1
& 0
 1
^ 123
 10
^ 218
& 150
| 935
& 61
| 588
& 897
| 411
| 584
^ 800
| 704
 3
& 1
& 3
& 5
 1
| 123
 1
^ 0
 1
| 1023
 3
& 242
^ 506
^ 522
 10
^ 160
& 1021
& 510
^ 470
& 1022
& 251
& 760
& 1016
| 772
| 515
 1
& 1023
 1
| 0
 2
| 56
^ 875
 1
^ 1023
 2
| 999
^ 689
 3
^ 125
^ 377
& 1019
 1
& 123

3
& 0
| 0
^ 0
 3
& 1023
| 0
^ 123
 3
& 763
| 763
^ 0
 3
& 1
| 0
^ 0
 3
& 1023
| 123
^ 0
 3
& 1023
| 0
^ 0
 3
& 1023
| 1023
^ 0
 3
& 1010
| 768
^ 240
 2
| 775
^ 112
 3
& 1023
| 0
^ 0
 3
& 1023
| 0
^ 0
 3
& 983
| 16
^ 835
 3
& 1023
| 0
^ 1023
 3
& 350
| 326
^ 16
 3
& 1019
| 0
^ 256
 3
& 123
| 0
^ 0

#include <bits/stdc++.h>
int main() {
  int n;
  scanf("%d", &n);
  int one = 1023, zero = 0;
  for (int i = 0; i < n; i++) {
    char otr;
    int ord;
    scanf(" %c %d", &otr, &ord);
    if (otr == '&') {
      one &= ord;
      zero &= ord;
    } else if (otr == '|') {
      one |= ord;
      zero |= ord;
    } else {
      one ^= ord;
      zero ^= ord;
    }
  }
  int _xor = 0, _and = 0, _or = 0;
  for (int i = 1; i < 1023; i *= 2) {
    if ((one & i) && (zero & i))
      _or |= i;
    else if ((one & i) && !(zero & i))
      _and |= i;
    else if (!(one & i) && (zero & i)) {
      _and |= i;
      _xor |= i;
    }
  }
  printf("3\n& %d\n^ %d\n| %d\n", _and, _xor, _or);
  return 0;
}
