And so instead of having the fragments where we stopped on the A's, we're going to have the fragments where we stop on the g's. And so, because we only have two CS, so this C doesn't count because it's part of the primer. So we have one C and we have a second C. So the complementary would have a g here and a g here. So we only form two fragments. And this lane would contain two bands because we only contain two fragments with different sizes. Then we repeat the process.