1
& 0
 1
^ 123
 10
^ 218
& 150
| 935
& 61
| 588
& 897
| 411
| 584
^ 800
| 704
 3
& 1
& 3
& 5
 1
| 123
 1
^ 0
 1
| 1023
 3
& 242
^ 506
^ 522
 10
^ 160
& 1021
& 510
^ 470
& 1022
& 251
& 760
& 1016
| 772
| 515
 1
& 1023
 1
| 0
 2
| 56
^ 875
 1
^ 1023
 2
| 999
^ 689
 3
^ 125
^ 377
& 1019
 1
& 123

3
& 0
| 0
^ 0
 3
& 1023
| 0
^ 123
 3
& 763
| 763
^ 0
 3
& 1
| 0
^ 0
 3
& 1023
| 123
^ 0
 3
& 1023
| 0
^ 0
 3
& 1023
| 1023
^ 0
 3
& 1010
| 768
^ 240
 2
| 775
^ 112
 3
& 1023
| 0
^ 0
 3
& 1023
| 0
^ 0
 3
& 983
| 16
^ 835
 3
& 1023
| 0
^ 1023
 3
& 350
| 326
^ 16
 3
& 1019
| 0
^ 256
 3
& 123
| 0
^ 0

q = int(input())

def calc(f):
    ret1 = 0
    ret2 = 1023
    for op in f:
        if op[0] == '&':
            ret1 &= op[1]
            ret2 &= op[1]
        elif op[0] == '|':
            ret1 |= op[1]
            ret2 |= op[1]
        elif op[0] == '^':
            ret1 ^= op[1]
            ret2 ^= op[1]

    return (ret1, ret2)

f = list()
for i in range(q):
    oper, n = input().split()
    n = int(n)
    f.append((oper, n))

op0, op1 = calc(f)

op0 = ('0000000000' + bin(op0)[2:])[-10:][::-1]
op1 = ('0000000000' + bin(op1)[2:])[-10:][::-1]

o = 0
x = 0

for i in range(10):
    if (op0[i] == '1') and (op1[i] == '1'):
        o += 2**i

    elif (op0[i] == '1') and (op1[i] == '0'):
        x += 2**i

    elif (op0[i] == '0') and (op1[i] == '0'):
        o += 2**i
        x += 2**i

print(2)
print('| ' + str(o))
print('^ ' + str(x))
