Step 3: Enter your full question details hereA particle moves
along a straight line and its position at time t is given by
s(t)= 2t^3 - 24 t^2 + 90 t where s is measured in feet and t in
seconds. Find the velocity (in ft/sec) of the particle at time
t=0: The particle stops moving (i.e. is in a rest) twice, once
when t=A and again when t=B where A < B. A is and B is What is
the position of the particle at time 16? Finally, what is the
TOTAL distance the particle travels between time 0 and time 16