And let's suppose that we have two moles of A, produces 1 mol of B and this is an elementary reaction. So this is the k value, the rate constant. And so in this case, the rate law v is equal to k multiplied by the concentration of A. But because this is an elementary reaction and the coefficient is two, what that means is we'll have a coefficient of two on top of that A. So this reaction is second order with respect to K and with respect to A. And the overall order is also second order.