So let's go to part C.
In part C we have NH three or ammonia. So in this case, we have an N atom. So let's throw out our electron configuration for N.
So two electrons go into the one s, two electrons going to the two s, and now we have three electrons going to our two p. So altogether we have five balanced electrons because we have five electrons in the outermost shell for anna. Now we have the same story as before. For h, we have one electron that goes into the one s. And because we have three h's, that the five plus three gives us eight electrons. So let's throw out our depiction here.