You are given a board of size n × n, where n is odd (not divisible by 2). Initially, each cell of the board contains one figure.

In one move, you can select exactly one figure presented in some cell and move it to one of the cells sharing a side or a corner with the current cell, i.e. from the cell (i, j) you can move the figure to cells: 

  * (i - 1, j - 1); 
  * (i - 1, j); 
  * (i - 1, j + 1); 
  * (i, j - 1); 
  * (i, j + 1); 
  * (i + 1, j - 1); 
  * (i + 1, j); 
  * (i + 1, j + 1); 



Of course, you can not move figures to cells out of the board. It is allowed that after a move there will be several figures in one cell.

Your task is to find the minimum number of moves needed to get all the figures into one cell (i.e. n^2-1 cells should contain 0 figures and one cell should contain n^2 figures).

You have to answer t independent test cases.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 200) — the number of test cases. Then t test cases follow.

The only line of the test case contains one integer n (1 ≤ n < 5 ⋅ 10^5) — the size of the board. It is guaranteed that n is odd (not divisible by 2).

It is guaranteed that the sum of n over all test cases does not exceed 5 ⋅ 10^5 (∑ n ≤ 5 ⋅ 10^5).

Output

For each test case print the answer — the minimum number of moves needed to get all the figures into one cell.

Example

Input


3
1
5
499993


Output


0
40
41664916690999888
"""Template for Python Competitive Programmers prepared by pa.n.ik, kabeer seth and Mayank Chaudhary """

# to use the print and division function of Python3
from __future__ import division, print_function

"""value of mod"""
MOD = 998244353
mod = 10**9 + 7

"""use resource"""
# import resource
# resource.setrlimit(resource.RLIMIT_STACK, [0x100000000, resource.RLIM_INFINITY])

"""for factorial"""

def prepare_factorial():
    fact = [1]
    for i in range(1, 10005):
        fact.append((fact[-1] * i) % mod)
    ifact = [0] * 10005
    ifact[10004] = pow(fact[10004], mod - 2, mod)
    for i in range(10004, 0, -1):
        ifact[i - 1] = (i * ifact[i]) % mod

    return fact, ifact

"""uncomment next 4 lines while doing recursion based question"""
# import threading
# threading.stack_size(1<<27)
import sys
# sys.setrecursionlimit(10000)


"""uncomment modules according to your need"""
# from bisect import bisect_left, bisect_right, insort
# from itertools import repeat
# from math import floor, ceil, sqrt, degrees, atan, pi, log
# from heapq import heappop, heapify, heappush
# from random import randint as rn
# from Queue import Queue as Q
from collections import Counter, defaultdict, deque
# from copy import deepcopy
# from decimal import *


def modinv(n, p):
    return pow(n, p - 2, p)


def ncr(n, r,  fact, ifact):  # for using this uncomment the lines calculating fact and ifact
    t = (fact[n] * (ifact[r]*ifact[n-r]) % mod)% mod
    return t



def get_ints(): return map(int, sys.stdin.readline().strip().split())
def get_array(): return list(map(int, sys.stdin.readline().strip().split()))
def input(): return sys.stdin.readline().strip()

"""*****************************************************************************************"""

def GCD(x, y):
    while (y):
        x, y = y, x % y
    return x

def lcm(x, y):
    return (x*y)//(GCD(x, y))

def get_xor(n):
    return [n,1,n+1,0][n%4]

def bin_pow(a, b):
    res = 1
    while b:
        if b&1:
            res = (res * a)
            b -= 1
        else:
            a = (a* a)
            b>>=1

    return res

""" ********************************************************************************************* """


def main():

    def summation(n):

        return (n*(n+1))//2

    T = int(input())
    while T:
        n = int(input())
        p = n//2

        ans = 0
        for i in range(p):
            ans += (summation(p)*8 - summation(i)*8)

        print(ans)
        T-=1

""" -------- Python 2 and 3 footer by Pajenegod and c1729 ---------"""

py2 = round(0.5)
if py2:
    from future_builtins import ascii, filter, hex, map, oct, zip

    range = xrange

import os, sys
from io import IOBase, BytesIO

BUFSIZE = 8192


class FastIO(BytesIO):
    newlines = 0

    def __init__(self, file):
        self._file = file
        self._fd = file.fileno()
        self.writable = "x" in file.mode or "w" in file.mode
        self.write = super(FastIO, self).write if self.writable else None

    def _fill(self):
        s = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
        self.seek((self.tell(), self.seek(0, 2), super(FastIO, self).write(s))[0])
        return s

    def read(self):
        while self._fill(): pass
        return super(FastIO, self).read()

    def readline(self):
        while self.newlines == 0:
            s = self._fill();
            self.newlines = s.count(b"\n") + (not s)
        self.newlines -= 1
        return super(FastIO, self).readline()

    def flush(self):
        if self.writable:
            os.write(self._fd, self.getvalue())
            self.truncate(0), self.seek(0)


class IOWrapper(IOBase):
    def __init__(self, file):
        self.buffer = FastIO(file)
        self.flush = self.buffer.flush
        self.writable = self.buffer.writable
        if py2:
            self.write = self.buffer.write
            self.read = self.buffer.read
            self.readline = self.buffer.readline
        else:
            self.write = lambda s: self.buffer.write(s.encode('ascii'))
            self.read = lambda: self.buffer.read().decode('ascii')
            self.readline = lambda: self.buffer.readline().decode('ascii')


sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip('\r\n')

# sys.stdin = open('input.txt', 'r')
# sys.stdout = open('output.txt', 'w')

""" main function"""

if __name__ == '__main__':
    main()
    # threading.Thread(target=main).start()