You can put this solution on YOUR website! if the length of one
side of a square is doubled and the length of an adjacent side
is decreased by 3, the area of the resulting rectangle exceeds
the area of the original square by 16. The length of a side of
the original square is? Let s = length of the side of the
original square s^2 = original area and the new rectangle
dimensions will be 2s by (s-3) New area - old area = 16 2s(s-3)
- s^2 = 16 2s^2 - 6s - s^2 = 16 2s^2 - s^2 - 6s - 16 = 0 s^2 -
6s - 16 = 0 (s-8)(s+2) = 0 s = 8 units, the length of the
original square Check this by finding the areas 16(8-3) = 80 8*8
= 64