This version of the problem differs from the next one only in the constraint on n.

Note that the memory limit in this problem is lower than in others.

You have a vertical strip with n cells, numbered consecutively from 1 to n from top to bottom.

You also have a token that is initially placed in cell n. You will move the token up until it arrives at cell 1.

Let the token be in cell x > 1 at some moment. One shift of the token can have either of the following kinds: 

  * Subtraction: you choose an integer y between 1 and x-1, inclusive, and move the token from cell x to cell x - y. 
  * Floored division: you choose an integer z between 2 and x, inclusive, and move the token from cell x to cell ⌊ x/z ⌋ (x divided by z rounded down). 



Find the number of ways to move the token from cell n to cell 1 using one or more shifts, and print it modulo m. Note that if there are several ways to move the token from one cell to another in one shift, all these ways are considered distinct (check example explanation for a better understanding).

Input

The only line contains two integers n and m (2 ≤ n ≤ 2 ⋅ 10^5; 10^8 < m < 10^9; m is a prime number) — the length of the strip and the modulo.

Output

Print the number of ways to move the token from cell n to cell 1, modulo m.

Examples

Input


3 998244353


Output


5


Input


5 998244353


Output


25


Input


42 998244353


Output


793019428

Note

In the first test, there are three ways to move the token from cell 3 to cell 1 in one shift: using subtraction of y = 2, or using division by z = 2 or z = 3.

There are also two ways to move the token from cell 3 to cell 1 via cell 2: first subtract y = 1, and then either subtract y = 1 again or divide by z = 2.

Therefore, there are five ways in total.
#include "bits/stdc++.h"
using namespace std;

#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>

typedef long long ll;
typedef vector< int > vi;
typedef vector< vi > vvi;
typedef pair< int,int > pi;
typedef pair< ll,ll > pll;
typedef vector <pi> vii;
typedef vector < ll > vll;
typedef vector < pll > vpll;
typedef vector< vll > vvll;
typedef pair < double,double > pd;
#define sz(a) int((a).size())
#define pb push_back
#define vt vector
#define ar array
#define all(c) (c).begin(),(c).end()
#define REP(i,a,b) for(int i =a;i<b;i++)
#define F first
#define S second
#define EACH(x, a) for (auto& x: a)

ll absolute(ll a , ll b){
    return max(a,b)-min(a,b);
}


template<class T> bool umin(T& a, const T& b) {
    return b<a?a=b, 1:0;
}
template<class T> bool umax(T& a, const T& b) {
    return a<b?a=b, 1:0;
}

ll FIRSTTRUE(function<bool(ll)> f, ll lb, ll rb) {
    while(lb<rb) {
        ll mb=(lb+rb)/2;
        f(mb)?rb=mb:lb=mb+1;
    }
    return lb;
}
ll LASTTRUE(function<bool(ll)> f, ll lb, ll rb) {
    while(lb<rb) {
        ll mb=(lb+rb+1)/2;
        f(mb)?lb=mb:rb=mb-1;
    }
    return lb;
}

template<class A> void read(vt<A>& v);
template<class A, size_t S> void read(ar<A, S>& a);
template<class T> void read(T& x) {
    cin >> x;
}
void read(double& d) {
    string t;
    read(t);
    d=stod(t);
}
void read(long double& d) {
    string t;
    read(t);
    d=stold(t);
}
template<class H, class... T> void read(H& h, T&... t) {
    read(h);
    read(t...);
}
template<class A> void read(vt<A>& x) {
    EACH(a, x)
        read(a);
}
template<class A, size_t S> void read(array<A, S>& x) {
    EACH(a, x)
        read(a);
}

string to_string(char c) {
    return string(1, c);
}
string to_string(bool b) {
    return b?"true":"false";
}
string to_string(const char* s) {
    return string(s);
}
string to_string(string s) {
    return s;
}
string to_string(vt<bool> v) {
    string res;
    REP(i,0,sz(res))
        res+=char('0'+v[i]);
    return res;
}

template<size_t S> string to_string(bitset<S> b) {
    string res;
    REP(i,0,sz(res))
        res+=char('0'+b[i]);
    return res;
}
template<class T> string to_string(T v) {
    bool f=1;
    string res;
    EACH(x, v) {
        if(!f)
            res+=' ';
        f=0;
        res+=to_string(x);
    }
    return res;
}

template<class A> void write(A x) {
    cout << to_string(x);
}
template<class H, class... T> void write(const H& h, const T&... t) {
    write(h);
    write(t...);
}
void print() {
    write("\n");
}
template<class H, class... T> void print(const H& h, const T&... t) {
    write(h);
    if(sizeof...(t))
        write(' ');
    print(t...);
}

void DBG() {
    cerr << "]" << endl;
}
template<class H, class... T> void DBG(H h, T... t) {
    cerr << to_string(h);
    if(sizeof...(t))
        cerr << ", ";
    DBG(t...);
}
#ifndef ONLINE_JUDGE
#define dbg(...) cerr << "LINE(" << __LINE__ << ") -> [" << #__VA_ARGS__ << "]: [", DBG(__VA_ARGS__)
#else
#define dbg(...) 0
#endif

template<class T> void offset(ll o, T& x) {
    x+=o;
}
template<class T> void offset(ll o, vt<T>& x) {
    EACH(a, x)
        offset(o, a);
}
template<class T, size_t S> void offset(ll o, ar<T, S>& x) {
    EACH(a, x)
        offset(o, a);
}

mt19937 mt_rng(chrono::steady_clock::now().time_since_epoch().count());
ll randint(ll a, ll b) {
    return uniform_int_distribution<ll>(a, b)(mt_rng);
}

template<class T, class U> void vti(vt<T> &v, U x, size_t n) {
    v=vt<T>(n, x);
}
template<class T, class U> void vti(vt<T> &v, U x, size_t n, size_t m...) {
    v=vt<T>(n);
    EACH(a, v)
        vti(a, x, m);
}

#define PI 3.141592653589793238462643383279
const int d4i[4]={-1, 0, 1, 0}, d4j[4]={0, 1, 0, -1};
const int d8i[8]={-1, -1, 0, 1, 1, 1, 0, -1}, d8j[8]={0, 1, 1, 1, 0, -1, -1, -1};
const int MAX = 10e5+5;
const ll INF = 10e12 + 4;
const ll MOD = 1e9 + 7LL;

void NO(){cout << "NO\n"; return;}
void YES(){cout << "YES\n"; return;}

struct UF {
    vi e;
    UF(int n) : e(n, -1) {}
    bool sameSet(int a, int b) { return find(a) == find(b); }
    int size(int x) { return -e[find(x)]; }
    int find(int x) { return e[x] < 0 ? x : e[x] = find(e[x]); }
    bool join(int a, int b) {
        a = find(a), b = find(b);
        if (a == b) return false;
        if (e[a] > e[b]) swap(a, b);
        e[a] += e[b]; e[b] = a;
        return true;
    }
};

void solve(){
    int n;ll mod;
    cin >> n >> mod;
    vll dp(n+1);
    dp[1] =  1;
    vll pref(n+1);
    dp[1] = 1;
    ll cur = 0;
    for(int i = 1 ;  i<= n ;i++){
        pref[i] = (pref[i-1] + pref[i])%mod;
        dbg(i,pref[i]);
        dp[i] = (cur + pref[i] + dp[i])%mod;
        for(int k = 1 ; k < n ; k++){
            int l = i,r = n;
            int ans = -1;
            while(l <= r){
                int m = l + (r-l)/2;
                int first = m/i;
                dbg(first , i);
                if(first <= k){
                    l = m+1;continue;
                }
                if(m/first == m/(first - k+1))
                    ans = m,r = m-1;
                else
                    l = m+1;
            }
            if(ans == -1)
                break;
            else
                pref[l] = (pref[l] + dp[i]);
        }
        cur = (dp[i] + cur) % mod;
    }
    cout << dp[n]%mod << endl;
    return;
}

int main(){
    ios_base::sync_with_stdio(false);
    cin.tie(NULL);
        solve();
    return 0;
}
