Now M is the slope that's v max divided by Km, x is a substrate concentration and Y is simply the velocity, the rate of that enzyme. So we see that this equation correctly describes the behavior of the enzyme at the beginning of that reaction. Not only that, but this equation also describes a reaction that has first order. So remember in our discussion on the rate law we said that if the rate law looks like this, then our reaction is in fact a first order reaction where V is the rate of that particular reaction, k is the rate constant and this is a substitute concentration. And this coefficient, this exponent of one basically describes a first order reaction. And this looks like this or this looks like this where V is v naught, k is V max divided by Km and this quantity is equal to this.