A string s of length n, consisting of lowercase letters of the English alphabet, is given.

You must choose some number k between 0 and n. Then, you select k characters of s and permute them however you want. In this process, the positions of the other n-k characters remain unchanged. You have to perform this operation exactly once.

For example, if s="andrea", you can choose the k=4 characters "a_d_ea" and permute them into "d_e_aa" so that after the operation the string becomes "dneraa".

Determine the minimum k so that it is possible to sort s alphabetically (that is, after the operation its characters appear in alphabetical order).

Input

The first line contains a single integer t (1 ≤ t ≤ 1000) — the number of test cases. Then t test cases follow.

The first line of each test case contains one integer n (1 ≤ n ≤ 40) — the length of the string.

The second line of each test case contains the string s. It is guaranteed that s contains only lowercase letters of the English alphabet.

Output

For each test case, output the minimum k that allows you to obtain a string sorted alphabetically, through the operation described above.

Example

Input


4
3
lol
10
codeforces
5
aaaaa
4
dcba


Output


2
6
0
4

Note

In the first test case, we can choose the k=2 characters "_ol" and rearrange them as "_lo" (so the resulting string is "llo"). It is not possible to sort the string choosing strictly less than 2 characters.

In the second test case, one possible way to sort s is to consider the k=6 characters "_o__force_" and rearrange them as "_c__efoor_" (so the resulting string is "ccdeefoors"). One can show that it is not possible to sort the string choosing strictly less than 6 characters.

In the third test case, string s is already sorted (so we can choose k=0 characters).

In the fourth test case, we can choose all k=4 characters "dcba" and reverse the whole string (so the resulting string is "abcd").
class BIT:
    def __init__(self, n):
        self.n = n
        self.bit = [0]*(self.n+1) # 1-indexed

    def init(self, init_val):
        for i, v in enumerate(init_val):
            self.add(i, v)

    def add(self, i, x):
        # i: 0-indexed
        i += 1 # to 1-indexed
        while i <= self.n:
            self.bit[i] += x
            i += (i & -i)

    def sum(self, i, j):
        # return sum of [i, j)
        # i, j: 0-indexed
        return self._sum(j) - self._sum(i)

    def _sum(self, i):
        # return sum of [0, i)
        # i: 0-indexed
        res = 0
        while i > 0:
            res += self.bit[i]
            i -= i & (-i)
        return res

    def lower_bound(self, x):
        s = 0
        pos = 0
        depth = self.n.bit_length()
        v = 1 << depth
        for i in range(depth, -1, -1):
            k = pos + v
            if k <= self.n and s + self.bit[k] < x:
                    s += self.bit[k]
                    pos += v
            v >>= 1
        return pos

    def __str__(self): # for debug
        arr = [self.sum(i,i+1) for i in range(self.n)]
        return str(arr)

import sys
import io, os
input = sys.stdin.readline
#input = io.BytesIO(os.read(0,os.fstat(0).st_size)).readline

t = int(input())
for _ in range(t):
    n = int(input())
    s = str(input().rstrip())
    bit = BIT(26)
    ans = 0
    for c in s:
        c = ord(c)-ord('a')
        if bit.sum(c+1, bit.n) > 0:
            ans += 1
        bit.add(c, 1)
    if ans:
        print(ans+1)
    else:
        print(ans)
