...52, \quad jk=1\mathcal{D},1\mathcal{U},1\mathcal{P},
\end{eqnarray}
where $\mathcal{B}_i$ are given in the appendix (B). For example
$\rho^{(qt)}_{00,00}=\mathcal{B}^{(qt)}_1$,\quad
$\rho^{(qt)}_{10,0\mathcal{D}}=\mathcal{B}^{(qt)}_{29}$,
$\rho^{(qt)}_{1\mathcal{P},1\mathcal{P}}=\mathcal{B}^{(qt)}_{52}$
and so on.

\end{enumerate}

\section{Dynamics of Entanglement}
To quantify the degree of entanglement $\mathcal{E}$ which is
contained in the accelerated  system, we use the negativity as a
measure. For any composite system $\rho_{ab}$ consists of two
subsystems with different dimensions. In our case, the system $a$
represents the qubit (2-dimensions) and $b$ refers to the qutrit
(3-dimensions). The negativity  for this system is defined as,
\begin{equation}
{\Large\mathcal{E}}=max\left(0,\sum_i{\lambda_i}\right),
\end{equation}
where $\lambda_i,i=1..6$ are the eigenvalues of the partial
transpose of $\rho^{T_a}_{ab}$ \cite{karpat}.

\subsection{Example one}

To investigate the effect of the accelerated  particles on the
degree of entanglement, we consider  a system of qubit-qutrit is
defined by,
\begin{eqnarray}
\row{s}&=&(0,0,s_3), \quad \row{t}=(0,0,t_3,0,0,0,0,0),
\nonumber\\
&&\mbox{and the non zero elements of the correlation matrix  is, }
\nonumber\\
 c_{11}&=&1,\quad c_{22}=-1, \quad c_{33}=1.
\end{eqnarray}
By using (7), we obtain the final state of the qubit-qutrit system
in the first region, $I$ of the Rindler space  when  only the
qubit is accelerated. This state is described by $6\times 6$
elements in the computational basis $00,01,02,10,11$ and $12$. The
non- zero elements of this accelerated state in region $I$ are
given by,
\begin{eqnarray}
\rho^{(q)}_{00,00}&=&c_q^2\varrho_{00,00},\quad
\rho^{(q)}_{00,11}=c_q\varrho_{00,11}, \quad
\rho^{(q)}_{01,01}=c_q^2\varrho_{01,01}, \quad
\rho^{(q)}_{01,10}=c_q\varrho_{01,10}
\nonumber\\
\rho^{(q)}_{02,02}&=&c_q^2\varrho_{02,02},\quad
\rho^{(q)}_{10,01}=c\varrho_{00,01}, \quad
\rho^{(q)}_{10,10}=\varrho_{10,10}+s_q^2\varrho_{00,00},
 \nonumber\\
\rho^{(q)}_{11,00}&=&c_q\varrho_{11,00},\quad
\rho^{(q)}_{11,11}=\varrho_{11,11}+s_q^2\varrho_{01,01}, \quad
\rho^{(q)}_{12,12}=\varrho_{12,12}+s_q^2\varrho_{01,02}.
\end{eqnarray}
Similarly,  If  only the qutrit is accelerated, then the non zero
elements of the  final state  of the accelerated  system in the
first region of Rindler space  can be written in  the basis
$\ket{\ell,0}, \ket{\ell,\mathcal{D}}, \ket{\ell,\mathcal{U}},
\ket{\ell,\mathcal{P}}$, ( $\ell=0,1)$  as,
\begin{eqnarray}
\rho^{(t)}_{00,00}&=&c_t^4\varrho_{00,00},\quad
\rho^{(t)}_{00,1\mathcal{D}}=c_t^3\varrho_{00,11}, \quad
\rho^{(t)}_{0\mathcal{D},0\mathcal{D}}=c_t^2\varrho_{01,01}+c^2_ts^2_t,
\quad \rho^{(t)}_{0\mathcal{D},10}=c_t^3\varrho_{01,10},
 \nonumber\\
\rho^{(t)}_{0\mathcal{P},0\mathcal{P}}&=&s_t^4\varrho_{00,00}+s^2_t(\varrho_{01,01}+\varrho_{02,02}),
\quad
\rho^{(t)}_{0\mathcal{P}p,1\mathcal{U}}=-c_ts^2_t\varrho_{01,10},\quad\rho^{(t)}_{02,1p}=-c^2_ts^2_t\varrho_{00,11},
\nonumber\\
\rho^{(t)}_{0\mathcal{U},0\mathcal{U}}&=&c_t^2s^2_t\varrho_{00,00}+c^2_t\varrho_{02,02},\quad
\rho^{(t)}_{10,0\mathcal{D}}=c^3_t\varrho_{10,01}, \quad
\rho^{(t)}_{10,10}=c^4_t\varrho_{10,10},
 \nonumber\\
\rho^{(t)}_{1\mathcal{D},00}&=&c_t^2\varrho_{11,00},\quad
\rho^{(t)}_{1\mathcal{D},1\mathcal{D}}=c^2_t\varrho_{11,11}+c_t^2s\varrho_{10,10},
\quad
\rho^{(t)}_{1\mathcal{U},1\mathcal{U}}=c^2_t\varrho_{12,12}+c^2_ts_t^2\varrho_{10,10},
\nonumber\\
\rho^{(t)}_{1\mathcal{U},0\mathcal{P}}&=&-c_ts^2_t\varrho_{10,01},\quad
\rho^{(t)}_{1\mathcal{P},0\mathcal{U}}=-c_ts^2_t\varrho_{11,00},
\quad\rho^{(t)}_{1\mathcal{P},1\mathcal{P}}=s_t^4\varrho_{10,10}+s_t^2(\varrho_{11,11}+\varrho_{12,12}).
\nonumber\\
\end{eqnarray}
\begin{figure}
  \begin{center}
     \includegraphics[width=19pc,height=15pc]{Example-1.eps}
 \includegraphics[width=19pc,height=15pc]{Example-2.eps}
  \put(-100,1){$r$}
  \put(-450,90){\Large$\mathcal{E}$}
   \put(-350,1){$r$}
     \put(-220,90){\Large$\mathcal{E}$}
      \caption{The degree of entanglement  $\mathcal{E}$, where we assume that $r_q=r_t=r$ and (a)
     $ s_3=1$, $t_3=1$, and  (b)$s_3=t_3=0$. The solid  and the dot lines shows the behavior of entanglement
       when only the qubit and only the qutrit are accelerated respectively.   }
  \end{center}
\end{figure}
Finally, let us assume that both particles are accelerated. In
this case, the  elements of the final state in the first region
$I_1$ are given by,
\begin{eqnarray}
\rho^{(qt)}_{00,00}&=&c_t^4c^2_q\varrho_{00,00},\quad
\rho^{(qt)}_{0\mathcal{D},0\mathcal{D}}=c^2_qc^2_t(\varrho_{01,01}+s_t^2),
\quad\rho^{(qt)}_{10,01}=c_qc_t^3(\varrho_{10,01}+\varrho_{02,01}),
\nonumber\\
\rho^{(qt)}_{0\mathcal{U},0\mathcal{U}}&=&c^2_qc^2_t(\varrho_{02,02}+\varrho_{00,00}s^2_t),
\quad\rho^{(qt)}_{1\mathcal{P},0\mathcal{U}}=-c_qc_ts^2_t\varrho_{11,00},\quad
\nonumber\\
\rho^{(qt)}_{0\mathcal{P},0\mathcal{P}}&=&c^2_qs^2_t(s^2_q\varrho_{00,00}+\varrho_{01,01}+\varrho_{02,02}),\quad
\rho^{(qt)}_{1\mathcal{U},0\mathcal{P}}=-c_qc_ts^2_t\varrho_{10,01},\quad\rho_{01,10}=c_qc^3_t\varrho_{01,10},
\nonumber\\
\rho^{(qt)}_{10,10}&=&c^4_t(s^2_q\varrho_{00,00}+c^4_t\varrho_{10,10}),\quad
\rho^{(qt)}_{00,1\mathcal{D}}=c_qc^3_t\varrho_{00,11},
\nonumber\\
\rho^{(qt)}_{1\mathcal{D},1\mathcal{D}}&=&s^2_qc^2_t(s^2_q+\varrho_{01,01})+c^2_t(\varrho_{11,11}+s^2_t\varrho_{10,10}),\quad
\rho^{(qt)}_{0\mathcal{P},1\mathcal{U}}=-c_qc_ts^2_t\varrho_{01,10},\quad
\nonumber\\
\rho^{(qt)}_{1\mathcal{U},1\mathcal{U}}&=&s^2_qc^2_t(\varrho_{02,02}+s^2_t\varrho_{00,00})+c^2_t(\varrho_{12,12}+s^2_t\varrho_{10,10}),
\quad
\rho^{(qt)}_{0\mathcal{U},1\mathcal{P}}=-c_qc_ts^2_t\varrho_{00,11},\quad
\nonumber\\
\rho^{(qt)}_{1\mathcal{P},1\mathcal{P}}&=&s^2_qs^2_t(\varrho_{00,00}s^2+\varrho_{01,01}+\varrho_{02,02})
+s^2_t(s^2_t\varrho_{10,10}+\varrho_{11,11}+\varrho_{11,01}),
\end{eqnarray}
where the suffix $"q"$,  $"t"$  and $"qt"$ refer to the
accelerated qubit, qutrit and qubit-qutrit, respectively.

 The behavior of
entanglement, $\mathcal{E}$ is described in Fig.(1a), where we
assume that both  subsystems are initially polarized on the third
direction, namely we set $s_3=t_3=1$. It is clear that, the
entanglement decreases as the acceleration of the accelerated
subsystems increase. The decay rate of entanglement depends on the
accelerated system. However, if the smaller dimensional system is
accelerated, then the decay rate of entanglement is smaller than
the decay which is caused by accelerating the larger dimensional
system. These results are clearly seen by comparing the behavior
of endamagement when only the qubit is accelerated
(solid-curve)and its behavior when only the qutrit is accelerated
(dash-curve).  Moreover, the decay rate of entanglement is larger
if both subsystems are accelerated.

In Fig.(1b), we consider another system , where we set
$s_2=t_3=0$. The general behavior is similar to that shown in
Fig.(1a), namely, the entanglement decreases as the accelerations
of the subsystem increase. However, the decay rate of entanglement
is larger than that depicted in Fig.(1a).  This shows that, the
  entanglement of the initial system plays an essential
roles on the degree of entanglement of the accelerated systems.

\subsection{ One-Parameter Family}
 This class of qubit-qutrit system is known by  one parameter family. The  density operator of this
 system is given by,

\begin{eqnarray}
\rho_{qt}^{(1)}&=&
\ket{0}_q\bra{0}\Bigl\{\frac{p}{2}\left(\ket{0}_t\bra{0}+\ket{1}_t\bra{1}\right)+\frac{1-2p}{2}\ket{2}_t\bra{2}\Bigr\}
+\ket{1}_q\bra{0}\Bigl\{\frac{p}{2}\ket{2}_t\bra{0}\Bigr\}
\nonumber\\
&+&\ket{0}_q\bra{1}\Bigl\{\frac{p}{2}\ket{0}_t\bra{2}+\frac{1-2p}{2}\ket{2}_t\bra{0}\Bigr\}+
\ket{1}_q\bra{1}\Bigl\{\frac{p}{2}\ket{1}_t\bra{1}+\frac{1-2p}{2}\ket{0}_t\bra{0}\Bigr\},
\end{eqnarray}
where $0\leq p\leq \frac{1}{2}$ and the subscript $"q"$ refers to
the qubit while $"t"$ refers to the qutrit. If we assume that,
only the qubit is accelerated, then the density operator of the
final state in the first region $(I)$ is defined by the  following
non-zero elements, of a matrix of size $2\times 3$,
\begin{eqnarray}
\rho^{(1_q)}_{00,00}&=&\frac{p}{2}c^2_q,\quad
\rho^{(1_q)}_{00,12}=\frac{p}{2}c_q, \quad
\rho^{(1_q)}_{01,01}=\frac{p}{2}c^2_q,\quad
\rho^{(1_q)}_{00,12}=\rho_{12,00},
\nonumber\\
\rho^{(1_q)}_{02,02}&=&\frac{1-2p}{2}c^2_q,\quad\rho^{(1_q)}_{10,02}=\frac{1-2p}{2}c_q,
\quad\rho^{(1_q)}_{10,10}=\left(\frac{1-2p}{2}+\frac{p}{2}s^2_q\right),
\nonumber\\
\rho^{(1_q)}_{02,10}&=&\rho_{10,02},\quad\rho^{(1_q)}_{11,11}=\frac{p}{2}(1+s^2_q),\quad
\rho^{(1_q)}_{12,12}=\left(\frac{1-2p}{2}s^2_q+\frac{p}{2}\right).\quad
\end{eqnarray}
On the other hand, if  only the qutrit is accelerated, then the
final state of the total system  in the first region is defined by
a matrix of size $8\times 8$. The non-zero elements are given by,
\begin{figure}
  \begin{center}
     \includegraphics[width=30pc,height=18pc]{Ent-OneFamily.eps}
     \put(-180,0){$r$}
     \put(-335,110){\Large$\mathcal{E}$}
      \caption{ The entanglement of one parameter family evaluated at $p=0.5, r_q=r_t=r$. The solid, dash and dot
       curves represent the entanglement $\mathcal{E}$, when only
       the qubit , only the qutrit, and both of them are accelerated.  }
  \end{center}
\end{figure}
\begin{eqnarray}
\rho^{(1_t)}_{00,00}&=&\frac{p}{2}c^4_t,\quad\rho^{(1_t)}_{12,00}=\frac{p}{2}c^3_t,\quad
\rho^{(1_t)}_{0\mathcal{D},0\mathcal{D}}=\frac{p}{2}c^2_t(1+s^2_t),\quad
\rho^{(1_t)}_{1\mathcal{P},0\mathcal{D}}=\frac{p}{2}c_ts^2_t,
\nonumber\\
\rho^{(1_t)}_{0\mathcal{U},0\mathcal{U}}&=&c^2_t\left(\frac{1-2p}{2}+\frac{p}{2}s^2_t\right),\quad\rho^{(1_t)}_{10,02}=\frac{1-2p}{2}c^3_t,\quad
\rho^{(1_t)}_{0\mathcal{P},0\mathcal{P}}=s^2_t\left(\frac{p}{2}(1+s_t^2)+\frac{1-2p}{2}\right),
\nonumber\\
\rho^{(1_t)}_{1\mathcal{D},0\mathcal{P}}&=&\frac{1-2p}{2}c_ts^2_t,
\quad\rho^{(1_t)}_{10,10}=\frac{1-2p}{2}c^4_t,\quad
\rho^{(1_t)}_{0\mathcal{U},10}=\rho^{(1_t)}_{10,0\mathcal{U}},\quad
\rho^{(1_t)}_{1\mathcal{D},1\mathcal{D}}=\frac{1-2p}{2}c^2_ts^2_t,\quad
\nonumber\\
 \rho^{(1_t)}_{0\mathcal{P},1\mathcal{D}}&=&\frac{1-2p}{2}c_ts^2_t,
 \quad\rho^{(1_t)}_{00,1\mathcal{U}}=\rho^{(1_t)}_{12,00},\quad
 \rho^{(1_t)}_{1\mathcal{U},1\mathcal{U}}=c^2_t\left(\frac{p}{2}+\frac{1-2p}{p}s^2_t\right),
 \nonumber\\
 \rho^{(1_t)}_{0\mathcal{D},1\mathcal{P}}&=&\frac{p}{2}c_ts^2_t, \quad
 \rho^{(1_t)}_{1\mathcal{P},1\mathcal{P}}=s^2_t\left(p+\frac{1-2p}{2}s_t^2\right).
\end{eqnarray}
Finally, if  both subsystems are accelerated, then the final state
in the first region, $I$ is defined by the following non-zero
elements of a matrix of $8\times 8$,
\begin{eqnarray}
\rho^{(1_{qt})}_{00,00}&=&c^2_q\rho^{(1_{t})}_{00,00}, \quad
\rho^{(1_{qt})}_{1\mathcal{D},00}=\frac{p}{2}c_qc^3_t,\quad
\rho^{(1_{qt})}_{0\mathcal{D},0\mathcal{D}}=c^2_q\rho^{(1_{t})}_{0\mathcal{D},0\mathcal{D}},\quad
\rho^{(1_{qt})}_{1\mathcal{P},0\mathcal{D}}=c_q\rho^{(1_{t})}_{1\mathcal{P},0\mathcal{D}},
\nonumber\\
\rho^{(1_{qt})}_{0\mathcal{U},0\mathcal{U}}&=&c^2_q\rho^{(1_{t})}_{0\mathcal{U},0\mathcal{U}},\quad
\rho^{(1_{qt})}_{10,0\mathcal{U}}=c_q\rho^{(1_{t})}_{10,0\mathcal{U}},\quad
\rho^{(1_{qt})}_{0\mathcal{P},0\mathcal{P}}=c^2_q\rho^{(1_{t})}_{0\mathcal{P},0\mathcal{P}},\quad
\rho^{(1_{qt})}_{1\mathcal{D},0\mathcal{P}}=c_q\rho^{(1_{t})}_{1\mathcal{D},0\mathcal{P}},
\nonumber\\
\rho^{(1_{qt})}_{10,10}&=&\rho^{(1_{t})}_{10,10}+\frac{p}{2}c^4_ts^2_q,
\quad
\rho^{(1_{qt})}_{0\mathcal{D},10}=c_q\rho^{(1_{t})}_{10,0\mathcal{U}},\quad
\rho^{(1_{qt})}_{1\mathcal{D},1\mathcal{D}}=\rho^{(1_{t})}_{1\mathcal{D},1\mathcal{D}}+c^2_t\frac{p}{2}\left(1+s^2_q+s^2_qs^2_t\right),
\nonumber\\
\rho^{(1_{qt})}_{0\mathcal{P},1\mathcal{D}}&=&c_q\rho^{(1_{t})}_{0\mathcal{P},1\mathcal{D}},\quad
\rho^{(1_{qt})}_{1\mathcal{U},1\mathcal{U}}=\rho^{(1_{t})}_{1\mathcal{U},1\mathcal{U}}+c^2_t\left(\frac{p}{2}(1+s^2_ts^2_q)+\frac{1-2p}{2}s^2_q\right),\quad
\rho^{(1_{qt})}_{00,1\mathcal{U}}=c_q\rho^{(1_{t})}_{00,1\mathcal{U}},
\nonumber\\
\rho^{(1_{qt})}_{1\mathcal{P},1\mathcal{P}}&=&\rho^{(1_{t})}_{1\mathcal{P},1\mathcal{P}}+s^2_qs^2_t\left(\frac{p}{2}s^2_t+\frac{1-p}{2}\right),\quad
\rho^{(1_{qt})}_{01,1\mathcal{P}}=c_q\rho^{(1_{t})}_{0\mathcal{D},1\mathcal{P}}.
\end{eqnarray}
The behavior of entanglement for this case is shown in Fig.(2),
where we initially start with a system defined by $p=0.5$. The
general behavior is similar to that shown in Fig.(1), namely the
entanglement decays as the the acceleration of the accelerated
subsystem increases. The upper and lower bounds of entanglement
depend on the accelerated subsystem and the initial degree of
entanglement. However, if the qubit is allowed to be accelerated,
then  the upper bounds of entanglement are always larger than that
shown if one allows the qutrit to be accelerated. The decay rate
of entanglement increases if both particles are accelerated, where
we considered  both particles are accelerated with the same
acceleration (i.e., $r_q=r_t=r$).

\subsection { Two-Parameters family}
In this subsection we consider the second example which is known
by a two-parameter family. In the computational basis, this class
can be written as,

\begin{eqnarray}
\rho^{(2)}_{qt}&=&\ket{0}_q\bra{0}\Bigl\{\beta\ket{0}_t\bra{0}+\frac{\beta+\gamma}{2}\ket{1}_t\bra{1}
+\alpha\ket{2}_t\bra{2}\Bigr\}+\ket{1}_q\bra{0}\Bigl\{\frac{\beta-\gamma}{2}\ket{0}_t\bra{1}\Bigr\}
\nonumber\\
&& +
\ket{0}_q\bra{1}\Bigl\{\frac{\beta-\gamma}{2}\ket{1}_t\bra{0}\Bigr\}
+\ket{1}_q\bra{1}\Bigl\{\frac{\beta+\gamma}{2}\ket{0}_t\bra{0}+\beta\ket{1}\bra{1}+\alpha\ket{2}_t\bra{2}\Bigr\},\quad
\end{eqnarray}
where $\gamma+2\alpha+3\beta=1$ and the suffix $2$ refers to the
two-parameter. If it  assumed that only the qubit is accelerated,
then the final state in the first region, $I$ of the Rindler space
is described by the following non-zero-elements of a matrix of
size $6\times 6$,
\begin{eqnarray}
\rho^{(2_{q})}_{00,00}&=&\beta c^2_q,\quad
\rho^{(2_{q})}_{01,01}=\frac{\beta+\gamma}{2}c^2_q,\quad\rho^{(2_{q})}_{10,01}=\frac{\beta-\gamma}{2}c_q,
\nonumber\\
\rho^{(2_{q})}_{02,02}&=&\alpha c^2_q,\quad
\rho^{(2_{q})}_{01,10}=\frac{\beta-\gamma}{2}c_q,\quad
\rho_{10,10}=\beta s^2_q,
\nonumber\\
\rho^{(2_{q})}_{11,11}&=&\left(\beta+\frac{\beta+\gamma}{2}s^2_q\right),\quad
\rho^{(2_{q})}_{12,12}=\alpha(1+s^2_q).
\end{eqnarray}
On the other hand,  if we  consider only the qutrit is accelerated
then, the final state in the first Rindler region is defined by
the following non-zero elements,
\begin{eqnarray}
\rho^{(2_{t})}_{00,00}&=&\beta c^4_t,\quad
\rho^{(2_{t})}_{01,0\mathcal{D}}=c^2_t\left(\beta
s^2_t+\frac{\beta+\gamma}{2}\right),\quad
\rho^{(2_{t})}_{10,0\mathcal{D}}=\frac{\beta-\gamma}{2}c^3_t,
\nonumber\\
\rho^{(2_{t})}_{0\mathcal{U},0\mathcal{U}}&=&c^2_t(\alpha+\beta
s^2_t),\quad
\rho^{(2_{t})}_{0\mathcal{P},0\mathcal{P}}=s^2_t(\left(\alpha+
\frac{3\beta+\gamma}{2}s^2_t\right),\quad
\rho^{(2_{t})}_{1\mathcal{U},0\mathcal{P}}=-\frac{\beta-\gamma}{2}c_ts^2_t,
 \nonumber\\
\rho^{(2_{t})}_{0\mathcal{D},10}&=&\frac{\beta-\gamma}{2}c^3_t,\quad
\rho^{(2_{t})}_{10,10}=\frac{\beta+\gamma}{2}c^4_t,\quad
\rho^{(2_{t})}_{1\mathcal{D},1\mathcal{D}}=c^2_t\left(\beta+\frac{\beta+\gamma}{2}s^2_t\right),
\quad\rho^{(2_{t})}_{0\mathcal{P},1\mathcal{U}}=\rho^{(2_{t})}_{1\mathcal{U},0\mathcal{P}}
\nonumber\\
\rho^{(2_{t})}_{1\mathcal{U},1\mathcal{U}}&=&c^2_t\left(\alpha+\frac{\beta+\gamma}{2}s^2_t\right),\quad
\rho^{(2_{t})}_{1\mathcal{P},1\mathcal{P}}=s^2_t\left(\alpha+\frac{3\beta+\gamma}{2}s^2_t\right).
\end{eqnarray}
Finally, when both subsystems are accelerated, then the final
state in the first region, $I$ is defined by a matrix of size
$8\times 8$ elements. These elements  can be written by (22) as,
\begin{eqnarray} \rho_{00,00}^{(2_{qt})}&=&c^2_q\rho^{(2_{t})}_{00,00},\quad
\rho^{(2_{qt})}_{0\mathcal{D},0\mathcal{D}}=c^2_q\rho^{(2_{t})}_{0\mathcal{D},0\mathcal{D}},
\quad
\rho^{(2_{qt})}_{10,0\mathcal{D}}=c_q\rho^{(2_{t})}_{10,0\mathcal{D}},\quad
\rho^{(2_{qt})}_{0\mathcal{U},0\mathcal{U}}=c^2_q\rho^{(2_{t})}_{0\mathcal{U},0\mathcal{U}}
\nonumber\\
\rho^{(2_{qt})}_{0\mathcal{P},0\mathcal{P}}&=&c^2_q\rho^{(2_{t})}_{0\mathcal{P},0\mathcal{P}},\quad
\rho^{(2_{qt})}_{1\mathcal{U},0\mathcal{P}}=c_q\rho^{(2_{t})}_{1\mathcal{U},0\mathcal{P}},\quad
\rho^{(2_{qt})}_{0\mathcal{D}10}=c_q\rho^{(2_{t})}_{0\mathcal{D},10},\quad
\rho^{(2_{qt})}_{10,10}=s^2_q\rho^{(2_{t})}_{10,10},
\nonumber\\
\rho^{(2_{qt})}_{1\mathcal{D},1\mathcal{D}}&=&\rho^{(2_{t})}_{11,11}+s^2_q\rho^{(2_{t})}_{0\mathcal{D},0\mathcal{D}},
\quad
\rho^{(2_{qt})}_{0\mathcal{P},1\mathcal{U}}=\rho^{(2_{qt})}_{1\mathcal{U},0\mathcal{P}},\quad
\rho^{(2_{qt})}_{1\mathcal{U},1\mathcal{U}}=\rho^{(2_{t})}_{1\mathcal{U},1\mathcal{U}}+s^2_q\rho^{(2_{t})}_{0\mathcal{U},0\mathcal{U}},
\nonumber\\
\rho^{(2_{qt})}_{1p,1p}&=&\rho^{(2_{t})}_{1\mathcal{P},1\mathcal{P}}+s^2_q\rho^{(2_{t})}_{0\mathcal{P},0\mathcal{P}},
\end{eqnarray}

\begin{figure}[t!]
  \begin{center}
     \includegraphics[width=30pc,height=18pc]{Ent-TwoFamily.eps}
\put(-180,0){$r$}
  \put(-335,110){\Large$\mathcal{E}$}
      \caption{The dynamics of entanglement in the first region for qubit-qutrit system of two-parameter family
      with $\alpha=\beta=0.5$. The solid, dash and dot-curves represent $\mathcal{E}$, when only the qubit, qutrit
      and both qubit and qutrit are accelerated.    }
  \end{center}
\end{figure}
The behavior of entanglement for this class  is described in
Fig.(3), where all the three possibilities are considered. It is
assumed that, the system is initially prepared in maximum
entangled state $\alpha=\beta=0.5$. Therefore the entanglement is
maximum i.e., $\mathcal{E}=1$ at $r_q=r_t=0$.  It  is clear that,
the behavior of entanglement is similar to that predicated for one
parameter family. However, the entanglement decays as the
acceleration of any subsystem increases, where we consider that,
both of the subsystems have the same acceleration $(r_q=r_t)$. The
rate of entanglement decay increases as the dimensions of the
accelerated  subsystems increase.  Moreover, if both subsystems
are accelerated, then  the entanglement decreases faster.

\section{Conclusion}
In this contribution, we consider a general system  composite of
two different dimensions. One of them is a two-dimensional qubit
and the other is of three dimensional qutrit. It is assumed that,
one or both subsystems are accelerated simultaneously or non-
simultaneously. The density operator of the final state in the
first region  of the accelerated is obtained analytical in a
general form. Different examples are introduced to show the main
task of this manuscript.

Our results show that, the entanglement decays as the acceleration
of the accelerated particle increases. However, the decay rate
depends on the dimensions of the accelerated  subsystem. If only
the qubit is accelerated, then the entanglement decays gradually
to reach its non-zero values at  infinity. On the other hand, if
we allow only  the qutrit to be accelerated, then the entanglement
decays faster and its upper bounds always smaller than that
depicted for accelerating qubit. Moreover, if  one allows for both
subsystems  to be accelerated, then the decay rate of entanglement
is larger.

The idea is shown  explicitly by considering  three different and
common examples. In the first example, we assume that both
subsystems are polarized in $z-$axis. It is clear that, the decay
of entanglement depends on the initial correlation between the two
subsystems. The second and third examples are known by one and
two-parameters families. These examples have been investigated
widely in the context of quantum information. It is shown that the
decay rate of entanglement depends on the initial degree of
entanglement in addition to the dimensions of the accelerated
subsystem.

{\it In conclusion:} the decay of entanglement depends on the
dimensions  of the accelerated subsystems, where the decay rate of
entanglement increases when the larger dimensional  subsystem is
accelerated. The robustness of the accelerated system depends on
the initial quantum correlation between the two subsystems. We
expect that these results could be important in building an
accelerated quantum network consists of different dimensions
nodes.

redpajama_set_name: RedPajamaArXiv


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text:
Mobile »
online fashion
Moda Rapido
Artie robot
Myntra's Artie robot to help you find the latest in fashion with little efforts
Myntra, the online fashion store owned by Flipkart, has launched Moda Rapido, a fashion brand powered by artificial intelligence.Varun Jain | ET Bureau | September 22, 2015, 10:18 IST
The next time you look for fashion on Myntra, Artie will help you find the latest styles and designs with little effort.
Myntra, the online fashion store owned by Flipkart, has launched Moda Rapido, a fashion brand powered by artificial intelligence. Artie is a robot character created by Myntra to represent Moda Rapido, the in-house brand that the company says will be capable of offering new styles and designs to its consumers every week round the year.
The software will scan fashion data available on the Internet looking for what consumers are looking for, and using that data it will come up with the key attributes that they like.
"We will bring new products every week. We will react to everything that is selling well, go back and make it, and bring it for our customers in 20 days," said Gautam Kotamraju, senior vice president for new initiatives at Myntra. "We have a nimble supply chain which allows us to do so."
It took eight months for a 25-member tech team at Myntra to build this brand at its Bengaluru facility. Myntra used computer vision for machine to learn fashion and its attributes and had a few design specialists who helped the machine to learn.
"Our artificial intelligence tells us what material we have on one side and what people are liking on the other side and therefore it puts across a basic skeletal framework together for the in-house designers, who would then tweak the designs according to the demand," Kotamraju said.
E-commerce majors like Snapdeal and Flipkart are aggressively working on technological fronts to engage more with their customers. Flipkart, the market leader, recently introduced Ping, a messaging platform which allows online shoppers to consult with friends and others in real-time to make a decision on what to buy.
It also launched a feature called the Image Search, which allows users to upload an image of the product they are looking for and find visually similar stuff on the platform. Rival Snapdeal has introduced findmystyle.in, a tool that filters the wide catalogue of apparels and footwear to show the most relevant products without the traditional way of using filters like keywords, brands, price, etc.
"Whatever products you see under the Moda Rapido brand are based purely on (artificial) intelligence and there are no designers involved in the process," said Ganesh Subramanian, head of new initiatives at Myntra. "It is machine created mostly. We are calling it the Insta Trend."
Initially, the brand will offer popular items such as jeans and t-shirts for men and women and then extend it to other categories. According to Myntra, this is the first step and in 2016 it will start sharing the insights and intelligence with their other partners as well.
"We will tell them (suppliers) the attributes which are working well. Those with the nimble supply chain and have the ability to react within the timeframe will react. When they start making products according to consumer liking, it will help both of us to go a long way in increasing our consumers," said Kotamraju.
Tags : Mobile, online fashion, Myntra, Moda Rapido, Flipkart, e-commerce, Artie robot
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redpajama_set_name: RedPajamaCommonCrawl


Be-IT Resourcing are currently working with a large software and analytics company based in Glasgow. They are seeking a Team Leader who will be responsible for the effective day to day operation of a team of engineers.
Delivering product scope or services to the department. They are actively engaged in all aspects of the software development lifecycle and need to manage the competing demands on finite team resources while removing any blockers to team progress. They will be responsible for the creation and maintaining a schedule for the team's scope and available resources.
They are responsible for tracking the team's delivery, reporting on progress to plan, managing the team's risks, issues and dependencies and balancing the competing demands being placed on the team.
Demonstrations. Clarify roles and responsibilities. Communicate clear boundaries, values, goals, expectations. Assess decisions/actions and recognise potential impacts on individuals and groups and make plans to meet the needs of all stakeholders as effectively as possible. Communicate progress, risks and issues via weekly status reports. Provide ad-hoc reporting as required.
Experience of version control systems e.g. Subversion, CVS, Git.
Experience of an IDE e.g. Eclipse, IntelliJ IDEA.
Understanding of cross-browser compatibility concerns.
Experience of root cause analysis.


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Q: PHP If-Else-Finally I am looking for smarter way of solving what I have called if-else-finally case.
The Case
According to different conditions the object's property requires different value. Only if this property has been changed persist the object to DB.
The example (pseudocode)
if _condition-A_ then
    set object.property to value-A
else if _condition-B_ then
    set object.property to value-B
else if _condition-C_ then
    set object.property to value-C
finally
    object.persist()

My solution
$changed = false;
if ($conditionA) {
    $changed = true;
    $this->property = 'A';
} elseif ($conditionB) {
    $changed = true;
    $this->property = 'B';
} elseif ($conditionC) {
    $changed = true;
    $this->property = 'C';
}
if ($changed) {
    $this->save();
}

Is there any better/smarter solution for this? The switch-case-default construct is not possible as the conditions are compounded from smaller partial conditions that differ in each if statement.

A: I just played with php array
if ( $property = array_search( true, array(
    'A' => $conditionA ,
    'B' => $conditionB ,
    'C' => $conditionC
)) ){
    $this->property = $property;
    $this->save();
};

A: You can avoid repeating $changed = true; by this way :
$changed = true;
if ($conditionA) {
    $this->property = 'A';
} elseif ($conditionB) {
    $this->property = 'B';
} elseif ($conditionC) {
    $this->property = 'C';
} else {
    $changed = false;
}
if ($changed) {
    $this->save();
}

A: Though this is not a real answer for my question (as I already accepted one), I wanted to post here some thoughts on using ternary operators and using here mentioned third-party iif function.
This iif stands for Immediate if and it's implementation could be this:
function iif($condition, $true, $false) {
    return ($condition ? $true : $false);
}

I am telling could because it is not a native part of PHP and if you want to use it, you need to define it somewhere globally and it is completely up to you how you define it, maybe even
function iif($condition, $true, $false) {
    return ($condition && $true ? true : $false);
}

(just for example). So one cannot be never sure what that stinky iif does in the end. As you can see, this iif can use ternary operator successfully, and it is in the end much predictable to use them directly. Therefore instead of running this black-box
$this->property = iif($conditionA, // what does this 'iif' do???
    'A',
    iif($conditionB, // what does this 'iif' do???
        'B',
        iif($conditionC, // what does this 'iif' do???
            'C','NONE')));

it is much brighter (when it comes to light conditions) to use
$this->property = $conditionA // ok, if matches then 'A'
    ? 'A'
    : $conditionB // ok, if matches then 'B'
        ? 'B'
        : $conditionC // ok, if matches then 'C' otherwise 'D'
            ? 'C'
            : 'D';

As you can see usage of ternary operators can be more readable and predictable even if they are used recursively.
And now I want to show you how can such complicated ternary operator be created. Imagine that you are doing a download of data into a CSV (; seprarated) file. You have to filter only the columns for CSV within the retrieved data and optionally trim the value if it exists. The ternary is quite simple:
foreach ($fields as $field) {
    $row[] = array_key_exists($field, $item) // if field is present and contains value trim it
        ? trim($item[$field])))
        : ''; // otherwise use empty string
}

This is running fine for a while until somebody comes and tells you that he wants to have Yes/No displayed instead of 1/0 in two columns. So, OK, no big deal, let's just slightly modify this condition:
foreach ($fields as $field) {
    $row[] = array_key_exists($field, $item) // if field is present and contains value
        ? ($field == 'col1' || $field == 'col2' // if it is a 'col1' or 'col2' field
            ? ($item[$field] ? 'Yes' : 'No') // display 'Yes'/'No'
            : trim($item[$field])) // otherwise trim the value
        : ''; // otherwise use empty string
}

OK... Now it is little bit complicated since we added one more level and the true expression of the inner level contains another ternary. And what if the same guy comes again and tells you to add two new columns, which can have values NULL, 0 and 1 and for each you have to display either '', No or Yes? Well, then it could look like this one:
foreach ($fields as $field) {
    $row[] = array_key_exists($field, $item)
        ? ($field == 'col1' || $field == 'col2'
            ? ($item[$field] ? 'Yes' : 'No')
            : ($field == 'col1_1' || $field == 'col2_2'
                ? ($item[$field] === 1 ? 'Yes' : $item[$field] === 0 ? 'No' : '')
                :trim($item[$field])))
        : '';
}

Here, at this point, I stopped for a while and started thinking about rewriting into if-else which would have more readability but I would have to write it all in more lines which I didn't want to do either. The code isn't that much confusing, it is nicely structured so that everybody sees where the new recursion starts and ends. But this is possible only since the conditions themselves are quite simple and single-layered.
In case of more complicated conditions for each ternary I would avoid using ternary operators and stick to if-else to preserve readability.

A: You could create a map of the conditions to the property value.
Example of the concept:
$conditionA = false;
$conditionB = true;
$conditionC = false;

$conditions = [
  'conditionA' => 'A',
  'conditionB' => 'B',
  'conditionC' => 'C'
];

foreach($conditions as $conditionName => $conditionValue) {
    if (!empty($$conditionName)) {
        $this->property = $conditionValue;
        $this->save();
        break;
    }
}

redpajama_set_name: RedPajamaStackExchange


Click below to review this Sunday's Order of Worship (March 31, 2019).
We hope you will join us for 10 a.m. Coffee & Conversation with Sam Smalldon. See other post for more details.
This will be followed by the 11 a.m. Worship Service. See you Sunday!
While researching in the Temple Library, Conference Director Susan Naylor ran across two Program for Reunions publications dated 1923 and 1924. "As I scanned the copy, it was impressed on me how often we have come together to make reunions and conferences happen over the decades. It takes numerous individuals to help facilitate programs and activities," she said.
It's been almost one-hundred years, and the 2019 World Conference is not any different. There are a variety of needs for someone to volunteer to be a part of this world-wide event staff.
A couple areas that are new this Conference is a need for some help around the lunch hour timeframe to assist in the dining room - wipe tables, carry trays, fill water glasses, to be a presence. There is one dinner opportunity, Friday, April 12, that needs dining room assistance.
Hosts are needed to assist with dinners for our international group Saturday through Friday - greeters, serve, help as needed, to be a presence.
This is a great place to work with long-time friends, make new friends and play a vital part in the World Conference. Maybe your congregation or delegation wants to sponsor a day. These are nice opportunities to pay it forward – where can you serve?
Check out the online sign-up for, SignUp Genius, and see where you might be able to assist one time or more. Bring a friend, you won't regret it!
Topic: "World Conference Resolution - Bridge of Hope Discussion"
Details: Sam Smalldon will be leading the congregation in a discussion on Bridge of Hope on Sunday, March 31 at 10 a.m. The document could have an impact on multiple resolutions, so this discussion will help to provide a good understanding heading into World Conference.
Please review these materials for the coffee and conversation and bring your questions.
Many dining opportunities are available during World Conference. The Laurel Club served for more than 100 years, but has closed its business. We are grateful for its service and ministries, and we say thank you. We're sharing this information so our readers can help push information out to delegates and others they know are coming to World Conference. This information is also available via the Conference App. We know this will be different and change can be challenging.
This Conference brings a new look to the serving line catered by several restaurants from Independence Square. The dining room is available to share table fellowship with friends, old and new.
In addition to the on-site options, all restaurants on Independence Square have worked on "10-minute menus." These are quick meals that enable Conference participants to get a quick getaway, eat, and return to Conference in the allotted time.
Conference attendees can watch for additional dining info on screens, in print, or at the information desks in the Auditorium and Temple.
We look forward to gathering with you online for World Conference!
Reflect on the questions in this video and share your responses in the comments. ?❓?
Click below to review this Sunday's Order of Worship (March 24, 2019).
We hope you will join us for 10 a.m. Coffee & Conversation with Shirley Smith on the topic of Art Smith's Herald magazine article (pages 6-10). Please read prior to Sunday morning and bring your copy of the Herald with you.
15 Days to World Conference!
Are you getting excited? We are!
Tropical Cyclone Idai made landfall in Mozambique with 175 kph (110 mph) winds last week and major rainfall and storm surge before moving inland into Zimbabwe and Malawi, affecting 1.5 million people in its wake.
Please keep the people of Mozambique, Zimbabwe, and Malawi in your prayers as they deal with the devastation of this storm. As of today, we do not have specific information about the impact to members and friends or church faciliities in those countries.
Since the announcement of the tragic shooting in your nation, the members of the First Presidency have held you and the people of New Zealand in our prayers. There is never adequate words to express at a time of deep loss and tragedy like all of you have experienced in the past several days. And yet, even in the midst of the pains and sorrows that grip all of us around the world, there is the consistent message of God's love and peace that seeks to be heard in our lives and in our responses to this kind of loss.
Please know that we unite our faith in God with your faith as we pray for healing for all the families impacted, the Christchurch community and your nation. As the Easter celebration is one month away, we need to remember that God's faithfulness will always seek to bring healing and new life out of suffering and tragedies we all face. This is the hope we hold on to for you and for the people of New Zealand. Though we are a long distance from you, we are united with you in our prayers, our hope, and our love and faith.
May each of you encounter moments of peace and blessings from our love and from God's presence that abides.


text:
Truth, lies and vengeance in the Public Protector's office
November 12, 2019 Written by Admin
On Thursday afternoon, the Mail & Guardian asked the public protector's office to respond to grave allegations by its former chief of operations in court papers — that Busisiwe Mkhwebane had lied, had acted unconstitutionally and for her "own ends".
The public protector's office dismissed Basani Baloyi's allegations as untrue and as "vindictive vengeance". Spokesperson Oupa Segalwe said Baloyi's claims "seek to feed into the meritless claims and perception[s] that are out there".
His answer crystalises with precision why Baloyi's claims are so significant.
Since Mkhwebane's appointment as public protector, there have been questions swirling about her motives. Baloyi's claims not only "seek" to feed into perceptions. They do feed into them. And whether the claims are meritless remains to be seen.
Baloyi filed court papers on Thursday, accusing the public protector of lying, of acting unconstitutionally and for her "own ends". She referred in her affidavit to two of the most politically contentious reports — with findings against President Cyril Ramaphosa and Public Enterprises Minister Pravin Gordhan — saying the investigations were "extremely unusual".
READ MORE: Public Protector 'played chess with the country'
Questions about Busisiwe Mkhwebane began from the moment of her appointment. But it was really with the Absa-Bankorp report — her report into 1980's bail-out by the Reserve Bank of Bankorp, which was acquired by Absa in 1992 — that people got seriously worried.
When the Reserve Bank and Absa challenged the report in court, it emerged during the litigation that Mkhwebane had consulted with the State Security Agency and the presidency and did not reveal the meetings with the presidency in her final report.
The Constitutional Court took a dim view of her explanations, saying they made "no sense" and were "contradictory" and only "compounded the case against her". The highest court ultimately ordered personal and punitive costs against her. Before that was the high court judgment on her Estina report, which found that the way she narrowed the scope of her investigation lacked "any logical or legitimate explanation".
But it was Gordhan who first threw down the political gauntlet, saying in no uncertain terms in court papers that her report into the early pension payout of former acting Sars commissioner Ivan Pillay was "politically motivated".
The President, at first cautious and respectful, has now also questioned her motives, accusing Mkhwebane of an ulterior motive in her investigation into the donation by the late Gavin Watson of Bosasa to Ramaphosa's CR17 campaign for the ANC presidency.
These two court cases have raised even more serious and alarming questions about the public protector — yet to be answered.
Questions include where she obtained the emails (now attached to the still sealed court record in the CR17 Bosasa litigation) that indicate Ramaphosa may have known much more about the donors to his campaign then he is letting on.
We want to know why she put Financial Intelligence Centre (FIC) documents — not supposed to be used as evidence — before the high court, when she could easily have verified the information the FIC provided her through her own subpoena powers. Was she in a rush? Why?
We want to know why she raised in her Bosasa report a suspicion of money laundering when the FIC's staff told her investigators that, on the information the Centre had, there was no indication of money laundering. And then, strangely, in her report, she refers to the Prevention and Combating of Corrupt Activities Act (Precca) instead of the Prevention of Organised Crime Act (Poca), which is the legislation that defines money laundering. What was that all about?
We are curious as to the source — she said it was anonymously sent to her — of the Inspector General of Intelligence report, a redacted version of which has now been declassified. The report supports Mkhwebane's finding that there was an unlawfully formed investigative unit within South African Revenue Service (Sars) that unlawfully spied on people. But how that report found its way into the hands of the public protector long before it was declassified — and even more strangely into the hands of the Economic Freedom Fighters' Floyd Shivambu — remains a mystery.
Transparency is supposed to be one of the hallmarks of the work of the public protector —unless she is acting in good faith under the Protected Disclosures Act to protect whistleblowers.
And why did the public protector seemingly discount so much evidence in her "rogue unit" investigation, as alleged by former acting Sars commissioner Ivan Pillay? Why is this apparent discounting of relevant evidence such a constant refrain in so many of the court cases challenging her reports — most recently raised by #UniteBehind in its challenge to the public protector's recent Passenger Rail Agency of South Africa report?
It is important to remember that these questions may yet be properly answered when the public protector files her answering affidavit in the CR17/Bosasa case — expected later this week — and to Part B of the "rogue unit" case.
But Baloyi's allegations shore up the view that the protector's motives are suspect. That's because now, someone privy to the innermost workings of the office at the high level of COO is saying yes, the "rogue unit" and Bosasa investigations were "extremely unusual".
Baloyi said external investigators were unnecessarily brought in for the Bosasa investigation and staff at the PP's office sidelined. These two highly politically sensitive investigations were prioritised over other investigations. The CEO, not supposed to be involved in investigations, was involved. When the PP's office earlier told the M&G that he wasn't this was "a lie", she said.
There is also the somewhat cryptic sms attached to Baloyi's court papers ""COO, I worked with few people to deal with the sabotage of the PG [Pravin Gordhan] camp. The notice is almost ready for rogue [unit], will issue this week and report will also be issued in the manner I will determine. The notice for the president is also ready, will call him this week to discuss the notice. It is not about you but one has to play the chess." A screenshot of the WhatsApp message is attached to the court papers.
Baloyi took the message to mean she was playing political games. Not at all, said the public protector — she was being strategic in the face of a media onslaught: "The text in question was sent at the time when the subject of the investigation was dealing with the public Protector through the media. The public protector's text was therefore referring to countering that."
When approached for comment, the public protector commendably answered Baloyi's allegations in record time. She said the number of people working on the Bosasa matter was reduced "due to the sensitivities involved".
"The matter involved the Head of State and the information gathered including bank statements had to be handled with care. In fact, Ms. Baloyi was on a number of times found to have revealed sensitive details of investigations during social gatherings, breaching confidentiality agreements, and was cautioned about that."
There is no truth in the claim of "rushed" investigations, she said. The Executive Members' Ethics Act required that the investigations be expedited. It puts a timeframe of 30 days. "The public protector hardly ever meets this deadline because of the complexity of the matters and due to lack of resources but she does work hard to finalise them sooner – in compliance with that law," her office said on Thursday.
They take as long as they take, she said. In order to really counter that, one would have to show that other investigations could in fact have taken less time, but were put on the back-burner in order to focus on the Bosasa and Rogue Unit ones. Baloyi does suggest this in her affidavit — when she says some investigations were prioritised — but does not give an example of one that could have gone quicker and against which her claim can be tested.
The fact that Baloyi has fallen out with Mkhwebane and left on bad terms also cannot be discounted. Mkhwebane calls Baloyi's court case "vindictive vengeance", and it may well be so.
It may also well be that her claims are both vindictive and true.
We would do well to wait for all the court papers — especially the answering papers in the Bosasa and rogue unit cases —before finally taking a view.
Polo rides the Beats smoothly
Australians trapped by bushfires told 'too late to leave'


Once there was a prince. An evil sorcerer had stolen his heart, and the boy was sent from his floating kingdom in the heavens to Earth in order to retrieve it. Wings gone, he fell to Earth.
You guys probably know this, but I thought I'd check in. I'm feeling genki genki and am about to return for the big family reunion. hehe. Well, my location's been encrypted into the ... well, enrypted mail. Yare yare ;p I'm getting as paranoid as you guys (minus Quatre of course) Come pick me up, cause I ain't got anything to travel with. Well, I guess I can always pick pockets... I'll see ya when I see ya!
No one argued when Heero abruptly volunteered to go, more than a hint of challenge in his voice.
His quest was a hard one. No one knew where the sorcerer had fled with his heart. The prince, now human boy, felt the numbness under his breastbone spread all throughout his soul. Then the rumours came to his ears. The sorcerer had hidden his heart with another human, and he journeyed ever further on Earth.
And the prince finally found the one who had held his heart. Or rather, they found each other.
The human boy offered his own heart in exchange. The prince accepted. And they lived... ever after.
Hehehe.. maybe an epilogue if I can think of an ok one ^^ What'cha think?


text:
Parkland Speaks: Live at CSPA March 21, 2019
Aimee Parsons
Photo by: Aimee Parsons
March 21, 2019 / Podcasts / Walsworth Live
Parkland Speaks: Live at CSPA
Written by Sarah Scott
The benefits of art and writing as a means to process trauma are widely acknowledged, and the survivors of the February 14, 2018, school shooting in Parkland, Florida, have turned that means of therapy into a book. "Parkland Speaks: Survivors from Marjory Stoneman Douglas Share Their Stories" was published by Crown Books, a division of Random House, in February of 2019, one year after the tragedy that left 17 members of their school community dead.
In the newest episode of Yearbook Chat with Jim, host Jim Jordan sat down with friend and yearbook adviser Sarah Lerner, CJE, andpublication students of Marjory Stoneman Douglas. Recorded live at the Columbia Scholastic Press Association (CSPA) Spring Convention in New York City, they shared their experience contributing to and compiling the book and read from the pieces they submitted.
Sarah Lerner
Lerner and her staff have completed the 2019 Aerie yearbook. They're attending CSPA, where Lerner will be given a Gold Key award – an honor CSPA bestows on exceptional publications advisers.
A senior editor from Random House approached Lerner about creating a collection of art, photos and writing by students and community members affected by the shooting. She accepted, and spent the summer of 2018 working on "Parkland Speaks."
"I really tried to get as much material as I could so that we were able to provide a very big-picture look at not just what the event meant to us, but how different people were dealing with things and processing their thoughts," said Lerner.
Her efforts resulted in a collection of pieces from the day and the attempts to process after it happened – including art, photos, writing, and parts of speeches and congressional testimony. She's been overwhelmed by the positive response.
"I love that [the book] gives a snapshot of not just that day, but the continued healing that we're all trying to do. Because we're ok, but we're not ok. And we will never be fully ok."
Cat Tibbetts
Caitlynn Tibbets (who prefers to go by Cat) has two poems in the book. The first, "Case Number 18001958CF10A," she'd posted online as a means of venting frustration about all the media attention being paid to the shooter. Lerner reached out to her asking if she'd like to include that poem. Later, Tibbetts remembered another piece that fit the book, "All Over Again," a poem about the first day back at school after February 14.
"All of a sudden, it was here, and it was really, really mind blowing that something I wrote, something that so many people wrote, is actually something that everyone can read," said Tibbetts.
Rebecca Schneid
Rebecca Schneid frequently wrote in her journals, so Lerner asked if she'd like to contribute to "Parkland Speaks." It just so happened that Schneid had stayed up the night before the request writing a poem she'd originally intended for spoken word. "Zoo Animal" shares her feelings about being in the national eye and feeling constantly watched and scrutinized.
Brianna Fisher
Lerner knew Brianna Fisher from her Journalism I class, and reached out to see if she had anything she'd like to contribute. Fisher chose to submit a photo she'd posted on Instagram the day of the shooting.
"The day everything happened, there was one picture everyone was posting on social media. And everyone had their long comments and what they wanted to say," said Fisher. "And I kind of wanted to do something more personal to me, because I fell so connected to the school.
That day, she chose to post a series of photos from times she'd been really happy, including the picture from freshman year orientation that was used in the book.
Leni Steinhardt
Leni Steinhardt fell in love with journalism while taking Lerner's Journalism I class as a freshman. When Lerner reached out asking if she'd like to submit a piece of writing, Steinhardt texted back a letter she'd sent to several local political officeholders just a few weeks after February 14. She'd been navigating emotional waters that few others experienced, so Steinhardt had turned to writing, which became, "a yelling rant to Marco Rubio." That letter, which was sent to Rubio and several other local politicians, demands change and asks for answers to questions that hadn't been answered.
"Of all the pieces in the book…I am the most impressed by what Leni wrote," said Lerner. "It blew me away when she gave it to me."
"Parkland Speaks" is widely available. You can hear these four read or describe their entries in the "Parkland Speaks: Live from CSPA" episode of Yearbook Chat with Jim, available at walsworthyearbooks.com/podcasts or wherever you get your podcasts, including Apple Podcasts, Spotify and Stitcher.
Sarah Scott is the Digital Marketing Manager for Walsworth. She enjoys working in a variety of mediums, from print to broadcast to social media. Sarah holds a Bachelor of Arts in Communication from Truman State University in Kirksville, Missouri.


As Brazil's largest mining company exits the fertilizer industry, Canada's leading potash exporter is ramping up its operations in South America's largest agricultural market.
Canpotex Ltd., the Saskatoon-based company that sells potash from 10 Saskatchewan mines to farmers around the world, is expected to announce the opening of its first office in Brazil on Monday. In an interview, Canpotex chief executive Ken Steitz said expanding its sales effort in Brazil is part of a $1-billion investment to better position the Canadian company as a dominant fertilizer supplier to a country that's expected to lead the world in food production over the next three decades.
The new Sao Paulo-based sales team is led by Talita Arcaro, hired in October as Canpotex's managing director in Brazil. Ms. Arcaro previously worked for a major domestic fertilizer distributor and the Brazilian arm of a Morocco-based fertilizer producer. She was born and educated in Brazil.
Brazil is the world's largest importer of potash and Canpotex is beefing up its presence after Rio de Janeiro-based Vale, one of the world's largest mining companies, disappeared as a competitor.
Vale sold its fertilizer division to Minneapolis-based Mosaic Co. for US$1.4-billion in a deal that closed in January, more than a year after it was announced, as part of a restructuring aimed at paying down debt. The unit included the largest potash mine in Brazil.
A Canpotex rail car waits to be loaded with potash.
Canpotex is owned by the Canadian arm of Mosaic and Nutrien Ltd., the company created from January's merger of Agrium Inc. and Potash Corp. of Saskatchewan Inc., and is responsible for the two company's potash sales outside North America. Canpotex has sales offices in three Asian cities — Shanghai, Tokyo and Singapore — but previously covered South America with agents in the region and a sales team based in Saskatchewan.
Brazilian farmers used approximately 10 million metric tons of potash in 2017, and imported 90 per cent of the fertilizer from six major suppliers, including companies based in Russia, Germany, Belarus and Morocco. Vale was the major domestic producer. Last year, Canpotex supplied almost three million tons of potash to soybean, corn, sugarcane and coffee farms in Brazil.
Canpotex's Mr. Seitz said Brazil's share of global food production and demand for fertilizer are expected to rise steadily over the next three decades, as the country's increasingly sophisticated agricultural sector expands crop yields and converts cattle ranches into farms. Mr. Seitz said in the past decade, Brazil's use of fertilizer increased 40 per cent, while crop production rose 72 per cent.
There's another potash play with Canadian links attempting to meet this demand for fertilizer. Brazil Potash, a privately owned junior mining company based in Toronto, is developing a property in the Amazon basin with a largely Canadian executive team and board that includes former federal cabinet minister Pierre Pettigrew.
For Canpotex, hiring a sales team in Sao Paulo is part of larger investment in logistics to get potash from Saskatchewan to Brazil. Mr. Seitz estimates the company has spent $1-billion on custom-built rail cars, port facilities and ships to carry fertilizer on what's typically a 35-day journey from mine to farm.
Brazil currently accounts for 25 per cent of Canpotex's sales and is the company's single largest market. Last year, Canpotex filled 25,000 rail cars and 60 cargo ships with potash destined for Brazil.
Potash prices in Brazil are now higher than in any other regional market, CIBC pointed out. The fertilizer fetched US$293 a ton in Brazil at the end of the first quarter of this year, up US$49 year over year. In Canada, the spot price of potash was US$258 a ton at the end of the quarter, up US$22 year over year. Potash price moves in Asia and the United States were in line with those in the Canadian market.
Potash prices spiked briefly to more than US$800 a ton in 2008, then declined steadily over most of the past decade, bottoming out at approximately US$215 over the past two years.


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1923 Edward 2022
Edward "Ned" Treptow
July 10, 1923 — January 3, 2022
Edward "Ned" Joseph Garvey Treptow
July 10, 1923 - January 3, 2022
Edward "Ned" Treptow passed away on January 3, 2022, at Aspirus Wausau Hospital.
The fourth son of the late Fred and Frances (Garvey) Treptow, Edward was born on July 10, 1923, on the southeast side of Wausau, Wisconsin. He is preceded in death by his parents and brothers Mark, John, and Robert.
Ned was a Wausau High School graduate (Class of '42) and enlisted in the Air Force soon after graduation. A proud WWII veteran, his service took him to Australia, India, the Philippines and Tinian.
On January 25, 1958, he married his sweetheart, Yvonne Bloomquist. Their marriage was blessed with two daughters. They shared a beautiful life together until Yvonne's passing on March 8, 2008.
Ned was employed by American Can and then Wisconsin Public Service where he retired from marketing after 32 years. A natural conversationalist, Ned never met a stranger he couldn't turn into a friend with his kind eyes and gentle heart. Ned always had a pocket full of treats for any lucky dogs who crossed his path. He loved fishing at Blue Lake in Minocqua, singing barbershop, checking out WWII history books from the library, windmill cookies and Campbell's chicken noodle soup, sharing coffee with fellow WWII veterans (the OFC -- Old Fart's Club) at the Wausau Downtown Airport, National Geographic magazine, day trips to the casino, the Evita soundtrack, and spending his days "surrounded by beautiful women" (his wife, daughters, and granddaughter, of course).
He was truly one of a kind, the most patient and least judgmental man. A lifelong Catholic, Ned's life is a beautiful testament to his deeply held faith and devotion to the Holy Mother.
His joyful memory will forever be a blessing to his beloved daughters Ann (Paul) Seehafer and Joan (Darin) Bellile; treasured grand-daughter, Carly (Seth) Marco; and great-grandson, Saul "Sully" Marco, whom Ned affectionately called "Buckshot."
The family would like to send a heartfelt thank you to Dr. Swe, Dr. Clements and the loving staff of Aspirus Palliative Care for their exceptional care, patience, and kindness.
A private memorial service will be held in the Spring.
To order memorial trees or send flowers to the family in memory of Edward "Ned" Treptow, please visit our flower store.


Many women consider their hair as one of the sources of their beauty, self-esteem, and pride. When a woman loses her hair, it can impact her mental health, aesthetics, and general well-being no matter the reason. Dr. Kimberly Cockerham (a board-certified oculofacial plastic surgeon) at the Northern California Hair Restoration Centers in Lodi, Modesto and Stockton, CA provides consultations to women at any stage of their hair loss.
Our team will examine the area of your hair loss, which can be on the scalp, eyebrows, or eyelashes to determine the best course of treatment. We can help you through nonsurgical and surgical treatments (when required) to look and feel your best. Hair loss doesn't have to make you feel like you have given up a component of your beauty. Let the Northern California Hair Restoration Centers assist you in renewing your confidence with treatments that will help you feel whole again.
Androgenetic alopecia, or female pattern hair loss, can be inherited from the mother or father's side of the family as a result of age or from a dihydrotestosterone (DHT) hormone imbalance. DHT destroys the hair by blocking and preventing the hair follicles from getting the nutrients it needs to grow and thrive. This results in recession of the hair creating coves and a high forehead.
When hair starts to shed in the resting phase of the hair growth cycle, telogen effluvium can happen. It appears as balding since a significant amount of hair is shed. Telogen effluvium does not generally happen in one specific spot on the scalp but is visibly noticeable and can happen with eyelashes and eyebrows. A majority of patients see hair loss at the crown. Women with this type of hair loss will regrow the hair within a few years unless they have chronic telogen effluvium. Many factors can be the cause or trigger of telogen effluvium, such as trauma to the skin and/or follicles, changes in hormones, a reaction to stress or a medication, poor diet, and much more.
With three types of classifications, the Ludwig Scale represents the rigorousness of the hair loss: Type I, II, and III (least to most severe). The Ludwig Scale shows how much hair was lost, how much hair can potentially be shed in the future, and the degree of intervention or treatment needed.
The Olsen Scale can describe the hair loss in a specific pattern at the middle or central part of the hair on the scalp. Severe cases can start all the way to the front hairline and expand into a wide area on the top of the head (some describe a having a "tree" or a triangular-shaped pattern).
When women show the same signs of hair loss as male pattern baldness, we use the Norwood Scale to score the loss from type 1 –7 (least to greatest loss). Even though this pattern is not common for women, a female patient can present with missing patches of hair on the sides and top of the head.
Grade 1 hair loss pattern can be seen in all prepubescent girls. This is a normal pattern for females up to the age of 80. Afterward, 50% of all women over age 80 will have Grade 1 hair loss.
"I was a little skeptical, but the hair restoration Dr Cockerham did for me turned out amazing! I had the procedure done in October, and now, 3 1/2 months later, I've got a beautiful and very natural looking patch of hair where there once was none. I highly recommend to anyone suffering from thinning hair!"
If you are a woman with thinning hair, the best course of action you can take is to have a consultation with a hair restoration specialist no matter if it runs in your family or not. We see women of all ages with hair loss at the Northern California Hair Restoration Centers. The majority of women seeking consultations have missing hair at the front and top of the scalp, or throughout the entire scalp.
Diagnosis of female pattern baldness can sometimes be a lengthy and more in-depth process than it is for men. Why? The majority of balding men can rule everything out except male pattern baldness. Women can lose their hair for many reasons and especially with changing hormones, such as during pregnancy or menopause.
Instead of trying to hide your hair loss with your bangs or wearing a wig, contact the Northern California Hair Restoration Centers to find out better ways to manage it. If you have just started to lose your hair or have lost a significant amount in a short period of time, it is best to see a doctor who specializes in female hair loss. Your consultation will include a discussion about your current medical history, medication list, diet and lifestyle habits, haircare routine, hair loss progression, a physical examination, and possibly a blood hormone analysis.


If you witness a sharp decline in your website traffic in the next few days, it's result of the latest algorithmic update by Google. Almost 60% of the web traffic comes from mobile and this significance compelled Google to include 'mobile friendliness' as a key search ranking factor. As per the notice on Google Webmaster Central Blog, the latest update has been rolled out.
What does this mean from SEO perspective? Continue reading How Will Google's Mobile-Friendly Update Impact Your Business and SEO?


Cryptocurrency regulation continues to be one of the hottest topics in 2018 and things are continuing to evolve. We've talked recently how South Korea could join G20 country members in order to apply the same regulatory framework and now the number of countries that could do that is expected to increase.
The FATF – an intergovernmental organization founded in 1989 on the initiative of the G7 members to develop policies to combat money laundering, had been reportedly cooperating with Japan (the second cryptocurrency market in the world, after the United States) in order to implement a cryptocurrency regulatory framework to a number of 37 countries.
These joint actions come after raising concerns related to cryptocurrencies that offer high levels of privacy. FSA – Financial Services Agency, which is one of the main financial regulators in Japan, showed a primary concern related to digital coins like Monero, ZCash, and Dash – all with increased privacy features and reportedly used by criminal groups.
A few days ago, the FATF had revealed intentions to begin discussions on binding cryptocurrency regulation for exchange platforms in order to ensure that all of them will comply with regulatory requirements.
There had been many scandals this year around cryptocurrency exchange platforms. Several investigations related to price manipulation are underway, the US Department of Justice and the SEC being the most active in this respect.
Governments are also beginning to take measures. Japan had announced a licensing plan for exchanges and South Korea wants to regulate them as commercial banks. There is also cooperation with officials from Europe and the United States.
A unified regulatory framework could be in place in a few months in order to urgently prevent cases of ICO scams, security breaches, hacking attacks and KYC issues.
All these events are currently putting pressure on the price of all cryptocurrencies and until some actual measures will be implemented the negative sentiment is expected to persist. If it will turn out that the joint cryptocurrency regulation can foster growth in the industry, things could change in the near future.


Canadian Interiors' Best of Canada Design Competition is the country's only design competition to focus on interior design projects and products without regard to size, budget or location. We welcome submissions from interior designers, architects, interior architects, decorators, and crafts persons.
Employing the adage "When it rains, it pours," last year was a rain shower of entries (175, at that point a record), but this year was a downpour. Categories for project submissions include: exhibit; hospitality; institutional; marketing; office; residential; and retail. This year we introduced an online submission portal, to eliminate the need to mail in hard copies of entrants as has been the process for the last 18 years, and when building anything online, there were bugs that needed working out, causing a tighter than normal window for submissions. But despite this, 316 entrants were received – an all-time record.
We were able to enlist the aid of four design industry heavyweights to wade through all the submissions to find the gold in this crucible. They are: Sue Bennett, CEO and principal of the eponymous Uxbridge, Ont.-based design firm Bennett Design; another principal and owner of an eponymous design firm, this one in Toronto, Johnson Chou; Scot Laughton, professor and Studio Head of the Industrial Design, School of Animation, Arts and Design department at Sheridan College Institute of Technology and Advanced Learning; and Jeremy Vandermeij, Executive Director of the Toronto Design Offsite Festival.
L. to R.: Johnson Chou; Sue Bennett; Jeremy Vandermeij (not pictured: Scot Laughton).
Because of the sheer number of entries, judging could not be contained to a one-day affair. Continuing the tradition of judging the projects and products anonymously and on their own merits, this year the process was broken into two phases: a first cull done off-site, and then a week later the judges convened at a location to debate, discuss and defend the remaining entrants. Ultimately, a total of 31 winners were chosen, which include three products and 28 projects representing a cross-Canada spectrum as well as international locales such as the United States and The Netherlands.
When it came time to select Project of the Year, the judges were unanimous that the honour be bestowed on two: the soft and glowing Aesop store on Queen Street West in Toronto, by superkül ("This is so refreshing! You can't say it's this or that style" / "It's not like it's part of any aesthetic that's being overused" were among the judges adulations); and He, She & It, a delicate project consisting of three artist studios, by Davidson Rafailidis ("The beauty! The simplicity! It's very poetic," enthused one judge, a sentiment shared by all).
Congratulations to all 31 winners! See the full list below, and open our digital edition to read and see the winners more fully.
Belmonte Raw — Green Tangerine Design Inc.
Lightspeed Office — Acdf Architecture inc.
Air France / KLM Lounge — Johnson Chou Inc.


Fannie Mae's Home Purchase Sentiment Index is based on the results of a monthly survey that asks Americans about their attitudes toward buying and selling a home, the economy, their household finances, home prices, mortgage rates, etc. In March, the index dropped 2.5 points from the previous month. This indicates Americans are feeling more cautious about the housing market and less optimistic about their jobs and income. Doug Duncan, Fannie Mae's senior vice president and chief economist, says Americans' feelings about the housing market are starting to become affected by pessimism about the overall economy. "Growing pessimism over the last three months about the direction of the economy seems to be spilling over into home purchase sentiment," Duncan said. "The gap between the share of consumers who think the economy is on the wrong track and the share who think it is on the right track has widened, nearly matching its reading last August, when concerns regarding China and oil prices led to the biggest stock market plunge in years. In turn, we saw dips this month in income growth perceptions, attitudes about the home selling climate, and job confidence, all of which contributed to the lowest HPSI reading in the last year and a half. These declines seem to be at odds with recent news of solid overall job creation, but may reflect weakening economic performance in certain industries." Still, despite the monthly dip, the index remains virtually unchanged from where it was at the same time last year. More here.


Q: Do you deliver the day of my event?
A: Typically we deliver the day before then pick up the next business day after your event.
Q: How many restrooms do I need?
A: That depends on how many guest you have and how long the event is. Feel free to fill out a quote request, or call us during normal business hours and we'll help you out!
Q: Can you pump out my RV Camper/Trailer?
Q: How long can I have it?
A: There is no one answer as every need is different but we will work with your project needs.
Q: Will you put it anywhere I want?
A: We will do our best to accommodate where you need / want the restroom, but our driver must be able to reach it to pump it out at pickup. Feel free to work together with the driver when he arrives.
Q: Do I have to be there when it's delivered?
A: If you give us a credit card, then no one has to be, unless you want to be present. If you ordered as a COD, there must be someone there to pay the driver cash (exact change only) or check or the driver will not leave the restroom.
Q: What time will the restroom be delivered?
A: Due to the nature of the business we cannot give or guarantee a delivery time; however you can request AM (between 7am and noon) or PM (between noon and 5pm) and we will do our best. This can also be impeded by traffic or a blown tire.
A: If you give us a credit card, then no one has to be, unless you want to be present. If you ordered as a COD, there must be someone there to pay the driver cash (exact change only) or check or the driver will not leave the dumpster.
Q: What can I put in there?
A: The best rule of thumb is anything BUT hazardous material. Please click here for more information.
Q: What if I go over the tonnage allowance?
A: Overage in tonnage are pro-rated at $45 per ton, which is usually billed separately.
Q: Can the dumpster go in the road/street?
Q: Can the dumpster go my yard?
A: It is always best to set the dumpster down on a sold surface such as a driveway or road as a yard can/will be damaged due to the weight of the dumpster. If the ground is soft and/or wet, the weight of the dumpster can cause it to sink; when the truck arrives to pick it up more damage may be cause to the yard.
Q: How full can the dumpster be?
A: Debris must be level, just below the top of the dumpster.
Q: Can I put yard waste in the dumpster?
A: Yes, but only if you rented a yard waste dumpster only. Nothing else can go in it, such as trash or other debris that is not yard waste. Doing so will incur additional cost.
A: Due to the nature of the business we cannot give or guarantee a delivery time; however you can request AM (between 7am and noon) or PM (between noon and 5pm) and we will do our best. This can also be impeded by traffic, line(s) at the landfill, a blown tire etc.


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Home » TBC reports second quarter record sales
TBC reports second quarter record sales
TBC Corp.'s second quarter net sales were $255.5 million, a 24% increase over $206.4 million for the same period last year.
TBC's second quarter net income totaled $5.5 million, up from $5 million.
The Memphis, Tenn.-based private brand group credits sales and income jumps, in part, to the growth of its Tire Kingdom and Big O Tire chains, which both added stores during the first half of the year.
"During the second quarter, we also made improvements in our wholesale operations," says TBC President and CEO Larry Day. "We expanded our Carroll's Tire unit in Virginia and Maryland by the opening of three new centers. We also formed a Private Brands division that will be responsible for the marketing and sales of TBC's proprietary private brands Multi-Mile, Cordovan, Sigma and the newly acquired Vanderbilt/Turbo-Tech line.
"We believe that our 2001 target remains reasonable for attaining the milestone mark of $1 billion in annual sales for the first time. Although we will face difficult year-to-year earnings comparisons in both the third and fourth quarters, we expect to show a gain for the second half as a whole."
TBC is the largest private brand marketer in the United States with 7.5% market share, according to Modern Tire Dealer data.


Canyon de Chelly and Canyon del Muerto were first occupied by the Kayenta Anasazi (Ancestral Pueblan) people sometime around 1000 BC. Both narrow canyons are 1,000 feet deep, and amazingly beautiful. Over thousands of years the Rio Chelly and other streams have eroded sandstone leaving the canyon walls streaked in a crust of manganese and iron oxide. As a result, the rock is rich in red and yellow colors. There are three major archaeological sites here. They are Antelope House, White House, and Mummy Cave. In addition, there are the smaller cliff dwellings, and amazing petroglyphs. These canyons became a national monument in 1931.
The Kayenta Anasazi and their predecessors have farmed the canyons and the mesas above for 3,000 years. They grew the standard crops of corn, squash, and beans, all of which were imported from Central Mexico. They also ate wild foods, prickly pear cactus, and deer which were plentiful. Archaeologists have found cotton seed and fibers at Antelope House. Cotton was woven with other fibers and traded as a commodity with surrounding cultures. It is believed that there are over 700 archaeological ruins in this immediate area. Almost all were constructed between the years 350 AD to 1300 AD. Amazingly, this group did not construct any great kivas. They did however construct a three kiva ceremonial center at Standing Rock.
Significant increases in rainfall allowed the canyon to prosper between the years 1050 AD to 1150AD. During this time period the population increased to 800 in the canyons. Then, sometime around 1200 AD a group of people from Mesa Verde came to live with them, and both architectural designs and pottery designs changed. At this time, they constructed Mummy Cave. The eastern end of the cave was occupied more than 2,000 years ago during the Basket Maker III era. Here the Kayenta Anasazi constructed 10 houses. When it was abandoned in 1300 AD there were seventy five rooms and kivas in use.
Archaeologists also tells us that the White House Ruins were built in Chacoan style and that the construction began in 1060 AD. It contained eighty rooms and kivas, and held a population of just under one hundred. Antelope House was believed to have been finished by 1100 AD in Kayenta style masonry. Archaeologist have found ruins under Antelope House that date to before 700 AD. Antelope House was a multistory pueblo that contained 91 rooms. This cliff dwelling gets its name from the nearby petroglyphs of antelope. Persistent drought forced the Anasazi to migrate northward in 1300. The first cliff dwelling to be abandoned was Antelope House in 1270. Subsequently, in later years the Hopi began occupying the canyon. Then, by 1700 the Navajo took control of the canyon and named it �Tseyi�, which means rock canyon.
After the Pueblo revolt of 1680 many tribes fled here. However, it was the Navajo that suffered at the hands of Kit Carson and his men in 1863. Carson was merciless and his men slaughtered the livestock and destroyed everything in the canyon. The Navajo were no match for the United States Army. They were forced on a �Long Walk� and were relocated in eastern New Mexico.