Okay? And we're given a specific heat of water, 4.8
joules per Celsius times gram. So we have to use this formula because we're using little C. So we let this change down GB, Q Two. We basically plug in our Master of Water, 800 grams times 4.8 joules per gram times Celsius times our difference in temperature. So eleven degrees Celsius, and we get 36,784 joules. So this main joules goes into heating the water, increasing temperature of water by eleven degrees.