This problem is an extension of the problem "Wonderful Coloring - 1". It has quite many differences, so you should read this statement completely.

Recently, Paul and Mary have found a new favorite sequence of integers a_1, a_2, ..., a_n. They want to paint it using pieces of chalk of k colors. The coloring of a sequence is called wonderful if the following conditions are met:

  1. each element of the sequence is either painted in one of k colors or isn't painted; 
  2. each two elements which are painted in the same color are different (i. e. there's no two equal values painted in the same color); 
  3. let's calculate for each of k colors the number of elements painted in the color — all calculated numbers must be equal; 
  4. the total number of painted elements of the sequence is the maximum among all colorings of the sequence which meet the first three conditions. 



E. g. consider a sequence a=[3, 1, 1, 1, 1, 10, 3, 10, 10, 2] and k=3. One of the wonderful colorings of the sequence is shown in the figure.

<image> The example of a wonderful coloring of the sequence a=[3, 1, 1, 1, 1, 10, 3, 10, 10, 2] and k=3. Note that one of the elements isn't painted.

Help Paul and Mary to find a wonderful coloring of a given sequence a.

Input

The first line contains one integer t (1 ≤ t ≤ 10000) — the number of test cases. Then t test cases follow.

Each test case consists of two lines. The first one contains two integers n and k (1 ≤ n ≤ 2⋅10^5, 1 ≤ k ≤ n) — the length of a given sequence and the number of colors, respectively. The second one contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ n).

It is guaranteed that the sum of n over all test cases doesn't exceed 2 ⋅ 10^5.

Output

Output t lines, each of them must contain a description of a wonderful coloring for the corresponding test case.

Each wonderful coloring must be printed as a sequence of n integers c_1, c_2, ..., c_n (0 ≤ c_i ≤ k) separated by spaces where

  * c_i=0, if i-th element isn't painted; 
  * c_i>0, if i-th element is painted in the c_i-th color. 



Remember that you need to maximize the total count of painted elements for the wonderful coloring. If there are multiple solutions, print any one.

Example

Input


6
10 3
3 1 1 1 1 10 3 10 10 2
4 4
1 1 1 1
1 1
1
13 1
3 1 4 1 5 9 2 6 5 3 5 8 9
13 2
3 1 4 1 5 9 2 6 5 3 5 8 9
13 3
3 1 4 1 5 9 2 6 5 3 5 8 9


Output


1 1 0 2 3 2 2 1 3 3
4 2 1 3
1
0 0 1 1 0 1 1 1 0 1 1 1 0
2 1 2 2 1 1 1 1 2 1 0 2 2
1 1 3 2 1 3 3 1 2 2 3 2 0

Note

In the first test case, the answer is shown in the figure in the statement. The red color has number 1, the blue color — 2, the green — 3.
12
10 3
3 1 1 1 1 10 3 10 10 2
4 4
1 1 1 1
1 1
1
13 1
3 1 4 1 5 9 2 6 5 3 5 8 9
13 2
3 1 4 1 5 9 2 6 5 3 5 8 9
13 3
3 1 4 1 5 9 2 6 5 3 5 8 9
10 3
3 1 1 1 1 10 3 10 10 2
4 4
1 1 1 1
1 1
1
13 1
3 1 4 1 5 9 2 6 5 3 5 8 9
13 2
3 1 4 1 5 9 2 6 5 3 5 8 9
13 3
3 1 4 1 5 9 2 6 5 3 5 8 9
 6
10 3
3 1 1 1 1 10 3 10 10 2
4 4
1 1 1 1
1 1
1
13 1
3 1 4 1 5 9 2 6 5 3 5 8 9
13 2
3 1 4 1 5 9 2 6 5 3 5 8 9
13 3
3 1 4 1 5 9 2 6 5 3 5 8 9

2 1 2 3 0 1 3 2 3 1 
1 2 3 4 
1 
1 1 1 0 1 1 1 1 0 0 0 1 0 
2 1 2 2 1 1 1 1 2 1 0 2 2 
1 1 3 2 1 3 3 1 2 2 3 2 0 
2 1 2 3 0 1 3 2 3 1 
1 2 3 4 
1 
1 1 1 0 1 1 1 1 0 0 0 1 0 
2 1 2 2 1 1 1 1 2 1 0 2 2 
1 1 3 2 1 3 3 1 2 2 3 2 0 
 2 1 2 3 0 1 3 2 3 1 
1 2 3 4 
1 
1 1 1 0 1 1 1 1 0 0 0 1 0 
2 1 2 2 1 1 1 1 2 1 0 2 2 
1 1 3 2 1 3 3 1 2 2 3 2 0 

import java.util.*;
import java.lang.*;
import java.io.*;

// Created by @thesupremeone on 23/07/21
public class B2 {
    static class Pair implements Comparable<Pair>{
        int element;
        TreeSet<Integer> set;
        public Pair(int element, TreeSet<Integer> set) {
            this.element = element;
            this.set = set;
        }
        @Override
        public int compareTo(Pair pair) {
            return Integer.compare(pair.set.size(), set.size());
        }
    }
    void solve() throws IOException {
        int ts = getInt();
        for (int t = 1; t <= ts; t++){
            int n = getInt();
            int k = getInt();
            HashMap<Integer, Integer> freq = new HashMap<>();
            TreeMap<Integer, TreeSet<Integer>> indexes = new TreeMap<>();
            int[] a = new int[n];
            for (int i = 0; i < n; i++){
                int ai = getInt();
                a[i] = ai;
                freq.put(ai, 1+freq.getOrDefault(ai, 0));
                TreeSet<Integer> set;
                if(indexes.containsKey(ai)){
                    set = indexes.get(ai);
                }else {
                    set = new TreeSet<>();
                    indexes.put(ai, set);
                }
                set.add(i);
            }
            long sum = 0;
            for (int e : freq.keySet()){
                sum += Math.min(k, freq.get(e));
            }
            int count = (int)(sum/k);
            int[] coloring = new int[n];
            int[] colorUsed = new int[k+1];
            Pair[] pairs = new Pair[indexes.size()];
            int i = 0;
            for(int element: indexes.keySet()) {
                pairs[i++] = new Pair(element, indexes.get(element));
            }
            Arrays.sort(pairs);
            int color = 1;
            for(Pair pair : pairs){
                TreeSet<Integer> locations = pair.set;
                if(colorUsed[color]==count) break;
                int start = color;
                for(int index : locations){
                    coloring[index] = color;
                    colorUsed[color]++;
                    color++;
                    if(color>k) color=1;
                    if(color==start) break;
                    if (colorUsed[color]==count) break;
                }
            }
            for (int c : coloring){
                print(c+" ");
            }
            println("");
        }
    }

    public static void main(String[] args) throws Exception {
        if (isOnlineJudge()) {
            in = new BufferedReader(new InputStreamReader(System.in));
            out = new BufferedWriter(new OutputStreamWriter(System.out));
            new B2().solve();
            out.flush();
        } else {
            localJudge = new Thread();
            in = new BufferedReader(new FileReader("input.txt"));
            out = new BufferedWriter(new FileWriter("output.txt"));
            localJudge.start();
            new B2().solve();
            out.flush();
            localJudge.suspend();
        }
    }
    static boolean isOnlineJudge(){
        try {
            return System.getProperty("ONLINE_JUDGE")!=null
                    || System.getProperty("LOCAL")==null;
        }catch (Exception e){
            return true;
        }
    }
    // Fast Input & Output
    static Thread localJudge = null;
    static BufferedReader in;
    static StringTokenizer st;
    static BufferedWriter out;
    static String getLine() throws IOException{
        return in.readLine();
    }
    static String getToken() throws IOException{
        if(st==null || !st.hasMoreTokens())
            st = new StringTokenizer(getLine());
        return st.nextToken();
    }
    static int getInt() throws IOException {
        return Integer.parseInt(getToken());
    }
    static long getLong() throws IOException {
        return Long.parseLong(getToken());
    }
    static void print(Object s) throws IOException{
        out.write(String.valueOf(s));
    }
    static void println(Object s) throws IOException{
        out.write(String.valueOf(s));
        out.newLine();
    }
}