So once again, once phosphate Enlyruvate is formed, once we form this molecule here, the reverse steps of Glycolysis are followed until fructose one SIG bisphosphate is formed, until we form this molecule here. And these steps, steps three to seven, are equilibrium and will readily occur under the conditions that favor the formation of those glucose molecules. But why doesn't fructose one six bisphosphate simply follow the reverse step that we saw in Glycolysis to form the fructose six phosphate? Well, because in Glycolysis, fructose six phosphate form fructose one six bits phosphate via an irreversible step. And what that means is in Glycolysis, this step was basically a very exergonic step. And in this case, we can't simply reverse the steps of Glycolysis because that would mean we would have to input a very large amount of energy.