Natasha is going to fly to Mars. She needs to build a rocket, which consists of several stages in some order. Each of the stages is defined by a lowercase Latin letter. This way, the rocket can be described by the string — concatenation of letters, which correspond to the stages.

There are n stages available. The rocket must contain exactly k of them. Stages in the rocket should be ordered by their weight. So, after the stage with some letter can go only stage with a letter, which is at least two positions after in the alphabet (skipping one letter in between, or even more). For example, after letter 'c' can't go letters 'a', 'b', 'c' and 'd', but can go letters 'e', 'f', ..., 'z'.

For the rocket to fly as far as possible, its weight should be minimal. The weight of the rocket is equal to the sum of the weights of its stages. The weight of the stage is the number of its letter in the alphabet. For example, the stage 'a 'weighs one ton,' b 'weighs two tons, and' z' — 26 tons.

Build the rocket with the minimal weight or determine, that it is impossible to build a rocket at all. Each stage can be used at most once.

Input

The first line of input contains two integers — n and k (1 ≤ k ≤ n ≤ 50) – the number of available stages and the number of stages to use in the rocket.

The second line contains string s, which consists of exactly n lowercase Latin letters. Each letter defines a new stage, which can be used to build the rocket. Each stage can be used at most once.

Output

Print a single integer — the minimal total weight of the rocket or -1, if it is impossible to build the rocket at all.

Examples

Input

5 3
xyabd


Output

29

Input

7 4
problem


Output

34

Input

2 2
ab


Output

-1

Input

12 1
abaabbaaabbb


Output

1

Note

In the first example, the following rockets satisfy the condition:

  * "adx" (weight is 1+4+24=29);
  * "ady" (weight is 1+4+25=30);
  * "bdx" (weight is 2+4+24=30);
  * "bdy" (weight is 2+4+25=31).



Rocket "adx" has the minimal weight, so the answer is 29.

In the second example, target rocket is "belo". Its weight is 2+5+12+15=34.

In the third example, n=k=2, so the rocket must have both stages: 'a' and 'b'. This rocket doesn't satisfy the condition, because these letters are adjacent in the alphabet. Answer is -1.
// AUTHOR : MAYANK SUNAL

import java.io.*;
import java.util.*;
import java.math.*;

public class Main {
	static final Random random = new Random();
	static PrintWriter out = new PrintWriter((System.out));
	static Reader sc = new Reader();

	public static void main(String args[]) throws IOException {
//		System.out.println(8&7);
//		int t = sc.nextInt();
//		while (t-- > 0) {
//        	CODE START FROM HERE long n = sc.nextLong();
		int n = sc.nextInt();
		int k = sc.nextInt();
		String s = sc.next();
		boolean chk = true;
		char tempArray[] = s.toCharArray();
		Arrays.sort(tempArray);
		s = new String(tempArray);
		if (n == 1) {
			System.out.println(1);
			chk = false;
		}
		if (chk) {
			boolean flag = true;
			int res = (int) s.charAt(0) - 96;
			char c = s.charAt(0);
			int count = 1;
			for (int i = 0; i < n; i++) {
				if (count == k) {
					flag = false;
					break;
				} else if ((int) s.charAt(i) == (int) c + 1 || s.charAt(i) == c)
					continue;
				else if (count < k) {
					count++;
					c = s.charAt(i);
					res += (int) s.charAt(i) - 96;
				}

			}

			if (flag)
				System.out.println(-1);
			else
				System.out.println(res);
		}
//		}

	}

// Fast Input Output
	static class Reader {
		BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
		StringTokenizer st = new StringTokenizer("");

		public String next() {
			while (!st.hasMoreTokens()) {
				try {
					st = new StringTokenizer(br.readLine());
				} catch (Exception e) {
					e.printStackTrace();
				}
			}
			return st.nextToken();
		}

		public int nextInt() {
			return Integer.parseInt(next());
		}

		public long nextLong() {
			return Long.parseLong(next());
		}

		public double nextDouble() {
			return Double.parseDouble(next());
		}

		public String nextLine() {
			try {
				return br.readLine();
			} catch (Exception e) {
				e.printStackTrace();
			}
			return null;
		}

		public boolean hasNext() {
			String next = null;
			try {
				next = br.readLine();
			} catch (Exception e) {
			}
			if (next == null) {
				return false;
			}
			st = new StringTokenizer(next);
			return true;
		}

	}

	// EFFICIENT SORTING Ascending
	static void ruffleSortAsc(Integer[] a) {
		int n = a.length; // shuffle, then sort
		for (int i = 0; i < n; i++) {
			int oi = random.nextInt(n), temp = a[oi];
			a[oi] = a[i];
			a[i] = temp;
		}
		Arrays.sort(a);
	}

//	EFFICIENT SORTING Descending
	static void ruffleSortDesc(Integer[] a) {
		int n = a.length; // shuffle, then sort
		for (int i = 0; i < n; i++) {
			int oi = random.nextInt(n), temp = a[oi];
			a[oi] = a[i];
			a[i] = temp;
		}
		Arrays.sort(a, Collections.reverseOrder());
	}

	// Array Sum
	static long sum(Integer[] arr) {
		long sum = 0;
		for (int i : arr)
			sum += i;
		return sum;
	}

	// ArrayList Sum
	static long sumal(ArrayList<Integer> al) {
		long sum = 0;
		for (int i : al)
			sum += i;
		return sum;
	}

	// swap array elements
	static void swap(int arr1[], int arr2[], int i, int j) {
		int temp = arr1[i];
		arr1[i] = arr2[j];
		arr2[j] = temp;
	}

	// reading array value;
	static void read(Integer[] arr) {
		for (int i = 0; i < arr.length; i++)
			arr[i] = sc.nextInt();
		return;
	}

//    reading arraylistValue

	static void readal(List<Integer> l, int n) {
		for (int i = 0; i < n; i++)
			l.add(sc.nextInt());
		return;
	}

	// check for even odd
	static boolean isEven(long n) {
		return ((n & 1) != 1);
	}

	// max in a array
	static int max(Integer[] arr) {
		int max = Integer.MIN_VALUE;
		for (int i = 0; i < arr.length; i++)
			if (max < arr[i])
				max = arr[i];
		return max;
	}

//  print array
	static void printarr(Integer arr[]) {
		for (int i : arr)
			System.out.println(i);
	}

// ceil of two elements
	static int ceil(int a, int b) {
		return (int) Math.ceil(((double) a / (double) b));
	}

// floor of two elements
	static int floor(int a, int b) {
		return (int) Math.floor(((double) a / (double) b));
	}
}