And because the cyclic form is more stable and lower in energy, it's the cyclic form of the sugar that will predominate. So let's take a look at glucose. Glucose is an example of an aldohexose. And what that means is it contains an alkali group on one end, and it contains six carbon atoms, confirmed 12345 and six. So the D glucose will predominate in the cyclic form. And because this is the open chain form, it will have to undergo an intramolecular nucleophilic addition reaction to form the cyclic conformation.