Results as dict/array of dict?
### Edit

This issue was 8 years old when it was brought to my attention again. Here are the methods you would want to use:

* [dicts()](http://docs.peewee-orm.com/en/latest/peewee/api.html#BaseQuery.dicts)
* [tuples()](http://docs.peewee-orm.com/en/latest/peewee/api.html#BaseQuery.tuples)
* [namedtuples()](http://docs.peewee-orm.com/en/latest/peewee/api.html#BaseQuery.namedtuples)

```python
query = SomeModel.select().dicts()
for row in query:  # Each row is a dict.
    print(row['id'])
```

The information further down is no longer correct.

See comment:

https://github.com/coleifer/peewee/issues/134#issuecomment-704935841

----------------------------

I'm not sure why this should be a part of peewee itself, unless for performance reasons you're concerned about the overhead of class creation.  You can see in flask-peewee some helpers already exist:
- https://github.com/coleifer/flask-peewee/blob/master/flask_peewee/serializer.py
- https://github.com/coleifer/flask-peewee/blob/master/flask_peewee/utils.py#L65

You can save by not creating model instances by iterating over the cursor:

``` python

db = SqliteDatabase(...)

query = SomeModel.select()
cursor = db.execute(query)

ncols = len(cursor.description)
colnames = [cursor.description[i][0] for i in range(ncols)]
results = []

for row in cursor.fetchall():
    res = {}
    for i in range(ncols):
        res[colnames[i]] = row[i]
    results.append(res)
```

If you want to get even more low-level, you can take the sql generated by peewee and use a row factory:
- http://docs.python.org/2/library/sqlite3.html#row-objects
 Well, actually, because it's cumbersome to do that even for single rows - getting a dict out of a row makes it much easier to do functional coding than iterating through the column names, and even though I usually do use row factories when using SQL directly, that's the kind of thing I expect a model to do for me.

So please consider doing this, at least for single rows.

(also, I'm not using flask)

On Dec 5, 2012, at 03:00 , Charles Leifer notifications@github.com wrote:

> I'm not sure why this should be a part of peewee itself, unless for performance reasons you're concerned about the overhead of class creation. You can see in flask-peewee some helpers already exist:
> 
> https://github.com/coleifer/flask-peewee/blob/master/flask_peewee/serializer.py
> https://github.com/coleifer/flask-peewee/blob/master/flask_peewee/utils.py#L65
> You can save by not creating model instances by iterating over the cursor:
> 
> db = SqliteDatabase(...)
> 
> query = SomeModel.select()
> cursor = db.execute(query)
> 
> ncols = len(cursor.description)
> colnames = [cursor.description[i][0] for i in range(ncols)]
> results = []
> 
> for row in cursor.fetchall():
>     res = {}
>     for i in range(ncols):
>         res[colnames[i]] = row[i]
>     results.append(res)
> If you want to get even more low-level, you can take the sql generated by peewee and use a row factory:
> 
> http://docs.python.org/2/library/sqlite3.html#row-objects
> —
> Reply to this email directly or view it on GitHub.
 If it's not for performance reasons, you could probably just use a helper @coleifer linked to and so something like that. I haven't tested this though.

``` python

from itertools import imap
from flask_peewee.utils import get_dictionary_from_model

for dct in imap(get_dictionary_from_model, model.select()):
     print dct
```

Or if that's too much code to write everytime, define your own BaseModel and wrap `select`.
 Yeah, as @squiddy said -- there are a lot of ways to do this, and if it is not for performance reasons just wrap select(), or give your model instances an "to_dict()" method or something.
 :japanese_ogre: 
 As I do In MySQL (as I didn't check others):

1. `select().execute()` in one step
2. iterate through cursorwrapper
3. getting values by literal column names through Model attributes instead of numeric indexing, as former is more straightforward for me

```
cursorwrapper = SomeModel.select().execute()

colnames = [name[0] for name in cursorwrapper.cursor.description]
results = []

for row in cursorwrapper:
    res = {}
    for cname in colnames:
        res[cname] = getattr(row, cname)
    results.append(res)
``` This is 8 years old. For quite a long time, Peewee has supported this out-of-the-box with the following query methods:

* [dicts()](http://docs.peewee-orm.com/en/latest/peewee/api.html#BaseQuery.dicts)
* [tuples()](http://docs.peewee-orm.com/en/latest/peewee/api.html#BaseQuery.tuples)
* [namedtuples()](http://docs.peewee-orm.com/en/latest/peewee/api.html#BaseQuery.namedtuples) @coleifer Thank you for your info and your work. Though as @coleifer pointed out  that this is a 8 years old post, but as this github issue is among the top finds of search engines regarding this topic and I didn't find a good example code for usage of the pretty useful `dicts()` method (thank to @coleifer of course), I decided to post one for future readers:

```
query = SomeModel.select().dicts()

for row in query:
    print(type(row))
```
**Out:**
```
<class 'dict'>
<class 'dict'>
.
.
<class 'dict'>
``` More concisely retaining the query:
```python
query = SomeModel.select()
print(list(query.dicts()))
```
One liner:
```python
print(list(SomeModel.select().dicts))
```
It would be grand if one could do something like this:

```
    >>> m = Model()
    >>> print m.select()
    [{'id':1, 'name':'foo'},{'id':2, 'name':'bar'}]
```

i.e., returning each row as a dict. This would be especially handy for returning JSON result sets, and could probably be done using **iter** to return self._data for the model.
