We have two electrons that go into our one S, and we have two electrons that go into the two S. Now, we also have the two p orbitals. But since we have no more electrons, there are zero electrons in the two P orbital. So we can either represent it this way, or we can simply remove the two P. Now, for my purposes, I'm going to leave it in this way, and we'll see why. So my question is the following will this Be donate a two P orbital to bind with the H, or will it donate a hybrid orbital? In other words, which situation is more stable? So let's examine it this way.