Now this time initial is zero. So that becomes zero and we bring over this guy to the right side and we get natural log of the concentration final equals negative k times t final plus because this guy was brought over natural log of the concentration of an initial. Now, this guy also has the same form as the line as a line y equals MX plus B, where this guy is our Y value this guy. The b is our Y intercept. Our slope is negative k, and our x value is time. So let's graph this on an XY plane.