So we have m omega squared r multiplied by one minus v bar multiplied by rho minus FV is equal to zero. So, once again, if we multiply this out, we get back this equation here, and that's why these are essentially equivalent. Now, in the next step, we want to bring this term f multiplied by v to the right side. And so we get m multiplied by omega squared multiplied by R multiplied by one minus v bar, the density of the fluid is equal to is equal to F multiplied by v. Now, if we keep the velocity on this side and bring the F to this side, we basically get the following results. So m omega squared r multiplied by one minus v bar rho is equal to v, and this is divided by no, not rho, but F, which is a frictional coefficient of that particle. Okay?