You are given a sequence of n integers a_1,   a_2,   ...,   a_n.

Does there exist a sequence of n integers b_1,   b_2,   ...,   b_n such that the following property holds?

  * For each 1 ≤ i ≤ n, there exist two (not necessarily distinct) indices j and k (1 ≤ j,   k ≤ n) such that a_i = b_j - b_k. 

Input

The first line contains a single integer t (1 ≤ t ≤ 20) — the number of test cases. Then t test cases follow.

The first line of each test case contains one integer n (1 ≤ n ≤ 10).

The second line of each test case contains the n integers a_1,   ...,   a_n (-10^5 ≤ a_i ≤ 10^5).

Output

For each test case, output a line containing YES if a sequence b_1,   ...,   b_n satisfying the required property exists, and NO otherwise.

Example

Input


5
5
4 -7 -1 5 10
1
0
3
1 10 100
4
-3 2 10 2
9
25 -171 250 174 152 242 100 -205 -258


Output


YES
YES
NO
YES
YES

Note

In the first test case, the sequence b = [-9,   2,   1,   3,   -2] satisfies the property. Indeed, the following holds: 

  * a_1 = 4 = 2 - (-2) = b_2 - b_5; 
  * a_2 = -7 = -9 - (-2) = b_1 - b_5; 
  * a_3 = -1 = 1 - 2 = b_3 - b_2; 
  * a_4 = 5 = 3 - (-2) = b_4 - b_5; 
  * a_5 = 10 = 1 - (-9) = b_3 - b_1. 



In the second test case, it is sufficient to choose b = [0], since a_1 = 0 = 0 - 0 = b_1 - b_1.

In the third test case, it is possible to show that no sequence b of length 3 satisfies the property.
//This code is written by प्रविण शंखपाळ 

//package wizard;

import java.io.*;
import java.math.*;
import java.util.*;
import java.text.*;

public class Luna_Lovegood {

	public static void main(String[] args) {

//		try {

		FastReader fr = new FastReader();
		PrintWriter pt = new PrintWriter(System.out);

		int t = fr.nextInt();

		while (t > 0) {

			int n = fr.nextInt();
			long A[] = new long[n];
			for (int i = 0; i < n; i++) {
				A[i] = fr.nextLong();
			}

			HashSet<Long> x = new HashSet<>();

			for (int i = 0; i < 1 << n; i++) {
				long sum = 0;
				for (int j = 0; j < n; j++) {
					if ((i & (1 << j)) == 0) {
						sum += A[j];
					}
					x.add(sum);
				}
			}

			pt.println(x.size() == 1 << n ? "NO" : "YES");

			t--;

		}

		pt.close();

//		} catch (
//
//		Exception e) {
//			return;
//		}
	}

	static int lower_bound(long[] arr, int begin, int end, long tar) {
		while (begin < end) {
			int mid = begin + (end - begin) / 2;
			if (arr[mid] < tar)
				begin = mid + 1;
			else if (arr[mid] >= tar)
				end = mid;
		}
		return begin;
//		lower bound gives largest index of a number smaller than (if target is not present) or equal to target(if target is present) 
//      for complete array use begin = 0 and end = n
	}

	static int upper_bound(long[] arr, int begin, int end, long tar) {
		while (begin < end) {
			int mid = begin + (end - begin) / 2;
			if (arr[mid] <= tar)
				begin = mid + 1;
			else if (arr[mid] > tar)
				end = mid;
		}

		return begin;
//		upper bound gives smallest index of a number strictly greater than target
//	    for complete array use begin = 0 and end = n
	}

	public static void mergeSort(String[] nameGo) {
		if (nameGo.length > 1) {
			String[] leftGo = new String[nameGo.length / 2];
			String[] rightGo = new String[nameGo.length - nameGo.length / 2];
			for (int so = 0; so < leftGo.length; so++) {
				leftGo[so] = nameGo[so];
			}
			for (int ki = 0; ki < rightGo.length; ki++) {
				rightGo[ki] = nameGo[ki + nameGo.length / 2];
			}
			mergeSort(leftGo);
			mergeSort(rightGo);
			merges(nameGo, leftGo, rightGo);
		}
	}

	public static void merges(String[] nameH, String[] leftH, String[] rightH) {
		int as = 0;
		int bs = 0;
		for (int i = 0; i < nameH.length; i++) {
			if (bs >= rightH.length || (as < leftH.length && leftH[as].compareToIgnoreCase(rightH[bs]) < 0)) {
				nameH[i] = leftH[as];
				as++;
			} else {
				nameH[i] = rightH[bs];
				bs++;
			}
		}
	}

	static void merge(int arr[], int l, int m, int r) {

		int n1 = m - l + 1;
		int n2 = r - m;

		int L[] = new int[n1];
		int R[] = new int[n2];

		for (int i = 0; i < n1; ++i)
			L[i] = arr[l + i];
		for (int j = 0; j < n2; ++j)
			R[j] = arr[m + 1 + j];

		int i = 0, j = 0;

		int k = l;
		while (i < n1 && j < n2) {
			if (L[i] <= R[j]) {
				arr[k] = L[i];
				i++;
			} else {
				arr[k] = R[j];
				j++;
			}
			k++;
		}

		while (i < n1) {
			arr[k] = L[i];
			i++;
			k++;
		}

		while (j < n2) {
			arr[k] = R[j];
			j++;
			k++;
		}
	}

	static void sort(int arr[], int l, int r) {
		if (l < r) {

			int m = l + (r - l) / 2;

			sort(arr, l, m);
			sort(arr, m + 1, r);

			merge(arr, l, m, r);
		}
	}

	static class Pair implements Comparable<Pair> {
		int a, b;

		Pair(int a, int b) {
			this.a = a;
			this.b = b;
		}

		public int compareTo(Pair o) {
			// TODO Auto-generated method stub
			if (this.a != o.a)
				return Integer.compare(this.a, o.a);
			else
				return Integer.compare(this.b, o.b);
			// return 0;
		}

		public boolean equals(Object o) {
			if (o instanceof Pair) {
				Pair p = (Pair) o;
				return p.a == a && p.b == b;
			}
			return false;
		}

	}

	static int binarySearch(int arr[], int first, int last, int key) {
		int mid = (first + last) / 2;
		while (first <= last) {
			if (arr[mid] < key) {
				first = mid + 1;
			} else if (arr[mid] == key) {
				return mid;
			} else {
				last = mid - 1;
			}
			mid = (first + last) / 2;
		}
		return -1;
	}

	static class FastReader {
		BufferedReader br;
		StringTokenizer st;

		public FastReader() {
			br = new BufferedReader(new InputStreamReader(System.in));
		}

		String next() {
			while (st == null || !st.hasMoreElements()) {
				try {
					st = new StringTokenizer(br.readLine());
				} catch (IOException e) {
					e.printStackTrace();
				}
			}
			return st.nextToken();
		}

		int nextInt() {
			return Integer.parseInt(next());
		}

		long nextLong() {
			return Long.parseLong(next());
		}

		double nextDouble() {
			return Double.parseDouble(next());
		}

		String nextLine() {
			String str = "";
			try {
				str = br.readLine();
			} catch (IOException e) {
				e.printStackTrace();
			}
			return str;
		}
	}
}
