Alice and Borys are playing tennis.

A tennis match consists of games. In each game, one of the players is serving and the other one is receiving.

Players serve in turns: after a game where Alice is serving follows a game where Borys is serving, and vice versa.

Each game ends with a victory of one of the players. If a game is won by the serving player, it's said that this player holds serve. If a game is won by the receiving player, it's said that this player breaks serve.

It is known that Alice won a games and Borys won b games during the match. It is unknown who served first and who won which games.

Find all values of k such that exactly k breaks could happen during the match between Alice and Borys in total.

Input

Each test contains multiple test cases. The first line contains the number of test cases t (1 ≤ t ≤ 10^3). Description of the test cases follows.

Each of the next t lines describes one test case and contains two integers a and b (0 ≤ a, b ≤ 10^5; a + b > 0) — the number of games won by Alice and Borys, respectively.

It is guaranteed that the sum of a + b over all test cases does not exceed 2 ⋅ 10^5.

Output

For each test case print two lines.

In the first line, print a single integer m (1 ≤ m ≤ a + b + 1) — the number of values of k such that exactly k breaks could happen during the match.

In the second line, print m distinct integers k_1, k_2, …, k_m (0 ≤ k_1 < k_2 < … < k_m ≤ a + b) — the sought values of k in increasing order.

Example

Input


3
2 1
1 1
0 5


Output


4
0 1 2 3
2
0 2
2
2 3

Note

In the first test case, any number of breaks between 0 and 3 could happen during the match: 

  * Alice holds serve, Borys holds serve, Alice holds serve: 0 breaks; 
  * Borys holds serve, Alice holds serve, Alice breaks serve: 1 break; 
  * Borys breaks serve, Alice breaks serve, Alice holds serve: 2 breaks; 
  * Alice breaks serve, Borys breaks serve, Alice breaks serve: 3 breaks. 



In the second test case, the players could either both hold serves (0 breaks) or both break serves (2 breaks).

In the third test case, either 2 or 3 breaks could happen: 

  * Borys holds serve, Borys breaks serve, Borys holds serve, Borys breaks serve, Borys holds serve: 2 breaks; 
  * Borys breaks serve, Borys holds serve, Borys breaks serve, Borys holds serve, Borys breaks serve: 3 breaks. 
import java.io.*;
import java.util.HashSet;

public class A740B {
    public static void main(String[] args) {
        JS scan = new JS();
        PrintWriter out = new PrintWriter(System.out);
        int t = scan.nextInt();
        while(t-->0){
            int a = scan.nextInt();
            int b = scan.nextInt();
            int games = a+b;
            HashSet<Integer> set = new HashSet<>();
            for(int tt = 0;tt<2;tt++) {
                int one = (games+1)/2;
                int two = games-one;
                int aliceServes =0;
                int bobServes = 0;
                if(tt==0) {
                    aliceServes = one;
                    bobServes = two;
                }else{
                    aliceServes = two;
                    bobServes = one;
                }
                for (int i = 0; i <= Math.min(b, aliceServes); i++) {
                    //how many did bob break
                    int broken = i;
                    if (b > i) {
                        int self = b - i;
                        //this many actually did not break tiles
                        int actualself = Math.min(bobServes, self);
                        //this many did still break tiles :^^(
                        int forced = self - actualself;
                        broken += forced;
                    }
                    int openAlice = aliceServes-broken;
                    broken+=a-openAlice;
                    set.add(broken);
                }
            }
            out.println(set.size());
            for(Integer curr:set){
                out.print(curr+" ");
            }
            out.println();
        }
        out.flush();
        out.close();
    }
    static class JS {
        public int BS = 1 << 16;
        public char NC = (char) 0;
        byte[] buf = new byte[BS];
        int bId = 0, size = 0;
        char c = NC;
        double num = 1;
        BufferedInputStream in;

        public JS() {
            in = new BufferedInputStream(System.in, BS);
        }

        public JS(String s) throws FileNotFoundException {
            in = new BufferedInputStream(new FileInputStream(new File(s)), BS);
        }

        public char nextChar() {
            while (bId == size) {
                try {
                    size = in.read(buf);
                } catch (Exception e) {
                    return NC;
                }
                if (size == -1) return NC;
                bId = 0;
            }
            return (char) buf[bId++];
        }

        public int nextInt() {
            return (int) nextLong();
        }

        public long nextLong() {
            num = 1;
            boolean neg = false;
            if (c == NC) c = nextChar();
            for (; (c < '0' || c > '9'); c = nextChar()) {
                if (c == '-') neg = true;
            }
            long res = 0;
            for (; c >= '0' && c <= '9'; c = nextChar()) {
                res = (res << 3) + (res << 1) + c - '0';
                num *= 10;
            }
            return neg ? -res : res;
        }

        public double nextDouble() {
            double cur = nextLong();
            return c != '.' ? cur : cur + nextLong() / num;
        }

        public String next() {
            StringBuilder res = new StringBuilder();
            while (c <= 32) c = nextChar();
            while (c > 32) {
                res.append(c);
                c = nextChar();
            }
            return res.toString();
        }

        public String nextLine() {
            StringBuilder res = new StringBuilder();
            while (c <= 32) c = nextChar();
            while (c != '\n') {
                res.append(c);
                c = nextChar();
            }
            return res.toString();
        }

        public boolean hasNext() {
            if (c > 32) return true;
            while (true) {
                c = nextChar();
                if (c == NC) return false;
                else if (c > 32) return true;
            }
        }
    }
}
