You are given two positive integers n and s. Find the maximum possible median of an array of n non-negative integers (not necessarily distinct), such that the sum of its elements is equal to s.

A median of an array of integers of length m is the number standing on the ⌈ {m/2} ⌉-th (rounding up) position in the non-decreasing ordering of its elements. Positions are numbered starting from 1. For example, a median of the array [20,40,20,50,50,30] is the ⌈ m/2 ⌉-th element of [20,20,30,40,50,50], so it is 30. There exist other definitions of the median, but in this problem we use the described definition.

Input

The input consists of multiple test cases. The first line contains a single integer t (1 ≤ t ≤ 10^4) — the number of test cases. Description of the test cases follows.

Each test case contains a single line with two integers n and s (1 ≤ n, s ≤ 10^9) — the length of the array and the required sum of the elements.

Output

For each test case print a single integer — the maximum possible median.

Example

Input


8
1 5
2 5
3 5
2 1
7 17
4 14
1 1000000000
1000000000 1


Output


5
2
2
0
4
4
1000000000
0

Note

Possible arrays for the first three test cases (in each array the median is underlined):

  * In the first test case [\underline{5}] 
  * In the second test case [\underline{2}, 3] 
  * In the third test case [1, \underline{2}, 2] 
import java.io.*;
import java.util.*;

public class global_16_a {
	public static void main(String args[]){
		FScanner in = new FScanner();
		PrintWriter out = new PrintWriter(System.out);
		int t = in.nextInt();
		while(t-->0) {
        int n=in.nextInt();
        int s=in.nextInt();
        if(n==1)
        	out.println(s);
        else if(s<n)
        	out.println(0);
        else
        {
        	n=n/2+1;
        	out.println(s/n);
        }
		 
        }
		out.close();
	}

    static class FScanner {
		BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
		StringTokenizer sb = new StringTokenizer("");
 
		String next(){
			while(!sb.hasMoreTokens()){
				try{
					sb = new StringTokenizer(br.readLine());
				} catch(IOException e){ }
			}
			return sb.nextToken();
		}
		String nextLine(){
			try{ return br.readLine(); } 
			catch(IOException e) { } return "";
		}
 
		int nextInt(){
			return Integer.parseInt(next());
		}
 
		long nextLong() {
			return Long.parseLong(next());
		}
 
		int[] readArray(int n) {
			int a[] = new int[n];
			for(int i=0;i<n;i++) a[i] = nextInt();
			return a;
		}
 
		float nextFloat(){
		return Float.parseFloat(next());
		}
		
		double nextDouble(){
		return Double.parseDouble(next());
		}
	}
}
	