At the same time, what happens is the other residue, the spartic acid, uses its H to basically interact with the oxygen of the Carbonal. So the oxygen here contains a partial negative charge and the H here contains a partial positive charge. And so, as they interact here, what begins to take place is we basically make the carbon of the carbonyl a better electrophile. So the ultimate reason why we have these two different we have the aspartate and the spartic acid is because one transforms the water into a better nuclear file and the other one transforms the incoming substrate into a better electrophile. And now we can have our reaction take place. The similar reaction, the same type of reaction that took place here, we have this bond breaking, forming a bond with carbon, attacking the carbon nucleophilically, displacing the pi bond, forming that same type of tetrahedral intermediate.