So now we substitute two into one. We replace the concentration of Es with this entire ratio and this is basically what we are left with. So V Naught, the velocity of that enzyme, the rate at which the enzyme catalyzes is equal to K capped, divided by Km multiplied by the concentration of the enzyme multiplied by the concentration of the substrate. Now, we are not yet done. Now, what we basically want to do is we want to assume this same condition that we assumed previously. So I said that under normal physiological conditions, when the reactions take place inside our cells, the concentration of the substrate is much smaller than the concentration than the Km value.