For given integers m and n, compute mn (mod 1,000,000,007). Here, A (mod M) is the remainder when A is divided by M.

Constraints

* 1 ≤ m ≤ 100
* 1 ≤ n ≤ 109

Input


m n


Two integers m and n are given in a line.

Output

Print mn (mod 1,000,000,007) in a line.

Examples

Input

2 3


Output

8


Input

5 8


Output

390625
#include <bits/stdc++.h>
long long int power(long long int x, long long n, long long int M) {
  long long int tmp = 1;
  if (n > 0) {
    tmp = power(x, n / 2, M);
    if (n % 2 == 0)
      tmp = (tmp * tmp) % M;
    else
      tmp = (((tmp * tmp) % M) * x) % M;
  }
  return tmp;
}
int main(void) {
  long long int m, n;
  int i;
  scanf("%lld %lld", &m, &n);
  printf("%lld\n", (m, n, 1000000007));
  return 0;
}
