Consider four vectors ~ F1, ~ F2, ~ F3, and ~ F4, wheretheir
magnitudes are F1= 43 N, F2= 36 N, F3 = 19 N, andF4 = 54 N.Let
θ1 =120o, θ2 = −130o,θ3 = 200, and θ4 = −67o, measured from
thepositive x axis with the counter-clockwiseangular direction
aspositive. What is the magnitudeof the resultant vector ~F ,
where ~F = ~ F1 +~ F2 +~ F3 +~ F4? Answer in units of N. What is
the direction ofthis resultant vector~F? Note: Give the anglein
degrees, use counterclockwise as the positiveangular direction,
between the limits from the positive xaxis. Answer in units ofo
I worked out the first part of thequestion by using trigonomic
rules. My X value=-5.68671and my Y value=-33.5474. The magnitude
came out to 34.026N. I tried finding the direction by
usingθ=tan-1(y/x) but i cant get the rightanswer.