The Olympic Games have just started and Federico is eager to watch the marathon race.

There will be n athletes, numbered from 1 to n, competing in the marathon, and all of them have taken part in 5 important marathons, numbered from 1 to 5, in the past. For each 1≤ i≤ n and 1≤ j≤ 5, Federico remembers that athlete i ranked r_{i,j}-th in marathon j (e.g., r_{2,4}=3 means that athlete 2 was third in marathon 4).

Federico considers athlete x superior to athlete y if athlete x ranked better than athlete y in at least 3 past marathons, i.e., r_{x,j}<r_{y,j} for at least 3 distinct values of j.

Federico believes that an athlete is likely to get the gold medal at the Olympics if he is superior to all other athletes.

Find any athlete who is likely to get the gold medal (that is, an athlete who is superior to all other athletes), or determine that there is no such athlete.

Input

The first line contains a single integer t (1 ≤ t ≤ 1000) — the number of test cases. Then t test cases follow.

The first line of each test case contains a single integer n (1≤ n≤ 50 000) — the number of athletes.

Then n lines follow, each describing the ranking positions of one athlete.

The i-th of these lines contains the 5 integers r_{i,1},\,r_{i,2},\,r_{i,3},\,r_{i,4},  r_{i,5} (1≤ r_{i,j}≤ 50 000) — the ranking positions of athlete i in the past 5 marathons. It is guaranteed that, in each of the 5 past marathons, the n athletes have distinct ranking positions, i.e., for each 1≤ j≤ 5, the n values r_{1,j},  r_{2, j},  ...,  r_{n, j} are distinct.

It is guaranteed that the sum of n over all test cases does not exceed 50 000.

Output

For each test case, print a single integer — the number of an athlete who is likely to get the gold medal (that is, an athlete who is superior to all other athletes). If there are no such athletes, print -1. If there is more than such one athlete, print any of them.

Example

Input


4
1
50000 1 50000 50000 50000
3
10 10 20 30 30
20 20 30 10 10
30 30 10 20 20
3
1 1 1 1 1
2 2 2 2 2
3 3 3 3 3
6
9 5 3 7 1
7 4 1 6 8
5 6 7 3 2
6 7 8 8 6
4 2 2 4 5
8 3 6 9 4


Output


1
-1
1
5

Note

Explanation of the first test case: There is only one athlete, therefore he is superior to everyone else (since there is no one else), and thus he is likely to get the gold medal.

Explanation of the second test case: There are n=3 athletes. 

  * Athlete 1 is superior to athlete 2. Indeed athlete 1 ranks better than athlete 2 in the marathons 1, 2 and 3. 
  * Athlete 2 is superior to athlete 3. Indeed athlete 2 ranks better than athlete 3 in the marathons 1, 2, 4 and 5. 
  * Athlete 3 is superior to athlete 1. Indeed athlete 3 ranks better than athlete 1 in the marathons 3, 4 and 5. 



Explanation of the third test case: There are n=3 athletes. 

  * Athlete 1 is superior to athletes 2 and 3. Since he is superior to all other athletes, he is likely to get the gold medal. 
  * Athlete 2 is superior to athlete 3. 
  * Athlete 3 is not superior to any other athlete. 



Explanation of the fourth test case: There are n=6 athletes. 

  * Athlete 1 is superior to athletes 3, 4, 6. 
  * Athlete 2 is superior to athletes 1, 4, 6. 
  * Athlete 3 is superior to athletes 2, 4, 6. 
  * Athlete 4 is not superior to any other athlete. 
  * Athlete 5 is superior to athletes 1, 2, 3, 4, 6. Since he is superior to all other athletes, he is likely to get the gold medal. 
  * Athlete 6 is only superior to athlete 4. 

import java.io.*;
import java.util.*;

public class Solution {

    /* -------------------------------------- Main Start ----------------------------------- */
    public static void main(String[] args) throws IOException {
        FastReader fs = new FastReader();
        StringBuilder sb = new StringBuilder();
        int t = Integer.parseInt(fs.nextLine().trim());
        while (t-- > 0) {
            int n = fs.nextInt();
            int[][] marathon = new int[n][5];
            for (int i = 0; i < n; i++) {
                for (int j = 0; j < 5; j++) {
                    marathon[i][j] = fs.nextInt();
                }
            }
            int[] wins = new int[n];
            for (int i = 0; i < 5; i++) {
                int min = marathon[0][i];
                int idx = 0;
                for (int j = 0; j < n; j++) {
                    if (marathon[j][i] < min) {
                        min = marathon[j][i];
                        idx = j;
                    }
                }
                wins[idx]++;
            }
            int max = 0;
            int idx = -1;
            for (int i = 0; i < n; i++) {
                if (wins[i] >= max) {
                    max = wins[i];
                    idx = i;
                }
            }
            ArrayList<Integer> count = new ArrayList<>();
            for (int i = 0; i < n; i++) {
                if (max == wins[i]) {
                    count.add(i);
                }
            }
            if (count.size() != 1) {
                System.out.println("-1");
                continue;
            }
            int store = 0;
            int index = -1;
            for (int i = 0; i < n; i++) {
                int[] c = new int[n];
                for (int k = 0; k < 5; k++) {
                    for (int j = 0; j < n; j++) {
                        if (marathon[j][k] > marathon[i][k] && i != j) {
                            c[j]++;
                        }
                    }
                }
                boolean isPoss = true;
                for (int j = 0; j < n; j++) {
                    if (j != i && c[j] < 3) {
                        isPoss = false;
                        break;
                    }
                }
                if (isPoss) {
                    index = i + 1;
                    break;
                }
            }
            if (index != -1) {
                System.out.println(index);
            } else {
                System.out.println("-1");
            }
        }

    }

    /* ---------------------------------------------------------------------------------------------------------------------------------------------------------------------- 
  
      StringBuilder sb = new StringBuilder();
      sb.append(x + "\n");
    
      Collections.sort(arr, (a, b) -> Integer.compare(a[0], b[0]))
      arr.toArray(new int[arr.size()][])
    
     */
    private static final int MOD_1 = 1000000000 + 7;

    static class FastReader {

        BufferedReader br;
        StringTokenizer st;

        public FastReader() throws IOException {
            br = new BufferedReader(new InputStreamReader(System.in));
        }

        String next() throws IOException {
            while (st == null || !st.hasMoreElements()) {
                try {
                    st = new StringTokenizer(br.readLine());
                } catch (IOException e) {
                    e.printStackTrace();
                }
            }
            return st.nextToken();
        }

        int nextInt() throws IOException {
            return Integer.parseInt(next());
        }

        long nextLong() throws IOException {
            return Long.parseLong(next());
        }

        double nextDouble() throws IOException {
            return Double.parseDouble(next());
        }

        String nextLine() throws IOException {
            String str = "";
            try {
                str = br.readLine();
            } catch (IOException e) {
                e.printStackTrace();
            }
            return str;
        }

        /* --------------------------------------------------------------------------------------------------------------------------------------------------------------------- */
        void printArray(int[] arr) {
            System.out.println(Arrays.toString(arr));
        }

        void printArray(String[] arr) {
            System.out.println(Arrays.toString(arr));
        }

        void printArray(long[] arr) {
            System.out.println(Arrays.toString(arr));
        }

        void print(int data) {
            System.out.println(data);
        }

        void print(String data) {
            System.out.println(data);
        }

        void print(long data) {
            System.out.println(data);
        }

        int[] II(int n) throws IOException {
            int[] d = new int[n];
            String[] arr = nextLine().split(" ");
            for (int i = 0; i < n; i++) {
                d[i] = Integer.parseInt(arr[i]);
            }

            return d;
        }

        String[] IS(int n) throws IOException {
            return nextLine().split(" ");
        }

        long[] IL(int n) throws IOException {
            long[] d = new long[n];
            String[] arr = nextLine().split(" ");
            for (int i = 0; i < n; i++) {
                d[i] = Long.parseLong(arr[i]);
            }
            return d;
        }

        public long gcd(long a, long b) {
            if (a == 0) {
                return b;
            }
            return gcd(b % a, a);
        }

        public long power(long x, long y, long p) {
            long res = 1;
            x = x % p;
            if (x == 0) {
                return 0;
            }

            while (y > 0) {
                if ((y & 1) == 1) {
                    res = (res * x) % p;
                }
                y = y >> 1;
                x = (x * x) % p;
            }
            return res;
        }

        void sieveOfEratosthenes(boolean prime[], int size) {
            Arrays.fill(prime, true);
            prime[0] = prime[1] = false;
            prime[2] = true;

            for (int p = 2; p * p < size; p++) {
                if (prime[p] == true) {
                    for (int i = p * p; i < size; i += p) {
                        prime[i] = false;
                    }
                }
            }
        }

        public long fact(long n) {
            long ans = 1;
            for (int i = 2; i <= n; i++) {
                ans = (ans * i) % MOD_1;
            }
            return ans;
        }

        public long lcm(long a, long b) {
            return (a * b) / gcd(a, b);
        }

        public int log2(int N) {
            int result = (int) (Math.log(N) / Math.log(2));
            return result;
        }

        // find first element in the arr that is equal to the x. 
        // If x is not present in arr then it will return first element that is greater than x
        // It return arr.size() if all element are smaller than x
        public int lowerBound(int[] arr, int x) {
            int low = 0, high = arr.length, mid = -1;

            while (low < high) {
                mid = (low + high) / 2;

                if (arr[mid] >= x) {
                    high = mid;
                } else {
                    low = mid + 1;
                }
            }

            return low;
        }

        // find first element in the arr that is greater than x. 
        // It return arr.size() if all element are smaller than x
        public int upperBound(int[] arr, int x) {
            int low = 0, high = arr.length, mid = -1;

            while (low < high) {
                mid = (low + high) / 2;

                if (arr[mid] > x) {
                    high = mid;
                } else {
                    low = mid + 1;
                }
            }

            return low;
        }

    }

}
