You are given a sequence of n integers a_1,   a_2,   ...,   a_n.

Does there exist a sequence of n integers b_1,   b_2,   ...,   b_n such that the following property holds?

  * For each 1 ≤ i ≤ n, there exist two (not necessarily distinct) indices j and k (1 ≤ j,   k ≤ n) such that a_i = b_j - b_k. 

Input

The first line contains a single integer t (1 ≤ t ≤ 20) — the number of test cases. Then t test cases follow.

The first line of each test case contains one integer n (1 ≤ n ≤ 10).

The second line of each test case contains the n integers a_1,   ...,   a_n (-10^5 ≤ a_i ≤ 10^5).

Output

For each test case, output a line containing YES if a sequence b_1,   ...,   b_n satisfying the required property exists, and NO otherwise.

Example

Input


5
5
4 -7 -1 5 10
1
0
3
1 10 100
4
-3 2 10 2
9
25 -171 250 174 152 242 100 -205 -258


Output


YES
YES
NO
YES
YES

Note

In the first test case, the sequence b = [-9,   2,   1,   3,   -2] satisfies the property. Indeed, the following holds: 

  * a_1 = 4 = 2 - (-2) = b_2 - b_5; 
  * a_2 = -7 = -9 - (-2) = b_1 - b_5; 
  * a_3 = -1 = 1 - 2 = b_3 - b_2; 
  * a_4 = 5 = 3 - (-2) = b_4 - b_5; 
  * a_5 = 10 = 1 - (-9) = b_3 - b_1. 



In the second test case, it is sufficient to choose b = [0], since a_1 = 0 = 0 - 0 = b_1 - b_1.

In the third test case, it is possible to show that no sequence b of length 3 satisfies the property.
import sys, math, cmath, time, collections
from collections import deque, Counter, OrderedDict, defaultdict
from heapq import nsmallest, nlargest, heapify, heappop, heappush, heapreplace
from math import ceil, floor, log, log2, sqrt, gcd, factorial, pow, pi
from bisect import bisect_left, bisect_right

start_time = time.time()


def solve(a, n):
    """
    The actual solution begins here
    c = a + b
    print(c)
    """
    cur = [0]
    for i in range(n):
        cur = cur + [x + a[i] for x in cur] + [x - a[i] for x in cur]
        # print(f"The current is: {cur}")
    print('YES' if sum(x == 0 for x in cur) > 1 else 'NO')

def main():
    """
    Main function dedicated to get the I/P
    a, b = map(int, input().split())
    solve(a, b)
    """
    n = int(input())
    arr = list(map(int, input().split()))
    solve(arr, n)


if __name__ == "__main__":
    testcases = int(input())
    for i in range(testcases):
        main()