An identity permutation of length n is an array [1, 2, 3, ..., n].

We performed the following operations to an identity permutation of length n:

  * firstly, we cyclically shifted it to the right by k positions, where k is unknown to you (the only thing you know is that 0 ≤ k ≤ n - 1). When an array is cyclically shifted to the right by k positions, the resulting array is formed by taking k last elements of the original array (without changing their relative order), and then appending n - k first elements to the right of them (without changing relative order of the first n - k elements as well). For example, if we cyclically shift the identity permutation of length 6 by 2 positions, we get the array [5, 6, 1, 2, 3, 4]; 
  * secondly, we performed the following operation at most m times: pick any two elements of the array and swap them. 



You are given the values of n and m, and the resulting array. Your task is to find all possible values of k in the cyclic shift operation.

Input

The first line contains one integer t (1 ≤ t ≤ 10^5) — the number of test cases.

Each test case consists of two lines. The first line contains two integers n and m (3 ≤ n ≤ 3 ⋅ 10^5; 0 ≤ m ≤ n/3).

The second line contains n integers p_1, p_2, ..., p_n (1 ≤ p_i ≤ n, each integer from 1 to n appears in this sequence exactly once) — the resulting array.

The sum of n over all test cases does not exceed 3 ⋅ 10^5.

Output

For each test case, print the answer in the following way:

  * firstly, print one integer r (0 ≤ r ≤ n) — the number of possible values of k for the cyclic shift operation; 
  * secondly, print r integers k_1, k_2, ..., k_r (0 ≤ k_i ≤ n - 1) — all possible values of k in increasing order. 

Example

Input


4
4 1
2 3 1 4
3 1
1 2 3
3 1
3 2 1
6 0
1 2 3 4 6 5


Output


1 3
1 0
3 0 1 2
0

Note

Consider the example: 

  * in the first test case, the only possible value for the cyclic shift is 3. If we shift [1, 2, 3, 4] by 3 positions, we get [2, 3, 4, 1]. Then we can swap the 3-rd and the 4-th elements to get the array [2, 3, 1, 4]; 
  * in the second test case, the only possible value for the cyclic shift is 0. If we shift [1, 2, 3] by 0 positions, we get [1, 2, 3]. Then we don't change the array at all (we stated that we made at most 1 swap), so the resulting array stays [1, 2, 3]; 
  * in the third test case, all values from 0 to 2 are possible for the cyclic shift: 
    * if we shift [1, 2, 3] by 0 positions, we get [1, 2, 3]. Then we can swap the 1-st and the 3-rd elements to get [3, 2, 1]; 
    * if we shift [1, 2, 3] by 1 position, we get [3, 1, 2]. Then we can swap the 2-nd and the 3-rd elements to get [3, 2, 1]; 
    * if we shift [1, 2, 3] by 2 positions, we get [2, 3, 1]. Then we can swap the 1-st and the 2-nd elements to get [3, 2, 1]; 
  * in the fourth test case, we stated that we didn't do any swaps after the cyclic shift, but no value of cyclic shift could produce the array [1, 2, 3, 4, 6, 5]. 
import java.io.OutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.PrintWriter;
import java.util.List;
import java.util.InputMismatchException;
import java.io.IOException;
import java.util.ArrayList;
import java.io.InputStream;

/**
 * Built using CHelper plug-in
 * Actual solution is at the top
 */
public class Main {
    public static void main(String[] args) {
        InputStream inputStream = System.in;
        OutputStream outputStream = System.out;
        InputReader in = new InputReader(inputStream);
        PrintWriter out = new PrintWriter(outputStream);
        ESdvigPerestanovki solver = new ESdvigPerestanovki();
        int testCount = Integer.parseInt(in.next());
        for (int i = 1; i <= testCount; i++)
            solver.solve(i, in, out);
        out.close();
    }

    static class ESdvigPerestanovki {
        public void solve(int testNumber, InputReader in, PrintWriter out) {
            int n = in.nextInt();
            int m = in.nextInt();

            int[] a = new int[n];
            int[] aw = new int[n];

            int[] ct = new int[n];
            for (int i = 0; i < n; i++) {

                a[i] = in.nextInt() - 1;
                aw[a[i]] = i;
                int shift = 0;
                if (a[i] <= i) {
                    shift = i - a[i];
                } else {
                    shift = i + (n - a[i]);
                }
                ct[shift] += 1;
            }

            int[] b = new int[n];
            int[] bw = new int[n];

            List<Integer> ans = new ArrayList<>();

            label:
            for (int shift = 0; shift < n; shift++) {
                int inPlace = ct[shift];
                int displaced = n - inPlace;
                if ((displaced + 1) / 2 > m) {
                    continue;
                }
                System.arraycopy(a, 0, b, 0, n);
                System.arraycopy(aw, 0, bw, 0, n);


                int cur = shift == 0 ? 0 : n - shift;
                int swaps = 0;
                for (int i = 0; i < n; i++) {
                    if (b[i] != cur) {
                        int is = bw[cur];
                        int z = b[i];
                        b[i] = b[is];
                        b[is] = z;
                        bw[b[i]] = i;
                        bw[b[is]] = is;
                        swaps++;
                        if (swaps > m) {
                            continue label;
                        }
                    }
                    cur++;
                    if (cur >= n) {
                        cur = 0;
                    }
                }
                ans.add(shift);
            }

            out.print(ans.size());
            for (Integer shift : ans) {
                out.print(" " + shift);
            }
            out.println();
        }

    }

    static class InputReader {
        private static final int BUFFER_LENGTH = 1 << 10;
        private InputStream stream;
        private byte[] buf = new byte[BUFFER_LENGTH];
        private int curChar;
        private int numChars;

        public InputReader(InputStream stream) {
            this.stream = stream;
        }

        private int nextC() {
            if (numChars == -1) {
                throw new InputMismatchException();
            }
            if (curChar >= numChars) {
                curChar = 0;
                try {
                    numChars = stream.read(buf);
                } catch (IOException e) {
                    throw new InputMismatchException();
                }
                if (numChars <= 0)
                    return -1;
            }
            return buf[curChar++];
        }

        public String next() {
            int c = nextC();
            while (isSpaceChar(c)) {
                c = nextC();
            }
            StringBuilder res = new StringBuilder();
            do {
                res.append((char) c);
                c = nextC();
            } while (!isSpaceChar(c));
            return res.toString();
        }

        public int nextInt() {
            int c = skipWhileSpace();
            int sgn = 1;
            if (c == '-') {
                sgn = -1;
                c = nextC();
            }
            int res = 0;
            do {
                if (c < '0' || c > '9') {
                    throw new InputMismatchException();
                }
                res *= 10;
                res += c - '0';
                c = nextC();
            } while (!isSpaceChar(c));
            return res * sgn;
        }

        public int skipWhileSpace() {
            int c = nextC();
            while (isSpaceChar(c)) {
                c = nextC();
            }
            return c;
        }

        public boolean isSpaceChar(int c) {
            return c == ' ' || c == '\n' || c == '\r' || c == '\t' || c == -1;
        }

    }
}

