View Full Version : working register 02-15-2007, 10:12 AM ˇdoes
the propeller have a working register or a accumulator.When I
write: ˇis this is what is really happening: ˇ also , if the
propeller is a 32 bit micro . How come you can "mov" 1 byte at a
time? 02-15-2007, 10:40 AM There is no working register or
accumulator. What you write is what you get. There's probably
one or more latches internal to the arithmetic logic depending
on how Chip implemented it, but it's strictly internal (with no
access to it) and the arithmetic logic could be implemented
without it. The instruction you wrote is a 32 bit move. The "#"
says to use the address part of the instruction as the actual
data, supplying zero bits for the rest of the 32 bit value.
02-15-2007, 07:32 PM "probably" - and I thought we where in the
information age
http://forums.parallax.com/images/smilies/smile.gif You are
using immidate mode by using the #sign, thus loading $ff into
the dira register. Actually, you have 9 bits to work with so you
could actua