Okay, lemme do this for Upriver: Radius of the sun: 7 108 m Mass
of the sun: 2 1030 kg Average density: 1410 kg m-3 Density of
iron: 8 103 kg m-3 So we take a shell of iron of thickness D and
calculate how heavy it is. Volume is 4 pi R2 D (when the
thickness is much smaller than the radius of the Sun). V = 4 pi
R2 D = 6 1018 D m[sup3[/sup] = A D Knowing the density of iron
and the volume with parameter D and the mass of the Sun we can
get an estimate of how thick the iron layer can be: D = M / A*Fe
= 2 1030 / 6 1018 * 8 103 = 41 106 m Well, here we see that the
iron shell in the Sun is only 6% of the radius of the Sun. I
assume that the inside of the shell is filled with cheese :-)