A binary string is a string that consists of characters 0 and 1. A bi-table is a table that has exactly two rows of equal length, each being a binary string.

Let \operatorname{MEX} of a bi-table be the smallest digit among 0, 1, or 2 that does not occur in the bi-table. For example, \operatorname{MEX} for \begin{bmatrix} 0011\\\ 1010 \end{bmatrix} is 2, because 0 and 1 occur in the bi-table at least once. \operatorname{MEX} for \begin{bmatrix} 111\\\ 111 \end{bmatrix} is 0, because 0 and 2 do not occur in the bi-table, and 0 < 2.

You are given a bi-table with n columns. You should cut it into any number of bi-tables (each consisting of consecutive columns) so that each column is in exactly one bi-table. It is possible to cut the bi-table into a single bi-table — the whole bi-table.

What is the maximal sum of \operatorname{MEX} of all resulting bi-tables can be?

Input

The input consists of multiple test cases. The first line contains a single integer t (1 ≤ t ≤ 10^4) — the number of test cases. Description of the test cases follows.

The first line of the description of each test case contains a single integer n (1 ≤ n ≤ 10^5) — the number of columns in the bi-table.

Each of the next two lines contains a binary string of length n — the rows of the bi-table.

It's guaranteed that the sum of n over all test cases does not exceed 10^5.

Output

For each test case print a single integer — the maximal sum of \operatorname{MEX} of all bi-tables that it is possible to get by cutting the given bi-table optimally.

Example

Input


4
7
0101000
1101100
5
01100
10101
2
01
01
6
000000
111111


Output


8
8
2
12

Note

In the first test case you can cut the bi-table as follows:

  * \begin{bmatrix} 0\\\ 1 \end{bmatrix}, its \operatorname{MEX} is 2.
  * \begin{bmatrix} 10\\\ 10 \end{bmatrix}, its \operatorname{MEX} is 2.
  * \begin{bmatrix} 1\\\ 1 \end{bmatrix}, its \operatorname{MEX} is 0.
  * \begin{bmatrix} 0\\\ 1 \end{bmatrix}, its \operatorname{MEX} is 2.
  * \begin{bmatrix} 0\\\ 0 \end{bmatrix}, its \operatorname{MEX} is 1.
  * \begin{bmatrix} 0\\\ 0 \end{bmatrix}, its \operatorname{MEX} is 1.



The sum of \operatorname{MEX} is 8.
#----------FASTIOSTART-----------#
from __future__ import division, print_function
import os
import sys
from io import BytesIO, IOBase
if sys.version_info[0] < 3:
	from __builtin__ import xrange as range
	from future_builtins import ascii, filter, hex, map, oct, zip
BUFSIZE = 8192
class FastIO(IOBase):
	newlines = 0
	def __init__(self, file):
		self._fd = file.fileno()
		self.buffer = BytesIO()
		self.writable = "x" in file.mode or "r" not in file.mode
		self.write = self.buffer.write if self.writable else None
	def read(self):
		while True:
			b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
			if not b:
				break
			ptr = self.buffer.tell()
			self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
		self.newlines = 0
		return self.buffer.read()
	def readline(self):
		while self.newlines == 0:
			b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
			self.newlines = b.count(b"\n") + (not b)
			ptr = self.buffer.tell()
			self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
		self.newlines -= 1
		return self.buffer.readline()
	def flush(self):
		if self.writable:
			os.write(self._fd, self.buffer.getvalue())
			self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
	def __init__(self, file):
		self.buffer = FastIO(file)
		self.flush = self.buffer.flush
		self.writable = self.buffer.writable
		self.write = lambda s: self.buffer.write(s.encode("ascii"))
		self.read = lambda: self.buffer.read().decode("ascii")
		self.readline = lambda: self.buffer.readline().decode("ascii")
def print(*args, **kwargs):
	sep, file = kwargs.pop("sep", " "), kwargs.pop("file", sys.stdout)
	at_start = True
	for x in args:
		if not at_start:
			file.write(sep)
		file.write(str(x))
		at_start = False
	file.write(kwargs.pop("end", "\n"))
	if kwargs.pop("flush", False):
		file.flush()
if sys.version_info[0] < 3:
	sys.stdin, sys.stdout = FastIO(sys.stdin), FastIO(sys.stdout)
else:
	sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
#----------FASTIOFINISH----------#
import collections,string,bisect,re,random,queue,itertools,statistics,math
from collections import *
from bisect import *
from string import *
from itertools import * 
from statistics import *
from math import *
from re import *
from queue import *
#----------SASTA_STL-------------#
# stack
class Stack:
    def __init__(self):self.items = []
    def push(self, item):self.items.append(item)
    def pop(self):return self.items.pop()
    def empty(self):return self.items == []
    def size(self):return len(self.items)
    def at(self,idx):
    	try:return self.items[idx]
    	except:return -1
#priority_queue
class priority_queue(object):
    def __init__(self):self.queue = []
    def __str__(self):return ' '.join([str(i) for i in self.queue])
    def empty(self):return len(self.queue) == 0
    def push(self, data):self.queue.append(data)
    def pop(self):
        try:
            max = 0
            for i in range(len(self.queue)):
                if self.queue[i] > self.queue[max]:
                    max = i
            item = self.queue[max]
            del self.queue[max]
            return item
        except IndexError:
            print()
            exit()
#----------SASTA_STL-------------#
mod  = int(1e9+7)
imax = float("inf")
imin = float("-inf")
true = True
false= False
N 	 = int(1e5+10)
none = None
inp = lambda : input()
I   = lambda : int(inp())
M   = lambda : map(int,inp().split())
MS  = lambda : map(str,inp().split())
S   = lambda : list(MS())
L   = lambda : list(M())
def IO():
	try:sys.stdin = open('input.txt', 'r');sys.stdout = open('uttar.txt', 'w')
	except:pass
IO()
#----------TOTKA-----------#
"""
def check(s,n,cc):
	cnt=cc
	for i in range(1,n):
		if s[i]=="0":
			if s[i-1]=="0":continue;
			else:cnt+=1
	return cnt;
def B_(s,n):
	# totka hai dosto !
	cnt=1 if s[0]=="0" else 0
	res=check(s,n,cnt)
	return min(res,2)
def dec(s):
	return int(s,2)
def subs(s,n):
	new=[]
	for i in range(n):
		for j in range(i+1,n+1):
			new.append(dec(s[i:j]))
	return new"""


def kabraji_ka_totka():
	# totka hai dosto !
	n=I()
	res=0
	found="2"
	for i,j in zip(inp(),inp()):
		if i!=j:
			res+=2
			found = "2"
		else:
			res+=(i=="0")
			if i!=found and found != "2":
				res+=1
				found="2"

			else:
				found=i;
	print(res)	

#----------TOTKA----------#
if __name__ == '__main__':
	for i in range(I()):
		#print("Case #"+(str(i+1))+": ")
		kabraji_ka_totka()