You are given an integer n. Find any string s of length n consisting only of English lowercase letters such that each non-empty substring of s occurs in s an odd number of times. If there are multiple such strings, output any. It can be shown that such string always exists under the given constraints.

A string a is a substring of a string b if a can be obtained from b by deletion of several (possibly, zero or all) characters from the beginning and several (possibly, zero or all) characters from the end.

Input

The first line contains a single integer t (1 ≤ t ≤ 500) — the number of test cases.

The first line of each test case contains a single integer n (1 ≤ n ≤ 10^5).

It is guaranteed that the sum of n over all test cases doesn't exceed 3 ⋅ 10^5.

Output

For each test case, print a single line containing the string s. If there are multiple such strings, output any. It can be shown that such string always exists under the given constraints.

Example

Input


4
3
5
9
19


Output


abc
diane
bbcaabbba
youarethecutestuwuu

Note

In the first test case, each substring of "abc" occurs exactly once.

In the third test case, each substring of "bbcaabbba" occurs an odd number of times. In particular, "b" occurs 5 times, "a" and "bb" occur 3 times each, and each of the remaining substrings occurs exactly once.
from bisect import insort,bisect_right,bisect_left
from sys import stdout, stdin, setrecursionlimit
from heapq import heappush, heappop, heapify 
from io import BytesIO, IOBase
from collections import *
from itertools import *
from random import * 
from string import *
from queue import *
from math import *
from re import *
from os import *

# sqrt,ceil,floor,factorial,gcd,log2,log10,comb

####################################---fast-input-output----#########################################


class FastIO(IOBase):
    newlines = 0

    def __init__(self, file):
        self._fd = file.fileno()
        self.buffer = BytesIO()
        self.writable = "x" in file.mode or "r" not in file.mode
        self.write = self.buffer.write if self.writable else None

    def read(self):
        while True:
            b = read(self._fd, max(fstat(self._fd).st_size, 8192))
            if not b:
                break
            ptr = self.buffer.tell()
            self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
        self.newlines = 0
        return self.buffer.read()

    def readline(self):
        while self.newlines == 0:
            b = read(self._fd, max(fstat(self._fd).st_size, 8192))
            self.newlines = b.count(b"\n") + (not b)
            ptr = self.buffer.tell()
            self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
        self.newlines -= 1
        return self.buffer.readline()

    def flush(self):
        if self.writable:
            write(self._fd, self.buffer.getvalue())
            self.buffer.truncate(0), self.buffer.seek(0)


class IOWrapper(IOBase):
    def __init__(self, file):
        self.buffer = FastIO(file)
        self.flush = self.buffer.flush
        self.writable = self.buffer.writable
        self.write = lambda s: self.buffer.write(s.encode("ascii"))
        self.read = lambda: self.buffer.read().decode("ascii")
        self.readline = lambda: self.buffer.readline().decode("ascii")


stdin, stdout = IOWrapper(stdin), IOWrapper(stdout)
graph, mod, szzz =  {}, 10**9 + 7, lambda: sorted(zzz())
def getStr(): return input()
def getInt(): return int(input())
def listStr(): return list(input())
def getStrs(): return input().split()
def isInt(s): return '0' <= s[0] <= '9'
def input(): return stdin.readline().strip()
def zzz(): return [int(i) for i in input().split()]
def output(answer, end='\n'): stdout.write(str(answer) + end)
def lcd(xnum1, xnum2): return (xnum1 * xnum2 // gcd(xnum1, xnum2))


def getPrimes(N = 10**5):
    SN = int(sqrt(N))
    sieve = [i for i in range(N+1)]
    sieve[1] = 0
    for i in sieve:
        if i > SN:
            break
        if i == 0:
            continue
        for j in range(2*i, N+1, i):
            sieve[j] = 0
    prime = [i for i in range(N+1) if sieve[i] != 0] 
    return prime
def primeFactor(n,prime=getPrimes()):
    lst = []
    mx=int(sqrt(n))+1
    for i in prime:
        if i>mx:break
        while n%i==0:
            lst.append(i)
            n//=i
    if n>1:
        lst.append(n)
    return lst    

dx = [-1, 1, 0, 0, 1, -1, 1, -1]
dy = [0, 0, 1, -1, 1, -1, -1, 1]
daysInMounth = [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]


#################################################---Some Rule For Me To Follow---#################################
"""
    --instants of Reading problem continuously try to understand them.

    --Try & again try, maybe you're just one statement away!

"""
##################################################---START-CODING---###############################################

import math
 

def maximumXOR(n, l, r):
    x = 0

    for i in range(31, -1, -1):
        if (n & (1 << i)): # Set bit
            if  (x + (1 << i) - 1 < l):
                x ^= (1 << i)
        else: # Unset bit
            if (x ^ (1 << i)) <= r:
                x ^= (1 << i)
   
    return x
 


num = getInt()

for _ in range(num):
    n = getInt()

    ans1 = 'a'*(n//2)
    if n%2==0:
        mid='b'
    else:
        mid='bc'
    print((ans1+mid+ans1[:-1])[:n])