The Olympic Games have just started and Federico is eager to watch the marathon race.

There will be n athletes, numbered from 1 to n, competing in the marathon, and all of them have taken part in 5 important marathons, numbered from 1 to 5, in the past. For each 1≤ i≤ n and 1≤ j≤ 5, Federico remembers that athlete i ranked r_{i,j}-th in marathon j (e.g., r_{2,4}=3 means that athlete 2 was third in marathon 4).

Federico considers athlete x superior to athlete y if athlete x ranked better than athlete y in at least 3 past marathons, i.e., r_{x,j}<r_{y,j} for at least 3 distinct values of j.

Federico believes that an athlete is likely to get the gold medal at the Olympics if he is superior to all other athletes.

Find any athlete who is likely to get the gold medal (that is, an athlete who is superior to all other athletes), or determine that there is no such athlete.

Input

The first line contains a single integer t (1 ≤ t ≤ 1000) — the number of test cases. Then t test cases follow.

The first line of each test case contains a single integer n (1≤ n≤ 50 000) — the number of athletes.

Then n lines follow, each describing the ranking positions of one athlete.

The i-th of these lines contains the 5 integers r_{i,1},\,r_{i,2},\,r_{i,3},\,r_{i,4},  r_{i,5} (1≤ r_{i,j}≤ 50 000) — the ranking positions of athlete i in the past 5 marathons. It is guaranteed that, in each of the 5 past marathons, the n athletes have distinct ranking positions, i.e., for each 1≤ j≤ 5, the n values r_{1,j},  r_{2, j},  ...,  r_{n, j} are distinct.

It is guaranteed that the sum of n over all test cases does not exceed 50 000.

Output

For each test case, print a single integer — the number of an athlete who is likely to get the gold medal (that is, an athlete who is superior to all other athletes). If there are no such athletes, print -1. If there is more than such one athlete, print any of them.

Example

Input


4
1
50000 1 50000 50000 50000
3
10 10 20 30 30
20 20 30 10 10
30 30 10 20 20
3
1 1 1 1 1
2 2 2 2 2
3 3 3 3 3
6
9 5 3 7 1
7 4 1 6 8
5 6 7 3 2
6 7 8 8 6
4 2 2 4 5
8 3 6 9 4


Output


1
-1
1
5

Note

Explanation of the first test case: There is only one athlete, therefore he is superior to everyone else (since there is no one else), and thus he is likely to get the gold medal.

Explanation of the second test case: There are n=3 athletes. 

  * Athlete 1 is superior to athlete 2. Indeed athlete 1 ranks better than athlete 2 in the marathons 1, 2 and 3. 
  * Athlete 2 is superior to athlete 3. Indeed athlete 2 ranks better than athlete 3 in the marathons 1, 2, 4 and 5. 
  * Athlete 3 is superior to athlete 1. Indeed athlete 3 ranks better than athlete 1 in the marathons 3, 4 and 5. 



Explanation of the third test case: There are n=3 athletes. 

  * Athlete 1 is superior to athletes 2 and 3. Since he is superior to all other athletes, he is likely to get the gold medal. 
  * Athlete 2 is superior to athlete 3. 
  * Athlete 3 is not superior to any other athlete. 



Explanation of the fourth test case: There are n=6 athletes. 

  * Athlete 1 is superior to athletes 3, 4, 6. 
  * Athlete 2 is superior to athletes 1, 4, 6. 
  * Athlete 3 is superior to athletes 2, 4, 6. 
  * Athlete 4 is not superior to any other athlete. 
  * Athlete 5 is superior to athletes 1, 2, 3, 4, 6. Since he is superior to all other athletes, he is likely to get the gold medal. 
  * Athlete 6 is only superior to athlete 4. 


import java.util.*;
import java.io.*;

public class B {
	static StringBuilder sb;
	static dsu dsu;
	static long fact[];
	static int mod = (int) (1e9 + 7);

	static void solve() {
		int n = i();
		int[][] arr = new int[n][5];

		for (int i = 0; i < n; i++) {
			arr[i] = readArrayi(5);
		}

		LinkedList<int[]> stack = new LinkedList<>();
		stack.addFirst(arr[0]);
		int idx = 0;

		for (int i = 1; i < n; i++) {
			int[] temp1 = arr[i];
			int[] temp2 = stack.removeFirst();

			int count = 0;
			for (int j = 0; j < 5; j++) {
				if (temp1[j] < temp2[j]) {
					count++;
				}
			}

			if (count >= 3) {
				stack.addFirst(temp1);
				idx = i;
			} else {
				stack.addFirst(temp2);
			}
		}

		int[] check = stack.removeFirst();
		for (int i = 0; i < n; i++) {
			if (i != idx) {
				int count = 0;
				for (int j = 0; j < 5; j++) {
					if (check[j] < arr[i][j]) {
						count++;
					}
				}

				if (count < 3) {
					sb.append("-1\n");
					return;
				}
			}
		}

		sb.append(idx + 1 + "\n");
	}

	public static void main(String[] args) {
		sb = new StringBuilder();
		int test = i();
		while (test-- > 0) {
			solve();
		}
		System.out.println(sb);

	}

	/*
	 * fact=new long[(int)1e6+10]; fact[0]=fact[1]=1; for(int i=2;i<fact.length;i++)
	 * { fact[i]=((long)(i%mod)1L(long)(fact[i-1]%mod))%mod; }
	 */
//**************NCR%P******************	 
	static long ncr(int n, int r) {
		if (r > n)
			return (long) 0;

		long res = fact[n] % mod;
		// System.out.println(res);
		res = ((long) (res % mod) * (long) (p(fact[r], mod - 2) % mod)) % mod;
		res = ((long) (res % mod) * (long) (p(fact[n - r], mod - 2) % mod)) % mod;
		// System.out.println(res);
		return res;

	}

	static long p(long x, long y)// POWER FXN //
	{
		if (y == 0)
			return 1;

		long res = 1;
		while (y > 0) {
			if (y % 2 == 1) {
				res = (res * x) % mod;
				y--;
			}

			x = (x * x) % mod;
			y = y / 2;

		}
		return res;
	}

//**************END******************

	// *************Disjoint set
	// union*********//
	static class dsu {
		int parent[];

		dsu(int n) {
			parent = new int[n];
			for (int i = 0; i < n; i++)
				parent[i] = -1;
		}

		int find(int a) {
			if (parent[a] < 0)
				return a;
			else {
				int x = find(parent[a]);
				parent[a] = x;
				return x;
			}
		}

		void merge(int a, int b) {
			a = find(a);
			b = find(b);
			if (a == b)
				return;
			parent[b] = a;
		}
	}

//**************PRIME FACTORIZE **********************************//
	static TreeMap<Integer, Integer> prime(long n) {
		TreeMap<Integer, Integer> h = new TreeMap<>();
		long num = n;
		for (int i = 2; i <= Math.sqrt(num); i++) {
			if (n % i == 0) {
				int nt = 0;
				while (n % i == 0) {
					n = n / i;
					nt++;
				}
				h.put(i, nt);
			}
		}
		if (n != 1)
			h.put((int) n, 1);
		return h;

	}

//****CLASS PAIR ************************************************
	static class Pair implements Comparable<Pair> {
		int x;
		long y;

		Pair(int x, long y) {
			this.x = x;
			this.y = y;
		}

		public int compareTo(Pair o) {
			return (int) (this.y - o.y);

		}

	}
//****CLASS PAIR **************************************************

	static class InputReader {
		private InputStream stream;
		private byte[] buf = new byte[1024];
		private int curChar;
		private int numChars;
		private SpaceCharFilter filter;

		public InputReader(InputStream stream) {
			this.stream = stream;
		}

		public int read() {
			if (numChars == -1)
				throw new InputMismatchException();
			if (curChar >= numChars) {
				curChar = 0;
				try {
					numChars = stream.read(buf);
				} catch (IOException e) {
					throw new InputMismatchException();
				}
				if (numChars <= 0)
					return -1;
			}
			return buf[curChar++];
		}

		public int Int() {
			int c = read();
			while (isSpaceChar(c))
				c = read();
			int sgn = 1;
			if (c == '-') {
				sgn = -1;
				c = read();
			}
			int res = 0;
			do {
				if (c < '0' || c > '9')
					throw new InputMismatchException();
				res *= 10;
				res += c - '0';
				c = read();
			} while (!isSpaceChar(c));
			return res * sgn;
		}

		public String String() {
			int c = read();
			while (isSpaceChar(c))
				c = read();
			StringBuilder res = new StringBuilder();
			do {
				res.appendCodePoint(c);
				c = read();
			} while (!isSpaceChar(c));
			return res.toString();
		}

		public boolean isSpaceChar(int c) {
			if (filter != null)
				return filter.isSpaceChar(c);
			return c == ' ' || c == '\n' || c == '\r' || c == '\t' || c == -1;
		}

		public String next() {
			return String();
		}

		public interface SpaceCharFilter {
			public boolean isSpaceChar(int ch);
		}
	}

	static class OutputWriter {
		private final PrintWriter writer;

		public OutputWriter(OutputStream outputStream) {
			writer = new PrintWriter(new BufferedWriter(new OutputStreamWriter(outputStream)));
		}

		public OutputWriter(Writer writer) {
			this.writer = new PrintWriter(writer);
		}

		public void print(Object... objects) {
			for (int i = 0; i < objects.length; i++) {
				if (i != 0)
					writer.print(' ');
				writer.print(objects[i]);
			}
		}

		public void printLine(Object... objects) {
			print(objects);
			writer.println();
		}

		public void close() {
			writer.close();
		}

		public void flush() {
			writer.flush();
		}
	}

	static InputReader in = new InputReader(System.in);
	static OutputWriter out = new OutputWriter(System.out);

	public static long[] sort(long[] a2) {
		int n = a2.length;
		ArrayList<Long> l = new ArrayList<>();
		for (long i : a2)
			l.add(i);
		Collections.sort(l);
		for (int i = 0; i < l.size(); i++)
			a2[i] = l.get(i);
		return a2;
	}

	public static int[] sort(int[] a2) {
		int n = a2.length;
		ArrayList<Integer> l = new ArrayList<>();
		for (int i : a2)
			l.add(i);
		Collections.sort(l);
		for (int i = 0; i < l.size(); i++)
			a2[i] = l.get(i);
		return a2;
	}

	public static long pow(long x, long y) {
		long res = 1;
		while (y > 0) {
			if (y % 2 != 0) {
				res = (res * x);// % modulus;
				y--;

			}
			x = (x * x);// % modulus;
			y = y / 2;
		}
		return res;
	}

//GCD___+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
	public static long gcd(long x, long y) {
		if (x == 0)
			return y;
		else
			return gcd(y % x, x);
	}
	// ******LOWEST COMMON MULTIPLE
	// *********************************************

	public static long lcm(long x, long y) {
		return (x * (y / gcd(x, y)));
	}

//INPUT PATTERN********************************************************
	public static int i() {
		return in.Int();
	}

	public static long l() {
		String s = in.String();
		return Long.parseLong(s);
	}

	public static String s() {
		return in.String();
	}

	public static int[] readArrayi(int n) {
		int A[] = new int[n];
		for (int i = 0; i < n; i++) {
			A[i] = i();
		}
		return A;
	}

	public static long[] readArray(long n) {
		long A[] = new long[(int) n];
		for (int i = 0; i < n; i++) {
			A[i] = l();
		}
		return A;
	}

}