|Perl: the Markov chain saw| Adding 0 to the string "00001"
forces the string to be interpreted as a number. In your code,
when you say: You force "00001" to be treated as a number, too.
What *is* interesting is *why* "00001" is treated as a number,
since there is also the possibility of doing "aaa" ... "zzz" and
having it work, too. So why does "00001" end up being treated as
"1" by the ".." operator? Probably the perl interpreter looks at
your $low and $high and decides they look like numbers. BTW, you
should not do this $low .. $high stuff - it can hang you badly
if $low and $high end up to be interpreted as strings. At least
use int($low) .. int($high), to force $low and $high to be
interpreted as numbers. In reply to Re: Re: Re: Re: Finding
missing elements in a sequence (code)