An ant moves on the real line with constant speed of 1 unit per second. It starts at 0 and always moves to the right (so its position increases by 1 each second).

There are n portals, the i-th of which is located at position x_i and teleports to position y_i < x_i. Each portal can be either active or inactive. The initial state of the i-th portal is determined by s_i: if s_i=0 then the i-th portal is initially inactive, if s_i=1 then the i-th portal is initially active. When the ant travels through a portal (i.e., when its position coincides with the position of a portal): 

  * if the portal is inactive, it becomes active (in this case the path of the ant is not affected); 
  * if the portal is active, it becomes inactive and the ant is instantly teleported to the position y_i, where it keeps on moving as normal. 



How long (from the instant it starts moving) does it take for the ant to reach the position x_n + 1? It can be shown that this happens in a finite amount of time. Since the answer may be very large, compute it modulo 998 244 353.

Input

The first line contains the integer n (1≤ n≤ 2⋅ 10^5) — the number of portals.

The i-th of the next n lines contains three integers x_i, y_i and s_i (1≤ y_i < x_i≤ 10^9, s_i∈\{0,1\}) — the position of the i-th portal, the position where the ant is teleported when it travels through the i-th portal (if it is active), and the initial state of the i-th portal.

The positions of the portals are strictly increasing, that is x_1<x_2<⋅⋅⋅<x_n. It is guaranteed that the 2n integers x_1,   x_2,   ...,   x_n,   y_1,   y_2,   ...,   y_n are all distinct.

Output

Output the amount of time elapsed, in seconds, from the instant the ant starts moving to the instant it reaches the position x_n+1. Since the answer may be very large, output it modulo 998 244 353.

Examples

Input


4
3 2 0
6 5 1
7 4 0
8 1 1


Output


23


Input


1
454971987 406874902 1


Output


503069073


Input


5
243385510 42245605 0
644426565 574769163 0
708622105 208990040 0
786625660 616437691 0
899754846 382774619 0


Output


899754847


Input


5
200000000 100000000 1
600000000 400000000 0
800000000 300000000 0
900000000 700000000 1
1000000000 500000000 0


Output


3511295

Note

Explanation of the first sample: The ant moves as follows (a curvy arrow denotes a teleporting, a straight arrow denotes normal movement with speed 1 and the time spent during the movement is written above the arrow). $$$ 0 \stackrel{6}{\longrightarrow} 6 \leadsto 5 \stackrel{3}{\longrightarrow} 8 \leadsto 1 \stackrel{2}{\longrightarrow} 3 \leadsto 2 \stackrel{4}{\longrightarrow} 6 \leadsto 5 \stackrel{2}{\longrightarrow} 7 \leadsto 4 \stackrel{2}{\longrightarrow} 6 \leadsto 5 \stackrel{4}{\longrightarrow} 9  Notice that the total time is 6+3+2+4+2+2+4=23$$$.

Explanation of the second sample: The ant moves as follows (a curvy arrow denotes a teleporting, a straight arrow denotes normal movement with speed 1 and the time spent during the movement is written above the arrow). $$$ 0 \stackrel{454971987}{\longrightarrow} 454971987 \leadsto 406874902 \stackrel{48097086}{\longrightarrow} 454971988  Notice that the total time is 454971987+48097086=503069073$$$.

Explanation of the third sample: Since all portals are initially off, the ant will not be teleported and will go straight from 0 to x_n+1=899754846+1=899754847.
/*
stream Butter!
eggyHide eggyVengeance
I need U
xiao rerun when
 */
import static java.lang.Math.*;
import java.util.*;
import java.io.*;
import java.math.*;

public class x1552F
{
    static final long MOD = 998244353L;
    public static void main(String hi[]) throws Exception
    {
        BufferedReader infile = new BufferedReader(new InputStreamReader(System.in));
        StringTokenizer st = new StringTokenizer(infile.readLine());
        int N = Integer.parseInt(st.nextToken());
        int[] left = new int[N];
        int[] right = new int[N];
        boolean[] on = new boolean[N];
        for(int i=0; i < N; i++)
        {
            st = new StringTokenizer(infile.readLine());
            right[i] = Integer.parseInt(st.nextToken());
            left[i] = Integer.parseInt(st.nextToken());
            on[i] = st.nextToken().charAt(0) == '1';
        }
        long[] dp = new long[N];
        dp[0] = (right[0]-left[0])%MOD;
        long[] prefix = new long[N];
        prefix[0] = dp[0];
        for(int i=1; i < N; i++)
        {
            dp[i] = right[i]-left[i];
            if(dp[i] >= MOD)
                dp[i] -= MOD;
            if(left[i] < right[i-1])
            {
                int low = 0;
                int high = i-1;
                while(low != high)
                {
                    int mid = (low+high)>>1;
                    if(left[i] < right[mid])
                        high = mid;
                    else
                        low = mid+1;
                }
                long addon = prefix[i-1];
                if(low > 0)
                {
                    addon -= prefix[low-1];
                    if(addon < 0)
                        addon += MOD;
                }
                dp[i] += addon;
                if(dp[i] >= MOD)
                    dp[i] -= MOD;
            }
            prefix[i] = prefix[i-1]+dp[i];
            if(prefix[i] >= MOD)
                prefix[i] -= MOD;
        }
        long res = right[N-1]+1;
        for(int i=0; i < N; i++)
            if(on[i])
                res += dp[i];
        System.out.println(res%MOD);
    }
}