So this quantity is equivalent to 21,300 Joules and that's a positive value. While this quantity, we said just a moment ago we're going to use negative five kilojoules, or equivalently negative 5000 Joules. Now, the goal is to ultimately calculate what the Q value has to be, what the ratio of the concentrations of the products to the reactants has to be for the reaction to actually be product favored, for this to be negative 5000 on negative value. Now, notice we could have also used negative five joules or negative 1 million joules. Basically any negative value here works because any negative value means this reaction will be spontaneous under that Q situation, under that concentration of products and reactants. So if we take this equation now and solve for a log of Q, we get that log of Q is equal to so this term is brought to this side.