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 4
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 6
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 3
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 4
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 10
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 6
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 4
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 2
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 5
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 2
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 3
lt
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 4
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//#define NDEBUG

#include <bits/stdc++.h>
#include <bits/extc++.h>

#define StarBurstStream ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0);
#define iter(a) a.begin(), a.end()
#define riter(a) a.rbegin(), a.rend()
#define lsort(a) sort(iter(a))
#define gsort(a) sort(riter(a))
#define pb(a) push_back(a)
#define eb(a) emplace_back(a)
#define pf(a) push_front(a)
#define pob pop_back()
#define pof pop_front()
#define mp(a, b) make_pair(a, b)
#define F first
#define S second
#define mt make_tuple
#define gt(t, i) get<i>(t)
#define iceil(a, b) (((a) + (b) - 1) / (b))
#define tomax(a, b) ((a) = max((a), (b)))
#define printv(a, b) {bool pvaspace=false; \
for(auto pva : a){ \
    if(pvaspace) b << " "; pvaspace=true;\
    b << pva;\
}\
b << "\n";}

//#define TEST

using namespace std;
using namespace __gnu_pbds;

typedef long long ll;
typedef unsigned long long ull;
typedef long double ld;

using pii = pair<int, int>;
using pll = pair<ll, ll>;
using pdd = pair<ld, ld>;
using tiii = tuple<int, int, int>;

const ll MOD = 1000000007;
const ll MAX = 2147483647;

template<typename A, typename B>
ostream& operator<<(ostream& o, pair<A, B> p){
    return o << '(' << p.F << ',' << p.S << ')';
}

int main(){
    StarBurstStream

    int n;
    cin >> n;

    vector<int> cnt(26);

    string s;
    cin >> s;
    int tmp = 1;
    for(int i = 1; i < s.size(); i++){
        if(s[i] == s[i - 1]) tmp++;
        else cnt[s[i - 1] - 'a'] = max(cnt[s[i - 1] - 'a'], tmp), tmp = 1;
    }
    cnt[s.back() - 'a'] = max(cnt[s.back() - 'a'], tmp);

    for(int i = 1; i < n; i++){
        cin >> s;
        int pr = 1, sf = 1;
        for(; pr < s.size() && s[pr] == s[0]; pr++);
        for(; sf < s.size() && s[s.size() - 1 - sf] == s.back(); sf++);
        for(int j = 0; j < 26; j++){
            if(s[0] == 'a' + j && pr == s.size()){
                cnt[j] = cnt[j] + (cnt[j] + 1) * pr;
                continue;
            }
            cnt[j] = 1;
            if(s[0] == 'a' + j && s[0] == s.back()) cnt[j] = max(cnt[j], 1 + pr + sf);
            if(s[0] == 'a' + j) cnt[j] = max(cnt[j], 1 + pr);
            if(s.back() == 'a' + j) cnt[j] = max(cnt[j], 1 + sf);
        }
    }

    cout << *max_element(iter(cnt)) << "\n";

    return 0;
}