A binary string is a string that consists of characters 0 and 1.

Let \operatorname{MEX} of a binary string be the smallest digit among 0, 1, or 2 that does not occur in the string. For example, \operatorname{MEX} of 001011 is 2, because 0 and 1 occur in the string at least once, \operatorname{MEX} of 1111 is 0, because 0 and 2 do not occur in the string and 0 < 2.

A binary string s is given. You should cut it into any number of substrings such that each character is in exactly one substring. It is possible to cut the string into a single substring — the whole string.

A string a is a substring of a string b if a can be obtained from b by deletion of several (possibly, zero or all) characters from the beginning and several (possibly, zero or all) characters from the end.

What is the minimal sum of \operatorname{MEX} of all substrings pieces can be?

Input

The input consists of multiple test cases. The first line contains a single integer t (1 ≤ t ≤ 10^4) — the number of test cases. Description of the test cases follows.

Each test case contains a single binary string s (1 ≤ |s| ≤ 10^5).

It's guaranteed that the sum of lengths of s over all test cases does not exceed 10^5.

Output

For each test case print a single integer — the minimal sum of \operatorname{MEX} of all substrings that it is possible to get by cutting s optimally.

Example

Input


6
01
1111
01100
101
0000
01010


Output


1
0
2
1
1
2

Note

In the first test case the minimal sum is \operatorname{MEX}(0) + \operatorname{MEX}(1) = 1 + 0 = 1.

In the second test case the minimal sum is \operatorname{MEX}(1111) = 0.

In the third test case the minimal sum is \operatorname{MEX}(01100) = 2.
import java.util.*;
import java.io.*;
import java.lang.*;


public class cf742 {
//HashSet<Integer> hs=new HashSet<>();
//PriorityQueue<Integer> pq=new PriorityQueue<>();
//HashMap<Integer,Integer> hm=new HashMap<>();
//ArrayList<Integer> lt=new ArrayList<>();
    static long mod=1000_000_007;

    //Must Do dry Run Before submitting soln. and think also about corner testcases will be passed or not.
    public static void solve1() throws Exception{
        InputStreamReader ip=new InputStreamReader(System.in);
        BufferedReader br = new BufferedReader(ip);
        int t = Integer.parseInt(br.readLine());
        StringBuilder asb=new StringBuilder();
		
       while(t-->0){
        // int n =Integer.parseInt(br.readLine());
        // String[] strs=(br.readLine()).trim().split(" ");
        // int n=Integer.parseInt(strs[0]),k=Integer.parseInt(strs[1]),r=Integer.parseInt(strs[2]),s=Integer.parseInt(strs[3]);
         String str=(br.readLine()).trim();
        // int[] arr=new int[n];
        // for(int i=0;i<n;i++){arr[i]=Integer.parseInt(strs[i]);}

            int n=str.length();
            char prev='0';  int ct0=1;
            if(str.charAt(0)=='1'){ prev='1'; ct0=0; }

            

            for(int i=1;i<n;i++){
                if(prev!=str.charAt(i)){
                    if(str.charAt(i)=='0'){ ct0++; }
                    prev=str.charAt(i);
                }
            }

            if(ct0>2){ ct0=2; }   //  01010

            asb.append(ct0+"\n");

         }

         System.out.println(asb);
    }

   
//******************************************************************************************************************** */
    public static void main(String[] args) throws Exception{
        solve1();
    
     }

     public static void solve2() throws Exception{
        InputStreamReader ip=new InputStreamReader(System.in);
        BufferedReader br = new BufferedReader(ip);
        int t = Integer.parseInt(br.readLine());
        StringBuilder asb=new StringBuilder();
		
       while(t-->0){
        // int n =Integer.parseInt(br.readLine());
        // String[] strs=(br.readLine()).trim().split(" ");
        // int n=Integer.parseInt(strs[0]),k=Integer.parseInt(strs[1]),r=Integer.parseInt(strs[2]),s=Integer.parseInt(strs[3]);
        //  String str=(br.readLine()).trim();
        // int[] arr=new int[n];
        // for(int i=0;i<n;i++){arr[i]=Integer.parseInt(strs[i]);}
         }
    }
   
//******************************************************************************************************************** */

    public static long modInverse1(long a, long m){
        // int g = gcd(a, m);
        // if(g!=1) {System.out.println("Inverse Doesnot Exist");}  
        return binexp(a, m - 2, m);
       }
   
    public  static long binexp(long a, long b, long m){
        if (b == 0)return 1; 
            
        long res = binexp(a, b / 2, m);
        if (b % 2 == 1) return (( (res*res)%m )*a) % m;
        else return (res*res)%m;
    }

    //binexp
    public static long binexp(long a,long b){
        if(b==0)return 1;

        long res=binexp(a, b/2);

        if(b%2==1){
            return (((res*res))*a);
        }else return (res*res);
    }

    //Comparator Interface
    public static class comp implements Comparator<int[]>{
        public int compare(int[] a,int[] b){
            return a[0]-b[0];
        }
    }

	//gcd using Euclid's Division Algorithm  
    public static long gcd(long a,long b){   
        if(b==0)return a;
        else return gcd(b, a%b);
    }

	//check prime in root(n)
    public static int isprime(int n){
        for(int i=2;i<=Math.sqrt(n);i++){
            if(n%i==0)return i;
        }

        return -1;   //means n is prime
    }

	//SOE
	static  int[] sieve;
	public static void SOE(int n){
        sieve=new int[n+1];

        // System.out.println("All prime number from 1 to n:-");
        
        for(int x=2;x<=n;x++){
            if(sieve[x]!=0){  //Not prime number
                continue;
            }
            // System.out.print(x+"  ");
            for(int u=2*x;u<=n;u+=x){
                sieve[u]=x;
            }
        }

		//If  sieve[i]=0 means 'i' is primr else 'i' is not prime 
    }

    //sort
     public static void sort(long[] arr) {
		int n = arr.length;
		for (int i = 0; i < n; i++) {
			int idx = (int) Math.random() * n;
			long temp = arr[i];  arr[i] = arr[idx];  arr[idx] = temp;  //swap
		}
		Arrays.sort(arr);
	}
 
	public static void sort(int[] arr) {
		int n = arr.length;
		for (int i = 0; i < n; i++) {
			int idx = (int) Math.random() * n;
			int temp = arr[i];  arr[i] = arr[idx]; arr[idx] = temp;  //swap
		}
		Arrays.sort(arr);
	}
    //1d print
    public static void print(int[] dp) {
		for (int val : dp) {
			System.out.print(val + " ");
		}
		System.out.println();
	}
 
	public static void print(long[] dp) {//Method Overloading
		for (long val : dp) {
			System.out.print(val + " ");
		}
		System.out.println();
	}  
    //2d print
	public static void print(long[][] dp) {//Method Overloading
		for (long[] a : dp) {
			for (long val : a) {
				System.out.print(val + " ");
			}
			System.out.println();
		}
	}
 
	public static void print(int[][] dp) {
		for (int[] a : dp) {
			for (int val : a) {
				System.out.print(val + " ");
			}
			System.out.println();
		}
	}
 
	
}
