12
 1378
 51202278
 989898989
 4
 7
 9
 6
 8
 12193721
 999999995
 999999999
 11
 999999996
 999999998
 3
 14
 15
 10
 999999994
 1000
 13781378
 5
 999999997
 1000000000
 13
 16
 0

6
 4
 4
 8
 6
 2
 8
 4
 6
 8
 2
 2
 2
 6
 4
 2
 4
 2
 4
 4
 6
 4
 8
 8
 6
 8
 6
 1

# lets see if we can find a trivial pattern

# 1378 = 2*53*13

# we know it's going to be even only since we have the two

# we can just examine what happens at the last digit actually

# 1378 = 1000+300+70+8
# if we are concerned with only the last digit, 1378^n % 10 will be just concerned with the 8^n term

i = int(input())
n = 1
if i != 0:
    i = i%4+4
    while i > 0:
        i -= 1
        n *= 8
        n = n%10
print(n)
