A binary string is a string that consists of characters 0 and 1.

Let \operatorname{MEX} of a binary string be the smallest digit among 0, 1, or 2 that does not occur in the string. For example, \operatorname{MEX} of 001011 is 2, because 0 and 1 occur in the string at least once, \operatorname{MEX} of 1111 is 0, because 0 and 2 do not occur in the string and 0 < 2.

A binary string s is given. You should cut it into any number of substrings such that each character is in exactly one substring. It is possible to cut the string into a single substring — the whole string.

A string a is a substring of a string b if a can be obtained from b by deletion of several (possibly, zero or all) characters from the beginning and several (possibly, zero or all) characters from the end.

What is the minimal sum of \operatorname{MEX} of all substrings pieces can be?

Input

The input consists of multiple test cases. The first line contains a single integer t (1 ≤ t ≤ 10^4) — the number of test cases. Description of the test cases follows.

Each test case contains a single binary string s (1 ≤ |s| ≤ 10^5).

It's guaranteed that the sum of lengths of s over all test cases does not exceed 10^5.

Output

For each test case print a single integer — the minimal sum of \operatorname{MEX} of all substrings that it is possible to get by cutting s optimally.

Example

Input


6
01
1111
01100
101
0000
01010


Output


1
0
2
1
1
2

Note

In the first test case the minimal sum is \operatorname{MEX}(0) + \operatorname{MEX}(1) = 1 + 0 = 1.

In the second test case the minimal sum is \operatorname{MEX}(1111) = 0.

In the third test case the minimal sum is \operatorname{MEX}(01100) = 2.
import sys
import math
import heapq
from collections import defaultdict as dd
from collections import OrderedDict as od
from collections import deque
from itertools import permutations as pp
from itertools import combinations as cc
from sys import stdin
from functools import cmp_to_key as ctk
from functools import lru_cache
from bisect import bisect_left as bs_l
from bisect import bisect_right as bs_r
input = sys.stdin.readline
mod=10**9+7
sys.setrecursionlimit(10**5)
def comparator(x,y):
    if x[0]==y[0]:
        return y[1]-x[1]
    return True
def ncr(n, r):
    if n < r: return 0
    return fc[n] * pow(fc[r] * fc[n - r] % mod, mod - 2, mod) % mod
T=int(input())
for _ in range(T):
    #n=int(input())
    s=input().strip()
    ze,on=s.count('0'),s.count('1')
    if ze==0:
        print(0)
    elif on==0:
        print(1)
    else:
        gr=0
        c=0
        for i in s:
            if i=='1':
                if c:
                    gr+=1
                c=0
            else:
                c+=1
        if c:
            gr+=1
        print(min(2,gr))
