And we know from part D that this is equal to also one eight plus one 8th plus one eight or three eighths. So to find the final probability, we simply add up these individual probabilities of these three mutually exclusive events. So we have one eight plus three eight plus three eighths. And that gives us seven eights. So this is the probability of these two individuals, the couple producing at most two boys. So we have one eight in this case for zero boys, three eights for one boy, and three eighths for two boys.