So now we're basically going to use the same argument as in this case, but we're going to reverse because at the end of the reaction so when we have a very, very high concentration of substrate that means the Km value is much smaller than the substrate concentration. So for example, if we're somewhere here along the X axis, this quantity, this concentration is much higher than Km. And so what that means is towards the end we see that the concentration of S is much, much higher than the value of Km. And so by the same logic that we used here, the sum of Km and the substrate concentration is about equal to simply the substrate concentration. And so if we take this mechanics methane equation it will simplify itself to this. So V knot is equal to V max divided by the ratio.