A binary string is a string that consists of characters 0 and 1.

Let \operatorname{MEX} of a binary string be the smallest digit among 0, 1, or 2 that does not occur in the string. For example, \operatorname{MEX} of 001011 is 2, because 0 and 1 occur in the string at least once, \operatorname{MEX} of 1111 is 0, because 0 and 2 do not occur in the string and 0 < 2.

A binary string s is given. You should cut it into any number of substrings such that each character is in exactly one substring. It is possible to cut the string into a single substring — the whole string.

A string a is a substring of a string b if a can be obtained from b by deletion of several (possibly, zero or all) characters from the beginning and several (possibly, zero or all) characters from the end.

What is the minimal sum of \operatorname{MEX} of all substrings pieces can be?

Input

The input consists of multiple test cases. The first line contains a single integer t (1 ≤ t ≤ 10^4) — the number of test cases. Description of the test cases follows.

Each test case contains a single binary string s (1 ≤ |s| ≤ 10^5).

It's guaranteed that the sum of lengths of s over all test cases does not exceed 10^5.

Output

For each test case print a single integer — the minimal sum of \operatorname{MEX} of all substrings that it is possible to get by cutting s optimally.

Example

Input


6
01
1111
01100
101
0000
01010


Output


1
0
2
1
1
2

Note

In the first test case the minimal sum is \operatorname{MEX}(0) + \operatorname{MEX}(1) = 1 + 0 = 1.

In the second test case the minimal sum is \operatorname{MEX}(1111) = 0.

In the third test case the minimal sum is \operatorname{MEX}(01100) = 2.
//package MyPackage;
import java.io.*;
import java.util.*;
public class MyClass {
    final static int mod = 998_244_353;
    final static int mini = Integer.MIN_VALUE;
    final static int maxi = Integer.MAX_VALUE;
    static long gcd(long a, long b) {
        if (b == 0) return a;
        return gcd(b, a % b);
    }
    static long ncr(long n, long r) {
        if (r > n - r) r = n - r;
        long[] C = new long[(int) r + 1];
        C[0] = 1;
        for (int i = 1; i <= n; i++) {
            for (long j = Math.min(i, r); j > 0; j--)
                C[(int) j] = (C[(int) j] + C[(int) j - 1]) % mod;
        }
        return C[(int) r];
    }
    static boolean isPrime(long n) {
        if (n <= 1)
            return false;
        else if (n == 2)
            return true;
        else if (n % 2 == 0)
            return false;
        for (int i = 3; i <= Math.sqrt(n); i += 2) {
            if (n % i == 0)
                return false;
        }
        return true;
    }
    static boolean isPalindrome(String s) {
        int i = 0, j = s.length() - 1;
        while(i < j) {
            if(s.charAt(i) != s.charAt(j)) return false;
            i++;
            j--;
        }
        return true;
    }
    static long lcm(long a, long b) {
        return (a / gcd(a, b)) * b;
    }
    static void sort(long[] a) {
        ArrayList<Long> l = new ArrayList<>();
        for (long value : a) {
            l.add(value);
        }
        Collections.sort(l);
        for (int i = 0; i < l.size(); i++)
            a[i] = l.get(i);
    }
    static int ceil(int a, int b) {
        return a % b == 0 ? a / b : a / b + 1;
    }
    static void sort(int[] a) {
        ArrayList<Integer> l = new ArrayList<>();
        for (int value : a) {
            l.add(value);
        }
        Collections.sort(l);
        for (int i = 0; i < l.size(); i++)
            a[i] = l.get(i);
    }
    static void reverse(int[] arr) {
        int l = 0;
        int h = arr.length - 1;
        while (l < h) {
            swap(arr, l, h);
            l++;
            h--;
        }
    }
    static String reverse(String s) {
        StringBuilder res = new StringBuilder(s);
        return res.reverse().toString();
    }
    static void swap(int[] arr, int i, int j) {
        int temp = arr[i];
        arr[i] = arr[j];
        arr[j] = temp;
    }
    static class FastReader {
        BufferedReader br;
        StringTokenizer st;

        public FastReader() {
            br = new BufferedReader(new InputStreamReader(System.in));
        }

        String n() {
            while (st == null || !st.hasMoreElements()) {
                try {
                    st = new StringTokenizer(br.readLine());
                } catch (IOException e) {
                    e.printStackTrace();
                }
            }
            return st.nextToken();
        }

        int nint() {
            return Integer.parseInt(n());
        }

        long nlong() {
            return Long.parseLong(n());
        }

        double ndouble() {
            return Double.parseDouble(n());
        }

        int[] narr(int n) {
            int[] a = new int[n];
            for (int i = 0; i < n; i++) a[i] = nint();
            return a;
        }
        int[][] narr(int n, int m) {
            int[][] a = new int[n][m];
            for (int i = 0; i < n; i++)
                for (int j = 0; j < m; j++)
                    a[i][j] = nint();
            return a;
        }

        String nline() {
            String str = "";
            try {
                str = br.readLine();
            } catch (IOException e) {
                e.printStackTrace();
            }
            return str;
        }
    }
    public static void main(String[] args) {
        FastReader sc = new FastReader();
        PrintWriter out = new PrintWriter(System.out);
        // int t = 1;
        int t = sc.nint();
        while(t-- > 0) {
            char[] arr = sc.n().toCharArray();
            int o = 0, z = 0;
            for(char c : arr) {
                if(c == '0') z++;
                else o++;
            }
            if(z == 0) out.println(0);
            else if(o == 0) out.println(1);
            else {
                int n = arr.length;
                int change = 0;
                for(int i = 0; i < n - 1; i++) {
                    if(arr[i] != arr[i + 1]) change++;
                }
                if(change < 2) out.println(1);
                else if(change == 2 && arr[0] == '0') out.println(2);
                else if(change == 2 && arr[0] == '1') out.println(1);
                else out.println(2);
            }
        }
        out.flush();
        out.close();
    }
}