1
& 0
 1
^ 123
 10
^ 218
& 150
| 935
& 61
| 588
& 897
| 411
| 584
^ 800
| 704
 3
& 1
& 3
& 5
 1
| 123
 1
^ 0
 1
| 1023
 3
& 242
^ 506
^ 522
 10
^ 160
& 1021
& 510
^ 470
& 1022
& 251
& 760
& 1016
| 772
| 515
 1
& 1023
 1
| 0
 2
| 56
^ 875
 1
^ 1023
 2
| 999
^ 689
 3
^ 125
^ 377
& 1019
 1
& 123

3
& 0
| 0
^ 0
 3
& 1023
| 0
^ 123
 3
& 763
| 763
^ 0
 3
& 1
| 0
^ 0
 3
& 1023
| 123
^ 0
 3
& 1023
| 0
^ 0
 3
& 1023
| 1023
^ 0
 3
& 1010
| 768
^ 240
 2
| 775
^ 112
 3
& 1023
| 0
^ 0
 3
& 1023
| 0
^ 0
 3
& 983
| 16
^ 835
 3
& 1023
| 0
^ 1023
 3
& 350
| 326
^ 16
 3
& 1019
| 0
^ 256
 3
& 123
| 0
^ 0

LEN = 10
mapping = [[0, 1] for _ in range(LEN)]
n = int(raw_input())
for _ in range(n):
    cmd = raw_input().split()
    val = int(cmd[1])
    if cmd[0] == '|':
        for i in range(LEN):
            cur_digit = ((val & (1 << i) ) != 0)
            if cur_digit:
                mapping[i][0], mapping[i][1] = 1, 1
    elif cmd[0] == '&':
        for i in range(LEN):
            cur_digit = ((val & (1 << i) ) != 0)
            if not cur_digit:
                mapping[i][0], mapping[i][1] = 0, 0
    else:
        for i in range(LEN):
            cur_digit = ((val & (1 << i) ) != 0)
            if cur_digit:
                mapping[i][0], mapping[i][1] = mapping[i][0] ^ 1, mapping[i][1] ^ 1

# construct answer
# &
and_val = (1 << LEN) - 1
for i in range(LEN):
    if mapping[i][0] == 0 and mapping[i][1] == 0:
        and_val = and_val ^ (1 << i)

or_val = 0
for i in range(LEN):
    if mapping[i][0] == 1 and mapping[i][1] == 1:
        or_val = or_val | (1 << i)

xor_val = 0
for i in range(LEN):
    if mapping[i][0] == 1 and mapping[i][1] == 0:
        xor_val = xor_val | (1 << i)

print 3
print '& %d' % and_val
print '| %d' % or_val
print '^ %d' % xor_val
