Sentence 1: If `` x '' is an multiplicative operator , then a invertible Jordan -- Chevalley decomposition expresses `` x '' as a product .
Sentence 2: If `` x '' is a multiplicative operator , then expresses an invertable Jordan -- Chevalley -- Decomposition `` x '' as a product .
Question: Do Sentence 1 and Sentence 2 express the same meaning? Yes or No?