text:
Kwanza recognized, students weigh in on holiday
Sarah Fagan
The holidays are one of the most festive times of the year. People dress up, decorate their houses and sing songs. Christmas and Hanukkah are well-known, but there is another, less prominent holiday around this time, often overshadowed by the Christmas trees and menorahs. Most people don't actually know anything about this holiday, but sometimes refer to when talking about the holidays. That holiday is Kwanzaa.
Although there is a large number of people who celebrate this holiday, with about 28 million celebrants per year, many students here don't know what Kwanzaa is. "Is that some Jewish holiday?" junior Young Sol Kim said. "Like where they take matzah and celebrate coming out of Egypt? Maybe something like that."
Kwanzaa is celebrated from Dec. 26 to Jan. 1 every year, and is held in the United States and in other nations of the in the Americas. The main idea of the holiday is to celebrate African-American heritage and culture, and is a relatively young holiday since it was created just under 50 years ago, in 1966-67.
Students have lots of misconceptions about Kwanzaa, one of the most frequent of those is that the holiday is based on a religion, which it is not. "I honestly had no idea," senior Will Quam said. "I guess I just kind of assumed it was a religious holiday because it is around the same time as Christmas and Hannukah."
Another common misconception is that it is a substitute for Christmas. Most people who celebrate Kwanzaa also celebrate Christmas. The time period in which Kwanzaa is celebrated was chosen not as a substitute for traditional holidays but rather as a means of taking advantage of the seasonal excitement during this time of year.
Even though most students aren't educated about what Kwanzaa is, some believe that students should know what it is about. "I think that we should be aware of this holiday in our school," senior SGA president Alisha Dhallan said. "It's important for students to understand different cultures around them to promote unity in school."
Other students believe that it should be a more prominent, but for different reasons. "It's good for young African-Americans to know their roots and not just forget them," senior Ornella Ihirwe Bayigamba said. "It's still part of them and it's sad whenever someone forgets their heritage."
Charlie Eichberg
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Are math programs in MCPS unnecessarily challenging or stressful: Teachers don't agree
So you say you're taking the ACT…
Students boast strong opinions on Thanksgiving dishes
Chemistry teacher Rebecca Firoved's love for teaching came later in life
Best holiday treats to make over your break


Published 04/25/2019 04:36:05 am at 04/25/2019 04:36:05 am in How Much Does A 20 Oz Bottle Of Water Weigh.
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text:
Q: Response time, Load Testing and Stress testing with Rest Assured I know there is a way to measure the response time of a Rest API with Rest Assured. But can we increase the user load and measure the response time using Rest assured ,or is there any other suggested way to count in those parameters (Load / Stress) using API Testing. TIA

A: If you're interested in Response Time only you can run your Rest Assured tests into with JMX (Java Microbenchmark Harness) to get some basic information how your system behaves under the load.
However be aware that load and stress testing is not only about response time

*

*You need to come up with realistic patterns of your API usage as if your load test will not represent end-user or end-application workload this test does not make sense

*It is better to increase and decrease the load gradually as this way you will be able to correlate increasing response time and other metrics with the increased number of threads (virtual users)

*It is better to go for a specialised tool as response time is not enough when it comes to bottleneck analysis, you will need at least to measure time required to establish the connection, network latency and time to first byte. It will also be good to include collection of at least CPU, RAM, Network, Disk usage on the application under test side and your application-specific metrics (if any)

So I would recommend going for i.e. Apache JMeter you can re-use your Rest Assured code in JSR223 Sampler(s) or JUnit Request Sampler

redpajama_set_name: RedPajamaStackExchange


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Bachelor's or Master's Degree, preferably in Business and/or Information Communication Technology related field.


Learn more about the Doctor of Philosophy in Mathematics.
The Ph.D. program in Mathematics prepares students for careers that depend on advanced mathematics. These include broad directions such as advanced research and development, education, government, industry, and national laboratories. For new students, the program offers a repertoire of coursework and research opportunities that ease the transition from undergraduate to advanced graduate studies. The courses provide a sound mathematical background, while helping beginning students to mature mathematically. Naturally, individuals with enough maturity and knowledge need not take these more basic courses. In the Mathematics Department, our philosophy is to participate actively in our students' development as future professionals whose work involves advanced mathematics. We take pride in caring for our students. Our faculty are accessible and willing to talk mathematics with any inquiring student. It is this attitude that most distinguishes our program from other mathematics graduate programs. While requiring excellence, we work hard at providing the environment for achieving it.
Ranking: The Ph.D. program is designed to provide opportunities for education and research that are commensurate with national standards. Faculty are active in professional meetings and initiatives organized by the American Mathematical Society and the Mathematical Association of America.
Both prospective and matriculated students are encouraged to browse faculty web pages and contact faculty directly for more detailed information regarding areas of specialization and opportunities for further research.
For full consideration, applications should be received by the stated deadlines. Applications received after these dates will be considered on a case-by-case rolling basis.
GRE General Test and GRE Subject Test in Mathematics: Rigid minimum score criteria is not used. The department considers an applicant's overall record. Students who wish to discuss their scores are encouraged to contact the department directly.
Students are required to take at least 16 graduate courses, which are chosen with the advice and consent of the student's advisor. These courses should be taken during the first two years of graduate study and include foundational 8000-level courses for the topics in which the student plans to take the Ph.D. Comprehensive Examination. Students who have had graduate courses in these subjects prior to admission may omit some or all of the courses with the consent of their advisor and the Graduate Committee.
Students can choose any three of these sections for their examination. After exams in three different topics have been attempted, an exam in a fourth topic can only be taken under exceptional circumstances, and only after specific approval by the Graduate Committee. Each section is a three-hour test based primarily on the corresponding two-term 8000-level graduate course sequence. The separate section tests are given on different days, during one two-week period, twice a year: once in August just before the beginning of the Fall term, and once in January during the two weeks prior to the beginning of the Spring term. Students do not have to take all three of the section tests during the same two-week period. Each section test may be repeated once to obtain a higher grade.
Each of the three-hour section tests is further divided into two parts. Part I contains four questions, of which the student is asked to answer three. These questions are designed to test mastery of the facts of the subject. Part II contains three questions, of which two are to be answered. These questions test the ability to solve in-depth problems in the subject.
Students should begin taking the components of the Comprehensive Exam as soon as possible after finishing the corresponding coursework. Students are expected to complete and pass the Comprehensive Examination by August of their second year of study. While some delay in this schedule may be permitted, under exceptional circumstances, students not making good progress toward completing and passing their Comprehensive Examination in a timely fashion will be asked to leave the Ph.D. program.
Incoming students may, with approval of the Graduate Chair, take up to three of the written Ph.D. Comprehensive Examination sections once prior to their first term of enrollment. Upon request by the student, any of these pre-enrollment attempts can be removed from the student's record.
Each section is graded independently by two faculty members, using a scale of 0 to 25. The grades are compared and reconciled in the event of a discrepancy. A total score of at least 60, with a score on each individual section test of at least 13, is required to pass. If a student falls slightly short of this standard, the Graduate Faculty may, at their discretion, recommend a grade of pass based on the whole of the student's academic record.
A student who achieves a total score of at least 40 from the three sections of the Ph.D. Comprehensive Examination, with no individual section below 8, has obtained a master's pass on the examination and has fulfilled the examination requirement for the M.S. degree. If one of the individual exam scores falls below 8 points, that exam may be repeated once, or the exam in a different topic may be attempted once, or the student may take the Master's Comprehensive Examination. As above, such arrangements are subject to approval by the Graduate Committee, and if a student falls slightly short of the required standards, then the Graduate Faculty may, at their discretion, recommend a grade of pass, basing their decision on the student's entire academic record.
The preliminary examination is a two-hour oral exam. It should be taken by the end of the sixth term and must be passed by the end of the seventh term. The Ph.D. preliminary examination can be repeated, in whole or in part, only once. No student is permitted to take the preliminary examination before passing the written Ph.D. Comprehensive Examination and satisfying the foreign language requirement.
The student chooses a chief examiner with the advice and consent of the Mathematics Graduate Committee -- and with the consent of the proposed chief examiner. The chief examiner, in accepting his/her assignment, implicitly offers to be the student's dissertation supervisor if the examination is passed. Approximately one-half of the preliminary examination is conducted by the chief examiner, who asks questions in the area that the student has chosen as a specialty. The other half of the examination is devoted to questions asked by other faculty members on two or more elementary topics related to the area of specialization. The exact description of the elementary topics to be included in the examination is determined by the chief examiner, who will also be responsible for assigning examiners to cover the topics. The examination committee consists of the chief examiner, the examiners for the elementary topics, and any other faculty who choose to attend. All faculty in attendance may vote on the outcome of the examination. The examination is considered passed if the chief examiner and at least one-half of the other faculty present vote in favor of passing.
Students who are preparing to write their preliminary examination should confirm a time and date with the chair of their Doctoral Advisory Committee and register with the Graduate Secretary. The student and chair receive confirmation of the time, date, room, and proctor for the examination.
The candidate's dissertation must be a distinctive and original contribution to research in mathematics. It must be an individual work, with only one author. Previously published work by the candidate may be included, if it represents research done while the student was enrolled in the Ph.D. program in Mathematics at Temple University and was not used to obtain any other degree. Joint work that cannot be attributed to the candidate alone must not be included in the body of the dissertation, but may be attached as an appendix. All previously published work must be logically connected and integrated into the dissertation, with a common introduction, conclusion, and bibliography. Existing copyrights must not be violated.
Preparation of the dissertation is supervised by the student's Doctoral Advisory Committee (DAC). This committee must include at least three Temple graduate faculty, two of whom must be in the Mathematics Department. The chair of the committee must be a member of the Temple University Mathematics Department. The DAC may include members of other Temple University departments; it is also possible for faculty from other universities or expert advisors employed in non-university settings to be included in the DAC.
The first step in preparing the dissertation is to write a dissertation proposal, which must be approved by the candidate's DAC. The proposal is kept on file, and if it becomes necessary to alter the proposal, the changes should be approved by the DAC and filed with the proposal.
The dissertation defense may be attended by faculty and graduate students from Temple University or other institutions, as well as mathematicians or scientists employed in a non-academic setting. The candidate's Dissertation Examining Committee (DEC) must attend the defense. This committee includes the candidate's DAC and at least one additional member, who must be a faculty of some Temple University department other than Mathematics or a faculty member of another university. The DEC meets at the conclusion of the dissertation defense and decides, by majority vote, if the candidate was successful.
If a student needs to change a member of a committee, the new member must be approved by the Mathematics Graduate Committee and registered with the Graduate Secretary and the Graduate School.
When the dissertation is deemed complete by the candidate and the DAC, a defense is scheduled. Students who are preparing to defend their dissertation should confirm a date and time with their DAC and register with the Graduate Secretary at least 20 days before the defense is to be scheduled. The Graduate Chair arranges the date, time, and room. The Graduate Secretary forwards to the student the appropriate forms.
This dissertation defense must be announced in writing at least 10 days in advance of its occurrence. Copies of the announcement must be directed to each member of the candidate's DEC, each faculty member of the Mathematics Department, the Dean of the College of Science and Technology, and the Graduate School. Copies of the announcement are to be posted at the Department Office, the College Office, and on the Graduate School website.


text:
package goinsta

import (
	"encoding/json"
	"fmt"
)

type LocationInstance struct {
	inst *Instagram
}

func newLocation(inst *Instagram) *LocationInstance {
	return &LocationInstance{inst: inst}
}

type LayoutSection struct {
	LayoutType    string `json:"layout_type"`
	LayoutContent struct {
		Medias []struct {
			Media Item `json:"media"`
		} `json:"medias"`
	} `json:"layout_content"`
	FeedType        string `json:"feed_type"`
	ExploreItemInfo struct {
		NumColumns      int  `json:"num_columns"`
		TotalNumColumns int  `json:"total_num_columns"`
		AspectRatio     int  `json:"aspect_ratio"`
		Autoplay        bool `json:"autoplay"`
	} `json:"explore_item_info"`
}

type Section struct {
	Sections      []LayoutSection `json:"sections"`
	MoreAvailable bool            `json:"more_available"`
	NextPage      int             `json:"next_page"`
	NextMediaIds  []int64         `json:"next_media_ids"`
	NextMaxID     string          `json:"next_max_id"`
	Status        string          `json:"status"`
}

func (l *LocationInstance) Feeds(locationID int64) (*Section, error) {
	// TODO: use pagination for location feeds.
	insta := l.inst
	body, err := insta.sendRequest(
		&reqOptions{
			Endpoint: fmt.Sprintf(urlFeedLocations, locationID),
			Query: map[string]string{
				"rank_token":     insta.rankToken,
				"ranked_content": "true",
				"_csrftoken":     insta.token,
				"_uuid":          insta.uuid,
			},
			IsPost: true,
		},
	)
	if err != nil {
		return nil, err
	}

	section := &Section{}
	err = json.Unmarshal(body, section)
	return section, err
}

redpajama_set_name: RedPajamaGithub


text:
Q: Why image is not displayed in browser when using react-img-mapper I am using react-img-mapper from GitHub, but it is not displaying results, just showing an empty page in the browser.
    import React from 'react';
    import ImageMapper from 'react-img-mapper';

    import "../assets/style.css";

    function AreaOperation() {
      const URL = 'https://raw.githubusercontent.com/img-mapper/react-docs/master/src/assets/example.jpg';
      const MAP = {
        name: 'my-map',
        // GET JSON FROM BELOW URL AS AN EXAMPLE
        areas: [
          {
            id: "469f9800-c45a-483f-b13e-bd24f3fb79f4",
            active: true,
            title: "Hardwood",
            shape: "poly",
            name: "BB(1-4)",
            fillColor: "eab54d4d",
            strokeColor: "black",
            coords: [
              520.0646766169153,
              393.0348258706467,
              85.23880597014923,
              378.6069651741293,
              637,
              479,
              13.099502487562177,
              478.10945273631836,
              11.606965174129343,
              438.3084577114427
            ]
          }
        ]
      };

      return <ImageMapper src={URL} map={MAP} />
    }

    export default AreaOperation;

My packages are
  "react": "^18.2.0",
  "react-dom": "^18.2.0",
  "react-image-mapper": "0.0.15",
  "react-img-mapper": "^1.4.0",
  "react-router-dom": "^5.2.0",


text:
Hyundai Engineering & Construction Wins $300 Million Order to Build Doha New Port Facilities
Hyundai Engineering & Construction (HDEC) on August 13 that had won a US$301-million order to build a new port at Qatar's Doha jointly with the Middle East unit of the Netherlands' Royal Boskalis Westminster N.V. and Brazil's Construtora OAS.Commissioned by the Qatari New Port Project Steering Committee.
The latest project calls for building berths for small- and medium-sized vessels and connecting passageways in the QEZ3 section of No. 3 economic zone.
The company, whose share of the order is $186 million, will complete the construction in 30 months after the work begin.
Hyundai (HDEC) has been active in Qatar since it entered the market in 1978 when it built the Sheraton Doha Resort & Convention Hotel.
Lately it succeeded in landing a total of 17 deals worth $7,583 million, including the Ras Laffan combined cycle power plant project in 2009, the 2010 Heart of Doha phase 1 project to rebuild the city center, the 2011 Qatar National Museum project, and the Lusail Expressway project in 2012.
A Hyundai Engineering & Construction (HDEC) official said, "We could clinch the port construction deal thanks to the good relationship we have maintained with the Qatari government through previous large-scale projects.
We will keep working hard to win more infrastructure projects that the government is commissioning ahead of the 2022 World Cup Games."
Korea Times

redpajama_set_name: RedPajamaCommonCrawl


Jackson Odell, a 20-year-old actor known for his role on "The Goldbergs," was found dead Friday, the Los Angeles County coroner's office reported.
Odell was found unresponsive around 1:45 p.m. at a sober-living home in the Los Angeles neighborhood of Tarzana, a coroner's lieutenant said. The cause of death has not been released pending an autopsy, but the lieutenant said foul play is not suspected.
TMZ.com reports that Odell had been at the home for about three weeks, and had a history of heroin use.
He had also been working as a singer-songwriter and contributed songs to the movies "Forever My Girl" (2018) and "Great Plains" (2016).


text:
Q: Signing exe-files under Linux When I try to sign an EXE file under Linux with Wine, it requires some dll - mfc42.dll. Also tried install that dll with winetricks, but I cannot get it running.
Maybe you know a better way to sign a .EXE under Linux?

A: Another possible solution is the "OpenSSL-based signcode utility", see http://sourceforge.net/projects/osslsigncode/
I haven't tried it yet, but it sounds promising (much leaner than installing Mono anyway).


text:
Cartoon Museum: Kuta, Bali
At long last cartoonists are being recognised for their art and insight into the daily happenings across the archipelago. Now, Indonesian cartoonists finally have a place to call home after the Indonesia Cartoon Museum was officially opened with dozens of cartoons and cartoonists featured from around the country. "We want the whole world to know that Indonesian cartoonists have great drawings, which is why we have built the museum," senior cartoonist Pramono R Pramoedjo said. He said a strict screening mechanism was applied to exhibitions and only selected drawings would be accepted according to Dicky Christanto.
"First of all, the drawings must be fun to look at and they must show some kind of intellectual value, so that people can be amused and learn at the same time," Pramono said.
"This is the difference between cartoon drawing and usual paintings.
"Cartoon drawings offer a more intellectual side."
Pramono has worked as a cartoonist for Sinar Harapan daily newspaper for many years and he said as many as 600 cartoon drawings from various cartoonists had been collected for the museum's initial collection.
Noted cartoonists include GM Sudarta of Kompas daily and Priyanto of Tempo news magazine.
Bali was chosen for the museum site because of the island's strong tourism trade and its international community.
"Many people from many places around the world gather on this island so we hope news about this museum will travel fast," he said.
Pramono and his colleagues with the Association of Indonesian Cartoonists (Pakarti) said they have been collecting and hunting for cartoon drawings for more than two years.
"There are still many drawings worth collecting, such as those from our founding fathers," Pramono said.
"I bet people will be surprised to learn (former President) Sukarno was actually also a cartoonist," he said.
Established on 1989 in Yogyakarta, Central Java, the Pakarti association is now home to some 600 cartoonists from all over the country. Almost half its members were now working for various publications and newspapers as newspapers and many others freelance. Chairman of Pakarti, Jango Paramartha, said he hoped the museum would encourage other cartoonists to organize activities related their work.
"My vision is to have a museum that will accommodate activities related to cartoons so the museum can serve as a home for all cartoonists," Jango said.
"It is a place where they can freely express themselves through cartoons," he said.
He said Pakarti would ask the government to join forces in managing the museum.
"As it also serves as one of the nation's assets."
The land the museum was built on originally belonged to cartoonist and businessman, Istio Adi, who owned a chain of cartoon apparel shops called Jangkrik 85.
The museum building is on a 1,200-square-meter plot of land on Sunset Road in Kuta and a number of additional facilities are expected to be included in the museum, including as cafe, a cartoon library and an exhibition hall.
"These additional facilities will help the museum generate funds to support its existence," Jango said.


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text:
Q: Unity error: InvalidOperationException: HTTP/1.1 403 Forbidden so all of a sudden I'm getting this error in my unity project.
InvalidOperationException: HTTP/1.1 403 Forbidden
    UnityEngine.Networking.DownloadHandler.GetCheckedDownloader[T] (UnityEngine.Networking.UnityWebRequest www) (at /Users/bokken/buildslave/unity/build/Modules/UnityWebRequest/Public/DownloadHandler/DownloadHandler.bindings.cs:145)
    UnityEngine.Networking.DownloadHandlerAssetBundle.GetContent (UnityEngine.Networking.UnityWebRequest www) (at /Users/bokken/buildslave/unity/build/Modules/UnityWebRequestAssetBundle/Public/DownloadHandlerAssetBundle.bindings.cs:64)
    API+<GetDisplayBundleRoutine>d__5.MoveNext () (at /Users/remy/Unity/AREA/Assets/Scripts/API.cs:58)
    UnityEngine.SetupCoroutine.InvokeMoveNext (System.Collections.IEnumerator enumerator, System.IntPtr returnValueAddress) (at /Users/bokken/buildslave/unity/build/Runtime/Export/Scripting/Coroutines.cs:17)

I'm using my own website/server to request an asset bundle. I believe I recently updated the php version to 7.4 of the webserver. Could that be part of the problem? No sure if that is related.
Underneath the script which I use to sort the asset bundles from the server within the app. Not sure if that is related to my current problem though.
I'm requesting bundle in my app via this php-script om the server.
 // The tab key will cycle through the settings when first created
    // Visit https://codexns.io/products/sftp_for_subime/settings for help

    // sftp, ftp or ftps
    "type": "sftp",

    "save_before_upload": true,
    "upload_on_save": false,
    "sync_down_on_open": false,
    "sync_skip_deletes": false,
    "sync_same_age": true,
    "confirm_downloads": false,
    "confirm_sync": true,
    "confirm_overwrite_newer": false,

    "host": "ssh.strato.com",
    "user": "******",
    "password": "******",
    "port": "22",

    "remote_path": "/",
    "ignore_regexes": [
        "\\.sublime-(project|workspace)", "sftp-config(-alt\\d?)?\\.json",
        "sftp-settings\\.json", "/venv/", "\\.svn/", "\\.hg/", "\\.git/",
        "\\.bzr", "_darcs", "CVS", "\\.DS_Store", "Thumbs\\.db", "desktop\\.ini"
    ],
    //"file_permissions": "664",
    //"dir_permissions": "775",

    //"extra_list_connections": 0,

    "connect_timeout": 30,
    //"keepalive": 120,
    //"ftp_passive_mode": true,
    //"ftp_obey_passive_host": false,
    //"ssh_key_file": "~/.ssh/id_rsa",
    //"sftp_flags": ["-F", "/path/to/ssh_config"],

    //"preserve_modification_times": false,
    //"remote_time_offset_in_hours": 0,
    //"remote_encoding": "utf-8",
    //"remote_locale": "C",
    //"allow_config_upload": false,
}

This is the script I use for api access:
using System.Collections;
using System.Collections.Generic;
using System.Linq;
using UnityEngine;
using UnityEngine.Events;
using UnityEngine.Networking;

public class API : MonoBehaviour {

    const string BundleFolder = "https://www.remykonings.nl/AssetBundles/";
    const string ItemList = "https://www.remykonings.nl/ItemList.php";

    public void GetItemList(UnityAction<List<string>> callback) {
        StartCoroutine(GetItemListRoutine(callback));
    }

    IEnumerator GetItemListRoutine(UnityAction<List<string>> callback) {
        UnityWebRequest www = UnityWebRequest.Get(ItemList);
        yield return www.SendWebRequest();

        if (www.result == UnityWebRequest.Result.ConnectionError) {
            Debug.Log("Network error");
        } else {
            string rawText = www.downloadHandler.text;
            //split string by comma
            string[] items = rawText.Split(',');
            //remove empty values and convert to list
            List<string> itemList = items.Where(x => !string.IsNullOrEmpty(x)).ToList();
            //return list to caller
            callback.Invoke(itemList);
        }
    }

    public void GetBundleObject(string assetName, UnityAction<GameObject> callback, Transform bundleParent) {
        StartCoroutine(GetDisplayBundleRoutine(assetName, callback, bundleParent));
    }

    IEnumerator GetDisplayBundleRoutine(string assetName, UnityAction<GameObject> callback, Transform bundleParent) {

        string bundleURL = BundleFolder + assetName + "-";

        //append platform to asset bundle name
#if UNITY_ANDROID
        bundleURL += "Android";
#else
        bundleURL += "IOS";
#endif

        Debug.Log("Requesting bundle at " + bundleURL);

        //request asset bundle
        UnityWebRequest www = UnityWebRequestAssetBundle.GetAssetBundle(bundleURL);
        yield return www.SendWebRequest();

        if (www.result == UnityWebRequest.Result.ConnectionError) {
            Debug.Log("Network error");
        } else {
            AssetBundle bundle = DownloadHandlerAssetBundle.GetContent(www);
            if (bundle != null) {
                string rootAssetPath = bundle.GetAllAssetNames()[0];
                GameObject arObject = Instantiate(bundle.LoadAsset(rootAssetPath) as GameObject,bundleParent);
                bundle.Unload(false);
                callback(arObject);
            } else {
                Debug.Log("Not a valid asset bundle");
            }
        }
    }
}

I'm fairly new at all of this. Hoping for some help :)
Thank you.


ALEXANDRE LACAZETTE struck a brilliant equaliser to earn Arsenal a point against Liverpool which proves they are the real deal.
Lacazette whipped home into the far corner to seal a deserved draw for the Gunners as they went toe-to-toe with Jurgen Klopp's title chasers.
Unai Emery's side knew this match was their first big test of the progress they have made since he took over from Arsene Wenger.
And they passed with flying colours as they slugged it out with Liverpool in a breathless match at the Emirates.
Klopp's side looked to be heading for all three points when James Milner seized on a mistake from Bernd Leno to rifle in the opening goal.


Update October 22: Well, there there's new license in all its glory.
Under 21 IDs will be rotated to a vertical format so they can be easily spotted.
The new cards will be available online by February 1, 2011 and they will be appearing in local offices by November of this year. According to the department, you do not need to replace your current driver's license or identification card until it expires.
The new licenses are not part of the Real ID program and contain no RFID chip.
Update October 21: Well folks, today is the day that the new South Carolina drivers licenses will be announced and the public will get a glimpse at these new and improved identification cards.
According to The Post and Courier, the DMV has refused to provide an example of the new licenses or explain the new security features prior to today's scheduled announcement.
Governor Mark Sanford and DMV Director Marcia Adams will be unveiling the new cards this morning; we'll be sure to keep you posted.
First reporting: The South Carolina Department of Motor Vehicles has announced they'll be issuing more secure driver's license and state identification card come late September or early October.
This is the first upgrade to South Carolina's credentials since 1990.
According to The State. the new cards will have, "a new appearance to users, but more importantly, will come armed with three new levels of security built in."
Hop on over to The State to learn all about the new upgrades.


The most area of Bhalwal is related to the agriculture, it is located under the district of Sargodha in Punjab Province, and various educational institutes are offering their services to educate the entire population located in the Bhalwal Tehsil.
Colleges/Universties in Bhalwal are providing their educational services for the students of Bhalwal to boost their career, the students of this region are getting benefits of higher education from the institutes of Bhalwal.
Among the lists of Colleges/Universities in Bhalwal the Govt. Vocational Training Institute and Career Institute of Science & Technology are providing up to date educational services for the students. Other government /private colleges are also offering the educational services for the students of Bhalwal to make them good educated citizens.


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Q: Changing Tab Text color when selecting the tab I have Tab text which is blue and background is white. I want to show blue background and white tab text when a tab selected.
I changed the background by using a selector. But I tried multiple times text color is not changing when selected. Please help me on this.
styles.xml
<style name="MainTheme" parent="android:Theme.Holo.Light.DarkActionBar">
    <item name="android:actionBarTabTextStyle">@style/tab_text_color</item>
</style>

<style name="actionbar_tab_style" parent="@android:style/Widget.Holo.Light.ActionBar.TabBar">
     <item name="android:background">@drawable/tab_background_select</item>
    <item name="android:textColor">@drawable/tab_text_select</item>
</style>

tab_background_select.xml
    <?xml version="1.0" encoding="utf-8"?>
<selector xmlns:android="http://schemas.android.com/apk/res/android" >
    <item android:state_selected="true"
        android:drawable="@color/blue"/>
</selector>

tab_text_select.xml
<?xml version="1.0" encoding="utf-8"?>

<selector xmlns:android="http://schemas.android.com/apk/res/android" >
   <item
        android:state_selected="true"
        android:color="#FFFFFF"/>
    <item
        android:state_selected="false"
        android:color="#0000FF"/>
      <!--
        <item android:state_selected="true">
            <shape>
                <solid android:color="@color/white"/>
            </shape>
        </item>
        <item>
            <shape>
                <solid android:color="@color/light_blue"/>
            </shape>
        </item> -->

</selector>

A: I found the answer. I had to put tab_text_select.xml in ti res/colors folder(If you don't have the folder just create it).
Then
<style name="actionbar_tab_text_style" parent="@android:style/Widget.Holo.Light.ActionBar.TabText">
 <item name="android:textColor">@color/tab_background_select</item>

Then apply above style to main theme name as android:actionBarTabTextStyle


THE DAILY PIC: The great cartoonist shows his chops as a painter.
THE DAILY PIC (#1435): William Hogarth's caricatures are so great that it's easy to imagine that their wild distortions somehow come straight and inevitably from who he is, naturally, as an artist. Since I don't believe that any artist has such a thing as a "natural" way of seeing, I was pleased to be reminded that Hogarth the caricaturist was also hugely skilled at making high-end, undistorted realist portraits. I saw this one, of the Honorable John Hamilton, in the Frick Art and Historical Center in Pittsburgh.
The painting on that embroidered waistcoat alone is enough to make any esthete weak-kneed with pleasure. But come to think of it, Hogarth the cartoonist does seem to be lurking in its swirls, and in the twinkle in John Hamilton's eye.


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Gregorio Pagani (Florència, 14 de juliol de 1559 - Florència, 1605), pintor italià actiu durant l'apogeu del manierisme tardà.

Biografia
Fill del també pintor Francesco Pagani, va començar el seu aprenentatge amb Maso da San Friano, per a després passar al taller de Santi di Tito, de qui va ser alumne i posteriorment ajudant. El seu primer treball com a artista independent la pintura al fresc del claustre de Santa Maria Novella, reflecteix clarament la seva vinculació a l'estil academicista del mestre.

Tanmateix, a propòsit d'un viatge a Arezzo amb el seu amic el també pintor Ludovico Cigoli -segons refereix Filippo Baldinucci-, Pagani va descobrir les excel·lències de l'art emilià liderat per Federico Barocci. A partir d'aleshores va modelar el seu estil segons els patrons dels nous coneixements adquirits. La combinació dels recursos descriptius apresos de Santi amb efectes de caràcter dramàtic fan de Pagani un dels precursors de l'incipient estil del barroc.

Pagani va desenvolupar un estil més naturalista i va poder exercir una certa influència sobre l'art espanyol contemporani, gràcies a la seva amistat amb Bartolomeo Carducci. Les seves figures sempre gaudeixen d'una acurada composició, amb varietat d'actituds que els concedeix un dinamisme i una vivesa superiors a les de la majoria dels seus contemporanis, encara ancorats en les regles del manierisme, ja en franca decadència. Entre els seus alumnes va destacar sobretot, Cristofano Allori.

Obres destacades
 Conferma della Regola di San Domenico
 Incontro tra San Domenico e San Francesco
 Ricerca della Vera Croce
 Crocifissione e Santi
 San Lorenzo
 Adorazione dei Magi
 Discesa dello Spirito Santo
 Vergine con Bambino e SS Michele Arcangelo e Benedetto
 Madonna con Bambino tra i Santi Francesco d'Assisi, Giovanni battista, Margherita e Gregorio Magno, Museu de l'Hermitage, Sant Petersburg

Referències

Bibliografia
 Sydney Joseph Freedberg (1978). Pintura en Italia, 1500-1600. Editorial Cátedra, Madrid.
 The Grove Dictionary of Art, MacMillan Publishers (2000)

Enllaços externs

 Gregorio Pagani a Artcyclopedia

Pintors italians del manierisme
Pintors florentins
Morts a Florència

redpajama_set_name: RedPajamaWikipedia


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Ibis Tek, Inc
PPP Loan Data — Ibis Tek, Inc, Saxonburg, PA
Industry: Military Armored Vehicle, Tank, and Tank Component Manufacturing
Location: Saxonburg, PA
Ibis Tek, Inc is a corporation located at 220 S. Noah Dr in Saxonburg, Pennsylvania that received a Coronavirus-related PPP loan from the SBA of $4,551,300.00 in April, 2020.
Ibis Tek, Inc in Saxonburg, PA received a Paycheck Protection Loan of $4.55M through CIBC Bank USA, which was approved in April, 2020.
For Ibis Tek, Inc, the calculation used to estimate payroll costs is shown below:
Based on the standard PPP eligibility formula, it may be possible to estimate the payroll expenses represented by a company on their PPP application (see details above). In order to qualify for the PPP loan amount received, Ibis Tek, Inc's 2019 payroll expenses are estimated to be at least $21.85M.
On the PPP application, Ibis Tek, Inc reported intending to use the proceeds of their PPP loan for the following expenses:
Because the loan received by Ibis Tek, Inc is at least $2M dollars, it is subject to a full review by the SBA to ensure eligibility and compliance with PPP program requirements.
Business Information - Ibis Tek, Inc in Saxonburg, PA
220 S. Noah Dr
Military Armored Vehicle, Tank, and Tank Component Manufacturing
Butler County, PA — SBA Office 0358 — Congressional District: PA-16
Similar Companies near Saxonburg
In the Saxonburg area, 2 businesses in the "Military Armored Vehicle, Tank, and Tank Component Manufacturing" industry received a PPP loan. These local businesses reported an average of 355 employees (compared to this company's 415) and received an average PPP loan of $3,275,650 (compared to this company's $4.55M).
Xper Inc. F/K/A Ibis Tek Inc
$2M PPP Loan
Nationwide, 81 businesses in the "Military Armored Vehicle, Tank, and Tank Component Manufacturing" industry received a total of $35.75M in PPP loans. This industry in total received less than 1% of the total PPP funding distributed.
PPP recipients in this industry report an average of 38 employees, 91% lower than Ibis Tek, Inc's reported 415 employees, and received an average PPP loan of $441,419, 90% lower than this company's loan of $4.55M.
Source: www.federalpay.org/paycheck-protection-program/ibis-tek-inc-saxonburg-pa


October 26, 2017 – His Holiness Patriarch Kirill of Moscow and All Russia and His Beatitude Patriarch Daniel of Romania held talks at the Patriarchal Palace in Bucharest. Before the talks began, Patriarch Daniel showed Patriarch Kirill the interior of the Patriarchal Palace.
Participating in the bilateral talks were: from the Russian Orthodox Church, Metropolitan Hilarion of Volokolamsk, head of the Moscow Patriarchate department for external church relations (DECR); Archbishop Sergiy of Solnechnogorsk, head of the Moscow Patriarchate administrative secretariat; Archpriest Igor Yakimchuk, DECR secretary for inter-Orthodox relations; Rev. Alexander Volkov, head of the Patriarchal Press Service; and Archpriest Andrey Bondarenko, acting head of the Patriarchal Protocol Service.
From the side of the Romanian Orthodox church there were Metropolitan Niphon of Târgovişte, head of the Romanian Patriarchate department for external church relations, Archpriest Michael Tica, patriarchal adviser for international affairs; and Deacon Eugene Rogoti, a Romanian Patriarchate staff member.
In the course of the two-hour fraternal talk, which was held in an atmosphere of mutual understanding, the Primates exchanged information about the service and various aspects of the work of the Russian and Romanian Orthodox Churches and discussed inter-church cooperation.
Patriarch Kirill spoke in particular about the forthcoming events in Moscow devoted to the centenary of the 1917-1918 Local Council, the restoration of the Patriarchal Office and the election of St. Tikhon to the Patriarchal see and about the beginning of the era of persecution against the Russian Orthodox Church. Patriarch Daniel was invited to come for the commemorative events.
Along with the bilateral relations, they discussed such topics as the situation of Christians in the Middle East, the aid to persecuted Christians, the situation in Ukraine and the peacemaking service of the Ukrainian Orthodox Church. They dealt in particular with problems involved in the aggressive actions of non-canonical groups and representatives of the Greek Catholic Church, the violation of human rights in Ukraine and attempts of certain forces to lobby discriminatory draft laws.
The participants also considered the further development of common Orthodox interaction and exchanged evaluations of the Council of Primates and representatives of Local Orthodox Churches which took place in 2016 in Crete.
This entry was posted in Featured, Featured News, News and tagged Moscow Patriarchate, Patriarchal Palace, Romanian Patriarchate, Russian Orthodox Church, Ukraine by Orthodoxy Cognate PAGE. Bookmark the permalink.


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Category: Flodden Field
Saturday Snapshot – Flodden
September 28, 2013 ~ Margaret	~ 12 Comments
It's the 500th anniversary of the Battle of Flodden this year – it was on 9th September 1513 that the armies of England and Scotland met at Flodden Field, near Branxton in Northumberland. There have been events this year to commemorate the battle and the men from both nations who died in this last medieval battle between England and Scotland.
Living not far from the site of the battle this week we went to see what had changed as a result of the anniversary. There's now a surfaced path leading up to the Monument.
(Click on the photos to see them enlarged)
There are some more information boards and signs to guide you round the Battlefield Trail:
The monument isn't actually on the site of the battle but stands on Piper's Hill.
From the monument you can look towards the north down on the village of Branxton:
The two armies lined up south of the monument with a marshy dip between them. The Scots advanced first, unaware of the of the ground conditions below them. Now it's a ditch but in 1513 there was a brook surrounded by a reeded quagmire downhill – where the Scots were bogged down, the rear ranks pushing forward into the front ranks, crushing the fallen bodies and causing chaos. They were then easy prey for the deadly English billhooks.
It looks like this now – the ditch between the hedge and fence is now nearly dry, after weeks of rain in 1513 it was a quagmire:
and the two armies came face to face:
Flodden 1513: Scotland's Greatest Defeat by John Sadler is an excellent account of the strategies and tactics of both armies, with maps and plans showing how the battle began and a time timeline of the various conflicts giving a detailed account of events.
Having read this book and the information boards around the trail I was able to visualise the battle, even on a peaceful weekday afternoon 500 years later. The Scottish troops had moved from their original position on Flodden Edge as the English approached the battlefield, putting them at a disadvantage. The outcome could have been different if they had seen the dip below them as they charged down the hill – or even if the English had attacked first.
But then, the battle needn't have taken place at all if James IV of Scotland had not invaded England in an attempt to divert English troops from their fight against the French. Indeed he had entered into a Treaty of Perpetual Peace with England in 1502. But in 1512 he had also renewed the Auld Alliance with the French, putting him in the position of either declaring for France against Henry VIII (James's brother-in-law) or remaining neutral, which would make him vulnerable to any further English expansion, as Henry had revived his claim to the Scottish throne.
Despite pressure from senior members of his council to avoid an outright breach with England, when Henry arrived in Calais preparing to wage war against the French, James decided to go to war against the English. Prior to the battle at Flodden he had crossed the River Tweed into England where he then attacked and captured Norham Castle, and then destroyed both Etal and Ford Castles whilst the English were still mustering their troops. But the outcome was a disaster for Scotland and James was killed on Flodden Field:
The king's was but one of many hundreds of bodies, sprawled and piled on the bloodied turf. The whole hillside from the brook northwards was a killing ground, the dead, maimed and horribly injured competing for space, severed limbs and streaming entrails spilling fresh gore. The din would have been terrific, with hoarse shouts and the screams of the dying men, the crash of spears, a crescendo rising and spilling like breakers against the shore. (page 82, Flodden 1513 by John Sadler)
Each time I go to Branxton, or see the monument as we drive south along the A697, I think about the battle and all those who died there in 1513.
For more Saturday Snapshots see Melinda's blog West Metro Mommy Reads.
May 4, 2013 ~ Margaret	~ 12 Comments
This is the Flodden Visitor Centre. It's in a former telephone box in the village of Branxton in Northumberland. It claims to be the smallest visitor centre in the world:
It's part of the commemoration of the Battle of Flodden which took place 500 years ago in September between the English and Scottish armies in the fields near Branxton.
Inside there is a map showing the routes of the two armies and indicating several sites related to the battle. There are leaflets and even a button to press the hear about the battle.
If you are in London on 14 May you can get tickets for a lunchtime lecture on the Battle of Flodden 1513 by historian Clive Hallam Baker at the Tower of London. He is the author of The Battle of Flodden: Why and How.
Other books about Flodden, with links to my reviews:
After Flodden by Rosemary Goring (a new book to be published in June)
Tom Fleck: a novel of Cleveland and Flodden by Harry Nicholson
Non fiction:
Flodden: the Scottish Invasion of Henry VIII's England by Nigel Barr
New Light on Floddon (sic) by Gerard F T Leather – I have not written about this short book published in 1938, which Leather, a member of the Berwickshire Naturalists' Club had written after studying the battle for a talk. As he explained there were actually four distinct fights going on a more or less the same time and the old name of the battle was that of Branxton Moor, a more correct title, in his opinion, as the battle scene was a mile and a half from Flodden.
For more Saturday Snapshots see Alyce's blog At Home With Books.
Flodden: the Scottish Invasion of Henry VIII's England
October 4, 2010 ~ Margaret	~ 6 Comments
Flodden by Niall Barr is an account of the Battle of Flodden between the English and the Scots in 1513, which challenges the traditional view of the battle. In 1512 James IV, Henry VIII's brother-in-law, had renewed the 'Auld Alliance' with France, promising mutual support should England attack either country. So when Henry made war on France, James had no alternative and he crossed the River Tweed into England with about 40,000 men.
The weather that September was much like it's been this September – wet and stormy. The battle field was at Branxton, then just a few houses surrounded by bog and woodland. The two armies came face to face separated by a small valley with the English at the bottom of Flodden Hill. The Scots attacked down the hill and were chopped to pieces by the English and James himself was killed. Barr shows how, contrary to the traditional view, James led a well organised and prepared army and considers that it was using new, continental weapons and military tactics in the wrong situation that led to his defeat.
There is a bit too much detail about the weapons used and military history for my liking and I scan read the chapters dealing with that. But the book as a whole gives a real flavour of the times, the diplomacy, the main protagonists and the battle. I found it interesting, maybe because I live in the area where it all took place. I've been to the battle field, which today is so peaceful and tranquil, but I could imagine the terrible carnage that took place there nearly 500 years ago.
Map on the notice board in the car park below Flodden Field
Flodden Field
September 15, 2009 ~ Margaret	~ 4 Comments
Whilst searching for a house D and I were near Flodden Field, so of course we just had to go and have a look at it. Flodden Field is near the village of Branxton in Northumberland, a peaceful setting now, but nearly five hundred years ago this was the site of the most famous battles in the borders between the kings of England and Scotland – the Battle of Flodden Field in 1513. It was disastrous for the Scots when their King, James IV was killed.
An information board in the little car park next to the field gives many details of the battle.
The field is on a hill overlooking Branxton and there is a steep climb up to the monument. In 1513 the battleground was an undrained boggy morass in which the Scottish troops were knee-deep in mud with more troops coming down the hill behind them, whereas the English troops were on the higher ground with room to manoeuvre.
At the top of the hill there is a monument and wonderful views of the surrounding countryside.
Below is the village of Branxton.
The wider scene
I haven't read Flodden 1513: Scotland's Greatest Defeat Campaign by John Sadler and Stephen Walsh but I think it looks interesting. If you look at it on Amazon you can read a few pages of the opening chapter: The Origins of the Campaign.
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HomeObituariesJACK SHINDLEMAN (September 30, 1923 - October 28,...
JACK SHINDLEMAN (September 30, 1923 – October 28, 2020)
Young at 97 years and 4 weeks. Yes, Jack Shindleman was young. He lived independently, cooked, cleaned and drove himself. His joy of life included being a loyal minyannaire at Shaarey Zedek for 22 years. Jack deserved to be fearless of age, and proud of it too. How young he seemed, was and looked.
Jack Shindleman was the second youngest of seven children, and grew up knowing the challenges of being a member of an immigrant family, particularly when others were not always friendly. His parents, Harry and Shprintza came to Canada from Zhitomer, Russia with their first two children, Clara and Max. His siblings, all of blessed memory, were Clara Greenberg, Max Shindelman, Sophie Goldstein, Elsie Yuffe, Eddie Shindleman and Gladys Kushner. Jack was also predeceased by his loving companion, Doris Bordian.
Jack learnt to become a watch repairman, but ultimately left his hometown of Winnipeg to join his sister Clara and his brother Eddie in Portage la Prairie. Jack and Eddie became a team at work in a grocery store, as livestock buyers, and as dealers in scrap metals and furs. He was also a founder of Prairie Abattoir in Portage la Prairie. Over the years, they were the true welcoming team to many a Portage family. With humour and a large dose of generosity, bonds of trust and loyalty were developed with customers. Many adults today will remember the joking and teasing, as well as the genuine interest in and care for their welfare that came along with a visit to the grocery store. Jack was an integral part of this. Jack always had a story to share, always made people welcome.
Elected and re-elected several times as city councillor in Portage la Prairie, Jack's approach was summed up in one sentence: "My name is Jack Shindleman and I will work for Portagers to make Portage a better place." Simple. To the point. And, indeed, that is just what he did. Jack also served as Deputy Mayor.
He had an expansive knowledge of world affairs, but he also had an encyclopedic mind of every corner and highway in the province of Manitoba. In his early years, Jack drove a horse and buggy to travel rural Manitoba along with his father in the livestock trade. A trade he continued throughout his life. And, those roads were indelibly written in his mind. Imagine the winter storms he prevailed through. It showed, because no matter how challenging the weather or road conditions, Jack was the driver (by horse and later by car) who remained calm and always got to the destination. It did not hurt, as well, that the horses knew the way home!
In 1967, baseball matches of the Pan Am Games were held in Portage la Prairie. Jack was there to help and support the teams. He took a continuing interest in the sport throughout the decades that followed. One of his last conversations with his great nephew Edward, who recalls that Jack's mind remained sharp, was about the upcoming World Series. Jack's passing was hours after the completion of this year's World Series. How timely for a man passionate about the sport.
His regular visits with his nephews and nieces were Jack's truest pride. His advice was sought on innumerable topics. His visits with family were much awaited. Jack never missed a birthday of a nephew or niece. He was always there with a hug, stories to share, and loving kindness.
Few people actually capture the essence of a place. Manitoba is "Friendly Manitoba". Jack took this to become his mantra. He took a genuine interest in those he met. He had a view on how others could be helped, or indeed how they could help themselves. His experiences of people from all across society fostered wisdom that he shared eagerly.
After his sister Clara became a widow, Jack took it upon himself to attend to Clara's wellbeing and was very dedicated to her. Jack was mechanically-inclined and well organized. He could fix everything and anything. Just give him a task and he did it. Somehow he always figured it out.
Going to an appointment meant that Jack first stopped to buy Morden's chocolates to give as a gift to whomever he met, and their assistants. It was an act of kindness without any expectation. True kindness. Jack came from most humble beginnings, experienced the Great Depression and the war years, and lived a modest lifestyle.
He became a fixture on the local casino circuit, as well as taking casino tours to the United States with friends.
After returning to Winnipeg for retirement, he soon found that retirement could be as busy as work. With brother Eddie, he travelled around always busy with too many tasks to complete in a day. The loss of Eddie in 1998 lead to an ever-increasing bond with Eddie's sons, Robert and Sandy. Breakfasts, lunches and dinners together. Baseball and hockey games too, always together. Caring for the family pets, always together. Shabbos and holidays spent together with family were a longstanding tradition not to be missed.
Jack's siblings predeceased him. He is survived by many nephews and nieces, including great and great great nephews and nieces, and their families. We wish to express our appreciation for the care and comfort Jack received at the St. Boniface Hospital, by Dr. Kevin Coates, and a very special note of appreciation to Marlene who became Jack's faithful aid, driver and companion. We also thank the pallbearers, Howard Yuffe, Stephen Yuffe, Michael Kushner, Jared Kushner, Stephen Rosenfield, and Howie Raber.
Doing the right thing came naturally to Jack. Donations of food, clothing, his time, as well as financial support were all part of his way. Should anyone wish to make a donation, please contribute to the Gray Academy of Jewish Education, the Canadian Institute for the Study of Antisemitism ("CISA"), or a charity of your choice.
Jack is missed, but not forgotten. His humour and humility, his friendship and fellowship, his wisdom and wishes for others, will always be remembered to bring light to future days. May Jack's memory forever be a blessing.
We're visiting Auschwitz because the fight against antisemitism didn't end with liberation
Lord David Young, British-Jewish politician and favorite fixer for Margaret Thatcher, dies at 90
Four young Jewish women join together to create "SIMCHA Zine"


text:
Turbonilla hecuba is a species of sea snail, a marine gastropod mollusk in the family Pyramidellidae, the pyrams and their allies.

Description
The shell grows to a length of 6.1 mm.

Distribution
This species occurs in the following locations:
 Northwest Atlantic: off Nova Scotia at a depth of 35 m.

Notes
Additional information regarding this species:
 Distribution: Barrington Passage, Nova Scotia

References

External links
 To Biodiversity Heritage Library (1 publication)
 To Encyclopedia of Life
 To ITIS
 To World Register of Marine Species

hecuba
Gastropods described in 1913


Residual categories are those which cannot be formally represented within a given classification system. We examine the forms that residuality takes within our information systems today, and explore some silences which form around those inhabiting particular residual categories. We argue that there is significant ethical and political work to be done in exploring residuality.


EMS SQL Manager for Oracle Freeware is a high performance database tool for Oracle database development and administration. SQL Manager for Oracle works with any Oracle versions from 8.1.7 to the newest one and supports the latest Oracle Database features and data types including compressed, OLAP, read-only and read-write tables; invisible indexes; compound triggers, triggers with FOLLOWS clause and others. It offers plenty of powerful Oracle tools for effective Oracle security management and many more useful features for efficient Oracle administration. SQL Manager for Oracle has a state-of-the-art graphical user interface with a well-described wizard system, so clear in use that even a newbie will not be confused with it.


Internationally-oriented, Mar-In Controls B.V. supplies equipment to customers all over the globe. Modules and control equipment of the Mar-In Controls B.V. brand can be found on a diverse fleet of vessels, from Bulk carriers to luxury Cruise ships and land applications as power plants.
Our strong brand name, created through a dedication to service and the quality of our products, has become a preference among many of the leading industries and shipyards around the world.
To improve worldwide product supply and facilitate growth, Mar-In Controls B.V. has expanded its operations into the Chinese shipbuilding market. On the 15th of June, 2005, Mar-In Controls Nantong Co. Ltd., a Joint Venture between the shareholders of Mar-In Controls B.V. and a Chinese partner was founded, with its own manufacturing operation of 900m² in Quidong City, Jiangsu Province. The primary aim of Mar-In Controls Nantong Co. Ltd. will be the production of Fuel Supply Units, Preheating modules and other modules identical to those made by the sister company Mar-In Controls B.V. specifically for the Chinese market.


... you to critique the validity of claims, research results, or even theories in a particular text. Along the same lines, if you are putting together your own argumentative paper (KAM, dissertation proposal, prospectus, etc.), understanding argument structure and fallacies will help you avoid errors of reasoning in your own work.


text:
\section{Introduction}

Recently, a new model, named ModMax model, of nonlinear electrodynamics (NED) which is duality and conformal invariant, as well as Maxwell electrodynamics, was proposed in \cite{Bandos}. Some aspects of this model and its applications were studies in \cite{Kosyakov,Habib,Bandos1,Townsend,Flores,Kubiznak}. Earlier proposals of conformal invariant NED was in \cite{Cembranos,Cembranos1,Denisov,Denisova}.

The duality-invariant conformal electrodynamics was introduced in \cite{Bandos} and it is described by the Lagrangian density
\begin{equation}
L=-{\cal F}\cosh(\gamma)+\sqrt{{\cal F}^2+{\cal G}^2}\sinh(\gamma),
\label{1}
\end{equation}
where
\begin{equation}
{\cal F}=\frac{1}{4}F_{\mu\nu}F^{\mu\nu}=\frac{1}{2}\left(\textbf{B}^2-\textbf{E}^2\right),~~~~{\cal G}=\frac{1}{4}F_{\mu\nu}\tilde{F}^{\mu\nu}=\textbf{B}\cdot \textbf{E},
\label{2}
\end{equation}
are Lorentz invariants with $\textbf{B}$, $\textbf{E}$ being the magnetic induction and electric fields correspondingly, $F_{\mu\nu}=\partial_\mu A_\nu-\partial_\nu A_\mu$, $\tilde{F}^{\mu\nu}=(1/2)\epsilon^{\mu\nu\alpha\beta}F_{\alpha\beta}$ is the dual electromagnetic field, and $\gamma$ is the dimensionless parameter.
This model as well as Maxwell electrodynamics with the Lagrangian density ${\cal L}_M=-{\cal F}$ possess singularities in the centre of point-like charges. In addition, the electromagnetic energy of charges is infinite. To smooth singularities we propose the generalized ModMax model with the Lagrangian density
\begin{equation}
{\cal L}=\frac{1}{\beta}\left(1-\left(1-\frac{\beta L}{\sigma}-\frac{\beta \lambda{\cal G}^2}{2\sigma}\right)^\sigma\right),
\label{3}
\end{equation}
where $L$ is given by Eq. (1), $\beta$ and $\lambda$ have the dimensions of $(length)^4$ and $\sigma$ is the dimensionless parameter. At $\sigma=1$, $\lambda=0$ we come to ModMax model, when $\gamma=0$ one has the Born--Infeld-type model \cite{Kruglov}, \cite{Kruglov1}, at $\sigma=1/2$, $\gamma=0$ we arrive at the generalized Born--Infeld model \cite{Kruglov2}, and at $\sigma=1/2$, $\gamma=0$, $\lambda=\beta$ one comes to Born--Infeld model ($\beta=1/b^2$) \cite{Born}. At $\sigma\rightarrow\infty$ the Lagrangian density (3) becomes
\begin{equation}
{\cal L}_{exp}=\frac{1}{\beta}\left(1-\exp\left(-\beta L-\beta \lambda{\cal G}^2/2\right)\right).
\label{4}
\end{equation}
Some exponential NED models were considered in \cite{Hendi}, \cite{Kruglov3}. Thus, our model (3) allows us to consider different NED by fixing the parameters introduced. The Born--Infeld model is of interest because at the low energy D-brain dynamics is governed by Born--Infeld-type
action \cite{Fradkin}, \cite{Tseytlin}. Making use of the Taylor series, at $\beta L\ll 1$, $\beta\lambda{\cal G}^2\ll 1$, the Lagrangian density (3) becomes
\begin{equation}
{\cal L}=L+\frac{\beta(1-\sigma)L^2}{2\sigma} + \frac{\lambda}{2}{\cal G}^2+{\cal O}(LG^2)+
{\cal O}(L^3).
\label{5}
\end{equation}
As a result, in the weak-field limit and small $\gamma$ when the condition $\beta L\ll 1$ is satisfied, the Lagrangian density (3) approaches to the ModMax model. At $\gamma=0$ Eq. (5) corresponds to the Heisenberg--Euler-type electrodynamics \cite{Kruglov4}.

Adding to Eq. (3) the source term $A_\mu j^\mu$ and varying the action we obtain the Euler--Lagrange equations
\begin{equation}
\partial_\mu\left({\cal L}_{\cal F}F^{\mu\nu}+{\cal L}_{\cal G}\tilde{F}^{\mu\nu}\right)=j^\nu,
\label{6}
\end{equation}
where
\[
{\cal L}_{\cal F}=\frac{\partial {\cal L}}{\partial {\cal F}}=\left(1-\frac{\beta L}{\sigma}-\frac{\beta \lambda{\cal G}^2}{2\sigma}\right)^{\sigma-1}L_{\cal F},~~~
L_{\cal F}=-\cosh(\gamma)+\frac{{\cal F}\sinh(\gamma)}{\sqrt{{\cal F}^2+{\cal G}^2}},
\]
\begin{equation}
{\cal L}_{\cal G}=\frac{\partial {\cal L}}{\partial {\cal G}}=\left(1-\frac{\beta L}{\sigma}-\frac{\beta \lambda{\cal G}^2}{2\sigma}\right)^{\sigma-1}(L_{\cal G}+\lambda G),~~~
L_{\cal G}=\frac{{\cal G}\sinh(\gamma)}{\sqrt{{\cal F}^2+{\cal G}^2}}.
\label{7}
\end{equation}
Field equations (6) can be represented as Maxwell equations
making use of definitions of the electric displacement and magnetic fields
\[
\textbf{D}=\frac{\partial {\cal L}}{\partial \textbf{E}}=\varepsilon \textbf{E}+\nu\textbf{B},~~~\varepsilon=-{\cal L}_{\cal F},~\nu={\cal L}_{\cal G},
\]
\begin{equation}
\textbf{H}=-\frac{\partial {\cal L}}{\partial \textbf{B}}=\mu^{-1}\textbf{B}-\nu \textbf{E},~~~\mu=\varepsilon^{-1}.
\label{8}
\end{equation}
With help of Eq. (8) Euler--Lagrange equations (6) can be represented as Maxwell equations in Gaussian quantities
\begin{equation}
\nabla\cdot\textbf{D}=4\pi\rho,~~\frac{\partial\textbf{D}}{\partial t}-\nabla\times \textbf{H}=4\pi\textbf{j}.
\label{9}
\end{equation}
Second pair of Maxwell equations follows from the Bianchi identity $\partial_\mu\tilde{F}^{\mu\nu}=0$,
\begin{equation}
\nabla\cdot\textbf{B}=0,~~\frac{\partial\textbf{B}}{\partial t}+\nabla\times\textbf{E}=0.
\label{10}
\end{equation}
From Eq. (8) we obtain the relation
\begin{equation}
\textbf{D}\cdot\textbf{H}=(\varepsilon^2-\nu^2){\cal G}+2\varepsilon\nu {\cal F}.
\label{11}
\end{equation}
According to the criterion of \cite{Gibbons} the dual symmetry takes place if $\textbf{D}\cdot\textbf{H}=\textbf{E}\cdot\textbf{B}$. One can verify from Eq. (11) that the dual symmetry holds in two cases: $\sigma=1$, $\lambda=0$ which corresponds to ModMax model or for Born--Infeld-type model with $\sigma=1/2$, $\lambda=\beta$. It is worth noting that the two-parametric generalized Born--Infeld model ($\sigma=1/2$, $\lambda=\beta$) was considered and shown to be duality invariant in \cite{Bandos1}.

From Eq. (9), for the source of the point-like charged particle with the electric charge $q$, in Gaussian units, we obtain the equation as follows
\begin{equation}
\nabla\cdot\textbf{D}=4\pi q\delta(\textbf{r}),
\label{12}
\end{equation}
with the solution
\begin{equation}
\textbf{D}=\frac{ q\textbf{r}}{r^3}.
\label{13}
\end{equation}
From Eqs. (8) and (13) one finds
\begin{equation}
E\exp(\gamma)\left(1-\frac{\beta E^2}{2\sigma}\exp(\gamma)\right)^{\sigma-1}=\frac{ q}{r^2}.
\label{14}
\end{equation}
Introducing the dimensionless variables
\begin{equation}
v=\frac{\sqrt{\beta} E}{\sqrt{2\sigma}}\exp\left(\frac{\gamma}{2}\right),~~~u=\frac{r\sqrt[4]{2\sigma}}{{\sqrt[4]\beta} \sqrt{q}}\exp\left(\frac{\gamma}{4}\right),
\label{15}
\end{equation}
Eq. (14) takes the form
\begin{equation}
v\left(1-v^2\right)^{\sigma-1}=\frac{1}{u^2}.
\label{16}
\end{equation}
It follows from Eq. (16) that at $u\rightarrow 0$, $v(0)=1$ for $\sigma<1$, or in terms of electric fields
\begin{equation}
E(0)=\sqrt{\frac{2\sigma}{\beta}}\exp\left(-\frac{\gamma}{2}\right).
\label{17}
\end{equation}
Thus, the electric field of the point-like charged particle in the center is finite and possesses the maximum value for $\sigma<1$. When $\sigma$ increases the maximum value of electric fields increases, but if $\gamma$  increases the electric field in the center decreases.
For the cases $\sigma=1/2$ (Born--Infeld-type model) and $\sigma=3/4$ exact solutions to Eq. (16) and their asymptotic as $u\rightarrow 0$ are
\[
v=\frac{1}{\sqrt{1+u^4}},~~~~v=1-\frac{u^4}{2}+\frac{3u^8}{8}+{\cal O}(u^{12})~~~~\sigma=\frac{1}{2},
\]
\begin{equation}
v=\frac{\sqrt{\sqrt{1+4u^8}-1}}{\sqrt{2}u^4},~~~~v=1-\frac{u^8}{2}  +{\cal O}(u^{16})~~~~\sigma=\frac{3}{4}.
\label{18}
\end{equation}
The plots of function $v(u)$ for $\sigma=1/4$, $\sigma=1/2$ and $\sigma=3/4$ are given in Fig. (1).
\begin{figure}[h]
\includegraphics[height=4.0in,width=4.0in]{K.eps}
\caption{\label{fig.1}The plot of the function $v(u)$ for $\sigma=1/4$, $\sigma=1/2$ and $\sigma=3/4$.}
\end{figure}
In the general case for $\sigma<1$, the functions $v(u)$ as $u\rightarrow 0$ ($r\rightarrow 0$) and $u\rightarrow \infty$ ($r\rightarrow\infty$) become
\[
v=1-\frac{u^{2/(1-\sigma)}}{2}+{\cal O}(u^{4/(1-\sigma)})~~~~u\rightarrow 0,
\]
\begin{equation}
v=\frac{1}{u^2}-\frac{1-\sigma}{u^6}+{\cal O}(u^{-8})~~~~u\rightarrow\infty.
\label{19}
\end{equation}
Making use of Eqs. (15) and (19) we obtain the asymptotic value of the electric field as $r\rightarrow 0$ and $r\rightarrow\infty$
\[
E=\sqrt{\frac{2\sigma}{\beta}}\exp\left(-\frac{\gamma}{2}\right)-\frac{(2\sigma)^{(2-\sigma)/(2(1-\sigma))}r^{2/(1-\sigma)}}
{2\beta^{(2-\sigma)/(2(1-\sigma))}q^{1/(1-\sigma)}}\exp\left(\frac{\gamma\sigma}{(2(1-\sigma)}\right)
\]
\[
+{\cal O}(r^{4/(1-\sigma))})~~~~~~r\rightarrow 0,
\]
\begin{equation}
E=\frac{q}{r^2}\exp(-\gamma)-\frac{(1-\sigma)\beta q^3}{2\sigma r^6}\exp(-2\gamma)+{\cal O}(r^{-8})~~~~~~r\rightarrow\infty.
\label{20}
\end{equation}
Equation (20) gives the correction to Coulomb's law as $r\rightarrow\infty$. We have damping of the electric field because of parameter $\gamma$.
Corrections to Coulomb's law for the case of Born--Infeld-type electrodynamics ($\sigma=1/2$) and exponential-like electrodynamics (4) ($\sigma=\infty$) are similar but with the opposite sign. At $\sigma=1$, $\lambda=0$, $\gamma=0$, one has Maxwell's electrodynamics and we come to the Coulomb law $E=q/r^2$ as $r\rightarrow\infty$, but the electric field at the origin is infinite.

The energy-momentum tensor is given by

\begin{equation}
T_{\mu\nu}=F_{\mu\alpha}\left({\cal L}_{\cal F}F_{~\nu}^{\alpha}+{\cal L}_{\cal G}\tilde{F}_{~\nu}^{\alpha}\right)-g_{\mu\nu}{\cal L}.
\label{21}
\end{equation}
From Eq. (21) we obtain the energy density
\begin{equation}
T_{0}^{~0}=-E^2{\cal L}_{\cal F}-G{\cal L}_{\cal G}-{\cal L}.
\label{22}
\end{equation}
In the case of pure electric field ($\textbf{B}=0$) the energy density (22) becomes
\begin{equation}
T_{0}^{~0}=E^2e^\gamma\left(1-\frac{\beta E^2}{2\sigma}e^\gamma\right)^{\sigma-1}-\frac{1}{\beta}\left(1-\left(1-\frac{\beta E^2}{2\sigma}e^\gamma\right)^\sigma\right).
\label{23}
\end{equation}
For the Born--Infeld-type electrodynamics with $\sigma=1/2$ we can calculate the total electrostatics energy of point-like charged particles. Introducing the dimensionless variables
\begin{equation}
y=\beta E^2\exp(\gamma),~~~~x=\frac{r^2\exp(\gamma/2)}{q\sqrt{\beta}},
\label{24}
\end{equation}
we obtain from Eq. (14) equation
\begin{equation}
y=\frac{1}{1+x^2}.
\label{25}
\end{equation}
Then, making use of Eqs. (23), (24) and (25), the total electrostatics energy of point-like charged particles (for $\sigma=1/2$) is given by
\[
{\cal E}=4\pi\int_0^\infty T_{0}^{~0}r^2dr=\frac{2\pi q^{3/2}\exp(-3\gamma/4)}{\beta^{1/4}}I,
\]
\begin{equation}
I=\int_0^\infty\left(\frac{\sqrt{1+x^2}}{\sqrt{x}}-\sqrt{x}\right)dx=-\frac{2}{3}\sqrt{x}\left(x-3 {_2}F_1\left(-\frac{1}{2},\frac{1}{4};\frac{5}{4};-x^2\right)\right)_0^\infty.
\label{26}
\end{equation}
Taking into account the asymptotic of hypergeometric function  $_2F_1(-1/2,1/4;5/4;-x^2)$ we obtain the total electrostatics energy of point-like charged particles
\begin{equation}
{\cal E}\approx 15.5327\frac{q^{3/2}}{\beta^{1/4}}\exp\left(-\frac{3\gamma}{4}\right).
\label{27}
\end{equation}
For Born--Infeld electrodynamics ($\beta=1/b^2$) at $\gamma=0$ we come to the result obtained in \cite{Born}.

To study the conformal invariance of the proposed model (3), we calculate the trace of the energy-momentum tensor $T_\mu^{~\mu}$. According to \cite{Hagen}, the conformal invariance takes place if $T_\mu^{~\mu}=0$. From Eqs. (7) and (27) we obtain
\[
T_\mu^{~\mu}=4\left({\cal F}{\cal L}_{\cal F}+{\cal G}{\cal L}_{\cal G}-{\cal L}\right)
\]
\begin{equation}
=4\left(1-\frac{\beta L}{\sigma}-\frac{\beta \lambda{\cal G}^2}{2\sigma}\right)^{\sigma-1}\left(\frac{(\sigma-1)L}{\sigma}+\frac{(2\sigma-1)\lambda G^2}{2\sigma}+\frac{1}{\beta}\right)-\frac{4}{\beta}.
\label{28}
\end{equation}
Equation (28) shows that the conformal invariance ($T_\mu^{~\mu}=0$) holds only for $\sigma=1$, $\lambda=0$ corresponding to the ModMax model.

In accordance with \cite{Born} we introduce the ``free charge density" $\rho_{free}$ by the equation
\begin{equation}
\nabla\cdot E=\frac{1}{r^2}\frac{d}{dr}(r^2E)=4\pi\rho_{free},
\label{29}
\end{equation}
where $E$ obeys Eq. (14). To calculate the distribution of the free charge one has to obtain $\rho_{free}$ from Eq. (29). We have exact solutions to Eq. (14) for $\sigma=1/2$ and $\sigma=3/4$. Making use of Eq. (15), from Eq. (18) we find
\[
E=\frac{q\exp(-\gamma/2)}{r_0^2\sqrt{1+(r/r_0)^4\exp(\gamma)}}~~~~~~~~\sigma=\frac{1}{2},
\]
\begin{equation}
E=\frac{qr_0^2\exp(-3\gamma/2)\sqrt{\sqrt{1+(9r^8/r_0^8)\exp(2\gamma)}-1}}{\sqrt{3}r^4}~~~~~~~~\sigma=\frac{3}{4},
\label{30}
\end{equation}
where $r_0=\sqrt[4]{\beta}\sqrt{q}$. When $q$ is the charge of the electron, $r_0$ is the electron radius \cite{Born}. It follows from Eq. (30) that for $r\rightarrow\infty$ the electric field $E\rightarrow (q/r^2)\exp(-\gamma)$ and for $r\rightarrow 0$ we have
\[
 E\rightarrow \frac{1}{\sqrt{\beta}}\exp\left(-\frac{\gamma}{2}\right)~~~~~~~~~\sigma=\frac{1}{2},
\]
 \begin{equation}
  E\rightarrow \sqrt{\frac{3}{2\beta}}\exp\left(-\frac{\gamma}{2}\right)~~~~~~~~~\sigma=\frac{3}{4},
 \label{31}
\end{equation}
 according to Eq. (20). From Eqs. (29) and (30) we obtain ``free charge density"
 \[
 \rho_{free}=\frac{q\exp(-\gamma/2)}{2\pi r_0^2r(1+(r/r_0)^4\exp(\gamma))^{3/2}}    ~~~~~~~~~\sigma=\frac{1}{2},
 \]
\begin{equation}
\rho_{free}=\frac{qr_0^2\exp(-3\gamma/2)}{2\sqrt{3}\pi r^5}\sqrt{\frac{\sqrt{1+(9r^8/r_0^8)\exp(2\gamma)}-1}{1+(9r^8/r_0^8)\exp(2\gamma)}}   ~~~~~~~~~\sigma=\frac{3}{4},
\label{32}
\end{equation}
For Born--Infeld electrodynamics, in the case $\sigma=1/2$, $\gamma=0$, one comes from Eq. (32) to the result found in \cite{Born}. Now we can calculate free charges
\begin{equation}
q_{free}=4\pi\int_0^\infty r^2\rho_{free}dr=\left(r^2E^2\right)_0^\infty.
\label{33}
\end{equation}
Making use of Eqs. (20) and (33) we find the free charge for any parameter $\sigma$
\begin{equation}
q_{free}=q\exp(-\gamma).
\label{34}
\end{equation}
Equation (34) shows that the free charge is less from $q$ by the factor $\exp(-\gamma)$.
From Eq. (30) we obtain the free electric charges, in the cases $\sigma=1/2$ and $\sigma=3/4$, inside the sphere $r<r_0$
\[
q_{free}(r_0)=4\pi\int_0^{r_0} r^2\rho_{free}dr=\left(r^2E\right)_0^{r_0}=q_{free}\frac{\exp(\gamma/2)}{\sqrt{1+\exp(\gamma)}}~~~~~\sigma=1/2,
\]
\begin{equation}
q_{free}(r_0)=q_{free}\frac{\sqrt{\sqrt{(1+9\exp(2\gamma)}-1}}{\sqrt{3}}\exp\left(-\frac{\gamma}{2}\right)  ~~~~~~~~~~~~~\sigma=3/4
\label{35}
\end{equation}
The plots of the functions $q_{free}(r_0)/q_{free}$ versus $\gamma$ is presented in Fig. 2.
\begin{figure}[h]
\includegraphics[height=4.0in,width=4.0in]{K1.eps}
\caption{\label{fig.2}The plot of the functions $q_{free}(r_0)/q_{free}$ versus $\gamma$ for $\sigma=1/2$ and $\sigma=3/4$.}
\end{figure}
It follows from Eq. (35) and the Fig. 2 that at $\gamma=0$ $q_{free}(r_0)/q_{free}\approx 0.71$ for $\sigma=1/2$ and $q_{free}(r_0)/q_{free}\approx 0.85$ for $\sigma=3/4$. Therefore, $71\%$ of the electron charge $q_{free}$ is contained in the electron radius sphere  for $\sigma=1/2$ and $85\%$ of the electron charge is concentrated within the electron radius for $\sigma=3/4$. When parameter $\gamma$ increases
more charge is inside the electron radius sphere.

For the magnetic monopole we have equation
\begin{equation}
\nabla\cdot\textbf{B}=4\pi Q\delta(\textbf{r}),
\label{36}
\end{equation}
where $Q$ is the magnetic charge. For a magnetic monopole we have equation
\begin{equation}
B=\frac{Q}{r^2}.
\label{37}
\end{equation}
From Eq. (22) we obtain the magnetic energy density ($E=0$) of the magnetic monopole
\begin{equation}
T_{0}^{~0}=-{\cal L}=\frac{1}{\beta}\left(\left(1+\frac{\beta Q^2}{2\sigma r^4}e^{-\gamma}\right)^\sigma-1\right).
\label{38}
\end{equation}
The total magnetic energy is given by
\begin{equation}
{\cal E}_m=4\pi\int_0^\infty T_{0}^{~0}r^2dr=-\frac{4\pi}{\beta}\int_0^\infty r^2\left(1-\left(1+\frac{\beta Q^2}{2\sigma r^4}e^{-\gamma}\right)^\sigma\right)dr
\label{39}
\end{equation}
Integral (39) converges for $0<\sigma<1$ and the energy of the magnetic monopole is finite within our model. In Table 1 we present the approximate values of the dimensionless energy $\bar{\cal E}_m=\beta^{1/4}Q^{-3/2}\exp(3\gamma/4){\cal E}_m$ for $\sigma=0.1,0.2,..,0.7$.
\begin{table}[ht]
\caption{The dimensionless energy $\bar{{\cal E}}_m$}
\centering
\begin{tabular}{c c c c c c c c}\\[1ex]
\hline
$\sigma$ & 0.1 & 0.2 & 0.3 & 0.4 & 0.5 & 0.6 & 0.7  \\[0.5ex]
\hline
 $\bar{\cal E}_m$ & 6.58 & 8.38 & 10.13 & 12.28 & 15.45 & 22.29 & 58.78 \\[0.5ex]
\hline
\end{tabular}
\end{table}
Table 1 shows that with increasing parameter $\sigma$ the magnetic energy of the monopole increasing. When parameter $\gamma$ increases the magnetic energy ${\cal E}_m$ decreases.

From Eq. (8) we obtain the magnetic field of the monopole
\begin{equation}
\textbf{H}=\frac{Q}{r^2}e^{-\gamma}\left(1+\frac{\beta Q^2}{2\sigma r^4}e^{-\gamma}\right)^{\sigma-1}.
\label{40}
\end{equation}
The ``free magnetic charge density" $\eta_{free}$ is defined by the equation
\begin{equation}
\nabla\cdot H=\frac{1}{r^2}\frac{d}{dr}(r^2H)=4\pi\eta_{free}.
\label{41}
\end{equation}
Making use of Eq. (41) one finds from Eq. (40) the ``free magnetic charge density"
\begin{equation}
\eta_{free}=-\frac{\beta Q^3(\sigma-1)}{2\pi \sigma r^7}e^{-2\gamma}\left(1+\frac{\beta Q^2}{2\sigma r^4}e^{-\gamma}\right)^{\sigma-2}.
\label{42}
\end{equation}
Similar to Eq. (33) we obtain, by using Eq. (40), the free magnetic charge
\begin{equation}
Q_{free}=\frac{1}{4\pi}\int \nabla\cdot Hd^3x=\int_0^\infty\frac{d}{dr}(r^2H)dr=\left(r^2H^2\right)_0^\infty=Q\exp(-\gamma).
\label{43}
\end{equation}
Thus, the equation for the free magnetic charge is similar to the free electric charge (34).
From Eq. (40), one finds the free magnetic charge inside the sphere of the radius $r_m=\beta^{1/4}\sqrt{Q}$
\begin{equation}
Q_{free}(r_m)=\left(r^2H\right)_0^{r_0}=Q_{free}\left(1+\frac{1}{2\sigma}e^{-\gamma}\right)^{\sigma-1}.
\label{44}
\end{equation}
The plots of the functions $Q_{free}(r_m)/Q_{free}$ versus $\gamma$ for $\sigma=1/8$, $\sigma=1/2$ and $\sigma=3/4$ is presented in Fig. 3.
\begin{figure}[h]
\includegraphics[height=4.0in,width=4.0in]{K2.eps}
\caption{\label{fig.3}The plot of the functions $Q_{free}(r_m)/Q_{free}$ versus $\gamma$ for $\sigma=1/8$, $\sigma=1/2$ and $\sigma=3/4$.}
\end{figure}
According to Eq. (44) $(1+e^{-\gamma}/(2\sigma))^{\sigma-1}$ of the magnetic charge $Q_{free}$ is inside the sphere of the radius $r_m$. The plot of the function $Q_{free}(r_m)/Q_{free}$ is in Fig. 4.
\begin{figure}[h]
\includegraphics[height=4.0in,width=4.0in]{K3.eps}
\caption{\label{fig.4}The plot of the functions $Q_{free}(r_m)/Q_{free}$ versus $\sigma$, for $\gamma=0,1,2,3$.}
\end{figure}
Figure 4 shows that the ratio $Q_{free}(r_m)/Q_{free}$ increases with increasing parameters $\sigma$ and $\gamma$. As a result, more magnetic charge is concentrated in the sphere of the radius $r_m$ with greater values of $\sigma$ and $\gamma$.

The generalised ModMax model proposed as compared to ModMax model (1) possesses the attractive features as follows.

$\bullet$ At some parameters $\beta$, $\lambda$, $\gamma$ and $\sigma$ we come to different models (including the Born--Infeld electrodynamics) discussed in the literature.

$\bullet$ In the weak-field limit and $\gamma=0$, the Lagrangian density leads to the Heisenberg--Euler electrodynamics.

$\bullet$ The electric field of the point-like charged particle in the origin is
finite and possesses the maximum value (for $\sigma<1$).

$\bullet$ The electric and magnetic energies of point-like charged particles is finite for some parameters $\sigma$.

Such properties take place also for the two-parametric duality invariant
generalization of  Born--Infeld electrodynamics found in \cite{Bandos}, \cite{Bandos1}.

In addition, we calculated the free electric and magnetic densities in our model that allow us to study the distributes of the electric and magnetic charges in the space.

redpajama_set_name: RedPajamaArXiv


Brilliantly funny Britain's Got Talent finalist Daliso Chaponda presents his hilarious new show 'What The African Said'. After receiving Amanda Holden's Golden Buzzer, Daliso has gone on to amass over 50 million views online and has sold out venues across the UK on his debut nationwide tour. He has been heard on BBC Radio 4 on The News Quiz, The Now Show, and his own critically acclaimed series Citizen of Daliso as he discusses his new found fame, how he deals with online trolls, and help him decide just how racist some people really are.'A real talent to look out for.' **** Metro'He is hot property' - Evening Standard'Not to be missed .....a never-ending fountain of side-splitting gags' - The Sun This DVD will be signed by Daliso and can include a short personal message up to 10 words long e.g. "Merry Xmas Jane, hope you enjoy it"


The women's Vionic Ellis sneaker is a little bit edgy and incredibly comfortable. This cool style puts its metallic zipper front and center, offering adjustability and a touch of flare. Inside, you'll find a removable orthotic insole for all-day wearability.


Hey kids, I'm really excited because the other day I got an invitation to a friend's party/wedding/dinner [you could hold up an invitation–even if it's not real]. I'm really happy that I get to go because there's going to be food/games/fun, but I'm also happy because it shows that my friend cares about me and likes to hang out with me … Think about when it's your birthday and you're going to have a celebration or a party. You normally get to decide who you're going to invite. Today's story contains a special invitation!
One day Jesus was on his way towards the shore of the Sea of Galilee. There was a tax booth there on the outskirts of the town. Farmers or fishermen who wanted to take their produce (vegetables, or livestock, or fish) to the other side of the lake had to pay a transit tax at the tax booth before they could cross over. A tax is money that you pay to the government to help run the country, but the Jewish people didn't like these taxes at all! Israel was being ruled by the Romans and they did not like that the Romans were taking their money.
Now, the people who sat at the tax booth and collected the moneys were called tax collectors. The Jewish people, especially the religious leaders, did not like the tax collectors! They did not want to be friends with them because they were friends with the Romans. So, the only friends that the tax-collectors had were other tax collectors and outcasts—people who were seen as bad!
As soon as Jesus said to him "follow me", Matthew left his job as a tax collector and he became a disciple of Jesus! He accepted Jesus' invitation.
Later, Matthew decided that he wanted to have a feast at his house. He probably wanted to celebrate that somebody special wanted to actually be his friend!!! He decided to invite Jesus to the feast. He also decided to invite many other people who nobody wanted to be friends with, because Jesus would be friends with them too!
So, they had their feast at Matthew's house and they were having so much fun! Pretty soon though, the Pharisees and the religious leaders saw what was going on and they didn't like it. They said: "Why is Jesus being friends with those horrible people?" When Jesus heard that he said to them: "It is not the healthy who need a doctor, but the sick. I have not come to call the righteous, but sinners to repentance." (Lk 5:31–32 NIV).
What can we learn from this story? Jesus showed that he came so that everyone could be close to God. Jesus wants everybody to be his friend, even those people who others don't want to be friends with. It was fun to see how kind Matthew was because even though he now had a very special and important friend, he didn't forget about his old friends who weren't popular.
The wonderful news for us is that Jesus has invited each one of you to be his follower too! Each one of you are special to him and he wants each one of you to know him and to be his friend. That means that we can talk to him, we can tell him about things that bother us and ask him for help. It also means that we can share joyful moments with Jesus.
It honors Jesus when we invite Jesus to be part of our lives too. We can invite Jesus to be part of everything we do because everything is better with Jesus!
Prayer: Thank God that he has invited each one of us to be a his friend and that God has called each one of us to follow him. Pray that the children would hear God's voice and find the courage to follow him the way that Matthew did.
What was Matthew doing when Jesus came to him?
What did he say to Matthew?
Who did Matthew invite to his house?
What did Jesus say to them?
Supplies: an equal number of red, yellow, blue and green balloons.
Object: Just as Matthew chose to follow Jesus, the kids will follow a leader and do as they do with a balloon. Then kids will get their balloons to the feast!
To play: part one- choose someone to be the leader. (I recommend a volunteer to lead to start). Hand out one ballon to each child, giving out the same amount of red, yellow, blue and green balloons. (This is for part two of the game.). Have the children spread out so they are not too close to one another. The leader will do an action with their balloon and the children must follow. Examples: hold balloon over your head, pass between your legs, throw in air and catch it, throw in air and spin around one time and catch it, bounce off knee or foot or head. Be creative. It's ok if kids drop their balloons. Just have fun! Pick a new leader and play several rounds.
Another option. Once the balloons are in their corners, Write one word of the memory verse on each balloon. Split kids into 4 teams designated to a color. Line teams up across from the corner where their balloons are. Have them relay to retrieve one ballon each, then have them put the verse in order. First team done is the winner.