44 58 90 53
 20 14 37 71
 4 2 4 2
 1 2 5 5
 1 2 8 9
 99 100 3 98
 92 69 83 97
 3 1 1 1
 18 88 18 18
 1 1 1 1
 69 7 44 30
 90 30 30 30
 1 2 3 5
 1 1 3 1
 6 3 6 6
 26 52 7 19
 6 4 8 6
 10 2 3 5
 34 11 84 39
 1 1 14 12
 3 2 1 1
 2 4 6 6
 1 1 2 1
 72 96 2 26
 97 95 91 27
 1 2 1 3
 1 1 2 3
 1 1 1 2
 1 1 10 20
 2 3 2 5
 1 2 10 7
 2 1 28 9
 4 4 4 8
 2 2 4 6
 72 52 62 62
 76 97 99 74
 100 100 99 100
 30 74 41 63
 5 10 1 6
 18 17 17 20
 2 4 1 1
 7 3 6 3
 1 1 4 5
 2 2 6 2
 1 2 6 3
 3 5 1 3
 70 100 10 86
 48 14 3 31
 2 6 3 2
 2 3 10 10
 4 4 12 4
 14 9 10 6
 100 98 99 97
 5 7 1 3
 1 1 4 2
 14 10 18 24
 1 100 100 1
 1 2 4 5
 1 2 3 4
 1 2 3 3
 4 4 4 5
 66 68 16 82
 1 2 3 2
 2 3 3 4
 100 100 100 100
 1 2 2 7
 3 14 36 53
 1 1 3 4

NO
 YES
 YES
 NO
 YES
 NO
 NO
 YES
 NO
 YES
 NO
 YES
 NO
 YES
 NO
 YES
 YES
 YES
 YES
 YES
 NO
 NO
 NO
 YES
 NO
 NO
 NO
 NO
 NO
 NO
 YES
 NO
 NO
 NO
 YES
 YES
 NO
 YES
 YES
 NO
 YES
 NO
 NO
 YES
 YES
 YES
 NO
 YES
 NO
 NO
 YES
 NO
 YES
 YES
 YES
 NO
 YES
 YES
 YES
 NO
 NO
 NO
 YES
 YES
 YES
 NO
 YES
 NO

'''input
1 7 11 5
'''
from collections import defaultdict as dd
from collections import Counter as ccd
from itertools import  permutations as pp
from itertools import combinations as cc
from random import randint as rd
from bisect import bisect_left as bl
from bisect import bisect_right as br
import heapq as hq
from math import gcd
'''
Author : dhanyaabhirami
Hardwork beats talent if talent doesn't work hard
'''
'''
Stuck?
See github resources
Derive Formula
Kmcode blog
CP Algorithms Emaxx
'''
mod=pow(10,9) +7
def inp(flag=0):
    if flag==0:
        return list(map(int,input().strip().split(' ')))
    else:
        return int(input())

# Code credits
# assert(debug()==true)
# for _ in range(int(input())):

# n,k=inp()
# s=list(input().strip())
# i=0
# while i<n and k>0:
#     if i==0:
#         if n==1:
#             s[i]='0'
#         elif s[i]!='1':
#             s[i]='1'
#             k-=1
#     elif s[i]!=0:
#         s[i]='0'
#         k-=1
#     i+=1
# print("".join(s))
def canPartition( nums):
    if len(nums) < 2: return False
    
    total = sum(nums)
    if total & 1: return False
    
    target, memo = total//2, {}
    return dfs(tuple(nums),target,memo)

def dfs( nums,target,memo):
    if not nums: return False
    
    if nums in memo: 
        return memo[nums]
    
    s = sum(nums)
    if s == target: 
        memo[nums] = True
        return True
    
    if s < target: 
        memo[nums] = False
        return False
    
    for i in range(len(nums)):
        _nums = list(nums)
        n = _nums.pop(i)
        if dfs(tuple(_nums),target,memo):
            memo[nums] = True
            return True
        
    memo[nums] = False
    return False
l= inp()
if canPartition(l):
    print("YES")
else:
    print("NO")

