# 再帰関数
# 入力文字列の最大の正整数を返す
# def func( in_str: str, prev: str ):
#     if len(in_str) == 0:
#         return 0
#     for i in range(len(in_str)):
#         s = in_str[0:i+1]
#         if s == prev:
#             continue
#         else:
#             new_str = in_str[i+1:]
#             ret = func(new_str, s)
#             if ret == -1:
#                 continue
#             return 1 + ret
#
#     return -1

#再帰じゃない
def func( in_str: str ):
    result = 0
    prev =""
    new_str = in_str
    stack_str =[]
    stack_i = []
    stack_K = []
    K = 0
    old_i = 0
    is_separate = False
    while(True):
        num = len(new_str)
        if num == 0:
            break
        for i in range(old_i, num):
            s = new_str[0:i+1]
            if s == prev:
                is_separate = False
                continue
            else:
                # 分岐前に状態保存
                stack_str.append(new_str)
                stack_i.append(i+1)
                stack_K.append(K)

                new_str = new_str[i+1:]
                prev = s
                K += 1
                is_separate = True
                break;
        # 失敗したらスタックからもとに戻す
        if is_separate == False:
            new_str = stack_str.pop()
            old_i = stack_i.pop()
            K = stack_K.pop()
        else:
            old_i = 0

    return K

s = input()
#s="aabbaa"
#s="aaaccacabaldkfjadhjdhafidhkajhdkfjahdskjhfakhdkfaababc"*1000
#num = func( s, "")
num = func( s )

print(num)