An identity permutation of length n is an array [1, 2, 3, ..., n].

We performed the following operations to an identity permutation of length n:

  * firstly, we cyclically shifted it to the right by k positions, where k is unknown to you (the only thing you know is that 0 ≤ k ≤ n - 1). When an array is cyclically shifted to the right by k positions, the resulting array is formed by taking k last elements of the original array (without changing their relative order), and then appending n - k first elements to the right of them (without changing relative order of the first n - k elements as well). For example, if we cyclically shift the identity permutation of length 6 by 2 positions, we get the array [5, 6, 1, 2, 3, 4]; 
  * secondly, we performed the following operation at most m times: pick any two elements of the array and swap them. 



You are given the values of n and m, and the resulting array. Your task is to find all possible values of k in the cyclic shift operation.

Input

The first line contains one integer t (1 ≤ t ≤ 10^5) — the number of test cases.

Each test case consists of two lines. The first line contains two integers n and m (3 ≤ n ≤ 3 ⋅ 10^5; 0 ≤ m ≤ n/3).

The second line contains n integers p_1, p_2, ..., p_n (1 ≤ p_i ≤ n, each integer from 1 to n appears in this sequence exactly once) — the resulting array.

The sum of n over all test cases does not exceed 3 ⋅ 10^5.

Output

For each test case, print the answer in the following way:

  * firstly, print one integer r (0 ≤ r ≤ n) — the number of possible values of k for the cyclic shift operation; 
  * secondly, print r integers k_1, k_2, ..., k_r (0 ≤ k_i ≤ n - 1) — all possible values of k in increasing order. 

Example

Input


4
4 1
2 3 1 4
3 1
1 2 3
3 1
3 2 1
6 0
1 2 3 4 6 5


Output


1 3
1 0
3 0 1 2
0

Note

Consider the example: 

  * in the first test case, the only possible value for the cyclic shift is 3. If we shift [1, 2, 3, 4] by 3 positions, we get [2, 3, 4, 1]. Then we can swap the 3-rd and the 4-th elements to get the array [2, 3, 1, 4]; 
  * in the second test case, the only possible value for the cyclic shift is 0. If we shift [1, 2, 3] by 0 positions, we get [1, 2, 3]. Then we don't change the array at all (we stated that we made at most 1 swap), so the resulting array stays [1, 2, 3]; 
  * in the third test case, all values from 0 to 2 are possible for the cyclic shift: 
    * if we shift [1, 2, 3] by 0 positions, we get [1, 2, 3]. Then we can swap the 1-st and the 3-rd elements to get [3, 2, 1]; 
    * if we shift [1, 2, 3] by 1 position, we get [3, 1, 2]. Then we can swap the 2-nd and the 3-rd elements to get [3, 2, 1]; 
    * if we shift [1, 2, 3] by 2 positions, we get [2, 3, 1]. Then we can swap the 1-st and the 2-nd elements to get [3, 2, 1]; 
  * in the fourth test case, we stated that we didn't do any swaps after the cyclic shift, but no value of cyclic shift could produce the array [1, 2, 3, 4, 6, 5]. 

import java.io.*;
import java.util.*;

public class PermutationShift implements Runnable {

   void solve() {
      int t = ri();
      while (t-- > 0) {
         int n = ri(), m = ri();
         int[] perm = iArr(n);
         for (int i = 0; i < n; i++) {
            perm[i] = ri();
         }
         int[] count = iArr(n);
         for (int i = 0; i < n; i++) {
            int offset = i + 1 - perm[i];
            if (offset < 0)
               offset += n;
            count[offset]++;
         }

         List<Integer> ans = new ArrayList<Integer>();
         for (int i = 0; i < n; i++) {
            if (count[i] + 2 * m >= n && check(n, m, i, perm)) {
               ans.add(i);
            }
         }
         print(ans.size() + " ");
         ans.forEach(o -> print(o + " "));
         println("");

      }
   }

   boolean check(int n, int m, int k, int[] perm) {
      List<Integer> lst = new ArrayList<Integer>();
      int start = n - k + 1;
      for (int i = 0; i < k; i++) {
         lst.add(start++);
      }
      start = 1;
      for (int i = k; i < n; i++) {
         lst.add(start++);
      }

      int notGood = 0;
      for (int i = 0; i < n; i++) {
         if (perm[i] != lst.get(i))
            notGood++;
      }
      return (notGood) / 2 <= m;
   }

   /************************************************************************************************************************************************/
   public static void main(String[] args) throws IOException {
      new Thread(null, new PermutationShift(), "1").start();
   }

   static PrintWriter out = new PrintWriter(System.out);
   static Reader read = new Reader();
   static StringBuilder sbr = new StringBuilder();
   static int mod = (int) 1e9 + 7;
   static int dmax = Integer.MAX_VALUE;
   static long lmax = Long.MAX_VALUE;
   static int dmin = Integer.MIN_VALUE;
   static long lmin = Long.MIN_VALUE;
   static int[] dprimes = new int[] { 1, 11, 101, 1087, 99991, 100001, 1000003, 15485863, 999999937 };

   @Override
   public void run() {
      solve();
      out.close();
   }

   static class Reader {
      private byte[] buf = new byte[1024];
      private int index;
      private InputStream in;
      private int total;

      public Reader() {
         in = System.in;
      }

      public int scan() throws IOException {
         if (total < 0)
            throw new InputMismatchException();
         if (index >= total) {
            index = 0;
            total = in.read(buf);
            if (total <= 0)
               return -1;
         }
         return buf[index++];
      }

      public int intNext() throws IOException {
         int integer = 0;
         int n = scan();
         while (isWhiteSpace(n))
            n = scan();
         int neg = 1;
         if (n == '-') {
            neg = -1;
            n = scan();
         }
         while (!isWhiteSpace(n)) {
            if (n >= '0' && n <= '9') {
               integer *= 10;
               integer += n - '0';
               n = scan();
            } else
               throw new InputMismatchException();
         }
         return neg * integer;
      }

      public double doubleNext() throws IOException {
         double doub = 0;
         int n = scan();
         while (isWhiteSpace(n))
            n = scan();
         int neg = 1;
         if (n == '-') {
            neg = -1;
            n = scan();
         }
         while (!isWhiteSpace(n) && n != '.') {
            if (n >= '0' && n <= '9') {
               doub *= 10;
               doub += n - '0';
               n = scan();
            } else
               throw new InputMismatchException();
         }
         if (n == '.') {
            n = scan();
            double temp = 1;
            while (!isWhiteSpace(n)) {
               if (n >= '0' && n <= '9') {
                  temp /= 10;
                  doub += (n - '0') * temp;
                  n = scan();
               } else
                  throw new InputMismatchException();
            }
         }
         return doub * neg;
      }

      public String read() throws IOException {
         StringBuilder sb = new StringBuilder();
         int n = scan();
         while (isWhiteSpace(n))
            n = scan();
         while (!isWhiteSpace(n)) {
            sb.append((char) n);
            n = scan();
         }
         return sb.toString();
      }

      public String rline() throws IOException {
         StringBuilder sb = new StringBuilder();
         int n = scan();
         while (n != '\n') {
            sb.append((char) n);
            n = scan();
         }
         return sb.toString();
      }

      private boolean isWhiteSpace(int n) {
         if (n == ' ' || n == '\n' || n == '\r' || n == '\t' || n == -1)
            return true;
         return false;
      }
   }

   static void print(Object object) {
      out.print(object);
   }

   static void println(Object object) {
      out.println(object);
   }

   static int[] iArr(int len) {
      return new int[len];
   }

   static long[] lArr(int len) {
      return new long[len];
   }

   static long min(long a, long b) {
      return Math.min(a, b);
   }

   static int min(int a, int b) {
      return Math.min(a, b);
   }

   static long max(Long a, Long b) {
      return Math.max(a, b);
   }

   static int max(int a, int b) {
      return Math.max(a, b);
   }

   static int ri() {
      try {
         return read.intNext();
      } catch (IOException e) {
         e.printStackTrace();
      }
      System.exit(2);
      return -1;
   }

   static long rl() {
      try {
         return Long.parseLong(read.read());
      } catch (IOException e) {
         e.printStackTrace();
      }
      System.exit(2);
      return -1;
   }

   static String rs() {
      try {
         return read.read();
      } catch (IOException e) {
         e.printStackTrace();
      }
      System.exit(2);
      return "";
   }

   static String rline() {
      try {
         return read.rline();
      } catch (IOException e) {
         e.printStackTrace();
      }
      System.exit(2);
      return "";
   }

   static char rc() {
      return rs().charAt(0);
   }

   static double rd() {
      try {
         return read.doubleNext();
      } catch (IOException e) {
         e.printStackTrace();
      }
      System.exit(2);
      return -1;
   }
}
