volume with calculus find the volume of the solid whose base is
the area bounded by the lines y=1-(x/2), y=(x/2)-1 and x=0 and
whose cross sections perpendicular to the x axis are equilateral
triangles. do i do v=the integral of (1/2)(2x*x) dx that seems
too simple... also, find the volume of the solid generated by
revolving the region bounded by the graph y=x^2, y=4x-x^2 and
revolved about the line y=6 i got 64/3 pi, is this right? what
am i doing wrong in these two problems?(Headbang)(Bow) How would
you arrive at that integral? What is length of the base of one
of those equilateral triangles? What is the height of that
triangle? What is the area? i have no idea.its an equilateral
triangle so would each side be x?