100 1
1000000 100 1000
 5 3
1 4 10
2 2 5
3 1 6
 10 4
1 5 20
2 5 200
100 6 20
101 1 100
 5 3
1 3 4
4 3 4
6 4 1
 4 1
6 1 1
 8 6
1 3 20
4 2 1
6 6 5
9 1 1
15 3 6
21 8 8
 4 5
1 2 3
2 1 3
3 1 2
4 3 3
5 4 1
 8 4
1 3 2
2 3 100
10 6 20
11 5 20
 4 10
1 1 1
3 1 2
4 1 2
6 1 2
8 1 2
13 1 2
16 1 1
17 1 2
19 3 1
20 1 1
 5 3
1 4 4
4 2 2
5 5 2
 4 3
1 3 10
2 2 15
12 4 1
 5 4
1 1 4
2 4 4
5 2 20
11 5 2
 1 10
4 1 1
9 1 1
10 1 1
12 1 1
13 1 1
15 1 1
16 1 1
18 1 1
19 1 1
20 1 1

5050
 10
-1
5
 15
40
-1
1
 6
-1
10
 1
 6
9
-1
4
15
36
 3
3
4
-1
10
 6
15
-1
21
 1
1
2
1
1
1
1
1
6
1
 10
-1
15
 6
-1
10
 1
14
-1
15
 1
1
1
1
1
1
1
1
1
1

#include <bits/stdc++.h>
using namespace std;
const long double pi = 3.14159265358979323846;
long long MOD = 1e9 + 7;
const char nl = '\n';
const long long inf = 1e15;
long long nxt() {
  long long x;
  cin >> x;
  return x;
}
long long mul(long long x, long long y) {
  return (1ll * (x % MOD) * (y % MOD));
}
long long modpow(long long x, long long y) {
  long long z = 1;
  while (y > 0) {
    if (y % 2) z = mul(z, x);
    x = mul(x, x);
    y /= 2;
  }
  return z;
}
long long power(long long x, long long y) {
  long long z = 1;
  while (y > 0) {
    if (y % 2) z = z * x;
    x = x * x;
    y /= 2;
  }
  return z;
}
long long gcd(long long a, long long b) {
  if (a < b) return gcd(b, a);
  if (b == 0) return a;
  return gcd(b, a % b);
}
long long min(long long a, long long b) {
  if (a < b) return a;
  return b;
}
long long max(long long a, long long b) {
  if (a > b) return a;
  return b;
}
long long sq(long long a) {
  long long ans = (1ll * a * a);
  return ans;
}
void solve() {
  long long n, q;
  cin >> n >> q;
  vector<long long> ot(n + 1);
  for (long long j = 0; j < q; j++) {
    long long t, k, d;
    cin >> t >> k >> d;
    long long fst = -1;
    for (long long i = 1; i <= n; i++) {
      if (ot[i] < t) {
        fst = i;
        break;
      }
    }
    if (fst == -1 || fst + k - 1 > n) {
      cout << -1 << nl;
      continue;
    }
    long long ans = 0;
    for (long long i = fst; i <= fst + k - 1; i++) {
      ot[i] = t + d - 1;
      ans += i;
    }
    cout << ans << nl;
  }
}
int main() {
  ios::sync_with_stdio(false);
  cin.tie(0), cout.tie(0);
  long long TC = 1;
  while (TC--) {
    solve();
  }
  cerr << "Time : " << 1000 * ((double)clock()) / (double)CLOCKS_PER_SEC
       << "ms\n";
}
