2 10 1 1 1
1
10
1
1 5 1 8
 4 4 1 0 1
1

1
1 2 1 4
 2 5 1 0 1
2

1
1 4 1 5
 10 10 1 8 4
10
2 3 4 5 6 7 8 9
10
1 1 3 1
2 1 7 1
1 1 9 1
7 1 4 1
10 1 7 1
2 1 7 1
3 1 2 1
5 1 2 1
10 1 5 1
6 1 9 1
 2 4 1 1 1
1
4
1
1 2 1 3
 2 2 0 1 1

1
1
1 2 2 2
 1000 1000 1 1 10
1
2
1
1 900 1 1000
 5 5 1 1 1
3
2
1
1 5 1 1
 2 4 1 1 1
1
2
1
2 3 2 4
 4 4 1 0 1
4

5
1 1 2 2
1 3 2 2
3 3 4 3
3 2 2 2
1 2 2 3

3
 2
 1
 3
4
4
3
3
4
3
3
4
3
 1
 3
 100
 4
 1
 6
4
3
5
4

#include <bits/stdc++.h>
using namespace std;
int ans[100005], pos[100005];
pair<int, int> flro, frro;
int main() {
  int m, n, c1, c2, v, q, upordown;
  scanf("%d%d%d%d%d", &m, &n, &c1, &c2, &v);
  for (int i = 0; i < c1 && i < n; i++) scanf("%d", &ans[i]);
  for (int i = 0; i < c2 && i < n; i++) scanf("%d", &pos[i]);
  scanf("%d", &q);
  while (q--) {
    scanf("%d%d%d%d", &flro.first, &flro.second, &frro.first, &frro.second);
    int totaltime = 9999999999;
    if (flro.first == frro.first) {
      printf("%d", abs(frro.second - flro.second));
      continue;
    }
    int sear = lower_bound(ans, ans + c1, flro.second) - ans;
    if (sear < c1) {
      upordown = ans[sear];
      totaltime = min(totaltime, abs(upordown - flro.second) +
                                     abs(frro.first - flro.first) +
                                     abs(upordown - frro.second));
    }
    if (sear > 0) {
      upordown = ans[sear - 1];
      totaltime = min(totaltime, abs(upordown - flro.second) +
                                     abs(frro.first - flro.first) +
                                     abs(upordown - frro.second));
    }
    sear = lower_bound(pos, pos + c2, flro.second) - pos;
    if (sear < c2) {
      upordown = pos[sear];
      totaltime =
          min(totaltime, abs(upordown - flro.second) +
                             (abs(flro.first - frro.first) + v - 1) / v +
                             abs(upordown - frro.second));
    }
    if (sear > 0) {
      upordown = pos[sear - 1];
      totaltime =
          min(totaltime, abs(upordown - flro.second) +
                             (abs(flro.first - frro.first) + v - 1) / v +
                             abs(upordown - frro.second));
    }
    printf("%d\n", totaltime);
  }
  return 0;
}
