So these are the substrate molecules and these are the product molecules. What the turnover value tells us what the turnover number tells us is the total number of substrate molecules that can be transformed into the product molecules per unit time, for example, per second, when only a single active site, a single enzyme is actually being used. Now, to demonstrate how this actually works and how we can calculate the K two value, let's take a look at the following hypothetical example. So let's suppose we have the beaker. Inside that beaker we have a mixture of some particular type of enzyme and the concentration, a total of that enzyme inside the mixture is given to us to be 0.1 molar now, let's suppose that experimentally, we calculate the V max value of that particular enzyme to be 60,000 molar per second. So at this concentration, when all the active sites of that enzyme mixture are filled with the substrate, we know that the maximum rate of the reaction is 60,000 molar every single second.