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Emojimania: Fans and brands crying tears of joy
Leanne Italie
NEW YORK — When it comes to emojis, the future is very, very … Face with Tears of Joy.
If you don't know what that means then you: a) aren't a 14-year-old girl. b) love to hate those tiny pictures that people text you all the time. Or c) are nowhere near a smartphone or online chat.
Otherwise, here in 2016, it's all emojis, all the time. And Face with Tears of Joy, by the way, is a bright yellow happy face with a classic, toothy grin as tears fall.
The Face was chosen by Oxford Dictionaries as its 2015 "word" of the year, based on its popularity and reflecting the rise of emojis to help charitable causes, promote businesses and generally assist oh-so-many-more of us in further expressing ourselves on social media and in texts.
Emoji users more likely to have sex, survey finds
The Beyhive knows. The collective fan base of Beyonce recently spammed Amber Rose with little bumblebee emojis when they sensed a diss of their queen.
Taco Bell also knows. Emoji overseers approved a taco character last year after a yearlong campaign by the company to get one up and running, rewarding users of said taco on Twitter with gifts of free photos, GIFs and other virtual playthings to celebrate.
Chevrolet uses emojis to promote 2016 Cruze reveal
So what's it all about? Here's a look at the past, present and rosy future of emojis:
While there's now a strict definition of emojis as images created through standardized computer coding that works across platforms, they have many, many popular cousins by way of "stickers," which are images without the wonky back end. Kimojis, the invention of Kim Kardashian, aren't technically emojis, for instance, at least in the eyes of purists.
In tech lore, the great emoji explosion has a grandfather in Japan and his name is Shigetaka Kurita. He was inspired in the 1990s by manja and kanji when he and others on a team working to develop what is considered the world's first widespread mobile Internet platform came up with some rudimentary characters. They were working a good decade before Apple developed a set of emojis for the first iPhones.
Like it? Facebook gets angry and sad buttons as friends
Emojis are either loads of fun or the bane of your existence. One thing is sure: There's no worry they'll become a "language" in and of themselves. While everybody from Coca-Cola to the Kitten Bowl have come up with little pictographs to whip up interest in themselves, emojis exist mainly to nuance the words regular folk type, standing in for tone of voice, facial expressions and physical gestures — extended middle finger emoji added recently.
"Words aren't dead. Long live the emoji, long live the word," laughed Gretchen McCulloch, a Toronto linguist who, like some others in her field, is studying emojis and other aspects of Internet language.
Emojis have been compared to hieroglyphs, but McCulloch is not on board. That ancient picture-speak included symbols with literal meaning, but others stood in for actual sound.
Emoji enthusiasts have played with telling word-free stories using their little darlings alone and translating song lyrics into the pictures, "but they can't be put together like letters to make a pronounceable word," McCulloch said.
THE EMOJI OVERSEERS
Back when Kurita was creating some of the first emojis, chaos already had ensued in trying to make all the pagers and all the emerging mobile phones and the newfangled thing called email and everything else Internet-ish that was bubbling up speak to each other. And also to allow people in Japan used to a more formal way of communicating make themselves understood in the emerging shorthand.
Enter the Unicode Consortium, on the coding end. It's a volunteer nonprofit industry organization working in collaboration with the International Organization for Standardization, the latter an independent non-governmental body that helps develop specifications for all sorts of things, including emojis, on a global scale.
Unicode, co-founded and headed by Mark Davis in Zurich, has a big, big mission, of which emojis have a place: making sure all the languages in the world are encoded and supported across platforms and devices.
The key word here is volunteer. Davis has a whole other job at Google, but he has dedicated himself to the task above. He also co-chairs the consortium's emoji subcommittee, a cog in a vetting process for new emojis that can take up to two years before new ones are put into the Unicode Standard for the likes of Apple, Google, Microsoft and Facebook to do with what they wish.
Where does Davis sit with the rapid rise of emojis?
"It has been a surprise. We didn't fully understand how popular they were going to be," he said.
At the moment, Unicode has released 1,624 emojis, with more options when you factor in modifiers for such things as skin tone. The emoji subcommittee fields about 100 proposals for new emojis a year. Not all make it through the vetting process.
"We don't encode emoji for movie or fictional people, or for deities. And we're not going to give you a Donald Trump," Davis said.
Gender, he said, is among the next frontiers for emojis. Demand for a female runner, for instance, will be voted on in May as critics have questioned a male-female divide. The consortium is trying to come up with a way to more easily and quickly customize emoji for gender, hair color and other features, Davis said.
"Personally, I am very much looking forward to a face palm emoji," he joked.
EMOJI LOVERS AND HATERS
Meet Elle Brown. She's a 9-year-old "kidpreneur" from Plant City, Fla. She makes emoji-theme jewelry and key fobs that she sells at school and church, and that her mom sells from her desk at an insurance firm.
"My favorite one is the "poo" emoji, and the money emoji," said Elle.
People of all ages buy from her mom, Zee Brown.
"It's like having Girl Scout cookies. People come to me," she said.
While marketers are all over emojis these days, professional brander Kevin Winslow in Boise, Idaho, was a reluctant adopter.
"I thought they were rather silly. It didn't seem to me like something a grown-up would use," he said. "Now they're a necessity in social media campaigns. Sometimes they help do away with the exclamation point, which I also despise."
Vivian Rosenthal is founder and head of Snaps, a platform on which keyboards full of branded images are launched, including marketing campaigns intended to support social causes, such as the plight of refugees.
With nearly half of all Instagram posts now including at least one emoji and with more than 270 billion text messages sent a day across all mobile devices, brands are trying big time to monetize emojis, Rosenthal said.
"Basically, messaging is social 2.0," she added. "People want to convey more and more emotion. The language of the future is a visually based language. It's very universal and democratic."
Rosenthal estimated somewhere around 6 billion emojis and stickers are sent every day across devices and services.
EMOJIS AND THE YOUNGINS
Clearly, emojis are the darlings of the Millennial and GenZ generations. Other age groups are in the game, but Tayfun Karadeniz said age isn't the entire story.
He's the founder and head of EmojiXpress, a third-party app for iOS that supplies users with every emoji available in the Unicode Standard. He's also a new voting member of the Unicode Consortium.
Of roughly 50 million downloads of his app over the past three years, 80% of his users are female. Are they just about the fun? Are we, in the grand scheme, now dependent on emojis in some profound way?
"I wouldn't say our society would break down if we didn't have them, but you could also ask why do we need art, why do we need TV shows?"
Akash Nigam, the 23-year-old co-founder and chief executive of Blend, a group messaging app focused on Millennials and GenZers, thinks emoji use among those age groups has a slightly more urgent element.
"They're integral to their daily lives," he said. "With this audience, it's kind of like the punch line. Whoever uses the most unique emojis alongside a very witty text kind of gets the most kudos. Everybody is always pounding their keyboards looking for emojis that haven't been used. I mean, yeah, you could paint a picture or write an essay, but it doesn't feel the same."


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POWER OF THE PEDAL: Pirates bring the interactive screening experience to the public
By: Massiel Sánchez
About Massiel Sánchez
Massiel Sanchez (1984) was born in San-Juan de La Maguana, Dominican Republic. She has also lived in Australia but now resides in Utrecht (NL). In the past she worked as a webeditor, digital archiver and database-employee at various institutions and companies including Philips Electronics and the Royal Institute for the Tropics. She is finishing an M.A. in New Media, likes to work as a freelance producer/assistant for tv programs like EenVandaag and PBS Newshour. She is also producer/director of a long-term short documenty filmed in Moshi, Tanzania. She has been responsible in various multimedia projects for all aspects of field segments, from pitching idea to on-the-ground reporting to editing video for broadcast. Last but not least, she is more than interested in issues regarding digital culture, gender and Internet Freedom.
(by Jacqueline @ Magneet Festival)
On Saturday 29th of September, Pirate Cinema attended Polderweg Damoclash festival, (located in Amsterdam-Oost), with their five-wheeled bicycle installation. Pirate Cinema's essence lies in the synthesis of the mobile media and in its inclusion of the socially engaged message of public participation. As a non permanent object, rooted in a physical space, but at the same time detached from it, it has acquired the ability to create a media space anywhere. A communal bicycle that is exposed to visitors, invites them not only to engage in the viewing experience, but also to support the functioning of the instrument itself. If audience participates, a common experience is created. It is a unique practice that forms a cross-combination of the locative media and the urban screen projections.
Pirate Cinema is a five-wheeled bicycle that enables three people to ride it, or produce electricity, by the simple act of pedaling (forward and backwards accordingly). This moving installation is equipped with an audio-visual and sound systems that allow various interactions to happen. Conceived in a form of installation, but being a part of a wider movement, the organisation behind Pirate Cinema promotes principles of social justice by engaging notions of art in the public space, and empowerment of people and sustainable energy. Short films, movies, experimental music and performances are all displayed in the pursuit of creating fun, and sustainable media art.
Regarding the medium content, selection of material undergoes a democratic process, in which everyone willing to participate and provide the content for the screening, play a tune, or be a DJ, is free to do so. It presents us with an alternative to a static movie-night-out at the cinema.
Pirate Cinema and its collective bear close resemblance to that of the urban screen projections. It is stated that, in doing so, Pirate Cinema managed to engender collective moments in public spaces (Taylor; 2005).
The experience of film, photo and music is provided by the audience itself – producing electricity by the act of pedaling enables technological equipment to function. Furthermore, audiences are stimulated to engage with the Pirates by bringing and plugging in their own material. In addition, this onsite engagement occurs in a real-time.
Pirate Cinema @ Magnet Festival
Through Pirate Cinema, we are expected to partake in a social activity, that not only embodies active participation, but also includes technological and socio-cultural engagement. Indeed, as Auerbach claims, these types of urban screen projections are experimental, and at times things can turn awry. Sometimes equipment fails to work, movie formats collide with the software used, or no one feels like cycling.
Bringing social issues closer to their on-wheels-cinema, is an unconventional, but at the same time very effective way of guiding the visitors into their roles. Not as passive viewers, but as active members as they are expected to take part in the production of artistic work and experience. The result is a shining cinema with beams of light projecting onto it, without the necessity of a permanent space, and all charged by the mere power of two pedals.
More curiously, Pirate Cinema does not follow a specific set of rules, no regular code of conduct and up til now it has remained under the radar.
dropstuff.nl on display during the Venice Biennale, 2011.
Pirate Cinema forms part of a number of interactive screen projections in the City of Amsterdam and the Netherlands at large. Another relevant project, Dropstuff.nl, also represents a great value. This organisation embeds urban projections in public spaces, such as city squares, parks and train stations in order to stimulate active participation.
DROPSTUFF.nl – a 'museum without walls', functioning as a cultural space, and displaying art with the use of a digital medium, making it available to the wider audience. Artwork presented includes movies, media artifacts, or games of an artistic value. Its main purpose is to bring the digital media work into the public space, and initiate participation in live broadcasting of the artistic program. Daily exposition in different locations – such as railway stations, central squares, or parks, is a method of increasing awareness of new media arts among general population. Dropstuff Netherlands also provides smaller screens for the museum exhibitions, cultural and educational institutions, and is responsible for the live broadcasting online on live.dropstuff.nl. Events, as well as the online streaming, can both be synchronized in a real-time, which makes the interaction possible with as little as the usage of a simple broadcasting software on smartphones, or the passers-by participation in games played with other users.
By emphasizing the elements of play and interaction, Pirate Cinema and actors like dropstuff.nl, create a sphere of negotiation and a public conversation regarding the particular screening experience. Yet, it becomes clear that the Pirate Cinema beams a larger sense of the immediateness, the re-interpretation of the notion of activity performed inside, as opposed to the aforementioned commercial cinematic experiences. Whilst doing so, visitors internalise not only the screening, but also gain more understanding of the elements needed to take on, feel, see and experience the performance. They expose the extent, to which the simple and invisible things like electricity are vital to your experience of the screen. Within that framework, they challenge traditional concepts of presence, distance, and time, while engaging their audience with one singular simultaneous experience.
Auerbach, Anthony (2006) "Interpreting Urban Screens." First Monday.
url: http://firstmonday.org/htbin/cgiwrap/bin/ojs/index.php/fm/article/view/1546/1461
Lester, Martin (2006) "Urban Screens: the beginning of a universal visual culture." First Monday.
Taylor, Kate (2006) "Programming video art for urban screens in public space." First Monday.
Patrycja Szumacher
Massiel Sanchez
Geoff Kim
Tags: alternatives, amsterdam, Pirate Cinema, screening experience, urban projections
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redpajama_set_name: RedPajamaCommonCrawl


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Meixian (, Hakka: Moiyen), formerly Meihsien, is a district of Meizhou City, in northeastern Guangdong Province, China. The county is an important Hakka settlement and is the ancestral home of many Hakka descendants living in Taiwan.

History
Its original name was Chengxiang county () during the southern Han Dynasty where it was first created, all the way to the Song, Yuan and Ming dynasties, and then renamed Jiaying county during the Qing dynasty. It only obtained the name Meixian in 1911 during the Xinhai Revolution.

Geography

Meixian almost completely surrounds Meizhou's central urban Meijiang District. This is due to the old urban core of Meixian becoming separated from the bulk of the county in the territorial reorganization following the 1949 establishment of the People's Republic of China, when it was given equal status.

Ethno-linguistic make-up

Meixian is noted for its large Hakka population.

Administrative divisions
Meixian has administrative jurisdiction over one subdistrict and 18 towns.

 Subdistrict
 Xincheng ()

 Towns
Chendong ()
Shisan ()
Meixi ()
Daping ()
Shikeng ()
Shuiche ()
Meinan ()
Bincun ()
Baidu ()
Songyuan ()
Longwen ()
Taoyao ()
Shejiang ()
Yanyang ()
Songkou ()
Nankou ()
Chengjiang ()
Fuda ()

Culture
With a majority Hakka population, Meixian, along with Dabu County, is known as the home of Standard Hakka.

References

External links

County-level divisions of Guangdong
Meizhou

redpajama_set_name: RedPajamaWikipedia


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Q: create a master branch after all my work has already been committed in develop branch I have created a repository for my project, and there has been only a "develop" branch. I just forget to create a "master" branch at the beginning. Now, All my work is on the "develop" branch.
Now, I would like to create a "master" branch, but I don't want this "master" branch to be created from "develop", instead, I'd like to have it as an independent branch that doesn't contain my work at all. How to create this "master" branch?

A: To create a new master branch pointing at your repo's initial commit :
git branch master $(git rev-list --max-parents=0 @)

redpajama_set_name: RedPajamaStackExchange


Our bricks and mortar specialty drinks store is located in Dublin, Ireland. We are in the historic Powerscourt Town Centre, on the corner of Coppinger Row and Clarendon Street. Our shop didn't seem to have a street number, so we adopted thirteen.


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Tellus National Airborne Survey 2018
The Tellus Survey – a nationwide programme of Geological Survey Ireland, which collects geochemical and geophysical data on rocks, soil and water across Ireland – has officially embarked on its 2018 airborne survey. To collect this data, an aircraft equipped with state-of-the-art geophysical technology will be flying the skies at low heights over west Cork, Limerick, north Tipperary, and south Offaly from August until the end of 2018 (weather permitting).
The data collected from the Tellus Survey is helping to map and sustainably manage our environment and natural resources and to protect public health in the future. Previous phases of Tellus have provided new data to improve radon risk mapping, assisted local exploration for mineral resources, enabled new third-level research on environmental pollution, agricultural productivity and peat and wetlands which helps provide a comprehensive picture of the environment within Ireland. Data collected throughout the project is made publically and freely available to all on the Tellus website (www.tellus.ie).
GSI Tellus Survey – West Cork Survey Area 2018.
The aircraft is a white, twin propeller plane, which is easily identified by its red tail and black stripe as well as the word 'SURVEY' and registration number C-GSGF written across both sides of the plane. Based at Kerry airport, the plane will be flying at 60 metres over rural areas – about eight times the height of a two storey house – and 240 metres over urban areas over the coming months, as approved by the Irish Aviation Authority. The aircraft is able to sense geological properties not apparent from conventional mapping techniques, effectively 'seeing through' Ireland's often deep glacial deposits and extensive peat and soil cover.
Dr James Hodgson, Senior Geologist and Project Manager for Tellus, said: "The Tellus Survey is an important and exciting project which keeps providing us with significant information about the geological composition of Ireland. This latest airborne phase builds on the work done up until now and is the first step towards 'mapping' 75% of Ireland by 2020. The survey will bring new insights into the geology of the region in particular the significant mineral resources and agricultural properties across the west and southwest. This is shown in the support and part-funding for the survey by two separate exploration companies Group Eleven Resources Ltd and First Quantum Mineral Ltd. We would also like to extend our sincere thanks to the local communities for their continued support and understanding during the survey activity."
The sound of the plane is similar to that of a passing lorry but could possibly startle sensitive livestock, such as horses. GSI issued information leaflets to all homes and business in the survey zones via post at the end of April to provide advance notice of the survey.
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Three Research Technologist 1 positions are available beginning May 13, 2019 in the structural biology laboratories of Dr. Song Tan and Dr. Jean-Paul Armache in the Department of Biochemistry and Molecular Biology. This project focuses on understanding how chromatin enzymes regulate gene expression. Responsibilities include (a) express proteins and protein complexes in E. coli, (b) purify proteins, protein complexes and protein/DNA complexes using low pressure and high performance chromatography, (c) analyze proteins and protein/DNA complexes by electrophoresis, spectroscopy, immunoassays and enzyme activity assays, (d) set up and evaluate crystallization trials, (e) maintain written and electronic laboratory records, (f) assist with ordering laboratory supplies, (g) maintain laboratory equipment. Typically requires a Bachelor's degree or higher plus one year of related experience, or an equivalent combination of education and experience. A Bachelor's degree or equivalent in a biological science, chemistry or physics preferred. This is a fixed-term appointment funded for one year with excellent possibility of refunding.


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Virginia Women's Center Delivers New Short Pump Location, Welcomes First Patients
Posted by RFM Staff
Virginia Women's Center's (VWC) new Short Pump location is open and welcoming patients.
The 36,000 square-foot facility was officially completed on April 1. A total of 65 staff members, including 13 doctors, and 3 nurse practitioners, will care for patients at VWC's newest location.
Virginia Women's Center coordinated a strategic move into the new location – just off West Broad Street and Gayton at 12129 Graham Meadows Drive. "Our vision was to meet our patients where they live, work, shop and play, and we believe we've achieved that goal with the opening of our new location," said VWC President Dr. Kay Stout. "Not only are we able to offer more services to our patients, but the location is easy to find and very accessible to women throughout the area. It also offers an array of women's healthcare services like no other single location in central Virginia."
The addition of the new Short Pump office enables Virginia Women's Center to make healthcare as convenient as possible for the women of Central Virginia. VWC recognizes that in today's busy world, convenience is paramount to women getting the care they need and deserve.
At the new location, VWC will offer comprehensive gynecologic and obstetrical care along with numerous subspecialties—including urogynecology, urology, maternal fetal medicine, genetic counseling, clinical research, mental health, bone health, and breast health services. VWC will also offer the most up-to-date 3D mammography, and the ability for women to get their mammogram on the same day as their annual well-woman exam. In addition to screening mammography, Virginia Women's Center offers comprehensive breast care including diagnostic mammography, breast ultrasound, and breast biopsies.
The new location features a 300 square-foot community room where lecture series will be offered, as well as prenatal yoga classes.
"Our goal is to offer comprehensive, connected, collaborative care─all under one roof," Stout said. Our new service area ensures that we're convenient to women across the RVA region. And, poised to deliver babies and perform gynecologic services at area hospitals—including Henrico Doctors' Hospital, Memorial Regional Medical Center, St. Francis Medical Center and St. Mary's Hospital."
Virginia Women's Center is a full-service women's health care practice specializing in gynecology, obstetrics, urogynecology, high-risk obstetrics, genetic counseling, breast, bone and mental health, ultrasound, in-office surgeries and procedures and clinical research. With offices in Midlothian, Mechanicsville, Short Pump, the West End, Tappahannock, and Kilmarnock, we're conveniently located to care for patients—where they live, work, shop and play.
Virginia Women's Center provides a holistic approach that cares for both body and mind. More than just another doctor's appointment, patients get a partner who takes their health personally.
previous post: Shopping, Dining, and Entertainment Heats Up in Short Pump
next post: Enjoy Dinner at a Short Pump Mall Restaurant, Receive a Mall Gift Card
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text:
Quick Answer: How Old Is A 70 Lb Child?
Is 200 pounds fat for a 13 year old?
What age is a 25 lb baby?
What age is a 15kg child?
How old is a 35 lb child?
What is overweight for a 11 year old?
How old is a 7 year old supposed to weigh?
What is the average weight for a 13 year old?
Is 70 kg overweight for a 13 year old?
Is my 7 year old overweight?
How old is the average 50 lb child?
What's a good bedtime for a 13 year old?
What's a normal bra size for a 13 year old?
Weighing 200 pounds is within the healthy weight range ONLY if the person is 6′ 5″ or taller, but that is uncommonly, unusually tall.
Under 5′ tall into the severely or morbidly obese range..
According to the CDC, most 13-year-old girls weigh between 76 and 148 pounds (lb). The 50th percentile for weight in this group is around 101 lb. This means that about 50% of girls this age weigh less than 101 lb. … If a 13-year-old girl weighs above the 95th percentile, the doctor may diagnose obesity.
Most babies double their birth weight by five to six months of age and triple it by the time they are a year old. By one year, the average weight of a baby girl is approximately 19 pounds 10 ounces (8.9 kg), with boys weighing about 21 pounds 3 ounces (9.6 kg).
Age Vs Weight & Height TableBaby's ageWeightHeightMonth 129kg – 12.5kg70cm – 80cmYear 210kg – 15kg80cm – 90cmYear 311kg – 17kg86cm – 100cmYear 413kg – 20kg92cm – 109cm13 more rows
TopsSizeAgeWeight18 – 24 M18 – 24 Months28 – 30 lbs 13 – 14 kg2T2 Years30 – 32 lbs 14 – 15 kg3T3 Years32 – 35 lbs 15 – 16 kg4T4 Years35 – 39 lbs 16 – 18 kg4 more rows
If she is a very short child, 54 or 55 inches, then 120 lbs. is very overweight. If she is tall for her age, let's say about 62 inches, then 120 lbs. could be a reasonable weight for an athletic, muscular child.
Obesity is defined as a BMI at or above the 95th percentile for children and teens of the same age and sex. For example, a 10-year-old boy of average height (56 inches) who weighs 102 pounds would have a BMI of 22.9 kg/m2.
For this statistically average size of child, most harnessed car seats would be outgrown by height long before weight. A child in the 95th percentile for weight would likely reach 60 lbs somewhere between ages 6 and 7 That same child would likely reach 80 lbs somewhere between 8 and 9 years old.
Big Kid weight and height averagesAgeSizeGirlsHeight3 ft 7 in (108 cm)6 yearsWeight44 lb 12 oz (20.3 kg)Height3 ft 9 in (115 cm)7 yearsWeight50 lb 8 oz (22.9 kg)8 more rows•Apr 8, 2020
For example, a 7-year-old boy who is 3 feet 11 inches (119 cm) tall would have to weigh at least 56.9 pounds (25.8 kg) ( BMI = 17.9) to be considered overweight, and a 13-year-old girl who is 5 feet, 3 inches (160 cm) tall would be considered obese if she weighed 161 pounds (73 kg) ( BMI = 28.5).
Even though a 13 year old who is 70 kg is considered to be overweight as they suggest you should be weighing more like 50 to 60 plus kg, you are a growing teenager (providing that you are still growing, I'm only saying this because when I was your age I stopped growing unfortunately for me).
If your child's BMI is in the 85th percentile – meaning it's higher than that of 85 percent of children his age and gender – he would be considered overweight. If he's in the 95th percentile, he's considered obese.
Normal GrowthAgeHeight Females in InchesWeight Females in Pounds437 to 42.528 to 44642 to 4936 to 60847 to 5444 to 801050 to 5954 to 1067 more rows
Kids at this age are still very physical, but they learn in a more focused and less hectic way than when they were younger. These kids typically gain about 4–5 pounds (2 kilograms) and grow about 2–3 inches (5 to 8 centimeters) per year. An average 4-year-old weighs about 40 pounds and is about 40 inches tall.
Most teenagers need 8-10 hours of sleep each night. Some need as little as 7 hours or as much as 11 hours. It's very common for children in the early teen years to start wanting to go to bed later at night and get up later in the morning.
34C34C is pretty average for full grown adults of healthy weight. Above average for your age as most 13 years old's breasts are still developing, some don't even have enough breast to wear bras yet. 34C is pretty average for full grown adults of healthy weight.
The CDC also reports that a 12-year-old girl's weight is usually between 68 and 135 pounds, and the 50th percentile weight for girls is 92 pounds. If your child is in the 50th percentile for weight, it means that out of 100 children their age, 50 may weigh more than they do and the other 50 may weigh less.
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Is it bad to park on rocks? To address your concern directly;


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Coca-Cola is running My Coke Rewards Program every year for last 10 years. It is a customer loyalty marketing program from the Company. When customers buy specially marked Coca-Cola products, they get codes on the packaging or underneath the cap. On entering these codes in code entry field at www.mycokerewards.com , you will are given points. You can also earn points when you make friends or family members to sign up. The accrued points can be redeemed for various rewards as well as to enter sweepstake entry. You can donate the points for charity or you can unlock certain activities. Even the points can be carried over to the next year.
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By Coca Cola products, enjoy it, get the code, make code entry and get rewarded!


text:
using System;
using System.Collections.Generic;
using System.Text;
using FlatRedBall.IO;
using System.Diagnostics;
using EditorObjects.Parsing;
using System.IO;
using System.Windows.Forms;
using System.ComponentModel;
using System.Threading;
using System.Threading.Tasks;

namespace EditorObjects.SaveClasses
{
    [TypeConverter(typeof(PropertySorter))]
    public class BuildToolAssociation
    {
        #region Properties

        [Category("Primary Arguments"), PropertyOrder(100)]
        [EditorAttribute(typeof(System.Windows.Forms.Design.FileNameEditor), typeof(System.Drawing.Design.UITypeEditor))]
        public string BuildTool
        {
            get;
            set;
        }

        public string BuildToolProcessed
        {
            get
            {
                var toReturn = BuildTool;
                if(toReturn != null)
                {
                    var folder = FileManager.GetDirectory(System.Reflection.Assembly.GetEntryAssembly().Location);
                    toReturn = toReturn.Replace("%Glue%", folder);
                }

                return toReturn;
            }
        }

        [Category("Primary Arguments"), PropertyOrder(110)]
        public bool IsBuildToolAbsolute
        {
            get;
            set;
        }

        [Category("Primary Arguments"), PropertyOrder(200)]
        public string SourceFileType
        {
            get;
            set;
        }

        [Category("Primary Arguments"), PropertyOrder(300)]
        public string DestinationFileType
        {
            get;
            set;
        }

        [Category("Primary Arguments"), PropertyOrder(350)]
        public bool IncludeDestination
        {
            get;
            set;
        }

        [Category("Secondary Arguments"), PropertyOrder(400)]
        public string SourceFileArgumentPrefix
        {
            get;
            set;
        }

        [Category("Secondary Arguments"), PropertyOrder(500)]
        public string DestinationFileArgumentPrefix
        {
            get;
            set;
        }

        [Category("Secondary Arguments"), PropertyOrder(600)]
        public string ExternalArguments
        {
            get;
            set;
        }

        #endregion

        public BuildToolAssociation()
        {
            IncludeDestination = true;
        }

        public BuildToolAssociation Clone()
        {
            return (BuildToolAssociation) this.MemberwiseClone();
        }

        public string PerformBuildOn(string sourceFile, string destinationFile, string additionalArguments,
            Action<string> printOutput, Action<string> printError)
        {
            return PerformBuildOn(sourceFile, destinationFile, additionalArguments, printOutput, printError, false);
        }

        public string PerformBuildOn(string absoluteSourceFile, string absoluteDestinationFile, string additionalArguments,
            Action<string> printOutput, Action<string> printError, bool runAsync)
        {
            if (FileManager.IsRelative(absoluteSourceFile))
            {
                throw new ArgumentException("absoluteSourceFile needs to be an absolute path");
            }
            if (FileManager.IsRelative(absoluteDestinationFile))
            {
                throw new ArgumentException("absoluteDestinationFile needs to be an absolute path");
            }

            string errorString = "";

            string executable = BuildToolProcessed;

            if (FileManager.IsRelative(executable))
            {
                executable = FileManager.RelativeDirectory + executable;
            }

            if (!File.Exists(executable))
            {
                errorString = "Could not find the tool " + executable;
            }
            else
            {

                absoluteSourceFile = FileManager.Standardize(absoluteSourceFile).Replace("/", "\\");
                absoluteDestinationFile = FileManager.Standardize(absoluteDestinationFile).Replace("/", "\\");

                string destinationDirectory = FileManager.GetDirectory(absoluteDestinationFile);

                if (!System.IO.Directory.Exists(destinationDirectory))
                {
                    System.IO.Directory.CreateDirectory(destinationDirectory);
                }

                string arguments = GetArgumentsForProcess(absoluteSourceFile, absoluteDestinationFile, additionalArguments);

                Process process = CreateProcess("\"" + executable + "\"", arguments);

                if (printOutput != null)
                {
                    printOutput(process.StartInfo.FileName + " " + process.StartInfo.Arguments);
                }

                if (runAsync)
                {
                    new Task(
                        () => RunProcess(absoluteSourceFile, absoluteDestinationFile, printOutput, printError, errorString, executable, process)).Start();
                }
                else
                {
                    errorString = RunProcess(absoluteSourceFile, absoluteDestinationFile, printOutput, printError, errorString, executable, process);
                }
            }

            return errorString;
        }

        private static Process CreateProcess(string executable, string arguments)
        {
            Process process = new Process();

            process.StartInfo.Arguments = arguments;
            process.StartInfo.UseShellExecute = false;
            process.StartInfo.FileName = executable;
            process.StartInfo.RedirectStandardError = true;
            process.StartInfo.RedirectStandardInput = true;
            process.StartInfo.RedirectStandardOutput = true;
            process.StartInfo.CreateNoWindow = true;

            return process;
        }

        private string GetArgumentsForProcess(string sourceFile, string destinationFile, string additionalArguments)
        {
            string arguments = null;
            if (!string.IsNullOrEmpty(SourceFileArgumentPrefix))
            {
                arguments = SourceFileArgumentPrefix + " \"" + sourceFile + "\"";
            }
            else
            {
                arguments = "\"" + sourceFile + "\"";
            }

            if (IncludeDestination)
            {
                if (!string.IsNullOrEmpty(DestinationFileArgumentPrefix))
                {
                    arguments += DestinationFileArgumentPrefix + " \"" + destinationFile + "\"";
                }
                else
                {
                    arguments += " \"" + destinationFile + "\"";
                }
            }

            if (!string.IsNullOrEmpty(ExternalArguments))
            {
                arguments += " " + ExternalArguments;
            }

            if (!string.IsNullOrEmpty(additionalArguments))
            {
                arguments += " " + additionalArguments;
            }
            return arguments;
        }

        private static string RunProcess(string sourceFile, string destinationFile, Action<string> printOutput, Action<string> printError, string errorString, string executable, Process process)
        {
            process.Start();
            // Unfortunately we need to wait for the build to complete so that we can copy any referenced files that we need
            int numberOfWaitTimes = 0;

            bool doesUserWantToWait = false;
            const int numberOfTimesToWait = 150;
            bool hasUserTerminatedProcess = false;

            StringBuilder outputWhileRunning = new StringBuilder();

            while (!process.HasExited)
            {
                System.Threading.Thread.Sleep(150);
                numberOfWaitTimes++;
                // Not sure why
                // but the TMX to
                // SCNX tool used to
                // freeze.  I found that
                // if I simply check if the
                // StandardOutput is not at EndOfStream,
                // then nothing freezes.  I figured this out
                // by attaching to a frozen TmxToScnx.exe process
                // in visual studio and found that it was stuck on
                // a command line output.  I thought I'd have to read
                // from the stream, but just seeing if it's at the end
                // fixes it.
                if (!process.StandardOutput.EndOfStream)
                {   }

                if (numberOfWaitTimes > numberOfTimesToWait && doesUserWantToWait == false)
                {
                    DialogResult dialogResult = MessageBox.Show("The tool\n\n" + executable + "\n\nis taking a long time to build the file\n\n" +
                        sourceFile + "\n\nWould you like to end this build process?", "End process?", MessageBoxButtons.YesNo);

                    if (dialogResult == DialogResult.Yes)
                    {

                        if (!process.HasExited)
                        {
                            // Just in case it happens to exit on its own:
                            try
                            {
                                if (printError != null)
                                {
                                    printError("User cancelled build.  Command line:\n\t" +
                                                            process.StartInfo.FileName + " " + process.StartInfo.Arguments);
                                }
                                process.Kill();
                            }
                            catch
                            {
                                // do nothing, it happened to exit between the if check and the Kill call
                            }
                        }
                        hasUserTerminatedProcess = true;
                    }
                    else
                    {
                        doesUserWantToWait = true;
                    }
                }
            }

            if (process.ExitCode != 0)
            {
                if (hasUserTerminatedProcess)
                {
                    errorString = "The process\n\n" + executable + "\n\nhas been terminated";
                }
                else
                {
                    errorString = process.StandardError.ReadToEnd() + "\n\n" + process.StandardOutput.ReadToEnd();
                }
            }
            else
            {
                string str;

                while ((str = process.StandardOutput.ReadLine()) != null)
                {
                    if (printOutput != null)
                    {
                        printOutput(str);
                    }
                }

                while ((str = process.StandardError.ReadLine()) != null)
                {
                    if (printError != null)
                    {
                        printError(str);
                    }
                    errorString += str + "\n";
                }
                if (!string.IsNullOrEmpty(errorString))
                {
                    errorString += "\n";
                }
            }

            if (!File.Exists(destinationFile))
            {
                errorString += "The process\n\n" + executable + "\n\nfailed to build the file\n\n" + destinationFile;

            }
            return errorString;
        }

        public override string ToString()
        {
            string buildTool = "<NO TOOL>";
            string sourceFileType = "<NO SOURCE>";
            string destinationFileType = "<NO DESTINATION>";

            if (!string.IsNullOrEmpty(SourceFileType))
            {
                sourceFileType = "*." + SourceFileType;
            }

            if (!string.IsNullOrEmpty(DestinationFileType))
            {
                destinationFileType = "*." + DestinationFileType;
            }

            if (!string.IsNullOrEmpty(BuildToolProcessed))
            {
                buildTool = FileManager.RemovePath(BuildToolProcessed);
            }

            return sourceFileType + " -> " + buildTool + " -> " +
                destinationFileType;
        }
    }
}

redpajama_set_name: RedPajamaGithub


SYDNEY (Reuters) - An inquiry into Australia's financial sector heard on Monday examples of possible misconduct by insurance companies, including spying on policyholders, overcharging customers and misleading sales calls.
TAL, the Australian unit of Japanese insurance giant Dai-ichi Life Holdings <8750.T>, said in a submission that it had made hundreds of misleading sales calls, Orr said.
Hong Kong-based AIA Group <1299.HK> said it had overcharged customers on their premiums, while the Swiss giant Zurich Insurance Group reported cases in which it had applied the terms of its policies incorrectly. Orr did not elaborate.
Insurance Australia Group , which holds a nearly 20 percent share of the country's life insurance market according to IBIS World, told the inquiry it had identified 112 instances of misconduct, including systemic problems with its sale processes and the handling of claims, Orr said.
She said reports of misconduct were also received from the insurance units of Commonwealth Bank , Westpac Banking Corp , National Australia Bank , and Australia and New Zealand Banking Group .
QBE Insurance , which holds about 8.7 percent of the life insurance market, was the only firm that did not report instances of misconduct to the inquiry, Orr said, adding that QBE described some "issues" and "incidents".
Before the public hearings, companies are asked to identify in their submissions any misconduct they had engaged in, or any conduct that fell below community standards and expectations since 2008.


Our Gold DJ setup is what we recommend to any client for events of 70 to 130 guests. It is 6m wide but can shrink to 5.5m wide if need be. It combines the Sniper and spot/beam setups as per Bronze and Silver for a real wow factor light show that delivers atmosphere to the whole dance floor, but also delivers some lower level search light lighting at the front of the dance floor. We regularly hear guests say "wow" when the setup is revealed to them.
The sound system here is configured here like the Silver system with the EVO 6SH top speakers which deliver the purist sound you will ever experience. But again can be upgraded to expand the energy even further for up to 300 guests by adding our 21" subs. However above 150 people we recommend going to the Platinum system for a more appropriate lighting rig.
Why not look at adding our LASER show for really impressing your guests in those big "hands in the air" moments?
Remember our lighting is operated all night by a dedicated engineer thus the lighting will always be matched to the energy of the music.
The Gold DJ package includes.


For a limited time only, we are now offering reduced rent! Call today! No matter what your lifestyle holds, The Residences at Great Pond in Randolph, MA offers premier luxury apartments to suit your needs. With a wide variety of one and two bedroom apartments, you're sure find your perfect apartment here. Experience sophistication without feeling cramped. Each of our floor plans features wide spaces and oversized windows, amplified by a flawless finish collection, so you'll never feel confined. Choose from multiple floor plans to suit every state of mind, from cozy and chic to spacious and suave. Your home is an extension of your lifestyle, so make sure you have the right fit. We offer various one and two bedroom floor plans for a reason—we know you love options. We also know space is a factor, so we've designed each apartment to optimize your room with open spaces and private places. Check online here for availability, or call our office to schedule a tour today!


Alex Klose, VP of Marketing at IMImobile, looks at the opportunity for enterprises to differentiate customer experience by combining new rich-media messaging channels such as RCS (Rich Communication Services) with customer journey automation platforms.
There is no doubt that consumers have a huge desire for messaging-based experiences. In fact, 66% of consumers prefer to reach brands, or be reached by brands through messaging apps, and two-thirds expect to increase their engagement with businesses via messaging channels over the next two years.
The role of messaging is becoming instrumental for how consumers interact with brands and with increasing app fatigue, enterprises must ensure they adapt to the shift in consumer behaviour towards new messaging channels.
Not only is it about meeting customer expectations for how they want to engage and access services, but also about responding to increasing competition from agile start-ups who have enabled their entire service offering on channels such like Facebook Messenger.
The race to engage, win and differentiate through messaging-based experiences is well and truly on. So how can enterprises get ahead?
The battleground amongst companies like Amazon, Apple, Facebook and Google to provide rich media messaging services is well under way. There's Facebook who launched Messenger 2.0, WhatsApp who earlier this year launched 'WhatsApp Business' in five markets, as well as Google's latest support of Rich Communication Services (RCS) for Android devices, and there are even rumours about an Amazon messaging app.
But no matter which company or messaging service, the objective is very simple – they all seek to be the medium for consumers and businesses to talk to each other. Whether that's through the use of AI-powered chatbots, high-res image carousels, videos, audio, action buttons, and much more, to transform conversational messaging experiences.
At IMImobile, we believe that for enterprises, it should be less about which messaging channel is used to engage with consumers and more about the opportunity to automate customer interactions, services and self-care across business systems and processes.
Using a customer journey automation platform that can seamlessly integrate with back-end systems, enterprises can unify integrations of any messaging channel, connect siloed business systems and link these to specific communication triggers and business processes. By doing this, CX professionals and developers have a central hub for managing two-way customer interaction across multiple channels.
With all the necessary integrations and assets centralised, customer journeys can then be mapped to combine the use of data and rich media messaging functionality. This is the fastest and most cost-effective route for enterprises to create highly personalised, contextual and automated experiences, ultimately helping them to improve CX on the messaging channels that are most relevant to consumers.
To help further visualise the possibilities of the messaging-based experience, above are some examples of RCS demos we developed with some of our UK enterprise clients for the GSMA Mobile World Congress 2018.
Customer Service: A customer service chatbot that can answer FAQs to help reduce inbound call volumes at peak times into contact centres.
Workforce Management: Automated appointment reminders and rescheduling options for customers can improve operational efficiencies of a business's workforce to reduce costs for 'no show appointments'.
Marketing: Action buttons and rich media coupons to can streamline the redemption of promotions and rewards to increase marketing ROI.
You can learn more about how to use Rich Media messaging channels in the latest eGuide from IMImobile. The Messaging+ eGuide provides insight and guidance on how to differentiate customer engagement and service across new messaging channels. Featuring a list of seven key channels and technologies, arranged by priority rating based on their current capabilities, and exploring how enterprises can take control of an increasingly complex customer communications ecosystem.


text:
November 27, 2019by badasseryNo Commentsfitness
Q&A: Heather 'Anish' Anderson, Epic Thru-Hiker
© Heather Anderson
Unless you have a keen interest in thru-hiking, you might have missed the news that last year, Heather 'Anish' Anderson completed America's Triple Crown of thru-hiking within in a single calendar year. That's hiking the 2200-mile Appalachian Trail, the 2650-mile Pacific Crest Trail and the 3100-mile Continental Divide. It's the third time Heather has completed the Triple, and the first time it's been done by a woman within a single calendar year.
Heather, who goes by the trail name of 'Anish', also holds the outright self-supported Fastest Known Time record for the Pacific Crest Trail (PCT), which saw her hike an average of 44 miles a day for just over 60 days, often rising at 4am to start her hike and not finishing until gone midnight. Although known for her incredible hiking accolades, Heather has also completed six 100-mile trail races including the renowned Western States 100.
For an insight into Heather's record-breaking PCT FKT record I'd highly recommend reading her book, Thirst – 2600 MILES TO HOME, which documents her journey, including near-death experiences and mountain lion encounters. In the meantime, here's a quick Q&A with Heather.
Your book, Thirst, launched this year. Was stepping back into Anish's shoes a happy, cathartic process or was it quite emotional?
It was a good experience. The hardest part was only telling the personal development up until the end of that hike and not everything I've learned since.
Last year you became the first woman to complete America's Triple Crown in a calendar year. What shape was your body in by the time you'd finished?
My body was fine. Mostly I was just tired.
What's the mental process like when you finish a huge hike and are no longer on the trail every day – is there a big period of adjustment and mental recovery so to speak?
There's always a period of adjustment and depression as you cope with the transition. Depending on the hike these periods are sometimes short and sometimes they take months. It's important to sit with the loss and process it.
How did you approach the enormity of your FKT thru-hike distances without feeling overwhelmed?
Once I was on trail it was relatively easy to compartmentalise and focus only on the next water/food/town, etc. Anytime I began to think about the whole [distance] it would be completely overwhelming.
During your PCT FKT record, it seemed like you overcame a lot of self-doubt. Is it fair to say that with each hike you've grown in confidence and got to know yourself better?
You've said that your achievements have been 90% mental. What do you think made you stick it out where others quit?
I was born stubborn! I also never even start things unless I'm willing to see it through and am fully committed.
You've run several 100-milers and have lined up for the likes of Western Stages and The Barkley Marathon. How do they compare with the demands of your thru hikes? And will we see you running more ultras?
They're just different. They're harder for a short time, but over in a day. I hope to run more since I've missed it. But I don't know that I'll do many races or keep doing long mountain runs for fun.
What's the greatest life lesson your thru-hikes have taught you?
To accept myself and others.
What are your thru-hiking bare essentials?
Gossamer Gear Gorilla pack, Montbell down hugger sleeping bag, Gossamer Gear tent and nightlite pad.
Are you sponsored by anyone right now?
Not in the traditional sense. I've never received true sponsorships, but I've been well supported in my endeavours by a few companies that supply my gear needs.
You can follow Heather on social media via www.instagram.com/anishhikes, www.twitter.com/anishhikes and www.facebook.com/anishhikes. To find out more about Anish visit www.anishhikes.wordpress.
Camille Herron: Ultrarunning Phenomenon
A DAY IN THE LIFE OF… Helena Hills, Co-Founder, TRUESTART Coffee
Lydia Philip: Running from War Towards Hope
Fanny Kuhn: ÖtillÖ Swimrun World Champion
Laura Siddall: "It's a privilege to race the best in the world"


text:
entertainment Januar 4, 2021 Januar 4, 2021
Wham's last Christmas completes his 36-year journey to the top of the UK chart
by Karl Althaus
Last Christmas, which was not yet better than No. 2, garnered 9.2 million streams on the latest frame. And I did so on its fourth anniversary George Michael the death.
Wham co-founder Andrew Ridgley wrote on social media: "I'm happy, somewhat amazed, and profoundly happy that Wham!" It's a fitting tribute to George's songwriting genius and one of which he would be extremely proud and extremely cheerful. "
Now, "Last Christmas" can shed the unwanted title as the best-selling song in the UK that never reached # 1, with 1.9 million combined sales since its release.
This record is being passed Maroon 5 Screening of "Moves Like Jagger" Christina Aguilera, Which has 1.55 million "pure" sales, the OCC reports.
With Wham tops the number five, 28 holiday itineraries impact the top 40 tracks, including Jose Feliciano The classic "Velez Navidad" (BMG), which made its debut in the Top 40 list almost 50 years after its release. It comes to 44-40.
In fact, every title in the Top 10 has a Christmas theme, except Little Mix Sweet Melody (RCA), above 20 to 9.
Christmas bells are still ringing on the official UK Albums chart, which it leads Michael Buble birthday (Reissue) blockbuster movies.
birthday I rose 5–1 at Week 90 of the survey, for my fourth non-consecutive period at the top. Originally released in October 2011, birthday This week is postponed Taylor Swift forever (EMI), unchanged at # 2.
The highest new entry on this week's chart is Playboi Carti's Billboard 200 leaders A full red lotta (Interscope). It is new at number 17 in the UK
READ Prince Harry is "sad" by the royal family's tensions since the megast
Karl Althaus
"Wegbereiter für leidenschaftliches Bier. Unheilbarer Alkoholiker. Bacon Geek. Allgemeiner Web-Junkie."
More from Karl Althaus
James Marsden turned down the role of Magic Mike, fearing he would be an " extra player running in the series "
James Marsden reveals that he turned down the role of Magic Mike...
Taylor Swift cleaned up the Nashville country myths mural. but why?
Stephen Colbert rages on Republicans calling for "unity" after the Capitol riot
Hilaria Baldwin on Spain, Boston, Alec and Instagram
Previous articleRover to explore the soul landing on Mars
Next articleThe mayor of Miami is considering putting some of the city's treasury reserves into bitcoin
What does the Martian Sound and Rover Welcome Party look like


The company's operating income during the quarter fell 11.6% on a year-on-year (YoY) basis. The expenses were up by 2.3% YoY during the same period.
The company's operating profit declined by 61.2% YoY during the quarter. Consequently, operating profit margins witnessed a decline and stood at 9.6% in 2QFY19 as against 22.0% in 2QFY18.
Depreciation charges increased by 83.1% and finance costs declined by 50.0% YoY, respectively.
Other income increased by 7.5% YoY during the quarter.
Net profit for the quarter declined by 56.5% YoY. Net profit margins during the quarter declined from 14.6% in 2QFY18 to 7.2% in 2QFY19.
The company's operating income during the quarter fell 27.5% on a quarter-on-quarter (QoQ) basis. The expenses were down by 24.9% QoQ during the same period.
The company's operating profit declined by 47.0% QoQ during the quarter. Consequently, operating profit margins witnessed a decline and stood at 9.6% in 2QFY19 as against 13.2% in 1QFY18.
Net profit for the quarter declined by 39.0% QoQ, while net profit margins declined from 8.6% in 1QFY18 to 7.2% in 2QFY19.
To see how AVANTI FEEDS has performed over the last eight quarters, please visit here.
Over the last one year, AVANTI FEEDS share price has moved up from Rs 960.7 to Rs 379.4, registering a Loss of Rs 581.4 or around 60.5%.
At the current price of Rs 379.4, the price to earnings (P/E) ratio of AVANTI FEEDS stands at 15.4 times its trailing twelve months earnings, while its price to book value (P/BV) ratio stands at 5.0 times.
Equitymaster requests your view! Post a comment on "AVANTI FEEDS Announces Quarterly Results (2QFY19); Net Profit Down 56.5%". Click here!


text:
Blepharistemma serratum is a species of plant in the family Rhizophoraceae, and the only the species of the genus Blepharistemma.

References

Monotypic Malpighiales genera
Rhizophoraceae


text:
Q: PDFKit usage Rails 5 I have managed installing PDFKit and wkhtmltopdf on Windows 10 for using with Rails 5.
But I can't find any relevant exemple on how to render a html.erb file to PDF.
I took a look on this : pdfkit Usage and it works to save any website to PDF.
I have a <div> that I want to render to PDF.

A: I recommend you to use Wicked_pdf gem to generate quick and easy pdfs on rails. Here are some examples for both wicked pdf and pdfkit.

A: Answer :
1) Add gem 'pdfkit
gem 'wkhtmltopdf-binary' to Gemfile.
2) Run bundle install
3) Install wkhtmltopdf, and run which wkhtmltopdf then paste this path to config/initializers/pdfkit.rb
`# config/initializers/pdfkit.rb
     PDFKit.configure do |config|
      config.wkhtmltopdf = '/home/harri/.rbenv/shims/wkhtmltopdf'
      config.default_options = {
        :page_size => 'A4',
        :encoding      => 'UTF-8',
        :print_media_type => true
      }
      config.default_options[:load_error_handling] = 'ignore'

# Use only if your external hostname is unavailable on the server.
  config.root_url = "http://localhost"
  config.verbose = false
end `
4) In your controller :
`html = render_to_string(:action => "edit", :layout => false)
      kit = PDFKit.new(html)
      kit.stylesheets << "#{Rails.root}/app/assets/stylesheets/pdf.css"
      #kit.to_file("#{Rails.root}/public/system/daoe/daoe" + @daoe.id.to_s+'.pdf')
send_data(kit.to_pdf, :filename => 'report.pdf', :type => 'application/pdf', :disposition => 'inline'`

Use kit.to_file if you want to save the PDF, or send_data if you want to render the PDF fullpage.


We do offer foundation program in Netherlands, Australia,New Zealand,UK,Ireland and USA,Malaysia, Romania. After completed the foundation program student can get admission into Bachelor Degree programs.
The City University college, Malaysia.


text:
Q: how to print finite number of digits USING the scientific notation I have some values that I need to print in scientific notation (values of the order of 10^-8, -9)
But I would like to don't print a long number, only two digits after the .
something as:
9.84e-08
and not
9.84389879870496809597e-08
How can I do it? I tried to use
     "%.2f" % a
where 'a' is the number containing the value but these numbers appear as 0.00

A: try with this :
print "%.2e"%9.84389879870496809597e-08 #'9.84e-08'

A: This works with format function of the string (as % may be soon deprecated)
>>> n
9.843898798704968e-08
>>> print ("{0:.2e}".format(n))
9.84e-08

A: %f stands for Fixed Point and will force the number to show relative to the number 1 (1e-3 is shown as 0.001). %e stands for Exponential Notation and will give you what you want (1e-3 is shown as 1e-3).


Shawna Gordon is a soccer player born on the date January 18, 1990 in Fontana, California. According to her bio, Shawna's belongs to American nationality and her ethnicity is mixed. There isn't any information disclosed relating Shawna's family. Shawna's wiki states she currently is playing for Sky blue FC as the midfielder in the National Women's Soccer League. She has also played for the team "Boston Breakers", "Sky Blue FC", "the Western Sydney Wanderers" in Australia, and "Umea IK" in the Swedish Damallsvenskan before being involved in the National team.
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text:
Q: what is application signature in hyperledger fabric and how to set it?
what is Application's own signature in this context, and how can someone using hyperledger fabric node SDK can set the application's signature?

A: the application that you are talking about is simply a client app which talks to the ledger. The issue here is not the client app, the issue here is that you need a proper endorsement policy which establishes how anything goes onto the ledger.
Imagine this scenario ...
you have 2 orgs, Org1 and Org2, both owning one peer, P1 belongs to Org1, P2 belongs to Org2 and both peers joined on a channel, let's call it defaultchannel.
you deploy and instantiate your chaincode and set a basic endorsement policy which is 1-Of.
Each org has a client application, running against their own peer. When Org1 submits a transaction to the ledger, its validity is endorsed by itself, but not by the second org, because your policy requires only one to accomplish this. Basically in any network where you have more than one org, you really want a proper endorsement policy. 2-Of would work in the case of our example as any transaction would need to be validated by both orgs and that gives the ledger much better integrity.
Bottom line, your fabric network needs to be properly built and protected, especially in a production environment and this allows it to be protected by any client apps which have rights to interact with it. Your network being protected means that it doesn't matter how a client app is built and what it tries to do, it won't be able to bypass mechanisms such as the endorsement mechanisms.


text:
\section{Introduction}
Let $M$ be a $4k$ dimensional closed oriented smooth manifold. In \citet{witten1988index}, a multiplicative genus is defined by formally applying the equivariant Atiyah-Singer index theorem to a hypothetical Dirac operator in the loop space and we can get the analogue of $\hat{A}$-genus
\begin{equation*}
	W(M)=\left\langle\hat{A}(TM) Ch(\Theta(T_\mathbb{C}M)),[M] \right\rangle,
\end{equation*}
where
\begin{equation*}
	\Theta(T_{\mathbb{C}}M)=\underset{m=1}{\overset{\infty}{\bigotimes}} S_{q^{m}}(T_{\mathbb{C}}M-\mathbb{C}^{4k})
\end{equation*}
is the Witten bundle where $q=e^{2\pi\sqrt{-1} \tau}$ with $Im(\tau)\geq 0$. Also,
		\begin{equation*}
			S_{q^m} (T_{\mathbb{C}}M-\mathbb{C}^{4k}) :=\sum^\infty_{k=0}(S^k (T_{\mathbb{C}}M-\mathbb{C}^{4k}))(q^m)^k,
		\end{equation*}
where $S^k(T_\mathbb C M-\mathbb C^{4k})$is the k-th symmetric power of the formal difference $T_\mathbb C M-\mathbb C^{4k}$ in the K-theory.
To manifest the modular aspects of Witten genus, following \cite{liu1996elliptic}, we can also write it as
\begin{equation*}
	W(M)=\left\langle\prod_{i}\frac{z_i \theta'(0,\tau)}{\theta(z_i,\tau)},[M]\right\rangle
\end{equation*}
where $\{\pm 2\pi\sqrt{-1}z_i,1\leq i\geq 2k\}$ are the formal Chern roots of the bundle $T_{\mathbb{C}}M$.

The oriented manifold $M$ is called \textbf{spin} if the  second Stiefel-Whitney class $w_2(TM)$ vanishes. Moreover, manifold $M$ is called \textbf{string} if the half first Pontryagin class vanishes. According to the Atiyah-Singer index theorem, when manifold is spin, the Witten genus is an integral expansion in terms of $q$ (cf. \cite{hirzebruch1992manifolds}). It is also well known that if the manifold is string, the Witten genus is a modular form of weight $2k$ over $SL(2,\mathbb{Z})$ with integral Fourier expansion (\cite{zagier1988note}).
Analogous to Lichnerowicz's classical result on $\hat{A}$ genus (cf. \cite{lawson2016spin}), which stated that $\hat{A}$ genus on spin manifold with positive scalar curvature vanishes, Stolz conjectured that the Witten genus on string manifold with positive Ricci curvature vanishes(for the original arguments, cf. \cite{stolz1996conjecture}, and for a review cf. \cite{dessai2009some}).

Toward the Stolz's conjecture, several vanishing results have been discovered. There are basically two types of methods. One is to apply the theorem of \cite{dessai1994witten} which is based on \cite{liu1995modular} when the manifold admits some nontrivial action of a semi-simple Lie group. The current results via this method include:
\begin{enumerate}
\item String homogeneous spaces of compact semi-simple Lie groups.(\cite{dessai1994witten,liu1995modular}.
\item Total spaces of fiber bundles with fiber $G/H$, with compact semi-simple structure group $G$ \cite{stolz1996conjecture}.
\item Generalized string complete intersection in irreducible, compact, Hermitian, symmetric spaces\cite{forster2007stolz}.
\item String manifold with effective torus action such that $dim\  T>b_2(M)$ \cite{wiemeler2017note}, where $T$ is a compact torus and $b_2(M)$ is the second Betti number of $M$.
\end{enumerate}

Alternatively, sometimes, one can reduce the calculation of Witten genus to calculation of residues. This method was first used by Landweber and Stone \cite{hirzebruch1992manifolds}, which is purely computational and more direct. The vanishing results include:
\begin{enumerate}
\item String complete intersection in projective space\cite{hirzebruch1992manifolds}.
\item String generalized complete intersection in products of projective spaces \cite{chen2008witten}。
\item String complete intersection in products of Grassmannians and flag manifolds\cite{zhou2014witten,zhuang2016vanishing}。
\end{enumerate}
This method also has many applications in elliptic genus, e.g., \cite{ma2005elliptic,gorbounov2008mirror}.
In this paper we generalize the result of~\cite{chen2008witten} to string complete intersections in Toric varieties. We mainly follow the second method in our calculation and also borrow the techniques of equivariant localization in \cite{dessai2016torus}.

\subsection*{Main Result}
Consider a symplectic toric variety $X$ with a set of  invariant divisors $\{D_{\rho_j}\}_{1\leq j\leq r}$ and of Picard number $k$. Choose a basis $\{q_1,...,q_k\}$ of the Picard group to expand all the invariant divisors with integer coefficients
\begin{equation*}
D_{\rho_j}=\left\{
\begin{aligned}
& q_j & 1\leq i\leq k\\
& \sum_{i=1}^k m_{j i} q_i  &k+1\leq j\leq r.
\end{aligned}
\right.
\end{equation*}
Consider a smooth complete intersection $Y\subset X$ as a generic intersection of $s$ hypersurfaces $\{Y_l\}_{1\leq l\leq s}$. Each $Y_l$ is dual to the cohomology class $\sum_{j}^k d_{l i} q_i$.
\begin{thm}\label{thm:main}
When the integer matrix elements $(m_{ji})$ and $(d_{ji})$ satisfy
$$
\sum_{j=1}^n d_{ji} d_{j l}-\sum_{j=k+1}^r m_{ji}m_{j l}=0 \text{  for } i\neq l.
$$
and
$$
\sum_{j=1}^n d_{ji}^2-\sum_{j=k+1}^r m_{ji}^2-1=0,
$$
then the complete intersection $Y$ is string and its Witten genus vanishes.
\end{thm}
\section{Preparations}
We will gather all the necessary notions and lemmas in this section.
\begin{dfn}
$M$ is a $4k$-dimensional compact oriented manifold with a real vector bundle $E$  of rank $2n$, the \textbf{Witten class} of $E$ is defined to be
$$
\mathcal{W}(E,M):=\hat{A}(E)Ch(\Theta(E\otimes \mathbb C)).
$$
\end{dfn}
One can check that Whitney product formula holds for Witten class, i.e. for an exact sequence of real vector bundle $0\rightarrow E\rightarrow F\rightarrow G\rightarrow 0$, we have
$$
\mathcal{W}(E)\cdot\mathcal{W}(G)=\mathcal{W}(F).
$$

It is customary to choose Chern roots $\{\pm 2\pi\sqrt{-1}z_i,1\leq i\geq 2k\}$, which simplifies the Witten genus to
\begin{equation*}
	W(M)=\left\langle\prod_{i}\frac{z_i \theta'(0,\tau)}{\theta(z_i,\tau)},[M]\right\rangle,
\end{equation*}
where $\theta(x,\tau)$ is the first Jacobi theta function.
\subsection*{Global Residue Theorem}
First, we recall the residue theorem (Chapter 5 of~\cite{Griffiths1994principles}). Let $M$ be a compact complex manifold of dimension $s$. Suppose that $D_i$ for $i=1,...,m$ are effective divisors, the intersection of which is a finite set of points. Let $D=D_1+...+D_m$. Let $\omega$ be a meromorphic $m-$form on $M$ with polar divisor $D$. For each point $P\in D_1\cap...\cap D_m$, we may restrict $\omega$ to a neighborhood $U_P$ of $P$ and define the residue at $P$, denoted by $Res_P\omega$. Then, one has:
\begin{lemma}(Residue theorem).
$$
\sum_{P\in D_1\cap...\cap D_m} Res_P\omega=0.
$$
\end{lemma}
\subsubsection*{Jacobi Theta Functions}
We collect all the necessary fact of Jacobi theta function here, all of which can be found in \cite{chandrasekharan1985elliptic}. The theta functions are defined as follows:
\begin{equation*}
\begin{aligned}
	\theta (v,\tau ) & =2 q^{1/8} \sin(\pi  v) \prod _{j=1}^{\infty } \left[\left(1-q^j\right) \left(1-e^{2 \pi  i v} q^j\right) \left(1-e^{-2 \pi  i v} q^j\right)\right],\\
	\theta _1(v,\tau )& =2 q^{1/8} \cos(\pi  v) \prod _{j=1}^{\infty } \left[\left(1-q^j\right) \left(1+e^{2 \pi  i v} q^j\right) \left(1+e^{-2 \pi  i v} q^j\right)\right],\\
\end{aligned}
\end{equation*}
\begin{equation*}
\begin{aligned}
	\theta _2(v,\tau )&=\prod _{j=1}^{\infty } \left[\left(1-q^j\right) \left(1-e^{2 \pi  i v} q^{j-\frac{1}{2}}\right) \left(1-e^{-2 \pi  i v} q^{j-\frac{1}{2}}\right)\right],\\
	\theta _3(v,\tau )&=\prod _{j=1}^{\infty } \left[\left(1-q^j\right) \left(1+e^{2 \pi  i v} q^{j-\frac{1}{2}}\right) \left(1+e^{-2 \pi  i v} q^{j-\frac{1}{2}}\right)\right],
\end{aligned}
\end{equation*}
where $q=e^{2\pi\sqrt{-1} \tau}$ with $Im(\tau)\geq 0$. We also have the Jacobi identity:
\begin{equation*}
\theta '(0,\tau )=\frac{\partial }{\partial v}\theta (v,\tau )|_{v=0}=\pi\theta_1(0,\tau )\theta _2(0,\tau )\theta _3(0,\tau ).
\end{equation*}
They satisfy the transformation law under the translation on lattice $\{\mathbb Z+b\mathbb Z\}$
\begin{equation}\label{theta}
\begin{aligned}
\ &\theta (v+m,\tau ) =(-1)^m\theta (v,\tau ),& &\theta (v+n \tau ,\tau )=(-1)^n e^{ -2 \pi  i n v-\pi  i n^2 \tau}\theta (v,\tau ),\\
\ &\theta_1 (v+m,\tau ) =(-1)^m\theta_1 (v,\tau ),& &\theta_1 (v+n \tau ,\tau )= e^{ -2 \pi  i n v-\pi  i n^2 \tau}\theta_1 (v,\tau ),\\
\ &\theta_2 (v+m,\tau ) =\theta_2 (v,\tau ), & &\theta_2 (v+n \tau ,\tau )=(-1)^n e^{ -2 \pi  i n v-\pi  i n^2 \tau}\theta_2 (v,\tau ),\\
\ &\theta_3 (v+m,\tau ) =\theta_3 (v,\tau ),& &\theta_3 (v+n \tau ,\tau )= e^{ -2 \pi  i n v-\pi  i n^2 \tau}\theta_3 (v,\tau ).
\end{aligned}
\end{equation}
\subsection*{Equivariant Localization and Genera as Residues}

There is a ring morphism between the ordinary cohomology ring $H^\bullet(X,\mathbb{Q})$ and the equivariant cohomology ring $H_{T}^{\bullet}(X,\mathbb{Q})$. $H^\bullet_T(X_\Sigma)$ can be thought of as an $H^\bullet(BT)$-module. Note also that the inclusion of a fiber $i_{X}: X_\Sigma\rightarrow X\times_G EG$ induces the ``Non-equivariant limit'' map $i^*_X: H^\bullet_T(X_\Sigma)\rightarrow H^\bullet(X_\Sigma)$, which amounts to mapping all $\lambda_i$ to 0. In the case of toric varieties, there is a equivariant version of Jurkiewicz-Danilov Theorem, see Chapter 12 of \cite{cox2009toric}
\begin{lemma}
Every $D_\rho$ has an equivariant counterpart $(D_\rho)_T$, where $\rho\in \Sigma(1)$. This map induces the morphism between cohomology and their equivariant counterpart.
\begin{equation*}
\begin{aligned}
D_\rho & \longrightarrow (D_{\rho})_T=D_\rho-\lambda_\rho\in H^2_T(X,\mathbb Q)\\
 H^\bullet (X,\mathbb Q)&\longrightarrow H^\bullet_T(X_\Sigma,\mathbb{Q})=\mathbb{Q}[(D_{\rho_1})_T,...,(D_{\rho_r})_T]/(\mathcal{I}_T+\mathcal{J}_T)\\
\end{aligned}
\end{equation*}
where
\begin{equation*}
\mathcal{I}_T = \langle (D_{i_1})_T\cdot\cdot\cdot (D_{i_s})_T | i_j \text{ are distinct and } \rho_{i_1}+...+\rho_{i_s} \text{ is not a cone of } \Sigma\rangle
\end{equation*}
and $\mathcal{J}_T$ is the ideal generated by the linear forms
\begin{equation*}
\sum_{i}^r\langle m, u_i \rangle (D_{\rho_i})_T
\end{equation*}
where $m$ ranges over $M$ (or equivalently, over some basis for $M$).
\end{lemma}

We can find an explicit way to proceed calculations via the Atiyah-Bott localization. The following formula can be found in \cite{givental1998mirror}
\begin{lemma}
$f(q_1,...,q_k,\{\lambda_i\})$ is a polynomial in $H^\bullet_T(X,\mathbb Q)$, integrating it over the fundamental class $[X]$ maps it into $\mathbb Q[\lambda_1,...,\lambda_r]$. Explicitly, we have
\begin{equation}\label{localization}
\int_{X} f(q_1,...,q_k,\{\lambda_i\})=\sum_\alpha Res_\alpha \frac{f(q_1,...,q_k,\{\lambda_i\})}{(D_1)_T\cdot (D_2)_T\cdot ...\cdot (D_r)_T} d q_1 dq_2...dq_k.
\end{equation}
The symbol $Res_\alpha$ refers to the residue of the $k-$form at the pole by the order set of equations
$$
\sum^k_{i=1}p_i m_{i j_s}=\lambda_s,\ s=1,...,k
$$
\end{lemma}

\section{Main Results}
From now on, we will abuse the notation to write $D_\rho$ instead of $[D_\rho]$ as the cohomology classes and divisor classes. We consider a smooth compact toric variety $X_\Sigma$ corresponding to $\Sigma\in N_\mathbb R$, where $N$ is a lattice of dimension $n$ and $M$ being its dual lattice. Let $\Sigma(1)$ denote the set of one dimensional cones in $\Sigma$ and assume that $|\Sigma(1)|=r$. By Proposition 4.2.1 and 4.2.5 in \cite{cox2009toric}, we know $\text{Pic}(X_\Sigma)$ is torsion-free and
\begin{equation*}
0\longrightarrow M\longrightarrow \mathbb Z^r\longrightarrow \text{Pic}(X_\Sigma)\longrightarrow 0.
\end{equation*}
If we set the Picard number $k$, we have the relation
\begin{equation*}
	\text{dim }X_\Sigma =\text{dim }N=n=r-k.
\end{equation*}
After we quotient the ideal generated by the linear relations, we can equivalently say that the cohomology ring is multiplicatively generated by a basis of the Picard group. We denote the basis of Picard group as $q_1,...q_k$, and express the invariant divisors as
\begin{equation*}
D_{\rho_i}=\left\{
\begin{aligned}
& q_i & 1\leq i\leq k\\
& \sum_{j=1}^k m_{i j} q_j  &k+1\leq i\leq r
\end{aligned}
\right.
\end{equation*}
Then let's consider a smooth complete intersection $Y$ as a generic intersection of $s$ hypersurfaces $\{Y_l\}_{1\leq l\leq s}$. Each $Y_l$ is dual to the cohomology class $\sum_{j}^k d_{l j} q_j$. In the context of smooth manifold, by the transversality argument, one can always deform the hypersurfaces (not algebraic now) so that they intersects transversally. Thus $Y$ is submanifold of complex dimension $r-k-s$. In this section we will consider the Witten genus on $Y$. From now on, we will use both $X:=X_\Sigma$ to denote the toric variety, when there is no confusion.
\subsection{Proof of Theorem~\ref{thm:main}}
For smooth toric varieties, there is a \textbf{generalized Euler sequence}( see Theorem 8.1.6 in \cite{cox2009toric}).
\begin{equation*}
0\longrightarrow \mathcal{O}_{X_\Sigma}^{\oplus k}\longrightarrow\oplus_{\rho\in \Sigma(1)}\mathcal{O}_{X_\Sigma}(D_\rho)\longrightarrow TX_{\Sigma}\longrightarrow0,
\end{equation*}
where $k$ is the rank of $\text{Pic}(X_\Sigma)$ or equivalently the rank of $H^2(X_\Sigma,\mathbb{Z})$.
from which we can calculate the total Chern class and all the multiplicative genera of $TX_{\Sigma}$.

The $\mathcal{O}_{X_\Sigma}(D_\rho)$ is the line bundle defined by the divisor $D_\rho$ in the Picard group, of which the first Chern class is $D_\rho\in H^2(X_\Sigma,\mathbb Z)$.
Then by the multiplicative property of total Chern class, we have
\begin{equation*}
	c(TX_\Sigma)=\oplus_{\rho\in\Sigma(1)}\  c(\mathcal{O}_{X_\Sigma}(D_\rho))=\prod_{\rho\in \Sigma(1)}(1+D_\rho).
\end{equation*}
The $\{D_\rho\}$ play the role of Chern roots here, which is not coincidence.
For a general multiplicative genus $\varphi_Q$ corresponding to even power series $Q(x)$, we observe that
\begin{equation*}
\varphi_Q(TX_\Sigma)=\frac{\varphi_Q\left(\bigoplus_{\rho\in \Sigma(1)}\mathcal{O}(D_\rho)\right)}{\varphi_Q(\mathcal{O}(X_\Sigma)^{\oplus k})}=\frac{\prod_{\rho\in \Sigma(1)} Q(D_\rho)}{Q(0)^k},
\end{equation*}
In the case of Witten genus, we have
\begin{equation*}
\begin{aligned}
\mathcal{W}(T_\mathbb R X)&=\prod_{\rho\in \Sigma(1)}D_\rho \frac{\theta'(0,\tau)}{\theta(D_\rho,\tau)},\\
W(X_\Sigma)&=\left\langle\mathcal{W}(X_\Sigma),[X_\Sigma]\right\rangle
\end{aligned}
\end{equation*}
Consider the inclusion map $\iota: Y\rightarrow X_\Sigma$, we have the adjunction formula:
$$
0\longrightarrow TY\longrightarrow\iota^*TX_{\Sigma}\longrightarrow\iota^* N_Y X\longrightarrow0,
$$
where the normal bundle $N_Y X$ is isomorphic to $\bigoplus_{l=1}^s\mathcal{O}(\sum_{j}^k d_{l j} q_j)$.
By the multiplicative properties of Chern class, we have the following data:
\begin{equation*}
c(TY)=\iota^*\left(\frac{c(TX)}{c(N_Y X)}\right)=\iota^*\left(\frac{\prod_{i=1}^k (1+q_i)\prod_{j=k+1}^{r}(1+\sum_{i=1}^k m_{ji}q_i)}{\prod_{l=1}^s(1+\sum_{j}^k d_{l j} q_j)}\right).
\end{equation*}
Following these we have
$$
\begin{aligned}
w_2(T_\mathbb{R}Y)& \equiv c_1(TY) (\text{mod } 2)\\
& =\iota^*\left(\sum_{i=1}^k q_i+\sum_{j=k+1}^{r} \sum_{i=1}^k m_{ji}q_i-\sum_{l=1}^s\sum_{i=1}^k d_{l i}q_i\right) \text{     (mod } 2)
\end{aligned}
$$
and
$$
p_1(T_{\mathbb{R}}Y)=\iota^*\left(\sum_{i=1}^k q_i^2+\sum_{j=k+1}^r (\sum_{i=1}^k m_{ji}q_i)^2-\sum_{l=1}^s(\sum_{i=1}^k d_{l i}q_i)^2\right).
$$
Because we know little about the $H^4(X,\mathbb Z)$, it is difficult to tell whether the above presentation of Pontryagin class vanishes in the general case. Still, we know the complete intersection is string when all the coefficients of $\{q_i q_j\}$ vanishes. On the other hand, because of the multiplicative property of Witten class, we have
\begin{equation*}
\begin{aligned}
\mathcal{W}(T_\mathbb R Y)
&=\iota^*\left(\frac{\mathcal{W}(T_\mathbb R X)}{\mathcal{W}((N_Y X)_\mathbb R)}\right)\\
&=\iota^*\left(\frac{\prod_{i=1}^k q_i \frac{\theta'(0,\tau)}{\theta(q_i,\tau)}\prod_{j=k+1}^r (\sum_{t=1}^k m_{j t}q_t) \frac{\theta'(0,\tau)}{\theta(\sum_{t=1}^k m_{jt}q_t,\tau)}}{\prod_{l=1}^s(\sum_{j=1}^k d_{l j} q_j) \frac{\theta'(0,\tau)}{\theta(\sum_{j=1}^k d_{l j} q_j,\tau)}}\right).
\end{aligned}
\end{equation*}
Integrate the above formula over the fundamental class of Y, we have
$$
\begin{aligned}
&\int_{Y} \mathcal{W}(T_\mathbb R Y) \\
& =\int_X \iota_!\iota^*\left(\frac{\mathcal{W}(T_\mathbb R X)}{\mathcal{W}((N_Y X)_\mathbb R)}\right)\\
& =\int_X \left(\frac{\mathcal{W}(T_\mathbb R X)}{\mathcal{W}((N_Y X)_\mathbb R))}\right)\smile e(N_Y X)\\
& =\int_X \left(\frac{\prod_{i=1}^k q_i \frac{\theta(q_i,\tau)}{\theta'(0,\tau)}\prod_{j=k+1}^r (\sum_{t=1}^k m_{j t}q_t) \frac{\theta(\sum_{t=1}^k m_{jt}q_t,\tau)}{\theta'(0,\tau)}}{\prod_{l=1}^s(\sum_{j=1}^k d_{l j} q_j) \frac{\theta(\sum_{j=1}^k d_{l j} q_j,\tau)}{\theta'(0,\tau)}}\right)\cdot \prod_{l=1}^s(\sum_{j=1}^k d_{l j} q_j)\\
& =\int_X \left(\frac{\prod_{i=1}^k q_i \frac{\theta(q_i,\tau)}{\theta'(0,\tau)}\prod_{j=k+1}^r (\sum_{t=1}^k m_{jt}q_t) \frac{\theta(\sum_{t=1}^k m_{jt}q_t,\tau)}{\theta'(0,\tau)}}{\prod_{l=1}^s \frac{\theta(\sum_{j=1}^k d_{l j} q_j,\tau)}{\theta'(0,\tau)}}\right),
\end{aligned}
$$
where $e(N_Y X)$ in the second line is the Euler class of the normal bundle.

If we take the non-equivariant limit we can get an explicit formula to calculate the the integration of $f(p,0)$ over the fundamental class $[X]$.
\subsection{Vanishing result for some string complete intersection}
What we want to calculate is
\begin{equation*}
\begin{aligned}
\int_{Y} \mathcal{W}(T_\mathbb R Y)
& =\int_X \iota_!\iota^*\left(\frac{\mathcal{W}(T_\mathbb R X)}{\mathcal{W}((N_Y X)_\mathbb R)}\right)\\
& =\int_X \left(\frac{\prod_{i=1}^k q_i \frac{\theta'(0,\tau)}{\theta(q_i,\tau)}\prod_{j=k+1}^r (\sum_{t=1}^k m_{jt}q_t) \frac{\theta'(0,\tau)}{\theta(\sum_{t=1}^k m_{jt}q_t,\tau)}}{\prod_{l=1}^s \frac{\theta'(0,\tau)}{\theta(\sum_{j=1}^k d_{l j} q_j,\tau)}}\right).
\end{aligned}
\end{equation*}
Note that the complete intersection $Y$ is generally not invariant under the action of torus, but remember that $TX_\Sigma$ and $N_Y X\cong {\cal O}(\sum^k_j d_{lj} q_j)$ are invariant bundles, we know that the differential form on the right hand side is invariant.
With the localization argument before, we can consider a integral of polynomial $\mathcal{W}(q,\{\lambda_i\})$ in $H^\bullet_T(X,\mathbb Q)$ which under nonequivariant limit gives the integral we want. The choice is not unique. We can choose

\begin{equation*}
\begin{aligned}
&\int_{Y} \mathcal{W}(T_\mathbb R Y)\\
& =i_X^*\int_X \left(\frac{\prod_{i=1}^k (q_i-\lambda_i) \frac{\theta'(0,\tau)}{\theta(q_i-\lambda_i,\tau)}\prod_{j=k+1}^r (\sum_{t=1}^k m_{jt}q_t-\lambda_j) \frac{\theta'(0,\tau)}{\theta(\sum_{t=1}^k m_{jt}q_t-\lambda_j,\tau)}}{\prod_{l=1}^s \frac{\theta'(0,\tau)}{\theta(\sum_{j=1}^k d_{l j} q_j,\tau)}}\right)\\
\end{aligned}
\end{equation*}
Then by Eq.~\ref{localization},
\begin{equation*}
\begin{aligned}
&\int_{Y} \mathcal{W}(T_\mathbb R Y) \\
& =i_X^*\sum_\alpha res_\alpha \frac{\left(\frac{\prod_{i=1}^k (q_i-\lambda_i) \frac{\theta'(0,\tau)}{\theta(q_i-\lambda_i,\tau)}\prod_{j=k+1}^r (\sum_{t=1}^k m_{jt}q_t-\lambda_j) \frac{\theta'(0,\tau)}{\theta(\sum_{t=1}^k m_{jt}q_t-\lambda_j,\tau)}}{\prod_{l=1}^s \frac{\theta'(0,\tau)}{\theta(\sum_{j=1}^k d_{l j} q_j,\tau)}}\right)}{\prod_{i=1}^k (q_i-\lambda_i)\prod_{j=k+1}^r (\sum_{t=1}^k m_{jt}q_t-\lambda_j)}\\
& =i_X^*\sum_\alpha res_\alpha\left(\frac{\prod_{l=1}^s \frac{\theta(\sum_{j=1}^k d_{l j} q_j,\tau)}{\theta'(0,\tau)}}{\prod_{i=1}^k  \frac{\theta(q_i-\lambda_i,\tau)}{\theta'(0,\tau)}\prod_{j=k+1}^r  \frac{\theta(\sum_{t=1}^k m_{jt}q_t-\lambda_j,\tau)}{\theta'(0,\tau)}}\right)dq_1...dq_k\\
&=\lim_{\lambda_i\rightarrow0}\sum_\alpha res_\alpha \frac{g(q,\tau)}{\prod_{j=1}^r f_j (q,\tau,\{\lambda_i\})}dq_1...dq_k,
\end{aligned}
\end{equation*}
where
\begin{equation*}
\begin{aligned}
g(q_1,..,q_k,\tau)=\prod_{l=1}^s\frac{\theta(\sum_{j=1}^k d_{l j} q_j,\tau)}{\theta'(0,\tau)}
\end{aligned}
\end{equation*}
and
\begin{equation*}
f_j(q_1,...,q_k,\tau,\{\lambda_i\})=\left\{
\begin{aligned}
&\frac{\theta(q_j-\lambda_j,\tau)}{\theta'(0,\tau)} & \text{ for } 1\leq j\leq k\\
& \frac{\theta(\sum_{t=1}^k m_{jt}q_t-\lambda_j,\tau)}{\theta'(0,\tau)} &\text{for } k+1\leq j\leq r
\end{aligned}
 \right.
\end{equation*}
Let's analyze how $g$ and $f$ transform under the translation over the lattice $\{\mathbb Z+\mathbb Z \tau\}$. By the transforming laws of theta functions[\ref{theta}], without loss of generality, $q_1\rightarrow q_1+1$.
\begin{equation*}
	g(q_1+1,...,q_k,\tau)=(-1)^{d_{11}+...+d_{s1}}g(q_1,...,q_k,\tau),
\end{equation*}
\begin{equation*}
f_j(q_1+1,...,q_k,\tau,\{\lambda_i\})=\left\{
\begin{aligned}
	& - f_1(q_1,...,q_k,\tau,\{\lambda_i\})&\text{for $j=1$}\\
	& f_j(q_1,...,q_k,\tau,\{\lambda_i\})&\text{for $j \neq 1$ and $j\leq k$} \\
	& (-1)^{m_{j1}} f_j (q_1,...,q_k,\tau,\{\lambda_i\})&\text{for $k+1\leq j\leq r$}
\end{aligned}
\right.
\end{equation*}
Then,
\begin{equation*}
\begin{aligned}
&\frac{g(q_1,...,q_i+1,...,q_k,\tau)}{\prod_{j=1}^r f_j (q_1,...,q_i+1,...,q_k,\tau,\{\lambda_i\})}\\
&=(-1)^{\sum_{j=1}^s d_{ji}-\sum_{j=k+1}^r m_{ji}-1}\frac{g(q_1,...,q_k,\tau)}{\prod_{j=1}^r f_j (q_1,...,q_k,\tau,\{\lambda_i\})}.
\end{aligned}
\end{equation*}
On the other hand under the translation $q_1\rightarrow q_1+\tau$, we have
\begin{equation*}
g(q_1+\tau,...,q_k,\tau)
=(-1)^{d_{11}+...,d_{s1}} e^{-2\pi i\sum_{l=1}^s d_{l1}(\sum^k_j d_{lj}q_j)-\pi i\sum_{l=1}^s d^2_{l1}\tau} g(q_1,...,q_k,\tau),
\end{equation*}
and
\begin{equation*}
\begin{aligned}
&f_j(q_1+\tau,...,q_k,\tau,\{\lambda_i\})=\\
&\left\{
\begin{aligned}
&(-1)e^{-2\pi i (q_1-\lambda_1)-\pi i \tau} f_1(q,\tau,\{\lambda_i\}) &\text{ for $j=1$ }\\
&f_j(q,\tau,\{\lambda_i\}) &\text{ for $i\neq 1$ and $j\leq k$}\\
& (-1)^{m_{j1}} e^{-2\pi i m_{j1}(\sum^k_t m_{jt}q_t-\lambda_j)-\pi i m_{j1}^2 \tau}f_j(q,\tau,\{\lambda_i\})&\text{$k+1 \leq j\leq r$}
\end{aligned}
\right.
\end{aligned}
\end{equation*}
Then the we have the transforming law
\begin{equation*}
\begin{aligned}
&\frac{g(q_1,...,q_i+\tau,...,q_k,\tau)}{\prod_{j=1}^r f_j (q_1,...,q_i+\tau...,q_k,\tau,\{\lambda_i\})}\\
&=(-1)^{\sum_{t=1}^s d_{ti}-\sum_{t=k+1}^r m_{ti}-1}\\
&\times e^{-2\pi \sqrt{-1}[\sum_{v\neq i}^k(\sum_{t}^s d_{t i} d_{tv}-\sum_{u=k+1}^r m_{u i} m_{uv})q_v+(\sum_{t=1}^s d_{ti}^2-\sum^r_{u=k+1}m_{ui}^2-1)q_i-\lambda_i+\sum_{u=k+1}^r m_{ui}\lambda_u]}\\
&\times e^{-\pi \sqrt{-1}(\sum_{t=1}^s d_{ti}^2-\sum^r_{u=k+1}m_{ui}^2-1)\tau}\\
&\times \frac{g(q_1,...,q_i,...,q_k,\tau)}{\prod_{j=1}^r f_j (q_1,...,q_i...,q_k,\tau,\{\lambda_i\})}
\end{aligned}.
\end{equation*}
Remember that
\begin{equation*}
\begin{aligned}
w_2(T_\mathbb{R}Y)& \equiv c_1(TY) (\text{mod } 2)\\
& =\iota^*\left(\sum_{i=1}^k q_i(1+\sum_{j=k+1}^{r} m_{ji}-\sum_{l}^s d_{l i})\right) \text{     (mod } 2),
\end{aligned}
\end{equation*}
and
\begin{equation*}
\begin{aligned}
p_1(T_{\mathbb{R}}Y)&=\iota^*\left(\sum_{i=1}^k q_i^2+\sum_{j=k+1}^r (\sum_{i=1}^k m_{ji}q_i)^2-\sum_{l=1}^s(\sum_{i=1}^k d_{l i}q_i)^2\right)\\
&=\iota^*\left(\sum_{i=1}^k q_i^2(1+\sum_{j=k+1}^r m_{ji}^2-\sum_{l=1}^s d_{l i}^2)+\sum_{i=1}^k\sum_{l=1}^k q_i q_l(\sum^r_{j=k+1}m_{ji}m_{jl}-\sum_{u}^s d_{u i}d_{ul})\right)\\
\end{aligned}
\end{equation*}
Also notice that, when
\begin{equation*}
1+\sum_{j=k+1}^r m_{ji}^2-\sum_{l=1}^s d_{l i}^2=0,
\end{equation*}
$\omega_2(T_\mathbb R Y)$ vanishes automatically because
\begin{equation*}
\sum_{j=k+1}^r m_{ji}^2-\sum_{l=1}^s d_{l i}^2\equiv \sum_{j=k+1}^{r} m_{ji}-\sum_{l}^s d_{l i}\ (\mod 2).
\end{equation*}
At nonequivariant limit, we take $\lambda_i=0$, assuming
$$
\sum_{j=1}^n d_{ji} d_{j l}-\sum_{j=k+1}^r m_{ji}m_{j l}=0 \text{  for } i\neq l.
$$
and
$$
\sum_{j=1}^n d_{ji}^2-\sum_{j=k+1}^r m_{ji}^2-1=0,
$$
then the complete intersection $Y$ is string and
the function
\begin{equation*}
\frac{g(q,\tau)}{\prod_{j=1}^r f_j (q,\tau,0)}
\end{equation*}
is elliptic over the lattice $\Gamma:=\{\mathbb Z+\mathbb Z\tau\}$. Then equivalently, we
can regard
\begin{equation*}
\frac{g(q,\tau)}{\prod_{j=1}^r f_j (q,\tau,0)}dq_1...dq_k
\end{equation*}
as a meromorphic form over the compact torus $(\mathbb C/\Gamma)^s$.
Then by the global residue theorem, the Witten genus
\begin{equation*}
\begin{aligned}
&\int_{Y} \mathcal{W}(T_\mathbb R Y) \\
&=\sum_\alpha res_\alpha \frac{g(q,\tau)}{\prod_{j=1}^r f_j (q,\tau,0)}dq_1...dq_k,
\end{aligned}
\end{equation*}
vanishes.
\begin{flushright}
\qedsymbol
\end{flushright}
\begin{cor}
In the special case where the toric variety is  product of projective spaces of the form $\mathbb{P}^{n_1}\times \mathbb{P}^{n_2}\times\cdot \cdot \cdot \times \mathbb{P}^{n_t}$, then
up to reordering, the matrix $m_{ij}$ can be written as
$$
\begin{pmatrix}
\underbrace{1,1,...,1}_{n_{1}} & 0 & \dots  & 0\\
0 & \underbrace{1,1,...,1}_{n_{2}} & \dots  & 0\\
\vdots  & \vdots  & \ddots  & \vdots \\
0 & 0 & \dots  & \underbrace{1,...,1}_{n_{k}}
\end{pmatrix}.
$$
The vanishing condition reduces to
$$
\sum_{j=1}^n d_{ji} d_{j l}=0 \text{  for } i\neq l.
$$
and
$$
\sum_{j=1}^n d_{ji}^2-n_i-1=0,
$$
which reproduces the result of~\cite{chen2008witten}.
\end{cor}
\section*{Acknowledgement}
This paper is a short version of the author's Master thesis.
I am grateful to Doctor Qingtao Chen for a lot of discussion and help on the Witten genus. I also thanks Doctor Honglu Fan for inspiring suggestions on toric varieties.  I would like to thank Professor Ana da Silva for her kind help in clarifying some doubts about symplectic toric variety. Special thank goes to Professor Giovanni Felder. Thanks to his patient discussion and sharp questions, I managed to correct the false understandings of some black-boxes.

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