On the board, Bob wrote n positive integers in [base](https://en.wikipedia.org/wiki/Positional_notation#Base_of_the_numeral_system) 10 with sum s (i. e. in decimal numeral system). Alice sees the board, but accidentally interprets the numbers on the board as base-11 integers and adds them up (in base 11).

What numbers should Bob write on the board, so Alice's sum is as large as possible?

Input

The input consists of multiple test cases. The first line contains an integer t (1 ≤ t ≤ 100) — the number of test cases. The description of the test cases follows.

The only line of each test case contains two integers s and n (1 ≤ s ≤ 10^9; 1 ≤ n ≤ min(100, s)) — the sum and amount of numbers on the board, respectively. Numbers s and n are given in decimal notation (base 10).

Output

For each test case, output n positive integers — the numbers Bob should write on the board, so Alice's sum is as large as possible. If there are multiple answers, print any of them.

Example

Input


6
97 2
17 1
111 4
100 2
10 9
999999 3


Output


70 27 
17 
3 4 100 4
10 90
1 1 2 1 1 1 1 1 1 
999900 90 9

Note

In the first test case, 70_{10} + 27_{10} = 97_{10}, and Alice's sum is $$$70_{11} + 27_{11} = 97_{11} = 9 ⋅ 11 + 7 = 106_{10}. (Here x_b represents the number x in base b.) It can be shown that it is impossible for Alice to get a larger sum than 106_{10}$$$.

In the second test case, Bob can only write a single number on the board, so he must write 17.

In the third test case, 3_{10} + 4_{10} + 100_{10} + 4_{10} = 111_{10}, and Alice's sum is $$$3_{11} + 4_{11} + 100_{11} + 4_{11} = 110_{11} = 1 ⋅ 11^2 + 1 ⋅ 11 = 132_{10}. It can be shown that it is impossible for Alice to get a larger sum than 132_{10}$$$.
import sys
import math
import heapq
import bisect
from collections import Counter
from collections import defaultdict
from io import BytesIO, IOBase
from itertools import permutations
import string


class FastIO(IOBase):
    newlines = 0

    def __init__(self, file):
        import os
        self.os = os
        self._fd = file.fileno()
        self.buffer = BytesIO()
        self.writable = "x" in file.mode or "r" not in file.mode
        self.write = self.buffer.write if self.writable else None
        self.BUFSIZE = 8192

    def read(self):
        while True:
            b = self.os.read(self._fd, max(self.os.fstat(self._fd).st_size, self.BUFSIZE))
            if not b:
                break
            ptr = self.buffer.tell()
            self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
        self.newlines = 0
        return self.buffer.read()

    def readline(self):
        while self.newlines == 0:
            b = self.os.read(self._fd, max(self.os.fstat(self._fd).st_size, self.BUFSIZE))
            self.newlines = b.count(b"\n") + (not b)
            ptr = self.buffer.tell()
            self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
        self.newlines -= 1
        return self.buffer.readline()

    def flush(self):
        if self.writable:
            self.os.write(self._fd, self.buffer.getvalue())
            self.buffer.truncate(0), self.buffer.seek(0)


class IOWrapper(IOBase):
    def __init__(self, file):
        self.buffer = FastIO(file)
        self.flush = self.buffer.flush
        self.writable = self.buffer.writable
        self.write = lambda s: self.buffer.write(s.encode("ascii"))
        self.read = lambda: self.buffer.read().decode("ascii")
        self.readline = lambda: self.buffer.readline().decode("ascii")


sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")


def get_int():
    return int(input())


def get_ints():
    return list(map(int, input().split(' ')))


def get_int_grid(n):
    return [get_ints() for _ in range(n)]


def get_str():
    return input().strip()


def get_strs():
    return get_str().split(' ')


def flat_list(arr):
    return [item for subarr in arr for item in subarr]


def yes_no(b):
    if b:
        return "YES"
    else:
        return "NO"


def binary_search(good, left, right, delta=1, right_true=False):
    """
    Performs binary search
    ----------
    Parameters
    ----------
    :param good: Function used to perform the binary search
    :param left: Starting value of left limit
    :param right: Starting value of the right limit
    :param delta: Margin of error, defaults value of 1 for integer binary search
    :param right_true: Boolean, for whether the right limit is the true invariant
    :return: Returns the most extremal value interval [left, right] which is good function evaluates to True,
            alternatively returns False if no such value found
    """

    limits = [left, right]
    while limits[1] - limits[0] > delta:
        if delta == 1:
            mid = sum(limits) // 2
        else:
            mid = sum(limits) / 2
        if good(mid):
            limits[int(right_true)] = mid
        else:
            limits[int(~right_true)] = mid
    if good(limits[int(right_true)]):
        return limits[int(right_true)]
    else:
        return False


def prefix_sums(a):
    p = [0]
    for x in a:
        p.append(p[-1] + x)
    return p


def solve_a():
    n = get_int()
    s = get_str()
    r = []
    if 'U' in s:
        for x in s:
            if x == 'U':
                r.append('D')
            else:
                r.append(x)
    else:
        for x in s:
            if x == 'D':
                r.append('U')
            else:
                r.append(x)
    return ''.join(r)


xors = [0]

for i in range(1, 3 * 10 ** 5):
    xors.append(xors[-1] ^ i)

def solve_b():
    a, b = get_ints()
    xor = xors[a - 1]
    if xor == b:
        return a
    elif b ^ xor == a:
        return a + 2
    else:
        return a + 1


def solve_c():
    s = list(map(int, get_str()))

    k = 1 << max(0, len(s) - 2)

    cnt = 0
    adds = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0]

    for i in range(k):
        r = s.copy()
        for j in range((len(s) - 2)):
            if i & (1 << j):
                r[j] -= 1
                r[j + 2] += 10
        tmp = 1
        for x in r:
            tmp *= adds[x]
        cnt += tmp
    return cnt - 2


def solve_d():
    s, n = get_ints()
    ans = []
    while n > 1:
        n -= 1
        j = len(str(s))
        while j > -1:
            if s - 10 ** j >= n:
                ans.append(10 ** j)
                s -= 10 ** j
                break
            j -= 1
    ans.append(s)
    return ans



t = get_int()
for _ in range(t):
    print(*solve_d())
