And so we get m multiplied by omega squared multiplied by R multiplied by one minus v bar, the density of the fluid is equal to is equal to F multiplied by v. Now, if we keep the velocity on this side and bring the F to this side, we basically get the following results. So m omega squared r multiplied by one minus v bar rho is equal to v, and this is divided by no, not rho, but F, which is a frictional coefficient of that particle. Okay? And the last step is, well, our goal is to make this equation look like the right side of this equation. So notice that the right side of this equation has m one V bar Rho and F, but it doesn't have the omega and R. So we want to bring the omega squared multiplied by R to the other side. Of the equation, and we basically obtain so we have v divided by omega squared r is equal to m one minus v bar rho divided by f. And so this right side of this equation is the same as the right side of this equation.