So let's begin with one. The VMAX is lowered and the VMAX is lowered for the same reason that the VMAX is lowered in this uncompetitive inhibition case. So we simply decrease the number of active size, number of enzymes that are functional. And if we decrease that value, we essentially decrease the VMAX. So since some number of inhibitors are balanced on the enzyme at any given moment in time and that inhibits the functionality of the enzyme, less functional enzymes will be present, and so VMAX will decrease. Now, let's move on to two.