Number two, it depends on the concentration of that enzyme. And number three, it depends on the rate constant, KCAD divided by Km. Now, A makes sense because if we have more substrate, more substrate is going to bind on the active side and more that substrate will basically be transformed into the product as a result. Likewise, if we increase the concentration of the enzyme we have more active sites and so more likelihood that the substrate will be transformed into the product. And finally, what about KCAD divided by Km? What exactly is the meaning behind KCAD divided by Km, the rate constant of this reaction?