The area of a rectangle is 80. What is the angle between the
diagonal of the rectangle and its longer side? 1. The perimeter
of the rectangle is 84 2. The shorter side of the rectangle is 2
Its easy to find from each statement that the longer side is 40
and the shorter is 2. However, how do we find the angle b/w the
diagonal and the longer side? Are the angle measures formed by
the diagonal of a rectangle fixed??? Thanks. L*W = 80 2*(80/w +
w)=84 w^2 -42w +80 =0 Factorizing, we get (w-40)(w-2) = 0 w=40
or 2 Therefore, longer side is 40 and shorter is 2, which is
easier part as you have mentioned. ( First, yes, the internal
angles of a rectangle are 90deg But that wont help you much
here) Neither knowing that the diagonals of the rectangle are of
equal length and they bisect each other. Hmmm.....I am not sure
how to proceed in a fast way.... If I could use Trigonometry, we
can find the angle. Anyways, as the angle can be found using
both the statements ( i ) and ( ii ), the answer in GMAT DS
should be "C".! Re