A binary string is a string that consists of characters 0 and 1. A bi-table is a table that has exactly two rows of equal length, each being a binary string.

Let \operatorname{MEX} of a bi-table be the smallest digit among 0, 1, or 2 that does not occur in the bi-table. For example, \operatorname{MEX} for \begin{bmatrix} 0011\\\ 1010 \end{bmatrix} is 2, because 0 and 1 occur in the bi-table at least once. \operatorname{MEX} for \begin{bmatrix} 111\\\ 111 \end{bmatrix} is 0, because 0 and 2 do not occur in the bi-table, and 0 < 2.

You are given a bi-table with n columns. You should cut it into any number of bi-tables (each consisting of consecutive columns) so that each column is in exactly one bi-table. It is possible to cut the bi-table into a single bi-table — the whole bi-table.

What is the maximal sum of \operatorname{MEX} of all resulting bi-tables can be?

Input

The input consists of multiple test cases. The first line contains a single integer t (1 ≤ t ≤ 10^4) — the number of test cases. Description of the test cases follows.

The first line of the description of each test case contains a single integer n (1 ≤ n ≤ 10^5) — the number of columns in the bi-table.

Each of the next two lines contains a binary string of length n — the rows of the bi-table.

It's guaranteed that the sum of n over all test cases does not exceed 10^5.

Output

For each test case print a single integer — the maximal sum of \operatorname{MEX} of all bi-tables that it is possible to get by cutting the given bi-table optimally.

Example

Input


4
7
0101000
1101100
5
01100
10101
2
01
01
6
000000
111111


Output


8
8
2
12

Note

In the first test case you can cut the bi-table as follows:

  * \begin{bmatrix} 0\\\ 1 \end{bmatrix}, its \operatorname{MEX} is 2.
  * \begin{bmatrix} 10\\\ 10 \end{bmatrix}, its \operatorname{MEX} is 2.
  * \begin{bmatrix} 1\\\ 1 \end{bmatrix}, its \operatorname{MEX} is 0.
  * \begin{bmatrix} 0\\\ 1 \end{bmatrix}, its \operatorname{MEX} is 2.
  * \begin{bmatrix} 0\\\ 0 \end{bmatrix}, its \operatorname{MEX} is 1.
  * \begin{bmatrix} 0\\\ 0 \end{bmatrix}, its \operatorname{MEX} is 1.



The sum of \operatorname{MEX} is 8.
// हर हर महादेव
import java.util.*;
import java.lang.*;
import java.io.*;
import java.text.DecimalFormat;

public final class Solution {

    static int inf = Integer.MAX_VALUE;
    static int mod = 1000000000 + 7;
  
  static int getMex(HashSet<Integer> st){
      if(st.contains(0) && st.contains(1)){
          return 2;
      }
      if(st.contains(0) && !st.contains(1)){
          return 1;
      }
      return 0;
  }

  
    static void ne(Scanner sc, BufferedWriter op) throws Exception {
        int n=sc.nextInt();
        String r1=sc.next();
        String r2=sc.next();
        int[][] arr= new int[2][n];
        for(int i=0;i<n;i++){
            arr[0][i]=Integer.parseInt(String.valueOf(r1.charAt(i)));
            arr[1][i]=Integer.parseInt(String.valueOf(r2.charAt(i)));
          
        }
        long count=0L;
        for(int i=0;i<n;i++){
         
            if(arr[0][i]==0 && arr[1][i]==1){
               arr[0][i]=-1;
               arr[1][i]=-1;
               count+=2;
            }
            if(arr[0][i]==1 && arr[1][i]==0){
               arr[0][i]=-1;
               arr[1][i]=-1;
               count+=2;
            }
            
        }

        for(int i=1;i<n;i++){
            if(arr[0][i]==0 && arr[0][i-1]==1){ count+=2; arr[0][i]=-1; arr[0][i-1]=-1;}
            if(arr[0][i]==1 && arr[0][i-1]==0){ count+=2; arr[0][i]=-1; arr[0][i-1]=-1;}
        }
        for(int i=0;i<n;i++){
            if(arr[0][i]==0) { count++;}
        }
        op.write(count+"\n");      

    }
    static int gcd(int a, int b){
        if(a==0) return b;
        return gcd(b%a,a);
    }
    

    public static void main(String[] args) throws Exception {
        BufferedWriter op = new BufferedWriter(new OutputStreamWriter(System.out));
        Scanner sc = new Scanner(System.in);

        int t = sc.nextInt();
        while (t-- > 0) {
            ne(sc, op);
            // op.flush();
        }
        op.flush();
    }

    static void print(Object o) {
        System.out.println(String.valueOf(o));
    }

}

class pair {
    int xx;

    int yy;

    pair(int xx, int yy) {
        this.xx = xx;
        this.yy = yy;
    }
}

class sortY implements Comparator<pair> {
    public int compare(pair p1, pair p2) {
        if (p1.yy > p2.yy) {
            return 1;
        } else if (p1.yy == p2.yy) {
            if (p1.xx > p2.xx) {
                return 1;
            } else if (p1.xx < p2.xx) {
                return -1;
            }
            return 0;

        }
        return -1;
    }
}

class sortX implements Comparator<pair> {
    public int compare(pair p1, pair p2) {
        if (p1.xx > p2.xx) {
            return 1;
        } else if (p1.xx == p2.xx) {
            if (p1.yy > p2.yy) {
                return 1;
            } else if (p1.yy < p2.yy) {
                return -1;
            }
            return 0;

        }
        return -1;
    }
}

class debug {

    static void print1d(long[] arr) {
        System.out.println();
        for (int i = 0; i < arr.length; i++) {
            System.out.print(arr[i] + " ");
        }

    }

    static void print1d(int[] arr) {
        System.out.println();
        for (int i = 0; i < arr.length; i++) {
            System.out.print(arr[i] + " ");
        }

    }

    static void print1d(boolean[] arr) {
        System.out.println();
        for (int i = 0; i < arr.length; i++) {
            System.out.println(i + "= " + arr[i] + " ");
        }

    }

    static void print2d(int[][] arr) {
        System.out.println();
        int n = arr.length;
        int n2 = arr[0].length;
        for (int i = 0; i < n; i++) {
            for (int j = 0; j < n2; j++) {
                System.out.print(arr[i][j] + " ");
            }
            System.out.println();
        }

    }

    static void print2d(long[][] arr) {
        System.out.println();
        int n = arr.length;
        int n2 = arr[0].length;
        for (int i = 0; i < n; i++) {
            for (int j = 0; j < n2; j++) {
                System.out.print(arr[i][j] + " ");
            }
            System.out.println();
        }

    }

}

class Reader {
    final private int BUFFER_SIZE = 1 << 16;
    private DataInputStream din;
    private byte[] buffer;
    private int bufferPointer, bytesRead;

    public Reader() {
        din = new DataInputStream(System.in);
        buffer = new byte[BUFFER_SIZE];
        bufferPointer = bytesRead = 0;
    }

    public Reader(String file_name) throws IOException {
        din = new DataInputStream(new FileInputStream(file_name));
        buffer = new byte[BUFFER_SIZE];
        bufferPointer = bytesRead = 0;
    }

    public String readLine() throws IOException {
        byte[] buf = new byte[64]; // line length
        int cnt = 0, c;
        while ((c = read()) != -1) {
            if (c == '\n') {
                if (cnt != 0) {
                    break;
                } else {
                    continue;
                }
            }
            buf[cnt++] = (byte) c;
        }
        return new String(buf, 0, cnt);
    }

    public int nextInt() throws IOException {
        int ret = 0;
        byte c = read();
        while (c <= ' ') {
            c = read();
        }
        boolean neg = (c == '-');
        if (neg)
            c = read();
        do {
            ret = ret * 10 + c - '0';
        } while ((c = read()) >= '0' && c <= '9');

        if (neg)
            return -ret;
        return ret;
    }

    public long nextLong() throws IOException {
        long ret = 0;
        byte c = read();
        while (c <= ' ')
            c = read();
        boolean neg = (c == '-');
        if (neg)
            c = read();
        do {
            ret = ret * 10 + c - '0';
        } while ((c = read()) >= '0' && c <= '9');
        if (neg)
            return -ret;
        return ret;
    }

    public double nextDouble() throws IOException {
        double ret = 0, div = 1;
        byte c = read();
        while (c <= ' ')
            c = read();
        boolean neg = (c == '-');
        if (neg)
            c = read();

        do {
            ret = ret * 10 + c - '0';
        } while ((c = read()) >= '0' && c <= '9');

        if (c == '.') {
            while ((c = read()) >= '0' && c <= '9') {
                ret += (c - '0') / (div *= 10);
            }
        }

        if (neg)
            return -ret;
        return ret;
    }

    private void fillBuffer() throws IOException {
        bytesRead = din.read(buffer, bufferPointer = 0, BUFFER_SIZE);
        if (bytesRead == -1)
            buffer[0] = -1;
    }

    private byte read() throws IOException {
        if (bufferPointer == bytesRead)
            fillBuffer();
        return buffer[bufferPointer++];
    }

    public void close() throws IOException {
        if (din == null)
            return;
        din.close();
    }
}