Frodo was caught by Saruman. He tore a pouch from Frodo's neck, shook out its contents —there was a pile of different rings: gold and silver...

"How am I to tell which is the One?!" the mage howled.

"Throw them one by one into the Cracks of Doom and watch when Mordor falls!" 

Somewhere in a parallel Middle-earth, when Saruman caught Frodo, he only found n rings. And the i-th ring was either gold or silver. For convenience Saruman wrote down a binary string s of n characters, where the i-th character was 0 if the i-th ring was gold, and 1 if it was silver.

Saruman has a magic function f, which takes a binary string and returns a number obtained by converting the string into a binary number and then converting the binary number into a decimal number. For example, f(001010) = 10, f(111) = 7, f(11011101) = 221.

Saruman, however, thinks that the order of the rings plays some important role. He wants to find 2 pairs of integers (l_1, r_1), (l_2, r_2), such that:

  * 1 ≤ l_1 ≤ n, 1 ≤ r_1 ≤ n, r_1-l_1+1≥ ⌊ n/2 ⌋ 
  * 1 ≤ l_2 ≤ n, 1 ≤ r_2 ≤ n, r_2-l_2+1≥ ⌊ n/2 ⌋ 
  * Pairs (l_1, r_1) and (l_2, r_2) are distinct. That is, at least one of l_1 ≠ l_2 and r_1 ≠ r_2 must hold.
  * Let t be the substring s[l_1:r_1] of s, and w be the substring s[l_2:r_2] of s. Then there exists non-negative integer k, such that f(t) = f(w) ⋅ k.



Here substring s[l:r] denotes s_ls_{l+1}… s_{r-1}s_r, and ⌊ x ⌋ denotes rounding the number down to the nearest integer.

Help Saruman solve this problem! It is guaranteed that under the constraints of the problem at least one solution exists.

Input

Each test contains multiple test cases.

The first line contains one positive integer t (1 ≤ t ≤ 10^3), denoting the number of test cases. Description of the test cases follows.

The first line of each test case contains one positive integer n (2 ≤ n ≤ 2 ⋅ 10^4) — length of the string.

The second line of each test case contains a non-empty binary string of length n.

It is guaranteed that the sum of n over all test cases does not exceed 10^5.

Output

For every test case print four integers l_1, r_1, l_2, r_2, which denote the beginning of the first substring, the end of the first substring, the beginning of the second substring, and the end of the second substring, respectively.

If there are multiple solutions, print any.

Example

Input


7
6
101111
9
111000111
8
10000000
5
11011
6
001111
3
101
30
100000000000000100000000000000


Output


3 6 1 3
1 9 4 9
5 8 1 4
1 5 3 5
1 6 2 4
1 2 2 3
1 15 16 30

Note

In the first testcase f(t) = f(1111) = 15, f(w) = f(101) = 5.

In the second testcase f(t) = f(111000111) = 455, f(w) = f(000111) = 7.

In the third testcase f(t) = f(0000) = 0, f(w) = f(1000) = 8.

In the fourth testcase f(t) = f(11011) = 27, f(w) = f(011) = 3.

In the fifth testcase f(t) = f(001111) = 15, f(w) = f(011) = 3.
import java.io.*;
import java.util.*;

public final class Main {

    static PrintWriter out = new PrintWriter(System.out);
    static FastReader in = new FastReader();
    static Pair[] moves = new Pair[]{new Pair(-1, 0), new Pair(1, 0), new Pair(0, -1), new Pair(0, 1)};
    static int mod = (int) (1e9 + 7);

    public static void main(String[] args) {
        int tt = i();

        while (tt-- > 0) {
            solve();
        }
        out.flush();
    }

    private static void solve() {
        int n = i();
        String s = s();
        int idx = -1;
        for (int i = 1; i <= n; i++) {
            if (s.charAt(i - 1) == '0') {
                idx = i;
                break;
            }
        }
        if (idx > -1) {
            //idx n idx n-1
            if (n - idx >= n / 2) {
                out.println(idx + " " + n + " " + (idx + 1) + " " + n);
            } else {
                out.println(1 + " " + idx + " " + 1 + " " + (idx - 1));
            }
        } else {
            out.println(1 + " " + n / 2 * 2 + " " + 1 + " " + n / 2);
        }
    }

    static int[] pre(int[] a) {
        int[] pre = new int[a.length];
        pre[0] = a[0];
        for (int i = 1; i < a.length; i++) {
            pre[i] = pre[i - 1] + a[i];
        }
        return pre;
    }

    static int[] preRev(int[] a) {
        int[] pre = new int[a.length];
        pre[a.length - 1] = a[a.length - 1];
        for (int i = a.length - 2; i >= 0; i--) {
            pre[i] = pre[i + 1] + a[i];
        }
        return pre;
    }

    static void print(char A[]) {
        for (char c : A) {
            out.print(c);
        }
        out.println();
    }

    static void print(boolean A[]) {
        for (boolean c : A) {
            out.print(c + " ");
        }
        out.println();
    }

    static void print(int A[]) {
        for (int c : A) {
            out.print(c + " ");
        }
        out.println();
    }

    static void print(long A[]) {
        for (long i : A) {
            out.print(i + " ");
        }
        out.println();
    }

    static void print(List<Integer> A) {
        for (int a : A) {
            out.print(a + " ");
        }
    }

    static int i() {
        return in.nextInt();
    }

    static long l() {
        return in.nextLong();
    }

    static String s() {
        return in.nextLine();
    }

    static int[][] inputWithIdx(int N) {
        int A[][] = new int[N][2];
        for (int i = 0; i < N; i++) {
            A[i] = new int[]{i, in.nextInt()};
        }
        return A;
    }

    static int[] input(int N) {
        int A[] = new int[N];
        for (int i = 0; i < N; i++) {
            A[i] = in.nextInt();
        }
        return A;
    }

    static long[] inputLong(int N) {
        long A[] = new long[N];
        for (int i = 0; i < A.length; i++) {
            A[i] = in.nextLong();
        }
        return A;
    }

    static int GCD(int a, int b) {
        if (b == 0) {
            return a;
        } else {
            return GCD(b, a % b);
        }
    }

    static long GCD(long a, long b) {
        if (b == 0) {
            return a;
        } else {
            return GCD(b, a % b);
        }
    }

    static long LCM(int a, int b) {
        return (long) a / GCD(a, b) * b;
    }

    static long LCM(long a, long b) {
        return a / GCD(a, b) * b;
    }

    static void shuffleAndSort(int[] arr) {
        for (int i = 0; i < arr.length; i++) {
            int rand = (int) (Math.random() * arr.length);
            int temp = arr[rand];
            arr[rand] = arr[i];
            arr[i] = temp;
        }
        Arrays.sort(arr);
    }

    static void shuffleAndSort(int[][] arr, Comparator<? super int[]> comparator) {
        for (int i = 0; i < arr.length; i++) {
            int rand = (int) (Math.random() * arr.length);
            int[] temp = arr[rand];
            arr[rand] = arr[i];
            arr[i] = temp;
        }
        Arrays.sort(arr, comparator);
    }

    static void shuffleAndSort(long[] arr) {
        for (int i = 0; i < arr.length; i++) {
            int rand = (int) (Math.random() * arr.length);
            long temp = arr[rand];
            arr[rand] = arr[i];
            arr[i] = temp;
        }
        Arrays.sort(arr);
    }

    static boolean isPerfectSquare(double number) {
        double sqrt = Math.sqrt(number);
        return ((sqrt - Math.floor(sqrt)) == 0);
    }

    static void swap(int A[], int a, int b) {
        int t = A[a];
        A[a] = A[b];
        A[b] = t;
    }

    static long pow(long a, long b, int mod) {
        long pow = 1;
        long x = a;
        while (b != 0) {
            if ((b & 1) != 0) {
                pow = (pow * x) % mod;
            }
            x = (x * x) % mod;
            b /= 2;
        }
        return pow;
    }

    static long pow(long a, long b) {
        long pow = 1;
        long x = a;
        while (b != 0) {
            if ((b & 1) != 0) {
                pow *= x;
            }
            x = x * x;
            b /= 2;
        }
        return pow;
    }

    static long modInverse(long x, int mod) {
        return pow(x, mod - 2, mod);
    }

    static boolean isPrime(long N) {
        if (N <= 1) {
            return false;
        }
        if (N <= 3) {
            return true;
        }
        if (N % 2 == 0 || N % 3 == 0) {
            return false;
        }
        for (int i = 5; i * i <= N; i = i + 6) {
            if (N % i == 0 || N % (i + 2) == 0) {
                return false;
            }
        }
        return true;
    }

    public static String reverse(String str) {
        if (str == null) {
            return null;
        }
        return new StringBuilder(str).reverse().toString();
    }

    public static String repeat(char ch, int repeat) {
        if (repeat <= 0) {
            return "";
        }
        final char[] buf = new char[repeat];
        for (int i = repeat - 1; i >= 0; i--) {
            buf[i] = ch;
        }
        return new String(buf);
    }

    public static int[] manacher(String s) {
        char[] chars = s.toCharArray();
        int n = s.length();
        int[] d1 = new int[n];
        for (int i = 0, l = 0, r = -1; i < n; i++) {
            int k = (i > r) ? 1 : Math.min(d1[l + r - i], r - i + 1);
            while (0 <= i - k && i + k < n && chars[i - k] == chars[i + k]) {
                k++;
            }
            d1[i] = k--;
            if (i + k > r) {
                l = i - k;
                r = i + k;
            }
        }
        return d1;
    }
}

class Pair {

    int i, j;

    Pair(int i, int j) {
        this.i = i;
        this.j = j;
    }
}

class FastReader {

    BufferedReader br;
    StringTokenizer st;

    public FastReader() {
        br = new BufferedReader(new InputStreamReader(System.in));
    }

    String next() {
        while (st == null || !st.hasMoreElements()) {
            try {
                st = new StringTokenizer(br.readLine());
            } catch (IOException e) {
                e.printStackTrace();
            }
        }
        return st.nextToken();
    }

    int nextInt() {
        return Integer.parseInt(next());
    }

    long nextLong() {
        return Long.parseLong(next());
    }

    double nextDouble() {
        return Double.parseDouble(next());
    }

    String nextLine() {
        String str = "";
        try {
            str = br.readLine();
        } catch (IOException e) {
            e.printStackTrace();
        }
        return str;
    }
}