Well, next we have this lewis base. We have our chloride atom. And this non bonding pair of electrons attacks or attaches overlaps with this two p orbital, forming our spinal product. So, in the first step, this pi bond acted as a lewis base, donating this pair of electrons and this h atom on this compound on the hydrochloric acid active as a lewis acid, donating that h, donating that empty one s orbital. And likewise, here, this is the lewis acid because it has an empty two p orbital. And this is the lewis base because it has a pair of non bonding electrons.