A framer wants to enclose a rectangular field by a fence divide
it into two smaller rectangular fields by constructing another
fence parallel to one side of the field. The farmer has 3000
yards of fencing. Find the dimension of the field so that total
enclosed area is a maximum. (hint let h be the height and w be
the width) then 3h+2w=3000 You want to maximize the area hw. If
you solve for h in terms of w then substitute into the
expression hw, you get a quadratic function (you could just as
well solve for w in terms of h) Find the maximum of quadratic
using one of three techniques)