A triangle is inscribed in a circle. The vertices of the
triangle divide the circle into three arcs of lengths 3,4,and 5.
What is the area of the triangle? Not sure how to start the
problem... Could I get some hints please? You must draw a
diagram. Inscribe a triangle in a circle. Draw three radial
segments, one from each vertex to the center, Now you have three
sub-triangles. The sum of their areas is the area you want. The
radius of the circle is . How and why? The angle subtending the
arc of length 5 measures . Again how and why?. If are the length
of two sides of a triangle and is the measure of the angle
between then the area to that triangle is . I think I got it. It
took me a while though.... I understand the radius is 6/pi
because 2pir = 12 r= 6/pi. Then I understood the angle
subtending the arc of length 5 is 5pi/6 because 2pi X 5/12 =
5pi/6 arc of length 4 2pi X 4/12 = 2pi/3 arc of length 3 2pi X
3/12 = pi/2 I fully understand why 1/2absin(theta) gets the area
therefore, 1/2 X 6/pi X 6/pi X sin 5pi/