#pragma GCC optimize("O3")

#define _GLIBCXX_DEBUG
#include <iostream>
#include <vector>
#include <string>
#include <string_view>
#include <algorithm>
#include <cmath>
#include <iomanip>
#include <cassert>
#include <list>
#include <map>
#include <set>
#include <queue>
#include <deque>
#include <stack>
using namespace std;

/*----------macros----------*/

//output================
#define endl '\n'
#define fcout cout << fixed << setprecision(15)

//typedef===============
typedef long long       ll;
typedef long double     ld;
typedef pair<int, int>  Pii;
typedef pair<ll, ll>    Pll;

//const number==========
constexpr ll INF9   = (ll)1e9 + 1;
constexpr ll INF18  = (ll)1e18 + 1;
constexpr ll MOD    = 1000000007;
constexpr ld PI     = 3.141592653589793L;

//member================
#define pb push_back
#define eb emplace_back
#define pf push_front
#define mp make_pair
#define fi first
#define se second

//others================
#define all(x)          (x).begin(), (x).end()
#define rall(x)         (x).rbegin(), (x).rend()
#define rep(i, n)       for(int i = 0; (i) < (n); ++(i))
#define reps(i, n)       for(int i = 1; (i) <= (n); ++(i))
#define rrep(i, n)      for(int i = n - 1; (i) >= 0 ; --(i))
#define CtoI(c)         int((c)) - int('0')
#define ItoC(c)         char((c) + '0')

//functions=============
template<typename T1, typename T2>
inline bool chmax(T1 &a, T2 b) { return a < b && (a = b, true); }

template<typename T1, typename T2>
inline bool chmin(T1 &a, T2 b) { return a > b && (a = b, true); }

//vector<int> dx = {1, 0, -1, 0}, dy = {0, 1, 0, -1};
//vector<int> dx2 = { 1,1,0,-1,-1,-1,0,1 }, dy2 = { 0,1,1,1,0,-1,-1,-1 };

/*--------additional--------*/

#define MOD2 998244353
int dp[200005];

/*----------main------------*/

int main() {
/*----------fastio----------*/
    std::cin.tie(nullptr);
    std::cout.tie(nullptr);
    std::ios::sync_with_stdio(false);
/*----------solve-----------*/

    int n, k; cin >> n >> k;
    vector<int> L(k), R(k);
    vector<int> s;
    s.reserve(200005);

    rep(i, k){
        cin >> L[i] >> R[i];
        if(L[i] == R[i]) s.pb(L[i]);
        else if(L[i] < R[i]){
            for(int j = L[i]; j <= R[i]; ++j) s.pb(j);
        }
    }

    sort(all(s));

    ll ans = 0, sum = 0;
    for(auto &x : s){
        sum += x;
    }

    for(int i = 1; i <= n; ++i){
        if(sum )
    }

return 0;
}