Alice and Borys are playing tennis.

A tennis match consists of games. In each game, one of the players is serving and the other one is receiving.

Players serve in turns: after a game where Alice is serving follows a game where Borys is serving, and vice versa.

Each game ends with a victory of one of the players. If a game is won by the serving player, it's said that this player holds serve. If a game is won by the receiving player, it's said that this player breaks serve.

It is known that Alice won a games and Borys won b games during the match. It is unknown who served first and who won which games.

Find all values of k such that exactly k breaks could happen during the match between Alice and Borys in total.

Input

Each test contains multiple test cases. The first line contains the number of test cases t (1 ≤ t ≤ 10^3). Description of the test cases follows.

Each of the next t lines describes one test case and contains two integers a and b (0 ≤ a, b ≤ 10^5; a + b > 0) — the number of games won by Alice and Borys, respectively.

It is guaranteed that the sum of a + b over all test cases does not exceed 2 ⋅ 10^5.

Output

For each test case print two lines.

In the first line, print a single integer m (1 ≤ m ≤ a + b + 1) — the number of values of k such that exactly k breaks could happen during the match.

In the second line, print m distinct integers k_1, k_2, …, k_m (0 ≤ k_1 < k_2 < … < k_m ≤ a + b) — the sought values of k in increasing order.

Example

Input


3
2 1
1 1
0 5


Output


4
0 1 2 3
2
0 2
2
2 3

Note

In the first test case, any number of breaks between 0 and 3 could happen during the match: 

  * Alice holds serve, Borys holds serve, Alice holds serve: 0 breaks; 
  * Borys holds serve, Alice holds serve, Alice breaks serve: 1 break; 
  * Borys breaks serve, Alice breaks serve, Alice holds serve: 2 breaks; 
  * Alice breaks serve, Borys breaks serve, Alice breaks serve: 3 breaks. 



In the second test case, the players could either both hold serves (0 breaks) or both break serves (2 breaks).

In the third test case, either 2 or 3 breaks could happen: 

  * Borys holds serve, Borys breaks serve, Borys holds serve, Borys breaks serve, Borys holds serve: 2 breaks; 
  * Borys breaks serve, Borys holds serve, Borys breaks serve, Borys holds serve, Borys breaks serve: 3 breaks. 
import java.io.*;
import java.util.*;

public class B {
	public static void main(String[] args) {
		FastReader in = new FastReader();
		
		int T = in.nextInt();
		while(T-- > 0) {
			int a = in.nextInt();
			int b = in.nextInt();
			HashSet<Integer> breaks = new HashSet<>();

			int p = (int) Math.ceil((a+b)/2);
			int q = a+b-p;

			for(int x = 0; x <= p; x++) {
				int y = a - (p-x);
				if(0<=y && y<=q) breaks.add(x+y);
			}
			for(int x = 0; x <= q; x++) {
				int y = a - (q-x);
				if(0<=y && y<=p) breaks.add(x+y);
			}

			System.out.println(breaks.size());
			for(int k : breaks) System.out.print(k + " ");
			System.out.println();
		}
	}

	static class FastReader {
		BufferedReader br;
		StringTokenizer st;
		public FastReader() { br = new BufferedReader(new InputStreamReader(System.in)); }
		String next() {
			while (st == null || !st.hasMoreElements()) {
				try { st = new StringTokenizer(br.readLine()); }
				catch(IOException e) { e.printStackTrace(); }
			}
			return st.nextToken();
		}
		int nextInt() { return Integer.parseInt(next()); }
		long nextLong() { return Long.parseLong(next()); }
		double nextDouble() { return Double.parseDouble(next()); }
		String nextLine() {
			String str = "";
			try { str = br.readLine(); }
			catch(IOException e) { e.printStackTrace(); }
			return str;
		}
		int[] readInt(int size) {
			int[] arr = new int[size];
			for(int i = 0; i < size; i++)
				arr[i] = Integer.parseInt(next());
			return arr;
		}
		long[] readLong(int size) {
			long[] arr = new long[size];
			for(int i = 0; i < size; i++)
				arr[i] = Long.parseLong(next());
			return arr;
		}
		int[][] read2dArray(int rows, int cols) {
			int[][] arr = new int[rows][cols];
			for(int i = 0; i < rows; i++) {
				for(int j = 0; j < cols; j++)
					arr[i][j] = Integer.parseInt(next());
			}
			return arr;
		}
	}
}