1
& 0
 1
^ 123
 10
^ 218
& 150
| 935
& 61
| 588
& 897
| 411
| 584
^ 800
| 704
 3
& 1
& 3
& 5
 1
| 123
 1
^ 0
 1
| 1023
 3
& 242
^ 506
^ 522
 10
^ 160
& 1021
& 510
^ 470
& 1022
& 251
& 760
& 1016
| 772
| 515
 1
& 1023
 1
| 0
 2
| 56
^ 875
 1
^ 1023
 2
| 999
^ 689
 3
^ 125
^ 377
& 1019
 1
& 123

3
& 0
| 0
^ 0
 3
& 1023
| 0
^ 123
 3
& 763
| 763
^ 0
 3
& 1
| 0
^ 0
 3
& 1023
| 123
^ 0
 3
& 1023
| 0
^ 0
 3
& 1023
| 1023
^ 0
 3
& 1010
| 768
^ 240
 2
| 775
^ 112
 3
& 1023
| 0
^ 0
 3
& 1023
| 0
^ 0
 3
& 983
| 16
^ 835
 3
& 1023
| 0
^ 1023
 3
& 350
| 326
^ 16
 3
& 1019
| 0
^ 256
 3
& 123
| 0
^ 0

#include <bits/stdc++.h>
using namespace std;
const int MAX = 5e5 + 5;
int XOR = 0, AND = 1, OR = 2;
int N;
vector<pair<int, int> > v;
int A[MAX], B[3];
int main() {
  ios_base::sync_with_stdio(false);
  cin >> N;
  for (int i = 1; i <= N; ++i) {
    char x;
    cin >> x;
    int y;
    cin >> y;
    if (x == '^')
      v.push_back({XOR, y});
    else if (x == '&')
      v.push_back({AND, y});
    else if (x == '|')
      v.push_back({OR, y});
  }
  for (int i = 0; i < 10; ++i) {
    int swap = 1, same = 1, one = 0, zero = 0;
    for (int j = 0; j <= 1; ++j) {
      int prev = j;
      for (int k = 0; k < v.size(); ++k) {
        if (v[k].first == XOR) {
          if (v[k].second & (1LL << i))
            prev ^= 1;
          else
            ;
        }
        if (v[k].first == AND) {
          if (v[k].second & (1LL << i))
            ;
          else
            prev = 0;
        }
        if (v[k].first == OR) {
          if (v[k].second & (1LL << i))
            prev = 1;
          else
            ;
        }
      }
      if (prev == j)
        swap = 0;
      else
        same = 0;
      if (prev == 0)
        ++zero;
      else
        ++one;
    }
    if (same)
      A[i] = 0;
    else if (swap)
      A[i] = 1;
    else if (zero == 2)
      A[i] = 2;
    else
      A[i] = 3;
  }
  for (int i = 0; i < 10; ++i) {
    if (A[i] == 0)
      B[1] |= (1LL << i);
    else if (A[i] == 1)
      B[0] |= (1LL << i), B[1] |= (1LL << i);
    else if (A[i] == 2)
      ;
    else if (A[i] == 3)
      B[1] |= (1LL << i), B[2] |= (1LL << i);
  }
  cout << 3 << endl;
  cout << "^ " << B[0] << endl;
  cout << "& " << B[1] << endl;
  cout << "| " << B[2] << endl;
  return 0;
}
