A chess tournament will be held soon, where n chess players will take part. Every participant will play one game against every other participant. Each game ends in either a win for one player and a loss for another player, or a draw for both players.

Each of the players has their own expectations about the tournament, they can be one of two types:

  1. a player wants not to lose any game (i. e. finish the tournament with zero losses); 
  2. a player wants to win at least one game. 



You have to determine if there exists an outcome for all the matches such that all the players meet their expectations. If there are several possible outcomes, print any of them. If there are none, report that it's impossible.

Input

The first line contains a single integer t (1 ≤ t ≤ 200) — the number of test cases.

The first line of each test case contains one integer n (2 ≤ n ≤ 50) — the number of chess players.

The second line contains the string s (|s| = n; s_i ∈ \{1, 2\}). If s_i = 1, then the i-th player has expectations of the first type, otherwise of the second type.

Output

For each test case, print the answer in the following format:

In the first line, print NO if it is impossible to meet the expectations of all players.

Otherwise, print YES, and the matrix of size n × n in the next n lines.

The matrix element in the i-th row and j-th column should be equal to:

  * +, if the i-th player won in a game against the j-th player; 
  * -, if the i-th player lost in a game against the j-th player; 
  * =, if the i-th and j-th players' game resulted in a draw; 
  * X, if i = j. 

Example

Input


3
3
111
2
21
4
2122


Output


YES
X==
=X=
==X
NO
YES
X--+
+X++
+-X-
--+X
#!/usr/bin/env python3
import sys
import getpass  # not available on codechef
import math, random
import functools, itertools, collections, heapq, bisect
from collections import Counter, defaultdict, deque
input = sys.stdin.readline  # to read input quickly

# available on Google, AtCoder Python3, not available on Codeforces
# import numpy as np
# import scipy

M9 = 10**9 + 7  # 998244353
yes, no = "YES", "NO"
# d4 = [(1,0),(0,1),(-1,0),(0,-1)]
# d8 = [(1,0),(1,1),(0,1),(-1,1),(-1,0),(-1,-1),(0,-1),(1,-1)]
# d6 = [(2,0),(1,1),(-1,1),(-2,0),(-1,-1),(1,-1)]  # hexagonal layout
MAXINT = sys.maxsize

# if testing locally, print to terminal with a different color
OFFLINE_TEST = getpass.getuser() == "hkmac"
# OFFLINE_TEST = False  # codechef does not allow getpass
def log(*args):
    if OFFLINE_TEST:
        print('\033[36m', *args, '\033[0m', file=sys.stderr)

def solve(*args):
    # screen input
    if OFFLINE_TEST:
        log("----- solving ------")
        log(*args)
        log("----- ------- ------")
    return solve_(*args)

def read_matrix(rows):
    return [list(map(int,input().split())) for _ in range(rows)]

def read_strings(rows):
    return [input().strip() for _ in range(rows)]

def minus_one(arr):
    return [x-1 for x in arr]

def minus_one_matrix(mrr):
    return [[x-1 for x in row] for row in mrr]

# ---------------------------- template ends here ----------------------------


def solve_(srr):
    # your solution here

    res = [["=" for _ in srr] for _ in srr]

    for i in range(len(srr)):
        res[i][i] = "X"

    if srr.count("2") == 1:
        return []

    arr = [i for i,x in enumerate(srr) if x == "2"]
    brr = arr[1:] + arr[:1]

    for a,b in zip(arr, brr):
        res[a][b] = "+"
        res[b][a] = "-"

    return res


# for case_num in [0]:  # no loop over test case
# for case_num in range(100):  # if the number of test cases is specified
for case_num in range(int(input())):

    # read line as an integer
    k = int(input())

    # read line as a string
    srr = input().strip()

    # read one line and parse each word as a string
    # lst = input().split()

    # read one line and parse each word as an integer
    # a,b,c = list(map(int,input().split()))
    # lst = list(map(int,input().split()))
    # lst = minus_one(lst)

    # read multiple rows
    # arr = read_strings(k)  # and return as a list of str
    # mrr = read_matrix(k)  # and return as a list of list of int
    # mrr = minus_one_matrix(mrr)

    res = solve(srr)  # include input here

    # print length if applicable
    # print(len(res))

    if res == []:
        print(no)
        continue

    print(yes)

    # parse result
    # res = " ".join(str(x) for x in res)
    # res = "\n".join(str(x) for x in res)
    res = "\n".join("".join(str(x) for x in row) for row in res)

    # print result
    # print("Case #{}: {}".format(case_num+1, res))   # Google and Facebook - case number required

    print(res)