text:
Stories from the heart. This category combines Romantic Fiction with Sagas and Romance to create a collection of lovely tales. From rags to riches stories to tales of tight-knit communities, this carefully curated collection is bound to have the perfect match for you, and as the Beatles said, 'love is all you need'.
By Title (A-Z)
By Title (Z-A)
By Author (A-Z)
By Author (Z-A)
Author: Cecelia Ahern Format: Hardback Release Date: 19/09/2019
Huge, in fact, huger than huge klaxon alert as Cecelia Ahern has written a sequel to her truly wonderful debut, P.S. I Love You. It's been seven years since Gerry died, and after Holly talks about his letters in a podcast, a group approaches her asking for help. I adore Cecelia Ahern's writing, it just speaks to, and connects with my entire being. Confession time, I didn't write any notes as I read, I just read for the pure pleasure of it. Which in itself, really makes a statement doesn't it? Holly is honest, and entirely human as she initially tries to distance herself from the group. This is an older Holly, an altered Holly, she has moved on while Gerry and the letters have remained anchored in time. The other characters are absolutely fascinating, I grew to care about the group members and fell completely in love with Ginika. After reaching the end I found myself reflecting, the writing not only entered my heart, it also still sits in my thoughts. Postscript is just as brilliant, just as emotional, just as gorgeous, as P.S., and while linking so effectively to the past, grows into a truly beautiful novel in its own unique right.
Author: Veronica Henry Format: Paperback Release Date: 25/07/2019
Just as special and completely lovely as you would expect. Veronica Henry's novels are must-reads for me. I set aside plenty of reading time, then overindulged in one sitting and felt full to overbrimming with book love by the time I finished. After the death of their adored Great Uncle, cousins Tabitha and Georgia inherit Dragonfly Farm alongside a completely unknown third party. What secrets will be unearthed as they hunt for answers, and will the farm remain intact? Veronica Henry has created characters that become known and loved within a short space of time. Even if on the page for moments, each sings with colourful, vivid intensity. The storyline flows beautifully, easy to follow, yet delightfully dynamic and compelling. I felt a connection with, and cared about the farm and everyone linked to it. The past comes to visit every now and then, filling in the jigsaw puzzle of secrets. A Home From Home is an absolute treat of a read and I have chosen it as one of my Liz Robinson picks of the month.
How to Build a Boyfriend from Scratch
Author: Sarah Archer Format: Paperback Release Date: 22/07/2019
A thoughtful, comical, thoroughly entertaining relationship story with a difference. Kelly is an introverted perfectionist, she is also a leading robotics engineer. When she feels overwhelming pressure from her family to find a date for her sister's wedding, it makes complete sense to build her own boyfriend… doesn't it? I instantly fell into the pages, this is such a delightfully readable tale, made all the more refreshing by Kelly's family and friends. If this were a film, it would be billed as an offbeat Hollywood romcom. It borders on the quirky (perhaps more than borders with a robot as the romantic interest!). The chaos surrounding Kelly's decision snowballs, creating smirks, and also intrigue, how on earth was she going to rescue the situation? While Sarah Archer embraces fantastical, she also focuses on legitimate thoughts and feelings, creating a wonderful and original balance. How to Build A Boyfriend From Scratch is a positive, smile-filled, engaging read, I thoroughly enjoyed it.
The Magnificent Mrs Mayhew
Author: Milly Johnson Format: Paperback Release Date: 11/07/2019
What a wonderful, charming, readable story to simply fall into, and fall in love with. When cooly glamorous Sophie runs away from her high profile life, she ends up back in her childhood stomping ground. Taking time to relax and enjoy her neighbours and surroundings, she discovers a community that could have been ready made, just for her. But… Sophie has a difficult decision to make. I started reading, and didn't come up for air. This is a book that is all too easy to sink into and not want to surface from, so ensure you pop your 'do not disturb' sign on the door. Milly Johnson expertly built the story, successfully keeping me on tenterhooks before Sophie breaks ranks and escapes. There are some rip-roaringly fabulous characters on offer here, including some that I could quite happily have booed and hissed at. I loved getting to know Sophie, she really is quite delightful, as I read, I smiled and cheered her on. The Magnificant Mrs Mayhew is a gorgeously lively, affectionate and satisfying read. It comes as highly recommended from me, and deservedly sits in our star books selection.
59 Memory Lane
Author: Celia Anderson Format: Paperback Release Date: 27/06/2019
Enchanting, colourful, delightful… a quirky absolute joy of a read (yes I fell in love with 59 Memory Lane). At 110 years old, and quite determined to reach 111, May Rosevere is a collector of memories. However, a new friendship brings an added sense of awareness, just what happens within the gap of a memory doomed to be lost forever? May quickly took root in my heart, and the rest of the characters followed. From the oldest to the youngest, each person matters, and adds to the distinctive nature of the story. Celia Anderson encourages each relationship to grow, to exist, to be of consequence. There are no labels on show to create diversity, each person is an individual, behaving as such. There is intrigue and a bewitching charm to be discovered along the way, weaving a glorious spell. Be aware though, this is not a gooey overly sweet confection. Yes this read is wonderfully charming, it also holds a nettle-sting prickle of warning. Just that little bit different, and so very readable, 59 Memory Lane is a reading treasure trove of delight and must sit as one of my Liz Robinson picks of the month.
Author: Sophie Kinsella Format: Paperback Release Date: 27/06/2019
The irresistible new standalone from Sophie Kinsella is a story of love, empowerment and an IOU that changes everything . . . Fixie Farr can't help herself. Straightening a crooked object, removing a barely-there stain, helping out a friend . . . she just has to put things right. It's how she got her nickname, after all. So when a handsome stranger in a coffee shop asks her to watch his laptop for a moment, Fixie not only agrees, she ends up saving it from certain disaster. To thank her, the computer's owner, Sebastian, scribbles her an IOU - but of course Fixie never intends to call in the favour. That is, until her teenage crush, Ryan, comes back into her life and needs her help - and Fixie turns to Seb. But things don't go according to plan, and now Fixie owes Seb: big time. Soon the pair are caught up in a series of IOUs - from small favours to life-changing debts - and Fixie is torn between the past she's used to and the future she deserves. Does she have the courage to fix things for herself and fight for the life, and love, she really wants? ***** EVERYBODY LOVES SOPHIE KINSELLA: ***** 'Left me giddy with laughter. I loved it' JOJO MOYES 'Life doesn't get much better than a new Sophie Kinsella novel' RED 'One of the most relatable books I've read in a long time, I couldn't put it down.' LOUISE PENTLAND (SprinkleofGlitter)
Happiness for Beginners
Author: Carole Matthews Format: Paperback Release Date: 30/05/2019
What a lovely, charming, friendly read this is, an enticing 'will they, won't they' romance is equally matched by the story of animals in need and children requiring an alternative learning environment. Molly Baker runs her beloved farm as a school, when a new student arrives, Molly's life is turned thoroughly upside down and in to a roundabout spin. I adored the explanation at the beginning of the novel by Carole Matthews that Hope Farm is based on the real Animal Antiks Farm. The first sentence had me chortling and I settled further down into the comfort of my sofa to enjoy the read. Molly tells her own story, I could really hear her voice and her personality shines through. Can I say that the animals very nearly steal the show for me, having had a downright grumpy (read that as flesh tearing vampire) rescue cat myself, their individual quirks made me smile. 'Happiness for Beginners' is entertaining, heart-warming and ever so readable, I raced through in one sitting and enjoyed every second.
I Heart Hawaii
Author: Lindsey Kelk Format: Paperback Release Date: 30/05/2019
If you've been following this fabulously enjoyable series by Lindsey Kelk, then just to let you know that this is the eighth and last book about Angela. While you could read 'I Heart Hawaii' as a standalone, you will have so much more fun if you join Angela and her friends at the beginning with 'I Heart New York'. Jenny invites Angela on a press trip to Hawaii, as is normal, chaos and havoc accompany them. Our leading lady is gorgeously relatable, even though she lives a covetable life. Part of her charm, as well as her huge heart, is her tendency to stumble from one mess to another. Her friends and family are a gorgeously readable bunch, even the one or two who could charitably be described as frightful. 'I Heart' is an entertaining series from start to end, and I smiled, smirked and ahh'd my way through this engaging, toasty-warm read.
Nettie's Secret
Author: Dilly Court Format: Paperback Release Date: 16/05/2019
The new novel from the Sunday Times bestselling author. Taking one last look around her attic room in Covent Garden Nettie knows there is no turning back, they must run for their lives... London, 1875. Thanks to her hapless father, Nettie Carroll has had to grow up quickly. While Nettie is sewing night and day to keep food on the table, her gullible father has trusted the wrong man again. Left with virtually nothing but the clothes they stand up in, he's convinced that their only hope lies across the English Channel in France. Nettie has little but her dreams left to lose. Even far from home trouble follows them, with their enemies quietly drawing closer. But Nettie has a secret, and it's one with the power to save them. Can she find the courage to trust in herself and pave the way for a brighter future?
Ellie and the Harpmaker
Author: Hazel Prior Format: Hardback Release Date: 02/05/2019
An absolutely delightful story ready and waiting to wrap you up in a delicious blanket of warming feel-good. Ellie thinks she is happy, assumes she is happy, but a present from a harp-making stranger heralds change. Oh I did enjoy this story, told in alternate chapters by Ellie and Dan, I settled myself into a comfy spot and stayed there until I had finished. Dan introduces himself in the most simple and beautiful way, he is able to see through clutter to the heart of things and I have to admit to rather falling in love with him. Hazel Prior doesn't spell things out for you, instead I felt that I was able to explore and encouraged to contemplate. The descriptions of Exmoor, nature, and colour are particularly special, and I now find myself taking the time to look properly, to really see, to feel, to smile. Ellie and the Harp Maker is truly lovely and rather special, if you feel like a hug, then read this book!
Rachel's Pudding Pantry
Author: Caroline Roberts Format: Paperback Release Date: 18/04/2019
Ahh, what a lovely, generous, enjoyable read this is. Rachel finds it increasingly difficult to make a living on her family farm, with the support of friends, locals, and a particularly lovely neighbour called Tom, can Rachel and her Mum find a way to keep Primrose Farm? Caroline Roberts has a beautifully light touch, she explores difficult emotions and balances the tale with love and laughter too. The different generations knit together perfectly, from gorgeous 5 year old Maisy through to Granny Ruth, each woman (and girl) an integral part of the storyline. The romance doesn't smother the tale, it sits as an engaging sweet treat alongside friendship and family. If you seek an escape from your own reality, and want to snuggle down with a helping of delicious romance then look no further, Rachel's Pudding Pantry is ready to greet you.
The Temptation of Gracie
Author: Santa Montefiore Format: Paperback Release Date: 18/04/2019
THE EXTRAORDINARY NEW NOVEL FROM THE NUMBER ONE BESTSELLING AUTHOR Never give up on your dreams, no matter how long you hold on to them . . . When Gracie Burton stumbles upon an advertisement for a week-long cookery course in the heart of the Tuscan countryside, she cannot resist, and ploughs her life savings into the trip. Her only family - daughter Carina and granddaughter Anastasia - are hesitant about what has prompted this seemingly random venture. But they have no sense of Gracie's past; of what could possibly be calling her to Italy. They have no idea that Gracie is harbouring the secret of an extraordinary life that preceded them . . . Bestselling author, Santa Montefiore, returns with an unforgettable tale of love lost and rediscovered, set across the beautiful landscape of Italy
A Breath on Dying Embers
Wolves at the Door
The Unmaking of Ellie Rook
Fatal Inheritance
The Glittering Hour
A Modern Family
If Only I Could Tell You
Mom's Perfect Boyfriend
LoveReading Bookshop of the Month: The Broadway Bookshop
Save the Date for Victorious festival! 23rd-25th August 2019
Industry Insight: Q&A with Kate and Sarah Beal
Putting Authors / Illustrators in the Picture #11: Gavin Extence
LoveReading Bookshop of the Month: Owl and Pyramid
Love in a Cold Climate
We all love a good saga. From Wuthering Heights and Jamaica Inn, to the modern works of authors like Katie Flynn, Katherine Webb and Nadine Dorries, there is something so captivating about the journey of a romantic heroine through an unfamiliar world, where the hearts and desires of all around her form the centre of everything. These stories can take place on grand settings: on the High Seas and foreign lands, or on a small cobbled street in a northern mining town. It doesn't matter, as the journey of the heart is the most important of all. Get your tissues at the ready and find yourself happily shipwrecked on the ragged rocks of epic romance.
Wouldn't it be nice to know that you're never too far away from your next great read, great events, competitions and discounts? Sign up for our free emails and let the passion of our experts guide you to some wonderful new reading.
That book you loved has finally come to an end. Where do you go next? With our unique Author Like for Like tool, you'll discover other authors guaranteed to be right up your street. Login, sit back, put your feet up and enjoy.
Reading Groups! Let us help you find your next hot topic. Visit our Special Section bursting with thought provoking titles and get an extra 5% discount if you buy 5 or more copies.
A selection of authors who will feature in this Lovereading category include:


text:
Covert Geopolitics
White Hats Reports
Ben Fulford Updates
Nazism & Zionism
New World Disorder
The Situation is So Intense, it Involves the Entire US Government | FBI Insider
Turkey Crisis
Global Settlements
The Interview The Global Elite Never Want You To Hear
BRICS / SCO / EAEU
Maritime Silk Road
Nuclear/Kinetic Warfare
HAARP / Manmade Disasters
Drugs & Trafficking
Intelligence/Espionage
US Militia
New World Disorder, Yemen Crisis
United States and France Jointly Responsible for Famine in Yemen
May 5, 2019 GeoPolitics101	4 Comments
A French military intelligence note dated September 2018 shows that Saudi Arabia is making extensive use of French armaments in its war against Yemen, specifically "Leclerc tanks, Archer artillery howitzers, Mirage 2000-9 fighter jets, Cobra radars, Aravis armoured vehicles, Cougar and Dauphin helicopters, Caesar cannons …».
The maps included in the classified military report were presented to President Emmanuel Macron on October 3, 2018 during a "restricted" Defence Council meeting in the French Presidential office.
The leaked document, released on March 15, 2019 by the investigative media outlet Disclose, complements the revelations already published on June 16, 2018 by the newspaper Le Figaro, which confirmed the presence of French special forces fighting alongside the Saudi Arabian army during the battle in the Yemeni city of Hodeida [also known as al-Hudayda].
Despite the disclosures, the French government continues to deny that French armaments and French special forces are involved in offensive operations against Yemen, insisting that they are only deployed in defensive positions on the Yemeni border.
In the United States, a bill sponsored by Democratic Senator Bernie Sanders prohibiting any form of US participation in the war against Yemen was passed by both the Senate, in March, and the House of Representatives, in April. Earlier this week, on April 17th, President Donald Trump vetoed the bill.
The strategy of the Israeli-Saudi Joint Chiefs of Staff, supported by the United States, France and the United Arab Emirates, now envisages seeking victory in Yemen by starving the population.
At least one third of the targets attacked by the warring coalition in Yemen are not military but civilian targets. At least 50,000 Yemeni children have already died as a result of the famine caused by the Saudi Arabian-led coalition attacks.
Translation: Artemis Pittas
Poland: Israel reveals its military hand in Yemen
The Ministerial Conference in Poland on Peace and Security in the Middle East addressed but one important issue and this issue was not on the agenda. At the conference, Israël publicly demonstrated that it had relations with Arab States – the representatives of these countries engaging in conversations inter se. This is remarkable because officially, there are no diplomatic relations between these states.
Israeli Prime Minister Benjamin Netanyahu exploited the US House of Representatives' vote against the war in Yemen to reveal its military hand in this conflict.
If the truth be known, right at the beginning of this war in Yemen, troops from Saudi Arabia, the Emirates and Israel took part. These three states set up a joint general staff in Somaliland. The latter is not recognized as a state and is controlled by Israel. This war had been the subject of several years of negotiation between Israel and Saudi Arabia. Its objective was to exploit the oil reserves in the "desert of Rub-Al Khali", the area straddling Saudi Arabia and Yemen. Further exploitation will take place through a joint project in the Horn of Africa.
For Israel, showing its hand in Yemen follows on from its public recognition of its incessant interventions in Syria. This amounts to a rewriting of History, for prior to the Israeli interventions, there were no Iranians – either in Syria or Yemen.
For the United States, this revelation is another step towards the establishment of a Judeo-Sunnite alliance against the Shiites, as announced by US Secretary of State, Mike Pompeo.
About sixty foreign delegates participated in this show and reacted as if comatosed. The Western Press has not deemed this conference to be newsworthy.
Translation : Anoosha Boralessa
Help bring down the criminal cabal by boycotting Big Pharma for good.
famine in yemenFranceSaudi Arabia
Previous PostChina-led New Silk Road is Taking Over the Global Economy with Fully Armed RussiaNext PostWithout Disinformation, NATO Would Crumble
4 thoughts on "United States and France Jointly Responsible for Famine in Yemen"
K. Chris C. says:
Soon another Jew, or maybe the same one, will come up with a charity "LiveAid-Yemen" to enable the extraction of even more wealth from us under the guise of "helping" the victims. Left out will be the fact that it's wealth stolen from us that created the victims in the first place.
For those that aren't Jew-wise, "charities" are one of the Jews' primary means of plundering while destroying.
"Ignorance is Strength." I'm weak.
drbhelthi says:
– for example, consider the "American Cancer Society", the salary of the administrator, the years in deceptive robbery, and the fact that NOT a SINGLE cancer cure has been either supported or published. Meanwhile, cancer is the only epidemic in the USA, having increased to one in five persons. Natural cures that actually function are suppressed by "Oncology". "Oncology" MDs, pimps for the pharmaca industry, continue to use chemo and radiation to massacre the cancer masses .
Shapiemau says:
And yet sooo many victims of these diseases believe in these charities/institutions and do NOT do their own research in finding the cures that have been written about and published but, kept quiet! I know many of them that will not consider reading info from any other sources.
I do not support charities full stop.
We need to wake up and look for the truth.
kennyboy says:
Lets SEE, now…France is ruled by a WHITE man…The Corporate United States is ruled by a WHITE man…BOTH "Incorporated" by the VATICAN???
Whatcha' Spose Ya Gunna Git?!
Its no secret WHITE Supremist has been attempting to rid the world of "People of Color" since they created the Vatican from Rome…They have been attempting to convince to planet that GOD is a WHITE man too.
AWAKEN!
We do appreciate sensible comments... Cancel reply
"Never underestimate the power of a few committed people to change the world. Indeed, it is the only thing that ever has."
~ Margaret Meade
Covert Hybrid WW3: Starving the Beast S01E03
13,749,871 views | Thank you for flying with us!
British Empire Perfidy Further Exposed, as Trump Steps Toward a New Paradigm with Russia, China
The Untold Story of Christian Zionism's Rise to Power in the United States
Fake Wars and Big Lies: The Muslim Brotherhood as Assassins
British Government Killed 10 Million Iranians in 1919
A Summer of Confrontation Looms in the South China Sea
The Taliban Have Won in Afghanistan
30 British Marines Seized Iranian Oil Tanker
Vladimir Putin Slams 'Obsolete Liberalism'
Trump Admin Dangles $50Bn Bribe for Palestinian Surrender
Russia-India-China Share A Room with A View
The Civil War Now in America
Troika of Evil: Monsters Walk the Earth
Declassified: The Sino-Russian Masterplan To End U.S. Dominance In Middle East
Trump's Pick to Lead Military is Staunch anti-Chinese WarHawk
Provoking Iran Could Start a War and Crash the Entire World Economy
Behold, the Cognitive Dissonance of the Media in One Graph
American Gov't, NGOs Fuel and Fund Hong Kong Anti-Extradition Protests
Archives Select Month July 2019 (11) June 2019 (25) May 2019 (31) April 2019 (24) March 2019 (34) February 2019 (24) January 2019 (14) December 2018 (26) November 2018 (24) October 2018 (23) September 2018 (22) August 2018 (21) July 2018 (21) June 2018 (12) May 2018 (9) April 2018 (24) March 2018 (19) February 2018 (16) January 2018 (9) December 2017 (14) November 2017 (8) October 2017 (26) September 2017 (39) August 2017 (48) July 2017 (29) June 2017 (54) May 2017 (46) April 2017 (38) March 2017 (48) February 2017 (38) January 2017 (55) December 2016 (47) November 2016 (27) October 2016 (29) September 2016 (31) August 2016 (19) July 2016 (29) June 2016 (34) May 2016 (34) April 2016 (32) March 2016 (32) February 2016 (36) January 2016 (36) December 2015 (63) November 2015 (50) October 2015 (41) September 2015 (49) August 2015 (38) July 2015 (69) June 2015 (74) May 2015 (100) April 2015 (74) March 2015 (101) February 2015 (74) January 2015 (89) December 2014 (65) November 2014 (95) October 2014 (76) September 2014 (70) August 2014 (76) July 2014 (40) June 2014 (22) May 2014 (31) April 2014 (24) March 2014 (37) February 2014 (17) January 2014 (19) December 2013 (11) November 2013 (10) October 2013 (17) September 2013 (23) August 2013 (9) July 2013 (16) June 2013 (18) May 2013 (11) April 2013 (20) March 2013 (9) February 2013 (13) January 2013 (21) December 2012 (11) November 2012 (7) October 2012 (14) September 2012 (5) August 2012 (19) July 2012 (22) June 2012 (18) May 2012 (12) April 2012 (23) March 2012 (20) February 2012 (8) January 2012 (6) December 2011 (16) November 2011 (2) October 2011 (7) September 2011 (4) August 2011 (2) July 2011 (4) June 2011 (10) May 2011 (8) April 2011 (12) March 2011 (7) February 2011 (2) January 2011 (1) December 2010 (4) December 2009 (1)
Dusty Rusty on Hidden History of the Incredib…
Romanov Romantik on Hidden History of the Incredib…
Jay Clark on Zionist UAE False Flag Fails,…
Willie Brown on The Taliban Have Won in Afghan…
kennyboy on Fake Wars and Big Lies: The Mu…
dcapit8 on Trump Admin Dangles $50Bn Brib…
mistryj7 on Fake Wars and Big Lies: The Mu…
Beyond the Smoke & Mirrors
Lost Land of Maharlika
Understand the Philippines, and You Understand the New Multipolar World Order
3,500 Ton Philippine Gold Bars Unlawfully Shipped Out, But for Whose Benefit?
US State Department Blueprint to Oust Duterte Leaked by A US Embassy Insider
Mayor Duterte is Not Genocidal, The West is. Here's the proof…
Why CIA Created the Abu Sayyaf in the Philippines
Philippine Decision 2016
Behold the Philippines Under U.S. Democracy for 113 Years!
Why U.S. Mercenaries are in the Philippines?
Why is China Reclaiming The Kalayaan Group of Islands?
What Was the U.S. Role in the Slaughter of 44 Filipino Special Ops Police?
U.S. Attacked Philippines with HAARP
Unacknowledged American Atrocities in the Philippines
The Last Senseless War
Pivot Away from Containment
Has Obama Lost Control Of the Philippines?
US Pays Out 'Peanuts' for Eco-Crime Committed in Philippines
Learn the Tricks of the Trade & Set Yourself Free
The Articles of Agreement that Should Boil Everyone's Blood
Governments are Corporations
Vatican: The Greatest Usurper
Bank for International Settlements (BIS) – The Vatican's Central Bank
Proof All of Your Debt is Prepaid!
The UCC Connection to Our Slavery & How to Access Our Strawman Account
How the Cabal Maintains Their Power & How to Defeat Them
The Corporation: History & Revolution
Khazarian Mafia History
The Khazarian Mafia 2.0
The Protocols of Zion is Derived from the Jewish Talmud, But never Semitic
Israel's Secretive Nuclear Facility Leaking as Watchdog Finds Israel Has Nearly 100 Nukes
Deep State Nazionists Establishing A Parallel State for Ratline 2.0
Corporate Power and Expansive U.S. Military Policy | Prof. Gaffney
Covert War Between Russia and Khazarian Jewry
DEEP STATE 2.0
The Top of the Pyramid
The Rothschilds are Jesuits
Powerful Bloodlines
Technocracy: A Scientific Dictatorship
From State Sponsored Terror to State Sponsored "Freedom"
Jade Helm: Mastering the Human Domain thru Artificial Intelligence
Social Engineering for Global Slavery
The True Purpose of U.N. Agenda 21 "Sustainable Development"
Chemtrail Pilot Blows the Lid Off OPERATION INDIGO SKYFOLD
Top 10 Ways They're Killing Us
The Foundation for The New World Economic Order
BRICS Latest Updates
Russia, China Offer Eurasian Emporium, the US – Sabre Rattling
BRICS Global Bank Will Open Coffers by Year-End, Coinciding Jesuits' Debt Jubilee
The Ultimate Geopolitical Game Changer Is Here
GeoPolitical and SocioEconomics Q1 Summary
Conquer fear & Live free!
Enjoy Healthcare Freedom Now!
Defeat the Cabal by Supporting this site
This is a self-funded site. But with your help, we can sustain the task of informing the world with reliable information and objective analyses, while your own family enjoys healthcare freedom that they deserve.
Find more about how we can help each other from our healthcare site. Or, you can be our next Patreon partner.
Bishop Accountability
International Tribunal into Crimes of Church and State
The Zeitgeist Movement
Pete Santilli Show
PressCore
Technocracy News
Executive Intelligence Review
Gerald Celente
Institute for the Study of Globalization and Covert Politics
Max Keiser
Eric Jon Phelps
Forbidden Archaeology
Illuminati Confessions
Michael Tsarion
Project Avalon
Cut Poison Burn
Dr Leonard G. Horowitz
Dr. Russel Blaylock
Dr. Tullio Simoncini
Jane Bürgermeister
Vaccine Resistance Movement
GMWatch
Active Stills
Internet & the Web
Norse Corp.

redpajama_set_name: RedPajamaCommonCrawl


Welcome to our website! We are the Will Geiseman family and we are excited to serve the Lord in full-time itinerant evangelism! It is our desire to minister to churches and camps through solid Biblical preaching as well as soul-stirring, conservative, gospel music. We want to increase Christ in every way possible, preaching His saving death to sinners and His saving life to saints. We believe Christ is the only hope for this lost world but also for believers to live a victorious, abundant Christian life.
Please take a look through our site to get a better feel for who we are and what we believe. If we could be of any help to your ministry, please feel free to contact us. We want to come alongside the local church and be a co-laborer together to evangelize the lost and equip the saints. Wherever you are at today, our prayer is that Christ would be increasing in your life!
He MUST Increase. . . . . . .


This past weekend the Yakama Nation celebrated the Treaty of 1855. So what that means is that we celebrated our tribal recognition. There were many events, from parades to softball tournaments. Even the annual rodeo. And of course the Pow Wow in White Swan. Being The somewhat traditional native that I am. I always enjoy sticking to my roots. Even took a few pics.


then decide a color scheme. initially i was going to do an ombre effect with the yellows, but because the kitchen is so outdated, this yellow clock would have dated it even more so I added blue washi tape.
keep repeating step 3 until you've wrapped the whole clock.
and you're done. hang it up and call it cute!
The tapes I used are from Target. I can't remember the brand, but they are not my faves. Some of the tape wasn't sticking well at first so I had to make sure to press it down firmly. Maybe a light sanding would help the tape grip a little better?


Our 3 Hour Intro to Sailing lesson will get you familiar with the Hobie Wave Catamaran. You will learn how to read the winds and handle the boat whether its just you or with your family and friends. Taught by certified instructors, we will get you sailing in no time. This course meets the requirements of the qualification test to rent a catamaran with Eastern Watersports. Must be 13 if alone and 9 with an adult taking the class.
Brush up on your skills or learn some advanced techniques.
Call to make an appointment, 443-730-0300.


text:
Mother sues Etsy after child is strangled to death by teething necklace
Updated: 12:05 PM EDT May 8, 2019
A California mother has filed a lawsuit against Etsy after her 18-month-old son was strangled by an item bought on the retail website.Deacon Morin was found unresponsive after being placed down for a nap Oct. 5 at Marriott Family Child Care in Fontana. He was rushed to a hospital, where he died five days later.Investigators say the boy was wearing a beaded necklace around his neck when he took the nap. CBS Los Angeles reports the necklace tightened and did not release, causing Deacon to suffocate. The teething necklace was given to his mother, Danielle Morin, as a gift by a close friend who purchased it on Etsy, a website that specializes in handmade items. According to the online receipt, the necklace is meant to help alleviate pain for teething babies and is supposed to have a releasing safety clasp that automatically releases when pulled on. "Baby necklaces, if you use a baby necklace should have a releasing safety clasp so if there's any pulling on it, it releases. This one that was purchased on Etsy had a screw on clasp that could not be released. And so when baby Deacon was hung up on something, it didn't release and caused him to suffocate," Morin's attorney, John Carpenter, said. Carpenter said the Etsy is legally responsible for Deacon's death and has filed a lawsuit against the website in addition to the Lithuanian company that provided the necklace.The terms of use listed on Etsy's website state, in part, "the items in our marketplaces are produced, listed, and sold directly by independent sellers so Etsy cannot and does not make any warranties about their quality, safety, or even their legality. Any legal claim related to an item you purchase must be brought directly against the seller of the item. You release Etsy from any claims related to items sold through our services." Carpenter says that Morin did not agree to these legal disclosures because she received the necklace as a gift."I want parents to know there is no more Toys R Us and people need to go online to buy products and these products are dangerous and these products aren't always safe. No parent should have to grieve a child. No parent should have to bury their child," Morin said. A statement from an Etsy spokesperson reads: "Deacon's death was a great tragedy and our hearts are with his mother and family. While we understand the desire to take action, Etsy is a platform and did not make or directly sell this item. We believe the allegations should be directed at the criminally-negligent daycare providers or, if appropriate, the seller of the necklace. The seller has not had any products on our website since last year and we do not represent the seller in any way."
FONTANA, Calif. —
A California mother has filed a lawsuit against Etsy after her 18-month-old son was strangled by an item bought on the retail website.
Deacon Morin was found unresponsive after being placed down for a nap Oct. 5 at Marriott Family Child Care in Fontana. He was rushed to a hospital, where he died five days later.
Cans of Pam cooking spray have been exploding, creating massive fireballs
Investigators say the boy was wearing a beaded necklace around his neck when he took the nap. CBS Los Angeles reports the necklace tightened and did not release, causing Deacon to suffocate.
The teething necklace was given to his mother, Danielle Morin, as a gift by a close friend who purchased it on Etsy, a website that specializes in handmade items.
According to the online receipt, the necklace is meant to help alleviate pain for teething babies and is supposed to have a releasing safety clasp that automatically releases when pulled on.
"Baby necklaces, if you use a baby necklace should have a releasing safety clasp so if there's any pulling on it, it releases. This one that was purchased on Etsy had a screw on clasp that could not be released. And so when baby Deacon was hung up on something, it didn't release and caused him to suffocate," Morin's attorney, John Carpenter, said.
Carpenter said the Etsy is legally responsible for Deacon's death and has filed a lawsuit against the website in addition to the Lithuanian company that provided the necklace.
The terms of use listed on Etsy's website state, in part, "the items in our marketplaces are produced, listed, and sold directly by independent sellers so Etsy cannot and does not make any warranties about their quality, safety, or even their legality. Any legal claim related to an item you purchase must be brought directly against the seller of the item. You release Etsy from any claims related to items sold through our services."
Carpenter says that Morin did not agree to these legal disclosures because she received the necklace as a gift.
"I want parents to know there is no more Toys R Us and people need to go online to buy products and these products are dangerous and these products aren't always safe. No parent should have to grieve a child. No parent should have to bury their child," Morin said.
A statement from an Etsy spokesperson reads: "Deacon's death was a great tragedy and our hearts are with his mother and family. While we understand the desire to take action, Etsy is a platform and did not make or directly sell this item. We believe the allegations should be directed at the criminally-negligent daycare providers or, if appropriate, the seller of the necklace. The seller has not had any products on our website since last year and we do not represent the seller in any way."


text:
\section{Introduction and main result}

Let $n \in \mathbb{N}$, $T>0$ and let $\Omega \subset \mathbb{R}^n$ be a
bounded domain with $C^2$-boundary $\partial\Omega$. Let $\Gamma_{0}$ be an
open subset of $\partial\Omega$.
Throughout this paper, for a functional $v = v(x,t)$ with $x\in\Omega,~t\in (0,T)$, we use the following notations :
\begin{eqnarray*}
&&\nabla v = \left(\frac {\partial v}{\partial x_1},\dots, \frac {\partial v}{\partial x_n}\right),
\quad D^2v=\left(\frac {\partial^2 v}{\partial x_i\partial x_j}\right)_{1\leq i,j\leq n},
\quad \Delta v = \sum_{i=1}^{n}\frac {\partial^2 v}{\partial x_i^2},
\quad \partial_t v= \frac {\partial v}{\partial t},\\
&&\nu\in\mathbb{R}^n~\tn{ denotes the unit outward normal vector to } \partial\Omega~\tn{ and }
\partial_\nu v = \frac {\partial v}{\partial \nu}=\nabla v\cdot \nu.
\end{eqnarray*}

We consider the wave equation :
\begin{equation}\label{WE}
	\left\lbrace\begin{array}{ll}
		\partial_t^2y(x,t)-\Delta y(x,t)+q(x)y(x,t)=g(x,t),&\quad x\in\Omega,~t\in (0,T),\\
		y(x,t)=h(x,t),&\quad x \in\partial\Omega,~t\in (0,T),\\
		y(x,0)=y^0(x),\quad \partial_t y(x,0)= y^1(x),&\quad x\in\Omega.
	\end{array} \right.
\end{equation}
First of all, assuming that $y^0\in L^2(\Omega)$, $y^1\in H^{-1}(\Omega)$, $p\in L^\infty(\Omega)$, $h \in L^2(\partial\Omega \times (0,T))$  and $g \in L^1(0,T;L^2(\Omega))$ are known, and assuming the compatibility condition $h(x,0) = y_0(x)$ for all $x\in\partial\Omega$, the Cauchy problem \eqref{WE} is well-posed and one can also prove (using a method by transposition, since we have non-homogeneous boundary conditions) that
$$u\in C([0,T],L^2(\Omega)) \cap C^1([0,T],H^{-1}(\Omega)).$$
This result can be read in \cite{LionsMagenesBook} for instance. One will also find a classical existence and regularity result when the boundary data $h$ is equal to $0$ in Lemma~\ref{Energy} (see also \cite{Lions}), useful in the inverse problem result.\\

This paper treats at the same time two kinds of inverse problems which can be stated as follows.

\textbf{Non linear inverse Problem :}
Is it possible to retrieve the potential $q=q(x),~x\in\Omega~$ from measurement
of the  normal derivative $\left.\partial_\nu y\right|_{\Gamma_{0} \times (0,T)}$
where $y$ is the solution to (\ref{WE}), $\Gamma_0$ is a part large enough of the boundary $\partial\Omega$ and the observation time $T$ is also large enough ?\\

We will actually give local answer to this question. If we denote by $y[p]$ the weak solution of equation~\eqref{WE}, assuming that $p\in L^\infty(\Omega)$ is a given potential, we are concerned with the stability around $p$. That is to say $p$ and $y[p]$ are known while $q$ is unknown and we prove the following local lipschitz stability result.
In this direction, we will answer to two more precise problems.\\

\noindent\textbf{Uniqueness} :
Under geometrical conditions on $\Gamma_{0}$ and $T$, does the equality
$\partial_\nu y[q]=\partial_\nu  y[p]$ on $\Gamma_{0} \times(0,T)$
imply $q=p$ on $\Omega$ ?\\

\noindent\textbf{Stability} :
Under geometrical conditions on $\Gamma_{0}$ and $T$, is it possible to estimate $\|q-p\|_{L^2(\Omega)}$
or better, a stronger norm of $(p-q)$, by a suitable norm of
$\partial_\nu y[q]-\partial_\nu  y[p]$ on $\Gamma_{0}\times (0,T)$ ?\\

We will actually work on a linearized version of the inverse problem and consider the following wave equation :

\begin{equation}\label{WE2}
	\left\lbrace\begin{array}{ll}
		\partial_t^2u(x,t)-\Delta u(x,t)+q(x)u(x,t)=f(x)R(x,t),&\quad x\in\Omega,~t\in (0,T),\\
		u(x,t)=0,&\quad x \in\partial\Omega,~t\in (0,T),\\
		u(x,0)=0, \quad \partial_t u(x,0)= 0,&\quad x\in\Omega.
	\end{array} \right.
\end{equation}

\textbf{Linear inverse problem :}
Is it possible to determine $f(x),~x\in\Omega~$ from the knowledge of the normal derivative
$\left.\partial_\nu u\right|_{\Gamma_{0} \times(0,T)} $
where $R$ and $q$ are given and $u$ is the solution to (\ref{WE2})?\\

These questions for the wave equation have all already received positive answers
since the uniqueness result for the linear inverse problem has been proved by M.V. \textsc{Klibanov} in \cite{Klibanov92}
and Lipschitz stability results (for both linear and non-linear inverse problems) of M. \textsc{Yamamoto}, deriving from it, can be read in \cite{Yam99}.
The proof in \cite{Yam99} is based on a local Carleman estimate for the wave operator and a compactness-uniqueness argument in order to conclude to the stability from the uniqueness result and an observability estimate.
We aim in our document at giving a direct proof of a Lipschitz stability estimate from a global Carleman estimate, result also interesting by itself. Another gain of this new proof of the precise result given below is the weakened assumptions on the solution of the wave equation under study. Besides, from the Carleman estimate we prove in the sequel, we directly obtain that a measurement of the flux of the solution on a suitable part $\Gamma_0$ of the boundary  (instead of the whole boundary $\partial\Omega$) is sufficient.\\

To precisely state the results we will prove in this article, we introduce, for $m \geq 0$, the set
$$
	L^\infty_{\leq m} (\Omega) = \{q \in L^\infty(\Omega), \ s.t. \, \|q\|_{L^\infty(\Omega)} \leq m \}.
$$
Moreover, we also specify the geometrical assumption:
\begin{gather}
\exists x_{0}\not\in\Omega\quad \tn{such that} \quad \Gamma_{0}\supset \{x\in\partial\Omega ; (x-x_{0})\cdot \nu(x)\geq 0\}
\label{GCC}\\
T> \sup_{x\in \Omega} |x-x_0|
\label{GCCT}
\end{gather}

\begin{theo}\label{TWE}
Let $m>0$, $K>0$ and $r>0$. Let $p$ belong to  $L^\infty_{\leq m}(\Omega)$.
Assume that the solution $y[p]$ of equation \eqref{WE} is such that
\begin{equation}
\label{RegCond}
	\|y[p]\|_{H^1 (0,T;L^{\infty}(\Omega))} \leq K
\end{equation}
and assume also that the initial datum $y^0$ satisfies
\begin{equation}
	\label{InitialDataCond}
	 \inf \left\{|y^0(x)|,x\in (\Omega)\right\} \geq r.
\end{equation}
Under the hypothesis that $\Gamma_0$ satisfies the geometrical condition \eqref{GCC} and $T$ satisfies \eqref{GCCT},
then for all $q \in L^\infty_{\leq m}(\Omega)$,
$ \partial_\nu y[q]-\partial_\nu y[p]$ belongs to $H^1(0,T;L^2(\Gamma_0)) $
and there exists a constant $C = C(m,T,K,r)>0$ such that for any $q \in L^\infty_{\leq m} (\Omega)$,
\begin{equation}
	\label{ReverseEst}
	\left\|\dfrac{\partial y[q]}{\partial\nu}-\dfrac{\partial y[p]}{\partial\nu}\right\|_{H^1(0,T;L^2(\Gamma_0))}
	\leq C \|p-q\|_{L^2(\Omega)},
\end{equation}
\begin{equation}
	\label{StabilityContinuous}
	\|q-p\|_{L^2(\Omega)}\leq C\left\|\dfrac{\partial y[q]}{\partial\nu}-\dfrac{\partial y[p]}{\partial\nu}\right\|_{H^1(0,T;L^2(\Gamma_0))} .
\end{equation}
\end{theo}
Estimate \eqref{StabilityContinuous} is the Lispchtiz stability of the inverse problem while \eqref{ReverseEst} gives the continuous dependance of the derivative of the solution with respect to the potential.
\begin{rem}\label{RemReg}
	The condition $y[p] \in H^1 (0,T;L^{\infty}(\Omega))$ can be guaranteed uniformly for $p \in L^\infty_{\leq m} (\Omega)$ with more constraints on the data $(y^0, y^1), \ g,\ h$ in \eqref{WE}. Indeed, if we assume $(y^0,y^1)  \in   H^2(\Omega) \times H^1(\Omega)$,
$g  \in  W^{1,1}(0,T;L^2(\Omega))$ and $h \in H^2(0,T;H^2(\Omega))$, with the compatibility conditions $h(x,0) = y^0(x)$ and $\partial_t h(x,0) = y^1(x)$ for all $x\in\partial\Omega$ then
 $\partial_t y[p]$ solution of \eqref{WE} belongs to the space $C^0([0,T]; H^1(\Omega))\cap C^1([0,T]; L^2(\Omega))$, with estimates depending only on $m$ and the norms of $(y^0, y^1),\, g, \, h$ in these spaces. Therefore, due to Sobolev's imbedding, $\partial_t y[p] \in L^2 (0,T;L^{\infty}(\Omega))$.
 \end{rem}

\begin{rem}\label{RemReg}
	The condition on $y^0$ requires compatibility conditions for $y^0$ and $h$ on $\partial\Omega\times \{0\}$. In particular,
$|h(x,0)|\geq r> 0,~x\in\partial\Omega$ must be satisfied since $|y^0(x)|\geq r> 0,~ae$ in $\overline{\Omega}$.
 \end{rem}

The method of proof of Theorem \ref{TWE} is based on a global Carleman estimate and is very close to the approach of \cite{ImYamCom01}, that concerns the wave equation with Neumann boundary condition and Dirichlet observation for the inverse problem of retrieving a potential. Actually, it also closely follows the approach of \cite{Yam99} but this work requires less regularity conditions on $y$.

The use of Carleman estimate to prove uniqueness in inverse problems was introduced in \cite{BuKli81} by A. L. Bukhgeim and M. V. Klibanov.  Concerning inverse problems for hyperbolic equations with a single observation, we can refer to  \cite{PuelYam96}, \cite{PuelYam97}, where the method relies on uniqueness results obtained by local Carleman estimates  (see e.g. \cite{Im02}, \cite{Isakov}) and compactness-uniqueness arguments based on observability inequalities (see also \cite{Zhang00}). Related references \cite{ImYamCom01} and \cite{ImYamIP01} also use  Carleman estimates, but rather consider the case of interior or Dirichlet boundary data observation.

\section{Classical Global Carleman Estimate}
In this section, we are interested in proving a global Carleman estimate for the wave operator. One can find (local) Carleman estimates for regular functions with compact support in \cite{Carleman}, \cite{HormanderLPDE} and in \cite{Yam99}.\\

Let us define the usual wave operator $L$ by
$$
	Lv = \partial_t^2 v - \Delta v
$$
We consider a function $v\in L^2(-T,T;H^1_0(\Omega))$ such that $Lv \in L^2(-T,T;L^2(\Omega))$,
and  satisfying $v(\pm T) = 0$, $\partial_t v(\pm T) = 0$ on $\Omega$.

Let us now define, for $x_{0} \not\in\Omega$, $\lambda>0$ and $\beta \in (0,1)$, and
for all $(x,t) \in \Omega \times (-T,T)$:
\begin{equation}\label{weights}
	\psi(x,t) = |x-x_0|^2-\beta t^2+C_0 \quad \text{ and } \quad
	\varphi(x,t) = e^{\lambda \psi(x,t)}
\end{equation}

where $C_0>0$ is chosen so that $\psi\geq 1$ on $\Omega\times(-T,T)$. We also set, for $s>0$,
$$
	w(x,t)=v(x,t)e^{s\varphi(x,t)}.
$$
We define the operator $L_p$ for $p\in L^\infty_{\leq m} (\Omega)$ by
$$
L_pv = \partial_t^2 v - \Delta v + pv
$$
that satisfies $L_pv \in L^2(-T,T;L^2(\Omega))$ if $Lv \in L^2(-T,T;L^2(\Omega))$.\\

Let us first introduce the Carleman estimate we will prove by the formal calculation of
$$
	Pw = e^{s\varphi}L(e^{-s\varphi} w).
$$
We have easily
\begin{eqnarray*}
Pw &=& \partial_t^2 w-2s\lambda\varphi (\partial_t w\partial_t \psi -\nabla w.\nabla\psi)+s^2\lambda^2\varphi^2w(|\partial_t \psi|^2-|\nabla\psi|^2)
-\Delta w\\
&&- s \lambda\varphi w(\partial_t^2 \psi - \Delta \psi )-s\lambda^2 \varphi w(|\partial_t \psi|^2-|\nabla\psi|^2)
\end{eqnarray*}
and if we set
\begin{equation}\label{P}
	\begin{aligned}
	P_{1}w&=\partial_t^2 w-\Delta w+s^2\lambda^2\varphi^2w(|\partial_t \psi|^2-|\nabla\psi|^2)\\
	P_{2}w&=(\alpha - 1)s \lambda\varphi w(\partial_t^2 \psi - \Delta \psi )
		-s\lambda^2 \varphi w(|\partial_t \psi|^2-|\nabla\psi|^2)
		-2s\lambda\varphi (\partial_t w\partial_t \psi -\nabla w.\nabla\psi)\\
	Rw&=-\alpha s \lambda\varphi w(\partial_t^2 \psi - \Delta \psi )
	\end{aligned}
\end{equation}
with $\alpha$ chosen later  such that
$ \frac {2\beta}{\beta+n} < \alpha < \frac {2}{\beta+n}$ (see \eqref{encadrement}),
we get $$P_{1}w+P_{2}w=Pw-Rw.$$

Let us now give a global (meaning ``up to the boundary'') Carleman inequality, following Imanuvilov's method \cite{Im02}.
One can read other versions of global Carleman estimates for hyperbolic equations in \cite{Zhang00} and \cite{Tataru96}.

\begin{theo}\label{CarlemanLucie}
Let us suppose that there exists $x_{0} \not\in\Omega$ such that
$$
\Gamma_{0}\supset \{x\in\partial\Omega ; (x-x_{0})\cdot\nu(x)\geq 0\}
$$
Then for every $m>0$, there exists $\lambda_{0}>0$, $s_{0}>0$
and a constant $M=M(s_{0},\lambda_{0},T,m,\Omega,\beta,x_{0})$
such that for all $p\in L^\infty_{\leq m} (\Omega)$, and for all $\lambda>\lambda_{0}$, $s>s_{0}$:
\begin{gather}
	s\lambda \int_{-T}^{T} \int_{\Omega} e^{2s\varphi}(|\partial_t v|^2 + |\nabla v |^2)\,dxdt
	+ s^3\lambda^3\int_{-T}^{T} \int_{\Omega} e^{2s\varphi}|v|^2\,dxdt\nonumber\\
	+ \int_{-T}^{T} \int_{\Omega} |P_1 (e^{s\varphi}v)|^2 \,dxdt + \int_{-T}^{T} \int_{\Omega} |P_2( e^{s\varphi}v)|^2\,dxdt\label{CarlemClas}\\
	\leq M\int_{-T}^{T} \int_{\Omega} e^{2s\varphi}| L_pv|^2\,dxdt
	+ Ms\lambda \int_{-T}^{T} \int_{\Gamma_{0}} \varphi e^{2s\varphi} \left|\partial_\nu v\right|^2\,d\sigma dt.\nonumber
\end{gather}
for all $v\in H^1(-T,T;H^1_0(\Omega))$ satisfying
$$
	\left\lbrace\begin{array}{l}
		Lv \in L^2(\Omega\times (-T,T)),\\
		v(x,\pm T) = \partial_tv(x,\pm T)=0,~\forall x\in\Omega
	\end{array}\right.
$$
\end{theo}
We do not give here extensive references about Carleman estimates for hyperbolic equations, but one can have a look at \cite{Im02} and find references therein.
\begin{rem}
Estimate \eqref{CarlemClas} is uniform in $p$ when $p$ is in a bounded subset of $L^\infty_{\leq m}(\Omega)$.
Moreover, this Carleman estimate is proved for any arbitrary time $T$.
\end{rem}

\noindent {\bf Proof.}

We will first prove estimate \eqref{CarlemClas} with $Lv$ in the right hand side instead of $L_p v$. One will see at the end that the result hold as well for $L_p$ since $p\in L^\infty(\Omega\times(-T,T))$.\\

As we began to write, for $w = e^{s\varphi} v$ we have $Pw = e^{s\varphi}Lv$ and
\begin{gather}
	\int_{-T}^{T} \int_{\Omega}\left(| P_{1}w| ^2 + | P_{2}w| ^2\right)\,dxdt
	+~2\int_{-T}^{T} \int_{\Omega}P_{1}wP_{2}w\,dxdt \nonumber\\
	= \int_{-T}^{T} \int_{\Omega}| Pw-Rw|^2\,dxdt\label{PP}
\end{gather}
\bigskip
We will calculate and obtain a lower bound for
$$
	\int_{-T}^{T} \int_{\Omega}P_{1}wP_{2}w\,dxdt.
$$

The main goal of the proof will be indeed to minimize this cross-term by positive and dominant terms looking similar to the one of the left hand side of \eqref{CarlemClas} and negative boundary terms that will be moved to the right hand side of the estimate. In the sake of clarity, we will devide the proof in several steps.\\

\noindent {\textbf{Step 1. Explicit calculations}

We set $\ds\left\langle P_1w,P_2w\right\rangle_{L^2(\Omega\times(-T,T))}=\sum_{i,k=0}^n I_{i,k}$ where $I_{i,k}$ is the integral of the product of the $i$th-term in $P_1w$ and the $k$th-term in $P_2w$.
We mainly use integrations by parts and the properties of $w$ such as $w(\pm T) = 0$, $\partial_tw(\pm T) = 0$ in $\Omega$ and $w=0$ on $\partial\Omega\times (-T,T)$.\\

 Integrations by part in time give easily, since $\partial_t\Delta \psi = 0$,
\begin{eqnarray*}
	I_{11}&=&\int_{-T}^{T} \int_{\Omega}\partial_t^2 w((\alpha - 1)s \lambda\varphi w(\partial_t^2 \psi - \Delta \psi ))\,dxdt\\
	&=&(1-\alpha )s\lambda \int_{-T}^{T} \int_{\Omega} \varphi  | \partial_t w | ^2 (\partial_t^2 \psi - \Delta \psi ) \,dxdt\\
	&&- \dfrac {(1-\alpha )}2 s\lambda^2 \int_{-T}^{T} \int_{\Omega} \varphi | w | ^2 \partial_t^2 \psi 	(\partial_t^2 \psi - \Delta \psi ) \,dxdt\\
	&&- \dfrac {(1-\alpha )}2 s\lambda^3 \int_{-T}^{T} \int_{\Omega} \varphi | w | ^2  |\partial_t \psi|^2(\partial_t^2 \psi - \Delta \psi ) \,dxdt.
\end{eqnarray*}
In the same manner, since $\partial_t \nabla \psi = \bf 0$, one has
\begin{eqnarray*}
	I_{12}&=&\int_{-T}^{T} \int_{\Omega}\partial_t^2 w(-s\lambda^2 \varphi w(|\partial_t \psi|^2-|\nabla\psi|^2))\,dxdt\\
	&=&s \lambda ^2 \int_{-T}^{T} \int_{\Omega} \varphi |\partial_t w|^2(|\partial_t \psi|^2-|\nabla\psi|^2)\,dxdt
	-s\lambda^2 \int_{-T}^{T} \int_{\Omega} \varphi  |w|^2 |\partial_t^2 \psi|^2\,dxdt\\
	&&-(2+\dfrac 12)s\lambda^3 \int_{-T}^{T} \int_{\Omega} \varphi |w|^2 |\partial_t \psi|^2\partial_t^2 \psi\,dxdt
	+\dfrac {s\lambda^3}2 \int_{-T}^{T} \int_{\Omega} \varphi |w|^2 |\nabla\psi|^2\partial_t^2 \psi\,dxdt\\
	&&-\dfrac {s\lambda^4}2 \int_{-T}^{T} \int_{\Omega} \varphi  |w|^2 |\partial_t \psi|^2 (|\partial_t \psi|^2-|\nabla\psi|^2)\,dxdt
\end{eqnarray*}
and using also integrations by part in space variable, we get
\begin{eqnarray*}
	I_{13}&=&\int_{-T}^{T} \int_{\Omega}\partial_t^2 w(-2s\lambda\varphi (\partial_t w\partial_t \psi -\nabla w.\nabla\psi))\,dxdt\\
	&=& s\lambda \int_{-T}^{T} \int_{\Omega} \varphi | \partial_t w | ^2 \partial_t^2 \psi \,dxdt
	+s\lambda^2 \int_{-T}^{T} \int_{\Omega} \varphi | \partial_t w | ^2 |\partial_t \psi|^2 \,dxdt\\
	&&+ s\lambda \int_{-T}^{T} \int_{\Omega} \varphi | \partial_t w | ^2 \Delta \psi  \,dxdt
	+ s\lambda^2 \int_{-T}^{T} \int_{\Omega} \varphi | \partial_t w | ^2  |\nabla\psi|^2 \,dxdt\\
	&&-2s\lambda^2 \int_{-T}^{T} \int_{\Omega} \varphi \partial_t w\, \partial_t \psi \nabla w.\nabla\psi \,dxdt.
\end{eqnarray*}

We compute in the same way
\begin{eqnarray*}
	I_{21}&=&\int_{-T}^{T} \int_{\Omega}-\Delta w ((\alpha - 1)s \lambda\varphi w(\partial_t^2 \psi - \Delta \psi ))\,dxdt\\
	&=& -(1-\alpha ) s \lambda \int_{-T}^{T} \int_{\Omega} \varphi |\nabla w|^2 (\partial_t^2 \psi - \Delta \psi ) \,dxdt\\
	&&+ \dfrac {(1-\alpha )}2 s \lambda^2 \int_{-T}^{T} \int_{\Omega} \varphi |w|^2 \Delta \psi (\partial_t^2 \psi - \Delta \psi )\,dxdt\\
	&&+ \dfrac {(1-\alpha )}2 s \lambda^3 \int_{-T}^{T} \int_{\Omega} \varphi |w|^2  |\nabla\psi|^2 (\partial_t^2 \psi - \Delta \psi )\,dxdt
\end{eqnarray*}
and
\begin{eqnarray*}
	I_{22}&=&\int_{-T}^{T} \int_{\Omega}-\Delta w(-s\lambda^2\varphi w(|\partial_t \psi|^2-|\nabla\psi|^2))\,dxdt\\
	&=&-s \lambda^2 \int_{-T}^{T} \int_{\Omega} \varphi |\nabla w|^2(|\partial_t \psi|^2-|\nabla\psi|^2) \,dxdt\\
	&&-\dfrac{s \lambda^2}2 \int_{-T}^{T} \int_{\Omega} \varphi |w|^2 \Delta(|\nabla \psi|^2) \,dxdt\\
	&&+\dfrac {s \lambda^3}2 \int_{-T}^{T} \int_{\Omega} \varphi  |w|^2\Delta \psi (|\partial_t \psi|^2-|\nabla\psi|^2)\,dxdt\\
	&&+\dfrac {s \lambda^4}2 \int_{-T}^{T} \int_{\Omega} \varphi  |w|^2 |\nabla\psi|^2(|\partial_t \psi|^2-|\nabla\psi|^2)\,dxdt\\
	&&-s \lambda^3\int_{-T}^{T} \int_{\Omega} \varphi |w|^2 \nabla\psi \cdot \nabla(|\nabla\psi|^2) \,dxdt
\end{eqnarray*}
Using the fact that $w|_{\partial\Omega\times (-T,T)}=0$, we have, on $\partial\Omega\times (-T,T)$, $\nabla w = (\partial_\nu w) \nu$ that give $|w|^2 = |\partial_\nu w|^2$. Therefore, we obtain
\begin{eqnarray*}
	I_{23}&=&\int_{-T}^{T} \int_{\Omega}-\Delta w(-2s\lambda\varphi (\partial_t w\partial_t \psi -\nabla w \cdot \nabla\psi))\,dxdt\\
	&=& s\lambda \int_{-T}^{T} \int_{\Omega} \varphi |\nabla w|^2 (\partial_t^2 \psi - \Delta \psi )\,dxdt
	+2s\lambda^2 \int_{-T}^{T} \int_{\Omega} \varphi | \nabla \psi\cdot\nabla w |^2 \,dxdt\\
	&&-2s\lambda^2 \int_{-T}^{T} \int_{\Omega} \varphi\partial_t w\, \partial_t \psi \nabla w\cdot\nabla\psi \,dxdt
	+s\lambda^2 \int_{-T}^{T} \int_{\Omega} \varphi | \nabla w |^2  (|\partial_t \psi|^2-|\nabla\psi|^2) \,dxdt\\
	&&- s\lambda \int_{-T}^{T} \int_{\partial\Omega} \varphi | \partial_\nu w|^2 \nabla \psi \cdot \nu \,d\sigma dt
	+2s\lambda \int_{-T}^{T} \int_{\Omega} \varphi  D^2 \psi |\nabla w|^2\,dxdt
\end{eqnarray*}
since $D^2 \psi$ is symmetric.

One easily write
\begin{eqnarray*}
	I_{31}&=&\int_{-T}^{T} \int_{\Omega}  s^2\lambda^2\varphi^2w(|\partial_t \psi|^2-|\nabla\psi|^2)
	((\alpha - 1)s \lambda\varphi w(\partial_t^2 \psi - \Delta \psi ))\,dxdt\\
	&=&(\alpha -1) s^3\lambda^3 \int_{-T}^{T} \int_{\Omega} \varphi^3 |w|^2(\partial_t^2 \psi - \Delta \psi ) (|\partial_t \psi|^2-|\nabla\psi|^2)\,dxdt
\end{eqnarray*}
and
\begin{eqnarray*}
	I_{32}&=&\int_{-T}^{T} \int_{\Omega}   s^2\lambda^2\varphi^2w(|\partial_t \psi|^2-|\nabla\psi|^2)
	(-s\lambda^2 \varphi w(|\partial_t \psi|^2-|\nabla\psi|^2))\,dxdt\\
	&=&-s^3\lambda^4 \int_{-T}^{T} \int_{\Omega}\varphi^3  |w|^2 (|\partial_t \psi|^2-|\nabla\psi|^2)^2\,dxdt.
\end{eqnarray*}
Finally, some integrations by part enable to obtain, since $\nabla(|\partial_t \psi|^2) = \bf 0$,
\begin{eqnarray*}
	I_{33}&=&\int_{-T}^{T} \int_{\Omega}  s^2\lambda^2\varphi^2w(|\partial_t \psi|^2-|\nabla\psi|^2)
	(-2s\lambda  \varphi (\partial_t w \partial_t \psi -\nabla w.\nabla\psi)) \,dxdt\\
	&=&s^3\lambda ^3 \int_{-T}^{T} \int_{\Omega}\varphi^3 |w|^2 (\partial_t^2 \psi - \Delta \psi ) (|\partial_t \psi|^2-|\nabla\psi|^2) \,dxdt\\
	&&+s^3\lambda ^3 \int_{-T}^{T} \int_{\Omega}\varphi^3  |w^2|
		(2\partial_t^2 \psi|\partial_t \psi|^2 + \nabla\psi \cdot \nabla(|\nabla\psi|^2))\,dxdt\\
	&&+3s^3\lambda^4 \int_{-T}^{T} \int_{\Omega}\varphi^3  |w|^2  (|\partial_t \psi|^2-|\nabla\psi|^2)^2\,dxdt.
\end{eqnarray*}

Gathering all the terms that have been computed, we get
\begin{equation}\label{P1P2}
	\begin{aligned}
	\int_{-T}^{T} \int_{\Omega} P_{1}&wP_{2}w\,dxdt\\
	=& ~2s\lambda \int_{-T}^{T} \int_{\Omega} \varphi | \partial_t w | ^2 \partial_t^2 \psi \,dxdt
	- \alpha s\lambda \int_{-T}^{T} \int_{\Omega} \varphi | \partial_t w | ^2 (\partial_t^2 \psi - \Delta \psi ) \,dxdt\\
	&+~2s\lambda^2 \int_{-T}^{T} \int_{\Omega}\varphi \left( | \partial_t w | ^2 |\partial_t \psi|^2
	-2\partial_t w\, \partial_t \psi  \nabla w\cdot \nabla\psi + | \nabla \phi\cdot\nabla w |^2 \right) \,dxdt\\
	&+~2s\lambda \int_{-T}^{T} \int_{\Omega} \varphi  D^2 \psi |\nabla w|^2\,dxdt
	+\alpha s \lambda \int_{-T}^{T} \int_{\Omega} \varphi |\nabla w|^2 (\partial_t^2 \psi - \Delta \psi ) \,dxdt\\
	&-~s\lambda \int_{-T}^{T} \int_{\partial\Omega}\varphi \left| \partial_\nu w\right |^2 \nabla\psi\cdot\nu(x)\,d\sigma dt\\
	&+~2s^3\lambda^4 \int_{-T}^{T} \int_{\Omega} \varphi^3 |w|^2 (|\partial_t \psi|^2-|\nabla\psi|^2)^2\,dxdt\\
	&+~s^3\lambda ^3 \int_{-T}^{T} \int_{\Omega}\varphi^3  |w^2|
		(2\partial_t^2 \psi|\partial_t \psi|^2 + \nabla\psi \cdot \nabla(|\nabla\psi|^2) )\,dxdt\\
	&+~\alpha s^3\lambda^3 \int_{-T}^{T} \int_{\Omega}\varphi^3  |w|^2
		(\partial_t^2 \psi - \Delta \psi ) (|\partial_t \psi|^2-|\nabla\psi|^2)\,dxdt\\
	&+~ X_1
	\end{aligned}
\end{equation}
where $X_1$ satisfies, using the regularity of $\psi$ and the fact that  $\psi \geq 1$ implies $\lambda \leq e^{\lambda \psi} = \varphi$,
\begin{equation}\label{X1}
|X_1| \leq M s\lambda^3 \int_{-T}^{T} \int_{\Omega} \varphi^3 |w|^2  \,dxdt .
\end{equation}
Here and in the sequel, $M>0$ corresponds to a generic constant depending at least on $\Omega$ and $T$ but independant of $s$ and $\lambda$.\\

\noindent {\textbf{Step 2. Bounding each term from below}

On the one hand, one can notice that
\begin{multline}\label{00}
	2s\lambda^2 \int_{-T}^{T} \int_{\Omega}\varphi \left( | \partial_t w | ^2 |\partial_t \psi|^2
		-2\partial_t w \partial_t \psi  \nabla w \cdot \nabla\psi + | \nabla \psi\cdot\nabla w |^2 \right)\,dxdt\\
	=2s\lambda^2 \int_{-T}^{T} \int_{\Omega}\varphi \left( \partial_t w \partial_t \psi- \nabla w \cdot \nabla\psi\right)^2 \,dxdt \geq 0.
\end{multline}
Besides, considering the terms in $s\lambda$ that must now give the dominant terms in $| \partial_t w|^2 $ and $|\nabla w|^2$
and thus have to be strictly positive, one can guess that we need
$$
	2 \partial_t^2 \psi -\alpha (\partial_t^2 \psi - \Delta\psi) > 0 \quad \tn{ and } \quad
	2D^2\psi +\alpha  (\partial_t^2 \psi - \Delta \psi ) > 0.
$$
This will constrain the value of the unspecified constant $\alpha>0$ in the definition \eqref{P} of $P_2 w$.
We get, by explicit computations, that $\beta \in (0,1)$, and $\alpha$ must satisfy
\begin{equation}\label{encadrement}
	 \dfrac{2\beta}{\beta +n} < \alpha <  \dfrac{2}{\beta +n}.
\end{equation}
As a direct consequence, we can write
\begin{multline}
	\label{ordre1}
	2 s\lambda \int_{-T}^{T} \int_{\Omega} \varphi | \partial_t w|^2\partial_t^2 \psi \,dxdt
	-\alpha s\lambda \int_{-T}^{T} \int_{\Omega} \varphi | \partial_t w|^2(\partial_t^2 \psi - \Delta\psi) \,dxdt\\
	+2s\lambda \int_{-T}^{T} \int_{\Omega} \varphi D^2\psi |\nabla w|^2 \,dxdt
	+\alpha s \lambda \int_{-T}^{T} \int_{\Omega} \varphi |\nabla w|^2 (\partial_t^2 \psi - \Delta \psi ) \,dxdt\\
	\geq M s\lambda \int_{-T}^{T} \int_{\Omega} \varphi | \partial_t w|^2\,dxdt
	+ M s\lambda \int_{-T}^{T} \int_{\Omega} \varphi | \nabla w|^2 \,dxdt.
\end{multline}

On the other hand, we can observe that:
\begin{eqnarray*}
	&&2s^3\lambda^4 \int_{-T}^{T} \int_{\Omega}\varphi^3 |w|^2  (|\partial_t \psi|^2-|\nabla\psi|^2)^2\,dxdt\\
	&&+~s^3\lambda ^3 \int_{-T}^{T} \int_{\Omega}\varphi^3 |w^2|
		(2\partial_t^2 \psi|\partial_t \psi|^2 + \nabla\psi \cdot \nabla(|\nabla\psi|^2) )\,dxdt\\
	&&+~\alpha s^3\lambda^3 \int_{-T}^{T} \int_{\Omega}\varphi^3 |w|^2(\partial_t^2 \psi - \Delta \psi )
		 (|\partial_t \psi|^2-|\nabla\psi|^2)\,dxdt\\
	&=& s^3\lambda ^3 \int_{-T}^{T} \int_{\Omega}\varphi^3 |w^2|  F_{\lambda}(\phi) \,dxdt
\end{eqnarray*}
where
\begin{align*}
	F_{\lambda}(\phi)&=
	2\lambda(|\partial_t \psi|^2-|\nabla\psi|^2)^2 +  (2\partial_t^2 \psi|\partial_t \psi|^2 + \nabla\psi \cdot \nabla(|\nabla\psi|^2) )
		+ \alpha (\partial_t^2 \psi - \Delta \psi ) (|\partial_t \psi|^2-|\nabla\psi|^2)\\
	&= 32 \lambda (\beta^2t^2 - |x-x_0|^2)^2 - 16(\beta^3t^2 - |x-x_0|^2) -8 \alpha(\beta + n)(\beta^2t^2 - |x-x_0|^2)\\
	&= 32 \lambda (\beta^2t^2 - |x-x_0|^2)^2 - 8(\alpha(\beta + n) +2\beta) (\beta^2t^2 - |x-x_0|^2) +16(1-\beta)|x-x_0|^2.
\end{align*}
Since $x_0\not\in\Omega$, we have $16(1-\beta)|x-x_0|^2\geq c_*>0$.
Therefore, we are considering a polynome $P(X) \geq 32\lambda X^2 - 8\left( \alpha (\beta +n) + 2 \beta \right) X+c_*$ and taking $\lambda>0$ large enough, the minimum of $P$ will be strictly positive.
Consequently,
\begin{equation}
	\label{ordre0}
	s^3\lambda ^3 \int_{-T}^{T} \int_{\Omega} \varphi^3|w^2| F_{\lambda}(\phi) \,dxdt\\
	\geq M s^3\lambda^3 \int_{-T}^{T} \int_{\Omega} \varphi^3 | w|^2\,dxdt.
\end{equation}\\

Thus, plugging \eqref{00}, \eqref{ordre1} and \eqref{ordre0} in \eqref{P1P2}, we  obtain
\begin{multline*}
	\int_{-T}^{T} \int_{\Omega}P_{1}wP_{2}w\,dxdt
	+ 2 s \lambda\int_{-T}^{T} 	\int_{\partial\Omega}\varphi \left| \partial_\nu w\right|^2 (x-x_0)\cdot\nu(x)\,d\sigma dt - X_1\\
	\geq M s\lambda \int_{-T}^{T} \int_{\Omega} \varphi\left(| \partial_t w| ^2+|\nabla w|^2\right)\,dxdt
		+ M s^3\lambda ^3\int_{-T}^{T} \int_{\Omega}\varphi^3 | w| ^2\,dxdt.
\end{multline*}
Since we also have
\begin{multline*}
	\int_{-T}^{T} \int_{\Omega}| Pw-Rw|^2\,dxdt
		\leq 2\int_{-T}^{T} \int_{\Omega}| Pw|^2\,dxdt
		+2\int_{-T}^{T} \int_{\Omega}| Rw|^2\,dxdt\\
	\leq M\int_{-T}^{T} \int_{\Omega}| Pw|^2\,dxdt
	+Ms^2 \lambda^2\int_{-T}^{T} \int_{\Omega} \varphi^2 |w|^2 \,dxdt,
\end{multline*}
using \eqref{PP} and \eqref{X1}, we get
\begin{gather*}
	s\lambda \int_{-T}^{T} \int_{\Omega}\left(| \partial_t w| ^2+|\nabla w|^2\right) \varphi\,dxdt
		+ s^3\lambda ^3\int_{-T}^{T} \int_{\Omega} | w| ^2\varphi^3\,dxdt\\
	+\int_{-T}^{T} \int_{\Omega}\left(| P_{1}w| ^2 + | P_{2}w| ^2\right)\,dxdt\\
	\leq M\int_{-T}^{T} \int_{\Omega}| Pw|^2\,dxdt
		+M s \lambda\int_{-T}^{T} \int_{\partial\Omega}\varphi \left| \partial_\nu w\right|^2
			(x-x_0)\cdot\nu(x)\,d\sigma dt \\
	+~M s\lambda ^3\int_{-T}^{T} \int_{\Omega}\varphi^3 | w| ^2\,dxdt  + Ms^2 \lambda^2\int_{-T}^{T} \int_{\Omega} \varphi^2 |w|^2 \,dxdt.
\end{gather*}
We take now $s_0$ large enough so that the terms of the last line (coming from  $X_1$ and $| Rw|^2$) are absorbed by the dominant term in $s^3\lambda^3  |w|^2\varphi^3$ as soon as $s>s_0$. Using also the condition \eqref{GCC} on $\Gamma_0$, we finally obtain for some positive constant $M=M(s_{0},\lambda_{0},m,\Omega,\beta,x_{0})$,
\begin{gather}
	s\lambda\int_{-T}^{T} \int_{\Omega} \varphi(| \partial_t w|^2+|\nabla w|^2)\,dxdt
	+ s^3\lambda ^3\int_{-T}^{T} \int_{\Omega} \varphi^3 |w|^2\,dxdt\nonumber\\
	+\int_{-T}^{T} \int_{\Omega}|P_1 w|^2\,dxdt+\int_{-T}^{T} \int_{\Omega}|P_2 w|^2\,dxdt\label{CarlemW}\\
	\leq M\int_{-T}^{T} \int_{\Omega}| Pw|^2\,dxdt
	+Ms\lambda \int_{-T}^{T} \int_{\Gamma_0}  \varphi\left|\partial_\nu w\right|^2\,d\sigma dt \nonumber
\end{gather}
$\forall s>s_0$, $\forall \lambda > \lambda_0$.\\

\noindent {\textbf{Step 3. Return to the variable $v$}

Using that $w=ve^{s\varphi}$
gives for all $x\in \Omega$ and $t\in(-T,T)$
\begin{eqnarray*}
	&&e^{2s\varphi}|\partial_t v|^2 \leq 2|\partial_t w|^2+2s^2|\partial_t\varphi|^2|w|^2,\\
	&&e^{2s\varphi}|\nabla v|^2 \leq 2|\nabla w|^2+2s^2|\nabla\varphi|^2|w|^2,\\
	&&e^{2s\varphi}\left|\partial_\nu v\right|^2= \left|\partial_\nu w\right|^2 \tn{ on }\partial\Omega
\end{eqnarray*}
and that by construction $P w = e^{s\varphi} Lv$,
we can go back to the variable $v$ in \eqref{CarlemW} and obtain that there exists some positive constant $M=M(s_{0},\lambda_{0},m,\Omega,\beta,x_{0})$ such that for all $ s>s_0$ and $ \lambda > \lambda_0$,
\begin{gather}
	s\lambda \int_{-T}^{T} \int_{\Omega} e^{2s\varphi}(|\partial_t v|^2 + |\nabla v |^2)\,dxdt
	+ s^3\lambda^3\int_{-T}^{T} \int_{\Omega} e^{2s\varphi}|v|^2\,dxdt\nonumber \\
	+ \int_{-T}^{T} \int_{\Omega} |P_1 (e^{s\varphi} v)|^2 \,dxdt + \int_{-T}^{T} \int_{\Omega} |P_2 (e^{s\varphi} v)|^2\,dxdt \label{CarlemL}\\
	\leq M\int_{-T}^{T} \int_{\Omega} e^{2s\varphi}| Lv|^2\,dxdt
	+ Ms\lambda \int_{-T}^{T} \int_{\Gamma_0} \varphi e^{2s\varphi} \left|\partial_\nu v \right|^2 \,d\sigma dt. \nonumber
\end{gather}
It concludes the proof of a Carleman estimate for the operator $L=\partial_t^2 - \Delta$.\\

\noindent {\textbf{Step 4. Wave operator with potential}

The Carleman estimate \eqref{CarlemClas} for the operator $L_p=\partial_t^2 - \Delta + p$ with $p\in L^\infty_{\leq m} (\Omega)$ is a direct consequence of \eqref{CarlemL} noticing that on $\Omega\times(-T,T)$,
$$
	|Lv|^2 \leq 2 |L_pv|^2 + 2 \|p\|_{L^\infty_{\leq m} (\Omega)}|v|^2
	\leq 2 |L_pv|^2 + 2 m |v|^2.
$$
Indeed, choosing $s_0$ (or $\lambda_0$) large enough, one can absorb the term
$$
	2M m\int_{-T}^{T} \int_{\Omega} e^{2s\varphi}|v|^2\,dxdt
$$
in the left hand side of \eqref{CarlemL} and obtain \eqref{CarlemClas} with slightly different constants.
This ends the proof of Theorem~\ref{CarlemanLucie}.

\section{Stability of the inverse problem}

Before giving the proof of Theorem~\ref{TWE}, we will begin this section by a stability theorem for the linear inverse source problem stated after equation~\eqref{WE2}. The following answer is obtained using the global Carleman estimate given above.
\begin{theo}\label{Thm2}
Let $m>0$, $K>0$ and $r>0$. Let $q$ belong to  $L^\infty_{\leq m}(\Omega)$.
Assume that $f\in L^2(\Omega)$ and $R\in H^1(0,T;L^{\infty}(\Omega))$ with
$$|| R||_{H^1 (0,T;L^{\infty}(\Omega))} \leq K $$
and
\begin{equation} \label{RR}
\inf_{x\in\Omega} |R(x,0)| \geq r.
\end{equation}
Under the hypothesis that $\Gamma_0$  and $T$ satisfy the geometrical conditions
$$
\exists x_{0}\not\in\Omega\quad \textit{such that} \quad \Gamma_{0}\supset \{x\in\partial\Omega ; (x-x_{0})\cdot \nu(x)\geq 0\}
\quad \textit{and }\quad T> \sup_{x\in \Omega} |x-x_0|
$$
if $u[f]$ is the solution of equation~\eqref{WE2}:
$$
	\left\lbrace\begin{array}{ll}
		\partial_t^2u(x,t)-\Delta u(x,t)+q(x)u(x,t)=f(x)R(x,t),&\quad x\in\Omega,~t\in (0,T)\\
		u(x,t)=0,&\quad x \in\partial\Omega,~t\in (0,T)\\
		u(x,0)=0,~\partial_t u(x,0)= 0,&\quad x\in\Omega,
	\end{array} \right.
$$
then there exists a constant $C=C(T,\Omega,\Gamma_0,K,r)>0$ such that for all $f \in L^2(\Omega)$ :
\begin{equation}\label{stablin}
C^{-1}|| f||_{L^2(\Omega)}\leq   \left\|\dfrac{ \partial u[f]}{\partial\nu} \right\|_{H^1(0,T;L^2(\Gamma_0))} \leq C || f||_{L^2(\Omega)} .
\end{equation}
\end{theo}

\noindent {\bf Proof.}
We will apply the Carleman estimate given by \eqref{CarlemL} to $w=\chi \partial_t y$ where $\chi$ is a cutoff function to be detailed later. We divide the proof in several steps.\\

\noindent {\textbf{Step 1.} }
Let us first work on the equation satisfied by $z=\partial_t u$:
\begin{equation}\label{WE3}
	\left\lbrace\begin{array}{ll}
		\partial_t^2z(x,t)-\Delta z(x,t)+q(x)z(x,t)=f(x)\partial_t R(x,t),&\quad x\in\Omega,~t\in (0,T)\\
		z(x,t)=0,&\quad x \in\partial\Omega,~t\in (0,T)\\
		z(x,0)=0,\quad \partial_t z(x,0)= f(x) R(x,0),&\quad x\in\Omega.
	\end{array} \right.
\end{equation}
We gather in the following lemma the classical energy and trace estimates we will need in the sequel.
\begin{lemme}\label{Energy}
Assume that $p\in L_{\leq m}^{\infty}(\Omega)$, $g \in L^1(0,T;L^2(\Omega))$, $u^0\in H_0^1(\Omega)$ and $u^1\in L^2(\Omega)$
and consider the classical wave equation
\begin{equation}\label{e}
	\left\lbrace\begin{array}{ll}
		\partial_t^2v(x,t)-\Delta v(x,t)+q(x)v(x,t)=g(x,t),&\quad x\in\Omega,~t\in (0,T)\\
		v(x,t)=0,&\quad x \in\partial\Omega,~t\in (0,T)\\
		v(x,0)=v_0(x),\quad \partial_t v(x,0)= v_1(x)),&\quad x\in\Omega.
	\end{array} \right.
\end{equation}
The Cauchy problem is well-posed and equation \eqref{e} admits a unique weak solution
$$
	v\in C([0,T],H_0^1(\Omega)) \cap C^1([0,T],L^2(\Omega))
$$
and  there exists a constant
$C=C(\Omega,T,m)>0$ such that for all $t\in(0,T)$, the energy
$E_v(t) = ||\partial_t v(t)||^2_{L^2(\Omega)}+||\nabla v(t)||^2_{L^2(\Omega)}$ of the system satisfies
\begin{equation}\label{estimeenergy}
	E_v(t) \leq C\left(||v_0||^2_{H_0^1(\Omega)} + ||v_1||^2_{L^2(\Omega)} +
		||g||^2_{L^1(0,T,L^2(\Omega))} \right).
\end{equation}
Moreover, the normal derivative $\partial_\nu v$ belongs to $ L^2(0,T;L^2(\partial\Omega)) $ and satisfies
\begin{equation}\label{hiddenregularity}
	\left\|\dfrac{ \partial v}{\partial\nu} \right\|_{L^2(0,T;L^2(\partial\Omega))}\leq C \left(||v_0||^2_{H_0^1(\Omega)}
		+ ||v_1||^2_{L^2(\Omega)} + ||g||^2_{L^1(0,T,L^2(\Omega))} \right).
\end{equation}
\end{lemme}

This result is very classical and we  refer to \cite{LionsMagenesBook} (Chapter 3) for the proof of the existence and uniqueness of solution to equation~\eqref{e}. Estimate \eqref{estimeenergy} can formally be deduced from multiplication of \eqref{e} by $v_t$, and the integration of this equality on $(0,T)\times \Omega$, using some integrations by parts. Concerning estimate~\eqref{hiddenregularity}, we refer to \cite{Lions} (Chapter 1). This estimate is a hidden regularity result which can be obtained by multipliers technique. \\

We can apply this lemma to equation \eqref{WE3} since $f\in L^2(\Omega)$ and $R\in H^1(0,T;L^{\infty}(\Omega))$.
We denote the energy of the system by
$$
	E_z (t) = ||z(t)||^2_{H^1_0(\Omega)} + ||\partial_t z(t)||^2_{L^2(\Omega)}
$$
and we get
$
	z \in C([0,T],H_0^1(\Omega)) \cap C^1([0,T],L^2(\Omega))
$ with, for all $t \in (0,T)$:
\begin{eqnarray}
	E_z (t) &\leq& C E_z(0) + C \| f\partial_t R \|^2_{L^1(0,T;L^2(\Omega))} \nonumber\\
	&\leq& C||f||^2_{L^2(\Omega)}\left( ||R(0)||^2_{L^{\infty}(\Omega)} + ||R||^2_{H^1(0,T;L^{\infty}(\Omega))}\right),\label{energy}
\end{eqnarray}
and
$
\partial_\nu z \in L^2(0,T;L^2(\partial\Omega))
$ with
$$
	\left\|\dfrac{ \partial z}{\partial\nu} \right\|_{L^2(0,T;L^2(\partial\Omega))}
	\leq C ||f||^2_{L^2(\Omega)}\left( ||R(0)||^2_{L^{\infty}(\Omega)} + ||R||^2_{H^1(0,T;L^{\infty}(\Omega))}\right).
$$
This last estimate gives at the end $\partial_\nu u \in H^1(0,T;L^2(\partial\Omega))$
and proves the right hand side of the two sided estimate~\eqref{stablin}. It thus gives a meaning to the measurement of the flux of the solution $u[f]$ we make in our inverse problem. \\

\noindent {\textbf{Step 2.}} Let us now extend the problem \eqref{WE3} on $(-T,T)$ in an even way, setting $z(x,t)=z(x,-t)$ for all $(x,t)\in\Omega\times(-T,0)$. We also extend $\partial_t R$ on an even way and keep the same notations for the new problem. Therefore, we have
$$z\in C([-T,T],H_0^1(\Omega)) \cap C^1([-T,T],L^2(\Omega))\tn{ and }\partial_t R \in L^2(-T,T;L^{\infty}(\Omega)).$$

The goal we have in mind is to apply the Carleman estimate to a solution of the wave equation in order to be able to estimate a weighted norm of $f$ by
a weighted norm of the measurement $\partial_\nu u$. The solution $z$ could be a good candidate but is not equal to zero at time $\pm T$. This motivates the use of a cutoff function in time, that is calibrated to work well with the Carleman weight function $\psi$.

We recall that for $\beta \in (0,1)$, $\psi$ and $\varphi$ are defined by \eqref{weights}.
Since $T$ satisfies \eqref{GCCT}, one can choose $\beta$ such that $\beta T^2 >  \sup_{x\in \Omega} |x-x_0|^2$ so that for all $x\in\Omega$,
$\psi(x,\pm T)=|x-x_0|^2-\beta T^2 +C_0 < C_0$.
We then choose $\eta > 0$ such that
$$
	\psi(x,t) \leq C_0,~\quad \forall (x,t)\in\Omega\times[-T,-T+\eta] \cup [T-\eta,T].
$$
Besides, one observes that
$$
\psi(x,0)=|x-x_0|^2+C_0 > C_0,~ \quad\forall x\in\Omega.
$$
Therefore, for all $(x,t)\in\Omega\times[-T,-T+\eta] \cup [T-\eta,T]$,
\begin{equation}\label{psi}
	\varphi(x,t) \leq e^{\lambda C_0}< e^{\lambda \psi(x,0)}=\varphi(x,0)
\end{equation}
but we also have, for all $(x,t)\in\Omega\times[-T,T]$,
\begin{equation}\label{psi2}
	\varphi(x,t) \leq \varphi(x,0).
\end{equation}

Using the parameter $\eta$ introduced here, we define the cut-off function $\chi\in C^{\infty}(\mathbb{R};[0,1])$ such that
\begin{equation}\label{chi}
\left\lbrace
\begin{array}{ll}
\chi(\pm T) = \chi ' (\pm T) = 0&\\
\chi(t) =1&\forall t\in [-T+\eta,T-\eta]
\end{array} \right.
\end{equation}
and  we set $~v=\chi z~$ that satisfies the following equation:
\begin{equation}\label{WE4}
	\left\lbrace\begin{array}{ll}
		\partial_t^2v-\Delta v+qv= \chi f\partial_t R+ \chi''z+ 2 \chi' \partial_{t}z,&\quad \Omega\times(0,T)\\
		v(x,t)=0,&\quad x \in\partial\Omega,~t\in (0,T)\\
		v(x,0)=0,\quad \partial_t v(x,0)= f(x) R(x,0),&\quad x\in\Omega.
	\end{array} \right.
\end{equation}

Henceforth, $M>0$ will correspond to a generic constant depending on $s_0, \lambda_0,T,\Omega$, $\Gamma_0$, $\beta$, $\chi$, $r$, $K$, and $\eta$  but independent of $s>s_0$.\\

\noindent {\textbf{Step 3.} }
We use now the same notations as in the proof of the Carleman estimate. For $v$ solution of \eqref{WE4}, we set
$$w=e^{s\varphi} v~,~~P_{1}w=\partial_t^2 w-\Delta w+s^2\lambda^2\varphi^2w(|\partial_t \psi|^2-|\nabla\psi|^2),$$
and we then have for all $x\in \Omega$,
$w(x,\pm T)  =  \partial_t w(x,\pm T) = 0 $ and $ w(x,0)  =  0$ and
for all $(x,t)\in \partial\Omega\times(-T,T)$, $w(x,t) = 0$.

Inspired from an idea of O. Yu. Imanuvilov and M. Yamamoto \cite{ImYamCom01}, we consider the integral
$$\int_{-T}^0\int_{\Omega}P_1w(x,t)\,\partial_t w(x,t) \,dxdt.$$
On the one hand, using the properties of $w$, we can make the following calculation:
\begin{eqnarray*}
	&&\int_{-T}^0\int_{\Omega}P_1w\,\partial_t w \,dxdt\\
	& = &\int_{-T}^0\int_{\Omega} \left(\partial_t^2 w-\Delta w+s^2\lambda^2\varphi^2w(|\partial_t \psi|^2-|\nabla\psi|^2)\right)\partial_t w  \,dxdt\\
	& = & \dfrac 12 \int_{\Omega} |\partial_t w(0)|^2 \,dx
		- \dfrac {s^2\lambda^2}2  \int_{-T}^0\int_{\Omega} |w|^2 \partial_t \left(\varphi^2(|\partial_t \psi|^2-|\nabla\psi|^2)\right) \,dxdt\\
	& = & \dfrac 12 \int_{\Omega} |\partial_t w(0)|^2 \,dx
		 - 2 s^2\lambda^2  \int_{-T}^0\int_{\Omega}  |w|^2 \partial_t \left(\varphi^2(\beta^2 t^2-|x-x_0|^2)\right)\,dxdt\\
	& = & \dfrac 12\int_{\Omega} e^{2s\varphi(0)}|fR(0)|^2\,dx
		+ 8 s^2\lambda^3  \int_{-T}^0\int_{\Omega}  |w|^2\varphi^2 \beta t(\beta^2 t^2-|x-x_0|^2) \,dxdt\\
	& &- ~4 s^2\lambda^2  \int_{-T}^0\int_{\Omega}
|w|^2\varphi^2\beta^2 t.
\end{eqnarray*}
On the other hand, from this equality and a Cauchy-Schwarz estimate,
\begin{eqnarray}
	 \int_{\Omega} e^{2s\varphi(0)}|fR(0)|^2 \,dx
	& = &2 \int_{-T}^0\int_{\Omega}P_1w\, \partial_t w \,dxdt
		+ 8 s^2\lambda^2  \int_{-T}^0\int_{\Omega}  w^2\varphi^2\beta^2 t\,dxdt \nonumber\\
	&&- 16 s^2\lambda^3  \int_{-T}^0\int_{\Omega}  |w|^2\varphi^2 \beta t(\beta^2 t^2-|x-x_0|^2) \,dxdt \nonumber\\
	&\leq& 2 \left(\int_{-T}^0\int_\Omega\left| P_1w\right|^2\,dxdt \right)^{\frac 12}
		\left(\int_{-T}^0\int_ \Omega |\partial_t w|^2 \,dxdt\right)^{\frac 12} \nonumber\\
	&&+ M s^2\lambda^3 \int_{-T}^0\int_ \Omega  |w|^2\varphi^2 \left|\beta t(\beta^2 t^2-|x-x_0|^2)\right| \,dxdt\label{rhsw}.
\end{eqnarray}
Using now the `intermediate'' Carleman estimate~\eqref{CarlemW}  for a fixed $\lambda>\lambda_0$ not mentioned anymore, choosing $s$ large enough to absorb the last term in the right hand side \eqref{rhsw}, we obtain
\begin{eqnarray}
	&&\int_{\Omega}  e^{2s\varphi(0)}|fR(0)|^2 \,dx \nonumber\\
	&\leq& \dfrac 2{\sqrt s} \left(\int_{-T}^0\int_\Omega\left| P_1w\right|^2\,dxdt \right)^{\frac 12}
		\left(s\int_{-T}^0\int_ \Omega |\partial_t w|^2 \,dxdt\right)^{\frac 12}
		+ M s^2\lambda^3 \int_{-T}^T\int_\Omega |w|^2\varphi^2 \,dxdt \nonumber\\
&\leq& \dfrac M{\sqrt s}\left( \int_{-T}^T\int_{\Omega} |Pw|^2 \,dxdt
+ s\int_{-T}^T\int_{\Gamma_0} \varphi |\partial_\nu w |^2d\sigma dt\right)\nonumber\\
&\leq& \dfrac M{\sqrt s}\left( \int_{-T}^T\int_{\Omega} e^{2s\varphi}|Lv|^2 \,dxdt
+ s \int_{-T}^T\int_{\Gamma_0}  e^{2s\varphi}|\partial_\nu v|^2d\sigma dt\right)\label{estim}
\end{eqnarray}
the weight function $\varphi$ being bounded from above and below.\\

From equation \eqref{WE4} and the properties \eqref{chi} of the cut-off function~$\chi$ and that of the weight $\varphi$ given in \eqref{psi} and \eqref{psi2}, one gets that
\begin{eqnarray*}
&&\int_{-T}^T\int_{\Omega}  e^{2s\varphi }|L v |^2\,dxdt \\
& \leq & M \int_{-T}^T\int_{\Omega}  e^{2s\varphi }|\chi f  \partial_t R |^2\,dxdt
+ M  \int_{-T}^T\int_{\Omega}  e^{2s\varphi }\left(|\chi' \partial_t z |^2 + |\chi'' z  |^2\right)\,dxdt\\
& \leq & M \int_{-T}^T\int_{\Omega}  e^{2s\varphi }|f |^2 |\partial_t R |^2\,dxdt
+ M  \left( \int_{-T}^{-T+\eta} + \int_{T-\eta}^T \right)\int_{\Omega}  e^{2s\varphi }\left(|\partial_t z|^2 + |z| ^2\right)\,dxdt\\
& \leq & M \int_{-T}^T\int_{\Omega}  e^{2s\varphi (0)}|f |^2 |\partial_t R |^2\,dxdt
+ M  \left( \int_{-T}^{-T+\eta} + \int_{T-\eta}^T \right)\int_{\Omega}  e^{2se^{\lambda C_0}}\left(|\partial_t z|^2 + |z| ^2\right)\,dxdt\\
& \leq & M \|\partial_t R\|_{L^2(-T,T;L^\infty(\Omega))} \int_{\Omega}  e^{2s\varphi (0)}|f |^2 \,dx\\
&&\qquad+~ M e^{2se^{\lambda C_0}} \left( \int_{-T}^{-T+\eta} + \int_{T-\eta}^T \right)\int_{\Omega}  \left(|\partial_t z|^2 + |z| ^2\right)\,dxdt.
\end{eqnarray*}
Using the energy estimate given in \eqref{energy}, and again the property \eqref{psi} of the weight $\varphi$, one gets
\begin{eqnarray*}
\int_{-T}^T\int_{\Omega} e^{2s\varphi}|Lv|^2\,dxdt
& \leq & M  \int_{\Omega} e^{2s\varphi(0)}|f|^2 \,dx
+ M e^{2se^{\lambda C_0}} \left( \int_{-T}^{-T+\eta} + \int_{T-\eta}^T \right) E_z(t) dt\\
& \leq & M   \int_{\Omega} e^{2s\varphi(0)}|f|^2 \,dx\\
&&+ M \eta  \left( ||R(0)||^2_{L^{\infty}(\Omega)} + ||R||^2_{H^1(0,T;L^{\infty}(\Omega))}\right) e^{2se^{\lambda C_0}}  \int_{\Omega} |f|^2 \,dx\\
& \leq &  M   \int_{\Omega} e^{2s\varphi(0)}|f|^2 \,dx.
\end{eqnarray*}
Gathering this last estimate with \eqref{estim}, we have proved
$$ \int_{\Omega}  e^{2s\varphi(0)}|fR(0)|^2 \,dx
 \leq \dfrac M{\sqrt{s}} \int_{\Omega} e^{2s\varphi(0)}|f|^2 \,dx
+ M\sqrt{s} \int_{-T}^T\int_{\Gamma_0} e^{2s\varphi}|\partial_\nu v|^2\,d\sigma dt.$$
Therefore, the assumption \eqref{RR} made on $R$ allow to obtain
$$ \int_{\Omega}  e^{2s\varphi(0)}|f|^2 \,dx\\
 \leq \dfrac M{\sqrt{s}}  \int_{\Omega}e^{2s\varphi(0)}|f|^2 \,dx
+ M\sqrt{s} \int_{-T}^T\int_{\Gamma_0} e^{2s\varphi}|\partial_\nu v|^2\,d\sigma dt,$$
and the choice of $s$ large enough gives
\begin{eqnarray*}
\int_{\Omega}  e^{2s\varphi(0)}|f|^2 \,dx
 &\leq &M\sqrt{s}  \int_{-T}^T\int_{\Gamma_0} e^{2s\varphi}|\partial_\nu v|^2\,d\sigma dt\\
 &\leq &M\sqrt{s}  \int_{-T}^T\int_{\Gamma_0} e^{2s\varphi}|\partial_\nu(\partial_t u)|^2\,d\sigma dt.
 \end{eqnarray*}
The proof of Theorem~\ref{Thm2} is then complete.
\endproof

\noindent{\bf Acknowledgements.} The author acknowledges Jean-Pierre Puel for this work accomplished together under is supervision during the masters degree in 2001. It has a been an important step toward the study of an inverse problem for the Schr\"odinger equation in the author's PhD and was also more recently strongly used in several works.\\

\bibliographystyle{plain}

redpajama_set_name: RedPajamaArXiv


1787. At Sidaire also there was a very numerous audience. Here a lad named Wm. Keys, who had been converted during the recent revival in this neighbourhood, accompanied his mother to the service, and at its close the venerable evangelist laid his hands on the boy's head and solemnly prayed that the blessing of the Triune Jehovah might rest upon him. Deeply impressed, the youth began to work for Christ, and eventually entered the itinerancy.
1832. In some instances this awful visitation proved a means of much spiritual good. From his first circuit the Rev. Benjamin Bayly writes, "On July 28th I came to Monaghan, where cholera had made its appearance and summoned some to the bar of God. The people were greatly alarmed, and like others, 'poured out a prayer when His chastening hand was upon them.' Yet some have reason to bless God that He sent them the rod; many have been stirred up, and some have been converted. Our congregations are large and our societies many in number, but there are rarely more than twenty members in any one class.'' , Hundreds leapt to the Saviour, and at one service no less than sixty found the pardoning mercy of God.
1849. The Revs. William G. Campbell and Edward Best were appointed to the Irvinestown circuit, where their labours were greatly owned of God. In August a large field-meeting was held, at Mr Robert Graham's of Lettermoney, and was followed by a prayer-meeting, during which eight persons professed to have obtained a conscious sense of sins forgiven. The good work thus commenced soon spread. Service after service was held, at almost every one of which the Lord was present in converting power, more especially at the September love-feasts. At Irvinestown one of the converts was a man who had become a socialist in England, returned home, obtained admission to the meeting, and as so powerfully impressed that he cried aloud for mercy. The whole congregation was deeply moved, and earnest prayers for pardon were heard from different parts of the house, until not less than twenty contrite souls obtained peace in believing. During the December quarter the ministers preached in the open air, at fairs and markets, and it was not uncommon to see hundreds kneeling down in penitence of spirit. Thus the blessed work extended still more, including Ballinamallard and Sidaire and the whole moral and religious aspect of the country was changed. One of the Converts, an aged pensioner, in narrating his experience, said, "My father taught me the fear of the Lord, and I remember several of the old preachers who counselled me and gave me Scripture lessons, but I did not attend to them. During my foreign service I had no less than eighteen fevers and ten other diseases incident to foreign climates, and conscience frequently strove to vindicate its insulted rights, but I had no strength to carry out my convictions. Although I would promise, and vow, and pray, yet when the pressure of affliction was removed I was the same man over again. I was in several engagements, and often at the point of death. On one occasion, as I rushed into the breach of a besieged city, an officer hastened forward and said, 'Noble, allow me first,' and that instant his head was cut off. After all this I persevered in my rebellion against God, and thought when I should leave the army I would turn to Him; but alas! it was worse and worse I became until this night, and now I can declare to all that God has found me out, and pardoned all my sins."
Location unknown. The testimony below mentions a revival in the neighbourhood.


Roxley Game Laboratory has given Martin Wallace's Brass (2007) a beautiful makeover and is offering this popular gem, now known as Brass: Lancashire, along with a new sequel, Brass: Birmingham, on Kickstarter. Brass is well known as one of the best economic strategy games, consistently ranking in the top 25 games on Boardgamegeek. This new edition sports fantastic new artwork, high quality components, and new improved rules for lower player counts. The sequel, Brass: Birmingham, takes place during the Canal Era, has a dynamic board setup, new industries, actions and mechanics.
The Kickstarter Campaign for Brass continues through May 11, and is expected to deliver in January 2018.
An announcement was made by Ralph Anderson, on BoardGameGeek forums, stating that the dispute over Brass rights (between designer Martin Wallace and publishing company Eagle Gryphon Games) is over and that Wallace now owns rights for said game.
The dispute largely became public after Wallace posted, on his Treefrog Games website, the matter of the dispute over who held rights. After "too many to count" threads on BGG initiated by users and even the parties involved, came to light the dispute seemed to be centered around the belief that Wallace believed said rights had been transferred back to him due to breach of contract issues while EGG believed no breach had been made and they were legal owners of the Brass rights. Each side was quite vocal in their views.
Those that are fans of the game will be happy to know that Brass was recently released on iOS and is available for download and play here.
Originally published in 1973 and designed by Pat Reid, the man who lived through the events of the game, and writer Brian Degas, the writer who made a TV series about Pat, Escape from Colditz is a roll and move style game with some card drafting where you are either a prisoner trying to escape, or a guard trying to keep them in. Escape from Colditz is often touted as the greatest board game in British history and so when Osprey Games had the opportunity to publish it, they jumped at the chance. Now, 75 years after the events of the game, Osprey is going to release the 75th anniversary edition with a whole new look illustrated by Peter Dennis, who illustrated Brass and A Few Acres of Snow, and additional wooden bits that are replicas of artifacts from Brian's collection about Pat. The planned release date is October 2016 so we have a ways to go, hopefully they will let us in on the process as they go along. For now, here is the press release from Osprey Games.
Coming in October 2016, Osprey Games will be releasing the 75th Anniversary Edition of Escape From Colditz! Designed by Pat Reid, a British officer who escaped from the Colditz prisoner-of-war camp during World War II, and Brian Degas, writer of the iconic TV series based on Pat's escape, it is often named as one of the greatest board games in British history.
This edition, published to coincide with the 75th anniversary of Pat Reid's escape, will feature completely new artwork painted by fan-favourite historical artist, Peter Dennis. Along with a complete set of wooden pieces, the box will include replicas of prisoner-of-war artefacts from Mr. Degas' extensive collection!
One of my main goals since joining Osprey Games was to bring this game back into print. It's not just an iconic piece of game design, but an important touchstone in the history of British games and toys. I've been working closely with the original designer, Brian Degas, to ensure that this is the definitive edition of the game.
Osprey Publishing has been creating highly illustrated military history books for four decades. The chance to bring all of that expertise to bear on one of the best-loved and most-respected military-themed board games is too good an opportunity to miss.
As of August 25th, Treefrog Games made an announcement on their website that they will cease their publishing of games. But don't fret if you like their style games, they fully intend to continue designing games but they will be using other companies to have them published. The reasons for this change are many, but the main one they give is the cost of operating the company from New Zealand. This means that their newest game, A Handful of Stars, will be the last game published under the Treefrog name and will hopefully be released in the first half of 2016. Also, a new kickstarter edition of Brass will be published, but not by Treefrog, so they are in negotiations currently to see who we be publishing it.


We are your creative marketing partners.
Covering the length and breadth of the UK, Glow Creative is a full service digital marketing & design agency committed to creating inspiring marketing solutions. We love what we do & you'll see that for yourself when you meet us.
We work as part of your team - as your outsourced marketing department, we are comfortable working with you in the long term & we are equally as happy to deliver a one off project. No matter how you choose to work with us, your project will be our priority. Every client we have is our most important client & we make sure you feel that way. We care about you, your brand, your work, your deadlines.
Whether you have an open mind & need us to deliver the ideas, or you have specific goals in mind, such as gaining more website traffic, expanding into a new market or increasing client engagement, you are in the right place. We are a multi-disciplinary marketing agency ready & waiting to contribute to your business.
Working with Glow Creative has been a very positive experience. We see them as part of our team and an asset rather than a financial outlay. I would like to say thank you to Glow for their hard work and positive attitude.
We are delighted to be located in the beautiful, historical City of Durham.


B M F Industries Classic Musta is a business in Barre, MA.
B M F Industries Classic Musta classified under , with principal employer Dave Richards Full Name Report is located in 843 Worcester Road, Barre, Massachusetts MA 01005. For sales, support, account inquiries, and how to be an affiliate, the best way to get in touch is through numbers: (701) 733-2396 Full Phone Report.
It has been operating since , boasting total quality assurance, and an annual revenue of $100.000 to $499.999. Their Single Location can be reached with the use of the following coordinates: 42.391459,-72.081584. They currently have 1 to 4 employees, and you can learn more about their offerings at .
You can also view their clients' testimonials, government compliance and annual reports through their website. B M F Industries Classic Musta aims to strengthen their BOTH relationships through advertisements and brand promotion.
Registered codes from Standard Industrial Classification is 2035, and 311941 from North American Industrial Classification System. Customer feedback is highly appreciated; be sure to leave your comments on their website through survey forms. These are necessary for company service improvements.