And once the pyruvate moves in, we form this ternary structure in which we have the pyruvate and the NADH inside the active side. Of that enzyme. Once again, ternary simply means we have three molecules, the enzyme and the two substrate molecules. Now, once we form this complex, only now can we actually transform the Pyruvate into lactate and the NADH into the NAD plus. And once we form the two products, so lactate in this case is product C and NAD plus E is product D. Once we form these two products, only then can they be released from the active side of that enzyme. And because this is an ordered sequential reaction, the order at which these two products are released also matters.