This problem is an extension of the problem "Wonderful Coloring - 1". It has quite many differences, so you should read this statement completely.

Recently, Paul and Mary have found a new favorite sequence of integers a_1, a_2, ..., a_n. They want to paint it using pieces of chalk of k colors. The coloring of a sequence is called wonderful if the following conditions are met:

  1. each element of the sequence is either painted in one of k colors or isn't painted; 
  2. each two elements which are painted in the same color are different (i. e. there's no two equal values painted in the same color); 
  3. let's calculate for each of k colors the number of elements painted in the color — all calculated numbers must be equal; 
  4. the total number of painted elements of the sequence is the maximum among all colorings of the sequence which meet the first three conditions. 



E. g. consider a sequence a=[3, 1, 1, 1, 1, 10, 3, 10, 10, 2] and k=3. One of the wonderful colorings of the sequence is shown in the figure.

<image> The example of a wonderful coloring of the sequence a=[3, 1, 1, 1, 1, 10, 3, 10, 10, 2] and k=3. Note that one of the elements isn't painted.

Help Paul and Mary to find a wonderful coloring of a given sequence a.

Input

The first line contains one integer t (1 ≤ t ≤ 10000) — the number of test cases. Then t test cases follow.

Each test case consists of two lines. The first one contains two integers n and k (1 ≤ n ≤ 2⋅10^5, 1 ≤ k ≤ n) — the length of a given sequence and the number of colors, respectively. The second one contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ n).

It is guaranteed that the sum of n over all test cases doesn't exceed 2 ⋅ 10^5.

Output

Output t lines, each of them must contain a description of a wonderful coloring for the corresponding test case.

Each wonderful coloring must be printed as a sequence of n integers c_1, c_2, ..., c_n (0 ≤ c_i ≤ k) separated by spaces where

  * c_i=0, if i-th element isn't painted; 
  * c_i>0, if i-th element is painted in the c_i-th color. 



Remember that you need to maximize the total count of painted elements for the wonderful coloring. If there are multiple solutions, print any one.

Example

Input


6
10 3
3 1 1 1 1 10 3 10 10 2
4 4
1 1 1 1
1 1
1
13 1
3 1 4 1 5 9 2 6 5 3 5 8 9
13 2
3 1 4 1 5 9 2 6 5 3 5 8 9
13 3
3 1 4 1 5 9 2 6 5 3 5 8 9


Output


1 1 0 2 3 2 2 1 3 3
4 2 1 3
1
0 0 1 1 0 1 1 1 0 1 1 1 0
2 1 2 2 1 1 1 1 2 1 0 2 2
1 1 3 2 1 3 3 1 2 2 3 2 0

Note

In the first test case, the answer is shown in the figure in the statement. The red color has number 1, the blue color — 2, the green — 3.
12
10 3
3 1 1 1 1 10 3 10 10 2
4 4
1 1 1 1
1 1
1
13 1
3 1 4 1 5 9 2 6 5 3 5 8 9
13 2
3 1 4 1 5 9 2 6 5 3 5 8 9
13 3
3 1 4 1 5 9 2 6 5 3 5 8 9
10 3
3 1 1 1 1 10 3 10 10 2
4 4
1 1 1 1
1 1
1
13 1
3 1 4 1 5 9 2 6 5 3 5 8 9
13 2
3 1 4 1 5 9 2 6 5 3 5 8 9
13 3
3 1 4 1 5 9 2 6 5 3 5 8 9
 6
10 3
3 1 1 1 1 10 3 10 10 2
4 4
1 1 1 1
1 1
1
13 1
3 1 4 1 5 9 2 6 5 3 5 8 9
13 2
3 1 4 1 5 9 2 6 5 3 5 8 9
13 3
3 1 4 1 5 9 2 6 5 3 5 8 9

2 1 2 3 0 1 3 2 3 1 
1 2 3 4 
1 
1 1 1 0 1 1 1 1 0 0 0 1 0 
2 1 2 2 1 1 1 1 2 1 0 2 2 
1 1 3 2 1 3 3 1 2 2 3 2 0 
2 1 2 3 0 1 3 2 3 1 
1 2 3 4 
1 
1 1 1 0 1 1 1 1 0 0 0 1 0 
2 1 2 2 1 1 1 1 2 1 0 2 2 
1 1 3 2 1 3 3 1 2 2 3 2 0 
 2 1 2 3 0 1 3 2 3 1 
1 2 3 4 
1 
1 1 1 0 1 1 1 1 0 0 0 1 0 
2 1 2 2 1 1 1 1 2 1 0 2 2 
1 1 3 2 1 3 3 1 2 2 3 2 0 

import java.io.*;
import java.util.*;
public class A734Bbb {
    public static void main(String[] args) {
        JS scan = new JS();
        int t = scan.nextInt();
        PrintWriter out = new PrintWriter(System.out);
        loop:while(t-->0){
            int n = scan.nextInt();
            int k =scan.nextInt();
            int[] arr= new int[n];
            int[] freq =new int[n+1];
            int[] used =new int[n+1];
            ArrayList<number> numbers = new ArrayList<>();
            for(int i = 0;i<n;i++){
                arr[i] = scan.nextInt();
                freq[arr[i]]++;
            }
            boolean[] v = new boolean[n+1];
            for(int i = 0;i<n;i++){
                if(v[arr[i]])continue;
                v[arr[i]] = true;
                numbers.add(new number(arr[i],freq[arr[i]]));
            }
            Collections.sort(numbers);
            int ans = 0;
            int left = 0;
            for(int i = 1;i<=n;i++){
                if(freq[i]>=k)ans++;
                else{
                    left+=freq[i];
                }
            }
            ans+=left/k;
            int[] colors =new int[n];
            int[] start = new int[n+1];
            for (number curr:numbers){
                //System.out.println(curr.val+" "+curr.freq+" FREQ");
                start[curr.val] = Math.min(curr.freq,k);
            }
            for(int i = 0;i<n;i++){
                if(start[arr[i]]>0) {
                    //System.out.println(arr[i]+" "+start[arr[i]]);
                    colors[i] = start[arr[i]];
                    start[arr[i]]--;
                }
            }
            for(int i = 0;i<n;i++){
                out.print(colors[i]+" ");
            }
            out.println();
            //System.out.println(ans);

        }
        out.flush();
        out.close();
    }
    static class number implements Comparable<number>{
        int freq, val;
        public number(int a,int b){
            freq = b;
            val = a;
        }

        @Override
        public int compareTo(number o) {
            return o.freq-freq;
        }
    }
    static class JS {
        public int BS = 1 << 16;
        public char NC = (char) 0;
        byte[] buf = new byte[BS];
        int bId = 0, size = 0;
        char c = NC;
        double num = 1;
        BufferedInputStream in;

        public JS() {
            in = new BufferedInputStream(System.in, BS);
        }

        public JS(String s) throws FileNotFoundException {
            in = new BufferedInputStream(new FileInputStream(new File(s)), BS);
        }

        public char nextChar() {
            while (bId == size) {
                try {
                    size = in.read(buf);
                } catch (Exception e) {
                    return NC;
                }
                if (size == -1) return NC;
                bId = 0;
            }
            return (char) buf[bId++];
        }

        public int nextInt() {
            return (int) nextLong();
        }

        public long nextLong() {
            num = 1;
            boolean neg = false;
            if (c == NC) c = nextChar();
            for (; (c < '0' || c > '9'); c = nextChar()) {
                if (c == '-') neg = true;
            }
            long res = 0;
            for (; c >= '0' && c <= '9'; c = nextChar()) {
                res = (res << 3) + (res << 1) + c - '0';
                num *= 10;
            }
            return neg ? -res : res;
        }

        public double nextDouble() {
            double cur = nextLong();
            return c != '.' ? cur : cur + nextLong() / num;
        }

        public String next() {
            StringBuilder res = new StringBuilder();
            while (c <= 32) c = nextChar();
            while (c > 32) {
                res.append(c);
                c = nextChar();
            }
            return res.toString();
        }

        public String nextLine() {
            StringBuilder res = new StringBuilder();
            while (c <= 32) c = nextChar();
            while (c != '\n') {
                res.append(c);
                c = nextChar();
            }
            return res.toString();
        }

        public boolean hasNext() {
            if (c > 32) return true;
            while (true) {
                c = nextChar();
                if (c == NC) return false;
                else if (c > 32) return true;
            }
        }
    }
}
