
import heapq
import collections
import math
import sys
N =  int(input())
input = sys.stdin.readline
# num = a << b →  a  * (2 ** b)
# 1 << i → i桁目のマスク
# mask = 1 << i
# num = a << b
# num & mask


#
nums = list(map(int,input().split(" ")))
keta = [0] * 62
# ある桁の1の出現回数
# keta[k] → 2**k の桁
jijou = []
MOD = 10 ** 9 + 7


for num in nums:
    s = format(num,"b")
    l = len(s)

    for i in range(0,l):
        if s[l - i - 1 ] == "1":
            keta[i] += 1

ans = 0
temp = 1
for i in range(62):

    ans += ( keta[i] * (N - keta[i])) * temp
    ans %= MOD
    temp *= 2
    temp %= MOD
print(ans)