An identity permutation of length n is an array [1, 2, 3, ..., n].

We performed the following operations to an identity permutation of length n:

  * firstly, we cyclically shifted it to the right by k positions, where k is unknown to you (the only thing you know is that 0 ≤ k ≤ n - 1). When an array is cyclically shifted to the right by k positions, the resulting array is formed by taking k last elements of the original array (without changing their relative order), and then appending n - k first elements to the right of them (without changing relative order of the first n - k elements as well). For example, if we cyclically shift the identity permutation of length 6 by 2 positions, we get the array [5, 6, 1, 2, 3, 4]; 
  * secondly, we performed the following operation at most m times: pick any two elements of the array and swap them. 



You are given the values of n and m, and the resulting array. Your task is to find all possible values of k in the cyclic shift operation.

Input

The first line contains one integer t (1 ≤ t ≤ 10^5) — the number of test cases.

Each test case consists of two lines. The first line contains two integers n and m (3 ≤ n ≤ 3 ⋅ 10^5; 0 ≤ m ≤ n/3).

The second line contains n integers p_1, p_2, ..., p_n (1 ≤ p_i ≤ n, each integer from 1 to n appears in this sequence exactly once) — the resulting array.

The sum of n over all test cases does not exceed 3 ⋅ 10^5.

Output

For each test case, print the answer in the following way:

  * firstly, print one integer r (0 ≤ r ≤ n) — the number of possible values of k for the cyclic shift operation; 
  * secondly, print r integers k_1, k_2, ..., k_r (0 ≤ k_i ≤ n - 1) — all possible values of k in increasing order. 

Example

Input


4
4 1
2 3 1 4
3 1
1 2 3
3 1
3 2 1
6 0
1 2 3 4 6 5


Output


1 3
1 0
3 0 1 2
0

Note

Consider the example: 

  * in the first test case, the only possible value for the cyclic shift is 3. If we shift [1, 2, 3, 4] by 3 positions, we get [2, 3, 4, 1]. Then we can swap the 3-rd and the 4-th elements to get the array [2, 3, 1, 4]; 
  * in the second test case, the only possible value for the cyclic shift is 0. If we shift [1, 2, 3] by 0 positions, we get [1, 2, 3]. Then we don't change the array at all (we stated that we made at most 1 swap), so the resulting array stays [1, 2, 3]; 
  * in the third test case, all values from 0 to 2 are possible for the cyclic shift: 
    * if we shift [1, 2, 3] by 0 positions, we get [1, 2, 3]. Then we can swap the 1-st and the 3-rd elements to get [3, 2, 1]; 
    * if we shift [1, 2, 3] by 1 position, we get [3, 1, 2]. Then we can swap the 2-nd and the 3-rd elements to get [3, 2, 1]; 
    * if we shift [1, 2, 3] by 2 positions, we get [2, 3, 1]. Then we can swap the 1-st and the 2-nd elements to get [3, 2, 1]; 
  * in the fourth test case, we stated that we didn't do any swaps after the cyclic shift, but no value of cyclic shift could produce the array [1, 2, 3, 4, 6, 5]. 
        
import java.io.*;
import java.util.*;

public class PermutationShift implements Runnable {

    void solve() {
        int t = ri();
        while (t-- > 0) {
            int n = ri(), m = ri();
            int[] perm = iArr(n);
            for (int i = 0; i < n; i++) {
                perm[i] = ri();
            }
            int[] count = iArr(n);
            for (int i = 0; i < n; i++) {
                count[(i + n - perm[i]) % n]++;
            }

            List<Integer> ans = new ArrayList<Integer>();
            for (int i = 0; i < n; i++) {
                if (count[i] + 2 * m >= n && check(n, m, i, perm)) {
                    ans.add(i);
                }
            }
            print(ans.size() + " ");
            ans.forEach(o -> print(o + " "));
            println("");
        }
    }

    boolean check(int n, int m, int k, int[] perm) {

        DSU o = new DSU(n);
        for (int i = 0; i < n; i++) {
            o.unite((i + n - k) % n, perm[i]);
        }
        return (n - o.totalDistinct) <= m;
    }

    static class DSU {
        int[] parent;
        int[] size;
        int totalDistinct;

        public DSU(int n) {
            size = new int[n + 1];
            parent = new int[n + 1];
            Arrays.fill(parent, -1);
            Arrays.fill(size, 1);
            totalDistinct = n + 1;
        }

        public boolean unite(int a, int b) {
            a = find(a);
            b = find(b);
            if (a == b) {
                return false;
            }
            if (size[a] < size[b]) {
                a = a ^ b ^ (b = a);
            }
            parent[b] = a;
            size[a] += size[b];
            size[b] = 0;
            totalDistinct--;
            return true;
        }

        private int find(int num) {
            return (parent[num] == -1) ? num : (parent[num] = find(parent[num]));
        }

    }

    /************************************************************************************************************************************************/
    public static void main(String[] args) throws IOException {
        new Thread(null, new PermutationShift(), "1").start();
    }

    static PrintWriter out = new PrintWriter(System.out);
    static Reader read = new Reader();
    static StringBuilder sbr = new StringBuilder();
    static int mod = (int) 1e9 + 7;
    static int dmax = Integer.MAX_VALUE;
    static long lmax = Long.MAX_VALUE;
    static int dmin = Integer.MIN_VALUE;
    static long lmin = Long.MIN_VALUE;
    static int[] dprimes = new int[]{1, 11, 101, 1087, 99991, 100001, 1000003, 15485863, 999999937};

    @Override
    public void run() {
        solve();
        out.close();
    }

    static class Reader {
        private byte[] buf = new byte[1024];
        private int index;
        private InputStream in;
        private int total;

        public Reader() {
            in = System.in;
        }

        public int scan() throws IOException {
            if (total < 0)
                throw new InputMismatchException();
            if (index >= total) {
                index = 0;
                total = in.read(buf);
                if (total <= 0)
                    return -1;
            }
            return buf[index++];
        }

        public int intNext() throws IOException {
            int integer = 0;
            int n = scan();
            while (isWhiteSpace(n))
                n = scan();
            int neg = 1;
            if (n == '-') {
                neg = -1;
                n = scan();
            }
            while (!isWhiteSpace(n)) {
                if (n >= '0' && n <= '9') {
                    integer *= 10;
                    integer += n - '0';
                    n = scan();
                } else
                    throw new InputMismatchException();
            }
            return neg * integer;
        }

        public double doubleNext() throws IOException {
            double doub = 0;
            int n = scan();
            while (isWhiteSpace(n))
                n = scan();
            int neg = 1;
            if (n == '-') {
                neg = -1;
                n = scan();
            }
            while (!isWhiteSpace(n) && n != '.') {
                if (n >= '0' && n <= '9') {
                    doub *= 10;
                    doub += n - '0';
                    n = scan();
                } else
                    throw new InputMismatchException();
            }
            if (n == '.') {
                n = scan();
                double temp = 1;
                while (!isWhiteSpace(n)) {
                    if (n >= '0' && n <= '9') {
                        temp /= 10;
                        doub += (n - '0') * temp;
                        n = scan();
                    } else
                        throw new InputMismatchException();
                }
            }
            return doub * neg;
        }

        public String read() throws IOException {
            StringBuilder sb = new StringBuilder();
            int n = scan();
            while (isWhiteSpace(n))
                n = scan();
            while (!isWhiteSpace(n)) {
                sb.append((char) n);
                n = scan();
            }
            return sb.toString();
        }

        public String rline() throws IOException {
            StringBuilder sb = new StringBuilder();
            int n = scan();
            while (n != '\n') {
                sb.append((char) n);
                n = scan();
            }
            return sb.toString();
        }

        private boolean isWhiteSpace(int n) {
            if (n == ' ' || n == '\n' || n == '\r' || n == '\t' || n == -1)
                return true;
            return false;
        }
    }

    static void print(Object object) {
        out.print(object);
    }

    static void println(Object object) {
        out.println(object);
    }

    static int[] iArr(int len) {
        return new int[len];
    }

    static long[] lArr(int len) {
        return new long[len];
    }

    static long min(long a, long b) {
        return Math.min(a, b);
    }

    static int min(int a, int b) {
        return Math.min(a, b);
    }

    static long max(Long a, Long b) {
        return Math.max(a, b);
    }

    static int max(int a, int b) {
        return Math.max(a, b);
    }

    static int ri() {
        try {
            return read.intNext();
        } catch (IOException e) {
            e.printStackTrace();
        }
        System.exit(2);
        return -1;
    }

    static long rl() {
        try {
            return Long.parseLong(read.read());
        } catch (IOException e) {
            e.printStackTrace();
        }
        System.exit(2);
        return -1;
    }

    static String rs() {
        try {
            return read.read();
        } catch (IOException e) {
            e.printStackTrace();
        }
        System.exit(2);
        return "";
    }

    static String rline() {
        try {
            return read.rline();
        } catch (IOException e) {
            e.printStackTrace();
        }
        System.exit(2);
        return "";
    }

    static char rc() {
        return rs().charAt(0);
    }

    static double rd() {
        try {
            return read.doubleNext();
        } catch (IOException e) {
            e.printStackTrace();
        }
        System.exit(2);
        return -1;
    }
}
