1
& 0
 1
^ 123
 10
^ 218
& 150
| 935
& 61
| 588
& 897
| 411
| 584
^ 800
| 704
 3
& 1
& 3
& 5
 1
| 123
 1
^ 0
 1
| 1023
 3
& 242
^ 506
^ 522
 10
^ 160
& 1021
& 510
^ 470
& 1022
& 251
& 760
& 1016
| 772
| 515
 1
& 1023
 1
| 0
 2
| 56
^ 875
 1
^ 1023
 2
| 999
^ 689
 3
^ 125
^ 377
& 1019
 1
& 123

3
& 0
| 0
^ 0
 3
& 1023
| 0
^ 123
 3
& 763
| 763
^ 0
 3
& 1
| 0
^ 0
 3
& 1023
| 123
^ 0
 3
& 1023
| 0
^ 0
 3
& 1023
| 1023
^ 0
 3
& 1010
| 768
^ 240
 2
| 775
^ 112
 3
& 1023
| 0
^ 0
 3
& 1023
| 0
^ 0
 3
& 983
| 16
^ 835
 3
& 1023
| 0
^ 1023
 3
& 350
| 326
^ 16
 3
& 1019
| 0
^ 256
 3
& 123
| 0
^ 0

from operator import and_, or_, xor

n = int(input())
ops = []
for _ in range(n):
    s = input().split()
    ops.append([s[0], int(s[1])])

#print(ops)
samples = [0, 1023]
ans = []

tab = {'^': xor, '&': and_, '|': or_}
for s in samples:
    for op in ops:
        s = tab[op[0]](s, op[1])
    ans.append(s)

#print(ans)
diz, con, xxor = '', '', ''
for b1, b2 in zip(bin(ans[0])[2:], bin(ans[1])[2:]):
    if b1 == '1' and b2 == '0':
        diz += '0' # |
        con += '1' # &
        xxor += '1' # ^
    elif b1 == '0' and b2 == '1':
        diz += '0'
        con += '1'
        xxor += '0'
    elif b1 == '1' and b2 == '1':
        diz += '1'
        con += '1'
        xxor += '0'
    elif b1 == '0' and b2 == '0':
        diz += '0'
        con += '0'
        xxor += '0'
print(3)
print('|', int(diz, 2))
print('&', int(con, 2))
print('^', int(xxor, 2))

