text:
The Best Pet-Friendly Hotels in Vancouver
The Fairmont's Canine Ambassador, Ella | © Fairmont Hotels Vancouver
Hayley Simpson
Writer21 July 2017
Vancouver is a very pet-friendly city, with many off-leash areas, dog-friendly beaches, and open patios at breweries and restaurants. Fortunately, many hotels in the city also offer accommodation for your furry friend. Check out these amazing pet-friendly hotels in Vancouver.
The Westin Bayshore, Bayshore Drive
BusinessFamily
Enjoying the Heavenly Dog Bed® | © The Westin Bayshore Vancouver
Unavailable for the next 3 months
"It's a Heavenly Dog's Life in Vancouver." At the Westin Bayshore Vancouver, the staff will treat your pet like one of the family. Guests can bring one dog per room free of charge, as long as they are a maximum of 18 kilograms (40 pounds). Your pet is made comfortable with the Heavenly Dog Bed®, as well as food and water dishes in the room. The Concierge team is available to make dog-walking or sitting arrangements or to suggest dog-friendly activities. Fortunately, the hotel is within walking distance to Stanley Park so that guests don't have to go far for a scenic walk.
Georgian Court Hotel, Vancouver
BusinessRomanticLuxury
4.6/5 (1534 Reviews)
A member of the Small Luxury Hotels of the World group, the Georgian Court Hotel lies steps away from Rogers Arena and BC Place—the city's two big sports and entertainment stadiums. With no weight limits, all dogs are welcome at the hotel in designated guest rooms. Dog biscuits, food and water bowls, and a blanket are available upon arrival. The friendly staff at the front desk can also help with information on the best nearby dog-friendly parks and beaches, pet-sitting services, and can even secure reservations for you at pet-friendly restaurants.
Best Western Plus Sands, Vancouver
Located on lively Davie Street, the Best Western Plus Sands Hotel is a very central—and economical—pet-friendly accommodation option in Vancouver. There is a maximum of two pets per room, which can be dogs, cats, or even birds! Fortunately, there's no size restriction and a small charge of $14 per night. Each pet receives a gift bag that holds treats, emergency food, waste bags, a toy, and a local dog park guide. Dog beds and towels are available by request too. Other great amenities at the Best Western Plus Sands Hotel include two restaurants, as well as a fitness room with sauna.
BusinessFamilyRomanticLuxurySki
Known as Vancouver's "Castle in the City," this Fairmont hotel will treat you and your pooch like royalty. Fairmont properties in Canada are well-known for having canine ambassadors that greet guests in the lobby. Ella is the ambassador at Fairmont Hotel Vancouver. For $25 CAD per day, guests and their pet receive a welcome mat, dish, delicious handmade treats, a toy, and a pet activities information sheet. The same pet-friendly policy is in effect at other Fairmont hotels in Vancouver too, such as Fairmont Pacific Rim.
Pinnacle Hotel Harbourfront, Vancouver
BusinessFamilySki
Pinnacle Hotel Harbourfront truly is your home away from home. Amenities—besides being pet-friendly—include hotel cars, hotel bikes (seasonal availability), a pool, a fitness room, and live music events at the on-site P2B Bistro & Bar. At $35 per stay, pets at the Pinnacle Hotel Harbourfront receive a deep clean, food bowls, and a plush memory foam pet bed. Ensure you select the pet-friendly package when booking your accommodation through the hotel's website.
Hyatt Regency Vancouver
BusinessFamilyLuxury
Hyatt has an unbeatable reputation around the world. Fortunately, that has extended to allowing pets in their lower floor hotel rooms (for easy outside access) at the Hyatt Regency Vancouver on Burrard Street in downtown Vancouver. Dogs must weigh less than 23 kilograms (50 pounds), but two dogs are allowed as long as their combined weight is under 34 kilograms (75 pounds). There is a $100 fee for the first six nights, and pets receive a bowl and dog bed.
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Loden Hotel, Vancouver
Home at the Loden Hotel | © Loden Hotel
The Loden Hotel loves animals. They support the SPCA through various charitable efforts and even used past rescues in their promotional images. Four-legged friends, both big and small, are welcome at The Loden Hotel. There is a $45 per pet, per stay fee. The goodies awaiting your pet at the hotel include a plush bed, bowls, homemade dog biscuits, a dog walking map, a sanitary kit, and even a copy of Modern Dog Magazine. They can also arrange dog-sitting services as well. Your dog will love the hotel's Coal Harbour location.
Hotel BLU Vancouver
BusinessFamilyRomantic
Hotel Blu is an inexpensive pet-friendly accommodation option. For just $30 per stay, one pet is allowed in a guest room. At check in, pups will be given a special welcome package, which includes a treat, comfy bed, a bowl, and an information pack on city pet by-laws and pet-friendly areas. Hotel Blu's welcome treats come from a local pet store named Bones, which is conveniently located two blocks from the hotel and stocks healthy, natural products.
OPUS Hotel Vancouver
BusinessFamilyRomanticBoutique
OPUS Hotel's stunning on-site bar | © OPUS Hotel
Named one of the five trendiest hotels in the world by TripAdvisor, OPUS Hotel is a stylish property with two bars/restaurants on-site. They also welcome pets of all sizes, for a one-time $30 fee. Each dog receives a bed, bowl and treat, and staff members are even periodically available to take them for a break free of charge. The hotel's Yaletown location is quite handy as well. The off-leash Coopers Park is only two blocks away, and Barking Babies is around the corner, so your pet can pick up a souvenir too.
Granville Island Hotel, Vancouver
Enjoy one of Vancouver's best attractions alongside your pooch at Granville Island Hotel. For $25 per night, your pet can come on vacation with you. The hotel encourages dogs to be under 23 kilograms (50 pounds). Their pet-friendly rooms include tiled floors for easy cleanup and a balcony for pets who prefer the outdoors. There is also a special welcome gift on arrival, which is courtesy of The Granville Island Pet Treatery. The local business specializes in handmade, Canadian products and treats.
From this Article
placesToStay · Vancouver
4/5 (953 Reviews)
More Stays like This


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MusAbility Ltd
About MusAbility
Benefits of Music Therapy
Neurologic Music Therapy
Music Expression People Potential
Neurologic Music Therapy (NMT) is a specialist service and clinical approach within music therapy. Where standard music therapy can be free-flowing, NMT is made up of standardised, research based clinical techniques, which create neurological change for clients. Consequently, as a clinical and precise approach, NMT can track measurable change in all neurological conditions. In short, it can support:
Speech and Communication
Emotional Well-being and Expression
Cognition and learning
We provide full Neurologic Music Therapy assessments and ongoing NMT, and work alone or with full multi-disciplinary teams. These comprehensive assessments inform other health professionals in addition to revealing specific areas that need further input across domains, for instance.
MusAbility are the proud Northern partner of Chiltern Music Therapy. This partnership enables a wide reach for Neurological and Medical services in the UK. It is formed between two organisations founded on similar principals and ethics, and we work closely to provide the best service for our clients through trust and transparency. Read all about them here https://www.chilternmusictherapy.co.uk/
MATADOC Assessment
The Music Therapy Assessment Tool for Awareness in Disorders of Consciousness (MATADOC) is a standardised diagnostic music-based measure validated for use with adults with disorders of consciousness (DOC). The MATADOC provides a rigorous assessment and evaluation for use with people whose awareness is difficult to assess clinically due to complex clinical presentations compromising motor, cognitive and communication functioning. Although validated for adults with DOC, it can be used with other minimally responsive populations including children with DOC, those with profound developmental disabilities, end stage dementia or end stage terminal illness. This tool can be used for complex neurologic or legal cases which require support for a Disorder of Consciousness diagnosis.
What our friends say about us
We use MusAbility for several of our clients who are currently, and have previously been through the medical negligence court system. MusAbility's services are not only professional, timely and evidence-based in their clinical assessments, but the clients also show real developments in long-term work where many other health professionals declared none were possible. A truly inspirational team.
Not only can we see the clear changes in behaviour for the children that attend music therapy…but it's giving the staff new skills and techniques to work with the children that need a little extra support. Just brilliant.
Classroom Teacher, Mainstream School
It is absolutely fascinating to see how this child responds in music therapy…to be surrounded by verbal interaction, then be met in an environment when words are sometimes not used at all…it is incredibly impactive. I think it should be available to every child!
Support Assistant in Mainstream School
I have honestly never seen anything like it…music therapy reaches this child at such a profound level, we are in tears of joy every session, and their development visibly increases week to week.
Teaching Assistant, Specialist School
Some of the children in our school are that bit older…and they really struggle to engage both in the classroom and with staff on a 1:1 basis. Music therapy breaks down all boundaries. They love the sessions, and they think it's so 'cool' that they are pushed to reach their potential…sometimes without even realising it!
Deputy Head Teacher, School for Children with Special Needs
Our music therapist is an integral part of our team. Not only do they engage clinically with the clients, but they also liaise with staff within the multi-disciplinary team…most importantly always putting the client first. We absolutely could not do without music therapy…and our clients wouldn't allow it!
Manager of Specialist Neurological Team
See the difference music can make for you
At MusAbility we believe the client comes first and so will do everything in our power to support and help our clients to reach their maximum potential
© Musability Ltd. 2019 Registered Company No. 08672909
We provide music therapy services across Merseyside,
the North-West of England and North Wales.
MusAbility. Gladstone House, 2 Church Rd, Liverpool, L15 9EG
UK Web design & hosting by BFI®
We use cookies on our websites. You are free to manage this via your browser setting at any time. To learn more about how we use cookies, and how we store, process and protect your personal information, please see our cookie policy.

redpajama_set_name: RedPajamaCommonCrawl


14 weeks or 14 years what's the difference in Dog years?
When Sid gets off his ears then this gives Max a chance to turn into a bull and ram him from the side to help Sid understand who is the boss… not that he believes that for one minute!
When it's all over there's always time for a high 5!
When Sid first landed Max was not impressed but as every day goes by they are getting more connected and I'm sure Max is getting younger.


text:
Q: Where can I Find XML List of USA Cities and States? Can anyone share? Excel format is fine too.

A: Apparently, this is a cleaned up version of the 2000 US Census.
Link to article:
http://mhinze.com/archive/list-of-us-cities-all-city-names-and-states-regex-groups/
Direct link:
http://mhinze.com/static-content/cities.txt
It should be easy to just copy/paste this into excel, and do a "Text to Columns" command using Deliminated by Comma.

A: There's a great basic version here for $20
http://www.zipcodedownload.com/Products/Product/Z5Basic/Standard/Overview/

redpajama_set_name: RedPajamaStackExchange


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In The Games Corner – James Bond 007: Nightfire, Playstation 2
By Holly on 29 Sep 2019 • ( Leave a comment )
When I was at college, I used to have a lot of male friends and in the breaks between terms they used to meet up and play computer games and ever so often I would go along and play as well because I liked playing it and it was always such a laugh (especially seeing how seriously they took it).
One of the games that these guys used to be obsessed with was James Bond – you had to try and kill your opponents as may times as possible – it was a lot of fun and the maps were always exciting.
James Bond 007: Nightfire was released in 2002, it was published by EA Games and developed by Eurocam. It was a first person shooter game predominantly where you would play as secret agent James Bond. The game was a sequel to the game Agent Under Fire. The James Bond in the game was based on the Pierce Brosnan character and he even appeared on the front cover.
In the multiplayer game, you could play in many different locations including Fort Knox, Atlantis, Drake Castle and Skyrall. The game received a lot of positive response and sold 230,000 copies and earned $5.3 millions by mid 2006. The version of the game that got the worst response was the PC Version.
I think we used to play this on the Playstation 2, I remember it being really addictive and we got really competitive about beating each other. My favourite thing to do was hide and jump out of nowhere and attack, predominantly as a sniper hidden away it was so fun.
Tagged as: Games, gaming, james bond, James Bond 007: Nightfire, playstation, playstation 2
Off The Record – ALBUM FOCUS – NINE, Blink-182
Show Of The Week – INTERVIEW – Mad Monkey Improv: 6 Year Anniversary Show


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Hochbrand steht für:
 Glattbrand, eine Stufe der Porzellan-Herstellung

Hochbrand heißen folgende geographische Objekte:
 Hochbrand (Seckauer Tauern), 1426 m, bei Gaal im Murtal, Steiermark
 Hochbrand (Oberösterreichische Voralpen), 1242 m, im Ennstal nordwestlich von Altenmarkt bei St. Gallen, bei Weyer, Oberösterreich
 Hochbrand (Ennstaler Alpen), 1148 m, östlich der Haller Mauern, westlich von St. Gallen, Steiermark
 Hochbrand (Bosruck), 1144 m, Talberg am Pyhrnpass bei Spital, Oberösterreich
 Hochbrand (Schwechattal), 569 m, Anhöhe des Wienerwalds bei Klausen-Leopoldsdorf, Niederösterreich
 Hochbrand (Triestingtal), 544 m, Talberg des Wienerwalds bei Altenmarkt an der Triesting, Niederösterreich

 Hochbrand (Türnitzer Alpen), ca. 645 m, Sattel am Stierberg bei Kirchberg im Pielachtal, Niederösterreich

redpajama_set_name: RedPajamaWikipedia


text:
Q: How to interpret TraMineRs results of disstreedisplay and seqtreedisplay? I am not quite sure what the differences are between the outputs and results of disstreedisplay and seqtreedisplay. Maybe you could explain me the differences?
The TraMineR users guide and the otherwise detailed working paper about the WeightedCluster library do not explain so much about that. Here is my example R script:
library(TraMineR)
library(WeightedCluster)

data(mvad)
mvad.alphabet <- c("employment", "FE", "HE", "joblessness", "school", "training")
mvad.labels <- c("Employment", "Further Education", "Higher Education", "Joblessness",
"School", "Training")
mvad.scodes <- c("EM", "FE", "HE", "JL", "SC", "TR")
mvadseq <- seqdef(mvad[, 17:86], alphabet = mvad.alphabet, states = mvad.scodes,
labels = mvad.labels, weights = mvad$weight, xtstep = 6)

mvad.ham <- seqdist(mvadseq, method="HAM")

seqtree <- seqtree(mvadseq ~ gcse5eq + Grammar + funemp, data=mvad, diss=mvad.ham,
weight.permutation="diss")
seqtreedisplay(seqtree, type="d", border=NA)

disstree <- disstree(mvaddist ~ gcse5eq + Grammar + funemp, data = mvad, R = 10)
disstreedisplay(disstree, imagefunc=seqdplot, imagedata=mvadseq, border=NA,
withlegend=FALSE, axes=FALSE, ylab="")

You need to have installed GraphViz to see the graphs.

A: Sequence regression trees and dissimilarity based trees are fully presented in the following paper:
Studer, M., Ritschard, G., Gabadinho, A. & Müller, N.S. (2011), "Discrepancy Analysis of State Sequences", Sociological Methods and Research. Vol. 40(3), pp. 471-510.
Basically, seqtree and seqtreedisplay are shortcuts (helper functions) to disstree and disstreedisplay functions (specifying some defaults such as the plotting and printing function to use and so on). disstree is more general and can be used to analyse any kind of objects described by a distance matrix.
The difference in your output comes from the use of the weights. seqtree uses the sequences weights by default (those defined in seqdef). If you use disstree, you need to specify the weights explicitly to get the same result.
Thus, disstree must be:
disstree <- disstree(mvad.ham ~ gcse5eq + Grammar + funemp, data=mvad,
weights=mvad$weight, R=10, weight.permutation="diss")


A Hot Cup of Joey: I Ate My Kids' Halloween Candy!
I Ate My Kids' Halloween Candy!
Here's another one that I'm very late on. Jimmy Kimmel issued another challenge to parents: once again, tell your kids that you ate all their Halloween candy. While some of these kids make me cringe over how upset they get, the ones at the end restore faith in humanity.


We're happy you've found us!
When our summer camps wind down, our mission to help people know and grow in Jesus Christ doesn't. Camp Judson continues to provide the same inviting atmosphere for our guests throughout the fall, winter and spring in the form of church retreats, conferences and overnight stays.
Book your next getaway with us! We'll do the cooking, and our comfortable accomodations mean you and your ministry team can focus on taking care of your audience. We look forward to being the best part of your year, whatever the season!


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Glasgow Police Pipe Band is delighted to announce the appointment of Alisdair McLaren to the band management structure. Alisdair will come in as Joint Pipe Sergeant joining Duncan Nicholson with significant responsibility in developing the Pipe Corps going forward. PM Iain MacPherson said, " Alisdair previously played with Strathclyde Police before moving into the ranks of the World Famous Field Marshall Montgomery Pipe Band in 2009. He has gained fantastic experience and success there and I believe Alisdair's knowledge, professionalism and enthusiasm will help Glasgow Police Pipe Band make progress in the coming years".
On his appointment to the role, Alisdair McLaren said, "I am delighted to be returning to the ranks of Glasgow Police and honoured to be assuming the role of Pipe Sergeant, working alongside Pipe Major Iain MacPherson, Pipe Sergeant Duncan Nicholson and Drum Sergeant David Henderson. Having played with the band between 2005 and 2008, it is a great pleasure to return to the fold. During the intervening years, I have relished the opportunity to learn under Pipe Major Richard Parkes MBE and Pipe Sergeant Alastair Dunn and was very fortunate to enjoy a multitude of successes with FMM. This appointment marks a new chapter in my piping career and I am excited about the challenge ahead. To take on a leadership role in a band so rich in pipe band history is a great honour".
Drum Sergeant David Henderson said, "I am delighted that Alisdair is joining the ranks of the Glasgow Police Pipe Band as Pipe Sergeant. With his wealth of experience and success at the highest level, I am positive that he will be a significant factor in helping the band move forward. I look forward to working with Iain, Alisdair and Duncan in the coming months."


As a Senior Platform Engineer, you will focus on building next-generation platform services for Freshworks with your strong background in distributed systems and mentor your team to achieve this.You will have an opportunity to redefine customer experiences by building systems that are milli-second efficient, always available and working at internet scale. If you are the kind of engineer who is passionate about building systems, have a good eye for analysis and a mind that can think outside the box, we want to talk to you.
- Lead teams to deliver scalable, low latency, and cost-efficient solutions to the different product teams.
- Drive solutions and implementation leveraging different open source distributed systems and deliver a complete product.
- Build innovative solutions from scratch and liaise with architects and engineers from other product teams to build solutions and drive adoption.
- Implement and support compliance of self and team to Freshworks compliance and information security processes.


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AFI To Release New Album in 2021, New Music Coming Very Soon
Posted by charlessagona on January 7, 2021 in Featured, Latest News
AFI announced on Twitter that a new album is on the way and fans can expect to hear new music soon.
While the release date isn't know, it is expected to drop this year. The band's last release was in 2017.
The band wrote:
With the end of a year that has been, at best, challenging for all, we have news that we hope may bring you some joy. Very soon, new songs shall be yours. Before the year's end, our 11th album will follow. We could not be more happy with our latest work and hope you will feel the same. Thank you for joining us upon this next journey. We are thrilled to take it and honored to have you at our side.
With the end of a year that has been, at best, challenging for all, we have news that we hope may bring you some joy. Very soon, new songs shall be yours. Before the year's end, our 11th album will follow. We could not be more happy with our latest work… (cont.) pic.twitter.com/ERMwq2h5aU
— AFI (@AFI) January 1, 2021
Posted in Featured, Latest News | Tagged AFI, new album, NEW MUSIC
Kings of Leon: New Music On The Way→
Foo Fighters Debut New Song: No Son Of Mine→
Foo Fighters & Pearl Jam Drummers, Melvins Singer Unite For New Project→
Gretta Van Fleet Perform 'My Way, Soon' on Late Show→


text:
\section{Introduction}

We suggest a new model of a spinning particle which propagates in $d=4$
Anti-de Sitter space and has arbitrary fixed quantum numbers. The model
is an AdS counterpart of the massive spinning particle theory in the
Minkowski space proposed in Ref. [1].

A consistency of the interaction with external fields (including
gravity) has always been a problem for a higher spin (super)particle
theory. In this connection the model being studied is of special
interest as a simplest example of a consistent spinning particle theory
in the curved space which could probably be treated as a suitable
background for perturbative interaction switching on. In relation to
this topic it is pertinent to note that just the AdS space appears to
be an admissible vacuum for interacting higher spin fields (including
gravity) [2].

Let us discuss in outline the starting points of the model's
construction. The configuration manifold is chosen\footnote{\normalsize{This
choice of the configuration manifold differs from the other ones, being
usually used for spinning particles (e.g. see [3--7]), in that it does
not depend on the spin value.}} as ${\cal M}_\rho^6={\cal M}_\rho^4\times S^2$, where
${\cal M}_\rho^4$ is $d=4$ Anti-de Sitter space ($\rho <0$ is the
curvature) and $S^2$ is two-sphere. The case of $\rho=0$ (i.e.,
${\cal M}^4_0\equiv {\Bbb R}^{3,1}$) corresponds to the model studied in Ref.
[1]. It turns out that ${\cal M}_\rho^6$ can be endowed with a structure of a
homogeneous space for AdS group (see Sec. 2). Thus, ${\cal M}_\rho^6$ is able to
serve as an arena for some AdS-invariant dynamics.

There is a number of AdS-invariant functionals of world-line on
${\cal M}_\rho^6$, and each of them can seemingly be treated as an appropriate
action for the spinning particle. However, we are going to show that
the action functional will be unambigously determined if an identical
conservation law is required to hold for the AdS-counterparts of spin
and mass\footnote{\normalsize{It means, in fact, that the AdS particle
spin and mass should appear to coincide identically (i.e., off shell)
with some numerical parameters entering the action desired.}}. Thus, the
basic selection principle is that the action should possess two gauge
symmetries being provided the pair of N\"oether identities to appear.
{}From the standpoint of Hamiltonian formalism this principle means that a
pair of the AdS-invariant first-class constraints should be imposed
onto the cotangent bundle of ${\cal M}_\rho^6$ to extract physically contentable
degrees of freedom. On the other hand, it turns out that just the
theory with two gauge invariances in ${\cal M}_\rho^6$ has the proper number of the
physical degrees of freedom being characterized the spinning particle:
4 = 3(positions) + 1(spin). The mentioned properties of the model are
shown to cause the spinning particle theory quantization to give the
irreducible representation of AdS group.

The letter is organized as follows. In Sec. 2 we study an AdS-covariant
description for the configuration manifold and show that ${\cal M}_\rho^6$ is a
homogeneous transformation space for AdS group. In Sec. 3, we derive
the model action functional in an explicitly AdS-covariant manner and
discuss its local symmetries both in the first- and the second-order
formalism. In Sec. 4, we consider the model's description in terms of
inner ${\cal M}_\rho^6$ geometry. It shows also that the model can be treated as a
``minimal covariant extention'' of its flat-space counterpart [1]. We
also consider in the Section some obstructions to straightforward
generalization of the model to the case of arbitrary curved background.
The Conclusion includes discussion of the results and some
perspectives.

\section{Covariant realizations for the configuration space}

We start with describing two covariant realizations for the
configuration space ${\cal M}_\rho^6={\cal M}_\rho^4\times S^2$, where
${\cal M}_\rho^4$ presents itself an ordinary Anti-de Sitter space,
$S^2$ is two-dimensional sphere. It is useful for us to treat
${\cal M}_\rho^4$ as a hyperboloid embedded into a five-dimensional
pseudo-Euclidean space ${\Bbb R}^{3,2}$, with coordinates $y^A$, $A=5,
0, 1, 2, 3$, and defined by
$$
\eta_{AB}y^Ay^B=-R^2, \qquad \eta_{AB}=(--+++),
\eqno{(1)}$$
$\rho =-R^{-2}$ is the curvature of the AdS space. There is no problem,
however, to extend subsequent results to the case when ${\cal M}_\rho^4$ stands for
the universal covering space of the hyperboloid.

Similarly to ${\cal M}_\rho^4$, ${\cal M}_\rho^6$ can be endowed with the structure of a
homogeneous transformation space for an AdS group chosen below to be
the connected component of unit in $O(3,2)$ and denoted by
$SO^{\uparrow}(3,2)$\footnote{\normalsize{The elements of $SO^{\uparrow}(3,2)$ are specified
by the conditions that their diagonal $2\times 2$ and $3\times 3$
submatrices, numbering by indices $\overline{5,0}$ and $\overline{1,2,3}$
respectively, have positive determinants.}}. In order to explain this
statement, let us consider the tangent bundle $T({\cal M}_\rho^4)$ that will be
parametrized by 5-vector variables $(y^A,b^A)$ under the constraints
$$
y^Ay_A=-R^2,
\eqno{(2.a)}$$
$$
y^Ab_A=0.
\eqno{(2.b)}$$

The latter requirement simply expresses the fact that $b^A\partial/\partial y^A$
is a tangent vector to a point $y\in{\cal M}_\rho^4$. The $O(3,2)$-invariant
subbundle $\tilde T({\cal M}_\rho^4)$ of non-zero light-like tangent vectors is
embedded into $T({\cal M}_\rho^4)$:
$$
b^Ab_A=0,
\eqno{(3.a)}$$
$$
\{b^A\}\neq 0.
\eqno{(3.b)}$$
It turns out that ${\cal M}_\rho^6$ can be identified with the factor-space of
$\tilde T({\cal M}_\rho^4)$ with respect to the equivalence relation
$$
b^A\sim\lambda b^A, \qquad \forall\lambda\in{\Bbb R}\setminus\{0\}.
\eqno{(4)}$$
Really, there always exists a smooth mapping
$$
{\cal G}: {\cal M}_\rho^4\to SO^{\uparrow}(3,2)
\eqno{(5)}$$
such that ${\cal G}(y)$ moves a point $(y,b)$ at $\tilde T({\cal M}_\rho^4)$ to
$(\stackrel{\circ}{y},\stackrel{\circ}{b})$ having the form
$$
\stackrel{\circ}{y}{}^A = {{\cal G}^A}_B(y)y^B=(R,0,0,0,0)
\eqno{(6)}$$
and
$$
\stackrel{\circ}{b}{}^A = {{\cal G}^A}_B(y)b^B=(0,u^a) \qquad
a=0,1,2,3,
\eqno{(7.a)}$$
$$
\eta_{ab}u^au^b=0,
\eqno{(7.b)}$$
$$
\{u^a\}\neq 0.
\eqno{(7.c)}$$
For example, one can choose
$$
{\cal G}(y)=\left(\begin{array}{ccc}\begin{array}{cc}
\frac{\displaystyle{y^5}}{\displaystyle{R}} & \frac{\displaystyle{y^0}}
{\displaystyle{R}}\\
-~\frac{\displaystyle{y^0}}{\displaystyle\rho} & \frac{\displaystyle
y^5}{\displaystyle\rho}\end{array} &\stackrel{\vdots}{\vdots}&
\begin{array}{rrr}
-~\frac{\displaystyle y^1}{\displaystyle R} & -~\frac{\displaystyle
y^2}{\displaystyle R} & -~\frac{\displaystyle y^3}{\displaystyle R}\\
{\displaystyle 0} & {\displaystyle 0} & {\displaystyle 0}\end{array}\\
\dotfill &\vdots& \dotfill\\
\begin{array}[c]{cc}-~\frac{\displaystyle y^1y^5}{\displaystyle R\rho}
& -~\frac{\displaystyle y^1y^0}{\displaystyle R\rho}\\
-~\frac{\displaystyle y^2y^5}{\displaystyle R\rho} &
-~\frac{\displaystyle y^2y^0}{\displaystyle R\rho}\\
-~\frac{\displaystyle y^3y^5}{\displaystyle R\rho} &
-~\frac{\displaystyle y^3y^0}{\displaystyle R\rho}\end{array} &\vdots&
{\displaystyle\delta^{ij}}+\frac{\displaystyle y^iy^j}{\displaystyle
R(\rho +R)}\end{array}\right),
\eqno{(8)}$$
where
$$
\rho =\sqrt{(y^5)^2+(y^0)^2}, \qquad i,j=1,2,3.
$$
{}From Eq. (7) we see that the fiber $\{(\stackrel{\circ}{y},\stackrel{\circ}{b})\}$ over $\stackrel{\circ}{y}$ in
$\tilde T({\cal M}_\rho^4)$ looks exactly like the punctured light-cone in
Minkowski space. Equivalence relation (4) proves to reduce the
light-cone to $S^2$. Now, since the AdS group brings any equivalent
points to equivalent ones, we conclude that $SO^{\uparrow}(3,2)$
naturally acts on the factor-space ${\cal M}_\rho^4\times S^2$. Therefore, Eqs.
(2)-(4) present an AdS-covariant realization of ${\cal M}_\rho^6$.

There exists some inherent arbitrariness in the choice of $\cal G$
defined by Eqs. (5) and (6). Such a mapping can be equally well
replaced by another one
$$
{{\cal G}'}^A{}_B(y)={\Lambda^A}_C(y){{\cal G}^C}_B(y),
\eqno{(9.a)}$$
where $\Lambda$ takes it values in the stability group of the marked
point $\stackrel{\circ}{y}$,
$$
{\Lambda^A}_B(y)\stackrel{\circ}{y}{}^B=\stackrel{\circ}{y}{}^A,
\eqno{(9.b)}$$
and has the general structure
$$
\begin{array}{l}
\Lambda : {\cal M}_\rho^4\toSO^{\uparrow}(3,2)\\
{\Lambda^A}_B(y)=\left(\begin{array}{ccc} \displaystyle 1 & \vdots & 0\\
\dotfill & \vdots & \dotfill\\
\displaystyle 0 & \vdots & {\Lambda^a}_b(y)\end{array}\right), \qquad
{\Lambda^a}_b(y)\in SO^{\uparrow}(3,1).\end{array}
\eqno{(10)}$$
The set of all smooth mapping (10) forms an infinite-dimensional group
isomorphic to a local Lorentz group of the AdS space. This group acts
on $T({\cal M}_\rho^4)$ by the law
$$
(y,b)\longrightarrow\big(y,{\cal G}^{-1}(y)\Lambda(y){\cal G}(y)b\big),
\eqno{(11)}$$
$\cal G$ being a fixed solution of Eqs. (5), (6). As is obvious, the
local Lorentz group naturally acts on ${\cal M}_\rho^6$.

For getting explicit action of $SO^{\uparrow}(3,2)$ on ${\cal M}_\rho^6$, it appears useful from
the very beginning to replace the AdS-covariant parametrization
$(y^A,b^A)$ of $T({\cal M}_\rho^4)$ with a Lorentz-covariant one $(y^A,u^a)$, where
the 4-vector $u^a$ is related to $b^A$ as it is given by
Eq. (7.a). Given a group element $H\inSO^{\uparrow}(3,2)$, it moves $(y,b)$ to
$(Hy,Hb)$, hence $(y,u)$ to $(Hy,\Lambda_H(y)u)$, where
$$
\Lambda_H(y)\equiv{\cal G}(Hy)H{\cal G}^{-1}(y)
\eqno{(12)}$$
is a Lorentz transformation of the form (10). One readily finds
$$
\Lambda_{H_1}(y)\Lambda_{H_2}(y)=\Lambda_{H_1H_2}(y)
\eqno{(13)}$$
for arbitrary $H_1,H_2\inSO^{\uparrow}(3,2)$. We thus arrive at a nonlinear
representation of the AdS group. Now, the problem reduces to obtaining
action of the Lorentz group on $S^2$, what is well known and has been
described in detail in Ref. [1] in the convenient for our purposes
form. Also it will be given in Sec. 4.

\section{Derivation of the action functional}

Here we derive the model in an AdS-covariant way. The basic requirement
allowing us to choose the unique action functional is: the dynamical
content of the model on ${\cal M}_\rho^6$ must be completely determined by
identical conservation of classical counterparts of two Casimir
operators of AdS group.

Let us consider the model's phase space with the coordinates $y^A,b^A$
and their canonically conjugated momenta $P_A,K_A$, subjected to the
following nonvanishing Poisson bracket relations:
$$
\{y^A,P_B\}=\{b^A,K_B\}=\delta^A_B.
\eqno{(14)}$$
AdS group acts on the phase-space functions via brackets (14) by the
following generators:
$$
L_{AB}=y_AP_B-y_BP_A+b_AK_B-b_BK_A.
\eqno{(15)}$$
The theory being constructed must contain the constraints (2), (3) as
well as the equivalence relation (4) to be well defined on ${\cal M}_\rho^6$. Thus,
we impose the following AdS-invariant first-class constraints to
restrict an admissible dynamics of the model:
$$
T_{1,2,3,4}\approx 0,
\eqno{(16.a)}$$
where
$$
T_1=y_Ay^A+R^2, \qquad T_2=y_Ab^A, \qquad T_3=b_Ab^A,
\eqno{(16.b)}$$
$$
T_4=K_Ab^A.
\eqno{(16.c)}$$
The last constraint generates the equivalence relation (4) with respect
to the brackets (14). Being restricted to the surface (2), (3) the
classical counterparts of Casimir operators of the AdS group look as
$$
C_1=\frac{1}{2}L_{AB}L^{AB}|_{T_{1,2,3,4}=0}=R^2P_AP^A+(P_Ay^A)^2+
2(P_Ab^A)(K_Ay^A),
\eqno{(17.a)}$$
$$
C_2=\frac{1}{4}L_{AB}{L^B}_C{L^C}_DL^{DA}|_{T_{1,2,3,4}=0}=\qquad\qquad\qquad
$$
$$
\qquad\frac{1}{8}(L_{AB}L^{AB})^2-(P_Ab^A)^2[K_AK^AR^2+(K_Ay^A)^2].
\eqno{(17.b)}$$
Taking the proper account of the basic requirement formulated above in
this section and Eqs. (17.a-c) we introduce the two main first-class
constraints
$$
T_5=R^2P_AP^A+(P_Ay^A)^2+2(P_Ab^A)(K_Ay^A)+M\approx 0,
\eqno{(18.a)}$$
$$
T_6=(P_Ab^A)^2[K_AK^AR^2+(K_Ay^A)^2]+\delta\approx 0,
\eqno{(18.b)}$$
where $M$ and $\delta$ are some constants which are treated as
parameters of the model. It easily seen that
$$
C_1=-M, \qquad C_2=\frac{1}{2}M^2+\delta
\eqno{(19)}$$
on the total constrained surface.

Thus, the model postulated is characterized by six first-class
constraints: four of them $T_{1,2,3,4}$ are auxiliary ones (they reduce
the configuration space to ${\cal M}_\rho^6$), while the two principal constraints
$T_5$, $T_6$ determine the dynamics on ${\cal M}_\rho^6$ properly.

The first-order (Hamiltonian) action associated with these six
constraints is
$$
S=\int{\rm d}\tau \left(P_A\dot y^A+K_A\dot b{}^A-\sum_{i=1}^6
\frac{\nu_i}{2}T_i\right).
\eqno{(20)}$$
Here $\nu_i$ are auxiliary variables playing the role of Lagrange
multipliers to the first-class constraints $T_i$.

To bring this action to a second-order (Lagrange) form one must exclude
the momenta $P_A$, $K_A$ and the auxiliary constraints' multipliers
$\nu_{1,2,3,4}$ by making use of other equation of motion:
$$
\frac{\delta S}{\delta P_A}=0, \qquad \frac{\delta S}{\delta K_A}=0,
\qquad \frac{\delta S}{\delta\nu_{1,2,3,4}}=0.
\eqno{(21)}$$
It is easy to check that on the shell of Eq. (16, 18) the following
equalities hold:
$$
\dot y_Ab^A=\nu_5R^2(P_Ab^A),
\eqno{(22.a)}$$
$$
\dot y_A\dot y{}^A=\nu_5R^2\left(\nu_5(T_5-M)+2\nu_6(\delta-T_6)\right),
\eqno{(22.b)}$$
$$
\dot b_A\dot b^A=-\frac{1}{R^2}\frac{(\dot y_Ab^A)^2}{\nu^2_5}\left(\nu^2_5+
\frac{1}{2}\nu_6^2(\delta-T_6)\right),
\eqno{(22.c)}$$
$$
P_A\dot y^A+K_A\dot b^B=\nu_5(T_5-M)+2\nu_6(\delta-T_6),
\eqno{(22.d)}$$
Substituting these relations to Eq. (20) we are coming up with the
following action of the model:
$$
S_1=\int{\rm d}\tau\bigg[\frac{1}{2e_1}\big(\dot y_A\dot y^A-\frac{M}{R^2}
e_1^2\big)+\frac{1}{2e_2}\bigg(\Big(\frac{\dot b_A\dot b^A}{(\dot y_Ab^A)^2}
+\frac{1}{R^2}\Big)e_1^2-\delta\frac{e_2^2}{R^2}\bigg)\bigg]
\eqno{(23.a)}$$
where
$$
e_1\equiv\nu_5R^2, \qquad e_2\equiv -\nu_6R^2
\eqno{(23.b)}$$
and holonomic extra-constraints $T_{1,2,3}$ are imposed on $y^A$,
$b^A$.

This action is manifestly AdS invariant. What is more, it possesses
three local symmetries corresponding to three constraints depending on
momenta: $T_4$, $T_5$, $T_6$. They are
$$
\delta_5y^A=\bigg(\dot y^A-\frac{e_1^3}{e_2(\dot y_Ab^A)}\dot b^B\big(
\eta_{BC}+\frac{y_By_C}{R^2}\big)\dot b^Cb^A\bigg)m_5,
\eqno{(24.a)}$$
$$
\delta_5b^A=\frac{\dot y_Bb^B}{R^2}y^Am_5, \quad \delta_5e_1=\frac{\rm
d}{{\rm d}\tau}(e_1m_5), \quad \delta_5e_2=0;
\eqno{(24.b)}$$
$$
\delta_6y^A=\frac{e_1^3}{e_2(\dot y_Ab^A)}\dot b^B\big(\eta_{BC}+
\frac{y_By_C}{R^2}\big)\dot b^Cb^Am_6,
\eqno{(25.a)}$$
$$
\delta_6b^A=\big(\dot b^A-\frac{\dot y_Bb^B}{R^2}y^A\big)m_6, \quad
\delta_6e_2=\frac{\rm d}{{\rm d}\tau}(e_2m_6), \quad \delta_6e_1=0;
\eqno{(25.b)}$$
$$
\delta_4b^A=b^Am_4, \qquad \delta_4(\mbox{the rest variables})=0.
\eqno{(26)}$$
For instance, one can easily extract reparametrizations by taking
$m_5=m_6$ $=\mu$ and $m_4=0$. The third symmetry (26) reduces the theory
configuration manifold to ${\cal M}_\rho^6$ while transformations (24), (25) are
the model's characteristic features those provide the Casimir operators
to conserve identically (see Eq. (19)).

Now let us briefly discuss the question about physical observables of the
theory. It is easily comprehended that all nontrivial physical
observables are functions of the Hamiltonian generators of the AdS
group modulo constraints. Indeed, all AdS group generators, obviously,
commute with the first-class constraints, on the other hand these
constraints reduce the original 12-dimensional phase space of the model
(if auxiliary constraints are taken into account) to the 8-dimensional
physical one. Consequently, physical subspace can be covariantly parametrized
with 10 generators of the AdS group subject to the two constraints.

\section{Reformulation of the model in terms of inner ${\cal M}_\rho^6$ geometry}

In this Section, we give the another form for the action (23.a) which
could be treated as ``minimal covariant extension'' of the massive
spinning particle action in Minkowski space proposed earlier. Let us
consider some facts concerning ${\cal M}_\rho^6$ geometry in order to expose this
formulation.

Let $x^m$ ($m=0,1,2,3$) be the local coordinates on the
surface (1). The induced metric is
$$
g_{mn}(x)=\eta_{AB}\frac{\partial y^A}{\partial x^m}~\frac{\partial y^B}{\partial x^n},
\eqno{(27)}$$
$$
\eta_{AB}{\rm d}y^A{\rm d}y^B = g_{mn}{\rm d}x^m{\rm d}x^n.
$$
The following 1-form of vierbein is associated with the metric (27):
$$
e_{ma}(x)=\frac{\partial y^A}{\partial x^m}{\cal F}_{Aa}(y(x))=-y^A\frac{\partial{\cal F}_{Aa}}
{\partial x^m},
\eqno{(28.a)}$$
where
$$
{{\cal F}^A}_B(y)\equiv {({\cal G}^{-1})^A}_B(y)=\eta^{AC}\eta_{BD}{{\cal G}^D}_C
\equiv{{\cal G}_B}^A(y).
\eqno{(28.b)}$$
It is worth noting that
$$
{{\cal F}^A}_5(y)\equiv{{\cal G}_5}^A(y)=\frac{1}{R}y^A
\eqno{(29)}$$
as it follows from the very definition (6). Using the last formula it
is easy to check that $e_{ma}$ is really a vierbein, i.e.
$$
g_{mn}=e_{ma}e_{nb}\eta^{ab}.
\eqno{(30)}$$
The Lorentz connection associated with the vierbein (28.a) is
$$
{\omega_m}^{ab}(x)={\cal F}^{Aa}\partial_m{{\cal F}_A}^b.
\eqno{(31)}$$
To verify this assertion it is enough to examine that the torsion
constructed on the base of Eqs. (28.a) and (31) vanishes:
$$
T^a_{nm}=\partial_n{e_m}^a-\partial_m{e_n}^a-{e_n}^b{\omega_{mb}}^a+{e_m}^b
\omega_{nba}=0.
\eqno{(32)}$$
Indeed,
$$
\partial_{[n}{e_{m]}}^a=\partial_{[n}y^A\partial_{m]}{{\cal F}_A}^a
\eqno{(33.a)}$$
and
$$
{e_{[n}}^b{\omega_{m]b}}^a=\partial_{[n}y^A{{\cal F}_A}^b{{\cal F}^B}_b\partial_{m]}{{\cal F}_B}^a=\qquad
$$
$$
=\partial_ny^A\partial_m{{\cal F}_B}^A({\delta_A}^B-{{\cal F}_A}^5{{\cal F}^B}_5)=
\partial_{[n}y^A\partial_{m]}{{\cal F}_A}^a,
\eqno{(33.b)}$$
since
$$
(\partial_ny^A){{\cal F}_A}^5=\frac{1}{R}(\partial_ny^A)y_A=0.
\eqno{(33.c)}$$

Now let us consider the spinning part of ${\cal M}_\rho^6$ -- two sphere
$S^2$.\footnote{\normalsize{Our two-component spinor notations mainly
coincide with those adopted in Ref. [8], except we number spinor indices
by values 0, 1 and define spinning matrices $\sigma_{ab}$ and
$\tilde\sigma_{ab}$ with additional minus sign in comparison with Ref. [8].}}
It is covered by the two charts, $z$ and $w$ are the complex coordinates
in these charts, and
$$
z=-\frac{1}{w}
\eqno{(34)}$$
in the overlap of charts.

The Lorentz group $SO^{\uparrow}(3,1)=SL(2,{\cal C})/\pm 1$ acts on $S^2$ by
means of fractional-linear transformations:
$$
z' = \frac{az-b}{-cz+d}, \qquad \|N\|={N_\alpha}^\beta=\left(
\begin{array}{cc} a & b\\ c & d\end{array}\right)\in SL(2,{\cal C}).
\eqno{(35)}$$
It means that the two-component object
$$
z^\alpha\equiv (z)^\alpha =(1,z), \qquad \alpha =0,1
\eqno{(36)}$$
is transformed simultaneously as left Weyl spinor and spinor field on
$S^2$ under the Lorentz group (36):
$$
{z'}^\alpha =\left(\frac{\partial z'}{\partial z}\right)^{1/2} z^\beta
(N^{-1})_\beta{}^\alpha.
\eqno{(37)}$$
Let $p^a$ be a time-like 4-vector,
$$
p^2=p^ap_a<0.
\eqno{(38)}$$
One can associate with $p^a$ a smooth positive definite metric on $S^2$
of the form
$$
{\rm d}s^2 = \frac{4{\rm d}z{\rm d}{\bar z}}{(p^a\xi_a)^2}.
\eqno{(39.a)}$$
where
$$
\xi_a\equiv(\sigma_a)_{\alpha\dot\alpha}z^\alpha{\bar z}^{\dot\alpha}
\Rightarrow p^a\xi_a=p_{\alpha\dot\alpha}z^\alpha{\bar z}^{\dot\alpha},
\eqno{(39.b)}$$
$$
\xi_a\xi^a=0.
\eqno{(39.c)}$$
Metric (39.a) is Lorentz invariant in the following sense:
$$
\frac{{\rm d}z'{\rm d}{\bar z'}}{(p'_{\alpha\dot\alpha}{z'}^\alpha{\bar
z'}{}^{\dot\alpha})^2}=\frac{{\rm d}z{\rm d}{\bar z}}
{(p_{\alpha\dot\alpha}z^\alpha{\bar z}^{\dot\alpha})^2}
\eqno{(40.a)}$$
where
$$
p'_{\alpha\dot\alpha}={N_\alpha}^\beta{\bar N_\alpha}^{\dot\beta}
p_{\beta\dot\beta}.
\eqno{(40.b)}$$

In the case of massive spinning particle on the flat space, there
exists the only natural candidate to the role of $p^a$: it is tangent
vector to a particle's world line ${\dot x}^a$. That is why one can
construct the following world line Lorentz-invariant
$$
\frac{4{\dot z}\dot{\bar z}}{({\dot x}^a\xi_a)^2}
\eqno{(41)}$$
which together with ${\dot x}_a{\dot x}^a$ constitute the set of building
blocks for the Lagrangian of massive spinning particle on the Minkowski
space [1]:
$$
S'=\int{\rm
d}\tau\left\{\frac{1}{2e_1}({\dot x}_a{\dot x}^a-(me_1)^2)+\frac{1}{2e_2}\Big(
\frac{4{\dot z}\dot{\bar z}}{({\dot x}^a\xi_a)^2}+(\Delta e_2)^2\Big)\right\}.
\eqno{(42)}$$
This Lagrangian is invariant under global Poincar\'e transformations
when Poin\-car\'e-translations act trivially on $S^2$, and Lorentz group
is identified with diagonal of $SO(3,1)\big|{}_{R^{3,1}}\times
SO(3,1)\big|{}_{S^2}$, in accordance with Eq. (40).

We now show that the action of spinning particle on anti-de Sitter
space (23.a) could be derived by the minimal covariantization of
(23.a), i.e. by generalizing (23.a) to the form consistent with
general coordinate and local Lorentz covariance. If Lorentz
transformations are local, i.e. depend on $x^m$, Eq. (39.a) will not be
invariant because d$z$ is not local Lorentz-covariant differential.

However, the object
$$
Dz={\rm d}z +\frac{1}{2}{\rm d}x^m\omega_{mab}(x)\Sigma^{ab}
\eqno{(43.a)}$$
where
$$
\Sigma^{ab}\equiv(\sigma^{ab})_{\alpha\beta}z^\alpha z^\beta
\eqno{(43.b)}$$
is local Lorentz covariant:
$$
(Dz)'={\rm d}z'+\frac{1}{2}{\rm d}x^m\omega'_{mab}{\Sigma'}^{ab}=
\left(\frac{\partial z'}{\partial z}\right)Dz,
\eqno{(44.a)}$$
where
$$
\omega'_{mab}={\Lambda_a}^c{\Lambda_b}^d\omega_{mcd}+{\Lambda_a}^c\partial_m\Lambda_{bc},
\eqno{(44.b)}$$
(${\Lambda_a}^c(x)$ are the local Lorentz transformations parameters) is
the transformation law for Lorentz connection easy derivable from Eqs.
(9.a) and (31). Taking the proper account of the relation (43) we find
that local Lorentz and general coordinate covariant generalization of
the ``flat'' action (42) is
$$
S_2=\int{\rm d}\tau\bigg\{\frac{1}{2e_1}(g_{mn}{\dot x}^m{\dot x}^n-(me_1)^2)+
\frac{1}{2e_2}\bigg(\frac{4|Dz/{\rm d}\tau|^2}{({\dot x}{}^me_{ma}\xi^a)^2}+
(\Delta e_2)^2\bigg)\bigg\}.
\eqno{(45)}$$
It turns out that the following equality takes place:
$$
4\frac{|Dz/{\rm d}\tau|^2}{({\dot x}{}^me_{ma}\xi^a)^2}=\frac{\dot b_A\dot b{}^A}
{(\dot y_Ab^A)^2}+\frac{1}{R^2}
\eqno{(46)}$$
where the following parametrization of the light-cone (7) is used
$$
u^a=\xi^aE(u)
\eqno{(47)}$$
and $E(u)$ is some function on the light-cone.

To prove the equality (46) one need to employ the properties of
${{\cal F}^A}_a$ (5), (28.a), (29) and definitions of ${\omega_m}^{ab}$ and
$e_{ma}$ through ${{\cal F}^A}_a$ (28.a), (31). Then one can make sure that
$$
\dot y_Ab^A={\dot x}^me_{ma}\xi^aE,
\eqno{(48.a)}$$
$$
{{\cal F}^A}_a\dot{\cal F}_{Ab}={\dot x}^m\omega_{mab}.
\eqno{(48.b)}$$
The useful identity
$$
\varepsilon^{\alpha\beta}=z^\alpha\partial_zz^\beta -z^\beta\partial_zz^\alpha
\eqno{(49)}$$
allows one to prove that
$$
{\dot\xi}_a{\dot\xi}^a=4{\dot z}\dot{\bar z},
\eqno{(50.a)}$$
$$
{\dot\xi}^a\xi^b-\xi^a{\dot\xi}^b=2((\sigma^{ab})_{\alpha\beta}z^\alpha
z^\beta\dot{\bar z} -(\tilde\sigma^{ab})_{\dot\alpha\dot\beta}{\bar
z}^{\dot\alpha}{\bar z}^{\dot\beta}{\dot z} ).
\eqno{(50.b)}$$
Using (48)--(50) one obtains
$$
{\dot\xi}^2+{{\cal F}^A}_a\dot{\cal F}_{Ab}({\dot\xi}^a\xi^b-\xi^a{\dot\xi}^b)=\qquad\qquad
$$
$$
=4({\dot z}\dot{\bar z} +\frac{1}{2}{\dot x}^m\omega_{mab}((\sigma^{ab})_{\alpha\beta}
z^\alpha z^\beta\dot{\bar z} -(\tilde\sigma^{ab})_{\dot\alpha\dot\beta}{\bar
z}^{\dot\alpha}{\bar z}^{\dot\beta}{\dot z} )).
\eqno{(51.a)}$$
and
$$
({{\cal F}^A}_a\dot{\cal F}_{Ab}\xi^a\xi^b)R^2+({\dot x}^me_{ma}\xi^a)^2=|{\dot x}^m
\omega_{mab}(\sigma^{ab})_{\alpha\beta} z^\alpha z^\beta|^2R^2.
\eqno{(51.b)}$$
Two last equalities are directly equivalent to Eq. (46). Thus,
$$
S_1=S_2
\eqno{(52.a)}$$
under the identification (46) and
$$
m^2=M/R^2, \qquad \Delta^2=-\delta/R^2.
\eqno{(52.b)}$$

So, we have two formulations for a given spinning particle on AdS
background, $S_1$ and $S_2$. The first formulation exhibits AdS
invariance of the model in the straightforward way, while the second
one describes theory in terms of inner ${\cal M}_\rho^6$ geometry without
introduction of auxiliary degrees of freedom. It might be well to
mention that the derivation procedure used in Sec. 3 can be
successfully performed in the inner ${\cal M}_\rho^6$ terms. Namely let us consider
the space which is the cotangent bundle to ${\cal M}^6$
$$
\{x^m,p_n\}=\delta^m_n, \qquad \{z,p_z\}=1, \qquad \{\bar z,p_{\bar
z}\}=1.
\eqno{(53)}$$
The classical counterparts of AdS -- Casimir operators are
$$
C_1=R^2g^{mn}\nabla_m\nabla_n,
\eqno{(54.a)}$$
$$
C_2=\frac{1}{2}(C_1)^2+R^2(\nabla^me_{ma}{\cal F}^a)^2,
\eqno{(54.b)}$$
where
$$
\nabla_m\equiv p_m-\frac{1}{2}{\omega_m}^{ab}(x)S_{ab},
\eqno{(55.a)}$$
$$
S_{ab}=-(\sigma_{ab})_{\alpha\beta}z^\alpha z^\beta p_z+
(\tilde\sigma_{ab})_{\dot\alpha\dot\beta}{\bar z}^{\dot\alpha}{\bar
z}^{\dot\beta}p_{bar z},
\eqno{(55.b)}$$
$$
{\cal F}^a=2(\sigma^a)_{\alpha\dot\beta}z^\alpha{\bar z}^{\dot\beta}|p_z|.
\eqno{(55.c)}$$
Due to the general coordinate and local Lorentz covariance, relations
(54.a,b) can be verified in any useful coordinate system, for example,
in those for which AdS generators look like
$$
L_{ab}=x_ap_b-x_bp_a+S_{ab},
\eqno{(56.a)}$$
$$
L_{a5}=Rp_a+\frac{1}{4R}(2x_ax^bp_b-x^2p_a)+\frac{1}{2R}x^bS_{ab},
\eqno{(56.b)}$$
while the tetrade reads as follows
$$
e_{ma}=\eta_{ma}\left(1+\frac{x^2}{4R^2}\right)^{-1},
\eqno{(57.a)}$$
$$
{\omega_m}^{ab}=-\frac{1}{2R^2}(x^a{\delta_m}^b-x^b{\delta_m}^a)
\left(1+\frac{x^2}{4R^2}\right)^{-1}.
\eqno{(57.b)}$$
Now, the following action
$$
S_2^{\rm H}=\int{\rm d}\tau\bigg\{p_m{\dot x}^m+p_z{\dot z} +p_{\bar z}\dot{\bar z}-
\frac{e_1}{2}\bigg(\frac{C_1}{R^2}+m^2\bigg)-\qquad
$$
$$
\qquad-\frac{e_2}{2}\bigg(\frac{1}{R^2}\bigg(C_2-\frac{1}{2}C_1^2
\bigg)-\Delta^2\bigg)\bigg\}
\eqno{(58)}$$
is nothing but Hamiltonian formulation of $S_2$, i.e. if one exclude
momenta $p_m$, $p_z$, $p_{\bar z}$ by making use of their equations of
motion, he arrive exactly to $S_2$.

The following remark is very much to the point: the second formulation
(45), (54), (58) seems to be well defined on a general curved space,
i.e. when $g_{mn}(x)$ is arbitrary.

It turns out, however, that the classical dynamics of the model is
non-contradictory on maximal symmetric spaces (i.e., de
Sitter--Minkowski--Anti de Sitter) only. It can be seen as follows. The
action functional is obviously reparametrization invariant on general
background (see also Eq. (61)), that's why a first class constraint has
to exist in Hamiltonian formulation. At the same time, Hamiltonian
formulation (54), (55) and (58) is determined by two constraints (54)
subject to the following Poisson bracket relation:
$$
\{C_1,C_2\}=R^4{R_{nm}}^{cd}e^{am}{\cal F}_aS_{cd}\nabla^n
\eqno{(59)}$$
where ${R_{nm}}^{cd}$ is Riemann tensor.

The identity
$$
S^{cd}{\cal F}_d\equiv 0
\eqno{(60)}$$
makes the commutator (59) to be zero if and only if ($acd$)-traceless
projection of ${R_{nm}}^{cd}e^{em}$ vanishes. Making use of the Bianchi
identities one can see that the space-time has the constant curvature.
Otherwise the constraints $C_1$, $C_2$ turn out to be of the second
class that contradicts to the reparametrization invariance of the
action.

Unfortunately, it still remains unclear whether it is possible to find
appropriate curvature depending contributions to constraints $C_1$,
$C_2$ to make them involutive.

To conclude this section let us note that Lagrange multipliers $e_1$
and $e_2$ can also be eliminated with the aid of their equations of
motion. The result is ``Nambu--Goto form'' of the action
$$
S=\int{\rm d}\tau\sqrt{g_{mn}{\dot x}^m{\dot x}^n\left(m^2-4\Delta\frac
{|Dz/{\rm d}\tau|}{|{\dot x}{}^me_{ma}\xi^a|}\right)}=
$$
$$
=\int{\rm d}\tau\sqrt{\dot y_A\dot y^A\bigg(m^2-2\Delta\bigg(\frac
{\dot b_A\dot b^A}{(\dot y_Ab^A)^2}+\frac{1}{R^2}\bigg)^{1/2}\bigg)}.
\eqno{(61)}$$
For $\Delta=0$ this expression apparently reduces to the action of
spinless particle on AdS background, on the other hand the limit
$R\Rightarrow\infty $ results in the $(m,s)$-particle action [1] in Minkowski
space.

\section{Conclusion}

Let us give a brief overview of the results and some comments. We have
suggested the model of a spinning particle which propagates in $d=4$
Anti-de Sitter space. The configuration space of the theory is
six-dimensional manifold ${\cal M}_\rho^6$ being the product of $d=4$ AdS space and
two-dimensional sphere. The values of the phase-space counterparts of
the AdS group Casimir operators are fixed by two abelian first-class
constraints to be arbitrary real numbers. The model can conceptually be
treated as an universal and minimal AdS spinning particle theory in the
sense that configuration manifold is spin-independent and has the
minimal possible dimension which still provides dynamical activity both
for particle position and spinning degree of freedom. As a consequence
of model's minimality property all the observables turn out to be
functions of the AdS group generators only. So, the model quantization
problem reduces to the construction of the irreducible unitary
representation of the AdS group with given quantum numbers. This
problem has been solved in Ref.[9] where irreducible representations
have been found in the case of bounded energy that provides a proper
particle interpretation.

It is pertinent to note that it is not evident how to construct an
explicit Hilbert space realization (e.g. coordinate one) for this
(``constrained'') quantum mechanics, i.e. the question is how to frame
the AdS (spin)tensor field on ${\cal M}_\rho^6$ with an appropriate Hilbert space
structure. This problem has been exhaustively studied for the flat
space case in the paper [1] where all such realizations were
classified. We intend to give the similar investigation for the AdS
case in the forthcoming publication.

Let us mentioned that this model could be generalized for
$d$-dimensional ($d>4$) AdS space in the straightforward way (one need
to assume $y^A$, $b^A$ to be $d$-dimensional). However, such a simplest
extension would not able to describe the most general case of the
higher-dimensional AdS spinning particle. The reason is that the
higher-dimensional AdS group has some extra Casimir operators which
turn out to vanish identically in the cotangent bundle of ${\cal
M}^d_\rho\times S^{d-2}$. Thus the straightforward higher-dimensional
extension of the proposed model could describe only the particles
associated with the irreducible AdS group representations characterized
by zero eigenvalues of these extra Casimir operators.

\section*{Acknowledgments}

The researches of S.L.L., A.Yu.S., and A.A. Sh. are supported in part
by European Community Commission contract INTAS-93-2058 and by the
International Science Foundation grant No M2I000. Researches of S.M.K.
are supported by Alexander von Gumboldt Foundation fellowship.

\section*{References}

\noindent
[1] S.M. Kuzenko, S.L. Lyakhovich, and A.Yu. Segal, Preprint
TSU-TP-94-8, hep-th/9403196 ``A Geometric model of arbitrary spin
massive particle'', to appear in Int. J. Mod. Phys.{\bf A},(1994)\newline
[2] M.A. Vasiliev, Phys. Lett., {\bf B 243}, 378 (1990)\newline
[3] F.A. Berezin and M.S. Marinov, JETP Lett. {\bf 21}, 678 (1975);
Ann. Phys. {\bf 104}, 336 (1977).\newline
[4] A. Barducci, R. Casalbuoni, and L. Lusanna, Nuovo Cim. {\bf A35},
377 (1976).\newline
[5] L. Brink, S. Deser, B. Zumino, P. Di Vecchia, and P.S. Howe, Phys.
Lett. {\bf B 64}, 435 (1976).\newline
[6] P.S. Howe, S. Penati, M. Pernici, and P. Townsend, Phys. Lett. {\bf
B 215}, 255 (1988).\newline
[7] R. Marnelius and U. M\.{a}rtensson, Nucl. Phys. {\bf B335}, 395
(1991); Int. J. Mod. Phys. {\bf A6}, 807 (1991). U. M\.{a}rtensson,
Int. J. Mod. Phys. {\bf A8}, 5305 (1994).\newline
[8] J. Wess and J. Bagger, {\it Supersymmetry and Supergravity}
(Princeton Univ. Press., Princeton, 1983).\newline
[9] N.T. Evans, J. Math. Phys., {\bf 8}, 2 (1967).
\end{document}

redpajama_set_name: RedPajamaArXiv


text:
Q: Gitflow, managing hotfixes, version tags and releases I'm following the GitFlow workflow but I'd like to know how people approach the issue of bugs with versioning/releases
We have a set of features that are linked to versions.

feature set {A,B,C} --> v1.0.1

feature set {D,E,F} --> v1.0.2

Each time a feature set is completed we add a tag with the version number to develop branch. This allows development to continue at it's own speed and we can then selectively choose a version, based on the version tag, to cut to our release branch which can end up in SIT, PREPROD etc
Imagine a scenario where the develop branch has a latest version tag of v1.0.10 and Production environment is running v1.0.5. If a bug is noticed in Production

*

*you apply the fix to hotfix branch

*release hotfix to production

*merge hotfix to main branch

*merge main down to develop and tag with a hotfix reference

Later on if I wanted to move Production to the next version v1.0.6 and have that hotfix included, how would I do so? Isn't that hotfix only available now post tag v1.0.10 in develop?

A: Standard Git Flow doesn't really handle your specific workflow as you described. Fortunately I believe with a minor workflow tweak you can resolve it.
The standard Git Flow assumes everything on the develop branch is going to land in Production (and consequently master or in your case main), in the next release (or the one after if a release is already pending). In the case when a release branch exists, and a hotfix goes into main, you also merge that hotfix (or main) back into the release branch right away. In your question's scenario, when a release branch doesn't exist yet, you would merge it back into develop, and this is where your problem arises because you don't intend to release the tip of develop yet, which is where you're deviating from standard Git Flow.
To solve this, I would propose one of these options:

*

*As soon as you know which commit on develop will represent your next release, create a release branch for it. Then if a hotfix hits main you can merge main back into the release branch instead of develop, guaranteeing you won't overwrite the hotfix changes in production. Note this might correspond nicely with your PREPROD branch, in which case you should make sure it always exists at the time you need to merge hotfixes into main back down into it. At that time you might have to also merge PREPROD right back down to develop. From there, you simply need to make sure that the next time you make PREPROD it comes after that new merge in develop. If your release cycle is so delayed that even that isn't possible, then that leads us to the next option:

*You could add a sub-workflow to your existing Git Flow. This is exactly what we do at my organization. The basic concept is that you have another throwaway integration branch, which I recommend calling next, which is where feature branches go to get hardened. Once they are proven and ready, you re-merge those commits into develop which means they will be included in the next release branch. Although this adds more complexity, you gain the ability to work out bugs earlier and only merge well-tested code into develop. Furthermore, it also enables you to release features out of order if you wish to, because you get to decide which features to merge into develop. Since you seem to have a long cycle for hardening your feature branches before they get deployed, this may work well for you. If you go this route I would recommend not tagging those features on the next branch, since the next branch should be reset to develop periodically. You may not need to tag those features at all anymore, and could instead tag the releases containing multiple features, as you deploy them. By the way, this sub-workflow is called gitworkflows and is what the maintainers of Git use, but without Git Flow also tacked on to it.

Side Note: You may have noticed I mentioned merging main back into release or develop instead of merging the release or hotfix branches themselves back down as standard Git Flow describes. This is functionally equivalent to the standard Git Flow suggestion, but I prefer this simply so the extra merge commit on main gets brought back down too. This way extra merge commits don't collect on main over time and get brought down all at once with a hotfix. It also keeps develop fully up to date with main so you don't see any commit IDs on main that aren't present in develop.


text:
Q: Can't build unity project as im not to fimiliar with these sorts of problems i can only supply the compiler errors and hope you know what they mean... any help is appretiated;
enter image description here
[EDIT] new set of problems: enter image description here
i am using (what i think is the latest webGL player) and have it set to windows and have satisfied the player setting.
tried restarting unity
tried satisfying player settings before build
tried making it a seperate scene folder

A: It seems like the error message you received is indicating that the path you provided for the scene file is incorrect, or maybe even the scene name could be causing problems.
Make sure your scenes and/or scenes folder is in the Assets folder. Also, to be on the safe side, you should always make sure the names of your scenes are not using any characters other than: numbers, a-z, "-"
You want to also make sure that the scene is included in the 'Scenes In Build' list found in the 'Build Settings' window. To add a scene, open the scene in the editor, open the Build Settings, and click 'Add Open Scenes'


I had not had Tristan home very long at all when I got a message that there was someone who wanted to sponsor Tristan. I met Tammy on a rainy cold night in the parking lot of Petsmart. She had heard Tristan's story and wanted to help him, to give him things he had never had in his life…his very own toys, a soft cushy bed, matching collar and leash and many many tasty treats. His story touched her heart and I was in awe of the kindness from this complete stranger. She has followed along, sharing in his triumphs, his struggles and his amazing courage. She has become a friend and I always look forward to sharing Tristan updates with Tammy!
Not long after I had started the blog, one of the messages I received was from a woman named Shannon B, who told me she was there the day Tristan was taken out of the shelter to be transported to the vet where I would later pick him up. I remember weeping as I read her words, as I knew all too well the vivid description of this poor terrified dog she spoke of. She too was touched by Tristan in a very special way, I know she could not get him out of her head or her heart and I am so glad she has been able to follow his story and share in his new life. She has been so so generous with her pledge of the dog-lbs efforts and a huge source of support for me personally. Today I came home to find a big care package for Tristan to celebrate the official adoption! I feel so blessed to have made the connection with a fellow animal lover and wonderful person and to know that someone was there for Tristan in his darkest hour, to show him kindness when he knew only fear and pain. I can't thank her enough….but I try!
Then there are the supporters of the dog-lb project, from many cities, and countries around the world who I don't know and might never meet but I know them from their encouraging words, support and commitment to help me move forward. They give of their time, of their money, and share their own stories, struggles and hopes. The people who walk with me, the friendships that have developed and the difference in my own life as well as the lives of many dogs that hang in the balance waiting to be pulled from the isolation of death row every day. It is a massive bundle of goodness and goodwill and kindness that I have never know. I can't ever forget that it is Tristan who brought me out of a very dark and dangerous struggle with depression and became my reason to wake up each morning.
All of this from a dog that nobody wanted, that no one loved, a dog that the warden deemed "unfit" for adoption. I sit here today and can say to you with every fiber of my being… he was so very wrong.
This entry was posted on Wednesday, November 2nd, 2011 at 12:54 AM	and is filed under My Blog. You can follow any responses to this entry through the RSS 2.0 feed. You can skip to the end and leave a response. Pinging is currently not allowed.
That dog warden was wrong in so many ways. Tristan being just one example of how he condemned a dog just because he wasn't perfect in his eyes. Many of the dogs Recycled Doggies gets have been declared unadoptable, because they're too old, too skinny, too scared, or too sick. Those are the ones that need us most. Thank you for taking the leap and agreeing to foster this "unadoptable", so very lovable dog. If only more people would take that chance. The reward is amazing.
I remember the day we found Tristan and Journey at the shelter. We all wanted so much to help them. He was so lucky Recycled Doggies and Lori stepped in to help him! The patience, love and strength you have shown while you were fostering him is how I know you will succeed at anything you set your mind to! Sending you and Tristan (and the schnauzers too!) a great big hug! See you tomorrow!
« Behind every great dog rescued there is a schnauzer.
Kim Herman on Shed your skin.
Tammy Gentile on Shed your skin.
Susan on Shed your skin.
Lillian Westfelt on Shed your skin.
Nancy Bailey on Shed your skin.


text:
Legendary Composer Ennio Morricone Will Write Original Score for Tarantino's 'The Hateful Eight'
By Alison Nastasi
Quentin Tarantino's films aren't known for their original scores. The genre cinema-obsessed director is partial to the music of other movies. "One of the things I do when I am starting a movie, when I'm writing a movie or when I have an idea for a film is, I go through my record collection and just start playing songs, trying to find the personality of the movie, find the spirit of the movie," he once said. "Then, 'boom,' eventually I'll hit one, two or three songs, or one song in particular, 'Oh, this will be a great opening credit song.'" There's one composer Tarantino has been greatly inspired by, having used several of his works in various films: Ennio Morricone. The legendary Italian composer has not scored a western film in 40 years, but it was announced yesterday at Comic-Con that Morricone will compose the score for Tarantino's upcoming western The Hateful Eight.
"I want to make one announcement that people don't know yet. It wasn't for sure, but we just settled it," he told a packed audience. "You guys know that I don't use an original score in my movies, I kinda take scores from other movies and put 'em in there. This one, I thought should have an original score. So I'm here to announce that the great Ennio Morricone will be doing the score for The Hateful Eight. He's writing right now, and recording in Prague in the next couple of weeks."
Since the mid 1940s, Morricone has composed the scores for more than 500 film and TV works. His best-known compositions were for Sergio Leone's operatic spaghetti westerns The Good, the Bad and the Ugly, Once Upon a Time in the West, A Fistful of Dollars, and For a Few Dollars More. But chances are, you've heard a Morricone score in a variety of genres. From The Untouchables and Days of Heaven, to Once Upon a Time in America and Bugsy, Morricone's sweeping scores are breathtaking.
The Hateful Eight will be released for a roadshow presentation in 70mm on December 25, before being released in digital theaters on January 8, 2016.


text:
namespace Simple.Owin.Static
{
    using System.Collections.Generic;
    using System.Threading.Tasks;

    internal static class OwinHelpers
    {
        public static void SetResponseHeaderValue(IDictionary<string, object> env, string key, string value)
        {
            var headers = env.GetValueOrDefault<IDictionary<string, string[]>>(OwinKeys.ResponseHeaders);
            if (headers == null)
            {
                headers = new Dictionary<string, string[]>();
                env[OwinKeys.ResponseHeaders] = headers;
            }

            headers[key] = new[] { value };
        }

        public static T GetValueOrDefault<T>(this IDictionary<string, object> env, string key)
        {
            object obj;
            if (env.TryGetValue(key, out obj))
            {
                if (obj is T)
                {
                    return (T)obj;
                }
            }

            return default(T);
        }

        public static Task Completed()
        {
            var tcs = new TaskCompletionSource<int>();
            tcs.SetResult(0);
            return tcs.Task;
        }
    }
}

redpajama_set_name: RedPajamaGithub


It was business as usual at the State House Thursday, with committees from education to transportation going through the usual bills and resolutions. But the buzz from Tuesday's dramatic opening of the Katie Brennan hearings could still be felt, especially after the governor's grilling on the matter Wednesday.
But aside from the potential political fallout for the governor from all this, and Brennan's testimony on Tuesday, the stated purpose of the panel is to find out what policy changes can be made to make sure that what happened to Brennan after the alleged attack doesn't happen again. On that front, several committee members had plenty to say Thursday.
Sen. Teresa Ruiz, who was moved to tears several times during the session, said she's looking forward to a discussion about hiring practices and protocols for background checks and investigations. But, she said, reform needs to begin on the local level.
Brennan knows her way around the system and has friends in high places, but even that privilege couldn't help her get through to someone who could help. What, some committee members wondered, could a victim with less access, or a language barrier, for instance, expect in a similar circumstance?
"Why did I have to tell my story to The Wall Street Journal for the administration to acknowledge that it should not have hired Mr. Alvarez. I should not have to be here today," Brennan said during Tuesday's hearing.
Assemblywoman BettyLou DeCroce says hiring practices for "at will" employees, many in the top rungs of an administration, need reform.
"I think maybe there's got to be a tighter, more stringent policy put in place in the vetting process of the individuals that would be in those high-ranking positions," she said.
And that would go to the very heart of how politics works in Trenton. The committee meets again on Dec. 18. No word on who'll testify next, but invitation letters have gone out to many of the names Brennan mentioned in her testimony this week.


Purchasing a new home can be an exciting time. Once you own the home though, a new chapter begins. A time that is filled with a growing responsibility to protect your investment. With some careful planning and a bit of learning, you can ensure that you aren't emptying your wallet or bank account to pay for an issue that could have been prevented.
An important aspect of your home is its plumbing system. It is central to the delivery of water into your home as well as the departure of grey and waste waters. Maintenance of your plumbing is essential to its continued working order and avoiding issues such as leaks, development of mold, or even flooding due to a break.
Having a plumbing and heating inspection can alert you to repairs or preventable issues before they become an unnecessary headache. It can also allow you to prioritize and plan for any expenses that you may have in the future.
Locating your water main shut off valve is key in the event that you run into an issue with your plumbing. Having the ability to close this during an emergency will stop the flow of water into the system. This can be invaluable if you are dealing with the repair of a minor leak but especially if there is a major leak or break in a pipe. This can also make a significant difference in the amount of cleanup that needs to be done.
Who do you call when there is an issue with your plumbing? Knowing this ahead of time and having the appropriate emergency contact information in an easy to find location could make a huge difference. This should include both a plumbing company that has a dispatch and technician available at the largest range of times and your local water utility service.
Make sure that your supply valves and sewer clean outs are clear of any obstruction. The last thing that you want to have to do in the middle of an emergency is to move items in order to get to the appropriate valves to shut off the flow of water.
It might sound a bit unnecessary, but drain catchers can help to keep your pipes clear of debris that can easily be removed after each use. Spending a small amount here can help keep you from having bigger issues in the future. This can include catching hair, jewelry, food, or any other items that could clog your pipes.
These are never fun to deal with. Whether it is your toilet, shower, or a sink, having a clogged drain can be annoying and most likely create a sanitary issue. There are a couple of things that you can consider here depending on the drain that is clogged.
A clogged toilet can be dealt with a couple of different ways. The first is to ensure that you are not clogging your toilet by using too much paper product to clean up and more importantly by avoiding flushing items that are not meant to go here. If you do end up with a clogged toilet, then you will want to make sure that you have a plunger available. It may also help to keep a bucket that you can fill up to add water to the bowl in the event that it is too low to get a good seal between the plunger and the toilet drain.
You can also use a plunger here as a first attempt to clearing the obstruction. If that does not work, then you should have a snake handy or know where you can rent or purchase one. Typically, these will allow you to get in there and really remove whatever is keeping your drain from working properly. You may want to try to avoid liquid drain cleaners as they are capable of causing additional damage that may eventually cost more to fix. If you are unable to remove the clog with these steps then you may want to contact a local plumber for assistance.
As a new homeowner, preparation can be your best friend. In the event of an emergency, you will know what steps to take to minimize the damage to your home and your wallet. It can also give you the ability to spot an issue and find a solution before you are dealing with water where it doesn't belong.


Stem cell therapy may soon be the gold standard for treating – are you ready? – hair loss. Hundreds of thousands of men and women suffer from hair loss due to various causes. Each year, thousands of them opt for hair transplant procedures, which are invasive, don't always work and often result in scarring. Stem cell therapy for hair regrowth, on the other hand, doesn't have these same drawbacks. It is far less invasive and leaves no scars, and the early reports are that it is quite successful for a number of types of hair loss.
According to one specialist in treating hair loss, stem cells are especially helpful for women dealing with female pattern hair loss – hair thinning that leaves scalp shining through. For patients dealing with thinning hair, stem cells can promote thicker hair and regeneration of dead hair follicles.
Stem cells are the body's natural healing engine. They are undifferentiated body cells that have the capacity to specialize into particular cell types, like the cells that produce hair. Thinning hair is the result of hair follicles dying off. Stem cells have the potential to regenerate the lost cells and produce more hair follicles, and thus, more hair growing from the scalp.
The procedure for re-growing hair with stem cells starts with taking a small amount of the patient's blood. The doctor then uses a special type of centrifuge to separate out platelet-rich plasma and stem cells. That mixture is combined with special nutrients and healing factors, and injected into the scalp. The doctor then triggers a healing response by using small needles to create tiny wounds in the scalp.
Does Hair Regrowth with Stem Cells Work?
According to doctors who work in the field and have been using the procedure, they typically see about 80 percent hair regrowth in their patients.
A number of clinics and hair loss facilities around the country offer stem cell hair regrowth treatments. In addition, similar stem cell treatments are being used for other cosmetic procedures, including lip plumping, breast enhancement, acne scar treatment and wrinkle reduction. The stem cell treatments are less expensive, less invasive and carry fewer risks than surgical procedures used for the same purpose. Stem cell treatments are also often offered for general rejuvenation and renewal purposes, and may be helpful in treating many disorders and diseases.


text:
Upper Valley Music Center
Arts & CraftsEducation
8 South Park Street Lebanon NH 03766
UV Music Center is conveniently located just off Interstate 89 at Exit 18 in downtown Lebanon, New Hampshire, Five miles east of White River Jct., VT and five miles south of Hanover.
The Upper Valley Music Center is a community music school based in Lebanon, NH, serving more than 1,200 students a year from across the Upper Valley region of Vermont and New Hampshire. UVMC's expert faculty work with beginning through advanced students and teach programs designed for ages birth through adulthood. UVMC is a 501(c)3 non-profit organization and relies on the generosity of individuals, foundations, and businesses to support music education activities.
Individual Lessons on a range of instruments
Suzuki Program on cello, viola, and violin
Music Together early childhood music classes
Community Orchestra and Chorus for adults
Many programs for beginners
Gallery Image uv%20music%20center.1.jpg
Fiddle Class Open House
Fiddle, Open house, UVMC, Upper Valley Music Center, Fun, Openhouse,
Slow Jam
Slow Jam, Music,
Friday Feb 3, 2023
Chamber Music Reading & Potluck
Music, Chamber Music, UVMC, Upper Valley Music Center, Folk, Classical
Friday Feb 17, 2023
Friday Mar 3, 2023
Chamber Music Reading
Chamber Music, Music, UVMC, Upper Valley Music Center, Folk, Classical,
Friday Mar 17, 2023


text:
Gonzalo Ruiz-Navarro - Artist
Back to Visual Arts Faculty List
Glen Echo Park Arts Center
Gonzalo Ruiz Navarro is a native of Spain. His interest in painting began at an early age inspired by the rich heritage left in his country by great masters such as Diego Velázquez or Joaquín Sorolla. He started his formal education pursuing a Master's in Fine Arts from the University of Valencia. This was followed by studies on Drawing and Painting at the University of Toledo, the University of Alcalá de Henares, the College of Doctors and Graduates in Madrid and the Taller del Prado Academy in Madrid. Later, Gonzalo had the privilege of working under the personal instruction of noted Spanish portraitist Carlos Moreu Spa and also studied figure painting at the Academy of Art and Contemporaneous Artists in Madrid, under the direction of the world-renown Chilean artist Guillermo Muñoz Vera.
Currently based in Washington, DC, Gonzalo works as a landscape painter and portrait artist commissioned by clients in both the USA and Europe. He gives art instruction at The Yellow Barn Studio (Glen Echo, MD), Washington Artworks (Rockville, MD) and The Griffin Art Center (Frederick, MD).
See Sample Works by Faculty Artists
Gonzalo has shown his works in numerous exhibitions and won several awards. During his time in Spain, he exhibited in galleries throughout the country. Recently he had several solo exhibitions in Washington, DC and Maryland. He has participated in collective exhibitions in DC , Virginia, Maryland and Massachusetts. He has been selected in juried exhibitions and has been awarded in Spain with the First Prize in the 23 APACC TYRIUS Art Competition 2007, the First Prize in the Painting Competition of Aranjuez 2001, and the Second Prize in the Painting Competition of Aranjuez 2000. Alongside his career as a painter, Gonzalo has extensive teaching experience and has held management positions at several educational institutions. He is Art Committee Chair at the International Monetary Fund and a member of the Portrait Society of America.


We can judge whether Raymond James Financial, Inc. (NYSE:RJF) is a good investment right now by following the lead of some of the best investors in the world and piggybacking their ideas. There's no better way to get these firms' immense resources and analytical capabilities working for us than to follow their lead into their best ideas. While not all of these picks will be winners, our research shows that these picks historically outperformed the market when we factor in known risk factors.
Is Raymond James Financial, Inc. (NYSE:RJF) a superb investment now? The smart money is becoming less hopeful. The number of long hedge fund bets fell by 6 lately. Our calculations also showed that RJF isn't among the 30 most popular stocks among hedge funds. RJF was in 25 hedge funds' portfolios at the end of December. There were 31 hedge funds in our database with RJF positions at the end of the previous quarter.
Let's view the fresh hedge fund action regarding Raymond James Financial, Inc. (NYSE:RJF).
How have hedgies been trading Raymond James Financial, Inc. (NYSE:RJF)?
Heading into the first quarter of 2019, a total of 25 of the hedge funds tracked by Insider Monkey held long positions in this stock, a change of -19% from the previous quarter. On the other hand, there were a total of 28 hedge funds with a bullish position in RJF a year ago. So, let's check out which hedge funds were among the top holders of the stock and which hedge funds were making big moves.
When looking at the institutional investors followed by Insider Monkey, Andreas Halvorsen's Viking Global has the number one position in Raymond James Financial, Inc. (NYSE:RJF), worth close to $185.5 million, corresponding to 1.1% of its total 13F portfolio. The second most bullish fund manager is Glenn Greenberg of Brave Warrior Capital, with a $168.9 million position; the fund has 8.6% of its 13F portfolio invested in the stock. Remaining members of the smart money that are bullish comprise Ken Fisher's Fisher Asset Management, Ken Griffin's Citadel Investment Group and Steven Richman's East Side Capital (RR Partners).
Due to the fact that Raymond James Financial, Inc. (NYSE:RJF) has faced a decline in interest from the aggregate hedge fund industry, it's easy to see that there were a few hedgies that decided to sell off their positions entirely heading into Q3. Intriguingly, Jonathon Jacobson's Highfields Capital Management dumped the largest stake of the 700 funds watched by Insider Monkey, comprising close to $106.1 million in stock. James Parsons's fund, Junto Capital Management, also sold off its stock, about $95.6 million worth. These bearish behaviors are intriguing to say the least, as aggregate hedge fund interest fell by 6 funds heading into Q3.
Let's now review hedge fund activity in other stocks similar to Raymond James Financial, Inc. (NYSE:RJF). These stocks are Varian Medical Systems, Inc. (NYSE:VAR), Live Nation Entertainment, Inc. (NYSE:LYV), Domino's Pizza, Inc. (NYSE:DPZ), and HEICO Corporation (NYSE:HEI). This group of stocks' market values are similar to RJF's market value.
As you can see these stocks had an average of 32.5 hedge funds with bullish positions and the average amount invested in these stocks was $1064 million. That figure was $728 million in RJF's case. Live Nation Entertainment, Inc. (NYSE:LYV) is the most popular stock in this table. On the other hand Varian Medical Systems, Inc. (NYSE:VAR) is the least popular one with only 30 bullish hedge fund positions. Compared to these stocks Raymond James Financial, Inc. (NYSE:RJF) is even less popular than VAR. Our calculations showed that top 15 most popular stocks among hedge funds returned 19.7% through March 15th and outperformed the S&P 500 ETF (SPY) by 6.6 percentage points. Unfortunately RJF wasn't in this group. Hedge funds that bet on RJF were disappointed as the stock returned 10.6% and underperformed the market. If you are interested in investing in large cap stocks, you should check out the top 15 hedge fund stocks as 13 of these outperformed the market.
Were Hedge Funds Right About Souring On Vornado Realty Trust (VNO)? Were Hedge Funds Right About Flocking Into Marvell Technology Group (MRVL)? Is Seagate Technology (STX) A Good Stock To Buy? Hedge Funds Haven't Been This Bullish On DexCom, Inc. (DXCM) Since 2015... Were Hedge Funds Right About Dumping Elanco Animal Health Incorporated (ELAN... Do Hedge Funds Love Lincoln National Corporation (LNC)?


text:
Q: how to solve error when trying to connect DB in SQL SERVER using JDBC DRIVER Hello i have this issue trying to connecting  the Database, it seem's to be an error while the driver is connecting to the DB, i have the Controller Code , I am using PreparedStatement , this declaration its ok whit the 6.0.8 Version of the driver?
I post the controller Code. its something like this. i require some help. I found a Solution in my other post. Regards.
package application;

import java.net.URL;
import java.sql.Connection;
import java.sql.DriverManager;
import java.sql.PreparedStatement;
import java.sql.ResultSet;
import java.sql.SQLException;
import java.util.ResourceBundle;

import javafx.collections.FXCollections;
import javafx.collections.ObservableList;
import javafx.fxml.FXML;
import javafx.fxml.Initializable;
import javafx.scene.control.Button;
import javafx.scene.control.TableColumn;
import javafx.scene.control.TableView;
import javafx.scene.control.TextField;
import javafx.scene.control.cell.PropertyValueFactory;

public class Controlador implements Initializable{

    ObservableList <Cliente> data =FXCollections.observableArrayList();
   @FXML TableView<Cliente>  tablacliente;
   @FXML TableColumn<Cliente, String> nombrescol;
   @FXML TableColumn<Cliente,String > apellidoscol;
   @FXML TableColumn<Cliente, Integer>  clienteid;
   PreparedStatement preparedStatement=null;
   ResultSet rs=null;
   Connection Conexion=null;
   @FXML  private TextField nm;
    @FXML private TextField ap;
    @FXML private Button btn;

@Override
public void initialize(URL arg0, ResourceBundle arg1) {
    clienteid.setCellValueFactory(new PropertyValueFactory <Cliente, Integer>("id_cliente"));
    nombrescol.setCellValueFactory(new PropertyValueFactory <Cliente, String>("nombres"));
     apellidoscol.setCellValueFactory(new PropertyValueFactory <Cliente, String>("apellidos"));
    agregar();
}

// connect main class to controller

public void conexion(){

    String query="select * from cliente";

    try {

        Conexion=DriverManager.getConnection("jdbc:sqlserver://DESKTOP-4JA6SFR:1433;databaseName=prueba", "sa", "123");
        preparedStatement=Conexion.prepareStatement(query);
        rs=preparedStatement.executeQuery(query);

        while ( rs.next() )
        {
        data.add(new Cliente(
                rs.getString("nombre"),
                rs.getString("apellido"),
                rs.getInt("id")
                ));
        tablacliente.setItems(data);
        }

        preparedStatement.close();
        rs.close();

        }

    catch (SQLException e) {
         e.printStackTrace();
     }
     if(Conexion!=null) {
         System.out.println("conexion exitosa");

     }
     if(Conexion==null) {
         System.out.println("no se conecto ");

     }
}

public void agregar() {
 String Nombre=nm.getText();
 String Apellido=ap.getText();
 String query="INSERT INTO CLIENTE (nombre,apellido)VALUES (?,?)";

 preparedStatement=null;

 try
 {
     preparedStatement=Conexion.prepareStatement(query);
     preparedStatement.setString(1, Nombre);
     preparedStatement.setString(2, Apellido);

 }
 catch (SQLException e) {
     e.printStackTrace();
 }
 finally {
     try {
        preparedStatement.execute(query);
    } catch (SQLException e) {

        e.printStackTrace();
    }
     try {
        preparedStatement.close();
    } catch (SQLException e) {

        e.printStackTrace();
    }
 }
   nm.clear();
   ap.clear();
   conexion();

}
}

this is the error's that i had trying to connect and insert the data into the database in SQL SERVER 2014.
java.sql.SQLException: No suitable driver found for jdbc:sqlserver://DESKTOP-4JA6SFR:1433;databaseName=prueba
    at java.sql.DriverManager.getConnection(Unknown Source)
    at java.sql.DriverManager.getConnection(Unknown Source)
    at application.Controlador.agregar(Controlador.java:88)
    at application.Main.main(Main.java:33)
    at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
    at sun.reflect.NativeMethodAccessorImpl.invoke(Unknown Source)
    at sun.reflect.DelegatingMethodAccessorImpl.invoke(Unknown Source)
    at java.lang.reflect.Method.invoke(Unknown Source)
    at com.sun.javafx.application.LauncherImpl.launchApplicationWithArgs(LauncherImpl.java:389)
    at com.sun.javafx.application.LauncherImpl.launchApplication(LauncherImpl.java:328)
    at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
    at sun.reflect.NativeMethodAccessorImpl.invoke(Unknown Source)
    at sun.reflect.DelegatingMethodAccessorImpl.invoke(Unknown Source)
    at java.lang.reflect.Method.invoke(Unknown Source)
    at sun.launcher.LauncherHelper$FXHelper.main(Unknown Source)
java.lang.ClassNotFoundException: com.microsoft.sqlserver.jdbc.SQLServerDriver
    at java.net.URLClassLoader.findClass(Unknown Source)
    at java.lang.ClassLoader.loadClass(Unknown Source)
    at sun.misc.Launcher$AppClassLoader.loadClass(Unknown Source)
    at java.lang.ClassLoader.loadClass(Unknown Source)
    at java.lang.Class.forName0(Native Method)
    at java.lang.Class.forName(Unknown Source)
    at application.Controlador.conexion(Controlador.java:51)
    at application.Controlador.agregar(Controlador.java:97)
    at application.Main.main(Main.java:33)
    at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
    at sun.reflect.NativeMethodAccessorImpl.invoke(Unknown Source)
    at sun.reflect.DelegatingMethodAccessorImpl.invoke(Unknown Source)
    at java.lang.reflect.Method.invoke(Unknown Source)
    at com.sun.javafx.application.LauncherImpl.launchApplicationWithArgs(LauncherImpl.java:389)
    at com.sun.javafx.application.LauncherImpl.launchApplication(LauncherImpl.java:328)
    at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
    at sun.reflect.NativeMethodAccessorImpl.invoke(Unknown Source)
    at sun.reflect.DelegatingMethodAccessorImpl.invoke(Unknown Source)
    at java.lang.reflect.Method.invoke(Unknown Source)
    at sun.launcher.LauncherHelper$FXHelper.main(Unknown Source)
java.sql.SQLException: No suitable driver found for jdbc:sqlserver://DESKTOP-4JA6SFR:1433;databaseName=prueba
    at java.sql.DriverManager.getConnection(Unknown Source)
    at java.sql.DriverManager.getConnection(Unknown Source)
    at application.Controlador.conexion(Controlador.java:56)
    at application.Controlador.agregar(Controlador.java:97)
    at application.Main.main(Main.java:33)
    at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
    at sun.reflect.NativeMethodAccessorImpl.invoke(Unknown Source)
    at sun.reflect.DelegatingMethodAccessorImpl.invoke(Unknown Source)
    at java.lang.reflect.Method.invoke(Unknown Source)
    at com.sun.javafx.application.LauncherImpl.launchApplicationWithArgs(LauncherImpl.java:389)
    at com.sun.javafx.application.LauncherImpl.launchApplication(LauncherImpl.java:328)
    at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
    at sun.reflect.NativeMethodAccessorImpl.invoke(Unknown Source)
    at sun.reflect.DelegatingMethodAccessorImpl.invoke(Unknown Source)
    at java.lang.reflect.Method.invoke(Unknown Source)
    at sun.launcher.LauncherHelper$FXHelper.main(Unknown Source)
java.lang.ClassNotFoundException: com.microsoft.sqlserver.jdbc.SQLServerDriver
    at java.net.URLClassLoader.findClass(Unknown Source)
    at java.lang.ClassLoader.loadClass(Unknown Source)
    at sun.misc.Launcher$AppClassLoader.loadClass(Unknown Source)
    at java.lang.ClassLoader.loadClass(Unknown Source)
    at java.lang.Class.forName0(Native Method)
    at java.lang.Class.forName(Unknown Source)
    at application.Controlador.conexion(Controlador.java:51)
    at application.Main.main(Main.java:34)
    at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
    at sun.reflect.NativeMethodAccessorImpl.invoke(Unknown Source)
    at sun.reflect.DelegatingMethodAccessorImpl.invoke(Unknown Source)
    at java.lang.reflect.Method.invoke(Unknown Source)
    at com.sun.javafx.application.LauncherImpl.launchApplicationWithArgs(LauncherImpl.java:389)
    at com.sun.javafx.application.LauncherImpl.launchApplication(LauncherImpl.java:328)
    at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
    at sun.reflect.NativeMethodAccessorImpl.invoke(Unknown Source)
    at sun.reflect.DelegatingMethodAccessorImpl.invoke(Unknown Source)
    at java.lang.reflect.Method.invoke(Unknown Source)
    at sun.launcher.LauncherHelper$FXHelper.main(Unknown Source)
java.sql.SQLException: No suitable driver found for jdbc:sqlserver://DESKTOP-4JA6SFR:1433;databaseName=prueba
    at java.sql.DriverManager.getConnection(Unknown Source)
    at java.sql.DriverManager.getConnection(Unknown Source)
    at application.Controlador.conexion(Controlador.java:56)
    at application.Main.main(Main.java:34)
    at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
    at sun.reflect.NativeMethodAccessorImpl.invoke(Unknown Source)
    at sun.reflect.DelegatingMethodAccessorImpl.invoke(Unknown Source)
    at java.lang.reflect.Method.invoke(Unknown Source)
    at com.sun.javafx.application.LauncherImpl.launchApplicationWithArgs(LauncherImpl.java:389)
    at com.sun.javafx.application.LauncherImpl.launchApplication(LauncherImpl.java:328)
    at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
    at sun.reflect.NativeMethodAccessorImpl.invoke(Unknown Source)
    at sun.reflect.DelegatingMethodAccessorImpl.invoke(Unknown Source)
    at java.lang.reflect.Method.invoke(Unknown Source)
    at sun.launcher.LauncherHelper$FXHelper.main(Unknown Source)


tested with scummvm daily build (5 may - 0.4.1 cvs).
indiana jones 4 atlantis german disk version.
music themes of the entire game are played.
silent. This applies to Midi as well as Adlib.
Ticket imported from: #733401. Ticket imported from: bugs/760.
atlantis.s05 (46.9 KB) - added by SF/trinity78 16 years ago.
get reloaded from a savegame, but the queue pointers do.


text:
The Bars where Hemingway drank
It sometimes seems that wherever we go we're following in the footsteps of one Ernest Hemingway, particularly when it comes to bars! The Nobel Prize–winning author could not only write, but drink way better than most. From his time in places like Paris, South of France, Havana, Lima, Venice and the United States, Hemingway loved a drink. From the fanciest hotel bars to dirtiest dives – as long as the drinks were good – he was eager to indulge.
Here, we take a look at some of Hemingway's favourite bars around the world where our paths might have crossed!
The Ritz (Paris, France)
The Ritz, which we recently visited, is so closely tied to the author – who set part of The Sun Also Rises (1926) here – that a bar here is named after him. Hemingway famously liberated the hotel from German forces in 1944, racking up a bar tab of 51 dry martinis shortly thereafter.
Hotel Lutetia (Paris, France)
Another of Hemingway's many Parisian haunts, Hotel Lutetia is where James Joyce wrote part of Ulysses (1922), with Hemingway acting as occasional editor between drinks. The hotel has relatively recently reopened after renovation.
Caffé Roma (Alassio, Italy)
This may have slipped under the radar but there are photographs of Hemingway at the bar in the 1950s when he suggested to the painter Mario Berrino (former owner of the caffé) that the wall of the public garden opposite should be covered with small tiles signed by celebrities. Et voilà!
Les Deux Garcons (Aix-en-Provence, France)
Now closed due to a 2019 fire, this has been Aix's most famous brasserie since it opened in 1792. Paul Cézanne, Émile Zola, Albert Camus, Ernest Hemingway, and other prominent figures all spent time here.
Hotel Casa de Suecia (Madrid, Spain)
Hemingway had a lifelong love affair with Spain. He visited many times from the 1920s and throughout the 1930s – when he covered the Spanish Civil War – to his final visit in 1960. People joke that there are few places in Madrid that don't claim Ernest Hemingway drank there, but he definitely had his favourites. Including this place where he lived here in the fifties. It has since been fully renovated and is now owned by NH group who've since installed the aptly-named Hemingway Cocktail Bar.
Café Iruña (Pamplona, Spain)
Hemingway who documented his Pamplona experiences in his novel 'The Sun Also Rises', fell in love with Pamplona and its bars, most of which are still there today in the main square. Quite possibly his favourite was this one founded in 1888. It's one of the most beautiful places in Pamplona to have a drink because its original appearance has been painstakingly preserved.
Just as Hemingway's novel pays homage to Café Iruña, the venue itself pays homage to Hemingway by having a quiet designated bar area called 'El Rincón de Heminway' where you can find the writer himself in the form of a bronze statue which leans over the bar as if waiting to be served, as Hemingway would have done so many times before.
Harry's Bar (Venice, Italy)
During Hemingway's time in Venice in the late '40s, he practically lived at Harry's Bar, where he had a table of his own and often drank with the owner. The bar features in his short story Over the River and Into the Trees (1950).
Where have you been following in Hemingway's famous footsteps?
Category: Europe, TripsTags: Ernest Hemingway
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33 Comments on "The Bars where Hemingway drank"
Pingback: ReBlogging 'The Bars where Hemingway drank' – Link Below | Relationship Insights by Yernasia Quorelios
We have only been to the Hemingway bars in Key West. His home away from home was probably Captain Tony's. We have also been to the Hemingway House, where descendants of his six toed cats still lay around as if they own the place. One will obligingly extend it's six toes long enough for a tourist to snap a picture. He lived in Key West before relocating to Cuba. Good bar choices.
If you ever get to Key West…
You're on
Well proud to say I not Hemingway, also drank at the bar of the Ritz and Lutecia in Paris! And yes ,also at Key West, Fl and Havana Cuba!! Cheers
Are you sure you're not Ernest in disguise ?
Just the fame not my type of guy..
Yeah, Another Blogger
Greetings. A few months ago I read To Have And Have Not, a Hemingway novel. I wanted to like it more than I did. It's flawed.
I have to ask. How is it flawed?
There are sequences and characters that, to me, didn't need to be in the book.
Interesting, maybe he could've done with your editorial services.
lolaWi
very interesting read, Sheree!
I love the bar in Pamplona. I've been to several places that Hemmingway visited that most if not all of your readers have ever been to or heard of. In the Bighorn Mountains at the Spear-O-Wigwam ranch there's the Hemmingway Cabin where he stayed and wrote and while looking up the information, I found out he also stayed at Folly Ranch, the ranch right next to where our cabin is. We've ridden through there many a time. 🙂 Rather exciting. He also stayed at the Sheridan Inn which I visited last summer.
That man was everywhere! Thanks fir the additional information.
love this and am going to "reblog" this weekend!
So neat!
Cindy Georgakas
Good to know he drank in style Sheree.
whoa, " 51 dry martinis shortly thereafter." what was the span of that do you know?
I'd like to think it was several days but who knows?
A splendid collection, making J.K. Rowling's café look most abstemious
Indeed and I've only touched on a few of his haunts.
Very cool! You've been to some fabulous places.
I know but not quite as many as EH
I. J. Khanewala
Given how much he drank, this list possibly does not even scratch the surface 🙂
You're absolutely spot on
Reblogged this on prior probability and commented:
I am reblogging Sheree's post featuring some of Ernest Hemingway's favorite watering holes; via "View from the Back".
Pingback: The Bars where Hemingway drank | prior probability
michelegoesglossy
Great tour around the bars Hemingway drunk 👏